help-0

[little drum]

Got it!? @raw sleet

[raw sleet]

got it

[little drum]

And lastly... we'll have to use Wolfram to calculate the product 4 times 9 times 1/2 because it's not possible by hands... and get the limit as

,w 490.5

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ansh#3502

[raw sleet]

18

:0

[little drum]

18 let's gooo

[raw sleet]

i hate university

lol

[little drum]

No wowwies

you're gonna be here soon too :P

[raw sleet]

oof

[lone heart]

@raw sleet Has your question been resolved?

Channel closed

Closed by @raw sleet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[royal meadow]

can i just get a quick check

wait no i'm a fool

[lone heart]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fervent sonnet]

Is this right ?

[tacit arch]

what's your logic here?

[fervent sonnet]

Adding up the scores of both colleges ?

[tacit arch]

How did you come up with the numbers?

the way the question's phrased, they're looking for a general formula, nothing to do with the actual outcome of a single game

[fervent sonnet]

Well I don’t know

What would the general formula be ?

Just S =?

[tacit arch]

If my team only scores 30 free throws and no baskets in a game, what's S?

If my team only scores 15 2 pointers in a game, what's S?

If my team only scores 10 3 pointers in a game, what's S?

[little drum]

If my team scores a free throws, b two pointers and c three pointers, what's S?

[fervent sonnet]

Ok

I think I got it

So would it be this ?

[lone heart]

@fervent sonnet Has your question been resolved?

[fervent sonnet]

<@&286206848099549185>

[wet trellis]

k ngl I'm a baseball guy and not 100% sure on basketball points

BUT

let's try

can you tell me how many points UCONN scored with just 2 point baskets?

[fervent sonnet]

Im not 100% sure I’m kinda lost now

[wet trellis]

all good

start from just the problem you gave me

there were 25 baskets worth 2 points each

how many points is that?

[fervent sonnet]

Man tbh I gave up, tmr when I wake up I’ll get one of my friends to help me out since she already finished it

It’s 2 am I’m trying to go to sleep

[tacit arch]

sleep's very important for doing math

[fervent sonnet]

Indeed

[tacit arch]

feel free to .close

[fervent sonnet]

Alright

Thank you @tacit arch and @wet trellis

.close

[lone heart]

Channel closed

Closed by @fervent sonnet

Use .reopen if this was a mistake.

[tacit arch]

and @little drum

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[muted island]

how do i do this

what i know is addition and subtraction does nothing to variance

so the multiplication of 4 makes me wonder how should i do i

it*

[tacit arch]

data = x_i

new_data = 4(x_i + 3)

var(aX+b) = a^2 var(X)

https://en.wikipedia.org/wiki/Variance#Basic_properties

[muted island]

oh

thanks

.close

[lone heart]

Channel closed

Closed by @muted island

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plain spoke]

how can this be solved?

ik im supposed to use "nth terms of a geometric sequence formula" and "the sum of an infinite geometric sequence formula"

[echo socket]

In geometric series b_n = b_1*q^(n - 1), where b_1 is the first term and b_n is nth term and q is some number

So here it says that b_2 = b_1*q = 2 and b_6 = b_1 * q^5 = 8

So you have these two equations to solve
b_1q = 2
b_1q^5 = 8

What I'd recommend is rewriting b_1*q^5 as

[plain spoke]

yes

[echo socket]

b_1 * q * q^4

[plain spoke]

am why?

[echo socket]

Because we know that b_1 * q is

It's 2

So b_1 * q * q^4 = 2q^4 = 8

q^4 = 4

[plain spoke]

oh oh yea

that makes sense

[gray isle]

this is sort of a poor question

[plain spoke]

how do i solve it afterwards?

[echo socket]

Just solve for q in q^4 = 4 and then for b_1

[plain spoke]

can i get a value of q^4 = 4 without using calculator

[gray isle]

yes, use exact values, don't feel the urge to give decimal approximations

[echo socket]

Yeah, using 4th root

And don't forget to put the plus or minus sign, although in some questions you may have to choose between positive or negative so that the original equations all make sense

[plain spoke]

ohhh i see

ill try solving it and if im stuck again ill come back

thank you!!!!

.close

[lone heart]

Channel closed

Closed by @plain spoke

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zenith compass]

If the living area of this particular house falls above the 75th percentile in the market. What would be the minimum value of this house's living area?

[zenith compass]

Sorry I don’t even know how to attempt this question

Though I know the 75th percentile

Which is 2223

But how to relate it to the minimum value? Or what does this actually mean?

I wonder if the minimum value is simply referring to the 75th percentile

[lone heart]

@zenith compass Has your question been resolved?

[zenith compass]

<@&286206848099549185>

[tacit arch]

It's just 2223

[zenith compass]

Ok thank you Riemann

.close

[lone heart]

Channel closed

Closed by @zenith compass

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[icy kraken]

Ask:
can someone help me figure it out?
Question: While at race track, a person bets on each of the 9 horses in a race to come in accordance to how they are favoured. Total ways in which the horses reach the finish line so that he loses all his bets is

I know the total number of ways would be 9! for all possible outcomes but how do i figure out how the horses lose

This was part of my university and I randomly guessed since i didnt know how to solve it. The question paper is over so just looking for some guidance and had missed a few lessons due to IRL issues

[lone heart]

@icy kraken Has your question been resolved?

[icy kraken]

<@&286206848099549185>

[lone heart]

@icy kraken Has your question been resolved?

[lone heart]

@icy kraken Has your question been resolved?

[hasty elk]

have you heard of derangements?

@icy kraken

[icy kraken]

yes but i am not familiar with it must have missed that lesson

[hasty elk]

a derangement is a permutation where every element doesn't remain in the same place

for for instance, 1 2 3 --> 3 1 2 is a derangement

and 1 2 3 --> 1 3 2 is not a derangement

[icy kraken]

ah ok will go through derangement videos on youtube and give it a try thanks i was using permutation and combination but wasnt working

[hasty elk]

yes, there's a simple formula for it, but you need inclusion-exclusion to understand where it comes from!

have fun!

[icy kraken]

thanks ❤️

[icy kraken]

Ohh I did it wish I could award you lol. Thanks again

[alpine sable]

ayo i need help with a math questio

[icy kraken]

.close

[lone heart]

Channel closed

Closed by @icy kraken

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[waxen harness]

How do you write the base of this trapezoid? Would you say line BC and line AD?

[slender gull]

Just say BC and AD.
If really necessary say line segment.

[waxen harness]

Thank you very much.

.close

[lone heart]

Channel closed

Closed by @waxen harness

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner hinge]

Answer is k > 40 and k < 0. Plz explain how

[inner hinge]

I am doing question 13

[covert agate]

do you know determinant

[inner hinge]

No

Are you talking about the discriminant?

[slender gull]

@inner hinge

Do you know what discriminant is?

[inner hinge]

Yes

[pale kestrel]

They mean discriminant

[inner hinge]

Yea so I got the answer k>40 but it was also k<0 anyone know why

[pale kestrel]

what is the discriminant?

and how did you get k > 40

[inner hinge]

This is my working out

[slender gull]

So what is the issue?
Take union good day.

[inner hinge]

The top is the original ewuation and the bottom is my working

I only got k>40

[slender gull]

oh i see.

[pale kestrel]

stop

[slender gull]

Me?

:'(

[pale kestrel]

Why did you divide by k @inner hinge

[inner hinge]

Cant I do that?

Do I have to swuare root

[pale kestrel]

You can.

[slender gull]

Not in inequalities.

[pale kestrel]

If you can justify it

[slender gull]

With variables.

[slender gull]

[inner hinge]

Wdym justify

[slender gull]

Make cases.

[pale kestrel]

Give a mathematical reason why dividing is ok

Let me give an example, what if k = -1?

[inner hinge]

Because it got k on its own and that’s what I’m trying to find

[pale kestrel]

You should know that inequalities are flipped when dividing by negatives

[inner hinge]

Yea but I didn’t divide by negative

[pale kestrel]

Why is k non-negative?

[slender gull]

k could be negative!

[surreal canyon]

helping math i dont think i cant help that much but im helping till 8th grade 1st sem lmao

[inner hinge]

K?

[inner hinge]

How

[surreal canyon]

mhm

[slender gull]

k is a variable.

it could be any real number.

[pale kestrel]

why can k not be negative?

[inner hinge]

Ok so what should I have done

[pale kestrel]

I am asking how not

[inner hinge]

Idk

[pale kestrel]

k also could be 0

Then you definitely cannot divide

see the problem

[inner hinge]

Oh

So if it was 0 then it wouldn’t work

[pale kestrel]

what you need to do instead is to factorise

or split cases

[inner hinge]

So I can divide but I shouldn’t because it might be 0

[pale kestrel]

but factorise is much better

[slender gull]

Or negative too.

[inner hinge]

Ok

So what would you guys have done

[pale kestrel]

Factorise

[slender gull]

Just now they told, either factorise or split cases.

[pale kestrel]

delete that last line

[slender gull]

Factorise works best.

[slender gull]

You have $k^2 - 40k>0$

[ocean seal]

Sakata Yaksha

[slender gull]

Factorise now.

[inner hinge]

K (k-40)

Yea or nah

[pale kestrel]

yes

thays how you factorise

now k(k-40) represents a quadratic

can you draw this curve?

Then using that, determine when it is greater than 0

[inner hinge]

Ohhhhhh

[pale kestrel]

Just a quick sketch

[inner hinge]

Do you use null factor law

Or nah

I wouldn’t know how to sketch that

[slender gull]

Alright so k(k-40)>0

So when is the product of two numbers greater than 0?

This is one way you could approach.

[inner hinge]

When they are 1 or more

[pale kestrel]

You dont know how to sketch quadratics???

You should learn considering you're studying them right now

[alpine sable]

You know is 0 when it's 40 or 0, it means that you have 3 intervals, you just have to decide where it's negative or positive by trying one number of each of this interval. You don't need to sketch it

[pale kestrel]

Curve sketching should be a skill you have regardless

It takes 2 seconds to make a sketch. It doesnt need any details except for the orientation and roots

[slender gull]

Um no, not really.
At this point, do what shuri says.

[inner hinge]

I’ve learnt before but forgotten so watching a YouTube video now

[pale kestrel]

@inner hinge do you know how quadratics are shaped?

There are only 2 kinds, essentially

[inner hinge]

Like bowl shape

Parabola

[pale kestrel]

exactly

so you can sketch

first determine if it is smiling or frowning

[inner hinge]

Positive

[pale kestrel]

smiling ok

Next,

you know where the roots are

So you mark them. Then you have your sketch

[inner hinge]

.close

[lone heart]

Channel closed

Closed by @inner hinge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[whole wadi]

Sin 3x = sin 3π/4

3x = 3π/4 + 360n
3x = π - 3π/4 + 360n

x = 3π/12 + 120n
x = π/12 + 120n

But they say that -5π/12 is another solution, and I don't know how they get it?

[vale wigeon]

you should not mix degrees and radians like this.

it's +2πn, not +360n

once you correct for that, it'll become clear that x = -5π/12 is obtained from x = 3π/12 + 2πn/3 by taking n = -1

[whole wadi]

So:
3x = 3π/4 + 2πn
x = 3π/12 + 2πn/3
when n = -1 => 3π/12 - 2π*4/3*4 which is 3π/12 - 8π/12 = -5π/12

Good?

[vale wigeon]

yes, sure

[whole wadi]

.close

[lone heart]

Channel closed

Closed by @whole wadi

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pulsar delta]

hi, g is a function defined on R by g(x) = 1 - (x - 2)e^(x - 1) and g'(x) = -(x + 3)e^(x - 1)
I want to prove that g(x) = 0 has only one solution on R. I can use the Intermediate Value Theorem, and the corollary that states that, if the function studied is strictly monotone, then g(x) = k, with k belonging to the image of the interval studied, has one and only one solution.

now showing that there is only one solution to g(x) = 0 in [-3; +∞) is straight-forward with the corollary, but I'm struggling to show rigorously that there is no solution to g(x) = 0 in (-∞ ; -3[.

or maybe I'm just thinking too much and it's trivial that g(x) only has values between 1 and 1+e^{-4} on the interval (-∞ ; -3[?

[lone heart]

@pulsar delta Has your question been resolved?

[vale wigeon]

yes, it is trivial that g(x) only has values between 1 and 1+e^{-4} on the interval (-∞ ; -3[

[lone heart]

@pulsar delta Has your question been resolved?

[pulsar delta]

ok, thank you

.Close

[lone heart]

Channel closed

Closed by @pulsar delta

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[surreal spear]

Plz some help 4 these exercises

https://prnt.sc/26v30g8

[lone heart]

@surreal spear Has your question been resolved?

[serene junco]

@surreal spear Could you possibly translate the instructions to English?

Oh, is it asking for the modulus and argument?

[surreal spear]

yes

help me for the third plz

[serene junco]

Did you already evaluate the exponent?

[surreal spear]

a²+ 2ab + b²

i already did it

[pulsar delta]

first you can calculate the modulus with the distance function

[surreal spear]

i did this

[pulsar delta]

that's it for the modulus

[surreal spear]

yes

i find this

but i have to simplify

idk the english goodest terms to translate

[pulsar delta]

i'm french, if that can help
not sure if foreign languages are allowed on these channels

[surreal spear]

parfait alors

[pulsar delta]

tu peux simplifier sqrt(72) en trouvant les facteurs premiers de 72

[surreal spear]

comment faire

c'est sa

je dois mettre sous la forme : a sqrt(b)

Pour placer sur le cercle par la suite

[pulsar delta]

donc, si tu décomposes 72 en facteurs premiers, tu as 72 = 2^3 * 3^2

que tu peux exprimer sous la forme 72 = (2*3)^2 * 3
à partir de ça tu peux simplifier sqrt(72)

[surreal spear]

^ = exposant ?

[pulsar delta]

c'est ça oui, x^2 représente la même chose que x²

et * la multiplication

[surreal spear]

merci je peux t'ajouter en ami si j'ai besoin de te contacter directement ?

[pulsar delta]

oui oui, pas de soucis !

[surreal spear]

merci 🙂

[lone heart]

@surreal spear Has your question been resolved?

Channel closed

Closed by @surreal spear

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim mason]

How do you solve 24. Not rlly sure where to start

[gray isle]

find the slope of the tangent line

[slim mason]

so find the slope at x=-1 for that equation?

[gray isle]

yes

[slim mason]

ok

so i got -11 as the slope

[gray isle]

and then apply properties of parallel lines

i.e. what is the slope of a line that's parallel to a line with a slope of -11?

[slim mason]

is there a way to determine that or just guess & check?

[gray isle]

by definition and

properties of parallel lines

[slim mason]

i havent learnt about the im just starting gr12 calc

[gray isle]

you should have

especially if you're already doing derivatives

[slim mason]

let me check my notes

we arent

[gray isle]

and you're probably massively overthinking/overlooking

[slim mason]

we are doing limits

[gray isle]

seems like your applying limit definitions of the derivative which is pretty much derivatives

and regardless, properties of slopes of parallel lines comes well before that

[slim mason]

i guess ill just watch a video on that cause last week was our first and we didnt do that

[gray isle]

do a quick search on slopes of parallel lines should remind you

[slim mason]

any recommened videos?

[gray isle]

any should be sufficient

[slim mason]

recommended*

wait are you talking about seacant lines?

[gray isle]

no

this is a lot simpler

e.g. if i gave you the equations of two lines
y = 3x + 5
y = 2x + 3
how would you efficiently determine whether they're parallel or not

[slim mason]

rise over run?

[gray isle]

if by that you mean the slope...

how would you consider the slopes here to see if they're parallel

[slim mason]

i was asking if thats what ur talking about for that though i know degree one equations are always linear

[gray isle]

no

this is a LOT simpler

and you're probably massively overthinking/overlooking

[slim mason]

they are constant

going up by the same number

[gray isle]

poor wording...
but how would you apply that to

y = 3x + 5
y = 2x + 3

[slim mason]

are you asking how i would find the slope of that?

[gray isle]

that would be part of it. and more specifically i'm asking how you would use the values of the slope to determine if the lines are parallel

[slim mason]

you can graph it

[gray isle]

without graphing

[slim mason]

make a table of values

[gray isle]

this seems like an even bigger issue that i initially thought

as you seem to have a major knowledge gap in coordinate geometry

[slim mason]

thanks

[gray isle]

and you should do a review on that

note that the equations of the lines i gave are in
slope - intercept form

and the slopes can be identified immediately in that form

no graphing needed

[slim mason]

i know they can...

its 2 and 3

[gray isle]

and now that you have the slopes, tell me whether those lines are parallel and the reason

[slim mason]

they would intercect each other no?

intercept*

[gray isle]

(without doing any graphing if you're thinking about that)

i'm looking for an explanation explicitly related to their slopes

[slim mason]

if you have different slopes

you cannot be parallel

[gray isle]

so what's special about the slopes of parallel lines?

[slim mason]

they are the same

[gray isle]

yes

that's what i wanted

the slopes of parallel lines are the same

[slim mason]

so relating that to our question we just need a line with a slope of -11

and passses through 2,2

[gray isle]

(2,2)

yes

[slim mason]

so is this part guess and check?

[gray isle]

no

[slim mason]

ohhh

i put it into

y=mx+b

sub in my x and y

find b

[gray isle]

that's a valid way of doing it
and its NOT called guess+check

[slim mason]

i realized that lol

[gray isle]

guess and check would be randomly guessing values for b,
and seeing if plugging (2,2) works

[slim mason]

ok thank you

.close

[lone heart]

Channel closed

Closed by @slim mason

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open roost]

could someone help me understand the equation for a

and explain how the vertex was found?

[lone heart]

@open roost Has your question been resolved?

[lone heart]

@open roost Has your question been resolved?

[pulsar delta]

@open roost what do you mean by the vertex? the maximum of the function R?

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open roost]

like v(p,q)

[lone heart]

@open roost Has your question been resolved?

[alpine sable]

sorry

the x intercepts are the roots

to find the vertex

you rewrite the quadratic in the form of $y-k=a(x-h)^2$

[ocean seal]

crabbo

[alpine sable]

the vertex is $(-k,-h)$

[ocean seal]

crabbo

[alpine sable]

i think what is written down in the image is a very good exdplanation

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[alpine sable]

Can someone translate this for me

IDK what the : in b:b means

[glass lichen]

b such that b=Ax

[lone heart]

@alpine sable Has your question been resolved?

Channel closed

Closed by @full cliff

Use .reopen if this was a mistake.

[alpine sable]

.close

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slender rampart]

How do I do this

Without hopital rule btw

[stoic hound]

If x is really really big, then -x^3 is really really small (as in very negative)

so adding 1 doesn't really make much of a difference to it

in fact, if x is going towards infinity, we might as well say that 1-x^3 is preeettty much the same as just -x^3

Can you see where this is going?

[slender rampart]

Nope

I’m confused

So it’s just x then?

[stoic hound]

If we approximate 1-x^3 as just -x^3, then what does the radical simplify to?

[slender rampart]

Negative root doesn’t exist

[stoic hound]

It's a cuberoot so it's fine

[slender rampart]

So it’s just -x then

[stoic hound]

yep

[slender rampart]

So it’s x-x? Which is 0

[stoic hound]

Yep!

[slender rampart]

Can I ask one more question if u don’t mind

[stoic hound]

yah sure

[slender rampart]

Approaches to 0 btw

And I need it w/o hopital rule

[stoic hound]

Do you know about series expansions?

[slender rampart]

no :((

[stoic hound]

ohh.. this might be tricky

wait a sec

[slender rampart]

Np take your time

[stoic hound]

I think the sandwich theorem will be involved somehow

just a hunch

[slender rampart]

yeah it’s usually involved w trig identities

[stoic hound]

Aha I think I got it

[slender rampart]

but idk how to do that

[stoic hound]

cos(blah blah) will fall between -1 and 1

[slender rampart]

right

[stoic hound]

So, x^2 times cos(...) will be between -x^2 and +x^2

[slender rampart]

Owhh yes

[stoic hound]

Now take the limit, which sandwiches it to 0

[slender rampart]

that makes sense

thank you so much

[stoic hound]

I thought itd be more complicated

with the whole cuberoot thing

but it was straightforward haha

[slender rampart]

Just one more question before I leave if u don’t mind

[stoic hound]

yea

[slender rampart]

Could u show me how to do this w conjugation

Part e ^

[stoic hound]

uh hang on im thinking

Whew ok

So you know how a^3-b^3=(a-b)(a^2+ab+b^2)?

Let a=cuberoot(x) and b=1. We have (a-b) in the denominator, so multiply and divide by (a^2+ab+b^2). We get x-1 in the denominator now

Now, we can split x-1 as [sqrt(x)-1][sqrt(x)+1], and now we can cancel with the sqrt(x)-1 in the numerator. After that it's just substitution

[slender rampart]

but when we take a^2 and all it becomes x^2/3 right?

Like it’s the sqaure of the roots

[stoic hound]

that's in the numerator, so it's fine

I mean in the end you just want to get rid of 'problematic' stuff in the denominator so that you can just plug in

[slender rampart]

No I’m talking about denominator

[stoic hound]

oh

sorry

well it's all stuff that's added, so it's not problematic

[slender rampart]

Could u write it down i guess I’m a bit unclear

If u can that is

[stoic hound]

okay one sec

Hope it's clear

[slender rampart]

Thank u so much!

Have a great day

[stoic hound]

Is the answer clear tho..?

[slender rampart]

Yep

I understand

[stoic hound]

Cool, awesome

[stoic hound]

Thanks, you too!

[slender rampart]

.close

[lone heart]

Channel closed

Closed by @slender rampart

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limpid flame]

A gumball machine dispenses one gumball at a time. It dispenses red, yellow, green and blue balls at equal rates. Tommy wants 10 of each colored gumballs. What is the expected number of balls for Tommy to get 10 of each colored gumballs?

[limpid flame]

I know the expected number for getting 10 of a color is 40. But I don't know how to approach 2 or more.

[lone heart]

@limpid flame Has your question been resolved?

[limpid flame]

<@&286206848099549185> Help with probability/statistics please.

[noble sinew]

Coupon collecters problem.

View as geometric distribution and linearity of expectation

[tacit arch]

pretty extensive description and similar examples here
https://brilliant.org/wiki/coupon-collector-problem/

[limpid flame]

So far the cases are for 1 of each kind, I'm looking for 40 of each instead.

In Wikipedia, there are extensions similar to mine but not applicable.

https://en.wikipedia.org/wiki/Coupon_collector's_problem

The value of n is 4 in my question. It's not a big number so I don't think it'll be a good approximation.

[lone heart]

@limpid flame Has your question been resolved?

Channel closed

Closed by @limpid flame

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thin urchin]

so I know product rule is f'(x)g(x)+f(x)g'(x)

f(x)=(3x^2 +8)^5 , g(x)=(-4x^2 +4)^13

and I calculate that f'(x) and g'(x) are the following

f'(x)=30x(3x^2 +8)^4

and

[buoyant kayak]

how'd you get 30x in front

wait nevermind

[thin urchin]

g'(x)=-104x(-4x^2 +4)^12

[buoyant kayak]

my eyes are bad

[thin urchin]

but when I set them up with product rule and combine like terms I get the answer that it says is wrong

[buoyant kayak]

what terms are you combining exactly

[thin urchin]

so set up with product rule I have

(30x(3x^2 +8)^4)((-4x^2 +4)^13)+(-104x(-4x^2 +4)^12)(3x^2 +8)^5)

is this just the answer maybe I was not supposed to combine terms

oh it took it

nvm 🙂 thanks

.close

[lone heart]

Channel closed

Closed by @thin urchin

Use .reopen if this was a mistake.

[lone heart]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[upbeat isle]

Hi

[upbeat isle]

So I came to the conclusion that it is none of the above but I’m not sure

My brain literally melts as soon as there’s a problem with fractions over fractions etc

[wary stream]

Not 100% sure if it can be simplified but simplify the fractions first

By factoring

Should make it cleaner

[upbeat isle]

Can I cancel those (x+2)?

And even then bruh my brain hurts

[versed crater]

And x+1

[wary stream]

Don't forget $$\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \cdot \frac{d}{c}$$

[ocean seal]

dldh06

[wary stream]

The dividing by fractions

Is keep the numerator, change the division to multiply, flip the denominator

And then you should see things cancel out better

[upbeat isle]

Dude I love you

How did I forget that

[wary stream]

That should make it easier to look at

Than the mess you have

[upbeat isle]

Yea I got it solved Ty Ty 😂😂

.close

[lone heart]

Channel closed

Closed by @upbeat isle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[icy dagger]

hello

[versed crater]

Hi

[icy dagger]

so there is where im at so far

the next thing i should do is appy the power rule to the terms in the parenthesis right

[undone hinge]

you gotta use chain rule here, do you know what that is?

$g´(x) = a´(i(x)) \cdot i´(x)$

[ocean seal]

Big xdddd
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[undone hinge]

you have to define your own functions, one the outter function called a(x) and one the inner function called i(x)

[icy dagger]

oh okay

so how would that look?

[icy dagger]

i did the power rule after this and got this

not sure if its correct though

[undone hinge]

this is correct yea

you literally used the chain rule

[icy dagger]

oh haha

[undone hinge]

so first derivate e^x (your outter function) which is also e^x and derivate your inner function (x^2+x) and you mulitply the derivative of your inner function with the other part here

[icy dagger]

ohhhhhhhhh

okay so thats how that works

quick question

[undone hinge]

yea dont forget this one

[icy dagger]

when you use the power rule on a single variable like x why is it 1

i know its the exponent times the leading coef then - 1 from the exponent but idk how thats one

i kinda guessed that lol

[undone hinge]

$\frac{dy}{dx}x^n = n*x^{n-1}$

[versed crater]

And n =0

[ocean seal]

Big xdddd

[undone hinge]

so if you got x^0

[icy dagger]

ohhhhhhhhh

[undone hinge]

or what you mean n = 1 or n = 0?

[icy dagger]

anything raised to 0 is 1

i see

thank you

[undone hinge]

ok wait

tell me what the derivate of 1/x is

[undone hinge]

yes

[icy dagger]

ide say it would be 1 right?

[undone hinge]

think, 1/x is the same as x^(-1)

[icy dagger]

ohhhhhhhhhhhhhhhhhhhhh

[undone hinge]

derivate this with the formular

[icy dagger]

okay so it would be -1/x^2

[undone hinge]

great job!

[icy dagger]

lets goooo

[undone hinge]

😁

[icy dagger]

thank you

i appreciate the help

[undone hinge]

no problem

[icy dagger]

.close

[lone heart]

Channel closed

Closed by @icy dagger

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[carmine ridge]

@hasty elk hii i was wondering if we could continue our discussion here : )

[carmine ridge]

i understand like that x doesn't have an effect on the cancelling since its not negative

[hasty elk]

mmhmm

[carmine ridge]

but like how does this work?

like they didn't take the exponent of x into consideration ..? o-o

[hasty elk]

because you know that $a+b+c = 2006$

[ocean seal]

Camilleone

[carmine ridge]

oh so like if b = 1, a+c = 2005

[hasty elk]

and if you know c, you also know a, yes

[carmine ridge]

so like one of them is odd and one of them should be even

is this like essentially stars and bars

oh no wait

since we have fixed b to be odd, (negative), c must be even otherwise it doesnt yield a negative term in the end

is this right?

[hasty elk]

yes, that's exactly it!

[carmine ridge]

nice! so in the end we have 1003+1002+...+2+1 = 1003*1004/2

but we also have to consider that b and c can be swapped so we multiply it by 2

thanks! ive understood it :D

tysm :))

[hasty elk]

:))

[lone heart]

@carmine ridge Has your question been resolved?

Channel closed

Closed by @carmine ridge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rigid crane]

hey

[rigid crane]

I got a quick question

Does this integral make sense?

I know it would if it was to be swapped

but can it be swapped?

[hasty elk]

errrrrr...no, this doesn't quite make sense

[rigid crane]

yea, but if it was swapped, it would

but it can't be swapped, I suspect

[hasty elk]

you shouldn't, it doesn't make sense notationally

[rigid crane]

without changing the variables, at least

I see

While we're at it, can this be done without error functions?

I wasn't able to

[pale kestrel]

You need Erf(x) yes...

[rigid crane]

I see

[pale kestrel]

If I read this, I would take this as a function of x

The x on the limit is different from the dummy x inside.

Probably not what you meant

It certainly has a different meaning to when the integrals are swapped.

@glass lichen do u not?

[glass lichen]

jacobian

[rigid crane]

Yea, but afaik, the integrals can't be swapped without changing the variables (at least that I read from math stack)

[pale kestrel]

You can't if the limits are variable, no.

[rigid crane]

with them swapped, it'd make perfect sense

[glass lichen]

You can swap order if the bounds are variable

you just have to do it carefully

[pale kestrel]

Uhh for this if you convert to polar you don't have to use erf?

is that what you're saying mosh or did i miss

[glass lichen]

Yeah, you'd use polar for that

cause... circle

[pale kestrel]

woops

[rigid crane]

But from the standpoint of being mathematically correct, would this suffice?

[glass lichen]

Polar form makes it MUCH easier, and quicker

[pale kestrel]

This is not the correct region

[glass lichen]

that too

[pale kestrel]

?

[rigid crane]

Why is that?

[glass lichen]

circles aren't rectangles

[pale kestrel]

you've done some rectangular region

[rigid crane]

Aa okay

[glass lichen]

$\int_{-3}^3\int_0^{\sqrt{9-x^2}}\exp(x^2+y^2)\dd{y}\dd{x}$ if you feel truely sadistic

[ocean seal]

Mosh

[rigid crane]

Aaaa okay, I see

one of the integrals has to include a function, indeed

[glass lichen]

all the integrals include functions

one just isn't a constant function

[rigid crane]

true

[glass lichen]

However, your first instinct for this question shouldn't be cartesian coordinates

[rigid crane]

I see, I'll try to get familiar with using polars for this

[glass lichen]

$\int_{-3}^3\int_0^{\sqrt{9-x^2}}\exp(x^2+y^2)\dd{y}\dd{x}$ vs $\int_0^\pi\int_0^3 e^{r^2}r\dd{r}\dd{\theta}$

[ocean seal]

Mosh

[rigid crane]

It looks a whole lot neater

[glass lichen]

Yep

and the polar one is actually integrable with elementary functions

[rigid crane]

It seems to be, yeah

Thank you for spotting the error!

[pale kestrel]

wow 👀

[lone heart]

@rigid crane Has your question been resolved?

[rigid crane]

the ans came to approx 12,700

I guess the function caused it to be that large

e^9 * pi / 2

[lone heart]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steep knoll]

It says im wrong

Help

[serene junco]

How did you come up with that equation exactly?

[steep knoll]

The equation?

[serene junco]

Yes, your answer

It's close

[steep knoll]

Aight

So i looked at the problem

4.34 per 10

Meaning

4.34=10x

Dividing that gets

0.434 per 1

[serene junco]

Okay I see

Right now, if we plugged d=0 into your equation, we'd get p=-15

Which means that at a depth of 0 there's pressure of -15

Which is not quite right

[steep knoll]

Oh thats a plus sign

Thats a plus sign

It looks like a minus

[serene junco]

Really?

It really looks like a minus lol

[steep knoll]

Nah trust

Its the font

And my phone

[serene junco]

In that case, your equation is right. The only other thing is they used capital P for pressure, you used a lowercase p in your equation

That's the only other "problem" I see

[steep knoll]

Christ

[serene junco]

Did that do it?

[steep knoll]

One sec

I cant change the answer

So that sucks

It literally says 3/9

[serene junco]

🤷 Maybe your teacher will give you that point back

I would.

[wary stream]

Nah, I doubt it

[steep knoll]

Dang

[serene junco]

Seems like a silly reason to penalize a student

[steep knoll]

Dang

Aight thanks

Might come again in like 10 mins

But close this place for others

[wary stream]

I had a hw, 10 points a question, answer was lowercase, accidentally capitalized the first letter, mark it wrong, talked to prof, he said he doesn't care because it's auto graded

[steep knoll]

Oh wait

Back

Back

The p in the equation is the pressure at the surface?

[serene junco]

@wary stream Yeah, but teachers are different, you never know. I've seen teachers go back and fix stupid things the computer did

The P in the equation is the pressure at a depth of d

[steep knoll]

Cause it said I was wrong for saying the increase of pressure per lowest point of descent

[wary stream]

I mean he said he wasn't gonna change it for me, which was sad because it was the only one I missed

[steep knoll]

Back

[serene junco]

I'm not sure what you mean @steep knoll

P=0.434d+15 definitely answers the question asked

[steep knoll]

It said the pressure at the surface is the right answer

For the previous

So basically

330 and 200

And 480 and 800

Are basically x and y intercepts right?

@serene junco

[serene junco]

not the intercepts

First of all, look at the graphs, do you see how distance(d) is on the x-axis, and cost(C) is on the y-axis?

[steep knoll]

I do

[serene junco]

So $330 for 200 miles.

200 is the distance, 330 is the cost.

[steep knoll]

Thanks

[serene junco]

That means (200,330) is a point on the graph

Not an intercept

and (800,480) is another point on the graph

So you need to find the equation of a line that passes through those two points

[steep knoll]

1/4?

+250

[serene junco]

1/4 is the slope

How did you get 250?

[steep knoll]

I went a bit ahead

And got the b

[serene junco]

Double check, 250 is not right

[steep knoll]

Y-330=1/4(x-200)

[serene junco]

I agree so far

[steep knoll]

Y-330=1/4x-50

[serene junco]

Yes

[steep knoll]

Oh

[serene junco]

so we'd end up with 280, right?

Then just make sure you use the variables they used

So as not to upset the computer overlords

[steep knoll]

Aight

[serene junco]

$C=\frac{1}{4}d+280$

[steep knoll]

Uh

[ocean seal]

tatpoj

[steep knoll]

Why is a linear relationship a suitable model?

For this situation?

Is what they asked

[serene junco]

🤷 As long as the price of gas doesn't change too much, and the mpg of your car doesn't change too much, then each mile is going to cost about the same

[steep knoll]

So its not

[serene junco]

In reality it would only be roughly linear. But they told us to assume it's linear

[steep knoll]

Oh

I see

Ah

C intercept of the graph

Represent cost

Per mile

[serene junco]

No, the slope represents the cost per mile.

The C-intercept represents the cost to drive 0 miles

Presumably she has a car payment or something

[steep knoll]

These are the options they give me

The fixed cost each month, the cost per mile, the number of months lynn drives, the rate at which the price of gas is increasing

[serene junco]

The fixed cost each month

It's what she has to pay for her car, even if she doesn't drive at all

[steep knoll]

Ohhhh

[serene junco]

That's why the point is (0,280)

[steep knoll]

Im so dumb

[serene junco]

Even if she drives 0 miles, it costs $280

[steep knoll]

I se

[serene junco]

The slope is always going to be the (something) per (something)

Because it's a rate

In this case the cost per mile

[steep knoll]

Aight

Aight

So

[serene junco]

So?

[steep knoll]

Sorry

Im trying to

Type out

How to say

Do you habe a ti84?

@serene junco

Sorry

Do you have a ti84?

[serene junco]

No, but I can't imagine why I would need one lol

[steep knoll]

Aight

[serene junco]

I have a ti89 that I haven't touched in like ten years haha

[steep knoll]

I dont think youll be able to help me for this next one

You know a stat plot right?

[serene junco]

sure

[steep knoll]

Aight

So i need to make a

Line based on the data

Using the calc

Let me send pic

[serene junco]

I usually just use desmos or somethin

[steep knoll]

The top one

This too

Wrong

[serene junco]

lol

[steep knoll]

Actually

Sorry

Lets focus on the first one

How would I do the first one

Just with the numbers

[serene junco]

I don't remember how you'd do it on a ti. But I can do it in desmos

[steep knoll]

Dang

Thanks

Ill try to figure out the calc way

I wont have access to desmos on the test

[serene junco]

Sorry, I haven't used a calculator like that in a very long time

[steep knoll]

All good mate

[serene junco]

For what it's worth, desmos gives A=6.451D-0.152

[steep knoll]

So

Y= 6.45102x-0.152279

[serene junco]

Um, we got the same y-intercept but your slope is way different than mine

OH

you're looking at the regression consant

m is the slope

[steep knoll]

Sorry

[serene junco]

all good

on the ti-84 it will give it as ax+b, not mx+b

iirc

[steep knoll]

I see

[serene junco]

Yes, but round m and b to three decimal places

[steep knoll]

Aight

Thanks

[serene junco]

sure thing

[steep knoll]

Wait

So

6.451

[serene junco]

6.451D-0.152

Because it says round to the nearest thousandth

[steep knoll]

Could you help me for two

Oh

[serene junco]

That was ii

oh I see

[steep knoll]

Oh

Do I just

Count from 26?

[serene junco]

count from 26?

I don't follow

[steep knoll]

Use the data of the scatter plot

[serene junco]

Oh

[steep knoll]

Using 1958 as year 0

So count from 26?

[serene junco]

You mean 1984 would be t=26

yes

[steep knoll]

So

What I got was

C=1.629+ 301.436

[serene junco]

Mine is just slightly different. Let me doule check and make sure I have the data right

I get C=1.632+301.356

It's very very close.

Tbh I'm not even sure what the calculator is doing behind the scenes

But can you double check your data? I checked my table three times

[steep knoll]

I

It looks like stuff is the same

[serene junco]

🤷

[steep knoll]

Well

Let me put into the thing

Amd we'll see whose correct

Okay

Okay

[serene junco]

Maybe they have different tolerances for estimating. I'm guessing the question was designed with a ti calculator in mind

[steep knoll]

Im confused

So theres a second thing

That says to imput a number right

Did all the stuff

Put the number into the equation

The second thing was right

But the equation was wrong

[serene junco]

The second question only asks you to round to the nearest tenth. It's not as strict. So your equation could be a little off and you might still get that part right

[steep knoll]

1.6299

Rounded

1.629

301.4364.

[serene junco]

1.6299 to the nearest thousandth is 1.630

And 301.4364 to the nearest thousandth is 301.436

[steep knoll]

Huh

Said it was wrong

So i need to redo it again

No we clear

Gave me the same question again

[serene junco]

lol

Make sure you round correctly, did you see what I said?

[steep knoll]

Yeah

Changed it to 1.630

Said it was wrong

[serene junco]

Can you send me a picture of the data table on your calculator?

[steep knoll]

One sec

[serene junco]

The very first entry

Should be 344.3, not 344.4

[steep knoll]

BRO

Man

Im gonna fail my test

1.6318

Then goes to

1.632

Or no

[serene junco]

Yes

That's right

[steep knoll]

1.632

Aight

[serene junco]

And the b?

[steep knoll]

301.456

It says

Thst the new answer is wrong tho

[serene junco]

Are you sure it's not 301.356? That's what desmos says

[steep knoll]

Welp

YO

Clutch

That was the last submission too

Lets go

[serene junco]

Did your calculator actually give you 301.356?

[steep knoll]

Nah

But I trusted your answer

I mustve screwed something

How do you calc percent in a model

Nevermind

[lone heart]

@steep knoll Has your question been resolved?

[steep knoll]

Sorry

I need more help

Or

Does

That negatively impact you

AH

@serene junco

Did that negatively impacted you

Sorry

[lone heart]

@steep knoll Has your question been resolved?

Channel closed

Closed by @steep knoll

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sturdy glen]

how was ndS found to be <0, 0, 1>?

i cant figure out what they did to get that at all

i get the dS = dxdy part because of the bounts but why does n = <0, 0, 1>?

[lone heart]

@sturdy glen Has your question been resolved?

[sturdy glen]

<@&286206848099549185>

[lone heart]

@sturdy glen Has your question been resolved?