#help-0
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A ball is tossed into the air from the roof of a building. Its height, h metres above the ground after t seconds is modeled by the relation
h = -3.5(t – 3)² + 60
What is the height of the building
what have you thought about
Well at first I tried substituting t for 0 and that gave me
h = -3.5(t – 3)² + 60 h = -3.5(-3)² + 60 h = -3.5(-9) +60 h = 31.5 + 60 h = 91.5
I feel like this is wrong
ℝamonov
Oh it's +9
h = -3.5(t – 3)² + 60 h = -3.5(-3)² + 60 h = -3.5(9) +60 h = -31.5 + 60 h = 28.5
This then?
yes
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quick question
what do you call factoring, but into additions instead of multiplications?
for example
a=b+c
not sure how
a=b+c
shows what you're trying to describe
wdym by
into additions instead of multiplications
can you show me examples of what you mean by
factoring into additions and
factoring into multiplications
oh, I think I got it,
I think the word I'm looking for is decomposition
like fourier decomposition
so
what I want is something like this
f(a,b) = g(a) + h(b) + m(a,b)
would you call this decomposition?
@gritty veldt Has your question been resolved?
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That wasn't so hard, was it
...
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Not quite. The slope of the tangent is given by $\dfrac{dy}{dx}$. First write $y = r\sin(\theta) = 2\sin(2\theta)\sin(\theta)$, then find $\dfrac{dy}{d\theta}$. Similarly, find $\dfrac{dx}{d\theta}$. Now apply the chain rule to obtain $\dfrac{dy}{dx}$
1345631
I know it's not the intended method, but you could always multiply both sides by $r^2$, and then get convert to cartesian and then implicit differentiation
azeem321
Oh i see
I.e. $(x^2+y^2)\sqrt{x^2+y^2}=4xy$
So u convert polar to parametric
azeem321
And go from there
@alpine sable Has your question been resolved?
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Hi
isn't their answer wrong?
why did the negative disappear and ln of x change to ln 1/x
$$-\ln{x} = -1 \cdot \ln{x} = \ln{x^{-1}} = \ln{\frac{1}{x}}$$
illuminator3
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Carl has 15 colored balls in his pocket. The balls have three different colors. Carl randomly take the balls out of his pocket. What is then the smallest number of balls that Carl has to pick up to surely get at least one ball of each color?
Information given:
(1) 1/3 of the number of balls are black.
(2) 7 balls are red and 3 balls are blue.
Can we solve this with info 1, info 2, separately, or combined?
(1) B = 15*1/3 = 5
5+X+Y = 15
(2) R = 7, Y = 3, X = 5
=> R+Y+X = 15
I was thinking in information (1), we don't know how many of the balls are of different colors.
Information (2), we know the color of every ball, so the information is sufficient to solve the question.
Any comments?
of course we can solve it in every case, we just get different answers
Please explain how we can solve it with information one only.
The balls have 3 different colors, so there is at least one ball of each color. If he picks up all 15 balls, he clearly has one of each color
Well the answer is that it can only be solved with information (2) alone, (1) is insufficient.
15 isn't necessarily the smallest
What do you mean by ’smallest’?
You think my reasoning was ok?
yes
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Im stuck with these equation (factorization)):
-16t²+48t+488 = 0
I've tried to factorize it
-8(2t²-6t-61)
but i cant find common factor between the three terms
61 is prime
,w -16t^2 +48t +488
i did that

is that the furthest it can be done?
Yes
yes, but it must be with the quad formula , right?
because after that i did:
2t²=0
t²=-2
And the square root of -2
And with the other
-6t = 0
t= 6
and i supposed that 6 was the answer i dont know if im correct
Wth did you do here?
2t^2-6t-61=0 doesn’t mean 2t^2=0, -6t=0 and so on
These are your roots
You need to do is use quadratic formula here
Thats it
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How would I solve for the first five terms? The homework suggests that we need to reach the binomial series using the factoring I did in the beginning. I’m not sure how to account for variable a if I’m not doing the original Taylor series
However if I do use the original taylor series, how would I build out the terms using the original (or the factored version)?
@hallow sparrow Has your question been resolved?
<@&286206848099549185>
Does it say to calculate the Taylor series ? Show the instructions
What you did looks fine. I don't get why you want to use Taylor series
It asks for the first five terms
@tacit arch I'm just confused because I feel like it needs to be in a Taylor form since the center isn't 0.
The professor hinted the factor 3^(1/3) in the beginning
Which makes sense, but to use a binomial series here throws me for a loop
@hallow sparrow Has your question been resolved?
<@&286206848099549185>
@hallow sparrow Replace x by 4x for the first one, for the second you can write it as (1+4x) (1+4x)^(1/3)
you know (1+4x)^(1/3) from the first part, multiply by (1+4x)
ah
I ended up writing out terms using the original taylor series, despite my professor's "hint" to set it up to binomial series form
Because the binomial series form afaik doesn't account for a
I left a comment on the problem asking how to account for it
@hallow sparrow Has your question been resolved?
@hallow sparrow Has your question been resolved?
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Can someone please help me with this, the word cut at the start is “using”
a^(b/c) =cthrootof(a^b) right?
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hello! my question is:
Find the range of values of k if the curve y=kx^2−2x+(2k−1) lies completely above the x−axis.
I don't know where to start in answering this question, thank you!
It is clear that k must be positive (assuming we want a quadratic curve), since otherwise the graph would open negatively
Now what property must the graph have for it to not go below the x-axis?
(And is it sufficient)
@lost briar Has your question been resolved?
hint: ||what kind of roots would it have?||
bigger hint: ||what kind of roots would it have if it never touches the x axis||
biggest hint: ||since your roots are y=(-b±sqrt(b^2-4ac))/2a, for there to be no roots, b^2-4ac must be negative, making your roots imaginary (thus no intersection). plug in your a b and c values and find the k values that make the roots imaginary.||
@lost briar Has your question been resolved?
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Please don't occupy multiple help channels.
Don't open multiple channels
Ok
So close this channel
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Why would adding x *I to a matrix not change the eigenvectors?
work it out. What does it mean to have an eigenvector/value?
Doesn’t change the direction
But does adding xI not change dorection
Ay=λy then (A+xI)y=(λ+x)y
@mystic sinew Has your question been resolved?
I don't think that's obvious
That if Ay=λy then (A+xI)y=(λ+x)y
@mystic sinew Has your question been resolved?
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How do you write in algebraic form
with some variables x, y, z...?
@indigo dock Has your question been resolved?
Not what I mean
Sorry. What do you mean?
@indigo dock Has your question been resolved?
@indigo dock wdym
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What about f(0)
That's part of it yes.
so i found the derivative which ended up to be
3(x+3)(x+1)
critcal values
x=-3 x=-1
The other part is evaluating at the boundaries
so i would have to esstentially guess and check
by plugging in -4, -1 , 0, 3
into the f(x)
f'(x)*
That's not guessing, that's enumerating
nah f(x) itself
sorry f(x)*
would that process be correct
do the critical values not always tell u the ABSOLUTE max/min?
They do not
wait u might need to take the double derivative as well
sorry
then what does a critical number tell u?
when the points change direction
okok
i used desmos and noticed
Wait you need to understand the curve
Umm don’t desmos already bruh
Do you mean point of inflection?
Which option do you want to select
@ocean spindle Has your question been resolved?
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help
Write down the area of the triangle formula using known variables
@alpine sable Has your question been resolved?
no
lmao
mf
there are very unhelpful people and this server is innactive
cuz america is currently asleep
Write down the formula for the area of a triangle
@alpine sable Has your question been resolved?
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small brain moment... why is it b and not a
found the tangent of y=4x-4 not sure what they did after this to obtain (3,8)
What
Why would the tangent be 4x-4
Do you understand the concept of differentiation?
is the tangent rule not y=4x - 4
oh what the answers said it was lol
The derivative is 2x
yes...
How did you get a from y=4x-4
4x - 8 + 4 = 4x - 4
get what sorry
,calc 3*4-4
Result:
8
Result:
0
oh
i didnt even think of that lmao wtf
testing values ahhh i see
thank you fellas
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What’s the name of this topic
I forgot what the | means
But I think it’s just u put 0 into x and becuase of that function ur answer turns positive
Modulus
So ur min val is 1?
AH YEA ty
For that I think we would have to use differentiation
Yeah I think it’s 1
Answer is 59 I suppose
Nah it just asks for what’s the min value u can get right?
Acc ur right
One sec
So to go from x-1 to 119x-1 we have gone 120 times
And if the minimum modulus of each function is 1, then the answer should be 120
Because the lowest real number u can put in to the function to get a low number is x=0
120 was coming as my answer too but exercise sheet says 59 is the answer
Nah
I don’t think differentiating will help
Does the question tell u how many marks it is
Ya
Ya
Is there a way u can differentiate the equation
It wouldn’t make sense tho would it
U would just get 1,2,3 and so on
Yes
I think there’s a different formula maybe but I rly can’t recall bro I’m sorry
Did it work when u differentiated it
Lmk if u work it out because I kinda wanna know 😂😂😂
<@&286206848099549185>
@lime igloo Has your question been resolved?
You said this is an a level question
From what book?
One way to go about this is to use the absolute value inequality $\mid x - a \mid + \mid x - b \mid \ge \mid a - b \mid$
dk.dkn
just type |. \mid wasnt made for that
Alright, I’m used to doing it on a computer where I don’t have that button
\vert is also an option
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Hello
I have a hwfor stats and prob
i get a z score which is -25, and it is abnormally big
<@&286206848099549185>
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✅
@soft cosmos Has your question been resolved?
@soft cosmos Has your question been resolved?
@soft cosmos Has your question been resolved?
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Hi
what have you tried?
consider using the substitution
u = x^3
also don't forget your dx
oh yea
but the point is
i wanna know
how to get rid of the 3x^2
i realised i stuck at every question with the variable behind when it isn't a constant
cuz then i can't simply pull out
and thats what confuses me
@gray isle
go through the whole process of integration by substitution starting with the substitution
u = x^3
i know
go through the whole standard process and it'll become clear
from
u = x^3
find the relation between dx and du
@alpine sable Have you learnt the reverse chain rule?
my teacher said there is no chain rule in integration
reverse
chain rule is everywhere in calculus
u = x^3
du/dx = ?
3x^2
yes
????
and then du = ?
yes...
you have du/dx
What have you actually learnt in integration?
What methods do you know for integrating
$\dv{u}{x} = 3x^2 \implies \dd{u} = , ?$
ℝamonov
i just know we need to reverse the differentiation method
from - *
to + divide
x^3?
i don't seem to understand
this is really basic algebra
like really really basic algebra 1 algebra
yes
Yea I’m not sure he’s manipulated derivatives before
which is present in your original integral
You’ll learn about it soon enough
nah i don't depend on my teacher
lol
also
@gray isle
what about du?
wdym
indicates which variable you are not integrating with respect to
im totally not with you lol
but its okay
:((( maybe the methods we come across are totally diff
@gray isle
look up integration by substitution
IG I NOW KNOW
More resources available at www.misterwootube.com
T HANKS TO MY FAV TEACHER
EDDIE WOO
thanks @gray isle
ughhh my teacher never taught this before
I SWEAR
I sort of always viewed them as separate things before
you're starting with
$$\int \sin(x^3)\cdot 3x^2 \dd{x}$$
using the substitution: $u = \red{x^3}$ leads to $\dd{u} = \blue{3x^2\dd{x}}$
$$\int \sin\underbrace{(\red{x^3})}{u}\cdot \underbrace{\blue{3x^2 \dd{x}}}{\dd{u}}$$
$$\int \sin(u) \dd{u}$$
ℝamonov
which gets you something that you should definitely know how to integrate
@alpine sable Has your question been resolved?
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okay, 88 and 888 are just trial and error right?
we only need 8 8s to get to 1000
but we still don't know how many digits we should put in a row
consider
1000 = 8 * 125
888 = 8 * 111
88 = 8 * 11
8 = 8* 1
have a think about it
hmmm
add the ones
and you'll get 125
888 = 8 * 111
88 = 8 * 11
8 = 8* 1
8 = 8* 1
8 = 8* 1
it still doesn't explain how we know it's 888 + 88 + 8 + 8 + 8 instead of 88 + 88 + 888 + 8 for example
if you think about it properly it will
1000 = 8 * 125
adding a total of 125 8s gets you 1000
888 = 8 * 111
by adding 888 you're effectively adding 111 8s
same idea for the rest
888 = 8 * 111
88 = 8 * 11
8 = 8* 1
8 = 8* 1
8 = 8* 1
how many 8s are you effectively adding by adding
888 + 88 + 8 + 8 + 8
and compare that to
88 + 88 + 888 + 8
125
yes
here why do we stop at 10?
why doesn't he continue adding 1 with nth number of 8s like he did with 40 and 20?
they're getting to the closest multiple of 10
and in this case they must get 10 for the final sum to be 1000
trying the same thing with number 4
and I just realized that if you multiply an even number by 5, you'll get 0 as the last digit of the sum
with 4, I understand that you need 250 4s to get to 1000
but I still don't know how many digits I should put in a row
consider positive integer solutions to
$$111a + 11b + c = 250$$
ℝamonov
for efficiency you'd want a as high as possible
@wet spindle Has your question been resolved?
wait
ok for 8, we need 8 8s to add together
for 4, we need 7 to get to 1000
right?
since
huh?
Did the same with 8
8 8s is needed to get to 1000
tried the same with 4 but I couldn't get an answer
here we have 8 8s
here we have 7 4s
but I couldn't find any other way to get to 250
use more 4s
I only need 7
where's that coming from
here?
just like this right?
i don't see how that leads to the conclusion that you can get to 1000 using 7 4s
set up the addition table properly
the 4 one?
yes
with more than 7 fours?
see what happens when you try and follow their approach
note that i dislike their approach and would recommend that you just use what i set up
the first problem in Gelfand's Algebra and boy is it hard
@wet spindle Has your question been resolved?
yeah I can't solve it
@wet spindle Has your question been resolved?
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what have you done so far
,rotate
don't spoonfeed
@ripe ore Has your question been resolved?
dk.dkn
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It’s telling me this is wrong
I think you forgot to divide both sides by -1
At which point do I do that?
At -x²-6x=-1
Now why do you do that?
I had an earlier problem that I didn’t have to do that
I don’t remember the professor showing us an example like that
Because if you complete the square, it's not going to be correct.
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Hello I am a student who speaks Spanish, but I do not have the help of a teacher due to the economic situation and in my school the teachers cannot help with the homework, perhaps for some this is easy, but it is difficult for me to be able to understand it, geometry has always been a weak point of mine, I have tried to solve it but it is difficult, I don't know if someone could help me with this, I have translated it, I even translate this to be able to communicate, I hope to have your help
<@&286206848099549185>
@orchid path Has your question been resolved?
Yes?
....
is teaching students by professors considered waste of time
since they just repeat same things and same explanations over and over again
do they consider they could spend that time more productively on research and stuff like that, science?
or do they always keep getting something out of teaching students like new ideas, new insights - stuff like that
i mean they do have time for science and everythinb but i am talking about these couple extra hours specifically
Everything is complicated, but do you know how to solve it? In spite of everything, it is a task and if I do not deliver it I will be failed, I do not ask you to solve it, only your help to be able to solve them together
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anyone has tips on how to easily know if it is a one tailed or two tailed test?
A one-tailed test is when you are testing if the population value is less then or greater than the null, but a 2 tailed is when you are testing if the population value is simply different from the null
my teacher said if its finding the paramaters its a two tailed test
is that always correct?
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If we have two independent events in probability (A and B). How do you calculate the smallest value of P[A n B]? Isn't it always 0?
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Sort of an abstract question - I have a scenario where I'm applying k++ means clustering, but I want to define each area of a centroid in the fashion of a square (doesn't necessarily have to be a square, as long as I can get some definable area) - can anyone point me to any literature or definitions that can achieve something like this?
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<@&286206848099549185>
@sour dew Has your question been resolved?
Without really thinking about it that carefully, it just sounds like you are replacing the usual euclidean metric with the taxicab metric. I doubt scikit-learn or anything has that built in so it'd be a bit of work to code yourself.
@sour dew Has your question been resolved?
hm, do you have an example of what the taxicab metric would look like in clustering? how would i get the lengths of the sides for each centroid grouping
is there anyway I can ensure in that each grouping the lengths of the area are identical? even if the areas overlap
I haven't thought enough about the problem to comment further. I would expect you would find very little literature because it will be unpleasant at best.
It looks like the MATLAB statistical toolbox has a cityblock argument: https://www.mathworks.com/help/stats/kmeans.html
This MATLAB function performs k-means clustering to partition the observations of the n-by-p data matrix X into k clusters, and returns an n-by-1 vector (idx) containing cluster indices of each observation.
If you have a license you can just open up the source code and tinker with it
ok thank you
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I apologise, I had a math class. What I meant was how to write algebraic equations in discord e.g. @oak perch usually writes some kind of code and then the bot reads it as an equation, like x/(x+3) except it writes it how you would on paper if you know what I mean. How do you do that?
it's using texit
#resources the last message here
you can use #bots for trying it out
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lmfao you pinged the wrong person
OH my bad xD
oh thanks
Lemme try though I am still unsure
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Is dy/dx the final answer or d/dx?
?
I'm not understanding what the question is sorry? Also what level of maths is this?
Is there a question?
im asking if I should use dy/dx or d/dx for the final answer
is there a difference between the two?
I might be stupid but to me d/dx would imply that there is no y. But I cannot say for sure what you are asking without seeing the original question.
when you differentiate you are using d/dx on both sides. For example, y=x differentiated is d/dx y = d/dx x. You are basically multiplying d/dx by y which is why you have dy/dx iirc
Because you are differentiating with respect to x
So you can either say d/dx (y) = 1 or dy/dx = 1 for y=x
It will probably make more sense when you do implicit differentiation
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Hey there
=> Assume T is invertible. It is thus injective and surjective. Use injectivity to conclude {T(b_1) ,..., T(b_n)} is llinearly indepedent, and use surjectivity to conclude that it also spans W.
<= Assume T sends a basis of V to a basis of W. Conclude from this that dim V = dim W, so T is an isomorphism and thus bijective.
Hope this helps you get started
all the complex numbers z such that z^2 = -5+12i
No thank you.
I need the solution
That's fascinating, but it's quite rude to order people to do your homework.
@round stump this channel is occupied, and also we don't give out answers.
Still, it's rude to order people to do what you want. Phrase your question in a more neutral way, such as "Can someone help me with the question about ...". Just saying "Find all complex .." means you are ordering people to do your work for you.
Math help (AVAILABLE)
^ also that
@alpine sable do not encourage channel stealing.
I write . reopen but nothing changed
it's when someone insists on posting their question in someone else's channel
Ah I see
@round stump you have opened your own channel #help-14 by posting in it
now you wait for someone to come along and help you
ok
I will keep that in mind in the future
I will there
@tawny fable are you still here?
I recognise the question he asked. It is from Linear Algebra done right book lol
Very difficult book in general
@tawny fable Has your question been resolved?
first of all thanks
now for the =>
I am struggling on understanding how can I use the surjective to show it spans W
@bitter vault
We know that for every vector in W there is a vector in V s.t T(v) = w
w in W, and v in V
yeah
don't omit names when introducing things
okay, yes
and what would it mean if {Tb_1, ..., Tb_n} were to span W?
write this out formally too
if span{Tb_1, ..., Tb_n} = W
...not what i wanted tbh
Then alpha_1Tb_1 + alpha_2Tb_2 + ... + alpha_n*Tb_n = 0 iff alpha_1....alpha_n = 0
oh sorry
i wanted "every vector in W is a linear combination of Tb_1, ..., Tb_n"
then every vector in W can be written as a linear combination
But that is all assuming that it spans W
you can never say "a linear combination" on its own
no, we aren't assuming anything.
i'm asking you to translate the statement "span {Tb_1, ..., Tb_n} = W" into something we can work with
and the translation i expected is: $$(\forall w \in W)(\exists c_1, \dots, c_n \in K)(w = c_1Tb_1 + \dots + c_nTb_n)$$
Ann
Yeah ok
I get it
I just don't understand how does that help me with the question
like
ofc it is
assuming towards a contradiction?
Is that the way you are aming for?
@vale wigeon
wait
if {Tb_1,...Tb_n} is LI
- T is surjective
Ok I have one side
T is invertible
thus dimV = dimW
thus that set {Tb_1, ... , Tb_n} is LI with the size of n
thus a basis for W
sorry am in class
in class?
You're a student?
You're like a hundred times better than my teacher
lol
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need some help proving a trig equation
so i have
how do you think you can get tan from sin and cos?
yes
what is it
close, but that's the identity for tan(a+b)
the bottom sign should be +
alright now replace 1 with tan(pi/4)
i think i get it now
yep, got it
theres always litterally 1 step in these question that i dont think about and i lose the entire thingg
anyway, thanks for the help!
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is this correct? i didnt know u could cross multiply addition of fractions
you need to prove 1/1-cosp + 1/1+cosp = 2cosec²p
yes it is correct
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is $(k+1)!(k+1) = (k+2)!$
Ziggy
Try k = 0, does the equality hold?
yes
No, why?
oh no it doesnt
recall the basic definition of the factorial
$(k+1)!(k+2)=(k+2)!$ though by definition
Zanarcane
no, but (k+1)!(k+2) is
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What part of this whole figure is shaded?
What have you tried?
What are the areas of the semicircle and the circle?
What two shapes do-
πr^2/2 and πr^2
is the radius of the circle r?
Are you sure?
r/2
$$A_{semicircle}=\pi r^{2}\times \frac{1}{2}$$
$$A_{semicircle}=\frac{\pi r^{2}}{2}$$
$$A_{circle}=\pi (\frac{r}{2} )^{2}$$
$$A_{circle}=\frac{\pi r^{2}}{4}$$
good, now you can probably solve it
AuHasard
@knotty spire How do I find out how much is shaded now?
Well, you want to find out what part of the semicircle is shaded by the circle.
What would that be?
Do I divide them?
Which by what
The circle divided by the semicircle.
yup
This? $\frac{\frac{\pi r^{2}}{4} }{\frac{\pi r^{2}}{2} } =\frac{2}{4} =\frac{1}{2}$
yes
AuHasard
@hollow shale Is this right?
Yes.
So half of it is shaded?
Yes.
That's why we use math, and don't just eyeball it.
It doesn't look like 1/2, but the numbers don't lie.
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The cleaner Yngwe has 4,000 less in monthly salary than the teacher Arber. Arber has two thirds as much salary as the doctor Chandra. Together, the three have as much in salary as the Member of Parliament Joar, who has 66,900 in monthly salary.
How much does Arber have in monthly salary?
Yngwe gets 4000 less Arber. Arber has 2/3 higher salary with doctor Chandra, right? Or how do I write?
this is what I've got so far, can someone give me more advice?
@normal wing So 2x/3 - 4000 + 2x/3 + x = 66900, right?
correct
$$66900=\frac{2x}{3} -4000+\frac{2x}{3} +x$$
$$66900=\frac{4x}{3} +\frac{3x}{3} -4000$$
$$66900=\frac{7x}{3} -4000$$
$$70900=\frac{7x}{3}$$
$$70900\times 3=\frac{7x}{3} \times 3$$
$$70900\times 3=7x$$
$$30386 ≈ x$$
@normal wing Is that right?
AuHasard
$$\frac{2}{3} \times 30385.7=20257.14$$
AuHasard
@normal wing This is Arber's salary right?
correct
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can somone help me with this
why arent we including 3 and 4
so wont it be like 6x6x6
@kindred wing Has your question been resolved?
Can't get skew-symmetric matrix with those, because there is no -3, -4.
ahhhh ok ok thanks a lot!
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Hi
I don't understand why you would subtract 120 from 180 to get the degrees
isnt it just 120?
@serene moon Has your question been resolved?
how to find the percent of markup
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Hi
I need some help with b
How do you represent a ratio as a pper of 2
Power of 2*
,rotate
What is the sequence?
2^3 , 2^2, 2^1, 2^0
Have you found the n-th term of this sequence?
Mhm
What is the ninth number then?
,rotate
This
What is the ratio of the first number and the ninth?
Wdym ratio
(first number)/(ninth number)
Uh 2^3/2^-5
And that is equal to 2^(?)
Uh 9
Not quite.
8?
Oh okay
Evaluating that gets you 256
How do we calculate the position of a number that is 4096 times bigger than another number
Express 4096 as a power of 2.
Set the ratio of the two numbers to 4096.
This is where having the n-th term (and not just a table) comes in handy, since n is just the position, so you can solve directly for it.
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I didn’t really understand chain rule so I don’t understand that
@violet iron Has your question been resolved?
do you just need to find the derivative?
oh i understand the question
so let's name 6x-5=u
then the derivative of u^4
equals 4*u^3
then you should multiply this solution with the derivative of u
so the derivative of 6x is 6
in the first column you should wright 4*(6x-5)^3
and in the second (4*(6x-5)^3)*6
so it becomes 24*(6x-5)^3
let me know if you need some more explanation
Yeah but with chain rule
Hmm let me think and try to understand
I didn’t understand the second column part
to take the derivative there are some general rules
there aint no rule for the first equation
but we do recognise u^4
of which we do know how to take the derivate
so we rewrite 6x-5 as u
but ones we've taken the derivative of u^4
we still have to take the derivative of u
but we know that u is 6x-5
so we have to take the derivative of it and that becomes 6
which we multiply with the derivative of u^4
The chain rule states that the derivative of f(g(x)) is f'(g(x))g'(x). In other words, it helps us differentiate composite functions. For example, sin(x) is a composite function because it can be constructed as f(g(x)) for f(x)=sin(x) and g(x)=x_. Using the chain rule and the derivatives of sin(x) and x_, we can then find the derivative of s...
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HELLO
@tame moss Yes
Yes
why?
cause they're correct?
