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1 messages · Page 1026 of 1

slim iron
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so should i do log4782969/-log3 and use the absolute value of the answer as the exponent?

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wair my calculator wasnt working

alpine sable
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In that case

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n will be a complex number

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Powers of negative number cannot be represent with real numbers unless their exponent is an integer

slim iron
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hmm, i see

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thanks for the input, i think i got it figured out though

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.close

lone heartBOT
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wanton nova
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@daring reef

lone heartBOT
wanton nova
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Hi

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You can ask your question here

daring reef
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i got it

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you could close this

wanton nova
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Ok

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.close

lone heartBOT
#
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daring reef
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thank you for the help

wanton nova
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Np

lone heartBOT
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lone heartBOT
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terse smelt
lone heartBOT
terse smelt
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I drew the diagram for q2

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How do I proove it simmilar

lone heartBOT
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@terse smelt Has your question been resolved?

terse smelt
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<@&286206848099549185>

icy crane
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wat is L

lime vine
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for b)

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this is the solution

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This is for a)

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similar thing

lone heartBOT
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@terse smelt Has your question been resolved?

lone heartBOT
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ashen pulsar
lone heartBOT
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Please don't occupy multiple help channels.

alpine sable
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$\ln (x+1) - \ln (x-2) = \ln x$

$e^{\ln (x+1) - \ln (x-2)} = e^{\ln x}$

$\frac{e^{\ln (x+1)}}{e^{\ln (x-2)}} = e^{\ln x}$

$\frac{x+1}{x-2} = x$

$x^2 -3x - 1 = 0$

ocean sealBOT
#

Yustina

alpine sable
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,w x^2 - 3x - 1 = 0

ashen pulsar
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it would be a right

neat sierra
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Or you can similarly use ln(a) - ln(b) = ln(a/b). You'd get the same result

ashen pulsar
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would the negative solution

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be extraneous

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@neat sierra

last ether
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Wait

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Isn't there an easier way

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You can factor ln(x) out

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I guess it works both ways

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You would still get the quadratic

ashen pulsar
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but would there be an extraneous solution

last ether
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Well you can try plugging it in and see if it's true

ashen pulsar
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can someone help with this

last ether
last ether
ashen pulsar
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idk how to

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😭

last ether
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$$3\log\left(2a\right)-\log\left(2a\right)$$
$$\log\left(\left(2a\right)^{3}\right)-\log\left(2a\right)$$
$$\log\left(\frac{\left(2a\right)^{3}}{2a}\right)$$
$$\log\left(\left(2a\right)^{2}\right)$$

ocean sealBOT
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Umbraleviathan

last ether
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thats for the lefthand side

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you understand what I did there?

ashen pulsar
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sorta

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where would i go from there

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cancel the log out?

last ether
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Yeah

last ether
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which line specifically?

ashen pulsar
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ohhhhh

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i looked at my notrs and i get it

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but for some reason my answer isnt on there

last ether
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lets see

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$$3\log\left(2a\right)-\log\left(2a\right)=\log\left(11a+3\right)$$
$$\log\left(\left(2a\right)^{3}\right)-\log\left(2a\right)=\log\left(11a+3\right)$$
$$\log\left(\frac{\left(2a\right)^{3}}{2a}\right)=\log\left(11a+3\right)$$
$$\log\left(\left(2a\right)^{2}\right)=\log\left(11a+3\right)$$
$$4a^{2}=11a+3$$
$$4a^2-11a-3=0$$

Check extraneous solutions

ocean sealBOT
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Umbraleviathan

ashen pulsar
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tysm

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can. uhelp me with this

last ether
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Im not good with compounded stuff

ashen pulsar
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shoot

last ether
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Lemme see

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If I can remember

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$$A = I\left(1+\frac{r}{12}\right)^{12t}$$

$A$ is the amount, $I$ is the initial value (deposit), $r$ is the interest rate as a decimal, $t$ is time in years

ocean sealBOT
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Umbraleviathan

last ether
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@ashen pulsar

ashen pulsar
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what do i do from here

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@last ether

last ether
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Plug in the information given to you

ashen pulsar
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whats rate

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would it be 1.085

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or 0.0085

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nvm

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why is r divided by 12 there

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@last ether

last ether
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It's just the formula

ashen pulsar
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whats the original formula

last ether
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I don't know jackshit about finances lol

ashen pulsar
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im so lost

last ether
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$$A = I\left(1+\frac{r}{k}\right)^{kt}$$

$A$ is the amount, $I$ is the initial value (deposit), $r$ is the interest rate as a decimal, $t$ is time in years, $k$ is the frequency of compounding

ashen pulsar
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this due in one hour

ocean sealBOT
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Umbraleviathan

ashen pulsar
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im stressing out

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@last ether what do u think the asnwer would be

last ether
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Plug it in.

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What was the initial deposit Carlos made

lone heartBOT
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@ashen pulsar Has your question been resolved?

ashen pulsar
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@last ether

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can u help me with this

last ether
ashen pulsar
last ether
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Ope

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Is this a quiz or something

ashen pulsar
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yes

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its open notes tho

last ether
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Uhh

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I guess you can use logarithmic regression on your calculator

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But I gotta sleep

ashen pulsar
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oh ya

lone heartBOT
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@ashen pulsar Has your question been resolved?

lone heartBOT
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fervent timber
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why do people even use such a confusing notation for angles?

can’t we just stick to good old decimals?

tacit arch
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Boats, I think

lone heartBOT
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@hushed ether Has your question been resolved?

swift shore
median oar
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It also separates things better for a human mind to grasp

swift shore
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It’s such a niche specific mechanic skill

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Surely any person using maps in navigation will learn this again at their job, or more likely, have a computer perform it

lone heartBOT
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@hushed ether Has your question been resolved?

swift shore
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@hushed ether do you know how to convert from stupid DMS to decimal

median oar
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There are 60 minutes in a degree and 60 seconds in a minute

swift shore
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No no

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It’s 90° minus (48° plus 22’ plus 13’’)

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@hushed ether

median oar
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Yeah he understands that

swift shore
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Oh

median oar
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It’s 90-48 for the first box

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And 60-22 for the next box

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Well

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Not quite

swift shore
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Ah that’s so weird

median oar
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Because you need to borrow from before

swift shore
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I would just convert to decimal, subtract, then convert back

median oar
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Like 100- 12 is not quite 198

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First you do 1 degree minus 22 minutes and 13 seconds

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That should equal 37 minutes and 47 seconds

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Because when u add them

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13 seconds + 47 seconds is 1 minute 0 seconds

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Then 22 minutes + 37 minutes is 59 minutes, plus the 1 minute from before it’s 1 degree 0 minutes

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They are like digits of a number

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Normally in decimal you go to 10 and it shifts the digit

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Here it goes to 60 then shifts

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Instead of ones, tens, hundreds

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You have seconds, minutes, degrees

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10 ones make a ten, 10 tens make a hundred

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60 seconds make a minute, 60 minutes make a degree

swift shore
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Ah that’s an interesting way to see it

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Like base 60, in a way

median oar
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No it’s more like 90.00.00 - 48.22.13

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And u need 60 to shift a “digit” or a dot here

swift shore
median oar
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yeah, like 92° 42" 52.942'

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no

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should be 59 - 22 for the minutes

lone heartBOT
#

@hushed ether Has your question been resolved?

lone heartBOT
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signal pecan
lone heartBOT
signal pecan
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i dont know how to create this equation i am stuck
the rate is not the same
so what would be the b value
a value would be 49 since its the starting value
but what about the b and x value

sudden hinge
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either do as instructed and approximate the parameters using desmos or plug in 2 arbitrary rows into the equation y = ab^x to solve for the parameters

lone heartBOT
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@signal pecan Has your question been resolved?

signal pecan
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i get like the first 2 points right and then others wont work

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one point is right but others wont work

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@signal pecan Has your question been resolved?

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stiff surge
lone heartBOT
flat ore
#

what have you tried

stiff surge
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I know how to solve quadratic equation but I don't know how to solve these types of questions

stiff surge
flat ore
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do you know the quadratic formula?

stiff surge
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yep

flat ore
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use that

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thats what you have to do anyway

stiff surge
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Sorry I don't know how to use this bot

flat ore
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i dont think there are other ways

stiff surge
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Can you teach me how to use this bot?

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I will show you

flat ore
stiff surge
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okay

flat ore
stiff surge
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@flat ore

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$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

ocean sealBOT
#

realhuman

flat ore
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yes use this

stiff surge
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a=3, b=-5 and c= 1

flat ore
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a=3, b=-5, c= 1

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yes

stiff surge
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so

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let me solve it

flat ore
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You dont have to use the bot

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just tell me the answer

stiff surge
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ye

ocean sealBOT
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realhuman

tight locust
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Lol

stiff surge
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I will just tell the answer.. Also the above answer is wrong it is supposed to be 5 instead of negative 5

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The answer is option b

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@flat ore The answer for that question is option b

flat ore
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is it?

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check the sign of 5

stiff surge
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Ye

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-5?

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so what?

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(-5) square is 25

stiff surge
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@flat ore

flat ore
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yeah nvm

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you wrote that wrong

stiff surge
stiff surge
flat ore
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its 5 pm sqrt(13)

stiff surge
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oops ye

flat ore
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not -5

stiff surge
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I am not sure how to use the bot

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@flat ore Thanks for helping

alpine sable
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Damn

stiff surge
stiff surge
alpine sable
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Nothin

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Yall just 100988× smarter than me

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Thats all

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🥲

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I been failing math bro

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Ong

lone heartBOT
#
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tight locust
#

,calc 1 + 12/(2 + 12/(2+12))

ocean sealBOT
#

Result:

5.2
alpine sable
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,calc 100 × 2

ocean sealBOT
#

The following error occured while calculating:
Error: Undefined symbol ×

tight locust
#

,calc sqrt(13)

ocean sealBOT
#

Result:

3.605551275464
alpine sable
#

Damn

lone heartBOT
#
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alpine sable
#

,calc 100 x 2

ocean sealBOT
#

The following error occured while calculating:
Error: Undefined symbol x

lone heartBOT
alpine sable
#

Damn

wanton nova
#

,calc 100*2

ocean sealBOT
#

Result:

200
lone heartBOT
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tired shard
lone heartBOT
honest wren
tired shard
#

i mean i did 1/sin300

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but like i need exact values

honest wren
#

Yea

tired shard
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and idk how to convert -1.1547 into exact values

honest wren
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Do you know what sin60 is?

tired shard
#

yeah

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sqrt3/2

honest wren
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Do you know what sin300 is in terms of sin60

tired shard
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no

honest wren
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Do you know how the relationship between angles of the 4 quadrants?

tired shard
#

ik which is positive for which

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and negative for which

honest wren
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Do you know how to draw a diagram to represent it in terms of a triangle?

tired shard
honest wren
#

yea

tired shard
#

so how do you get the exact value?

honest wren
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So sine is opposite/hypotenuse

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Say the hypotenuse is 1

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What's the length of the opposite?

tired shard
#

sqrt3/2?

honest wren
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Yeah but since it's pointing down we take it as negative

tired shard
#

right

honest wren
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So sine300 is

tired shard
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-sqrt3/2

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ahhh

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that makes sense

honest wren
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Yeah so you can find cosec300

tired shard
#

could you explain how thats cosec i dont really understand that aspect

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since its cosec shouldnt its be -(2/sqrt3)?

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.close

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mossy tusk
#

(x+3)+4 (x+4)+4

lone heartBOT
mossy tusk
#

do i treat the +4 like it is in front?

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(x+3)+4 = 4x+12?

amber heart
#

what?

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could you clarify further

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are you trying to solve an equation?

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@mossy tusk

gray isle
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no

alpine sable
#

it’s an unnecessary bracket

gray isle
#

if
(x+3)(+4) was written, multiplication between the (x+3) and 4 would be implied,

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yeh, the parentheses around the x+3 are useless

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and its presence or absence won't affect the value of the expression

alpine sable
#

so u remove them, and sum x + 3 + 4 = x + 7

gray isle
#

not quite

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note that whole expression isn't just (x+3)+4

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there's stuff after it too

alpine sable
#

oh yeah mb

turbid phoenix
#

if you are trying to simplify (x+3)+4 (x+4)+4

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expand the middle term

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collect x terms

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add constants

lost dirge
#

yes^

gray isle
#

if it was just (x+3)+4, that'd simplify to x+7,
but isn't what you're starting with

lost dirge
#

unless you’re missing an = sign

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depends which +4 you’re talking about @mossy tusk

lone heartBOT
#

@mossy tusk Has your question been resolved?

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torpid chasm
lone heartBOT
torpid chasm
#

is this false, right?

lone heartBOT
#

@torpid chasm Has your question been resolved?

north adder
#

but i hope you understand why

torpid chasm
#

yes

small wave
#

i have a question

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what is 9+10=

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#

@torpid chasm Has your question been resolved?

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sudden pasture
#

I know I already have a channel open, but this one is simpler. Is it true that:

lone heartBOT
#

Please don't occupy multiple help channels.

sudden pasture
#

I couldn’t find this anywhere as a rule, but think it’s true

hushed tinsel
#

yes it is true

hushed tinsel
#

you can verify by putting the values of x

sudden pasture
#

wikipedia cals them identities

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I use them as rules

wary stream
# lone heart

FYI, @sudden pasture as the bot stated, don't open multiple channels, so close the other channels you have open

hushed tinsel
#

its still valid

sudden pasture
#

This is just a smaller question I needed for the other one. I already said that in the opening

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thank you for the confirmation @hushed tinsel

hushed tinsel
sudden pasture
#

yea ill try

sudden pasture
#

.close

lone heartBOT
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rose sable
#

alright so

lone heartBOT
rose sable
#

Im working on indices

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And stuck on this small part

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how can I know that sqr root of 8 is 2^3/2

keen bear
#

well, what is the prime factorization of 8?

rose sable
#

2x2x2

keen bear
#

so what is that in power notation?

rose sable
#

well thats the part im confused on why its 3/2

keen bear
#

2x2x2 is 2^3, right?

rose sable
#

yes

keen bear
#

so now we can take the square root of it. We need two important facts to get to why it's 3/2

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$\sqrt{x}=x^{\frac{1}{2}}$

ocean sealBOT
#

GoldenPhoenix

rose sable
#

yes i understand that

keen bear
#

$(x^{a})^{b}=x^{ab}$

ocean sealBOT
#

GoldenPhoenix

rose sable
#

yes

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like 5^2/3 is cube root five to power 2

keen bear
#

$(2^{3})^{\frac{1}{2}}=2^{3*\frac{1}{2}}$

ocean sealBOT
#

GoldenPhoenix

keen bear
#

which gets your result

rose sable
#

one min lemme see

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OH

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thanks

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appreacite it

keen bear
#

yeah, this leads to the nice property that a root of a power is the same as the power of a root

rose sable
#

so if its for example cube root of 8 it would be

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give me a sec

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8/3

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i think i did it wrong

keen bear
#

not quite

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$8^{\frac{1}{3}}$

ocean sealBOT
#

GoldenPhoenix

keen bear
#

now you substitute in the prime factorization of 8, and that gives you $(2^3)^{\frac{1}{3}}=2^{\frac{3}{3}}=2^1=2$

ocean sealBOT
#

GoldenPhoenix

rose sable
#

let me try one se

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sec

#

alright

#

thanks

#

.close

lone heartBOT
#
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vagrant rover
#

I don't even understand where to start answering this

vagrant rover
#

If anyone could help me get started that would be very appreciated

lone heartBOT
#

@vagrant rover Has your question been resolved?

vagrant rover
#

This is the information that I have gathered so far.

#

My current misunderstanding is that I’ve never seen a rational function in the form of (ac+b)/(cx+d). I’ve only seen rational functions in factored form.

#

<@&286206848099549185>

abstract fractal
#

What makes you think the horizontal asymptote is 0?

lone heartBOT
#

@vagrant rover Has your question been resolved?

vagrant rover
#

I thought so cause it looked like 0.2 approached y=0

abstract fractal
#

It says that, standing really far away from the magnet, the measurement is 0.2

vagrant rover
#

But we don’t have anything to compare it to

abstract fractal
#

I think the implication is that you're standing arbitrarily far

vagrant rover
abstract fractal
#

In other words, the asymptote, I would say, is 0.2

vagrant rover
#

The magnet doesn’t go forever

#

So eventually it will tend toward 0

abstract fractal
#

But there are magnets everywhere, plus the earth's magnetic field. I think 0.2 is just the "ambient" magnetic field

vagrant rover
abstract fractal
#

When it says that the measurement is 0.2 standing really far from the magnet, plus the fact it doesn't tell us how far, I can't see many other ways to interpret it

vagrant rover
#

You don’t think it could be tending toward 0 though?

#

I can see what you mean

#

Well regardless of the HA for now, wouldn’t we need more information to actually construct a function

abstract fractal
#

I don't think so, honestly. Otherwise you can't really use the 0.2 number

#

You'd need how far away you are. The only way it can be of use is if it's the asymptote

vagrant rover
#

Yeah fair enough

#

Makes sense

abstract fractal
#

Plus, 0.2 is a nice fraction. Makes for nice coefficients of a and c

vagrant rover
#

true

#

Oh yeah that makes a lot of sense now

#

@abstract fractalI don't know what to do next

#

I need a vertical asymptote or a vertical intercept to find the equation, right?

#

Idk how I would find the vertical intercept, so I would assume that the vertical asymptote is what I need to find

#

But idk how

abstract fractal
#

You know a and c, or at least what they could be

vagrant rover
#

yeah 2 and 10

abstract fractal
#

I would have gone with 1 and 5, but 2 and 10 works too

vagrant rover
#

yeah

abstract fractal
#

There's only two variables left to find

#

And you have two points

vagrant rover
#

b and d

#

what is b and d

#

Like what do they represent

abstract fractal
#

With the two points, you'll have two equations. Two equations, two unknowns

vagrant rover
abstract fractal
vagrant rover
#

Ah okay

#

Wait so how do we get two equations from two points

abstract fractal
#

By plugging them in

vagrant rover
#

do you mean like two linear equations?

#

OHHHHHHH

#

okay okay sec lemme try

#

@abstract fractalWait no I still don't get it

#

2.3 = (2(6)+b)/(10(6)+d)

#

That's what I wrote

#

and after that idk

abstract fractal
#

That's one equation

#

Woah, that shouldn't be 60(6).

#

That should either be 10(6) or just 60

vagrant rover
#

Oh my bad

#

Yeah that's what I meant

abstract fractal
#

Anyway, now you should plug in your other point

#

To get the second equation

vagrant rover
#

4.4= (2(8)+b)/(10(8)+d)

abstract fractal
#

Yep

#

Now to solve with your favorite systems of equations method.

#

Substitution, elimination, whatever you want

vagrant rover
#

OHHHH

#

OHHHHH

#

genius

#

Okay okay okay sec

#

I like this

vagrant rover
#

but just one quick quesiton

#

shouldn't it be 2 and 10 and not 1 and 5 since we're multiplying

#

by x

#

like wouldn't simplifying here result in different functions

abstract fractal
#

Let's say it's supposed to be 2 and 10 but we guess 1 and 5

#

Then b and c will be fractions

#

They'll be /2

#

To get rid of the fraction, we'd multiply the top and bottom by 2, turning 1 and 5 to 2 and 10

#

Similarly, the other way around, if we guess 2 and 10 and it's supposed to be 1 and 5, then b and c will be even, and we can divide out a factor of 2 from the top and bottom

#

Either way, we'll get the same answer

vagrant rover
#

Hm

#

I see

abstract fractal
#

It'll be like how 1/2 and 2/4 are the same

#

Anyway, what answer did you get?

vagrant rover
abstract fractal
#

Yep. Notice you have the case where you can factor out a 2 from the top and bottom

#

That'll just simplify the fraction

vagrant rover
#

Should I rewrite as

abstract fractal
#

That's fine

vagrant rover
#

Wait which one is fine

abstract fractal
#

Either one, really. The latter is most simplified

vagrant rover
abstract fractal
#

Now you have the function, and you can answer the next parts

vagrant rover
#

It's okay the this function shows on both sides, right?

#

like

#

what i mena

#

Because that doesn't make intutive sense to me

abstract fractal
#

Yeah, that's fine. That's how rational functions work. Though, in order to physically make sense with what the function actually means, we would probably take the absolute value, but that's unnecessary and doesn't affect the answer to any of the problems

vagrant rover
#

But if we get to like say, 11, feet near it

#

it would switch up?

#

that makes no sense to me

#

OHH

#

THat's the answer for one of the other question parts

#

it's 10 feet into the room

abstract fractal
#

Yep

vagrant rover
#

right?

#

YAY

#

Very kewl question

abstract fractal
#

Thus, standing at x = 9 and x = 11 should give the same result. It's the wrong sign in practice, which is why one may use the absolute value, however I wouldn't suggest putting the function in absolute values as it unnecessarily complicates things

vagrant rover
#

Right right right

#

Wait uh

#

yeah okay

#

wait

#

how would I put it in absolute value if I did want to?

#

Just absolute everything?

abstract fractal
#

Yep, since physically we only care about the magnitude, not the sign

vagrant rover
#

ahh okay okay okay okay okay

#

THIS IS SO KEWL

#

Tysm ❤️@abstract fractal

abstract fractal
#

Np rin

vagrant rover
#

.close

lone heartBOT
#
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polar solar
#

the marscheme says that "it should be 33/100" i got 33/100. is my answer right

polar solar
#

because the marchscheme also says use 2 comparable figures, 33 and 100

lone heartBOT
#

@polar solar Has your question been resolved?

polar solar
#

<@&286206848099549185>

shut socket
#

Gcse fella

polar solar
#

what?

zenith carbon
#

Yes you’re correct

#

You don’t really need to do that really long addition you did of pi

polar solar
#

i was just tryna make sure because i thought the mark scheme said i was wrong

polar solar
zenith carbon
#

Yh I did it at some point

lone heartBOT
#

@polar solar Has your question been resolved?

#
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real sparrow
lone heartBOT
real sparrow
#

Hi, I need help with question 4 (ii)

karmic rapids
#

use the formula for the area of a circle

#

$$A = \pi r^2$$

ocean sealBOT
#

illuminator3

karmic rapids
real sparrow
#

I know but the radius is 5/pie

karmic rapids
#

pi not pie lol

wanton nova
#

haha

real sparrow
#

yea soz

#

anywyas

#

when i put the radius into the formula i can’t like solve it

karmic rapids
#

<@&268886789983436800>

wanton nova
#

🥧

karmic rapids
#

why can't you?

real sparrow
#

hold on

sly mantle
#

@alpine sable pls use a free channel

real sparrow
#

How do i solve this😭

wanton nova
#

get rid of the bracket

#

by raising both numerator and deneminator to the 2

karmic rapids
#

$$\left(\frac{a}{b}\right)^2 = \frac{a^2}{b^2}$$

real sparrow
#

And then what do i do with the pie squared at the bottom

ocean sealBOT
#

illuminator3

real sparrow
#

damn auto correct

wanton nova
karmic rapids
#

hate mobile

wanton nova
#

haha

karmic rapids
wanton nova
#

🥧

real sparrow
#

so will i get pi? at the bottom

wanton nova
#

yes

real sparrow
#

ah okok

karmic rapids
#

indeed

real sparrow
#

thank you very much

#

expect me later

#

.close

lone heartBOT
#
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wanton nova
#

np

#

bye

lone heartBOT
#
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alpine sable
#

Hi! How would you do this problem?

lone heartBOT
alpine sable
#

so the person would travel around the circumference 6 times

#

how would you find the circumference?

#

2 pi r

#

yeah so instead of r

#

its t

#

so 2pi t

#

*6

#

so 12pi t

#

Oh, because they would travel around it 6 times

#

yeah

#

you got it?

#

thank you

#

yes

#

np

#

.close

#

.close

#

.close

lone heartBOT
#
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wanton nova
#

i got it

#

.close

lone heartBOT
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tawdry jolt
#

What am I doing wrong here?

lone heartBOT
tawdry jolt
#

I also said it was 0 and that was wrong too

#

Desmos shows that both are kind of correct

dusty fox
#

And that's why neither are correct

tawdry jolt
#

Ohhh

#

Thank you

#

.close

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safe lark
#

how can i prove here that ADC is congruent to ACM and that DBC is congruent to BNC

safe lark
wanton nova
#

you're only given the pic?

safe lark
#

ABC is a right triangle "around" it is a circle distances of points A and B to the tangent which passes throught point C are m and n. What are lenghts of legs?

safe lark
safe lark
wanton nova
#

well

safe lark
wanton nova
#

both triangles have a right angle

safe lark
#

yea

wanton nova
#

oof

#

idk

safe lark
#

so 1 sec

#

ima draw it in paint

#

tell me if its correct

safe lark
#

anyone?

wanton nova
#

you can ping helpe

#

r

#

s

#

now

safe lark
#

<@&286206848099549185>

lone heartBOT
#

@safe lark Has your question been resolved?

safe lark
#

<@&286206848099549185>

lone heartBOT
#

@safe lark Has your question been resolved?

frigid hatch
# safe lark

you could say that angle ACB is alfa and angle CAD is beta so 90 + alfa + beta = 180, alfa + beta = 90.
now if you look at the triangle ACB the angle CAB is alfa and si the angle CBD must be beta, you can use the same logic to complete triangle MCA and triangle NCB so that you can prove that, for example, ACD is congruent to MCA because they have one length in common and two angles

frigid hatch
#

ACD

#

it doesn't really matter

safe lark
frigid hatch
safe lark
#

yea thats what u get in the end

frigid hatch
#

yes so where's the problem

safe lark
#

how do u know that MCA is same as DCA

#

you cant just say it

frigid hatch
#

MCA is congruent to ACD because AC is in common and alfa and beta are adjacent to AC

safe lark
frigid hatch
#

you need at least two angles and a length to prove two triangles congruent

safe lark
#

i understand that

#

but how do i prove that angles MAC is same as DAC, MCA is same as CDA...

#

we cant just say it is we have to prove it

safe lark
frigid hatch
#

do you know the external angle theorem?

safe lark
#

if what u mean is like when a side is continued as a line the internal angle + external equal 180deg

frigid hatch
#

this

safe lark
#

oh yes

safe lark
frigid hatch
#

you could probably work this out knowing that two angles subtending the same arc are congruent

#

MCA and CBA for example

#

have you done that theorem?

safe lark
#

nope

safe lark
frigid hatch
safe lark
#

yea i know what it is

frigid hatch
#

lol

safe lark
#

but idk if i can use the theorem if we didnt learn it

frigid hatch
#

what have you learnt

safe lark
safe lark
frigid hatch
#

where are you from?

safe lark
#

croatia

frigid hatch
#

ok

safe lark
frigid hatch
#

italy

safe lark
#

oh nice

frigid hatch
#

you would still need some other knowledge other than congruency and similarity, especially if you're asked to prove something

#

but anyway, I'll let you know if I find another way of proving it

safe lark
#

this is on electronic book, like "compexer tasks" (literal translation), we usually dont have that hard on test but i saw the teacher gave us one of these questions when we were revising for a test so im doing it

safe lark
#

same color - same angle

#

<@&286206848099549185>

frigid hatch
#

you could just prove it

#

if you didn't do it yet

safe lark
#

i tried extending this to get a rectangle

safe lark
lone heartBOT
#

@safe lark Has your question been resolved?

lone heartBOT
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alpine sable
#

i need to do 2 slides on 2 roman operations

alpine sable
#

like division and fractions or something like that

#

Something short like this

#

Thats multiplication i already done that

#

<@&286206848099549185>

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

ashen sage
#

The hell they teaching these days

alpine sable
#

close

#

.close

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#
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strong wedge
#

hello

lone heartBOT
strong wedge
#

when is u subsitution not required? when should i know if its nessesary to use or not

rigid smelt
#

Intuition, sometimes it works and doesnt work, and there is not really a time that it is unnecessary

#

For example in exercise 6, you can either substitute or algebraically manipulate the integrand

tight gulch
#

You can also just play around with setting u= to parts of the equation and find du (the derivative) and see if anything will cancel out nicely

near hollow
#

If two functions seem to have no relation and are products for instance 12... then parts is the way

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#

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sterile nimbus
#

Hi, I'm trying to solve this recurrence:
but I'm unsure about how to transform $2^n$ into the proper form of $n^klog_p\left(n\right)$

ocean sealBOT
#

Dr Xionel

lone heartBOT
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@sterile nimbus Has your question been resolved?

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frail rivet
#

hello, if a function f_n is uniformly convergent (which means f is continuous) does it imply that its continuous?

frail rivet
#

LMAO

stone glen
#

I don't understand thonkzoom

frail rivet
#

Ok i googled it its not the case

#

couldnt find anything before

stone glen
#

Refer to Google before here

frail rivet
#

yea i did

#

to prove for continuity on [0,2]->R,
I plug in 1/n for n^2*(1/n) = n and 1/n for 2n - n^2*(1/n) = n. is approaching it like this enough or do i need lim?

merry depot
#

you probably don't need to do a limit, but you should at least mention why you only check those points.

frail rivet
#

because they are different functions?

merry depot
#

how do you know there's not a discontinuity somewhere else

dawn birch
#

you can individually prove continuity on [0, 1/n), (1/n, 2/n), and (2/n, inf) then verify x = 1/n and x = 2/n

#

to thus prove continuity on [0, inf)

frail rivet
#

individually prove continuity?

dawn birch
#

yes

#

for each function

#

on that interval

frail rivet
#

oh with the delta epsilon criteria?

dawn birch
#

if they’re being really strict yeah

#

you might just get away with asserting the limit equals the value of the function at the points on the interval so it converges

#

depending on level of required rigorousness

merry depot
#

you can probably just note that each of those are polynomials

dawn birch
#

yes

frail rivet
#

Oh true

novel night
#

Is the question simply whether f_n defined above is continuous? Or was the question something about uniform convergence?

frail rivet
#

just continuity

#

but i thought u could prove it with uniform convergence

frail rivet
novel night
#

If a sequence of functions f_n converges uniformly to a function f, and each f_n is continuous, then the limit function f is continuous as well. That doesn't really apply here to showing that f_n itself is continuous.

#

It's a general fact that if a function is defined piece-wise like f_n above, the function will be continuous if each of the pieces are continuous, and they agree on the overlaps.

frail rivet
#

okay thank u guys

#

.close

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#
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slim steppe
#

can i get some help with this?

lone heartBOT
#

@slim steppe Has your question been resolved?

slim steppe
#

<@&286206848099549185>

tacit arch
slim steppe
slim steppe
tacit arch
#

Yup does help

#

Write your sequence as arithmetic operations of the two previous terms

#

a_n =f(a_(n-1 ), a_(n-2))

slim steppe
tacit arch
#

7

#

Figure out the function. It should be simple, like the ones in 6

slim steppe
tacit arch
#

Maybe you should do 6 before 7

slim steppe
#

Okay

silver drum
#

hi

#

can u help me with my math plz

slim steppe
#

.close

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vocal fulcrum
lone heartBOT
vocal fulcrum
#

Can anyone tell me the topic I need to cover to be able to solve this

oak perch
#

Can you choose one of them and ask it

#

Whatever I answer 1

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  1. left hand side is log_2(2020)
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  1. that is a linear fractional transformation, or simply solve it by definition, very easy
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3)t^2+at+b=0 has exactly one real root t

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  1. is too easy, omit
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  1. seems interesting let me think about it
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Use $Z[x]/((x-1)x^{2}) \cong Z[x]/(x-1) \oplus Z[x]/(x^2)$
Find the inverse image of $(2,2x+3)$

ocean sealBOT
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Cogwheels of the mind

oak perch
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Now since the inverse image of (0,1) and (1,0) are 1-x^2 and x^2 respectively, so answer is (2)x^2+(2x+3)(1-x^2)=-3x^2+2x+3 mod (x-1)x^2

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So (-3,2,3)

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Can’t do you homework for you, 2,3 left to yourself

lone heartBOT
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@vocal fulcrum Has your question been resolved?

vocal fulcrum
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Wish I had learnt stuff like this
Not my homework

vocal fulcrum
oak perch
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Study?

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Those aren’t open questions

vocal fulcrum
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Open questions?

oak perch
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In fact they are too simple

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I don’t see anything you can research about those questions

vocal fulcrum
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Didn't read let me check them out forst then zoomEyes

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Parametric equations
Some terms I don't understand
And then the probability question
Should be doable
Had read some reviews of maths b being very difficult and in a video a guy went as far as saying you can't prepare for it in 2-3 months
Might have gotten influenced by him
Wtever thnxx

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.close

lone heartBOT
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red timber
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I will make a presentation to show a visit to the water park with friends or family. Through the work on this, i will show practical use of mathematics. It is important that i include more of the topics in the subject. I will have to make a plan that includes prices, size, room, volume. I decide myself what i want to present at my presentation. A visit to a water park can be very varied from time to time. In the presentation I must also explain how i worked and delimit the topic, what sources i have used and how i have worked with it. Im not really an expert at math and not sure where or how to start, so help would be appreciated. Thank you.

nimble fern
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Oh, I like maths project! Do you mind tell us what grade is this project for?

nimble fern
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I think you are list out the possible uses of those criteria,

  • prices
  • size
  • room
  • volume
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What can you think of from these topics?

red timber
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regarding room, volume, size, would i search the average size of a waterpark or would i search up a waterpark nearby that i can use as an example?

nimble fern
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Of course! That would be a brilliant idea! Also, you can get the price of tickets and meals inside the park

red timber
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yea!

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one second

nimble fern
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You can also compare size of different pool, depths and volume of water, capacity for each facility
Or even time for queuing

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There are so many things to do in this project!

red timber
nimble fern
oak perch
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Sorry to interrupt

nimble fern
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And draw each pool with an extra sheet, and prices with table, etc.

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Good luck with your project! @red timber

red timber
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@red timber Has your question been resolved?

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chrome shore
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Why is the answer 0?

lone heartBOT
north adder
chrome shore
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The derivative...

north adder
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differentiate F(x) = f(x)/g(x)

gray ingot
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quotient rule

chrome shore
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Then yeah quotient

north adder
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sure product or quotietn

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if your question has been answered please close the channel

chrome shore
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Oh got it, thanks

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.close

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tough orbit
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Can any1 explain how to do 6b? I did a and got the answer as 13.5 cm2

median oar
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so that's the cross section right?

tough orbit
median oar
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so if it were 30cm long

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how would u find the volume

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try draw it

oak perch
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30 times what you got for a)

tough orbit
median oar
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how do you find the volume of a prism

tough orbit
median oar
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ok prism isn't the right word

tough orbit
median oar
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Well

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u can integrate a straight line from 0 to 30

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but like i doubt that's what you're looking for

rustic stirrup
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length will be height in the case and plug in the forumla ( pi times r^2 times height) , where height is 30 and radius is 7

median oar
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u know what the cross sectional area is

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from part a

tough orbit
median oar
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that's what u calculated right?

tough orbit
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But I think I’ll be able to calculate it

median oar
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the area of the shaded region

tough orbit
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Yes ik the area

median oar
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so the volume should be that * the length of the pipe

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which u could prove via integration i suppose

tough orbit
median oar
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but even with a triangular prism

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the volume is the area of the cross section * height

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a cube is also the cross section * height

tough orbit
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Yh

median oar
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a cylinder would be also πr^2 * h

tough orbit
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Ye

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Ok thanks for the help guys @median oar @rustic stirrup

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.close

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rustic stirrup
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A cylinder of volume V has height (5 * pi)/2, and radius r. f(x) = [2 * sin(2 * x - 4 * pi) + 184]^(1/2). This function makes a solid when revolved around the x axis. The volume of this function is the same as V in the domain pi/2 to (3 * pi)/6. Find the radius of the cylinder.

lone heartBOT
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Please don't occupy multiple help channels.

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@rustic stirrup Has your question been resolved?

lone heartBOT
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@rustic stirrup Has your question been resolved?

nimble fern
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Hello, do you still need help with your question?@rustic stirrup

tough orbit
lone heartBOT
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@rustic stirrup Has your question been resolved?

abstract oriole
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hi

rustic stirrup
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HI

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Still need help @nimble fern

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Thanks

nimble fern
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Hint: integration

rustic stirrup
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Maybe I am applying the limits of integration wrong

nimble fern
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Can you show your work, maybe we can go through it and see if there is any mistake

ocean sealBOT
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Lelouch

stone glen
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,w integrate sqrt(2sin(2x)+184)

stone glen
ocean sealBOT
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Lelouch

stone glen
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Recheck the question

rustic stirrup
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.close

lone heartBOT
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stone glen
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Lmao w?

lone heartBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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sage locust
lone heartBOT
sage locust
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any hints?

stone glen
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Yeah

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Newton's method

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This is clearly a JEE main question

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They are tryna trap you, from the $p_{n+2}$ thing, make sure you have that right

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@sage locust

sage locust
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preparing for ioqm

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wait two is not in subscript?

stone glen
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No wait i messed it up

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I suck at latex excuse me

vale wigeon
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$p_{n+2}$

ocean sealBOT
vale wigeon
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this is how you latex it

stone glen
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Thank yew ann

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Appreciate it

ocean sealBOT
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Lelouch

sage locust
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hmm

stone glen
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Do you know the Newton's method?

sage locust
stone glen
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Well then...

sage locust
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what is that about

stone glen
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Its about quadratics

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It would take me ages to explain it here

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So i assume u speak Hindi?

sage locust
stone glen
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Ok

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So just google 'Unacademy Atoms Quadratic Equations One shot' on YouTube , and there will be a lecture from Nishant Vora ( The Mozart of Math Teachers)

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It's a lecture on quadratic equations

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Just skip to the Newton's method section if you only want to learn that, but i suggest u watch the whole thing tbh

sage locust
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this one?

stone glen
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Yeah correct

sage locust
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tysm

stone glen
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I suggest watch all the One Shots of this #BounceBack series, it's all Free , and this guy ( Nishant Vora ) is arguably the best math teacher for high school math

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@sage locust

stone glen
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Google #BounceBack