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flat saddle
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because I don't know if I have to do it set by set

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as in if I should do for all x in A x1 is in B and x2 is in B therefore A is a subset of B

potent garnet
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The only x that satisfy the quadratic equation are x=1, and x=3, so A = {1,3}. Since A = B = {1,3}, they are identitical.

flat saddle
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okay

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thanks

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.close

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wide bay
lone heartBOT
wide bay
#

I need help with both of these problems please

potent garnet
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So for the first problem, I would find the area of the whole rectangle (pool+deck) and subtract the area of the inner rectangle (pool).

wide bay
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thats what i first assumed but why does it say the widwth if it is 2 meters

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should I add the 2 to the 12?

potent garnet
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First of all, the deck is going around the whole pool, so you don't just add something to the width of the pool. Second of all, you need to add 4, since you are adding 2 on each side.

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Does that make sense?

wide bay
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only slightly, why would i add 4 if i only need the one side of width

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cause rectangles are lw=a

flat saddle
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yeah and the length and width will be increased by 2 on each side

wide bay
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okay so its 14 on the bottom and 14 on th etop

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how do i calculate the width

flat saddle
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you see this

wide bay
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mhm i do

flat saddle
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thats why it is 4

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you do the same for width

wide bay
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so the lenght is 14 or 16

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and the length is 22 or 24

flat saddle
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look at the picture I sent

wide bay
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im looking

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i see the 2 2m

flat saddle
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if the pool is 20m long and the deck is 2m longer at each end then the decks length is?

wide bay
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24m

flat saddle
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repeat the same for the width

wide bay
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so the width would be 16

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so my final answer is 144

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tyvm

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do you know how to do #20 by any chance

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.close

lone heartBOT
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languid bolt
#

need help with #20 ?

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oh it's closed

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nvm

wide bay
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whoops sorry

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i made a new one

lone heartBOT
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lean lily
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y is just a random variable like x, you decide what it equals, and by convention people in a lot of exercices set f(x)=y

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yes

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this is wrong btw

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f(y) = |2y|^3 = 8|y|^3

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he cubed the 2 and kept in inside

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ye

lone heartBOT
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@alpine sable Has your question been resolved?

lone heartBOT
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@alpine sable Has your question been resolved?

vale wigeon
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@alpine sable what are those strange black spots over the y's at the end?

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right...

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and i presume that the L shape with a number inside it means factorial?

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ok then y = e^x

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hybrid rune
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hi can someone help me with this question please thank you

real gazelle
hybrid rune
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14 days

real gazelle
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yup

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so if 3 carpenters do one wardrobe in 14 days

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how much does 1 carpenter do in 14 days

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(assuming they work independently)

hybrid rune
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14/3?

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=4.6

real gazelle
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not quite

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dividing by 3 is right though

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but which number do you want to divide by 3

hybrid rune
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14

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or is it 4

real gazelle
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no 14 is the # of days that stays the same

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what changes is how much wardrobe they make

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so if 3 carpenters make 1 wardrobe in 14 days

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how much does 1 carpenter make in 14 days?

hybrid rune
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0

real gazelle
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how did you get 0

hybrid rune
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i have no idea actually, i don’t understand

real gazelle
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lemme ask you a different question

hybrid rune
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3/1?

real gazelle
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if three people can eat a cake in one day, how much can one person eat in a day?

hybrid rune
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1

real gazelle
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no if the three of them together eat 1

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then one of them can't eat 1

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right?

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how much of the cake can one of them eat

hybrid rune
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oh yeah 1/3

real gazelle
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yup 1/3

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so going back to the original question, if 3 carpenters make 1 wardrobe then how much does 1 carpenter make

hybrid rune
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1/3

real gazelle
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yup

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so then if 1 carpenter makes 1/3 wardrobe in 14 days

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how much does 1 carpenter make in 1 day

hybrid rune
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is it 1/3 divided by 14?

real gazelle
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yup

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so what is that

hybrid rune
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i get a decimal number

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or do u want fraction?

real gazelle
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you can leave it as a fraction

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easier to write

hybrid rune
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okay 1/42

real gazelle
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yup

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so then if it's 1 carpenter does 1/42 wardrobe in 1 day

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then how much do they do in 6 days

hybrid rune
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multiply by 6

real gazelle
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yup

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what do you get

hybrid rune
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which is 1/7

real gazelle
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yup!

hybrid rune
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omg

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thank you (:

real gazelle
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no prob! but that's not the final answer

hybrid rune
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oh

real gazelle
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if each carpenter does 1/7 of the job

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how many carpenters do you need

hybrid rune
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7

real gazelle
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yep! that's the answer

hybrid rune
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oh HAHAHAH THANK U

#

.close

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pliant flume
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Hi people, could anyone tell me what the big line in the middle means?

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empty plover
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where does this come from?

lone heartBOT
keen bear
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are you asking how the identity holds?

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trig functions mantra: when in doubt, draw a triangle

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$n^2+n+1=\frac{n^3-1}{n-1}$

ocean sealBOT
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GoldenPhoenix

empty plover
empty plover
keen bear
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what does arctan mean?

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and what type of argument does it accept?

empty plover
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arctan is the inverse of tan so it takes arguments from -inf to +inf

keen bear
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not what is its domain, what type of argument does it take? an angle measure, a fraction, an integer?

empty plover
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ah shit no a fraction

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tan= opp/adj

keen bear
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tan(theta)=opp/adj
gotta be careful to include the argument here

empty plover
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Deal

keen bear
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because we can rewrite this as theta=arctan(opp/adj)

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do we have a fraction in the argument of arctan here?

empty plover
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yes

keen bear
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so do we know the opposite and adjacent sides for our triangle?

empty plover
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so the opp side is length 1 and the adj side is length n^2+n+1?

keen bear
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yes

empty plover
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but how do i draw the n^2+n+1 side ?

keen bear
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draw a triangle and label one side with that polynomial

empty plover
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and how does this help

keen bear
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well, it turns into a difference of two other arctans, right?

empty plover
keen bear
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(I'll be honest I'm mostly spitballing here to stumble through it, but this is the basic process for how to demonstrate that a trig identity holds)

keen bear
coral prairie
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Is anyone able to help me with my math problems

keen bear
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so our goal is to try and get from the triangle we have to get to the right side

empty plover
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okay but isnt the other side angle just arctan (n^2+n+1)?

coral prairie
keen bear
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it looks like you already have someone helping you in your channel

coral prairie
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they left

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are you available to help me please

coral prairie
empty plover
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go and help him @keen bear its fine ill try to walk through it again with what you told me

lone heartBOT
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@empty plover Has your question been resolved?

empty plover
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no

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<@&286206848099549185>

empty plover
languid bolt
empty plover
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what x

languid bolt
empty plover
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dk why

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anw i ve got to go so nvm

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no help :/

languid bolt
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autoclose is usually 15 minutes+ dw

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ima try to understand the question

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brb

empty plover
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its not really important its just bothering me that its put in my notes as an example with no justification for it whatsoever as if its obvious

languid bolt
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nvm gtg eat, i dont understand

empty plover
#

Deal

lone heartBOT
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fervent grail
#

#help

lone heartBOT
fervent grail
#

The number of real solution of x^2-2x+2+|x-1|=0 is ?

empty plover
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none

fervent grail
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How

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<@&286206848099549185>

iron mulch
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Graph it bro

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Then you’ll see if it ever equals 0

fervent grail
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Any other way ?

iron mulch
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It’s the easiest way

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And the laziest way

fervent grail
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Any other way ?

iron mulch
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You can google a graphing calculator

fervent grail
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Ikt but I want to do it with evaluation and all

iron mulch
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Okay well use the quadratic equation to factor the first 3 terms of the equation and see if it gives you any real answer, and then see if there are real answers plug it into the absolute value function and see if it gives you a 0

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Otherwise if the roots of the quadratic don’t work then there is no real solution

fervent grail
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I am not able to remove the mod

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<@&286206848099549185>

iron mulch
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What

tacit arch
fresh parcel
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well you could do casework for x<1 and x>1

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and solve both of those quadratics

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to see if it gives you a solution

lone heartBOT
#

@fervent grail Has your question been resolved?

lone heartBOT
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azure trout
lone heartBOT
azure trout
#

How would I start with this?

languid bolt
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multiplying both sides

ocean sealBOT
#

MarveI

azure trout
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so its the first one

languid bolt
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uhh

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show work

azure trout
languid bolt
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there's brackets here

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there's none on the first options

azure trout
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yea i added them

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but when i dont add them i get no listed answer

languid bolt
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$(5\sqrt{3} - 2)\sqrt{2} \neq 5\sqrt{3} - 2\sqrt{2}$

ocean sealBOT
#

MarveI

azure trout
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this is what I get when i dont add brackets

languid bolt
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try using distributive properties

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i forgot the name

azure trout
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ive legit tried everything

languid bolt
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$\sqrt{2}(5\sqrt{3} - 2)$

ocean sealBOT
#

MarveI

azure trout
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i knew that

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TOTALLY

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LMFAO

languid bolt
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do you know how to distribute the square root of 2?

azure trout
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i got it

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its the 2nd one

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thanks again man

languid bolt
#

ye

azure trout
#

❤️

#

.close

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azure trout
lone heartBOT
azure trout
#

i tried solving for x but it didnt make sense

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nvm im dumvb

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forgot to make it =0

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.close

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languid bolt
#

ok?

lone heartBOT
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orchid heron
#

what is the difference between the line and vector

abstract fractal
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Ones a line, the others a vector

orchid heron
#

vector is the direction ?

weary wyvern
#

A line is a certain type of a set of vectors

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Each point on the line is a vector

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azure trout
lone heartBOT
azure trout
#

.close

lone heartBOT
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azure trout
#

.reopen

lone heartBOT
#

azure trout
#

Is this correct?

frigid rune
#

Yes that's correct

ancient moss
#

yes

azure trout
#

thank you

#

.close

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ember grotto
#

I want to get target's relative angle to my plane's heading vector
The compass is my heading angle and theta is its standardized value (I had to do some computations to transform game's output to standard mathematics)
x and y are my plane's coordinates and x2 and y2 are target's coordinates
Another important note is that the y axis is reversed in game's output so deltaY is actually -deltaY so in some of the calculations I used -deltaY to neutralize the reversed axis' effect

distance variable is calculated easily based on deltaX and deltaY

From now on please correct me if i'm wrong

Now let's assume I am at the center of coordinates (0, 0)

Let's calculate line equation of my plane's heading vector
It will be: y = tan(theta).x
So tan(theta).x - y = 0
Now based on the formula of distance between a dot and a line which is:

Ax + By + C = 0 => distance = (|A.x0 B.y0 + C|) / sqrt(X0^2 + Y0^2)
A = tan(theta); x0 = deltaX; B = -1; y0 = -deltaY; C = 0;
lineDistance variable is calculated:
(|tan(theta).deltaX + deltaY|) / distance

Now the thing is if I did all the calculations correctly, distance always would have been greater than line distance. But most of the times distance is less than lineDistance which is odd
By the way all the distances (x, y, x2, y2) are between -1 and +1

tacit arch
#

show your work?

ember grotto
tacit arch
#

if I did all the calculations correctly

ember grotto
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Ah this

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Ok

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I mean most of the work is code
Here it is:

  deltaX = x2 - x;
  deltaY = y2 - y;

  theta = -compass + 90;
  nomalizedTheta = degreeNormalize(theta);

  distance = sqrt(deltaX * deltaX + deltaY * deltaY);
  lineDistance = (tan(radians(nomalizedTheta )) * deltaX + deltaY).abs() / distance; // .abs() is |-1| ==> +1

  alpha = degrees(math.asin(lineDistance / distance));
#

Let me simplify it

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I hope it's clear
I have some stuff written on paper but those aren't very clear 😅

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Compass is my plane's heading angle

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Hopefully it's fine to ping helpers now
<@&286206848099549185> 👋 😅
Cheers!

tame willow
#

oop

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I don’t read code well

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sorry

iron mulch
ember grotto
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Oh well I can write it somewhere on paper or something

tame willow
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I just mean like

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What’s the problem you want to solve

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If it’s within code I cannot really read it

iron mulch
#

Sorry I only know basic python :)

ember grotto
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@ember grotto Has your question been resolved?

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@ember grotto Has your question been resolved?

lone heartBOT
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@ember grotto Has your question been resolved?

ember grotto
#

I will close this question for now, since I am going offline

#

.close

lone heartBOT
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warm moth
lone heartBOT
warm moth
#

hey guys I am kinda noob at English

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can anyone confirms that this one means the origin is at (0,5) ?

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not the height of the pillar

placid zinc
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The origin is always at (0,0)

warm moth
#

hmm

placid zinc
#

That's what an origin is haha

warm moth
#

lowest point of the cable intersecting the vertical axis

placid zinc
#

Lowest point of the cable is at (0,5)

warm moth
placid zinc
#

It says "the resultant force W(x)"
The resultant force of what?

#

Eh, well they're getting into what shape the wire is, I suppose.

warm moth
#

if I want to show sth to be first linear ode

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how can I approach this qs

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I got my dy/dx = W(t)/H

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oh sike

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gtg

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someone pls give me some guidance if possible

lone heartBOT
#

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wooden owl
lone heartBOT
wooden owl
#

this unit is permutations and combinations

#

not sure how to begin solving this question

#

formula sheet

lone heartBOT
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@wooden owl Has your question been resolved?

lone heartBOT
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@wooden owl Has your question been resolved?

fossil gate
#

Is there any more context for the question? Or is that it? @wooden owl

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stable night
lone heartBOT
stable night
#

Hi, can someone help me with part ii?

lone heartBOT
#

@stable night Has your question been resolved?

distant estuary
stable night
#

erm

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so do i try to turn the equation for curve C to the new eqn given?

stable night
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@stable night Has your question been resolved?

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lone heartBOT
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unborn meteor
lone heartBOT
unborn meteor
#

Question b iv

#

What does it mean by find the endurance limit?

#

‘When repeatedly subjected to force F’

#

And the ‘endurance limit is the force below which the steel will not break even if subjected to an infinite number of application of that force’

#

Meaning it can be hit by 70 Newton’s of force infinitely and not be affected at all

#

But if it’s hit by 71 Newton’s of force repeatedly

#

There will be some damage

#

It should be a constant value

#

So then how do I do this

lone heartBOT
#

@unborn meteor Has your question been resolved?

lone heartBOT
#

@unborn meteor Has your question been resolved?

placid zinc
#

It's not being "hit by"
It's being "stressed with"

#

You're trying to pull that metal bar apart by pulling on it many times

#

If your math is correct, then 70N of force, no matter how many times it is applied, will never break the bar.

#

Worth saying that 70N is very small

#

What did you do to get 70N?

lone heartBOT
#

@unborn meteor Has your question been resolved?

lone heartBOT
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lone heartBOT
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vital dagger
#

2^* X 5* = 8000

lone heartBOT
vital dagger
noble sinew
#

$2^x \cdot 5^x=8000$?

ocean sealBOT
#

ScapeProf

noble sinew
#

Type it as 2^x * 5^x=8000

#

Now it is readable

pliant wave
#

these are private help channels. if you want to have one of your own, read the channel instructions first

vital dagger
#

actually the base number 2 is raised to the power of 2x not x

#

mb

noble sinew
#

Prime factor 8000

kindred anchor
#

Why not use logarithm?

vital dagger
#

i dont follow

noble sinew
#

Its the same

vital dagger
vital dagger
noble sinew
#

Can you use a calculator? Can you prime factor?

vital dagger
#

ok

#

ohhh

#

ty

#

.close

lone heartBOT
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solid imp
lone heartBOT
solid imp
#

hi so the question was what are the asymptotes

#

and give their function

#

SA is diagonal asymptote

#

but id understand that ''In x'' means

#

in minus inf and in positive inf

#

like dont both asymptotes exists in both + & - infinity

vale wigeon
#

sure, the asymptotes themselves are straight lines that extend infinitely in both directions

#

but your graph only approaches the slanted asymptote as you go left

#

and only approaches the horizontal asymptote as you go right

solid imp
#

so the In +inf and In -inf talks about the direction of the x-axis

#

alright thankyou

#

.close

lone heartBOT
#
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sick venture
#

I have this spectral curve plotted as a function of wavelength. However as you can see, it bottoms out at around 600nm. I would like to extend the characteristic of the slope so that it continues at the same rate it was declining before bottoming out (regardless if that decline is exponential). I want to essentially remove the bottoming out and instead extend it's decline down to 0. How would I go about this?

lone heartBOT
#

@sick venture Has your question been resolved?

noble sinew
#

Remove the points from 600 to 610 or whatever

#

And then just fit the points until 640 or whatever

#

Now you have a regression line you can continue

sick venture
noble sinew
#

Wdym

sick venture
#

Meaning factor in the trajectory of the slope. So that the values which extend it are relevant to the path it was taking

#

With the bottoming out values removed

#

I tried by finding the medium of relative change between each point. Then deducting that value from each previous point down to 0.

#

But I don't think it was very elegant. Visually it made the extension look like I all of a sudden just added a straight line past the point

#

Meaning, it didn't seem to follow the overall trajectory of the slope in a smooth way

#

example

#

that definitely AIN't it

#

I need a way to know the trajectory it is moving, so I can generate relevant values to continue the slope down to 0

sick venture
#

I'm working from the actual values

noble sinew
#

Because it wasn’t linear in the 1st place

#

And you are trying to make it linear

sick venture
#

exactly my issue

#

How to generate values to continue the slope, when it's not linear

sick venture
noble sinew
#

I said fit

#

Not fit linear

#

You can fit exponential too

sick venture
#

How

noble sinew
#

Any program

sick venture
#

Let's say I took the range of values between 610nm to 650nm. How can I find out what the none linear change is. So that I can generate relevant values to extend the slope to 0.

#

?

noble sinew
#

y=a * b^x

#

If its perfect exponential its just picking two points and solve for a,b

#

Otherwise you need regression

#

If that is the case use any program to do that for you

sick venture
#

I don't believe it's exponential. It seems to hit a straight line portion after the toe

noble sinew
#

After what?

sick venture
#

I'm really don't know jack about math HAHA. What's a regression

noble sinew
#

,w linear regression

noble sinew
#

Is an example (linear regression)

sick venture
noble sinew
#

You have points which aren’t perfectly linear so you make a least squared fit for it

sick venture
#

What's a least squared fit?

noble sinew
#

Google is a thing and I don’t see how its relevant to what you are asking

sick venture
sick venture
noble sinew
#

And like I said any program can do it

sick venture
#

Okay, how do I do it in google sheets

noble sinew
#

Google is still a thing

#

Google linear regression (your program)

sick venture
#

If I wanted help through google I wouldn't have asked here

#

I thought you'd actually give me the answer. I don't study math. I'm just trying to solve a problem

noble sinew
#

And I don’t want to google how to do it for you

sick venture
#

Don't get me wrong I appreciate the source of concepts. But can we just cut to the chase

noble sinew
#

When you can google it yourself

#

This isn’t math anymore

#

This is tech support

sick venture
#

Save me the hassle of trying to understand it for like 2 hours

noble sinew
#

There is nothing to understand

sick venture
noble sinew
#

You just need to click whatever buttons

#

Your program needs

#

Which google tells you

#

How is this math

sick venture
#

So your response to me not understanding the concepts is that I should use google or figure out how my program can do the math. I'm trying to understand the math so I can apply it. If you understand how to solve this problem why are you redirecting me to figure the rest out

noble sinew
#

I understand it

#

I’m saying it isn’t really doable by hand

sick venture
#

Okay great, this is math help. Teach me

noble sinew
#

So I said go google how to do it in your fav program

#

You refused and wanted me to google it for you

#

For me to type what google said?

sick venture
#

So the program was written by AI, the math that the program operates on is not mathematically producible by humans?

noble sinew
#

What?

sick venture
#

You're saying the math to solve this problem is not doable by hand

#

Who wrote the script

noble sinew
#

I’m saying the calculations aren’t feasible to do by hand

sick venture
#

For these programs

#

AI?

noble sinew
#

Yes?

#

Calculate 2^19281+261^2 by hand

#

Please

sick venture
#

So AI discovered this mathematical concept, and the only way to execute it, is to use the program the AI wrote. Or maybe just maybe, people who understood the math wrote the program. To complete the task. Of which they understand the math and can reproduce it. Because how else would they write the program.

sick venture
#

Why do I need a program

noble sinew
#

And your program is just a calculator

sick venture
#

So google sheets is nothing but a calculator

noble sinew
#

All I said was google and figure out how your fav program calculates line of best thing for you

#

Yes?

#

Like what

#

I don’t understand why you are getting mad

sick venture
#

That's different to using a calculator. That's finding an operation. Preset calculations. Of which was written by a human. Let's skip the part where I hope and pray I can find this very specific operation available in google sheets. And just tell me the formula. Is it really that difficult?

#

tell me the secret formula crabs

noble sinew
#

$$\hat\alpha=\bar{y}-(\hat\beta \bar{x})$$ and $$\hat\beta=\frac{\sum_{i=1}^n (x_i-\bar{x})(y_i-\bar{y})}{\sum_{i=1}^n (x_i-\bar{x})^2}$$

sick venture
#

Thank you. Can you define the variables please

noble sinew
#

y_i=alpha+beta x_i+eps_i

ocean sealBOT
#

ScapeProf

sick venture
#

?

noble sinew
#

?

sick venture
#

The variables

#

Can you please define them so I can follow

noble sinew
#

I did

sick venture
#

I only symbols I understand in there is sum

noble sinew
#

Seems like just using your fav program is faster doesn’t it?

#

y=alpha+beta x is linear relation

sick venture
#

Not if you want to understand what you're doing

noble sinew
#

Hats are estimates

#

Bars are means

sick venture
#

I'm surprised how many absolute symbols there is in math

#

I was under the impression, most were just definable variables per equation. Like programming

#

Thanks for your help

#

So for this specific curve, it would require a linear regression right?

#

Not a nonlinear regression?

lone heartBOT
#

@sick venture Has your question been resolved?

#
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dark hull
#

so for this question

lone heartBOT
dark hull
#

how do i prove that this is a decreasing series

#

so far i have

weary wyvern
#

This is not a sequence

dark hull
#

$\frac{n^n}{n!} \geq \frac{n^n}{(n+1)!}$

ocean sealBOT
#

Kekistan

dark hull
weary wyvern
#

Wdym by a decreasing series

dark hull
#

next term less than the first

weary wyvern
#

Hmm well that's not true here

dark hull
#

$\frac{n^n}{n!} \geq \frac{(n+1)^{n+1}}{(n+1)!}$

#

this can't be proven?

ocean sealBOT
#

Kekistan

weary wyvern
#

Each term alternates between being positive and negative

#

It keeps going above and below 0

#

Because of (-1)^(n+1)

#

So it's neither increasing nor decreasing

dark hull
#

what about just the series

#

$\frac{n^n}{n!}$

ocean sealBOT
#

Kekistan

weary wyvern
#

Well the numerator grows a lot quicker than the denominator

#

So the sequence tends to infinity

#

So it can't be decreasing

dark hull
#

i see

#

thanks

weary wyvern
dark hull
weary wyvern
#

It might be a good idea to plot the sequence on desmos btw, if you want to see how it behaves

dark hull
#

alright alrigh

#

.close

lone heartBOT
#
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rancid trail
#

find all the zeroes of the polynomial $f(x)=2x^4-9x^3+5x^2+3x-1$, given $\alpha=2+\sqrt{3}$, $\beta=2-\sqrt{3}$

ocean sealBOT
#

ThickduckPlayz

rancid trail
#

i feel like i need to divide $f(x)$ by $x-\alpha$

ocean sealBOT
#

ThickduckPlayz

gray isle
#

there's a nicer way to approach it

#

as alpha and beta are conjugates,
it would be less tedious to expand (x-a)(x-b) before doing division

#

alternatively since you're given 2/4 of the roots, it would also be relatively simple to consider sum and product of roots

rancid trail
#

oooohhhh

#

thank you

#

after calculating it, i got $x^2-4x+1$

ocean sealBOT
#

ThickduckPlayz

rancid trail
#

should i divide it with the polynomial?

gray isle
#

if you're using this approach yeh

rancid trail
#

also one doubt.
why does it make sense to divide this with the polynomial?

#

my teacher said it is common sense to divide the factors with the polynomial because the remainder is zero

#

but it doesn't make any sense to me, what am i going to do with the quotient and how is it related to the other zeroes?

gray isle
#

are you familiar with factor theorem

rancid trail
#

yeah

#

if a is an zero of f(x), (x-a) is a factor of f(x)

#

also when i divide, i get remainder to be 32x-8

gray isle
#

consider the factored form of a quartic polynomial (can be applied to pretty much any degree)
k(x-a)(x-b)(x-c)(x-d)

rancid trail
#

ok

gray isle
#

if you know that (x-a) is a factor,
dividing by (x-a) gives leaves you with a polynomial 1 degree lower: which makes it easier to find the remaining zeroes/roots

rancid trail
#

ok

#

that means i have to do 32x-8=0

gray isle
#

where's 32x-8 = 0 coming from

#

you should have a quadratic

lone heartBOT
#

@rancid trail Has your question been resolved?

lone heartBOT
#
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grave lance
lone heartBOT
grave lance
#

Hey I was given both of these and told I am supposed to search for the area Integral of those shown

#

but Im a bit confused... what exactly am I supposed to do?

#

I mean I'm guessing I have f_1(x,y)=x and f_2(x,y)=y²+3L²

#

And then integrate them over the area shown in the diagramm

#

but how exactly do I tackle the circle?

lone heartBOT
#

@grave lance Has your question been resolved?

versed crater
#

What does a represent

lone heartBOT
#

@grave lance Has your question been resolved?

grave lance
wet pagoda
#

build in wolfram how they look like

#

you will get endpoints where they intersect

grave lance
#

What do you mean exactly intersect?

#

They way I understood is, is that I need 2 curves or lines or whatever shape to build the boundaries of one of the Integrals but I am looking at a linear function and a circle

#

I mean doing the double integral of the linear line would be easy

#

but the circle kind of gives me big???

slender marten
# grave lance

Just split the region up into three regions.
For the circular region at the top, it's a circle of radius L centered at (2L,2L).
Thus (x - 2L)^2 + (y - 2L)^2 = L^2.

grave lance
#

so one with boundaries for the dy Integral with 0 -> 2x

#

one with with the boundaries from 1L < x < 3L

#

And one with the circle as the boundaries?

#

But for me I'm still a bit confused how to incorporate the circle

slender marten
#

0 to 2x?

#

I'd probably solve (x - 2L)^2 + (y - 2L)^2 = L^2 for y and use the fact that the third region will be one with the positive square root. Then we clearly have L <= L <= 3L.

grave lance
#

well isnt the Integral for the straight with a gradient of 2 for the dy Integral 0 to 2x?

#

because it's not just a straight line

#

so it's 0 <= y <= 2x

slender marten
#

You're looking at the subregion labelled 1?

grave lance
#

yea

slender marten
#

That seems correct.

#

Region 1: 0 <= x <= L, 0 <= y <= 2x.

grave lance
#

ok

#

so for the square it's also just straightforward

slender marten
#

Yes.

grave lance
#

because it's just a square region

#

so it's a bit easier for the circle can't I do a coordinate transform?

#

let x~ = x + 2L

#

and the same for y to put those at the center of the circle

slender marten
#

You could but I wouldn't if you're keeping it in cartesian anyway.

#

Well for setting it up anyway. For evaluating then it makes sense.

#

I'd imagine both are fine when I think of it.

grave lance
#

I'm still looking at the circle and idk how to incorporate it into the integral

slender marten
#

View it like this.

#

Since we have a circle of radius L centered on (2L, 2L) then we know it's equation is
(x - 2L)^2 + (y - 2L)^2 = L^2.

grave lance
#

yea

slender marten
#

Solve it for y.

#

We obtain that (y - 2L)^2 = L^2 - (x - 2L)^2. And the desired curve is
y = 2L + sqrt(L^2 - (x - 2L)^2)

#

R3: L <= x <= 3L, 2L <= y <= 2L + sqrt(L^2 - (x - 2L)^2)

grave lance
#

ok yea sure that makes sense

slender marten
#

Just write your integral as the sum of the three double integrals over the three regions and you should be done.

grave lance
#

yea I understood that part aswell

#

but I'm already looking at the integration of a sqrt boy is this gonna be fun again

slender marten
#

Have you used polar coordinates before?

#

If so could be worth using x = 2L + r cos(theta), y = 2: + r sin(theta). dA = r dr dtheta still.

#

Or just use a integral calculator.

grave lance
#

hm yeah this isnt just for fun in my freetime

#

so I gotta actually learn how to do these Integrals by hand for the test

#

which is gonna be annoying

slender marten
#

Well you have to integrate with respect to y first anyway so you end up with a y^4 so it might not be too bad.

grave lance
#

well if I first just do the f(x,y)=x

slender marten
#

Oh right.

#

Well in that case.

#

Instead of isolating for y. Insolate for x instead.

grave lance
#

if I get rid of the first integral for the circle I'm left with the Integral of L -> 3L of x*sqrt(x²+4Lx-3L²)

slender marten
#

R3: 2L <= y <= 3L, 2L - sqrt(L^2 - (y - 2L)^2) <= x <= 2L + sqrt(L^2 - (y - 2L)^2)

grave lance
#

y twice?

slender marten
#

Fixed.

#

It didn't simplify stuff that much really or at all.

grave lance
#

yea

#

I mean I'm even confused why its going from a sqrt term to sqrt term now

slender marten
grave lance
#

Ah

#

yea ok I get it

slender marten
#

In the x direction you are bounding by two curves. In contrast the the other where you was bounded below by the flat line y = 2L up to the curve.

grave lance
#

but wouldnt those boundaries up there that you wrote be true for the entire circle area

#

not just half of it

slender marten
#

It is but the y bound ensures we have only the top part we require.

#

2L <= y <= 3L.

grave lance
#

oh right yea

#

I mean if in the integration I dont have to integrate a sqrt term

#

and just simplify it

#

that would already help a lot

#

bcs I'm pretty sure we cant even solve quadratic terms under a sqrt

#

I can solve something with a²-x² under a sqrt

slender marten
#

That's what I thought since if we integrate x we get a x^2 term to simplify things.

#

I got the integrand to be 4Lsqrt(L^2 - (y- 2L)^2) between y = 2L and y = 3L.

grave lance
#

lemme slap it into an integral calculator

slender marten
#

$\iint_{R_3} x \dd{A} = 4L\int_{y = 2L}^{3L} \sqrt{L^2 - (y - 2L^2)} \dd{y}$.

ocean sealBOT
#

stabulo

grave lance
#

Hm but you still have to do the ax²+bx+c term under the sqrt

#

which I am unable to solve

#

unless you can rewrite it but I cant see how

slender marten
grave lance
#

is there not a way to somehow define the boundaries in a way that you get the sqrt term wheen you have to integrate by a variable that isnt inside the sqrt

#

I mean to me all roads kind of point towards a polar double integral

#

which I think simplifies the integral for the circle

slender marten
#

I think there's a simple way to get the answer. One second.

#

The integral is the area of the quarter circle of radius L.
Therefore the integral is 4L( 1/4 pi L^2) = pi L^3.

#

$4L\int_{y = 2L}^{3L} \sqrt{L^2 - (y - 2L^2)} \dd{y} = 4L \left(\frac{\pi L^2}{4} \right) = \pi L^3$.

ocean sealBOT
#

stabulo

grave lance
#

ok yea makes sense

#

but that's like just looking at the circle and knowing what the area function is and then multiplying that by the distance towards the plane

#

but what about when you have the term y² + 3L²

slender marten
#

Maybe there's a similar trick. I've not looked.

grave lance
#

yea bcs then it's not just a cylinder but one with one side being the 2d plane of the function f(x,y)

lone heartBOT
#

@grave lance Has your question been resolved?

lone heartBOT
#
Channel closed

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lone heartBOT
#
Available help channel!

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unreal crow
#

So I am solving a non linear equation of motion problem, I am told to first use the first two terms of the taylor series to change the equation of motion to one which has cubic nonlinearity, what does this mean? The equation of motion should have ^3?

lone heartBOT
#

@unreal crow Has your question been resolved?

lone heartBOT
#

@unreal crow Has your question been resolved?

tacit arch
unreal crow
#

Hopefully you can see that.

tacit arch
#

Nah just screenshot and upload

unreal crow
lone heartBOT
#

@unreal crow Has your question been resolved?

last ether
lone heartBOT
#

@unreal crow Has your question been resolved?

tacit arch
ocean sealBOT
#

riemann

molten pivot
#

Am I the only one who thinks that this is phrased ambiguously

tacit arch
iron mulch
#

.close

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tropic oasis
lone heartBOT
tropic oasis
#

could i get some help on starting out on this problem?

iron mulch
#

First draw or look at the graph of that function

tropic oasis
#

ill use desmos

#

so its a parabola

iron mulch
#

Yes

#

So you then need to put a rectangle with its right edge touching the point (1,3)

tropic oasis
#

where did the 3 come from?

iron mulch
#

And then place 5 more and then find area

#

Because f(1) is 3

#

Silly

tropic oasis
#

ohh i see

#

okay

#

so its basically telling me to only go from

#

-2 -1 0 1

#

on the x axis?

#

for finding the area?

iron mulch
#

Uhhhhh wha

tropic oasis
#

this part

iron mulch
#

I’m just saying you need to put 6 rectangle with the rivht most ending at 1,3 and then fit them evenly spaced within thay region

#

I hate Riemann sums and suck at them so @tacit arch can you give help

tropic oasis
#

yeah i'm kind of confused 😭

tacit arch
tropic oasis
#

LOL

iron mulch
tropic oasis
#

like i get the drawing the rectangle part

tropic oasis
# tropic oasis

is this part basically telling me my limits for my x axis for where i find my area?

iron mulch
#

Riemann you got this 👍🏻

tacit arch
#

make a table

#

that's the hardest part. the rest is multiplying length times width repeatedly to get areas of rectangles and adding them up

tropic oasis
#

okayyy

#

what limits do i use for my x though?

tacit arch
tropic oasis
#

okay

#

done i got my table

#

-2,5
-1,2
0,1
1,2

tacit arch
#

you only gave 3 subintervals

#

[-2, -1], [-1, 0], and [0, 1]

#

can you find a way to divide [-2, 1] into six sub-intervals, preferably each of equal length?

tropic oasis
#

hmm

#

i could divide 4 by 6?

#

it's basically telling me to find 6 points of those limits?

#

meaning theyre going to be some sort of fraction if im understanding it correctly

tacit arch
#

hint: length of [-2, 1] is 1 - (-2) = 3

tropic oasis
#

found this in my notes

tacit arch
#

looks right

tropic oasis
#

(1 - (-2))/6 = 3/6 = 1/2

#

which answer is 1/2

#

so my graph should have

#

-2, -3/2, -1, -1/2, 0, 1/2, 1?

tacit arch
tropic oasis
#

right end points

#

so it would be 6 starting from the right?

#

which basically excludes the -2?

tacit arch
#

yup

tropic oasis
#

so now i can do x*y

#

for my 6 points

#

and add up the area

tacit arch
tropic oasis
#

-39/8?

#

is what i got if i did things right lol

tacit arch
tacit arch
tropic oasis
#

so i drew it out like the video

#

my width should be 1/2

#

i got 59/8

tacit arch
#

,w integral -2 to 1 of x^2 + 2

tacit arch
#

,calc 59/8

ocean sealBOT
#

Result:

7.375
tropic oasis
#

hm

tacit arch
#

,calc ((-3/2)^2 + (-1)^2 + (-1/2)^2 + 0^2 + (1/2)^2 + 1^2 + 6*2) * 1/2

ocean sealBOT
#

Result:

8.375
tacit arch
#

you probably just have an algebra mistake somewhere

#

,calc 8.375 * 8

ocean sealBOT
#

Result:

67
tropic oasis
#

oh...

#

i see what i did wrong

#

i was doing x^(2)+1

#

in my calculator 😄

#

instead of x^(2)+2

tacit arch
#

ha

tropic oasis
tacit arch
tropic oasis
#

LMAO i think so too

#

ty for the help!

#

.close

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#
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flat mortar
#

<@&286206848099549185> is 10/31, 10/32, 10/33 answers for the question

"List 3 Intergers between 1/2 and 1/3"

thank you for helping 🙂

lilac nest
#

!15m

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#

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iron mulch
#

You complete fuck

pliant sun
#

LMAO

iron mulch
#

You absolute fuck WHY CAN NO ONE READ

pliant sun
#

feel caden's wrath

flat mortar
#

sorry lol

pliant sun
#

are we not gonna talk about the question though

iron mulch
pliant sun
#

3 integers between 1/3 and 1/2 LMFAO

iron mulch
#

An integer is a whole number that is positive or negative

#

This is my 13th reason

gray isle
#

maybe they misquoted the question

#

people might choose to not help out of spite

flat mortar
#

ok i got it

#

ok sorry

#

will not happen again

#

sorry mods and helpers

iron mulch
flat mortar
#

.close

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pliant sun
#

we forgive you

#

caden doesn't

iron mulch
#

I don’t

flat mortar
#

thanks

iron mulch
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knotty wren
#

good resources to learn these two units?

lone heartBOT
pliant sun
#

wait its probably not

#

I got excited for a bit

languid bolt
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#

@knotty wren Has your question been resolved?

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sharp moth
#

Am I understanding phase shift correctly?

lone heartBOT
sharp moth
#

You have to put the periodic function in the form of Asin(B(x-C))+D

#

And that yields the horizontal movement of the graph (which is C)

north glacier
#

Basically, for all f(x+a) where a is a positive real no., the graph is shifted a units to the left. Hope this helps

sharp moth
#

Okay thank you

#

.close

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knotty wren
knotty wren
pliant sun
#

go

#

I receommend using coachingactuaries

knotty wren
#

whats that?

pliant sun
#

its expensive but it helped me pass it first try

#

its software to help study for the exam

knotty wren
#

oh but i have only 2 days

#

i just want simple videos

#

to learn these concepts

pliant sun
#

best bet is probably youtube then

knotty wren
#

i cant find videos on youtube

pliant sun
#

uhhh

#

idrk then these concepts are pretty niche

#

how have you studied for the exam thus far

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knotty wren
#

but these topics are so specific I cant find any videos

pliant sun
#

how long have you been studying for the exam

#

I'm not sure where you could find any videos

#

maybe in a manual somewhere but

#

you might have to pay

knotty wren
#

rip

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#

@pliant sun Has your question been resolved?

pliant sun
#

.close

#

.close

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kind eagle
#

Hi, can I have help with b & c?

lone heartBOT
pliant sun
#

pa means per annum here?

kind eagle
#

yes

pliant sun
#

you can do this by just brute force

#

there's probably a formula that makes it faster but I can't think of it off the top of my head

kind eagle
#

for b, I know how to solve it, but wondering why the arithmetic series is
( 40000 * (1.04^n - 1) ) / (1.04 - 1)
and not
( 40000 * 1.04 * (1.04^n - 1) ) / (1.04 - 1)

pliant sun
#

ah right arithmetic series

#

so the increase happens

#

the 2nd year right

#

so your initial term is 40,000

#

not 40,000 x 1.04

kind eagle
#

oh right ok yep that makes sense

#

and for c, the equation would be arithmetic series for eleanor = geometric series for henry, but not sure how to solve it

#

( 40000 * (1.04^n - 1) ) / (1.04 - 1) = (10/2) * ( 2 * 40000 + 2000(n-1) )

pliant sun
#

you may have to use natural logs

#

to pull the n down from being an exponent

#

or again you could brute force it but that's not the most efficent way to solvve

kind eagle
#

the answer suggests "the start of the 13th year", but for some reason I'm getting n = 9 instead, by trying to simplify and brute force that equation

#

is the equation set up correctly?

#

oh wait that 10 should be an n

#

which apparenlty gives

#

oh wait that's over the integers

#

i think i'm just answering my own question here, i'll work on it more :)

#

.close

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alpine sable
#

I wanted to know what's factor theorem and remainder theorem

gray isle
#

those are easily searchable

#

read up and come back if there are any parts you don't understand

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
gray isle
#

what were you watching and which parts don't you understand

#

we're more or less going to be saying the same thing

#

be more specific and we may be able to clarify certain parts for you

alpine sable
#

I just want it to be explained about it slowly.. and like in simple words... I don't have anything to specify.. wanna know from start

gray isle
#

when a polynomial P(x) is divided by (x-a),
P(a) will give the remainder (which is the remainder theorem)
if a is a root/zero, (x-a) will be a factor. and the remainder when dividing by P(x) by (x-a) will be 0 (which is the factor theorem which is a special case of the remainder theorem)

vale sapphire
#

To write it all out, the key is that you can perform euclidean division on polynomials. Hence, you can write P = (X-a)*Q + R, for R of degree 0 (strictly less than 1, the degree of X-a) i.e a constant. If you evaluate this at a, you get R + (a-a)Q = P(a), i.e R = P(a).

So P = (X-a)*Q + P(a)

vague mirage
#

@alpine sable
In very simple Words
Factor theorem is used for taking out the factor like How you factorise and it's just factor theorem and reminder Theorem are same but has a little bit of difference
And the Reminder theorem
Is just a replacement for long division method is used when you just want to calculate the reminder

alpine sable
#

Thanks a lot for your help! I'll try solving sums based on this and will ask any more doubts if i have 4_884262055874531338 @vague mirage @vale sapphire @gray isle

vague mirage
#

Wlcm

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keen python
#

the leibnitz kriteria doesnt say that it converges absolut right ?

marsh rapids
#

the one for alternating series ?

#

if so then no

#

because (-1)^n / n converges as an alternating series, but doesn't converge absolutely

keen python
#

exactly ye

#

why does it not converge absolut

marsh rapids
#

why should it ?

#

the alternating convergence test works because the series is alternating

#

because you go back and forth, it suffices that each step is smaller than the last for your back and forth to converge

#

if you always went in the same direction, you'd need your steps to get smaller and smaller at a sufficient pace

keen python
#

a series converges absolut when you put it in absolut

so |-1^n|/n = |-1|^n / n = 1 / n

#

ah an

#

Sum of 1/n is an harmonic series

#

which does not converge

#

bc there is a sentence

#

a series converges if the sequence is a zero sequence.... but I see its not that way around

#

I'm not sure on how to write an answer here

#

ive a potenz series

#

and calculated the convergenzradius

#

is the potenz series absolut converget in (1/2 ; 3/2) AND !!! convergent in the edge point x = 1 / 2
and divergent for x < 1/2 AND!!! x >= 3/2 ?

#

i think this would be correct answer

karmic rapids
#

are you german

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#

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lone heartBOT
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cinder condor
#

does this have an expansion?

lone heartBOT
cinder condor
#

if so

#

what is it

marsh rapids
#

this is just a geometric series

cinder condor
#

oh no

#

omg

alpine sable
#

Lol

cinder condor
#

goddit

#

.close

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thick lynx
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