Have you worked with modular arithmetic before
#help-0
molten pivot
molten pivot
b-ax mod a != 0 that's what you're trying to say ?
b+ax mod a is not 0
vale crag
yeah that's what I wrote
molten pivot
Oh ok
vale crag
not that it should matter in modular arithmetic anyway
molten pivot
Yeah shouldn't make a difference then
hushed mica
guys ?
vale crag
I mean yeah so where do you get from there ?
hushed mica
whats going with mod lol
vale crag
how do you show that gcd(a, b+ax) = 1 from there ?
hushed mica
guys someone explain me also whats with this mod 🥲
@vale crag
can u tell me how to solve this like
how where did e|d suddenly fall from
molten pivot
Simple. We show that since b mod a is not 0, then b+ax mod a is not 0. So then we have exactly three possibilities:
- x is coprime to a and b
- x is not coprime to a (and therefore coprime to b)
- x is not coprime to b (and therefore coprime to a)
If (1), then the resulting expression b+ax cannot be factored.
If (2), then the resulting expression still cannot be factored, because ax+b mod a > 0
If (3), then the resulting expression can be factored in terms of some factor of b, but this still produces a number that is not divisible by a, therefore gcd(b,ax+b) = 1 in all three cases
molten pivot
@vale crag were you going to finish your explanation now
hushed mica
<@&286206848099549185>
vale crag
@hushed mica yeah let's restart from the beginning I guess
hushed mica
<@701043425029652550> yeah let's restart from the beginning I guess
phew
lol
thanks
vale crag
(sorry my cat did a mess in the kitchen :/)
molten pivot
Alright then, I guess that was a pointless diversion if you don't understand modulo
hushed mica
(sorry my cat did a mess in the kitchen :/)
haha understandable
molten pivot
Sorry for interrupting haha
hushed mica
Alright then, I guess that was a pointless diversion if you don't understand mod...
actually it is modulo for which i am doing nt
vale crag
so yeah we want to show the two gcd's are equal
hushed mica
cause i am doing a book for algebra and that book needs some basic knowledge about modulo
hushed mica
so yeah we want to show the two gcd's are equal
yes
vale crag
the way they go about it is to show that e|d and d|e
since the gcd's are positive, this implies they're equal
hushed mica
since the gcd's are positive, this implies they're equal
yep
vale crag
(and it's quite a natural way of expressing equality with gcd's since gcd's give statements about divisibility)
hushed mica
yep
vale crag
so yeah do you understand where (i) and (ii) come from ?
hushed mica
yep
vale crag
they probably introduced it before in the book
hushed mica
its from the bezouts theorem
vale crag
bézout identity and stuff
yeah
now the central fact about division they're using (which is pretty much used at each step) is the following
if d|a and d|b, then d|ax+by for every x, y in Z
hushed mica
if d|a and d|b, then d|ax+by for every x, y in **Z**
yep
vale crag
can you convince yourself that this is true ?
hushed mica
can you convince yourself that this is true ?
yep
vale crag
okay then they're pretty much spamming this fact all over the place
hushed mica
kinda lol
vale crag
reposting the pic
hushed mica
hmm
vale crag
if you know that d|a and d|b (since d is the gcd of a and b, this is true)
then also d | a(u+xv) + bv
and from (ii) we know a(u+xv)+bv = e
hushed mica
yep
hushed mica
hmm
vale crag
if d|a and d|b, then d|ax+by for every x, y in **Z**
the way you have to interpret this is that if d | a and d | b then d divides any linear combination of a and b
the x and y that I put can be literally what I want (as long as they're integers of course)
molten pivot
Let a = d×A and b=d×B. That might clarify the factorization
hushed mica
Let a = d×A and b=d×B. That might clarify the factorization
i have got upto e | b
i am jst stuck in the last one like how it suddenly became e | d
vale crag
yep e|b, and since e is the gcd of a and b+ax, you also have e|a
hushed mica
yep
vale crag
(since it's a common divisor of a and b+ax)
hushed mica
yep
hushed mica
yep
vale crag
and finally e|d
hushed mica
oh yes
vale crag
(since d=ar+bs from (i))
hushed mica
this can be done
tysm guys for helping me understand this from so much time 😄
.close
lone heartBOT
molten pivot
tysm guys for helping me understand this from so much time 😄
Np, glad to help
lone heartBOT
Available help channel!
spare tree
.
junior warren
not sure how i would test for these
lone heartBOT
not sure how i would test for these
abstract fractal
What have you tried?
junior warren
in previous questions i have subbed the parametrics of the line into the x,y,z of the plane
but i think that is only for intersection correct?
abstract fractal
Sure. And if the line is in the plane, it intersects everywhere
junior warren
right so i can check that way
ok that makes sense
and if i get something such as
3t=2
or whatnot
then obviously certain t values dont work
and therefore it wouldnt lie in the plane
?
abstract fractal
Yep
junior warren
so t just cant be restricted
abstract fractal
It needs to satisfy the equation for all t
somber spoke
lone heartBOT
somber spoke
I’m confused on part b
Surely u want to find p(x>=312)
And show that that’s greater/smaller than 0.95
The markscheme says something different
<@&286206848099549185>
lone heartBOT
@somber spoke Has your question been resolved?
lone heartBOT
@somber spoke Has your question been resolved?
jade ibex
ishan wahst good what you doing on this server
lone heartBOT
@somber spoke Has your question been resolved?
iron swallow
Hey
wary stream
<@&286206848099549185>
You have to wait at least 15 minutes before pinging helpers
cinder flint
think of it this way
if you want to see all of those whales
the number of "rarest" whales in a month must give bigger values
iron swallow
K
cinder flint
L
iron swallow
L
wary stream
M?
chrome plank
when will you have the highest chance of seeing all species of whales?
when you'll have the highest chance of seeing even the rarest one of that month
chrome plank
are you sure?
chrome plank
the rarest of november is the humpback
chrome plank
what's the rarest of March
iron swallow
November is other
chrome plank
what's it's number of sightings approximately
iron swallow
Average
chrome plank
Go slow
iron swallow
Per month or total
chrome plank
For that month (march)
iron swallow
5
iron swallow
Other is 30 for July
chrome plank
yes, and what about november?
chrome plank
yes that's about it
chrome plank
So in which month do you have the highest chance of finding even the rarest of the whales?
iron swallow
So July
chrome plank
Exactly
iron swallow
🙏 thanks
chrome plank
chrome plank
yes, 90 clockwise
chrome plank
Bye!
iron swallow
.close
buoyant junco
Hey, I got a question and I solved it but now it is asking me to "Round my answer to two decimal places". The answer I got was 19.6912
buoyant junco
would I round this to 19.69 or 19.70
different sources are giving different information.
warm halo
I'd say round it to 19.70 because the last digit (9) of 19.69, which is what you get when you put the answer in only two decimal places, is greater than 5, so you would increase it by one to 10. If the last digit was less than or equal to 5, you would leave it as it is.
Please disregard this.
lone heartBOT
wary stream
would I round this to 19.69 or 19.70
Two decimal places would make the result be 19.69
warm halo
Oh wait, you are absolutely right, the digit before the 9 in 19.69 is 1, so the 9 would not get rounded up... oops.
lone heartBOT
Available help channel!
alpine sable
Hello
alpine sable
So I did this simplification of a radical fraction
I was wondering which one of the answers would be more appropriate
Thanks
.closed
wary stream
They're both the same
wary stream
$$\frac{-a}{b} = \frac{a}{-b}$$
ocean sealBOT
dldh06
wary stream
It doesn't matter, they'll both result in the same solution
cursive crescent
lone heartBOT
cursive crescent
I'm trying to do this problem but I'm ending up with a different solution
where my solution is instead: tan(t+y) - sec(t+y) - t = C
Could someone help me remember if there is an easy way to check solutions? It would be much appreciated
lone heartBOT
@cursive crescent Has your question been resolved?
cursive crescent
<@&286206848099549185> any integration fans?
My line of thought:
dv/dt = 1 + dy/dt
dv/dt = sin(v) + 1
dv/(sin(v)+1) = dt
integrating dv/(sin(v)+1), multiply top and bottom by (1-sin(v)) to get:
(1 - sin(v)) / [(1 + sin (v))(1-sin(v)]
(1+sin(v))(1-sin(v)) = cos^2(v)
oh
.close
carmine bronze
,w \frac{3x^{2}-2x-8}{x^{2}-4} x->2
lone heartBOT
,w \frac{3x^{2}-2x-8}{x^{2}-4} x->2
carmine bronze
aww it doesn't show the steps
abstract fractal
Why go on a help channel to use wolfram alpha for the steps instead of just using wolfram alpha?
abstract fractal
Well, what have you tried?
carmine bronze
I did this a few days ago I forgot
abstract fractal
Try factoring the numerator and denominator
carmine bronze
First thing I tried
abstract fractal
And? What'd you get?
carmine bronze
well I didn't successfully factor it
abstract fractal
Try successfully factoring it
carmine bronze
is this using synthetic division?
carmine bronze
there's an easier way?
abstract fractal
Yeah. Just factor the things
Start with the numerator
How do you factor 3x² - 2x - 8?
abstract fractal
Do you know how to factor equations when there's a coefficient with x²?
carmine bronze
cool I like this guy
alright thanks @abstract fractal and theorganicchemistrytutor
.close
lavish pier
lone heartBOT
lavish pier
i understand this but can someone answer my hypothetical question 2x -5y + 13 = 20
i dont understand where to 'where you will put the + 13 into the y = mx + b form
abstract fractal
Well, what happens when you solve for y?
abstract fractal
What do you get for y?
lavish pier
-4
abstract fractal
?
lavish pier
for this question
abstract fractal
2x - 5y + 13 = 20 simplifies to y = -4?
And to answer that question you need y in mx + b form
abstract fractal
I'm saying that in order to find the y intercept, or even the gradient, you need to solve for y
That's for the og question
I thought you were asking about 2x - 5y + 13 = 20?
Which is different from the problem you posted of 2x - 5y = 20
lavish pier
yeah im asking what happens to the 13
abstract fractal
Wdym what happens to the 13?
When you solve for y, you'll subtract it, I suppose
lavish pier
ok
so it wont be 20 -13
it would be 7
i just thought that wouldnt satisfy the y intercept fkr
abstract fractal
7 isn't the y intercept, if that's what you're saying
abstract fractal
Well, I suppose it'll add 13/5 to the y intercept
abstract fractal
No, I'm saying it'll add 13/5 to the previous y intercept, which was -4
7/5 = -4 + 13/5
lavish pier
yes
thanks for the help dio
.cIose
.cIose
thats weird
can you close the channel plsz
.cIose
abstract fractal
It'll close on its own after enough time
plush nacelle
Should I choose -4,-5 or 2,1 to solve the equation
lone heartBOT
Should I choose -4,-5 or 2,1 to solve the equation
normal ingot
is it just me or do I see a black image
dry ridge
tacit arch
Should I choose -4,-5 or 2,1 to solve the equation
,rotate
ocean sealBOT
plush nacelle
Q10
normal ingot
you can choose one of (-4, -5) or (2, 1) to substitute back into the equation
either will give the same answer
plush nacelle
Ok thx
lone heartBOT
@plush nacelle Has your question been resolved?
plush nacelle
Yes
lone heartBOT
plush nacelle
reopen
lone heartBOT
Available help channel!
plush nacelle
lone heartBOT
normal ingot
what do you get if you substitute x=-3 into x^2-x
plush nacelle
what do you get if you substitute x=-3 into x^2-x
?
plush nacelle
What does ^ mean
normal ingot
$x^2-x$
ocean sealBOT
lirmirit
normal ingot
$(-3)^2\neq-3^2$
ocean sealBOT
lirmirit
normal ingot
you mean 9 + 3
frigid hatch
yes
plush nacelle
Thx guys I have exam later so thank you
lone heartBOT
@plush nacelle Has your question been resolved?
alpine sable
lone heartBOT
alpine sable
why does it equal -infinity? where does it come from
i know that 1/t^2 - 5t = 0
alpine sable
.close
ebon fog
When creating logic gates - Do you add the brackets () after the AND output.
ebon fog
Brackets are in the wrong place - as i don't know when to add them. Should x+y(z') be (x+yz')
tall hearth
ebon fog
Thank you - do you just add () after AND and not OR
small ocean
Pardon the english
A ship left the dock at 14.00 and sailed to south at 20km/h. Another ship sailed to east at 15km/h and arrived in the dock at 15.00. At what time did the ships were closest from each other
restive tendon
it shud be at 14.00
cuz the 1st ship is alredy at the port
and at 15.00 the other ship reaches the port
since the speed of second ship is 15 kmph
and it reaches just after 1 hr
so the ships are 15 km far from each other
once the 1st ship starts travelling
its speed is 20 kmph
so it wil start moving farther and farther from the second ship
small ocean
Yeah, my teacher asked to apply derivation there
restive tendon
ok so i dont really know what derivation is
but wat i said
is dat wat ur looking for?
small ocean
I also thought that way
small ocean
is dat wat ur looking for?
Yep
restive tendon
So now your problem is resolved right?
small ocean
Kinda, but i wanna know where do the derivative applied
river fossil
we let t=0 be 14:00
we can model the first ship's displacement from dock as
f(t) = 20t
and the second ship's is
g(t) = 15(t-1) since it passes the dock at t=1 or 15:00
they are traveling perpendicular to each other so what would their distance as a function be?
small ocean
Like pythagorean stuff?
river fossil
Like pythagorean stuff?
yup
river fossil
almost, don't forget the square root
since we want the distance, not the square of the distance
river fossil
yup, since the minimum of the distance would be when they are closest
i think that's how you'd do it
river fossil
yup that's my answer, what time is t=0.36?
river fossil
almost, .6 minutes isn't 60 seconds
small ocean
Thank you so much
river fossil
no problem 👍
small ocean
.close
lone heartBOT
lone heartBOT
Available help channel!
pastel trench
I wrote the coefficient,but i don't know how to get the binomial series.
frigid rune
$$(1+x)^n = 1 + nx + \frac{n(n-1)}{2!}x^2 + \frac{n(n-1)(n-2)}{3!} x^3 .......$$
ocean sealBOT
Nathan_
frigid rune
do you know this formula?
pastel trench
I know
frigid rune
since you have 2+ not 1+ you need to factor out the 2 and then you can use the formula
pastel trench
so write like that?
frigid rune
im not sure where the 2n-3 is coming from but if that is correct then yes the rest looks fine
spring jackal
How do I solve for y again?
lone heartBOT
How do I solve for y again?
spring jackal
Subbing in x (into 2x^2-2x-24) gives 0
carmine oar
what is the question sorry
amber niche
This is really hard to read
vale wigeon
you want to solve the equation 3x^2 - 5x - 24 = x^2 - 3x?
spring jackal
Sorry I’ll send a picture of the actual question
Q8
I have found both x intercepts already
carmine oar
you want to solve the equation 3x^2 - 5x - 24 = x^2 - 3x?
@spring jackal maybe start from here ig
spring jackal
When you solve that you receive 2x^2-2x-24
ocean sealBOT
||𝓚𝓪𝓼𝓹𝓮𝓻||
spring jackal
Then when you use the quadratic formula for x you get 4, -3
But I don’t know what to do to get y
carmine oar
pluging x into any of y=x^2 -3x or y=3x^2 -5x -24
spring jackal
4^2-3(4)=4
vale wigeon
there you go
so you have (4, 4) as the first intersection point
and the second is (-3, _)
spring jackal
(-3)^2-3(-3)=0
spring jackal
Sorry 18
vale wigeon
well again there you go
obtuse hatch
lone heartBOT
obtuse hatch
hello there! I know that i took the second derivative to get a(t)
how is it wrong
vt is first derivative
woven crane
what's the derivative of 9t^2 + 7
woven crane
lol
lone heartBOT
lone heartBOT
Available help channel!
proud shoal
Yo Can someone do q31 A? I think the question is wrong
lone heartBOT
Yo Can someone do q31 A? I think the question is wrong
proud shoal
alright thanks the question is wrong
obtuse hatch
rationalize the denominator
obtuse hatch
sorry about that then
obtuse hatch
ya np
spring jackal
.
lavish pier
lone heartBOT
long iris
lone heartBOT
lone heartBOT
✅
carmine oar
first
lavish pier
i dont get this part
carmine oar
try and express root of 32 in terms of root 8
karmic rapids
the fuck is surds
karmic rapids
@lavish pier $$\sqrt{ab} = \sqrt{a} \sqrt{b} \implies \sqrt{a^2b} = a \sqrt{b}$$
ocean sealBOT
illuminator3
carmine oar
that does
lavish pier
how is root 4 root 2
karmic rapids
omg that doesnt even relate to my question
it does lol
vale wigeon
<@616880914135253013> $$\sqrt{ab} = \sqrt{a} \sqrt{b} \implies \sqrt{a^2b} = a \...
that last step is only valid for a >= 0
lavish pier
maybe the main question but not the one i had
carmine oar
that last step is only valid for a >= 0
right but this is not our main concern tho here tbh
karmic rapids
that last step is only valid for a >= 0
which one?
vale wigeon
i don't see where the claim is made that sqrt(4)=sqrt(2) @lavish pier
vale wigeon
which one?
the one where you write sqrt(a^2) as a
ocean sealBOT
||𝓚𝓪𝓼𝓹𝓮𝓻||
carmine oar
consider this @lavish pier
lavish pier
i get it now
karmic rapids
the one where you write sqrt(a^2) as a
._. \pm a, happy?
lone heartBOT
balmy warren
they are calculating area of ABFE
BCF is outside that area
so they subtract
ADE is inside that area
so they add
yup
wicked blaze
The FC squad is made up of 3 goalkeepers, 7 defenders, 6 midfielders and 5 forwards. The coach always plays with 1-4-3-3 (1 goalkeeper, 4 defenders, 3 midfielders and 3 forwards), a system that is not negotiable despite the fact that with 1-4-4-2 he obtains better results. How many different line-ups can be made (considering that each player plays solely and exclusively in his demarcation)?
Solution: 21,000 different lineups
solar tulip
hello could anybody help how shld i start? thankuu
lone heartBOT
hello could anybody help how shld i start? thankuu
sharp grotto
isnt it just 0...?
cuz u can just separate it out to lim n->infinity each term individually
the largest term will be lim n->infinity n/(n+n^2) which is 0
so all the terms before it will also be 0
so 0...?
solar tulip
so 0...?
oyeah i get this i wasnt sure if theres more to it but thankss
can i cfm that whenever the denominator is infinity, it will be 0 (unless the numerator is infinity too)
sharp grotto
oyeah i get this i wasnt sure if theres more to it but thankss
im not sure tho
cuz the no of terms increases to infinity as n approaches infinity
idk if there are any hidden traps behind this
ok
there is prolly a trap cuz
LOL
solar tulip
o
sharp grotto
wolfram alpha refuse to give a step by step solution btw
solar tulip
<@&286206848099549185> sry for the ping but was wondering if anyone could explain how to get 1/2? thankiew
frigid rune
try combining all of the fractions into a single fraction
then you only need to consider the term with the highest power of n
@solar tulip
solar tulip
try combining all of the fractions into a single fraction
oh but arent they all different denominators?
sharp grotto
try combining all of the fractions into a single fraction
actuallly no matter how u combine them the highest power of n in numerator will always be lower than power of n in the denominator right?
but its not 0
frigid rune
actuallly no matter how u combine them the highest power of n in numerator will ...
almost
give me a sec to type out latex
solar tulip
give me a sec to type out latex
okay thankss 
sry for the trouble
frigid rune
$$\lim_{n-to\infty} \frac{1}{1+n^2} + \frac{2}{2+n^2} + \frac{3}{3+n^2} + ....... + \frac{n}{n+n^2}$$
$$=\lim_{n\to\infty} \frac{1(2+n^2)(3+n^2)...(n+n^2) + 2(1+n^2)(3+n^2)...(n+n^2) + ...}{(1+n^2)(2+n^2)(3+n^2).....(n+n^2)}$$
ocean sealBOT
Nathan_
frigid rune
then if you expended all of these brackets and only took the term with the highest power of n you would get
$$\lim_{n\to\infty} \frac{(1+2+3+...+n)n^{2n-2}}{n^{2n}}$$
sharp grotto
bruh it will be n^n-1 * 1+2+3+..+n
ocean sealBOT
Nathan_
sharp grotto
actually interesting question thanks a lot i learned something too
solar tulip
$$\lim_{n\to\infty} \frac{(1+2+3+...+n)n^{2n-2}}{n^{2n}}$$
i don't get how u get this sorry
frigid rune
i don't get how u get this sorry
if you expended the brackets in the denominator you would get a long polynomial in n right
solar tulip
yup
frigid rune
and the term with the highest power of n will just be when you multiply all of the n^2 terms
frigid rune
and then the same sort of thing for each term in the numerator except you have one less (x+n^2) term so the overall power is n^(2n-2)
then you can use the summation formula to say that $$1+2+3....+n = \frac{1}{2}n(n+1)$$
ocean sealBOT
Nathan_
frigid rune
which makes the limit $$\lim_{n\to\infty} \frac{\frac{1}{2}n(n+1) n^{2n-2}}{n^{2n}}$$
ocean sealBOT
Nathan_
solar tulip
and then the same sort of thing for each term in the numerator except you have o...
sorry :( i dont rly get the numerator
frigid rune
sorry :( i dont rly get the numerator
if you just take the first term then you have 1(2+n^2)(3+n^2)...(n+n^2) which is exactly the same as the denominator except with 1 instead of (1+n^2)
so when you expend it you will get the term with the highest power when you multiply all of the n^2 terms and since there are n-1 of them you get a power of n^2(n-1) = n^(2n-2)
and since all the n^2 terms have coefficient 1 this term has coefficient 1 too
solar tulip
oHHHH yeahhh ure super clear tyy
frigid rune
**Nathan\_**
so do you get where this comes from now?
solar tulip
yupp i get it
solar tulip
**Nathan\_**
then from here its jus 1/2
harsh girder
a simple way is using sandwich theorem
$$\frac{1+2+\dots+n}{n+n^2}<\frac{1}{1+n^2} + \frac{2}{2+n^2} + \dots + \frac{n}{n+n^2}<\frac{1+2+\dots+n}{1+n^2}$$
ocean sealBOT
秋水
frigid rune
a simple way is using sandwich theorem
$$\frac{1+2+\dots+n}{n+n^2}<\frac{1}{1+n^...
wow thats so much simpler :(
mortal trellis
oh, \dots is a thing
there is also $\cdots, \vdots, \ddots, \ldots$ and probably others
ocean sealBOT
Denascite
frigid rune
interesting, i assume the others are most useful in a matrix and i always screw up matricies in latex
frigid rune
sry do u mind explaining
are you familiar with the sandwitch theorem ( or as i know it the squeeze theorem )
solar tulip
nope :/
frigid rune
ah
well basically the idea is to find 2 functions that you know the limit must be between and and you can evaluate the limit for those 2 functions
so if you want to find the lim of f(x) and you know that g(x)<=f(x)<=h(x)
then you can find lim of g(x) = G and h(x) = H
so G <= lim of f(x) <= H
but if G=H then you have that G <= lim of f(x) <= G
so lim of f(x) must equal G
not sure if this is a good explanation or not, never tried explaining this to anyone before
solar tulip
well basically the idea is to find 2 functions that you know the limit must be b...
ohh i think i kinda get it
yeahh ure RLY good at explaining tysm soz im not a math student T_T just that a fren asked for help
frigid rune
**秋水**
so in this case you can choose these to functions
do you get why that inequality works?
solar tulip
so in this case you can choose these to functions
do you get why that inequality...
yup yup i understand
thankss 
frigid rune
np
solar tulip
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shell urchin
lone heartBOT
shell urchin
Statistics
I am not sure if I filled certain ones right or how to do the others?
lone heartBOT
@shell urchin Has your question been resolved?
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@shell urchin Has your question been resolved?
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@shell urchin Has your question been resolved?
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@shell urchin Has your question been resolved?
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@shell urchin Has your question been resolved?
edgy flare
What exactly are you needing help with? Can you pick a specific part to start with?
tacit arch
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patent cairn
Hi
patent cairn
How can I simplify this so that I'm left with y = whatever the rest is
I'm not trying to know what C is. I am just trying to get this organised so that I can rewrite the function as f(x) = whatever the rest is
alpine sable
Hi I'd like to ask for a demonstration on how to solve the surface area of a cylinder
alpine sable
please
tacit arch
patent cairn
Hi I'd like to ask for a demonstration on how to solve the surface area of a cyl...
Hi, if I'm not mistaken you are asking for this?
alpine sable
yes pls
patent cairn
Well, in that case, imagine you have a toilet paper roll and you cut it
The area of the rectangle you can form out of it is composed by it's height (let's call it h) and the length of the circumference
patent cairn
So what you are left with, it's h . dπ
patent cairn
i want to know how to calculate by net pls
by net?
alpine sable
by net?
like lets say the circle is 20cm
idk
and the rectangle is 10cm
and the other circle is 12cm
and i have to find surface area
patent cairn
Do you mean volume?
patent cairn
oh, do you mean like the area of the cylinder taking into account the "lids"?
alpine sable
and here they are telling us to calculate surface area hmph
alpine sable
oh, do you mean like the area of the cylinder taking into account the "lids"?
uh wdym
explain further pls
@patent cairn
like lets say i'm given a rectangle n circle with all the measurements
patent cairn
In that case is the height (h) times the length of the circumference, which is diameter times pi, + 2 times the area of the circle, which is pi times (radius ^2)
alpine sable
d=r2?
radius squared
oki
c is just double of d
got it
continue
pls
i could just try another shape like a triangular prism?
and just close this
patent cairn
alpine sable
i still don't get shit
ah i stg let me just find 1 more shape apart from a triangular prisim
then i can be done with this stupid homework
ig i can close this
patent cairn
no
alpine sable
thx for trying to help me @patent cairn
patent cairn
hold on
alpine sable
ok?
patent cairn
i'm genuinely confused... what do you have for homework?
alpine sable
i was never really born a natural at math
@patent cairn choose any 4 3D shapes find their surface area
alpine sable
i tried cylinder cuz everyone said it was easy
patent cairn
how about a cube? that should be fairly easy
alpine sable
so you chose a cylinder, a pyramid, anything else?
i chose a cube,cubiod triangular prism
no pyramid
not today
patent cairn
right now?
patent cairn
ok don't you worry, I will help you.
alpine sable
oh ya i also need to explain how manufacturers would use these shapes n their designs
7 pages word doc
patent cairn
Give me some minutes because I have to graph it all so that it is clear to you. If I'm not mistaken the main purpose of this server is to learn maths, I don't think I'm allowed to just send you the homework done
patent cairn
oh ya i also need to explain how manufacturers would use these shapes n their de...
nah u lost me there
patent cairn
what's your main language?
alpine sable
English
patent cairn
oh
alpine sable
i speak guju
but that's with cousins and shit
otherwise i prefer to avoid it
maybe i'd like to learn japanese
alpine sable
Give me some minutes because I have to graph it all so that it is clear to you. ...
oh ya it needs to be done using nets
and i can make up the measurements
just have to hand it in
patent cairn
oh ya it needs to be done using nets
Okie
alpine sable
wuts the easiest shapes for u to calculate surface area of?
patent cairn
A cube, which should be side^2 times 6
S^2 should give you the area of the square, multiply it by 6 and you would get the total superficial area
You choose a value for S
alpine sable
i'm already done with cube and cubiod
i told u this before those 2 are easy
tho thx for trying to teach me those
i can learn those easily
patent cairn
patent cairn
tho thx for trying to teach me those
I'm sorry, I didn't mean to underestimate you.
alpine sable
I'm sorry, I didn't mean to underestimate you.
i didn't take it as that
i just took it as
'repeating stuff we've already covered'
which is pointless
@patent cairn anyways u can try teach me something else
like a sphere?
or a cone maybe?
patent cairn
alpine sable
triangular prisim
patent cairn
h being the height, b the base of the triangle
alpine sable
yes
patent cairn
So, only one left?
alpine sable
yes yes
patent cairn
why does numbers?
alpine sable
r2
patent cairn
those
patent cairn
22/7 I believe is just a way of aproximating pi
alpine sable
ik
maybe try teaching me something simpler like a cone?
or i think we're done here?
@patent cairn
patent cairn
maybe try teaching me something simpler like a cone?
simpler like a cone? ._.
I'm sorry I don't know how ehhah
patent cairn
nice meeting u too
alpine sable
and u tutoring meh
lmao uwu i am hopeless for maths
at least i almost got 70 on my last exam
69 😐
anyways later
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lone heartBOT
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Available help channel!
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tacit arch
Show your work
weary wyvern
$\sqrt{x^2} \neq x$
ocean sealBOT
giannis_money
tacit arch
Try it for any negative x
weary wyvern
square a negative number then take its square root
tight locust
What is (-1)^2
weary wyvern
square a negative number then take its square root
obviously
tight locust
What is sqrt(1)
So what is sqrt((-1)^2)
Really?
You just told me that (-1)^2 is 1
And that sqrt(1) is 1
So how is sqrt((-1)^2) = -1
tacit arch
So what is sqrt((-1)^2)
Plug this into your calculator @timid edge
tight locust
Thats the thing
Order of operations matters
The square root function is not a perfect inverse
alpine sable
Shi man was it like that I d be happy
Given lim x-0 f(X)/X=5
Find lim x-0 f(f(X))/f(X)
Yeah sure👍
weary wyvern
@timid edge if x is positive what's sqrt(x^2)?
yes
and if x is negative?
wrong
play with examples of doing this with negative x
tight locust
Shi man was it like that I d be happy
Given lim x-0 f(X)/X=5
Find lim x-0 f(f(X)...
f(5)
alpine sable
Alr, I ll have that as my answer, I just can't figure out the way to solve it, Ty nonetheles
I think √x^2 is equal to |x|
In the end it must be either positive or 0
Yes
alpine sable
lone heartBOT
alpine sable
Do I just divide with X on dominator and denominator?
I can't figure out a way to solve this
proper urchin
icy crescent
lone heartBOT
wary stream
What did you try?
icy crescent
$\frac{2}{\sqrt{x}} - \frac{3}{2x}$
ocean sealBOT
androo
icy crescent
this what i got
wary stream
Okay, and what's the issue?
icy crescent
is it correct?
wary stream
There are online derivative calculators, in which you can use to check your answer
icy crescent
its for a problem set and when i entered it in it says its wrong
glossy temple
Yeah sorry
last ether
I think you have eyes to see that there's someone here who needed help first
last ether
You computed the derivative of the second term incorrectly; use the reciprocal rule
wary stream
$\frac{2}{\sqrt{x}} - \frac{3}{2x}$
And fyi, g'(x) doesn't mean $\frac{3}{\text{d/dx } x^2}$
ocean sealBOT
dldh06
wary stream
Close enough
last ether
Let $C$ be a constant (therefore a coefficient):
$$\frac{d}{dx}\frac{C}{f(x)} = \frac{-Cf'(x)}{[f(x)]^2}$$
ocean sealBOT
Umbraleviathan
wary stream
It means you don't take the derivative of just the denominator
Fyi, if you wanted to, you can apply product rule, by applying this concept, $a^{-x} = \frac{1}{a^x}$
ocean sealBOT
dldh06
last ether
You could also do that. I just like using reciprocal rule. Personal preference towards either
wary stream
You could also do that. I just like using reciprocal rule. Personal preference...
Reciprocal rule as in quotient rule?
last ether
Reciprocal rule as in quotient rule?
It's just a specific case of quotient rule
icy crescent
course hasnt covered reciprocal rule yet il just use the product rule ty
wary stream
It's just a specific case of quotient rule
As Umbraleviathan mentioned
last ether
**Umbraleviathan**
And it's right here
Riemann hi
FUCJ
Shit
This is not the gd server
Wrong server lol
I almost sent a random video lol
Okay well apart from my near fiasco, you can use power rule
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Available help channel!
azure bison
Water is being let out of a cylindrical tank of radius 10 feet. If the depth of the water in the tank is decreasing at the rate of 3 feet per second. How quickly is the amount of water decreasing at the instant the depth is five feet?
azure bison
Its most probably vertical
prime badge
they obviously mean it's horizontal
azure bison
I have to solve using derivatives but I have no idea
I think in english its called rate of change
The subject
prime badge
if it's not standing upright, you can't exactly solve it, because then the height matters
azure bison
What confuses me is why I need the radius if its asking for depth
prime badge
but if it's standing, then the current depth is irrelevant
i've no idea btw, i'm not typing anything
azure bison
fk
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azure bison
<@&286206848099549185>
lavish pier
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lavish pier
just for ii my teacher forget the answer sheet so can someone give me their answer to double check if imcorrect
i got 67.21
wary stream
i got 67.21
Post work
lavish pier
wary stream
,rotate
ocean sealBOT
wary stream
You realize that the angle is 34 degrees and not 32, which is what you wrote down
But correct process
wary stream
Yes
edgy sail
👍
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