or are you intending to plot the solutions of this inequality on a graph?
#help-0
vale wigeon
dreamy shoal
Is it possible to find the minimal and maximal values of both X and W?
I want the expression to have the lowest possible value given X and W are integers
vale wigeon
anyway let's see here
i'd start by doing some cleanup
$\frac{2wx - 2x^2}{w^2} + \frac{2x}{w} - \frac{4x^2}{w^2} = \frac{2wx - 2x^2 - 2wx - 4x^2}{w^2} = -\frac{2x^2}{w^2}$
ocean sealBOT
Ann
lone heartBOT
@dreamy shoal Has your question been resolved?
vale wigeon
i think this expression has no minimum even if x and w are required to be integers
just take x = whatever and w = 1
you can make it go to minus infinity
dreamy shoal
the minimum above 0
ocean sealBOT
Uri
lone heartBOT
@dreamy shoal Has your question been resolved?
mortal trellis
the second 2wx term should be positive. so the sum is (4wx-2x^2)/w^2
vale wigeon
oh my bad
lament basalt
Help
lament basalt
About the right triangles
Since it composes of 180 degrees
What's also the standard measurement of its sides?
wanton nova
it doesnt have one
raven dagger
The sides can vary with the other 2 angles
wanton nova
i dont exactly understand the question
lament basalt
i dont exactly understand the question
The measurements of sides
stone glen
The maximum perimeter of a triangle ?
lament basalt
What's the standard measurements of right triangle's sides? (like is it 1?)
1 for each sides?
wanton nova
still dont get it
clear crow
do you mean like in proportion to each other?
wanton nova
what does standard measurement mean
lament basalt
what does standard measurement mean
No what I mean is
Does right triangle's sides have numbers?
wanton nova
yes
lament basalt
Is it 1 for each sides?
flat ore
the answer to your question is no
wanton nova
they cant all be 1
stone glen
It could be in any ratio, there are infinite no. Of them
lament basalt
Ohhh I see
stone glen
I think there are infite right?
wanton nova
yes
flat ore
yes
flat ore
btw not just right triangles, in all triangles the angles add up to 180deg
stone glen
Dharmann with Eminem tf?
"kid makes fun of dharmann on discord, lives to regret it"
lament basalt
Bcs I need to find the reference angle of 960 degrees (which is 60 degrees)
And the circular functions
No given number for a right triangle's side at least
wanton nova
So you see...
lament basalt
We're not just telling stories
lament basalt
Bcs I need to find the reference angle of 960 degrees (which is 60 degrees)
And ...
We're solving math too! 
So yeah idk how to find this out
lament basalt
https://tenor.com/view/dhar-mann-so-you-see-gif-23268701
We're not just telling stories
We're in need of how to solve the problem 😅
wanton nova
lament basalt
Bcs I need to find the reference angle of 960 degrees (which is 60 degrees)
And ...
I don't know how to solve this without given values of a right triangle's side at least
.close
lone heartBOT
lone heartBOT
Available help channel!
echo shoal
Can someone explain to me the goniometric equations
lone heartBOT
Can someone explain to me the goniometric equations
echo shoal
I have no idea what that is and how it work
I have like cos(2x)=0.35 and need to find u1 and u2 in L={[0;2pi[}
lone heartBOT
@echo shoal Has your question been resolved?
echo shoal
<@&286206848099549185> 
sleek cargo
I have like cos(2x)=0.35 and need to find u1 and u2 in L={[0;2pi[}
oooh so you are looking for roots i guess
sleek cargo
what do you mean by u1 and u2
hybrid zenith
Goniometeic = trig
So I think they are asking for multiple solutions to an equation (e.g. Cos2x=. 35) within 0 to 2pi
lone heartBOT
@echo shoal Has your question been resolved?
echo shoal
Goniometeic = trig
So I think they are asking for multiple solutions to an equat...
Yes
There are 2 solutions
hybrid zenith
Only 2? I see 4 on the graph
lone heartBOT
@echo shoal Has your question been resolved?
echo shoal
Only 2? I see 4 on the graph
Should be just 2
hybrid zenith
but dont forget your finding soultions for cos2x
so if you write y=2x
cos(y)= 0.35 in the range 0 to 4pi
then half the solutions
you obtain 4 not 2?
fiery adder
what does the preimage of a noninjective function look like
lone heartBOT
what does the preimage of a noninjective function look like
fiery adder
looking at this
given A_0, f(A_0) is a subset of B that is the image of A under f, call it B_i
then f^-1(B_i) is the preimage of B_i (i.e. all the elements of A that map to B_i)... but isn't that all of A_0?
im failing to see how it would ever not be equal
also ann contradicted me on this before but doesnt a function need to be bijective for f^-1 to exist in the first place
<@&286206848099549185>
vale crag
im failing to see how it would ever not be equal
let's take an extreme example
imagine I have the function f : N -> {1}, such that f(n) = 1, for all n positive integer
vale crag
you can probably see how you can pretty much take any A_0 and the equality will not hold
vale crag
what i dont get is f^-1({1})
well which elements of **N ** map to 1 (through f)?
fiery adder
all of them
fiery adder
then is it cuz it's not necessarily equal
like the preimage could be N but it could also be {1,2,3}
or any subset of N for that matter
vale crag
well the preimage of {1} is N (by f)
there's no hypothetical here
I guess you're trying to say something else though
fiery adder
OH wait
vale crag
which is pretty much what you're trying to prove
vale crag
yeah that's why there's the inclusion in the question
f^-1(f(A_0)) could be equal to A_0
but it's generally bigger
if your function is not injective it screws with everything
fiery adder
will try and formalize and post here in a moment 
can equality hold even if there isn't injectivity?
actually yeah that's obvious
take the subset of N that is all of N 
vale crag
yeah lol ^^
fiery adder
part of my mistake was thinking of it as an iff
ok i definitely understand it but i can't seem to formalize it 
can i argue that the preimage of the image will never be a subset of A_0, so it must be either equal or a superset of A_0
@vale crag sorry 4 ping just wanna double check 👉 👈
vale crag
<@177516015033384960> sorry 4 ping just wanna double check 👉 👈
I'm not really sure how you get to the contradiction
and your idea of proof doesn't sound that great to begin with
fiery adder
i didnt think so tbh
vale crag
like excluding the fact that you're a subset doesn't mean that you're automatically equal or super
fiery adder
oh woops
vale crag
you could have a set which, starting from A_0, take one element off, and add one element out of A_0
that's neither a subset or a superset of A_0
but there's a direct proof for that
fiery adder
ah i see
vale crag
let's just do the ole "what's the definition of inclusion?" proof
fiery adder
a \in A_0 implies a \in preimage of image
fiery adder
but then it kinda just ends up being "by definition" doesnt it
vale crag
it's always by definition
I mean in beginning undergrad or before it's pretty much true
fiery adder
it's just an early exercise in munkres that stumped bc i was overcomplicating
vale crag
the ole munkres book
why does discord keep recommending me pictures as I type?
what a shitty new feature
literally had a little popup like "hey you wanna put a picture of munkres' book"
fiery adder
it's the stickers on the right
vale crag
yah
fiery adder
vale crag
I get it at least
fiery adder
i gotta practice not overthinking things
fiery adder
that's just showing that the preimage of the image if a subset of A_0 in the injective casse
will formalize
lone heartBOT
still dont know this 💀
prime badge
you can't tell a+b from this
alpine sable
I tried but i have no idea if this makes any sense at all
gray isle
you can't tell a+b from this
unless there's some important info that's being conveniently omitted
alpine sable
> you can't tell a+b from this
Hmm yea i guessed so but umm can you tell me why what i did doesn't make sense/work
prime badge
you somehow got "a − ab = 31/a", should be a − b = 31/a
gray isle
well you have 2 variables and only one equation
alpine sable
you somehow got "a − ab = 31/a", should be a − b = 31/a
Hmm wouldn't the minus go to the other side alongisde the a
gray isle
under normal circumstances, you can't get unique solutions
alpine sable
Hmm wouldn't the minus go to the other side alongisde the a
So it'd be like a + b = 31/a ÷ -a
gray isle
there are infinitely many ordered pairs / solutions to a(a-b) = 31
and there'd be infinitely many possible values to a+b
alpine sable
Oh so it's just impossible to actually get a proper answer with it(?)
gray isle
that's what i said
lone heartBOT
@iron parcel Has your question been resolved?
vestal quartz
Idk how to find A and B
lone heartBOT
lone heartBOT
Available help channel!
queen lodge
What is the graph of greatest integer of 1-(x²/4)
lone heartBOT
What is the graph of greatest integer of 1-(x²/4)
balmy warren
wdym graph of greatest integer
do you mean the graph
or find the greatest integer
queen lodge
Graph
queen lodge
wanton nova
,rotate
ocean sealBOT
swift shore
Wdym
worn fox
Use some more words
balmy warren
search it up
gray isle
the floor function is an alternate name for the greatest integer function
gray isle
Then redraw w floor
after you have that
terse oak
x(t) = sin(5πt)
x(n) = sin(5πn)```
do both of these signals have the same period `2/5`
first is continuos time signal and second is discrete time signalyes
terse oak
sure?
terse oak
being discrete valued function has no effect?
terse oak
-infinity < t < infinity , n belongs to integer
queen lodge
Yes
balmy warren
so you need to multiply by 5
terse oak
2?
balmy warren
yes
I think so
might need to check with someone
but I am 90% sure
basically you first set 5pin = 2pi
then solve for n
which is 2/5
but the fundamental frequency is an integer
so you need to multiply by the denominator
I think that's how it works
but not too sure
sorry I can't be of more help
terse oak
i understand what u r saying
queen lodge
which is 2/5
True
queen lodge
As 2pie is the period
terse oak
```c
x(t) = sin(5πt)
x(n) = sin(5πn)```
do both of these signals have the same p...
is this false then?
both signals dont have a period of 2/5 ?
sullen agate
is this false then?
yes
queen lodge
Both have same period
terse oak
being discrete valued function has no effect?
@queen lodge ?
queen lodge
Period of sin5πn is 2/5
terse oak
i guess u dont know bout discrete valued functions
queen lodge
They do effect i think
As sin x has period of 2π it doesn't mean that if you muntiply any constant with it will have same period
If you add something with x then it will have same period
But if you muntiply or divided it will change
balmy warren
As 2pie is the period
2pi is not the period
queen lodge
2pi is not the period
I was saying about sin x
balmy warren
oh ok
@queen lodge discrete and continous are different
you can't just treat them the same
@terse oak I think it is 2 but yeah as I said I'm 90% sure. I've only ever come across them once and that was a while ago
terse oak
lone heartBOT
terse oak
answer will be infinity?
placid zinc
This is an interesting limit if T approaches 0. Is it possible that it's supposed to?
If T approaches inf, then yeah this goes to inf
keen pasture
e approaches Infinity 😂
terse oak
Sin(5pi*n)
What will be the period of this signal if n is integer
lone heartBOT
@terse oak Has your question been resolved?
terse oak
https://www.mathsisfun.com/algebra/amplitude-period-frequency-phase-shift.html
but it is discrete
so it will be equal to zero
if n is integer
even then will it be periodic?
if yes, the period?
tacit arch
even then will it be periodic?
Try plugging in small values of n and find a pattern
terse oak
Try plugging in small values of n and find a pattern
for every value of n answer will be zero
no?
as sin (pi*n) = 0
keen pasture
Yes
lone heartBOT
@terse oak Has your question been resolved?
keen basin
Hello
keen basin
if I have this formula y(x) = 3 sen (2x)
Amplitude is 3
Frequency is 2
and it says Period is PI
Why?
T = 1 / f
right?
but how the answer is pi
lol
how 1 / 2 is = pi
keen basin
hmm
So let me try
P = 2pi/2
ohh
Let me try the second
P = 2pi/0,2
ohhh
it works!
keen bear
there you go. Makes sense now?
keen bear
yep, just remember that the normal period is 2pi
keen basin
ok!
keen bear
so you divide your normal period by the frequency
keen basin
so you divide your normal period by the frequency
if I want to find F it would be F = 2pi/t ?
keen bear
try it and see if it works going backwards
lone heartBOT
@keen basin Has your question been resolved?
lone heartBOT
Can someone please help me with my exam preperation
mild matrix
I do not understand this question and I think it will be on the test
It is grade 9 math
I understand how to find the individual areas, but I am unsure how to find the perimeters.
limpid spade
Sum of the sides
drowsy willow
what perimeter do u not know
mild matrix
Since its a triangle for A1
mild matrix
Yes
drowsy willow
idk he's in public school?
mild matrix
I am
clear stump
you can count the squares
drowsy willow
he wants perimeter
drowsy willow
1+1+root 2
limpid spade
Pyrhagoras
drowsy willow
the slant is root 2
mild matrix
Hypotenuse
Ok let me write that down
Let me write 1.414
One decimal place
Oh
1.4
A2
Is a trapezoid
drowsy willow
yes
drowsy willow
a+b+c?
drowsy willow
there are 2 slants this time
drowsy willow
each are root 2
mild matrix
Sir yes sir
drowsy willow
u learned pythagorean theorem?
drowsy willow
yeah
mild matrix
so 2.8 for both slants
limpid spade
By counting
drowsy willow
the other sides of the trapezoid
drowsy willow
yeah
mild matrix
Is that all for A2
drowsy willow
dude are you doing part 2 of the question
drowsy willow
if so, the lines in the INTERIOR of the shape do NOT count
drowsy willow
its just the outside part
mild matrix
Not 2.8 + 2 + 4?
drowsy willow
u only need to count the lines that are outside of the shape
clear stump
the trapezoid is just 1+2\sqrt{2}
mild matrix
For perimeter?
clear stump
the ones needed for this
mild matrix
So
mild matrix
Yes sir
drowsy willow
for the perimeter of the figure
mild matrix
The lenght around
drowsy willow
The lenght around
exactly
drowsy willow
yeah
clear stump
well yes but no
drowsy willow
but one side is inside the figure
mild matrix
Oh
limpid spade
Yesnt
drowsy willow
so youdont need to count that side
drowsy willow
yes
drowsy willow
lines inside the figure remember
drowsy willow
2.8 + 2 + 4 + 1
no
clear stump
no
mild matrix
.
clear stump
there are 2 slipes and 1 straight bit
mild matrix
Yes
drowsy willow
2.8+1
drowsy willow
theres only 1 side that is not the sland that is outside
clear stump
You can just count the squares that you see
mild matrix
Oh
clear stump
well that is the perimeter of A3 yes but we are looking for the perimeter of the whole thing that was made with the shapes
clear stump
yes but no
clear stump
how many of them are next to white squares
clear stump
yes
clear stump
yes
clear stump
yes
clear stump
so
mild matrix
pie x 0.5?
clear stump
the circumference(C) is $c=2\pi r$
ocean sealBOT
.,..
mild matrix
Yes
clear stump
that circumference is in 4 squares and we only need 3 of them
mild matrix
C = 2 pie r
Yes
we divide our result by 0.75
or multiply then subtract
Ok
So
C = 2 Pi R
R = ?
clear stump
we dont divide by 0.75
mild matrix
Oh
clear stump
how do we get the circumference of 3/4 of the circle
mild matrix
We have to
Uh
We have to
Well
We would need to multiply 3/4 by our result
3 x result / 4
I think
clear stump
so we get $\frac{6\pi r}{4}$
mild matrix
Yes
ocean sealBOT
.,..
clear stump
now cause we got two of em bitches we can multiply this by 2 giving us
mild matrix
Yes sir
clear stump
$\frac{12\pi r}{4}$
mild matrix
🤣
ocean sealBOT
.,..
clear stump
so its just 3pi r
mild matrix
12 x pi
clear stump
what about it
mild matrix
37.68 x radius / 4
clear stump
whats 12/3
mild matrix
4
clear stump
I mean 12/4
mild matrix
3
mild matrix
Simplify
clear stump
we get $3\pi r$
ocean sealBOT
.,..
clear stump
radius
mild matrix
What is the radisu
clear stump
yes
clear stump
how do you figure that
clear stump
explain
mild matrix
radius = 1
clear stump
yes
clear stump
btw * is used for multiplication instead of x
clear stump
you dont need to do it individually
clear stump
y
mild matrix
K
y is in why or y as in yes
Anyways
Since we got everything
The total perimiter is
2.4 + 3.8 + 6 + 4.7 + 4.7
Perimeter is 21.6
clear stump
cool
topaz scaffold
prime badge
i wouldn't say ambiguous, it's more like hard
i'm struggling
oh
one marble
pshew
definitely 10!/4!2!3!
i'm sure
that's the point of having colors, you have to ignore that they have matching colors to get 10!
no
it's indeed ambiguous, but there's no reason to pick the one that makes less sense
sometimes problems have blatant red herrings
but this should be treated as relevant information
yep
there's a simple reason it can;t be that
because it means 1 way of distributing if you do that
if you disregard colors, what else is left
no
then you introduce difference between marbles
after deliberately ignoring difference that was given
that's messed up
okay
finite flax
wouldn't the mean and standard deviation be on your cheat sheet for distributions?
the mean would be the expected value
standard deviation, the square root of variance
ok, then we want to use the...theorem...what's it called...that makes binomial distributions approximately normal
me neither
but I did it
I think
$z_{x} =\frac{x - \bar{x}}{s}$
ocean sealBOT
Disorganized
finite flax
this is not official notation.
I've only ever seen z scores using population means and standard deviations
but whatever
$z_{340} = \frac{340-360}{16.5408585} = -1.209127084$
ocean sealBOT
Disorganized
finite flax
$z_{390} = \frac{390-360}{16.5408585} = 1.813690625$
ocean sealBOT
Disorganized
finite flax
then I looked these values up in the z-table (left sided)
I forget this notation especially
but
$z_{340} \Rightarrow 0.0985\
z_{390} \Rightarrow 0.9649$
ocean sealBOT
Disorganized
finite flax
subtracting those
got 0.8664
to get the space between the x-values
which is the probability that x is between these values
are you able to check the solution?
hopefully?
I mean it does, to the nearest percent...
well I mean I didn't mess up any arithmetic
I just wondering if we're using the correct formulas
we should get a stats guy in here
<@&286206848099549185>
yeah let me know so I can better myself
$\Phi (z_x) = \text{the decimal that comes from the table, associated with the z-score}$
ocean sealBOT
Disorganized
finite flax
this is the notation I recall that maps a z-score to the percent of the normal distribution to the left of that position
the x-value gets mapped onto a normalized bell curve, and that mapping is the z-score
so...I at least remember that
the subtraction I was doing was subtracting the areas under the curve, which left me with the area between the normalized values
...which is the same as it would be between the original statistics, 360 and 390
tidal zealot
lone heartBOT
tidal zealot
can someone do this
i already know how to do it
i just wanna see if the solutions are wrong
bcs i got a different answer to the solution
tacit arch
just show your work and someone can look.
tidal zealot
tacit arch
Did you round too early
lone heartBOT
@tidal zealot Has your question been resolved?
tidal zealot
Yeh but what does that have to do with it being minus ?
but in other questions
i didnt have to doi -0.5
why specifically for this question
what makes it different
can i just leave it as 0.7673
alright
thanks
.close
halcyon tartan
lone heartBOT
chrome salmon
Is that 34?
halcyon tartan
it’s 30
chrome salmon
Take log_10 both sides
crude rose
chrome salmon
It's days
halcyon tartan
i dont actually know how this works
i just need to know what Y is gonna be
is there a formula for this type of situation that i can use for further calculations?
chrome salmon
You can take log
halcyon tartan
i don’t know how to do that
nimble holly
use this property
ocean sealBOT
Ji
halcyon tartan
can you provide the answer based on my numbers with this property?
halcyon tartan
i’m not familiar with the term ‘log’ here. how is it used in the calculation?
chrome salmon
i’m not familiar with the term ‘log’ here. how is it used in the calculation?
Are you using a calculator
nimble holly
waitt isn't it just taking sqr 30 both sides?
halcyon tartan
Are you using a calculator
i was trying to come up with the answer on paper but now saw the ‘Log’ in the calculator so lets give it a shot
chrome salmon
i was trying to come up with the answer on paper but now saw the ‘Log’ in the ca...
Even using that it needs calculator
chrome salmon
waitt isn't it just taking sqr 30 both sides?
So if we have y³⁰ = 10⁶ shall we divide by 6?
halcyon tartan
So if we have y³⁰ = 10⁶ shall we divide by 6?
i remember teacher explaining this before i dropped out. still didn’t learn
halcyon tartan
so is it like y = 1.58
nimble holly
$a^{\frac{m}{n}}=\sqrt[n]{a^{m}}$
ocean sealBOT
Ji
nimble holly
so is it like y = 1.58
yeahh
chrome salmon
The man the myth the legend
halcyon tartan
the fäf the problem solver
nimble holly
no
halcyon tartan
.close
lone heartBOT
nimble holly
dont use 1.58
halcyon tartan
shi-
halcyon tartan
its alright i wanted an estimated answer
nimble holly
alrightt
halcyon tartan
tysm
last ether
Is this homework
fiery pike
Yeah
drowsy willow
yes it is correct @pliant mural
small swift
lone heartBOT
https://gyazo.com/6d93e88a347fcc905aea9057cfa2ed72
small swift
Hello why is my answer for part c incorrect?
abstract fractal
Try plugging in x = 0 in your equation
small swift
uhm 1 sec gotta find camera
well i got c = 72
and then I did
2y^2 = 72 + 1/2 * x^2
i then divide by 2 and sqrt
small swift
i did sqrt over whole
so sqrt(72 + 1/2 * x^2)
plus w/ this if you plug in x = 0
you don't get -6
small swift
i see
ashen pulsar
Hi
simple turtle
Can someone help me come up with an equation for this
I can help. what part you do not understand?
lone heartBOT
@ashen pulsar Has your question been resolved?
ashen pulsar
I can help. what part you do not understand?
Idk how to write an equation
That regards the problem
lone heartBOT
lone heartBOT
Available help channel!
simple turtle
you have to find LWH
lone heartBOT
you have to find LWH
ashen pulsar
you have to find LWH
Yes
simple turtle
@ashen pulsar You accidentally closed but we can talk here
ashen pulsar
But there’s no height?
ashen pulsar
<@384379703097819138> You accidentally closed but we can talk here
Oh ya my bad
simple turtle
Height is x
If you have a piece of paper and cut the four corners and make a box and look at it. the height is x
the corners you cut
simple turtle
so you can say that W = 24-2x
ashen pulsar
L is 48-2x?
simple turtle
correct
ashen pulsar
It also says
determine x so that the box has a volume. of 1800 cubic inches
How would I solve for x
simple turtle
then set that equation equal to 1800
ashen pulsar
Ya
But how I get x by itself
Also I think there’s more than 1 answer so idrk what to do
ashen pulsar
Multiply the factors?
ashen pulsar
Yes
simple turtle
yes to both?
ashen pulsar
Do I c where they intersect?
ashen pulsar
yes to both?
I can use calc but it’s precalc
ocean sealBOT
ashen pulsar
There’s 3 possible answers?
simple turtle
good, you can graph it as it is. Yes there are possible answers
simple turtle
graph it see where is the highest
I forgot how to use ti to find max. here is some instruction. It is for quadratic, but works the same
2) Press [GRAPH] to graph the parabola.
3) Press [2nd] [TRACE] [4] to select the "maximum" command from the CALC menu.
4) The handheld will prompt for a "Left Bound." Using the arrow keys, move the cursor to the left side of the function (past the maximum
point) and press [ENTER].
https://education.ti.com/en/customer-support/knowledge-base/ti-83-84-plus-family/product-usage/34845
Also, here is an example of extrema. for cube function
@ashen pulsar can I close this now?
.close
lone heartBOT
lone heartBOT
Available help channel!
ember wave
Question:
ember wave
Not sure where to really start (solve for x)
ember wave
Wait is that allowed?
gray ingot
then factor a (x+5)^1/3
gray ingot
Wait is that allowed?
yes
ember wave
Oop I thought you couldn’t do that because it could be like removing a possibility
gray ingot
if you have a fraction $\frac{a}{b}$ then it can only be 0 if the numerator is 0
ember wave
Oh okok
gray ingot
Oop I thought you couldn’t do that because it could be like removing a possibili...
x can't be 0 in the first place so its not removing any possibilities
gray ingot
$\frac{4}{3}x(x+5)^{1/3} - (x+5)^{4/3} \
= \frac{4}{3}x(x+5)^{1/3} - (x+5)(x+5)^{1/3} \
= (x+5)^{1/3}\left(\frac{4}{3}x - (x+5)\right)$
gray ingot
@ember wave ^
ocean sealBOT
ocean sealBOT
ember wave
.close
alpine sable
Hi, I'm reviewing for a quiz and trying to differentiate this function. I've tried this many times and compared answers with WolframAlpha derivative calculator and keep getting different answers.... (I've checked the alternate forms too it all seems different)
If someone could show me the step-by-step solutions that usually is the best way for me to understand a question but any help at all would be appreciated.
alpine sable
I got f'(x) = [3xsin(2x) - 8(sinx)^2(cosx)^2] / x^3
It should be x^4
Or is that after simplification
After simplification
I cancelled one x out
You know the product rule?
Yeah I could send a picture of the work I did?
Maybe I'm making a stupid mistake somewhere one sec Ill send the work
Go ahead
elder grail
Hi, I'm reviewing for a quiz and trying to differentiate this function. I've tri...
do u notice that 4sin^2x cos^2x = (2sinxcosx)^2?
alpine sable
O,o I didn't notice that no
elder grail
might save some effort
alpine sable
Okay gonna give it another shot
ok so this is the answer I want to get
somehow IM getting that
:/
elder grail
looks correct
elder grail
ok so this is the answer I want to get
so u mean u want it in this form?
elder grail
just take 2 in
elder grail
and use 2cos^2(2x)-1 = cos4x
alpine sable
Thank u so much
elder grail
lol
alpine sable
Thank you :)))
elder grail
np
lone heartBOT
sullen agate
rank is 2
and yes it has 2 variables
yeah
it's rank is 2 too
it has infinitely many solutions because you can take any value of x
you only know that y=-18 and z=-12
?
r is the number of columns which has 1 as a leading number
and whole column is not full of zeros
n is the total number of columns
though I suggest you to not remember this as it may cause confusion later on
for determining rank or for checking the solutions ?
wait let me explain
in the 3rd row
you are getting 0=1 on solving
unfortunately, I don't know any other method for finding rank other than the standard method in which you have to find the ref and then check for the no. of non zero rows or columns
no
rank is 2 yeahh sorry
sorry I didn't get you
yes
yeah
basically yeah
well you will have to convert it into an ref first before checking any of these
practice and clear all your doubts🤷♂️
lone heartBOT
@acoustic plover Has your question been resolved?
north adder
.close
magic anchor
I've gotten the answer but misread the power and i've gotten to many different answers, im a bit lost on this one
north adder
I've gotten the answer but misread the power and i've gotten to many different a...
whats the answer and what is your answer
magic anchor
The answer i had was 52cm but I accident had used ^2 not ^3
north adder
The answer i had was 52cm but I accident had used ^2 not ^3
wdym ^2 not ^3?
magic anchor
the question is saying the mass of the fish directly proportional to the cube of the length, I missread that and used power of 2 instead of power of 3, but after retrying it i got like 4 different answers, sorry for the bad explanation
north adder
no worries
north adder
I've gotten the answer but misread the power and i've gotten to many different a...
should be 45240 cm^3
I think its 35.63205462....
magic anchor
aaah nice, do you mind me asking what formula you used? just so i know for next time
north adder
aaah nice, do you mind me asking what formula you used? just so i know for next ...
Sure
so I knew that the mass = constant x length^3
since they are proportional
nvm
i mightve
did it wrong D:
magic anchor
oh
north adder
so I knew that the mass = constant x length^3
this is the correct conept tho
magic anchor
I used D=KX
north adder
what do those variables represent?