#help-0

1 messages · Page 974 of 1

fringe yoke
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You know how we multiply probabilities together to see what the overall probability of them happening together is?

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So we multiply successes together, but do I always have to multiply the failures as well?

glass lichen
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You mean $P(A\cap B)=P(A)P(B)$?

ocean sealBOT
glass lichen
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that only holds for independent events

fringe yoke
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This is only for indep

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ye

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But

ionic crown
fringe yoke
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When do I also multiply by the failures?

glass lichen
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Not fully sure what you mean

naive valley
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depends what you're trying to compute

fringe yoke
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like getting 2 heads out of 11 throws is: $(11c2)\cdot (0.5)^2 \cdot (0.5)^9$

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why do you also have the failure multiplied into it

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Wait shit

glass lichen
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that's just how the distribution is defined?

naive valley
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yes because you're looking for a very specific sequence of successes and failures

ocean sealBOT
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Tim O'Brien

naive valley
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2 heads AND 9 failures

fringe yoke
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Yeah

naive valley
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versus say P(2 heads in the first two tosses) without caring about what happens in the other 9

fringe yoke
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Ohhh

fringe yoke
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We are looking specifically at 11 throws

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So we consider everything that can happen

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If that was unbounded the probability of getting 2 heads consecutively would be 1/4 right ?

glass lichen
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If $X\sim \operatorname{Bin}(n,p)$, then $P(X=x)=\binom{n}{x}p^x(1-p)^{n-x}$

ocean sealBOT
fringe yoke
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Right

glass lichen
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Binomial distributions are fundamentally a sequence of independent bernoulli trials, so each flip is either a success or a fail, so you need to account for every action in the sequence of n trials

fringe yoke
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Yeah I drew it out on a tree and this makes sense

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What happens if I send n to infinity?

glass lichen
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to which the nCx is just accounting for the permutations of the x successes

fringe yoke
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Yeah

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So if we weren't looking at a specific n, then the probability of getting 2 heads after any consecutive coinflips would be 1/4 right?

glass lichen
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yes

fringe yoke
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Because then the distribution isn't binomial (we don't know n)

glass lichen
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though n would be 2 there

fringe yoke
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Oh

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well

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yeah

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XD

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lol

glass lichen
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cause you're asking "Out of 2 flips, P(both heads)"

fringe yoke
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Yea

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(2 2) 0.5^2 (0.5)^(2-2) = 1/4

glass lichen
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If you wanted say "What's the probability I get my 3rd head on my 8th flip?", that wouldn't be binomial

fringe yoke
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hmm

glass lichen
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That'd be NegBin iirc

fringe yoke
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rly?

glass lichen
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Yeah

fringe yoke
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they are independent and p is fixed and we also have an n

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that's weird

glass lichen
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Binomial counts the number of successes in a given n-long string of indep. Bernoullis

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NegBin will tell you P(xth head on the Nth flip)

lone heartBOT
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@fringe yoke Has your question been resolved?

fringe yoke
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I will ask my teacher about that one tomorrow, thanks again for your help Mosh

lone heartBOT
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cinder sundial
lone heartBOT
cinder sundial
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Those two equation Are the same

severe sluice
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how did you get here?

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explain your reasoning please

cinder sundial
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Those two (-a/r) cancel out each other

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Like x/x=1

severe sluice
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yep!

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so you get....

cinder sundial
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God

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I see the problem

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It’s a/b on the right side

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It’s solved

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.close

lone heartBOT
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keen mulch
lone heartBOT
keen mulch
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9a please

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And also 6B

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<@&286206848099549185>

wary stream
lone heartBOT
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@keen mulch Has your question been resolved?

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spice lark
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how do you find who

lone heartBOT
spice lark
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h=90
w=43
o=47
t=20

wary stream
spice lark
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my bad

wary stream
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Apply supplementary angles concept to find WHO

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You know what that symbol at MHO means, right?

spice lark
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can you by chance use dummy terms

wary stream
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That symbol means it's perpendicular. Do you know what that means?

spice lark
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I’m bad at math but I’m not like dumb dumb

wary stream
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I mean, supplementary is a commonly used geometry term, and you stated that you didn't know what it meant, so I wanted to make sure if you knew what perpendicular meant

spice lark
wary stream
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Almost

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Supplementary angles is when two angles add up to 180 degrees

spice lark
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yeah that one

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can you just help me with it
i forgot how to get it
i know its something to do with subtracting 180 from numbers

wary stream
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WHO + MHO = 180

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That's your hint

spice lark
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i feel dumb

spice lark
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wait no

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ah its 100

wary stream
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Not exactly

spice lark
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alright lets see

wary stream
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Remember when I asked what that symbol at MHO was?

spice lark
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90+43+47

spice lark
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90 degrees

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its not 4 is it

spice lark
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am i right

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for mho

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h = 90
and o = 47

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180-137

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what does mho have to do with anything

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you got me confused

wary stream
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You were asking how to find WHO

spice lark
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yes

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is it 4

wary stream
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And I was saying WHO + MHO = 180 because supplementary angles

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You know the angle at MHO because it's perpendicular

spice lark
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133 is my final guess

wary stream
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If MHO is perpendicular, what is that angle?

spice lark
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which angle

wary stream
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MHO

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That angle

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What is the angle value of MHO?

spice lark
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does that mean you add all 3

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now im lost

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i dont like triangle theorem

wary stream
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So you are asking how to find the angle for WHO, which I drew in orange. That black line, which I'm calling MHO, is given because of that perpendicular symbol. That blue line I drew is supplementary, meaning two angles added equals 180. If that is supplementary, then WHO + MHO = 180

spice lark
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dang your dedicated

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if your meaning to tell me its been 90 this whole time

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i feel dumb

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it is 90 right

wary stream
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Yes, the value for WHO is 90

spice lark
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OH MY GOSH THANK YOU

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.close

lone heartBOT
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wary stream
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Now you have WHO, you can find t

spice lark
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t = 20

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5t-10=90

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90+10=100/5 = 20

lone heartBOT
#
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lone heartBOT
spice lark
#

.close

lone heartBOT
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wary stream
lone heartBOT
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pale arch
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okay where do i even begin with this

lone heartBOT
pale arch
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i know how to divide a polynomial but

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is it asking me to divide the one top by the long ass one on the bottom??? ive just gotten started with dividing by stuff like x + 2 or whatever

small horizon
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The idea of added integer carries over pretty much the same now that you have a squared term and a linear term

pale arch
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shit
im just gonna write out the long division
ill be back if i cant figure out wtf im doing

small horizon
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If I’m interpreting what the question is asking for correctly

pale arch
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dumb question but if you divide a number w x squared by a number w x squared do the sqaured x's cancel out

small horizon
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You mean like this right:

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$ \frac{wx^2}{wx^2}$

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ack my latex is shoddy

pale arch
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like uh
20x^2 divided by 4x^2 is just 5

small horizon
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Yes

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What you might consider an extension of that is polynomial long division in algebra 2

pale arch
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i feel like i have done something wrong o_o
the assignment im doing usually has like. pre-laid out boxes for the long division questions but for this question it didnt have those.....

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urgh
my professor frustrates me sometimes
hes a nice guy but the homework will sometimes have questions on stuff we havent covered yet

small horizon
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Don’t forget it’s -4 at the end but yes you have the right idea

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I think what they then want is the binomial remainder in the second box

pale arch
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oh shoot u right
lemme just. send a pic of the question rq

small horizon
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It’s above

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I see it already

pale arch
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no i mean on the computer

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OOPS

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im a dummy LOL sorry

small horizon
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Does your software let you try answers multiple times

pale arch
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yup

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how in the world do i divide -27x by 5x^2
i dunno if its gonna allow decimals or fractions

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negative 5.4 times the square root of x...?

small horizon
pale arch
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ohhh! lemme try that then!

small horizon
# pale arch ohhh! lemme try that then!

When polynomials don’t divide perfectly, we can put the result of an integer (the ideal quotient based on the highest degree terms’ coefficients) and a remainder polynomial divided by the same divisor polynomial

pale arch
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i typed in -27x + 3 and it said wrong
ouch

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hmm

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wait hold on rq

small horizon
pale arch
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nope
lets see

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3 and -4 have no x right?

small horizon
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Yes

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Because the whole point of the Q term is to be an integer

pale arch
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wrong again :-(

small horizon
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Can you send pic again?

pale arch
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and uhh

small horizon
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LOL

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You have to put the remainder polynomial in the second box!

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You can’t leave it blank

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only the -4 goes in the first box

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And you need to specify the power of x on 27

pale arch
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ok the -4 was right
but i put -27x + 3 in the second one and it says wrong

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also im still strugglingg a little to understand where u got the -4

small horizon
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Because 5 goes into -20 -4 times

pale arch
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ah right!

small horizon
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You can’t divide the remaining terms properly which is why we need to partition this remainder polynomial fraction off

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Can you send a picture of what you put in the box?

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Software could be finicky with formatting

pale arch
small horizon
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OH

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Mb lol

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Here’s the formal way to get the right remainder:

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Take your OG polynomial dividend

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And subtract off -4 times the divisor

pale arch
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kk

small horizon
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$-20x^2 -11x -1 - , -4(5x^2 + 4x - 1)$

ocean sealBOT
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giratinalawyer

small horizon
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= 5x - 5

pale arch
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omg yay! u got it right, tysm!
its probably gonna be a while til i really get it, but still ty

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.close

lone heartBOT
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pale arch
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aw crap another one

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.reopen

lone heartBOT
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pale arch
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lets see here

small horizon
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It was just a signs issue, which is usually the easiest hurdle conceptually to figure out

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It boils down to finding the largest integer multiple of the largest degree in the divisor that goes into the dividend, then subtracting out that multiple of the divisor from the dividend and getting the remainder polynomial

pale arch
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i see!
xcubed divided by xsquared is uhhh just x right

small horizon
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Consider factoring out the x’s separately then cancelling

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$\frac{x x x}{xx} = x$

ocean sealBOT
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giratinalawyer

pale arch
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ah!

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im gonna try that thing you just did

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$\frac{xx}{xx} = x$

ocean sealBOT
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selkiesHiraeth

pale arch
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my dog keeps trying to play with me. noo sorry go away!

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hmm. where do i go from here...?
do i add the -6x to -13x?

small horizon
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There shouldn’t be an X on that in the first place

pale arch
umbral citrus
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i think that the -6x is supposed to be positive

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and ur also saying that 2x x 4x^2 is 8x^2

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and thats how u get

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that second -6x

pale arch
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oh shoot youre right
whoops. gotta go fix that
hold on rq

umbral citrus
pale arch
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okay i fixed it
but now im left with this
do i just bring down the 6x - 9?

umbral citrus
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get rid of these too

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and then u get -x-3

pale arch
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hm. isnt 8x^2 divided by 4x^2 equal 2x? thats what the little umm. program thing i typed here told me

umbral citrus
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when ur dividing w exponents u subtract

pale arch
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ohh!

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thank you!

umbral citrus
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when u did 8x^3/4x^2 u got 2x(^1) bc 3-2=1

umbral citrus
pale arch
#

.close

lone heartBOT
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hollow axle
#

Find the Jacobian matrix of the function f : R3→ R2 defined as f(x,y,z) = (x+y+z, xyz) and evaluate it at (2,1,3).

hollow axle
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Suppose a computer program has an error in it. To detect the error, the programmer conducts a series of independent tests. The probability of a random test detecting an error is 0.10. Find the expected number of tests required to detect the error.

lone heartBOT
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@hollow axle Has your question been resolved?

sly mantle
#

@hollow axle pls use 1 channel, and post what u tried

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@hollow axle Has your question been resolved?

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raw fractal
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What angle are you referring to?

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Uh, can you draw a brief sketch?

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Because I don't understand which angle you mean, but it should be findable.

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Angle between the parabola and the horizontal?

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Ah, OK, you can use calculus to find this.

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Lemme draw a sketch real quick. One sec.

sudden hinge
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slope triangle seems like a good idea @alpine sable

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you can make it really small ;)

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infinitesimally small, so to speak

raw fractal
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So, let f(x) be the equation of the parabola. Then, the slope of the parabola at a is its derivative at a, f'(a).

sudden hinge
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and then think about what the derivative means again with respect to the slope triangle

raw fractal
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Yeah, so $\tan \theta = f'(a)/1$, so $\theta = \arctan f'(a)$.

ocean sealBOT
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PhenomPlasma

raw fractal
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Nah.

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Hopefully that's the right angle you wanted.

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Nice!

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Yep.

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alpine sable
#

what did i do wrong

lone heartBOT
rigid smelt
#

for the first ibp, which did you pick for u and which did you pick for dv?

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@alpine sable Has your question been resolved?

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alpine sable
#

Trying to differentiate* the following:
f(x) = x^3 -3x +1

I got x = sqrt(1)

But after looking online, people seem to have different answers. Am I doing something wrong?

alpine sable
silver adder
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use power rule

alpine sable
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I did

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3x^2 -3

silver adder
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how

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ok and then

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ur done

alpine sable
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well

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going further

silver adder
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it has been differentiated

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no

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why

alpine sable
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3(x^2 -1) = 0
x^2 -1 = 0

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im doing min max values

silver adder
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ok sure

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find the critical values

alpine sable
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so the critical value would be 1?

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right

silver adder
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x^2 - 1 = 0 has 2 roots

alpine sable
#

sqrt1

alpine sable
silver adder
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x^2 = 1

alpine sable
#

-> sqrt(1)?

silver adder
#

,w plot x^2 - 1 = 0

alpine sable
#

oh

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.close

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cold arch
#

A triangular prism is 37 inches long and has a triangular face with a base of 42 inches and a height of 28 inches. The other two sides of the triangle are each 35 inches. What is the surface area of the triangular prism?

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@cold arch Has your question been resolved?

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white ferry
#

Discrete Math Proof. Is anyone able to help me work through this example?

white ferry
#

For instance a list of all the things I need to prove to prove the whole proof?

spark creek
white ferry
#

Like I can follow the question and example. But lets say I just got given the question. whats the first thing I should be doing. I need to prove left side is a subset of right side and right side is a subset of left side for them to be =, is there anything else I need to be thinking?

spark creek
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For questions like these you can either prove the left side to the right side or you can solve both sides up till the point they are equal

white ferry
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which have they done in the example? This is quite confusing for me sorry, this is the second example of a proof they have shown me.

spark creek
white ferry
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im actually being asked in the work book to write this proof

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obviously the answer is there but struggling to put the steps together without seeing the answer I guess

spark creek
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So AU(BUC) is a set
and assuming x belongs to this set
So x can either belong to Set A or the union of Set B and C
So the first case they take is to assume x to be in A
And solve ahead

Second case they take is to assume x to be in the union

The second case has 2 sub cases:
x can belong to B
x can belong to C
And they solve from there

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Sorry if I'm not clear, I'm finding it a bit tough to concisely explain the working here

white ferry
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im reading through now thanks

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ok so what am I solving in each step? that x can be in A then B and then C?

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the last line here. How can we know its a subset of the right hand side

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I mean I know it is, its all joined by unions, so if x is in any of them it has to be in the right hand side.

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are we assuming that is true?

spark creek
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A basic overview of the solution is proving lhs is a subset of rhs and then proving RHS is a subset of LHS
This is only possible if both sides are exactly equal

white ferry
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yep I understand that much. I dont know why I need to show x in A B and C

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if x in A then its also in RHS

spark creek
white ferry
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Yeh I just dont know how to figure out the steps

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like trigger in my head ok for this I need to prove X in A B and C for LHS for example

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What is the give away that thats what i need to do here?

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am I always trying to do stuff to the LHS to make it written the same as the RHS?

spark creek
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So you usually for set questions you can start with assuming an element to be in a set and then going ahead from there
Frankly speaking it depends from question to question

spark creek
white ferry
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ok thanks ill keep working on it.

spark creek
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Lmk if you have any other doubts

white ferry
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thanks

cold depot
#

I don't like how that solution just jumped to (A∪B)∪C. A more detailed proof should say that if an element's a member of a set, it's also a member of any set that's a superset of that set, and that the union of set X and set Y is a superset of set X.

spark creek
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Since they already proved LHS to be a subset of RHS, they went on to RHS to prove the same thing
I get what you're saying but I guess some things are implied here so that the solution doesn't become unnecessarily complex

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normal night
#

How am I supposed to notice this?

lone heartBOT
alpine sable
normal night
#

This is better.

#

My problem is not with a specific case scenario.

#

I just cannot see these things.

#

I don't notice them. I don't get how I am supposed to notice them. I keep making mistakes because I derail and try to solve questions other ways.

alpine sable
#

What would the question be ?

normal night
#

In that last image the question was.

silver adder
#

its noticeable that both 24 and 8 are divisible by 8

normal night
#

I don't notice it.

alpine sable
#

Just put an equality and solve it

#

24y-8 = 8(3y-1)

#

and solve the right side

silver adder
normal night
#

The question was that if (24y-8)=29 what is 3y-1.

normal night
#

I know that 8*3 is 24. I used that in the question before this one. So I know that to heart.

#

I still couldn't see it.

alpine sable
#

If 3y-1 is 8 times less than 24y-8 what would 29 be in the 3y-1 case?

normal night
#

I don't know.

alpine sable
#

Oke so

#

24y-8 = 29 which we know

#

we also know that 24y-8 = 8 * (3y-1)

#

right ?

normal night
#

Yes you divide it.

silver adder
normal night
#

I don't know that 24y-8 = 8*(3y-1)

alpine sable
#

The text mentions that 24y-8 is 8 times 3y -1, so they are the same

normal night
#

Cause I didn't notice it.

normal night
#

It is step one.

#

And I failed at it.

#

I got 21/75 as an answer instead.

alpine sable
#

Ahhh

#

Now I understand what you mean

normal night
#

I don't have problems with the actual solving part.

#

I just cannot see or notice that 24y-8 is 8 times 3y-1

#

I just don't get it.

#

I never notice these and fail on every question that relies on me noticing it.

alpine sable
#

Oke so do you know how prime numbers work ?

normal night
#

I do know how prime numbers work.

alpine sable
#

oke so which numbers are involved in creating 24 ?

normal night
#

What does that have to do with anything?

normal night
#

If you multiply them.

#

20+4

#

Infinite amount of answers to that question.

alpine sable
#

8 is not prime tho

normal night
#

What does that have to do with 24.

alpine sable
#

you want to simply 24y-8 to 3y-1

normal night
#

What

alpine sable
#

Seeing that 24 can be divided by 8 to create 3 is a big part

normal night
#

I cannot see it

#

I just don't

#

I want to know how to.

#

From what I can get it is magic.

silver adder
#

you know that 8*3 = 24 and 8*1 = 8

normal night
#

Yes.

#

But I cannot notice it in a question.

#

I do not understand how I would even notice that

silver adder
#

do you know that 8*3 = 24 also means 24 = 8*3

normal night
#

That's the same equality

#

written backwards

silver adder
#

what are the factors of 24?

normal night
#

8 and 3

silver adder
#

theres more factors than that

normal night
#

But i can only say that

normal night
#

I don't get how I am supposed to work back

#

my brain cannot do it

#

Is it natural to you?

#

Cause I cannot.

#

I'd have to run through the whole table to get the factors

silver adder
#

yeah cus i know all the factors

normal night
#

Am i supposed to memorize the factors of 24?

#

An all numbers

#

thats an impossible task

#

I have an exam in 2 months

silver adder
#

i recall that 24 = 1*24 = 2*12 = 3*8 = 4*6

normal night
#

I cannot recall that

#

On the spot

#

at all

#

how am i supposed to do that

#

I know 2 times 12 is 24

#

but i cannot tell you that 24's factors are 2 and 12

#

or 4 or 6

#

but if you asked me the other way around i would say 24

#

i don't get how this is supposed to work

alpine sable
#

Can you tell how many times you can divide 24 by 2 untill its not longer possible ?

normal night
#

here is another one

alpine sable
#

by 2

normal night
#

technically

#

oh by 2

#

well i can now

alpine sable
#

how many times can you divide it by 2 and not create a decimal number

normal night
#

cause i said what it was earler

#

12

alpine sable
#

no

#

like now what it equals

normal night
#

what?

#

it's 12

alpine sable
#

i am asking how many times you can divide it by 2 and create a number that does not have a decimal

normal night
#

oh

alpine sable
#

so 24/2 = 12

#

that is once

#

but you can do 12/2 = 6

#

so twice

normal night
#

3

alpine sable
#

exactly and what is left ?

normal night
#

3 is left

alpine sable
#

yes so now you can see the building blocks to create 24

#

3 times a 2 and once a 3

normal night
#

i do not see it

alpine sable
#

so

#

2 * 2 * 2 * 3

normal night
#

how is that helpful

alpine sable
#

Those are building blocks

#

you can use them

#

to create all factors

normal night
#

thats cool

alpine sable
#

so if you do 2 * 2 *2 = 8

#

you have 8 * 3 = 24

normal night
#

this doesn't help my problem

#

this has nothing to do with the problem i have

#

you want me to do this everytime i see a number?

alpine sable
#

You cant solve your problem if you dont see this

normal night
#

run through all the possible factors

#

one by one

#

to see if it is that way

#

i have a minute per question

#

this is impossible to do

#

i have only one brain

alpine sable
#

how many seconds did it take you to see the building block for 24

normal night
#

i don't know

#

i don't see it

#

to begin with

#

i didn't see it

#

i did not see that 24 is 8 times 3

#

i just dont see it

#

when i look at 24

#

i don't think

#

"that is 8 times 3"

#

it never comes to my mind

#

if i do it methodically it never works cause it takes too long

#

and i still have all the other stuff in the question to solve

#

i think you are missing the point here

#

i do not see the factors of 24 when i look at it

#

i just don't

#

i cannot do it

#

it never comes to my mind to check the factors

#

so i'd need to check it everywhere to make sure i wasn't missing them

#

from how no one seems to understand the problem i am having to begin with

#

i guess i am just disbled

#

well there goes my dreams then

#

i like math

#

but i cannot do anything with it appeantly

#

becusae of magic

#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

this is the answer for the question: the price of a shirt increased by 17.8 percent. the original price is 49.9

#

but why is it not just 49.9*0.178

lone heartBOT
#

@alpine sable Has your question been resolved?

ocean sealBOT
alpine sable
#

thats what i said too

#

but 58.78-49.9=8.88

#

i keep getting that too

alpine sable
lone heartBOT
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lone heartBOT
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cosmic oasis
#

What are the steps from Z_t to dZ_t?

lone heartBOT
#
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cosmic oasis
#

Huh

lone heartBOT
cosmic oasis
#

Bot glitched I guess

pale kestrel
lone heartBOT
#

@cosmic oasis Has your question been resolved?

lone heartBOT
#

@cosmic oasis Has your question been resolved?

cosmic oasis
#

.CLOSE

#

.close

lone heartBOT
#
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errant dagger
#

how do you

lone heartBOT
errant dagger
#

prove

#

nvm

#

!close

#

.close

lone heartBOT
#
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stoic barn
#

what type of techniques are used to find meromorphic extensions of functions?
I have some type of zetaish looking holomorphic function on Re(s) > 1 that also sums reciprocals to the power of s. except instead of reciprocals of natural numbers I have reciprocals of a certain sequence of complex numbers whose absolute value grows with roughly Kn + O(log(n)) (absolute value of the nth term). There are apart from that some other information about the argument of the terms but I won't go into much detail for now.

I've tried using the argument principle to get an integral representation of the sum, but didn't really get anywhere.

I've also tried to somehow adapt the approach they presented on wikipedia of the functional equation for the riemann zeta functions, but I didn't find a way to generalise it as the behaviour of my sequence isn't as clean as the sequence of natural numbers. They're all transcendental numbers in general and I can only give asymptotic approximations of where the terms of the sequence actually are.

lone heartBOT
#

@stoic barn Has your question been resolved?

lone heartBOT
#

@stoic barn Has your question been resolved?

stoic barn
#

<@&286206848099549185>

brittle sequoia
#

<@&286206848099549185> someone should help this guy

untold pier
#

i would if I could

#

maybe he should ask into advanced math

#

like here?

lone heartBOT
#

@stoic barn Has your question been resolved?

lone heartBOT
#
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gleaming terrace
#

help pls

lone heartBOT
alpine sable
#

do you know how to complete the square?

gleaming terrace
#

yes

lone heartBOT
#

@gleaming terrace Has your question been resolved?

gleaming terrace
#

<@&286206848099549185>

tacit arch
gleaming terrace
#

what do i do next

tacit arch
gleaming terrace
#

i did

tacit arch
#

what help do you need with next

gleaming terrace
#

idk what to do after completing the square

tacit arch
#

for part (i)

gleaming terrace
tacit arch
#

,rotate

ocean sealBOT
tacit arch
#

did you find a and b here?

gleaming terrace
#

no

tacit arch
gleaming terrace
#

i completed the square of 7-2x²-12x

gleaming terrace
#

the link doesnt work

tacit arch
#

put into your search engine: khan Parabola focus directrix review

gleaming terrace
#

i read it idk what it means

lone heartBOT
#

@gleaming terrace Has your question been resolved?

#
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kindred talon
#

I'm a bit confused on how to solve this problem on my hw, can I get some guidance please?
I know for a it's x[f'(x)]+x'f(x), but do I just plug in the values like x[3]+x'(5) so maybe 8?

lone heartBOT
#

@kindred talon Has your question been resolved?

kindred talon
#

<@&286206848099549185> 🙂

lone heartBOT
#

@kindred talon Has your question been resolved?

lone heartBOT
#
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edgy sand
lone heartBOT
edgy sand
#

I have the formulas for these but not sure on how to use them

knotty spire
#

Well what are they

edgy sand
#

these right?

knotty spire
#

Alright, so what do we know from the task

edgy sand
#

well i was going to start by finding chance in x

#

but unsure how to do that

knotty spire
#

well what are the bounds of our integration

edgy sand
#

oh is it b-a/N?

#

2 and 0

knotty spire
#

for equal width, yes

edgy sand
#

Okay so 2-0/4?

#

would that give us change in x?

knotty spire
#

Well, Delta_x isn't really the change in variable here, rather it is the width of an interval we take

#

but yes

edgy sand
#

okay so lets start with the left sumn then

#

I would have LN= 1/2 3sigma j=0(2+j(1/2)) ?

knotty spire
#

for your a

#

As you have written it right now, your bounds would be from 2 to 4

edgy sand
#

oh our a is 0?

knotty spire
#

Yep

#

$L_N = \frac{1}{2} \sum_{j=0}^{3} f(0+\frac{j}{2})$

ocean sealBOT
#

Remavas

knotty spire
#

Now you can evaluate this. This is a simple finite sum.

edgy sand
#

can i punch this into my calculator?

knotty spire
#

Yep

#

after substituting in f(x) = x^3 of course

edgy sand
#

wait you substituted f(0+j/2) ?

knotty spire
#

what I mean by that is insert the actual formula for the function f

#

instead of writing f(...)

#

$L_N = \frac{1}{2} \sum_{j=0}^{3} \frac{j^3}{2^3}$

ocean sealBOT
#

Remavas

edgy sand
#

you got x^3 from the original problem right?

knotty spire
#

mhm

#

I will use my wolfram superpowers instead

#

,w \frac{1}{2} \sum{j=0}^{3} \frac{j^3}{2^3}

edgy sand
#

i got 9/4

ocean sealBOT
knotty spire
#

,w 1/2 * the sum from j=0 to 3 of j^3 / 2^3

edgy sand
#

ez asf

knotty spire
#

correct

edgy sand
#

okay so right side is same process except the different values above and below the sigma right

knotty spire
#

yes

edgy sand
#

okay and lastly, how would I find the integral of this ?

knotty spire
#

$\int_0^2 x^3 \dd x$

edgy sand
#

I know with impropers where there is a inf at top or bottom i can do limit

ocean sealBOT
#

Remavas

knotty spire
#

well

#

how much do you know about definite integrals

#

I presume you already encountered the fundamental theorem of calculus

edgy sand
#

yes

knotty spire
#

$\int_0^2 x^3 \dd x = \frac{x^4}{4} \rvert_0^2 = 4 - 0 = 4$

ocean sealBOT
#

Remavas

knotty spire
#

Just apply the power rule to find the antiderivative

#

then apply the fundamental theorem of calculus

edgy sand
#

wait tahts it??

#

ezzz asfff

#

thanks for your help boss

knotty spire
#

Once you have the theoretical groundwork, yes, it is pretty easy

edgy sand
#

.close

lone heartBOT
#
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gray heart
#

How am i supposed to know if my angle should be larger than 90 when using arcsin?

tacit arch
gray heart
gray heart
#

but for angle b i got 83.5

#

then i learned i had to subtract it from 180 because the real answer was larger than 90

#

but if i never knew the real answer, how am i supposed to know if i should subtract from 180 or not?

tacit arch
gray heart
tacit arch
#

,calc sin(33 deg) * 27

ocean sealBOT
#

Result:

14.705253945406
tacit arch
#

,calc sin(33 deg) * 27 / 14.8

ocean sealBOT
#

Result:

0.99359823955444
alpine sable
#

help plz

tacit arch
#

,calc asin(sin(33 deg) * 27 / 14.8) * 180 / pi

ocean sealBOT
#

Result:

83.513367413633
gray heart
#

uh im confused

tacit arch
ocean sealBOT
#

riemann

gray heart
#

but the teacher always tells us we can’t assume angle measurements relative to other angles

#

i’ll have to ask her again

#

.close

lone heartBOT
#
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fallen rain
#

can someone give me some tips about this question?

lone heartBOT
#

@fallen rain Has your question been resolved?

fallen rain
#

@tacit arch

tacit arch
fallen rain
tacit arch
fallen rain
#

<@&286206848099549185>

#

........ okay

#

never mind

#

!close

#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

what is the X E R?

#

I forgor 💀

pine kettle
#

what math class are you in

alpine sable
#

gr 12

#

advanced functions

tacit arch
#

draw a sign chart

alpine sable
#

a sign chart?

tacit arch
alpine sable
#

i look that up and only thing I see is zodiac signs

alpine sable
#

what does the xer stand for?

#

is X the x intercepts?

prime badge
#

all numbers

#

cept complex

alpine sable
#

so all the real number in X?

alpine sable
#

was there a reason for the test numbers?

tacit arch
tacit arch
# alpine sable

this asks for values where the left side is negative or zero

alpine sable
#

idk why this is confusing

#

so do I have to show my work?

#

of the test values?

tacit arch
alpine sable
#

ok thank you

#

.close

lone heartBOT
#
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wet tusk
lone heartBOT
wet tusk
#

did i do this right?

tacit arch
#

Yes

wet tusk
tacit arch
wet tusk
#

^ this??

tacit arch
#

Ok a few mistakes going on

tacit arch
# wet tusk

You invented a 2 when substituting the definition of V(3x)

tacit arch
#

So either the formula is wrong or your algebra is wrong

wet tusk
#

ok this should be good now

lone heartBOT
#

@wet tusk Has your question been resolved?

#
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tribal geyser
#

Can anyone help with 24)b pls

lone heartBOT
#

@tribal geyser Has your question been resolved?

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#
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cinder sundial
lone heartBOT
cinder sundial
#

Is there anything I did wrong

#

The answer should be -1 tho

open folio
cinder sundial
open folio
cinder sundial
#

Yes but I have double checked it before

#

Couldn’t see to find the error myself

open folio
#

Huh....

cinder sundial
#

Here’s the solution on the book

open folio
#

Book might be wrong, unless that original equation is different than the one you solved

cinder sundial
#

Could you put it into sth like wolfram

#

Cuz I don’t know how to put trig on calculator

lone heartBOT
#

@cinder sundial Has your question been resolved?

silver adder
#

,calc cos(270 degrees)tan(180 degrees)cot(180 degrees)/(sin(90 degrees)tan(540 degrees))

ocean sealBOT
#

Result:

0.5
silver adder
#

wack

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daring kindle
lone heartBOT
daring kindle
#

What does $(g \circ f)(X)$ denote and how is it different from $g(f(X))$?

ocean sealBOT
glass lichen
#

they're the same thing

daring kindle
#

I am confused why wouldn't they just write it as the same thing?

glass lichen
#

Notation's like that

daring kindle
#

alright lol thanks for the help

#

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distant granite
#

I have a question on how to solve this problem

distant granite
trim plinth
#

what is the 70.4 made of

#

tip: rewrite 70.4 as a known angle and an unknown

distant granite
#

👌

trim plinth
#

try

#

I'm not allowed to type an answer for you

distant granite
#

Alr

undone chasm
distant granite
#

I think that hood enough either way I figured it out

#

But Ty

undone chasm
#

ok

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distant granite
#

.close

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teal frigate
#

Hey guys does the order of a cross produtter ? aka a X b vs b X a? if so, why?

lone heartBOT
#

@teal frigate Has your question been resolved?

tacit arch
#

produtter
huh?

lone heartBOT
#

@teal frigate Has your question been resolved?

tight locust
#

yes

#

the cross product is special though.

#

it's sort of like subtraction

#

(a-b) = -(b-a)

#

(a x b) = -(b x a)

#

we call this property "anticommutativity"

#

it is "anticommutative"

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stone scroll
lone heartBOT
stone scroll
#

My answer is -3/5 but my calculator says it's 0

#

Am I right?

tacit arch
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@stone scroll Has your question been resolved?

stone scroll
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steel turret
#

hello

lone heartBOT
steel turret
#

how to turn into number?

#

wat steos?

#

steps

bright hedge
#

is 216 a power of 6? if so, what is that power? that is your answer

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#

@steel turret Has your question been resolved?

steel turret
#

6^3

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glass vale
lone heartBOT
glass vale
#

Trying to use structural induction to prove part a.

#

This is what I have so far, but not too sure where to go from here.

#

Any thoughts?

tight locust
#

Make a "tree"

#

After applying the recursion the first time you have 2 new elements of S

glass vale
tight locust
#

Yes!

glass vale
tight locust
#

You tell me!

#

We are trying to prove that all members of S are even

#

Tbh i don't see why you need induction

glass vale
#

And we start at 2 because 2 is the only number in the set initially right?

tight locust
#

It is as simple as saying that the square of an even number is even and that twice an even number is even

#

And because the only number we start with is even then all members of the set must be even

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#

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autumn lantern
#

hi! what's meant by the set of integers $\mathbb{Z}_7^2$?

ocean sealBOT
#

richard

autumn lantern
#

what elements does the set have? sorry i am not familiar with the notation

tight locust
#

Z_n means integers mod n

#

not sure what the superscript means

autumn lantern
#

same that's what I'm having problems with haha

merry depot
#

it means $\bZ_7\times \bZ_7$

ocean sealBOT
#

Zybikron

merry depot
#

the same way $\bR^2 = \bR\times \bR$

ocean sealBOT
#

Zybikron

autumn lantern
#

Ohhhh got this, thank you so much!

#

.close

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split vector
lone heartBOT
split vector
#

how do u find c

merry depot
#

are you given some kind of initial condition or anything?

split vector
#

is c=0?

#

nope

#

thats all that was given

merry depot
#

I don't know if you're supposed to find a number for C or just state what it represents

#

without some numbers to work with, I don't know if you can find an actual quantity for C

split vector
#

yeah thats why im a bit confused

merry depot
#

i think they mean to just state what C represents in the equation

#

in a horribly worded sort of way

lone heartBOT
#

@split vector Has your question been resolved?

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visual plinth
#

$$\int_{\large sin^2(t)cos(t)dt}^{}$$

lone heartBOT
ocean sealBOT
visual plinth
#

What is method should I use to integrate this

spark creek
#

Substitution

visual plinth
#

is there a clear substitution here ?

lone heartBOT
#

@visual plinth Has your question been resolved?

spark creek
#

Yes

#

Sin(t)=x

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distant kestrel
lone heartBOT
distant kestrel
#

Hi can someone help me please with number one

#

All the extra information i know is that BPO is 90 degrees

spark creek
#

Use the fact that OA and OP are the radii of the circle

distant kestrel
#

OH RIGHT

#

THANK YOU

#

.close

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strange fractal
#

0

lone heartBOT
strange fractal
#

Can someone help? why is it 1,1?

feral sluice
#

definition of x intercept is the x value of where the value "intercepts" the x axis, which is when y = 0

#

and vice versa for the y intercept

#

so check the table for what x is equal to at y= 0

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stone scroll
lone heartBOT
stone scroll
#

The only discontinuous point is zero, right?

#

-2 and 2 are not included

winged rock
#

Looks like it

stone scroll
#

Thanks!

#

.close

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split cloud
lone heartBOT
split cloud
#

this is the answer

#

idfk how

rigid smelt
#

have you heard of conjugates?

split cloud
#

no

#

spanish?

#

jk..

#

but no

rigid smelt
#

actually nvm, that's just going to make it look worse

#

anyway, in order to get rid of that square root, what do you think we can do?

split cloud
#

what i did first was

#

add sqrt x-1 to the 1

#

moved it

#

then i sqaured both

#

leaving 2x-5=x+2 sqroot x-1

#

x-5=2sqrtx-1

rigid smelt
#

yeah looks good

split cloud
#

it does?

rigid smelt
#

yep

split cloud
#

but how do i get that answer

rigid smelt
#

well just continue what you did

#

you have another square root

split cloud
#

square root?

rigid smelt
#

so what can you do to get rid of that square root?

split cloud
#

thats what i did but i got a non factorable standard form

#

square both sides

rigid smelt
#

show me what you got after squaring both side

split cloud
#

ok 1s

#

x^2-10x+25=4x-4

rigid smelt
#

yep, thats great

split cloud
#

make =0?