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inside a normal integral we get pi r^2 dr
but in this case we get dA, where A is the area
Yeah that makes sense. I don't know why I associate it with complex analysis rather than electromagnetism with real geometry
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I try to do a and b but whenever I try to eliminate x or y or z then everything else eliminates too, what can I do to solve this?
In a the 1st and the last equations are linearly dependant (they're equivalent), meaning that there can be infinitely many solutions to a
So you have an extra degree of freedom if you need to present one of the solutions
What does this mean
It means that you can freely choose any value for either x, y, or z
you can't, the system of equation satisfies for all x, y, z that satisfy any one of the three equations
there is no distinct solution
as Beans stated, all equations are equivalent
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Hey, im am struggeling the past days with that task.
I have to bring (2-4 root 2)Β² into x+y root 2
but any approach I take. I don't succeed
You realize that $(2 - 4 \sqrt{2})^2 = (2 - 4 \sqrt{2})(2 - 4 \sqrt{2})$
dldh06
$(2 - 4 \sqrt{2})^2 \neq -2^2 + 4^2 \sqrt{2}^2$
dldh06
I didn't realise that
It's the same thing as $(x + 1)^2$
dldh06
You have $(x + 1)^2 = (x + 1)(x + 1)$
dldh06
Because $(x + 1)^2 \neq x^2 + 1^2$
dldh06
Hopefully that helps
It did gave me another perspective to solving that task
But why isnt (x +1) ^2 = xΒ²+1Β² I always thought it would be like that
Because you're not distributing the squared
It's saying there are 2 sets
Like if you had 2^2, that's 2 * 2
But something more complex, is (2 + 3)^2 that's just saying (2 + 3)(2 + 3)
Not 2^2 + 3^3
yeahhh you right. I dont know how I could mess that up so bad
You can also math it out too (2 + 3)^2 = 25 because (2 + 3)(2 + 3) = 5 * 5 = 25
But if you did 2^2 + 3^2, that equals to 13
In how many ways can you distribute 13 distinct balls into 5 distinct boxes such that each box contains at least one ball + In how many ways can you distribute 13 distinct balls into 5 identical boxes where there are no restrictions(box may contain 0 balls as well) ?
Don't ask in an occupied channel
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apologies
Hopefully, you can get it from there
Yeah I hope so. I will try again, otherwise I could ask again again right ?
Yes
ok thanks a lot :))
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My homeworks been asking me to write a polynomial function of fourth degree with integer coefficients, a leading
coefficient of one, and zeros of x = 3, -5, 2i
I have been banging my head on this for awhile
Have you tried expanding (x - 3)(x + 5)(x - 2i)^2?
No, how could I do that?
Wait
just multiply everything by everything
Oh alright ill try that
Ah nvm
Thank you
(x - 3)(x + 5)(x - 2i)x would be easier imo
Unless the problem is asking us to make 3, -5 and 2i the only roots tho
Im expanding it rn ill let you know how it works out
@errant latch Has your question been resolved?
@echo socket it doesn't look like I'm doing this right
I haven't factored in the last step yet
Look them up maybe?
i couldnt find hard Equations
π alright
,w rotate
i did that with ease
k
(x - 3)(x - 5) is x^2 - 8x + 15
Let me see
Yes it's correct but you should have done the same but with x + 5 instead lol
If you want to avoid extra effort
Here's the answer
ok i couldnt slove it
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prove:
sec^2A -4sin^2A= 2sec^2A
I also want to know if trigonometric identities can be proven by a specific pattern or from any angle possible. Thank you
$\sec^2 A - 4 \sin^2 A = 2 \sec^2 A$ is $ - 4 \sin^2 A = \sec^2 A$, which does not hold in general, did you make a typo somewhere by any chance or is a specific value of $A$ given?
xdk1235
actually it's never true for any real $A$
xdk1235
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Ok thx
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could someone help me with this... How do i solve this equation?
$\log _x 5 \sqrt{5} = \log _x \sqrt{5}^3 = 3 \log_x \sqrt{5}$, and maybe substitute $t := \log_x \sqrt{5}$
xdk1235
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$a^2+ab+b^2 \geq 3(ab-1)$
that is equivalent to $a^2 - 2ab + b^2 \ge -3$
xdk1235
xdk1235
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β
$$a^2-3a+3 \geq 0$$
min value of the function $$a^2-3a+3$$ is ( by derivatives) $$\frac{3}{4}$$reminder that function is convex therefore proven
but I am confused how it will help me
why I need disc tho
ig because typically it's shown using the discriminant
to show $x^2 - 2x + 5 \ge 0$ you use that the discriminant is less than 0
xdk1235
so you rearrange everything in your problem like $b^2 + (a-3)b + (a^2 - 3a + 3) \ge 0$
xdk1235
treat b as a variable, a as a constant
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how to figure out theta in this example?
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I got negative 45 degrees tho.. and the terminal angle of that is 360-45 which isnβt (3/4)pi
arctan doesnt solve all your problems
tan isnt bijective
so arctan can only invert part of it
the range of arctan is from -90 to +90 degrees
If you sketch a graph of tan x
that means arctan only gives you back your original x if x was in that range.
Otherwise you need to think about the quadrant
Also. remember the argument of a complex number is defined as the anticlockwise angle from the positive x axis
Arctan2 moment
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Kris is a salesperson for IBM. He makes a base salary of 80,000 per year plus 4% of net sales. He is paid bi-weekly, and commission is paid when the sale is billed. This period, they billed a 25,000 sale. Kris has also made another 25,000 sale but it was not billed until the day after the close of the pay period. What should Kris expect his gross pay this period to be?
A. 1,000
B. 3,076.992
C.4,076.92
D.5076.92
LandzzzzzzOD
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Please! Help!
@alpine sable Has your question been resolved?
NO!
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what is the problem
i get that square roots cancel each other out, buuut why does sqrt(x) * sqrt(x) get rid of one of them
if that makes sense
because think about it
it's the definition of a square root
by definition
what do you think a square root is
wdym by get rid of "one of them"
What is β2 * β2?
sqrt(this) * sqrt(this) = this
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cubic root of 64^2 is not 64^3/2, it actually is 64^2/3
so then what would the step after that be written as. Would it be (64 1/3)^2?
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help pls
i know that 2x+5y=50
Might help that the angles of a triangle = 180
and substitute in
C = F, so A + B + C = 180
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oh ok ty
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ok thx i solved it
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Can I please get help for questions 1-7?
do u have ideas for #1?
I have no idea other than the answer is probably "negative"
it is negative
yeah
yes
identify roots, identify axis of symmetry using x = -b/(2a) and identify vertex by subbing that x value into f(x)
find the roots and vertex
(concave up = opening up)
ye
OK I'm going to find the vertex for both rn
After I find the vertex could I graph in just vertex form?
<@&286206848099549185> I found the vertex what do I do now to graph the two equations
@languid scaffold Has your question been resolved?
@languid scaffold Has your question been resolved?
on 2?
@languid scaffold
you usually just need a handful of points for each
its important their vertices and intersects
these are the points you should include explicitly
then connect the rest
question on number 7 @remote heron
huh?
what is vertex form π€
the vertex is the global extremum of a parabola
so, yea
I think its like where two points meet
a maybe good question is like
in simple terms
how can you be sure that the vertex is the minimum
(that a minimum even exists)
but thats secondary really
the vertex really work fine for this without too much thought
vertex form encodes the coordinate of the vertex in the equation
i understand after u said what it was π
ah
but nope, haven't come across that term
I mean at least Mase explained it in simple terms for Shuri π
do you know how to find the vertex of this parabola?
idk what mase means
For number 7? isn't it just -b/2a and then plug it back in?
and then the vertex is the minimum?
gimme a sec solving it rn
Not trying to butt in here or anything, but what i mean is, if you were going to graph this equation to find the max/min number on the parabola of the equations graphed form, it'd be where the points meet at the top/bottom, in a way. But not really π
No it's okay I need as much help as I can get
yea youre good
for my vertex i got (-2,-11)

So is it saying that the minimum is at x=-2?
yup
I'm sorry I'm trying to translate this inside my head
youre chill
because I wanted to do the work that it's showing me
have you looked at a picture yet?
I only saw the first picture it sent me
I pressed more
and there's no explanation
,w graph y=x^2+4x-7
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oh whatever
lol
its a vertical line that goes through the the parabola
and everything on both sides is the same
such a line will always go through the minimum or the maximum
does this mean if I had plugged in -11, it would spit out as x=-2?
Sorry dumbing it down for me lol
at the vertex its nice that its just one, though
nah youre good
heres this
idk if youre curious
since wolfram isnt work
you can slide the sliders around and see that axis of symmetry move
upwards how many units?
oops I should've wrote opens upwards
I wrote opens upwards, left 6 units and down 31 units
because the vertex I had gotten from number 6 is (-6,-31)
i dont think this is correct
oh, and sorry, its definitely not a plus there
this is wrong, im tired lol
its a down ward shift
this is not the vertex
you dont need the vertex necessarily to do this
id go as far as to say this is a bad way to approach this problem although its nice here since x^2 has such a trivial vertex
its more just normal translation and transformation
for f(x), f(x-a) moves a to the right by a units
for f(x), f(x) + b moves b up b units
so f(x-2)-4 moves f(x) to the right 2 units, and down 4
you can do it your way though
the math might have just gotten messed up
you should get to (x-2)^2 -4 = x^2 -4x
then the x coordinate of the vertex is -4/-2 = 2
which checks out
since the x coordinate of the vertex of x^2 is 0, and we expect (x-2)^2 -4 to be shifted 2 to the right
Why is it downwards shifting again or opens downward?
dont worry about opens
it doesnt even really matter if it opens up or down here, translations are still going to work the same way even if this thing isnt a parabola
its shifting downwards because of the -4 piece
f(x) - 4 right
you start with some f(x)
we usually pair up like
f(x)=y
this gives us our y coordinate for some x
then you go through and plot all the (x,y) or probably use a computer or your imagination
thats how you get a graph
now f(x)-4 is just y-4
for every x
so for every (x,y), we now have (x,y-4)
Ohh sorry, I was just curious of the "opens" part because my alg 2 teacher says "include the direction where it opens" if it's a parabola
just every point, moved down 4 vertically
ohhhh
well there are a lot of ways you can answer that question
but the direction it opens is indepedent of the direction its shifted
you can think about if a is positive or negative in (x-2)^2 - 4
alternatively if the vertex is a minimum then it opens up
alternatively, f(x) is just x^2 right?
does f(x-2)-4 flip the parabola?
I said opens upward because I'm generally assuming a positive 1 is outside of the parentheses
yea
So it would be an upwards opening parabola. π
usually what flips the parabola is something like
-2f(x)
it would be opening up, yea
which you can confirm in like 20 different ways if you wanted to
or just look at your parent function
and see if youve done something to break it
Also for this problem how do I put whether or not it's a wide or thin parabola?
my teacher wants me to include that also
oh
trying to explain it as best as I can
My teacher's notes say #>1 is thinner while 0<#<1 is wider
so i warn everyone but like just be aware that a lot of this language about uhh
thinner and wider or stretches and squishes or whatever they call it
so I guess the imaginary one isn't bigger or smaller than 1
imaginary one outside of the parentheses
Neither.
yup, id agree
in a more uhh
thinking about the points moving
idk if this is helpful but
well its not gonna be helpful
lol i was gonna talk about linear maps
but thats maybe too much
idk if youve ever seen like
transformations and stuff on just a number line
instead of a plane
i dont think i saw them before i saw these kind of things you are looking at
and it would have been helpful
me too
π
im so tired
haha
its pretty cool like
well its so hard to explain over text
if you imagine the x and y axis as number lines, this transformation is really just grabbing them both and sliding them a little
i think this is the more sensible way to think about them
than like is a factor bigger or less than 1
and then you have like stretches that are really compressions but by reciprocal factors
its very weird terminology
anyways how do you feel on the questions now
i think im gonna go to bed
unless you had more confusions
@languid scaffold

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If a conic section is defined as the ratio of a the length from the focus and the perpendicular distance from the directrix to be the constant eccentricity then how do we say the eccentricity of a circle is 0?
circles are an edge case
if you take an ellipse and move its two foci closer together while keeping the focal sum constant, the directrices will go off to infinity
so circle is an ellipse with the directrix at infinity?
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<@&286206848099549185>
what are you having trouble with?
do you know how to find the average of a set of numbers?
u collect thae amount of numbers than put in order right?
what?
sorry i dont
to find the average of a set of numbers, you add all the numbers together, then divide by how many numbers you had.
for example, the average of 5, 2, 3, 420, 69 is (5 + 2 + 3 + 420 + 69)/5.
so do i add the bicycles sold than divide
that's a somewhat butchered version of what i said, but yes.
monthly fixed costs went up by 2000? what were they before that?
it should say somewhere in the problem
500 right?
no...
your image doesn't say what the fixed monthly costs were pre-expansion. so i have no reason to think they would be Β£500
can you please screenshot and send the whole problem, with all parts?
is there nothing before "The company decided to expand"?
this is the question before i was skipping through the question sorry
this question is so long 
hold on ive got the full one
how many paragraphs are there π
was wondering what does it fix 
so let's come back to this, shall we?
yeah
alright.
so in our case, what income do we have?
or rather
where does our income come from?
i don't want any numbers here.
i want you to reason through how the company gains money rather than how much of it.
come from the company?
source of money basically
what, are you gonna tell me the company has a money printer? 
the company produces bicycles?
producing bicycles by itself does not create money for the company.
a maximum of 40 bicyicles per month
oh sorry
right right
because when you sell a bike, that's when the customer gives you money.
so we have:
INCOME
Bicycle sales
EXPENSES
???
we aren't done yet obviously
right obviously
but i wanted to make sure you understand the cash flow here rather than just apply some memorized formulas.
right
so what are our expenses?
this time, unlike income, there's more than one thing to consider
do i put nuimbers now?
no
no numbers
we're still figuring out where money comes from and where money goes
err
we will have two things that the company needs to spend money on.
rent, salaries and utilities are lumped together under fixed costs.
rught
there's something else we need to spend money on.
materials?
you've got the right idea.

we abstract this away into variable costs, which in practice would include the materials as well as labor wages for whoever assembles your bikes
basically anything that depends on the number of bikes produced, we call it variable costs. this simplifies our accounting somewhat.
ah ok
INCOME
Bicycle sales
EXPENSES
Fixed costs
Variable costs
so now, we have the option of calculating profit per month or calculating profit for the whole six-month period at once.
i personally think it would be better to do it per month simply because most of our costs are given per month.
are you ok with that?
yes thats fine
alright
so let's look at bicycle sales
how many bikes did the company sell per month (on average)?
numbers?
yes, now that we've got our balance sheet ready we're going to fill it with numbers.
if so Β£12,000
no
?
"how many bikes blah blah blah?" "twelve thousand pounds"
think about what question i'm asking you
don't just blurt out the first number that pops into your mind.
right ok
you alr found it!!
^
40?
you have already calculated this number. all i'm asking you to do is read it out.
i suck at maths
no, it's not 40.
look at the blanks you filled in earlier 
this isn't even math anymore this is just basic reading comprehension
49
that's right.
ohhhhh
Β£1000?
oh 800
39200?
are you unsure?
no im sure
then why the question mark
the answer is 39200
okay, yes, the sales revenue is 39200.
and since that's our only source of income, it's going to be our total income.
INCOME
Bicycle sales 49 * Β£800 ............... Β£ 39,200
EXPENSES
Fixed costs
Variable costs
okay, now the fixed costs.
what are our monthly fixed costs?
12,000 per month
14,000
yes.
INCOME
Bicycle sales 49 * Β£800 ............... Β£ 39,200
EXPENSES
Fixed costs ..........................Β£ 14,000
Variable costs
and now the variable costs.
how many bikes did we produce?
500 remained the same
read the question i'm asking you
"how many bikes did we produce?" "500"
no, we didn't produce five hundred bikes.
oh yeah that was the cost
again,
reading comprehension,
you should understand that "amount of bikes produced" is not the same as "production cost per bike"
40
40? why 40?
it says the company can produce 40 per month maximum
49...
Β£1,000
no
think about it
why would you spend 1000 quid to produce a bike that only sells for 800
tbh im confused about the order of the information 
"cost to produce" β "selling price" β "old selling price"
im not sure when did the maximum kick in
800 sorry
the cost of producing a bicycle remained the same (Β£500)
ohhhh ofc
again
this is all in the problem
you just need to READ it
not fish out the first number you see
right right
you know how to read, right?
i do man
yeah so
why aren't you reading
or at least
it feels as if you aren't reading the problem
i just skim through the info
okay okay
skimming makes it easier to miss details and hence having mistakes 
49 bikes
costs Β£500 to produce each one
how much do we spend on production in total
im not sure
Β£500 to create one, how much you need for 49 of those
Β£24500
!!!
wrong??
please
you said you skimmed the problem
can you at least not skim my messages
cause it sounds like you did just that
and things you were able to do mere minutes ago now you're saying you're "not sure"
yes it's 24500 it's literally just multiplication...
INCOME
Bicycle sales 49 * Β£800 ............... Β£ 39,200
EXPENSES
Fixed costs ..........................Β£ 14,000
Variable costs 49 * Β£500 ................Β£ 24,500
so now we have all this
can you now tell us
what the profit per month is
based on this MONTHLY income/expense analysis
so i did 39,200/14,000?
is that meant to be a division symbol
yes
why are you dividing 

i asked you if you knew this, and you said you did, but then half an hour down the line you completely forgot about it?
profit is income MINUS expenses.
i read your message as divide
i wqas confused at first
no, that slash did not mean division.
thought so
25200
how are you getting that?
Β£1000
i added the fixed and variable then minused from income
so, you added the fixed and variable costs, and what did that give you?
please reply as a complete sentence like this: "I added the fixed and variable costs and got Β£_____."
sigh
okay
so you got 38500 as the total expenses
and then you subtracted that, or "minused" as you say, from the income.
and what did you get from that?
wdym i am
so you got 38500 as the total expenses
and then you subtracted that, or "minused" as you say, from the income.
and what did you get from that?
the answer to this question is meant to be a number
i'm asking you about a step in your calculations
i'm not asking you to look at it and tell me whether it's wrong or not
i'm asking you to tell me what it is
cause i'm supposed to be the one judging whether it's wrong or not
what NUMBER did you get holy shit just tell me the bloody number already wont you
and got 700 now
THERE WE GO
FINALLY
after like
5 rounds of back and forth
you now give me a number
finally
i was doing it step by step like u said
yes
this is correct
700 pounds per month
now
we weren't asked how much profit the company made per month
we were asked how much profit the company made in six months
so how much would that be?
i did 700 x 6 and got 4200
there we go
in all seriousness, this was like 10% arithmetic and 90% reading comprehension.
thank you
lol nice
i need help on this please

on every single one?
uh ye sure
so
the 1st question is asking you about the number of students in the sport
so, whats the number of students in total (read the question)
20,000
and the % of students that are member of warwick sports
27% of students and 17% of employees
yes yes
so the question is asking about number of students in the sport
how can you calculate it
you already listed the things to get the answer of Q1
err
20000 students and 27% is in the sports
do we do 27% students of 20,00 stud
thank you thank you
so, for Q2, it is asking you the total number of members
what makes the total number
student + ?
could i just add 20000 and 5000
well thats the total number of students and employee
we're trying to find the total number of members
so there are two types of people in the sports, students and?
employees?
yes yes
then find the number of employees in the sports
like how we just found the number of students in the sports
so 17% of 5000?
you can be sure about your response π
850?
yes yes
so, the total number of member is?
i got 6250
Q3 is asking the percentage of all ppl in the uni. that is in the sport
so how many people in total is in the uni?
there's 2 types of ppl from what we talked about, students and employees
theres 6250 people
err
do i add 20,000 and 5,000
thought it was wronmg
well whats the result of that?
25,000
6250 people in the sports
im unsure
thank you
no off. but what grade are you?
grade?
you dont know whats grade?
well im in year 12
..
well nvm, lets pretend i didnt ask that question
continue with calculating the %
and lmk if you got answer
thanks
reposting so i dont have to keep scrolling 
right will do
so probability
pretty similar to percentage stuff
so its like asking you
what are the chances of picking a guy that is in the sport
among everyone in the university
so same question, what is the total number of people in the sports and in the university respectively
we alr calculated those, just trying to remind you again
else you will forget all of those in split seconds
the total number of people in sports 6250
yes, and the ppl in the university?
in the uni is 25,000
YES
so
probability = event/all outcomes
so event is basically the people in the sports
that the question is asking you the chances of picking one
and all outcomes = all the people in the university
so how would we calculate the probability?
by doing 6250/25000
i got 0.25
then thats the answer
ye ty
so
Q5 is asking which campaign gives a greater increase
so we have 2 campaign
A increases student members by 1.5%
and B increases employee members by 6.5%
so, our current total member count is 6250 right?
right
try to calculate the total number of members after campaign A and campaign B respectively
and send the answer here
im unsure on this one
well you can do the old fashion way
recalculate the entire thing by changing 27% to 28.5%
or you can just add 1.5%*20000 (the increase of student members) to 6250
im trying to get you to find the number of members after the campaigns
so. campaign A gives us extra 1.5% of the students to become members
so how many people is 1.5% of the students
1.5% *20000 is 300
6550
so now, do the same mindset but with campaign B
campaign B increases employee members by 6.5%, meaning we will get an extra 6.5% of employees to become our member
so how many people is 6.5% of employees?
1300?
ok so
total number of employees = 5000
6.5% of that is?
we're finding EMPLOYEES now
not students
this is another campaign, campaign B
yes yes
and add that to 6250, which makes 6575
so now, tell me
6550 or 6575 is larger
YES
ty
i did
nice!!
so now
we have the last question, question 6
what would be the new percentage of all the ppl that would be the sports member after the campaign launched
so
the campaign is refering to the campaign we got from Q5
which is campaign B
and we found that 6575 is the new member count after that campaign right?
right
so
total number of people is still 25000
that never changes
no matter how many fucking campaigns you launch
so still
lol okay
percentage = ppl in sports/all ppl * 100%
so how would you calculate the percentage?
do 6250 /25000*100?
oh
so what is the total number of people after campaign B again?
6575
ty i did
@mortal siren Has your question been resolved?
Your principal amount is 5000
Interest rate is 3 percent
And thereβs 48 months in 4 years
And it gets compounded monthly
Plug the values into da formula
@mortal siren u got it ?
still confused

