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tacit arch
#

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verbal compass
#

A ball is tossed into the air from the roof of a building. Its height, h metres above the ground after t seconds is modeled by the relation
h = -3.5(t – 3)² + 60
What is the height of the building

gray isle
#

what have you thought about

verbal compass
# gray isle what have you thought about

Well at first I tried substituting t for 0 and that gave me
h = -3.5(t – 3)² + 60 h = -3.5(-3)² + 60 h = -3.5(-9) +60 h = 31.5 + 60 h = 91.5

I feel like this is wrong

gray isle
#

you stuffed up your algebra

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$(-3)^2 \neq -9$

ocean sealBOT
#

ℝamonov

verbal compass
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Oh it's +9

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h = -3.5(t – 3)² + 60 h = -3.5(-3)² + 60 h = -3.5(9) +60 h = -31.5 + 60 h = 28.5

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This then?

gray isle
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yes

verbal compass
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Hmm

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Ok that works

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Thank you

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:)

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gritty veldt
#

quick question

lone heartBOT
gritty veldt
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what do you call factoring, but into additions instead of multiplications?

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for example

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a=b+c

gray isle
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not sure how

a=b+c
shows what you're trying to describe

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wdym by

into additions instead of multiplications

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can you show me examples of what you mean by
factoring into additions and
factoring into multiplications

gritty veldt
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oh, I think I got it,
I think the word I'm looking for is decomposition

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like fourier decomposition

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so

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what I want is something like this

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f(a,b) = g(a) + h(b) + m(a,b)

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would you call this decomposition?

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tacit arch
#

That wasn't so hard, was it

alpine sable
#

...

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alpine sable
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alpine sable
#

is this correct?

bitter vault
# alpine sable

Not quite. The slope of the tangent is given by $\dfrac{dy}{dx}$. First write $y = r\sin(\theta) = 2\sin(2\theta)\sin(\theta)$, then find $\dfrac{dy}{d\theta}$. Similarly, find $\dfrac{dx}{d\theta}$. Now apply the chain rule to obtain $\dfrac{dy}{dx}$

ocean sealBOT
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1345631

supple tundra
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I know it's not the intended method, but you could always multiply both sides by $r^2$, and then get convert to cartesian and then implicit differentiation

ocean sealBOT
#

azeem321

supple tundra
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I.e. $(x^2+y^2)\sqrt{x^2+y^2}=4xy$

alpine sable
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So u convert polar to parametric

ocean sealBOT
#

azeem321

alpine sable
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And go from there

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lucid wadi
#

Hi

lone heartBOT
lucid wadi
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isn't their answer wrong?

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why did the negative disappear and ln of x change to ln 1/x

karmic rapids
ocean sealBOT
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illuminator3

knotty spire
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Basic properties of logarithms

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also the reason they are useful for differentiation

lucid wadi
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oh alright

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thank you

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tame hound
#

Carl has 15 colored balls in his pocket. The balls have three different colors. Carl randomly take the balls out of his pocket. What is then the smallest number of balls that Carl has to pick up to surely get at least one ball of each color?

Information given:
(1) 1/3 of the number of balls are black.
(2) 7 balls are red and 3 balls are blue.

Can we solve this with info 1, info 2, separately, or combined?

tame hound
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(1) B = 15*1/3 = 5
5+X+Y = 15

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(2) R = 7, Y = 3, X = 5
=> R+Y+X = 15

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I was thinking in information (1), we don't know how many of the balls are of different colors.

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Information (2), we know the color of every ball, so the information is sufficient to solve the question.

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Any comments?

drifting hull
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of course we can solve it in every case, we just get different answers

tame hound
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Please explain how we can solve it with information one only.

drifting hull
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The balls have 3 different colors, so there is at least one ball of each color. If he picks up all 15 balls, he clearly has one of each color

tame hound
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Well the answer is that it can only be solved with information (2) alone, (1) is insufficient.

gray isle
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15 isn't necessarily the smallest

tame hound
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What do you mean by ’smallest’?

gray isle
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the fewest number

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addressing Alex's comment

tame hound
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You think my reasoning was ok?

gray isle
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yes

tame hound
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Ok thanks.

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ember token
#

Im stuck with these equation (factorization)):
-16t²+48t+488 = 0

ember token
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I've tried to factorize it
-8(2t²-6t-61)

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but i cant find common factor between the three terms

short cobalt
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61 is prime

ripe rain
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,w -16t^2 +48t +488

knotty spire
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you can still factor it

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,w factor -16t^2 +48t +488

ember token
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i did that

ripe rain
ember token
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is that the furthest it can be done?

ripe rain
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Yes

short cobalt
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yes, but it must be with the quad formula , right?

ember token
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because after that i did:
2t²=0
t²=-2

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And the square root of -2

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And with the other

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-6t = 0
t= 6

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and i supposed that 6 was the answer i dont know if im correct

ripe rain
ember token
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its equation

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the goal was to find t

ripe rain
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2t^2-6t-61=0 doesn’t mean 2t^2=0, -6t=0 and so on

ripe rain
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You need to do is use quadratic formula here

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Thats it

ember token
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k thanks

#

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hallow sparrow
#

How would I solve for the first five terms? The homework suggests that we need to reach the binomial series using the factoring I did in the beginning. I’m not sure how to account for variable a if I’m not doing the original Taylor series

hallow sparrow
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However if I do use the original taylor series, how would I build out the terms using the original (or the factored version)?

lone heartBOT
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@hallow sparrow Has your question been resolved?

hallow sparrow
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<@&286206848099549185>

tacit arch
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Does it say to calculate the Taylor series ? Show the instructions

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What you did looks fine. I don't get why you want to use Taylor series

hallow sparrow
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It asks for the first five terms

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@tacit arch I'm just confused because I feel like it needs to be in a Taylor form since the center isn't 0.

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The professor hinted the factor 3^(1/3) in the beginning

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Which makes sense, but to use a binomial series here throws me for a loop

lone heartBOT
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@hallow sparrow Has your question been resolved?

hallow sparrow
#

<@&286206848099549185>

shell widget
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@hallow sparrow Replace x by 4x for the first one, for the second you can write it as (1+4x) (1+4x)^(1/3)

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you know (1+4x)^(1/3) from the first part, multiply by (1+4x)

hallow sparrow
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I'm on 196, sorry for the confusion

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@shell widget

shell widget
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ah

hallow sparrow
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I ended up writing out terms using the original taylor series, despite my professor's "hint" to set it up to binomial series form

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Because the binomial series form afaik doesn't account for a

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I left a comment on the problem asking how to account for it

lone heartBOT
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@hallow sparrow Has your question been resolved?

lone heartBOT
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@hallow sparrow Has your question been resolved?

tacit arch
#

.close

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violet canopy
#

Can someone please help me with this, the word cut at the start is “using”

limpid spade
#

a^(b/c) =cthrootof(a^b) right?

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lost briar
#

hello! my question is:
Find the range of values of k if the curve y=kx^2−2x+(2k−1) lies completely above the x−axis.

I don't know where to start in answering this question, thank you!

rotund plank
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Now what property must the graph have for it to not go below the x-axis?

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(And is it sufficient)

lone heartBOT
#

@lost briar Has your question been resolved?

cursive badger
#

hint: ||what kind of roots would it have?||

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bigger hint: ||what kind of roots would it have if it never touches the x axis||

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biggest hint: ||since your roots are y=(-b±sqrt(b^2-4ac))/2a, for there to be no roots, b^2-4ac must be negative, making your roots imaginary (thus no intersection). plug in your a b and c values and find the k values that make the roots imaginary.||

lost briar
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hmm, roots that are imaginary ..

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i see negative values

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do not work at all

lone heartBOT
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@lost briar Has your question been resolved?

lost briar
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as well as 0, so only positive values

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ok i get it now thank you!

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#

Please don't occupy multiple help channels.

wary stream
#

Don't open multiple channels

eternal hedge
#

Ok

wary stream
#

So close this channel

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mystic sinew
#

Why would adding x *I to a matrix not change the eigenvectors?

merry depot
#

work it out. What does it mean to have an eigenvector/value?

mystic sinew
oak perch
#

Ay=λy then (A+xI)y=(λ+x)y

lone heartBOT
#

@mystic sinew Has your question been resolved?

mystic sinew
#

That if Ay=λy then (A+xI)y=(λ+x)y

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indigo dock
#

How do you write in algebraic form

lone heartBOT
simple turtle
lone heartBOT
#

@indigo dock Has your question been resolved?

indigo dock
simple turtle
simple turtle
lone heartBOT
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@indigo dock Has your question been resolved?

swift shore
#

@indigo dock wdym

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ocean spindle
lone heartBOT
ocean spindle
#

Hey could someone correct me if im wrong

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but the answer is -3

tacit arch
ocean spindle
#

wait sorry

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one sec

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in this cause would i solve for critical numbers

tacit arch
ocean spindle
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so i found the derivative which ended up to be
3(x+3)(x+1)

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critcal values
x=-3 x=-1

tacit arch
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The other part is evaluating at the boundaries

ocean spindle
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so i would have to esstentially guess and check

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by plugging in -4, -1 , 0, 3

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into the f(x)

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f'(x)*

tacit arch
#

That's not guessing, that's enumerating

ruby hinge
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nah f(x) itself

ocean spindle
#

sorry f(x)*

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would that process be correct

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do the critical values not always tell u the ABSOLUTE max/min?

ruby hinge
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wait u might need to take the double derivative as well

ocean spindle
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sorry

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then what does a critical number tell u?

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when the points change direction

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okok

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i used desmos and noticed

ripe rain
#

Wait you need to understand the curve

ripe rain
ocean spindle
#

can someone explain why x^2-1/x^2

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the critical numbers 1

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and not 0

ripe rain
ocean spindle
#

yep

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i got it

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thanks

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Could u explain this?

oak perch
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alpine sable
#

help

lone heartBOT
alpine sable
#

ok so

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i need he,p

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anyone!?!?!?

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help me plzzzz

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<@&286206848099549185>

safe needle
#

Write down the area of the triangle formula using known variables

lone heartBOT
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@alpine sable Has your question been resolved?

alpine sable
#

no

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lmao

#

mf

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there are very unhelpful people and this server is innactive

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cuz america is currently asleep

opaque inlet
#

Write down the formula for the area of a triangle

lone heartBOT
#

@alpine sable Has your question been resolved?

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real wolf
#

small brain moment... why is it b and not a

real wolf
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found the tangent of y=4x-4 not sure what they did after this to obtain (3,8)

tight locust
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What

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Why would the tangent be 4x-4

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Do you understand the concept of differentiation?

real wolf
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is the tangent rule not y=4x - 4

tight locust
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No?

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Tf

real wolf
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oh what the answers said it was lol

tight locust
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The derivative is 2x

real wolf
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yes

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sub in 2 for gradient at that point?

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y-4=4(x-2)

tight locust
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So at the point (2,4) you get the slope is 4

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And then use point slope formula

real wolf
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yes...

tight locust
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Oh I see what you did

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My bad I misread

real wolf
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lmao

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all good homie

vital crown
tight locust
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4x - 8 + 4 = 4x - 4

real wolf
#

get what sorry

vital crown
#

,calc 3*4-4

ocean sealBOT
#

Result:

8
vital crown
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(3,8) fits y=4x-4

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,calc 4*1-4

ocean sealBOT
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Result:

0
vital crown
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(1,0) fits y=4x-4.

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Not (1,-4)

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Seems like a careless mistake on your part

real wolf
#

oh

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i didnt even think of that lmao wtf

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testing values ahhh i see

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thank you fellas

#

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lime igloo
lone heartBOT
indigo flint
#

I forgot what the | means

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But I think it’s just u put 0 into x and becuase of that function ur answer turns positive

lime igloo
#

Modulus

indigo flint
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So ur min val is 1?

indigo flint
lime igloo
#

For that I think we would have to use differentiation

indigo flint
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Yeah I think it’s 1

lime igloo
#

Answer is 59 I suppose

indigo flint
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Nah it just asks for what’s the min value u can get right?

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Acc ur right

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One sec

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So to go from x-1 to 119x-1 we have gone 120 times

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And if the minimum modulus of each function is 1, then the answer should be 120

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Because the lowest real number u can put in to the function to get a low number is x=0

lime igloo
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120 was coming as my answer too but exercise sheet says 59 is the answer

indigo flint
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Oh bruh

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Did they show working out?

lime igloo
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Nah

indigo flint
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I don’t think differentiating will help

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Does the question tell u how many marks it is

lime igloo
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6

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Marks

indigo flint
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Damn that’s quite a lot

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Is this a level question?

lime igloo
#

Ya

indigo flint
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I can’t recall whether I did something similar to this question or not

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Year 13?

lime igloo
#

Ya

indigo flint
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Is there a way u can differentiate the equation

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It wouldn’t make sense tho would it

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U would just get 1,2,3 and so on

lime igloo
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Yes

indigo flint
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I think there’s a different formula maybe but I rly can’t recall bro I’m sorry

indigo flint
lime igloo
#

Na

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😔

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wait i think figured something out

indigo flint
lime igloo
#

<@&286206848099549185>

lone heartBOT
#

@lime igloo Has your question been resolved?

rotund plank
#

From what book?

lime igloo
#

An exercise sheet

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Given to me by my institute

rotund plank
#

One way to go about this is to use the absolute value inequality $\mid x - a \mid + \mid x - b \mid \ge \mid a - b \mid$

ocean sealBOT
#

dk.dkn

lime igloo
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Oh ok

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Got it

vale wigeon
rotund plank
vale wigeon
#

\vert is also an option

lone heartBOT
#

@lime igloo Has your question been resolved?

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soft cosmos
#

Hello

lone heartBOT
soft cosmos
#

I have a hwfor stats and prob

#

i get a z score which is -25, and it is abnormally big

#

<@&286206848099549185>

lone heartBOT
#

@soft cosmos Has your question been resolved?

#
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soft cosmos
#

.repoen

#

.repoen

#

.reopen

lone heartBOT
#

lone heartBOT
#

@soft cosmos Has your question been resolved?

soft cosmos
#

<@&286206848099549185> PLEASE

#

can you show the mistake?

lone heartBOT
#

@soft cosmos Has your question been resolved?

lone heartBOT
#

@soft cosmos Has your question been resolved?

lone heartBOT
#
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alpine sable
#

Hi

lone heartBOT
alpine sable
#

Can somebody help me to solve this integral?

#

∫sin(x^3).3x^2

gray isle
#

what have you tried?

alpine sable
#

I stopped halfway cuz i know this method won’t work after checking the answer

gray isle
#

consider using the substitution
u = x^3
also don't forget your dx

alpine sable
#

oh yea

#

but the point is

#

i wanna know

#

how to get rid of the 3x^2

#

i realised i stuck at every question with the variable behind when it isn't a constant

#

cuz then i can't simply pull out

#

and thats what confuses me

#

@gray isle

gray isle
#

go through the whole process of integration by substitution starting with the substitution
u = x^3

alpine sable
#

no i mean

#

the 3x^2 behind :(((

gray isle
#

i know

#

go through the whole standard process and it'll become clear

#

from

u = x^3
find the relation between dx and du

rotund plank
#

@alpine sable Have you learnt the reverse chain rule?

alpine sable
#

my teacher said there is no chain rule in integration

rotund plank
#

reverse

gray isle
#

chain rule is everywhere in calculus

alpine sable
#

no

#

i think my teacher

#

avoids that part

#

im not sure

#

man

#

sorry

gray isle
#

u = x^3
du/dx = ?

alpine sable
#

3x^2

gray isle
#

yes

alpine sable
#

????

gray isle
#

and then du = ?

alpine sable
#

alright

#

du?

gray isle
#

yes...

alpine sable
#

how to get du alr?

#

forgive me

gray isle
#

you have du/dx

alpine sable
#

i am dumb

#

yes

#

how to get du then?

gray isle
#

solve for du

#

basic algebra

rotund plank
#

What have you actually learnt in integration?

#

What methods do you know for integrating

gray isle
#

$\dv{u}{x} = 3x^2 \implies \dd{u} = , ?$

ocean sealBOT
#

ℝamonov

alpine sable
#

from - *

#

to + divide

alpine sable
gray isle
#

no

#

don't overthink this

alpine sable
#

i don't seem to understand

gray isle
#

this is really basic algebra

alpine sable
#

anything

#

here

#

ugh

gray isle
#

like really really basic algebra 1 algebra

alpine sable
#

3x^2dx

#

?

gray isle
#

yes

alpine sable
#

what

#

lmao

#

okay

#

😂

rotund plank
#

Yea I’m not sure he’s manipulated derivatives before

gray isle
#

which is present in your original integral

alpine sable
#

damn when the du dx comes in

#

my whole world is messed up?

#

lol

rotund plank
#

You’ll learn about it soon enough

alpine sable
#

wait a min

#

i think i know alr

alpine sable
#

lol

#

also

#

@gray isle

#

what about du?

gray isle
#

wdym

alpine sable
#

i get du and then sub back to the equation

#

what does it do tho?

gray isle
#

indicates which variable you are not integrating with respect to

alpine sable
#

im totally not with you lol

#

but its okay

#

:((( maybe the methods we come across are totally diff

#

@gray isle

gray isle
#

look up integration by substitution

alpine sable
#

IG I NOW KNOW

#

T HANKS TO MY FAV TEACHER

#

EDDIE WOO

#

thanks @gray isle

#

ughhh my teacher never taught this before

#

I SWEAR

rotund plank
#

I sort of always viewed them as separate things before

gray isle
#

you're starting with
$$\int \sin(x^3)\cdot 3x^2 \dd{x}$$
using the substitution: $u = \red{x^3}$ leads to $\dd{u} = \blue{3x^2\dd{x}}$
$$\int \sin\underbrace{(\red{x^3})}{u}\cdot \underbrace{\blue{3x^2 \dd{x}}}{\dd{u}}$$
$$\int \sin(u) \dd{u}$$

ocean sealBOT
#

ℝamonov

gray isle
#

which gets you something that you should definitely know how to integrate

alpine sable
#

THANK YOU

#

@gray isle

#

<33

lone heartBOT
#

@alpine sable Has your question been resolved?

#
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sly mantle
#

.close

lone heartBOT
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wet spindle
lone heartBOT
wet spindle
#

okay, 88 and 888 are just trial and error right?

#

we only need 8 8s to get to 1000

#

but we still don't know how many digits we should put in a row

gray isle
#

consider
1000 = 8 * 125
888 = 8 * 111
88 = 8 * 11
8 = 8* 1

wet spindle
#

okay

#

how does this help?

gray isle
#

have a think about it

wet spindle
#

hmmm

#

add the ones

#

and you'll get 125

#

888 = 8 * 111
88 = 8 * 11
8 = 8* 1
8 = 8* 1
8 = 8* 1

#

it still doesn't explain how we know it's 888 + 88 + 8 + 8 + 8 instead of 88 + 88 + 888 + 8 for example

gray isle
#

if you think about it properly it will

#

1000 = 8 * 125
adding a total of 125 8s gets you 1000

#

888 = 8 * 111
by adding 888 you're effectively adding 111 8s

#

same idea for the rest

#

888 = 8 * 111
88 = 8 * 11
8 = 8* 1
8 = 8* 1
8 = 8* 1
how many 8s are you effectively adding by adding
888 + 88 + 8 + 8 + 8

#

and compare that to

88 + 88 + 888 + 8

gray isle
#

yes

wet spindle
#

okay

wet spindle
#

why doesn't he continue adding 1 with nth number of 8s like he did with 40 and 20?

gray isle
#

they're getting to the closest multiple of 10

#

and in this case they must get 10 for the final sum to be 1000

wet spindle
#

trying the same thing with number 4

#

and I just realized that if you multiply an even number by 5, you'll get 0 as the last digit of the sum

#

with 4, I understand that you need 250 4s to get to 1000

#

but I still don't know how many digits I should put in a row

gray isle
#

consider positive integer solutions to
$$111a + 11b + c = 250$$

ocean sealBOT
#

ℝamonov

gray isle
#

for efficiency you'd want a as high as possible

lone heartBOT
#

@wet spindle Has your question been resolved?

wet spindle
#

ok for 8, we need 8 8s to add together

#

for 4, we need 7 to get to 1000

#

right?

gray isle
#

huh?

wet spindle
#

Did the same with 8

#

8 8s is needed to get to 1000

#

tried the same with 4 but I couldn't get an answer

wet spindle
#

here we have 7 4s

#

but I couldn't find any other way to get to 250

gray isle
#

use more 4s

wet spindle
#

I only need 7

gray isle
#

I only need 7
where's that coming from

wet spindle
wet spindle
gray isle
#

i don't see how that leads to the conclusion that you can get to 1000 using 7 4s

wet spindle
#

hmmm

#

that was the case with 8

gray isle
#

set up the addition table properly

wet spindle
gray isle
#

yes

wet spindle
gray isle
#

see what happens when you try and follow their approach

#

note that i dislike their approach and would recommend that you just use what i set up

wet spindle
#

the first problem in Gelfand's Algebra and boy is it hard

lone heartBOT
#

@wet spindle Has your question been resolved?

wet spindle
#

yeah I can't solve it

lone heartBOT
#

@wet spindle Has your question been resolved?

lone heartBOT
#
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ripe ore
lone heartBOT
karmic rapids
#

what have you done so far

alpine sable
#

,rotate

ocean sealBOT
graceful juniper
#

Is what I did

#

In Indio = me

karmic rapids
#

don't spoonfeed

lone heartBOT
#

@ripe ore Has your question been resolved?

rotund plank
# ripe ore

Is that $2\sqrt{2}\cdot x$ or $2\sqrt{2x}$?

ocean sealBOT
#

dk.dkn

lone heartBOT
#
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sage rain
#

It’s telling me this is wrong

lone heartBOT
sage rain
#

Standard form to vertex form

#

I don’t understand how

leaden shadow
#

I think you forgot to divide both sides by -1

sage rain
#

At which point do I do that?

leaden shadow
#

At -x²-6x=-1

sage rain
#

Now why do you do that?

#

I had an earlier problem that I didn’t have to do that

#

I don’t remember the professor showing us an example like that

leaden shadow
#

Because if you complete the square, it's not going to be correct.

sage rain
#

Wouldn’t it just be -x^2-6x+(-6/2)^2

#

So the left side is -x-3)^2

#

?

lone heartBOT
#

@sage rain Has your question been resolved?

#
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lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#

@alpine sable Has your question been resolved?

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orchid path
#

Hello I am a student who speaks Spanish, but I do not have the help of a teacher due to the economic situation and in my school the teachers cannot help with the homework, perhaps for some this is easy, but it is difficult for me to be able to understand it, geometry has always been a weak point of mine, I have tried to solve it but it is difficult, I don't know if someone could help me with this, I have translated it, I even translate this to be able to communicate, I hope to have your help

orchid path
#

<@&286206848099549185>

lone heartBOT
#

@orchid path Has your question been resolved?

orchid path
#

anyonee?

frigid fulcrum
#

Yes?

dull storm
#

is teaching students by professors considered waste of time

#

since they just repeat same things and same explanations over and over again

#

do they consider they could spend that time more productively on research and stuff like that, science?

#

or do they always keep getting something out of teaching students like new ideas, new insights - stuff like that

#

i mean they do have time for science and everythinb but i am talking about these couple extra hours specifically

orchid path
#

Everything is complicated, but do you know how to solve it? In spite of everything, it is a task and if I do not deliver it I will be failed, I do not ask you to solve it, only your help to be able to solve them together

lone heartBOT
#

@orchid path Has your question been resolved?

lone heartBOT
#
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lone heartBOT
#
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alpine sable
lone heartBOT
lone heartBOT
#

@alpine sable Has your question been resolved?

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idle spindle
#

anyone has tips on how to easily know if it is a one tailed or two tailed test?

surreal sinew
idle spindle
#

my teacher said if its finding the paramaters its a two tailed test

#

is that always correct?

#

.close

lone heartBOT
#
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balmy gale
#

If we have two independent events in probability (A and B). How do you calculate the smallest value of P[A n B]? Isn't it always 0?

lone heartBOT
#

@balmy gale Has your question been resolved?

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#

@balmy gale Has your question been resolved?

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sour dew
#

Sort of an abstract question - I have a scenario where I'm applying k++ means clustering, but I want to define each area of a centroid in the fashion of a square (doesn't necessarily have to be a square, as long as I can get some definable area) - can anyone point me to any literature or definitions that can achieve something like this?

lone heartBOT
#

@sour dew Has your question been resolved?

sour dew
#

<@&286206848099549185>

lone heartBOT
#

@sour dew Has your question been resolved?

last tendon
#

Without really thinking about it that carefully, it just sounds like you are replacing the usual euclidean metric with the taxicab metric. I doubt scikit-learn or anything has that built in so it'd be a bit of work to code yourself.

lone heartBOT
#

@sour dew Has your question been resolved?

sour dew
#

is there anyway I can ensure in that each grouping the lengths of the area are identical? even if the areas overlap

last tendon
#

I haven't thought enough about the problem to comment further. I would expect you would find very little literature because it will be unpleasant at best.

#

If you have a license you can just open up the source code and tinker with it

sour dew
#

ok thank you

lone heartBOT
#

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indigo dock
# simple turtle Sorry. What do you mean?

I apologise, I had a math class. What I meant was how to write algebraic equations in discord e.g. @oak perch usually writes some kind of code and then the bot reads it as an equation, like x/(x+3) except it writes it how you would on paper if you know what I mean. How do you do that?

regal schooner
#

it's using texit

#

you can use #bots for trying it out

lone heartBOT
#

@indigo dock Has your question been resolved?

lone heartBOT
#
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indigo dock
lone heartBOT
regal schooner
indigo dock
#

Lemme try though I am still unsure

#

.close

lone heartBOT
#
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lone heartBOT
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vague iris
#

Is dy/dx the final answer or d/dx?

lone heartBOT
indigo dock
vague iris
#

imn not sure if my notation is correct

indigo dock
#

Is there a question?

vague iris
indigo dock
coral moss
#

when you differentiate you are using d/dx on both sides. For example, y=x differentiated is d/dx y = d/dx x. You are basically multiplying d/dx by y which is why you have dy/dx iirc

#

Because you are differentiating with respect to x

#

So you can either say d/dx (y) = 1 or dy/dx = 1 for y=x

#

It will probably make more sense when you do implicit differentiation

lone heartBOT
#

@vague iris Has your question been resolved?

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#
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tawny fable
#

Hey there

lone heartBOT
tawny fable
#

I have a question in linear algebra.

#

Struggling on both sides

bitter vault
# tawny fable

=> Assume T is invertible. It is thus injective and surjective. Use injectivity to conclude {T(b_1) ,..., T(b_n)} is llinearly indepedent, and use surjectivity to conclude that it also spans W.
<= Assume T sends a basis of V to a basis of W. Conclude from this that dim V = dim W, so T is an isomorphism and thus bijective.

#

Hope this helps you get started

round stump
#

all the complex numbers z such that z^2 = -5+12i

bitter vault
round stump
#

I need the solution

bitter vault
round stump
#

not homework

#

I am not a student currently

vale wigeon
#

@round stump this channel is occupied, and also we don't give out answers.

bitter vault
# round stump not homework

Still, it's rude to order people to do what you want. Phrase your question in a more neutral way, such as "Can someone help me with the question about ...". Just saying "Find all complex .." means you are ordering people to do your work for you.

round stump
#

where I find channel

#

?

vale wigeon
#

Math help (AVAILABLE)

bitter vault
vale wigeon
#

^ also that

round stump
#

I am unable to reopen

#

how to open a channel

vale wigeon
#

@alpine sable do not encourage channel stealing.

alpine sable
#

hm?

#

I don't understand

#

what is channel stealing?

round stump
#

I write . reopen but nothing changed

vale wigeon
#

it's when someone insists on posting their question in someone else's channel

alpine sable
#

Ah I see

vale wigeon
#

@round stump you have opened your own channel #help-14 by posting in it

#

now you wait for someone to come along and help you

round stump
#

ok

alpine sable
round stump
#

I will there

vale wigeon
#

@tawny fable are you still here?

alpine sable
#

I recognise the question he asked. It is from Linear Algebra done right book lol

#

Very difficult book in general

lone heartBOT
#

@tawny fable Has your question been resolved?

tawny fable
#

So sorry

#

missed it.

tawny fable
#

now for the =>
I am struggling on understanding how can I use the surjective to show it spans W

#

@bitter vault

vale wigeon
#

T is surjective. write out what this means formally

#

just that, nothing else

tawny fable
#

We know that for every vector in W there is a vector in V s.t T(v) = w

vale wigeon
#

w in W, and v in V

tawny fable
#

yeah

vale wigeon
#

don't omit names when introducing things

#

okay, yes

#

and what would it mean if {Tb_1, ..., Tb_n} were to span W?

#

write this out formally too

tawny fable
#

if span{Tb_1, ..., Tb_n} = W

vale wigeon
#

...not what i wanted tbh

tawny fable
#

Then alpha_1Tb_1 + alpha_2Tb_2 + ... + alpha_n*Tb_n = 0 iff alpha_1....alpha_n = 0

vale wigeon
#

no

#

that's linear independence

#

not what we are talking about rn

tawny fable
#

oh sorry

vale wigeon
#

i wanted "every vector in W is a linear combination of Tb_1, ..., Tb_n"

tawny fable
#

then every vector in W can be written as a linear combination

vale wigeon
#

except with quantifiers

#

a linear combination of something.

tawny fable
#

But that is all assuming that it spans W

vale wigeon
#

you can never say "a linear combination" on its own

vale wigeon
#

i'm asking you to translate the statement "span {Tb_1, ..., Tb_n} = W" into something we can work with

#

and the translation i expected is: $$(\forall w \in W)(\exists c_1, \dots, c_n \in K)(w = c_1Tb_1 + \dots + c_nTb_n)$$

ocean sealBOT
tawny fable
#

Yeah ok

#

I get it

#

I just don't understand how does that help me with the question

#

like

#

ofc it is

#

assuming towards a contradiction?

#

Is that the way you are aming for?

#

@vale wigeon

#

wait

#

if {Tb_1,...Tb_n} is LI

#
  • T is surjective
#

Ok I have one side

#

T is invertible

#

thus dimV = dimW

#

thus that set {Tb_1, ... , Tb_n} is LI with the size of n

#

thus a basis for W

vale wigeon
#

sorry am in class

tawny fable
#

in class?

#

You're a student?

#

You're like a hundred times better than my teacher

#

lol

#

.close

lone heartBOT
#
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leaden tiger
#

need some help proving a trig equation
so i have

leaden tiger
#

and i need to get it in terms of tan

gray ingot
#

how do you think you can get tan from sin and cos?

leaden tiger
#

im not sure i tried dividing vrything by cos

gray ingot
#

alright

#

now you do you what's tan(a-b)

leaden tiger
#

yes

gray ingot
#

what is it

leaden tiger
#

its the identity right?

gray ingot
#

close, but that's the identity for tan(a+b)

leaden tiger
#

the bottom sign should be +

gray ingot
#

yes, now what is 1 in terms of tan

#

or what x will give tanx = 1

leaden tiger
#

pi/4

#

dammit these question r so annoying

gray ingot
#

alright now replace 1 with tan(pi/4)

leaden tiger
#

i think i get it now

gray ingot
#

yup

leaden tiger
#

yep, got it

#

theres always litterally 1 step in these question that i dont think about and i lose the entire thingg

#

anyway, thanks for the help!

#

.close

lone heartBOT
#
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quiet sinew
#

is this correct? i didnt know u could cross multiply addition of fractions

quiet sinew
#

you need to prove 1/1-cosp + 1/1+cosp = 2cosec²p

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@quiet sinew Has your question been resolved?

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tame moss
#

is $(k+1)!(k+1) = (k+2)!$

lone heartBOT
ocean sealBOT
blissful temple
#

Try k = 0, does the equality hold?

tame moss
#

yes

blissful temple
#

No, why?

tame moss
#

oh no it doesnt

gray isle
#

recall the basic definition of the factorial

blissful temple
#

$(k+1)!(k+2)=(k+2)!$ though by definition

ocean sealBOT
#

Zanarcane

normal wing
#

no, but (k+1)!(k+2) is

tame moss
#

okay

#

thank you

#

im working on proof by induction

#

with inequalities

#

.close

lone heartBOT
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tame hound
#

What part of this whole figure is shaded?

knotty spire
#

What have you tried?

tame hound
#

I haven't tried anything yet.

#

@knotty spire Do you know how to think here?

hollow shale
#

What are the areas of the semicircle and the circle?

knotty spire
#

What two shapes do-

tame hound
knotty spire
#

is the radius of the circle r?

hollow shale
#

Are you sure?

tame hound
#

r/2

#

$$A_{semicircle}=\pi r^{2}\times \frac{1}{2}$$
$$A_{semicircle}=\frac{\pi r^{2}}{2}$$
$$A_{circle}=\pi (\frac{r}{2} )^{2}$$
$$A_{circle}=\frac{\pi r^{2}}{4}$$

knotty spire
#

good, now you can probably solve it

ocean sealBOT
#

AuHasard

tame hound
#

@knotty spire How do I find out how much is shaded now?

knotty spire
#

Well, you want to find out what part of the semicircle is shaded by the circle.

#

What would that be?

tame hound
#

Do I divide them?

knotty spire
#

Which by what

tame hound
#

The circle divided by the semicircle.

knotty spire
#

yup

tame hound
#

This? $\frac{\frac{\pi r^{2}}{4} }{\frac{\pi r^{2}}{2} } =\frac{2}{4} =\frac{1}{2}$

knotty spire
#

yes

ocean sealBOT
#

AuHasard

tame hound
#

@hollow shale Is this right?

hollow shale
#

Yes.

tame hound
#

So half of it is shaded?

hollow shale
#

Yes.

knotty spire
#

That's why we use math, and don't just eyeball it.

hollow shale
#

It doesn't look like 1/2, but the numbers don't lie.

lone heartBOT
#

@tame hound Has your question been resolved?

lone heartBOT
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tame hound
#

The cleaner Yngwe has 4,000 less in monthly salary than the teacher Arber. Arber has two thirds as much salary as the doctor Chandra. Together, the three have as much in salary as the Member of Parliament Joar, who has 66,900 in monthly salary.

How much does Arber have in monthly salary?

tame hound
#

Yngwe gets 4000 less Arber. Arber has 2/3 higher salary with doctor Chandra, right? Or how do I write?

tame hound
#

this is what I've got so far, can someone give me more advice?

normal wing
tame hound
#

@normal wing So 2x/3 - 4000 + 2x/3 + x = 66900, right?

normal wing
#

correct

tame hound
#

$$66900=\frac{2x}{3} -4000+\frac{2x}{3} +x$$
$$66900=\frac{4x}{3} +\frac{3x}{3} -4000$$
$$66900=\frac{7x}{3} -4000$$
$$70900=\frac{7x}{3}$$
$$70900\times 3=\frac{7x}{3} \times 3$$
$$70900\times 3=7x$$
$$30386 ≈ x$$

#

@normal wing Is that right?

normal wing
#

It’s actually in decimals

#

but you rounded it up

#

so yes

ocean sealBOT
#

AuHasard

tame hound
#

$$\frac{2}{3} \times 30385.7=20257.14$$

ocean sealBOT
#

AuHasard

tame hound
#

@normal wing This is Arber's salary right?

normal wing
#

correct

tame hound
#

Ok thanks.

#

.close

lone heartBOT
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kindred wing
lone heartBOT
kindred wing
#

can somone help me with this

#

why arent we including 3 and 4

#

so wont it be like 6x6x6

lone heartBOT
#

@kindred wing Has your question been resolved?

bitter vault
kindred wing
#

.close

lone heartBOT
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serene moon
#

Hi

lone heartBOT
serene moon
#

I don't understand why you would subtract 120 from 180 to get the degrees

#

isnt it just 120?

lone heartBOT
#

@serene moon Has your question been resolved?

alpine sable
#

how to find the percent of markup

lone heartBOT
#

@serene moon Has your question been resolved?

lone heartBOT
#

@serene moon Has your question been resolved?

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unborn jewel
#

Hi

lone heartBOT
unborn jewel
#

I need some help with b

#

How do you represent a ratio as a pper of 2

#

Power of 2*

hollow shale
#

,rotate

ocean sealBOT
hollow shale
#

What is the sequence?

unborn jewel
hollow shale
#

Have you found the n-th term of this sequence?

hollow shale
#

What is the ninth number then?

unborn jewel
#

,rotate

ocean sealBOT
unborn jewel
hollow shale
#

What is the ratio of the first number and the ninth?

unborn jewel
hollow shale
#

(first number)/(ninth number)

unborn jewel
hollow shale
#

And that is equal to 2^(?)

unborn jewel
hollow shale
#

Not quite.

unborn jewel
hollow shale
#

Yes.

#

So the first number is 2*8 times the ninth number.

unborn jewel
#

Oh okay

hollow shale
#

Evaluating that gets you 256

unborn jewel
#

Ty

#

Uh

unborn jewel
hollow shale
#

Express 4096 as a power of 2.

#

Set the ratio of the two numbers to 4096.

#

This is where having the n-th term (and not just a table) comes in handy, since n is just the position, so you can solve directly for it.

lone heartBOT
#

@unborn jewel Has your question been resolved?

lone heartBOT
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violet iron
#

I didn’t really understand chain rule so I don’t understand that

violet iron
#

Can anyone help me and tell me how this is done please

#

I’m in number 1

lone heartBOT
#

@violet iron Has your question been resolved?

alpine sable
#

do you just need to find the derivative?

#

oh i understand the question

#

so let's name 6x-5=u

#

then the derivative of u^4

#

equals 4*u^3

#

then you should multiply this solution with the derivative of u

#

so the derivative of 6x is 6

#

in the first column you should wright 4*(6x-5)^3

#

and in the second (4*(6x-5)^3)*6

#

so it becomes 24*(6x-5)^3

#

let me know if you need some more explanation

violet iron
#

Yeah but with chain rule

#

Hmm let me think and try to understand

#

I didn’t understand the second column part

alpine sable
#

to take the derivative there are some general rules

#

there aint no rule for the first equation

#

but we do recognise u^4

#

of which we do know how to take the derivate

#

so we rewrite 6x-5 as u

#

but ones we've taken the derivative of u^4

#

we still have to take the derivative of u

#

but we know that u is 6x-5

#

so we have to take the derivative of it and that becomes 6

#

which we multiply with the derivative of u^4

lone heartBOT
#

@violet iron Has your question been resolved?

lone heartBOT
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tame moss
#

HELLO

lone heartBOT
tame moss
#

are these proofs any good?

shell widget
#

@tame moss Yes

tame moss
#

THEY ARE?!!?

#

😭

shell widget
#

Yes

tame moss
#

why?

shell widget
#

cause they're correct?

tame moss
#

idk this stuff just doesn't sink in with me

#

im doing something and reciting the steps

#

but i feel like i just still don't understand