#help-0
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In that case
n will be a complex number
Powers of negative number cannot be represent with real numbers unless their exponent is an integer
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@daring reef
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thank you for the help
Np
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@terse smelt Has your question been resolved?
<@&286206848099549185>
wat is L
@terse smelt Has your question been resolved?
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$\ln (x+1) - \ln (x-2) = \ln x$
$e^{\ln (x+1) - \ln (x-2)} = e^{\ln x}$
$\frac{e^{\ln (x+1)}}{e^{\ln (x-2)}} = e^{\ln x}$
$\frac{x+1}{x-2} = x$
$x^2 -3x - 1 = 0$
Yustina
,w x^2 - 3x - 1 = 0
it would be a right
Or you can similarly use ln(a) - ln(b) = ln(a/b). You'd get the same result
Wait
Isn't there an easier way
You can factor ln(x) out
I guess it works both ways
You would still get the quadratic
but would there be an extraneous solution
Well you can try plugging it in and see if it's true
there will be one yes
use log proprties
$$3\log\left(2a\right)-\log\left(2a\right)$$
$$\log\left(\left(2a\right)^{3}\right)-\log\left(2a\right)$$
$$\log\left(\frac{\left(2a\right)^{3}}{2a}\right)$$
$$\log\left(\left(2a\right)^{2}\right)$$
Umbraleviathan
Yeah
ohhhhh
i looked at my notrs and i get it
but for some reason my answer isnt on there
lets see
$$3\log\left(2a\right)-\log\left(2a\right)=\log\left(11a+3\right)$$
$$\log\left(\left(2a\right)^{3}\right)-\log\left(2a\right)=\log\left(11a+3\right)$$
$$\log\left(\frac{\left(2a\right)^{3}}{2a}\right)=\log\left(11a+3\right)$$
$$\log\left(\left(2a\right)^{2}\right)=\log\left(11a+3\right)$$
$$4a^{2}=11a+3$$
$$4a^2-11a-3=0$$
Check extraneous solutions
Umbraleviathan
Im not good with compounded stuff
shoot
Lemme see
If I can remember
$$A = I\left(1+\frac{r}{12}\right)^{12t}$$
$A$ is the amount, $I$ is the initial value (deposit), $r$ is the interest rate as a decimal, $t$ is time in years
Umbraleviathan
@ashen pulsar
Plug in the information given to you
whats rate
would it be 1.085
or 0.0085
nvm
why is r divided by 12 there
@last ether
It's just the formula
whats the original formula
I don't know jackshit about finances lol
im so lost
$$A = I\left(1+\frac{r}{k}\right)^{kt}$$
$A$ is the amount, $I$ is the initial value (deposit), $r$ is the interest rate as a decimal, $t$ is time in years, $k$ is the frequency of compounding
this due in one hour
Umbraleviathan
@ashen pulsar Has your question been resolved?
_ _
Uhh
I guess you can use logarithmic regression on your calculator
But I gotta sleep
oh ya
@ashen pulsar Has your question been resolved?
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why do people even use such a confusing notation for angles?
can’t we just stick to good old decimals?
Boats, I think
@hushed ether Has your question been resolved?
Because they need garbage to fill up the curriculum
Because you use that for maps, degrees minutes seconds
It also separates things better for a human mind to grasp
It’s such a niche specific mechanic skill
Surely any person using maps in navigation will learn this again at their job, or more likely, have a computer perform it
@hushed ether Has your question been resolved?
@hushed ether do you know how to convert from stupid DMS to decimal
There are 60 minutes in a degree and 60 seconds in a minute
Yeah he understands that
Oh
Ah that’s so weird
Because you need to borrow from before
I would just convert to decimal, subtract, then convert back
Like 100- 12 is not quite 198
First you do 1 degree minus 22 minutes and 13 seconds
That should equal 37 minutes and 47 seconds
Because when u add them
13 seconds + 47 seconds is 1 minute 0 seconds
Then 22 minutes + 37 minutes is 59 minutes, plus the 1 minute from before it’s 1 degree 0 minutes
They are like digits of a number
Normally in decimal you go to 10 and it shifts the digit
Here it goes to 60 then shifts
Instead of ones, tens, hundreds
You have seconds, minutes, degrees
10 ones make a ten, 10 tens make a hundred
60 seconds make a minute, 60 minutes make a degree
Wait you you hear about decimal seconds

No it’s more like 90.00.00 - 48.22.13
And u need 60 to shift a “digit” or a dot here
Huh
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i dont know how to create this equation i am stuck
the rate is not the same
so what would be the b value
a value would be 49 since its the starting value
but what about the b and x value
either do as instructed and approximate the parameters using desmos or plug in 2 arbitrary rows into the equation y = ab^x to solve for the parameters
@signal pecan Has your question been resolved?
i am but its not working
i get like the first 2 points right and then others wont work
one point is right but others wont work
@signal pecan Has your question been resolved?
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Help
what have you tried
I know how to solve quadratic equation but I don't know how to solve these types of questions
Just tried manually solving them but it is too complicated due to there is usually a different way
do you know the quadratic formula?
yep
Sorry I don't know how to use this bot
i dont think there are other ways
#resources scroll all the way to the top
okay
realhuman
yes use this
a=3, b=-5 and c= 1
ye
realhuman
Lol
I will just tell the answer.. Also the above answer is wrong it is supposed to be 5 instead of negative 5
The answer is option b
@flat ore The answer for that question is option b
ye
no?
oops ye
not -5
Damn
What?
?
Nothin
Yall just 100988× smarter than me
Thats all
🥲
I been failing math bro
Ong
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,calc 1 + 12/(2 + 12/(2+12))
Result:
5.2
,calc 100 × 2
The following error occured while calculating:
Error: Undefined symbol ×
,calc sqrt(13)
Result:
3.605551275464
Damn
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,calc 100 x 2
The following error occured while calculating:
Error: Undefined symbol x
,calc 100*2
Result:
200
@alpine sable Has your question been resolved?
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What have you tried
Yea
and idk how to convert -1.1547 into exact values
Do you know what sin60 is?
Do you know what sin300 is in terms of sin60
no
Do you know how the relationship between angles of the 4 quadrants?
sorta not really
ik which is positive for which
and negative for which
Do you know how to draw a diagram to represent it in terms of a triangle?
i can draw a unit circle
yea
so how do you get the exact value?
So sine is opposite/hypotenuse
Say the hypotenuse is 1
What's the length of the opposite?
sqrt3/2?
Yeah but since it's pointing down we take it as negative
right
So sine300 is
Yeah so you can find cosec300
could you explain how thats cosec i dont really understand that aspect
since its cosec shouldnt its be -(2/sqrt3)?
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(x+3)+4 (x+4)+4
what?
could you clarify further
are you trying to solve an equation?
@mossy tusk
no
it’s an unnecessary bracket
if
(x+3)(+4) was written, multiplication between the (x+3) and 4 would be implied,
yeh, the parentheses around the x+3 are useless
and its presence or absence won't affect the value of the expression
so u remove them, and sum x + 3 + 4 = x + 7
oh yeah mb
if you are trying to simplify (x+3)+4 (x+4)+4
expand the middle term
collect x terms
add constants
yes^
if it was just (x+3)+4, that'd simplify to x+7,
but isn't what you're starting with
@mossy tusk Has your question been resolved?
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is this false, right?
@torpid chasm Has your question been resolved?
yes
@torpid chasm Has your question been resolved?
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I know I already have a channel open, but this one is simpler. Is it true that:
Please don't occupy multiple help channels.
I couldn’t find this anywhere as a rule, but think it’s true
yes it is true
there is no rule
you can verify by putting the values of x
FYI, @sudden pasture as the bot stated, don't open multiple channels, so close the other channels you have open
This is just a smaller question I needed for the other one. I already said that in the opening
thank you for the confirmation @hushed tinsel
yea ill try
np
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alright so
Im working on indices
And stuck on this small part
how can I know that sqr root of 8 is 2^3/2
well, what is the prime factorization of 8?
2x2x2
so what is that in power notation?
well thats the part im confused on why its 3/2
2x2x2 is 2^3, right?
yes
so now we can take the square root of it. We need two important facts to get to why it's 3/2
$\sqrt{x}=x^{\frac{1}{2}}$
GoldenPhoenix
yes i understand that
$(x^{a})^{b}=x^{ab}$
GoldenPhoenix
$(2^{3})^{\frac{1}{2}}=2^{3*\frac{1}{2}}$
GoldenPhoenix
which gets your result
yeah, this leads to the nice property that a root of a power is the same as the power of a root
so if its for example cube root of 8 it would be
give me a sec
8/3
i think i did it wrong
GoldenPhoenix
now you substitute in the prime factorization of 8, and that gives you $(2^3)^{\frac{1}{3}}=2^{\frac{3}{3}}=2^1=2$
GoldenPhoenix
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I don't even understand where to start answering this
If anyone could help me get started that would be very appreciated
@vagrant rover Has your question been resolved?
This is the information that I have gathered so far.
My current misunderstanding is that I’ve never seen a rational function in the form of (ac+b)/(cx+d). I’ve only seen rational functions in factored form.
<@&286206848099549185>
What makes you think the horizontal asymptote is 0?
@vagrant rover Has your question been resolved?
Yeah you’re right it could be something else
I thought so cause it looked like 0.2 approached y=0
It says that, standing really far away from the magnet, the measurement is 0.2
But we don’t have anything to compare it to
I think the implication is that you're standing arbitrarily far
Yeah so I put 10 feet back as an approximation
In other words, the asymptote, I would say, is 0.2
Wait wait wait actually
The magnet doesn’t go forever
So eventually it will tend toward 0
But there are magnets everywhere, plus the earth's magnetic field. I think 0.2 is just the "ambient" magnetic field
Yeah but I wouldn’t image that’s part of this question
Hmmm
When it says that the measurement is 0.2 standing really far from the magnet, plus the fact it doesn't tell us how far, I can't see many other ways to interpret it
You don’t think it could be tending toward 0 though?
I can see what you mean
Well regardless of the HA for now, wouldn’t we need more information to actually construct a function
I don't think so, honestly. Otherwise you can't really use the 0.2 number
You'd need how far away you are. The only way it can be of use is if it's the asymptote
Plus, 0.2 is a nice fraction. Makes for nice coefficients of a and c
Ah okay
true
Oh yeah that makes a lot of sense now
@abstract fractalI don't know what to do next
I need a vertical asymptote or a vertical intercept to find the equation, right?
Idk how I would find the vertical intercept, so I would assume that the vertical asymptote is what I need to find
But idk how
You know a and c, or at least what they could be
yeah 2 and 10
I would have gone with 1 and 5, but 2 and 10 works too
yeah
With the two points, you'll have two equations. Two equations, two unknowns
right
Dunno. Numbers. I'm not sure what they physically represent, if anything
By plugging them in
do you mean like two linear equations?
OHHHHHHH
okay okay sec lemme try
@abstract fractalWait no I still don't get it
2.3 = (2(6)+b)/(10(6)+d)
That's what I wrote
and after that idk
That's one equation
Woah, that shouldn't be 60(6).
That should either be 10(6) or just 60
4.4= (2(8)+b)/(10(8)+d)
Yep
Now to solve with your favorite systems of equations method.
Substitution, elimination, whatever you want
Hey so I got the answer I think
but just one quick quesiton
shouldn't it be 2 and 10 and not 1 and 5 since we're multiplying
by x
like wouldn't simplifying here result in different functions
Let's say it's supposed to be 2 and 10 but we guess 1 and 5
Then b and c will be fractions
They'll be /2
To get rid of the fraction, we'd multiply the top and bottom by 2, turning 1 and 5 to 2 and 10
Similarly, the other way around, if we guess 2 and 10 and it's supposed to be 1 and 5, then b and c will be even, and we can divide out a factor of 2 from the top and bottom
Either way, we'll get the same answer
Yep. Notice you have the case where you can factor out a 2 from the top and bottom
That'll just simplify the fraction
Should I rewrite as
That's fine
Wait which one is fine
yeah yeah I see what you mean
Either one, really. The latter is most simplified
Ah okay, I'll go with this
Now you have the function, and you can answer the next parts
Oh actually one question
It's okay the this function shows on both sides, right?
like
what i mena
Because that doesn't make intutive sense to me
Yeah, that's fine. That's how rational functions work. Though, in order to physically make sense with what the function actually means, we would probably take the absolute value, but that's unnecessary and doesn't affect the answer to any of the problems
But if we get to like say, 11, feet near it
it would switch up?
that makes no sense to me
OHH
THat's the answer for one of the other question parts
it's 10 feet into the room
Yep
Thus, standing at x = 9 and x = 11 should give the same result. It's the wrong sign in practice, which is why one may use the absolute value, however I wouldn't suggest putting the function in absolute values as it unnecessarily complicates things
Right right right
Wait uh
yeah okay
wait
how would I put it in absolute value if I did want to?
Just absolute everything?
Yep, since physically we only care about the magnitude, not the sign
Np 
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the marscheme says that "it should be 33/100" i got 33/100. is my answer right
because the marchscheme also says use 2 comparable figures, 33 and 100
@polar solar Has your question been resolved?
<@&286206848099549185>
Gcse fella
what?
Yes you’re correct
You don’t really need to do that really long addition you did of pi
thanks
i was just tryna make sure because i thought the mark scheme said i was wrong
oh you have the same test
Yh I did it at some point
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Hi, I need help with question 4 (ii)
illuminator3
read #❓how-to-get-help pls
I know but the radius is 5/pie
pi not pie lol
haha
<@&268886789983436800>
🥧
wdym
why can't you?
hold on
@alpine sable pls use a free channel
$$\left(\frac{a}{b}\right)^2 = \frac{a^2}{b^2}$$
And then what do i do with the pie squared at the bottom
illuminator3
damn auto correct
🥧 squared?
beat me to it
hate mobile
haha
cancel out with the other pie
🥧
so will i get pi? at the bottom
yes
ah okok
indeed
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Hi! How would you do this problem?
so the person would travel around the circumference 6 times
how would you find the circumference?
2 pi r
yeah so instead of r
its t
so 2pi t
*6
so 12pi t
Oh, because they would travel around it 6 times
yeah
you got it?
thank you
yes
np
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What am I doing wrong here?
I also said it was 0 and that was wrong too
Desmos shows that both are kind of correct
And that's why neither are correct
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how can i prove here that ADC is congruent to ACM and that DBC is congruent to BNC
you're only given the pic?
ABC is a right triangle "around" it is a circle distances of points A and B to the tangent which passes throught point C are m and n. What are lenghts of legs?
i just gotta know how to prove those triangles are congruent
and the picture isnt givent its part of the solution
wait i think i might know
both triangles have a right angle
yea
<@&286206848099549185>
@safe lark Has your question been resolved?
<@&286206848099549185>
@safe lark Has your question been resolved?
you could say that angle ACB is alfa and angle CAD is beta so 90 + alfa + beta = 180, alfa + beta = 90.
now if you look at the triangle ACB the angle CAB is alfa and si the angle CBD must be beta, you can use the same logic to complete triangle MCA and triangle NCB so that you can prove that, for example, ACD is congruent to MCA because they have one length in common and two angles
you mean ABC is alfa?
ACB is 90
i know all of that, but you just say ACD is congruent to MCA because they have one length in common and two angles, how do i prove for the second angle, idk how to apply what you said to that
yea thats what u get in the end
yes so where's the problem
MCA is congruent to ACD because AC is in common and alfa and beta are adjacent to AC
the angle
you need at least two angles and a length to prove two triangles congruent
i understand that
but how do i prove that angles MAC is same as DAC, MCA is same as CDA...
we cant just say it is we have to prove it
also you said that CAD is beta and later on that CBD must be beta, that would mean that ABC is an isosceles triangle
do you know the external angle theorem?
tell me what it is, idk the names on english
if what u mean is like when a side is continued as a line the internal angle + external equal 180deg
oh yes
and what then?
forget the last thing I said
you could probably work this out knowing that two angles subtending the same arc are congruent
MCA and CBA for example
have you done that theorem?
nope
maybe we have in primary school but not here in hs, and we dont usually need something we didnt go over in hs
yea i know what it is
lol
but idk if i can use the theorem if we didnt learn it
what have you learnt
i cant list everything we learned xd
this is a chapter with congruency and similarity of triangles if thats what its called in english
where are you from?
croatia
ok
you?
italy
oh nice
you would still need some other knowledge other than congruency and similarity, especially if you're asked to prove something
but anyway, I'll let you know if I find another way of proving it
this is on electronic book, like "compexer tasks" (literal translation), we usually dont have that hard on test but i saw the teacher gave us one of these questions when we were revising for a test so im doing it
maybe this can help you
same color - same angle
<@&286206848099549185>
tbh I can only think of this
you could just prove it
if you didn't do it yet
i tried extending this to get a rectangle
sure
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i need to do 2 slides on 2 roman operations
like division and fractions or something like that
Something short like this
Thats multiplication i already done that
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The hell they teaching these days
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hello
when is u subsitution not required? when should i know if its nessesary to use or not
Intuition, sometimes it works and doesnt work, and there is not really a time that it is unnecessary
For example in exercise 6, you can either substitute or algebraically manipulate the integrand
You can also just play around with setting u= to parts of the equation and find du (the derivative) and see if anything will cancel out nicely
If two functions seem to have no relation and are products for instance 12... then parts is the way
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Hi, I'm trying to solve this recurrence:
but I'm unsure about how to transform $2^n$ into the proper form of $n^klog_p\left(n\right)$
Dr Xionel
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hello, if a function f_n is uniformly convergent (which means f is continuous) does it imply that its continuous?
LMAO
I don't understand 
Refer to Google before here
yea i did
to prove for continuity on [0,2]->R,
I plug in 1/n for n^2*(1/n) = n and 1/n for 2n - n^2*(1/n) = n. is approaching it like this enough or do i need lim?
you probably don't need to do a limit, but you should at least mention why you only check those points.
because they are different functions?
how do you know there's not a discontinuity somewhere else
you can individually prove continuity on [0, 1/n), (1/n, 2/n), and (2/n, inf) then verify x = 1/n and x = 2/n
to thus prove continuity on [0, inf)
individually prove continuity?
oh with the delta epsilon criteria?
if they’re being really strict yeah
you might just get away with asserting the limit equals the value of the function at the points on the interval so it converges
depending on level of required rigorousness
you can probably just note that each of those are polynomials
yes
Oh true
Is the question simply whether f_n defined above is continuous? Or was the question something about uniform convergence?
but i dont get why lim isnt necessary here
If a sequence of functions f_n converges uniformly to a function f, and each f_n is continuous, then the limit function f is continuous as well. That doesn't really apply here to showing that f_n itself is continuous.
It's a general fact that if a function is defined piece-wise like f_n above, the function will be continuous if each of the pieces are continuous, and they agree on the overlaps.
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can i get some help with this?
@slim steppe Has your question been resolved?
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Are we supposed to know Q6
no, what im confused on is what recursive rule any of those are i can't figure it out
Knowing Q6 would probably help
Yup does help
Write your sequence as arithmetic operations of the two previous terms
a_n =f(a_(n-1 ), a_(n-2))
is this for q6 or q7?
could you explain this in words, it would be a lot easier to understand
.
Maybe you should do 6 before 7
Okay
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Can you choose one of them and ask it
Whatever I answer 1
- left hand side is log_2(2020)
- that is a linear fractional transformation, or simply solve it by definition, very easy
3)t^2+at+b=0 has exactly one real root t
- is too easy, omit
- seems interesting let me think about it
Use $Z[x]/((x-1)x^{2}) \cong Z[x]/(x-1) \oplus Z[x]/(x^2)$
Find the inverse image of $(2,2x+3)$
Cogwheels of the mind
Now since the inverse image of (0,1) and (1,0) are 1-x^2 and x^2 respectively, so answer is (2)x^2+(2x+3)(1-x^2)=-3x^2+2x+3 mod (x-1)x^2
So (-3,2,3)
Can’t do you homework for you, 2,3 left to yourself
@vocal fulcrum Has your question been resolved?
This is for a study in japan scholarship
Filled out the form and there will be a written test
No syllabus is given and only past year papers are avilable online
Open questions?
In fact they are too simple
I don’t see anything you can research about those questions
Didn't read let me check them out forst then 
Parametric equations
Some terms I don't understand
And then the probability question
Should be doable
Had read some reviews of maths b being very difficult and in a video a guy went as far as saying you can't prepare for it in 2-3 months
Might have gotten influenced by him
Wtever thnxx
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I will make a presentation to show a visit to the water park with friends or family. Through the work on this, i will show practical use of mathematics. It is important that i include more of the topics in the subject. I will have to make a plan that includes prices, size, room, volume. I decide myself what i want to present at my presentation. A visit to a water park can be very varied from time to time. In the presentation I must also explain how i worked and delimit the topic, what sources i have used and how i have worked with it. Im not really an expert at math and not sure where or how to start, so help would be appreciated. Thank you.
Oh, I like maths project! Do you mind tell us what grade is this project for?
10th grade
I think you are list out the possible uses of those criteria,
- prices
- size
- room
- volume
What can you think of from these topics?
regarding room, volume, size, would i search the average size of a waterpark or would i search up a waterpark nearby that i can use as an example?
Of course! That would be a brilliant idea! Also, you can get the price of tickets and meals inside the park
You can also compare size of different pool, depths and volume of water, capacity for each facility
Or even time for queuing
There are so many things to do in this project!
thanks for the ideas! Could u help me doing so?
I don't think I have enough time to going through all of them, but you can try draw the blueprints for your imaginary water park, and plan the whole thing.
I always think that drawing out ideas would help a lot!
Alright, thank you!!
1 is solved, 2 you said you can do it yourself, so only 3 right?
3(1), dy/dx=(dy/dθ)/(dx/dθ)
2)y(t)d(x(t))=y(t)x’(t)dt
3)πy(t)^2d(x(t))=πy(t)^2x’(t)dt
Sorry to interrupt
Something like this
And draw each pool with an extra sheet, and prices with table, etc.
Good luck with your project! @red timber
thank u so much! I appreciate it lots
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Why is the answer 0?
try finidng the derivative of this
The derivative...
differentiate F(x) = f(x)/g(x)
quotient rule
Then yeah quotient
sure product or quotietn
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Can any1 explain how to do 6b? I did a and got the answer as 13.5 cm2
so that's the cross section right?
Ye
30 times what you got for a)
Pi r square h
how do you find the volume of a prism
Prism?
ok prism isn't the right word
But could you explain why?
Well
u can integrate a straight line from 0 to 30
but like i doubt that's what you're looking for
length will be height in the case and plug in the forumla ( pi times r^2 times height) , where height is 30 and radius is 7
Is it given? No
that's what u calculated right?
But I think I’ll be able to calculate it
the area of the shaded region
Oh yh sorry idk why I assumed you said volume
Yes ik the area
so the volume should be that * the length of the pipe
which u could prove via integration i suppose
Ohh ok thanks
but even with a triangular prism
the volume is the area of the cross section * height
a cube is also the cross section * height
Yh
a cylinder would be also πr^2 * h
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A cylinder of volume V has height (5 * pi)/2, and radius r. f(x) = [2 * sin(2 * x - 4 * pi) + 184]^(1/2). This function makes a solid when revolved around the x axis. The volume of this function is the same as V in the domain pi/2 to (3 * pi)/6. Find the radius of the cylinder.
Please don't occupy multiple help channels.
@rustic stirrup Has your question been resolved?
@rustic stirrup Has your question been resolved?
Hello, do you still need help with your question?@rustic stirrup
I assume he does cuz he said his question hasn’t been resolved but I’m not sure he migh5ve solved it alr
@rustic stirrup Has your question been resolved?
hi
Do you know what to do with f(x)? It says revolve around x-axis
Hint: integration
yup ! I know how to solve , but the volume is coming out to be 0 , and if that is the case the radius is 0 too , which is not possible
Maybe I am applying the limits of integration wrong
Can you show your work, maybe we can go through it and see if there is any mistake
$\sqrt{2sin(2x)+184}$
Lelouch
,w integrate sqrt(2sin(2x)+184)
It's essentially says from $\frac{\pi}{2}$ to $\frac{\pi}{2}$
Lelouch
Recheck the question
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Lmao w?
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any hints?
Yeah
Newton's method
This is clearly a JEE main question
They are tryna trap you, from the $p_{n+2}$ thing, make sure you have that right
@sage locust
aye i am in 10th now
preparing for ioqm
wait two is not in subscript?
$p_{n+2}$
Ann
this is how you latex it
Lelouch
Do you know the Newton's method?
no
Well then...
what is that about
Its about quadratics
It would take me ages to explain it here
So i assume u speak Hindi?
haa
Ok
So just google 'Unacademy Atoms Quadratic Equations One shot' on YouTube , and there will be a lecture from Nishant Vora ( The Mozart of Math Teachers)
It's a lecture on quadratic equations
Just skip to the Newton's method section if you only want to learn that, but i suggest u watch the whole thing tbh
All of NV Sir's FREE CLASSES: http://tinyurl.com/specialclassNV10
Nishant Vora FREE SERIES: https://unacademy.onelink.me/RICs/c3s245gl
Nishant Vora FREE SERIES: https://unacademy.onelink.me/RICs/714c7mib
PDF Notes: https://bit.ly/2YxBQ8c
Follow Nishant Vora Sir on Unacademy App: https://unacademy.com/@vora1310
Use Special Code: "NVLIVE" (To ava...
this one?
Yeah correct
ya i dont want to learn half the thing and get confused
tysm
I suggest watch all the One Shots of this #BounceBack series, it's all Free , and this guy ( Nishant Vora ) is arguably the best math teacher for high school math
@sage locust
he has a playlist?
Google #BounceBack

