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tacit arch
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A standard normal table, also called the unit normal table or Z table, is a mathematical table for the values of Φ, which are the values of the cumulative distribution function of the normal distribution. It is used to find the probability that a statistic is observed below, above, or between values on the standard normal distribution, and by e...

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You'll need the complementary cumulative identity here

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In your notation, $P(Z \le z) = 1 - P(Z > z)$

ocean sealBOT
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riemann

pale mauve
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Thanks

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.close

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slender bane
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Im having trouble understanding the answer to this problem

slender bane
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where do we get 4 from

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ohhhhhh

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since 4<x^2<4

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yeah...

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i see now

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.close

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plush ermine
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This isn't really a pure math question. I'm wondering how to estimate fuel burn over time for a rocket where I know the acceleration at all times, and the mass at the beginning and ending of the burn.

plush ermine
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So I know m0, mf, and a(t), and I want to find m(t).

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Approximately.

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First thought is mdot=constant, but this is probably very wrong. Another idea is Isp=constant, which is closer to true.

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But I don't know how to use that to get m(t)

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Because I(t) is not known either.

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$I=\int_0^t m(\tau)a(\tau)d\tau$

ocean sealBOT
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PhysMan

lone heartBOT
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@plush ermine Has your question been resolved?

plush ermine
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!close

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.close

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desert zephyr
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Check what

pale mauve
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Sorry

lone heartBOT
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@alpine sable Has your question been resolved?

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visual plinth
lone heartBOT
visual plinth
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Anyone knows how the term on the left handside expands into the part underlined?

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ty

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im just getting to grips with all this proof stuff

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.close

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visual plinth
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Ty ,like I know how to expand brackets but I needed to break it down like you said to get 2^P+1 for the proof which is not how im used to thinking

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yeah. it seems so.

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last ether
lone heartBOT
last ether
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Lemme latex my work in a sec

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I have a feeling whoever made this form bugged out

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But wouldn't f(-4) be $3 -\int_{-4}^{2}f'\left(x\right)dx$

ocean sealBOT
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Umbraleviathan

last ether
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I'm getting 2π-2

lone heartBOT
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@last ether Has your question been resolved?

last ether
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<@&286206848099549185> it's a review thing btw.

last ether
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.close

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last ether
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.reopen

lone heartBOT
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last ether
last ether
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.close

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last ether
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.reopen

lone heartBOT
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last ether
last ether
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Which I'm getting 2π-2

late bridge
last ether
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Which is not an answer

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I'm wondering if I had set the integral up incorrectly

late bridge
late bridge
last ether
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Your question is vague

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Are you asking about the value of the integral

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Or what I'm trying to solve

late bridge
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the integral, it's what you messed up

last ether
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Aight lemme get back to you in a bit and see where I messed up

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Are you saying that I had evaluated it incorrectly or had set it up incorrectly

late bridge
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evaluated

last ether
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I realized

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I took it from -6

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Can't believe it

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Lmao

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Thanks

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.close

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undone saffron
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I need help with parallel line proofs, I started learning this yesterday and this homework is very confusing for me

last ether
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Let's see

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Show some of the work

undone saffron
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I am in 9th grade btw

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this is what I have so far

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i just have no idea where to keep moving

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and what the steps are supposed to be

last ether
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,rotate

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Might wanna crop out the teacher's names in case some weirdo tries to locate your school

undone saffron
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oh

last ether
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It's happened to me before

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Just a heads up

undone saffron
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can you delete the image rq

last ether
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Yeah

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Delete this too

undone saffron
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sorry if im being dumb

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its just so confusing

last ether
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No it's proofs

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Everyone hates proofs

undone saffron
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,rotate

ocean sealBOT
last ether
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Oh yeah there's a thing called same interior angle theorem

undone saffron
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yeah

last ether
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1 + 2 = 180°

undone saffron
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idk how it could be used here tho

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oh wait

last ether
undone saffron
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so

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m<1 + m<2 = 180

last ether
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Transversal would be AH

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yeah

undone saffron
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the reasoning would be same side interior angle theorem?

last ether
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You can state that AH is a transversal

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And then state that they are supplementary because of the same interior angle theorem

undone saffron
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my brain is exploding

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could i say transitive property of congruence or something?

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i think thats what my teacher taught me

last ether
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Just state that AH is a transversal of MA and TH because it intersects both parallel lines

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Which means you can apple Same Interior Angle Theorem

undone saffron
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i dont remember taking any notes on that hm

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let me check

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yeah theres no where that states anything about transversals

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this is what I have

last ether
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Transversal is a line that intersects two or more parallel lines

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Well

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Two or more lines

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They don't have to be parallel

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I guess it's implied that it's a transversal if it's a shape

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So I would actually jump straight into Same Side Interior

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Mb

undone saffron
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what

last ether
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Okay let's go back to the problem

undone saffron
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yes

last ether
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You know that MA || TH

undone saffron
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yep

last ether
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And that AH is a line that touches both of them

undone saffron
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ah?

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you mean AT

last ether
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I'm blind

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AT

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AT is a line that touches both of them

undone saffron
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yep

last ether
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And then you can use same side interior

undone saffron
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theorem?

last ether
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Yeah

undone saffron
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so what I have now is

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m<1 + m<2 = 180 degree

last ether
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Which, in itself, states taht angle 1 and angle 2 are supplementary to each other

undone saffron
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and reasoning is same side interior theorem

last ether
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Yeah

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So it's really just 2 steps

undone saffron
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wait

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so the entire thing is

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only 2 steps

last ether
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Given
Same Side Interior

undone saffron
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,rotate

ocean sealBOT
last ether
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Yeah pretty much

undone saffron
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WHAT

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ITS THAT SIMPLE?

last ether
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Sometimes

undone saffron
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bruhh

last ether
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You pray you get questions like those

undone saffron
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why does proofs exist

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i hate my life

last ether
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Because math sucks ass

undone saffron
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i was doing good before this

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and bam

last ether
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Yeah it takes practice

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Like

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A lotta

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Practice

undone saffron
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hold o

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im going to try a question

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and see if i did it right

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this thing right here

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wait

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are those isosceles triangles?

last ether
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Yeah

undone saffron
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so step 1 after given

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i will do

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m<1 + m<2 = 180 degrees

last ether
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no

undone saffron
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no

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IM STUPid

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ignore me for a second

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1 is congurent to 3

last ether
undone saffron
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is first step

last ether
undone saffron
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wgat

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ok

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uh

last ether
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State that BCD is an isosceles triangle first

undone saffron
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2 and 3 are corresponding?

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oh

last ether
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So that you can say that 1 = 3

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And by that one property, 1 = 2 = 3, so 1 = 3

undone saffron
last ether
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And because opposite side interior, those lines are parallel

last ether
undone saffron
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oh

last ether
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is why it's isoceles

undone saffron
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can I say see diagram tho

last ether
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No

undone saffron
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i think i did that somewhere in practice at school

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i forgot where tho

last ether
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You can say that if it's marked as equal

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But

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It isn't

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It's only given, in words

undone saffron
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ok let me see

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what graed are you in btw?

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just wondering

last ether
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11th

undone saffron
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dam

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wait

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is it converse of

last ether
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Yeah

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Converse of interior opposite angles

undone saffron
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,rotate

ocean sealBOT
last ether
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Yup

undone saffron
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i probably made mistake somewhere

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is this right?

last ether
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You got it

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Yeah

undone saffron
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omg

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i cant believe it

last ether
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You did it

undone saffron
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yayayysdyasdyasy

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last thing

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i am missing like 3 boxes

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,rotate

last ether
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Ye hold on

ocean sealBOT
last ether
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Uh

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This is weird

undone saffron
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yea?

last ether
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Of

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Oh

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m3 and m4 are supplemtary

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Wait no

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That's been stated

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Well

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I guess m3 + m2 = 180

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That's my guess

undone saffron
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did i do the other stuff right tho

last ether
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Yeah

undone saffron
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for 8 i cant understand what the reasoning is supposed to be

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cause it says its same side interior on step 9

last ether
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You can just use substitution property

undone saffron
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so just substitution??

last ether
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If 2 = 3 and 2 + 4 = 180

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Then 3 + 4 = 180

undone saffron
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i have to stap like step 3 right

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like substitution (step 3)

last ether
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Basically

undone saffron
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or is it another step?

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okay finally done

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this actually helped a lot

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tysm @last ether

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how do i close this thing?

last ether
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.close

last ether
undone saffron
#

.close

lone heartBOT
#
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lone heartBOT
#

@alpine sable Has your question been resolved?

oblique pier
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wa?

oblique pier
lone heartBOT
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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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#

@alpine sable Has your question been resolved?

tacit arch
#

What kind of answer are you looking for? A field with two elements is a set with only two elements so of course it's different from sets with countably and uncountably infinite cardinality.

alpine sable
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@alpine sable I'm not sure the question is coherent yet. What do you mean by "it has a different solution set"? what is the solution set of a field?

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do you mean to ask about the solutions to a polynomial equation or something like that?

tacit arch
#

.close

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hardy skiff
lone heartBOT
#

@hardy skiff Has your question been resolved?

slate jolt
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idk what is a centroid Y-bar, but I can help if you want the centroid of the shape

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@hardy skiff Has your question been resolved?

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peak stag
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is it right if i say that the sum of constants is another constant?

peak stag
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also, constants can't contain variables right?

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like the quadratic expression:
ax^2 + bx + c
where a, b and c are constants. I can't have x in a or b or c i believe

vale wigeon
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yes

peak stag
#

cool thanks

#

.close

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peak stag
#

also in the quadratic expression:
ax^2 + bx + c

is ax^2 and bx considered as variables?

peak stag
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i know that a, b and c are constants but not so sure if i have constants multiplied by variables

tight locust
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No

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Just x is the variable

peak stag
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so the whole term isn't a variable?

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it can't be a constant either

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cause x is a variable

vague holly
#

A polynomial is an expression, I wouldn't say it's a variable

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#

@peak stag Has your question been resolved?

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zenith compass
lone heartBOT
zenith compass
#

I want to ask about the notation problem

So basically I know $\mu$ and $\bar{x}$ are referring to population and sample mean respectively

But I saw some version just denote the mean by $M$

So my question is, what does this $M$ refer to? Population or sample?

Can I further replace $M$ by $\mu$ or $\bar{x}$?

ocean sealBOT
#

Trenton

bitter vault
ocean sealBOT
#

1345631

zenith compass
#

.close

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tight locust
#

$\bar{\mu}$

ocean sealBOT
#

EndTimes

$\bar{\mu}$
zenith compass
lone heartBOT
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zenith compass
lone heartBOT
ocean sealBOT
#

Trenton

zenith compass
#

Oh sorry

#

.close

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tight locust
#

Lmao

zenith compass
#

Lol

zenith compass
#

In anime

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Two bars

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So cute

tight locust
fluid flame
#

mf got sum bars

zenith compass
#

$\bar{\sum}$

ocean sealBOT
#

Trenton

zenith compass
#

Lol

fluid flame
#

that shit tiny wtf 💀

zenith compass
#

Lol

#

Btw the “chill” channel disappeared?

fluid flame
#

What?

granite imp
#

integral?

fluid flame
zenith compass
#

I miss that channel

fluid flame
granite imp
#

$\bar{\integral}$

zenith compass
fluid flame
#

$\bar{\int}$

ocean sealBOT
#

Plumbum

granite imp
#

hehe xd

zenith compass
fluid flame
#

$\not{\int}$

vale wigeon
ocean sealBOT
#

Plumbum

zenith compass
granite imp
#

${\int}$

ocean sealBOT
#

Melik
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

vale wigeon
#

is there a question being discussed here?

fluid flame
#

Bruh wtf

zenith compass
#

Nope. Problem solved

vale wigeon
#

okay.

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.close

zenith compass
#

It is closed

vale wigeon
#

ah.

fluid flame
#

@zenith compass btw

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no it's not closed

zenith compass
#

?

zenith compass
fluid flame
#

...

zenith compass
#

Ummmmmmm

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Maybe I was banned

vale wigeon
#

channels sometimes take a few minutes to close

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it's notmal

#

normal*

zenith compass
#

But I really can’t find “chill”

zenith compass
fluid flame
#

cuz u ain't "chill"

#

fkn burn lmao

zenith compass
#

QAQ

lone heartBOT
#
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dim vine
lone heartBOT
dim vine
#

How come the statement I've underlined is wrong

#

Can I not use X as 49/Sin(A) ?

limpid spade
#

what is X

dim vine
#

Sorry. It's the force dragging the 5kg "particle" down the slope

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I've got it labelled as 81.67 but apparently I'm wrong

limpid spade
#

what's given

dim vine
#

Angle A and the masses

limpid spade
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what's angle A

dim vine
#

36.87

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Sin^-1(3/5)

limpid spade
#

no friction?

dim vine
#

Nope

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We assume there's none for this one

random zinc
#

should be *sin if you search the force

limpid spade
#

is there acceleration

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or is it constant speed

dim vine
#

Constant acceleration

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U mean 49*SinA? That's what the solution guy did but I don't understand where I go wrong if I take it at 49/SinA

random zinc
# dim vine

what you did here, is you calculated the geometric hypothenuse of the triangle. If you search for the force you have to calculate it inside a force parallelogram

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connect your x arrow with the 49N arrow, then you got a new triangle

dim vine
#

Ok let me think for a second

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Wait isn't that the triangle I've been using?

random zinc
dim vine
#

Ty

random zinc
#

If you search for the force, you have to use the red triangle. What you did you calculated the blue one (not quite exactle because the triangle is not 49 high. Does this helps ?

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the red arrow showing down is your Gravitation Force. It could happen that the red and the blue triangle are the same but very unlikely

dim vine
#

Oh so is it not 49 high because there are other forces going in that direaction?

random zinc
#

your triangle not, your force is 49. But take a look on the sketch. Now your Gravitation Force is the hypothenuse. In the blue one you handled it like the opposite side

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these are two different triangles. One for the actual block, and one for the forces

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you calculated the length of the block, if you now what I mean. But not the x Force

dim vine
#

Aaahh

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ok thank you

random zinc
#

your alpha angle is on the bottom, where I drew a small circle. You can proof that by some angle identities but not necessary

dim vine
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Yeah I ended up using the 53.13 as the top right angle and it came out as right

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It was 49Cos53.13

#

Thanks a lot though. Hopefully I'll remember this

random zinc
#

Awesome!

dim vine
#

Although stuff is a lot easier to remember when you understand it so thanks again

#

.close

lone heartBOT
#
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crisp perch
#

hi

lone heartBOT
silver adder
#

hi

crisp perch
#

do u guys know this

lone heartBOT
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@crisp perch Has your question been resolved?

last ether
#

Yeah

#

You would integrate

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crisp perch
#

i

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crisp perch
#

who knows this?

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fallen plover
#

Why is B the 'A' and not A itself

lone heartBOT
fallen plover
#

Can anyone help plz

#

Thank yoy

#

You

#

The formula to find the angle using cosine rule is CosA=b²+c²-a²/2bc

#

But idk why that top A isn't the 'A' and instead it's the B instead

#

Bc of that I got my answer wrong too which could be harmful in exams

#

<@&286206848099549185>

lone heartBOT
#

@fallen plover Has your question been resolved?

dim vine
#

'A' is just the angle with the known side, 'a', opposite it. 'b' and 'c' are the other two sides in no particular order

fallen plover
#

Ik I was just wondering why the opposite 'a' in this question wasn't 9m and was 10m instead

#

Or maybe the A point in that triangle can't have the angle A on it perhaps

#

Damn idk lol

dim vine
#

Are you just asking why they decided to label the sides in a way that was confusing to use the cosine rule with? Because they did it so that it would be confusing to use the cosine rule with to 'test the understanding'

fallen plover
#

Damn that's kinda harsh but makes sense

#

Okay I see thanks for ur help

#

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@alpine sable Has your question been resolved?

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fresh relic
#

I want to be able to solve problems like this. What topics/videos should I look at to be able to do these?

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tropic sail
#

Hello

lone heartBOT
tropic sail
#

When doing implicit diffenciation with respect to x,

#

Why do we put dydx after a y term?

placid zinc
#

That's the chain rule

#

Let's say we're taking the x derivative of some f(y) = u. Then:
du/dx = du/dy × dy/dx

#

The left is what you want.
The middle is the actual derivative
The right is the dy/dx that gets stuck on the end

tropic sail
#

What about the derivation of

#

ln(y) = x^2

#

Why is it

placid zinc
#

(1/y)(dy/dx) = 2x

tropic sail
#

Yes but why the dydx

#

Why not (1/y) = 2x

rotund plank
#

Chain rule

#

The guy said

placid zinc
#

In order words:
d[ln(y)]/dx = d[ln(y)]/dy × dy/dx

rotund plank
#

We always use the chain rule, just sometimes it’s not obvious

placid zinc
#

Notice the dy "cancels" on the right, to give the result you want on the left

tropic sail
#

Ah yes

#

Ty

#

.close

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wheat sapphire
#

Can anyone tell me the answer?

lone heartBOT
wheat sapphire
#

am I right?

naive valley
#

yes

wheat sapphire
#

Bro, my book says the answer is 4

#

how?

naive valley
#

haha what, where would 4 come from

#

it's d/dx(r_x) + d/dy(r_y) + d/dz(r_z), which is d/dx(x) + d/dy(y) + d/dz(z) = 1 + 1 + 1

#

which is 3 last time I checked 😆

wheat sapphire
naive valley
#

must just be a typo

wheat sapphire
#

yeah, it must be

#

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midnight prairie
#

how do i make divisions easily?

lone heartBOT
midnight prairie
#

like today i had to do 205700/14075

supple hinge
#

calculator

#

unless youre in like 2nd grade

#

even if

#

calculator lol

solar pebble
#

i mean you can divide both by 5

#

41 140/2815

#

then 5 again

#

but that's really the most you're gonna get

supple hinge
#

when u get past like middle school

#

all u use is calculators tbf

midnight prairie
#

im in elementary school 8th grade

supple hinge
#

then you should be allowed calculators

midnight prairie
#

im not

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midnight prairie
#

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desert lantern
#

(reposting bc I fell asleep last night before anyone responded) probably a very simple question but I'm struggling. I have values that are between 0 and 1, and I want to amplify them so that they skew closer to the extreme ends of the scale if that makes sense

desert lantern
#

someone suggested a density function or something but I didn’t understand that bc I am a bozo and when I googled it i could not understand 🤡

naive valley
#

lots of ways to do this, for example for numbers between 0 and 1 you make them larger (but still in [0,1]) by taking square roots or higher roots

desert lantern
naive valley
#

ok

#

squaring and higher powers have the opposite effect

#

you could do a piecewise function: if x is <= 0.5 then square it or cube it (or higher power), if x is > 0.5 then square root it or cube root it (or higher root)

#

that's one approach anyway

last tendon
#

The way you would normally do this is to use a probability integral transform

#

This lets you convert and uniform [0,1] random variable to another probability distribution function, so all that is required is that you pick a distribution with the skewness properties you want and apply the transform on your random samples

#

The big picture ideal is to view your uniformly distributed random numbers as a quantile, and the invert it to get a probability following whatever distribution you need

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#

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desert lantern
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low thorn
lone heartBOT
lethal flint
#

Hi I have a question, what is AE?

buoyant kayak
buoyant kayak
lethal flint
#

ok

low thorn
buoyant kayak
#

how did you get either of those numbers

low thorn
#

I have no idea

#

I think I did either equation then I subtracted them

buoyant kayak
#

what

low thorn
#

I don't know 😕

#

I think I figured it outututututt

#

.close

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quasi nacelle
lone heartBOT
quasi nacelle
#

how do i do this?

buoyant kayak
#

do you know the general formula for sum of a geometric series

quasi nacelle
#

u r a goat @buoyant kayak

buoyant kayak
#

hmm actually i think you need to use the formulas for the sum of k and k^2

#

from 1 to n

quasi nacelle
#

is it 18(n-1)/n^2

buoyant kayak
#

give me a sec

#

no it is not

quasi nacelle
#

what am i doing wrong am i not suppose to subsitute the n

buoyant kayak
#

can you show me exactly what you're doing

#

cause i'm not sure how you arrived at that answer

quasi nacelle
#

yeah idk can u show me how start and continue it

buoyant kayak
#

do you know $\sum_{k=1}^nk$ and $\sum_{k=1}^nk^2$?

ocean sealBOT
#

a disappointing son

quasi nacelle
#

.close

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alpine sable
#

How is this calculated ?

lone heartBOT
alpine sable
#

I have tried a few methods but I’m not getting the right answer

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#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

#

Please anyone 🥺

#

<@&286206848099549185>

#

Sorry for pinging again, I only have 10 mins left to answer this question, I’ve done it before but I’m having a mind blank and totally forgot how I did it

#

.close

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shell tree
#

Hello, i’ve solved this as far as I feel confident and now must conclude if it’s divergent or convergent, my question is if the value like in my example is a real number then will it be convergent? and in the case my value went to infinity would it be divergent?

shell tree
#

.close

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gray trout
#

would this be considered a linear oblique asymptote?

gray trout
#

or this???, im p sure its the first

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@gray trout Has your question been resolved?

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leaden prawn
#

Eqn 1 --- 23 = k(2^n) + 7
Eqn 2 --- 61 = k(3^n) + 7
How do I find k and n?

jagged imp
#

Take 7 from both equations, then divide one equation by the other to eliminate k

leaden prawn
#

Ah got it, thanks

#

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hexed night
#

pls help in part f)

lone heartBOT
hexed night
#

I hv tried finding inverse

#

but its not good

#

then i tried taking g(x) = a + bx + cx^2

#

since x= g(x) * e^g(x)

#

but not really sure how to do the ques

#

someone can send working pls?

#

thank you

hexed night
hexed night
#

please

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#

@hexed night Has your question been resolved?

hexed night
lone heartBOT
#

@hexed night Has your question been resolved?

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@hexed night Has your question been resolved?

tacit arch
#

.close

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primal thicket
#

question: state exact value of Tan(2pi/3) without using calculator

primal thicket
#

this is what im doing

#

tan(theta) = sin(theta)/cos(theta)

#

and when i compute sin(2pi/3) and cos(2pi/3)

#

only cos(2pi/3) is -pi/6

#

why isnt sin(2pi/3) = -pi/6

wary stream
#

Because cos is the x direction

barren olive
#

just use the tan(A+B) rule

#

in this case Tan(2A)

wary stream
#

2pi/3 is in quadrant 2

#

Using the unit circle, you'll observe that cos is -pi/6

#

And sin is positive

primal thicket
#

jsut to make sure, quadrant 2 is the top right of the circle?

wary stream
#

Top left

primal thicket
#

ahhh

#

ok this makes sense

barren olive
#

quadrant 2 , = pi/2 to pi

#

ASTC is good way to remember whats gonna be positive in what quadrant

#

A means all

primal thicket
#

i see

#

thanks!

#

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alpine sable
lone heartBOT
alpine sable
#

@timid heath

timid heath
#

ok, have you learned the process where you look for if the top or bottom of the fraction has a higher power?

alpine sable
#

yeah i think so

timid heath
#

so what kind of situation is it in part 1

alpine sable
#

the power is greater in the denominator than numerator

timid heath
#

yup

#

and what does that imply about convergence/divergence?

alpine sable
#

therefore it converges?

timid heath
#

oh sorry. It's a bit more complicated than I thought. You're dealing with sums

#

I was just thinking limit of a sequence

#

okay, it's still not too bad

#

try breaking up that fraction over the +

#

and simplify

alpine sable
#

n/n^(2) + 7/n^(2)

#

1/n + 7/n^(2)

timid heath
#

correct

#

now do you remember learning something about the infinite sum of 1/n ?

alpine sable
#

it diverges?

timid heath
#

yup

#

so the whole thing also diverges

alpine sable
#

ok so from the choices at the top it would be A?

timid heath
#

yup

#

your series is strictly greater than series A, which is known to diverge

#

so by comparison test yours diverges

alpine sable
#

Ok!

#

For 2 it's D and it converges right?

timid heath
#

yea nice

alpine sable
#

ok i just got all of them correct

timid heath
#

excellent

alpine sable
#

ok for this one what do i do when there is 2 n terms in demonominator?

timid heath
#

the general idea is to figure out if it's strictly greater or smaller than one of those you're comparing it with

#

so the exact number of terms doesn't matter

#

things like + or - matter

alpine sable
#

ok for the first one is it D and converges?

timid heath
#

there's a better match for it than D

alpine sable
#

is it C

timid heath
#

no, it's B

#

the series 1/(n^2 + n + 1) is similar to 1/n^2, they both have the same highest power

#

but each term of 1/(n^2 + n + 1) is strictly less than the corresponding term of 1/n^2

#

because n^2 + n + 1 > n^2

alpine sable
#

less than

#

?

timid heath
#

because having a greater bottom means the overall fraction is smaller

#

like 1/5 < 1/4

alpine sable
#

i see

#

ok i solved all the problems on that page

#

is the power rule the same thing as well

#

i can just ignore it?

#

for #2

timid heath
#

try to rearrange it so it's more directly comparable to one of those four

#

splitting the fraction up over the top often helps

alpine sable
#

so like n/n^2 + 2/1

timid heath
#

yeah

#

well not quite

#

n/(n+1)^2 + 2/(n+1)^2

#

it might help to do a change of variable

#

let m = n + 1

#

then it can be written (m+1)/m^2

#

that's 1/m + 1/m^2

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

I see thank you

lone heartBOT
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warm latch
#

how do you do this like the sulotion?

lone heartBOT
drowsy lagoon
#

Do you understand what is perpendicular?

warm latch
#

yes

#

90 degrees

#

but I dont see square so idk

drowsy lagoon
#

Do you know what does this symbol means?

warm latch
#

perpendicular?

drowsy lagoon
#

Yes

warm latch
#

oh

drowsy lagoon
#

so, now read the question again

warm latch
#

then 2x is 90?

drowsy lagoon
#

no

warm latch
#

or x = 90

drowsy lagoon
#

BA ⊥ BC

warm latch
#

ye

drowsy lagoon
#

and ⊥ means perpendicular

warm latch
#

oh then

#

BA = 90

#

?

drowsy lagoon
#

no

warm latch
#

is

#

perpendicular

drowsy lagoon
#

BA and BC is perpendicular

#

This means angle between BA and BC is 90

#

also known as angle ABC is 90

warm latch
#

then

#

what is

#

BA

#

Now

#

2x or 90

#

or

#

div?

drowsy lagoon
#

BA is just the side though

#

there is no angle in BA

#

BA is just a straight line

warm latch
#

ye

drowsy lagoon
#

There is no angle in a straight line

warm latch
#

so

#

X = 42?

#

or no

drowsy lagoon
#

how do you get x is 42?

warm latch
#

i did

#

2x/2 90/2

#

= 42

drowsy lagoon
#

do you realise that angle ABD + angle DBE + angle EBC = angle ABC?

warm latch
#

ok

drowsy lagoon
#

so now angle ABC is 90

warm latch
#

so

#

the x was 90 or 2x

#

since

#

A and C

#

a= 2x

#

and c is x

drowsy lagoon
#

angle ABD + angle DBE + angle EBC = angle ABC
2x + 30 + x = 90

warm latch
#

so uh

#

how do

#

I find out

#

what is

#

X

#

do I subtract those 2?

#

or 30 - 90

#

then div

#

2x

#

to 60

#

2x/2 60/2 = 30

#

is that X?

drowsy lagoon
#

wrong

warm latch
#

HM

#

then how

drowsy lagoon
warm latch
#

ye

#

oh yea

#

i forgot

#

I am finding X

#

uhhhhhhhhhhhhhhhhhhhhhhh

drowsy lagoon
#

okay

warm latch
#

then how do I find

#

what do I do?

#

do I add

#

wait

#

180?

#

then

#
  • 30
#

150

#

then I division to 2?

#

then 75?

drowsy lagoon
#

2x + 30 + x = 90

warm latch
#

yeah

#

then

drowsy lagoon
#

2x + x = 3x

warm latch
#

oh

drowsy lagoon
#

so 3x +30 = 90

warm latch
#

3x

#

but the X

#

how

drowsy lagoon
#

3x + 30 = 90
3x = 90 - 30
3x = 60
3x/3 = 60/3
x = 20

warm latch
#

OH

#

i was close

#

dang

drowsy lagoon
#

hmm

warm latch
#

i answered 60

#

oh thats why

#

I divided by 2

#

not 3

#

lol

#

thanks

drowsy lagoon
#

okay

#

welcome

warm latch
#

btw how would I find

#

degrees

#

wait

#

abd is

#

2x

#

how do I turn to degrees?

#

2x to degrees

drowsy lagoon
#

now x is 20

#

it means one x is 20

#

two x = 2x

#

so 2x is?

warm latch
#

3x?

drowsy lagoon
#

x = 20
2x = 2(x)
2x = 2(20)

warm latch
#

ohh

#

so 2(20)

#

but degree

#

do I add?

drowsy lagoon
#

yes

warm latch
#

22 degrees?

drowsy lagoon
#

degree is just the symbol

warm latch
#

yes

drowsy lagoon
#

40 is correct

warm latch
#

but idk where is that symbol

#

ohh

#

yea

#

THANKS

#

FOR GUIDING ME

#

SENSEI 😭

#

thank you!

drowsy lagoon
#

try to practice more on algebra

warm latch
#

yee

#

I am kinda bad

drowsy lagoon
#

algebra is super important

warm latch
#

at it

#

yeah for college

#

i am highscholler

#

highschool

#

thanks btw

drowsy lagoon
#

you are welcome

warm latch
#

ty ty

lone heartBOT
#

@warm latch Has your question been resolved?

lone heartBOT
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agile yarrow
#

Hey, with some help of the community yesterday i got closer to a solution i guess but im stuck again. Im trying to solve for y for the following equation: x=(1-0.5^y)^(1/y)
Currently i have: x^y+0.5^y=1 (added some intermediate steps in the screenshot). Now the problem is that i know of no ln propery or exponent property that could help me out here. Does anyone have a idea on where i went wrong / where to go from here?

lone heartBOT
#

@agile yarrow Has your question been resolved?

agile yarrow
#

Since this doesn't seem to be easily resolved i dont want to occupy this channel any longer. Ill try again later. If anyone in the meantime finds a solution to my question feel free to dm me :)

#

.close

lone heartBOT
#
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#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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alpine sable
#

Area of a pls

lone heartBOT
drowsy lagoon
lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
drowsy lagoon
#

correct

alpine sable
#

Thank you

lone heartBOT
#

@alpine sable Has your question been resolved?

#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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pale arch
#

hellooooo i need help w writing this logarithm

pale arch
#

it seems simple enough but its not accepting any of my answers (log2 3, log2 3y, log2 3y^2)

#

nvm got it

#

.close

lone heartBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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night sigil
#

quick question is the inequality sign meant to be reversed when taking the negative square root?

plucky lynx
gray ingot
#

if there are no steps above what you sent then its not meant to be reversed

night sigil
#

so this would be right?

plucky lynx
# night sigil

How did you get -1/2 <= k <= 1/2? What you have above that is fine.

#

It should be k <= 1/2.

gray ingot
#

thats what they wrote

#

its correct

night sigil
#

this is what's in the solution to the questions

#

the range of k is that exluding 0

#

I just want to know if it's always true that the inequality sign should be reversed when taking a negative square root

gray ingot
#

in that you weren't supposed to change the sign

night sigil
#

yes I wrote it wrong to begin with I think sorry

gray ingot
#

however if it was k^2 > 1/4 then what you did is correct, but avoid writing k > +-a

#

because k^2 > a
doesn't imply k > +- a

night sigil
#

well it's a square root

#

don't those usually have a positive and negative solution

gray ingot
#

yes they do
k^2 > a
implies k > sqrt(a) or k < -sqrt(a)

night sigil
#

ah ok that makes sense

gray ingot
#

k > +- sqrt(a) is wrong

#

because if k > -sqrt(a) then it has to be greater than sqrt(a)

#

and k^2 > a doesn't mean k > -sqrt(a)

night sigil
#

yes

#

thank you

#

.close

lone heartBOT
#
Channel closed

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lone heartBOT
#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

frigid hatch
#

quick question, let's say this graph represents a car moving, would I be right if I said that on t=0 the car is still?

bitter vault
frigid hatch
#

what about t=10

#

it should be still there too, no?

bitter vault
alpine sable
alpine sable
#

the y axis

frigid hatch
bitter vault
bitter vault
frigid hatch
#

ok

#

last thing

#

would the gradient on t=10 equal 0?

bitter vault
frigid hatch
#

or vertical?

#

like in this case

lone heartBOT
#

@frigid hatch Has your question been resolved?

lone heartBOT
#
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#
Available help channel!

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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

pulsar aspen
#

Equalize the denominator

#

Find the smallest common multiple of 5 and 9

#

Wait, there is a closed form formula:

#

a/b + c/d = (ad+bc)/bd

#

But then you need to simplify the fraction

#

Okay, identify the a b c and d

alpine sable
pulsar aspen
#

At 8th degree you should be already familiar with the concept of variable

#

Okay, let's use the common multiple method algorithm instead

#

Some people will find the formula easier, that's why I included that.

#

You already got the common multiple 45, right, then, make both of the denominator 45

#

You know how to change denominator, right?