#help-0
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Okay, let me recollect here
d(1/x) is not 1/h for any particular value h. d(1/x) is how much 1/x changes when you give it a little nudge, a nudge of dx for instance
So, you could think of it like 1/(x+dx)-1/x
the little change in 1/x when dx gets really small is what we call d(1/x)
right
But yes, the main point is that if dx is really small, if the variation is truly tiny, that rectangle in the top-right becomes very small
negligibly so
So you're only left with the green and red rectangles
sorry, got confused myself for a second
Before dx was added, the red area was there but not the green one
After dx is added, ie the green area is added, that red rectangle is no longer there
What 3b1b is saying, is that (neglecting the top-right rectangle), what you gained in one place must have been reflected in the other one
i.e the areas of the two rectangles must be the same
did you get to the end where he tells you to come up with d(1/x)/dx?
well, the end of the section of the video
it's been a hot minute since i watched this
I understand the concept of what is happening here. What I don't understand is how the fuck you're supposed to come up with d(1/x)/dx using this image.
uhhhhh
ahh, see I don't even know
I can write out in words what a derivative is
he gives you the width and the height, who cares if it's symbolic, the formula you learned in whatever-th grade still applies
is it a trick question?
are you telling me that d(1/x)/dx is the area of the red/green rectangle?
the red rectangle is d(1/x)/dx.
what is the formula for area of a rectangle
what is the width of the red rectangle
correct
what's the height
d(1/x)
yes
so area is?
it's signed
oops
height is d(1/x) but remember this is a negative area
keep that in mind
i guess it's technically -d(1/x) huh
yeah it is
I'm stuck
this is not a trick question
you know the width
you know the height
put them next to each other
that's the area
can you tell me what the area is
x * d(1/x)
correct
remember it's negative
-x * d(1/x)
actually correct
dx * 1/x
right
what do you know about these two areas?
they're equal
yes
write that and solve
so solve for d(1/x)/dx
if it helps you can show your work and we can point out what's wrong
I see it
so...
the issue I guess
was that I was trying to simplify the problem by substituting
but I was substituting something that wasn't equivalent
I'm still stuck on why that is exactly
what did you substitute
I substituted d(1/x) for 1/h

what is h
f(x)=1/x, so if you wanted f(h), sure, that's 1/h
h is dx
but as systems already said
if dx is 0.01, 1/dx is 100
by writing d(1/x)=1/dx, you are telling me that when i go to the right by 0.01, 1/x increases by 100
it's a really simple formula
unfortunately it's wrong
the only answer my brain can come up with is that you can't put dx as x in d(1/x) because the function doesn't behave the same at every point. To get an accurate representation of how the function would behave at x+dx, that's what you have to plug in.
I can't tell if I'm lost at this point because I am that stupid or because I've subconsciously given up
d(1/x)=dy, dy != 1/dx
what is the ! for?
does not equal
so why do you think it does
I don't anymore

d(1/x) is (1/x+h) - (1/x) right?
if I stop thinking about the diagram it makes a shitload more sense
h being an infinitely small number
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A hypothesis test using 95 percent confidence has a significance level equal to
What do your notes say a significance level is?
@fringe dome Has your question been resolved?
Do what Buxy suggested
@fringe dome Has your question been resolved?
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In this function. I have found the secant slope which I believe to be 2 but what about the tangent slope?
How should I think
Do you know how to take a derivative?
yes and in this case it would be 3x^2 - 2
Yes. Do you know what the derivative represents?
The derivative is the slope of the tangent line at some x value
I should put them in the formula
What x value is the line tangent to on the graph?
So plug 1 in to the derivative
its 1
That's the slope
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Closed due to the original message being deleted
I can get to the answer unprofrofessionally
But whats the actual method ur supposed to use to get as high marks as possible
to solve for x?
Yea to get the value of x
distributive property
2(x+y) = 2x +2y
each term in the bracket is multiplied by 2
Whats the bracked
No need to distribute, tbh
Im not familiar with these english terms
Ah i figured
so 2(6 + x²) would become...?
Oh lol
FYI distribution is an extra, not needed step
ya that is true
i mean he said this tho
Is it needed to get an A on the question
Actual method is just solving for x
You don't need to do extra steps
As long as you solve for x, that's all you need
Mhm
And how would u do that
The way i did it was just that i knew that x² had to be 9
Therefore i knew the answer was 3
But how do you get to it profesionally or whatever
The proper term is algebraically
Also the answer is supposedly +-3
Alright
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Could you figure this out in your head?
I wanna understand if I'm slow because I had to use pen and paper and manipulate that equation a bunch of times until I found it
Is there a quick way to figure it out?
I can't lol
You have to use systems of equations
system of equation and it's done
I just wanted to make sure if I was dumb
I don't think there is a short cut unless it's super obvious
the values aren't so obvious tho so we cant find it in our head
I always have this feeling like I'm too slow or something
But it's probably just in my head lol
maths is dumb
wouldn't it be (6/(x^2))^(x)?
Well, with all those roles
haha

Would you tell me your thought process tho?
well not really
^ pretty much that, since your graph doesn't appear to go negative, you will have x^(even) somewhere
b = 2 or -2
then C = -3 or 3
but since the graph increases
positive values I guess
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can someone tell me why this happens?
Distributive property
thank you so much
You can easily prove this geometrically
Let me demonstrate with a rectangular argument:
This is fundamental

Now you know
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of paper money: the 17 Yacley bill and the 5 Yacley bill. How many different combinations
of these bills total 453 Yacley?```
I don't know how to approach this question
Casework
Start with one 17 Yacley bill, see if 453-17*1 is a multiple of 5, then move on to 2 Yacley bills, etc.
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My name is chad, I've been shooting hoops since I was 5 and I got 17 peoples lunch money today, 7 had 8 dollers and 6 had 3 dollars and 4 had 12 dollars, how do I figure out how much lunch money I have?
<@&286206848099549185>
Don't ping right away.
How old are you?
17
High schools don't have recess
Also that is very much, bar the stupidity of how it's written, an elementary age question
Just use a calculator and stop making a fool of yourself
I failed my maths gcse
Saturday recess?!
That too 
$0 You cant shoot hoops.
@shadow bloom Has your question been resolved?
not to mention i'm pretty sure it's damn near midnight in Britain
It is
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hello !(solving problems involving radicals)
A woman walks 5 kilometers to the east going to school and then bikes 9 kilometers northward going to church. How far is she from the church to the starting point which is her house?
Have you drawn it out?
yes i actually have a solution already-
my solution:
c= √9^2 + 5^2
c= √81+25
c= √106
c= 106km
is this correct ??
it feels weird bc my final answer is a pretty big number-
sqrt(106) sounds right
dldh06
idk either i just followed a yt video 🧍♂️
oh
I'm pretty sure that video didn't make it disappear
here's the vid-
Maybe if it was a squared number, like $c = \sqrt{81}$
dldh06
That's when it can disappear because sqrt of 81 is 9
do u guys mind telling me how to properly solve for it then? So i would know next time
because sqrt(100) = 10
Sqrt(106) is a valid answer
You just need to know when it's a square number
Like 106 is not a square number
But 100 is
≈10.29563km
Eh, decimals aren't exact though
yeah, which is why i used ≈
but often times teachers just want the answer like that
at least that from my experience
okay so which part of my solution was wrong- and how do i correct it?
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this is review, is this correct?
Hey nerds
.close
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Im being asked to prove that the theory of an F-space is complete (where F is a specific infinite field). But the trivial vector space is a vector space over the reals... a complete theory with an infinite model can't have any finite models. So, why isnt that a counterexample?
try an advanced channel
How do I get permission to chat in those?
thanks
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how do i solve this using shell method
would the radius be r=x-1
that is the book work not mine
this is different from what i normally do since the about x=1 is touching the equatoion
Have you drawn the region to start...?
yes
So, like riemann said, show your work...
and your work..?
that is all because i dont know how to approach it
the textbook never show this kind of example
i already serch thru and far cant find anything
professor suck really bad at teaching
In this chapter we will take a look at some applications of integrals. We will look at Average Function Value, Area Between Curves, Volume (both solids of revolution and other solids) and Work.
No, cause I really doubt you actually googled "shell method examples"
Shell Method is using cylinders...
i know but this one in particular is making go insane
The resource I linked has examples w/ cylinders.
yes but they dont have it with it rotating in the in the shaded area
do u get what im saying
no
you can just ignore the part of the region to the left
so radius is just x
Radius, as shuri told you already, is a difference of functions of y..
than it would be r=4x-x^2-1
@worthy adder Has your question been resolved?
How would you know from the problem whether it's the region to the left or right?
Edit: nvm I see. It's not that we're ignoring the left part, it just gets swallowed by the right part during the rotation, right?
I would shade in on your graph
the relevant region
thats being rotated
Identify the closed region.
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Is this arrow means psi is a mapping from M-dimensional real space to the Hilbert space? I this case, can I say that "psi \in H" ?
look in the textbook for notation
psi is a mapping from M-dimensional real space to the Hilbert space?
yes
"psi \in H" ?
no. the image of Psi is in H
Thank you. Do you mean it is "Psi \in H" ?
no. look up the definition of image
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hi
part b
it would be an honour if someone could explan it to me
i know one method is to just find the probability between 1 and 2 defectives
but why can I not use the conditional probability fomrula here
Find the probability that there are more than 2 defective lamps
why can i not use this formula for this case
is my question
they are independent events
Yes they are independent events, so conditional probability doesn't make sense
The defection of lamp A won't affect the probability that lamp B is defected
oh fuck
i see
thanks a lot
just to clarify
i can just do this right
P(X <= 2 | X > 0)
Yeah
@snow wind Has your question been resolved?
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what have you tried
I don’t know where to start from given all that information
they straight up gave you the roots
iirc, you've encountered these types of problems before
there are multiple ways to approach this
since you're given the roots, you could consider applying something like factor theorem
Do you recognize (x-a)(x-b)
I think I need help
I think, I forgot a little
Like others have mentioned, that's the factor theorem. When k is a root of a polynomial, (x-k) is a factor.
I’m still confused
When you look for roots in a polynomial in the form (x-a)(x-b) ... you're trying to make y = 0, and the way to do that is for x - k to be 0.
But it’s not in this form
Well the factored form tells you the roots, and in your original problem it tells you the roots
True but how would I find the value of a b and c
Is there anything you can do to go from (x-k)(x-h) to ax^2 + bx + c?
If you've done factoring this should look very familiar
We can expand it
Yes
don't forget about the scaling factor
What’s that?
the a
considering factor theorem, your function can be expressed in the form
f(x) = a(x-p)(x-q)
That makes it like a cubic equation
how does that make it a cubic
a is a constant
(i like to use p,q. avoid using variables that are already established in relevant formulas)
I don’t understand, what exactly are we trying to do?
I don’t understand because the chapter I did doesn’t talk about any of this
the ultimate goal is to determine a,b,c
Yes
factor theorem allows a simple way to determine a
and ultimately the entire quadratic polynomial in factored form
which you can then expand to identify the values of b and c
I still don’t get it
do you understand factor theorem
iirc based on what you've asked in the past, you've definitely done stuff on factor theorem before
Yh I have done some stuff in factor theorem
But what I mean is I haven’t properly started it in my book
Which is what’s asking me confused in this question
its pretty much
p is a root of the polynomial iff (x-p) is a factor
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can anyone tell me how to conclude that sqrt((a+c)^2+(b+d)^2) less than or equals to sqrt(a^2+b^2)+sqrt(c^2+d^2)
Though I can use am-gm ineq
But i am not sure if they are all logically equivalent
Also I wonder if there is a more straightforward way (perhaps dun hv to apply other theorems) to prove it
I am proving the general triangle inequality for complex number btw
If I have to make a formal proof
How to make it “formal”?

Use QM ≤ AM
QM?
me thinking.. quadratic mean would be insufficient, need at least biquadratic mean lol
Ummm
pretty sure you just need manipulation and squaring to get rid of square roots
Is that the root mean square
yep (realized you'd still need some manipulns tho)
can you figure the rest?
Umm use the cosine formula?
use whatever you would to show AB + BC ≥ AC ig
😑
Lol but I still don’t understand
well this'd be more intuitive ig, if you've done triangle law
Is it true that “$|u+v|^2=u^2+2|u+v|+v^2$”?
Trenton
I rmb it is true for absolute value, but dk if it still apply on modulus of complex number
But somehow this method use theorems that proved by the sqrt(a^2+b^2) definition
Just use the axiom that the minimal distance between two points is a line
Any path other than a line will necessarily be longer
No, u=3, v=-2
1 doesn’t equal 15
Ok
So now I am a step closer
Now I have to prove that u^2+v^2-|u+v|^2=-2Re(u(v bar))
excuse me this only works for reals
Oh yes, x=3+4i is a counter example
thinkin
screams
why was I thinking vectors 
nvm, just me being terrible at complex numbers :c
Now this change to |u|^2+|v|^2-|u+v|^2=-2Re(u(v bar))
why did we not just use a b c d again
ah
As abcd is kinda geometric interpretation
in complex numbers, $|z|^2 = z\overline{z}$
Camilleone
have fun
Oh thank you
omg thattttttttttt
Umm
you went the wrong way lol
Opps
don't move the square in
use $|z|^2 = z\overline{z}$ directly to get rid of the squares
Camilleone
whats a+7x?
Oh
how does that end up any different from the a b c d thingy, except a little difference by defining f(u, v) = (|u| + |v|)² - |u + v|²
what is a+7x
nu :c I've never once been formally introduced to complex numbers
opps lol
the two methods are more or less equivalent if you break things down, but this one is more concisely phrased
hence the |x|² = x² confusion (@_@;)
noted that!
Also, is using this circular? 
cause a little tweaking with argand plane and the usual triangular law shouldn't hurt
go on and expand that bad boy at the right, yeah
circular? huh?
I mean, using |u| + |v| ≥ |u + v| to prove |u| + |v| ≥ |u + v| lol
that is very certainly circular
can't use geometric arguments in complex plane then, ig
unless we've shown the triangular inequality holds I think it can be, cause the inequality only concerns the real parts
bite your tongue i totally use geometry to argue complex numbers
let's gooooo
But why the rightmost term is equals to Re(u + v bar)?
if you take a general $z = x + iy$, what is $z + \overline{z}$?
Camilleone
Only the real part x
*twice
As yi -yi cancel out each other
Oh yes
by the way it's not $2(u\overline{v} + v\overline{u})$, check your constants
Camilleone
So $z+\overline{z}=2Re(z)$
no, again check your constants
Trenton
This?
yes
also, this
sure, but do you know why you can do it?
well...you could do it, but i really was more looking for a knowledge of how complex conjugate plays with multiplication
Oh
like, if you knew what $\overline{zw}$ was
Camilleone
In general, $\overline{zw}= \overline{z} .\overline{w}= \overline{w} .\overline{z} =\overline{wz}$
Trenton
Yay
yeah, that's it
that's the one that tells you you can get the third line here
(also the fact that $\overline{\overline{z}} = z$, but this is more or less trivial)
Camilleone
what's the geometric interpretation of multiplication and division in complex plane though 
how to show bar{zw} = bar{z} bar{w} geometrically T_T
bar is a reflection
multiplication is a scaling plus a rotation
if you multiply $z$ by $w$, you scale $z$ by $|w|$, then rotate that position vector about the origin by $\arg w$
Camilleone
unlike vectors where product leaves you with the magnitude 
yeah, that's down to the fact you have an additional structure
$zw = (z |w|) \qty(\cos(\arg{w})+ i\sin(\arg{w}))$
yes
if you want to put it in that form
sure
personally i think it's easier to see using $re^{i\theta}$
yay! I see the rotation
Camilleone
:o
but whatever works for you hahaha
will take time understanding rotation in terms of e^{i\theta} ig 
have fun 😛
@zenith compass Has your question been resolved?
I think II is $Re(|u\overline{v}|)$
Trenton
But I am not sure what to compare
@zenith compass Has your question been resolved?
Is this okay?
I am not quite sure about the “Note that” statement
Looks good, yes
What you've written is essentially: $x^2 \leq x^2 + y^2 = \abs{\mu \overline{\nu}}^2$
Ok thank you
Thank you Ansh, Camilleone, Cogwheels of the mind and EndTimes
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Can anyone help me ? What is the correct max value?
in terms of magnitude, you’ll get one other value that is maximum too i think,
4 *-sin(theta) = r
so if -sin(theta) = 1
sin(theta) = -1
you’ll again get a max value
@fierce tartan Has your question been resolved?
So the correct answer is (-4,3pi/2)?
This is one of my profs presentation
Because according to the presentation, sine is fixed to be maximum when it is 1
I searched the max value of this one on google and it turns out that it is (7,3pi/2) rather than my prof’s answer. But what I think is that, she fixed the idea that sine is maximum when it is equal to 1 or pi/2
dw matey, i’ve done polar curves. basically the max value is when the differential = 0
you can think of it like that
for your example
it’s not necessary or wtv
but in general, for harder problems
dr/dtheta = 0
find theta
and plug it back into r
remember, we only care about the magnitude of r
so
yeah no. but it’s only magnitudes you see?
Ill confirm it to her tomorrow then Ill just follow her hahahahaha
it’s fine matey
your working looks alright to me,
but if it’s just a multiple , then you know. both,(pi/2) and (3pi/2) give you a maximum
just plug 3pi/2 in and see
you need to be able to adapt and see what do you need to get the maximum of the eqn as a whole
r = 3 - 4sin(theta) for example
you can’t get your max by plugging in pi/2
or for 2+ sin(3theta)
you need to know what to pic and stuff
maximum of sin function =1
minimum of sin function = -1
depending on the equation, you need to make choices
@fierce tartan Has your question been resolved?
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With 4044 cookies in the form of equilateral triangles, Mynor arranges to place them in a peculiar way consisting of two rows with the same number of cookies. The ones in line top numbers them from 1 to 2022, as shown in the image.
Mynor eats all those cookies in the top row that occupy position 6n + 4, with n ≠ 0, that is, those in positions 10, 16, 22,. . ., 2020.
When Mynor finishes eating the cookies, what is the perimeter of the new shape?
I don't really get the question itself, how am I supposed to calculate a perimeter if I don't have the measurements?
It's a really large shape though.
(Shadowed triangles = Eaten cookies).
I guess that I could calculate somehow the perimeter of the repeated shape in there.
And then just multiplying it? Not sure if that's right.
Oh, wdym?
i dont see how that drawn helps
what happens to the perimeter when a cookie is eaten?
New side of the shape?
?
uh
If the perimeter is P
at the start
and I eat the cookie at 10
what happens to P
P becomes a smaller number? Idfk, I don't understand-
You think the perimeter decreases when a cookie is eaten?
refer to your 1st diagram
what happens to the perimeter when the triangle 10 is taken away
Yes.
oh, nothing
idk i don't understand at all
You have this bar
what is the perimeter of it?
right now as it is drawn in your diagram
No cookies have been eaten
86?
no... how did you get that
that's the amount of cookies in the diagram 
how is that the perimeter though
what does perimeter of a shape mean?
thats perhaps the problem
sum of all the sides?
length around the outside
not all cookies are contributing to the perimeter
the cookie 11 adds nothing to it
oh gotcha
36?
38?
im looking
Not sure where this is from.......
I am trying to get you to see
the difference in perimeters
after taking 10 away
I don't see how you get 2 extra
The top side will not be 18.
oh okie uh
Ok so for the top side
how much of the perimeter is horizontal
I want to see how you got 18
I'm talking about after weve removed 10
i mean i usually counted 10, 12, 14, 16, 18(etc.) because they were part of the border of outside
but now that i don't have one and the top it's not horizontal
i don't really have any idea of what to do
i though maybe of like something like this but idrk what to do with that little bump
correct
all good, now what is the extra perimeter from the wedge
you marked the relevant perimeter yourself
remember these are equilateral triangles
it is 37
oh really?
well yes i mean...
you marked it very clearly yourself
my point is though, why does it go from 36 to 37
what exactly changes
the number of sides?
the number of sides increases
Very vague, be more specific
You marked on the diagram yourself
you marked what was new
the number of sides increase because uh
idk how to explain this
because the sides get split into two? idfk
Ok think about it this way?
what changes and what doesnt in the diagram
Everything else stays the same except at the 10 triangle yes?
the top side, the rest of the sides are the same
You dont even need to look at the entire top side
literally the only thing that changes is the triangle where 10 is at
When 10 is present
which of its sides counts towards its perimeter
and what about when its not
the top side?
the top side and the new little hole here?
Yes my point is
when 10 is there you count only the top side
when 10 isnt there you count only the other 2 sides
oh yea
Can you see why eating the cookie 10 will result in the total perimeter increasing by 1?
ye i get it thanks
Now apply this to solve the Q
okie
so, if in total, mynor eats 353 cookies
([352*2]+[2*352])+2+2
?
[352*2] comes from the split of the eaten cookies into two sides
[2*352] is the space between them
kinda like this?
im not sure about the final answer but as long as you have the right process 🙏
Just be careful what the end of this bar will look like.
okie
the bar also ends like this
that's why i subtracted 1 from 353
that's all then
thanks
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if 3sin(x) + 4cos(x) = 5
deduce the value of sin (x)
I've tried dividing the equation by 5 and feel like i there might be a relation between it ans cos^2 + sin^2 = 1 but i cant go further
perfect feeling!!!
here's a hint: $$sin(x + A) = \cos A \sin x + \sin A \cos x$$
uh whats the dashthrough circle symbol i dont think I've taken it
its the greek letter phi
oh I'll to solve it and respond in a couple mins
wait a sec! I'm kind of curious
how much on a rate of 1 to 10 are you comfortable with trigonometry?
it can also go beyond 10 out of 10 tbh lol, your call
~6 i guess
square both sides and use (cos x)² = (1 - (sin x)²)
we've only taken a bit this year and the lesson was removed from last year's curriculum so they kinda crammed both years lessons and im kinda lost
then it's just a quadratic
@fierce solar Has your question been resolved?
$16\cos^2 x = 25 - 30 \sin x + 9\sin^2 x$
$\implies 25\sin^2x - 30 \sin x + 9 = 0$
right?
yeah
$\implies (5 \sin x - 3)(5\sin x - 3) = 0$
$\implies \sin x = \frac{3}{5}$
alright thanks i'll revise it whole then tell u if i understood the concept
alright all solved
thanks for your help
:D
before you leave, I have a curious question
is that your cat flying towards the camera? in your pfp
maybe
arctan transformation
$\int \frac{1}{100\qty(1+\qty(\frac{3x}{10})^2)} \dd{x}$
unfortunately no
i'll leave now so i wont disrupt u helping
btw .close before you leave (@_@;)
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tyvm
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Hi
I need to have the same base
But I forgot how I can do that
When I have the same base I can substract the exponent
We did this a long time ago in class but I forgot how to do it
don't you have the same base?
you have 5 x^m x^-2
wont it be 10 outside?
Where is the 5
i didn't take the 5 into account the 5 is just in front
Oh okay
Tysm
sylveon handwriting
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@harsh swallow quick question
What is the right answer for this
When the base and exponent are the same
Do we multiply the base and add the exponents
Or just keep the bases as they are and add the exponents?
$10x^{10m} * 10x^{10m} = 10 * 10 * x^{10m + 10m}$
Katharine
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yes
i can't read it :S
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$\lim_{x \to \infty}\frac {x (log x)^3} { 1+x + x^2}$
Deep
Can we do it without l’hospital
Occupied
bro I'm here before you
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@ripe rain can you reopen?
.reopen
✅
ok thanks
.reopen
i'll ask you when we're done
bruh
😄
okay
,rotate
Couldn't find an attached image in the last 10 messages.
your du = isn't correct
finish deep and we'll discuss abt mine
i asked him to reopen so that we can continue here
otherwise you'd have to open a new one
whole hasstle
Ur wish
hassle
if u = 3x^2/10
I shld find the calculus 2-integrals
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Why can't this equal zero???
...because that vector is non-zero...?
because it’s not zero?
^^
you know how to find det of matrix right ?
i, j and k are unit vectors in this case,
by definition they’re non zero
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i just don't really know how to get the dimensions of the triangle
hint: start by figuring out the edge length of a hexagon
use the hexagon area formula
as camilleone said
try to find the area of one small triangle
then add areas like -
12+ (6* area of one small triangle)
Area of a hexagon = (3√3* side*side)/2
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How do we show that Thomae function is continuous at all irrational numbers and discontinuous at all rational numbers
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I need help with all parts
@stiff hornet Has your question been resolved?
<@&286206848099549185>
@stiff hornet Has your question been resolved?
someone help
Do you know what discrete uniform distribution is?
no
In probability theory and statistics, the discrete uniform distribution is a symmetric probability distribution wherein a finite number of values are equally likely to be observed; every one of n values has equal probability 1/n. Another way of saying "discrete uniform distribution" would be "a known, finite number of outcomes equally likely to ...
"data" means points of the form [(x1,y1), (x2,y2),...,(xn,yn)]
So all of the datum has probability 1/n
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Given a f(x) what is a sufficient condition for one of the roots to be between two numbers(let's say 2<x1<-1) and the other not to be
