#help-0
1 messages · Page 1056 of 1
as in if I should do for all x in A x1 is in B and x2 is in B therefore A is a subset of B
The only x that satisfy the quadratic equation are x=1, and x=3, so A = {1,3}. Since A = B = {1,3}, they are identitical.
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I need help with both of these problems please
So for the first problem, I would find the area of the whole rectangle (pool+deck) and subtract the area of the inner rectangle (pool).
thats what i first assumed but why does it say the widwth if it is 2 meters
should I add the 2 to the 12?
First of all, the deck is going around the whole pool, so you don't just add something to the width of the pool. Second of all, you need to add 4, since you are adding 2 on each side.
Does that make sense?
only slightly, why would i add 4 if i only need the one side of width
cause rectangles are lw=a
yeah and the length and width will be increased by 2 on each side
mhm i do
look at the picture I sent
if the pool is 20m long and the deck is 2m longer at each end then the decks length is?
24m
repeat the same for the width
so the width would be 16
so my final answer is 144
tyvm
do you know how to do #20 by any chance
.close
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y is just a random variable like x, you decide what it equals, and by convention people in a lot of exercices set f(x)=y
yes
this is wrong btw
f(y) = |2y|^3 = 8|y|^3
he cubed the 2 and kept in inside
ye
@alpine sable Has your question been resolved?
@alpine sable Has your question been resolved?
@alpine sable what are those strange black spots over the y's at the end?
right...
and i presume that the L shape with a number inside it means factorial?
ok then y = e^x
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hi can someone help me with this question please thank you
how many days is 2 weeks
14 days
yup
so if 3 carpenters do one wardrobe in 14 days
how much does 1 carpenter do in 14 days
(assuming they work independently)
not quite
dividing by 3 is right though
but which number do you want to divide by 3
no 14 is the # of days that stays the same
what changes is how much wardrobe they make
so if 3 carpenters make 1 wardrobe in 14 days
how much does 1 carpenter make in 14 days?
0
how did you get 0
i have no idea actually, i don’t understand
lemme ask you a different question
3/1?
if three people can eat a cake in one day, how much can one person eat in a day?
1
no if the three of them together eat 1
then one of them can't eat 1
right?
how much of the cake can one of them eat
oh yeah 1/3
yup 1/3
so going back to the original question, if 3 carpenters make 1 wardrobe then how much does 1 carpenter make
1/3
yup
so then if 1 carpenter makes 1/3 wardrobe in 14 days
how much does 1 carpenter make in 1 day
is it 1/3 divided by 14?
okay 1/42
yup
so then if it's 1 carpenter does 1/42 wardrobe in 1 day
then how much do they do in 6 days
multiply by 6
which is 1/7
yup!
no prob! but that's not the final answer
oh
7
yep! that's the answer
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Hi people, could anyone tell me what the big line in the middle means?
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where does this come from?
are you asking how the identity holds?
trig functions mantra: when in doubt, draw a triangle
$n^2+n+1=\frac{n^3-1}{n-1}$
GoldenPhoenix
And?
I am not sure how that would go
arctan is the inverse of tan so it takes arguments from -inf to +inf
not what is its domain, what type of argument does it take? an angle measure, a fraction, an integer?
tan(theta)=opp/adj
gotta be careful to include the argument here
Deal
because we can rewrite this as theta=arctan(opp/adj)
do we have a fraction in the argument of arctan here?
yes
so do we know the opposite and adjacent sides for our triangle?
so the opp side is length 1 and the adj side is length n^2+n+1?
yes
but how do i draw the n^2+n+1 side ?
draw a triangle and label one side with that polynomial
and how does this help
well, it turns into a difference of two other arctans, right?
when? :/ i now just have a triangle
(I'll be honest I'm mostly spitballing here to stumble through it, but this is the basic process for how to demonstrate that a trig identity holds)
you have a triangle representing the left side, but we have a right side as well
Is anyone able to help me with my math problems
so our goal is to try and get from the triangle we have to get to the right side
okay but isnt the other side angle just arctan (n^2+n+1)?
can anyone help me please
it looks like you already have someone helping you in your channel
I would really appreciate it
go and help him @keen bear its fine ill try to walk through it again with what you told me
@empty plover Has your question been resolved?
any clue?
btw click the X if you're not finished so it doesnt autoclose
what x
its not really important its just bothering me that its put in my notes as an example with no justification for it whatsoever as if its obvious
nvm gtg eat, i dont understand
Deal
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#help
The number of real solution of x^2-2x+2+|x-1|=0 is ?
none
Any other way ?
But it can't be done without a graphing calculator
Any other way ?
Ikt but I want to do it with evaluation and all
Okay well use the quadratic equation to factor the first 3 terms of the equation and see if it gives you any real answer, and then see if there are real answers plug it into the absolute value function and see if it gives you a 0
Otherwise if the roots of the quadratic don’t work then there is no real solution
What
do you know the definition of absolute value
well you could do casework for x<1 and x>1
and solve both of those quadratics
to see if it gives you a solution
@fervent grail Has your question been resolved?
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How would I start with this?
multiplying both sides
MarveI
so its the first one
$(5\sqrt{3} - 2)\sqrt{2} \neq 5\sqrt{3} - 2\sqrt{2}$
MarveI
ive legit tried everything
$\sqrt{2}(5\sqrt{3} - 2)$
MarveI
do you know how to distribute the square root of 2?
ye
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i tried solving for x but it didnt make sense
nvm im dumvb
forgot to make it =0
.close
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ok?
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what is the difference between the line and vector
Ones a line, the others a vector
vector is the direction ?
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.close
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✅
Is this correct?
Yes that's correct
yes
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I want to get target's relative angle to my plane's heading vector
The compass is my heading angle and theta is its standardized value (I had to do some computations to transform game's output to standard mathematics)
x and y are my plane's coordinates and x2 and y2 are target's coordinates
Another important note is that the y axis is reversed in game's output so deltaY is actually -deltaY so in some of the calculations I used -deltaY to neutralize the reversed axis' effect
distance variable is calculated easily based on deltaX and deltaY
From now on please correct me if i'm wrong
Now let's assume I am at the center of coordinates (0, 0)
Let's calculate line equation of my plane's heading vector
It will be: y = tan(theta).x
So tan(theta).x - y = 0
Now based on the formula of distance between a dot and a line which is:
Ax + By + C = 0 => distance = (|A.x0 B.y0 + C|) / sqrt(X0^2 + Y0^2)
A = tan(theta); x0 = deltaX; B = -1; y0 = -deltaY; C = 0;
lineDistance variable is calculated:
(|tan(theta).deltaX + deltaY|) / distance
Now the thing is if I did all the calculations correctly, distance always would have been greater than line distance. But most of the times distance is less than lineDistance which is odd
By the way all the distances (x, y, x2, y2) are between -1 and +1
show your work?
What work? On paper?
if I did all the calculations correctly
Ah this
Ok
I mean most of the work is code
Here it is:
deltaX = x2 - x;
deltaY = y2 - y;
theta = -compass + 90;
nomalizedTheta = degreeNormalize(theta);
distance = sqrt(deltaX * deltaX + deltaY * deltaY);
lineDistance = (tan(radians(nomalizedTheta )) * deltaX + deltaY).abs() / distance; // .abs() is |-1| ==> +1
alpha = degrees(math.asin(lineDistance / distance));
Let me simplify it
I hope it's clear
I have some stuff written on paper but those aren't very clear 😅
Compass is my plane's heading angle
Hopefully it's fine to ping helpers now
<@&286206848099549185> 👋 😅
Cheers!

Oh well I can write it somewhere on paper or something
I just mean like
What’s the problem you want to solve
If it’s within code I cannot really read it
Have you checked this? 😄
Sorry I only know basic python :)
@tame willow
Making sure you haven't missed this message 😄
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@ember grotto Has your question been resolved?
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hey guys I am kinda noob at English
can anyone confirms that this one means the origin is at (0,5) ?
not the height of the pillar
The origin is always at (0,0)
hmm
That's what an origin is haha
lowest point of the cable intersecting the vertical axis
Lowest point of the cable is at (0,5)
It says "the resultant force W(x)"
The resultant force of what?
Eh, well they're getting into what shape the wire is, I suppose.
if I want to show sth to be first linear ode
how can I approach this qs
I got my dy/dx = W(t)/H
oh sike
gtg
someone pls give me some guidance if possible
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this unit is permutations and combinations
not sure how to begin solving this question
formula sheet
@wooden owl Has your question been resolved?
@wooden owl Has your question been resolved?
Is there any more context for the question? Or is that it? @wooden owl
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Hi, can someone help me with part ii?
@stable night Has your question been resolved?
algebra
oh random but happy birthday? LOL i saw it in ur status
@stable night Has your question been resolved?
@stable night Has your question been resolved?
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Question b iv
What does it mean by find the endurance limit?
‘When repeatedly subjected to force F’
And the ‘endurance limit is the force below which the steel will not break even if subjected to an infinite number of application of that force’
Meaning it can be hit by 70 Newton’s of force infinitely and not be affected at all
But if it’s hit by 71 Newton’s of force repeatedly
There will be some damage
It should be a constant value
So then how do I do this
@unborn meteor Has your question been resolved?
@unborn meteor Has your question been resolved?
It's not being "hit by"
It's being "stressed with"
You're trying to pull that metal bar apart by pulling on it many times
If your math is correct, then 70N of force, no matter how many times it is applied, will never break the bar.
Worth saying that 70N is very small
What did you do to get 70N?
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2^* X 5* = 8000
sorry the asterisk is supposed to be the variable x
$2^x \cdot 5^x=8000$?
ScapeProf
these are private help channels. if you want to have one of your own, read the channel instructions first
oh ok thanks
yea how do i solve this
actually the base number 2 is raised to the power of 2x not x
mb
Prime factor 8000
Why not use logarithm?
Its the same
this is supposed to be mainly indices only
what am i supposed to do
Can you use a calculator? Can you prime factor?
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hi so the question was what are the asymptotes
and give their function
SA is diagonal asymptote
but id understand that ''In x'' means
in minus inf and in positive inf
like dont both asymptotes exists in both + & - infinity
sure, the asymptotes themselves are straight lines that extend infinitely in both directions
but your graph only approaches the slanted asymptote as you go left
and only approaches the horizontal asymptote as you go right
so the In +inf and In -inf talks about the direction of the x-axis
alright thankyou
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I have this spectral curve plotted as a function of wavelength. However as you can see, it bottoms out at around 600nm. I would like to extend the characteristic of the slope so that it continues at the same rate it was declining before bottoming out (regardless if that decline is exponential). I want to essentially remove the bottoming out and instead extend it's decline down to 0. How would I go about this?
@sick venture Has your question been resolved?
Remove the points from 600 to 610 or whatever
And then just fit the points until 640 or whatever
Now you have a regression line you can continue
Is there a way to make the extension mathematically relevant to the change that was taking place from the point of when the slop started?
Wdym
Meaning factor in the trajectory of the slope. So that the values which extend it are relevant to the path it was taking
With the bottoming out values removed
I tried by finding the medium of relative change between each point. Then deducting that value from each previous point down to 0.
But I don't think it was very elegant. Visually it made the extension look like I all of a sudden just added a straight line past the point
Meaning, it didn't seem to follow the overall trajectory of the slope in a smooth way
example
that definitely AIN't it
I need a way to know the trajectory it is moving, so I can generate relevant values to continue the slope down to 0
This is tabulated data. In csv form. It's not just a graphic.
I'm working from the actual values
exactly my issue
How to generate values to continue the slope, when it's not linear
Not my goal, only the outcome of not knowing how to continue it's none linear slope
How
Any program
Let's say I took the range of values between 610nm to 650nm. How can I find out what the none linear change is. So that I can generate relevant values to extend the slope to 0.
?
y=a * b^x
If its perfect exponential its just picking two points and solve for a,b
Otherwise you need regression
If that is the case use any program to do that for you
I don't believe it's exponential. It seems to hit a straight line portion after the toe
After what?
I'm really don't know jack about math HAHA. What's a regression
,w linear regression
Is an example (linear regression)
toe
You have points which aren’t perfectly linear so you make a least squared fit for it
What's a least squared fit?
Google is a thing and I don’t see how its relevant to what you are asking
sorry not toe I meant shoulder
I'm just following that you said I need to make a least squared fit. Again I need help with the math. I don't understand any of these concepts
And like I said any program can do it
Okay, how do I do it in google sheets
If I wanted help through google I wouldn't have asked here
I thought you'd actually give me the answer. I don't study math. I'm just trying to solve a problem
And I don’t want to google how to do it for you
Don't get me wrong I appreciate the source of concepts. But can we just cut to the chase
Save me the hassle of trying to understand it for like 2 hours
There is nothing to understand
What's the difference?
You just need to click whatever buttons
Your program needs
Which google tells you
How is this math
So your response to me not understanding the concepts is that I should use google or figure out how my program can do the math. I'm trying to understand the math so I can apply it. If you understand how to solve this problem why are you redirecting me to figure the rest out
Okay great, this is math help. Teach me
So I said go google how to do it in your fav program
You refused and wanted me to google it for you
For me to type what google said?
So the program was written by AI, the math that the program operates on is not mathematically producible by humans?
What?
You're saying the math to solve this problem is not doable by hand
Who wrote the script
I’m saying the calculations aren’t feasible to do by hand
So AI discovered this mathematical concept, and the only way to execute it, is to use the program the AI wrote. Or maybe just maybe, people who understood the math wrote the program. To complete the task. Of which they understand the math and can reproduce it. Because how else would they write the program.
I have a calculator
Why do I need a program
And your program is just a calculator
So google sheets is nothing but a calculator
All I said was google and figure out how your fav program calculates line of best thing for you
Yes?
Like what
I don’t understand why you are getting mad
That's different to using a calculator. That's finding an operation. Preset calculations. Of which was written by a human. Let's skip the part where I hope and pray I can find this very specific operation available in google sheets. And just tell me the formula. Is it really that difficult?
tell me the secret formula crabs
$$\hat\alpha=\bar{y}-(\hat\beta \bar{x})$$ and $$\hat\beta=\frac{\sum_{i=1}^n (x_i-\bar{x})(y_i-\bar{y})}{\sum_{i=1}^n (x_i-\bar{x})^2}$$
Thank you. Can you define the variables please
y_i=alpha+beta x_i+eps_i
ScapeProf
?
?
I did
I only symbols I understand in there is sum
Seems like just using your fav program is faster doesn’t it?
y=alpha+beta x is linear relation
Not if you want to understand what you're doing
I'm surprised how many absolute symbols there is in math
I was under the impression, most were just definable variables per equation. Like programming
Thanks for your help
So for this specific curve, it would require a linear regression right?
Not a nonlinear regression?
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so for this question
This is not a sequence
$\frac{n^n}{n!} \geq \frac{n^n}{(n+1)!}$
Kekistan
series*
Wdym by a decreasing series
next term less than the first
Hmm well that's not true here
Kekistan
Each term alternates between being positive and negative
It keeps going above and below 0
Because of (-1)^(n+1)
So it's neither increasing nor decreasing
Kekistan
Well the numerator grows a lot quicker than the denominator
So the sequence tends to infinity
So it can't be decreasing


It might be a good idea to plot the sequence on desmos btw, if you want to see how it behaves
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find all the zeroes of the polynomial $f(x)=2x^4-9x^3+5x^2+3x-1$, given $\alpha=2+\sqrt{3}$, $\beta=2-\sqrt{3}$
ThickduckPlayz
i feel like i need to divide $f(x)$ by $x-\alpha$
ThickduckPlayz
there's a nicer way to approach it
as alpha and beta are conjugates,
it would be less tedious to expand (x-a)(x-b) before doing division
alternatively since you're given 2/4 of the roots, it would also be relatively simple to consider sum and product of roots
ThickduckPlayz
should i divide it with the polynomial?
if you're using this approach yeh
also one doubt.
why does it make sense to divide this with the polynomial?
my teacher said it is common sense to divide the factors with the polynomial because the remainder is zero
but it doesn't make any sense to me, what am i going to do with the quotient and how is it related to the other zeroes?
are you familiar with factor theorem
yeah
if a is an zero of f(x), (x-a) is a factor of f(x)
also when i divide, i get remainder to be 32x-8
consider the factored form of a quartic polynomial (can be applied to pretty much any degree)
k(x-a)(x-b)(x-c)(x-d)
ok
if you know that (x-a) is a factor,
dividing by (x-a) gives leaves you with a polynomial 1 degree lower: which makes it easier to find the remaining zeroes/roots
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Hey I was given both of these and told I am supposed to search for the area Integral of those shown
but Im a bit confused... what exactly am I supposed to do?
I mean I'm guessing I have f_1(x,y)=x and f_2(x,y)=y²+3L²
And then integrate them over the area shown in the diagramm
but how exactly do I tackle the circle?
@grave lance Has your question been resolved?
What does a represent
@grave lance Has your question been resolved?
it's a double integral
What do you mean exactly intersect?
They way I understood is, is that I need 2 curves or lines or whatever shape to build the boundaries of one of the Integrals but I am looking at a linear function and a circle
I mean doing the double integral of the linear line would be easy
but the circle kind of gives me big???
Just split the region up into three regions.
For the circular region at the top, it's a circle of radius L centered at (2L,2L).
Thus (x - 2L)^2 + (y - 2L)^2 = L^2.
so one with boundaries for the dy Integral with 0 -> 2x
one with with the boundaries from 1L < x < 3L
And one with the circle as the boundaries?
But for me I'm still a bit confused how to incorporate the circle
0 to 2x?
I'd probably solve (x - 2L)^2 + (y - 2L)^2 = L^2 for y and use the fact that the third region will be one with the positive square root. Then we clearly have L <= L <= 3L.
well isnt the Integral for the straight with a gradient of 2 for the dy Integral 0 to 2x?
because it's not just a straight line
so it's 0 <= y <= 2x
You're looking at the subregion labelled 1?
yea
Yes.
because it's just a square region
so it's a bit easier for the circle can't I do a coordinate transform?
let x~ = x + 2L
and the same for y to put those at the center of the circle
You could but I wouldn't if you're keeping it in cartesian anyway.
Well for setting it up anyway. For evaluating then it makes sense.
I'd imagine both are fine when I think of it.
I'm still looking at the circle and idk how to incorporate it into the integral
View it like this.
Since we have a circle of radius L centered on (2L, 2L) then we know it's equation is
(x - 2L)^2 + (y - 2L)^2 = L^2.
yea
Solve it for y.
We obtain that (y - 2L)^2 = L^2 - (x - 2L)^2. And the desired curve is
y = 2L + sqrt(L^2 - (x - 2L)^2)
R3: L <= x <= 3L, 2L <= y <= 2L + sqrt(L^2 - (x - 2L)^2)
ok yea sure that makes sense
Just write your integral as the sum of the three double integrals over the three regions and you should be done.
yea I understood that part aswell
but I'm already looking at the integration of a sqrt boy is this gonna be fun again
Have you used polar coordinates before?
If so could be worth using x = 2L + r cos(theta), y = 2: + r sin(theta). dA = r dr dtheta still.
Or just use a integral calculator.
hm yeah this isnt just for fun in my freetime
so I gotta actually learn how to do these Integrals by hand for the test
which is gonna be annoying
Well you have to integrate with respect to y first anyway so you end up with a y^4 so it might not be too bad.
well if I first just do the f(x,y)=x
Oh right.
Well in that case.
Instead of isolating for y. Insolate for x instead.
if I get rid of the first integral for the circle I'm left with the Integral of L -> 3L of x*sqrt(x²+4Lx-3L²)
R3: 2L <= y <= 3L, 2L - sqrt(L^2 - (y - 2L)^2) <= x <= 2L + sqrt(L^2 - (y - 2L)^2)
y twice?
In the x direction you are bounding by two curves. In contrast the the other where you was bounded below by the flat line y = 2L up to the curve.
but wouldnt those boundaries up there that you wrote be true for the entire circle area
not just half of it
It is but the y bound ensures we have only the top part we require.
2L <= y <= 3L.
oh right yea
I mean if in the integration I dont have to integrate a sqrt term
and just simplify it
that would already help a lot
bcs I'm pretty sure we cant even solve quadratic terms under a sqrt
I can solve something with a²-x² under a sqrt
That's what I thought since if we integrate x we get a x^2 term to simplify things.
I got the integrand to be 4Lsqrt(L^2 - (y- 2L)^2) between y = 2L and y = 3L.
lemme slap it into an integral calculator
$\iint_{R_3} x \dd{A} = 4L\int_{y = 2L}^{3L} \sqrt{L^2 - (y - 2L^2)} \dd{y}$.
stabulo
Hm but you still have to do the ax²+bx+c term under the sqrt
which I am unable to solve
unless you can rewrite it but I cant see how
I think the integral is simply the area of a particular circle.
is there not a way to somehow define the boundaries in a way that you get the sqrt term wheen you have to integrate by a variable that isnt inside the sqrt
I mean to me all roads kind of point towards a polar double integral
which I think simplifies the integral for the circle
I think there's a simple way to get the answer. One second.
The integral is the area of the quarter circle of radius L.
Therefore the integral is 4L( 1/4 pi L^2) = pi L^3.
$4L\int_{y = 2L}^{3L} \sqrt{L^2 - (y - 2L^2)} \dd{y} = 4L \left(\frac{\pi L^2}{4} \right) = \pi L^3$.
stabulo
ok yea makes sense
but that's like just looking at the circle and knowing what the area function is and then multiplying that by the distance towards the plane
but what about when you have the term y² + 3L²
Maybe there's a similar trick. I've not looked.
yea bcs then it's not just a cylinder but one with one side being the 2d plane of the function f(x,y)
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So I am solving a non linear equation of motion problem, I am told to first use the first two terms of the taylor series to change the equation of motion to one which has cubic nonlinearity, what does this mean? The equation of motion should have ^3?
@unreal crow Has your question been resolved?
@unreal crow Has your question been resolved?
yes
Show the full original question
Hopefully you can see that.
Nah just screenshot and upload
Okay here you go.
@unreal crow Has your question been resolved?
Oh hell naw Riemann without the green role
@unreal crow Has your question been resolved?
it means to put $\sin(\theta) \approx \theta - \theta^3 / 3!$
riemann
Am I the only one who thinks that this is phrased ambiguously
yea it is. that's why i asked for the full question. but got ignored, so /shrug
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could i get some help on starting out on this problem?
First draw or look at the graph of that function
where did the 3 come from?
ohh i see
okay
so its basically telling me to only go from
-2 -1 0 1
on the x axis?
for finding the area?
Uhhhhh wha
I’m just saying you need to put 6 rectangle with the rivht most ending at 1,3 and then fit them evenly spaced within thay region
I hate Riemann sums and suck at them so @tacit arch can you give help
yeah i'm kind of confused 😭
just pretend they're called caden sums
LOL

like i get the drawing the rectangle part
is this part basically telling me my limits for my x axis for where i find my area?
Riemann you got this 👍🏻
make a table
that's the hardest part. the rest is multiplying length times width repeatedly to get areas of rectangles and adding them up
.
you only gave 3 subintervals
[-2, -1], [-1, 0], and [0, 1]
can you find a way to divide [-2, 1] into six sub-intervals, preferably each of equal length?
hmm
i could divide 4 by 6?
it's basically telling me to find 6 points of those limits?
meaning theyre going to be some sort of fraction if im understanding it correctly
hint: length of [-2, 1] is 1 - (-2) = 3
looks right
(1 - (-2))/6 = 3/6 = 1/2
which answer is 1/2
so my graph should have
-2, -3/2, -1, -1/2, 0, 1/2, 1?
your table should use 6 of these points. which 6 depends on if you're using the left or right endpoints
right end points
so it would be 6 starting from the right?
which basically excludes the -2?
yup

i think you misunderstood what the x is in x*y
a rectangle's area is given by length * width. find out what the width is. if you're stuck, i recommend watching this video.
,w integral -2 to 1 of x^2 + 2
,calc 59/8
Result:
7.375
hm
,calc ((-3/2)^2 + (-1)^2 + (-1/2)^2 + 0^2 + (1/2)^2 + 1^2 + 6*2) * 1/2
Result:
8.375
Result:
67
oh...
i see what i did wrong
i was doing x^(2)+1
in my calculator 😄
instead of x^(2)+2
ha
i got this as my answer
okay maybe i lied. the hardest part is getting the right function in your calculator

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<@&286206848099549185> is 10/31, 10/32, 10/33 answers for the question
"List 3 Intergers between 1/2 and 1/3"
thank you for helping 🙂
!15m
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You complete fuck
LMAO
You absolute fuck WHY CAN NO ONE READ
feel caden's wrath
sorry lol
are we not gonna talk about the question though
There are no integers between that they are fractions
3 integers between 1/3 and 1/2 LMFAO

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I don’t
thanks

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good resources to learn these two units?
is this for the probability exam?
wait its probably not
I got excited for a bit
do you want a book reccomendation or a website reccomendation
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Am I understanding phase shift correctly?
You have to put the periodic function in the form of Asin(B(x-C))+D
And that yields the horizontal movement of the graph (which is C)
Basically, for all f(x+a) where a is a positive real no., the graph is shifted a units to the left. Hope this helps
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video or website
yes
whats that?
its expensive but it helped me pass it first try
its software to help study for the exam
best bet is probably youtube then
i cant find videos on youtube
uhhh
idrk then these concepts are pretty niche
how have you studied for the exam thus far
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youtube
but these topics are so specific I cant find any videos
how long have you been studying for the exam
I'm not sure where you could find any videos
maybe in a manual somewhere but
you might have to pay
rip
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Hi, can I have help with b & c?
pa means per annum here?
yes
you can do this by just brute force
there's probably a formula that makes it faster but I can't think of it off the top of my head
for b, I know how to solve it, but wondering why the arithmetic series is
( 40000 * (1.04^n - 1) ) / (1.04 - 1)
and not
( 40000 * 1.04 * (1.04^n - 1) ) / (1.04 - 1)
ah right arithmetic series
so the increase happens
the 2nd year right
so your initial term is 40,000
not 40,000 x 1.04
oh right ok yep that makes sense
and for c, the equation would be arithmetic series for eleanor = geometric series for henry, but not sure how to solve it
( 40000 * (1.04^n - 1) ) / (1.04 - 1) = (10/2) * ( 2 * 40000 + 2000(n-1) )
you may have to use natural logs
to pull the n down from being an exponent
or again you could brute force it but that's not the most efficent way to solvve
the answer suggests "the start of the 13th year", but for some reason I'm getting n = 9 instead, by trying to simplify and brute force that equation
is the equation set up correctly?
oh wait that 10 should be an n
which apparenlty gives
oh wait that's over the integers
i think i'm just answering my own question here, i'll work on it more :)
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I wanted to know what's factor theorem and remainder theorem
those are easily searchable
read up and come back if there are any parts you don't understand
@alpine sable Has your question been resolved?
Mhm, i wished to be explained here ... I tried on yt before but still didn't got it
what were you watching and which parts don't you understand
we're more or less going to be saying the same thing
be more specific and we may be able to clarify certain parts for you
I just want it to be explained about it slowly.. and like in simple words... I don't have anything to specify.. wanna know from start
when a polynomial P(x) is divided by (x-a),
P(a) will give the remainder (which is the remainder theorem)
if a is a root/zero, (x-a) will be a factor. and the remainder when dividing by P(x) by (x-a) will be 0 (which is the factor theorem which is a special case of the remainder theorem)
To write it all out, the key is that you can perform euclidean division on polynomials. Hence, you can write P = (X-a)*Q + R, for R of degree 0 (strictly less than 1, the degree of X-a) i.e a constant. If you evaluate this at a, you get R + (a-a)Q = P(a), i.e R = P(a).
So P = (X-a)*Q + P(a)
@alpine sable
In very simple Words
Factor theorem is used for taking out the factor like How you factorise and it's just factor theorem and reminder Theorem are same but has a little bit of difference
And the Reminder theorem
Is just a replacement for long division method is used when you just want to calculate the reminder
Thanks a lot for your help! I'll try solving sums based on this and will ask any more doubts if i have
@vague mirage @vale sapphire @gray isle
Wlcm
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the leibnitz kriteria doesnt say that it converges absolut right ?
the one for alternating series ?
if so then no
because (-1)^n / n converges as an alternating series, but doesn't converge absolutely
why should it ?
the alternating convergence test works because the series is alternating
because you go back and forth, it suffices that each step is smaller than the last for your back and forth to converge
if you always went in the same direction, you'd need your steps to get smaller and smaller at a sufficient pace
a series converges absolut when you put it in absolut
so |-1^n|/n = |-1|^n / n = 1 / n
ah an
Sum of 1/n is an harmonic series
which does not converge
bc there is a sentence
a series converges if the sequence is a zero sequence.... but I see its not that way around
I'm not sure on how to write an answer here
ive a potenz series
and calculated the convergenzradius
is the potenz series absolut converget in (1/2 ; 3/2) AND !!! convergent in the edge point x = 1 / 2
and divergent for x < 1/2 AND!!! x >= 3/2 ?
i think this would be correct answer
are you german
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does this have an expansion?
this is just a geometric series
Lol
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