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1 messages · Page 1024 of 1

nocturne dove
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arcsin(fx)

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If fx is between -1 to 1

north adder
#

but x gives us the domain

nocturne dove
#

For all x belongs R

north adder
#

OH

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ok

nocturne dove
#

I'm sorry if I wasn't able to convey it properly, but I'm trying xd

north adder
#

okay to summerise what youre saying is they should show the fraction in case of abs(x)

#

nono I really appreciate your effort

nocturne dove
#

Oh ok

#

I get it now

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@north adder

north adder
#

also also sorry to go back on this but how is this relevant

nocturne dove
#

They have written |x|≤1 because the function is not bijective otherwise

north adder
nocturne dove
#

I think if you apply the formula of arctana - arctanb it should all cancel out nicely

nocturne dove
north adder
#

okay yea

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it

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makes sense by a thin line

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im surprised you sitll remember all of this stuff

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even though its been a year

nocturne dove
#

Hehe I'm preparing for jee

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That's why I remember all this

north adder
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I feel like the 2x/(1+x^2)

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luckily coincides with the -1 to 1

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it wouldnt apply if for example it was 3x

nocturne dove
#

Yep bijective in -1 to 1

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No it wouldn't

north adder
nocturne dove
#

Thanks man.

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What grade u in btw?

north adder
#

finished 12th

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but didnt do cbse

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and have to do cbse for cuet

nocturne dove
#

Ohh

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Good luck with that

north adder
#

oh also

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another thing i noticed while learning these ridiculous formulas was

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the tan ntheta formula

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is like the binomial theorem?

nocturne dove
#

Yess

north adder
#

ohhh thats cool :')

nocturne dove
#

Its

north adder
#

how long have you been preparing for jee btw?

nocturne dove
#

(1 at a time - 3 at a time and so on)/ (1-sum of 2 at a time+(4 at a time)-....)

nocturne dove
north adder
north adder
nocturne dove
#

Gap uesr

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Year*

north adder
#

interesting

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youre smart tho, I think it will work out to your favour

nocturne dove
#

Unsure about it tho

nocturne dove
north adder
#

either ways, staying on task, so for this question you said tan^-1 x - tan^-1 y?

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but wouldnt that only work if denom was like 1 + xy

nocturne dove
#

I was talking about considering x/y as a and (x-y)/(x+y) as b

north adder
#

how do you think of this stuff.

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alright will do that

nocturne dove
north adder
#

initially i tried tan addition formula

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lol its the same thing

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okay im breaking

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thanks Teek

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appreciate it

#

.close

lone heartBOT
#
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low drift
#

How do I do fixed point iteration on a TI-84 calculator?

north adder
#

pretty sure you cant

low drift
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Like x=f(x) into a TI84 and just spamming = sign is what I was told

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Apparently you can, I just don't know how

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And then it should converge

north adder
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what

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wait

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are you talking about stationary points?

low drift
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I think so?

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I havent heard that term used before but probably

north adder
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nvm im dumb you can do 2nd trace max or min right?

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if you want a stationary point

low drift
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No idea

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Not very adept with teh ti84

north adder
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lol nvm I think youre talking about advanced math

low drift
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0.2-((2x^2+.0562x)/(x^2+.0562x+.00305)*.1)

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That's f(x)

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Solving for x by the fixed point iteration but idk how to do it on the ti84

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I know you can solve with the graphs or wolfram alpha, etc, but I'm trying to use fixed point iteration

north adder
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sorry, yea idk how to do that on the ti84

low drift
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All good I can wait if anybody happens to know

lone heartBOT
#

@low drift Has your question been resolved?

lone heartBOT
#

@low drift Has your question been resolved?

simple turtle
low drift
#

wait it's that simple???

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lol

lone heartBOT
#

@low drift Has your question been resolved?

lone heartBOT
#
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cunning trout
lone heartBOT
cunning trout
#

So where am I wrong here?

gray isle
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they want the equation of the normal

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(not tangent)

cunning trout
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Ok I see

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What did I do now?

gray isle
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-1/e^3 isn't equal to e^-3

cunning trout
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But isn’t it negative reciprocal of gradient?

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Which would result in a positive sign

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And then a negative power

gray isle
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the values themselves weren't equal which is one issue
so you should be writing any equations saying that

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and they're not negative reciprocals of each other which is another

cunning trout
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Then what would the gradient be?

gray isle
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take the negative reciprocal properly

cunning trout
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Ok

gray isle
#

it looks like you did the negative power stuff in addition to taking the reciprocal

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which just undoes what you did

cunning trout
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I see

gray isle
#

so overall you just did the negative here

cunning trout
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So would m=e^3 ?

gray isle
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where m represents the gradient of your normal line, yes

cunning trout
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Ok

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And are my points correct?

gray isle
#

you should write something like
$$m_{norm}$$
to be clear in your work

ocean sealBOT
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ℝamonov

cunning trout
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Mm ok sure

gray isle
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your point is correct

cunning trout
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Ok

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Can you tell me where I went wrong

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  1. the ans says something else
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Ramonov?

pliant wave
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textbook is wrong

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ignore the weird slant, i have weird axis numbers

cunning trout
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Ok right I see

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Thanks

#

.close

lone heartBOT
#
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tidal zealot
lone heartBOT
tidal zealot
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may someone identify what i did wrong

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bcs the answers are suspoed to be 63 and 39

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<@&286206848099549185>

wide raven
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a negative sign missing

nimble fern
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Does the question mean this?

gray isle
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they too the negs of everything before applying qf

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the values seem alright

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,w solve 35=22tcos(x) and 8 = -4.9t^2 + 22t*sin(x) + 2 and 0<x<pi/2

gray isle
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,calc 0.609918 * 180 / pi

ocean sealBOT
#

Result:

34.94572724906
gray isle
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,calc 1.13066 * 180 / pi

ocean sealBOT
#

Result:

64.782046064262
nimble fern
wide raven
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wait what's happening?

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ohh damm i thought you were asking a question

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i'm sorry😅

nimble fern
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Since Ramonov confirmed about the numbers,
@tidal zealot
must have misunderstand the question about "35 m from where the ball was thrown"

gray isle
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the wording is open to interpretation

tidal zealot
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hmm

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wait so

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am i wrong

nimble fern
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The words are unclear, but if the answer need to be 63°, 39°, then yea, you're wrong.

tidal zealot
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so wht did i do wrong

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in my equation

nimble fern
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35 is not the horizontal distance

tidal zealot
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hmm

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so would i have to use pytag to get the horizontal

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wait

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then

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what is 22

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oh shit

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wait

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22 is the speed

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not veloctiy

nimble fern
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22 is the speed, that part you're correct imo

tidal zealot
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how would i get the velocity

nimble fern
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You did used sine and cosine to get the horizontal and vertical speed using 22

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So, for those two equations that you've constructed, the only part that is wrong is the 35.

tidal zealot
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hm

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im confused

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wht do i put instead of 35 then

nimble fern
nimble fern
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Replace the 35 with
sqrt( 35²-6² )

tidal zealot
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im not getting the right answer still @nimble fern

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far outt

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idk what im doing wrong

lone heartBOT
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@tidal zealot Has your question been resolved?

tidal zealot
#

would you asssume that these two questions are somewhat similar? <@&286206848099549185>

north adder
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yes, but dont instaping

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.close

lone heartBOT
#
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tidal zealot
#

but anyways

lone heartBOT
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digital spoke
#

Can anyone give me a hint on why the last equation is true?

lone heartBOT
#

@digital spoke Has your question been resolved?

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remote kettle
#

If |sinx + cosx| = |sinx| + |cosx|, where sin x /= 0, cosx /= 0, then in which quadrant does x lie ?

remote heron
#

in general where does |x+y| = |x| + |y|?

remote kettle
#

sed

remote heron
#

you can split this out into every possible case and even then its only what like 9?

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x can be negative, 0, or positive

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same with y

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your problem removes 0

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so you only need to check positive and negative

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thats 4 cases

remote kettle
#

hmm

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ye

remote heron
#

you should check where |x+y|=|x|+|y|

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do the 4 cases

remote kettle
#

how to do ?

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the 4 cases

oak perch
remote kettle
#

how did u get thid

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this*

remote heron
#

cogwheels is around bearlain

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why even try

remote kettle
#

im doing inequalities and got this question

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so i don't even completely understand what you r trying to say

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sed

oak perch
#

I just thought maybe he can draw some diagrams😂

remote heron
#

idk if drawing diagrams like

oak perch
#

Thought he knew what |x|+|y|=k looks like

remote kettle
#

sed

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idk

remote heron
#

think about it like this

remote kettle
#

yes ?

remote heron
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|x+y| where both are negative

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so just rename them if u need to

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say theyre -a and -b

remote kettle
#

the absolute val will be (+)

remote heron
#

where a and b are positive numbers

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so we have |(-a)+(-b)|

remote kettle
#

ye

remote heron
#

|(-1)(a+b)|

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|(-1)||(a+b)|

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|(a+b)|

remote kettle
#

oh

remote heron
#

they are strictly positive

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so (a+b)

remote kettle
#

is it modulus

remote heron
#

it is not modulus

remote kettle
#

?

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then ?

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what is | |

remote heron
remote kettle
#

they mean the absolute values

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ryt ?

remote heron
#

yea

remote kettle
#

like

remote heron
#

its just distance right

remote kettle
#

|-x| = x

remote heron
#

distance from zero

remote kettle
#

oh

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OHHHH

remote heron
#

if you drive a mile from your house

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it doesnt matter if you go east

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or west

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or north

remote kettle
#

like magnitude ?

remote heron
#

youre still a mile from your house

remote kettle
#

kinda

remote heron
#

yea

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same idea

remote kettle
#

ok got it

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so

remote heron
#

thats why |-x|=|x|

remote kettle
#

sinx + cosx is strictly positive

remote heron
#

dont even worry about sin and cos

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solve the x+y problem first

remote kettle
#

oh

remote heron
#

heres what i would suggest

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pick one of the four cases

remote kettle
#

we have to do every possibility ?

remote heron
#

then like i just did, represent x and y in terms of some strictly positive variable

remote kettle
#

hmm

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then

remote heron
#

then see if you can make the equation true

remote kettle
#

hmm

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ok

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so

remote heron
#

try the positive positive case

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is is true then?

remote kettle
#

i shud pick every possibility for both the sides

remote kettle
#

wait a sec

remote heron
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you are just trying 4 possibilities

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theyre both positive, both negative

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you could even reduce it to three

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both positive, both negative, or one of each

remote kettle
#

i think both positive case satisfies the equations

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equation*

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oh

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i got it

remote heron
#

how about negative negative

remote kettle
#

it also satisfies

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ig

remote heron
#

positive negative?

remote kettle
#

no

remote heron
#

its that lefthand side, right

remote kettle
#

ye

remote heron
#

because |x+y| = |-(x+y)|

remote kettle
#

ye

remote heron
#

but theres no fixing |x-y|=|y-x|

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so ye

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you have solved the easier problem

remote kettle
#

Oh

remote heron
#

|x+y|=|x|+|y| is true where ....

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how can you translate this back into cos and sin?

remote kettle
#

so in this case no need to worry about sinx and cosx

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nvm

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sed

remote heron
#

there is a need, since the problem is asking

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but

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its a harder problem

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you said its true where both are negative

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or both are positive

remote kettle
#

ye

remote heron
#

so theres your answer

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but where is it satisfied with sin and cos

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,w plot cosx and sinx

remote heron
#

or you could maybe use a unit circle

remote kettle
#

unit circle ?

remote heron
#

dwai

remote kettle
#

dwai ?

remote heron
#

dont worry about it

remote kettle
#

oh

remote heron
#

just use whatever method is comfortable for figuring it out

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you are on the final step of the problem

remote kettle
#

how to figure it out ?

remote heron
#

👀

remote kettle
#

i don't know to

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find

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the value of

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sinx

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where x is an integer

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sed

remote heron
#

can you restate like

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okay whats the problem now, whats the next step?

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what are you trying to do at this point

remote kettle
#

hmm

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trying to balance the equation ?

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smthing lik that

remote heron
#

what was the solution to where |x+y|=|x|+|y|?

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what conditions did we need for x and y?

remote kettle
#

+,+

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-,-

remote heron
#

yea

remote kettle
#

so for sin and cos how does it differ ?

remote heron
#

so what conditions are on |sinx+cosx|=|sinx|+|cosx|

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what makes you think it will differ? catThink

remote kettle
#

sinx is not equal to 0

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neither is cosx

remote kettle
#

thinking

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the value

#

ig

remote heron
#

you dont need to calculate sinx or cosx

remote kettle
#

then ?

remote heron
#

you just need to extend your reasoning on the |x+y|=|x|+|y| problem

remote kettle
#

oh

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Sad

remote heron
#

to this

remote kettle
#

how.....

remote heron
#

i dont want to spell it out explicitly

remote kettle
#

ok

remote heron
#

you know where the x y problem is satisfied

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im telling you

#

identical conditions will make it true in the cos/sin case

remote kettle
#

so

remote heron
#

+,+ and -,- as u say

remote kettle
#

+,+ & -,-

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is it correct ?

remote heron
#

where is this satisfied for sin and cos

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where are they the same sign?

remote kettle
#

RHS

remote heron
remote kettle
#

why ?

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in rhs only

remote heron
#

idk what you mean right hand side

remote kettle
#

no matter what the sign it becomes positive

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so

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even if it is +,-

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it becomes +,+

remote heron
#

you are misinterpreting what i am asking

remote kettle
#

oh

remote kettle
remote heron
#

i dont mean in your uhh

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sure quadrant 1

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what about 2 3 and 4

remote kettle
#

ye

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oh

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so the anser is

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quadrant 1 and 4

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😅

remote heron
#

are you sure?

remote kettle
#

YEs

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is it ryt ?

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😭

remote heron
remote kettle
#

wwaut

#

i dint know this

#

NANI

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i don't know this table

remote heron
#

you can use this graphic to correct your mistake

remote kettle
#

😭

remote heron
#

its pretty minor

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lol dont give up so easily

#

youre almost done

remote kettle
#

i still need to learn more

#

so quadrant 1 and 3

remote heron
#

yea

remote kettle
remote heron
#

and not 2 and 4?

remote kettle
remote heron
#

yea

remote kettle
#

cuz different sign

remote heron
#

so

remote kettle
#

so unbalanced equation

remote heron
#

just depends on how your questions wants the answer

#

but

#

you have the answer now

#

its where sin and cos have the same sign

remote kettle
#

hmm

remote heron
#

quadrant 1 and 3

remote kettle
#

yea

remote heron
#

well do they want degrees or what

remote kettle
#

no

remote heron
#

or what form to write it

remote kettle
#

lol

remote heron
#

oh it just says quadrant

remote kettle
remote heron
#

then youre done

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nice

remote kettle
#

if they ask degrees ?

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is it 180 degrees ?

remote kettle
remote heron
#

dwai

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just use quadrants

remote kettle
#

hmm

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quadrants ?

remote heron
#

👀

#

like you just said

#

1 and 3

remote kettle
#

ok

#

so

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quadrant 1

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90 degrees

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and quadrant 3 90 degrees

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so

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totally 180 degrees

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am i correct ?

stone glen
#

:/ you lack theoretical knowledge@remote kettle

remote kettle
remote heron
#

dont listen to this person

remote kettle
#

its ok

remote heron
#

i wouldnt worry about degrees right now

remote kettle
#

ok

remote heron
#

it just makes it more complicated

remote kettle
#

oh

remote heron
#

you can do that later

remote kettle
#

ok

#

thank you for ur time

remote heron
#

no prob

remote kettle
#

✌️

#

.close

lone heartBOT
#
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fallow cradle
#

What kind of transformation does a matrix product like this represent, geometrically?

fallow cradle
#

If we have a certain vector and a (2x2) matrix, then we can conclude that it’s a certain transformation, for example a rotation, but what does matrix vector multiplication of this type represent exactly?

vale wigeon
#

well you could view [2, -1] as a linear functional on R^2

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ie a linear map from R^2 to R

fallow cradle
#

And this is because we only have one basis vector?

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I’m really struggling to visualise this

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We have one basis vector with two coordinates and it collapses onto one point

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How

vale wigeon
#

???

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idk what you're talking about sorry

fallow cradle
#

How a (2x2) matrix takes a certain vector and makes it another vector

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How does this collapse onto one point

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While if we inversed the order of the matrixes we would get a (2x2)

vale wigeon
#

(2x2) multiplied by (2x1) yields (2x1)

fallow cradle
#

Yes

vale wigeon
#

(1x2) multiplied by (2x1) yields (1x1), i.e. a single number

jagged trout
fallow cradle
#

I’m not interested in the math but what the geometric interpretation is

fallow cradle
#

Also the person who was typing, whatever you were typing for a while please feel free to post I would be happy to hear everything

#

I mean the thing in blue

jagged trout
#

That's a Tensor-/Matrixproduct

fallow cradle
jagged trout
#

Error around the 2:00 mark--I wrote that basis vectors are contravariant and that basis covectors are covariant. The opposite is true. Basis vectors are covariant and basis covectors are contravariant.

I realize the audio quality in my videos is pretty bad. I've ordered a microphone which will hopefully remedy that.

▶ Play video
fallow cradle
#

I have no idea what tensors are aside from vaguely hearing about them so forgive my noobie questions

#

Okay nice thank you

#

Appreciate it a lot

jagged trout
#

Maybe you should look the playlist from the beginning

fallow cradle
#

Yea I will

#

Thank you

#

Appreciate it a bunch

#

.close

lone heartBOT
#
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lone heartBOT
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desert fractal
#

Post questions

tight locust
#

No

lone heartBOT
#

@toxic lake Has your question been resolved?

sly mantle
#

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weary shard
#

How do we got from
$$x+x^2F(x)+xF(x)$$
to
$$F(x)=\frac{x}{1-x-x^2}$$

ocean sealBOT
weary shard
#

I read about generating functions

mortal trellis
#

\begin{align*}F(x) &= x+x^2F(x)+xF(x) \
F(x)-x^2F(x)-xF(x) &= x \
F(x) (1-x^2-x) &= x \
F(x) &= \frac{x}{1-x^2-x} \end{align*}

ocean sealBOT
#

Denascite

weary shard
#

Oooh

#

Ok, thanks

#

.close

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dawn quail
lone heartBOT
dawn quail
#

I am very confused what the correct answer should be here

#

If the left version does not work, can someone help explain why?

worn fox
#

The second line of the left version

#

You have (h+1)h^2 on top

#

Expand that, see if it is equal to what is on the line before

dawn quail
#

Oohhh

#

Ty, that took me down the wrong road!

#

Good eyes

worn fox
#

No worries!

dawn quail
#

What is the cube formula called again? For the right side

#

It’s like saying 1 cubed

#

I didn’t bother to expand on that

worn fox
#

Uh it's sum of two cubes formula

dawn quail
#

Thanks

#

That one is hard to remember

#

I can remember difference of two squares

#

This will take more practice

worn fox
#

If you remember the formula for geometric sum then you can remember it easier

#

Divide both sides by h+1

#

And its a geometric sum formula with common ratio -h

dawn quail
#

😆

#

Haven’t learned that one yet either

#

Good to know!

worn fox
#

Oh lol, something to look forward to haha

dawn quail
#

Are you taking math in university?

worn fox
#

Just finished my integrated masters

dawn quail
#

Wow 🤩 Congrats!

worn fox
#

Thanks😄

dawn quail
#

What do you plan on doing after university?

worn fox
#

Got a PhD lined up in September

#

Basically avoiding the real world for as long as possible😅

dawn quail
#

Awesome! But after all the school you wanna get into a field with computer science or teaching or?

#

Nothing wrong with PhD 😄

#

Only the select few make it that far

worn fox
#

Will have to see, my opinion might change alot I 4 years hahaha, I wanna teach and do research but it involves a lot of moving around on temporary contracts

#

Will have to see if I'm up for that

#

Otherwise will go into industry

dawn quail
#

Yeah

#

Big money to make the 4nm SoaC at Apple 😉

#

But too small and get into quantum limits where electrons pass through logic gates

#

What Apple did with M1 is pretty remarkable

#

Anyways I will let you go

#

Thanks again!

worn fox
#

See you around:)

dawn quail
#

.close

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quaint orbit
lone heartBOT
quaint orbit
#

Hi just like to confirm,

My own answer to the question is: The nullspace of C contains vectors that lie in both the nullspace of A and the nullspace of B

#

that's the same as what the solution is saying right

mortal trellis
#

yes

quaint orbit
#

ok thank you 🙂

#

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dawn wraith
#

how do i go about doing question b?

lone heartBOT
#

@dawn wraith Has your question been resolved?

winter tangle
#

do you know what the standard deviation means?

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@dawn wraith Has your question been resolved?

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brazen copper
#

Anyone know how to get the answer to this? I tried a few times but only end up with impossible answers where z is a real number.

gray isle
#

can you show your attempts

brazen copper
#

well it was mentally but I can write it and then send

oak perch
#

This is quadratic in terms of 7^z

brazen copper
#

yes

gray isle
#

well it was mentally but I can write it and then send
yeh, don't do that mentally

alpine sable
#

Always write

gray isle
#

trying to do something that involves several lines of work mentally will most likely lead to mistakes

alpine sable
#

Hmm

#

There're no real roots I assume

median oar
#

no there isnt

brazen copper
#

i kinda gave up after that

#

bc 7^z = 0,-2 makes no sense

gray isle
#

are you sure you're being asked for real solutions?

median oar
#

well there is solution(s) if u know complex numbers

alpine sable
#

Yea you got it right

brazen copper
median oar
#

and that too, usually z indicates complex numbers

alpine sable
#

I assume they asked you to find all roots in complex range

gray isle
#

if z is being used then its possible that complex numbers are involved

brazen copper
#

school sent it for summer break practice (and I'm doing it on the last day) but I haven't been taught imaginary numbers

alpine sable
#

well

#

Then no roots

#

Since you hasn't been taught complex numbers

gray isle
#

then yeh, write no real solutions

brazen copper
#

so just z is not a real number?

alpine sable
#

Yea, you can write in both way, no roots or no real roots

brazen copper
#

why roots

#

like why write roots

#

just real number should be fine

alpine sable
#

To be precise

brazen copper
#

right

#

ty for your help

#

.close

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mild solstice
#

I know this is wrong, I know the silly mistake, but i just don't know how to get on with it the correct way

mild solstice
#

This is the working out

#

I just can't understand how to inverse this

cobalt remnant
#

this one is easy

mild solstice
#

i mean functions in general

#

but u get the idea

cobalt remnant
#

i am joking i dont understand this one too, i am trying to do it but i cant

mild solstice
#

oh rip

mild solstice
#

the h(x) is fg inverse

stone glen
#

Is ur answer not correct?

mild solstice
#

but i don't understand how to inverse it

stone glen
mild solstice
#

i think

stone glen
#

Is that not fog(x)

stone glen
#

Ask ur teacher

mild solstice
#

compound function

#

so id say 90% sure

stone glen
#

Okay

stone glen
#

@mild solstice

#

Nice name btw , i support it

lone heartBOT
#

@mild solstice Has your question been resolved?

mild solstice
#

So this?

#

Thanks

lone heartBOT
#
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stone glen
lone heartBOT
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ancient pecan
#

is this possible ?

lone heartBOT
oak perch
#

It converges

alpine sable
#

$\lim_{n \to \infty} \frac{3^n*n^3}{8^n}$

ocean sealBOT
#

π^2=g

ancient pecan
#

what does that even mean

#

😭

oak perch
#

What?

alpine sable
ancient pecan
#

basically

#

no

oak perch
#

Just Prove it is zero

ancient pecan
#

howww

stone glen
#

Zewo

median oar
#

that is very advanced for someone who hasn't even learned the basics about limits

oak perch
#

Wait why are you asking this without even knowing the definition of limit?

alpine sable
#

and understand them

ancient pecan
alpine sable
oak perch
#

Does language really matter in math?😂😂

ancient pecan
ocean sealBOT
#

π^2=g

stone glen
ancient pecan
#

arabic

#

and hebrew

alpine sable
#

oh man my man why does my latex sucks

#

,w convergence of limit in arabic

ocean sealBOT
stone glen
oak perch
#

My language from English is almost same as how far your language from English though…😂

oak perch
#

Mandarin

median oar
#

exponentials beat x^3

alpine sable
median oar
#

so ignore it

stone glen
alpine sable
#

thanks to google translate

ancient pecan
median oar
#

3^x loses to 8^x

#

so the bottom grows fasters

#

so it tends to 0

#

does that help XD

ancient pecan
#

yea it does but like Idk how much the n is

#

does that matter

stone glen
median oar
#

n is going to infinity

ancient pecan
#

like what if

#

OH WAIT

median oar
#

it's asking what the thing would equal

#

if n is very big

#

very very very big

ancient pecan
#

yea yea

#

okay okay

#

don't mind me guys i'm in high school

#

still learning limits

median oar
#

all good have fun

stone glen
#

By big he means VEEEEERRYYYY BIG

alpine sable
ancient pecan
median oar
alpine sable
#

perhaps what the thing is approaching as n becomes very very very .... big

median oar
#

sorry i slipped D:

stone glen
alpine sable
alpine sable
oak perch
#

Not sure he can solve this just by definition … I used Hopital…

stone glen
#

Honestly

ancient pecan
#

I still didn't learn about it or whatever

alpine sable
ancient pecan
#

or maybe we did and i missed classes

#

i'm doomed

#

😭

stone glen
oak perch
#

Then you better catch up..

alpine sable
#

💀 so you only know factoring methods?

ancient pecan
stone glen
#

BRUH

#

Dude

alpine sable
#

wait what

ancient pecan
#

well basically, we learn calc in high school but it's so basic, but since i'm " good " at math, a teacher took me and a couple of students and started teaching me college stuff

#

or whatever

alpine sable
#

is symbolab saying

ancient pecan
#

so yea 🙂

worn fox
alpine sable
#

,w limit as n goes to infinity (3^n*n^3)/8^n

stone glen
alpine sable
alpine sable
median oar
#

i dont think this is "college" level math yet

stone glen
ancient pecan
#

IN BASICS

#

don't kill me

#

🙂

#

I suck at limits

median oar
#

no im just saying this is like high school level advance stream type topic

ancient pecan
median oar
stone glen
#

@ancient pecan focus more on math than league

ancient pecan
#

i'm happy anyways with how far I came 🏃

ancient pecan
#

we don't talk about league

stone glen
#

League <<<

median oar
#

you can read up on how he does the proof for how exponentials grow faster than polynomials

median oar
#

then u can factor the x from 3 and 8

#

then put (8/3)^x on the bottom

stone glen
median oar
#

so you have a polynomial on the top

#

and exponential on the bottom

ancient pecan
#

well anyways

#

thank you for helping

#

am I supposed to close this ?

#

.close

lone heartBOT
#
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civic ferry
#

how could you solve this by factoring?

lone heartBOT
gray isle
#

start by rearranging the equation into general form

civic ferry
#

15c^2-8c-12=0?

#

@gray isle

gray isle
#

yes

civic ferry
#

where do i go from there>

#

?

gray isle
#

for non-monic quadratics consider stuff like ac-method and grouping

#

i.e. consider the value of ac, in this case 15 * -12
find a pair of values that multiply to that and sum to b=-8

#

and use that to split the -8c term

civic ferry
#

would it be wrong to solve it with quadratic formula?

gray isle
#

depends on what you're being asked to do

#

if there are no explicit instructions, you can use whatever valid method you want

civic ferry
#

it says "solve by factoring"

#

and that's it

gray isle
#

then yeh, it'd be wrong to use the QF

#

as that isn't solving by factoring

civic ferry
#

oh okay

#

i missed the lesson on solving by factoring so idrk

gray isle
#

for non-monic quadratics consider stuff like ac-method and grouping
i.e. consider the value of ac, in this case 15 * -12
find a pair of values that multiply to that and sum to b=-8
and use that to split the -8c term

#

i gave you a brief intro to the method i prefer

civic ferry
#

ok thanks

#

.close

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toxic fox
#

this question do be confusing me

lone heartBOT
toxic fox
#

the answers say this

#

where did the 11 and 6 come from and can someone explain this to me

drifting hull
# toxic fox

For a=11, b=6 you know that 82896=(a+b)^4-(a-b)^4. You can now simplify these as polynomials: (a+b)^4-(a-b)^4=8ab(a^2+b^2) for general a,b. So you get 82896=8 * 11 * 6 * (11^2+6^2)

#

I would guess that in part a) of the same exercise a similar thing was done...

toxic fox
toxic fox
drifting hull
#

🙂

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#

@toxic fox Has your question been resolved?

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obsidian wagon
#

For part b are they asking me to just integrate normally?

obsidian wagon
#

First time coming across a question like this for areas under a curve

#

<@&286206848099549185> 😭

lime bobcat
#

Yes

#

The first part is to calculate numerica integration. The second part is for exact symbolic integration

lone heartBOT
#

@obsidian wagon Has your question been resolved?

obsidian wagon
last ether
#

Numerical

#

Prob a typo

lone heartBOT
#

@obsidian wagon Has your question been resolved?

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iron tree
#

how do you find the LCM of an expression and then two numbers for example:
2/x + 2 - 1/3 = 1/15

slender gull
#

First take LCM for 2 - 1/3 for ease.

#

Then, with x in the denominator for the first term, you have to multiply x with the other denominator. Since you don't actually know the value of x, the product of x and the other denominator should actually be their LCM as of now.

#

Then repeat that with 15 if you wish to.

#

@iron tree

iron tree
#

Ok

#

so what's the real LCM

#

what do we multiply the 2, 1 and 1 with ??

lone heartBOT
#

@iron tree Has your question been resolved?

lone heartBOT
#

@iron tree Has your question been resolved?

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lone skiff
#

.close

lone heartBOT
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visual stag
lone heartBOT
visual stag
#

how could i integrate that

#

i used reverse chain rule aand got x/3(Inx)^3

#

but the markscheme used integration by parts and got something completely different

mortal trellis
#

try differentiating x/3 ln(x)^3

#

I don't know what you mean with "reverse chain rule". the tool to "undo" the chain rule of differentiation is a u-sub

#

but I don't know what you u-subbed here

visual stag
mortal trellis
#

chain rule and product rule?

visual stag
#

ahhh i see what u mean now

#

i cant use chain rule with 2 terms

#

tyy

#

.close

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night pumice
lone heartBOT
night pumice
#

pls help

high rapids
#

what have you tried maam

alpine sable
#

Eh

#

You know how y=x^3 looks like

#

Right

night pumice
#

I’ve learned nothing from my teacher

alpine sable
#

,w plot y=x^3

alpine sable
#

See

obtuse valve
#

anyone have chegg
i really need help here.

alpine sable
#

Just plug in the biggest number in the set

alpine sable
obtuse valve
#

sry

alpine sable
stone glen
night pumice
#

yea-

alpine sable
#

or simple way:

#

just plug all three values and compare

night pumice
#

is there like a video I can watch for me to catch up?

alpine sable
#

I have no idea what year are you in now

stone glen
#

I'd say grade 8

#

Not sure tho

alpine sable
#

uk or america?

night pumice
#

America, 7th grade 💀

stone glen
#

Yeah, there is alot of content in the internet just search for it

#

I found alot of it in my native language, I'm sure u will find alot in English

alpine sable
#

just search year 7 maths recap in youtube

night pumice
#

What do I search up

#

ok

stone glen
stone glen
stone glen
night pumice
#

idk I’m failing every mp

high rapids
#

Can you see the relationship between y and x here?

night pumice
#

no

high rapids
#

It's written at the top

#

Can you spot it?

night pumice
#

Oh ok

stone glen
night pumice
#

yes

high rapids
#

Can you write it here?

night pumice
high rapids
#

Yes

#

y=x^3 right?

night pumice
#

ye

high rapids
#

What can x be?

night pumice
#

idk

high rapids
#

It's written

night pumice
#

oh

#

-1/3, 1/2, 1/3

high rapids
#

It's either x = -1/3, 1/2 or 1/3

#

Yes

#

Suppose x is -1/3

#

What is y then?

night pumice
#

-1/3^3 ?

high rapids
#

Exactly

night pumice
#

yas

high rapids
#

Can you simplify more?

night pumice
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no

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idk

high rapids
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Well you can write -1/(3x3x3)

night pumice
#

oh

high rapids
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Which is -1/27

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Right ?

night pumice
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yea

high rapids
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Now what is y when x = 1/2?

night pumice
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.125?

high rapids
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Well yeah

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Or you could write as 1/8

night pumice
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yea

high rapids
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Now what s y when x = 1/3

night pumice
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1/27

high rapids
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Yes

night pumice
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yas

high rapids
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Now compare the results you got

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-1/27, 1/8 and 1/27

night pumice
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1/8

high rapids
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Which one is the biggest number?

stone glen
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-1/27

night pumice
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wat

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but that’s negative

high rapids
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Vanilla answer

night pumice
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1/8?

stone glen
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She did

high rapids
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Yes

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So 1/8 is the maximum value of y

night pumice
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oh

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yay thank you so much

high rapids
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You and @alpine sable both are quite similar

night pumice
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really

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how old is

high rapids
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I mean just look at his profile

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He's like 13

night pumice
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OMGG so cute dogggoo

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mines rats kissing

high rapids
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Yuck

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🤢🤮

night pumice
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maybe

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ok tysm!

high rapids
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I will kill those rats