#point-set-topology

1 messages · Page 210 of 1

fading vale
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shamrock i saw the equivalence of COV_B and TRA_B

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when B is transport local

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scary tbh

viral atlas
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Ahhhh, so like, within discrete metric a convergent sequence would eventually have the same point recurring in the sequence, and within the regular metric the corresponding sequence converges. However, there are more sequences in the regular metric converging to the same function value, while they all don't exactly have a pre-image in discrete metric? Idk I'm just rambling

fading vale
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that sounds right

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i dont know analysis

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but that sounds right

sleek thicket
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oof

sleek thicket
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if you like analysis, there's lots of examples on function spaces

fading vale
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moth AU where they know literally any analysis

sleek thicket
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On the set of continuous functions [0,1] -> R there's two natural metrics

fading vale
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coming in 15 business days or so

viral atlas
sleek thicket
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$d(f, g) = \sup_{x\in[0,1]} |f(x) - g(x)|$

gentle ospreyBOT
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!!Shamrock!!**

viral atlas
sleek thicket
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$d'(f, g) = \int_0^1 |f(x) - g(x)|, \mathrm{d}x$

gentle ospreyBOT
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!!Shamrock!!**

sleek thicket
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ah yeah this is sup norm vs Euclidean

viral atlas
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Oh, these are metrics on function spaces

sleek thicket
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Although I think taxi cab and Euclidean are equivalent?

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yes, sorry

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but does that make sense?

viral atlas
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Taxicab is generally greater than Euclidean

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It does, thanks!

sleek thicket
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Exercise: prove that these do not generate the same topology

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Find a sequence converging in one but not the other

viral atlas
fading vale
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cring

sleek thicket
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and show that one is finer than the other

viral atlas
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Nice

clear storm
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does anyone here know about fundamental groupoids

viral atlas
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I'll try this!

sleek thicket
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(all open sets open in one are open in the other)

fading vale
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@clear storm i know some

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lmao sham knows more

sleek thicket
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You've been learning about them a lot

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Recently

fading vale
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that is true

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i have learned terrible things

viral atlas
sleek thicket
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Exactly

fading vale
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like the equivalence of functors from Pi(B) -> SET and Pi(b, b)-SET

viral atlas
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Neat, I'll try this.

sleek thicket
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also, equivalent means they generate the same topology

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Not that they're actually equal

sleek thicket
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You can get uniform bounds

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c Euclidean <= taxicab <= C Euclidean

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The two metrics I showed you are the sup (or "L^infinity") and L^1 metrics

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Very important in functional analysis

fading vale
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shamrock cna you believe im actually going to learn multivariable

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its been like

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2 years

sleek thicket
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I'm so excited for you

fading vale
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my streak 😭

sleek thicket
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That was my fave math class

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Before proof stuff

fading vale
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im doing it for the difftop pill

sleek thicket
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g e o m e t r y

fading vale
sleek thicket
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hi sei, you can ignore our spam

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feel free to ask your question whenever

clear storm
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@fading vale I am trying to show that given a circle, set of all paths between points on circle modulo endpoints preserving homotopy is homeomorphic to R.

viral atlas
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Thanks for all the help, everyone.

clear storm
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also

sleek thicket
clear storm
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the way topology is defined on the set of paths are very weird to me

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yes

fading vale
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im not totally sure what you mean by this, the set of paths between two points x, y up to htpy?

clear storm
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basically the end goal is showing that fundamental groupoid of circle is homeomorphic to the infinite cilinder

sleek thicket
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moth, do you remember the construction of the universal covering space?

fading vale
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vaguely

clear storm
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i wasnt precise withj my phrasing

sleek thicket
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well unique lifts and a trivial monodromy and all tell us what it has to be

fading vale
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i just want ot make sure im clear on the thing sei is talking abt

sleek thicket
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any universal cover has to be identifiable with the space of homotopy classes of paths in X

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the fiber over p being all paths starting at p

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so you can construct it as such

clear storm
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given xand y on a circle you have a path between them. you have equivalence relation via homotopy.

sleek thicket
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I forget the topology, I think it might be ugly

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iirc the way I saw it was by declaring the "take first endpoint" map to be a local homeomorphism

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on sets where the base is simply connected

clear storm
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the topology is quite weiord

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you defined it via genetrating set

sleek thicket
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sei, could you share the reference you're using?

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It sounds a little nonstandard

clear storm
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wait i have a link

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from stack exchange

sleek thicket
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like, thinking of the set of arrows in the fundamental groupoid as being the universal cover or whatever

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even though it is true

clear storm
fading vale
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ohhh

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ive seen this i think

clear storm
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now i understand how topology is defined

sleek thicket
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did you check the reference in hatcher?

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but yeah this is one way to define the topology

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you take the base of sets from being semilocally simply connected

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or whatever

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and declare those to be evenly covered

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it's been a while since I looked at this construction

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although this only works for nice spaces

clear storm
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i tried looking for it in hatcher but didnt manage

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maybe somewhere in covering spaces chapter

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yes

sleek thicket
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yeah, that's where I meant

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I like the presentation of the universal cover in Introduction to Topological Manifolds by Lee

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it's very explicit and done in great detail

fading vale
sleek thicket
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ah gotcha

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sham stop simping for lee for one minute challenge

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oh actually

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i think topology and groupoids may have done this

fading vale
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the way i saw this presented was very umm

sleek thicket
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thinking

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no

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topology and groupoids takes a cover of the fundamental groupoid

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it develops a theory of covering groupoids

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and then constructs a space from such a thing

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yes

clear storm
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hmm i think given an explicit representative of an arbitrary path(morphism) in the groupoid i feel like there is natural way to come up with an isomorphism

sleek thicket
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an isomorphism between what

clear storm
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homeomprohism

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lol

sleek thicket
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between what?

fading vale
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tom dieck basically does this by getting an equivalence of the categories COV_B and TRA_B = [Pi(B), SET] where for a functor Phi: Pi(B) -> SET you get the cover thats basically uhh, take the disjoint unions of all the sets in the image of Phi and send Phi(c) to c for c in B lol

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and then the universal cover is associated with Hom(b, -)

clear storm
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betyween fundamental groupoid of circle and S cross R

sleek thicket
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ah

clear storm
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i.e infinite cilynder

sleek thicket
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i do not think you can produce an isomorphism from a single path

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wait

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hang on

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I am confused

fading vale
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i saw this done from van kampen

sleek thicket
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so you have a topology on the set of arrows

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and you have a topology on the set of objects

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how are you combing these?

fading vale
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with a topological groupoid G defined where the object space is S^1 and the morphism space is S^1 x R

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and van kampen established the isomorphism

clear storm
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well the topology of the underlying set stau the same

fading vale
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onto Pi(S^1)

clear storm
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right

sleek thicket
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oh I see, I'm being silly

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the universal cover isn't the space of all paths

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you fix a starting point

fading vale
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yea

sleek thicket
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ahhh okay

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im unconfused now

clear storm
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because the set of objects in the groupoid is just the underlying s@ace

fading vale
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its associated with the Hom functor from the grpoid

clear storm
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space

fading vale
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it sends the paths from b to c up to htpy to c

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where b is the basepoint

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(this sounds right, right sei lmao)

sleek thicket
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so when we say Pi_1(S^1) is homeomorphic to S^1 x R we're talking about the set of arrows

fading vale
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i presume so

sleek thicket
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what's "it" moth?

fading vale
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the Hom set stuff

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and the universal cover

sleek thicket
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i mean that sounds like the projection out of the universal cover

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yeah

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but in this case we have more stuff

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we have arrows with different bases

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so the idea should be like

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you have a path class p : x -> y

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in Arr(Pi_1(S^1))

fading vale
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this is basically in tom dieck

sleek thicket
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you can send this to (x, (lift of p to universal cover)(1))

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this doesn't feel right

fading vale
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if u want to read it sei

sleek thicket
fading vale
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2.6.1 is van kampen btw lol

clear storm
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whats the reference??

fading vale
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tammo tom dieck

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algebraic topology

clear storm
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this looks like what i needed

fading vale
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he does most of the basic pi_1 stuff from the perspective of groupoids

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it might help

sleek thicket
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this is an interesting question

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I should read dieck

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i was gonna read uhhh

fading vale
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its a good book

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inb4 lurie

sleek thicket
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algebraic topology from the homotopical viewpoint

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feel like im supposed to learn alg top at some point

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learn it good, actually

fading vale
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impossible

sleek thicket
fading vale
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i cant im leaving twitter

sleek thicket
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I feel like your followers would like it

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oh no

cedar pebble
sleek thicket
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Good for you

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Twitter is bad

fading vale
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ive been off it for 2 days

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the amount ive gotten done

sleek thicket
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Hey I just went to a spectral sequences talk

fading vale
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has gone way up

clear storm
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anyway

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thanks guys

fading vale
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np

clear storm
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i didnt actually expect anyone to help

fading vale
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heres a (legal) link to dieck

sleek thicket
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oh no ng

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this is

cedar pebble
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when you enable all the display options for the differentials

sleek thicket
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very very bad

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jesus fucking christ

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it slowed down my laptop

fading vale
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nG why are you bringing black magic into the chat

cedar pebble
sleek thicket
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iirc

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no

fading vale
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gamer moment

sleek thicket
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lol

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anyways yeah i went to a talk on spectral sequences tonight

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and learned about the GSS

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very cool

fading vale
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do u ever think about how probably at some point all the ways we talk and think about this stuff will seem like

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weird and dumb

cedar pebble
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oh my god it shows every step

fading vale
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when some better perspective is uncovered

sleek thicket
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absolutely moth

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spectral sequences seem so artificial

fading vale
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and itll be like "lol they struggled so much with htpy groups of spheres"

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"dummies"

sleek thicket
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Atiyah Hirzebruch spectral sequence computing $\mathit{KO}^*(\mathbb{RP}^{14})$

gentle ospreyBOT
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!!Shamrock!!**

sleek thicket
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RP^14

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why

fading vale
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"thats literally so easy just do the blah blah blah"

fading vale
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RP^15 would crash ur laptop

sleek thicket
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lmao

cedar pebble
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haha ng is such a moron all he does is calculate integrals imagine doing something so tedious

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also algebraic topologists:

sleek thicket
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i have said this

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many times

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you can search it in chat logs

gritty widget
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Oh, I thought you were a girl

sleek thicket
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lol

cedar pebble
sleek thicket
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ahhhhhhh

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i had a thing due

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for homological algbera

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did not finish it

fading vale
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holy shit

sleek thicket
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i had nothing else on this weekend

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lmao moth owned

fading vale
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tbf this is from like umm

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wait when did i join

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like 2.25 years ago?

sleek thicket
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lmfao owned

fading vale
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mfw a math discord changed my life

sleek thicket
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literally 4x

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if i were a high schooler i would simply resist math brain worms

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(no i wouldn't)

fading vale
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i was naive and 14

sleek thicket
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(i didn't)

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wow really?

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youre like benjamin button

fading vale
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yea when i joined

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i didnt start doing math seriously until like

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right b4 i turned 15 tho

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also on the topic of reminiscing this time last year i was freaking out about applying to sumac and now its due in 2 days and idek if i wanna go

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oh well

sleek thicket
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tfw your sick burn goes unnoticed

fading vale
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idk what benjamin button is

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im normal

sleek thicket
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wtf

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how

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benjamin button aged backwards

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is the reference

fading vale
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i hate u

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i will devastate ur entire lineage

sleek thicket
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lol

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how do you not know who benjamin button is

fading vale
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why would i know who benjamin button is!!

sleek thicket
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it is a very common cultural touchstone!!!

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ive never even seen it

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or read it

fading vale
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ur just a boomer

sleek thicket
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no

fading vale
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yes!

sleek thicket
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i retain my youth

fading vale
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☘️

sleek thicket
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you will not shake me

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☘️

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🦣

fading vale
sleek thicket
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many such cases

fading vale
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how do i motivate myself to do the problems for this summer camp when it covers intro AT and id literally just be paying like several thousand dollars to learn weaksauce version of intro AT online

sleek thicket
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¯_(ツ)_/¯

fading vale
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man.

tough imp
sleek thicket
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👀

pastel linden
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I was going to ask what the point of actually doing a weaksauce summer camp for money is

sleek thicket
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well I mean like

pastel linden
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is it to have physical clout of AT skills

sleek thicket
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It's only weaksauce because moth is absurdly chad

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I am defending the honor of this program

gray dirge
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lol. Weaksauce is better than no sauce? As always, the amount you have to pay is important.

sleek thicket
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Also, community and mentors and stuff

pastel linden
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it's genuinely insane that they pay undergrads to do math if you get into reus

gray dirge
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I'm not defending the program but it does matter how much it costs. 1 cent? Maybe it's worth it.

sleek thicket
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yeah haha

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Well

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I'm not going to get paid

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but mostly

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which is very good

pastel linden
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if I get both my research grant and my reu that's 7800 for the summer of just learning math

sleek thicket
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That would be so based

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What's the research grant ?

pastel linden
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to write a harmonic analysis exposition with my professor

gray dirge
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I'm confused are you in high school now?

pastel linden
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It's not really research

sleek thicket
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That would be really cool!

pastel linden
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it would be insane to have that opportunity but there's one grant and it's up for grabs for all math majors

sleek thicket
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Dang yeah not very likely

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I don't know of anything like that here

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There's some kind of outstanding junior arward I meant to apply to but I can't find any info

pastel linden
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I do think it's kind of likely that I'll get into that reu, since it turns out my professor knows the director

sleek thicket
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Doesn't seem to have been awarded last year

gray dirge
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It's just called "normal" research. If you know enough and are hard-working enough or creative enough or both to contribute you might get someone to work with you on research.

sleek thicket
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what

pastel linden
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email the department and say to them "I am an outstanding student and I want money"

sleek thicket
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lol

gray dirge
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No, you have to prove you know what you know and try to get "hired." It's just like every other job.

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Oh, and bury bodies. Don't tell anyone you harmed your past advisor ...

pastel linden
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??????

gray dirge
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I'm kidding.

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Seriously, you have to be skilled enough to do well if someone gives you a chance. (life lesson)

sleek thicket
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you seem to be saying a lot of stuff disconnected from the rest of the conversation and I don't understand what you're trying to say

gray dirge
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You're asking about REUs and calling some shams. I'm saying if you're good enough you have the option of possibly doing real research.

sleek thicket
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I'm not calling any of them shams

gray dirge
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I am.

pastel linden
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I wasn't calling the reu a sham, I just meant that exposition with my professor isn't research, it's a reading/expository project

gray dirge
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Fair enough. I lost the thread of the conversation.

sleek thicket
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Moth ("many such cases") is a high school student who is trying to decide whether they should apply to a summer program (which costs money) when they already know a lot of algebraic topology

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Bacono is an undergrad applying to both an REU and a research grant, the research grant is really for an expositional project with their professor. Both of these would pay them

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I'm an undergrad and have been admitted to the university of chicago REU which is very prestigious but accepts lots of applicants and can't distribute funding evenly. I was whining that I wouldn't be paid for this reu, unlike most

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I think that's the conversation in summary?

gray dirge
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I'm headed out :). My head hurts from helping others with calculus.

fading vale
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society if tom dieck clearly stated what the topology on this G-set is

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pretty sure its the discrete topology

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i hope.

marsh forge
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Either A) assume it has a given topology (i.e. its just some arb top space w action)

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B) assume its discrete

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C) it's a group that has a topology like SU(n)

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i think context makes which of these it is obvious

fading vale
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i mean i dont think this works otherwise tho

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he just says "let F be a G-set, p: E -> B a cover and take p_F: E x_G F -> B"

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but i dont think the fibers r discrete if F doesnt have the discrete topology so

marsh forge
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If they just say G-set and not like, topological G-set

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i think discrete is the only reasonable assumption

gritty widget
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hey pals, can you have a neighborhood U of p, where V is uncountable?

median glade
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can you have an open set containing p that is uncountable?

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is that what you mean?

gritty widget
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Correct me if im wrong, I thought U is p in X to a point in V, where V is in X,T. Is that right?

fading vale
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ummm

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im not sure what you mean

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a neighborhood of p is just a subset U with an open set V where p in V subset U

gritty widget
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Excuse the bad drawing.

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is that not what U is?

fading vale
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im not really sure what this is

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are U and V the sets?

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or points?

gritty widget
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Circles are sets, red dots are points

fading vale
#

I thought U is p in X to a point in V, where V is in X,T.
im not totally sure what you mean by this but a neighborhood doesnt involve two points, or an interval between two points (necessarily)

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like a neighborhood of p is just a set U whose interior contains p

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theres nothing wrong with your drawing im just not sure what you mean by "to a point in V"

gritty widget
fading vale
#

a neighborhood can be uncountable yes

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a neighborhood can have any cardinality depending on the underlying set and the topology placed on it

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the interval [0, 1] is a neighborhood of 0.5 in the reals with the standard topology

gritty widget
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yeah, gotcha

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Ok, thanks

median glade
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Do you actually use that definition?

fading vale
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thats literally the defn

median glade
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that seems real awkward compared to just defining it to be the open set V

fading vale
#

wut

wanton marsh
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what

fading vale
#

closed sets can be neighborhoods too

median glade
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I learned it as "A neighborhood of x is an open set containing x"

fading vale
#

ummmm thats not correct lol

wanton marsh
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that would be an open neighbourhood

fading vale
#

^

median glade
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It was in Munkres

fading vale
#

dan

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thats surprising

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neighborhood means that x is in the interior of V

median glade
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how often do you use "closed neighborhood" though?

fading vale
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i mean fairly frequently

median glade
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really?

fading vale
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for one thing separation isnt equivalent

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by open neighborhoods vs neighborhoods in general

median glade
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wdym?

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for reference

fading vale
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saying that any two points can be separated by closed neighborhoods is a stronger condition than saying they can be separated by neighborhoods in general

median glade
#

yeah

fading vale
median glade
#

the way munkres phrased that is: There exist neighborhoods U, V, with the closure of U distinct from V, and vice versa

fading vale
#

also if you want to do something like say

median glade
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which is equivalent

fading vale
#

neighborhood bases

median glade
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also Lee backs my pov up

fading vale
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when is that book from?

median glade
#

Introduction to Topological Manifolds (2011)

fading vale
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wacky

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the terminology is pretty non standardized unfortunately

median glade
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I feel like it's wacky to not do it this way

fading vale
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not really

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like it makes intuitive sense

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the idea of a neighborhood is that we have wiggle room around a point

median glade
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it makes sense to me, in the sense that any statement about a space has to use the open set structure

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so if I want to talk about wiggle room, it makes no sense to use a general set

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the wiggle room is an open set

fading vale
#

both defn use the open set structure

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thats wack

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every book ive used has done that

median glade
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dieck does it moth's way

fading vale
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dieck does

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bredon also does

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as does hatcher in his notes iirc

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i think the idea intuitively is that the point is the interior of the set

median glade
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it's less of a problem if you're coming from the "neighborhood = open set" school

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because then you read "open neighborhood" everywhere, and it's unambiguous

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but I guess it's usually clear through how they use the neighborhood, that they mean its open

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like idk, it seems weird to take a neighborhood, and then immediately discard it to work with an open set

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why not just take the open set directly

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😛

fading vale
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i think ive done exercises involving closed neighborhoods specifically

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but its been too long to remember anything specific

median glade
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I mean, at the end of the day, it doesn't really matter

fading vale
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the terminology is non standardized cuz no one cares about point set egg_hank

median glade
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if you need to talk about closed neighborhoods, you can just mention open neighborhoods whose closure has a certain property right

fading vale
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yea

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just take closure

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if ur working w/ general neighborhoods just take the interior (or the arbitrary open set contained within)

median glade
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for example like, did you learn regular as "every open neighborhood of x contains a closed neighborhood?"

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or well, did you see that version of regular

fading vale
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i learned regular as any closed set C and point p, p notin C, admit disjoint open neighborhoods

median glade
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yeah that's the definition

fading vale
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honestly couldnt even tell u if i saw urs

median glade
#

but an equivalent, and often more useful version is: for any point p, and open U containing p, there exists an open V containing p, with cl(V) contained in U

fading vale
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ive seen that

median glade
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right yeah

fading vale
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(i think)

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idk i guess it ultimately doesnt really matter because

median glade
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and this is equivalent to saying that any open neighborhood of a point contains a closed neighborhood

fading vale
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yea

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i guess the defn ive seen seems more natural to me also because its a little more general

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and exposure obviously

median glade
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nah it's the better definition

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going from hausdorff -> regular -> normal makes sense this way

fading vale
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mhm

median glade
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you can separate larger and larger things

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an equivalent formulation of hausdorff is that if x != y, then x has a closed neighborhood not containing y

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8^)

wanton marsh
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closed neighborhood is not the same as closure of open neighborhood

fading vale
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this is true you run into problems with empty interiors

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but i mean

#

if the interior is empty then it cant be a neighborhood of any point anyway

median glade
#

doesn't closed nbrhood mean: closed set, containing an open set?

fading vale
#

idk maybe there are other counterexamples i cant think of off the top of my head

median glade
#

closed set containing is indeed not great

#

because you might have a boundary point

fading vale
#

thats fair

median glade
#

indeed

long coyote
#

Let R_K be the K topology, what does R_K/K look like

#

the base of R_K is (a,b)U(a,b)\K

thin bramble
#

Anyone know Geometric Algebra?

flint cove
thin bramble
flint cove
#

sure, but I don't recall much of it, so not sure if I can actually help you with anything

zinc venture
#

Hoping this would be the right channel to ask/discuss this...

#

I am trying to find the gradient on a color image.
I understand the usual approach is to covert the image to grayscale, then take the gradient there. However, a clear problem is that e.g. a fully saturated color of some lightness would be the same color as gray, creating no gradient - obviously a problem.
If we were to take the gradients in each color channel separately and added those up though, then something like a pure green transitioning to a pure red would have two gradients of equal magnitude but opposing direction, which would cancel out, leaving us, again, with no gradient - obviously also a problem.

gritty widget
#

This is probably not the right channel 🙂 but maybe you could do something like taking the l2 norm of the channel separated gradients

#

Is there a reason that grayscale doesn't work for you?

zinc venture
#

Different colors of equal intensity would turn gray creating no edges where there clearly are some. Like clouds in the sky - light gray and light blue are the same in grayscale.

#

I really looked at all the channels, and I don't know... #calculus maybe?

gritty widget
#

Tbh I feel like this isn't a math question

zinc venture
#

No programming Discords really know what to make of it either. Too theoretical for their tastes. 😅
Digital Signal Processing, but that's too niche to have a separate community.
The norm you suggested - do I not lose the direction component with that, leaving only the magnitude, not allowing me to find which way the gradient goes?

gritty widget
#

I guess so, but I'm not sure what better you can do if you want a scalar output

#

That said I'm not particularly familiar with image processing so I don't know if there are standard ways to handle this situation

zinc venture
#

That's fair. Maybe there is no good solution. I'll keep thinking/searching.

split needle
#

try here: https://computergraphics.stackexchange.com/ and you can also convert your image to a different space such as HSL/HSV to separate "color" from "intensity" and take the gradient only on the "color" part. It also feels like you're asking an XY question and are already proposing a solution without telling us what you actually want to achieve. @zinc venture

brave gate
#

What is the meaning of $dx=x^2$ Is there any way for me to get rid of the dx?

gentle ospreyBOT
#

R3P34T3R

gritty widget
#

context?

brave gate
#

i incorrectly solved a differential equation

#

and this is what i was left with

#

and i was wondering what this thing could be

gritty widget
#

what's the differential equation

brave gate
#

i dont want you to solve the equation

#

i just used separation of variables incorrectly

gritty widget
brave gate
#

still im curious

#

wouldnt this be considered a differential?

tepid depot
#

@brave gate you could think of dx as a differential form, but then it wouldn't equal x^2. this is like if you got the equation 0=1, it just means you messed up

brave gate
#

so when you have an equation made up of differential forms it cannot contain a 'normal' function?

tepid depot
#

there's this way of creating a formal algebraic system which assigns meanings to stuff like dx, dy, df, etc.

#

that system is consistent with the manipulations you do in ODEs and whatnot

#

in that system, dx means something specific, and x^2 means something else specific, and those two things are different things

#

dx isn't really a function like x^2 is

#

so this equation doesn't really make sense

brave gate
#

ahhhh

#

i was kind of hoping if it wasnt like this

#

but i understand

ivory dragon
#

set d = x

tepid depot
#

cool. if you want to learn more about this topic the thing you'd google is differential forms. you can learn the algebra rules easily but the formalism rigorously is pretty advanced

brave gate
#

oh yeah

#

i knew of them before

#

and looked them up this time too

#

somehow i didnt realize what i was looking for was false

#

thank you so much tooru

urban yarrow
#

cancel x out on both sides you get d=x

gritty widget
#

make a bad post about it on twitter and you'll cancel the entire equation

gritty widget
#

Suppose we have a exact sequence:
0->A->B->C->D->0
Is it true in general that AxB is isomorphic to CxD

gritty widget
#

If anyone is interested the answer is no, take D=0 and pick an exact sequence that does not split

urban yarrow
#

This sequence looks pretty boring in general, but i guess you can try $A \times C$ and $B\times D$ in some specific categories. I’m not sure what will come out though

gentle ospreyBOT
obtuse meteor
#

what's a good way to tell if a covering is regular?

#

so like

#

if I have a covering of a wedge of two circles

#

and it has 3 vertices

#

and how I've lifted the edges is like

#

edge a has a loop on the left vertex

#

edge b has a loop on the right vertex

#

and there are transposition looking things from the middle vertex to the other two

#

this feels non-regular but I can't figure out why

#

like I kinda get it intuitively because there's a symmetry break but

#

hrm

obtuse meteor
#

@marsh forge can I placate your anger with topology?

#

ah wait I think I have a big brain way of doing this

#

so like if you look at the left and right vertex

#

you get an induced fundamental group from each

#

the left one has an a in it

#

the right one has a b in it

#

they can't be the same

#

because if they were it would be the whole group

#

which has index 1

#

not 3

marsh forge
#

everyone always things im angry

#

im watching puppies on tiktok during that entire convo

obtuse meteor
#

lol

#

puppies good

marsh forge
#

i showed my gf a bunch of cute ones

obtuse meteor
#

and so there can't be a deck transformation

#

that's sweet ^^

marsh forge
#

oh god

obtuse meteor
#

does this argument make sense?

marsh forge
#

coho theres a fast heuristic of like

#

if you can visualize it

#

any starting point should have similar paths

#

so like, name the lifts properly

#

and see if doing the same path on two points

#

looks the same

#

i also think there might be a more formal criterion

obtuse meteor
#

maybe

#

but what I said works :)

marsh forge
#

yeah i mean if there is a symmetry break

#

you can formalize this at the group theoretic level easily

obtuse meteor
#

not if you're bad at algebra like me max

marsh forge
#

basically anything that is a loop at one of the verticies

#

has to be a loop at the others

#

and that breaks pi_1 stuff

obtuse meteor
#

mhm

warm hedge
#

question 😛 completeness of a space isnt a topological property, right ?

wanton marsh
#

completeness of a space ?

warm hedge
#

if a space is complete (i dont know the english word i guess 😛 )

wanton marsh
#

don't you need a metric space for that ?

warm hedge
#

yeah

wanton marsh
#

so you want to find two homeomorphic metric spaces, only one of which is complete ?

urban yarrow
#

R and an open interval

warm hedge
#

oh yeah right

#

so it isnt topological property

#

but a space to be called polish needs to be complete and at the same time it is a topological property , how this is working ?

urban yarrow
#

it doesn’t need to be complete itself

bitter yoke
#

polish only requires that you're homeomorphic to complete right?

urban yarrow
#

open interval is also polish

warm hedge
#

the open interval can be complete with the discrete metric ?

hard wind
#

Need help on part b). My guess is I need to find a particular retraction to a subspace that has fundamental group Z^N, but I am not exactly sure how to find that.

urban yarrow
wanton marsh
hard wind
#

Okay... so we have countably many retractions r_n which are mapping to one particular circle. This gives us countably many morphisms from Hawaiian fundamental group into Z

#

I'm just not sure how to go about multiplying them all together

warm hedge
#

I see

#

Polish spaces is something new for me and i am trying to understand them

urban yarrow
#

it has a weird name

#

similar to tropical geometry

#

i think mathematicians are just not talented enough to invent namesholothink

warm hedge
#

ohh i see

long coyote
#

why do we need surjective for a quotient map

marsh forge
#

The most important reason is just motivational imo

#

A quotient is a very general notion in mathematics

#

and it almost universally means like

#

apply some equivalence relation to object A to get object B

#

so you want B to 'come from' A

#

if the map is not surjective this means something is in B that didn't come from A

ivory dragon
#

yeah its not like, divinely inspired; its more that quotient maps are introduced almost exclusively to study quotient spaces

#

and having a nonsurjective map doesnt make sense if you want your codomain to be determined entirely by an equivalence relation (i.e. a quotienting) on your domain

long coyote
#

thank you for detailed comments

digital peak
#

I don't get it

#

if I have say a lie group with a chart around identity

#

then I could rewrite multiplication "in coordinates"

#

i.e I'd have a map Psi : R^n x R^n -> R^n

#

and we can show that Psi(x, y) = x + y + B(x, y) + o(x^2+y^2)

#

and supposedly associativity of Psi gives us associativity of B?

#

but I just don't see that happening?

#

like, sure, if we expand Psi(Psi(x, y), z) we will get B(B(x, y), z)

#

but that won't be the only term of third order

#

cancer computation:

#

the B B thing is what I want but the other cubic term won't go away sully

#

hmm this tensor is symmetric in i,j

#

it's equal to a similar tensor that's symmetric in j,k

#

means its symmetric in i,j,k

#

there exist multiple totally symmetric nondegenerate tensors in rank 3 though

long coyote
#

how to show $\mathbb{R}^n/B\simeq\mathbb{R}^n$ where B is a closed unit ball

gentle ospreyBOT
#

亜城木 夢叶

sleek thicket
#

the way I would think about this is that R^n is homeomorphic to the space (S^{n-1} times [0, infinity))/(S^{n-1} x {0})

#

does that make sense?

#

basically, the map sending (x, r) to rx is a quotient map from S^(n-1) × [0,infty) to R^n

#

then to prove your claim you can just work on the radius and ignore the coordinate on the sphere

#

Because collapsing B to a point has the effect of collapsing [0,1] to a point in [ 0,infty)

#

I guess I'll take the 🤔 as a no?

long coyote
#

no, don't follow that

sleek thicket
#

A simpler way to say what I'm saying is that everything is radially symmetric, so you just have a find a nice function s(r) from [0,infinity) to [0,infinity) sending [0,1] to 0 and bijective everywhere else, and then you can define a function F : R^n -> R^n by F(x) = r(|x|)/|x| * x which squishes the unit ball to a point

#

So I guess even further, to show something is homeomorphic to a quotient you need to exhibit a quotient map going the right things together, right?

#

So the way you should think to prove R^n/B ≈ R^n is by exhibiting a quotient map R^n -> R^n squashing the unit ball to a point and injective on everything else

#

I'm saying that to find such a function you want to just think about the norm of a point and work with that, do everything in a radially symmetric way

long coyote
#

now, i understand what you mean, thanks

sleek thicket
#

Cool

#

Does it make sense that R^n \ {0} is homeomorphic to S^(n-1) × (0, infinity)?

long coyote
#

yes

sleek thicket
#

Yeah, so this extends to the case where you add in the origin and look at all of R^n

#

But then in S^(n-1) × [0, infty) you have to crush the sphere S^(n-1) × {0} to a point

digital peak
#

turns out

#

it's not even true

#

counterexample is the most obvious coordinate representation of SL2(R)

#

((a, b), (c, d)) mapsto (a-1, b, c)

gritty widget
#

So lets say I have some function f that is continuous on a subset D of R^n. Is this equivalent to it fulfilling the preimage conditions in D with subspace topology?

median glade
#

Usually this terminology means that f is defined only on D, and continuous on D (with the subspace topology)

#

so yeah

marsh forge
#

Thats not true for R^n

#

you have a notion of point-continuity

#

Contuinity on a subset is at least stronger. To see that it is at least stronger, the preimage of an open set of the image of D must be open in R^n and in particular this means it will be open in the subspace topology of D.

#

but it might be equivalent

#

let me think

#

On open subsets D it should coincide

#

and Im forgetting the details of continuity on a closed subset

sleek thicket
#

what about sequences

#

Can we use those to check continuity without worrying about being relatively open?

marsh forge
#

I'm not sure because how do you control sequences not taking place in D

sleek thicket
#

ah yeah

gritty widget
#

D can be closed as an example and then the preimages are no necessarily open in R^n

marsh forge
#

is the indicator for [0,1] conitnuous in R

gritty widget
#

but they will be an intersection of an open set and D afaik

marsh forge
#

or sorry continuous on [0,1]

#

Yeah desc thats what we are worried about

gritty widget
#

ye but they will be open in the subspace topology so it should be fine

marsh forge
#

Yes so one direction is simple

#

but I don't think if you have a function f : R^n\to R^n

#

and f is continuous restricted to the subspace topology

#

that necessarily makes it cont on D

#

as a subset

#

Actually yeah take the indiciator of [0,1]. This is continuous on [0,1] as a subspace but not as a subset

#

because the sequence approching 0 from the left (choose your favorite) won't be preserved

#

@sleek thicket ur idea worked in reverse i think hahaha

sleek thicket
#

Oh lol

marsh forge
#

this was a good exercise im gonna put in on a pset if i ever teach point set

gritty widget
#

I'd consider it continuous in [0,1] as a subset tho

marsh forge
#

It is by definition not continuous at 0 or 1

gritty widget
#

wait isnt this indicator =1 at 0 and 1

marsh forge
#

yep

#

but like

#

take a sequence approaching 0 from the left

#

you get nothing but 0s

gritty widget
#

Ye so the discontinuity is outside the subset

marsh forge
#

yes

#

so it is continuous as a subspace function

#

but not as a subset

#

like the function f : R^n \to R^n is not continuous on [0,1]

#

but the function it induces [0,1]\to R^n is genuinely continuous

gritty widget
#

If its discontinuous on the boundary thats fine for what im doing tho

marsh forge
#

well

#

i think this should work fine

gritty widget
#

as long as it isnt discontinuous approaching from inside so to say

marsh forge
#

pass to the interior of your set

#

yes continuity on a subset is certainly stronger

#

and if you have continuity as a subset you can pass to the interior

#

or more importantly like

#

you should be able to say that if D is a subset of R^n

#

and f is continuous on the interior of D as a subset of R^n

#

then f is continuous as a function on D as a subspace topology

#

i think something like this should work

gritty widget
#

there has to be something more because i could have the boundary completely messed up

marsh forge
#

yeah its too strong i think

#

maybe if you explain your context I can be more helpful

#

probably something like connected with nonempty interior might suffice

gritty widget
#

Well its stability analysis on a connected subset of R^n

#

I can make additional restrictions without much loss like borel

#

So I am interested in the preimages of a function V:D->R D\subseteq R^n

#

I am additionaly demanding V to have bounded sublevel sets

#

The sublevel sets of V are invariant sets of the dynamical system

#

If D is R^n then these are compact for preimages of closed bdd intervals which is very useful

#

So basically I'd like to characterise the continuity of V on D so that I get the preimages, and I think the subspace topology of D does that?

marsh forge
#

I would see if you can prove it directly without worrying about lemmas

gritty widget
#

Feels like it should just jump out at me

#

I mean it has to mean something when we say we have a function from a subset

marsh forge
#

V on D will certainly be continuous

#

if it's continuous on D as a subset of R^n

#

as I described above

gritty widget
#

Well yes, but what if it doesnt exist outside of D

marsh forge
#

the issue is that V can be continuous even without that (I think my example above about [0,1] fits your hypotheses, for example)

#

what do you mean

#

you can't talk about the continuity of a function on a space for which the function doesn't exist

gritty widget
#

I only care if its continuous in D, and continuous on the boundary from within D, outside D the function doesnt matter

marsh forge
#

I really am not understanding you then

gritty widget
#

so like [0,1] indicator, i dont care what happens in R-[0,1] it is of no importance in the context

marsh forge
#

what exactly are you trying to do

#

If you want to show V: D\to R is continuous

#

you just have to show it

#

you can use epsilon-delta stuff for this

gritty widget
#

I have given V is C1 on a subset D

#

I wonder if this means it has open preimages of open sets in the subspace D in the subspace topology

marsh forge
#

it does

gritty widget
#

noice

marsh forge
#

there are more open sets in the subspace topology

#

open subsets of D

gritty widget
#

yes

marsh forge
#

so its easier to be continuous

gritty widget
#

It is continuous in the metric sense within the subset at least

marsh forge
#

no its continuous in the subspace as well

#

just take the sequential characterization

#

if all sequences are preserved

#

certainly sequences in D are

gritty widget
#

ye

#

so V:D->R, preimage of [0,1] as an example would be closed by continuity, and bounded by assumption on V

#

But not compact depending on what the boundry is like

marsh forge
#

yeah you need V to be proper to get the latter

gritty widget
#

It is proper if D is compact because it would be an intersection of compact sets

#

Or if V goes to infinity at all boundaries not contained in D i suppose (V is bounded below by 0)

#

Thanks for clearing this up, although I still need to read up on some things 😛

strong heron
#

Any 1-form can be expressed as a finite sum $\displaystyle \sum_{i} f_i dg_i$ for some smooth functions $f_i$ and $g_i$. Here, by finite, I mean locally finite. In other words, I think we need to do some partitions of unity stuff here.

gentle ospreyBOT
strong heron
#

Help?

#

I can find suitable f_i I think. But I'm unable to see how to get the g_i...

#

Any help would be much appreciated...

gritty widget
#

can't you just do this in each coordinate chart and then patch it together with a partition of unity

strong heron
#

Yes, but how do you define the f_i and g_i globally?

gritty widget
#

to be zero outside of the coordinate neighbourhoods possibly?

#

then multiply by the bump functions in the POU to get something smooth

#

i haven't checked the details but something like that should work

strong heron
#

I agree, something like that has to work, but my question is basically that I'm unable to make it precise...

#

I can show you what I attempted

#

The f_i's above are defined globally. But what about the g_i's? I cannot figure that part out.

strong heron
#

@gritty widget You were saying something?

south minnow
#

Is there any way to find the possible number of topological orderings of a tree. (that is a tree like looking undirected graph

#

shit, I'm not a math major

#

lol, my bad

empty pond
#

hey I have a question and MasterTernimus said this is a better place to ask it

#

$$
\sinh^{-1}(2\pi p) + 2\pi p \sqrt{4 \pi^2 p^2+1} = \frac{4\pi v t}{d}
$$

gentle ospreyBOT
#

もの

empty pond
#

I'm trying to isolate p

#

I can also show how I got to this equation if you think there might be an easier way to get around this

gritty widget
#

I want to see that if V is a symplectic vector space, and J is a compatible complex structure then J sends a lagrangian subspace W to another lagrangian subspace and their intersection is trivial

#

I've show that the image of W is indeed a lagrangian subspace. but I can't see why the intersection has to be trivial

gritty widget
#

if $g$ is an inner product on $V$ such that the compatibility equation $g(u,v)=\omega(u,Jv)$ is satisfied, suppose that $w \in J(W)\cap W$. then $w=Jw'$ for some $w'\in W$. then $$g(w,w) = \omega(w,Jw) = \omega(w, J^2w')= -\omega(w,w') = 0,$$ where the last equality follows from the fact that $W$ is lagrangian. since $g$ is positive-definite, $w = 0$, which proves that $J(W) \cap W = 0$

#

omega and w a little hard to read lol

gentle ospreyBOT
#

(T*Terra, dqⁱ ∧ dpᵢ)

gritty widget
#

lagrangian splittings catThink

#

ah yes thank you

rotund thicket
#

Would $S^1 \times D$ where $D$ is the disk of unit radius be a torus with its insides filled?

gentle ospreyBOT
#

Trichloromethane

gritty widget
rotund thicket
#

That's the word I was looking for lol

#

What about T x I

#

where I = [0, 1]

#

Is that also a torus?

#

just beefier

#

Like it would have inner radius still 1 but the outer radius would be 3 instead of 2

#

Uhhhhh

#

Actually

#

idk

gritty widget
#

weird shape

rotund thicket
#

but its basically just a torus

#

but thiccer

gritty widget
#

im trying to imagine like, a torus, but with an interval attached to every point

#

a [0, 1]-bundle over T opencry

rotund thicket
#

I mean because you choose a point on the surface of the torus and just go out in the perpendicular

#

welpm, i gotta draw it

gritty widget
#

bro share some of your 4d paper

rotund thicket
#

ill just make flipart

sleek thicket
#

can't you just extrude in like they're saying

#

like

#

take a

#

t u b u l a r n e i b o r h o o d

#

by compactness you can choose a constant radius

#

That looks like what they're describing yeah?

#

and it's diffeomorphic to T × I

rotund thicket
#

that's good enough for me

#

lol

#

so S^1 x D is the same thing as T x I basically

sleek thicket
#

Yeah I think you're right :)

#

Just trying to convince tterra

#

Hmm, I don't think these are the same

gritty widget
#

i still don't have a response from fields

rotund thicket
#

I mean that's how my prof said to think about S^1 x I

#

you just choose a point on the circle and go some distance

sleek thicket
#

I think of it as a cylinder

rotund thicket
#

I mean the thinking is the same

#

I just go out some distance

#

whether in the same plane

#

or the other perpendicular one

sleek thicket
#

Hmm I think I disagree with what I was saying

#

earlier

#

Oh no

#

I see

#

So the thick torus S^1×D is filled in

#

in the middle

#

T×I still has a hole

#

In the tube

rotund thicket
#

Does it?

sleek thicket
#

Yup

#

You haven't filled anything in

#

Just extruded out the sides a little

rotund thicket
#

what about the inner radius going outward

sleek thicket
#

Think about it like this: take a torus and taken outward pointing a normal vector to it

#

Attach a stick in the direction of the normal vector at each point

rotund thicket
#

Ohhhhhhhhhh

sleek thicket
#

That's T^2 × I

rotund thicket
#

I see, i was thinking that I could, in your analogy, take the negative of the normal when im on the inner radius

sleek thicket
#

Well you can take the inward normal

#

But you can't fill everything in

#

You have to make sure the little sticks don't intersect

rotund thicket
#

So like half of the torus is filled?

sleek thicket
#

That's not how I'm thinking about it

#

It's like if you took a solid torus

#

And then took a smaller solid torus contained in it

#

And cut that out

rotund thicket
#

i see

sleek thicket
#

like, T×I = (S^1 × I) × S^1

#

S^1 × I can be thought of as an annulus in the plane

#

yeah?

#

So take the surface of revolution of the annulus

rotund thicket
#

Yeah breaking it up into its components makes it easier to think about

#

thanks!

#

So you can just commute the products?

sleek thicket
#

Yup

#

Up to homeomorphism

#

Geometrically this is like a reflection of R^3

#

Being applied to the shape

#

Swapping the y and z coordinates

rotund thicket
#

that's cool

#

Wait so that means that S^2 x I is homeomorphic (?) to T x I?

#

Im getting that S^2 x I is a 3d annulus

sleek thicket
#

no

rotund thicket
#

Oh crap i was adding the exponents :p

sleek thicket
#

What specifically do you mean by 3d annulus?

rotund thicket
#

i mean a cyllinder

sleek thicket
#

I think S^2 × I and T×I are both sort of this

rotund thicket
#

with a hollow center

sleek thicket
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I think that would just be S^2

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a hollow cylinder I mean

rotund thicket
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Oh wait I mixed myself up, S^2 x I is a sphere with a hollowed out center

sleek thicket
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careful with your words

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A sphere is a shell

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Like S^2

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also "ball with a hollow center" describes a sphere imo

rotund thicket
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yeah

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that's what i mean

sleek thicket
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Here you have some bits hollow and some not

rotund thicket
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ok, ball=filled, sphere=shell

sleek thicket
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anyways yeah that's what S^2×I looks like

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Whereas T×I is like the surface of revolution of an annulus

rotund thicket
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but its still filled around the inner torus?

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here's my drawings

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please dont judge

sleek thicket
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No judgment here haha

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Let's start at the bottom right

rotund thicket
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ok

sleek thicket
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I agree with this drawing

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Also S^2 × I

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Take a closed ball and scoop out an open ball inside

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Of eg half the radius

rotund thicket
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I'm imagining some mortal combat stuff rn lol

sleek thicket
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lmao

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I'm having trouble telling apart your drawings of S^1×D and T×I

rotund thicket
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Yeah so S^1×D is the solid torus

sleek thicket
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Right

rotund thicket
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and then T×I is like S^2×I in that we scooped out the child of the parent object

sleek thicket
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Yup, exactly

rotund thicket
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ok dope

sleek thicket
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wait, I'm totally wrong about T×I being like an annulus but you rotate it

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That will give you S^2×I

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Sorry for the confusion!

rotund thicket
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So they're flipped?

sleek thicket
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Your drawings/mental models are right

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I just said something wrong earlier

rotund thicket
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yeah yeah like the difference between it being filled and a surface

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makes sense now

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so basically multiplying by I causes hollowness

sleek thicket
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Hmm, sort of

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The objects you started with were "hollow", right?

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I think what's going on is sort of the difference between a cylinder and a cone

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Like, the cylinder is homeomorphic to an annulus whereas the cone is homeomorphic to a disk

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Hollow vs filled

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There's lots general definitions of a cylinder and a cone on a topological space (the above are the case where your base is the circle)

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The cylinder on X is X × I, the cone is more complicated (you need to have seen quotient spaces to define it)

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In the case of a sphere the cylinder is the hollow thing S^2 × I whereas the cone is the filled in ball

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This isn't exactly right for the torus examples though, so maybe I'm wrong

quartz edge
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if the eigenvalues of the second fundamental form of a surface at a point are the corresponding principal curvatures, what then are the eigenvalues of the first fundamental form? are they the principal 'speeds' of travel wrt. the parameterization?

quartz edge
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it would seem so from prodding at it

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yes

gentle ospreyBOT
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gristle

quartz edge
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my linear algebra is weak as i'm just now studying it, i merely know how to compute these things so the geometric intuition can be lost on me at times

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for instance i have trouble visualizing what it means to multiply a tangent vector by I_P

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what sort of transformation does that entail

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like what does the new vector correspond to

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i can compute lengths, areas, prove certain things analytically, but i guess understanding what this thing is as an object is confusing to me

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@gritty widget what do you mean when you say 'induces the inner product'

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this terminology is something i feel i ought to be able to use but the words don't really make any sense to me

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what is meant by induce

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and why is the inner product referred to as inner

gentle ospreyBOT
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~S^1
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

shut moat
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IMO it might be easier to get an intuition for what $\mathbf{v}^T I_P$ is. It's the function that takes $\mathbf{w} \mapsto \langle \mathbf{v}, \mathbf{w}\rangle$

gentle ospreyBOT
shut moat
gentle ospreyBOT
shut moat
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and dunno why it's called inner lul

quartz edge
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ye

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that much seems reasonable to me

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also

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for

gentle ospreyBOT
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gristle

quartz edge
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we need E=G to be able to say this is the same as

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yeah?

shut moat
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that second expression doesn't make sense

gentle ospreyBOT
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gristle

shut moat
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still doesn't really make sense

sleek thicket
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Wym approx?

shut moat
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I think you want to exchange v and w?

sleek thicket
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That makes sense to me?

quartz edge
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the dimensions work out

shut moat
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oh wait

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I read this as I_P(v.w)

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smh smh

quartz edge
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but yea it relies on symmetry of I_P right?

sleek thicket
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They're asking whether you need E=G for v^T I_p w = (I_p v)^T w

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Yes gristle

quartz edge
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i meant err

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WELL

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you dont need E=G

sleek thicket
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The inner product of a and b can be written as a^T b

quartz edge
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it always works actually

sleek thicket
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but you need symmetry

quartz edge
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cuz F=F

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ye

shut moat
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yeah

quartz edge
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nice

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i like that

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well

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so lemme get this straight

sleek thicket
quartz edge
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I_P v is a function

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it takes another vector w and spits out <v, w>

sleek thicket
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This is very sticky

quartz edge
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this much is clear

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if sticky

sleek thicket
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I would say I_p v is a vector

quartz edge
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yea

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same

sleek thicket
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You're multiplying a matrix by a vector