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remote heron
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no

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its fine

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its not a special case

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lone heartBOT
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pale kestrel
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huh what?

remote heron
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its not special

pale kestrel
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if n = 0, x can be anything?

remote heron
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2/5 ^ 0 = 1

pale kestrel
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x can be anything non-zero

remote heron
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eh

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austere star
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hello

lone heartBOT
austere star
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can I have help

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random mica
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Hello, how do you find this root from the equation without quadratic formula, just roots extractions

random mica
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there is 4 roots it seems, i found the other both

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but i don't get how i can find this one

pale kestrel
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if a is a root of the polynomial f(x), (x-a) is a factor of f(x)

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does that help?

random mica
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wil ltry

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well it become very odd, there is no way to solve it other way without quadratic equation or else ?
for the first root i did 4th roots on both side to remove the power of 4 and get sqrt(8) on right

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alpine sable
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Π(a+n-t) from t=1 to b+1

alpine sable
lone heartBOT
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@narrow pawn Has your question been resolved?

raw shard
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it would be $\prod_{t=1}^{b-1}(a+n-t)$

ocean sealBOT
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quantum

alpine sable
raw shard
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no it’s not

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you said b+1

alpine sable
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Oh yeah

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And it's b-1 bc - (b-1)=-b+1

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alpine sable
lone heartBOT
alpine sable
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I need to find the determinant of this matrix

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the answer I got is -57

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but the key says -41

lone heartBOT
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@alpine sable Has your question been resolved?

alpine sable
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<@&286206848099549185>

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My calculator says minus 11

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Do it again

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Its basic four operator question

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Actually instead of doing it again, show me what you multiplied and summed

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Maybe your process is wrong idk

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We'll see

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@alpine sable

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3 x |-5 2 3 1| -1 |8 2 -4 1| -2 |8 -5 -4 3|

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I don't use that method personally

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There is an easier one

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Logic is the same but visually it's better

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yea ik that method, it's very hard for me

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Seriously? I thought people use it more

alpine sable
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But anyways, your process is correct

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I think you probably made calculation mistake

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It happens to everyone

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I'm so stuck on where my calculation mistake is

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It's not important

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The point is knowing what to do

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You are wasting time looking for a simple mistake

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Don't you agree?

alpine sable
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thank you

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Np good luck

alpine sable
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rich basin
lone heartBOT
rich basin
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can someone please explain this

lone heartBOT
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@rich basin Has your question been resolved?

rich basin
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<@&286206848099549185>

rich basin
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this is for (ii)

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@rich basin Has your question been resolved?

lone heartBOT
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@rich basin Has your question been resolved?

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stable olive
lone heartBOT
stable olive
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pls help

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<@&286206848099549185>

buoyant kayak
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what exactly is giving you trouble here

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don't do people's work for them

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...

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if you want to

stable olive
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thank you here

buoyant kayak
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he's already seen it

stable olive
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from lhs to rhs

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ohh yes

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alpine sable
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what is 0÷0

lone heartBOT
buoyant kayak
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undefined

alpine sable
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oh wait I figured it out imagine that you have zero cookies and you have zero friends to give them to see it doesn’t make sense and you have no cookies and no friends

buoyant kayak
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thanks siri

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atomic lodge
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hi

lone heartBOT
atomic lodge
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can anyone help me with the derivative of ln[In(x)]

gray isle
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what have you tried?

atomic lodge
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i think it somewhat like chain rule so i got

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oh wait i know what i did wrong

gray isle
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are those u and v?
its hard to tell them apart

atomic lodge
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hold on

strange shale
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Your v is too differentiable if you know what I mean thats why it looks like a u

alpine sable
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hello guys i need a help with me homework

rough gale
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yes?

alpine sable
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what would be a answer ?

buoyant kayak
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lone heartBOT
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hybrid blade
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Hello, why is it that the area under the curve equals the integral of the function?

jagged imp
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The integral of a function is pretty much defined as the area under it. What is it that you think an integral is?

hybrid blade
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the inverse function of the derivative?

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I understand that it is defined as the area under it

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but I want to know why that is the case

alpine sable
hybrid blade
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yes

inland gyro
hybrid blade
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yes please do

jagged imp
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oh... good thing sloct corrected that. I guess i was completely misunderstanding what you were asking..

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alpine sable
lone heartBOT
alpine sable
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the length of the green line = 9.7sin14 = 2.34

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@buoyant kayak

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bottom angle of triangle = asin(2.34/8.1) = 16.8

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so therefor we know the angle z2 makes with the x-axis = 180 - (180 - 14 - 16.8) = 30.84

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then the real part of z2 is 8.1cos(30.84) and the Imaginary part is -8.1sin(30.84)

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so why is this wrong

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grave urchin
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Is this correct? or does tan theta < 0 make it false?

tropic sluice
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how is tanΘ < 0?

grave urchin
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isn't tan theta= 4/3 which is greater than 0?

vale wigeon
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you did not take into account the sign info given to you by the problem

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"isn't tan(θ) = 4/3 which is greater than 0? ...wait that means i fucked up didn't i"

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notation is a little all over the place too

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cos(theta) should be **-**3/5.

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precisely because tan(theta) is known to be negative and sin(theta) positive

orchid sparrow
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yes beacause -3^2 is 9

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there will be 2 values of base

grave urchin
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oh because sin is positive and tan is negative, cos must be negative

orchid sparrow
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coz the equation will be quadratic

grave urchin
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alpine sable
lone heartBOT
alpine sable
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|4x| =< 1 , |x| =< 1/4

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i know that

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what i dont know is why

woeful heart
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you know the generalised binomial expansion for (1+x)^n is valid for |x| < 1 right?

alpine sable
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yh i know it is

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but am unsure like why

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i know it is simply because it says that it is in my datasheet

woeful heart
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so if you have a sequence of numbers and sum them, sometimes you get a convergent sum and sometimes u have a divergent sum

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convergent means its finite divergent means its infinite

alpine sable
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yh

woeful heart
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if you have |x| >= 1, then if you look at your formula

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for expanding the binomials

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the terms don't eventually "get small", so it's impossible for it to be convergent

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as in they don't tend to zero

supple tundra
woeful heart
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just some intuition

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yeh im not being formal

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like if u see the terms for |x|<1, you can see the factorial terms tend to approximately 1 eventually

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so if you look at the series sum its less than a geometric sum

alpine sable
woeful heart
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which we know converges

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we know a geometric series converges if and only if the common ratio r < 1

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and this formula looks sort of like that when you get to the big numbers

alpine sable
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ah alright, thanks

woeful heart
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but yeah if u want rigour u need to learn a lot more stuff

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u need an actual textbook with all the definitions and build everything up from first principles

alpine sable
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yh ill have a look, thanks.

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frank plover
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I can't seperate the concept of vector spaces and a euclidian vector space 4 some reason, i keep trying to think of any vectors (take functions) as points in a R^3 space.. i think it has to do with the coordinates a euclidian vector space has

frank plover
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i guess in a way my question is, what are coordinates in terms of the vector space definition of euclidian space and do coordinates have any meaning for non euclidian vector spaces like the space with polynomials of any degree

vale wigeon
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coordinates have meaning when you construct a basis

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once you have a basis, you can write a vector in your space as a linear combination of your basis vectors

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and the coefficients in said linear combination will be the coordinates of your vector in that basis

frank plover
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How do you get a basis in R^2 (for example) without first having a coordinate system

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I guess it has to do with what i define to be my vectors in my vectorspace/set but i cant seem to put it in words

vale wigeon
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(1,0) and (0,1)

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these form a basis

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they are vectors in R^2 by the definition thereof

frank plover
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but (1,0) and (0,1) have no meaning without a coordinate system right?

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unless i just see real vectors as a list of numbers and think of euclidian space as a way of representing them

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i think thats my issue, i try thinking of vector spaces spacially, in my head vector spaces are R^n but the axis are changed to their respective basis

vale wigeon
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R^2 is by definition the set of ordered pairs of real numbers

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(1,0) and (0,1) are just as valid pairs of real numbers as (420,69) or (pi,e) or (32.34526435645, -0.4948485)

frank plover
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Oohhh okey okey

frank plover
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If R^n is defined that way, is the euclidian space of R^n just a way of visualizing it?

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And can i visualise all vector spaces like that if i think of the axis as their basis (for example 3x3 matrices-space) with x-axis =
\begin{pmatrix}
1&0&0\
0&0&0\
0&0&0\
\end{pmatrix}

ocean sealBOT
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نعمان
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

frank plover
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no wait

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the axis should be coefficients and the unit is just 1 basis matrix (3x3-space)

vale wigeon
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i think you might be overthinking it

crisp summit
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hey

frank plover
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Or i just suck at explaining what i mean lol

crisp summit
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anyone that can help me?

frank plover
vale wigeon
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@crisp summit please move to an available channel to receive help.

crisp summit
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uh okay tho, but what if its urgent

vale wigeon
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go get your own channel

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it's going to take less time than you're spending here arguing and trying to intrude on another conbo

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convo*

crisp summit
vale wigeon
frank plover
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but anyway, is what i'm saying a correct way of thinking?

vale wigeon
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the way it's worded is very wonky

frank plover
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lol true

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Hold on i'll try to explain what i mean better

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but first some questions

frank plover
vale wigeon
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well

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i suppose in some sense you could say that

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but im apprehensive about going full "yes this is exactly how that works"

frank plover
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alright

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Well if i assume it to be a way of visualising R^n

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Could that visualisation, using axis/coordinates defined by the basis vectors, be applied to any vector space?

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For example, in the 3x3-matrix vector space. The basis vectors are

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For x:
\begin{pmatrix}
1&0&0\
0&0&0\
0&0&0\
\end{pmatrix}
For y:
\begin{pmatrix}
0&0&0\
0&1&0\
0&0&0\
\end{pmatrix}
and for z:
\begin{pmatrix}
0&0&0\
0&0&0\
0&0&1\
\end{pmatrix}

ocean sealBOT
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vale wigeon
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no

frank plover
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or for the space of polynomials up to (inclusive) degree 2, the basis vectors would be "1" "x" and "x^2"

vale wigeon
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the space of 3x3 matrices has dimension 9, not 3.

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you're trying to pass something off as a basis that isn't

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the matrix $\bmqty{0&0&0\1&0&0\0&0&0}$ isn't a linear combination of the three matrices you presented

ocean sealBOT
frank plover
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Oh

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I guess the basis' are matrices with a 1 in one place and zero's in all the others

vale wigeon
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no such thing as "the" basis

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every real vector space has infinitely many possible bases

frank plover
vale wigeon
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it's convenient to express matrices in terms of

frank plover
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are there any criteria about which basis to use for a vector space?

vale wigeon
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no

frank plover
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hmm

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alright

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Thanks for the help! in a way i kindof understand my original question better now haha

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vague iris
#

I got 16 lies on the last question. I don't know how they got 10 or 20?

vague iris
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3(12)=2(1.2)^x
this is my equation

vale wigeon
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let's see

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so this reduces to 1.2^x = 18

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,calc log(18)/log(1.2)

ocean sealBOT
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Result:

15.853154222255
vale wigeon
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that... yeah, that sounds like 16

vague iris
#

.close

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wary plaza
#

I need to find an equation of the plane passing through the given point and parallel to the indicated plane. (6,5,-2), x + y - z + 1 = 0. I'm not getting the right answer. I tried using the the equation of a plane by getting the normal vector to be (1, 1, -1) from the plane. What am I doing wrong here?

vale wigeon
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what equation did you get

wary plaza
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$x+y-z=-12$

ocean sealBOT
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satoshi

vale wigeon
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this does not pass thru (6,5,-2)

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your right hand side should be 6 + 5 - (-2)

wary plaza
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so $x+y-z=13$

ocean sealBOT
#

satoshi

pale kestrel
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not sure how you couldve gotten 12

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-12

wary plaza
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$(x-6)+(y-5)-(z-2)=-1$

ocean sealBOT
#

satoshi

pale kestrel
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thats not the way

wary plaza
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how would I go about it then?

pale kestrel
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You have the answer already from what Ann said

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but if u want to use vec equation of plane

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its r.(1,1,-1) = D

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where D is to be determined

wary plaza
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D is 13?

pale kestrel
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yes

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You find it by inputting the specific

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r

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you are given

wary plaza
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yeah, thanks I have one more question

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Find an equation of the plane through the given point and witht he specified normal vector. (1,2,3), n = 15i + 9j - 12k. Here I get $15x+9y-12z=-3$, but thats wrong

ocean sealBOT
#

satoshi

pale kestrel
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its probably because you used the same wrong method?

pale kestrel
wary plaza
#

I just plugged in the numbers in the equation of a plane

pale kestrel
#

what is the plane equation

wary plaza
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$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$

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here a = 1, b = 2, c = 3

ocean sealBOT
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satoshi

pale kestrel
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im a bit confused myself

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i get -3 as well

wary plaza
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I used it for a similar problem, and I got the right answer

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according to my book the answer is 5x+3y-4z+1=0

pale kestrel
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well you can quickly check

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5+6-12+1 = 0...

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but that normal vector is completely wrong

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its not 1 2 3

wary plaza
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oh wait yeah

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sorry

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its (15, 9, -12)

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(1,2,3) is the point

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but I will still not get the right answer

pale kestrel
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wait im confused lol let me see

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no your answer is correct

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you just didnt factor out 3?

pale kestrel
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my bad, misread

wary plaza
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oh yeah

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sounds good

pale kestrel
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i havent seen this way before

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back to the 1st one

wary plaza
#

$15(x-1)+9(y-2)-12(z-3)$

ocean sealBOT
#

satoshi

wary plaza
#

$15x-15+9y-18-12z+36$, right?

ocean sealBOT
#

satoshi

pale kestrel
#

idk i havent seen this method before, like i said

#

the one I use is to use vector form

wary plaza
#

the book wants me to use that method

pale kestrel
#

r . n = D

#

They both end up doing the same math, im sure

wary plaza
#

I havent seen that form. How does that one work?

pale kestrel
#

you know dot product?

wary plaza
#

yes

#

r dot n?

#

is that what you mean

pale kestrel
#

yes

#

r is the variable vector

#

call it (x y z)

#

and you end up with the same plane equation

wary plaza
#

so in this case (1,2,3)?

pale kestrel
#

r . n = r_0 . n

#

You can also write it like this

#

if you have the normal vector n and a specific r_0 you know is on the plane

wary plaza
#

whats the method called?

pale kestrel
#

vector equation of plane

#

If you rearrange the math

#

you will end up with the aame formula you use

#

but i find think this is easier to remember

wary plaza
#

ive only seen people use the equation of a plane

pale kestrel
#

the intuition of this form comes from r . n = 0 means r and n are perpendicular

#

then the right side D, translates the plane

wary plaza
#

alright, cool

lone heartBOT
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runic condor
tame falcon
#

.close

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frank plover
#

What do points on a plane in R^3 have in common? I know it's a very simple question but my brain is overworked rn and i cant wrap my mind around it.

frank plover
#

I know something has to be held constant but idk what? (i think this because in the cases of xy/yz/zx -planes one of the three coordinate values is held at a constant 0)

pale kestrel
#

ngl theres a lot you can say

#

you can describe the plane by saying all the points satisfy an equation

severe sluice
#

well
i guess there's a value of a,b,c,d so that ax+by+cz+d=0 (literally the equation of a plane)

frank plover
#

oh yeah lol, i forgot about that equation.

#

So all the points on a plane have a,b,c and d in common, right?

frank plover
#

catThink thanks!

#

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dire basin
#

hi, i was doing some simulations for a three sided dice. Assuming i found a dice which has 1/3 probability of landing on each of it sides and i do a 1000 throws. We know that it is almost impossible that all the three sides(up, down, edge) come up 333, 333, 334 times(not particularly in this order). My question is what range of values can i accept so that i can assume that the dice i created is almost completly fair. example say i get 310 ups, 340 downs and 350 edges, can i say that this dice is fair?

dire basin
#

basically i dont know a lot of stats so i had to ask here

#

sorry if i phrased this badly

severe sluice
vale wigeon
#

if you want a physical design just do a cube with two sides labeled with each number

dire basin
severe sluice
vale wigeon
#

anyway look into hypothesis testing

#

and confidence intervals

bleak ridge
#

Hypothesis test gives me ptsd

dire basin
#

uhhh i have no idea what this is but i guess ill give it a look

pale kestrel
#

it is possible, but just very unlikely

dire basin
#

ye ik

#

u get my point tho 😅

pale kestrel
#

in the end, what range if values is kindof up to you

#

in stats you choose your confidence interval

#

but you choose it first, then run your experiment

dire basin
#

ok so umm a lil context here. this is basically for a physics competition. so i thought that maybe we have to find the range through some mathematical means but if i understand correctly u mean that i can just say that if the results are all in the range 310-340 the dice can be deemed fair(kinda)

#

the range means the number of times each of the three sides pops up after a total of 1000 throws*

pale kestrel
#

kindof, and you should justify your choice of confidence interval before doing the experiment

#

you need to work out the probability of this happening 310-340

#

if you choose that

dire basin
pale kestrel
#

find the distribution

dire basin
#

i dont know stats that's why i asked here 😥

lone heartBOT
#

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vestal aspen
lone heartBOT
vestal aspen
#

Can someone help please

#

Number 16

teal turtle
#

Do you have graph paper?

merry iris
#

Graph it

vestal aspen
#

Yes I do

vestal aspen
merry iris
#

Find where they intersect

#

That’s the answer

#

Because it satisfies both equations

vestal aspen
#

I just got done with my break and I forgot how to find slope

merry iris
#

Slope is the coefficient of x

teal turtle
#

Equation of line is y = mx + c, m is the slope and c is the y intercept

#

how did you do 15 without knowing how to find slope though?

vestal aspen
#

15 isn’t circled

merry iris
#

Lol

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weak snow
#

It's possible to integrate a matrix?
I have an formula that gives to me an integrate but the integrator will be a matrix.

weak snow
#

I need to "integrate" this:

#

Maybe i'm doing something wrong

#

idk

pale kestrel
#

I think by convention, thats what you do (I'm not 100% sure)

frank plover
pale kestrel
#

Don't think any other interpretation makes sense

weak snow
#

I can show more details of the problem if you want

#

Sure, one second

#

I have this sequence where f(x)=x'

pale kestrel
#

<@&268886789983436800> think troll ^

#

in a few channels

weak snow
#

and this EDO problem

#

I already find the solution which is x(t)=acos(t)+bsin(t); y(t)=x'

#

now I must to show that the sequence converges to the solution.

#

But i dont know how i can evaluate this sh*t

lone heartBOT
#

@weak snow Has your question been resolved?

lone heartBOT
#

@weak snow Has your question been resolved?

weak snow
#

<@&286206848099549185>

lone heartBOT
#

@weak snow Has your question been resolved?

karmic quail
#

Linear equation

#

2/3x= 1/4 - 1/6x

lone heartBOT
#

@weak snow Has your question been resolved?

acoustic spire
#

hi

lone heartBOT
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orchid pulsar
#

Is this correct?

lone heartBOT
bleak ridge
#

Did it just ask to set up the sum and integral?

orchid pulsar
#

Yes

bleak ridge
#

I mean it looks right to me

orchid pulsar
#

Alright thank u!

#

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timid jewel
lone heartBOT
timid jewel
#

Part i

#

@glass lichen Im just not getting anywhere im so confused

glass lichen
#

You already did part i.

timid jewel
#

yeah U x V

glass lichen
#

Yes.

#

so why the hell are you asking about it again?

timid jewel
#

ii

lone heartBOT
#

@timid jewel Has your question been resolved?

pale kestrel
#

without reading the material

#

you're not gonna be able to do it

#

these questions are getting deeper and deeper into the subject

#

better to read the material or watch videos to understand

lone heartBOT
#

@timid jewel Has your question been resolved?

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bold mantle
lone heartBOT
bold mantle
#

help

vivid charm
#

what have u tried

bold mantle
#

i want to do the think where it goes, what 2 numbers multiply to get -4 but also add/subtract to get 11 and i dont think thats possible

#

and i dont know another way

vivid charm
#

hmm

#

well lets try it-

#

how wud u factor 4

placid zinc
#

You're ignoring the 3, which changes how you'd think about the problem

vivid charm
#

well actually let's write out (3x .........)(x ........) for now

bold mantle
#

what

#

the 3?

vivid charm
#

yeah!

#

u have a 3x^2

bold mantle
#

yep

vivid charm
#

do u know how foiling works

#

or wutev u call it

bold mantle
#

yeah foil

vivid charm
#

i dun call it foil but ik ppl do

bold mantle
#

i call it foil

vivid charm
#

alri- so

#

lets just set stuff up first

bold mantle
#

wait let me try ut

#

it

#

pls

vivid charm
#

alri

#

u try it

#

ping me if ur confuzzled

#

or if u wan check

bold mantle
#

ok

#

@vivid charm lol sorry im stuck

#

i remember today learning about how i need to split the 11x

#

but i dont remember how to do ot

#

it

vivid charm
#

u shud be splitting 4

#

how would u split 4

bold mantle
#

ok

#

how

#

where do i put the two 2's

gray isle
#

applying the ac method
i.e. consider a pair of numbers that multiply to ac = 3 * -4 = -12
and sum to b = 11

#

use that to determine how to split the 11x and continue with factorisation by grouping

lone heartBOT
#

@bold mantle Has your question been resolved?

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paper coral
lone heartBOT
paper coral
#

i do not get this solution

#

so it says

#

well

#

let me get the question

swift harbor
#

side note is dat baki in ur pfp

paper coral
#

so the largest positive integer m for which 2^m is a divisor of 9!

#

yes

#

baki is epic

#

not cap

#

so isn't this saying (2^m)/9! where m is a integer and where that number is a integer

#

i cannot read nvm

#

.close

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nimble bane
#

How do I do this question

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#

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alpine sable
#

is the correct answer none of the above? i got x = 848.5 and y = 1697

wary stream
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#

@alpine sable Has your question been resolved?

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nimble bane
#

how i do this

lone heartBOT
nimble bane
lone heartBOT
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@nimble bane Has your question been resolved?

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tranquil kestrel
#

anyone can solve 2b)?

lone heartBOT
#

@tranquil kestrel Has your question been resolved?

hybrid blade
#

have you done 2A?

#

if so, can i see what you put

#

i may be able to help

#

A->W>or equal to 20

#

where w is the amount william drinks

#

B->W<20

#

C->W>or equal to 5

#

W<20 is logically equavelant to ~(W>or equal to 20)

#

therefore A and B are contradictories

#

If C is true, then either A or B is true

#

C-> A V B

#

C-> ~(A & B)

#

ok im not gonna use w

#

A -> ~B

#

B -> ~A

#

therefore ~B -> A

#

therefore A iff ~B

#

and B iff ~A

#

A -> C

tranquil kestrel
#

sure let me show you mine 2A

hybrid blade
#

therefore A -> ~B & C

#

B -> ~A

#

C -> A V B

#

idk llol

tranquil kestrel
#

My 2a) is Just the lines as given. A= He drinks at least 20 cups a day, B=, William drinks less than 20 cups a day and C= at least 5 cups a day. Basically wrote these.

hybrid blade
#

ok

#

~C -> ~A

tranquil kestrel
#

Then this is my 2b)

#

Which i tried to do

#

😅

hybrid blade
#

.rotate

#

is there any more to the problem?

#

or is this all

tranquil kestrel
#

so my working is wrong right?

hybrid blade
#

i dont know

#

i cant read your writing lol

tranquil kestrel
#

lol sorry

hybrid blade
#

i see

#

A -> ~B & C

#

B -> ~A

#

C -> A V B

#

If A is true, then ~B & C

#

the question wants to find who specifically (as in one person?) is right

#

therefore A cannot be true, for it implies that C is true and therefore two propositions are true

#

C implies that either A or B is true, which also implies that at least 2 propositions are true

#

therefore C cannot be true

#

thus, it is only possible for B to be true?

#

idk

#

If B is true, then we know that A is false

#

but C may be either true or false

#

B is necessarily true only if ~A & ~C

#

~C-> ~(A VB)

#

if B is necessarily true then B -> ~(A V B)

#

I think the answer is B

#

im thinking too mich

#

Just take it like so:

#

A -> ~B & C
B -> ~A
C -> A V B
If A is true, then ~B & C
the question wants to find who specifically (as in one person?) is right
therefore A cannot be true, for it implies that C is true and therefore two propositions are true
C implies that either A or B is true, which also implies that at least 2 propositions are true
therefore C cannot be true
thus, it is only possible for B to be true?

#

lmk if u still want help

tranquil kestrel
#

wowo bro, really thank you for the detail explanation

#

thanks a lot

#

.close

lone heartBOT
#
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opaque inlet
#

Hi

lone heartBOT
opaque inlet
#

I’ve got a series of questions related to combinations and permutations

#

We’ll start off with question 12.

#

Can anyone help me on this pls

orchid sparrow
#

how many outcomes are there in first case ?

#

@opaque inlet

opaque inlet
#

Yes sir

#

Hmmm

opaque inlet
orchid sparrow
#

yes

opaque inlet
#

6 outcomes

orchid sparrow
#

ok in 2nd?

opaque inlet
#

6 outcomes? I think?

orchid sparrow
#

yes

#

ok now the total outcomes

#

will be?

#

?

opaque inlet
#

I meant 36 outcomes

orchid sparrow
#

yes

pale kestrel
#

Thats not the answer btw.

orchid sparrow
#

yes u have to subtract the repeated outcomes

#

half of them will be reapeated

pure wasp
#

It would be easiest to just count them out tbh

#

And if you roll 0 either time it will be 0

pale kestrel
pure wasp
#

Are you sure you’re in the right class?

orchid sparrow
#

and then you have to subtract 4 more as

opaque inlet
pale kestrel
#

There are 36 'outcomes' but a lot are the same

#

0*5 = 11*0

#

For example.

opaque inlet
#

Oh ok

pale kestrel
# opaque inlet

imo a better way to count this is to notice you have 5 primes

#

and 0

#

a slow but sure way is to draw a 6x6 table

#

and write down all the possibilities

#

and count the different ones by putting them in order

orchid sparrow
#

half of the results will be when the digits will be reversed. and you will get 0 five time so u have to subtract 4 also

#

so the answer imo will be 14

opaque inlet
#

Ok

orchid sparrow
#

@pale kestrel am i correct

#

i am not sure of this

pale kestrel
#

idk

#

no paper here

#

let me try with primes

orchid sparrow
#

hm

pale kestrel
#

you have 5 primes and you pick any pair (including repeats)

#

somethings wrong uh...

opaque inlet
#

Is there a quicker method than doing the table method you suggested?

pale kestrel
#

what im doing

#

so 5 choose 2

#

is 10

#
  • repeats
#

is 15

#
  • 0
#

is 16

pale kestrel
pure wasp
#

I got 16 too

pure wasp
opaque inlet
pale kestrel
#

so the 'quick' method

opaque inlet
#

Let me check my textbook

pale kestrel
#

you have 5 primes

#

You can choose 2 different ones to make a product

#

thats 5 choose 2 = 10

#

you can choose the same one (squares)

#

thats 5

#

then theres also 0

#

so a total of 10+5+1 = 16

orchid sparrow
#

if u choose 5 and 5 then wont the product be 25

hybrid blade
#

lol

#

2 different primes

#

5 is 5

orchid sparrow
hybrid blade
#

oh

orchid sparrow
#

i was asking this

#

u cant choose the same

#

imo

pale kestrel
#

i counted that

#

?

#

10 - different primes
5 - same prime
1 - 0

opaque inlet
#

The answer is 15

#

LOL

#

U got 14 and 16 but it’s in between

#

Coincidence

orchid sparrow
#

is there any answer key?

opaque inlet
#

Yes

pure wasp
#

Nah it has to be 16 unless they didn’t count 0

opaque inlet
#

Just 15

pure wasp
#

How

orchid sparrow
opaque inlet
pure wasp
#

??

opaque inlet
#

It doesn’t provide a working out nor explanation tho

orchid sparrow
#

lol

pure wasp
#

That’s an answer key

orchid sparrow
#

yea

opaque inlet
#

Sorry

pure wasp
#

But I mean the work is simple and I did it and got 16

#

And the smart guy got 16 too

pale kestrel
#

why dont we list all 16 😢

orchid sparrow
#

yes

pale kestrel
#

meh this is IB textbook

#

there are typos everywhere in those

#

especially in the answers

opaque inlet
pale kestrel
#

is this not IB textbook

pure wasp
#

0,4,6,10,14,22,9,15,21,33,25,35,55,49,77,121

opaque inlet
#

What is that

jagged imp
#

This is an australian textbook

opaque inlet
#

Aussie Aussie Aussie oi oi

jagged imp
#

oi oi oi

pure wasp
#

Math works differently there

opaque inlet
opaque inlet
jagged imp
#

ye

opaque inlet
#

I’m a fan of one piece too

pure wasp
#

Are you caught up donta

opaque inlet
pure wasp
#

Wya

opaque inlet
pure wasp
#

Where are you at

opaque inlet
#

I don’t understand the question?

pure wasp
#

WHERE ARE YOU AT IN ONE PIECE

jagged imp
opaque inlet
#

I’m an anime only

jagged imp
#

i wonder how you figured i was a op fan

opaque inlet
#

I just finished watching kaido vs the scabbards

pure wasp
#

Zoro dies

opaque inlet
#

So

#

Can we do question 16 and 17?

pure wasp
#

Doesn’t really make sense to me what do they mean by rotated

#

Like the squares or

#

Or is it just factorial

pale kestrel
#

means you have 3 types of floor tiles

#

that are 2x2

#

and find how many floor patterns you have that are 2x6

jagged imp
#

first find out how many ways you can rotate those in one order and multiply that by the total number of ways you could arrange the tiles

opaque inlet
#

4! + 3! + 2!

#

? Is that it?

pale kestrel
#

no.

#

probably not

opaque inlet
#

Damn

pale kestrel
#

each of the tiles, how many ways to rotate

#

no

#

take the 1st tile

#

how many possibilities

opaque inlet
#

4 possibilities?

pale kestrel
#

yes

#

2nd?

opaque inlet
#

4

pale kestrel
#

and same for 3rd right

#

each has 4 orientations

opaque inlet
#

Yes

pale kestrel
#

How each are oriented

#

does not affect each other

opaque inlet
#

Yes

pale kestrel
#

so you multiply the possibilities

opaque inlet
#

64?

pale kestrel
#

yh

#

next you consider position order

#

how many ways to order 3 things

opaque inlet
#

6 ways

pale kestrel
#

3!, so yes

#

and then?

opaque inlet
#

Calculate the other tiles?

pale kestrel
#

no..

#

there are 2 things that are important here

#

how the tiles are oriented

#

and how they are ordered

#

do these 2 things affect each other?

opaque inlet
#

Of course not

pale kestrel
#

so you multiply again

#

the key is, you have no repeats in counting like this

#

since the tiles all look different

opaque inlet
#

So 216

pale kestrel
#

6*64

#

is not

opaque inlet
#

Oh

pale kestrel
#

i said 3! above, not 3

opaque inlet
#

OHHHHH

#

That make sense

#

Sorta

opaque inlet
opaque inlet
pale kestrel
#

,w 6*64

pale kestrel
#

ok

opaque inlet
#

4! * 4^3 * 2

#

Is that the answer for b.

#

@pale kestrel

pale kestrel
#

nope

#

There's a tricky part

#

think carefully

opaque inlet
#

😦

#

Oh wait

#

Is the answer 4! * 4^3 * 2

#

Surely

jagged imp
opaque inlet
#

Cijc jimemjmfcr

#

Thank uuuuuuuu

pale kestrel
#

think u got it

opaque inlet
#

Les goooooooo

#

Can we do 17 now

pale kestrel
#

any ideas

pale kestrel
opaque inlet
opaque inlet
#

The same thing applies for m

#

But I can’t do anything with it

#

I don’t think

pale kestrel
#

wont necessarily help no

#

replace 720 by 24

opaque inlet
#

But why 24?

pale kestrel
#

and try the question

#

because i chose it lol

opaque inlet
#

Ok god

#

Lol

#

m! * n! = 24

#

Now trial and error?

#

m = 4 and n = 1

#

m = 1 and n = 4

pale kestrel
#

yh

#

let me see

opaque inlet
#

Ohhh

#

Did you choose 24 because it’s a factor of 720

#

Okie

pale kestrel
#

thats not the full reason

#

24 = 4!

#

hint.

opaque inlet
#

I don’t get it

pale kestrel
#

24 = 4!

#

the person who wrote the question

#

didnt randomly choose 720

#

i also didnt randomly choose 24

opaque inlet
#

720=6!

pale kestrel
#

yh

opaque inlet
#

Oh ok

pale kestrel
#

also be careful

#

it says in q

#

m > n

#

anyways, so you have 1 easy solution for starters

opaque inlet
#

m! * n! = 6!

#

m = 6 and n = 1

pale kestrel
#

ok

opaque inlet
#

Bcuz m>n

pale kestrel
#

but u need to check if there are more

#

or no more

opaque inlet
#

No more

#

I don’t think there is

#

Wait

#

5! * 3! = 6!

#

Wait

pale kestrel
#

that is a solution

#

ah actually i think u missed something both times

#

for 24 and 720

opaque inlet
#

What I miss?

pale kestrel
#

0!

opaque inlet
#

OH

#

6! * 0! = 6!

#

m = 6 and n=1, m=5 and n= 3, m=6 and n=0

pale kestrel
#

yah so 3 solutions

#

just double check there arent more

opaque inlet
#

I double checked

#

There shouldn’t be more

pale kestrel
#

🙂

opaque inlet
#

There’s more solutions?

#

How?

pale kestrel
#

there arent

opaque inlet
#

How’d u do it?

#

Oh ok

pale kestrel
#

in the positive integers at least

opaque inlet
#

Nah we’re only working with positives here

#

No negatives

pale kestrel
#

yh ik

#

hh

opaque inlet
pale kestrel
#

lol i gotta go off

opaque inlet
#

Can we do question 6e?

#

Pls one more

opaque inlet
pale kestrel
#

glue them together

#

2 ways to glue them

#

anyways, see ya

alpine sable
#

@opaque inlet I can help

#

If u need help still

opaque inlet
alpine sable
#

Sure which one

opaque inlet
#

6e.

alpine sable
#

What u need to do is to treat the three people aka the two parents and youngest child as one entity

#

And permute it with the rest

#

And then permute the people in the entity

opaque inlet
#

(P,C,P),C,C,C

#

Is that what u mean?

alpine sable
#

There is initially 4! Ways to permute the entity along with the 3 remaining kids

#

And then 2! Ways to permute the parents within the entity

#

So answer is 2! x 4!

opaque inlet
#

Ahhh

#

I get it now

#

Can we do the whole of question 7.

alpine sable
#

Sure lemme see

#

Hmm this is a good one

#

U need to treat the 5 digits as separate empty spots

#

U can permute the first digit in 9 ways , ( not 10 because 0 will make it a 4 digit number)

#

Then 9 ways for second digit

#

And 8 for middle

opaque inlet
#

Ahhh ok

alpine sable
#

The last two digits will be fixed as the number is palindromic

#

So 9 x 9 x 8 x 1 x 1

opaque inlet
#

Wait so

opaque inlet
#

That makes sense

#

What about 7b?

alpine sable
#

Same

#

9 x 9 x 8 x 1 x 1 x 1

opaque inlet
#

Hm

alpine sable
#

Since the 3rd and 4th digit are same

opaque inlet
#

345543

#

How will a six digit palindromic number look like

#

Can u show an example?

alpine sable
#

128821

opaque inlet
#

Ok I get that