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1 messages ¡ Page 906 of 1

pine kettle
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$\frac{d}{dx}\left(C\right)=\ 0$

ocean sealBOT
dire crown
#

i understand that there has to be more to it, right?

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because i was talking to someone else and they had shown me this

pine kettle
#

I've only gotten to applications of derivatives, haven't even done integrals yet 😿

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Good luck

dire crown
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oh

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rip

smoky cloud
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do uk what an integral is ?

dire crown
#

yes

smoky cloud
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what is it ?

dire crown
#

area under a graph

smoky cloud
#

ya

dire crown
#

yk

smoky cloud
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definite integral will give in b/w the specified co-ordinates

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indefinite integral will be the general area formula ( it is like an expression )

dire crown
#

oh.

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so

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its literally something like x + 2

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and not x + 2 = 2

smoky cloud
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not like that wait let me share some pic for better understanding

dire crown
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ok

smoky cloud
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see this green is definite integral b/w point a and b
indefinite integral is the entire area's expression

dire crown
#

o

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k

smoky cloud
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understood ?

dire crown
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yes

smoky cloud
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cool

dire crown
#

.close

lone heartBOT
#
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dire crown
#

thank

lone heartBOT
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spark latch
lone heartBOT
spark latch
#

I am just not sure what it is asking or how to do it

pine kettle
#

I had a problem on my review exactly like this

spark latch
#

Did you understand what it was asking and how to do it?

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We are just learning this stuff and I am not understanding ngl

pine kettle
spark latch
#

ohhhh okay I get it

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I just didn't read the last part correctly

#

ty

lone heartBOT
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small flint
lone heartBOT
severe sluice
small flint
#

no

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@severe sluice

severe sluice
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anyways

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what are you having trouble with?

small flint
#

tri c

light ether
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I believe it is saying that you reflect the triangle over the line x=-1

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(which is not what I had in that previous image)

small flint
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hm

light ether
small flint
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so x=-1 is the new mirror?

light ether
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only for triangle c

small flint
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i know that

severe sluice
light ether
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Triangle C is just defined as Triangle B but reflected over the line x=-1

small flint
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ah

light ether
light ether
small flint
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how about triangle d

light ether
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I'm trying to remember if in matrix form y is above or below x

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the matrix
[-3
-4]
could either be (-3,-4) or (-4,-3) depending on whichever it is

light ether
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ty

severe sluice
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or at least that's usually howit works

light ether
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matricies are weird, but I just checked and yup, thankfully they're normal here

small flint
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so x for the top?

light ether
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so you're translating triangle a by (-3,-4)

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yup

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so it should look something like this

small flint
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so move triangle a from1,1 to -3,-4?

light ether
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a translation of vector (-3,-4) would mean moving the point (1,1) 3 across and 4 down

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basically

small flint
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oh

light ether
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you're taking the original point (1,1) and adding (-3,-4) to it

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(1+-3,1+-4) -> (-2,-3)

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That's how adding vectors work

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You add the components together

small flint
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makes sense

light ether
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now the scaling question is weird

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But I think I've interpreted it correctly

small flint
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ok

light ether
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okay so say you have a grid

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when scaling in relation to zero, you are pretending that shape's corner is centered at zero

small flint
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90 degree angle?

light ether
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so for example

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we're pretending that this triangle is centered at 0,0

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even though it's not

small flint
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how would this apply to a square?

light ether
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well, the square is a tool for us to think about the scaling

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because the triangle is "centered" at 0 now

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we have to pretend make sure it scales properly

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here's what it looks like scaled

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The square is half the size it was

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but if we're looking at the triangle, we'll see it's also moved

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Does that make sense?

small flint
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yes?

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how is it centered tho?

light ether
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the scaling is centered

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not the triangle

small flint
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ah

light ether
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I'm quite certain this is what it's asking for

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so, you basically scale it but it also shift in the direction of the center

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because of that invisible box

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if it was a scale factor of 2, it would get further away

small flint
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ok

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hey btw have you herd of the Collatz Conjecture

light ether
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It rings a bell, one moment

small flint
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ok

light ether
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oh yes

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3x+1

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yes, what about it

small flint
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i find it interesting

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also scary

light ether
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and no, I can't solve it XD

small flint
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did you know that you can use negative numbers?

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if you do there are 3 loops

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found out through this guy

light ether
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Fantastic channel

small flint
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yea

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engaging format too

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do you think it will be like negative numbers?

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like at first it wasn't accepted and now it's basic knowledge?

light ether
small flint
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wouldn't it be cool tho?

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like the scp's "missing number"?

light ether
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Sorry kinda busy

small flint
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yea

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sorry

light ether
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nw

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just do .close when you're done

small flint
#

thanks

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for helping

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.close

lone heartBOT
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undone scroll
lone heartBOT
undone scroll
#

i got this wrong can someone help

young bough
#

What did you use for U sub?

buoyant kayak
#

i mean it's right

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maybe try a decimal approximation? i dunno

young bough
undone scroll
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yea i used lnx for u

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should i try this, i have only 2 attempts so i can only have 1 more attempt

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or should i just do the decimal

buoyant kayak
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no idea what the program wants

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i would assume an exact answer, which you already had

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so sure, go for it

undone scroll
#

dang i got it wrong

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thats so weird hmm ill email my teacher about it

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thanks tho guys

#

.close

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cunning raven
#

Please help with negative polar coordinates

lone heartBOT
#

@cunning raven Has your question been resolved?

ocean sealBOT
cunning raven
#

wait I have another question

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Where did I do my work wrong? @tough hatch

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not exactly but i need the answer right now because i need to hand in in 10 min

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again, this is not a test

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hw

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I'll ask why it works later

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The only reason I'm cramming rn is I took too long trying to understand the previous ones

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you saw me post hw and never asking for answers straight away

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this is the only instance, and it's because I'm running against the clock

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@tough hatch

lone heartBOT
#

@cunning raven Has your question been resolved?

cunning raven
#

.close

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rich basin
lone heartBOT
gusty yew
#

It looks like to see more clearly that its a perfect square in $\mathbb{C}$

ocean sealBOT
#

glittersparkles

gusty yew
#

$1-4+4i = 1 +4i +4i^2 = (1+2i)^2$

ocean sealBOT
#

glittersparkles

rich basin
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@gusty yew but what kind of way did they find it?

gusty yew
#

Probably by the same concept as completing the square.

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But instead of x you have i and i^2

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So -8+6i=-8+9-9+6i=1+6i+9i^2=(1+3i)^2

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This will not work for any imaginary number

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(I think)

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Yeah it only works if for some a,b real numbers x+iy =a^2-b^2+2abi

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So the real part needs to be a difference of squares

lone heartBOT
#

@rich basin Has your question been resolved?

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steel aurora
#

Hi, so I have $\phi : Z_{30} \to Z_5$ be a homomorphism, where $\phi (3) = 4$, how do I find a formula for $\phi (x)$?

ocean sealBOT
#

Atehortua

steel aurora
#

I know that $\phi(x)^n = \phi( \underbrace{x + x + \cdots + x}_{n\text{-times}})$, so we can use that on $\phi(3)^n$, but since 3 divides 30 I can't get $\phi(1)$ this way

ocean sealBOT
#

Atehortua

steel aurora
#

or any element that generates $Z_{30}$ for that matter

ocean sealBOT
#

Atehortua

lone heartBOT
#

@steel aurora Has your question been resolved?

lone heartBOT
#

@steel aurora Has your question been resolved?

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@steel aurora Has your question been resolved?

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quiet salmon
lone heartBOT
quiet salmon
#

How do I solve this

#

Question

pine kettle
#

Use exponent rules

quiet salmon
#

You mean "laws of indices"

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??

pine kettle
#

Same thing lol

quiet salmon
#

Yeah so

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I came up to here

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Now what

quiet salmon
#

Can I just add the power

pine kettle
#

You can distribute the exponent

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You don't add exponents, you multiply when an exponent is to an exponent

quiet salmon
#

Ok

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So I multiplied

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Now

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It looks like this

pine kettle
#

2b(c-a) is not 2bc-a

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Also I suggest a dot instead of an x for multiplication

quiet salmon
#

Ok

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Now what

pine kettle
#

More simplifying

quiet salmon
#

So can I just add the power

pine kettle
#

Seems so

quiet salmon
#

However, It looks like this

pine kettle
#

2b(c-a) is not 2bc-a

quiet salmon
#

So is it 2bc - 2a

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??

pine kettle
#

No

quiet salmon
#

Yeah

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?

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What is it

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Thwn

pine kettle
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2bc-2ab

quiet salmon
#

Oh

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So

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Somehow I ended up like this

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@pine kettle

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Can I do

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2c(a-b)

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Cuz in both side they have 2c

pine kettle
#

Why couldn't you?

quiet salmon
#

So I did it and

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End up

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Like thus

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X^2c(a-b)

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$x$^2c(a-b)

ocean sealBOT
#

! BASU乛ᴬᴳ

$x$^2c(a-b)
```Compilation error:```! Missing $ inserted.
<inserted text> 
                $
l.55 $x$^
         2c(a-b)
I've inserted a begin-math/end-math symbol since I think
you left one out. Proceed, with fingers crossed.```
quiet salmon
#

That isn't the case

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I messed up

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So

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It's like this

pine kettle
#

2c(a-b)

quiet salmon
#

Yeah

pine kettle
#

Distribute

quiet salmon
#

Ol,

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2ca-2cb

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Like this

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??

pine kettle
#

Yes

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Also organize your variables

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2bc instead of 2cb

quiet salmon
#

Ok,

pine kettle
#

It will help you see like terms

quiet salmon
#

So what's the point

quiet salmon
#

@pine kettle

pine kettle
#

Is that the final answer?

quiet salmon
#

I don't think so as my books says the answer should be "1"

pine kettle
#

That means you didn't distribute or do exponent rules correctly

quiet salmon
#

Where was I wrong

#

Man,

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Sry dude

#

I ended up messing up

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And can you tell md

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How do I use this bot @ocean seal

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And thanks for the help I got the answer

#

I appreciate it

#

!close

#

.close

lone heartBOT
#
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fringe yacht
lone heartBOT
fringe yacht
#

Why is this not allowed in 28?

#

I can multiply the numerator and denominator by the same constant without issues right?

lone heartBOT
#

@fringe yacht Has your question been resolved?

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tidal saffron
#

I don't know if questions about genetic algorithms are appropriate to ask here since It partially falls under theoretical computer science, but I thought I should give it a go anyway.

tidal saffron
#

I am currently working through Schemas in genetic algorithms and came across the following question:

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"How many possible schemas are there of length 'm' binary strings".

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Intuitively my answer would be "2 to the power of m", however, this answer is wrong. Instead, it would be "3 to the power of m", but I don't entirely understand why that is the case. Would anyone be able to help me? Thanks.

raw shard
#

@neon gull this isn’t your channel, delete your message and go to an unoccupied channel

neon gull
#

Sorry

vale wigeon
#

what's a schema?

tidal saffron
#

A schema is a set of bit strings that can be described by a template made up of 1, 0 and *, where * stands for “wild card” ( 1 or 0).

vale wigeon
#

hm

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so then wouldn't it be kinda obvious that there are 3^n such templates

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each template is a string over {0,1,*}

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and different templates clearly describe different schemas

tidal saffron
#

Lmao, that does make sense. I guess I was confused by the wording of the explanation that was given on the worksheet for the question

"There are m positions in the schema, and each position can take one of 3 possible values: 0, 1 or m. So the total number of possible choices is 3 to the power m."

vale wigeon
#

0, 1 or *

tidal saffron
#

So would I be right in thinking that m is just basically * ?

vale wigeon
#

whoever wrote that answer key for some reason replaced the wildcard symbol with m

tidal saffron
#

Alright, that makes sense. Thanks for the help 👍

#

.close

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chrome salmon
#

Do u want to keep log or not

#

I can tell you two ways for this in that case

ocean sealBOT
#

it's Sam

chrome salmon
#

Use this and tell me what you get on both sides

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Ok

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Now remove log from both sides

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What do u get

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Now write 9 and 27 in terms of power of 3

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Good

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Now get the powers of 3 on both sides

ocean sealBOT
#

it's Sam

chrome salmon
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Ok so now both base are same

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So the power needs to be equal

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What do we get

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Good

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There's other way too

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By keeping log

ocean sealBOT
#

it's Sam

chrome salmon
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Are you aware of this?

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Ok np

ocean sealBOT
#

it's Sam

#

it's Sam

chrome salmon
#

I feel the presence of papa bread

#

\begin{aligned} (x+2) \log 9 &= x \log 27 \ (x+2) \log 3² &= x \log 3³ \ 2(x+2) \log 3 &= 3x \log 3 \ 2(x+2)&=3x \end{aligned}$

ocean sealBOT
#

it's Sam

\begin{aligned} (x+2) \log 9 &= x \log 27 \\ (x+2) \log 3² &= x \log 3³ \\ 2(x+2) \log 3 &= 3x \log 3 \\ 2(x+2)&=3x \end{aligned}$
```Compilation error:```! Package amsmath Error: \begin{aligned} allowed only in math mode.

See the amsmath package documentation for explanation.
Type  H <return>  for immediate help.
 ...                                              
                                                  
l.55 \begin{aligned} 
                     (x+2) \log 9 &= x \log 27 \\ (x+2) \log 3² &= x \log 3...

You're in trouble here.  Try typing  <return>  to proceed.
If that doesn't work, type  X <return>  to quit.```
chrome salmon
#

Yeah

#

Close the channel if you have no more doubts

lone heartBOT
#

@dusky shuttle Has your question been resolved?

fringe yacht
#

.reopen

lone heartBOT
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peak iron
#

Hey, how to solve this? Thanks

lone heartBOT
peak iron
#

(To prove or disprove the statement)

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@peak iron Has your question been resolved?

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lapis goblet
lone heartBOT
lapis goblet
#

Shouldn’t it be i-(whatever)j + (sjzhusb)k

#

Because the determinant

#

<@&286206848099549185>

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alpine sable
#

Find the centroid of the region bounded by the given curves: $y=3x+5, y=0, x=-1, x=2$

ocean sealBOT
alpine sable
#

How would I do this when there's two x-values? I've tried doing the integral where a = 0 and b = 2, but it doesen't give me right answer

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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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alpine sable
#

hi, could someone help me understand this worksheet?

alpine sable
#

i don't get what step pattern/mapping rule is

#

<@&286206848099549185>

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shy tide
#

I have a Google sheet that I am trying to figure out the following.

I am giving 50% to all my sales team of net and or profit of sale depending on the product. I figured it out my issue here is that some of my items cost is more then the sale, For instance line 19 price is $3 I am charging $4 for the product. In this case I want to make sure i am not losing money. So I need to do a few steps that i completed in the G,H,I,J col. But i cant figure it out a way to get the percentage amount at the end of the day between 50% Profit and lets say 48% profit. The reasoning i need to figure this out. I have a backend system that i can enter the percentage of net ONLY. This sheet will tell me what i need to put in the backend at the end of the day.

I want to show the percent they are getting for each year.
Year 1,2,3 the amount they will be getting in percentage.

shy tide
shy tide
# shy tide

Col L and M can be used for any math purposes

#

row 5 and 6 are different then the rest

#

Another screenshot

lone heartBOT
#

@shy tide Has your question been resolved?

lone heartBOT
#

@shy tide Has your question been resolved?

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

Can't figure it out.

#

Put it in the right form

zealous bloom
alpine sable
#

Find y

#

Writing equations in slope intercept forn

#

Form

#

My channel

fast zenith
#

oh sorry

fast zenith
ocean sealBOT
#

ShitakeMush

alpine sable
#

I did

#

6-y/7-17

fast zenith
#

just rearrange and solve for y?

zealous bloom
# alpine sable

Sorry my internet is being weird - point-slope form:
y - y1 = m(x-x1) -> m is given as 1

alpine sable
#

6-y over -10

#

I need y

#

I can't get y

#

@zealous bloom

zealous bloom
alpine sable
#

I got it y=16

#

Thx

#

.close

lone heartBOT
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neat wharf
#

How do I solve this problems correctly and even if I do, how do I figure out the value of the other sides?

neat wharf
#

I already figured out the first problem, by diving 9/15 and multiplying the answer of that by 9, getting 5.4

#

I'm just out of ideas in the second problem though.

#

I tried doing the same thing, but I don't know how I can get 7.86.

raven swallow
#

what if you knew XW?

neat wharf
#

I do not know how to determine the other sides besides the two already mentioned.

raven swallow
#

I'd start with two different expressions for cos(ZXW)

#

what are they?

#

leave XW just like that, no numbers yet

#

put these expressions for cos(left lower angle) equal

#

express XW

#

knowing it you can find a cosine too, and using cosine and XW you can also get WY

lone heartBOT
#

@neat wharf Has your question been resolved?

neat wharf
#

.close

lone heartBOT
#
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waxen adder
lone heartBOT
waxen adder
#

Not sure how to go about this one

#

Nvm i got it 👍

#

.close

lone heartBOT
#
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waxen adder
#

This one I’m not sure of

lone heartBOT
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shy tide
#

.reopen

#

.reopen

raven swallow
lone heartBOT
waxen adder
#

I haven’t tried much yet just because i didn’t know where to start so i opted for some other practice problems first 😕

raven swallow
#

How about using derivatives to minimize things

#

or to maximize

shy tide
# shy tide

I have tried a few methods.

  1. take the total*50% then minus the cost price.
waxen adder
#

Not sure i follow the set up

shy tide
#

not a math guy. use to be one, but forgot it during my older years. I can use the guidance on how to do it

raven swallow
waxen adder
#

Ok

shy tide
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#

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frozen matrix
#

can someone please help

lone heartBOT
#

@frozen matrix Has your question been resolved?

severe sluice
#

just... uh, separate this into parts and do integrals over each part?

frozen matrix
#

I did for likf

#

3 times

#

used calculator

#

still says its wrong

#

the big part is 6859/6

#

left part 59/6

#

right part 104/3

#

its just not accepting

#

and I have no idea what im doing wrong

#

left?

#

ugh im not sure

severe sluice
#

wait no

#

that's correct

frozen matrix
#

oh wait its wrong

#

is it 92/3?

#

ughhhhhhhhhhhh

#

I dont get it

severe sluice
#

i mean

#

you can just do

#

$-\int_{-10}^{-9} 90-x^2+x \dd x$

ocean sealBOT
#

Kagna Gang Advocate Adavocowana

severe sluice
#

, w$-\int_{-10}^{-9} 90-x^2+x \dd x$

frozen matrix
#

-10 -9?

#

I was talking about right part

severe sluice
frozen matrix
#

I found it 59/6 I think

#

but the right part

#

I did integral of 100-x2 from 10 to 12

#

minus 12

severe sluice
#

it's 10 to 11, i think?

frozen matrix
#

oh

#

god f

#

ur right

lone heartBOT
#

@frozen matrix Has your question been resolved?

#
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lone heartBOT
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strong hornet
#

anyone know how i might go about verifying this?

strong hornet
#

ive tried

#

changing sec2x

#

to

#

1/cos^2x-sin^2x

#

and 1/2cos^2x-1

#

but

#

idk how to bring the things to the numerator

pine kettle
#

Start from the right side

#

Turn cot into 1/tan

#

You will then get a pythagorean identity

strong hornet
#

i have to go from the left

#

and prove it is equal to the right

pine kettle
#

...

#

Start from the right side anyways lmao

strong hornet
#

oh ok lmao

#

ill try

#

and then do i just work backwords

#

to prove it fromt he left

pine kettle
#

I wouldn't

#

I would just prove it from the right if you can't prove it from the left

strong hornet
#

alright

#

thanks

pine kettle
#

But yes

strong hornet
#

lemme give it a try

pine kettle
#

Do work backwards after

#

So you know how to go from left to right

#

It is good practice

strong hornet
#

right

#

hmm

#

i ended up at

#

cos(2x)/sin^2xcos^2x

#

idk what happened

#

i just tried a bunch of things

#

here’s my working

#

i tried to make a cos2x

#

because of how 1/cos2x= sec2x

#

but idk how to get rid of this sin^2xcos^2x

#

@pine kettle

pine kettle
#

I'm going to try and get Notability on my personal iPad so I can work this out

strong hornet
#

ah okay

#

thank you so much

#

sorry for bothering you btw

pine kettle
#

I enjoy helping others

lone heartBOT
#

@strong hornet Has your question been resolved?

lone heartBOT
#

@strong hornet Has your question been resolved?

lone heartBOT
#
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boreal sedge
#

A small jar contains 41 dimes and quarters. The value of coins in the jar is 6.65. How many quarters are in the jar?

boreal sedge
#

A small jar contains 41 dimes and quarters. The value of coins in the jar is 6.65. How many quarters are in the jar?

#

How can I set this equation up for elimination?

vale wigeon
#

have you written down the equations themselves yet?

#

before you do any algebraic shit you need something to do said shit on

#

@boreal sedge

boreal sedge
#

yeah yeah i know and I cant figure out what the equations are

vale wigeon
#

okay so you should have begun with that

#

rather than jumping straight to pure algebraic techniques

boreal sedge
#

i have 6.65=10x+25y so far

vale wigeon
#

what's x and what's y?

boreal sedge
#

x is the dimes and y is the quarters

vale wigeon
#

x is the number of dimes, and y is the number of quarters

#

okay then your equation as written is wrong

boreal sedge
#

ah

vale wigeon
#

the left-hand side is (presumably) in dollars while the right-hand side is in cents

#

so what's up with that?

boreal sedge
#

right uhh

#

i meant 10 cents and 25 cents

#

6.65=0.10x+0.25y

vale wigeon
#

that's more like it.

#

so that's the equation describing the total value of your coins.

#

there's one more equation to be written down.

boreal sedge
#

right and it includes the amount of coins

#

I thought it was just 41=x+y but surely not

vale wigeon
#

why do you think it isn't 41=x+y?

boreal sedge
#

mainly cause my brother said it was wrong

vale wigeon
#

and is your brother 100% infallible?

boreal sedge
#

probably not

vale wigeon
#

did he explain in any way why he thinks you're wrong, or did he just say it outright and act hostile to you over it?

boreal sedge
#

just told me it was wrong

#

i'll assume it's the correct equation?

vale wigeon
#

well yes, it's your brother who is in the wrong here

boreal sedge
#

yeah

#

so after i have them lined up

#

0.10x+0.25y=6.65

#

x+y=41

vale wigeon
#

yes

#

now you can solve this system of equations in whatever way you like

#

unless you have been explicitly instructed to use some particular method in which case follow said instructions

boreal sedge
#

yeah i have to use elimination

#

so ill multiply by 10 on the bottom equation

vale wigeon
#

the bottom?

boreal sedge
#

the x+y?

vale wigeon
#

why not the top, and why not by 20? that way you get rid of all those decimals.

#

i mean, if you want to make your own life unnecessarily difficult and the numbers unnecessarily big, then by all means feel free to do so.

boreal sedge
#

haha preferably not

#

okay fair

#

so i multiply by 100 on the top to make them into whole numbers

#

well that doesn't really help me much

#

uhh

vale wigeon
#

if what you're doing doesn't help you much, then why not heed some of my suggestions?

boreal sedge
#

ok

#

top by -10

vale wigeon
#

you multiply the top equation by -10 on both sides, and get what?

boreal sedge
#

no wait i want the bottom to be by -10

#

that way i can subtract them

vale wigeon
#

it sounds like you're not listening to my suggestions at all

#

the way you're trying to do something completely different in what i can only describe as flopping around like a fish washed up on shore

#

do you want to solve the problem or do you want to keep floundering?

lone heartBOT
#

@boreal sedge Has your question been resolved?

vale wigeon
#

oh they left lol

#

.close

lone heartBOT
#
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rich basin
lone heartBOT
rich basin
#

could someone please try (a)

lone heartBOT
#

@rich basin Has your question been resolved?

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fast zenith
lone heartBOT
fast zenith
#

can someone help me with this qus

chrome salmon
#

Did you try anything

vocal edge
rich basin
#

can someone please try the problme i had, it is really similar

#

(a)

fast zenith
fast zenith
#

how does that eliminate theta

vocal edge
#

Eliminate usibg cos(theta) =x/r

fast zenith
lone heartBOT
#

@fast zenith Has your question been resolved?

vocal edge
fast zenith
vocal edge
#

@fast zenith something like this?

lone heartBOT
#

@fast zenith Has your question been resolved?

lone heartBOT
#
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misty bobcat
#

Let $R$ is a reflexive and transitive relation on a set A. Prove that relation $R \cap R^{-1}$ is a relation of equivalence on $A$. Denote $\mathcal{S}$ partition of set $A$ induced by relation $R \cap R^{-1}$ and we define on a partition S following relation:
$$
\preceq={(X, Y) \in \mathcal{S} \times \mathcal{S} ;(\exists x \in X)(\exists y \in Y) x R y}
$$
Prove that $\preceq$ is a partial order on a set $\mathcal{S}$.
Note.\Relation $R$ is reflexive and transitive on a set $\mathbb{Z}$, but it is not a partial order. This task basically describes general manual, how it is possible to get partial order from this kind of relation. In this case it means that numbers $a,-a$, which impair asymmetry, we will consider them as same and will will use them.

ocean sealBOT
#

Michal

misty bobcat
#

I have already proved that R intersection R^-1 is and equivalence relation, but i dont know how to solve second part of the task.

vale wigeon
#

which part of the definition are you having trouble verifying?

misty bobcat
#

$$
\preceq={(X, Y) \in \mathcal{S} \times \mathcal{S} ;(\exists x \in X)(\exists y \in Y) x R y}
$$

ocean sealBOT
#

Michal

misty bobcat
#

Prove that this is a partial order.

vale wigeon
#

which part of the definition of a partial order are you having trouble verifying?

#

refl, antisym or trans?

misty bobcat
#

basically all

vale wigeon
#

prove that for all $X, Y, Z \in \mathcal S$:
\begin{itemize}
\item $X \preceq X$
\item $X \preceq Y, Y \preceq X \implies X = Y$
\item $X \preceq Y, Y \preceq Z \implies X \preceq Z$
\end{itemize}

ocean sealBOT
#

Kanga Gang Annihilator Ann

vale wigeon
#

i think it's just a matter of writing out the definitions

misty bobcat
#

ok I will try

vale wigeon
#

maybe it will help if you first show \preceq can be defined in a different but equivalent way, with both \exists replaced with \foralls

misty bobcat
#

REFLEXIVE:
$\forall$ X: [X$\in S \implies (X,X)\in \preceq$]

ocean sealBOT
#

Michal

vale wigeon
#

do you insist on writing $(X,X) \in \preceq$ and not $X \preceq X$?

ocean sealBOT
#

Kanga Gang Annihilator Ann

misty bobcat
#

it does not matter to me

#

i dont know what to do with a definition of reflexivity

vale wigeon
#

you are supposed to show that your preceq satisfies it

#

take an arbitrary equivalence class of R cap R^-1, call it X. is it true that there exist x and x' in X such that x R x'?

misty bobcat
#

REFLEXIVE:
$\forall$ X: [X$\in S \implies (X,X)\in \preceq$]
\X is equivalence class of $R\cap R^{-1} \implies R\cap R^{-1}$ is a relation of equivalence, hence for $x\in R\cap R^{-1}$ holds that $xRx$ .

ocean sealBOT
#

Michal

misty bobcat
#

something like that ?

#

@vale wigeon

vale wigeon
#

you're kind of overcomplicating it i think

#

but yes

misty bobcat
#

ok, im going to try other properties

lone heartBOT
#

@misty bobcat Has your question been resolved?

misty bobcat
#

@vale wigeon what about this ?

vale wigeon
#

it's antisymmetric not asymmetric

misty bobcat
#

yes, typo

vale wigeon
#

and this is not correct as written

#

for transitivity:

from X preceq Y you get x in X and y in Y such that xRy and from Y preceq Z you get y' in Y (different than y) and z in Z such that y'Rz

#

however because y and y' are in the same eq class of R cap R^-1 you get y R y'

#

thus x R y R y' R z

misty bobcat
#

thus x R y R y' R z ?

#

i dont get the notation

#

@vale wigeon

vale wigeon
#

x R y, and y R y', and y' R z

misty bobcat
#

Hmm that's weird

misty bobcat
vale wigeon
#

no

misty bobcat
#

So I should also make the y'

#

And x'

vale wigeon
#

you should start by taking two arbitrary elements x and y in X and Y respectively and showing that x R y & y R x

misty bobcat
#

But that's what I did. Or not ?

vale wigeon
#

no, you just asserted it outright

#

you have from X preceq Y that there exist x' and y' with x' R y'

#

and you have from Y preceq X that there exist x'' and y'' with y'' R x''

#

x, x' and x'' are all in the same equivalence class

#

as are y, y' and y''

#

x R x' R y' R y

and y R y'' R x'' R x

#

and that well give you your goal

misty bobcat
#

And what about the note mentioned in excercise ?

#

About the a and -a elements

vale wigeon
#

no clue about that tbh

#

was this about some earlier exercise?

misty bobcat
#

Not

vale wigeon
#

maybe you could send a picture of the exercise as it appears in your book?

misty bobcat
#

It's just about that R is reflexive and transitive on set Z. And elements a and -a impair asymmetry.

#

It's not in English language...

#

I translated it

vale wigeon
#

ok well something is clearly getting lost in translation! because i have no idea where Z even came in until now!

misty bobcat
#

I dont get it too

#

its weird

#

okay, thanks a lot

#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

it's about infinte geometric series

#

and basically my thinking is 1/2 = 0.5 and the formula for a infinte geometric series is u sub 1 divided by 1 - r

#

so it would be 0.5 divided by 1-0.5

#

which is 1

#

but the answer key says it's 1/3

#

<@&286206848099549185> sry for pinging a bit earlier then i'm supposed to but i really need to go to sleep

gray isle
#

what's your r?

alpine sable
#

i'm fairly sure it's 0.5 right? cause it bounces 0.5 to 0.25 to 0.125

gray isle
#

no

#

the flea is moving left and right

alpine sable
#

yeah?

#

i'm not getting it how would it moving left to right affect r?

gray isle
#

it would affect the signs of your summands

alpine sable
#

i do not know what a summand is

gray isle
#

term being added

#

the r you used and what you calculated would be what would happen if the flea only jumps right

alpine sable
#

so then r is -0.5?

gray isle
#

yes

alpine sable
#

ohhhhhhh

#

wait yeah that makes sense when i put it on a number line

#

thank you for the hlp

#

.close

lone heartBOT
#
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lone heartBOT
#
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peak iron
#

Hey, how to prove that the determinant of a skew-symmetric matrix of size n is 0 if n is odd? Thanks

vale wigeon
#

look at the charpoly tbh

peak iron
#

hi Ann

#

what is the charpoly?

vale wigeon
#

characteristic polynomial

peak iron
#

thanks

#

from A=-A^T I don't know what I can conclude on the charpoly...

lone heartBOT
#

@peak iron Has your question been resolved?

vale wigeon
#

$p_A(\lambda) = \det(A - \lambda I) \ = \det(-A^T - \lambda I) \ (-1)^n \det(A^T + \lambda I) \ = -\det(A + \lambda I) \ = -p_A(-\lambda)$

ocean sealBOT
#

Kanga Gang Annihilator Ann

vale wigeon
#

so the charpoly as a function is odd

peak iron
#

ahh

#

Thanks a lot!

#

I'm unsure about smth, how do you formally conclude, from the fact that the charpoly is an odd function, that determinant is 0 if n is odd? 😅 I kinda see why but I don't know how to say it formally

vale wigeon
#

p_A(0) = det(A)

#

and from oddness you get p_A(0) = 0

peak iron
#

I see, thank you!

#

p_A(0) = det(A)
I didn't see this formulated like this in my book, is this a consequence of something?

shell widget
#

if u plug in lambda = 0 in the equation p_a (lambda) = det(A - lambda I), you get p_a (0) = det(A - OI) = det(A)

shell widget
#

Thank Ann(again) 🙂

chrome salmon
#

Dbout

vale wigeon
#

0I, not OI

lone heartBOT
#

@peak iron Has your question been resolved?

peak iron
#

Ann I got another question xD

#

we want least-squares solution, but they say: z(1) has to be an exact value, z(1) = 1.5 instead of "normal" least-squares

#

and they ask: "what does it change to the problem? what are the parameters to be determined?"

vale wigeon
#

hm.

#

well i suppose this lets is express one of the coefficients (alpha, beta, gamma) in terms of the other two

#

and then do what looks like ordinary least squares

peak iron
#

whoops sorry I forgot to desactivate the ping

vale wigeon
#

alpha * f(1) + beta * g(1) + gamma * h(1) = 1.5

#

isolate one of the greek letters as you normally would

#

just basic algebruh

peak iron
#

thanks 😅 that's true

chrome salmon
peak iron
#

and btw last question:

#

how to find this with QR?

chrome salmon
peak iron
#

(theta_2 just means parameters)

peak iron
#

how would you do that?

chrome salmon
#

Determinant of a matrix and its transpose are

#

Not equal?

peak iron
#

you mean -transpose

chrome salmon
#

Is saying det(A)=det(A^T) true?

#

det(A) = det(-A^T) = (-1)ⁿ det(A^T)
So first check if what I asked is true then you can continue from here

peak iron
#

ahh I think you're right

peak iron
chrome salmon
#

(-1)ⁿ becomes -1 as n is odd

peak iron
peak iron
chrome salmon
#

What do u think?

peak iron
#

yes

#

I'm just asking whether it's your argument haha

chrome salmon
#

Argument?

peak iron
#

nah forget
thanks!

chrome salmon
#

What's the meaning of argument?

peak iron
#

like your proof

chrome salmon
#

My proof?

#

I think I may be bren ded flonshed

chrome salmon
#

What's y_i and z~

peak iron
peak iron
peak iron
chrome salmon
#

No y_i on it

peak iron
#

z(x) = y

chrome salmon
#

Ok so you must've tried something by now

peak iron
#

first how do you write it as Ax=b?

#

I have an idea but unsure

chrome salmon
#

What does your "it" refers to?

#

You have to find z~ first right

chrome salmon
# peak iron

First you have to get answer for this question then use it in the question you sent now

peak iron
#

yeah but I mean how to use QR for least squares in general?

ocean sealBOT
#

it's Sam

peak iron
#

yeah

#

anyways thanks I think it's okay

lone heartBOT
#

@peak iron Has your question been resolved?

#
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royal patrol
lone heartBOT
royal patrol
#

How do I find the equation of the curve

#

I know it has roots -1 and -4

celest acorn
#

ez

#

thats how i see it

royal patrol
celest acorn
lone heartBOT
#

@royal patrol Has your question been resolved?

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• Show your work, and if possible, explain where you are stuck.
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pearl musk
#

how’d we get this?

lone heartBOT
urban pine
#

,tex

(a - bi)(c + di) \\
&= ac + adi - bci + bd \\
&= (ac + bd) + (ad - bc)i
ocean sealBOT
#

citrusmunch
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

late bridge
#

this channel is in use already

urban pine
#

,tex

(a + bi)(c - di) \\
&= ac - adi + bci + bd \\
&= (ac + bd) + (bc - ad)i
ocean sealBOT
#

citrusmunch
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

bleak ridge
lone heartBOT
#

@pearl musk Has your question been resolved?

lone heartBOT
#
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#
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• Be polite and have a nice day!

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alpine sable
#

is this correct?

lone heartBOT
#

@alpine sable Has your question been resolved?

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peak coral
lone heartBOT
peak coral
#

I know how to do a question like this when the differential is = say t^2 - t + 2 or something

#

But I’m not sure how to do it when it = sin

#

Feel free to ping

lone heartBOT
#

@peak coral Has your question been resolved?

peak coral
#

<@&286206848099549185>

#

Can someone help lol

raven rivet
#

hi luke, i dont wanna seem rude but ill try to be honest...what u posted doesnt feel like an interesting problem at all. it looks like one of those trivial easy exercises you can solve only by understanding the question and applying basic formulas.

#

i really hope you don't take this in a bad way. but i just wanted to tell the truth

#

at some point, it might be time for you to work and stop relying on people on discord servers. we won't be here to help you with your 1st grade questions in exams for example. you will have to count on yourself, but unfortunately that is not smth you're particularly used to.

#

this is not meant to offend you at all. sorry if it did, just tell me and i'll delete it

raw shard
#

@raven rivet if your message is somehow serious, i’m in the help channels all the time and i’ve never seen this person, so i have no clue what you’re talking about

lone heartBOT
#

@peak coral Has your question been resolved?

raven rivet
#

i do have a clue

peak coral
#

Ahahahahaha sounds rather passive aggressive bud, this is the first time I’ve asked a question in maybe a month

#

If you have such a fine grasp of differentials do you care to explain or point me in the direction of how it’s done?

#

I’ve literally explained I understand how to do do these types of questions and the exchange of real number t variables to trigonometry has thrown me off but label it as “1st grade exam questions” all you want

#

<@&268886789983436800> is this really the type of people that represent this sub?

tall wing
#

this is not acceptable

peak coral
#

And thanks @raw shard for actually pointing me to something I can use to better my knowledge

dreamy cedar
#

Hurb

#

Muted

tall wing
peak coral
#

No worries lol, couldn’t tell if it was a troll or not considering he seems to believe I rely heavily on this discord to get my degree

peak coral
#

Don’t know if you know how to solve them or just found the correct notes for it @raw shard but I’ve had a go at it now, I applied the quadratic formula and got -2+-2j which I applied to the homogenous formula and got

#

e^-2t(c1cos2t+c2sin2t)

raw shard
#

somehow i didn’t even think to ping the mods, oops

peak coral
#

Which leads me to believe it’s the second option and the value of a1 is -2

#

No problem was just taken a back a bit when I saw that response hahaha

raw shard
#

i’ll try it myself really quick if you have a few minutes

#

same lol

#

still convinced that person is a well written troll or something

peak coral
#

Yeah I’ve got time just doing maths tonight

#

Thanks

raw shard
#

i have to do something really quick, so it will be probably an extra 2 minutes

#

i’ll ping you when i’m done

peak coral
#

No problem at all, thanks a bunch

raw shard
#

@peak coral i’m asking because it looks a bit weird, but does that say 1*sin(3t) on the right?

#

because there seems to just be a space between the 1 and the sin(3t)

peak coral
#

Yeah i think its just how the software enters it

#

I just used sin(3t) I don’t think the 1 is there for any particular reason

raw shard
#

so far i have something in terms of sine and cosine, so i’m not sure if i’m doing it wrong or something else

#

because i did solve the homogeneous version of the DE

peak coral
#

Ah ok, well my final answer was the one that included sine and cosine so hopefully that’s the right way of doing it?

#

That’s what I finished with if it’s any help

raw shard
#

does it even ask for us to solve the nonhomogenous equation

#

i got the same thing

peak coral
#

Says by solving the homogenous equation however I didn’t think there was one as it’s got to be nonhomogenous as it’s using imaginary numbers no?

#

I’ll send the full question incase it’s any help

raw shard
#

ok

peak coral
#

The bits with blue are just me guessing answers I’ve not finalised anything yet and am going to change them

#

I’d assume the first can only be B and the next question where it’s asking for alpha 1 and 2 I’d leave alpha 2 empty and alpha 1 would be -2

raw shard
#

yeah the answers they put are something from a DE with real solutions

#

i guess let’s just focus on the stuff we know we can do

peak coral
#

Ah, so there’s real solutions for this?

raw shard
#

or we know they have right

#

no

peak coral
#

I’m confused then hahaha

raw shard
#

,w x^2+4x+8 = 0

peak coral
#

Yeah that’s what we both got I assume ?

raw shard
#

these are the characteristic polynomial roots

#

yeah

peak coral
#

Alright, and from that and our nonhomogenous identity id assume it’s the second option? Even tho it’s not exactly the same

raw shard
#

the sine isn’t being multiplied by t

#

ugh this question terrible, at least the answers are

#

although i assume A and B are numbers

peak coral
#

Yeah I did wonder why A didn’t have a multiple of t however none of the other answers make sense?

raw shard
#

well it’s up to you at this point lol

peak coral
#

Typical university questions

raw shard
#

since your guess is as good as mine, and it’s your work

peak coral
#

Well are you familiar with solving particular solutions at all?

#

As I can show you what I’ve done for that even tho my handwriting is awful

#

It’s everything to the right of the line if it’s even readable

raw shard
#

i’ve done it before, i don’t exactly remember though so i have a page open to help

#

so i can do it

peak coral
#

Cheers

raw shard
#

@peak coral i got $\frac{-1}{145} \cdot (12\cos(3t)+\sin(3t))$ for the particular solution

ocean sealBOT
#

quantum

peak coral
#

Oh, I must’ve done something wrong then?

raw shard
#

yeah you did, i even put it in wolfram alpha and mine was correct

#

<@&268886789983436800>

peak coral
#

Lord almighty that’s some question

sly mantle
#

@scarlet cargo dont troll

raw shard
#

just mute them already

#

they aren’t gonna get better

sly mantle
#

ok their historys all trolling

peak coral
#

How did u manage to put it into wolfram to get an answer?

raw shard
#

ban is good too

sly mantle
#

we try not to be so trigger happy on mutes

#

had to take a sec to see their history

raw shard
#

just ask for the solution to a specific differential equation

#

like

peak coral
#

I’m not good using the bot tbh lol

raw shard
#

,w solution to y’’ = ln(x)+sin(x)

#

this is gonna be bad

#

well that didn’t work

raw shard
#

what have i done

#

anyways you probably get it

#

,w solution to t*y’+cos(t)y = 3y

raw shard
#

this looks very cursed

peak coral
#

Ah you guys do it in this American way with y” instead of d^2x lol

raw shard
#

anyways those were just two examples

#

nah

peak coral
#

That’s what it was I was confused at the difference

raw shard
#

we do it the same

peak coral
#

Oh?

raw shard
#

just different notations

peak coral
#

Oh right I see