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1 messages · Page 903 of 1

tawny fable
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because p(0) must be equal to 0?

chrome salmon
tawny fable
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then it is also a subspace of R4[x]

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isnt it?

chrome salmon
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Yes

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First 3 are as far as I get it

tawny fable
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yeah

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and what is {0}

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0v?

chrome salmon
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Wait

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Let me check them first

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Yes I think first three are subspaces need to think about 4th

tawny fable
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I mean

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Arent the first 3 easy to say? I think I am missing something

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isnt it just like this one

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and also for p(0)

chrome salmon
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All go on the same line

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The last one won't be

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Not gonna think bout it yet

tawny fable
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what do you mean?

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do they mean it must be either 3 or 1?

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why do the point out that {0} is in it?

chrome salmon
tawny fable
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teh degree

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the

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sorry

chrome salmon
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Idk what that {0} is for thinkies

tawny fable
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O.o

chrome salmon
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Is that 0 in R or some Rⁿ

tawny fable
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Someone asked my teacher

chrome salmon
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Oh I see what that 0

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I get it

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The degree is odd

chrome salmon
tawny fable
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he said:
R4[x] is a vector space, which is why there exists a unique vector which will be additive identity and it will be 0v.

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That doesnt say anything...

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xD

chrome salmon
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So here in last problem

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Since they gave degree is odd

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We won't get zero polynomial in set that's why they added union of {0}

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We will get x,x³,x⁵, and such polynomiqls

tawny fable
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why you wont get it?

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isnt that when a,b,c,d,e are 0?

chrome salmon
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In all other cases they gave p(a)=0 that means p(x)=0 was one case too but here they gave
"Polynomial with odd degree"

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Is some constant like c is polynomial of odd degree?

tawny fable
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didnt we say it should be <= 4?

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the degree

chrome salmon
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Pls ranz you need to see the difference in both sets

tawny fable
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I see that it is an odd degree...

chrome salmon
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A constant is a 0 degree polynomial

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Is 0 odd?

tawny fable
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nope

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oh

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I get it

chrome salmon
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Then a constant won't be in the last set

tawny fable
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then they had to put {0} inside

chrome salmon
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Yup

tawny fable
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so it wont be easy xD

chrome salmon
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In other cases we could have constant polynomials

tawny fable
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yeah

chrome salmon
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In here we can have degree 1,3,5,...

tawny fable
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you mean as counter example right?

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if they wouldnt have put the {0} in

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we could just say that {0} is not a part of p this time because it does not have a odd degree

chrome salmon
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Yes

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That means All 4 are subspaces here

tawny fable
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so in the last one

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do I have to split into cases?

chrome salmon
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No need

tawny fable
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oh really?

chrome salmon
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What two cases?

tawny fable
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but how do you know from what degree it will be?

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it could be x^3 + 3x^2 -2x^1 and also 2x^3

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or

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-2x^1

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itselft

chrome salmon
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Let degree of p be m and degree of q be n
Then degree of p+q =< max{m,n}

tawny fable
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itself*

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oh

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yeah

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of course...

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idk why I get that so slow...

chrome salmon
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Oh wait

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Gimme a moment

tawny fable
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?

chrome salmon
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Let me think of this example

tawny fable
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o

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ok

chrome salmon
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Say p=x³+2x²+x and q=-x³+x²+x

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When we add both we get p+q=3x²+2x

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Which is of even degree

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Oh well we found a counter then

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That didn't came to me before

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Are you following?

tawny fable
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yeah

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when the odd degree canceles it self

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it is a counter example

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that it right yeah..

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when proving (c)

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do I have to show 3 cases?

chrome salmon
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3 cases for what

tawny fable
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when p(-2) = 0 and p(0) != 0

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when p(-2) != 0 and p(0) = 0

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and when both are true

chrome salmon
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What is third part btw

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I'm unable to find question

tawny fable
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lets say for addition

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closure

chrome salmon
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Doing p(-2)=0 separately and p(0) separately is enough

tawny fable
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do you mean like b?

chrome salmon
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See p such that p(-2)=0 and p(0)=0 have factor (x+2)x

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Right

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If you show separately that p with factor x+2 and p with factor x form subspace then it's enough

tawny fable
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but shouldnt I write it like I did in (a)?

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like you showed me?

chrome salmon
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Yes

tawny fable
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once for -2 and once for 0

chrome salmon
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Doing it in 3 cases as you said will be right too but there's no need to go the hard way

chrome salmon
tawny fable
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but that is exactly what I did in (b)

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was I wrong there then?

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usually they dont let us do the exact same things..

chrome salmon
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The and or difference

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You see in 2nd one you need polynomial with zeros -2,0

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Polynomials like x(x-2)

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But in 3rd one

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You can have polynomials like
x , x-2 , x(x-2)

tawny fable
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I do see the difference

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which is applicable because of distributivity we can factor x out and it will be in the form of x(x......number)

chrome salmon
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Ranz I think you should analyze the rest yourself

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First try it properly and if you have any more doubt then ask it

tawny fable
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ok

chrome salmon
tawny fable
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thanks @chrome salmon

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lethal lichen
lone heartBOT
lethal lichen
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how to integrate this by parts?

solar merlin
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try something like this:

lone heartBOT
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scarlet mango
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Can someone help me with this one?

lone heartBOT
scarlet mango
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I like half understand it, solving these has always been somewhat ambiguous to me

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<@&286206848099549185>

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Mb lmao

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In a similar vein, I don't feel like I really understand these either

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I understand how to get the fundamental set of solutions for all of them, but I don't understand how that translates to a particular solution and how to use the right side of the equation

placid zinc
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See "method of undetermined coefficients"

scarlet mango
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That would be for determining the actual A, B, C values no?
I just want to know how to get the equation shown as the answer

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Okay now I should be able to ping lmao

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<@&286206848099549185> ping me when you can help
I'm sure you guys are busy 👍

lone heartBOT
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@scarlet mango Has your question been resolved?

scarlet mango
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Nvm I think I understand it now

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short pumice
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There is a distinguishable professors and b distinguishable exercises to grade. There is more professors than exercises. How many ways are there to distribute the grading assuming every exercise is graded by exactly one lecturer and each lecturer grades at most one exercise?

lone heartBOT
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@short pumice Has your question been resolved?

short pumice
short pumice
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because if there is a professors then they can grade a! exercises but since there is not that many exercises we have to divide by (a-b)!?

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do my answer now would be the 6th option

lone heartBOT
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@short pumice Has your question been resolved?

short pumice
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<@&286206848099549185>

young violet
# short pumice because if there is a professors then they can grade a! exercises but since ther...

Your logic checks out. With b different exercises, the first one can be graded by a different professors. The second one could be graded by a-1, third by a-2, and so on. There would be a-b professors who don't grade an exercise. a!/(a-b)! would therefore be correct.
Example: 5 professors, 3 tests.
First test: 5 possible professors. Second: 4. Third: 3.
If we multiply them together to get the number of permutations, we get 5*4*3 = 5!/(5-3)! = 60

short pumice
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yes thank you!!

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frosty sparrow
lone heartBOT
frosty sparrow
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green line follows the curve of a circle

lone heartBOT
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@frosty sparrow Has your question been resolved?

frosty sparrow
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no

lone heartBOT
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@frosty sparrow Has your question been resolved?

bleak ridge
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I mean theres many ways you could go about doing that

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You could create n angles from arctan(c.y/c.x) to arctan(a.y/a.x) for example

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Then just (|c-b| cos(ang),|c-b| sin(ang)) for each angle

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Where |c-b| is the distance between c and b

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That comes with its own problems though

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Theres prob a better way to do it with complex numbers

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Do you have an application for this problem? @frosty sparrow

frosty sparrow
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that’s exactly what i’m doing rn

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and yeah it’s for rasterizing line loops with rounded corners

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i think i found a solution that’s fast computationally

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use dot product to find angle between a and b

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compute the matrix that rotates a point clockwise angle/(n+1) degrees

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frosty sparrow
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and then rotate A around B n+1 times and plot each of those

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that way u only call sin and cos once each

bleak ridge
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Yeah that sounds like itd work

frosty sparrow
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yup

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ur solution works too but it’s a lot of heavy functions being called

lone heartBOT
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lime kiln
#

I am having hard time to understand vacuous proof.
From the book I am reading, it states that vacuous proof happens when the hypothesis of the implication is always false and from the example in the book kinds of throw me off a little...

The example in book:
"Prove that if n is an integer with 10 <=n<=15 which is a perfect square, then n is also a perfect cube"
According to the solution in book:
"There are no perfect squares n with 10<=n<=15 because 3^2 = 9 and 4^2 = 16. Hence the statement that n is an integer with 10<=n<=15 which is a perfect square is false. Consequently the statement to be proved is true for all integers"
but I can't find any number between 10<=n<=15 to have perfect cube?

so what I understand from vacuous proof is that if p is not true, ~P -> Q is true?
Can someone maybe explain it in super layman style for me to understand or tell me if what I understood is wrong etc.?

placid zinc
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If P is false, then P → Q is true

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As can be seen on the truth table for →

lime kiln
placid zinc
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Have you seen a truth table for → before?

lime kiln
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no

placid zinc
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Here's one from Google

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This is how → is defined

bleak ridge
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Thats one weird truth table

lime kiln
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so we can kinda say that

If P = I live in Paris
and Q = I live in France
this P->Q is true but at the same time

if P not true = I do not live in Paris
but Q = I live in France (because I can still live in france but just not Paris)
If so, then the statement above is proven by using vacuous proof?

placid zinc
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So you've detailed why → is not ⇔

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Which is also very important to get, but is not an example of vacuous truth

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Let's say:
P = You live on the moon
Q = You live on Jupiter
Then P → Q is true, because you don't live on the moon.

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If P is false, then P → Q is true

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Which is given by the bottom two rows

lime kiln
placid zinc
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Because P is false

lime kiln
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so as long P is false it doesn't matter if Q is true or false, it can be proven P→Q true by vacuous proof?

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thanks!

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dense compass
#

How would I go about evaluating this integral? Thank you

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atomic lodge
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Question 8

lone heartBOT
atomic lodge
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<@&286206848099549185>

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I found the derivative and set that equal to 0

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I got 30x-300 =0
X=10
So at 10 there’s a min or max

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I got a min because I got the profit As -1500

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i need to find max

lime kiln
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you need to 2nd derivative it to check for min or max.
d^2y/dx^2 < 0 is max

atomic lodge
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the second derivative is f"(x) =30

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it can't be negative anywhere

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@lime kiln

lime kiln
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if that's the case, from what I get from reading the question is that the profit of the company is P(x). the number of units sold can be from 0<=x<=40 and it wants the greatest profit of the company. After plotting the graph of this equation, the min point is a x=10 (where the company will have it's lowest profit which is 0) and the max can be infinite. And since we want the max profit within the number of items sold. I would substitute x=40 into p(x) to get my max profit for the company since the company sold at most 40 units

atomic lodge
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ya that's what i thought ok i don't what the correct answer is

lime kiln
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oh wait sorry (min profit would be -1500)

atomic lodge
lime kiln
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substitute*

atomic lodge
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okok

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thanks

lone heartBOT
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alpine sable
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hi

lone heartBOT
alpine sable
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help pls

atomic lodge
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X+Y=34

alpine sable
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why

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i don’t understand the equation

atomic lodge
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Take the number of $5 as x and $10 as Y

alpine sable
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oh ok

atomic lodge
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It is saying there are a total of 34 notes (only 5 and 10 dollar notes)

alpine sable
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o

atomic lodge
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The other equation would be 5x+10Y =235

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One is telling u the value the other is telling u the number of notes

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Solve both the solutions by substituting

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U will get ur answer

alpine sable
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is x 21

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y is 13

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okay got it

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.close

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minor yacht
#

Hi, im trying to find what this topic is called

minor yacht
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and, if you can also suggest videos for this topic that would be great

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@minor yacht Has your question been resolved?

minor yacht
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<@&286206848099549185>

remote heron
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looks like multivar?

minor yacht
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What is the specific topic?

remote heron
minor yacht
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That is kinda broad, im looking for the specific topic. Still, thanks

knotty sleet
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Isn't it just geometry

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Vectors and geometry

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Polar coordinates

minor yacht
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yea that is in the scope of that, but what I want to know is the specific topic for this.

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maybe im wrong lol

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what i mean is that how can i know what i have to do for this, like do i use dot product or cross product and to what unit vector do I have to use dot/cross product

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^what is this topic called(if there is a specific topic)

knotty sleet
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I think it's just general problem solving in geometry

minor yacht
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Its in my vector analysis class, so i dont think its in ggeometry

knotty sleet
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You should be able to do things like this with a good grasp of resolving vectors and different coordinate systems

minor yacht
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but it can probably be solved through geometry as well

knotty sleet
minor yacht
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I tried but its not really helping that much

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hence im trying to find videos but i dont know what topic this is to search lol

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if you can suggest videos, i'll really appreciate it

knotty sleet
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I guess you've tried searching the name of your class

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Vector analysis

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Perhaps search up spherical coordinates

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Because this uses it

minor yacht
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yes, i tried but I could not find something that answers a similar question to this

knotty sleet
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Unfortunately idrk video resources for university material

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Oh 😰

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Then probably just do something else and find a chance to ask a friend/professor?

minor yacht
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most video resources just tackles the basic, converting, gradients, etc

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ill try but maybe someone here knows

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ima repost my question so people can see

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Hi, im trying to find what this topic is called

visual iris
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Maybe Tangent, Normal, and Binormal Vectors?

frosty sparrow
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probably polar coordinates too

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fresh tide
#

anyone know why this isn’t right?

lone heartBOT
fresh tide
raw shard
#

u = 9t+5, du = 9t dt, (1/9)du = dt \ $\frac{1}{9} \cdot \int u^{2.4} \dd{u}$

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@fresh tide did you do this

ocean sealBOT
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quantum

fresh tide
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yes

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did i out that in for an answer or did i do that step

raw shard
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well your coefficient is wrong

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1/9 = 0.1111111…

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either way it should be kept as a fraction

fresh tide
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it says 1/9 is wrong too lol

raw shard
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,w integral of (9t+5)^(2.4)

raw shard
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wow

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ignore that i guess

fresh tide
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lol

raw shard
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wolfram alpha is drunk

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anyways, (1/9)*(9t+5)^3.4 + C is correct

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oh darn wait

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i’m so dumb

fresh tide
raw shard
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i forgot the integral power rule

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(1/9)(10/34)*(9t+5)^3.4 + C

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(10/306)*(9t+5)^3.4 + C

fresh tide
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boom

raw shard
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me dumb

fresh tide
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i think i did the calculation wrong

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thank you

raw shard
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no problem

fresh tide
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what’s command to clsoe

raw shard
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it’s .close

chrome salmon
raw shard
#

@fresh tide

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remember to close the channel

fresh tide
#

.close

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royal trench
lone heartBOT
royal trench
#

need help with this problem, i have tried doing ln1.8/0.024 but its not right?

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got from using continuous interest formula but not sure if i should be using another

chrome salmon
royal trench
chrome salmon
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It's outside ln

ocean sealBOT
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it's Sam

royal trench
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oh my friend helped me get it

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final answer was 24.8

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.close

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onyx hatch
#

how do i show that $f_s : \mathbb{C} \backslash {0} \to \mathbb{C}, ; f_s = \frac{\overline{z}}{|z|^s}$ is boundless for $s>1$

ocean sealBOT
alpine sable
#

How do I find the area of a cylinder?

#

Volume*

onyx hatch
#

My argument would have been: \
Let $z_0 \in \mathbb{C} \backslash {0}$ be arbitrary. Choose $(z_n){n \geq 1}$ such that $z_n := \frac{1}{n}$ and $z_n \to \infty$ for $n \to \infty$. Then, we have: $$f_s(z_n) = \frac{\overline{1/n}}{(1/n)^s} = \frac{1}{n} \cdot \left(\frac{1}{n}\right)^{-s} = \left(\frac{1}{n}\right)^{-(s-1)}$$
So, there exists a $q \geq 1$ such that $q = s-1$. It follows that $f_s(z_n) = \left(\frac{1}{n}\right)^{-q} = n^q$. Since $q \geq 1$, it obviously diverges. So we get: $\lim
{n \to \infty} n^q \neq z_0$. The limit cannot exist.

ocean sealBOT
onyx hatch
#

.close

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#
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potent rain
#

How can I know where the midline intersection and extrama should be for a sinusoidal equation? Khan academy wants me to differentiate between the points and depending on which one I use it is wrong -- what am I doing wrong?

supple tundra
#

The midline is the horizontal line that cuts through the middle of a periodic function right?

#

Do you know how to graph $\sin(x)$?

ocean sealBOT
#

azeem321

potent rain
#

I could probably do it easily if I tried

#

Are you suggesting that I graph the functions on paper before answering?

#

Could work

supple tundra
#

I'm not even sure what your question is tbh

#

do you need help graphing the function

#

or

potent rain
#

I'm not sure how I'm supposed to know unless like you say I graph multiple points

#

Idk which is the extrema point that's probably my main issue

#

From for example y = 3sin(1/3(x)) + 4 I know that one point is (0, 1)

supple tundra
#

You should think about graphing this function by starting with $f(x) = \sin(x)$ and then applying transformations to the graph

ocean sealBOT
#

azeem321

supple tundra
#

What does $f(\frac{\pi}{2}x)$ do to a graph?

ocean sealBOT
#

azeem321

supple tundra
#

= f(1.57x)

potent rain
#

I'm not sure

#

I will use Desmos

supple tundra
#

Nooo

potent rain
#

Ok

supple tundra
#

Think about it

#

for example

potent rain
#

Ok well it multiplies it by pi/2

#

So like u said it multiplies x by 1.57

supple tundra
#

Right. So under this transformation $sin(1) \mapsto sin(1.57)$

ocean sealBOT
#

azeem321

supple tundra
#

You get to points faster

potent rain
#

So y has to be at 1.57 or above

#

0 to 1.57 and above

supple tundra
#

That's just one of the transformations. So $f(\frac{\pi}{2}x)$ compresses the function. What happens when you do $f(\frac{\pi}{2}x) + 2$ ?

ocean sealBOT
#

azeem321

supple tundra
#

If you added 2 to $\sin(x)$ what would happen?

ocean sealBOT
#

azeem321

potent rain
#

It's minimum value would be 2

supple tundra
#

??

potent rain
#

3.57 for the first one

supple tundra
#

nope

potent rain
#

The y value

supple tundra
#

$-1\leq \sin(x) \leq 1$

ocean sealBOT
#

azeem321

supple tundra
#

$-1\leq \sin(\frac{\pi x}{2}) \leq 1$

ocean sealBOT
#

azeem321

supple tundra
#

$1\leq \sin(\frac{\pi x}{2}) + 2 \leq 3$

ocean sealBOT
#

azeem321

supple tundra
#

Do you get that so far?

potent rain
#

I'm trying

#

0 gets 1

#

I guess it makes sense for sin x

#

Yeah I got it

supple tundra
#

Just think about applying graph transformations to the basic graph one by one

potent rain
#

So like with -3cos(pi*x/6)-6 I can focus on cos(pix/6) first

supple tundra
#

$f(x) + a$ lifts the graph up if it's positive and down if it's negative. $f(x-a)$ moves the graph to the right if it's positive and to the left it's negative. $af(x)$ stretches the y coordinates if it's positive and greater than 1 and compresses the y coordinates if it's between 0 and 1. $f(ax)$ compresses the graph in the x direction

potent rain
#

Then do * -3 and -6

ocean sealBOT
#

azeem321

supple tundra
#

With $-3\cos(\frac{\pi x}{6})-6$. I would start by graphing $\cos(x)$

ocean sealBOT
#

azeem321

supple tundra
#

and then I would graph $\cos(\frac{\pi x}{6})$

ocean sealBOT
#

azeem321

supple tundra
#

and then I would do $-3\cos(\frac{\pi x}{6})$

ocean sealBOT
#

azeem321

supple tundra
#

and finally $-3\cos(\frac{\pi x}{6})-6$

ocean sealBOT
#

azeem321

potent rain
#

Ok

#

I'm gonna use a calculator lol

supple tundra
# potent rain Ok

Also, note $\frac{\pi}{6} \approx 0.5$ So instead of compressing the graph in the x direction, it would stretch it out

ocean sealBOT
#

azeem321

supple tundra
potent rain
#

Ok. It's just taking time to plot out these points.

lone heartBOT
#

@potent rain Has your question been resolved?

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alpine sable
#

Discrete Math

How many bit strings of length 10 have
a) exactly three 0s?

#

Why is it 10 C 3?

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#

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fringe robin
lone heartBOT
fringe robin
#

can anyone help

buoyant kayak
#

keep following the pattern?

fringe robin
#

bruh

#

no i dont think thats the method

cinder mantle
#

im just learnign this topic so dont take my advice to heart. But i think this involves finding the series sum. Looking at this im assuming it is a geometric sequence. to make sure check if t2/t1=t4/t3

#

i dont remember the formula series sum for a geometric sequence but u just have to use that formula and slap it in

#

ill try and see if i can solve it but i doubt it, since i as well am learning this cancer of a topic

#

@fringe robin

lone heartBOT
#

@fringe robin Has your question been resolved?

cinder mantle
#

soz

#

couldnt solve it

#

but i do know it would have something to do along the lines of what i have explained

#

that much im confident in

lone heartBOT
#
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alpine sable
#

Determine each rule below is a function or not with the given domain

T/F

f: R-> R
f(x) = f(x) = x+1 if x >= 0 and x-1 if x <= 10

It's F but I don't know why

vale wigeon
#

...is that the exact wording of the question?

#

or did you omit something you thought was unimportant but actually was?

#

@alpine sable

alpine sable
#

Sorry I missed some parts

#

editing it

vale wigeon
#

can you maybe send a picture

#

it's a bit inconvenient to read like this

alpine sable
#

E

vale wigeon
#

,rccw

ocean sealBOT
vale wigeon
#

okay, so you think part e is a valid function definition, yes?

alpine sable
#

it's false

#

I got it wrong

vale wigeon
#

the definition contradicts itself for inputs between 0 and 10

#

for example, f(5) should be 6 according to the first piece but 4 according to the second

#

can't be both at once

alpine sable
#

ye

#

yea

#

I'm confused about that part

vale wigeon
#

this is the reason why it's not a valid function definition.

alpine sable
#

Oh

#

that makes a invalid function

#

.close

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#
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muted briar
#

Hello, I'm trying to understand basics statistics, the F value in linear regression - https://youtu.be/nk2CQITm_eo?t=1089 in this example here he says that F equals variation in mouse size explained by weight divided by variation in mouse size not explained by weight and then the equation is {[sumOfSquares(mean)-SumOfSquares(fit)]/(pfit-pmean)}/[SS(fit)/(n-pfit)] but im confused, should it be something like [sumOfSquares(mean)-SumOfSquares(fit)]/n instead of sumOfSquares(mean)-SumOfSquares(fit), because now its not variation in mouse size explained by weight but sum of squares in mouse size explained by weight?

The concepts behind linear regression, fitting a line to data with least squares and R-squared, are pretty darn simple, so let's get down to it! NOTE: This StatQuest comes with a companion video for how to do linear regression in R: https://youtu.be/u1cc1r_Y7M0
You can also find example code at the StatQuest github: https://github.com/StatQuest/...

▶ Play video
muted briar
#

where did the /n go in the numerator in the F value

lone heartBOT
#

@muted briar Has your question been resolved?

lone heartBOT
#

@muted briar Has your question been resolved?

lone heartBOT
#

@muted briar Has your question been resolved?

lone heartBOT
#

@muted briar Has your question been resolved?

lone heartBOT
#
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unkempt umbra
#

How would you show this?
these are properties of a subspace

α) 0 ∈ S;
β) ∀x, y ∈ S , x + y ∈ S;
γ) ∀k ∈ K , ∀x ∈ S , kx ∈ S

But how would they apply here?
Let's first take only Re - even functions

x+y would be g o f ?

glass lichen
#

they haven't defined explicitly vector addition and scaling, so it's assumed the standard operations

unkempt umbra
#

ok, and how would I prove that f+g is in Re if f, g ∈ Re?

glass lichen
#

The definition of a function being even and or odd

#

you're showing that the sum of even functions is even.

unkempt umbra
#
well we know that 
f(-x) = -f(x)  (1)
and
g(-x) = -g(x)  (2)

then we have to show that 
f(-x) + g(-x) = -(f(x) + g(x))  
(1), (2) -> f(-x) + g(-x) = -f(x) - g(x) = -(f(x) + g(x))

Is this alright?

chrome salmon
#

Ok

#

You can write (f+g)(x)

unkempt umbra
#
f(-x) = -f(x)  (1)
(1) -> k * f(-x) = -k * f(x)
#

does this prove the third property?

chrome salmon
#

Ok

unkempt umbra
#

oh i'm sorry

#

the proof above is for odd functions

#

not even

chrome salmon
#

Yes

unkempt umbra
#

but it's pretty similar for even i think

glass lichen
#

yes, $(f+g)(-x)=f(-x)+g(-x)=-f(x)-g(x)=-(f+g)(x)$

ocean sealBOT
glass lichen
#

so odd functions are closed under addition

unkempt umbra
#

(f+g)(-x) = f(x) + g(x) = (f+g)(x)

#

this is for even

glass lichen
#

yes.

unkempt umbra
#
f(-x) = f(x)  (1)
(1) -> k * f(-x) = k * f(x)
#

also 0 has to be an element of both Re and Ro

glass lichen
#

is it?

unkempt umbra
#

it is
i'm thinking about how to prove that

glass lichen
#

just show the 0 function is odd and even.

unkempt umbra
#

so it's enought to say that

f(x) = 0
f(-x) = -f(x) = -0 = 0 in Ro
and
f(x) = 0
f(-x) = f(x)= 0 in Re
```?
glass lichen
#

yes, but poor proof structure

#

$O(x):=0 \ O(-x)=0=\pm 0=\pm O(x)$

ocean sealBOT
glass lichen
#

you want 0 in the middle of the string of equality not at the end

#

you assumed it was odd and even in your proof

unkempt umbra
#

yes you're right

#
R^Ro ⊕ R^Re = {f + g | f ∈ R^Ro, g ∈ R^Re }

And we have to show that

R^Ro ⊕ R^Re = R^R
glass lichen
#

yep

unkempt umbra
#

Well I'm not exactly sure how to start this proof
Could you give me a hint?

glass lichen
#

It's probably a shit hint if you don't know sinh and cosh but:

Take inspiration from the exponential definition of sinh and cosh

#

$\sinh(x):=\frac{e^x-e^{-x}}{2}\ \cosh(x):=\frac{e^x+e^{-x}}{2}$

ocean sealBOT
glass lichen
#

alternatively, you want to somehow introduce f(-x) in somehow to use even and odd proprties

#

(also note that the sum of those is e^x)

unkempt umbra
#

i think i have seen something like this a few years ago in highschool
i'll try

#

$\g(x) = \frac{f(x) + f(-x)}{2}
\
h(x) = \frac{f(x) - f(-x)}{2}
\
g(x) + h(x) = \frac{f(x) + f(-x) + f(x) - f(-x)}{2}
\
g(x) + h(x) = \frac{2 f(x)}{2}
\
g(x) + h(x) = f(x)
\\\
g(x) = \frac{f(x) + f(-x)}{2} = \frac{f(-x) + f(x)}{2} = g(-x) \rightarrow even
\\\
h(x) = \frac{f(x) - f(-x)}{2} = -frac{f(-x) + f(x)}{2} = -h(x) \rightarrow odd$

ocean sealBOT
unkempt umbra
#

basically f(x) is a sum of an even and an odd function

glass lichen
unkempt umbra
#

and does this directly imply that R^Ro ⊕ R^Re = R^R?

glass lichen
#

yes, as long as f is in R^R

#

cause you've shown f is a sum of an odd function and an even function

unkempt umbra
#

alright

#

thank you for your help

chrome salmon
#

Close

unkempt umbra
#

.close

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thorny sentinel
#

does a real valued function of one real variable exist whose antiderivative is a complex velued function?

thorny sentinel
#

I've done some googling but didn't find anything (probably due to my mathematical immaturity :/ )

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#

@thorny sentinel Has your question been resolved?

thorny sentinel
#

<@&286206848099549185>

lone heartBOT
#

@thorny sentinel Has your question been resolved?

velvet magnet
#

¯\_(ツ)_/¯

thorny sentinel
velvet magnet
#

Nah im not even in college lol

thorny sentinel
#

cuz I suppose you would've came across one if you did and it does exist and it has been discovered

#

oh

#

ok

#

guess I'll just wait for someone with more insight 🙂

lone heartBOT
#

@thorny sentinel Has your question been resolved?

dark lichen
#

Hi

#

@thorny sentinel

#

Could you please state your question?

thorny sentinel
#

hope it's not a stupid question

dark lichen
#

I believe yes

#

Does anti derivative mean partial derivative?

glass lichen
glass lichen
#

you can plug complex numbers into 0.5x^2+C.

thorny sentinel
glass lichen
#

sine and cosine can be written as complex functions.

thorny sentinel
#

but they have a real antiderivative

#

I'm looking for a function that doesn't have one

glass lichen
#

Yeah, which can be written as a complex function.

thorny sentinel
glass lichen
#

what are you defining as a complex valued function..?

thorny sentinel
#

A function that maps some real numbers to complex

#

i suppose

glass lichen
#

then no

#

cause you're not satisfied with the fact R to R functions are a subset of C to C functions.

thorny sentinel
#

oh right, by complex i mean it has nonzero imaginary unit

glass lichen
#

Then no

thorny sentinel
#

Is there a proof or a reference you can give? or at least an intuitive explanation

glass lichen
#

integration maintains domain I suppose.

thorny sentinel
#

Good enough for my purposes

#

i suppose

#

thanks

#

.close

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misty bobcat
#

Decide if it's possible to find four vectors in $\mathbb{R}^4$ such that, every 3 of them are basis.

ocean sealBOT
#

Michal

misty bobcat
#

Any ideas ?

glass lichen
#

is it possible or not?

#

what do you think?

misty bobcat
#

I think yes

#

0,1,1
1,0,1
1,1,0
1,1,1

#

What do you think about it ?

#

@glass lichen

glass lichen
#

those arent R^4 vectors

misty bobcat
#

Sorry, it should be R^3

#

My bad

glass lichen
#

then yes, as long as each 3-vector subset is independent

misty bobcat
#

Ok thanks

#

So if i choose three of them, always it spans entire R^3 space ?

glass lichen
#

it should by extremal properties of bases

misty bobcat
#

Ok thanks

#

.close

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gaunt eagle
lone heartBOT
gaunt eagle
#

Hello! So this question is from calculus a full cource but I dont get how they come to the conclusion that B=0

#

I get everything else though!

bleak dune
#

so your factors are (A+1) and (x(A-1) + B)

#

if either of those is 0, then that whole side of the equation becomes 0

#

(if A+1 = 0, then it becomes 0*[x(A-1) + B] which is 0)

gaunt eagle
#

yup

bleak dune
#

right, so for the factor on the right, it's [x(A-1) + B] = 0

#

So it has to be that x(A-1) = -B no matter what x is. The only way for that to happen is if x(A-1) and B are both worth 0

#

Let's say you pick any other value for A. Let's say -2. The factor becomes -3x + B = 0. But you can't make it so B is always equal to -3x, because B is a constant.

#

So it doesn't work.

#

the only time that right hand factor will be zero is when A = -1 and B = 0

#

does that help?

gaunt eagle
#

but

#

cant B be another number?

#

since the whole term will become 0 anyways when A=-1?

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#

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raven ravine
#

Hello I’m having trouble isolating my variables to get the inverse

raven ravine
#

this has been my work so far

#

ignore the -5 ^^

buoyant kayak
#

so what do you think you should do next

#

wait it's a take home test

#

can't get help with tests here

raven ravine
#

no my teacher said it was review

buoyant kayak
#

it says take home test at the top

raven ravine
#

Ik but he said it was a review. I promise it’s not a test.

#

We have an exam next Wednesday

#

I understand the confusion and I apologize for how this may look. Can you close my ticket as completed.

#

.close

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lost steeple
#

How do I find the derivative of log(3x-2)?

lost steeple
#

According to my notes, it's g'(x) / g(x) * ln(b)

#

Which I got 3 / (3x-2)*ln(10)

#

But using the derivative calculator it's not right

#

How do I do it

jagged imp
#

The calculator assumes its base is e, and your answer assumes its base is 10

#

so it depends on that

lost steeple
#

log bbase is 1-

#

10

#

Is my answer correct?

jagged imp
#

yes

#

well actually, it depends on if your answer is 3/((3x-2)ln10) or 3/(3x-2) *ln10

#

Should be the former(the log is in the denominator)

lone heartBOT
#

@lost steeple Has your question been resolved?

#
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cold meadow
#

if i have

lone heartBOT
raw shard
#

no

#

close the channel

vague coral
#

no

cold meadow
#

why

raw shard
#

this is basically spam

cold meadow
#

i mis said it wrong

#

I said it wrong

#

wait

#

so if i have the odds, 3133507531 out of 436116003068178632599586304885865102436987283273192588087066946205825385420102245537617641171508064231363006853389201952225629937253532766998346708022315458543404066186915809029438078922052852453720811267502691138577239348756804955313693393091406303393978608038048294775593159201377364139187142305434603252709617151318958922901417601677040658907901408937709530384849660728157676437361951488873238454079633326062998564370475129597220298716911739158299214865235291416480348618758676919027696256066573122899301892912081375412160180698274455765997411725112824776559729034126511125728785207316456433746195093026529168420804699808556231371820824328024241019054519605469721555033733292097536/6197148516394364188900141323882322297210558701995146720297131484855101557855486731958221825570944947984004858553140186641155182016082966859736962550177180088600405321238825249746403835469727033342501800712896634341355449588496565230819852486507103432027694702173423912538079766299114717526424477880616639449302766419689877623466381205865605118390274355471509815278332251971759244543740352243076811277717664865760571719052087465244804777251295251995674217073974490490639368917793497383548456310727391232146480195472325811180553427557484142696840113044630459874629946903509481288793101524546602637214862483656004358674999005683914545225086663429140282193350054143291262884451455852063961426683890652699785527976797456599012104868536777488904438653913152719206119693088299602007397720839957389279772575408178106779022036761970796031083638898838300999211395119392678116082151174675257415694403682741632963982317824529718557167903433530955641359259898743752340961013280091956109688607349893209675381881203380524958393734988046719982595235111430847956368856989676534079417326438466595922976484817758530826916589148548056446877738990

#

whats the percent

#

Its not spam its a real question i swear

raw shard
#

0

vague coral
#

<@&268886789983436800>

raw shard
#

now go away

cold meadow
#

how

#

what is your problem

#

i need help

#

why are you so butthurt because i asked for help with a big number

#

.close

lone heartBOT
#
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rain crypt
#

Not sure how to start? A unit length stick is broken into two pieces at a uniformly distributed random point. Then the left
piece is broken again into two pieces at a uniformly distributed random point, and one takes the left
one of the resulting two. Find the expectation of its length.

lone heartBOT
#

@rain crypt Has your question been resolved?

lone heartBOT
#

@rain crypt Has your question been resolved?

bleak dune
#

are you looking for the average length of the left most stick?

rain crypt
#

yes

bleak dune
#

so i'm not sure how you're supposed to go about this, but I would start by adding up all possible values of the length of the stick after the first break, then divide that by the amount of possible values

#

and then do that again for the second break

#

have you seen integrals?

rain crypt
#

yes

bleak dune
#

do you know how to add up all the possible lengths of the left stick?

rain crypt
#

not really kind of abstract to me

bleak dune
#

it's basically just an integral in this case

#

varies from 0 to u (u being the length of a unit stick)

rain crypt
#

random experiment consists in tossing three fair coins. If the result is three heads or three tails,
it is considered to be a success; any other result is a failure. This experiment is repeated 1000 times.
Find the expectation of the number of successes.

#

what about this one ?

bleak dune
#

what are the chances one of the experiments succeeds?

rain crypt
#

1/2

bleak dune
#

not quite

#

the first coin can land either way, sure, but there are two other coins that need to land on the same side

rain crypt
#

oh I meant 1/8

bleak dune
#

not quite 1/8 either.

#

the first coin can land on whatever side it wants

rain crypt
#

the first coin is 1/2 right?

bleak dune
#

it can be either heads or tails

#

as long as the other two land on the same thing as the first one

rain crypt
#

.close

lone heartBOT
#
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alpine sable
lone heartBOT
alpine sable
#

Gotta need some help right here at let's try

#

I do not understand the question at all on how to solve it

#

.close

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radiant lantern
#

Hello I need help

lone heartBOT
radiant lantern
#

How can I find the equation of this quadratic question ?

bleak dune
#

alright, what are the parameters you're looking for?

radiant lantern
#

I really don’t know, because im not sure what form is the best for this problem

#

Like general factorised or cannonic

bleak dune
#

Well what are the pros and cons

radiant lantern
#

General= i got c, factorised = i got the zeros of the function and cannonic: I got h,k

#

But im not sure how to find cannonic because I dont have h and k

bleak dune
#

how do you find the h and k usually?

radiant lantern
#

And also I dont have the zeros of the function so I can’t use factorised

radiant lantern
#

But I don’t understand how to find it on a table of number like this

alpine sable
#

try starting with the equation ax^2+bx+c and putting in the information that can be found from the table

radiant lantern
#

I can only get the c

#

And one random point

#

But I still can’t find a and b

#

Like c is 12

alpine sable
#

there are two ways you can do this

#

one is a bit longer but more consistent

radiant lantern
#

How ?

alpine sable
#

ok, well let's start from the very beginning

radiant lantern
#

What do I need to do ?

alpine sable
#

the first logical step would be to find the difference between each point subsequently

#

so on a scratch sheet of paper, remember that the table does skip a few numbers

radiant lantern
#

Like to find the reflexion axis ?

bleak dune
#

you know

#

in this particular case

#

it might be easier to place the points on a graph and see what it looks like

radiant lantern
#

But like there is no algebric way?

#

Because im really bad with graphs

bleak dune
#

there is an algebraic way, but I'm not sure you've seen it yet

radiant lantern
#

Could you just explain to me, maybe ive seen it

alpine sable
#

the algebraic way is to find 2nd difference

radiant lantern
#

Like doing (0+4)/2 ?

#

I think it might give the h

#

Because 0 and 4 give the value of 12

alpine sable
#

if you don't want to graph

#

you have to find 2nd difference

#

and solve with a system of 3 linear equations

bleak dune
#

well if you consider Ax^2 + Bx + C = y, then you could just make three equations and treat it like a système d'équations linéaires

alpine sable
bleak dune
#

¯_(ツ)_/¯

radiant lantern
#

Like when you substitute the variables to find others

bleak dune
#

yep

radiant lantern
#

Oh yeah I see ok I will try

bleak dune
#

or you could say that this looks very much like a parabola

radiant lantern
#

And so I do this for a in b right ?

bleak dune
#

and that it has the same y value in x= 0 and x = 4

#

so the reflection axis is probably straight in the middle

bleak dune
radiant lantern
#

Wait but when I do it, a or b cancel out so I can’t find them

celest root
#

is this taken....

radiant lantern
#

Yes but you can take 10

celest root
#

thank your kind sir

radiant lantern
#

No problem

bleak dune
radiant lantern
#

2 and -4

#

For x and y in respect order

#

I find that a=(-8-b)/2

#

And when I replace it in -4=4a+2b+12 it cancel out

bleak dune
#

you need to use a different point

#

you have 2 unknown variables

#

that means you need to use two different equations to solve it

#

so you need two different coordinate pairs

radiant lantern
#

Oh like the other method of substracting an equation from an other ?

bleak dune
#

ye

radiant lantern
#

Ok I will try

bleak dune
#

or substitution

#

whichever you like better

radiant lantern
#

Well substitution didn’t worked

#

That’s what I used when all the variables canceled out

#

Well thank you for your help

#

I will try it by myself

#

.close

lone heartBOT
#
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nocturne beacon
lone heartBOT
buoyant kayak
#

do you have work?

#

@nocturne beacon

nocturne beacon
#

I took this a while ago so not at the moment

#

I can start something

#

I’ll share it in a few

buoyant kayak
#

alright

dense niche
#

maybe 6 I am not sure

buoyant kayak
#

don't do people's work for them, and "6" is not a radius of convergence

lone heartBOT
#

@nocturne beacon Has your question been resolved?

nocturne beacon
#

6 was actually the correct answer

#

.close

lone heartBOT
#
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wary stream
#

What did you try?

#

I believe what you need to do instead, use the rational root theorem, find a root of that expression, then use long division

#

Have you done polynomial long division before?

#

I suggest watching some videos

lone heartBOT
#

@alpine sable Has your question been resolved?

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alpine sable
#

I got a question

lone heartBOT
alpine sable
#

what kind of problem is this?

velvet magnet
#

long division

alpine sable
#

okay

#

thank yoy

#

you

#

.close

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#
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normal chasm
lone heartBOT
normal chasm
#

Can someone explain how i do this? Im kinda confused

velvet magnet
#

They r asking for what values of x is y=0

normal chasm
#

What

velvet magnet
#

Lemme try and phrase it better

#

The question that they are asking is

#

"What values of x can you substitute so that y will become equal to 0?"

normal chasm
#

Ohhhh

#

how do i find the substitutes of x

velvet magnet
#

Theres 3 factors on the rhs

#

We know that y will become 0 if at least one of these factors is 0

#

5 con never be zero for any value of x

#

Can (30-1.5x) be 0 for some value of x?

normal chasm
#

Yes i think?

velvet magnet
#

What is that value?

normal chasm
#

Can i guess

#

20?

#

I dont know

velvet magnet
#

Equate the factor to 0 and find out

#

Yes its 20

#

Similarly do it for 12+2x

normal chasm
#

Okok

#

Thanks

normal chasm
#

Sorry im a bit confused

velvet magnet
#

12+2x=0

velvet magnet
normal chasm
#

What about the 5 at the start? Do i do anything to that?

velvet magnet
#

U cant because 5 cannot become 0 for any value of x

normal chasm
#

Ohhhhh

#

So i just keep it as 5?

velvet magnet
#

Yes

normal chasm
#

Okay. I got it, thanks!!! :D

velvet magnet
#

Glad i could help 😀

lone heartBOT
#

@normal chasm Has your question been resolved?

lone heartBOT
#
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uncut frost
#

I have a couple questions about vectors.

  1. If you are told to write a vector in i+j+k form, are you just supposed to calculate the unit vector version of that? For example, if the components are <3,4>, are you supposed to write the vector in ijk form like 3/5i+ 4/5k?
uncut frost
#
  1. If you are given a vector in ijk form, are you supposed to assume that it is a unit vector?
pearl jasper
#
  1. if the components are <3, 4>, i think you're supposed to write it as 3i + 4j
lone heartBOT
#

@uncut frost Has your question been resolved?

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#
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manic pike
#

question: find the length of XY

lone heartBOT
manic pike
#

I know pythagoras theorem, how do I use it and solve the question?

copper pond
#

First you can use the pythagorean theorem to find XB, and see if you can work it out from there.

#

You can find XB by first finding AB and then subtracting 8cm.

glad tide
#

Once you've gotten XB, you can work out XC

manic pike
#

got both XB and XC

glad tide
#

hmm

manic pike
#

ohh its fine I got it

#

tysm

glad tide
#

np

#

dont forget to use .close

manic pike
#

.close

lone heartBOT
#
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proven hedge
#

someone help im stuck for abt 3 hrs already

proven hedge
#

this is the problem

lone heartBOT
#

@proven hedge Has your question been resolved?

proven hedge
#

<@&286206848099549185>

#

i need to use the ping because my problem was already here for abt 20 mins

#

<@&286206848099549185>

alpine sable
#

stop pinging

lone heartBOT
#

@proven hedge Has your question been resolved?

lone heartBOT
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lethal dock
#

arranging an algebraic equation in an ascending order in the regards of y, it will start from the smallest variation of y to the biggest and if there is a variation of x there, will it come at the end as we are doing it in the regards of y?

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#

@lethal dock Has your question been resolved?

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alpine sable
#

in this-then equations when we are trying to solve: If P, Then Find Q

alpine sable
#

then we minipulate P so that it becomes Q=(something)

smoky jacinth
#

Can someone explain how to solve this...?

alpine sable
#

now could a this-then equation be solved like this too

inner pine
#

Hello

alpine sable
#

where we manipulate P so that, it looks like a part of Q but not the whole Q; Q(piece)=(something)

#

and we take that (something) that the Piece of Q is equal to. and plug it into the original Q to find the answer

#

for ex; if 153=2(x+x)y, then find 2y(2x)-193

#

rewrite; 153=2y(2x), then plug 153 into 2y(2x)-193

#

153-193

#

=-40

#

TLDR; if we have a; If P, then find Q equation

#

so we take P and do we make one side of the P completely look like Q, Or do we can just make one side of p just equal to partially look like q

#

<@&286206848099549185>

#

is anyone there?

#

OR, if the problem says If (p), then find (q), then we have to make one side of p completely look like q

#

and , if the problem says, if (p), then find the value of (q), then we can make one side of p look like a part of q, and then plug the value into the original Q to find the value

#

TLDR AGAIN: IS THERE A DIFFERENCE BETWEEN "IF P, THEN FIND Q" and "IF P, THEN FIND THE VALUE OF Q"

#

.close

lone heartBOT
#
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shadow stream
#

How would I approach this problem? I'm a little clueless about it sad

lone heartBOT
#

@shadow stream Has your question been resolved?

gentle flame
#

. Find the longest pole length that can be put in a room of 10m ×5m

wth? is this question right?

chrome salmon
shadow stream
#

uh idk if i have the wrong understanding but if its continuous then its a pdf right?

#

i believe it is continuous between 2 and 3?

chrome salmon
#

Yeah typo from me

shadow stream
#

it should be a pdf

shadow stream
#

im not sure how to approach this question B_Dead

chrome salmon
shadow stream
#

x = y^2

#

?

#

and plug it in and try to integrate?

shadow stream