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alpine sable
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sheaf, prismatic, single intersection, 2 parallel and 1 cutting, none of them touching each other.

knotty sleet
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Because the two lines are each only the intersections of two of the three planes

alpine sable
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oh yes thats right

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whoops

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so 3 different ways for a solution

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2 other ways they can be

alpine sable
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thanks :))

knotty sleet
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Only sheaf and single intersection for solutions

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If 2 parallel or 3 parallel or prism then no solutions

alpine sable
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oh whooops yep i did it again

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prismatic dont count as solution yh

knotty sleet
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You can maybe draw a few diagrams on a page and keep it with your notes

alpine sable
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yea im gonna do that now, thank you :)) happy new year.

knotty sleet
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No worries, happy new year to you too 👍 😄

alpine sable
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lone heartBOT
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lavish monolith
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why dim of subspace W = {(x,y): x + y = 0; of R^2 isn't 2 ?

lavish monolith
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since it's R^2 shouldn't be 2 as dimension

robust geode
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Not really

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The concept of dimension is mostly about the indépendance of the variables

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(each ones representing values on different axis)

lavish monolith
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but we don't have matrix here how can I determine the dim

robust geode
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Because R² is a matrix? 🤔

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Since in this set W, x and y are linked together by the equation x+y=0, then if you have x, you have y (and it would be the same if you set a value for y first, too)

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You can also see that x+y=0 is exactly the same as y=-x

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Which is... A line in R²

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And a line is of dimension what?

lavish monolith
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oh thank you

lavish monolith
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thank you have a good day

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robust geode
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Please don't ignore what I said above @lavish monolith

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The independance of x, y, z,... Is the core of the concept of dimensions

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The fact that a line is of dimension 1 in R^n (n>=1) comes from that

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indigo tapir
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can i get help here

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indigo tapir
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i need to find out how to do a question

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do i subtract x^3 by x^-3?

lavish monolith
robust geode
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I just wanted to emphasize since it is the most important thing to understand in order for dimensions to make sense

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So not only graphically, but mostly algebraically

robust geode
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The difficulty I would say is to figure out the order

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Are you beginning to be used at using fractions?

indigo tapir
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well no

robust geode
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Have you seen them?

indigo tapir
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i have seen fraction before

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well i think which answer it is

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indigo tapir
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so how do i do this?

lone heartBOT
indigo tapir
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since all of the angle add up to 180

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should it be 180-3x

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wait it should be 2x

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bruh im confused

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because it should be either 2 or 4

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heck it could be 3

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i think to find it

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you have to do 180 minus the other 2 angles

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but then why is the other y+2x

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nvm ill figure it out

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shadow wadi
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hi, can someone explain this to me?

lone heartBOT
elfin snow
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it's just factored

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you can use the quadratic formula to arrive there

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undone agate
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undone agate
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I understand that im using FTOC, but why is the answer negative? If we graph out the function

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The function is always above the xaxis

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So the integral would measure the area between the xaxis and f(x) so why isnt the answer positive?

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It's negative according to FTOC but graphically i dont understand how it is negative

boreal drum
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You're integrating f(x) not F(x)

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And f(x) is the derivative of F(X) which will be negative for x less than 5

lone heartBOT
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@undone agate Has your question been resolved?

undone agate
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Thanks

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sturdy fog
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can someone tell me how i can find the radius of the smaller cone

severe sluice
sturdy fog
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im still confused could you please show it step by step?

glass lichen
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That's an obvious place to start.

sturdy fog
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v= 1/3Ah

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1/3pir^2h

glass lichen
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sure... more usefully is $V=\frac{\pi}{3}r^2h$

ocean sealBOT
glass lichen
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Find the volume of the cone, find the volume of the ice cream, then set up the appropriate eqn

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noting as bob pointed out, radius and height (for the ice cream specifically) are related through similar triangles

sturdy fog
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sorry im still really confused could you walk it thru w me

glass lichen
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No, about to log off.

sturdy fog
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ah okay

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thanks

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elder quartz
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My son wants to know what other maths you need to know for trigonometry and I have forgot. Can someone help

gray isle
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basic geometry and algebra

lone heartBOT
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@elder quartz Has your question been resolved?

elder quartz
#

Yes

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tawny fable
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Heyo

lone heartBOT
tawny fable
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I am back with the same question as before

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4.(c) if f is diff Df(x_0) = Df(x_0)

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I managed to prove that M(delta) = m(delta) for a specific delta, but I can't seem to prove that the limits are equal since we talk about a range of deltas as delta --> 0+

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<@&286206848099549185>

lone heartBOT
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@tawny fable Has your question been resolved?

tawny fable
#

<@&286206848099549185>

lone heartBOT
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@tawny fable Has your question been resolved?

tawny fable
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<@&286206848099549185>

tawny fable
#

anyone?

knotty sleet
tawny fable
#

I am sorry. I might have missed what you said.

knotty sleet
knotty sleet
tawny fable
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So thats using the squeeze rule isnt it?

knotty sleet
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Not really

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It's the same idea

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But not using the theorem per se

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It's really just definition of limits and manipulating inequalities

tawny fable
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but eventually as I undestand it

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you proved it for a specific delta

knotty sleet
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How do you mean?

tawny fable
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I mean

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As I understand it

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Df(x_0)

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means lim delta -- > 0+ of M(delta)

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thus it has to work for all deltas

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in the range of 0<delta<something

knotty sleet
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Yeah

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I've shown it works for 0<delta<delta'

tawny fable
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Could you look at the inequality m >= D - epsilon

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and change sides

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and then add the 2 inequalities?

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M(delta) + (-m(delta)) <= 2epsilon ?

knotty sleet
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Sure that's fine

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I don't see your point tho

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Oh

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If it's easier to understand that way then yh write it like that

tawny fable
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I think I need to write it down to understand it more clearly

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If you would work with the defenition of x - x_0

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without h = x - x_0

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would it be the same?

knotty sleet
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Yeah

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More or less

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Change up a few bits of notation but the idea won't be affected

lone heartBOT
#

@tawny fable Has your question been resolved?

orchid bane
#

can anyone solve my physics query

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if yes then ping me please

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rain canyon
#

Let xyz = 1
Calculate
X/xy+x+1 +y/yz+z+1 + z/xz+z+1

rain canyon
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I Will use xy = 1/z?

tawdry saffron
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$\frac{x}{xy}+x+1 + \frac{y}{yz}+z+1 + \frac{z}{xz}+z+1$

rain canyon
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Nah

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Not that

rocky atlas
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$\frac{x}{xy}+x+1 + \frac{y}{yz}+y+1 + \frac{z}{xz}+z+1$

ocean sealBOT
#

Ruffy🎄

rain canyon
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Like that

tawdry saffron
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oh

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parentheses exist

rain canyon
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No

rocky atlas
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Try substitutions with xy=1/z, yz=1/x and zx=1/y

vale wigeon
#

so you explicitly refuse to write $\frac{x}{xy+x+1}$ as \texttt{x/(xy+x+1)} in plaintext? is that what you're saying? @rain canyon

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tawdry saffron
lone heartBOT
tawdry saffron
#

Can someone help me

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Simplify this

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And need a 1/k^2 in front

lone heartBOT
#

@tawdry saffron Has your question been resolved?

lone heartBOT
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@tawdry saffron Has your question been resolved?

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@tawdry saffron Has your question been resolved?

harsh swallow
#

does that say $e^{-i k \pi}$?

ocean sealBOT
#

Katharine

tawdry saffron
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Yep

harsh swallow
#

is k an integer?

elfin snow
#

yes

tawdry saffron
lone heartBOT
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@tawdry saffron Has your question been resolved?

tawdry saffron
#

eh well

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.close I guess

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bleak hearth
#

can someone help me with 8b pls

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ancient saddle
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vocal slate
#

How do I prove/disprove $\lim _{x\to \infty }\left(\frac{\frac{2^x}{:x}}{\left(1.99\right)^x:}\right) = 0$

vocal slate
#

Plugging in values it seems to get closer and closer to 0, but wolfram alpha says it converges to infinity

ocean sealBOT
vocal slate
#

I have gotten to here:
$\lim_{x\to \infty} \left( \frac{\frac{2^x}{x}}{\frac{199^x}{100^x}} \right)$ so
$\lim_{x\to \infty} \left( \frac{2^x}{x} \times \frac{100^x}{199^x} \right)$

surreal meadow
#

i think ratio test should work

ocean sealBOT
vocal slate
# ocean seal **miku**

with this, the problem I have is the 2^x/x tends towards infinity but the 100^x/199^x tends to 0

surreal meadow
#

have you tried a ratio test?

vocal slate
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i will try it, thanks

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ill look up what it is

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i am bit confused, searching online is only coming up with stuff to do with series

copper stone
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its weird wolfram says infinity

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the graph looks like this

vocal slate
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the graph looks like it tends towards 0 too yeah

surreal meadow
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oh sorry, this is for a sequence

vocal slate
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,w lim x->infinity ((2^x/x)/((1.99)^x))

surreal meadow
#

this definitely diverges though

surreal meadow
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2^x will grow much more rapidly than 1.99^x * x at large numbers

vocal slate
#

this is quite confusing

copper stone
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but x grows much more rapidly than (2/1.99)^x

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as 2/1.99 is very close to 1

surreal meadow
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a^x / x diverges for a > 1

copper stone
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the graph is confusing

surreal meadow
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kind of, it’s just too small a scale to see the behavior at infinity

vocal slate
vocal slate
surreal meadow
#

you can use lhopital if you’ve heard of it

copper stone
#

as 2/1.99 > 1

vocal slate
vocal slate
#

it isn't a very nice one for this

copper stone
#

(2/1.99)^x / x -> inf

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as 2/1.99 > 1

copper stone
vocal slate
#

Wait how do you go from $\frac{\frac{2^x}{x}}{1.99^x}$ to $\frac{\left(\frac{2}{1.99}\right)^x}{x}$

ocean sealBOT
copper stone
#

its the same

surreal meadow
#

keep change flip

copper stone
#

$\frac{\frac{2^x}{x}}{1.99^x} = \frac{2^x}{x1.99^x}$

ocean sealBOT
#

nisrine

vocal slate
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OH! Thank you ahahah sorry

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I think that answers my question

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thank you for your help @surreal meadow and @copper stone

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.close

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white sphinx
#

3 and 4 are confusing me. I believe they are the same concept. how do I find the rate of change from what is given?

surreal meadow
#

do you know what a derivative is?

white sphinx
#

Yes

surreal meadow
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that’s the instantaneous rate of change

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so f’(2) is the rate of change at x = 2

white sphinx
#

so do I just take the derivative and then plug in?

surreal meadow
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yes

white sphinx
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I thought so but I was going through the beginning of my textbook bc my prof skipped over it and this part was supposed to be only abt limits so I didn’t know how to find w/o just taking the derivative

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thank you

surreal meadow
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the definition of a derivative is a limit

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so it kind of is about limits, especially if you find the derivative through first principles instead of the power rule

white sphinx
#

that’s what I did

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I still don’t rly know how to take a derivative

surreal meadow
#

derivative of x^2 is 2x

white sphinx
#

but I know I did it wrong be the answer is different in the book

surreal meadow
#

so instead of .04(8-x) it should be .04(8-2x)

white sphinx
alpine sable
#

Product rule looks incorrectly used and note that product rule is superfluous here

white sphinx
#

I’m not sure how to solve to get the derivative then

glass lichen
#

$f'(x)=0.04\dv{x}(8x-x^2)$

ocean sealBOT
white sphinx
#

why don’t you take the derivative of the whole thing?

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cinder sundial
lone heartBOT
cinder sundial
#

the y-axis stands for people by cumulative frequency, x-axis is the grade.

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well, it ask for the median

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so we got (50th+51th)/2= median
and 50th and 51th falls in the area between grade 60 and grade 70

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so the interval is 10/25=0.4

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then i got the median= (64+64.4)/2=64.2

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Here’s the process tho

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somehow its wrong, the answer on the book said the median is just 64

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can someone check this out for me

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is there anything wrong in the process

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<@&286206848099549185>

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SOS

#

help me

wary stream
cinder sundial
cinder sundial
#

or i have misinterpreted the chart?

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@cinder sundial Has your question been resolved?

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cinder sundial
lone heartBOT
cinder sundial
#

Can someone check the value of sin 15 degree for me

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I’m not sure if it’s correct or not

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also i got lineAB=sqrt6+sqrt2

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<@&286206848099549185>

severe sluice
#

roketto's sheet is useful

cinder sundial
cinder sundial
severe sluice
#

wait a sec half-angle isn't in roketto's trig

ocean sealBOT
#

bob ✓

$\sin\left(\frac{x}{2}\right) = \pm\sqrt{\frac{1-\cos(x)}{2}$
```Compilation error:```! Missing } inserted.
<inserted text> 
                }
l.55 ...{2}\right) = \pm\sqrt{\frac{1-\cos(x)}{2}$
                                                  
I've inserted something that you may have forgotten.
(See the <inserted text> above.)
With luck, this will get me unwedged. But if you
really didn't forget anything, try typing `2' now; then
my insertion and my current dilemma will both disappear.```
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cinder sundial
lone heartBOT
cinder sundial
#

That blue underlined part seems wrong

#

it should be b*c right

vale wigeon
#

yes

cinder sundial
#

thank you

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vestal aspen
#

Conic sections problem

lone heartBOT
vestal aspen
#

Solution of this problem:

#

I didn't understood why option d is wrong? I mean why b=0 implies that x+3=0?

remote heron
#

you lose y, right?

#

so you just have points

#

it becomes a(x+3)^2=0

#

a parabola would be a(x+3)^2=y

vestal aspen
#

oh, yes, thanks

#

.close

lone heartBOT
#
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misty bobcat
lone heartBOT
misty bobcat
#

,rotate

#

Is my solution correct ?

ocean sealBOT
misty bobcat
#

im changing my answer its a tautology

lone heartBOT
#

@misty bobcat Has your question been resolved?

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@misty bobcat Has your question been resolved?

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worldly cove
#

Do i ask for help here?

lone heartBOT
raw shard
#

yes

worldly cove
#

Ok

#

Let me take a sc and show what i dont understand and what i think i did correct give 10min

#

The questions from hegarty mayhs

#

Maths*

void solar
#

Just post your question in any open help channel and it will be pinned by the bot

worldly cove
#

Is this not open

#

Sorry

worldly cove
void solar
#

no this is open

#

Go for it

worldly cove
#

Oh ok

void solar
#

Just trying to help clarify

worldly cove
#

Thanks

#

Sorry im taking long just logging in

#

Let me show you were i went wrong / didn't understand cause i attempted it before a similar question but i got mixed up

#

Im in year 9 btw

void solar
#

Awesome, if you could show what you did we can help alot more

worldly cove
#

Ok just looking through my notes to see if i can find it

#

Should take a closer photo then ill describe the thought process of what is going on and what i thought

void solar
#

Yeah describe the thought process

worldly cove
#

So on the left hand side underneath where it says the shape of end face it says different shapes triangle rectangle etc

#

And when i watched the video on how to disect this question it wrote the shape end face of the different shapes e.g triangle 3 rectangle 4 etc

pulsar aspen
#

It seems that you already got the idea. You just have to prove it with more rigor.

void solar
#

You understand that the question is asking for you to right a formula to link the number of edges with the total faces right

worldly cove
#

And where it said edeges it said we times by 3 so from 3( triangle)we times by 3 for the number of edges etc for each one as you can see thats the pattern as you times 3 from the shape end face to get the number of edges which is why at the bottom of the screen it says 3s

void solar
#

Ok so we always know theres two faces at both ends right

worldly cove
#

Yes

void solar
#

Then each side of the shape will make a rectangle right

worldly cove
#

Yes?

#

Oh ok yh

void solar
#

So to get the total number of faces

worldly cove
#

Yep

void solar
#

It would be the two end faces plus the number of faces in the middle

#

We can right it as
2 + x = y
x = number of sides of the base shape
y = total faces

worldly cove
#

Ok

void solar
#

Do you get how that equation works?

worldly cove
#

Im trying to understand it

void solar
#

maybe i read the question wrong

#

let me double check

#

Looks like i did read it wrong, my bad

worldly cove
#

It was asking for the formula that connects it thats how he got 3s cause you times by 3

worldly cove
void solar
#

If we take x as the number of sides

void solar
#

Then 2x will cover the edges for both ends

#

So all we need is the middle right

worldly cove
void solar
#

triangle prism

#

You ok using this shape to figure out the general formual

worldly cove
void solar
#

Since each edge makes a rectangle it means four edges. But it shares 2 edges with the base shape

#

It also shares an edge with adjacent faces

#

So really each rectangle only makes one new edge

worldly cove
#

Ok

#

Could you go a bit slower sorry

void solar
#

no thats fine

#

Im probably explaining this badly

worldly cove
#

I do understand a bit

void solar
#

Since we already counted the edges of the base shape

worldly cove
#

Yep

void solar
#

We dont want to recount it

worldly cove
#

Ok

void solar
#

so really the only edges we will count are these

worldly cove
#

Yep

void solar
#

Cand you see the pattern between the faces and edges?

#

3 faces

#

3 edges

worldly cove
#

Yes

#

Wait

void solar
#

Yes?

worldly cove
#

5 faces no?

void solar
#

Im only talking about the middle part

worldly cove
#

Or do we only count the faces of the edges

worldly cove
void solar
#

Not counting the base shapes (triangle faces)

worldly cove
#

Ok i see

void solar
#

Since each reactangle face is made by the edge of the triangle

worldly cove
#

Yep

void solar
#

number of triangle edges = number of rectangle faces
Number of rectangle faces = Number of new edges

worldly cove
#

Ok

void solar
#

So number of edges on the base shape = number of edges in the middle section

#

So for the total edges

worldly cove
#

Yep

void solar
#

x = number of sides of base shape
y= total edges
x + x = y

#

Or in words

#

Sides of the base shape + Edges in the middle part = Total edges

#

We can try it with a square prism if you want

void solar
worldly cove
#

Can i just clarify something

void solar
#

yeah go for it

tight locust
#

What's the confusion

worldly cove
worldly cove
#

Right

#

If the edges are represented as E

#

Or im being stupid

void solar
#

yep

#

No no your right

#

I forgot something in my equation

worldly cove
#

Oh ok

#

Give me a sec ill be back

void solar
#

Which is jsut 3x = y

#

What you were doing was right

#

and now that you have the formula, just apply it to the second half of the question

worldly cove
#

Ok thanks

#

Sorry i took long to reply

#

My mum made look fro the remote for the tv

worldly cove
# worldly cove

So in conclusion the E50 = 150 because they timesed the 50 sided polygon by 3 which was the pattern

#

Close

#

+close

void solar
#

.close

worldly cove
#

. Close

void solar
#

no space

worldly cove
#

.close

lone heartBOT
#
Channel closed

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worldly cove
void solar
#

Turns out you were right from the start

lone heartBOT
#
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alpine sable
#

f:[0,1]->R
f(x)= { x , if x is rational
x^2, if x is irrational }
is f integrable?

alpine sable
#

ping me pls

pulsar aspen
#

Does not look to be even continuous

#

@alpine sable

#

Let's find out lim f(x) as x getting close to c.

#

First, we consider squarefree rational sequence to x^2.

alpine sable
pulsar aspen
#

Yes. All integrable functions are continuous, but the reverse is not guaranteed.

alpine sable
#

Arkos isnt that the opposite

#

or im tripping

pulsar aspen
#

In mathematics, the Weierstrass function is an example of a real-valued function that is continuous everywhere but differentiable nowhere

alpine sable
#

but thats differentiability

vale wigeon
#

@pulsar aspen continuity is a sufficient but not necessary condition for integrability

pulsar aspen
#

Another quote:

If f is differentiable at a point x0, then f must also be continuous at x0

#

Oh. I misread the question, sorry.

#

Then, is this Riemann integrability or Lebesque integrability?

vale wigeon
#

riemann probably

alpine sable
#

riemann

pulsar aspen
#

If it's Riemann integrability, then showing that the function is not continuous anywhere is enough.

#

Whoops. Some grammatical mistakes.

#

It's Lebesgue-Vitali theorem

alpine sable
#

swagthink havent read that yet sry

#

we just read upper,lower integral, and that to be riemann integrable: L(f)=U(f)

pulsar aspen
#

Is this homework or just for fun?

#

If it's just for fun, I recommended reading that theorem.

alpine sable
#

homework

pulsar aspen
#

Oh, so you are not allowed to use that theorem then.

alpine sable
#

cant use it if sir didnt teach itMiiShrug

#

ASsadcat whys analysis so hard

echo socket
#

Cuz it's rigor at its purest

pulsar aspen
#

Well, I found it at last.

#

For any subrange of [0,1], you should find the sup{f(x)}, and inf{f(x)}.

#

Hint, (use the rational and irrational approximation of a real number)

#

||Note that for 0<=x<=1, x^2<=x, so for supremum, we can ignore the irrational number (we can replace it with the rational approximation to that irrational number), and for infinum, we can ignore the rational number.||

#

||Then, sup{f(x)| x element of subrange, x rational} is sup{x| x element of subrange, x rational}, or more simply the supremum of the subrange itself||

#

||You can also do the same to the infinum. getting the infinum of the subrange itself, but squared.||

alpine sable
#

dan why r u censoring it, i cant do anything by myself

pulsar aspen
#

You can then plug it in into the formula of the upper and the lower integral, and you are done.

pulsar aspen
alpine sable
pulsar aspen
#

But yeah, the easiest way to solve is by proving that the function is nowhere continuous, and then invokes Lebesque-Vitali theorem.

alpine sable
#

I'll read that then

pulsar aspen
#

I mean, a sequence converging to x. The former means that every element is rational, and the latter means that every element is irrational.

#

The easiest way to get irrational approximation is by getting a squarefree rational approximation to x^2

#

And then you take a square root on each element.

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

Arkos well i need some time before i could respond so do i keep this channel occupied?

pulsar aspen
#

Then react with X

lone heartBOT
#

@alpine sable Has your question been resolved?

#
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rocky atlas
lone heartBOT
rocky atlas
#

What the answer is A instead of D

#

8, 6 and 10 exists too

silver marsh
#

Yeah but it’s asking you to write “a” Pythagorean triplet with 8 as the smallest number

#

Not the smallest Pythagorean triplet with 8 as the smallest number

rocky atlas
#

oooh

severe sluice
silver marsh
#

Oh yeah that too

rocky atlas
#

Ok

severe sluice
#

oops

silver marsh
#

@.@

#

Lol

rocky atlas
#

If there was no option given how would you find the answer?

silver marsh
#

Do you have questions like that?

rocky atlas
#

No but to make sure if there is a method other than making sure of the options

silver marsh
#

There’s an algorithm to generate Pythagorean triples, but I’m not sure if it does what you want (generates one with an input smallest number)

rocky atlas
#

is it something like m+n or m-n

silver marsh
#

3b1b has a video on it

rocky atlas
#

Oh

silver marsh
#

Idk I forgot

rocky atlas
#

Ok I'll check on youtube then

#

Thx

#

.close

lone heartBOT
#
Channel closed

Closed by @rocky atlas

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rocky atlas
#

.reopen

lone heartBOT
#

rocky atlas
#

If you got anything to add, if not I'll close

silver marsh
#

O no, you’re good

#

Gl!

rocky atlas
#

ok

#

Ty!

#

. close

#

.close

lone heartBOT
#
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#
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final summit
#

99% sure I'm right but you can't simplify ln(x)/ln(y) by just crossing out the ln, right? Since it's not a multiplication. Like you can't rewrite ln(x)/ln(y) as x/y.

final summit
#

Friend asked and I don't remember much about logs

#

I know the quotient rule but I haven't seen anything about this.

silver marsh
#

Yeah… you’re right

#

But you can simplify it

#

$\dfrac{\log_c(a)}{\log_c(b)} = \log_b(a)$

ocean sealBOT
final summit
#

Thanks

silver marsh
#

Np

final summit
#

.close

lone heartBOT
#
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lone heartBOT
#
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eternal fox
#

I am trying to (create?) a function that is basically a logit; but "wider"

eternal fox
#

something like this. f(0) = +inf; f(10^7) = 0. and a sigmoid like pattern between the two

#

f[n] == -20000000 Log[x/(1 - x)]

seems kinda on the right path; but it goes to negative infinity instead of zero

#

,close

#

, close

#

.close

lone heartBOT
#
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hasty grail
#

Does someone know how to solve this?

lone heartBOT
gray isle
#

you could try doing some factotisation

hasty grail
#

The thing is, you can factorise but some factorisations return you a false value

gray isle
#

wdym by return a false value

hasty grail
#

nvm I got it

#

Thx

lone heartBOT
#

@hasty grail Has your question been resolved?

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alpine sable
#

I really need help please 😢

#

Ask me If u don’t understand smth, i translated from French

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

I have to represent this function (f(x)) on [-4;4[

#

How can I do that

alpine sable
#

Is this the study of sequences?

#

@alpine sable

#

No , I’m done with that actually @alpine sable

lone heartBOT
#
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alpine sable
#

.reopen

lone heartBOT
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alpine sable
lone heartBOT
alpine sable
#

I have to determine the left and right limit of f(x) as x approaches p ∈ Z , help please I’m so lost

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

<@&286206848099549185>

lone heartBOT
#

@alpine sable Has your question been resolved?

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median mauve
#

can a arithmetic sequence be only contain one element

wheat zenith
median mauve
#

I am trying to find an artical

#

that proof this

wheat zenith
#

why do you need a proof

#

ig it depends how you define it but i think one would conventionally define it such that sucessive elements have a constant difference and one element would satisfy that

median mauve
#

can't 1 be a ap

#

arr = 1

#

I can say that

#

arr[0] and arr[0] have common different 0

wheat zenith
#

what do you need this for

#

it depends on your definition of arithmetic sequence/progression

median mauve
#

i am create an problem with AP

#

should I assume it have at least 2 elements

#

or I need to say that

wheat zenith
#

you should probably clarify to avoid ambiguity if it hasn't already been clarified

median mauve
#

oh ok

wheat zenith
#

if one element would make the solution trivial, you should specify that you don't consider it to be an arithmetic sequence, if one element would make the solution elegant and considering it not an arithmetic sequence would be annoying to deal with, specify that you do

median mauve
#

ok ty

#

.close

lone heartBOT
#
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alpine sable
#

$\frac{a\cdot r^{n-1}}{(r-1)}+d\left(\frac{2\cdot r^{n} +(n-1) \cdot r^{n+1}-1-n\cdot r^{n}}{(r-1)(1-r)}\right)$

Does this work for Arithmetico-geometric prograssion sum

ocean sealBOT
#

IDrinkWine

alpine sable
#

Does it?

#

Mosh

glass lichen
#

I was just gonna tell you why .close fucked up.

#

message needs to be just .close

alpine sable
#

Oh

#

Well anyways does it work

glass lichen
#

no clue.

alpine sable
#

Ah well I will verify it myself.

#

.close

lone heartBOT
#
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wanton kernel
#

Algebra

lone heartBOT
wanton kernel
#

what is it?

#

Like how does it work?

pine kettle
#

the part of mathematics in which letters and other general symbols are used to represent numbers and quantities in formulae and equations.

glass lichen
#

Algebra (from Arabic: الجبر, romanized: al-jabr, lit. 'reunion of broken parts, bonesetting') is one of the broad areas of mathematics. In its most general form, algebra is the study of mathematical symbols and the rules for manipulating these symbols; it is a unifying thread of almost all of mathematics. It includes everything from elementary e...

#

You too, can google

wanton kernel
#

Thank you

wheat zenith
#

the mathematical study of symmetry

glass lichen
severe sluice
wheat zenith
#

group theory \subset algebra

bleak ridge
#

The mathematical study of mathematics

wanton kernel
#

Hi

#

I now have a more appropiate name

glass lichen
#

Cool, if you have a question get a help channel.

pine kettle
#

@wanton kernel please open a new channel if you're about to aska a question

#

Bruh

wanton kernel
#

I'm not

glass lichen
#

So... why did you type here?

wanton kernel
#

I'm just stating that I have changed my name

glass lichen
wanton kernel
#

Ok

lone heartBOT
#

@wanton kernel Has your question been resolved?

severe sluice
glass lichen
#

same user

severe sluice
#

ohh-

#

okay

#

didn't notice that

glass lichen
#

Yeah... weird new users catshrug

#

<@&268886789983436800> this

lone heartBOT
#
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alpine sable
#

25x^2 + 10x - 3 = B^2 + 2B - 3

lone heartBOT
alpine sable
#

whats the value of B in terms of X

#

im p sure the answer is 5x but im not sure if its right or how to solve

raw shard
#

add 3 to both sides

#

then equate like terms

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

i tried doing this

#

but got caught up at what the next step is

raw shard
#

so you have 25x^2+10x = B^2+2B

#

which term on the right would be similar looking to 10x?

raw shard
#

yeah

#

so you’re assuming that 10x = 2B

#

solve for what B is

#

then see if that works for the whole thing

alpine sable
#

wait

#

u automatically would assume 10x = 2B

raw shard
#

yeah

alpine sable
#

so that would work for any equation

#

assume like terms r equivalent

raw shard
#

what do you mean

#

oh

#

i guess

#

i haven’t done many problems like this

alpine sable
#

oh i never knew that

raw shard
#

but that’s always how it seems to be

alpine sable
#

right thanks

#

have a g1

#

and happy new year

raw shard
#

thanks you too

alpine sable
#

.close

lone heartBOT
#
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limber shard
#

$$\begin{equation*}
A_{3,4} =
\begin{pmatrix}
1 & 3 & 4 & 8 \
0 & 0 & 8 & 0 \
0 & 0 & 0 & 21
\end{pmatrix} \end{equation*}$$

ocean sealBOT
#

Aarjav
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

limber shard
#

is the answer to this question correct?

#

<@&286206848099549185>

lone heartBOT
#

@limber shard Has your question been resolved?

lone heartBOT
#

@limber shard Has your question been resolved?

lone heartBOT
#

@limber shard Has your question been resolved?

small stag
#

sorry I can't help you

raw shard
limber shard
#

Alright. Thank you!

#

.close

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#
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tidal crest
#

I need help with this, I’m really sorry.

tidal crest
#

(I’m an online student for my school so no one explains it to me )

echo socket
#

What are you asked to do here?

tidal crest
#

how to Graph it.

echo socket
#

Oh, to graph a line it's enough know know 2 points that it crosses and then just connect those lines with an line (make sure the line goes beyond the points as well)

tidal crest
#

Ah ok.

echo socket
#

In this case what you could do is choose any value of x or y and then solve for the other unknown

tidal crest
#

How do I solve for it?

echo socket
#

As I said first choose any value that you want for x or y

#

Let's say we picked x=0

#

Then what we have is -5y = -25

#

Therefore y = 5

tidal crest
#

OOOOOOOHHHHHH

echo socket
#

So when x =0, then y = 5

#

And it means that

#

The line

#

Crosses the point (0, 5)

tidal crest
#

That makes a lot more sense lol

echo socket
#

Now you need 2 points to graph a line, so now you need to make a different choice

#

To find the other piint

#

Point*

tidal crest
#

Ok tysm ❤️

#

.close

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#
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surreal badger
#

if perimeter of rectangle is 68cm

and diagonal is 26 cm

how to find the dimensions of the rectangle ( length and breadth)

remote heron
#

use pythagorean thm

surreal badger
#

found it

#

lol

remote heron
#

oh

#

nice

surreal badger
#

i didnt think deep

remote heron
#

u get 10/24

#

ur good

surreal badger
#

its about triplets

remote heron
#

ah yea

#

it is isnt it

#

5 12 13

surreal badger
#

yh

remote heron
#

i didnt even think about that

surreal badger
#

lol

remote heron
#

i just did the algebra

#

like a dope

surreal badger
#

i mean pythogoras works

#

lol

#

its just too much time

#

guessing numbers

#

then making

#

lol

remote heron
#

not guessing

#

just 2a+2b=68

#

so (34-a)^2+a^2=26^2

#

then 240-34a+a^2=0

surreal badger
#

quadratic?

remote heron
#

gives a,b are 10,24 interchangably

#

yea

surreal badger
#

ah frick

#

that works too

#

lmao

#

wait that might be the q

#

cause the first q was about simultaneous

#

shit

thorny patio
#

That's definitely the way youre supposed to do a prob like that

#

Simultaneous equation with perimeter and area

#

Err

#

Not area

surreal badger
#

no like

#

part a was to make a simultaneous and solve x and y

thorny patio
#

The pythagorean relationship

surreal badger
#

part b find length breadth

#

i did using pytho

surreal badger
thorny patio
#

Yes becauseeeeee

#

If the numbers were not nice

#

You could not figure it out by intuitively checking right triangles

surreal badger
#

yh

#

true

#

examiners are smart

#

lmao

#

and also thinks about everyone too

#

lol

thorny patio
#

With the algebraic way you can figure it out for any rectangle

surreal badger
#

yh

surreal badger
thorny patio
#

Practice the problems as many times as you can first xD

remote heron
echo socket
surreal badger
thorny patio
#

Practice a wide variety of problems if you can but mostly practice

remote heron
#

so you have this formula from perimeter

#

2a+2b=68

#

just name some side a

#

some side b

#

of the rectangle

surreal badger
#

yh

remote heron
#

it follows that a+b=34

surreal badger
#

yes

remote heron
#

then anywhere we see b, we can substitute 34-a

surreal badger
#

yes

remote heron
#

pyth gives that a^2+b^2 = 26^2

#

sides of the rectangle and the diagonal

#

we substitute

#

and you get to what you had quoted

surreal badger
#

oh great it works

#

thing is the main thing i hate about the maths im doing

#

we arent supposed to use any calculators

remote heron
#

memorize some prime squares

#

and factor

#

if thats what youre worried about

#

what sort of math are you struggling with?

#

if it were me and i were on a test or something and you run into something you cant do without a calculator

#

give it 5 min maybe then just make a note like

#

im gonna call this number M

#

or something

#

honestly

#

idk how your class is for partial credit

surreal badger
#

oh

#

no like im doing OLs

#

i have my mocks next week

#

doing some past papers

#

also school papers are actually harder than

#

the the actual OL papers

surreal badger
#

its just inefficent multiplaying

#

takes time

remote heron
#

so thats

#

yea thats not an easy one

#

maybe you could use difference of squares here

#

idk how much time it saves

#

theyre nicer numbers though

#

60 and 8

#

instead of 34^2 and 26^2

#

you could probably do 60*8 in your head

surreal badger
#

yh

remote heron
#

since you have like

#

$34^2 - 26^2 - 68a + 2 a^2 = (34+26)(34-26) - 68a + 2a^2 = 2 \left( (17+13)(17-13) - 34a + a^2 \right)$

ocean sealBOT
#

jan Niku

remote heron
#

this works great

surreal badger
#

it does

#

also i think they will reduce marks if i did the triplet way

surreal badger
#

normal way

#

equation

#

or

remote heron
#

best?

surreal badger
#

completing the square

surreal badger
remote heron
#

i mean there are a lot of ways

#

it depends on what looks easiest

#

that you do need some experience

#

you should have a lot of methods at hand right

#

you just have to recognize which one seems like it will work best

#

it depends

surreal badger
#

then gotta study all

#

ig mods can close this

#

channel then

surreal badger
remote heron
#

you can close the channel if u want

#

@surreal badger

#

use .close

#

ur the last one

#

then ima go to bed

surreal badger
#

thanks!

#

gn

#

.close

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#
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tawny fable
#

Hi there

lone heartBOT
tawny fable
#

I need some help with this question

#

Someone can help?

lone heartBOT
#

@tawny fable Has your question been resolved?

tawny fable
#

<@&286206848099549185>

vale wigeon
#

consider: A and B are row-equivalent iff there exists an invertible n by n matrix R such that RA = B

#

this, and some thought, should let you do a, b and c

tawny fable
#

Yup

vale wigeon
#

d is a matter of thinking about the definition of nullspace and proving two sets are equal by element-chasing

tawny fable
vale wigeon
#

sure

#

row operations are just left-multiplications by particular matrices

tawny fable
#

yeah

#

But the thing is, I am getting confused by the difference between row operations and column operations

#

and how do the affect the column space

vale wigeon
#

row operations operate on rows. column operations operate on columns

#

column operations preserve column spaces while row operations do not

tawny fable
#

On the one hand I feel like a is true, because trying to throw some examples I see that the basis stays the same

vale wigeon
#

it is not true

tawny fable
#

Because anyways, I need to get to REF

#

Mhmm

vale wigeon
#

consider: row operations do not preserve column space

#

and you are acting as if they do

#

it is only natural that you arrive at a bullshit answer

#

consider: $\bmqty{1&0\0&0}$ vs. $\bmqty{0&0\1&0}$

ocean sealBOT
vale wigeon
#

row equivalent? yes. same column space? no.

tawny fable
#

like shouldn't all the pivots be on top?

vale wigeon
#

who gives a shit about REF?

#

you think a matrix does not deserve to exist unless it is immediately REF'd?

tawny fable
#

That is how we learned to find the basis of the column space

vale wigeon
#

setting aside the fact that there's no such thing as "the" basis,

#

even if you use row ops to find a basis for the col space, you go back to the original matrix you started with

#

you do not read the columns of the REF'd matrix directly to view them as making up your basis

#

but still, what just came from you sounds like matrixbashing at its finest: clearly you only view matrices as something to put in REF and nothing else.

tawny fable
#

I think my misunderstanding is what exactly is the column space equal to

#

for example in you're example

tawny fable
vale wigeon
#

the column space is the span of the columns

#

it could not be simpler as far as definitions go

tawny fable
#

So the column space = span{[0,1]} on the right one

#

and span{[1,0]} on the left one

#

?

vale wigeon
#

yes

#

and it should be clear as day to you that these are not the same in the slightest

#

sometimes it helps instead to view Col(A) as the set of all vectors of the form Ax, where x is an appropriately-sized but otherwise arbitrary column vector

tawny fable
#

in that example you said:
Col(A) = {[a,0] | a in F}

vale wigeon
tawny fable
#

And about 6.(b). when they say F^n

tawny fable
#

I mean doesn't that mean that the vectors that span the space are sized n?

vale wigeon
#

"This says the column space is F^n. Can the column space be something other than F^n?"

#

do you hear yourself

tawny fable
#

Is that totally wrong?

#

I meant when they say in the question that Col(A) = F^n

vale wigeon
#

yes, they say Col(A) = F^n so they mean Col(A) is all of F^n