#point-set-topology
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All forms on S^n are closed, so we just need to find a form with nontrivial integral
🧢
You can take the volume form
ty terra
The volume form of a submanifold can be computed using a unit normal vector
Although ig F isn't exactly the normal vector? Weird
it's a solid angle
so its integral over anything that encloses the sphere will be 4pi (if it doesn't do any funny stuff)
@dmashura
Okay I remembered correctly
But now I see
Your F is just a nonzero function times the volume form
errr
I think I'm still confused but also need to do analysis 
a lot of the stuff lee proves in ISM about riemannian manifolds are exercises in IRM chapter 2

good luck
remember triangle inequality
you got this 
Legit the theorem I'm most worried about applying correctly on the test is the triangle inequality*
*the Minkowski inequality for integrals
spinsicle
I think this is essentially the lifting property of a fibration, although I'm not sure. A map I^n -> B with boundary mapped to the basepoint x0 of B can be lifted to a map I^n -> E, and the boundary is now going to be mapped into F = the fiber over x0
I'm not comfortable with relative homotopy groups, so this might be wrong
But I think "lifting property of a fibration" is the right idea
Like we have a map (E, F) -> (B, x0), and the question is why this is bijective on homotopy groups. Surjective at πn should follow from being able to lift maps of cubes into B up to E and injective should follow from being able to lift homtopies between those maps
hmm I don’t really follow
ya I guess my question is how does that map (E,F)\to (B,*) induce an isomorphism of homotopy groups
fff concise is too concise
are you reading a talk of peters or something
i didnt know concise had language like that
Okay so I think this is the idea. If F is the fiber over the basepoint of B then maps (D^n,S^n-1)->(E,F) extend nicely to (B,x_0)
Then the maps D^n/S^n-1->B are also maps D^n->B
I mean you can just compose, can't you? The trick is going back the other way
you lift these
and it turns out
this is automatically a map of pairs for the lift to make sense
And these processes should be inverse to eachother
so sham had the correct idea
my point is that if the pair was (E,Y) with Y \neq F it wouldnt work
Ah sure
I have a final in a few hours but I think this should be correct @gritty widget
also pls do tell me if that paragraph is actually in concise bc it looks like lecture notes
and I think peter explains this better in real concise
(these lifting properties for Serre fibrations might be more obvious if you think I^n instead of D^n)
Can any kings or queens help me with thesis topic? The things I’ve most liked have been learning about characteristic classes and various bundles. I really like these ideas of when conditions on the topology of the base space putting restrictions on the total space
serre spectral sequence
You are into homotopy theory? Can I ask you about how you got into that after your final/ at some later stage?
oh id rather talk about this than my final anyway
honestly its like
50% reus and 50% working w a specific professor
if you are asking how I got into it in a literal sense
I can give book recs
More so, what in homotopy theory interested you
I’ve really enjoyed algebraic topology, but I think I preferred the cohomology side of things
And it spooks me a little when people say that now always homotopy theory is really a seperate field
Yes please
Oh so
I'm not like
a homotopy theorist homotopy theorist
but I normally work in the (stable) homotopy category
which is where modern alg top takes place
I am a topologist moreso than homotopy theorist by contemporary definition probably
My first rec is Hatcher
once you are comfy w the material in there
You should go through Concise
Okay, then I'm successfully between point 1 and point 2
and pay special attention to things like (co)fibrations
if you understood hatcher well concise should be kind of quick
(perhaps a short detour in category theory at the level of the first half of Riehl would be helpful)
But concise is a much more modern perspective
than hatcher
After that its a bit of a free for all
dependning on what you want to learn
Let's say I read 60% of hatcher, since I have more need for the cohomology stuff, but atm less for the homotopy stuff
My categorical foundations are decent I'd say
So probably I should go through chapter 4 of Hatcher and Read concise from beginnig to end 😄
I do enjoy May's writing style very much tho
I’ve had two pretty good courses on algebraic topology
And have seen a decent bit of his k-theory book
I have this fomo
thats a first
I thought I wanted to work in differential topology doing topology of manifolds
But I don’t really want to be doing PDEs the whole time
a lot of the interesting stuff about manifolds does seem to involve ODEs/PDEs
But I do want to be doing something a little more “hands on” working with spaces
I don’t want to end up doing something super abstract homotopy theory
Hmm maybe I should look into k-theory more
So maybe you'd be interested in the type of problems I personally care about
what about algebraic geometry? I think there's a lot of pretty concrete computational fun stuff there
despite its reputation for being horribly abstruse
using a hodgepodge of topological and algebraic techniques
Yeah
Wasn’t hugely gone algebraic geometry
or that don't even work up to homeomorphism
alg top might not be your cup of tea
Like many geometric structures are just out the window
Maybe a problem worth looking into @gritty widget
Is the Kervaire invariant one problem
which starts as a simple question about the middle cohomology of homotopy spheres (manifolds htpy eq to a sphere)
with differential structure
and eventually becomes a homotopy theoretic problem
after a few papers
I really enjoyed Milnors characteristic classes and the homotopy groups of sphere paper
Kervaire-Milnor have a paper titled
Groups of Homotopy Spheres
which is the origin of this longstanding problem
that was recently almost fully solved by Hill-Hopkins-Ravenel
using super high level homotopy-style algtop
But it kind of scared me that people were like this is now just a problem in stable homotopy kevaire invariant
I do really like the idea of learning about surgery
in the words of my mentor in undergrad
"Surgery theory is beautiful mathematics that has recently fell out of fashion among most topologists"
So my advice would be to learn it if you like it because there is probably lots to do in it
but to caution that its not super common in modern research
low dimensional topology has surgery
i remember an old prof who was still doing stuff with dehn surgery, so i think it's still happening
Idk about that
just a little less hype
but lots of great math is less hype
If you want to look into stuff like this
I know Andrew Putman works on problems you might like
Benson Farb as well
and their gang of collaborators
are all very famous and work in more concrete contexts
I really appreciate all this
Benson in particular has a sort of distaste for homotopy theory memes
whereas the read I get on Putman is they just don't fully click with him
(He has often self-deprecatingly joked about it being above his head but given how smart he is I sort of doubt this is the case)
np @gritty widget happy to help. I know @honest narwhal might be more well versed in this stuff bc his interests aligned more w benson and andy
Good luck with this final
Another idea I did like the sound of was this moduli space of riemannian metrics
The idea of moduli spaces is sort of ubiquitous nowadays
topologists sometimes use different names
like classifying spaces
Ooh we talking topology?
He was asking about modern research that isn't of the homotopy-esque flavor
and that might employ things like surgery
I know very little about this so I thought you might know something of use or have papers to rec
@gritty widget how much do you think you might like, on the one hand geometric group theory, and on the other hand "algtop \cap alg geo" type stuff?
It comes and it goes through periods of popularity
Sometimes it's the hot hot thing
And then a decade or two of nothing
Then bamm everyone's in it again
i'd imagine it has to do with how recently it was employed to solve something intersting
I mean
the slogan for perelmann's work
was "Ricci Flow w surgery"
so who knows maybe its in for a renaissance
I did not know anything about geometric group theory, I did not like my undergrad course on groups focusing on finite groups, I did lie my grad course on Lie groups
I like the idea of looking at the algebraic topology of the spaces you look at in algebraic geometry
I did not love the tools being used in algebraic geometry, but I did find it very cool how easy it was to include non smooth spaces in the theory
One thing that did seem cool that I’ve heard in passing is looking at how the topology changes around singularities
So this example of the family of spaces going from two paraboloids, to two touching cones, to one hyperaboloid
also thanks very much to everyone to all of you
So as someone who knows nothing about both
They could be cool things to try out
On the AG\cap AT side you have stuff like Hodge theory
this has been really helpful
Which like okay kinda involves PDE but in a nifty way
And yeah there's a prof at my school who works on topology of singular spaces
And it seems like good stuff. I'm actually taking his class officially but I got very behind this semester so once I catch up on other stuff I'll just go hard on it lol
But yeah that's I think one way to sorta do algebraic topology but not "straight algebra"
I did think about looking at hodge theory stuff, I was looking through my old notes from my undergrad and phone a set of notes on hodge theory i had printed after my electromag teacher said soemthing about it
Geometric group theory is more... I mean "studying groups geometrically" is the slogan. Some vague things include
i don't know what i was thinking trying to read them then
So if you give me a group with generators and relations you can form what's called the Cayley graph
i can barely read those notes now
Now you can put a metric on these graphs and now you have a space on which the group acts
So one thing is studying these for infinite groups
i was just about to ask
it seems that this means you are only working with finite groups
Oh yeah people study these a lot for infinite groups. Here's the one thing vaguely resembling a result I know
So there's a notion of a "hyperbolic metric space"
Basically means that you can find some delta > 0 such that every geodesic triangle is contained in a delta neighborhood of the union of its edges
This includes, obviously finite groups
But also fundamental groups of hyperbolic manifolds
Now it turns out that hyperbolic groups don't contain copies of Z^2
In particular this holds for pi_1(Sigma_g) for g > 2
Which is pretty cool. This was actually a problem in my algebraic topology final which I solved using just basic covering space stuff
But yeah I found it kinda cute that this had a GGT interpretation
@marsh forge you might like this too
But yeah lime soup the other thing I'm vaguely aware of GGT people caring about, and what I think you might actually like more from a super super vague impression
Mapping class groups
If you give me a manifold (possibly with adjectives), you take diffeomorphisms up to isotopy
I have less of a coherent elevator pitch about this stuff since what I know of is very scattered
But there's a lot of super cool math going on there, and it links to topology, algebraic geometry (short version is that these groups are connected with moduli of algebraic curves), apparently even group cohomology, etc
geometric group theory is kinda cool imo
it was something like
study what you like rather than what is fashionable
as you will likely make more progress in the former
Perhaps I should have said a nice real quote
Damn non commutativity of adjectives
What physics are you doing @marsh forge
magnetism
J is a complex structure except on a set of measure zero 
(i know)
you define measure zero for subsets of manifolds using charts and the usual notion in eucliean space iirc
i havent used it in a while
but its important for e.g. sard's theorem
Pretty much, the key is that smooth => preserves measure zero
locally lipschitz 
And that a manifold is second countable
it's in 30 minutes!
good luck
at a math talk rn about rational bitangents ^^
Nice!
Just remember
If you're ever stuck, reduce to algebra
And actually do that if you're not stuck too
coho... what if we kissed... while you took your midterm and i take my midterm... both in 30 minutes... hahaha jk.... unless?
max dont u have a gf
i reckon this discord server has a few narcs
Math Narcs smh
what are you fucking straight
I did this, not via your advice, but I was stuck trying to draw something and just couldn't lol
ohhhhhhhhh I am dummy now I have the picture in my head
that is a much clearer argument than the group theory damnit
not going to comment bc there are people taking the exam later
but
meh
it's okay I don't think a proof was necessarily expected on that part
this is always true in covering space theory except when the group theory is very trivial
Hey guys, hoping this is the right spot for this, let me know if not. I'm working with tensors at the moment, and following some notes. At one point, they have the following lines:
a_i (T^i-T'^(alpha) x^i_(alpha) = 0
delta^k_i (T^i-T'^(alpha) x^i_(alpha) = 0
So in other words they've just done something to both sides such that a_i --> delta^k_i
I'm sure I'm missing something clear here, but I'm wondering how they got from the covariant component a_i to a kronecker delta^k_i
can you latex that
ooh yep, sorry one sec
$a_i (T^i - T'^\alpha x^i_\alpha ) = 0 \
\delta^k_i (T^i - T'^\alpha x^i_\alpha ) = 0$
Spiff Munt
Man, I need to work on my latex skills
But yeah, I'm wondering how they get from the covariant $a_i$ in the first line to the kronecker delta $\delta^k_i$ in the second
Spiff Munt
bi
Damnit I’ve been foiled
I foiled myself
For every quotient map we can define an equivalence relation that turns it into a map from the space to the quotient space?
Like the definition of a quotient map is via surjective, but you can rephrase it in terms of equivalence relations?
yes
this is often called the fundamental theorem of quotient maps or something similar
munkres 22.2
er, 22.3 actually
corollary of 22.2
slimvesus
absolutely not, gfy
on the cotangent bundle of any smooth manifold there is a tautological 1-form, which differentiates to a symplectic form. is there an analogous construction on tangent bundles?

pls no "just pick a riemannian metric lol"
by "analogous" i don't have anything specific in mind
something along the lines of "is there anything nice that we get on a tangent bundle that we can define without picking coordinates / that isn't coordinate-dependent"
tea M
chm chose violence today
seems like maybe euler vector fields are related 
vector field on TM
geodesic field vibes

ok so you get a flow on TM given by Fl(t, X) = e^tX and this differentiates to what's called the "euler vector field" apparently
1-form on T*M and vector field on TM
seems analogous enough

you can prove the darboux theorem with this http://personal.psu.edu/mjf5726/DarbouxEuler.pdf
just pick a riemannian metric lmao

i am going to look into this tomorrow
i finished almost all of my other homework 
I need to write 2 more essays for my writing class 
is there an analogue of the exterior derivative of 1-forms for tangent vectors 
something that eats vector fields and gives me
uh oh
i don't know
2-vector fields 
musical isomorphism--> exterior derivative--> musical isomorphism back? 
i dont wanna make any choices of bundle isomorphisms (or in general i'd just like it to not rely on any extrinsic choices, e.g. riemannian metric)
if possible
vector field is a (1,0)-tensor field
(2,0)-tensor field 
what's a reasonable way to turn something that eats one 1-form into something that eats two 1-forms
i have DG brain rot
i think i mostly follow this argument up until the underlined part
i dont see why independence of x in W implies continuity of the transition map?
Let's see
Or okay this time let's actually see
@fading vale so W is an open path connected neighborhood of x, seems to basically say that in the first coordinate you're constant on path components?
mhm
functors from PI(B) to SET
So okay we're taking the disjoint union of Phi(b), and okay looking up tom Dieck
transport-simple means any two paths sharing endpoints are homotopic
looks to me that the first underlined sentence is just stating well-definedness, and continuity follows from SET
could anybody recommend a nice introduction to clifford algebras?
what they have to do with physics / geometry
it's easy to describe the set, but how do you actually picture it? since the only irreducible polynomials in ℝ[x] are of order 1 and 2, it's easy to imagine Spec ℝ[x] as kind of the orbit space of the action of Gal(ℂ/ℝ) on ℂ
but in ℚ[x], you can have irreducible polynomials of any degree at all, so how do you visualise Spec ℚ[x]
https://pbelmans.ncag.info/blog/atlas/ I think visualizing this in any conventional way is gonna be really weird, but here's some motivating images that do the same for integer polynomials
I guess if you wanted to stretch the analogy with the galois group of $\mathbb{C}/\mathbb{R}$, I guess maybe this space would be like the orbit space of the algebraic closure of $\bar{\mathbb{Q}}$ under the galois group of $\bar{\mathbb{Q}}/\mathbb{Q}$
Lartomato
Which sounds really cool and fancy but probably doesn't get more intuitive than that
i see
(but my engagement with algebraic geometry and these kinda things never went further than chapter 3 of the vakil lecture notes (the ones you're looking at right now) so maybe there's some big boy AG-people who feel more comfy saying something about this)
Does anyone (perhaps @marsh forge) have an recommendations for the more “abstract” of homotopy theory. I think I’ve actually just made myself irrationally afraid of the abstract side. I’ve worked through Hatcher fully and most of the topics in concise
how does continuity follow from SET here :?
@gritty widget As I understand it, there's not really any "natural operations" in differential geometry other than the identity map and the de Rham differential, if you're not willing to make an further choices
Section 34 of "Natural Operations in Differential Geometry" by Kolar, Michor, Slovak
"natural" is a bit cheeky here of course but basically if you're not willing to make choices like a Riemannian metric you gonna be sad
(i've not worked through it but the theorem sounds smart and cool enough for me)
thanks
Also just a general thanks very much to everyone, I think I have wanted to do a thesis in algebraic topology for a while. But the first "advanced maths" i did was a summer reading course in differential geometry. Since them I've had this fomo about not doing a thesis in differential geometry.
In hindsight i think i did just like the topology that appears in differential geometry
i completely forgot i had this book in my folder, thank you for reminding me of it
and ty for the section reference, i guess i have some reading to do 
question I asked my algtop teacher that I think some of yall might be interested in
So the whole deal with homotopy groups is that the homotopy classes of maps S^n -> X carry a group structure which we can write down.
In a sense we're using S^n as a "test space" to examine X via maps into X. Are there any nice spaces which have this same property, that homotopy classes of maps Y -> X always carry nice a group structure. And if so, why are we more interested in the higher homotopy groups than in these other cases. Aka: Why aren't we always considering RP^2-loops in our space.
This seems like a @marsh forge question :)
Also I aced my algtop midterm and I'm very proud of myself ^^
Congrats!!
inceresting
Spheres are the most natural example: they are suspensions of the two point space S^0
mhm
Do you know any reference where you have a formal justification for the following statement that appears in nLab?
https://ncatlab.org/nlab/show/suspensions+are+H-cogroup+objects
"Let $\mathcal{C}...
lmfao Denis
does anyone know how to justify the statement that the pinch map exhibits the cogroup structure?
Denis: Ok, let me try to give you a proof of something that is a lot stronger than what you asked for, but which hopefully is a bit more natural. Recall that an associative monoid in an ∞-category...
MO moment
bruh moment
@cedar pebble so here's a good answer
the only connected compact manifolds with an H-cogroup structure are the spheres
ripped from
ah nice
yea there we go
currently arguing with [redacted] that localizing at p versus localizing away from p are different things
he says they are the same and said I'm bad at CA

oh god
"by the generalized Poincare conjecture"
brother
but you can at least do all of it at once for n≥5

I've tried 3333 times but I still cannot show the Conway knot is not slice
yes

a lot of people tried though
had meeting with Daniel
figured out what was wrong with my computation
now I have a way forward I just have to compute uhhh
a few hundred integrals
might have to be a separate paper
which means another paper 
but it's fairly involved and is probably beyond the scope of the current paper

idk maybe there's a slick way to do it
christ
nG you're being brought along with Daniel to be his personal integral machine

I mean there's likely a better way to do this
using a lot of symmetry
but yea it still kinda sucks

if Y=\Sigma X for some X then [Y,Z] has a group structure induced in the same way
yeah found this out ^^
Alternatively you can play the same game with [X,\Omega Y]
but this is just adjointness stuff
what big theorem
oh that sphere is unique
I think that the dependence here on poincare is overstated
of course if there existed homotopy spheres not homeo to a sphere then you would have manifolds exhibiting the same homotopy properties of S^n
idk if this is particularly deep though
maybe
Like basically the proof is two parts
showing that you need to look homotopically like a sphere
and then trying to leave the homotopy world for a problem about homotopy
and it is very natural that this second part is much harder
yeah that makes sense
yea I think this theorem is largely unrelated to issues in homotopy theory so to speak
still it's interesting
I wonder if you could prove without poincare that the homotopy functors [S^n , -] are the unique H-cogroup functors coming from a connected compact manifold
this is a more homotopy type question
You guys know how to calculate a curvature?
@obtuse meteor You cannot prove it categorically (in hTop)
for the obvious reason that you cant even detect manifoldness
You might be able to do something in Top but it would probably have to be a model categorical approach of some kind?
yeah of course
re: not being able to prove it categorically
IDK how a model categorical approach would look
I'm not big brained enough yet
My point is more like, model category theory is probably the best way to simultaneously work in Top while respecting homotopy equivalences
I don't tend to think about these kinds of questions so idk
because the transition map just comes down to, for c and b fixed, \Phi(u_x v_x^{-1}) or something, and SET in Dieck has continuous maps as morphisms.
i should say, SET in alg top haha
often in alg top people say functions when they mean continuous or even smooth functions

I am once again poasting questions about algebraic topology that are probably dumb but make sense to my small brain
Algtop questions two. Electric Boogaloo: Homology
So are there any nice sequences of spaces X_n so that for any space Y the chain groups C_n(Y) = free group on maps X_n -> Y form a chain complex functorially?
Of course X_n = simplices or X_n = cubes work. (1/?)
empty space?
I need to write "examples in topology"
and every example is just "the empty space"
A locally compact hausdorff space?
A compact space?
A space where every point has a clopen and compact neighborhood?
8^)
very cool thank you

my algtop professor said the words "operad" in office hours today so we're officially in gamer territory
shamrock might know something about this
he talked about dold kan earlier and it seemed kinda similar
or maybe not idk
this feels familiarish
i feel like CW complexes would work 🤔
hmmm
in this case we'd want to expand a bit
like
we wouldn't get a sequence in that case
we'd get like a big filtery-looking thing
if we considered this for all CW complexes
yeah this seems sorta relevant
the defined test categories on the page all seem very combinatorial tho

a huge part of AT is driven by computations
(so, at least it's slightly more understandable...)
no I agree computations are good
I'm just meme
petthesully
I do wonder though if there is this entire world of like
not computable things that are still weird and interesting
and maybe if you have some smooth structure on the test spaces
it's still computable
(maybe only in smooth cases)
homotopy groups of spheres
cohomology/k-theory of classifying spaces would be the analogue of homotopy groups of spheres ig

people do study them extensively
and it is super cool
group cohomology is very interesting
Whats Openness
type theorists NEED to be stopped
Lmao
I swear
I did not see this
Before tweeting a reply
👀
also im like 3/5ths of the way done rereading ch 3 of tom dieck and proving everything myself

ok well like
85-90% myself
my algtop professor is now of the opinion that the like proofs of excision and similar things
are not important for us and are just gonna get sketched
are disgusting?
bc we must learn to compute
computing >>>>>>>>>
lol wait i wonder if tom dieck has some completely ridiculous proof of excision
nooooooo he does barycentric subdivision too
pain
shamrock im like 99% certain uve complained about barycentric subdivision and the proof of excision to me b4
I absolutely have
we didn't even do proof that homotopies give you chain homotopies
we were just like
"so intutitively you subdivide Delta^n x I into simplices, but it's disgusting"
chad Jenny
make up ur mind smh
I am multifaceted
tbh faye that approach isnt even that bad
i think reading abt it independently is better than going thru the tedium
Oh yeah Faye so what I'm thinking is like
For singular homology (and de rham coho)
You prove homotopy invariance by constructing a chain homotopy
yeah
It's not just that they abstractly are homotopic or whatever
and hopefully this is functorial on the level of homotopies

Functorial is my favorite bullshit adjective
are there any choices
It's so bad
The subdivision one?
Yee
It all comes from a subdivision of Δ^n × I
Not anything about the space
So it feels like, canonical
yeah
maybe you have to pick a subdivision of Delta^n x I
once
but once you do you're good right
so if you have a homotopy H : X×I -> Y
Let i0, i1 : X-> X×I include at the top and bottom
then you have these chain maps C(H°i0) and C(H°i1)
hmm
I'm trying to remember how this goes
Oh right
That's C(H) ° C(i0) and C(H) ° C(i1)
so what you really want
Is that i0, i1 are chain homotopic
For any X
Because then you can like, whisker or whatever it's called
So it comes down to why the maps C -> X×I induce chain homotopic maps on homology
Yeah, I think so
I'm just trying to like
Formally relate this all back to Δ^n×I
anyone down to help me check my work on Hatcher 2.2.28?
sorry this thing is mislabeled
but i broke it up into the 2-torus and the mobius band
honestly it’s the algebra i feel least confident on
yeah exact sequence stuff can be wacky
i think you should put a delta complex on the space
you have it set up as squares so you can put one on X and Y respectively and just make sure they agree
okay yeah i'll try that
(this might be easier if you remember that a mobius band can also be obtained from a delta complex on a triangle)
I want to go through a handout but don't want to do it alone
This is rather long
just do the first and last exericses
89 pages done immediately
:/
i feel like u should attempt these independently
and then come here if u need help after ruminating on a particular problem
I guess so. I was just looking if anyone else wants to because studying with other people can be easier
I will be back promptly then if I have a question
Is there are reason we define topological spaces with open subsets?
you can also define a topology as a collection of sets containing empty, whole set, which is closed under arbitrary intersection and finite union
define it by closed sets 
Are those two definitions equivalent?
try proving it
Since the sets would be complements right?
Hmm let me try to prove it and I will be back
if you define a topology this way (i.e. by its closed sets) then you take complements to get back to your open sets
and vice versa
Yea that was my guess just trying to make it rigorous
Is there a reason why not a mix of both?
Just general subsets
the idea of "open" as a label is that we are distinguishing some subsets from others
so im not totally sure what u mean by "why not a mix of both"
I meant why not define it with general subsets?
instead of putting the category of just open
"open" is an arbitrary label we assign to certain subsets of the set
well its not arbitrary though?
fulfilling certain conditions (union of open sets must be open, as must finite intersections, and the entire space and empty set)
isnt it the definition from real analysis
uh okay hold up what is your definition of a topology here
oh I just got it
since its not induced by a metric we are referring to general open sets
yeah
and those general sets can be any collection of subsets of our space X as long as they fulfill our 3 rules
ahhh thank you!
np
you did most of the work yourself anyway :p
kinda one of those cases where talking at someone abt it helps you clear it up for yourself lol
definitely haha

ill ask you
f:X->Y is a function between two topological spaces
Graph(f)={(x,f(x)) in X x Y| x in X}
Prove if f is continuous and Y Hausdorff then Graph(f) is closed.
So my guess is that we WTS X x Y - {(x,f(x)) in X x Y| x in X} is open
me thinks X x Y - {(x,f(x)) in X x Y| x in X} reduces to X x (Y- f(X))
is that correct?
Think about a constant function R-> R
What does the first set look like? The second?
These are sets in the plane
wait, I may have fucked up and found an example where this works...
R x R - R x {3}?
R x R - R x (img(f)=R+) = R x R-
That's the second set
wait it isnt the first?
X × (Y - f(X))
Nope
So the first set is the complement of the graph
You just cut a parabola out of the plane
I was thinking that graph was something weird like R x Img(f)
Ah gotcha
Shortcuts are how you do math :)
so if I dont simplify it further and just try to show that X x Y - Graph(f) is open
would I just apply theorem stating what makes a set open in product topology?
can I go straight to that
and also see if I can apply hausdorff and continuous
or are there some intermediate steps I could be missing?
i.e. should I just follow my nose?
Hmm
So I have a proof in mind
But it relies on a different result you may not have seen
wait
I would try following your nose
what does it deal with?
There's an equivalent condition to be hausdorff
oh
I would suggest trying to do this problem the way you were thinking of
Nope, singleton sets closed is weaker
Example: the cofinite topology on an infinite set
o
There are no disjoint nonempty open sets at all, right?
yea
another guess b4 i start trying stuff out
Mhm
does it have to do with seperability?
Do you mean separability in the sense of "hausdorff" being a separation axiom or are you talking about the property of a space having a countable dense subset?
i meant like a seperation
ive heard something about hausdroff being a seperation axiom
but not rly sure what it means
cuz my line of thought
It's sort of an informal term
is if I think of it as a graph on R2
You will need to use hausdorff at some point for sure
removing the graph seperates the space into two sections
In fact, having this for all spaces X and all maps f : X -> Y is equivalent to Y being hausrdoff
oh wait
i think i visualized a proof for r2
but
it doesnt make sense
because it isnt hausdroff
or wait
it is nvm
because like
if you remove parabola like you said
R2 - parabola
is an open set
Yup
cus u can take open sets from everywhere as close to missing graph
and union them
to make same shape again
so try to do that in general!
You already noticed you should try to go local
so i was given that earlier I think
U a subset of X x Y is open iff for every p in U, there is an A x B subset of U and A is open in X and B is open in Y
Yup
And that's sort of what you were saying here
(if I understood right)
I might be stuck now
because I get Y is hausdroff
but not rly sure what to do with X
I take U = X x Y - Graph (f)
so i just need to show that for every point in U, I can find an A open in X and a B open in Y where A x B is a subset of U
Sure, so take a point p = (x, y) in U
Let's start with B then
ok
since Y is hausdroff
for any two points in Y there is are disjoint open neighborhoods around them
Right
so for y in Y, I can take two points being f(x),y
Yup
and there will be an open neighborhood around y ill call B for every point in U.
for x I think i use continuous
well hang on
Sorry, continue
I was going to point something out but it's not super relevant rn
I can take an open neighrbood around B not containing f(x) right?
Well I'm not sure what you mean here
like uh
Isn't B such a neighborhood?
ok this is what im thinking
since Y hausdroff we can take two points f(x),y and they both have open disjoint neighborhoods O,B respectively. y is in U = X x Y - Graph(f) and f(x) in graph(f)
oh
Sorry what do you mean by y is in U?
Yup
so y is in B, and we can choose B to be a neighorhood around y that doesnt have f(x)
and in doing that the second component of p=(x,y) is done
now I need to find an open set A containing x where x is in the first component of X x Y - Graph(f)
yup
I think I would use continuous definition here
f is continuous meaning U in Y is open implies f-1(U) is open in X
Yup
A dont is not in graph f
wow english
I want A intersect graph f to be empty
no
wait
something similar but not semantically correct
Actually, this statement is a little off
Your sets A, B aren't related to p here
You could just take A, B to be empty always if this was the definition
not quite
A and B need to have x and y
its def true for B
Yup
but A = f-1(B)
x in A
means x is in preimage
so it would be in the graph
ok
so
right
I think I apply hausdroff
So x is not in A
again
Which isn't great
If I apply hausdroff
wait
f(x),y can have seperate open neighborhoods in Y
i wonder if the inverse image of the open neighorhood of f(x) is good then?
but that seems counter intuitive
because inverse img of whatever that is is def in graph me thinks
Well the inverse image won't be in the graph
The inverse image is a subset of X, not X × Y
Maybe try working this out with the parabola example again?
Like draw separating sets in Y or whatever
visualizing this is just funny though
like
if i think of {-1,0,1,2,...} -> {0,1,2,4,...}
but then a bunch of numbers inbetween those
and if I take a positive range from (1,4) in the second set
the preimage is what now?
never actually thought of it
shouldnt it be positive and negatives?
oh wait
I'm not sure what you mean, sorry
yea it was terribly explained my bad
but i have another idea ig
so if i have x^2
and I take a section of it
Like a cross section?
its preimage is gonna be the corresponding x axis?
yea
cross section
wait that isnt what I want
the cross section of the graph shouldnt be open
even though you said the inverse image wont be in the graph
is this always true?
like if you have 1/x as the function
isnt the inverse image in the graph?
or no
nvm
is it because the graph is a cartesian product
and the inverse image is just X
Exactly
i cant visualize that well though
the way i usually think of inverse image is with sets and arrows pointing to elements
like this
so let's stick with the parabola
Here's a random point not on the graph: p = (0,1)
what are sets like B, O?
We want disjoint open sets in Y around 1 and f(0) = 0
mb
im back
so an example of an open set around 1 is (0.5,1.5)
and around f(0)= 0 is (-0.5,0.25) @sleek thicket
f-1(-.5,.25)
It's all points x in R such that x^2 in (-0.5,0.25), right ?
yea
Is there a more explicit way to write this?
oh thats true
what though
-.5^2 = .25
so is it [0,.5)?
wait lol
that isnt inverese
if we are only choosing x in R wouldnt it be [0,0.5)
because we cant include complexes
dont they square to positive numbers only?
yes
oh damn
ok
i see lol
so inverse image of (-.5,.25) would be all numbers that when squared are in this range
Right
(-0.5,0.5)
So the hope is that we can take A to be this set
And you can draw a picture of this setup and see that it's disjoint from the graph
I think the example might have gotten us a little sidetracked though
and this isnt in the graph
the first component*
wait
i still dont see it
did stupid little sketch
We have this product (-0.5,0.5) × (0.5,1.5)
And the claim is this is disjoint from the parabola
it entirely is yes
yes
Well that's what we wanted out of A, B
ok
i guess this is part im confusd about
so when we take the x component of X x Y - Graph(f)
that X component can't be in the graph meaning it cant be in the domain or the preimage?
domain would be silly
arent we trying to find an open set A around the x component of any point in X x Y - Graph(f)
Ah sure
So p = (x, y) isn't in the graph
And you're saying x can't be in the domain or preimage?
The domain or preimage of what?
of the function
We want to have that x is in the set A
but that sounds silly
Yeah, it is sorry
yea we want x is in the set A
and A is a subset of the first product in X x Y - Graph(f), correct?
It's a subset of X
yea
it cant be any subset though
because like you said the preimage of B doesnt work even though f-1(B) is a subset of X
and I agreed because that is in the graph
We have p = (x, y) not in the graph
correct
We have open sets O,B in Y
With f(x) in O and y in B
And O, B are disjoint
Set A = f^-1(O)
You're concerned that maybe x isn't in A
Yeah?
yes
Well, what would it mean to have x in f^-1(O)?



