help-0

[alpine sable]

ohhh

thanks a lot @real glen !!!

.close

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[remote compass]

currently stuck on this one

[slender gull]

$x^{\log_2{x}} = \frac{x^4}{8}$

[ocean seal]

What the hell am I doing here?

[slender gull]

Is this the question?

[remote compass]

yes, thank you

.close

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[remote compass]

.reopen

[lone heart]

✅

[slender gull]

Bruh.

[remote compass]

oops

[slender gull]

Lol

[remote compass]

a bit new here

[slender gull]

I thought my presence helped you solve it already.

[remote compass]

so what do i do with the right side

[slender gull]

Um

$\log_2{\frac{x^4}{8}}$

You see

[ocean seal]

What the hell am I doing here?

[slender gull]

$\log_a{\frac{b}{c}}$

[ocean seal]

What the hell am I doing here?

[slender gull]

I mean do you know a way to simplify this?

[remote compass]

thats the part i cant figgure out

[slender gull]

I see

Well there are laws for that.

You should look up.

[remote compass]

i have them written down

[slender gull]

Fourth law.

Use that.

[remote compass]

oh man im clueless sometimes

thanks

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[slender gull]

You're welcome.

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[keen sandal]

Hello I have this question

[keen sandal]

idk my friend @open mica got confused doing this

and i told him he should come here

[wide raven]

you cant divide by zero

that's illegal you know

[alpine sable]

@keen sandal how will you prove x is a real number

[keen sandal]

bud idk

[alpine sable]

It's a crime in the world of maths

[wide raven]

exactly

[open mica]

I amn't doing that, just using simple algebra

[alpine sable]

If you cannot prove x is a real number, you simply cannot do normal algebra on it

[wide raven]

you cant divide by zero in simple algebra

in fact in any corner of math you can't do that

[alpine sable]

If you can prove x is a real number then yes 0/0=0

[open mica]

What kind of normal algebra

[alpine sable]

And sadly I have been to jail 100 times coz of it

[wide raven]

you are not alone my mate

[keen sandal]

wait he says he has a few question about iota aswell

[open mica]

So, i am just accompanying you in this crime

[keen sandal]

he asks is it legal to keep i in the denominator

[alpine sable]

@open mica @keen sandal so ur trying to prove 0/0=0 right?

[keen sandal]

not me ik thats something i should not waste my time on

[wide raven]

it's fine

[open mica]

@alpine sable yes

[wide raven]

1/i = -i

[alpine sable]

U yileded 0/0=x

And did algebra on it

[keen sandal]

he asks how

[alpine sable]

But

[keen sandal]

hes too slow to type so i do

[open mica]

Is it illegal as well?

[alpine sable]

U didn't prove x is a real number

[keen sandal]

lmao

[open mica]

It is, x = 2x and the only solution to it is 0

[alpine sable]

That is why u can't do normal algebra on it

[alpine sable]

X is not a real number

normal algebra won't work

Just like in the case of imaginary numbers

[keen sandal]

are you trying to say there is a way still?

[alpine sable]

There is no way 0/0=0

[keen sandal]

ok XD

btw what about tan90?

[alpine sable]

tan(90) = undefined

[keen sandal]

so its useless?

[keen sandal]

anyways where is he wrong here?

[alpine sable]

U can't say so if ur a math enthusiastic like me it gets kind of fun

but u will either end up

With something

Very interesting

Or something

Pure nonsense

[keen sandal]

like 1+2+3+..............=-1/12?

[alpine sable]

When u will be working with intermedinant form

[alpine sable]

It's not nonsense

[open mica]

It is the ramanujan paradox

[alpine sable]

It's the analytic continuation of zeta function

It's done carefully

That's why it's interesting

But I once proved e=0 it was nonsense basically

[worn fox]

you can't combine roots like that if one of the terms is negative, like from the 2nd bit to the 3rd bit

[wide raven]

yes thats very interesting indeed

[alpine sable]

Imaginary numbers are nicely defined such that it doesn't contradict our original defintions.

[keen sandal]

he asks what you mean by bit?

[alpine sable]

Unlike 0/0

[worn fox]

$\frac{\sqrt{1}}{\sqrt{-1}} \neq \sqrt{\frac{1}{-1}}$

[ocean seal]

iCaird

[alpine sable]

I asked the same question 1 week ago

About imaginary numbers

I remember

[keen sandal]

dang

[open mica]

Why is isn't it possible?

[alpine sable]

Imaginary have their own set of rules

By which we ** define ** them

Such that

We can get something

Actually usefull

$\sqrt {a}\sqrt {b} \neq \sqrt{ab}$

[ocean seal]

Frustrated Cat

[alpine sable]

In the imaginary world

It's their rule

Becauss without it

it won't be usefull

To us

[wide raven]

iff both a and b are of oppositer signs

[alpine sable]

That's why i said " In the imaginary world"

[keen sandal]

man hes getting confused

[open mica]

If it is not possible then how are we able to find out the roots of negative numbers

[alpine sable]

We have a defined system for them

Complex and imaginary numbers

Which we don't have for 0/0

Because defining it won't be useful

To us

[keen sandal]

he says your profile pic looks scary

[alpine sable]

[keen sandal]

i think we should take it to discussion

at this point

[alpine sable]

dw i wasted 7 hours of time arguing with a stranger on the internet

And finally understood it

[keen sandal]

come to #chill

.close

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[alpine sable]

Can I get some help with getting ADC

<@&286206848099549185>

[wary stream]

You have to wait at least 15 minutes before pinging helpers

[alpine sable]

.close

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[karmic falcon]

if ab= ac = 10cm what is perimeter of ebf

[karmic falcon]

bc,ba and ef are tangent to circle

<@&286206848099549185>

[weary crag]

since ae=em and mf = fc
perimeter is nothing but 10+10 = 20

@karmic falcon

[karmic falcon]

but it's ba and bc =10

[weary crag]

yeah

[karmic falcon]

are you sure that ae=em

[karmic falcon]

and by this you mean ae=5?

[weary crag]

think like that
AE + EB = AB
but AE = EM
so, EM + EB = AB

[weary crag]

no

[weary crag]

similarily complete the other half of the triangle

so 10 + 10 will be your answer

[karmic falcon]

but why ae=em

[weary crag]

because they are originating from the same point and are both tangents to the circle

its a property

[karmic falcon]

yes know i remember

[weary crag]

so you understood?

[karmic falcon]

but i'm still confused

how much is ae

or em

[weary crag]

you don't even need to know that

[weary crag]

see this once again

[karmic falcon]

i get this but there are no numbers here

how did you get to 10+10

[weary crag]

because AB = 10

similarly the other side

[karmic falcon]

this leads to em= ab-eb = 10-eb

[weary crag]

okay, lets do this again...
tell me , do you understand that EB + EM is the same as EB + EA which is 10?

[karmic falcon]

i understand eb=em since em=ae

[weary crag]

EB != EM

[karmic falcon]

ok yeah i get it

what

i mean

em=ea

sorry

[weary crag]

AE = EM != EB

understood?

[karmic falcon]

yes

mf=fc

[weary crag]

then maybe you understood the whole solution?

[weary crag]

correct, yeah

you got it :)

[karmic falcon]

but i'm extremly confused now

[weary crag]

-_-

[karmic falcon]

oh ok

i think i got it

it's em+eb =10 plus mf+fb = 10

so it's 20

right?

[karmic falcon]

so this is it?

[weary crag]

right

[karmic falcon]

thanks a lot

[weary crag]

welcome XD

[karmic falcon]

have a nice day

.close

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[weary crag]

you too :)

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[sleek sequoia]

How do I solve this

[weary crag]

solve what?

[alpine sable]

the question?

[sleek sequoia]

Sorry slow internet

[weary crag]

english plz

i can't understand ur language

[raven rover]

In the following figure, angle GEF measures 70˚. What is the measure of the angle GHF?

^^

[sleek sequoia]

Yea thanks

[raven rover]

Yay high school Spanish!

[alpine sable]

its the same

its 70

[weary crag]

oh yeah, maybe i could lol. didn't even read before ranting

[alpine sable]

so imagine GF is a chord

[raven rover]

Lmao - it be like that

[alpine sable]

and then by property angles at circumference from the same chord are equal

[sleek sequoia]

I'm kind of stupid but I don't really understand

I understand the chord part

?

[sleek sequoia]

Anyone know how to solve this?

[sleek sequoia]

Do you know?

Nvr mind thanks :)

.close

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[azure kelp]

.reopen hey i dont understand your language but i kinda understood the question

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[sleek sequoia]

In the following figure, angle GEF measures 70˚. What is the measure of the angle GHF?

[sleek sequoia]

That's the question in english

[azure kelp]

70

because they share the same chord

[sleek sequoia]

Yea that makes sence

I was just being a bit dumb earlier

But thanks for taking the time : )

[azure kelp]

happens from time to time

[azure kelp]

no worries

[sleek sequoia]

.close

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[alpine sable]

Can anybody help me with the concept “bearing”

[alpine sable]

<@&286206848099549185>

[wanton nova]

Bearings are angles, measured clockwise from north.

[alpine sable]

Yeah but can you help me with solving “P from Q”? @wanton nova

How do we solve these questions

[wanton nova]

think its angle npq at the 1st one

i dont really know

[lone heart]

@alpine sable Has your question been resolved?

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[magic plank]

help

[magic plank]

<@&286206848099549185>

[wary stream]

You have to wait at least 15 minutes before pinging helpers

[magic plank]

i did _))

[wary stream]

No you didn't

[magic plank]

Does it matter

[wary stream]

Yes, because there are rules

[tight locust]

Wtf is a kg wt

[wary stream]

Follow the rules

[magic plank]

Just kg

[magic plank]

Sorry for that

[tight locust]

A kg is a unit of mass

[magic plank]

yea gooddd

[tight locust]

A "kg wt" appears to be used as a unit of force

[magic plank]

lmao yes

whatever

doesn't matter

[tight locust]

It really does

[magic plank]

ok it's mentioned that they are 3 forces

so it's of course unit of force

can u solve it anyways

[tight locust]

What can you say about R

[bitter vault]

According to this https://byjus.com/question-answer/what-is-the-meaning-of-the-notation-kgwt-please-give-an-example-too/, 1 kg wt is the force needed to give a mass of 1kg an acceleration of g m/s^2 where g is the acceleration due to gravity on the surface of the earth, which is 9.80655 m/s^2

[magic plank]

I know the damn answer

lol

and the explanation as well yet I don't understand why there was a 150 degree angle

Can someone explain

[wary stream]

Because the 150 degree was given

It's in the diagram as given info

[tacit arch]

Blocking people who don't follow rules makes life way better

[magic plank]

I said I was sorry

[magic plank]

Uhmm in another website the diagram wasn't given

[wary stream]

Still kinda bothers me that you can still see the blocked messages, as hidden

[tacit arch]

You get used to it after like 5

[magic plank]

I wish someone answered my question

what a server

[limpid spade]

what question

[magic plank]

uhmm

[limpid spade]

what a question

[magic plank]

What an answer

[limpid spade]

[magic plank]

Can u PLEASE answer the question 🥲

[limpid spade]

again

what question

[magic plank]

It's exactly 9 messages above my message

Probably one scroll would be enough to see it

[limpid spade]

how can someone answer the question 'Uhmm in another website the diagram wasn't given' like what do u want us to say

and you stated that you know the answer and the explanation

[magic plank]

well

see

It's confusing

but in the other website the 150 degree angle is not mentioned

which means there could be a way to calculate it

I was just wondering if u know that way

[limpid spade]

what website

[magic plank]

BYJUS

[limpid spade]

send link

[magic plank]

https://byjus.com/neet/neet-physics-mcq-on-lamis-theorem/#:~:text=Lami's theorem states that three,an object in static equilibrium.

[limpid spade]

lol

access enied

[magic plank]

What

[limpid spade]

send a screenshot of the question at that website

[magic plank]

Without the diagram

[magic plank]

Thanks anyways, We live in a society😢 💔

I hope u don't answer the question anyways

Idc

[limpid spade]

ok

[magic plank]

SO MEAN

[lone heart]

@magic plank Has your question been resolved?

[magic plank]

i don't really know @lone heart

[lone heart]

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[mellow vapor]

How do u find out in a parametric curve where all the tangent lines are horizontal and vertical

[bitter vault]

Horizontal where dy/dx = 0 and vertical where dx/dy = 0

[mellow vapor]

so i set them equal to = and solve for the variable?

tht wont work here

cause id get 1 = 0

oh

nvm im stupid i mixed up 2 questions..

there was a diferent equatino for that questino

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[indigo harbor]

P is a prime number, P≥5
"Prove that P≅1[3]"
It says I can use Fermat theorem, which says a^(p-1)≅1[p] {p doesn't divide a and p is prime}

I started with p²≅1[3]
Took that 1 to the left
It became p²-1≅0[3]
Then (p+1)(p-1)≅0[3]
So that means
p≅1[3] or p≅-1[3]
Idk how to get rid of second possibility

[proper tangle]

I don't get you. Say 11 is a prime number, but

,,11\equiv2\pmod{3}

[ocean seal]

vin100

[indigo harbor]

@proper tangle there's another condition i forgot to mention
Whatever n in N*
n²+n+1≅0[p]

Apologizes

[proper tangle]

no worries

[untold carbon]

what if n is a multiple of p

so $1 \equiv 0 \pmod{p}$ which doesnt make much sense...

[ocean seal]

Takumi

[indigo harbor]

The condition applies on both ig
So if it is a multiple it doesn't account for that

[untold carbon]

well, ignoring that, we get that $p\mid (n-1)(n^2+n+1)=n^3-1$, so $n^3 \equiv 1 \pmod{p}$ so the order of n mod p must divide 3 but this means that it is either 1 or 3 but since this holds for all n, it must hold for an $n\not\equiv 1 \pmod{p}$ so for that $n$ we must have that the order of n mod p is 3 which implies that $3\mid p-1$ so $p\equiv 1 \pmod{3}$

[ocean seal]

Takumi

[indigo harbor]

Why does "the order of n mod p must divide 3"

[untold carbon]

do you know what the order is?

[indigo harbor]

No

[untold carbon]

the order of a mod p is defined to be the least integer n such that $a^n \equiv 1 \pmod{p}$

[ocean seal]

Takumi

[indigo harbor]

Ohhh
Didn't study that
Makes it simpler

[untold carbon]

yeah

if $a^m \equiv 1 \pmod{p}$ then the order of a mod p must divide m

[ocean seal]

Takumi

[untold carbon]

this just comes from writing m=kn+r where r<n

[indigo harbor]

I see

[untold carbon]

and by fermat's $a^{p-1} \equiv 1 \pmod{p}$ as you mentioned

[ocean seal]

Takumi

[untold carbon]

so the order of a mod p divides p-1

[indigo harbor]

Tysm

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[astral breach]

Hello. Does absolute value in integral affect integrating rules somehow or do I just take it into account when assigning values in definite integral? Like for example is integral of (1 - |y|)dy still y-|y^2/2|?

[marsh rapids]

It does. In general you can't get rid of it unless you know the function's sign to know when to use + or -. An example of it mattering would be that of sin t dt over a large interval

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[magic plank]

help

[magic plank]

do different planets have different magnetic fields and does this affect the electrical current ?!

<@&286206848099549185>

[alpine sable]

It's maths server my friend

[magic plank]

I mean someone still can help ?!

[wary stream]

Go to not a math server for science related questions

[magic plank]

U hate me, period\

<@&286206848099549185>

Guys

I have a real question

The answer is A

But why?

[wary stream]

Kinematics

[magic plank]

There are no more info just the given ones

yes kinematics

[wary stream]

There is more info

You just need to read between the lines

[magic plank]

Uhmm

Just the velocity

[wary stream]

It's a projectile

[magic plank]

and they want the range

[wary stream]

What affects projectiles?

[magic plank]

Gravity

Launch angle?

[lone heart]

@magic plank Has your question been resolved?

[limpid spade]

you get yourself a motor or a generator

[magic plank]

To increase or decrease the current flow?!

[magic plank]

Can u explain what that is pls?!

[lone heart]

@magic plank Has your question been resolved?

[lone heart]

@magic plank Has your question been resolved?

[lone heart]

@magic plank Has your question been resolved?

[carmine oar]

we do not know the angle

[magic plank]

Exactly

That's the freaking thing

[carmine oar]

well we can let theta be the angle

[magic plank]

Yay and..

[magic plank]

Ok

[carmine oar]

this is the standard result

of the range

[magic plank]

Ok

What to do next ? With no known angle

And only g and v

[carmine oar]

well as 1 >= sin 2 theta >= -1

the max range achieved is when sin 2theta =1

[magic plank]

Why not sin2 theta =0.9

Oh

The max range

Yea so u r assuming a vertical launch ?

Or a 30 degree ?

[carmine oar]

not verticl

45 degrees

cause 45*2 = 90

sin 90 = 1

[magic plank]

Ok soax range is always 45 degree

Lol right

I know that 😢

Just forgot

[carmine oar]

this is without drag froce

force

so ideal situation

but irl idk

[magic plank]

Ok

Well thanks buddy

[carmine oar]

np

[magic plank]

U r really

AMAZING ✨

[carmine oar]

thanks

[magic plank]

Can I give u a hug ?

[carmine oar]

umm maybe?

.close

[lone heart]

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[magic plank]

Wait I'm searching for a gif

Like a hug gif

[lone heart]

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[visual monolith]

How do I use substitution in this equation

[merry coral]

u have to use subsitution?

[visual monolith]

yes

[merry coral]

:/

lets get y on both sides

x = 3 + y
2x = -3 + y

x - 3 = y
2x + 3 = y

then u can sub

[wary stream]

Substitution isn't typically setting them equal to each other

It's taking one equation and plugging it into the other

[opal tusk]

x = 3 + y
sub x into the second equation :

2(3+y) - y = -3
solve for y
once you find y solve for x

[wary stream]

Don't do the work for people

[visual monolith]

so then y=-6

and now I find x with that correct?

[opal tusk]

ok sawri

[opal tusk]

hmm check that again

[opal tusk]

yes after you found y
use that to find x

[visual monolith]

y = -9

?

[keen sandal]

yes now that you have y you can easily solve for x

[visual monolith]

then just 2x + 9 = -3

[opal tusk]

use the first equation since you have x already isolated

[visual monolith]

x + 9 = 3

[opal tusk]

ye carry on

[visual monolith]

so then x = - 6

[keen sandal]

yes

[visual monolith]

Thank you guys!

.close

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[keen sandal]

if you have doubts you can try substituting these values in the second equation to check if your answers are wrong or correct

[visual monolith]

I have to graph them to check them anyways

[lone heart]

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[warm shell]

hii! i need some help combining functions and finding their domains!

[weary crag]

send your question please

[warm shell]

thank you!

f(x)= x^2
g(x)= 1/2x^2+5
find (f x g)(x) and its domain
find (f-g)(x) and its domain

are you able to read that okay :0

i can try to screenshot the problem if thats easier!

[buoyant kayak]

have you tried anything so far?

[warm shell]

its the domains that keep tripping me up lol, i ended up trying and got it wrong so im on to the next one, but i think im making some progress

so ill close this!

.close

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[kindred anchor]

If the angles of a triangle are in the ratio of 1:2:3 and its circum radius is 12cm, find the sides of the triangle

[kindred anchor]

<@&286206848099549185>

[wide raven]

its in bold

anyways, think about sine law

[kindred anchor]

ooh

im sorry

[kindred anchor]

what is sine law?

[wide raven]

https://en.wikipedia.org/wiki/Law_of_sines

the whole article if you want

[kindred anchor]

Ok, thanks.

I'll learn this and try this problem on my own!

[wide raven]

okay

feel free to dm me if you're stuck

[kindred anchor]

yeah!

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[eager kraken]

I have found the above (top line) bounds for a variable, but wanted to express the possible t values in set-notation. However I am unsure how I can do this. I provided (bottom line) something which it may look like however the way I formatted and 'logiced' is likely wrong.

[lone heart]

@eager kraken Has your question been resolved?

[eager kraken]

sorry to annoy but <@&286206848099549185>

[lone heart]

@eager kraken Has your question been resolved?

[eager kraken]

damn

.close

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[alpine sable]

is k = (i+j)?

[lone heart]

@alpine sable Has your question been resolved?

[rigid smelt]

no

i and j indicates the unit vectors and is not a constant

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[earnest lodge]

is there a mathematical formula/proof for this?

[vague coral]

You don't know the formula of the variance ?

[earnest lodge]

it's probability of something times( x - mean) squared

and added tgt

that's the summation formula righttt?

however for like var(3x+4) it becomes 9var(x) so is there like a formula for this?

[vague coral]

I had this formula in my head :
V(X) = E(X^2) - (E(X))^2

and V(aX+b) = a^2 V(X)

[earnest lodge]

shld I send the previous parts of the qn?

[earnest lodge]

yes yes

[vague coral]

$V(X^2 - 2) = E((X^2 - 2)^2) - (E(X^2 - 2))^2$

[ocean seal]

Ｈｅｒｅｌｓ

[vague coral]

$V(X^2 - 2) = E(X^4 - 4X^2 + 4) -(E(X^2) - 2)^2$

[ocean seal]

Ｈｅｒｅｌｓ

[vague coral]

$V(X^2 - 2) = E(X^4) - 4E(X^2) + 4 - (E(X^2))^2 + 4E(X^2) - 4$

[ocean seal]

Ｈｅｒｅｌｓ

[vague coral]

$V(X^2 - 2) = E(X^4) - (E(X^2))^2$

[ocean seal]

Ｈｅｒｅｌｓ

[vague coral]

I think that's it

[earnest lodge]

oh wait

you're a genius

I nvr thought of this approach

I get it now tyyy

.close

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[old cypress]

can anyone solve this

im confused about everything

[alpine sable]

(b)?

@old cypress

[old cypress]

a to c

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@old cypress Has your question been resolved?

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@old cypress Has your question been resolved?

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[split temple]

I've been trying to form a neat compact binomial form, but

[split temple]

I'm just not sure how to go about it...

[oak perch]

Consider (1+ix)^100

Where i=sqrt(-1)

[split temple]

....I am an idiot. I'd been trying to use (x+i)^100, but

That probably does it.

[oak perch]

Yeah, probably better

And use that x+i=sqrt(x^2+1)e^(iθ)

Where θ=arccos(x/(sqrt(x^2+1))

So t_0-t_2+t_4…=(x^2+1)^(50)cos(100θ), t_1-t_3+t_5…=(x^2+1)^(50)sin(100θ). So what you are looking for is sum of their squares, which is (x^2+1)^(100)

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[viscid pagoda]

quick question; what are the rules for 2^x times 4^x?

[candid torrent]

here

convert 4^x to base 2

[merry coral]

u add the exponents

[candid torrent]

try doing that

[viscid pagoda]

aah

[candid torrent]

they have different bases

you need to convert first

[merry coral]

oh nvm lol

[viscid pagoda]

2^x times 2^2x

[candid torrent]

correct

[viscid pagoda]

2^3x?

[candid torrent]

yes

[viscid pagoda]

thank you

[candid torrent]

np

wait

am i dumb

[merry coral]

,w solve 2^x * 4^x = 2^3x

[candid torrent]

@merry coral can you confirm me work

[merry coral]

,w solve 2^x * 4^x = 2^(3x)

[candid torrent]

,w solve 2^x * 4^x = 2^{3x}

[ocean seal]

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[merry coral]

w

[candid torrent]

yeah i'm right

for some reason i just had a crisis that i was wrong

[alpine sable]

$4^x=(2^2)^x=2^{2x}$

[ocean seal]

Frustrated Cat

[alpine sable]

$2^x*2^{2x}$

[ocean seal]

Frustrated Cat

[alpine sable]

Add the exponents

[viscid pagoda]

yes so you have to make the base the same

[alpine sable]

Yes

[viscid pagoda]

thank you

.close

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[quartz bolt]

How can I make this tick repeat infinitely?

[alpine sable]

Is this about desmos then #computing-software might be better

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[fallen patio]

How do I solve further?

[lone heart]

@fallen patio Has your question been resolved?

[harsh girder]

if $0<x<\frac{1}{2}$, then $\floor{x}=0$

[ocean seal]

秋水

[harsh girder]

if $x<0$, then $\floor{x}+4x<0$

[ocean seal]

秋水

[fallen patio]

I still don't get it

[harsh girder]

you can simplify it in different intervals

if $0 \leq x < \frac{1}{2}$, then $\floor{x}=0$, $\floor{x}+4x=4x=1$, so $x=\frac{1}{4}$

[ocean seal]

秋水

[harsh girder]

if $x<0$, then $\floor{x}+4x<0$, so $\floor{x}+4x \neq 1$

[ocean seal]

秋水

[harsh girder]

do you get it now?

[fallen patio]

Yeah, I get it now. Also, I was kinda confused while writing both the cases.
Why did you write 0 <= x< 1/2 ?

[harsh girder]

because you wrote x<1/2 before

[fallen patio]

Is it wrong?

[harsh girder]

not wrong, because you want to simplify abs(2x-1)

[fallen patio]

I just don't understand why you wrote 0<=

[harsh girder]

because when 0<=x<1, floor(x)=0;
when -1<=x<0, floor(x)=-1;
......

then you don't have floor sign

[fallen patio]

Ahh I'm still confused 😀

[harsh girder]

https://en.wikipedia.org/wiki/Floor_and_ceiling_functions#/media/File:Floor_function.svg

this is the plot of floor function, right? you can discuss it on [n,n+1)

[fallen patio]

I'm not sure what cases are to be made while considering |2x-1|

[harsh girder]

|2x-1| = 2x-1 (when x>=1/2), 1-2x (when x<1/2)

[fallen patio]

Why is there an = sign in the 1st case but not in the 2nd one?

[harsh girder]

it's the same

when x=1/2, 2x-1=1-2x=0

[fallen patio]

Yeah, I got it now.
But I don't understand this.
On what basis are we writing this? Where did 0=<x<1/2 come from?😀

[harsh girder]

because I want to simplify floor(x), so I need discuss it on [0,1),[1,2),[2,3),...[-1,0),[-2,1)...like this

[fallen patio]

I still don't understand this but you've helped me more than enough so I'll just skip this question 😀

.close

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[harsh girder]

you can plot a figure to help you

[lone heart]

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[alpine sable]

so i am solving this problem about rates of change and rectilinear motion in calculus. we are given the function s(t) where t is in hours and s(t) is in kilometers. do i have to convert it into seconds? or is it okay to be in hours?

[slender marten]

I think you will have to judge it based on previous problems.

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[alpine sable]

.close

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[rustic crest]

How can I write 13 (c) as a binomial distribution?

[marsh rapids]

while would you want that ? Also I believe that in the binomial distribution, order must not matter, and here it clearly does, so that isn't appropriate

[rustic crest]

Oh ok because this question is in a worksheet specifically for binomial distribution so I was wondering if it’s even possible for question 13 (c)

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@rustic crest Has your question been resolved?

[marsh rapids]

I wouldn't be surprised. Usually exercises are centered around the topic of interest, but obviously not every question has to be related/use it. Having a few unrelated questions here and there isn't really surprising

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[idle elk]

heyo oooh i get help 0 cuz i'm special

[undone hinge]

🤡

[idle elk]

hi

i don't need much i just need someone to try out my code and make sure i got it right

https://www.onlinegdb.com/fork/IC0Q8ENxf long story short this code takes 4 points, the first three are the triangles vertices and the last one, well it checks to see if it's inside the triangle or not

so do me a flavour and see if its accurate plz or if i missed something

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@idle elk Has your question been resolved?

[idle elk]

its whatever ig i'll just try coding places

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[gloomy onyx]

Help

<@&286206848099549185>

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[gloomy onyx]

No mate

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[gloomy onyx]

.close

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[frank elm]

I need help

[spark creek]

What do you have to find?

[frank elm]

The area

[spark creek]

Do you know the formula

[merry coral]

area = 1/2bh

b = base

h = height

what's base

and what's height

🤨

[frank elm]

44m

[merry coral]

go on

[frank elm]

15m

[merry coral]

ok cool

area = 1/2(44)(15)

just plugging those in

then simplify

so what would be the answer

[frank elm]

Idk

[merry coral]

solve this lol area = 1/2(44)(15)

[frank elm]

How?

[merry coral]

$$1/2(44)(15)$$

[ocean seal]

Chunkin

[merry coral]

simplify this

[frank elm]

Idk how

This is confusing

[merry coral]

https://youtu.be/rRTXKQpblEc

[frank elm]

Can I just have the awnser?

[limpid spade]

no

[frank elm]

Now I get it

1/2(44)(15)

22x7.5?

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[sweet vector]

baiscily to calculate vairance in binomial distribution function, it's np * (1-p ), why we needed the 3rd bracket here ?

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[pine kettle]

id distribute those fractions then start moving those lns around with log rules

[woven pollen]

try combining the ln's on the left, first.

[fringe token]

whats wrong here

[woven pollen]

why... it's sideways.

[fringe token]

Im on phone

Wait…

[hard patio]

,rotate

[woven pollen]

yay. I can't read your handwriting.. um, can you post the original question?

[fringe token]

😎

[pine kettle]

check pins

[finite flax]

@fringe token why do screenshots of your work not include the beginning of your work?

there's no b in the problem

[fringe token]

Bruv I created it as for my own comfort

[woven pollen]

,solve k^2-7k+9

how does that work in chat?

[tall hearth]

,ask k^2 - 7k + 9

[woven pollen]

anyways.. just complete the square

[ocean seal]

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[woven pollen]

✅

[finite flax]

well, the important thing when asking for math help is that you are comfortable, not that other people know what you are talking about, right bruv?

[woven pollen]

also, i made mistake. it should be -6k. but you'll see it.

,ask k^2-10k+9

[ocean seal]

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[woven pollen]

1 and 9. which you can plug into the original

[fringe token]

Ok noted ✍🏽

Tanks @woven pollen

.close

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[tropic oasis]

i’m a bit lost on this problem

i’m also not sure if my drawing is correct

i know the corner on the bottom left is 30

and top left is 30 (given in the question)

[fading aurora]

show me

[tropic oasis]

and 180-90-30=60

its above the question

[fading aurora]

oh mb lol

[tropic oasis]

all good

[hard patio]

no?

[hard patio]

hi cedric

[fading aurora]

nah the right angle should be 30

[tropic oasis]

wait angle with the ground

[fading aurora]

not top one

[tropic oasis]

mb

[fading aurora]

hello

[tropic oasis]

and the top left is 60?

[fading aurora]

ye

[tropic oasis]

okie

now from here

i would multiply the degrees with the hypotnuse?

[fading aurora]

use cosine to find the side at the ground

[tropic oasis]

cos of 60?

that’s the one pointing opposite to the ground

[fading aurora]

yes

wait

[tropic oasis]

1/2*12=6 (using cos60)

[fading aurora]

u know this

[tropic oasis]

yeah

[fading aurora]

well just use cos(30) * hypotenuse

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[mystic crypt]

Is 0 = 0 infinite solution or no solution (i forgot)

[frigid rune]

whats the context?

[weary wyvern]

probably infinite

[mystic crypt]

So is that infinite?

[frigid rune]

im guessing they mean that they have solved some simultaneous equations or something and ended up with 0=0 instead of a proper solution so they want to know if the equations have no solution or infinitely many

[mystic crypt]

Yeah

[frigid rune]

wow, lucky guess lol

infinite then

[mystic crypt]

Ok thanks

[frigid rune]

uhm not really, you can have like 2x + y = 3 and 4x + 2y = 6 which if you tried to solve would get you 0=0 or 6=6 or something similar which means they have infinite solutions

well ofc i am making the assumption that they didnt just multiply by 0 everywhere to come up with 0=0

[mystic crypt]

0 = 0 was infinite

Thanxs

.Close

.close

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[charred plank]

Hey guys, can anyone help with some combinatoric question?
I got a table of 4x19 and 3 colors, Blue, Yellow, Red, need to prove that theres a rectangle which his corners are same color.

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[maiden nexus]

someone help me with this plz 🙂

[maiden nexus]

<@&286206848099549185>

sorry for the ping

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[pearl wraith]

how to find cos2x

[tight locust]

In terms of?

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[blazing dock]

Julian is a manager at a clothing store for teens. He is analyzing the order for next season. Data for the previous 10 years suggests that teens are willing to spend an average of $75 for a pair of designer jeans with a standard deviation of $5. However, Julian thinks the average may have changed due to a recession. He finds that the last three seasons of data show that teens spent an average of $68 on a pair of jeans. Therefore, he performed a hypothesis test to see if the recent average is the same. Julian used a significance level of 5% to perform the test. Which of the following statements is valid based on the results?
A. Julian’s data shows that the recent seasons’ average jean price is not $75.
B. Julian’s data shows that he should order fewer jeans than before.
C. Julian’s data shows that the recent seasons’ average jean price is still $75.
D. Julian’s data is inconclusive, so he should order the same number of jeans.

[blazing dock]

.close

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[thin vigil]

hey my work is in code but I'll try to explain it as much as I can:
I'm looking to rotate a 3D object around a pivot point , I'm currently testing this in the X axis but going wrong somewhere in my maths.
Step 1: I get my pivot point
Step 2: I get how much ill be rotating by
Step 3: I turn my rotation into a quaternion
Step 4: I take away the pivot point from the objects location
Step 5: I then create a matrix by translating to the pivot , then multiplying the rotation then finally translating by the value I got from minusing the point from the object location
when this is put together I just end up with all objects rotating on their own centre

[thin vigil]

some code for some context maybe

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[thin vigil]

.reopen

[lone heart]

✅

[thin vigil]

<@&286206848099549185>

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[toxic radish]

idk how I can solve this

[toxic radish]

I have 0 clue where to start

and on my entire practice packet

[oblique pier]

use the Pythagorean theorem

@toxic radish

[toxic radish]

#16

how tho

[oblique pier]

yes

use the pyta theorem on the 1st triangle of the row

and u will get the hypotenuse

[toxic radish]

oh so that would make that hypotenuse sqrt of 2

[oblique pier]

yes

continue on

[toxic radish]

ok i'll solve that later. What about 17?

[toxic radish]

wait okay, for 16 I got x = root 17

is that correct

wait no nvm i did something wrong

root 5 is the answer

[oblique pier]

👍

[toxic radish]

for 17 what properties would I use to solve for AC

[toxic radish]

i know the diagonals aren't congruent for a rhombus

thats all

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[toxic radish]

<@&286206848099549185>

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[toxic radish]

.close

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[fossil mason]

Are there easier way to do bii?

[main kraken]

All minus none

[fossil mason]

I don’t think I did it right

The answer is 1584

[main kraken]

We do not want the committee to contain:
(1) just one doctor + 4 others,
(2) just one dentist + 4 others,
(3) 5 others (no docs and dentists)

we find the number of ways of selecting these undesired committees

and subtract them from all the ways of selecting the committee

[fossil mason]

Ohh ok let me try

[fossil mason]

I don’t think I did it correctly

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[fossil mason]

<@&286206848099549185>

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@fossil mason Has your question been resolved?

[fossil mason]

<@&286206848099549185>

[lone heart]

@fossil mason Has your question been resolved?

[fossil mason]

Anyone ?

<@&286206848099549185>

[remote heron]

just to check its correct?

[fossil mason]

It’s not right, could someone show me the working ?

[remote heron]

oh typing

yea, im trying to think of how id enumerate these

[fossil mason]

9b ii

Ok tysm

[remote heron]

okay so i think id do like this

one doctor, one dentist, first off

so 3 slots left

then we can choose a remaining 5*2*6 possible members

there are 6*3 ways to choose this initial pair

dont suppose you have the answer?

,calc 65236

[ocean seal]

Result:

1080

[remote heron]

alternatively

$\qty( \binom 6 1 \cdot \binom 3 1 ) \cdot \binom{ (6-1)+(3-1)+7 }{ (5-2) }$

[ocean seal]

jan Niku (@pomodoro role)

$\qty( \binom 6 1 \cdot \binom 3 1 ) \cdot \binom{ (6-1)+(3-1)+7 }{ (5-2) }$

[remote heron]

@fossil mason does this help?

im not certain this is the correct answer but i believe it is

,w 6c1 * 3c1 * 14c3

[ocean seal]

Results provided by WolframAlpha

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Requested by jan Niku#2119

[remote heron]

[remote heron]

this is incorrect

[remote heron]

i believe this is the correct approach

I get 6552 on a calculator

6*3*14c3

[fossil mason]

Why 7*(5-2)?

[remote heron]

the top line of the last binomial coefficient is like

its all the possible remaining members

[fossil mason]

The answer is 2850 tho

[remote heron]

oh

[fossil mason]

9b ii

[remote heron]

hmmm

OH

its at least one doctor and exactly one dentist

not at least one doctor and at least one dentist

this is not immediately clear

$\qty( \binom 6 1 \cdot \binom 3 1 ) \cdot \binom{ (6-1)+7 }{ (5-2) }$

[ocean seal]

jan Niku (@pomodoro role)

[remote heron]

yea?

,w 12 choose 3

[ocean seal]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by jan Niku#2119

[remote heron]

,calc 220*18

[ocean seal]

Result:

3960

[remote heron]

[fossil mason]