#help-0
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So we multiply successes together, but do I always have to multiply the failures as well?
You mean $P(A\cap B)=P(A)P(B)$?
Mosh
that only holds for independent events
When do I also multiply by the failures?
Not fully sure what you mean
depends what you're trying to compute
like getting 2 heads out of 11 throws is: $(11c2)\cdot (0.5)^2 \cdot (0.5)^9$
why do you also have the failure multiplied into it
Wait shit
that's just how the distribution is defined?
yes because you're looking for a very specific sequence of successes and failures
Tim O'Brien
2 heads AND 9 failures
Yeah
versus say P(2 heads in the first two tosses) without caring about what happens in the other 9
Ohhh
Yeah
We are looking specifically at 11 throws
So we consider everything that can happen
If that was unbounded the probability of getting 2 heads consecutively would be 1/4 right ?
If $X\sim \operatorname{Bin}(n,p)$, then $P(X=x)=\binom{n}{x}p^x(1-p)^{n-x}$
Mosh
Right
Binomial distributions are fundamentally a sequence of independent bernoulli trials, so each flip is either a success or a fail, so you need to account for every action in the sequence of n trials
Yeah I drew it out on a tree and this makes sense
What happens if I send n to infinity?
to which the nCx is just accounting for the permutations of the x successes
Yeah
So if we weren't looking at a specific n, then the probability of getting 2 heads after any consecutive coinflips would be 1/4 right?
yes
Because then the distribution isn't binomial (we don't know n)
though n would be 2 there
cause you're asking "Out of 2 flips, P(both heads)"
If you wanted say "What's the probability I get my 3rd head on my 8th flip?", that wouldn't be binomial
hmm
That'd be NegBin iirc
rly?
Yeah
Binomial counts the number of successes in a given n-long string of indep. Bernoullis
NegBin will tell you P(xth head on the Nth flip)
@fringe yoke Has your question been resolved?
Interesting
I will ask my teacher about that one tomorrow, thanks again for your help Mosh
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Those two equation Are the same
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Looks like a job for the physics server, linked in #old-network
@keen mulch Has your question been resolved?
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how do you find who
h=90
w=43
o=47
t=20
These values don't match the image you sent
Apply supplementary angles concept to find WHO
You know what that symbol at MHO means, right?
can you by chance use dummy terms
no
That symbol means it's perpendicular. Do you know what that means?
I’m bad at math but I’m not like dumb dumb
I mean, supplementary is a commonly used geometry term, and you stated that you didn't know what it meant, so I wanted to make sure if you knew what perpendicular meant
supplementary is a type of line/angle
yeah that one
can you just help me with it
i forgot how to get it
i know its something to do with subtracting 180 from numbers
I THOUGHT YOU MEANT A MATH TERM
i feel dumb
Not exactly
alright lets see
Remember when I asked what that symbol at MHO was?
90+43+47
yeah its a right angle
90 degrees
its not 4 is it
= 176 180-176 = 4
am i right
for mho
h = 90
and o = 47
180-137
what does mho have to do with anything
you got me confused
You were asking how to find WHO
And I was saying WHO + MHO = 180 because supplementary angles
You know the angle at MHO because it's perpendicular
133 is my final guess
If MHO is perpendicular, what is that angle?
which angle
So you are asking how to find the angle for WHO, which I drew in orange. That black line, which I'm calling MHO, is given because of that perpendicular symbol. That blue line I drew is supplementary, meaning two angles added equals 180. If that is supplementary, then WHO + MHO = 180
dang your dedicated
if your meaning to tell me its been 90 this whole time
i feel dumb
it is 90 right
Yes, the value for WHO is 90
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Now you have WHO, you can find t
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Yes
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okay where do i even begin with this
i know how to divide a polynomial but
is it asking me to divide the one top by the long ass one on the bottom??? ive just gotten started with dividing by stuff like x + 2 or whatever
Yes; It’s just a trinomial now
The idea of added integer carries over pretty much the same now that you have a squared term and a linear term
shit
im just gonna write out the long division
ill be back if i cant figure out wtf im doing
Yes. Not that fortunately the coefficient of the x^2 term in the denominator divides the coefficient in the numerator, so you will have a -4, it’s just a question of what the remainder is
If I’m interpreting what the question is asking for correctly
dumb question but if you divide a number w x squared by a number w x squared do the sqaured x's cancel out
Yes
You mean like this right:
$ \frac{wx^2}{wx^2}$
ack my latex is shoddy
like uh
20x^2 divided by 4x^2 is just 5
Yes
What you might consider an extension of that is polynomial long division in algebra 2
i feel like i have done something wrong o_o
the assignment im doing usually has like. pre-laid out boxes for the long division questions but for this question it didnt have those.....
urgh
my professor frustrates me sometimes
hes a nice guy but the homework will sometimes have questions on stuff we havent covered yet
Don’t forget it’s -4 at the end but yes you have the right idea
I think what they then want is the binomial remainder in the second box
oh shoot u right
lemme just. send a pic of the question rq
Does your software let you try answers multiple times
yup
how in the world do i divide -27x by 5x^2
i dunno if its gonna allow decimals or fractions
negative 5.4 times the square root of x...?
This is the point of the remainder r(x) expression
See this
ohhh! lemme try that then!
When polynomials don’t divide perfectly, we can put the result of an integer (the ideal quotient based on the highest degree terms’ coefficients) and a remainder polynomial divided by the same divisor polynomial
Did you put -4 in too
wrong again :-(
Can you send pic again?
LOL
You have to put the remainder polynomial in the second box!
You can’t leave it blank
only the -4 goes in the first box
And you need to specify the power of x on 27
ok the -4 was right
but i put -27x + 3 in the second one and it says wrong
also im still strugglingg a little to understand where u got the -4
You divided the polynomials and got -4
Because 5 goes into -20 -4 times
ah right!
You can’t divide the remaining terms properly which is why we need to partition this remainder polynomial fraction off
Can you send a picture of what you put in the box?
Software could be finicky with formatting
OH
Mb lol
Here’s the formal way to get the right remainder:
Take your OG polynomial dividend
And subtract off -4 times the divisor
kk
$-20x^2 -11x -1 - , -4(5x^2 + 4x - 1)$
giratinalawyer
= 5x - 5
omg yay! u got it right, tysm!
its probably gonna be a while til i really get it, but still ty
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✅
lets see here
It was just a signs issue, which is usually the easiest hurdle conceptually to figure out
It boils down to finding the largest integer multiple of the largest degree in the divisor that goes into the dividend, then subtracting out that multiple of the divisor from the dividend and getting the remainder polynomial
i see!
xcubed divided by xsquared is uhhh just x right
Yes
Consider factoring out the x’s separately then cancelling
$\frac{x x x}{xx} = x$
giratinalawyer
selkiesHiraeth
my dog keeps trying to play with me. noo sorry go away!
hmm. where do i go from here...?
do i add the -6x to -13x?
Zoom out
There shouldn’t be an X on that in the first place
i think that the -6x is supposed to be positive
and ur also saying that 2x x 4x^2 is 8x^2
and thats how u get
that second -6x
oh shoot youre right
whoops. gotta go fix that
hold on rq
which us also supposed to be postivie
okay i fixed it
but now im left with this
do i just bring down the 6x - 9?
hm. isnt 8x^2 divided by 4x^2 equal 2x? thats what the little umm. program thing i typed here told me
when ur dividing w exponents u subtract
when u did 8x^3/4x^2 u got 2x(^1) bc 3-2=1
yw
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Find the Jacobian matrix of the function f : R3→ R2 defined as f(x,y,z) = (x+y+z, xyz) and evaluate it at (2,1,3).
Suppose a computer program has an error in it. To detect the error, the programmer conducts a series of independent tests. The probability of a random test detecting an error is 0.10. Find the expected number of tests required to detect the error.
@hollow axle Has your question been resolved?
@hollow axle pls use 1 channel, and post what u tried
@hollow axle Has your question been resolved?
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What angle are you referring to?
Uh, can you draw a brief sketch?
Because I don't understand which angle you mean, but it should be findable.
Angle between the parabola and the horizontal?
Ah, OK, you can use calculus to find this.
Lemme draw a sketch real quick. One sec.
slope triangle seems like a good idea @alpine sable
you can make it really small ;)
infinitesimally small, so to speak
So, let f(x) be the equation of the parabola. Then, the slope of the parabola at a is its derivative at a, f'(a).
and then think about what the derivative means again with respect to the slope triangle
Yeah, so $\tan \theta = f'(a)/1$, so $\theta = \arctan f'(a)$.
PhenomPlasma
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what did i do wrong
for the first ibp, which did you pick for u and which did you pick for dv?
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Trying to differentiate* the following:
f(x) = x^3 -3x +1
I got x = sqrt(1)
But after looking online, people seem to have different answers. Am I doing something wrong?
you mean differentiate?
yea sorry
use power rule
x^2 - 1 = 0 has 2 roots
sqrt1
could you expand on that
x^2 = 1
-> sqrt(1)?
,w plot x^2 - 1 = 0
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A triangular prism is 37 inches long and has a triangular face with a base of 42 inches and a height of 28 inches. The other two sides of the triangle are each 35 inches. What is the surface area of the triangular prism?
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Discrete Math Proof. Is anyone able to help me work through this example?
For instance a list of all the things I need to prove to prove the whole proof?
I'm not sure what your question is, you want a explanation of the solution or something else?
Like I can follow the question and example. But lets say I just got given the question. whats the first thing I should be doing. I need to prove left side is a subset of right side and right side is a subset of left side for them to be =, is there anything else I need to be thinking?
For questions like these you can either prove the left side to the right side or you can solve both sides up till the point they are equal
which have they done in the example? This is quite confusing for me sorry, this is the second example of a proof they have shown me.
This question specifically is an identity so you might not be asked to prove this but instead more convoluted questions will be asked and you'll need to reduce them to this identity or something else
im actually being asked in the work book to write this proof
obviously the answer is there but struggling to put the steps together without seeing the answer I guess
So AU(BUC) is a set
and assuming x belongs to this set
So x can either belong to Set A or the union of Set B and C
So the first case they take is to assume x to be in A
And solve ahead
Second case they take is to assume x to be in the union
The second case has 2 sub cases:
x can belong to B
x can belong to C
And they solve from there
Sorry if I'm not clear, I'm finding it a bit tough to concisely explain the working here
im reading through now thanks
ok so what am I solving in each step? that x can be in A then B and then C?
the last line here. How can we know its a subset of the right hand side
I mean I know it is, its all joined by unions, so if x is in any of them it has to be in the right hand side.
are we assuming that is true?
Yup
A basic overview of the solution is proving lhs is a subset of rhs and then proving RHS is a subset of LHS
This is only possible if both sides are exactly equal
yep I understand that much. I dont know why I need to show x in A B and C
if x in A then its also in RHS
You're right but it is what it is lol, if it's asked in your assignment then you gotta go through the whole proof even it's extremely straight forward
Yeh I just dont know how to figure out the steps
like trigger in my head ok for this I need to prove X in A B and C for LHS for example
What is the give away that thats what i need to do here?
am I always trying to do stuff to the LHS to make it written the same as the RHS?
So you usually for set questions you can start with assuming an element to be in a set and then going ahead from there
Frankly speaking it depends from question to question
Yup, either this or solving both sides independently up to the point they're equal to each other
ok thanks ill keep working on it.
Lmk if you have any other doubts
thanks
I don't like how that solution just jumped to (A∪B)∪C. A more detailed proof should say that if an element's a member of a set, it's also a member of any set that's a superset of that set, and that the union of set X and set Y is a superset of set X.
Since they already proved LHS to be a subset of RHS, they went on to RHS to prove the same thing
I get what you're saying but I guess some things are implied here so that the solution doesn't become unnecessarily complex
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How am I supposed to notice this?
Could you provide more context ?
Wait that's the wrong image.
This is better.
My problem is not with a specific case scenario.
I just cannot see these things.
I don't notice them. I don't get how I am supposed to notice them. I keep making mistakes because I derail and try to solve questions other ways.
What would the question be ?
In that last image the question was.
its noticeable that both 24 and 8 are divisible by 8
I don't notice it.
do you know the multiplication table?
The question was that if (24y-8)=29 what is 3y-1.
I had issues learning it as a child. I did go through it with Anki and am much better at it now.
I know that 8*3 is 24. I used that in the question before this one. So I know that to heart.
I still couldn't see it.
If 3y-1 is 8 times less than 24y-8 what would 29 be in the 3y-1 case?
I don't know.
Yes you divide it.
he doesn't know that immediately
I don't know that 24y-8 = 8*(3y-1)
The text mentions that 24y-8 is 8 times 3y -1, so they are the same
Cause I didn't notice it.
No the text I sent is the explanation for the question.
It is step one.
And I failed at it.
I got 21/75 as an answer instead.
I don't have problems with the actual solving part.
I just cannot see or notice that 24y-8 is 8 times 3y-1
I just don't get it.
I never notice these and fail on every question that relies on me noticing it.
Oke so do you know how prime numbers work ?
I do know how prime numbers work.
oke so which numbers are involved in creating 24 ?
What does that have to do with anything?
8 and 3
If you multiply them.
20+4
Infinite amount of answers to that question.
8 is not prime tho
What does that have to do with 24.
you want to simply 24y-8 to 3y-1
What
Seeing that 24 can be divided by 8 to create 3 is a big part
I cannot see it
I just don't
I want to know how to.
From what I can get it is magic.
you know that 8*3 = 24 and 8*1 = 8
Yes.
But I cannot notice it in a question.
I do not understand how I would even notice that
do you know that 8*3 = 24 also means 24 = 8*3
what are the factors of 24?
8 and 3
theres more factors than that
But i can only say that
Yeah
I don't get how I am supposed to work back
my brain cannot do it
Is it natural to you?
Cause I cannot.
I'd have to run through the whole table to get the factors
yeah cus i know all the factors
Am i supposed to memorize the factors of 24?
An all numbers
thats an impossible task
I have an exam in 2 months
i recall that 24 = 1*24 = 2*12 = 3*8 = 4*6
I cannot recall that
On the spot
at all
how am i supposed to do that
I know 2 times 12 is 24
but i cannot tell you that 24's factors are 2 and 12
or 4 or 6
but if you asked me the other way around i would say 24
i don't get how this is supposed to work
Can you tell how many times you can divide 24 by 2 untill its not longer possible ?
24
infinitly
by 2
how many times can you divide it by 2 and not create a decimal number
i am asking how many times you can divide it by 2 and create a number that does not have a decimal
oh
3
exactly and what is left ?
3 is left
i do not see it
how is that helpful
thats cool
this doesn't help my problem
this has nothing to do with the problem i have
you want me to do this everytime i see a number?
You cant solve your problem if you dont see this
run through all the possible factors
one by one
to see if it is that way
i have a minute per question
this is impossible to do
i have only one brain
how many seconds did it take you to see the building block for 24
i don't know
i don't see it
to begin with
i didn't see it
i did not see that 24 is 8 times 3
i just dont see it
when i look at 24
i don't think
"that is 8 times 3"
it never comes to my mind
if i do it methodically it never works cause it takes too long
and i still have all the other stuff in the question to solve
i think you are missing the point here
i do not see the factors of 24 when i look at it
i just don't
i cannot do it
it never comes to my mind to check the factors
so i'd need to check it everywhere to make sure i wasn't missing them
from how no one seems to understand the problem i am having to begin with
i guess i am just disbled
well there goes my dreams then
i like math
but i cannot do anything with it appeantly
becusae of magic
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this is the answer for the question: the price of a shirt increased by 17.8 percent. the original price is 49.9
but why is it not just 49.9*0.178
@alpine sable Has your question been resolved?
Osi
no clue why this is the answser
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Huh
Bot glitched I guess
.
@cosmic oasis Has your question been resolved?
@cosmic oasis Has your question been resolved?
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how do you
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what type of techniques are used to find meromorphic extensions of functions?
I have some type of zetaish looking holomorphic function on Re(s) > 1 that also sums reciprocals to the power of s. except instead of reciprocals of natural numbers I have reciprocals of a certain sequence of complex numbers whose absolute value grows with roughly Kn + O(log(n)) (absolute value of the nth term). There are apart from that some other information about the argument of the terms but I won't go into much detail for now.
I've tried using the argument principle to get an integral representation of the sum, but didn't really get anywhere.
I've also tried to somehow adapt the approach they presented on wikipedia of the functional equation for the riemann zeta functions, but I didn't find a way to generalise it as the behaviour of my sequence isn't as clean as the sequence of natural numbers. They're all transcendental numbers in general and I can only give asymptotic approximations of where the terms of the sequence actually are.
@stoic barn Has your question been resolved?
@stoic barn Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185> someone should help this guy
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help pls
do you know how to complete the square?
yes
@gleaming terrace Has your question been resolved?
<@&286206848099549185>
jelly already told you a hint. complete the square
what do i do next
complete. the. square
i did
what help do you need with next
idk what to do after completing the square
show your completed square
for part (i)
,rotate
did you find a and b here?
no
where did this come from then
i completed the square of 7-2x²-12x
read that and try again
the link doesnt work
put into your search engine: khan Parabola focus directrix review
i read it idk what it means
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I'm a bit confused on how to solve this problem on my hw, can I get some guidance please?
I know for a it's x[f'(x)]+x'f(x), but do I just plug in the values like x[3]+x'(5) so maybe 8?
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<@&286206848099549185> 🙂
@kindred talon Has your question been resolved?
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I have the formulas for these but not sure on how to use them
Well what are they
Alright, so what do we know from the task
well what are the bounds of our integration
for equal width, yes
Well, Delta_x isn't really the change in variable here, rather it is the width of an interval we take
but yes
okay so lets start with the left sumn then
I would have LN= 1/2 3sigma j=0(2+j(1/2)) ?
why 2
for your a
As you have written it right now, your bounds would be from 2 to 4
oh our a is 0?
Remavas
Now you can evaluate this. This is a simple finite sum.
can i punch this into my calculator?
wait you substituted f(0+j/2) ?
what I mean by that is insert the actual formula for the function f
instead of writing f(...)
$L_N = \frac{1}{2} \sum_{j=0}^{3} \frac{j^3}{2^3}$
Remavas
you got x^3 from the original problem right?
mhm
I will use my wolfram superpowers instead
,w \frac{1}{2} \sum{j=0}^{3} \frac{j^3}{2^3}
i got 9/4
Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online
,w 1/2 * the sum from j=0 to 3 of j^3 / 2^3
ez asf
correct
okay so right side is same process except the different values above and below the sigma right
yes
okay and lastly, how would I find the integral of this ?
$\int_0^2 x^3 \dd x$
I know with impropers where there is a inf at top or bottom i can do limit
Remavas
well
how much do you know about definite integrals
I presume you already encountered the fundamental theorem of calculus
yes
$\int_0^2 x^3 \dd x = \frac{x^4}{4} \rvert_0^2 = 4 - 0 = 4$
Remavas
Just apply the power rule to find the antiderivative
then apply the fundamental theorem of calculus
Once you have the theoretical groundwork, yes, it is pretty easy
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How am i supposed to know if my angle should be larger than 90 when using arcsin?
what problem are you trying to solve?
i already know the answer
but for angle b i got 83.5
then i learned i had to subtract it from 180 because the real answer was larger than 90
but if i never knew the real answer, how am i supposed to know if i should subtract from 180 or not?
how did you get 83.5
,calc sin(33 deg) * 27
Result:
14.705253945406
,calc sin(33 deg) * 27 / 14.8
Result:
0.99359823955444
help plz
this channel's occupied. read #❓how-to-get-help
,calc asin(sin(33 deg) * 27 / 14.8) * 180 / pi
Result:
83.513367413633
uh im confused
So your confusion arises because $\sin(x) = \sin(180 - x)$. I think in this case, you're supposed to be able to tell from the diagram that angle $B$ is larger than 90 degrees.
riemann
i guess that makes sense
but the teacher always tells us we can’t assume angle measurements relative to other angles
i’ll have to ask her again
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can someone give me some tips about this question?
@fallen rain Has your question been resolved?
@tacit arch
don't ping me
...can you help me with this question please?
.
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what math class are you in
draw a sign chart
a sign chart?
i look that up and only thing I see is zodiac signs
so all the real number in X?
do Example 3.8.1
was there a reason for the test numbers?
For each test value, 𝑣 , determine if 𝑓(𝑣) is positive or negative and record the result on the sign chart for each region.
this asks for values where the left side is negative or zero
maybe watch a video
https://www.youtube.com/watch?v=Fd5ys4PQ-aM
This precalculus video tutorial provides a basic introduction into solving polynomial inequalities using a sign chart on a number line and expressing the solution as an inequality and using interval notation. You need to know how to factor polynomials and how to factor using synthetic division. This video contains plenty of examples and practi...
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did i do this right?
Yes
shouldnt it be 9x^3 - x^2
No
You lost a 9 being multiplied by x^2
So either the formula is wrong or your algebra is wrong
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Can anyone help with 24)b pls
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Negative/Negative = Positive
Yes but the correct answer is -1
Then I would assume you made an error?
Book might be wrong, unless that original equation is different than the one you solved
Could you put it into sth like wolfram
Cuz I don’t know how to put trig on calculator
@cinder sundial Has your question been resolved?
,calc cos(270 degrees)tan(180 degrees)cot(180 degrees)/(sin(90 degrees)tan(540 degrees))
Result:
0.5
wack
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What does $(g \circ f)(X)$ denote and how is it different from $g(f(X))$?
Bread
they're the same thing
I am confused why wouldn't they just write it as the same thing?
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I have a question on how to solve this problem
👌
Alr
the angle 70.4 is split into two smaller angles, what are they
ok
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Hey guys does the order of a cross produtter ? aka a X b vs b X a? if so, why?
@teal frigate Has your question been resolved?
produtter
huh?
@teal frigate Has your question been resolved?
yes
the cross product is special though.
it's sort of like subtraction
(a-b) = -(b-a)
(a x b) = -(b x a)
we call this property "anticommutativity"
it is "anticommutative"
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Are you inputting it into your calculator correctly
@stone scroll Has your question been resolved?
Nice, I found the problem HAHAHA thanks
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hello
is 216 a power of 6? if so, what is that power? that is your answer
@steel turret Has your question been resolved?
6^3
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Trying to use structural induction to prove part a.
This is what I have so far, but not too sure where to go from here.
Any thoughts?
Make a "tree"
After applying the recursion the first time you have 2 new elements of S
Like this?
Yes!
So from the tree, what exactly am I trying to find?
You tell me!
We are trying to prove that all members of S are even
Tbh i don't see why you need induction
And we start at 2 because 2 is the only number in the set initially right?
It is as simple as saying that the square of an even number is even and that twice an even number is even
And because the only number we start with is even then all members of the set must be even
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hi! what's meant by the set of integers $\mathbb{Z}_7^2$?
richard
what elements does the set have? sorry i am not familiar with the notation
same that's what I'm having problems with haha
it means $\bZ_7\times \bZ_7$
Zybikron
the same way $\bR^2 = \bR\times \bR$
Zybikron
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how do u find c
are you given some kind of initial condition or anything?
I don't know if you're supposed to find a number for C or just state what it represents
without some numbers to work with, I don't know if you can find an actual quantity for C
yeah thats why im a bit confused
i think they mean to just state what C represents in the equation
in a horribly worded sort of way
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$$\int_{\large sin^2(t)cos(t)dt}^{}$$
kenzo
What is method should I use to integrate this
Substitution
is there a clear substitution here ?
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Hi can someone help me please with number one
All the extra information i know is that BPO is 90 degrees
Use the fact that OA and OP are the radii of the circle
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0
Can someone help? why is it 1,1?
definition of x intercept is the x value of where the value "intercepts" the x axis, which is when y = 0
and vice versa for the y intercept
so check the table for what x is equal to at y= 0
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Looks like it
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have you heard of conjugates?
actually nvm, that's just going to make it look worse
anyway, in order to get rid of that square root, what do you think we can do?
what i did first was
add sqrt x-1 to the 1
moved it
then i sqaured both
leaving 2x-5=x+2 sqroot x-1
x-5=2sqrtx-1
yeah looks good
it does?
yep
but how do i get that answer
square root?
so what can you do to get rid of that square root?
show me what you got after squaring both side
yep, thats great
make =0?
