#help-0

1 messages · Page 953 of 1

vale sapphire
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fair enough

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Okay, let me recollect here

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d(1/x) is not 1/h for any particular value h. d(1/x) is how much 1/x changes when you give it a little nudge, a nudge of dx for instance

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So, you could think of it like 1/(x+dx)-1/x

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the little change in 1/x when dx gets really small is what we call d(1/x)

wooden sapphire
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right

vale sapphire
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But yes, the main point is that if dx is really small, if the variation is truly tiny, that rectangle in the top-right becomes very small

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negligibly so

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So you're only left with the green and red rectangles

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sorry, got confused myself for a second

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Before dx was added, the red area was there but not the green one

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After dx is added, ie the green area is added, that red rectangle is no longer there

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What 3b1b is saying, is that (neglecting the top-right rectangle), what you gained in one place must have been reflected in the other one

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i.e the areas of the two rectangles must be the same

wooden sapphire
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did you get to the end where he tells you to come up with d(1/x)/dx?

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well, the end of the section of the video

vale sapphire
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it's been a hot minute since i watched this

wooden sapphire
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I understand the concept of what is happening here. What I don't understand is how the fuck you're supposed to come up with d(1/x)/dx using this image.

vale sapphire
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what's the area of the red rectangle?

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(be careful, the area is signed)

wooden sapphire
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uhhhhh

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ahh, see I don't even know

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I can write out in words what a derivative is

vale sapphire
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he gives you the width and the height, who cares if it's symbolic, the formula you learned in whatever-th grade still applies

wooden sapphire
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is it a trick question?

vale sapphire
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nope

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just multiply

wooden sapphire
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are you telling me that d(1/x)/dx is the area of the red/green rectangle?

vale sapphire
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What?

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No

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The red rectangle

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not the top-right, not the green, just the red

wooden sapphire
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the red rectangle is d(1/x)/dx.

buoyant kayak
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what is the formula for area of a rectangle

wooden sapphire
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base times width

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er whatever the fuck

buoyant kayak
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what is the width of the red rectangle

wooden sapphire
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i dont know

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x

vale sapphire
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correct

buoyant kayak
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what's the height

wooden sapphire
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d(1/x)

buoyant kayak
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yes

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so area is?

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it's signed

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oops

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height is d(1/x) but remember this is a negative area

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keep that in mind

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i guess it's technically -d(1/x) huh

vale sapphire
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yeah it is

buoyant kayak
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either way you're just multiplying here

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so what is area

wooden sapphire
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I'm stuck

buoyant kayak
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this is not a trick question

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you know the width

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you know the height

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put them next to each other

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that's the area

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can you tell me what the area is

wooden sapphire
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x * d(1/x)

vale sapphire
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correct

buoyant kayak
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remember it's negative

vale sapphire
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well

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yeah the sign

wooden sapphire
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-x * d(1/x)

vale sapphire
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actually correct

wooden sapphire
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how is that d(1/x)/dx

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I don't see it

buoyant kayak
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it's not

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what's the area of the green rectangle

wooden sapphire
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dx * 1/x

buoyant kayak
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right

vale sapphire
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what do you know about these two areas?

wooden sapphire
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they're equal

buoyant kayak
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yes

vale sapphire
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write that and solve

buoyant kayak
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so solve for d(1/x)/dx

wooden sapphire
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I tried that earlier

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I'll try again

buoyant kayak
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if it helps you can show your work and we can point out what's wrong

wooden sapphire
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I see it

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so...

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the issue I guess

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was that I was trying to simplify the problem by substituting

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but I was substituting something that wasn't equivalent

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I'm still stuck on why that is exactly

buoyant kayak
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what did you substitute

wooden sapphire
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I substituted d(1/x) for 1/h

buoyant kayak
vale sapphire
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what is h

buoyant kayak
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f(x)=1/x, so if you wanted f(h), sure, that's 1/h

wooden sapphire
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h is dx

buoyant kayak
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but as systems already said

vale sapphire
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by writing d(1/x)=1/dx, you are telling me that when i go to the right by 0.01, 1/x increases by 100

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it's a really simple formula

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unfortunately it's wrong

wooden sapphire
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the only answer my brain can come up with is that you can't put dx as x in d(1/x) because the function doesn't behave the same at every point. To get an accurate representation of how the function would behave at x+dx, that's what you have to plug in.

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I can't tell if I'm lost at this point because I am that stupid or because I've subconsciously given up

buoyant kayak
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d(1/x)=dy, dy != 1/dx

wooden sapphire
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what is the ! for?

buoyant kayak
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does not equal

wooden sapphire
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yes, we've established that

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and I understand why it doesn't

buoyant kayak
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so why do you think it does

wooden sapphire
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I don't anymore

buoyant kayak
wooden sapphire
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d(1/x) is (1/x+h) - (1/x) right?

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if I stop thinking about the diagram it makes a shitload more sense

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h being an infinitely small number

lone heartBOT
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@wooden sapphire Has your question been resolved?

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lone heartBOT
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fringe dome
#

A hypothesis test using 95 percent confidence has a significance level equal to

wintry lotus
#

What do your notes say a significance level is?

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@fringe dome Has your question been resolved?

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@fringe dome Has your question been resolved?

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alpine sable
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In this function. I have found the secant slope which I believe to be 2 but what about the tangent slope?

alpine sable
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How should I think

abstract fractal
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Do you know how to take a derivative?

alpine sable
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yes and in this case it would be 3x^2 - 2

abstract fractal
#

Yes. Do you know what the derivative represents?

alpine sable
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Tangent slope

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what about the graph

abstract fractal
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The derivative is the slope of the tangent line at some x value

alpine sable
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I should put them in the formula

abstract fractal
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What x value is the line tangent to on the graph?

alpine sable
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right?

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1

abstract fractal
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So plug 1 in to the derivative

alpine sable
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its 1

abstract fractal
#

That's the slope

alpine sable
#

thanks

#

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lone heartBOT
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broken pine
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I can get to the answer unprofrofessionally

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But whats the actual method ur supposed to use to get as high marks as possible

proven meadow
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to solve for x?

broken pine
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Yea to get the value of x

proven meadow
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first distribute 2

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to the bracket

broken pine
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Distribute?

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Like remove?

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Or move?

proven meadow
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distributive property

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2(x+y) = 2x +2y

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each term in the bracket is multiplied by 2

broken pine
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Whats the bracked

wary stream
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No need to distribute, tbh

broken pine
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Im not familiar with these english terms

proven meadow
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brackets are the ()

broken pine
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Ah i figured

proven meadow
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so 2(6 + x²) would become...?

broken pine
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How do u write that

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What device are u on

proven meadow
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lol

broken pine
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Oh lol

wary stream
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FYI distribution is an extra, not needed step

proven meadow
broken pine
wary stream
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Actual method is just solving for x

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You don't need to do extra steps

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As long as you solve for x, that's all you need

broken pine
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Mhm

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And how would u do that

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The way i did it was just that i knew that x² had to be 9

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Therefore i knew the answer was 3

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But how do you get to it profesionally or whatever

wary stream
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The proper term is algebraically

broken pine
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Also the answer is supposedly +-3

broken pine
lone heartBOT
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dry echo
#

Could you figure this out in your head?

lone heartBOT
dry echo
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I wanna understand if I'm slow because I had to use pen and paper and manipulate that equation a bunch of times until I found it

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Is there a quick way to figure it out?

vague coral
manic wind
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You have to use systems of equations

dry echo
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oh okay

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yeah I did

vague coral
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system of equation and it's done

dry echo
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I just wanted to make sure if I was dumb

manic wind
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I don't think there is a short cut unless it's super obvious

dry echo
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Alright, thats fair

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thank you guys

vague coral
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the values aren't so obvious tho so we cant find it in our head

dry echo
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I always have this feeling like I'm too slow or something

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But it's probably just in my head lol

vague coral
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maths is dumb

wintry lotus
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wouldn't it be (6/(x^2))^(x)?

vague coral
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he knows how to do it

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right?

dry echo
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Well, with all those roles

wintry lotus
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haha

vague coral
dry echo
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They gotta know

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😂

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ok thanks everyone!

dry echo
vague coral
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6 = Cb
24 = Cb^3

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b^2 = 4

dry echo
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ah okay, I see

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systems of equations

vague coral
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well not really

wintry lotus
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^ pretty much that, since your graph doesn't appear to go negative, you will have x^(even) somewhere

vague coral
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b = 2 or -2

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then C = -3 or 3

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but since the graph increases

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positive values I guess

dry echo
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right

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makes sense

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appreciate the help 🙌

vague coral
dry echo
#

.close

lone heartBOT
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pseudo isle
lone heartBOT
pseudo isle
#

can someone tell me why this happens?

tacit arch
#

Distributive property

wary stream
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Move the 29 over, you get y^2 - 10y = 0

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Then factor

pseudo isle
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thank you so much

tight locust
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Let me demonstrate with a rectangular argument:

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This is fundamental

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Now you know

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alpine sable
#
of paper money: the 17 Yacley bill and the 5 Yacley bill. How many different combinations
of these bills total 453 Yacley?```
I don't know how to approach this question
manic wind
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Casework

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Start with one 17 Yacley bill, see if 453-17*1 is a multiple of 5, then move on to 2 Yacley bills, etc.

alpine sable
#

oh i c

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.close

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shadow bloom
#

My name is chad, I've been shooting hoops since I was 5 and I got 17 peoples lunch money today, 7 had 8 dollers and 6 had 3 dollars and 4 had 12 dollars, how do I figure out how much lunch money I have?

shadow bloom
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<@&286206848099549185>

glass lichen
shadow bloom
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Sorry man

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Come on dudes!

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I only had 12 minutes of recess

glass lichen
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How old are you?

shadow bloom
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17

glass lichen
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High schools don't have recess

shadow bloom
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Shit

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I'm from Britain so I didn't know thag

glass lichen
#

Also that is very much, bar the stupidity of how it's written, an elementary age question

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Just use a calculator and stop making a fool of yourself

shadow bloom
#

I failed my maths gcse

wintry lotus
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Saturday recess?!

glass lichen
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That too kekw

lone heartBOT
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@shadow bloom Has your question been resolved?

hasty elk
#

not to mention i'm pretty sure it's damn near midnight in Britain

glass lichen
#

It is

lone heartBOT
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native elbow
#

hello !(solving problems involving radicals)

A woman walks 5 kilometers to the east going to school and then bikes 9 kilometers northward going to church. How far is she from the church to the starting point which is her house?

wintry lotus
#

Have you drawn it out?

native elbow
#

yes i actually have a solution already-

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my solution:
c= √9^2 + 5^2
c= √81+25
c= √106
c= 106km

is this correct ??

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it feels weird bc my final answer is a pretty big number-

wintry lotus
#

sqrt(106) sounds right

wary stream
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That square root disappeared

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How?

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$c= \sqrt{106}$ is the final answer

ocean sealBOT
#

dldh06

wary stream
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Not sure what you did to get c = 106

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And make that sqrt disappear

native elbow
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idk either i just followed a yt video 🧍‍♂️

pale kestrel
#

its wrong.

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square roots dont disappear for no reason

native elbow
#

oh

wary stream
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I'm pretty sure that video didn't make it disappear

native elbow
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here's the vid-

wary stream
#

Maybe if it was a squared number, like $c = \sqrt{81}$

ocean sealBOT
#

dldh06

wary stream
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That's when it can disappear because sqrt of 81 is 9

native elbow
#

do u guys mind telling me how to properly solve for it then? So i would know next time

wintry lotus
#

because sqrt(100) = 10

wary stream
#

Sqrt(106) is a valid answer

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You just need to know when it's a square number

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Like 106 is not a square number

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But 100 is

distant flare
#

≈10.29563km

wary stream
#

Eh, decimals aren't exact though

distant flare
#

yeah, which is why i used ≈

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but often times teachers just want the answer like that

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at least that from my experience

native elbow
#

okay so which part of my solution was wrong- and how do i correct it?

distant flare
#

your solution was correct until you removed the √

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√106 is the correct solution

native elbow
#

oh okay thanks!

#

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frosty eagle
#

this is review, is this correct?

lone heartBOT
frosty eagle
#

thx

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bye now

shadow bloom
#

Hey nerds

tacit arch
#

.close

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somber basin
#

Im being asked to prove that the theory of an F-space is complete (where F is a specific infinite field). But the trivial vector space is a vector space over the reals... a complete theory with an infinite model can't have any finite models. So, why isnt that a counterexample?

pale kestrel
#

try an advanced channel

somber basin
#

How do I get permission to chat in those?

manic wind
somber basin
#

thanks

lone heartBOT
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worthy adder
#

how do i solve this using shell method

lone heartBOT
worthy adder
#

would the radius be r=x-1

tacit arch
#

Show your work?

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Radius is a difference of y curves

worthy adder
#

that is the book work not mine

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this is different from what i normally do since the about x=1 is touching the equatoion

glass lichen
worthy adder
#

yes

glass lichen
#

So, like riemann said, show your work...

worthy adder
glass lichen
#

and your work..?

worthy adder
#

that is all because i dont know how to approach it

glass lichen
#

Check your notes

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Google

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Look in your textbook

worthy adder
#

the textbook never show this kind of example

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i already serch thru and far cant find anything

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professor suck really bad at teaching

glass lichen
worthy adder
#

none of the example match this one

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@glass lichen u get what im sayong

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saying

glass lichen
#

No, cause I really doubt you actually googled "shell method examples"

worthy adder
#

i legit did

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discord would be my last resort

glass lichen
#

Shell Method is using cylinders...

worthy adder
#

i know but this one in particular is making go insane

glass lichen
#

The resource I linked has examples w/ cylinders.

worthy adder
#

yes but they dont have it with it rotating in the in the shaded area

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do u get what im saying

glass lichen
#

no

worthy adder
#

@glass lichen do you actually know how to solve this one

glass lichen
#

you can just ignore the part of the region to the left

worthy adder
#

so radius is just x

glass lichen
#

Radius, as shuri told you already, is a difference of functions of y..

worthy adder
#

than it would be r=4x-x^2-1

lone heartBOT
#

@worthy adder Has your question been resolved?

abstract fractal
pale kestrel
#

I would shade in on your graph

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the relevant region

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thats being rotated

#

Identify the closed region.

lone heartBOT
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grizzled ridge
#

Is this arrow means psi is a mapping from M-dimensional real space to the Hilbert space? I this case, can I say that "psi \in H" ?

tacit arch
#

psi is a mapping from M-dimensional real space to the Hilbert space?
yes

#

"psi \in H" ?
no. the image of Psi is in H

grizzled ridge
tacit arch
grizzled ridge
#

Oh.. that image, I think I understand now. Thank you again.

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snow wind
#

hi

lone heartBOT
snow wind
#

part b

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it would be an honour if someone could explan it to me

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i know one method is to just find the probability between 1 and 2 defectives

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but why can I not use the conditional probability fomrula here

manic wind
#

Find the probability that there are more than 2 defective lamps

snow wind
#

yes

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i have done that

manic wind
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Okay whats the confusion then?

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Or where do you need explaining

snow wind
#

why can i not use this formula for this case

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is my question

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they are independent events

manic wind
#

Yes they are independent events, so conditional probability doesn't make sense

#

The defection of lamp A won't affect the probability that lamp B is defected

snow wind
#

oh fuck

#

i see

#

thanks a lot

#

just to clarify

#

i can just do this right

#

P(X <= 2 | X > 0)

manic wind
#

Yeah

lone heartBOT
#

@snow wind Has your question been resolved?

#
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cunning trout
lone heartBOT
gray isle
#

what have you tried

cunning trout
#

I don’t know where to start from given all that information

desert cradle
#

they straight up gave you the roots

cunning trout
#

How do I use them

#

To solve

#

?

gray isle
#

iirc, you've encountered these types of problems before

#

there are multiple ways to approach this

#

since you're given the roots, you could consider applying something like factor theorem

cunning trout
#

Ok

#

Hmmm. I don’t get it

manic wind
#

Do you recognize (x-a)(x-b)

cunning trout
#

I think I need help

cunning trout
manic wind
#

Like others have mentioned, that's the factor theorem. When k is a root of a polynomial, (x-k) is a factor.

cunning trout
#

I’m still confused

manic wind
#

When you look for roots in a polynomial in the form (x-a)(x-b) ... you're trying to make y = 0, and the way to do that is for x - k to be 0.

cunning trout
manic wind
#

Well the factored form tells you the roots, and in your original problem it tells you the roots

cunning trout
#

True but how would I find the value of a b and c

manic wind
#

Is there anything you can do to go from (x-k)(x-h) to ax^2 + bx + c?

#

If you've done factoring this should look very familiar

cunning trout
#

We can expand it

manic wind
#

Yes

gray isle
#

don't forget about the scaling factor

cunning trout
#

What’s that?

gray isle
#

the a

#

considering factor theorem, your function can be expressed in the form
f(x) = a(x-p)(x-q)

cunning trout
#

That makes it like a cubic equation

gray isle
#

how does that make it a cubic

manic wind
#

a is a constant

gray isle
#

(i like to use p,q. avoid using variables that are already established in relevant formulas)

cunning trout
#

I don’t understand, what exactly are we trying to do?

#

I don’t understand because the chapter I did doesn’t talk about any of this

gray isle
#

the ultimate goal is to determine a,b,c

cunning trout
#

Yes

gray isle
#

factor theorem allows a simple way to determine a
and ultimately the entire quadratic polynomial in factored form

#

which you can then expand to identify the values of b and c

cunning trout
#

I still don’t get it

gray isle
#

do you understand factor theorem

cunning trout
#

Sort of

#

Haven’t started it because it’s later in my maths textbook

gray isle
#

iirc based on what you've asked in the past, you've definitely done stuff on factor theorem before

cunning trout
#

Yh I have done some stuff in factor theorem

#

But what I mean is I haven’t properly started it in my book

#

Which is what’s asking me confused in this question

gray isle
#

its pretty much
p is a root of the polynomial iff (x-p) is a factor

cunning trout
#

Ok I will see and ask for help if I still don’t get it

#

Thnks for help

#

.close

lone heartBOT
#
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zenith compass
lone heartBOT
zenith compass
#

can anyone tell me how to conclude that sqrt((a+c)^2+(b+d)^2) less than or equals to sqrt(a^2+b^2)+sqrt(c^2+d^2)

#

Though I can use am-gm ineq
But i am not sure if they are all logically equivalent
Also I wonder if there is a more straightforward way (perhaps dun hv to apply other theorems) to prove it
I am proving the general triangle inequality for complex number btw

#

If I have to make a formal proof

#

How to make it “formal”?

little drum
tight locust
#

Can we assume that a,b,c,d are all positive

#

That will make things very easy for us

little drum
#

Use QM ≤ AM

tight locust
#

QM?

little drum
#

thinkies me thinking.. quadratic mean would be insufficient, need at least biquadratic mean lol

zenith compass
#

Ummm

hasty elk
#

pretty sure you just need manipulation and squaring to get rid of square roots

zenith compass
little drum
#

yep (realized you'd still need some manipulns tho)

little drum
zenith compass
#

Umm use the cosine formula?

little drum
#

thinkies use whatever you would to show AB + BC ≥ AC ig

zenith compass
#

I just found sth interesting from google

little drum
#

😑

zenith compass
#

Lol but I still don’t understand

little drum
zenith compass
#

Is it true that “$|u+v|^2=u^2+2|u+v|+v^2$”?

ocean sealBOT
#

Trenton

zenith compass
#

I rmb it is true for absolute value, but dk if it still apply on modulus of complex number

zenith compass
tight locust
#

Just use the axiom that the minimal distance between two points is a line

#

Any path other than a line will necessarily be longer

oak perch
#

1 doesn’t equal 15

zenith compass
#

Umm

#

So if i hv to get rid of this term

#

And to conclude that it is equals to

little drum
#

btw if you didn't know,

#

$|x|^2 = x^2$

ocean sealBOT
zenith compass
zenith compass
zenith compass
#

So now I am a step closer

#

Now I have to prove that u^2+v^2-|u+v|^2=-2Re(u(v bar))

hasty elk
zenith compass
#

Oh yes, x=3+4i is a counter example

little drum
#

thinkin

#

screams

#

why was I thinking vectors thinkies

#

nvm, just me being terrible at complex numbers :c

zenith compass
hasty elk
#

why did we not just use a b c d again

zenith compass
#

We done a b c d that one

#

I just wonder if there is an alternative method

hasty elk
#

ah

zenith compass
#

As abcd is kinda geometric interpretation

hasty elk
#

in complex numbers, $|z|^2 = z\overline{z}$

ocean sealBOT
#

Camilleone

hasty elk
#

have fun

zenith compass
#

Oh thank you

little drum
zenith compass
hasty elk
#

mmhmm

#

go on

zenith compass
hasty elk
#

what

#

no

zenith compass
#

Umm

hasty elk
#

you went the wrong way lol

zenith compass
#

Opps

hasty elk
#

don't move the square in

zenith compass
#

Did u apply the power rule correctly?

#

Ok

hasty elk
#

use $|z|^2 = z\overline{z}$ directly to get rid of the squares

ocean sealBOT
#

Camilleone

odd herald
#

whats a+7x?

hasty elk
#

all of the squares

#

Ansh, wanna take it from here?

zenith compass
#

Oh

little drum
#

how does that end up any different from the a b c d thingy, except a little difference by defining f(u, v) = (|u| + |v|)² - |u + v|²

odd herald
#

what is a+7x

little drum
hasty elk
#

opps lol

hasty elk
little drum
#

hence the |x|² = x² confusion (@_@;)

little drum
#

Also, is using this circular? thinkies

zenith compass
little drum
#

cause a little tweaking with argand plane and the usual triangular law shouldn't hurt

hasty elk
little drum
#

I mean, using |u| + |v| ≥ |u + v| to prove |u| + |v| ≥ |u + v| lol

hasty elk
little drum
#

can't use geometric arguments in complex plane then, ig

#

unless we've shown the triangular inequality holds I think it can be, cause the inequality only concerns the real parts

zenith compass
hasty elk
little drum
#

let's gooooo

zenith compass
hasty elk
#

if you take a general $z = x + iy$, what is $z + \overline{z}$?

ocean sealBOT
#

Camilleone

zenith compass
#

Only the real part x

little drum
#

*twice

zenith compass
#

As yi -yi cancel out each other

zenith compass
hasty elk
# zenith compass

by the way it's not $2(u\overline{v} + v\overline{u})$, check your constants

ocean sealBOT
#

Camilleone

zenith compass
#

So $z+\overline{z}=2Re(z)$

hasty elk
ocean sealBOT
#

Trenton

zenith compass
#

This?

hasty elk
#

yes

little drum
zenith compass
#

Oh

#

How can I make such mistake

#

Thx for telling me

#

Can I just do this?

hasty elk
#

sure, but do you know why you can do it?

zenith compass
#

We have to use the a+bi definition?

#

Let u=a+bi

#

V=c+di

hasty elk
#

well...you could do it, but i really was more looking for a knowledge of how complex conjugate plays with multiplication

zenith compass
#

Oh

hasty elk
#

like, if you knew what $\overline{zw}$ was

ocean sealBOT
#

Camilleone

zenith compass
#

In general, $\overline{zw}= \overline{z} .\overline{w}= \overline{w} .\overline{z} =\overline{wz}$

ocean sealBOT
#

Trenton

zenith compass
#

Yay

hasty elk
#

yeah, that's it

hasty elk
#

(also the fact that $\overline{\overline{z}} = z$, but this is more or less trivial)

ocean sealBOT
#

Camilleone

zenith compass
#

Oh yes

#

Thank you, I will try to work on the rest of the arguments

little drum
#

what's the geometric interpretation of multiplication and division in complex plane though sad
how to show bar{zw} = bar{z} bar{w} geometrically T_T

hasty elk
#

bar is a reflection

#

multiplication is a scaling plus a rotation

#

if you multiply $z$ by $w$, you scale $z$ by $|w|$, then rotate that position vector about the origin by $\arg w$

ocean sealBOT
#

Camilleone

little drum
#

unlike vectors where product leaves you with the magnitude catThink

hasty elk
#

yeah, that's down to the fact you have an additional structure

little drum
#

$zw = (z |w|) \qty(\cos(\arg{w})+ i\sin(\arg{w}))$

ocean sealBOT
hasty elk
#

yes

#

if you want to put it in that form

#

sure

#

personally i think it's easier to see using $re^{i\theta}$

little drum
#

yay! I see the rotation

ocean sealBOT
#

Camilleone

little drum
#

:o

hasty elk
#

but whatever works for you hahaha

little drum
#

will take time understanding rotation in terms of e^{i\theta} ig thinkies

hasty elk
#

have fun 😛

lone heartBOT
#

@zenith compass Has your question been resolved?

zenith compass
ocean sealBOT
#

Trenton

zenith compass
lone heartBOT
#

@zenith compass Has your question been resolved?

zenith compass
#

Is this okay?

#

I am not quite sure about the “Note that” statement

little drum
#

Looks good, yes

ocean sealBOT
little drum
#

What you've written is essentially: $x^2 \leq x^2 + y^2 = \abs{\mu \overline{\nu}}^2$

ocean sealBOT
zenith compass
#

Ok thank you

#

Thank you Ansh, Camilleone, Cogwheels of the mind and EndTimes

#

.close

lone heartBOT
#
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lone heartBOT
#
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fierce tartan
#

Can anyone help me ? What is the correct max value?

solemn grove
#

4 *-sin(theta) = r

#

so if -sin(theta) = 1
sin(theta) = -1

#

you’ll again get a max value

lone heartBOT
#

@fierce tartan Has your question been resolved?

fierce tartan
#

So the correct answer is (-4,3pi/2)?

#

This is one of my profs presentation

#

Because according to the presentation, sine is fixed to be maximum when it is 1

fierce tartan
# fierce tartan This is one of my profs presentation

I searched the max value of this one on google and it turns out that it is (7,3pi/2) rather than my prof’s answer. But what I think is that, she fixed the idea that sine is maximum when it is equal to 1 or pi/2

solemn grove
#

dw matey, i’ve done polar curves. basically the max value is when the differential = 0

#

you can think of it like that

#

for your example

#

it’s not necessary or wtv

#

but in general, for harder problems

#

dr/dtheta = 0

#

find theta

#

and plug it back into r

#

remember, we only care about the magnitude of r

#

so

solemn grove
fierce tartan
#

Ill confirm it to her tomorrow then Ill just follow her hahahahaha

solemn grove
#

it’s fine matey

#

your working looks alright to me,

#

but if it’s just a multiple , then you know. both,(pi/2) and (3pi/2) give you a maximum

#

just plug 3pi/2 in and see

#

you need to be able to adapt and see what do you need to get the maximum of the eqn as a whole

#

r = 3 - 4sin(theta) for example

#

you can’t get your max by plugging in pi/2

#

or for 2+ sin(3theta)

#

you need to know what to pic and stuff

#

maximum of sin function =1
minimum of sin function = -1
depending on the equation, you need to make choices

lone heartBOT
#

@fierce tartan Has your question been resolved?

#
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old pelican
#

With 4044 cookies in the form of equilateral triangles, Mynor arranges to place them in a peculiar way consisting of two rows with the same number of cookies. The ones in line top numbers them from 1 to 2022, as shown in the image.

Mynor eats all those cookies in the top row that occupy position 6n + 4, with n ≠ 0, that is, those in positions 10, 16, 22,. . ., 2020.
When Mynor finishes eating the cookies, what is the perimeter of the new shape?

old pelican
#

I don't really get the question itself, how am I supposed to calculate a perimeter if I don't have the measurements?

#

It's a really large shape though.

#

(Shadowed triangles = Eaten cookies).
I guess that I could calculate somehow the perimeter of the repeated shape in there.

pale kestrel
#

try the question for smaller numbers?

#

but you could try get a pattern

old pelican
old pelican
pale kestrel
#

i dont see how that drawn helps

#

what happens to the perimeter when a cookie is eaten?

old pelican
#

New side of the shape?

pale kestrel
#

?

#

uh

#

If the perimeter is P

#

at the start

#

and I eat the cookie at 10

#

what happens to P

old pelican
#

P becomes a smaller number? Idfk, I don't understand-

pale kestrel
#

You think the perimeter decreases when a cookie is eaten?

#

refer to your 1st diagram

pale kestrel
old pelican
#

idk i don't understand at all

pale kestrel
#

You have this bar

#

what is the perimeter of it?

#

right now as it is drawn in your diagram

#

No cookies have been eaten

old pelican
#

86?

pale kestrel
#

no... how did you get that

old pelican
#

that's the amount of cookies in the diagram kekw

pale kestrel
#

how is that the perimeter though

#

what does perimeter of a shape mean?

#

thats perhaps the problem

old pelican
pale kestrel
#

length around the outside

#

not all cookies are contributing to the perimeter

#

the cookie 11 adds nothing to it

old pelican
#

oh gotcha

old pelican
pale kestrel
#

yes

#

Now I will take the triangle 10 away

#

what is our new perimeter?

old pelican
#

38?

pale kestrel
#

Reasoning behind this?

#

its not correct, but I want to know

old pelican
#

i just counted 9 as part of the top side perimetre

#

like this

pale kestrel
#

im looking

old pelican
#

i counted accidentally 41 too

#

uh

#

then 18+16+4=38

pale kestrel
#

Not sure where this is from.......

#

I am trying to get you to see

#

the difference in perimeters

#

after taking 10 away

#

I don't see how you get 2 extra

#

The top side will not be 18.

old pelican
#

oh okie uh

pale kestrel
#

Ok so for the top side

#

how much of the perimeter is horizontal

#

I want to see how you got 18

#

I'm talking about after weve removed 10

old pelican
#

i mean i usually counted 10, 12, 14, 16, 18(etc.) because they were part of the border of outside

#

but now that i don't have one and the top it's not horizontal

#

i don't really have any idea of what to do

#

i though maybe of like something like this but idrk what to do with that little bump

pale kestrel
#

correct

#

all good, now what is the extra perimeter from the wedge

#

you marked the relevant perimeter yourself

#

remember these are equilateral triangles

old pelican
#

maybe like idek this?

#

so like 2+1+1+16+15+2

#

37? something is wrong then uh

pale kestrel
#

it is 37

old pelican
#

oh really?

pale kestrel
#

well yes i mean...

#

you marked it very clearly yourself

#

my point is though, why does it go from 36 to 37

#

what exactly changes

old pelican
#

the number of sides?

pale kestrel
#

yes but how exactly

#

when you took away the 10

old pelican
#

the number of sides increases

pale kestrel
#

Very vague, be more specific

#

You marked on the diagram yourself

#

you marked what was new

old pelican
#

the number of sides increase because uh

#

idk how to explain this

#

because the sides get split into two? idfk

pale kestrel
#

Ok think about it this way?

#

what changes and what doesnt in the diagram

#

Everything else stays the same except at the 10 triangle yes?

old pelican
#

the top side, the rest of the sides are the same

pale kestrel
#

You dont even need to look at the entire top side

#

literally the only thing that changes is the triangle where 10 is at

pale kestrel
#

When 10 is present

#

which of its sides counts towards its perimeter

#

and what about when its not

old pelican
#

the top side?

pale kestrel
#

So only its top side counts when it is present

#

what about when u take it away?

old pelican
#

the top side and the new little hole here?

pale kestrel
#

Yes my point is

#

when 10 is there you count only the top side

#

when 10 isnt there you count only the other 2 sides

old pelican
#

oh yea

pale kestrel
#

Can you see why eating the cookie 10 will result in the total perimeter increasing by 1?

old pelican
#

ye i get it thanks

pale kestrel
#

Now apply this to solve the Q

old pelican
#

okie

old pelican
#

?

#

[352*2] comes from the split of the eaten cookies into two sides

#

[2*352] is the space between them

#

kinda like this?

pale kestrel
#

im not sure about the final answer but as long as you have the right process 🙏

#

Just be careful what the end of this bar will look like.

old pelican
#

okie

#

the bar also ends like this

#

that's why i subtracted 1 from 353

#

that's all then

#

thanks

#

.close

lone heartBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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fierce solar
#

if 3sin(x) + 4cos(x) = 5
deduce the value of sin (x)

fierce solar
#

I've tried dividing the equation by 5 and feel like i there might be a relation between it ans cos^2 + sin^2 = 1 but i cant go further

little drum
#

here's a hint: $$sin(x + A) = \cos A \sin x + \sin A \cos x$$

fierce solar
#

uh whats the dashthrough circle symbol i dont think I've taken it

gray isle
#

its the greek letter phi

ocean sealBOT
fierce solar
#

oh I'll to solve it and respond in a couple mins

little drum
#

wait a sec! I'm kind of curious

little drum
#

it can also go beyond 10 out of 10 tbh lol, your call

fierce solar
#

~6 i guess

little drum
#

oops

#

then here's what you could do:

#

$4 \cos x = 5 - 3 \sin x$

ocean sealBOT
little drum
#

square both sides and use (cos x)² = (1 - (sin x)²)

fierce solar
#

we've only taken a bit this year and the lesson was removed from last year's curriculum so they kinda crammed both years lessons and im kinda lost

little drum
#

then it's just a quadratic

lone heartBOT
#

@fierce solar Has your question been resolved?

fierce solar
#

still lost

#

i reached -9 = 25sin^2 -30sin

little drum
ocean sealBOT
little drum
#

$\implies 25\sin^2x - 30 \sin x + 9 = 0$

ocean sealBOT
little drum
#

right?

fierce solar
#

yeah

little drum
#

$\implies (5 \sin x - 3)(5\sin x - 3) = 0$

ocean sealBOT
little drum
#

$\implies \sin x = \frac{3}{5}$

ocean sealBOT
fierce solar
#

alright thanks i'll revise it whole then tell u if i understood the concept

#

alright all solved

#

thanks for your help

little drum
#

:D

#

before you leave, I have a curious question

#

is that your cat flying towards the camera? in your pfp

vague coral
#

maybe

alpine sable
#

Can anyone help me with this calculus integration

little drum
#

arctan transformation

little drum
ocean sealBOT
fierce solar
#

i'll leave now so i wont disrupt u helping

little drum
#

btw .close before you leave (@_@;)

fierce solar
#

.close

lone heartBOT
#
Channel closed

Closed by @fierce solar

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little drum
#

tyvm

lone heartBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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sharp glacier
lone heartBOT
sharp glacier
#

Hi

#

I need to have the same base

#

But I forgot how I can do that

#

When I have the same base I can substract the exponent

#

We did this a long time ago in class but I forgot how to do it

harsh swallow
#

don't you have the same base?

sharp glacier
#

No

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I have a 10 and a 2

harsh swallow
#

you have 5 x^m x^-2

sharp glacier
#

How

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I have a 10 and a 2

harsh swallow
sharp glacier
#

U want me to divide both by 2?

#

Do I write a + or a x between them lmao

harsh swallow
alpine sable
sharp glacier
harsh swallow
#

i didn't take the 5 into account the 5 is just in front

sharp glacier
#

Oh okay

harsh swallow
sharp glacier
#

Tysm

little drum
#

sylveon handwriting

sharp glacier
#

.close

lone heartBOT
#
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#
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sharp glacier
#

@harsh swallow quick question

lone heartBOT
sharp glacier
#

What is the right answer for this

#

When the base and exponent are the same

#

Do we multiply the base and add the exponents

#

Or just keep the bases as they are and add the exponents?

harsh swallow
#

$10x^{10m} * 10x^{10m} = 10 * 10 * x^{10m + 10m}$

ocean sealBOT
#

Katharine

sharp glacier
#

So it is 100x²⁰m

#

Thanks

#

.close

lone heartBOT
#
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harsh swallow
#

yes

alpine sable
#

Is this correct

#

for this question

harsh swallow
#

i can't read it :S

lone heartBOT
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ripe rain
#

$\lim_{x \to \infty}\frac {x (log x)^3} { 1+x + x^2}$

ocean sealBOT
ripe rain
#

Can we do it without l’hospital

alpine sable
ripe rain
alpine sable
#

bro I'm here before you

ripe rain
#

🙄

#

.close

lone heartBOT
#
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harsh swallow
#

@ripe rain can you reopen?

ripe rain
#

.reopen

lone heartBOT
#

harsh swallow
#

ok thanks

alpine sable
#

.reopen

harsh swallow
#

i'll ask you when we're done

alpine sable
#

bruh

harsh swallow
#

😄

alpine sable
#

okay

harsh swallow
#

,rotate

ocean sealBOT
#

Couldn't find an attached image in the last 10 messages.

harsh swallow
#

your du = isn't correct

alpine sable
#

finish deep and we'll discuss abt mine

harsh swallow
#

i asked him to reopen so that we can continue here

#

otherwise you'd have to open a new one

#

whole hasstle

alpine sable
#

Ur wish

harsh swallow
#

hassle

alpine sable
#

As u tell I will do

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what shld be my du is it 10/3?

harsh swallow
#

if u = 3x^2/10

alpine sable
#

yes

#

I took tht only

#

and maybe next step I made mistake

harsh swallow
#

lets start over

#

what is the thing you need to calculate

alpine sable
#

I shld find the calculus 2-integrals

lone heartBOT
#

@ripe rain Has your question been resolved?

#
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alpine sable
lone heartBOT
alpine sable
#

Why can't this equal zero???

hasty elk
#

...because that vector is non-zero...?

solemn grove
#

because it’s not zero?

solemn grove
#

you know how to find det of matrix right ?

#

i, j and k are unit vectors in this case,

#

by definition they’re non zero

alpine sable
#

I'm an idiot

#

Sorry

#

.close

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#
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old pelican
#

i just don't really know how to get the dimensions of the triangle

old pelican
#

help pls

#

"in the next shape the area for each hexagon is 12. calculate∆ABC's area

hasty elk
#

hint: start by figuring out the edge length of a hexagon

fallen sparrow
#

use the hexagon area formula

fallen sparrow
#

try to find the area of one small triangle

#

then add areas like -
12+ (6* area of one small triangle)

#

Area of a hexagon = (3√3* side*side)/2

lone heartBOT
#

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ripe rain
#

How do we show that Thomae function is continuous at all irrational numbers and discontinuous at all rational numbers

lone heartBOT
#

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lone heartBOT
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stiff hornet
lone heartBOT
stiff hornet
#

I need help with all parts

lone heartBOT
#

@stiff hornet Has your question been resolved?

stiff hornet
#

<@&286206848099549185>

lone heartBOT
#

@stiff hornet Has your question been resolved?

stiff hornet
#

someone help

tacit arch
stiff hornet
#

no

tacit arch
#

"data" means points of the form [(x1,y1), (x2,y2),...,(xn,yn)]

#

So all of the datum has probability 1/n

lone heartBOT
#

@stiff hornet Has your question been resolved?

lone heartBOT
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upbeat kayak
#

Given a f(x) what is a sufficient condition for one of the roots to be between two numbers(let's say 2<x1<-1) and the other not to be