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1 messages · Page 952 of 1

glad sluice
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close but no

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the total number of parts is a

zenith compass
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So a x (a-b)/b?

glad sluice
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still no

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let's go step by step

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first find this

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in 1 part, how much is wine and how much is water

zenith compass
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(a-b)/a?

glad sluice
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yep

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parenthesis though

zenith compass
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Ok

glad sluice
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so in 1 part, (a-b)/a is wine

zenith compass
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So the amount of wine in a gallon is a-b

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Umm so the amount of b gallons here is b(a-b)/a?

glad sluice
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yes

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and we remove b(a-b)/a from a-b (in the initial "a" parts)

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so final volume of wine is a-b-(b(a-b)/a)

zenith compass
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So $a-b-(b(a-b)/a)=a-b-b-b^2/a$

ocean sealBOT
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Trenton

zenith compass
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Then we divide it by a?

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So $(a-b-b-b^2/a)/a=1-2b/a-(b/a)^2$

ocean sealBOT
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Trenton

zenith compass
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Did I do sth wrong?

glad sluice
zenith compass
glad sluice
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take (a-b) common

zenith compass
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Oh

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(a-b)(1-b/a)=(a-b)(a-b)/a

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Oh

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I actually get it

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Thank you so much!!!!

glad sluice
lone heartBOT
#

@zenith compass Has your question been resolved?

lone heartBOT
#

@zenith compass Has your question been resolved?

zenith compass
#

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paper coral
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when doing partial fractions

lone heartBOT
paper coral
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for square root

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will it be a or waht

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let me give an exmaple

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is this correct?

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or square x has something to a

tacit arch
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you can't use partial fractions here

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In algebra, the partial fraction decomposition or partial fraction expansion of a rational fraction (that is, a fraction such that the numerator and the denominator are both polynomials) is an operation that consists of expressing the fraction as a sum of a polynomial (possibly zero) and one or several fractions with a simpler denominator.

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,w integral 1/(sqrt(x) (x^2 - 1))

paper coral
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oh i see

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what do i do after i get there then

tacit arch
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aren't you supposed to solve the integral yourself?

paper coral
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ye but the only thing i can think of is partial fractions

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is there something else i can do?

tacit arch
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i don't know how to get the solution, so i'd try trig substitution first, then maybe integration by parts

paper coral
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trig sub hmm

tacit arch
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there are 6, hopefully 1 of them works catthumbsup

paper coral
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alright thanks

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tacit arch
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Is this your recurrence
$c_n = 12 \cdot 11^{n-1} - c_{n-1}$, $c_2 = 12 \cdot 11 = 132$ ?

ocean sealBOT
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riemann

tacit arch
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can you write down the first 5 terms in the sequence ?

ocean sealBOT
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riemann

proud oriole
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wait, the base case is C2

ocean sealBOT
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riemann

proud oriole
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n >= 2

tacit arch
proud oriole
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do what?

tacit arch
proud oriole
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Do i need to know c1 though?

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Since n >= 2

tacit arch
proud oriole
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c2 = 12*11

tacit arch
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nope

proud oriole
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why

tacit arch
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plug in n =2

proud oriole
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right?

ocean sealBOT
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riemann

tacit arch
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.

tacit arch
proud oriole
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My question says don't use C1 and C0

tacit arch
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post the full question then

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that contradicts the use of $c_1$ here

ocean sealBOT
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riemann

tacit arch
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no

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just ask your question more clearly and provide necessary context

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you're not allowed to?

proud oriole
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no

tacit arch
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i never heard that before

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no

proud oriole
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ok

#

.close

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alpine sable
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I have found that A = 4/3 and r = 3 by doing 108 = ar^4 and 2916 = ar^7

alpine sable
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I have tried plugging in as Sn = (4/3(1-3^7))/(1-3)

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But it doesnt seem to be the answer

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what am I doing incorrectly?

pale kestrel
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You have gotten the indexes confused probably

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a4 = 108 = ar^4

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what exactly is this a?

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figure that out

alpine sable
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I did it by doing 2916/108 = r^3

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which is 27 = r^3

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and r is 3

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and plugging that into the function

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108 = a (3)^4

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and got a as 4/3

pale kestrel
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But what is a

near lagoon
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I think $a_k = a_1 r^{k-1}$, for $k \geq 1$

ocean sealBOT
pale kestrel
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or better, let me ask what a1 is

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in your working

alpine sable
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The first number that comes in the sequence?

pale kestrel
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what is a1 equal to

near lagoon
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So you should set 108 = a1 r^3, for instance

pale kestrel
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Its not a matter of which formulas is correct or whatever

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its being clear what your numbers/variables mean

alpine sable
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a1 should be the first number in the sequence

pale kestrel
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you decided an = ar^n

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it appears

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so what is a1

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you figured out a and figured out r

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You probably plugged a1 incorrectly into that formula

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It's not 4/3

alpine sable
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Then im not sure how to find a1

pale kestrel
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how did u get that formula for a3 and a7

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what did u write for each, you tell me

near lagoon
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Try out $$108 = a_1 r^3$$ $$ 2916 = a_1 r^6$$ @alpine sable

ocean sealBOT
pale kestrel
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bruh

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the issue isnt they picked the wrong formula

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They need to figure out what is wrong with the steps they tried

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Which is they dont seem to be clear on what a1 should be for what theyve written

near lagoon
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Their formula indeed is not wrong, they just need to use it accordingly

alpine sable
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For a4 i put 108 = a (r^4) and for a7 i put 2916 = a (r^7)

pale kestrel
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so what is a1 then?

alpine sable
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i cant find that without knowing the first number?

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? = a(r^1)

pale kestrel
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in terms of a and r of course

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exactly

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a1 = ar

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and you plugged in the wrong a1 earlier

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you thought a1 = a which is incorrect

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a would be the 0th term for what you have written

alpine sable
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then what step do i have to take to find a1?

pale kestrel
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???????

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Do you not understand your error

alpine sable
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3*4/3?

pale kestrel
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It requires you to plug in a1

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so plug in the correct a1

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which is ar

alpine sable
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Alright

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I understand

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Got it. Thank you

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.close

lone heartBOT
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raven spade
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My question is simple

lone heartBOT
karmic rapids
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what is your question?

raven spade
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how -1< x < 1 go to 0 < x^2 < 1?

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and then 2 < 2+x^2 < 3

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That's wrong right?

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I mean (-1)^2 = 1

grave matrix
raven spade
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ok

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let me get a photo

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for the question

grave matrix
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-1 < x < 1 implies 0 ≤ x^2 < 1

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not 0 < x

raven spade
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I don't get it?

grave matrix
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0 ≤ x < 1, not -as you've written- 0<x<1

raven spade
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Can you explain this?

grave matrix
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Note the bar under the <

raven spade
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yrs

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yes

grave matrix
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Right

raven spade
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how?

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This is right?

grave matrix
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The square of any real number is at least 0

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Draw the graph y = x^2

raven spade
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It's a parabola

grave matrix
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Between x = -1 and x = 1

raven spade
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Yeah

grave matrix
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Minimum of the parabola is...?

raven spade
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oh I get it

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yeah

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x^2 = parabola with vertex 0,0

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so the min is 0

grave matrix
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Yh

raven spade
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so

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if I always square I get 0 <= x^2 <= a^2

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consider a is the other number

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sorry fixed it

grave matrix
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Provided -a <= x <= a (assuming a is non-negative)

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yh

raven spade
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Oh

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Thank you

grave matrix
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nps

raven spade
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I got confused for a minute

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I have a major tomorrow

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wish me well

grave matrix
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Also, I think for comparison properties, you should use weak inequalities

raven spade
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weak inequalities?

grave matrix
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So start with -1 <= x <= 1 and continue

raven spade
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yeah

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that's what is in our textbook

grave matrix
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I always mess up the naming of weak (<=) and strong (<)

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But that's that

grave matrix
raven spade
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oh wait

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In this solve he used strong

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although the choses are in weak inequalities

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.close

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hasty gale
lone heartBOT
hasty gale
#

I understand the top equation

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I would just like to know

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what is linearization of f

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and why we need to add our equation of tangent plane to f(a,b)

tacit arch
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3 is just a definition

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$f(a, b)$ is just a point, not a plane

ocean sealBOT
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riemann

tacit arch
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the plane without $f(a, b)$ is a bad approximation to $f(x, y)$ at $(a, b)$

ocean sealBOT
#

riemann

lone heartBOT
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@hasty gale Has your question been resolved?

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lapis nest
#

does the set of solutions make sense

lone heartBOT
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@lapis nest Has your question been resolved?

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ocean sluice
#

Can i get help here

lone heartBOT
void niche
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What work have you done so far

ocean sluice
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got m =-1/3 and b =0 but im not sure

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@void niche

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oh both incorrect

tacit arch
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use implicit differentiation again

void niche
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Show work for us to be able to help

ocean sluice
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$2(x^{2}+y^{2})^{2} = 25(x^{2} - y^{2})\
4(x^{2}+y^{2})(2x + 2y\frac{dy}{dx}) = 25(2x - 2y\frac{dy}{dx})$

ocean sealBOT
#

Nix Valentine

ocean sluice
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$8x^{3}+8xy^{2} + (8x^{2}y+8y^{3})\frac{dy}{dx} = 50x - 50y\frac{dy}{dx}$

ocean sealBOT
#

Nix Valentine

ocean sluice
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$(8x^{2}y+8y^{3} + 50y)\frac{dy}{dx} = 50x - 8x^{3} - 8xy^{2}$

ocean sealBOT
#

Nix Valentine

ocean sluice
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$\frac{dy}{dx} = \frac{50x - 8x^{3} - 8xy^{2}}{8x^{2}y+8y^{3} + 50y}$

ocean sealBOT
#

Nix Valentine

ocean sluice
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,calc (50(3) - 8(3)^3 - 8(3)(-1)^2)/(8((3)^2)(-1) + 8(-1)^3 + 50(-1))

ocean sealBOT
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Result:

0.69230769230769
ocean sluice
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9/13

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Which is correct

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But i couldn’t get b

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$y + 1 = \frac{9}{13}(x - 3)$

ocean sealBOT
#

Nix Valentine

tacit arch
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What did you enter that said it was wrong

ocean sluice
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$y + 1 = \frac{9}{13}x - \frac{27}{13}$

ocean sealBOT
#

Nix Valentine

ocean sluice
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$y = \frac{9}{13}x - \frac{14}{13}$

ocean sealBOT
#

Nix Valentine

ocean sluice
#

so I entered -14/13

tacit arch
#

How did you get the second equation?

ocean sluice
tacit arch
ocean sluice
#

i subtracted 1 from both sides

tacit arch
#

,calc -27/13-1

ocean sealBOT
#

Result:

-3.0769230769231
tacit arch
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,calc -40/13

ocean sealBOT
#

Result:

-3.0769230769231
ocean sluice
#

I added 13 to -27 instead of subtracting 13

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dang

tacit arch
#

Stop ignoring minus signs

ocean sluice
#

-40/13 is it?

tacit arch
#

Minus signs have feelings

ocean sluice
#

yeah 💀

#

.close

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dry echo
#

What does "diverges" mean?

lone heartBOT
pale kestrel
#

not converge

vague coral
dry echo
#

lim as x approach infinity of cos(x)

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does not approach a value

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it diverges?

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Thanks!

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strange quartz
#

Hey, can I get help with this question please, Topic is Integration by Substitution.

I've got up to the final integration in terms of du, and am unsure of where to procceed from there, I can explain my working if neccacary,

Thanks

bright hedge
#

Hyperbolic arctan/ PFD

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Is what you should do from there

strange quartz
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because I don't think it's covered in my syllabus

bright hedge
#

Partial fraction decomp?

strange quartz
#

thats the next topic, but I'm not allowed to use that here

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if i gave you my simplified version

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sorry one second

bright hedge
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Well you get a 1/(4x^2 - 1)

strange quartz
bright hedge
#

I mean i guess you could do like a 2x = sec

vague coral
#

u = sqrt(x)
u² = x
du = dx/2u
no need for partial frac

strange quartz
#

2/ 4x^2 - 1

bright hedge
#

Yes ik

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so from here you could do a trig sub

strange quartz
bright hedge
#

or PFD (I recommend)

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No u hav the right integral

strange quartz
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oh okay

bright hedge
#

He was thinking I was talking abt PFD with the sqrt

vague coral
strange quartz
vague coral
#

derivative of sqrt is 1/2sqrt(x)

bright hedge
#

You are both wrong

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It is 1/(2sqrt(x))

strange quartz
bright hedge
#

Lol

strange quartz
#

i thoguht the power decreases too

strange quartz
#

thats what i said

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xD

bright hedge
#

Nah parenthesis misuse

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Oh wait nm

strange quartz
#

ah, I'm not good at simplifying it while typing xd

vague coral
bright hedge
#

Anyways teach verified how to do 1/(4x^2 -1) with no PFD or hyperbolic arctan

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Or find some other cool way to do this

strange quartz
#

I'll send my working

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its a bit messy but

vague coral
#

when you let u = sqrt(x), you have 2u/(u(4u²-1))

strange quartz
strange quartz
strange quartz
vague coral
#

ye

strange quartz
#

and now i'm left with

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2/(4u^2 -1) to integrate

vague coral
#

well partial frac I guess

strange quartz
#

how so

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like

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ohhh

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ohhhhhh

vague coral
#

4u² -1 = (2u)²-1² = (2u-1)(2u+1)

strange quartz
#

so i need to find the numerators of the partial fractions now

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?

vague coral
strange quartz
#

I do haha

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just making sure

vague coral
#

$\frac{1}{(2u-1)(2u+1)} = \frac{A}{2u-1} + \frac{B}{2u+1}$

ocean sealBOT
#

Herels

strange quartz
#

yup

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A(2u+1) + B(2u-1) = 1

vague coral
#

A = lim (u>1/2) 1/(2u+1) = 1/2

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B = lim (u>-1/2) 1/(2u-1) = -1/2

strange quartz
#

okay i got the other way around

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somehow

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A = -1/2, B = 1/2

vague coral
#

,wolf \frac{-1/2}{2x-1}+\frac{1/2}{2x+1}

strange quartz
#

hm

vague coral
#

I just want the result but whatever

strange quartz
vague coral
#

recheck your calculations

strange quartz
#

will do

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ah yes

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I

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swapped the wrong place

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makes sense

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A = 1/2, B = -1/2

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yup

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so the final is

vague coral
#

now integrate and dont forget that u = sqrt(x)

strange quartz
#

1/2(2u-1) - 1/2(2u+1)

strange quartz
#

ln(3) - 1/2 ln (5)

vague coral
#

im too lazy to verify, just use wolframalpha

strange quartz
#

xD

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thanks for the help anyways

vague coral
#

np

strange quartz
#

.close

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tawdry jolt
#

I'm quite stuck when writing a negated universal statement symbolically

tawdry jolt
#

No vegetarians eat meat.

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Should I define vegetarians and "eats meat" as separate variables?

#

I got this:

Let V = The set of all vegetarians
Let M = “eats meat”
∀ x ∈ V, ~M(x)
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But I'm not very confident.

mint shoal
#

no

formal cloud
#

yes

tawdry jolt
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What?

mint shoal
#

its a yes and no right?

tawdry jolt
#

No

formal cloud
#

yes

tawdry jolt
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No it's not

mint shoal
#

no ur question

formal cloud
#

jk lmao

#

only use one

tawdry jolt
#

I'm asking how to write something symbolically

mint shoal
#

ye

formal cloud
#

donyt overcomplicate

tawdry jolt
#

So how should I do it then?

formal cloud
#

this html right?

tawdry jolt
#

I'm actually trying to do this whole syllogism:

No vegetarians eat meat.
All vegans are vegetarian.
∴ No vegans eat meat.
#

No

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Discrete math

formal cloud
#

sheisse

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im dumb as hell

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thats your problem

lone heartBOT
#

@tawdry jolt Has your question been resolved?

tawdry jolt
#

I tried and got this:

Let P = “vegetarians”
Let Q = “vegans”
Let M = “does not eat meat”

P → M
Q → P
∴ Q → M
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But what type of argument is that?

tawdry jolt
#

It's not?

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Oh, I need to swap P and Q in line two

tawdry jolt
#

This should be transitivity

pulsar aspen
#

Yes, it's transitive property of implication.

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In Curry Howard correspondence, it corresponds to function composition.

tawdry jolt
#

Okay, cool

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Thank you

#

Now for the proofs D:

#

.close

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lapis forge
#

Had a controversial question on a quiz. Plane starts at 0m/s and ends at 100 m/s. The distance is 2.5 x 10^3 m. Sorry had this question on a different help chat but it got closed.

limpid flame
#

What is it asking for?

lapis forge
#

Sorry, average lowest acceleration

blissful whale
#

lowest acceleration?

lapis forge
#

Just the average

#

People I talked to got 0.04 or 2

bleak ridge
#

Is it a calc class?

lapis forge
#

Physics

bleak ridge
#

Kinematic formulas?

lapis forge
#

Yeah

bleak ridge
#

Which one would you use

lapis forge
#

If you use kinematics u get 2 but if u do 0.04 * 2.5 x 10^3 u get 100

blissful whale
#

distance = acceleration * time²/2
and
velocity = acceleration * time

bleak ridge
#

m/s^2 * m = m^2/s^2

#

Which isn't really useful in this case

lapis forge
#

It was multiple choice

#

1 of the answers was 0.04

bleak ridge
#

They prob said that to make sure people were actually solving it

#

Not just making a guess with a little bit of evidence from the choices

lapis forge
#

So the answer is 2?

blissful whale
#

Just compute it yourself.

#

Idk, have you cruncehd the numbers?

lapis forge
#

Yeah

blissful whale
#

By rearranging the equations you should get: distance = 1/2 velocity * time

#

and time = 2 distance / velocity. Then plug in secodn equation and get
velocity = 2 acceleration * distance / velocity
acceleration = velocity² / (2 distance)

lone heartBOT
#

@lapis forge Has your question been resolved?

blissful whale
#

,wolf (100m/s)²/(2 * 2.5km)

lone heartBOT
#
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nimble frost
#

i have a double integral, main function is y^{1/2}cos(y)dydx
with x from 0 to 1 and y from x^2 to 1

nimble frost
#

I am trying to reverse the order of the bounds

#

to my understanding the upper bounds will both still be 1

#

but x's lower bound would be y^1/2 i think?

#

and y's would be 0??

#

this is what i have so far

blissful whale
#

$$\int_0^1 dx \int_ {x^2}^1 dy \sqrt{y} \cos(y)$$

ocean sealBOT
glass lichen
nimble frost
#

im doing that in desmos atm

blissful whale
#

You must reverse integral signs if you revers oerder of bounds.

nimble frost
#

ok i at least have the order of my bounds correct now i think?

#

to my understanding the region would be between the four lines

glass lichen
#

the 4 curves defining the region are the bounds

blissful whale
#

You start with (x,y) such that y>x². Then sqrt(y)>x.

glass lichen
#

Not the integrand

blissful whale
#

I think you should integrate 0 to sqrt(y)

#

not sqrt(y) to 1.

nimble frost
#

ah yeah because its sideways i see what you mean

glass lichen
nimble frost
#

so the region of integration would be the entire space between the 4 bounds

#

?

glass lichen
#

it'd be the purply area

nimble frost
#

because the original function doesnt impact the region of integration>

#

i think thats what im getting hung up on

glass lichen
#

The integrand has nothing to do with the region, no

nimble frost
#

this is starting to look better i think

#

looking it over in desmos it seems correct?

glass lichen
#

yes

nimble frost
#

thank yall for helping explain it to me

#

for some reason i really struggle with bounds so ty

mellow sphinx
nimble frost
#

thanks guys

#

.close

lone heartBOT
#
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lone heartBOT
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exotic moth
#

Hello can someone check my answers if it's correct thank youuu

tacit arch
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exotic moth
lone heartBOT
exotic moth
# tacit arch Can't check your work without the questions
  1.   The scores on a Physics long test follow a normal distribution with a mean of 48 and a standard deviation of 3. Find the probability that a randomly selected score is above 50.
    
  2.   The scores on a History test follow a normal distribution with a mean of 48 and a standard deviation of 4. Find the probability that a score randomly selected is below 45.
    
  3.   What is the probability that Marco spends at least 240 min on online gaming if his mean time spent on it is 270 min with a standard deviation time of 15 min?
    
  4. The mean walking time of Louie to school is 20 minutes with a standard deviation of 2.5 min. What is the probability that he walks to school in not more than 18 min?
severe sluice
exotic moth
severe sluice
exotic moth
lone heartBOT
#

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lone heartBOT
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smoky gale
#

If i have a circle inscribed in a equilateral triangle and i know the sides of triangle. Can i find how the sides are divided by the touch points of circle and triangle?

lone heartBOT
#

@smoky gale Has your question been resolved?

severe sluice
sterile idol
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vale pulsar
#

b+a = 5
a-c = 3
bc - ac + c^2 - ab = ?

lone heartBOT
stoic hound
#

Note that squaring the second equation gives you a^2-2ac+c^2 = 9, and multiplying the two given equations gives you a^2-ac+ab-bc=15. Can you get to the desired expression using these two new pieces of information?

lone heartBOT
#

@vale pulsar Has your question been resolved?

vale pulsar
#

It's so easy but I got stuck in it.

raven rover
#

Do you have work for us to look at?

covert agate
vale pulsar
covert agate
#

$\begin{cases}
b + a = 5 \
a - c = 3
\end{cases}$

ocean sealBOT
#

Chromium

covert agate
#

correct?

vale pulsar
#

Yup

covert agate
#

you were suggested to square both equations

#

$\begin{cases}
(b + a)^2 = 25 \
(a - c)^2 = 9
\end{cases}$

ocean sealBOT
#

Chromium

vale pulsar
#

Yessss.
I could do it.
It should be -6, right?

lone heartBOT
#
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ashen vale
#

How??

raven rover
#

Do you have work?

ashen vale
#

I stuck at 2c-4a-30

lone heartBOT
#
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ashen vale
#

How could Tanjiha find the answer lol

lone heartBOT
raven rover
#

?

ashen vale
#

?

hasty elk
#

?

vale pulsar
ashen vale
#

Oh I got it now

#

Tysm

#

Is this an easier way??

covert agate
#

oh yea

#

it is

ashen vale
#

Okay

lone heartBOT
#

@ashen vale Has your question been resolved?

#
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swift basalt
#

please someone help me

lone heartBOT
swift basalt
#

please help me <@&286206848099549185>

wide raven
#

dude 15 mins

raven rover
swift basalt
wide raven
covert agate
#

that's the server rules

swift basalt
covert agate
#

before pinging...

wide raven
#

see T can take values 0, 1, 2, 3

#

you need to find how many possibilities for each

#

and then plot

lone heartBOT
#

@swift basalt Has your question been resolved?

swift basalt
#

help me

#

someone

#

please

#

<@&286206848099549185>

#

PLEASE HELP ME

tacit arch
swift basalt
swift basalt
#

GELP EME

#

HELP ME

#

HELP ME

#

PLSSSS

#

HELP

#

<@&286206848099549185> if anyone answers my question i will pay $10

alpine sable
#

ok

#

but there is no question

zenith compass
#

Don’t try to pay anyone for helps

alpine sable
#

I am purchasable, but only for 1 million dollars+ (per problem rate)

misty dagger
#

😍

zenith compass
#

Lmao

severe sluice
# swift basalt can you help me

try listing all the possible outcomes and their probabilities. assume coins are distinct (i.e. HTT is different from THT).

swift basalt
alpine sable
#

I mean still no question

swift basalt
alpine sable
#

you posted a problem, not a question

severe sluice
swift basalt
swift basalt
alpine sable
#

But not really a question, it doesn't illustrate what you want us to do

severe sluice
#

aside from the fact that you're a weirdo for putting the taskbar at the top of the screen, the table seems correct

swift basalt
severe sluice
#

no offense :\

swift basalt
severe sluice
#

bar graph?

swift basalt
swift basalt
severe sluice
#

list the outcomes on x-axis and the probabilities on y-axis and then draw bars

alpine sable
#

those bars better be sick

swift basalt
#

i mean all the results i will put on the grapgh or what

alpine sable
#

try it and post

swift basalt
alpine sable
#

looks good, although depending on how pedantic your teacher is the areas of the bars have to add up to 1

misty dagger
#

Is that window 11?

lone heartBOT
#

@swift basalt Has your question been resolved?

swift basalt
#

what is standard deviation?

swift basalt
#

<@&286206848099549185>

lone heartBOT
#

@swift basalt Has your question been resolved?

swift basalt
swift basalt
median dirge
#

Hey.

#

@swift basalt

swift basalt
#

hello

swift basalt
#

can you help me?

median dirge
#

Which ques.

swift basalt
#

im struggling finding the answer

#

@median dirge

#

please help me

#

😦

#

<@&286206848099549185> please help me please please please

median dirge
#

@swift basalt

swift basalt
#

please help me

swift basalt
median dirge
#

I wont find out your answers

swift basalt
median dirge
#

Come in a VC

swift basalt
#

why??

median dirge
#

8kbps

#

i'll stream

#

And remember

swift basalt
#

no i need the answers just type it here

median dirge
#

Dont abuse

#

The ping

swift basalt
#

ik

median dirge
#

And yes, we dont give away answers

swift basalt
#

can u tell me how to type it on calculator because i tried it and no results

median dirge
#

There are homework servers for that

swift basalt
#

what should i put

#

its not homework its exercise for us

#

we literally get no grades in this question lol

median dirge
#

I mean.

#

Then why

#

Are you in so much of a hurry to get answers

swift basalt
#

because i need to find out how to answer it

#

teach me

median dirge
#

Thats what I am saying

#

Ill show you

#

how to answe

#

But not "the answer"

swift basalt
#

just explain it here

median dirge
#

Okay

swift basalt
#

okay okay i get it u wont tell me the answer its okay

median dirge
#

No worries

#

Look

swift basalt
#

just tell me how to get the answer

#

ill be the one to solve

median dirge
#

The question you have

#

Is a piecewise function

swift basalt
#

all i did is put that problem and replace x

#

but no results

median dirge
#

So for all x values less than 0. It has a y-value of 2x-5
And for all x values equal to or greater than 0. It has a y-value of x+7

swift basalt
#

someone told me that i should write it like 2x(-1) then the result are -7

#

is it correct?

#

also i need solutions

median dirge
#

So first of all you see how the function looks like

swift basalt
median dirge
#

This is how the graph looks like

swift basalt
#

what do i need to do

median dirge
#

So tell me

#

What should be the limit of the function

#

At x= -1

swift basalt
#

wait

median dirge
swift basalt
#

-1?

median dirge
#

At x=-1

swift basalt
#

1

median dirge
#

What is the limit of this function

swift basalt
#

wait

#

20

#

20?

median dirge
#

How did you get that

swift basalt
#

i think 0

swift basalt
#

i have a answer but no solution because i use the calculator

#

wait my first answer is -7,-6,-0.5x,-0.02x,-0.002x

#

so i should rmeove the x then all the answers are ok now?

#

yes i have done but not this way

#

we dont use graph in solving the limits

#

wait dont erase im going to write what u write

#

okay i get it now thanks

lone heartBOT
#

@swift basalt Has your question been resolved?

tacit arch
#

.close

lone heartBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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fallen bane
#

Hey I was wondering if someone could tell me what kind of algorithm I would use to calculate the best path to target from start position
the blue line is path we wanna find
the black line's are walls that we want to ricochet off to the target position

peak kernel
#

Ok

#

So I want to learn more trigonometry

#

Where can I find that

ebon condor
#

Idk about best path

#

Is this mathwise or computational

manic wind
#

What is "best path"

ebon condor
#

There's a way you can find any path?

#

but it would include some trial and error

#

everyone is typing but no one is saying anything

#

okay if yall need help you can @ me

alpine sable
still elbow
# manic wind What is "best path"

for example using something like A* search algorithm to find best path to target object but we want to do this based on ricochet so we have the ability to change direction once it hits something (I.E a wall) but we don't know how calculate it using ricochet or even if this is the correct algorithm to use

fallen bane
#

yes

ebon condor
#

yeah idk about the shortest path guaranteed

#

but you can find a short path

#

Here's an iterative algorithm

#
  1. test if you can reach target
  2. if yeah cache result
  3. reflect all targets across each surface
  4. test if you can reach target
alpine sable
#

Don't Memorize

lone heartBOT
#

@fallen bane Has your question been resolved?

#
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lone heartBOT
#
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neon garden
lone heartBOT
neon garden
#

cant figure it out

pale kestrel
#

Consider the complement

neon garden
#

what does that mean

pale kestrel
#

look it up

#

complement probability

neon garden
#

is it some american term?

pale kestrel
#

Its english.

#

,w complement

neon garden
#

so just this?

pale kestrel
#

well yes

#

so the complement probability im referring to

#

is the probability of the complement event

neon garden
#

1/2?

pale kestrel
#

???

neon garden
#

what lol

pale kestrel
#

when in that very specific example you screenshotted then yes

#

but not in your original question

neon garden
#

ive never heard of what you're talking about are you asking for the probability of heads/tails

pale kestrel
#

What is the complement event in the q

#

In fact what is the event that happens in the Q, first of all

neon garden
#

(1/2)^2?

pale kestrel
#

????

neon garden
#

idk thats what i was wondering

pale kestrel
#

what?

neon garden
#

jesus chill

pale kestrel
#

What level of math are you taking

#

Has probability not been defined in terms of events

#

for you?

neon garden
#

idk what it is in the american system

#

year 11

#

so 10th grade maybe?

#

idk im not the best

pale kestrel
#

The event in the question is:

'Pat gets at least 1 head and at least 1 tail'

#

Im not from america either

pale kestrel
neon garden
#

yes

pale kestrel
#

ok now the complement of this event

#

is like the opposite

#

the event not happening

neon garden
#

so what would the opposite of that be?

pale kestrel
#

'Pat gets at least 1 head and at least 1 tail'

#

Think

#

if this doesnt happen what

neon garden
#

is it all heads

#

or all tails?

pale kestrel
#

correct

#

'Pat gets all heads or all tails'

#

is the complement

#

Have you been shown probability in terms of sets?

abstract fractal
#

I was gonna say "isn't it no heads or no tails" but then I realized I'm stupid lmao

pale kestrel
#

We might let the set A represent 'Pat gets at least 1 head and at least 1 tail'

#

The question wants P(A)

#

And I suggested to instead work out $P(A^c)$

ocean sealBOT
#

Shuri2060

pale kestrel
#

Do you know how $P(A)$ and $P(A^c)$ are related to each other?

ocean sealBOT
#

Shuri2060

pale kestrel
#

A^c means the complement of A

neon garden
#

well you said they are opposites right?

#

yeah

pale kestrel
#

right

neon garden
#

ok ill try and figure it out gimme a sec

pale kestrel
neon garden
#

is it that

#

wait

#

1-((1/2)^n+(1/2)^n)

pale kestrel
#

yes

#

The probabilities add to 1

#

if 2 events are complement

neon garden
#

.close

lone heartBOT
#
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#
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Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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plucky void
#

Can anyone solve this : (((l*q)+6)/l) = 98
l=___
q=___

ionic hazel
#

i am not the best at maths but i can try and tell you what i did if it helps

plucky void
#

k

ionic hazel
#

i multiplied by I to get (I*q)+6 = 98I

#

then divided to get q + 6/I = 98

#

didn't really do much

#

but it's in a better form

#

now this is a reciprocal graph

alpine sable
#

now you can see that there are infinitely many solutions

ionic hazel
#

can use q and I on x and y

plucky void
ionic hazel
#

can just put a q value in and get an I value that works

alpine sable
#

if you want one solution set q = 0 and solve for l

ionic hazel
#

q = 98 - 6/I

plucky void
plucky void
ionic hazel
#

so for example, when q=6, I = 97

#

98 - 6/6 = 97

plucky void
#

I simplified it to (l+6)/l=98, by setting q as 0

#

But how can you go further

ionic hazel
#

multiply by I

#

then you get I+6 = 98I

plucky void
ionic hazel
#

subtract I

#

6 = 97I

#

then divide by 97

#

and you get I = 97/6

ionic hazel
plucky void
wary stream
#

Perhaps watching videos on solving equations is a good start

#

To understanding

plucky void
#

can you make (l+6)/l=98, l+6=98*l

ionic hazel
#

no

wary stream
#

No

ionic hazel
#

now you can

plucky void
#

I edited it

wary stream
#

Now that edited version is correct

plucky void
#

I typed by mistake

#

k

ionic hazel
#

yeah. now you need to get all the I's together

plucky void
#

I think it is easier to solve now

ionic hazel
#

you have 98I on right side and 1I on left side

#

so if you subtract 1I from both sides, you get 6 = 97I

plucky void
#

Ya, now I got you

ionic hazel
#

great!

plucky void
#

l=(6/97)

#

Am I correct

#

l=0.0618556701030928

wary stream
plucky void
#

I used calculator for this

ocean sealBOT
#

dldh06

plucky void
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I set q to 0

wary stream
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Yes, and what you said was wrong as I mentioned

plucky void
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Let me check

wary stream
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You don't get $$\frac{l + 6}{l}=98$$ if q = 0

ocean sealBOT
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dldh06

plucky void
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Oh sorry, I set q to 1

wary stream
plucky void
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K

wary stream
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Don't use decimals because fractions are more exact

plucky void
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Ya

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I learned a lot from asking this question

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Thanks

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.close

lone heartBOT
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Channel closed

Closed by @plucky void

Use .reopen if this was a mistake.

#
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wooden sapphire
lone heartBOT
wooden sapphire
#

d(1/x)/dx = 1 because

d(1/x) = 1/h, d(x) = h, so (1/h /h) = 1

alpine sable
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is this exercise correct?

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I'm so confusing,i think the teacher make some mistake when she typing this

wooden sapphire
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so what's going on here?

distant flare
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d(1/x)/dx is the derivative of 1/x

wooden sapphire
#

yes

distant flare
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which is the same as x^(-1)

alpine sable
wary stream
wooden sapphire
#

and how do you get that from this diagram?

distant flare
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using power rule, you get -1/x²

wooden sapphire
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I'm not using the power rule

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I'm using this diagram

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why am I too stupid to figure this out?

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I've been staring at this for hours

buoyant kayak
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probably because you're trying to find a derivative using a graph with no points

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and getting a numeric answer?

wooden sapphire
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why does 3b1b tell you to do it then?

wary stream
# wooden sapphire

This is part of a video, if you're questioning about d(1/x)/dx equals what, if you continued in the video, wouldn't it tell you the answer?

wooden sapphire
#

no

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he doesn't explain it

distant flare
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so

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what the derivative is

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is basically the slope of a function

wooden sapphire
#

I understand

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what a derivative is

distant flare
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so how much y changes to x

buoyant kayak
#

what video is this?

wooden sapphire
#

Some common derivative formulas explained with geometric intuition.
This video was sponsored by Brilliant: https://brilliant.org/3b1b
Help fund future projects: https://www.patreon.com/3blue1brown
An equally valuable form of support is to simply share some of the videos.
Special thanks to these supporters: http://3b1b.co/lessons/derivatives-powe...

▶ Play video
buoyant kayak
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ah

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so your goal is to get $\frac{d(\frac{1}{x})}{d(x)}$

ocean sealBOT
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a disappointing son

buoyant kayak
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geometrically

wooden sapphire
#

yes

buoyant kayak
wooden sapphire
#

I'm gonna put my logic here. Tell me what you think. dx is a distance, h. d(1/x) is another distance 1/h, so d(1/x)/d(x) is 1/h /h or just 1.

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but... that doesn't make any sense

buoyant kayak
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i'm not sure how you reason d(1/x)=1/h

wooden sapphire
#

I'm not sure how I keep getting it either

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dx is h right?

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you can just

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say it's a distance

vale sapphire
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d(x²) ≠ dx²

buoyant kayak
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you could assign dx to h if you'd like, however i don't see that helping

wooden sapphire
#

so d(1/x) is 1/h

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right?

buoyant kayak
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no

wooden sapphire
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why

buoyant kayak
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i'm still unsure how you're arriving there

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d(1/x) is the change in height of the rectangle he drew

wooden sapphire
#

yeah

buoyant kayak
#

he's saying the area of that rectangle must be equal no matter how you change dx or d(1/x)

wooden sapphire
#

yes

vale sapphire
#

d(1/x) is asking the question "if i change x by an arbitrarily small amount, how does 1/x change"?

buoyant kayak
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so area of a rectangle is width * height

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height in your example being..?

wooden sapphire
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the function is 1/x, so if you plug in h, you get 1/h right?

buoyant kayak
#

sure but h is just a randomly assigned variable

wooden sapphire
#

yeah

buoyant kayak
#

d(1/x) does not mean plug in h for x in 1/x

vale sapphire
#

d of something is not plugging another value in

wooden sapphire
wooden sapphire
#

that's what's geometrically shown

buoyant kayak
#

no it ain't

wooden sapphire
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it's a Y distance

buoyant kayak
vale sapphire
#

yeah, but that doesn't mean it's the y distance you get when plugging in dx

wooden sapphire
#

oh wait

buoyant kayak
#

he shows d(1/x) as the change in height of the rectangle that occurs when you have a small change in x

vale sapphire
#

(also, note d(1/x) is negative here)

buoyant kayak
#

3b1b points that out already

vale sapphire
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if you slightly increase x, 1/x should slightly decrease

wooden sapphire
#

okay so

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the corner of the red rectangle

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to the corner of the green rectangle

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is dx

vale sapphire
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horizontally

wooden sapphire
#

yeah

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I can't figure out why we're disagreeing

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that

vale sapphire
#

Say dx is really small, like 0.1

wooden sapphire
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what you plug in

buoyant kayak
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you're not plugging in anything

vale sapphire
#

1/dx = 10

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Do you really think 10 is the height of that rectangle

wooden sapphire
buoyant kayak
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we're not

wooden sapphire
buoyant kayak
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we're not getting values

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we're expressing it in terms of the function

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f(x)=1/x

wooden sapphire
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I understand I'm wrong

vale sapphire
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Let me go the physicist route for this

buoyant kayak
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talk about muddying the waters

vale sapphire
#

Yeah well i don't think the formalism helps here

buoyant kayak
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do you want me to tell him to go ahead and plug in numbers

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cause you're not supposed to do that

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all 3b1b is saying is that the area of the red rectangle must equal the area of the green rectangle

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that's literally it

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and he already labels the length and width of both rectangles