Not sure why they're deliberately trying to use complicated words for an 8th grader above^^ haha
#help-0
alpine sable
You basically want to try and get the bottom half of each fraction the same
Once both of the bottom numbers of the fraction are the same, you can add the top numbers together
That video should help :)
lone heartBOT
@alpine sable Has your question been resolved?
queen nest
lone heartBOT
@queen nest Has your question been resolved?
oak mesa
Hello, can you help me with this question? I don't know if I'm going to use the function F or not
azure lance
Hello!
wide raven
you should use only one channel dude
other one's open so i'm closing this
hope you don't mind
.close
alpine sable
need some help on question 2b
lone heartBOT
need some help on question 2b
alpine sable
<@&286206848099549185>
I know that (a) that the distance is 5 after using the pythagoream therom
Need some assistance on the (b) question
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping helpers
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
did I ping helpers by accident OOF sorry
gilded citrus
you have r = sqrt(x^2 + y^2) by the pythagorean theorem
differentiate that with respect to t
you'd then have to plug in dx/dt, dy/dt, x and y which are all given in the question
gilded citrus
How did you do that?
how did i do what
gilded citrus
the distance between the two is $r = \sqrt{x^2 + y^2}$
ocean sealBOT
hsp
barren olive
pythagarous theorem ( i cant spell it)
its for right angle triangles
thats what’s being used here ^^
gilded citrus
to find the rate of change of the distance you differentiate it with respect to time
lone heartBOT
@alpine sable Has your question been resolved?
alpine sable
to find the rate of change of the distance you differentiate it with respect to ...
respect with time?
im js lost on that part
i know that a is 5
using the p thereom
gilded citrus
have you learnt differentiation and derivatives?
gilded citrus
"differentiate r with respect to time" means to "find dr/dt"
lone heartBOT
lone heartBOT
Available help channel!
tame hound
In a bowl are 8 red and 5 blue balls. How many balls do you have to randomly pick up to get two of a) the same color b) different color c) each color?
On this task I can imagine that ”containers” are counted as colors, but I do not know how to calculate how many balls you have to randomly pick up to safely get two of the same color, different color, and each color.
Anyone have any tips?
lone heartBOT
In a bowl are 8 red and 5 blue balls. How many balls do you have to randomly pic...
@tame hound Has your question been resolved?
alpine sable
In a bowl are 8 red and 5 blue balls. How many balls do you have to randomly pic...
3 6 6 (3 9 10)
b and c are practically the same, if you pick 5 balls you can get all 5 blues but if you pick 6 there will be atleast one red and blue
in a if you pick two you can get different colors but there are just 2 colors, so if you pick 3 atleast two will have the same
tame hound
3 6 6 (3 9 10)
Last one is 10, second one is 9
alpine sable
oh wait yeah i looked at blue as the bigger number for some reason...
anyway same logic
you can be unlucky and pick 8 red balls in a row but 9th will be blue
and for last one the same but you must have two of the same color so you take another one and that will make it
tame hound
“(b) and (c) If I pick 8 red balls I get get all reds, but if I pick 7 reds there will be atleast one red and 1 blue.”
alpine sable
“(b) and (c) If I pick 8 red balls I get get all reds, but if I pick 7 reds ther...
?
tame hound
you said same logic, so I just wrote about red balls instead of blue.@alpine sable
alpine sable
you said same logic, so I just wrote about red balls instead of blue.<@456226577...
but why there is a 7
tame hound
oh
alpine sable
should be if i pick 9 balls
tame hound
wrong
yes
So for question B, if I pick up eight balls then I'll pick up all the reds, but if I pick up nine balls then I pick up all the red balls and the one blue.
So the second part has the answer nine.
alpine sable
yeah and for part c you need atleast two blues and two reds
tame hound
So I need to pick up all the red balls and two blue balls.
When we deal with pigeonhole principle, do we consider the worst case scenario?
for instance, I could've easily picked up two blue balls and two red balls.
Why are we restricted to picking up all the red balls before we pick up two blue?
alpine sable
because you can't be sure that you picked 2 blues and 2 reds, you must think that you are picking them with your eyes closed and you must be 100% sure you have what is required
tame hound
because you can't be sure that you picked 2 blues and 2 reds, you must think tha...
but who is to say that I pick up all eight Red Balls in a row?
maybe I pick up seven balls that are red, then pick up three balls in a row that are blue, and then pick up another red.
7+3+1
so technically I am not exactly sure if I picked up eight balls in a row that are red.
we are after all picking up the ball at random.
or like you said, with our eyes closed
alpine sable
but who is to say that I pick up all eight Red Balls in a row?
yeah and you must imagine that you cant see what you picked
tame hound
yeah and you must imagine that you cant see what you picked
so in the best case scenario, we pick up all the red balls in a row and then consider picking up two extra balls that are blue, which leaves us with 10 balls picked from the bowl?
alpine sable
the best case scenario would be picking up two reds and two blues in 4 tries, but you must consider the worst case scenario to be 100% sure
tame hound
the best case scenario would be picking up two reds and two blues in 4 tries, bu...
OK thank you I think I got it.
.close
lone heartBOT
tame hound
.reopen
lone heartBOT
✅
tame hound
In this pigeonhole principle question, what are the pigeonholes and what are the pigeons?
A city has a population of 3.0 million. If we assume a human has a maximum of 400,000 hairs on his head, there must be at least x inhabitants in the city with exactly the same number of hairs on his head. Determine x.
rotund plank
In this pigeonhole principle question, what are the pigeonholes and what are the...
Try fitting people with varying numbers of hairs on their heads into groups based on the numbers of hairs on their heads
First of all it would be good to work out how many possible groups there are
Then you can map the problem to one not involving all the stuff about people and hairs and just consider objects in groups
tame hound
@rotund plank so, the number of items, nk+1, that can fit in a container n, where one container contains at least x items in the container.
but I'm not sure if the items in question are the population, 3 million, or the hair on the head which are 400,000.
or if the containers are 3 million.
I hope you understand what I mean by containers
rotund plank
Yeah I think the ‘3 million’ should be the containers
^classified based on hair numbers
tame hound
from what I was told, the amount of containers are ”the amount of people who has … hairs on the head”
rotund plank
Yeah
So maybe it would be more accurate to say the ‘3 million’ are the items, and the containers are amount of people with some number of hairs on their heads
They both involve the population so you have to be careful with vocabulary
tame hound
Sounds reasonable.
So n = 3,000,000 and k = 400,000?
Although from what I've been told, the constant k is 400,001…
and I'm not sure how they got that.
rotund plank
Well they can have maximum 400,000 hairs
They could have 0-400,000
You have to account for them having no hair at all
Also n = 4,000,000 seems a bit weird to me but it could be a typo
Or I’m not understanding your variable allocations
But you said the number of items is nk+1 and we certainly don’t have 400,004,000,001 items
tame hound
Meant 3,000,000
rotund plank
You meant nk+1 = 3,000,000 not n I’m guessing
rotund plank
Maybe you should just consider it logically rather than trying to allocate variables until you’re more comfortable
So just try to fit 3,000,000 objects into 400,001 containers
tame hound
There are 400,000 (technically 400,001 if you allow people to have no hair) different values for number of hairs on someone’s head.
Traversing through all the values, and only assigning the minimum number of people required, gives a minimum of floor(3,000,000/400,000)=7 people per hair value, meaning at least 7 people will share the exact same number of hairs as him.
Is this correct?
rotund plank
It is 400,001 but it doesn’t make a different here
gray isle
no
tame hound
It *is* 400,001 but it doesn’t make a different here
My teacher would have probably docked points off for me using 400,000 instead of 400,001 😂
gray isle
that isn't quite right
tame hound
that isn't quite right
what I wrote?
rotund plank
A city has a population of 3.0 million. If we assume a human has a maximum of 40...
Actually I think this is a bit unclear
Like what are we trying to minimise
Because I’m guessing the actual answer’s 8? If the question is phrased appropriately
If we’re trying to minimise the maximum number of people with a certain number of hairs
Then you take the ceiling
tame hound
Like what are we trying to minimise
The number of hairs on the head can vary between 0 and 400000. How many "containers" will there be?
The containers are "people who have 0 hairs on their heads", "people who have 1 hair on their heads", "people who have 2 hairs on their heads", "people who have 3 hairs on their heads", ... "people who have 399 998 hairs on the head "," people who have 399 999 hairs on the head "," people who have 400,000 hairs on the head ".
Then, you need to place 3 million inhabitants in 400,001 containers.
That's what I understand from the problem.
rotund plank
Yeah but you need to understand the logic behind it
tame hound
sure, what logic?
tame hound
No, it's in Swedish sorry.
rotund plank
Oh right
Okay well basically it’s important we know what we’re trying to minimise
What I ASSUME is that we want to minimise the largest number of people in the population with the same number of hairs
Then when we start splitting them into groups, 3,000,000/400,001 ≈ 7.5, so do you see where you went slightly wrong?
tame hound
If we put 7 people in each container, only 2.8 million inhabitants will fit. So we know that there must be at least 8 people who have exactly the same number of hairs in the city.
weak field
A city has a population of 3.0 million. If we assume a human has a maximum of 40...
let the number of persons in nth holes be the number of persons having n hairs... Therefore if u select any 2,800,008 persons some 8 persons will have the same number of hairs... Among these 2,800,008 persons, 2.8m persons have 400k groups where in each group 7 persons have the same number of hairs... The rest 199,992 people will have either 0 or 1 or 2.... or 400,000 hairs... To consider the worst case let us say that the rest 199,992 people each have different number of hairs such that 199,993 groups have 8 people with same number of hair...
Therefore in the worst case there will be 199,993 groups where in each group there are 8 people who have the same number of hairs...and 200,008 groups r there where in each group 7 people are there who have the same number of hairs...
Therefore the answer should be 8..
rotund plank
If we put 7 people in each container, only 2.8 million inhabitants will fit. So ...
Yeah
rotund plank
Number of items being allocated is n
Number of groups is k
Then the result is the ceiling of n/k
tame hound
what does it mean if the ceiling is greater or less than zero?
rotund plank
Zero?
tame hound
i.e., the number of items being allocated, divided by the number of groups, being greater or less than zero
tame hound
what does it mean if the ceiling is greater or less than zero?
I think I saw something like that on google
rotund plank
It doesn’t really make sense for it to be less than zero
At least in a standard setting like this
tame hound
OK ignore what I said, I'm just tired
rotund plank
Because the number of items and groups are both at least 1, otherwise this would be pointless
Alright
wicked tree
lone heartBOT
clear stump
Try shit and see what works
lone heartBOT
@wicked tree Has your question been resolved?
wicked tree
.close
stone dove
Hello, I need help with this problem:
lone heartBOT
Hello, I need help with this problem:
lone heartBOT
@stone dove Has your question been resolved?
obtuse parrot
Hey guys, how is it possible for the top equation to be simplified into the bottom one?
vale sapphire
It's the quadratic formula
tight locust
Yes.
vale sapphire
It's a bit rough, but it works
vale sapphire
(with respect to Y anyway)
quasi scarab
tacit arch
help channels are for math questions. please go to #discussion or #chill for off-topic questions
.close
lone heartBOT
tardy walrus
This question is to know about what mathematical technique is most appropriate for this question.
.reopen
lone heartBOT
✅
south anchor
hiya! so i have this question on geometric sums
Three weary mathematicians have to build a bridge over a 25-metre wide cliff. The first day they can build 10 metres, the second day they can only build 5 metres, the third day 2.5 metres, and so on. Find an expression for the length of the bridge after n days. Use the sum sign.
so i can see that with each day it shrinks with a factor of 0.5
n = 1 10 * 0.5⁰
n = 2 10 * 0.5¹
n = 3 10 * 0.5²
and so on
but how do i show dis w/ the sigma sign? thank u in adv
last ether
Yeah okay so
When you do these sums, there's no real "formula" for doing these
Its identifying a pattern
So, what stays the same when n = 1, 2, 3, so on?
south anchor
oh okay
ummmm the length 10 & the factor 0.5
0.5^(n-1) maybe?
i think that's the pattern i can see
last ether
10(0.5)^(n-1)
south anchor
alrighty
but i see these numbers above and beneath the sum sign
what do they even mean
last ether
Yeah
So
The bottom, usually is n = k
k is the initial point
So where the sum starts
On top is when it ends
south anchor
ok my mind overcomplicated it
when i read the cheat sheet it saiiid
so series starts at 0
last ether
Oh yeah
south anchor
and ends at n?
last ether
Series starts at 0
Ends at n
But k would be any dummy variable
Usually it's either n, k, or i
south anchor
does it matter what variable it is or
last ether
No really, as long as it is used in the sum to some capacity
last ether
Yeah, but n has to be used
Or like
If the pattern is changing, use n as a changing variable
wary crag
lone heartBOT
tacit arch
I first swapped the x and y
• Show your work, and if possible, explain where you are stuck.
wary crag
I am unsure whether this is correct
I tried and solved this multiple times and got this same answer
is the inverse even a function?
and how?
tacit arch
is the inverse even a function?
do you know the definition of function
wary crag
each input has a unique outpu
tacit arch
,w plot 1/(2x^2 - 1)
ocean sealBOT
tacit arch
each input has a unique outpu
check if the input has a unique output
wary crag
in that graph it does
so what abt the inverse
without graphing how can you tell that the inverse is a function
tacit arch
check if the input has a unique output
.
tacit arch
does every input have a unique output?
wary crag
does every input have a unique output?
yes
tacit arch
do you know what this symbol means
wary crag
positive and negative
tacit arch
what does $\pm 1$ mean?
ocean sealBOT
riemann
wary crag
positive and negative 1
tacit arch
is $y = \pm x$ a function?
ocean sealBOT
riemann
tacit arch
or even $y=\pm 1$
ocean sealBOT
riemann
ocean sealBOT
riemann
tacit arch
it's read as "plus OR minus"
wary crag
can you pls explain what it means
tacit arch
so $\pm 1$ is positive or negative 1
ocean sealBOT
riemann
tacit arch
so in $y=\pm 1$, it's two horizontal lines. One at y = 1 and one at y = -1
ocean sealBOT
riemann
tacit arch
every x value gets mapped to $\pm 1$, so you don't have 1 unique output. you have two. and by definition that's not a function
ocean sealBOT
riemann
tacit arch
**riemann**
similarly, every $x$ value gets mapped to $\pm x$, so it gets mapped to 2 values for all $x$ except 0.
ocean sealBOT
riemann
wary crag
so it would not be a function because there would be 2 outputs because of the $\pm$
ocean sealBOT
reckful
tacit arch
right
ocean sealBOT
reckful
last ether
Pretty much
wary crag
ok
last ether
Yeah but it's not a variable
last ether
That would
wary crag
but if u plug in 2 or -2 u get the same output
last ether
,w plot 1/(2x^2 - 1)
ocean sealBOT
last ether
but if u plug in 2 or -2 u get the same output
Yeah
That's fine
one x value cannot have two y values
wary crag
oh shoot im getting the definition of a function mixed up
mb
thank you
I actually understand it better now
.close
vernal shore
Can someone Tell me if my answer is right ?
lone heartBOT
Can someone Tell me if my answer is right ?
last ether
Yeah
u-substitution
Set u = cos(x)
That would become similar to the cubic function
y = 0, and u would equal to -1, 0.5, and 2
and because cos(x) = u
cos(x) = -1, 0.5, and 2
vernal shore
So what do I start with
vernal shore
Okay, I Will try to see what I can come up with
last ether
(Hint: the zeroes are given to you on the graph)
vernal shore
Do I put them into that equation ?
last ether
Well okay
Think about it
We substituted every cosine with "u"
And we're solving for zeroes
So rewrite the function
In terms of "u"
last ether
Yeah
Now that looks very similar to the graphed function, correct
As it's given to you
last ether
Yeah
you know that u = -1, 0.5, and 2
But you need to solve for x
you know that cos(x) = u
Replace u back with cos(x)
last ether
Okay so
What we did was that we had that ugly function with cosines
So we replaced every cos(x) with u
vernal shore
Yeah
last ether
Solved for "u"
Now it asks for the answers in terms of "x"
So we plug cos(x) back into u
This time, you know what u is
And you solve from there
last ether
I gtg but like
Hopefully someone can take over
Basically
• assigned u as a value of x
• plugged u in (substitution)
• solved for u
• solve for x with the u values
vernal shore
Thank you so much
scenic kraken
@vernal shore did you get it in the end?
vernal shore
No actually
I tried to put u in x
But didn’t work out
@scenic kraken
,rotate
ocean sealBOT
vernal shore
I don’t know what to do after this @scenic kraken
scenic kraken
What you did was unnecessary
You can see from the graph all the solutions to x (or u in your case)
Also, have you been given an interval to solve in?
@vernal shore
vernal shore
No that’s the only thing
vernal shore
You can see from the graph all the solutions to x (or u in your case)
Yeahh
U think u can draw it up for me ? And I will solve it
This my fourth try doing it
And I don’t know what to do after that
ocean sealBOT
Sam.
scenic kraken
If this were the interval, then your solutions would be $\pi , \frac{\pi}{3}, \frac{5\pi}{3}$
ocean sealBOT
Sam.
scenic kraken
Well if you know cos(x) = a, then x = arccos(a)
scenic kraken
Do you want an explanation or just answers?
vernal shore
I wanna know How to solve the equation
I haven’t solved a question before with for example cos^3 and cos^2
Involved
merry depot
I haven’t solved a question before with for example cos^3 and cos^2
If you let cos(x) = u, then you can rewrite this as a polynomial and factor it.
once it's factored you'll have (u-a)(u-b)(u-c) = 0, and you can resubstitute cos(x) back in. Then solve for x
vernal shore
once it's factored you'll have (u-a)(u-b)(u-c) = 0, and you can resubstitute cos...
That resubstitute part Is the part i don’t understand @merry depot
merry depot
from this (u-a)(u-b)(u-c) = 0 you have u=a, u=b, and u=c right?
merry depot
oh nice, i didn't see that
merry depot
great, so you have values for u
but the first thing you wrote was u = cos(x)
so you have cos(x) = u = -1
cos(x) = u = 1/2
merry depot
so where does cos(x) = -1?
vernal shore
U lost me
merry depot
so you have cos(x) = u = -1
^
merry depot
so you have cos(x) = -1
vernal shore
Yeah
merry depot
do you know the unit circle?
vernal shore
Not Really
merry depot
the x-coordinate at each angle is cosine of that angle, the y-coordinate is sine of that angle
vernal shore
So -1 would be pi
merry depot
i.e. $\cos(\pi/6) = \sqrt3/2$ and $\sin(\pi/6) = 1/2$
ocean sealBOT
Zybikron
vernal shore
Wait I’ll write this down on paper and show u Tell me if its right
But one of my points
Don’t exist right?
merry depot
right
merry depot
yep
merry depot
Yep
vernal shore
Yep
You are so good
Can Ask u about one more question if u have the time ? @merry depot
vernal shore
I have done it wrong I think @merry depot
Its suppose to say 03:00 am in the question above a)
merry depot
for a) you found the difference in height at the start and end of the day
not the maximum difference in heights
merry depot
what's the minimum value of cos(x)?
vernal shore
0
merry depot
nope
merry depot
So -1 would be pi
^^^^
merry depot
if the domain allows it, yes
lone heartBOT
@vernal shore Has your question been resolved?
vernal shore
if the domain allows it, yes
So what do I do ?
lone heartBOT
@gleaming mesa Has your question been resolved?
rich basin
lone heartBOT
rich basin
what is the negation of implies ?
lone heartBOT
@rich basin Has your question been resolved?
languid citrus
Hi I need help
lone heartBOT
Hi I need help
buoyant kayak
• After 15 minutes, feel free to ping @Helpers.
languid citrus
`• After 15 minutes, feel free to ping @Helpers.`
Yeah bud , waiting over 30mins and the channel closed
buoyant kayak
that's what happens when you just post your problem and leave
new channel, new 15 minutes
lone heartBOT
@languid citrus Has your question been resolved?
lone heartBOT
lone heartBOT
Available help channel!
fathom wasp
If 60 is at 79%, what is 60 at 100%? So the 21% is the difference. What would be the value increase of 60 with the added 21%?
merry depot
???
fathom wasp
Hello can I add more info into this?
olive oar
fathom wasp
Yeah. So this is related to mining. So the speed of the hash is 62 MH/s at 79%. Now this is not how fast it can go due to it being limited to 79%.
I was trying to find out if the how much more speed I can get with the missing 21% from a full 100%
I hope that made more sense
nvm I got it now
.close
delicate orbit
lone heartBOT
https://gyazo.com/c10f8ded0fd8cbe8a34f62fbc84a01bd
delicate orbit
im so confused
ocean prism
Solve for tangent
ocean prism
Square both sides
delicate orbit
i did that
ocean prism
To get tan
ocean prism
At what angle does tangent equal to $1/sqrt{3}$
ocean sealBOT
NicoA
delicate orbit
60 right?
ocean prism
U sure?
upbeat gorge
How do i put square roots in this bot?
backslash
ocean prism
Do sin/ cos
upbeat gorge
Instead of forward slash
upbeat gorge
$\sqrt{3}$
ocean sealBOT
CST
delicate orbit
at 180
ocean prism
U have your trig values?
delicate orbit
wait you meant sin(1/sqrt(3) / cos(1/sqrt(3)
upbeat gorge
Anyway, for your actual question, just a gentle reminder that tangent can yield positive or negative values
So don’t forget those
ocean prism
delicate orbit
ok, sorry i am so lost in this unit
ocean prism
ok, sorry i am so lost in this unit
No problem m8
Were here to help
Its kinda tricky to get used to the values
upbeat gorge
I disagree with the answers on two points
First, you were given tan^2, meaning that tan itself could be positive or negative and give the same tan^2
Second, the instructions imply that you need to express everything in radians
And round to 2 decimals
ocean prism
Pi/3 and 4pi/3?
ocean prism
Oohh i now understand it
upbeat gorge
to $\tan^2\theta=\frac{1}{3}$
ocean sealBOT
CST
ocean prism
I forgot about the plus and minus in a square root
ocean prism
There are four then right?
upbeat gorge
Yes
ocean prism
My b my b
upbeat gorge
It’s fine, these are natural mistakes
ocean prism
5pi/3
upbeat gorge
1 more
ocean prism
2pi/3
ocean prism
Replacing pi with its value?
upbeat gorge
Ye
You can just use a calc at this point tbh
You found the solutions yourself anyway
ocean prism
I try not to use calc
ocean prism
@delicate orbit
upbeat gorge
If you want to do it by hand
delicate orbit
lol i got you
sorry i have this shit that decides if i can pass this class due in an hour
ya boy gonna not passs
upbeat gorge
Wait was that a quiz question?
delicate orbit
just hw
its not a test or anything
for test we are put in a room with like just a calc and paper
i just havent been doing good in math and if i dont get this done in time ill need to liek ace my exam
this i am confused on as well
upbeat gorge
Play with trig identities
delicate orbit
the thing im confused on it there a start to it
like do i change the cot to cos/sin
and the tan to sin/cos
upbeat gorge
Try it out
upbeat gorge
Why 2 cos?
delicate orbit
cos/sin *cos
upbeat gorge
What does * mean
delicate orbit
mulitplu
upbeat gorge
So you’re saying that (cos)(cos)=2cos?
upbeat gorge
Ok
delicate orbit
and cos^2 is = to sin^2 +1
delicate orbit
i read notes wrong my bad
upbeat gorge
so sin + cos^2/sin
Which is why I suggest turning this expression into one fraction
delicate orbit
so in the end i would have (sin * -sin^2 + 1 / sin)
for the one fraction
wai tno
i cant think
i give up
i fucked up
ocean prism
The answer is a
delicate orbit
not reall
i have this lab report due that im wokring on now and if i finish it before midnight imma go back to math for like the 10 min ill have left
delicate orbit
.close
visual plinth
lone heartBOT
near hollow
Take the curve at the top to the one at the bottom
near hollow
Ye
near hollow
Any sort of translation and you make it more complicated
There are 2 nice reflections that get you straight to it
visual plinth
Are these the two transformations?
@near hollow
for some reason im struggling to think how the negative sign interacts with that fraction
lone heartBOT
@visual plinth Has your question been resolved?
visual dew
Displacement is (t+5)^2
find time at which velocity is zero.
why did i get a negative answer
lone heartBOT
lone heartBOT
Available help channel!
supple tundra
m
lone heartBOT
@supple tundra Has your question been resolved?
lone heartBOT
@supple tundra Has your question been resolved?
lone heartBOT
@supple tundra Has your question been resolved?
rotund plank
Let l and m have arguments theta and phi
And it could be good to consider the iff statement both ways
supple tundra
Do you mean arg(l) and arg(m) or the angle SLM and SML
rotund plank
The argument
supple tundra
SLM = SML right?
rotund plank
Yeah
If you can show that is LM and PQ are perpendicular lm + pq = 0, and if lm + pq = 0 then LM and PQ are perpendicular, you’ve proved the statement
alpine sable
<@&286206848099549185>
Start with option A:
182 days - 8p per day. 182*8=1456p or £14.62
You need to multiply this by 3 because the customer pays this back for each £500 borrowed and they have loaned £1500. 1500/500=3
So for option A, they are paying back 1500+43.86=£1543.86
Option B is fairly straightforward. Simply multiply 1500 by 1.027 = £1540.5
pale urchin
Thanks
alpine sable
For Option C:
A monthly repayment of 0.5% for 6 months is a total repayment of 3%. So multiply £1500 by 1.03 = £1545
So option B is the cheapest
pale urchin
Thank you so much
alpine sable
No worries
supple tundra
Bruv this is my channel
noble sinew
They want the answers in percentage
alpine sable
200 people stand in a circle in order to 1 to 200 . number 1 has a sword he kills the next person (i.e. No. 2) and gives the sword to the next living person (i.e. No. 3). all people do the same until only 1 survives. wich number surivives to the end?
rotund plank
200 people stand in a circle in order to 1 to 200 . number 1 has a sword he kill...
Seriously
Big red channel #❓how-to-get-help and you decide to click on this random channel instead without even considering where to go to get help
supple tundra
i think im gonna close this channel and reopen a new one lol
my question has been lost
.close
final thorn
how would i determine a definite integral when I have two unknowns unlike the usual one being x
main kraken
3 times 4
wary stream
On a computer, that has a calculator
wary stream
You can use a calculator to check
gray isle
the internet has plenty
ocean sealBOT
main kraken
atomic acorn
stop trolling man cmon
wary stream
,w 3x4
You seriously had to do that for them?
They can literally Google a calculator
obtuse finch
💀
gray isle
looks like you had some legitimate geo questions earlier
last ether
Either this kid is 8 and breaking the TOS
main kraken
so uhh
obtuse finch
madness
last ether
Or trolling
wary stream
The computer has a built-in calculator
main kraken
i am 2
gray isle
if you want to get proper help in the future, stop trolling at the risk of getting mod pinged and kicked
atomic acorn
lmao
atomic acorn
How are you on discord then
placid zinc
Y'all hard wasting your time
main kraken
is your sister
gray isle
being underage is not something to joke about
last ether
Idk
atomic acorn
don't tell your personal details on a public forum
last ether
Jim from the office is gonna whoop your ass anyways
atomic acorn
Jim from the office is gonna whoop your ass anyways
🙂
wary stream
This is unrelated
fading zephyr
rigid barn
Hi I wanted to ask a question about this
lone heartBOT
Hi I wanted to ask a question about this
rigid barn
The parts marked in red
I dont understand the question and how i can prove it belongs to the sigma algebra
lone heartBOT
@rigid barn Has your question been resolved?
lone heartBOT
@rigid barn Has your question been resolved?
rigid barn
.close
tiny goblet
For this integral it’s saying to coming 1/2 and x^2 and I was wondering why exactly you would combine them and why it would still be x^2 afterwards
vale wigeon
sounds like an odd way to say they're rewriting $\frac12x^2$ into $\frac{x^2}{2}$
ocean sealBOT
Ann
tiny goblet
So for these type of problems do you usually replace the 1 with the x^2
tiny goblet
Oh
proper tangle
the bot is programmed that way i think
vale wigeon
more like it's automatic if you do it by hand
alpine sable
how would i differentiate b,c, d ive tried but can’t seem to complete it
winter tangle
(b) product rule
(c) quotient rule (or product if you treat denominator to the -1)
(d) it's like doing 2^x
glad terrace
b) cos2 x 1/cos(square)x ?
winter tangle
b) cos2 x 1/cos(square)x ?
tf you on about?
alpine sable
(b) product rule
(c) quotient rule (or product if you treat denominator to the -...
thanks!!
alpine sable
is this? more accurate for b
winter tangle
agile compass
What is (-1)^1?
Yep
What is (-1)^2?
No. (-1)^2 = -1 × -1
And a negative times a negative is a positive
What about (-1)^3?
ocean prism
Is negative
-1•-1•-1
Every odd power is negative
And every even is positive
So youll have 50 odd
50 negatives
50-50 its just 0
Its just going to be like this
agile compass
You could write it as -1 + 1 - 1 + .... + 1 and say that you have 50 ones and 50 negative ones
agile compass
Youre welcome
raven rover
.close
lone heartBOT
lone heartBOT
Available help channel!
tame hound
It takes 7 days for four identical machines to perform a certain task together. How many more such machines are needed for the same task to be performed in 4 days?
slender gull
Kind of.
The question asks for how many more such machines.
So keep that in mind.
tame hound
So keep that in mind.
Yeah, so 3 more machines, right?
slender gull
Right.
tame hound
Is it correct to say that 4/7 is the combined rate of all machines to perform the task?
And x is the amount of machines we're interested in.
And 4 is the amount of days we want the work done in.
slender gull
Is it correct to say that 4/7 is the combined rate of all machines to perform th...
Are you implying all the machines together do 4/7 of the task?
tame hound
Are you implying all the machines together do 4/7 of the task?
I'm sorry, I think I meant the individual speed is 4/7 with respect to the combined speed?
Or atleast I don't know how to put it eloquently.
tame hound
Is the individual speed 4/7?
slender gull
No.
It's not.
That's where it gets different.
4 do the task in 7 days.
1 will do in how many days?
slender gull
It's not.
tame hound
is it the combined speed?
tame hound
Formula from physics wrt velocity:
s = vt
Givens: t = 7, s = 4
4 = 7v
v = 4/7
Someone said we could use x/4 = 7 => x = 28.
What is x representing here, time?
I just need to know how we arrange the equation.
last gate
x is representing the amount of days 1 machine needs
slender gull
That is where I was getting too initially.
Then you had doubts regarding combined time or something so I passed on that for a while.
Anyway now you have that.
tame hound
x is representing the amount of days 1 machine needs
How do we get that equation?
x/4 = 7
slender gull
4 machines do that work in 7 days.
1 machine will do that work in more time of course.
So it is more like, 1 machine will take four times the time taken by 4 machines.
Overall giving x = 7×4
Where x is the number of days one machine will take to complete that task.
tame hound
4 machines do that work in 7 days.
1 machine will do that work in more time of ...
So originally, I wrote
(4/7)x = 4.
where I put the number of machines in the numerator, but in the case of
x/4 = 7
we seem to put the number of machines in the denominator instead. Why? This is why I was curious about how we arrange the equation.
Ping me in case anyone responds.
tame hound
It takes 7 days for four identical machines to perform a certain task together. ...
Question here.
lone heartBOT
@tame hound Has your question been resolved?
slender gull
This is because, the number of machines is inversely proportional to the number of days required to perform the task.
@tame hound
lone heartBOT
@tame hound Has your question been resolved?
jade latch
do i move every point up?
lone heartBOT
do i move every point up?
wary stream
do i move every point up?
Yes
cunning copper
Is the gradient at a point of inflection of a curve always -1 or 1?
bitter vault
Is the gradient at a point of inflection of a curve always -1 or 1?
No. For example, f(x) = x^3 + 2x. Then (0,0) is an inflection point, but f'(0) = 2.
lone heartBOT
@cunning copper Has your question been resolved?
long panther
**waffle**
they have multiplied and divided "u" right about here
ocean sealBOT
waffle
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
long panther
**waffle**
Compile Error! Click the <:errors:504266556054962196> reaction for mo...
alright my bad i did not look at it clearly at first, they mention
and x is derived as
substituting these in x/sqrt(2x-1)
you will get ((u^2+1)/2)*(1/u)
and not 1/sqrt(u)
sorry I do not know how to use Texit since i am new here
no worries had me confused for a bit there
ocean sealBOT
waffle
