aka "arithmetic sequence"
#help-0
soft needle
@finite flax Did I do it incorrectly?
finite flax
<@598041720583618605> Did I do it incorrectly?
you're doing it right
soft needle
Oh
finite flax
You're confused about what now
soft needle
Oh so you didn't read what I had sent here
soft needle
Ah ok
finite flax
sorry
finite flax
looks fine
finite flax
It's actually pretty simple
yes.
it gets much worse but you probably won't ever see that in school
soft needle
I'll finish #3 and #4 and get back to you
finite flax
just hmu if you can't verify something
soft needle
it gets much worse but you probably won't ever see that in school
My last year of math is geometry 
Which is next school year
Then I won't have to take any math related class in my senior year
soft needle
isn't geometry sophomore year? 🤔
They changed it, there's these Keystone exams at the end of the school year which have to do with algebra 2.
soft needle
so only 2 years of math?
I'm a sophomore right now
finite flax
ok
soft needle
Freshman was Alg 1
soft needle
Yeah
finite flax
hrm
soft needle
I'll have the credits needed to graduate
finite flax
I think when I was in school only 2 years was required
soft needle
I think when I was in school only 2 years was required
Oh wow, that's awesome. I wish I had that
finite flax
I think kids should do...useful things in hs
but since we aren't doing that anyway
4 years of useless math.
soft needle
I think kids should do...useful things in hs
Definetly
Math is very useless when it gets to adding letters
I have yet to actually use it in the real world
finite flax
none of this would be uselessl if there were better applications
soft needle
Yeah.. anyways I'll get back to it. Have a good one
finite flax
Math is very useless when it gets to adding letters
I mean that's kinda the building blocks of all useful math tbh
finite flax
Yeah.. anyways I'll get back to it. Have a good one
k
soft needle
I mean that's kinda the building blocks of all useful math tbh
Tbh I wouldn't know yet, I still have a long way ahead of me
finite flax
all of this looks fine
finite flax
<@598041720583618605> How do I do the next ones, 5, 6, and 7?
you need to know what the important pieces of arithmetic sequences and geometric sequences are, and how to tell what kind of sequence it is given just a list of numbers.
the good news is, this information is all over the internet
so if one webpage has a crappy explanation, another page will be better.
I will even tell you what they are
and you can look them up
direct equations for these sequences both involve the first term, usually given as
$a$
ocean sealBOT
Disorganized
ocean sealBOT
Disorganized
finite flax
the formula for an arithmetic sequence involves a common difference, d
the formula for a geometric sequence involves a common ratio, r
look up explanations that tell you how to find those and you will be good
finite flax
np
ocean sealBOT
n256
naive valley
are you sure you're parsing it correctly? "finite $\mu$-almost everywhere" means finite everywhere except possibly on a set $E$ such that $\mu(E) = 0$
ocean sealBOT
OurBelovedBungo
naive valley
in other words, it's "finite almost everywhere", where the mu is included to emphasize that they mean almost everywhere with respect to mu
yep
fallen rain
Can someone help me with part d pls?
lone heartBOT
Can someone help me with part d pls?
fallen rain
lone heartBOT
@fallen rain Has your question been resolved?
vagrant cobalt
is this an exam question?
woven crane
I would help if the exam is rn
??
vale wigeon
bye bye
tall wing
banned
woven crane
that was a trap
I mean looks like they're already trapped lol
vagrant cobalt
.close
surreal delta
What sign is this? 😅
lone heartBOT
What sign is this? 😅
woven crane
What sign is this? 😅
product over the index {i}
surreal delta
Ah so its like "Sum" but with product?
woven crane
yep
remote bay
Hello
remote bay
I must simplify and I don't know how
alpine sable
hmm
correct me if im wrong, but it cant be simplified
because the pronumerals dont match
remote bay
Simplifying Ratios
Lesson Name
alpine sable
otherwise it'll be (replace = with :)
remote bay
Really nothing at the lesson say this
alpine sable
A person who has a deeper knowledge about this will suit better
abstract fractal
Consider if it was written as $\frac{10a^2b}{15ab^2}.$ How would you simplify it then?
ocean sealBOT
Gamer Dio
abstract fractal
Just cancel out the common factors
How do you simplify 2/4? Cancel out a factor of 2 to get 1/2
How to simplify a²/ab? Cancel out an a to get a/b
Same process
remote bay
Okay thanks
thorn tapir
A simpler algorithm - Find out the Greatest Common Divisor (Highes Common Factor) of the two numbers, and divide both by that. You'll have the reduced ratio.
If there was more than 2 numbers, then also do the same (find the GCD/HCF for all and divide everything with that)
If your GCD = 1, then the ratio is already simplified
short cove
lone heartBOT
short cove
What’s wrong with my working?
ocean sealBOT
covered call club
merry depot
nothing?
woven crane
it doesnt take into account the full solution set
short cove
it doesnt take into account the full solution set
how
woven crane
how
i dont know how to explain it well, but doing the cross multiplication step throws away half of the solution
instead keep them as fractions and simplify
merry depot
oooooh shit, yeah. x or x+2 can be negative, so multiplying would change the sign direction
tribal oxide
What’s wrong with my working?
U cant cross multiply cuz u dont know what the value ur multiplying with is
woven crane
oooooh shit, yeah. x or x+2 can be negative, so multiplying would change the sig...
right thats it^^
oblique pier
because it will helped you find x
woven crane
but why would rearrangement work?
you dont make any implicit assumptions in doing so
oblique pier
woven crane
you dont make any implicit assumptions in doing so
like above, when you cross multiply, you basically assume the sign of the cross-multiplied terms to be +, which restricts your solution set artificially
short cove
i see
oblique pier
@short cove in inequalities
short cove
it makes sense now
oblique pier
u aren't allow to cross product
short cove
thanks
that removes my confusion
i do understand about the conversion of positive to negative at times
but i didnt expect it to happen in this case
tribal oxide
u aren't allow to cross product
You can if ur sure about the sign of the thing youre cross multiplying with, even if u do cross multiply and ur not sure abt the sign then one way we can do it is by taking cases with x>0 and x<0
silver drum
The selling price of snowboards fluctuates bwtween a maximum of $150 and a minimum of $100 over a year. If the peak selling month is January (t=0) and the slowest time is in July (t=6).
a) determine an equation in the form y=acosk(x-p)+q
b) Determine when the selling price is $125 (there will be 2 months).
thick lynx
For one game the bet is 1€. Two tetrahedron dice are thrown.
If the same number appears twice, you get 3€. Otherwise nothing is paid out.
thick lynx
What's the probability of getting nothing?
vagrant cobalt
{(1,1),(2,2)...(6,6)} consider this subset from sample space
wait
tetrahedron
got it
naive valley
tetra = 4 😁
thick lynx
To win 2€, the probability is 1/4, so to not is 1 - 1/4 = 3/4
but now I don't want to do it with the 1 -
I want to do it with calculations right away
how do I do that?
1/4 * 3/4 * 4?
vagrant cobalt
{(1,1),(2,2),(3,3),(4,4)}
are the cases where you win
so you have in total 16 possibilities
so remaining we have 12 waays where we get nothing
12/16= 3/4
naive valley
how do I do that?
1/4 * 3/4 * 4?
you can argue like this: the first die can have any number, and the second one can have anything except the one on the first die
so the number of outcomes that pay nothing is 4*3
thick lynx
you can argue like this: the first die can have any number, and the second one c...
Yes, so 1/4 * 3/4, right?
thick lynx
so the number of outcomes that pay nothing is 4*3
But why do you not have to do the * 2 thing here?
P("First", "AnythingButFirst")
P("AnythingButFirst", "First")
or does that not make sense
naive valley
But why do you not have to do the * 2 thing here?
P("First", "AnythingButFirst")...
pretend that the dice are colored or something, so you can distinguish them
say red and blue
the red one can be anything and the blue one can be anything except what the red one has
or you can argue the other way, the blue one can be anything and the red one can be anything except what the blue one has
same answer either way
thick lynx
oh
thick lynx
same answer either way
So it's not the same as "throwing a 3 and a 4 with a dice"
then it would be 1/6 * 1/6 * 2
because you could first throw the 4 or the 3
naive valley
right, we're just counting mismatches
and to do that, you can pretend that you can distinguish or that one was rolled before the other, in order to aid in counting
(because the probability of a mismatch is the same whether the dice are distinguishable or not)
thick lynx
1/4 * 3/4 = P("rolling anything", "rolling anything but the first roll")
3/4 * 1/4 = P("rolling anything but the first roll", "rolling anything")
But if we roll anything in the first roll, the probability for rolling anything in the second should be 3/4, not 1/4
is that also a possible explanation?
lone heartBOT
lone heartBOT
Available help channel!
iron swallow
lone heartBOT
iron swallow
<@&286206848099549185>
alpine sable
,rotate
ocean sealBOT
iron swallow
Hello
Help pls
<@&286206848099549185>
<@&286206848099549185>
@alpine sable you going to help
short cove
lone heartBOT
short cove
i dont understand the question, which made my solution:
Can someone explain to me about my misunderstanding?
vale wigeon
you want the distance moved by the shuttle
bitter vault
i dont understand the question, which made my solution:
It's moving in an arc of a circle. You've only found the radius of the circle so far
vale wigeon
not the distance from it to the earth's core
short cove
oh
naive valley
Is your problem solved if it is could I have my Chanel back
you already have one open, #help-6
iron swallow
Could I have some help in this
short cove
gimme a sec
so i assume that by adding 6380 and 330, thats the new radius to be used. and the s from s = r theta will be the required arc
right?
.close
celest herald
lone heartBOT
gray ingot
what have you tried?
celest herald
Squaring both sides to get rid of 2 square roots on the right
naive valley
when there are two square roots being added, it's usually helpful to move one of them to the other side before squaring
celest herald
hm ill try that
naive valley
it's odd that they ask for x^2 + x + 1, makes me wonder if there's a clever trick that doesn't involve finding x first and then plugging it into x^2 + x + 1
it's easy enough to find x though
celest herald
I got x=3.5
which when plugged into the second part doesnt give one of the choices
woven crane
I got x=3.5
you must've made a mistake somewhere, because this doesn't satisfy that equation
harsh girder
you can start from $2\sqrt{x}-1 = \sqrt{4x-11}$, square the both sides
ocean sealBOT
秋水
harsh girder
yes
woven crane
25 + 11
naive valley
it's a cliche that mathematicians can't do simple artihmetic
so you must be a mathematician @celest herald 😁
naive valley
yep
celest herald
uh if i want to ask another question do i open a new channel?
naive valley
seems ok to just ask it in this one
celest herald
naive valley
oh yuck
celest herald
my first guess would be to go through the powers until they reach 500
like 2^2, 2^3.....2^8
naive valley
the good news is that a can't be larger than 22
celest herald
then move on to 3^2, 3^3
naive valley
since b has to be > 1
still a lot of manual checking unless there's a clever way to tackle this
also you need to skip 4^2,4^3 etc because those are also powers of 2
celest herald
alright
i wanted to see if there was a mathematical way to do it instead of brute force
naive valley
the other good news is that once you reach a=9, the only possible value for b is 2
because 9^3 is bigger than 500
(also you'll skip 9 anyway because those are powers of 3)
naive valley
i wanted to see if there was a mathematical way to do it instead of brute force
yeah that would certainly be preferable, but offhand i don't know of a nice way
naive valley
hmm well if the original sides were x and y
and therefore the original area was xy
then the news sides are x+10 and y+10
so the new area is (x+10)(y+10)
celest herald
right
naive valley
and you know the new area minus the old area is 300
that should allow you to eliminate one of the variables
ah
and it turns out that suffices
try computing (new area minus old area) and setting it to 300 and simplifying
naive valley
you actually won't be able to solve for them individually
but consider the formula for perimeter
celest herald
alright
naive valley
(be careful: the perimeter is not x+y)
naive valley
hmm maybe there's some smarts that can be applied
if you factor a^2 - b^2 you get (a+b)(a-b)
so (a+b)(a-b) = (3)(5)
so either a+b or a-b is divisible by 3
and similarly one of them is divisible by 5
elder grail
u could eliminate all even powers after counting square cases
naive valley
yes
elder grail
lil lesser work
naive valley
not sure if you gain anything by taking it modulo 3 or modulo 5
my brain is too tired lol it's 4:30 here
i'm gonna head to bed
celest herald
alright cya
naive valley
nite
celest herald
.close
blissful anchor
Hey can someone please help me link two steps
lone heartBOT
Hey can someone please help me link two steps
gray ingot
first principle?
pallid bolt
Hello
wraith meteor
Go
wraith meteor
So both sides are equal?
pallid bolt
I have to put a number for x
wraith meteor
6
wraith meteor
If you substitute 6 into x
gray ingot
I have to put a number for x
yes
start with putting 1,
LHS = 5x-3 = 5(1)-3= 5-3 =2
RHS = 2x + 15 = 2(1) + 15 = 2 + 15 = 17
LHS != RHS
keep doing this till LHS = RHS
wraith meteor
You will get the same answer on both sides
pallid bolt
bit confusing
wraith meteor
Should it be 56 or 5 • 6
Multiply
pallid bolt
So 5•6
lone heartBOT
@pallid bolt Has your question been resolved?
novel dove
You need to transform the power into a root
Like a^x/y is sqrt(y)a^x
No,just drop them into roots
Calculate 2a and b,you gonna end up with (a+b)^2
Then derive it into (a-b)(a+b) so you can cancel out the bottom
You should end up with a final sum of root 3a + root 3b+root 3c
Sure,go ahead
lone heartBOT
@alpine sable Has your question been resolved?
dense lily
Can someone please explain to me why x + 2y = 5 is graphed the way it is graphed
Wat
WHAT
Wait wait wait wait
Wait
Waita
Wait
Stop
Rihgt
There
Why tf is -x there
Its just positive x
oh
What is the final y = mx + b outcome then
Oh
And 2.5 is the y-intercept
So with your explanation
This
Is correct?
clear stump
Yes?
dense lily
Moveur paper lmfao i dont see the ending of 9a
ocean sealBOT
.,..
clear stump
Moveur paper lmfao i dont see the ending of 9a
And why does that matter excactly
he is stuck on 8a
novel dove
You need to form it into (a-b)(a+b)
(A+B-C)(A+B+C) / (A+B-C)
Cancel out and you're gonna be left with 3rd roots of a b and c
You understand?Since c^2 is outside,you can equivalate it into the formula
Enjoy :)
Yeah,you had (a+b)^2 - c^2
So yeah
split olive
lone heartBOT
split olive
how do i go from the first equation to the next
lone heartBOT
@split olive Has your question been resolved?
lone heartBOT
@split olive Has your question been resolved?
lone heartBOT
@split olive Has your question been resolved?
rugged sun
Hi, one moment
split olive
thank youuuuuu
rugged sun
Can you tell me, have they done the substitution x=sin(theta)
split olive
x=cos(theta)
rugged sun
Ok
They are doing a change of variable in the derivative, I am just trying to replicate their result, 2 minutes please
split olive
thank you, take your time
rugged sun
Ok Thanks
rugged sun
thank you, take your time
Sorry, I'll need a little more time, I have seen this before but I can't get it to look exactly like what they have, do bear with me, if the chanel times out, would you mind if I dm you a solution?
rugged sun
Ok thanks, i have it roughly
rugged sun
No worries, thanks a lot for helping me
Ok, so I have a way I am happy with
rugged sun
Basically what confused me initially is that the variable in the function Y changes from x to y in a way I couldn't replicate
But it is helpful to think of the coordinate transform in the following way
split olive
Right
rugged sun
In "x-space" if you will, the function is Y(x). In "y-space", we will define a new function called Y*(y) in the following way
Let the coordinate transform be denoted y(x)=sqrt(1-x^2)
Therefore
,, Y(x)=Y(y^{-1}(y(x)))
ocean sealBOT
Social Capital Gainer
rugged sun
The y and inverse y cancel
split olive
Right
rugged sun
We will merge the Y and y^-1 into a new function called Y*
,, Y(x)=Y(y^{-1}(y(x)))=Y^(y(x))=Y^(y)
ocean sealBOT
Social Capital Gainer
rugged sun
We will now get their result in terms of the function Y*
In y-space
For the derivatives, we can write the following
,, \frac{dY(x)}{dx}=\frac{dY^(y(x))}{dx}=\frac{dY^(y)}{dy}\frac{dy}{dx}=\frac{dY^*(y)}{dy}\left(-\frac{x}{y}\right)
ocean sealBOT
Social Capital Gainer
rugged sun
I will focus only on the derivative part of your differntial equation
split olive
Right
rugged sun
Putting in y^2 in place of 1-x^2 in both places, we get
,,y^2\frac{d}{dx}y^2\frac{dY^*(y)}{dy}\left(-\frac{x}{y}\right)
ocean sealBOT
Social Capital Gainer
split olive
Yeah, make sense
rugged sun
Where I used our expression for dY/dx
Rearranging a bit
,,-y^2\frac{d}{dx}xy\frac{dY^*(y)}{dy}
ocean sealBOT
Social Capital Gainer
rugged sun
Now using the product rule to differentiate wrt x
,,-y^2\left(y\frac{dY^(y)}{dy}+x\frac{dy}{dx}\frac{dY^(y)}{dy}+xy\frac{d}{dx}\frac{dY^*(y)}{dy}\right)
ocean sealBOT
Social Capital Gainer
split olive
Okok
rugged sun
For the middle term, we differntiate the y(x) to get
,,-y^2\left(y\frac{dY^(y)}{dy}+x\left(-\frac{x}{y}\right)\frac{dY^(y)}{dy}+xy\frac{d}{dx}\frac{dY^*(y)}{dy}\right)
ocean sealBOT
Social Capital Gainer
rugged sun
For the term on the right, we note that Y*'(y) is a function of y, so when we differntiate wrt x, we use the chain rule like so
,,-y^2\left(y\frac{dY^(y)}{dy}+x\left(-\frac{x}{y}\right)\frac{dY^(y)}{dy}+xy\frac{d^2Y^*(y)}{dy^2}\frac{dy}{dx}\right)
ocean sealBOT
Social Capital Gainer
split olive
Okok, I see it
rugged sun
Put in y'(x) as before and make several simplification steps
Then put in x^2=1-y^2 and thats it
rugged sun
Nice
split olive
You’re a life saver
rugged sun
No problem!
rugged sun
That's absolutely fine, I remember encountering this in qm
split olive
You studied physics as well?
split olive
Niccce
That’s helped me a lot
Now I can finally solve that damn equation without feeling empty inside lol
rugged sun
Hehe, I'm really glad
I'll probably head off now, enjoy the rest of your equation solving o/
lone heartBOT
@split olive Has your question been resolved?
royal dirge
Ok
royal dirge
I just need to know if I did this right
Turning this into standard
Would the radius be 3 or sqrt(6)
<@&286206848099549185>
Ping me
tacit arch
Would the radius be 3 or sqrt(6)
Square root
tacit arch
Check your work by expanding
tacit arch
Expand this and show that it's equal to your given equation
wary stream
It’s wrong
Because it's sqrt(6), as mentioned above
wary stream
Don't ping me
woven totem
asking for the critical numbers of g(x) which means how would I find that without the graph or function
somehow i would have to reverse the derivative function?
based on the graph I see x=3 and x=8 as critical numbers
I can also see concave down, which means local max
tacit arch
I can also see concave down, which means local max
right
woven totem
that local max would be respective to the x=8 i believe
because the slope of the tangent line goes down
tacit arch
Did you learn second derivative test yet
woven totem
i can do the second derivative yes but not sure how id do it without the functio
function
tacit arch
you just need the conclusion of the test
i.e. g''(x) > 0 / g'' < 0 then it's a min/max
woven totem
so when g''(x) > 0 we get a local minimum
so x=3 would give us neither a max or min
wait actually not sure
at least i know i got the critical values right
i just dont know how'd id see the second derivative on a graph
like what would g''(3) look like on a graph
tacit arch
so when g''(x) > 0 we get a local minimum
Oh yea it's inconclusive. But since g is increasing before 3, and then increasing again after 3, then it's not a local min/max
Kinda like x^3 around 0
lone heartBOT
@woven totem Has your question been resolved?
woven totem
Oh yea it's inconclusive. But since g is increasing before 3, and then increasin...
thannk you for the help
gaunt herald
lone heartBOT
untold carbon
what is your question?
vivid inlet
lone heartBOT
lone heartBOT
Available help channel!
valid thunder
lone heartBOT
valid thunder
i have no idea how to approach this
placid zinc
Follow the product limit law proof, except use g•g rather than f•g
valid thunder
Follow the product limit law proof, except use g•g rather than f•g
i do g * g instead beacause its g(x) * g(x)^2 right?
i follow this? correct?
wait
lim g(x)g(x) = K * K
???
actually i think i get it
tyty
.close
south monolith
i have a question
south monolith
so im in pre calc and i did not know how to answer this question
i was confused on C due to the extended variables
@fervent timber
south monolith
i am not sure i understand the parameters of your response..
south monolith
ok what did you try
induction and intrusion but that failed
native granite
Expanding just means writing all the terms, right ?
south monolith
Expanding just means writing all the terms, right ?
correct, it is simplifying the parameters therefore allowing you to solve it bit by bit and go from there
native granite
So, what bothers you in c) ?
south monolith
i have trouble simplifying it due to the negative
native granite
What have you done so far ?
south monolith
i have expanded sigma (x)
native granite
Show work 👀
lone heartBOT
@south monolith Has your question been resolved?
tiny basalt
How was the question set up?
tiny basalt
howd they come up w f(x)
abstract fractal
Well, how long is VW?
abstract fractal
Yep
lone heartBOT
lone heartBOT
Available help channel!
sharp raven
lone heartBOT
sharp raven
I’m nervous to submit because if it’s wrong i have to redo 9 questions 😟
sweet chasm
does the khanacademy question have an option to watch a video without taking a hint
sharp raven
no
sweet chasm
dang
sharp raven
do you know who can help me?
sweet chasm
looks right
sharp raven
are you sure (anxious to submit)
lone heartBOT
@sharp raven Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
minor gulch
Please answer this for me thanks im very dumb
Morbius is playing with a garden hose and holding it right down to the ground. The water sprays out at a speed of 8.0 m/s. He directs the hose slightly upwards to be able to spray water on his morbidly obese cousin who is lying and sunbathing in the grass 5.0 m away. At what angle should he direct the hose?
lone heartBOT
Please answer this for me thanks im very dumb
Morbius is playing with a garden h...
@minor gulch Has your question been resolved?
kind sierra
Please answer this for me thanks im very dumb
Morbius is playing with a garden h...
trigonometry problem
technically you can't find the answer with the data given here
alpine sable
,w garden hose?
ocean sealBOT
gray ingot
Please answer this for me thanks im very dumb
Morbius is playing with a garden h...
Wtf is this question
left vector
Morbius 😭
minor gulch
something to do with projectile motion apparently
left vector
something to do with projectile motion apparently
morbidly obese was not necessary 💀
alpine sable
technically you can't find the answer with the data given here
ig so
alpine sable
kind sierra
You have speed which isn't enough
kind sierra
to find the side length
kind sierra
sin cant be greater than 1
yes
alpine sable
hmm does this has anything to do with physics?
kind sierra
hmm does this has anything to do with physics?
This is a physics problem 😂
alpine sable
This is a physics problem 😂
I am out then
also @minor gulch ask it in physics server
this is for maths
go to #old-network
alpine sable
Dont ask that anywhere
gray ingot
🗿
Wait
its possible
I entered the wrong value for speed
R = (v^2sin2x)/g
5 = 64sin2x/9.8
sin2x = 49/64
,w sin2x = 49/64
ocean sealBOT
gray ingot
,w sin2x = 0.76562
ocean sealBOT
ocean sealBOT
gray ingot
,w 0.436 rad to deg
ocean sealBOT
minor gulch
woah tysm
lone heartBOT
@minor gulch Has your question been resolved?
raven rover
@minor gulch .close
raven rover
That is correct - but there are multiple upper bounds.
For the 1/2, 2/3, 3/4, etc.
1 is an upper bound, because all terms are less than or equal to 1.
the same applies with 2 being an upper bound, but 1 is more useful as an upper bound
The absolute value doesn't matter all that much, it's still a sequence with a least upper bound
lone heartBOT
@violet ore Has your question been resolved?
noble rain
hi i have a question regarding matrices
lone heartBOT
hi i have a question regarding matrices
noble rain
how do i turn this into a matrix form?
this is what i did, but i dont like that there’s a matrix in a matrix
flat ore
how do i turn this into a matrix form?
first align the variables
wary stream
You want something like this
Another example would be this
Notice how all the variables are lined up like columns
Then the coefficients is one matrix
noble rain
oh i see
wary stream
The variables are another
noble rain
so like this then?
wary stream
Yes
fast oak
How to compute grades in excel
lone heartBOT
How to compute grades in excel
simple turtle
How to compute grades in excel
There are many examples online.
lone heartBOT
@fast oak Has your question been resolved?
alpine sable
how to find angle by sides in a triangle
lone heartBOT
how to find angle by sides in a triangle
vale wigeon
angle by sides? do you mean that you know all three side lengths and you want to know the angles?
@alpine sable
if yes then law of cosines.
alpine sable
angle by sides? do you mean that you know all three side lengths and you want to...
yes
vale wigeon
do you have anything else to ask?
alpine sable
if yes then law of cosines.
how to do that?
alpine sable
no
vale wigeon
$a^2 = b^2 + c^2 - 2bc \cos(A)$
ocean sealBOT
Ann
vale wigeon
this is what im talking about
ocean sealBOT
Asagao 朝顔
alpine sable
i just know normal trigonometry
like sin theta , cos theta etc
vale wigeon
same thing different notation
well then you might want to read up on the laws of sines and cosines
if you don't have them then you don't have the tools to solve your problem
alpine sable
now how to get theta
vale wigeon
i mean sure if you're somehow able to derive the law of cosines from scratch
is this an unrelated question to the previous? @alpine sable
alpine sable
nope
vale wigeon
oh, so all this time you've actually been doing the same question but you've hidden it from us and forced us to help you blind
anyway, you already have theta right there. it's arctan(3/4). or tan^-1(0.75) as you wrote it.
alpine sable
anyway, you already have theta right there. it's arctan(3/4). or tan^-1(0.75) as...
its tan^-1(0.75)
vale wigeon
yes, that's what i said.
alpine sable
how to solve tan^-1(0.75)
lethal stump
calculator
vale wigeon
what do you mean by "solve"?
do you want to get an approximate value? if so then yeah, use a calculator.
otherwise leave it as-is.
lethal stump
without calculator
you can't really solve it its not an equation
vale wigeon
there is none.
vale wigeon
if you do not have a calculator then you can just put tan^-1(3/4) as your answer
just as you could put sqrt(2) as your answer to a different problem
there is nothing wrong with that
asagao you could do the taylor approximation thing on arctan if you so desired 
alpine sable
just as you could put sqrt(2) as your answer to a different problem
we can also solve sqrt 2 by long division method
alpine sable
yes
lethal stump
you can use the taylor approximation ig
but it won't converge very quickly for larger values
and won't converge at all for values greater than 1
vale wigeon
to clarify, you are definitely not expected to do that in an exam or test.
alpine sable
ahh ig its higher level maths , i will just put arctan(3/4)
vale wigeon
it is much higher level math
vale wigeon
otherwise leave it as-is.
also i told you to leave it as is earlier
lethal stump
you can also use tanx = x and arctan(x) = x for small angles as well
yeppers
yea its not bad
you can use x - x^3/6 if you want an even better approximation
fine
sinx = x for all x
vale wigeon
...
can y'all go to like, #chill or something
@alpine sable do you have anything else to ask?
alpine sable
.close
lone heartBOT
lone heartBOT
Available help channel!
idle spindle
when it is "changed significantly" its two tailed right
lone heartBOT
when it is "changed significantly" its two tailed right
idle spindle
cuz it doesnt say if its higher or lower
fallen monolith
How to ask question?
fallen monolith
Ok
idle spindle
.close
peak geyser
Does anyone knows this?
lone heartBOT
Does anyone knows this?
wary stream
Well, do you know what SOP and POS means?
wary stream
I know what the abbreviation means, but do you know exactly what a SOP equation means or looks like?
wary stream
wary stream
Did you read that link?
Because if you did, it provided an example of SOP
And the minterms
lone heartBOT
@peak geyser Has your question been resolved?
lone heartBOT
@peak geyser Has your question been resolved?
peak geyser
Not yet
lone heartBOT
@peak geyser Has your question been resolved?
lone heartBOT
Available help channel!
full herald
Yo can someone help me out? Stuck on this one annoying task
lone heartBOT
Yo can someone help me out? Stuck on this one annoying task
dense sleet
Yo can someone help me out? Stuck on this one annoying task
Well send it
Dont wait for someone to respond
near hollow
u need to divide by y first
full herald
B)
near hollow
$\frac{1}{y} \frac{dy}{dt} = -0.45$
ocean sealBOT
Max..
ocean sealBOT
Max..
ocean sealBOT
near hollow
But the last part is what annoying me, b
for the halving time you're looking for how long it takes for A to become A/2
put in A and A/2 and solve simultaneously
full herald
for the halving time you're looking for how long it takes for A to become A/2
I dont follow with the A variable
near hollow
near hollow
I dont follow with the A variable
we dont need to find A we are saying that the halving time must always be the same
so for some arbitrary value, how long does it take to become A/2
full herald
Ahhhhhh yeah that makes sense, great explanation. Ill see if I can solve c.
near hollow
good luck!
formal vortex
lone heartBOT
formal vortex
hello
help me
that looks easy but i have no idea what to do
nvm
i just have to convert that 1-cosx to sin form
.close
uneven oyster
lone heartBOT
uneven oyster
okay im pretty stupid but can anyone help me of how can i find out that the function curve hits the x axis at -2, 0, and 2?
like it's when x=0 right
but when i substitute 0 into the function then it becomes just 0
gray isle
if subbing x=0 gets you 0 for f(x),
that would indicate that it hits the x-axis at x=0
a is an x-intercept if f(a) = 0
uneven oyster
yes and it did
oh wait
i just realized can u use factoring to solve this?
x(x^2-4) means that
x=0 / x^2 = 4 which is x=2
oh wait no nvm my bad
clear stump
+-2
gray isle
factorising and applying factor theorem would be the most efficient
uneven oyster
oh wait issit?
uneven oyster
+-2
wait BECAUSE the x has an exponent of 2 that means there are 2 x's?
and so it can be both -2 and 2
because that's the rule...?
clear stump
what is the square root of 4
clear stump
Dont forget negatives they cost points
north nova
Quick question, which symbol should I use to compare angle 1 and 2? This < or this ≤
north nova
This < right?
normal lion
what kind of triangle is BAD
north nova
Inequality
Choices are
A. m ∠1< m∠2
B. m ∠1> m∠2
C. m ∠1≥ m∠2
D. m ∠1 ≤ m∠2
My answer's A but I'm not sure
normal lion
thats why i am asking what kind of triangle is BAD
north nova
ummm idk, It's not provided
clear stump
10 and 7 are lenghts yes?
north nova
10 and 7 are lenghts yes?
Yes, that's what I think
clear stump
Is 10=7?
north nova
no
clear stump
thanks
north nova
Another question hehe
lone heartBOT
Another question hehe
north nova
In angle 1, do I add 8 and 5?
I think 8 and 5 are the lengths in angle 1
oh nevermind
.close
lone heartBOT
lone heartBOT
Available help channel!
alpine sable
lone heartBOT
fossil sundial
6 billion
alpine sable
Really??