#help-0
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Closed by @remote heron
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huh what?
its not special
if n = 0, x can be anything?
2/5 ^ 0 = 1
x can be anything non-zero
eh
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hello
Closed by @austere star
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Hello, how do you find this root from the equation without quadratic formula, just roots extractions
there is 4 roots it seems, i found the other both
but i don't get how i can find this one
wil ltry
well it become very odd, there is no way to solve it other way without quadratic equation or else ?
for the first root i did 4th roots on both side to remove the power of 4 and get sqrt(8) on right
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Π(a+n-t) from t=1 to b+1
Calculate what this expression gives yourself
@narrow pawn Has your question been resolved?
not exactly
it would be $\prod_{t=1}^{b-1}(a+n-t)$
quantum
That's what I said
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I need to find the determinant of this matrix
the answer I got is -57
but the key says -41
@alpine sable Has your question been resolved?
<@&286206848099549185>
My calculator says minus 11
Do it again
Its basic four operator question
Actually instead of doing it again, show me what you multiplied and summed
Maybe your process is wrong idk
We'll see
@alpine sable
3 x |-5 2 3 1| -1 |8 2 -4 1| -2 |8 -5 -4 3|
I don't use that method personally
There is an easier one
Logic is the same but visually it's better
yea ik that method, it's very hard for me
Seriously? I thought people use it more
yea more ppl do use it, but personally I find the pattern stuff to be kinda hard to remember
But anyways, your process is correct
I think you probably made calculation mistake
It happens to everyone
I'm so stuck on where my calculation mistake is
It's not important
The point is knowing what to do
You are wasting time looking for a simple mistake
Don't you agree?
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can someone please explain this
@rich basin Has your question been resolved?
<@&286206848099549185>
this is for (ii)
@rich basin Has your question been resolved?
@rich basin Has your question been resolved?
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what exactly is giving you trouble here
don't do people's work for them
...
if you want to
thank you here
he's already seen it
i couldn't figure out the transposing stuff
from lhs to rhs
ohh yes
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what is 0÷0
undefined
oh wait I figured it out imagine that you have zero cookies and you have zero friends to give them to see it doesn’t make sense and you have no cookies and no friends
thanks siri
That's a siri answer
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hi
can anyone help me with the derivative of ln[In(x)]
what have you tried?
are those u and v?
its hard to tell them apart
hold on
Your v is too differentiable if you know what I mean thats why it looks like a u
hello guys i need a help with me homework
yes?
@atomic lodge Has your question been resolved?
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Hello, why is it that the area under the curve equals the integral of the function?
The integral of a function is pretty much defined as the area under it. What is it that you think an integral is?
the inverse function of the derivative?
I understand that it is defined as the area under it
but I want to know why that is the case
I think your question was why is the inverse of the derivative the integral
yes
I can send you a very good link for that...may I?
yes please do
oh... good thing sloct corrected that. I guess i was completely misunderstanding what you were asking..
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the length of the green line = 9.7sin14 = 2.34
@buoyant kayak
bottom angle of triangle = asin(2.34/8.1) = 16.8
so therefor we know the angle z2 makes with the x-axis = 180 - (180 - 14 - 16.8) = 30.84
then the real part of z2 is 8.1cos(30.84) and the Imaginary part is -8.1sin(30.84)
so why is this wrong
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Is this correct? or does tan theta < 0 make it false?
it seems correct
how is tanΘ < 0?
isn't tan theta= 4/3 which is greater than 0?
you did not take into account the sign info given to you by the problem
"isn't tan(θ) = 4/3 which is greater than 0? ...wait that means i fucked up didn't i"
notation is a little all over the place too
cos(theta) should be **-**3/5.
precisely because tan(theta) is known to be negative and sin(theta) positive
oh because sin is positive and tan is negative, cos must be negative
coz the equation will be quadratic
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you know the generalised binomial expansion for (1+x)^n is valid for |x| < 1 right?
yh i know it is
but am unsure like why
i know it is simply because it says that it is in my datasheet
so if you have a sequence of numbers and sum them, sometimes you get a convergent sum and sometimes u have a divergent sum
convergent means its finite divergent means its infinite
yh
if you have |x| >= 1, then if you look at your formula
for expanding the binomials
the terms don't eventually "get small", so it's impossible for it to be convergent
as in they don't tend to zero
You would need to do some wider reading into convergence of series
just some intuition
yeh im not being formal
like if u see the terms for |x|<1, you can see the factorial terms tend to approximately 1 eventually
so if you look at the series sum its less than a geometric sum
oh yh of course i understand that
which we know converges
we know a geometric series converges if and only if the common ratio r < 1
and this formula looks sort of like that when you get to the big numbers
ah alright, thanks
but yeah if u want rigour u need to learn a lot more stuff
u need an actual textbook with all the definitions and build everything up from first principles
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I can't seperate the concept of vector spaces and a euclidian vector space 4 some reason, i keep trying to think of any vectors (take functions) as points in a R^3 space.. i think it has to do with the coordinates a euclidian vector space has
i guess in a way my question is, what are coordinates in terms of the vector space definition of euclidian space and do coordinates have any meaning for non euclidian vector spaces like the space with polynomials of any degree
coordinates have meaning when you construct a basis
once you have a basis, you can write a vector in your space as a linear combination of your basis vectors
and the coefficients in said linear combination will be the coordinates of your vector in that basis
How do you get a basis in R^2 (for example) without first having a coordinate system
I guess it has to do with what i define to be my vectors in my vectorspace/set but i cant seem to put it in words
(1,0) and (0,1)
these form a basis
they are vectors in R^2 by the definition thereof
but (1,0) and (0,1) have no meaning without a coordinate system right?
unless i just see real vectors as a list of numbers and think of euclidian space as a way of representing them
i think thats my issue, i try thinking of vector spaces spacially, in my head vector spaces are R^n but the axis are changed to their respective basis
they do
R^2 is by definition the set of ordered pairs of real numbers
(1,0) and (0,1) are just as valid pairs of real numbers as (420,69) or (pi,e) or (32.34526435645, -0.4948485)
Oohhh okey okey
so does the latter part of this still hold up?
If R^n is defined that way, is the euclidian space of R^n just a way of visualizing it?
And can i visualise all vector spaces like that if i think of the axis as their basis (for example 3x3 matrices-space) with x-axis =
\begin{pmatrix}
1&0&0\
0&0&0\
0&0&0\
\end{pmatrix}
نعمان
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no wait
the axis should be coefficients and the unit is just 1 basis matrix (3x3-space)
i think you might be overthinking it
hey
Or i just suck at explaining what i mean lol
anyone that can help me?
@crisp summit check out #❓how-to-get-help
@crisp summit please move to an available channel to receive help.
uh okay tho, but what if its urgent
go get your own channel
it's going to take less time than you're spending here arguing and trying to intrude on another conbo
convo*
what do you mean?
read #❓how-to-get-help
but anyway, is what i'm saying a correct way of thinking?
the way it's worded is very wonky
If this is how R^n is defined, does that mean that the coordinate system (up to dimension n) is just a way of visualising R^n? If not are they both equivalent definitions of R^n?
well
i suppose in some sense you could say that
but im apprehensive about going full "yes this is exactly how that works"
alright
Well if i assume it to be a way of visualising R^n
Could that visualisation, using axis/coordinates defined by the basis vectors, be applied to any vector space?
For example, in the 3x3-matrix vector space. The basis vectors are
For x:
\begin{pmatrix}
1&0&0\
0&0&0\
0&0&0\
\end{pmatrix}
For y:
\begin{pmatrix}
0&0&0\
0&1&0\
0&0&0\
\end{pmatrix}
and for z:
\begin{pmatrix}
0&0&0\
0&0&0\
0&0&1\
\end{pmatrix}
نعمان
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reaction for more information.
(You may edit your message to recompile.)
no
or for the space of polynomials up to (inclusive) degree 2, the basis vectors would be "1" "x" and "x^2"
the space of 3x3 matrices has dimension 9, not 3.
you're trying to pass something off as a basis that isn't
the matrix $\bmqty{0&0&0\1&0&0\0&0&0}$ isn't a linear combination of the three matrices you presented
Ann
Oh
I guess the basis' are matrices with a 1 in one place and zero's in all the others
no such thing as "the" basis
every real vector space has infinitely many possible bases
is there something special about this basis?
it's convenient to express matrices in terms of
are there any criteria about which basis to use for a vector space?
no
hmm
alright
Thanks for the help! in a way i kindof understand my original question better now haha
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I got 16 lies on the last question. I don't know how they got 10 or 20?
3(12)=2(1.2)^x
this is my equation
Result:
15.853154222255
that... yeah, that sounds like 16
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I need to find an equation of the plane passing through the given point and parallel to the indicated plane. (6,5,-2), x + y - z + 1 = 0. I'm not getting the right answer. I tried using the the equation of a plane by getting the normal vector to be (1, 1, -1) from the plane. What am I doing wrong here?
what equation did you get
$x+y-z=-12$
satoshi
so $x+y-z=13$
satoshi
$(x-6)+(y-5)-(z-2)=-1$
satoshi
thats not the way
how would I go about it then?
You have the answer already from what Ann said
but if u want to use vec equation of plane
its r.(1,1,-1) = D
where D is to be determined
D is 13?
yeah, thanks I have one more question
Find an equation of the plane through the given point and witht he specified normal vector. (1,2,3), n = 15i + 9j - 12k. Here I get $15x+9y-12z=-3$, but thats wrong
satoshi
its probably because you used the same wrong method?
use what i just said
I just plugged in the numbers in the equation of a plane
what is the plane equation
satoshi
I used it for a similar problem, and I got the right answer
according to my book the answer is 5x+3y-4z+1=0
well you can quickly check
5+6-12+1 = 0...
but that normal vector is completely wrong
its not 1 2 3
oh wait yeah
sorry
its (15, 9, -12)
(1,2,3) is the point
but I will still not get the right answer
wait im confused lol let me see
no your answer is correct
you just didnt factor out 3?
divide thru by 3
my bad, misread
i think your method is fine, but maybe you flipped the signs wrong
i havent seen this way before
back to the 1st one
$15(x-1)+9(y-2)-12(z-3)$
satoshi
$15x-15+9y-18-12z+36$, right?
satoshi
idk i havent seen this method before, like i said
the one I use is to use vector form
the book wants me to use that method
I havent seen that form. How does that one work?
you know dot product?
yes
r is the variable vector
call it (x y z)
and you end up with the same plane equation
so in this case (1,2,3)?
yes
r . n = r_0 . n
You can also write it like this
if you have the normal vector n and a specific r_0 you know is on the plane
whats the method called?
vector equation of plane
If you rearrange the math
you will end up with the aame formula you use
but i find think this is easier to remember
ive only seen people use the equation of a plane
the intuition of this form comes from r . n = 0 means r and n are perpendicular
then the right side D, translates the plane
alright, cool
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What do points on a plane in R^3 have in common? I know it's a very simple question but my brain is overworked rn and i cant wrap my mind around it.
I know something has to be held constant but idk what? (i think this because in the cases of xy/yz/zx -planes one of the three coordinate values is held at a constant 0)
ngl theres a lot you can say
you can describe the plane by saying all the points satisfy an equation
well
i guess there's a value of a,b,c,d so that ax+by+cz+d=0 (literally the equation of a plane)
oh yeah lol, i forgot about that equation.
So all the points on a plane have a,b,c and d in common, right?
yep!
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hi, i was doing some simulations for a three sided dice. Assuming i found a dice which has 1/3 probability of landing on each of it sides and i do a 1000 throws. We know that it is almost impossible that all the three sides(up, down, edge) come up 333, 333, 334 times(not particularly in this order). My question is what range of values can i accept so that i can assume that the dice i created is almost completly fair. example say i get 310 ups, 340 downs and 350 edges, can i say that this dice is fair?
basically i dont know a lot of stats so i had to ask here
sorry if i phrased this badly
- how can you make a 3 sided die? a cylinder?
- no, there's no telling if the dice is fair for certain. there's always a probability that a fair dice comes up with your result. you might want to look into p-values in statistics though.
if you want a physical design just do a cube with two sides labeled with each number
- basically a cylinder but thats not relevant atm
- ik we cant tell for certain but is it like possible to somehow use some stats or smthing to get a range allowing a little error
oh no thats done
yeah, you can certainly do that.
Hypothesis test gives me ptsd
uhhh i have no idea what this is but i guess ill give it a look
'impossible' is a strong term
it is possible, but just very unlikely
in the end, what range if values is kindof up to you
in stats you choose your confidence interval
but you choose it first, then run your experiment
ok so umm a lil context here. this is basically for a physics competition. so i thought that maybe we have to find the range through some mathematical means but if i understand correctly u mean that i can just say that if the results are all in the range 310-340 the dice can be deemed fair(kinda)
the range means the number of times each of the three sides pops up after a total of 1000 throws*
kindof, and you should justify your choice of confidence interval before doing the experiment
you need to work out the probability of this happening 310-340
if you choose that
and how do we do that?
find the distribution
i dont know stats that's why i asked here 😥
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Do you have graph paper?
Graph it
Yes I do
Obviously
I just got done with my break and I forgot how to find slope
Slope is the coefficient of x
Equation of line is y = mx + c, m is the slope and c is the y intercept
how did you do 15 without knowing how to find slope though?
15 isn’t circled
Lol
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It's possible to integrate a matrix?
I have an formula that gives to me an integrate but the integrator will be a matrix.
I think by convention, thats what you do (I'm not 100% sure)
I think you're supposed to integrate component wise (not sure either lol)
Check out this link: https://math.stackexchange.com/questions/450560/integrating-a-matrix/450565
Don't think any other interpretation makes sense
I can show more details of the problem if you want
Sure, one second
I have this sequence where f(x)=x'
and this EDO problem
I already find the solution which is x(t)=acos(t)+bsin(t); y(t)=x'
now I must to show that the sequence converges to the solution.
But i dont know how i can evaluate this sh*t
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<@&286206848099549185>
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@weak snow Has your question been resolved?
hi
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Is this correct?
Did it just ask to set up the sum and integral?
Yes
I mean it looks right to me
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You already did part i.
yeah U x V
ii
@timid jewel Has your question been resolved?
without reading the material
you're not gonna be able to do it
these questions are getting deeper and deeper into the subject
better to read the material or watch videos to understand
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help
what have u tried
i want to do the think where it goes, what 2 numbers multiply to get -4 but also add/subtract to get 11 and i dont think thats possible
and i dont know another way
You're ignoring the 3, which changes how you'd think about the problem
well actually let's write out (3x .........)(x ........) for now
ya most likely
yep
yeah foil
i dun call it foil but ik ppl do
i call it foil
ok
@vivid charm lol sorry im stuck
i remember today learning about how i need to split the 11x
but i dont remember how to do ot
it
why split 11?
u shud be splitting 4
how would u split 4
applying the ac method
i.e. consider a pair of numbers that multiply to ac = 3 * -4 = -12
and sum to b = 11
use that to determine how to split the 11x and continue with factorisation by grouping
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side note is dat baki in ur pfp
so the largest positive integer m for which 2^m is a divisor of 9!
yes
baki is epic
not cap
so isn't this saying (2^m)/9! where m is a integer and where that number is a integer
i cannot read nvm
.close
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How do I do this question
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is the correct answer none of the above? i got x = 848.5 and y = 1697
You might have 2y = 1697
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how i do this
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anyone can solve 2b)?
@tranquil kestrel Has your question been resolved?
have you done 2A?
if so, can i see what you put
i may be able to help
A->W>or equal to 20
where w is the amount william drinks
B->W<20
C->W>or equal to 5
W<20 is logically equavelant to ~(W>or equal to 20)
therefore A and B are contradictories
If C is true, then either A or B is true
C-> A V B
C-> ~(A & B)
ok im not gonna use w
A -> ~B
B -> ~A
therefore ~B -> A
therefore A iff ~B
and B iff ~A
A -> C
sure let me show you mine 2A
My 2a) is Just the lines as given. A= He drinks at least 20 cups a day, B=, William drinks less than 20 cups a day and C= at least 5 cups a day. Basically wrote these.
so my working is wrong right?
i see
A -> ~B & C
B -> ~A
C -> A V B
If A is true, then ~B & C
the question wants to find who specifically (as in one person?) is right
therefore A cannot be true, for it implies that C is true and therefore two propositions are true
C implies that either A or B is true, which also implies that at least 2 propositions are true
therefore C cannot be true
thus, it is only possible for B to be true?
idk
If B is true, then we know that A is false
but C may be either true or false
B is necessarily true only if ~A & ~C
~C-> ~(A VB)
if B is necessarily true then B -> ~(A V B)
I think the answer is B
im thinking too mich
Just take it like so:
A -> ~B & C
B -> ~A
C -> A V B
If A is true, then ~B & C
the question wants to find who specifically (as in one person?) is right
therefore A cannot be true, for it implies that C is true and therefore two propositions are true
C implies that either A or B is true, which also implies that at least 2 propositions are true
therefore C cannot be true
thus, it is only possible for B to be true?
lmk if u still want help
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Hi
I’ve got a series of questions related to combinations and permutations
We’ll start off with question 12.
Can anyone help me on this pls
The first roll?
yes
6 outcomes
ok in 2nd?
6 outcomes? I think?
I meant 36 outcomes
yes
Thats not the answer btw.
It would be easiest to just count them out tbh
And if you roll 0 either time it will be 0
more
Are you sure you’re in the right class?
and then you have to subtract 4 more as
Who? Me?
Oh ok
imo a better way to count this is to notice you have 5 primes
and 0
a slow but sure way is to draw a 6x6 table
and write down all the possibilities
and count the different ones by putting them in order
half of the results will be when the digits will be reversed. and you will get 0 five time so u have to subtract 4 also
so the answer imo will be 14
Ok
hm
Is there a quicker method than doing the table method you suggested?
I get 16 🤔
I got 16 too
I just did table took like 1 min
Damn
so the 'quick' method
Let me check my textbook
you have 5 primes
You can choose 2 different ones to make a product
thats 5 choose 2 = 10
you can choose the same one (squares)
thats 5
then theres also 0
so a total of 10+5+1 = 16
if u choose 5 and 5 then wont the product be 25
.
oh
is there any answer key?
Yes
Nah it has to be 16 unless they didn’t count 0
Just 15
How
then how do u know?
It doesn’t say ‘how’
??
The answer is in the textbook
It doesn’t provide a working out nor explanation tho
lol
That’s an answer key
yea
why dont we list all 16 😢
yes
meh this is IB textbook
there are typos everywhere in those
especially in the answers
What’s a IB textbook
is this not IB textbook
0,4,6,10,14,22,9,15,21,33,25,35,55,49,77,121
What is that
This is an australian textbook
oi oi oi
Math works differently there
No it doesn’t lol
Are u Australian?
ye
Are you caught up donta
No
Wya
What does that mean?
Where are you at
I don’t understand the question?
WHERE ARE YOU AT IN ONE PIECE
yeah im caught up to the manga, but not the anime.
Oh. You have to tell me that you’re a one piece fan
I’m an anime only
i wonder how you figured i was a op fan
Zoro dies
Doesn’t really make sense to me what do they mean by rotated
Like the squares or
Or is it just factorial
means you have 3 types of floor tiles
that are 2x2
and find how many floor patterns you have that are 2x6
first find out how many ways you can rotate those in one order and multiply that by the total number of ways you could arrange the tiles
hmm.
Damn
each of the tiles, how many ways to rotate
no
take the 1st tile
how many possibilities
4 possibilities?
4
Yes
Yes
so you multiply the possibilities
64?
6 ways
Calculate the other tiles?
no..
there are 2 things that are important here
how the tiles are oriented
and how they are ordered
do these 2 things affect each other?
Of course not
so you multiply again
the key is, you have no repeats in counting like this
since the tiles all look different
So 216
Oh
i said 3! above, not 3
Yes sorry for the mistake
So 384 is how many ways it can be done
,w 6*64
ok

think u got it
any ideas
hint: try it for 24, first
Wdym 24
I was thinking about making n! = n(n-1) * (n-2)!
The same thing applies for m
But I can’t do anything with it
I don’t think
But why 24?
Ok god
Lol
m! * n! = 24
Now trial and error?
m = 4 and n = 1
m = 1 and n = 4
I don’t get it
24 = 4!
the person who wrote the question
didnt randomly choose 720
i also didnt randomly choose 24
720=6!
yh
Oh ok
also be careful
it says in q
m > n
anyways, so you have 1 easy solution for starters
ok
Bcuz m>n
that is a solution
ah actually i think u missed something both times
for 24 and 720
What I miss?
0!
🙂
there arent
in the positive integers at least

Nah we’re only working with positives here
No negatives
lol i gotta go off
Bye
Yes pls
Sure which one
6e.
What u need to do is to treat the three people aka the two parents and youngest child as one entity
And permute it with the rest
And then permute the people in the entity
There is initially 4! Ways to permute the entity along with the 3 remaining kids
And then 2! Ways to permute the parents within the entity
So answer is 2! x 4!
Sure lemme see
Hmm this is a good one
U need to treat the 5 digits as separate empty spots
U can permute the first digit in 9 ways , ( not 10 because 0 will make it a 4 digit number)
Then 9 ways for second digit
And 8 for middle
Ahhh ok
The last two digits will be fixed as the number is palindromic
So 9 x 9 x 8 x 1 x 1
Wait so
Hm
Since the 3rd and 4th digit are same
128821
Ok I get that
thanks!