#help-0

1 messages · Page 1037 of 1

carmine bronze
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I can't do it

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Confused

river fossil
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start by writing down the limit definition of the derivative

carmine bronze
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And how do I do this??

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Ok

river fossil
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bot broken?

carmine bronze
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and half the internet

river fossil
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damn

carmine bronze
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can't connect to discord from US

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anyways yes I wrote down the definition

river fossil
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can you make any simplifications?

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also send a picture

carmine bronze
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ok let me do in paint

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but they told me to use the power rule and differentiation

river fossil
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oh, so no need for the limit definition?

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because the power rule is a lot faster

carmine bronze
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I tried to find stuff for polynomial derivatives and couldn't find one that helped me out

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well whatever works at this point

river fossil
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the question asks for the limit definition so i guess we'll continue that

carmine bronze
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and I believe this is wrong

river fossil
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apply the rule for every term

carmine bronze
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doesn't it need exponent to work?

river fossil
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x is x¹

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and 2 is technically 2x⁰

carmine bronze
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and for 2 I don't do

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ah

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ok

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brain dead moment

river fossil
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and for the second question, just apply the power rule once again

carmine bronze
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?

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like this?

river fossil
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yess

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nice

river fossil
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yup

carmine bronze
river fossil
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correct!

carmine bronze
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cool thank you!

river fossil
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there we go, wasn't so bad

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though, are you sure doing it without the limit definition is fine?

carmine bronze
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riemann told me to watch a bunch of basic differentiation rules stuff on khan academy

river fossil
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i'd recommend the same

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khan is cool

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that's where i first learned calc

carmine bronze
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I know but I don't think he explained this

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maybe I skipped it

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he didn't do any polynomial lessons that I saw

river fossil
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the power rule, im sure he covered it

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maybe he didn't apply it to polynomials

carmine bronze
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I'm sure he did too just not on polynomials. At least none that I could find

river fossil
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could be the case

carmine bronze
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I'm stuck on quite a few others too

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heyy the bot is back

river fossil
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nice

carmine bronze
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I have 2 channels now

river fossil
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stick to this one

carmine bronze
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ok let's start one at a time

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ok this one was a bit weird let me draw it out

river fossil
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do you need to show your work?

carmine bronze
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Not for this assignment but I do go through all the steps on paper

river fossil
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ah alright

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do you wanna try to do this one with the limit definition?

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or use the shortcut that is the power rule?

carmine bronze
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oh I can use the power rule for this?

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so I don't have to do this?

river fossil
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well you don't have to, but it's the method you were told to use

carmine bronze
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but it takes much more work doesn't it?

river fossil
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it does

carmine bronze
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But I guess if it says using the limit definition then it works

river fossil
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ok let's do it

river fossil
carmine bronze
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uh

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many numbers and letters

river fossil
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yeah, try to not get lost

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the numerator is
(a - b)(a + b) = a² - b²

carmine bronze
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ohh that helps

river fossil
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there's an h missing in the denominator

carmine bronze
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there's only 1 h

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in x+h

river fossil
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$\frac{16h}{h(4\sqrt{x+h-4}+4\sqrt{x-4})}$

carmine bronze
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see no h

ocean sealBOT
carmine bronze
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mm

river fossil
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right?

carmine bronze
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uhh

river fossil
carmine bronze
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ohhhhhhhhhhhhhhhh

river fossil
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yeahhh

carmine bronze
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ahhhh

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the h

river fossil
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you can cancel them now to get

carmine bronze
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gotchu

river fossil
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$\frac{16}{(4\sqrt{x+h-4}+4\sqrt{x-4})}$

ocean sealBOT
river fossil
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nice

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further simplify now

carmine bronze
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should I learn how to type texit

river fossil
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can be useful if you plan on writing math often

river fossil
carmine bronze
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I also saw 4 I could get rid of

river fossil
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there's a litte more simplification you can do

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if you combine the √x-4 together

carmine bronze
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impossible

river fossil
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2√x-4 😳

river fossil
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do it!

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after this i'll show you the power rule method

carmine bronze
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is it possible to simplify it to 2/sqr(x-4) ?

river fossil
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yup

carmine bronze
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looking nice

river fossil
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tadaa!

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there's your answer

carmine bronze
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alright shortcut method time

river fossil
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here we go

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$4\sqrt{x-4} = 4(x-4)^{1/2}$

ocean sealBOT
river fossil
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now applying the power rule

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$1/2\times4(x-4)^{1/2-1}$

ocean sealBOT
river fossil
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$=\frac{2}{(x-4)^{1/2}}$

ocean sealBOT
river fossil
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$=\frac{2}{\sqrt{x-4}}$

ocean sealBOT
river fossil
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though i advise you not to use this rule until your teacher teaches this

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since chain rule can mess things up

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stick to the limit definition for now

carmine bronze
balmy warren
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you multiply by the power

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then take 1 from the power

river fossil
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$\frac{d}{dx} x^a = ax^{a-1}$

ocean sealBOT
river fossil
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so you drop ½ from the exponent

carmine bronze
river fossil
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½ × 4

carmine bronze
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ok so you simplify from here

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-1/2 is exponent

river fossil
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yes

carmine bronze
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did you get rid of the 2?

river fossil
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which two

carmine bronze
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like this?

river fossil
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yeah like that

carmine bronze
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then wouldn't it be

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oh

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the exponent doesn't cover the 2

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maybe that's why

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ah ok makes more sense

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I think the prof is making us do limit definition though so I will stick to that just to be safe

river fossil
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yep

carmine bronze
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are US servers online now?

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the bot is online

river fossil
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not sure

carmine bronze
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Which country are you in?

river fossil
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im Indonesian

carmine bronze
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Cool

river fossil
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i think we're done, time to close the channel?

carmine bronze
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yeah I was just working on a few problems to see if I was gonna get stuck again

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Is it ok if I friend you? You seem like a cool person and you helped me a lot today.

river fossil
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im sorry but i only friend irl friends

carmine bronze
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alright np

river fossil
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i gotta go now, good luck on your problems, see ya

carmine bronze
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see you on the server sometime

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.close

lone heartBOT
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steep ether
lone heartBOT
steep ether
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is this correct?

vale wigeon
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the problem appears to be understated
having a website consist of only three pages (sign-in, sign-up, home, and nothing else) feels weird
it appears you were only expected to say "the vertices are the pages while the edges are links"

steep ether
vale wigeon
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sure it works

steep ether
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there is another example as well for the facebook friends

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im not sure if its right cause there is a thing called mutual friends does it counts as friends?

vale wigeon
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a "mutual friend of A and B" is just a person who is friends with A and with B at the same time

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also i think if you're going to make concrete examples for this (which, again, i don't think is what's expected of you, but you're the one to judge)
then surely the friendship graph should be undirected

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not directed with each arrow going both ways as you drew

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i think you are only expected to say which objects serve as vertices and which as edges

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nothing else

steep ether
vale wigeon
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...

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yes but i think you missed my point entirely...

steep ether
vale wigeon
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yes

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and by this i mean that you are NOT supposed to give explicit examples like that

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but only say things like "vertices: people, edges: friendships between people"

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things to that effect

steep ether
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makes sense now

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thank you so much, is there any pointing system to give points to the helpers?

vale wigeon
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no

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i don't even have the helper role anyway

steep ether
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anyways thank you so much for the time and the effort

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.close

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untold sparrow
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How can this type of sum be solved?

lone heartBOT
gray ingot
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2^n

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look at the pascal's triangle, the sum of each row is 2^row

mortal trellis
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alternatively from the binomial theorem, using the expansion of (1+1)^n

untold sparrow
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I know how to calculate a sum but this is a sum of combination. As far as I read, this type of sum can be solved using the Leibniz Rule.

mortal trellis
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I only know a leibniz rule about differentiation. I guess you can use that here somehow but seems pretty convoluted. to what rule are you referring?

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you can also solve it using induction. although that is essentially the proof using pascals triangle because for that you also proof that the row sum is 2^n using induction

tawny schooner
untold sparrow
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Leibniz rule generalizes the product rule of differentiation. The Leibniz rule states that if two functions f(x) and g(x) are differentiable n times individually, then their product f(x).g(x) is also differentiable n times.

mortal trellis
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yeah no forget about that

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check out the binomial theorem

untold sparrow
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ok

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thanks

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.close

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grizzled vortex
#

Hi all, I'm reviewing for final and I saw that the instructor asked us to use Parseval's identity to compute the sum of an infinite series, but he did so by computing the generalized Fourier expansion and then just plugged some number in(like this⬇️). I wonder. how is this equivalent to using Parseval's theorem or am I misunderstanding something?

grizzled vortex
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he just plugged in a number

lone heartBOT
#

@grizzled vortex Has your question been resolved?

lone heartBOT
#

@grizzled vortex Has your question been resolved?

novel night
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Been a while since I had to do anything rigorous with Fourier anything, but I agree this doesn't seem related to Parseval's theorem. The part about plugging in pi/2 is, I think, based on some version of the Fourier inversion theorem -- that f(x) is equal, point-wise, to the sum of its Fourier series.

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#

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scarlet oriole
#

I am stuck at this problem. I've solved up until one point but I don't know how to end it tho

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@scarlet oriole Has your question been resolved?

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@scarlet oriole Has your question been resolved?

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hollow coyote
#

After staring at this proof for a solid amount of time, all I can prove is that triangles PRQ and SRT are similar, along with that the corresponding angles are congruent. What would be the next step?

indigo lotus
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and since these angles also show a pair of alternate interior angles, the lines PQ and TS will be parallel

hollow coyote
#

OHHHHH

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I’m an idiot

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ty

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.close

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graceful mountain
#

This is the problem I am trying to solve.

graceful mountain
#

The solution tells me that the integral is a projection of the surface onto the xy plane. How?

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Why does the integral give the area of the projection of the surface?

tacit arch
#

Did you try using Stokes theorem

graceful mountain
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Yes

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I want to understand why the integral is the area of the projection of the surface on the xy plane

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I know how to calculate with the perimeter.

tacit arch
#

Do you know what $\hat{x} \cdot da$ is?

ocean sealBOT
#

riemann

graceful mountain
#

Not conceptually

tacit arch
#

What do you know about it

lone heartBOT
#

@graceful mountain Has your question been resolved?

lone heartBOT
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wheat lagoon
#

I don’t know how to approach his question

wheat lagoon
vale wigeon
#

check your notes and/or google and/or your textbook for how to find the mean, median and mode of a dataset

wheat lagoon
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I don’t have them it’s the last day

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We handed in our textbooks and my notebook is at my house

vale wigeon
#

then google?

wheat lagoon
#

Oh then what’s the point of this server?

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I was looking for guidance and help so I can understand in the future

vale wigeon
#

there isn't much guidance to be given on a problem that is almost exclusively about computation

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to find the mean, find the total amount of money made from sales (taking into account the amount of each burger sold, so it's not just 4.00+6.95+7.00 and so on) and divide by the total number of burgers sold

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to find the median, find how many burgers were sold in total and then find which burger type you stop at when you take all the burgers starting from the cheapest until you have exactly half of all burgers sold

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to find the mode, find which type of burger has the most sales

wheat lagoon
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Ah ok

vale wigeon
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all of these are things which are easy to find by googling them yourself, and imo knowing how to use search engines is a very vital skill to have in this day and age

wheat lagoon
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I should be fine I got a good start

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Ik how lol

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It’s easier when things are explain in different ways to m

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Me

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Not everyone learns the same.

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.close

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alpine sable
#

given $n = \sum_{i=1}^k n_i$ where each $n_i$ represents the number of repetitions of elements of type $i$ then the total number of permutations is equal to $\frac{n!}{\prod_{i=1}^{k} n_i!}$

alpine sable
#

how would u write this better?

ocean sealBOT
#

mahmooz

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

uh doesnt matter

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could refer to the number i

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so n_i refers to the number of repetitions of i

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this is a lemma for multisets

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not sets

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where elements can be repeated

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so say {boy, boy, boy, girl, boy, girl}

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i=1 refers to girl

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i=2 refers to boy

lone heartBOT
#

@alpine sable Has your question been resolved?

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alpine sable
#
Variation with Repetition
A combination is a way of selecting k items from a collection of n items, such that (like permutations) the order of selection does matter. The repetition of items is allowed.
#

what does a combination have to do with variation?

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don't send links

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send screenshots

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nice ip grabber

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uh ok i linked the paragraph anyway, plus i doubt mathreference.org isnt a known website..

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fathom hearth
#

'no square leaves a remainder 2 upon division by 4'

fathom hearth
#

how do i prove this?

alpine sable
#

There's a pattern for the even and odd squares

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Even squares always leave no remaider upon division by 4

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And odd squares always leave a remainder 1

fathom hearth
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ah yeah i am silly

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that makes sense ty

alpine sable
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Anytime

fathom hearth
#

i am looking at this question

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given an integer N, determine if there exists two integers a,b such that a^2-b^2=N

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why is true that if N leaves no remainder 2 upon division by 4 then there does exist two integers a,b

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#

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@fathom hearth Has your question been resolved?

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shadow steeple
lone heartBOT
shadow steeple
#

HELPPELASE

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PLEASE

karmic rapids
shadow steeple
dawn birch
#

set x = 6 and y = 1 in the equation 2x + 3y + b = 0 @shadow steeple

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what do u get

shadow steeple
dawn birch
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b = -15 yes

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so then 2x + 3y + b = 0 becomes 2x + 3y - 15 = 0

shadow steeple
#

.close

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#
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patent swallow
#

the chart of
3/x is the same as the chart of 2/x or even 1/x right?

patent swallow
#

cause the X and Y asymptotes are 0 always

rose sigil
#

hey what does chart mean here?

carmine harbor
#

Both graphs will have the same x and y asymptotes but that doesn’t necessarily mean they are the same graphs

lone heartBOT
#

@patent swallow Has your question been resolved?

patent swallow
patent swallow
#

right?

carmine harbor
abstract fractal
#

I guess they do look similar, though "similar" in this sense doesn't have a rigorous definition and is just based on your own perception

carmine harbor
#

They do however approach the same values and look very similar the further you go along both the x and y axis but they do not intersect

lone heartBOT
#

@patent swallow Has your question been resolved?

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crystal narwhal
#

how do i do this question?

lone heartBOT
crystal narwhal
#

I did two different methods to get a>-9

#

then i did it a different way to get a < -9

#

which is the right anwser

#

i did a derivative to find minimum at x = -3

#

i substituted it back in to get - 9 - a > 0

#

which gave me a < -9

#

but why were my first two methods wrong?

#

the first two were about finding all values of a which yield a positive discriminant

lime bobcat
#

Positive discrimant means the polynomial has two real roots

#

You want to see when the polynomial is positive

#

They're two different questions

lone heartBOT
#

@crystal narwhal Has your question been resolved?

lime bobcat
#

If you solve $x^2+6x-a=0$ you get $x=-\sqrt{a+9}-3$ or $x=\sqrt{a+9}-3$.

ocean sealBOT
#

Categorist

lime bobcat
#

So we have the following factorization:

$x^2+6x-a=(x+\sqrt{a+9}+3)(x-\sqrt{a+9}+3)$

ocean sealBOT
#

Categorist

crystal narwhal
#

this was one of the ways to find the solution on the mark scheme

#

but they made the inequality so that the discriminant is negative being less than 0

crystal narwhal
#

they also used this methods but it makes no sense to me

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deep mantle
#

hey, how do you express the amount of x in a volume at time t, when the rate of change in and out are both proportional to itself?

deep mantle
#

It's supposed to be a modeling question for first order differential equations

#

if what i said doesn't make sense I can elaborate further

lime bobcat
#

Can you please elaborate further?

#

In and out? Is it a volume inside another volume?

deep mantle
#

it's oxygen in a space

#

basically trying to model how oxygen changes over time in a confined space with a single person in it

#

oxygen initially should be ~21% of the volume

#

the way I thought I'd express it was rate in would be the amount exhaled per hour and rate out would be the rate inhaled

#

i could be totally off about that tho

lime bobcat
#

Oh, interesant

marsh rapids
#

You should indeed be able to setup a differential equation with this. I'd expect an exponential decay towards 0 as the solution

deep mantle
#

yes that's what I expect as well

#

however setting it up is what is messing me up

marsh rapids
#

Is there any info given or is this a problem you came up with ?

deep mantle
#

It's my own question but i have more info i can share

#

the average person takes 960 breaths per hour

#

iirc the volume per breath is 380 ml

marsh rapids
#

I'd say you need something like: volume inhaled/exhaled per minute, percentage of oxygen inhaled that is actually consumed, volume of the room

lime bobcat
#

I think one can sum up inhale and exhale so the change of amount of oxigen only depends on the difference

#

And that is proportional bc proportional - proportional = proportional

marsh rapids
#

That's pretty much my "actual amount of O2 consumed" factor

lime bobcat
#

x'(t)=-k maybe LOL (k positive)

deep mantle
#

btw, the typical amount of oxygen that is exhaled is at around 15%

marsh rapids
#

So 1/4 of the O2 inhaled is consumed

lime bobcat
deep mantle
marsh rapids
#

So O2/min = volume/minute * O2/volume * consumption rate

#

That should give you your differential equation

#

For the simplest reasonable model

deep mantle
marsh rapids
#

That's 2 constants and 1 variable that you care about

#

Try to visualize the process to see what factors come into play

deep mantle
#

volume is and consumption rate are both constants in this case

#

per min so min=1 i assume

#

sorry

#

no

#

min is the variable

marsh rapids
marsh rapids
deep mantle
#

yeah regardless, thanks that's a lot clearer!

marsh rapids
deep mantle
#

I see what was messing me up

deep mantle
marsh rapids
#

I don't intend on staying online for much longer though, so you can always try, but otherwise I'll have a bit of time in some 6 hours and then some 6 hours more

deep mantle
#

I see thanks

lone heartBOT
#

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edgy flare
#

I need help with trying to find an algebraic expression.

edgy flare
#

My professor said this:

#

And I did this: but I am supposed to find values for u_0, v_0, and r

#

This is a COMPLEX VARIABLES COURSE.

#

<@&286206848099549185>

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@edgy flare Has your question been resolved?

edgy flare
#

<@&286206848099549185>

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@edgy flare Has your question been resolved?

lone heartBOT
#

@edgy flare Has your question been resolved?

edgy flare
#

Any help?

#

<@&286206848099549185>

edgy flare
#

Maybe tomorrow.

#

.close

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quick flower
#

can someone please help me pass geometry

quick flower
#

it makes no sense

narrow moat
#

Geometry is the study of a shapes or sumfink.

#

.close

golden moss
#

.close

quick flower
median oar
#

ok

#

so can you put the statement given in math terms?

#

like if it said "x is 2 times y" you would write x = 2y

oblique pier
quick flower
#

yes please

oblique pier
oblique pier
median oar
#

no but im talking about getting a math style thinking for problem solving

oblique pier
#

and we need to know m1 and m2

quick flower
#

ok

median oar
#

it's very helpful to write down the givens with math

#

so you can do operations on them

oblique pier
median oar
#

you cant do operations on english sentences

oblique pier
#

since we need to find m2

quick flower
#

k

oblique pier
#

as we you know m1 is two time m2 what does m1 equal to

#

in term of x

median oar
#

what does "m1 is two times m2" mean in math

lone heartBOT
#

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warm mason
#

Question 9. Question 9 asks in what quadrant of the argand diagram do you find z^5 if z=cos.... Motivate your answer.

tacit arch
warm mason
#

It's 0 i don't know where to start i didn't study this for a while

tacit arch
#

Use De Moivre's theorem

warm mason
#

Okay 1 min

#

I'm just relearning it sry for taking a while

#

Is this the right start?

warm mason
#

Why?

tacit arch
#

You still haven't used demoivre's theorem

tacit arch
warm mason
#

Why is r equals to 1?

tacit arch
#

Yea you got it

warm mason
#

Okay

tacit arch
#

Your 1 looked like an r to me

warm mason
#

Haha

#

Mb

#

XD

tacit arch
#

You should know those sin/cos values from the unit circle

warm mason
#

Yea they are in 3rd Quadron

#

So both values are -

#

But i don't know how to answer the question?

#

It's 45 degrees in the 3rd Quadron

#

So cos 225 + i sin 225 equals to what?

tacit arch
warm mason
#

Yea but that i get

#

But it's i didn't finish calculating the question right but is it impossible at my stage

#

Because of i?

tacit arch
#

I don't understand what you're stuck on

warm mason
#

And then so i answer only sin(x) and cos(x)

#

Oh i think we answered the question

#

This is outside of the question to make me understand

#

Deeper

#

If that's okay to ask?

#

Cus question is cos (5π/4) + i sin (5π/4) but we only answer in what quadrant cos (5π/4) and this sin (5π/4) is. But not what happens if we actually put them together and how i affects the final answer. So i guess I'm asking can you answer the question with an i in it?

#

Or is this as far as i can go?

tacit arch
#

Yes. questions about complex numbers can have complex numbers as answers

warm mason
#

I see

#

So we basically just simplified it?

tacit arch
#

Well you still didn't simplify it completely

warm mason
#

What else can I do?

tacit arch
#

But you don't need to

#

You already found the quadrant

warm mason
#

I see but can you teach me

#

I'm curious now

#

What is example sin(2π/5)?

warm mason
#

But it only shows the 45° 60° and so on

#

It doesn't show in-between those values?

#

Like the values between

tacit arch
#

Screenshot what the link looks like

warm mason
#

Maby i just don't get it?

#

Like how to read it

tacit arch
#

It's the chart

#

5pi/4 is the same point as -3pi/4

#

Because cos(x + 2pi n) = cos(x) for all integers n

#

Similarly for sin

warm mason
#

Wutttt

#

How did i not know that

#

Okay thank you so much!!

#

.close

lone heartBOT
#
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chilly tulip
#

Hello, we were given a question that involves subtracting matrices with variable exponents, while we were taught what to do with matrices with exponents, we weren't taught how to handle matrices with variable exponents. Is it literally just the same as normal matrix operations or is there some sort of special method to it?

tacit arch
#

Just show the problem

chilly tulip
tacit arch
#

That means transpose

chilly tulip
#

transpose?

#

I'll look into it thanks

#

.close

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deft kettle
#

if i say integral of sin 90 dx, then it's gonna be 0 right?

median oar
#

no

#

this is an indefinite integral

deft kettle
#

i know i know

#

wait ill tell u why am i doing this

vale wigeon
#

neither sin(90°) or sin(90 rad) are equal to zero

median oar
#

and even if it was 0 it's still just + c at the end... so still not 0

deft kettle
#

is this correct?

median oar
#

uh

#

i dont thin kthis is the way to go

#

you cant just split (1-sinx)^-1 into 2 integrals

deft kettle
#

but thats what i did

#

1 is the same as x^0 and -sin x^-1 is that same as -cosec x

#

then i integrated both of these after splitting

median oar
#

maybe these 2 from the table of integrals can help you out

median oar
ocean sealBOT
#

Frosst

deft kettle
#

well seems like i made a mistake

#

i just thought its gonna be something like

median oar
# deft kettle

your handwriting is really badi cant tell what you're writing lol

deft kettle
#

ooof wait ill write it neatly

#

this better?

median oar
#

how did you get from step 2 to step 3

deft kettle
#

well its just negative power 1

#

power 1 of anything is just the number itself?

median oar
#

1 ≠ -1

deft kettle
#

tru

#

i see

#

got it

#

.close

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orchid python
#

hi

lone heartBOT
orchid python
#

how can I do the c question

lone heartBOT
#

@orchid python Has your question been resolved?

orchid python
#

can anybody help me with that/

#

<@&286206848099549185> can somehow show me the direction for solving this one? the C question

lone heartBOT
#

@orchid python Has your question been resolved?

lone heartBOT
#

@orchid python Has your question been resolved?

orchid python
#

hi anybody

orchid python
#

hi

carmine shuttle
#

I guess that in (c), $\lambda$ is no longer in $5 unit^{-1}$,
so let $\lambda$ be mean rate of request in \textit{\textbf{0.5}} unit time.

$$P(X=\lambda) = \dfrac{e^{-\lambda} {\lambda}^0}{0!}$$
$$e^{-\lambda} = 0.9$$
$$\lambda = - \ln 0.9$$

ocean sealBOT
#

kelvinchan9786

orchid python
#

hi

#

can anybody help me with this one

final olive
#

mean for X1-X2 =75-70=5

and std error of X1-X2 =(s1^2/n1+s2^2/n2)^(1/2 )=4.472

a)hence P(X1-X2>4)=1-P(X1-X2<4)=1-P(Z<(4-5)/4.472)=1-P(Z<-0.2236)=1-0.4115=0.5885

b)P(3.5<X1-X2<5.5)=P((3.5-5)/4.472<Z<(5.5-5)/4.472)=P(-03354<Z<0.1118)=0.5445-0.3687=0.1758

#

@orchid python

orchid python
#

hi

#

@final olive are you there

final olive
#

whats up

orchid python
#

what is s12 and s22

final olive
#

sorry edited

orchid python
#

where did you get this formula

#

i only found this one

final olive
#

thats the formula for a single population

#

let me find the derivation

#

my formula is for standard error of x1-x2

orchid python
#

and how do you calculate the probability from the z score, i don't know how to do it

final olive
#

i used the z score probability table

orchid python
#

how did you do it

final olive
orchid python
#

how did you do this part: P(-03354<Z<0.1118)=0.5445-0.3687

final olive
#

that is

orchid python
#

P(Z < 0.1118) - P (Z < -0.3354)

final olive
#

yeah

orchid python
#

so what's next

final olive
#

you could approximate it using a detailed table if yo have one on hand

#

i just used this site

#

where i entered the z score, and got the corresponding probablity

orchid python
#

so the values you give me are all correct

#

can you help me with this one @final olive

violet portal
#

can i have help with b i dont know where to begin

#

for b

orchid python
#

hi

orchid python
#

can anybody help?

#

for the 4-76 a, is the answer is 0.99997?

#

P(Z < -4) = 0.99997?

#

why taking the first value?

placid zinc
#

You're using P(x > Z) when you want to use P(x < Z)

#

Being 4 SD below the mean is very unlikely.

#

@orchid python

orchid python
#

yeah i'm here

#

for the third question i don't know why they have 2phi(x/0.1) -1

#

can anybody explian?

orchid python
#

for the a question

#

i need to add them together?

#

P(x=0) + P(x=1) + P(x=2) + P(x=3) ?

#

or i need to use the exponential distributed formula?

#

hi anybody???

carmine shuttle
#

(I assume that it is 4 "unit time" instead of 4 "minutes") \
... It is not how Poisson distribution works 😅 \
Let X be the random variable that represents mean rate of request in 4 minutes. \
As mean is five per unit time, $\lambda = 4 \times 5 = 20 (5 \text{unit})^{-1}$ (Don't mind the $(5 \text{unit})^{-1}$, it is just a unit) \
You should calculate $1 - P(X = 0)$, since $P(X=0)$ does not satisfy the condition that the first request is less than 4 minutes.

#

@orchid python

ocean sealBOT
#

kelvinchan9786

lone heartBOT
#

@orchid python Has your question been resolved?

orchid python
#

is this correct?

carmine shuttle
#

Do you mix up Stochastic process? 😅

#

Exponential distribution is cont. but Poisson distribution is discrete...

#

@orchid python

lone heartBOT
#

@orchid python Has your question been resolved?

lone heartBOT
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harsh girder
#

a+bi conjugate to a-bi

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stable shore
#

I shall announce my question

lone heartBOT
stable shore
#

Okay, what was my mistake in solving this integral?

#

My work:

#

Marked in red is the final WRONG answer

#

I used u-substitution and integration by parts, but my answer is wrong. Here is the solution without u-substitution:

#

The final, RIGHT ANSWER is in white

lone heartBOT
#

@stable shore Has your question been resolved?

tacit arch
tacit arch
stable shore
#

the red answer shouldnt be compared

#

dammit

tacit arch
#

Can you just show the original problem

stable shore
#

let me fix it

tacit arch
#

Screenshot or picture is best

stable shore
#

I know the solution.

harsh girder
stable shore
#

I just want to know what I did wrong. To reach the wrong integral

harsh girder
#

here should be -(-1)

stable shore
#

But, why is this logic wrong

#

The red is wrong

harsh girder
harsh girder
#

it's correct

stable shore
#

Okay, got it. Appreciate it!

#

THIS CHANNEL IS NOW OPEN!

tacit arch
lone heartBOT
#
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shell mortar
lone heartBOT
shell mortar
#

can someone help to solve this problem

narrow moat
# shell mortar

Since they're consecutive, you can rewrite them as some number y, some number y+1, some number y+2, and some number y+3.

#

So a₁/(a₁+a₂) would be y/(2y+1).

shell mortar
#

yes

narrow moat
shell mortar
narrow moat
shell mortar
#

bro

harsh girder
shell mortar
#

yeah

harsh girder
#

they are 4 consecutive terms in this

narrow moat
shell mortar
harsh girder
narrow moat
narrow moat
harsh girder
#

It's okay, maybe you haven't learned this yet.

shell mortar
narrow moat
narrow moat
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#

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wind pumice
lone heartBOT
gray ingot
#

Don't ghost ping helpers 🗿

wind pumice
#

<@&286206848099549185> \

lone heartBOT
#

@wind pumice Has your question been resolved?

wind pumice
#

<@&286206848099549185>

tacit arch
tacit arch
#

@wind pumice you have one here

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#

@wind pumice Has your question been resolved?

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tribal oxide
lone heartBOT
tribal oxide
#

i have the domain, but in class we were told two ways to find the range for these types of questions

#

one method was by multiplying both sides by the denominator, and then forming a quadratic in x

#

and taking b^2-4ac>=0, but im not getting the answer

#

and the other method was by graph which im also not sure how to draw

#

OH the graph was for no common factors between the numerator and denominator

#

okay ive found the answer through the graph, but why am i not getting it through the other method?

lone heartBOT
#

@tribal oxide Has your question been resolved?

hazy atlas
#

let the funcn equal to something let sey y

#

denominator goes to other side, then quadratic in y generates

#

then simply proceed with Discriminant greater than equal to 0

tribal oxide
#

And this is what i described

hazy atlas
#

then where are you getting errors

tribal oxide
#

From that i got y belong to R-{1/5}, but theres also supposed to be a 1 which should not be included in the answer, which i got in the graph

hazy atlas
#

can you show your working?

tribal oxide
#

Ignore the limits part, we havent done limits yet, i was just testing something 💀

#

Oh wait

#

Actually...

#

The last step is wrong

#

It should be y belong to R?💀 Which is even more wrong

hazy atlas
#

(5y-1)²>=0
after solving the inequality

#

answer should be

#

y>=1/5 or y<=1/5

#

all steps are correct imo

tribal oxide
hazy atlas
#

yep

#

nah wait

tribal oxide
#

The last step in the picture is incorrect cuz i probably already knew 1/5 wasnt there in the ans cuz of my graph meyhod

#

So the quadratic method is giving me y belong to R

#

💀

hazy atlas
#

wait wait wait

#

numerator and denominator makes factors

tribal oxide
#

Yes they do

#

Thats why i thought abt using limits💀

hazy atlas
#

nah

#

first find domain

tribal oxide
#

Domain is found

hazy atlas
#

then for range

tribal oxide
#

Domain is R-{-3,2}

hazy atlas
#

1 factor should be common

#

you can cancel that and check domain

tribal oxide
hazy atlas
#

if it is included in domain you can add that

tribal oxide
#

The thing is i can still check for the point x=2 will not give by taking the limit x tends to 2, but how will i find, that 1 is also not a part of the range without using the graph🤔

hazy atlas
tribal oxide
hazy atlas
#

so now simply you're left with y = x-1/x+3

#

after solving you will get y not 1

tribal oxide
#

Yep

#

Okay, ill just keep making sure i get matching answers with graphs

#

Thanks

#

.close

lone heartBOT
#
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#
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queen lodge
#

What is f(x) when f is even and x is neither

queen lodge
#

?

rose sigil
#

huh?

queen lodge
#

What will the fx be even or neither

rose sigil
#

is this something you made up or is it from a problem you saw?

queen lodge
#

Problem that i saw

rose sigil
#

can you send it?

queen lodge
#

Top one

#

?

rose sigil
#

,rotate

ocean sealBOT
queen lodge
#

?

rose sigil
#

I'd have to think about that one 😬

tribal oxide
queen lodge
tribal oxide
queen lodge
#

Neither

tribal oxide
#

i mean like an actual expressio

#

expression

queen lodge
#

It has to be +ve

tribal oxide
queen lodge
#

Oh

#

Thanks

#

. close

#

.close

lone heartBOT
#
Channel closed

Closed by @queen lodge

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#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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mild otter
#

can someone help with q13

lone heartBOT
#

Please don't occupy multiple help channels.

languid bolt
#

still need help?

mild otter
#

yeah

#

just closed other channel

#

anyway yeah

languid bolt
#

try inserting the informations you have to the equation

mild otter
#

i tried, do i insert the raw numbers? or like 10ms^-2

languid bolt
#

up to you

mild otter
#

then i got this

#

which happens to be wrong, i think

#

idk what to do

languid bolt
#

$4 = 2\pi\sqrt{\frac{l}{10}}$

ocean sealBOT
#

MarveI

languid bolt
#

$\frac{4}{2\pi} = \sqrt{\frac{l}{10}}$

mild otter
#

oh okay i was over complicating it with the signs and units

ocean sealBOT
#

MarveI

languid bolt
#

$\frac{4}{2\pi}\sqrt{10} = \sqrt{l}$

ocean sealBOT
#

MarveI

languid bolt
#

still following until this part?

mild otter
#

hmm did you multiply by sqrt 10?

languid bolt
#

yes

mild otter
#

okay, yeah i follow

#

and then just sqrt l ^2 ?

languid bolt
#

yeah but the left side will be $\frac{160}{4\pi^2}$

ocean sealBOT
#

MarveI

languid bolt
#

i feel like it's kinda wrong

mild otter
#

answer in book is 40 over pi ^2

languid bolt
#

oh ok good

#

it's correct then

mild otter
#

cool ty

#

i was just confused cause

#

while you entered 10, the unit it said was 10ms ^-2

#

and like

#

idk what to do with the ^-2

languid bolt
#

that is the unit...

#

you dont actually calculate the exponent

mild otter
#

yeah ik its the unit, just wasn’t sure if i had to leave it in

#

oh right, thank you

languid bolt
#

np

mild otter
#

.close

lone heartBOT
#
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queen lodge
#

I was not able to do top question

#

Help

wide raven
#

plug in -x and see if they fit the definition of odd or even functions

queen lodge
#

How to solve it then

wide raven
#

what do you get if you put -x

queen lodge
#

Cos log -x+√x²+1

wide raven
#

yes

#

and isn't cos(x)=cos(-x)?

#

if you do that

queen lodge
#

Yes

wide raven
#

and also

queen lodge
#

But it is cos log -x√x²+1

wide raven
#

-log(x)=log(1/x)

#

yes so

queen lodge
#

-is inside log

wide raven
#

cos(log -x√x²+1)=cos(-log -x√x²+1)

#

not like that

wide raven
queen lodge
wide raven
#

well

wide raven
queen lodge
#

Oh

wide raven
#

and then if you reciprocate what's inside log

#

and then rationalize it

#

you get f(x) itself

#

so even function

queen lodge
#

Oh thanks

wide raven
#

np

queen lodge
#

I have one more question

wide raven
#

umm

#

i gtg actually

#

you can close this one and ask in a fresh channel

queen lodge
#

. close

wide raven
#

i can help if i get back in time

#

for now

#

cya!

wide raven
queen lodge
#

.close

lone heartBOT
#
Channel closed

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wide raven
#

if you want it to work

lone heartBOT
#
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random haven
#

sally jean wants to plant a garden with a perimeter of 40ft.what dimensions will allow the garden to have maximum area

carmine oar
#

a circle is the largest, tho these kinds of problems want squares or rectangles

#

what are you stuck with

random haven
#

If i want to create a circle,what dimension would i have to mention?

alpine sable
#

Rewriting in terms of plane algebra :

$a+b=20$
$\implies b=20-a$

so u have

Area=$a(20-a)=-a^2+20a$

ocean sealBOT
#

∆y/∆x=πy+π^2x

alpine sable
#

a,b are the dimensions

#

now u want the maximum value of the area

carmine oar
alpine sable
random haven
#

It's pretty complex ngl

carmine oar
#

btw what grade is this

alpine sable
#

it's quite simple ig

random haven
#

Pre college

rose sigil
#

is that supposed to say plain or plane 🤔

random haven
#

I am dumb

carmine oar
random haven
#

So should I consider a circle, rectangle or a square?

carmine oar
alpine sable
#

well

#

I can

#

but it's not necessary

carmine oar
#

for not using pi

alpine sable
#

teachers like rectangles

carmine oar
random haven
#

So should I go with square

carmine oar
#

like just remember the fact that square has the largest areas

random haven
#

How would I solve it then

carmine oar
#

tho it can be false

carmine oar
#

this is def not rigorous

random haven
#

I know perimeter of of square is 4*side

alpine sable
#

ig we are moving with some rough assumptions

carmine oar
#

but enough to solve this kinds

alpine sable
#

it's better to use rect ig

carmine oar
#

@random haven Just make sure that for quadrilaterals
square is always the largest
tho side lengths may not be integer

carmine oar
random haven
#

So what should I do ahead lol

#

Should I equate the perimeter to 4*side

#

And then when out length of the side

alpine sable
# ocean seal **∆y/∆x=πy+π^2x**

lemme explain this in a simpler manner let's say $a, b$ are ur dimensions

Perimeter=2(a+b)
as per condition,
2(a+b)=40

$\implies a+b=20$

$\implies b=20-a$

now we have Area=$a(20-a)$ we now want to find what a gives maximum area

random haven
#

Or something else needs to be done?

ocean sealBOT
#

∆y/∆x=πy+π^2x

random haven
alpine sable
#

so now try it yourself

alpine sable
#

ig

carmine oar
alpine sable
#

coz then u can't even solve it

u will have

side=10

now u only have 1 and only 1 area no maximisation

#

and the question explictly asks to maximize

carmine oar
#

JUST KEEP IT TO YOURSELF