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Yes
Wait
Let me check them first
Yes I think first three are subspaces need to think about 4th
I mean
Arent the first 3 easy to say? I think I am missing something
isnt it just like this one
and also for p(0)
Yes
All go on the same line
The last one won't be
Not gonna think bout it yet
what do you mean?
do they mean it must be either 3 or 1?
why do the point out that {0} is in it?
3 or 1?
Idk what that {0} is for 
O.o
Is that 0 in R or some Rⁿ
Someone asked my teacher
Yes what
he said:
R4[x] is a vector space, which is why there exists a unique vector which will be additive identity and it will be 0v.
That doesnt say anything...
xD
Zero polynomial but that's already done
So here in last problem
Since they gave degree is odd
We won't get zero polynomial in set that's why they added union of {0}
We will get x,x³,x⁵, and such polynomiqls
In all other cases they gave p(a)=0 that means p(x)=0 was one case too but here they gave
"Polynomial with odd degree"
Is some constant like c is polynomial of odd degree?
Pls ranz you need to see the difference in both sets
I see that it is an odd degree...
Then a constant won't be in the last set
then they had to put {0} inside
Yup
so it wont be easy xD
In other cases we could have constant polynomials
yeah
In here we can have degree 1,3,5,...
you mean as counter example right?
if they wouldnt have put the {0} in
we could just say that {0} is not a part of p this time because it does not have a odd degree
No need
oh really?
What two cases?
but how do you know from what degree it will be?
it could be x^3 + 3x^2 -2x^1 and also 2x^3
or
-2x^1
itselft
Let degree of p be m and degree of q be n
Then degree of p+q =< max{m,n}
Let me think of this example
Say p=x³+2x²+x and q=-x³+x²+x
When we add both we get p+q=3x²+2x
Which is of even degree
Oh well we found a counter then
That didn't came to me before
Are you following?
yeah
when the odd degree canceles it self
it is a counter example
that it right yeah..
when proving (c)
do I have to show 3 cases?
3 cases for what
Doing p(-2)=0 separately and p(0) separately is enough
do you mean like b?
See p such that p(-2)=0 and p(0)=0 have factor (x+2)x
Right
If you show separately that p with factor x+2 and p with factor x form subspace then it's enough
Yes
once for -2 and once for 0
Doing it in 3 cases as you said will be right too but there's no need to go the hard way
Yes
but that is exactly what I did in (b)
was I wrong there then?
usually they dont let us do the exact same things..
The and or difference
You see in 2nd one you need polynomial with zeros -2,0
Polynomials like x(x-2)
But in 3rd one
You can have polynomials like
x , x-2 , x(x-2)
I do see the difference
which is applicable because of distributivity we can factor x out and it will be in the form of x(x......number)
Ranz I think you should analyze the rest yourself
First try it properly and if you have any more doubt then ask it
ok
Close until then and come back in case of doubt
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how to integrate this by parts?
@lethal lichen Has your question been resolved?
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Can someone help me with this one?
I like half understand it, solving these has always been somewhat ambiguous to me
<@&286206848099549185>
Mb lmao
In a similar vein, I don't feel like I really understand these either
I understand how to get the fundamental set of solutions for all of them, but I don't understand how that translates to a particular solution and how to use the right side of the equation
See "method of undetermined coefficients"
That would be for determining the actual A, B, C values no?
I just want to know how to get the equation shown as the answer
Okay now I should be able to ping lmao
<@&286206848099549185> ping me when you can help
I'm sure you guys are busy 👍
@scarlet mango Has your question been resolved?
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There is a distinguishable professors and b distinguishable exercises to grade. There is more professors than exercises. How many ways are there to distribute the grading assuming every exercise is graded by exactly one lecturer and each lecturer grades at most one exercise?
@short pumice Has your question been resolved?
Do you think I picked the right answer for this question ?
because if there is a professors then they can grade a! exercises but since there is not that many exercises we have to divide by (a-b)!?
do my answer now would be the 6th option
@short pumice Has your question been resolved?
<@&286206848099549185>
Your logic checks out. With b different exercises, the first one can be graded by a different professors. The second one could be graded by a-1, third by a-2, and so on. There would be a-b professors who don't grade an exercise. a!/(a-b)! would therefore be correct.
Example: 5 professors, 3 tests.
First test: 5 possible professors. Second: 4. Third: 3.
If we multiply them together to get the number of permutations, we get 5*4*3 = 5!/(5-3)! = 60
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green line follows the curve of a circle
@frosty sparrow Has your question been resolved?
no
@frosty sparrow Has your question been resolved?
I mean theres many ways you could go about doing that
You could create n angles from arctan(c.y/c.x) to arctan(a.y/a.x) for example
Then just (|c-b| cos(ang),|c-b| sin(ang)) for each angle
Where |c-b| is the distance between c and b
That comes with its own problems though
Theres prob a better way to do it with complex numbers
Do you have an application for this problem? @frosty sparrow
that’s exactly what i’m doing rn
and yeah it’s for rasterizing line loops with rounded corners
i think i found a solution that’s fast computationally
use dot product to find angle between a and b
compute the matrix that rotates a point clockwise angle/(n+1) degrees
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and then rotate A around B n+1 times and plot each of those
that way u only call sin and cos once each
Yeah that sounds like itd work
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I am having hard time to understand vacuous proof.
From the book I am reading, it states that vacuous proof happens when the hypothesis of the implication is always false and from the example in the book kinds of throw me off a little...
The example in book:
"Prove that if n is an integer with 10 <=n<=15 which is a perfect square, then n is also a perfect cube"
According to the solution in book:
"There are no perfect squares n with 10<=n<=15 because 3^2 = 9 and 4^2 = 16. Hence the statement that n is an integer with 10<=n<=15 which is a perfect square is false. Consequently the statement to be proved is true for all integers"
but I can't find any number between 10<=n<=15 to have perfect cube?
so what I understand from vacuous proof is that if p is not true, ~P -> Q is true?
Can someone maybe explain it in super layman style for me to understand or tell me if what I understood is wrong etc.?
uhh meaning? sweat
Have you seen a truth table for → before?
no
Thats one weird truth table
so we can kinda say that
If P = I live in Paris
and Q = I live in France
this P->Q is true but at the same time
if P not true = I do not live in Paris
but Q = I live in France (because I can still live in france but just not Paris)
If so, then the statement above is proven by using vacuous proof?
So you've detailed why → is not ⇔
Which is also very important to get, but is not an example of vacuous truth
Let's say:
P = You live on the moon
Q = You live on Jupiter
Then P → Q is true, because you don't live on the moon.
If P is false, then P → Q is true
Which is given by the bottom two rows
so like the example given by the book. the P is false but isn't the Q also false? how would that fall under vacuous proof? 
Because P is false
so as long P is false it doesn't matter if Q is true or false, it can be proven P→Q true by vacuous proof?
thanks!
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How would I go about evaluating this integral? Thank you
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Question 8
<@&286206848099549185>
I found the derivative and set that equal to 0
I got 30x-300 =0
X=10
So at 10 there’s a min or max
I got a min because I got the profit As -1500
i need to find max
you need to 2nd derivative it to check for min or max.
d^2y/dx^2 < 0 is max
if that's the case, from what I get from reading the question is that the profit of the company is P(x). the number of units sold can be from 0<=x<=40 and it wants the greatest profit of the company. After plotting the graph of this equation, the min point is a x=10 (where the company will have it's lowest profit which is 0) and the max can be infinite. And since we want the max profit within the number of items sold. I would substitute x=40 into p(x) to get my max profit for the company since the company sold at most 40 units
ya that's what i thought ok i don't what the correct answer is
oh wait sorry (min profit would be -1500)
yes
sub 40 into the equation and you will get an answer which is also the answer option
substitute*
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hi
X+Y=34
Take the number of $5 as x and $10 as Y
oh ok
It is saying there are a total of 34 notes (only 5 and 10 dollar notes)
o
The other equation would be 5x+10Y =235
One is telling u the value the other is telling u the number of notes
Solve both the solutions by substituting
U will get ur answer
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Hi, im trying to find what this topic is called
and, if you can also suggest videos for this topic that would be great
@minor yacht Has your question been resolved?
<@&286206848099549185>
looks like multivar?
What is the specific topic?
im not sure
maybe calculus in different coordinate systems
That is kinda broad, im looking for the specific topic. Still, thanks
yea that is in the scope of that, but what I want to know is the specific topic for this.
maybe im wrong lol
what i mean is that how can i know what i have to do for this, like do i use dot product or cross product and to what unit vector do I have to use dot/cross product
^what is this topic called(if there is a specific topic)
I think it's just general problem solving in geometry
Its in my vector analysis class, so i dont think its in ggeometry
You should be able to do things like this with a good grasp of resolving vectors and different coordinate systems
but it can probably be solved through geometry as well
Oh well could you just review the materials from class?
I tried but its not really helping that much
hence im trying to find videos but i dont know what topic this is to search lol
if you can suggest videos, i'll really appreciate it
I guess you've tried searching the name of your class
Vector analysis
Perhaps search up spherical coordinates
Because this uses it
yes, i tried but I could not find something that answers a similar question to this
Unfortunately idrk video resources for university material
Oh 😰
Then probably just do something else and find a chance to ask a friend/professor?
most video resources just tackles the basic, converting, gradients, etc
ill try but maybe someone here knows
ima repost my question so people can see
Hi, im trying to find what this topic is called
Maybe Tangent, Normal, and Binormal Vectors?
probably polar coordinates too
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anyone know why this isn’t right?
u = 9t+5, du = 9t dt, (1/9)du = dt \ $\frac{1}{9} \cdot \int u^{2.4} \dd{u}$
@fresh tide did you do this
quantum
well your coefficient is wrong
1/9 = 0.1111111…
either way it should be kept as a fraction
it says 1/9 is wrong too lol
,w integral of (9t+5)^(2.4)
lol
wolfram alpha is drunk
anyways, (1/9)*(9t+5)^3.4 + C is correct
oh darn wait
i’m so dumb
i forgot the integral power rule
(1/9)(10/34)*(9t+5)^3.4 + C
(10/306)*(9t+5)^3.4 + C
boom
me dumb
no problem
what’s command to clsoe
it’s .close

.close
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need help with this problem, i have tried doing ln1.8/0.024 but its not right?
got from using continuous interest formula but not sure if i should be using another
You need to use ln(1.8)/0.024
i did that but its not right
Didn't you write 0.024 in ln?
It's outside ln
it's Sam
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how do i show that $f_s : \mathbb{C} \backslash {0} \to \mathbb{C}, ; f_s = \frac{\overline{z}}{|z|^s}$ is boundless for $s>1$
lewis
My argument would have been: \
Let $z_0 \in \mathbb{C} \backslash {0}$ be arbitrary. Choose $(z_n){n \geq 1}$ such that $z_n := \frac{1}{n}$ and $z_n \to \infty$ for $n \to \infty$. Then, we have: $$f_s(z_n) = \frac{\overline{1/n}}{(1/n)^s} = \frac{1}{n} \cdot \left(\frac{1}{n}\right)^{-s} = \left(\frac{1}{n}\right)^{-(s-1)}$$
So, there exists a $q \geq 1$ such that $q = s-1$. It follows that $f_s(z_n) = \left(\frac{1}{n}\right)^{-q} = n^q$. Since $q \geq 1$, it obviously diverges. So we get: $\lim{n \to \infty} n^q \neq z_0$. The limit cannot exist.
lewis
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How can I know where the midline intersection and extrama should be for a sinusoidal equation? Khan academy wants me to differentiate between the points and depending on which one I use it is wrong -- what am I doing wrong?
The midline is the horizontal line that cuts through the middle of a periodic function right?
Do you know how to graph $\sin(x)$?
azeem321
I haven't tried to graph sin x yet I don't have graphing paper though
I could probably do it easily if I tried
Are you suggesting that I graph the functions on paper before answering?
Could work
I'm not even sure what your question is tbh
do you need help graphing the function
or
Well if you look at the pics basically I sometimes answer wrong because the graph looks wrong based off which point I use.
I'm not sure how I'm supposed to know unless like you say I graph multiple points
Idk which is the extrema point that's probably my main issue
From for example y = 3sin(1/3(x)) + 4 I know that one point is (0, 1)
You should think about graphing this function by starting with $f(x) = \sin(x)$ and then applying transformations to the graph
azeem321
What does $f(\frac{\pi}{2}x)$ do to a graph?
azeem321
= f(1.57x)
Nooo
Ok
Right. So under this transformation $sin(1) \mapsto sin(1.57)$
azeem321
You get to points faster
That's just one of the transformations. So $f(\frac{\pi}{2}x)$ compresses the function. What happens when you do $f(\frac{\pi}{2}x) + 2$ ?
azeem321
If you added 2 to $\sin(x)$ what would happen?
azeem321
It's minimum value would be 2
??
3.57 for the first one
nope
The y value
$-1\leq \sin(x) \leq 1$
azeem321
$-1\leq \sin(\frac{\pi x}{2}) \leq 1$
azeem321
$1\leq \sin(\frac{\pi x}{2}) + 2 \leq 3$
azeem321
Do you get that so far?
Just think about applying graph transformations to the basic graph one by one
So like with -3cos(pi*x/6)-6 I can focus on cos(pix/6) first
$f(x) + a$ lifts the graph up if it's positive and down if it's negative. $f(x-a)$ moves the graph to the right if it's positive and to the left it's negative. $af(x)$ stretches the y coordinates if it's positive and greater than 1 and compresses the y coordinates if it's between 0 and 1. $f(ax)$ compresses the graph in the x direction
Then do * -3 and -6
azeem321
With $-3\cos(\frac{\pi x}{6})-6$. I would start by graphing $\cos(x)$
azeem321
and then I would graph $\cos(\frac{\pi x}{6})$
azeem321
and then I would do $-3\cos(\frac{\pi x}{6})$
azeem321
and finally $-3\cos(\frac{\pi x}{6})-6$
azeem321
Also, note $\frac{\pi}{6} \approx 0.5$ So instead of compressing the graph in the x direction, it would stretch it out
azeem321
Review graph transformations it will help you with trigonometry and make it really easy to understand when you start with solving trig equations and stuff
Ok. It's just taking time to plot out these points.
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Discrete Math
How many bit strings of length 10 have
a) exactly three 0s?
Why is it 10 C 3?
@alpine sable Has your question been resolved?
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can anyone help
keep following the pattern?
im just learnign this topic so dont take my advice to heart. But i think this involves finding the series sum. Looking at this im assuming it is a geometric sequence. to make sure check if t2/t1=t4/t3
i dont remember the formula series sum for a geometric sequence but u just have to use that formula and slap it in
ill try and see if i can solve it but i doubt it, since i as well am learning this cancer of a topic
@fringe robin
@fringe robin Has your question been resolved?
soz
couldnt solve it
but i do know it would have something to do along the lines of what i have explained
that much im confident in
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Determine each rule below is a function or not with the given domain
T/F
f: R-> R
f(x) = f(x) = x+1 if x >= 0 and x-1 if x <= 10
It's F but I don't know why
...is that the exact wording of the question?
or did you omit something you thought was unimportant but actually was?
@alpine sable
,rccw
okay, so you think part e is a valid function definition, yes?
the definition contradicts itself for inputs between 0 and 10
for example, f(5) should be 6 according to the first piece but 4 according to the second
can't be both at once
this is the reason why it's not a valid function definition.
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Hello, I'm trying to understand basics statistics, the F value in linear regression - https://youtu.be/nk2CQITm_eo?t=1089 in this example here he says that F equals variation in mouse size explained by weight divided by variation in mouse size not explained by weight and then the equation is {[sumOfSquares(mean)-SumOfSquares(fit)]/(pfit-pmean)}/[SS(fit)/(n-pfit)] but im confused, should it be something like [sumOfSquares(mean)-SumOfSquares(fit)]/n instead of sumOfSquares(mean)-SumOfSquares(fit), because now its not variation in mouse size explained by weight but sum of squares in mouse size explained by weight?
The concepts behind linear regression, fitting a line to data with least squares and R-squared, are pretty darn simple, so let's get down to it! NOTE: This StatQuest comes with a companion video for how to do linear regression in R: https://youtu.be/u1cc1r_Y7M0
You can also find example code at the StatQuest github: https://github.com/StatQuest/...
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How would you show this?
these are properties of a subspace
α) 0 ∈ S;
β) ∀x, y ∈ S , x + y ∈ S;
γ) ∀k ∈ K , ∀x ∈ S , kx ∈ S
But how would they apply here?
Let's first take only Re - even functions
x+y would be g o f ?
f+g is f+g
they haven't defined explicitly vector addition and scaling, so it's assumed the standard operations
ok, and how would I prove that f+g is in Re if f, g ∈ Re?
The definition of a function being even and or odd
you're showing that the sum of even functions is even.
well we know that
f(-x) = -f(x) (1)
and
g(-x) = -g(x) (2)
then we have to show that
f(-x) + g(-x) = -(f(x) + g(x))
(1), (2) -> f(-x) + g(-x) = -f(x) - g(x) = -(f(x) + g(x))
Is this alright?
f(-x) = -f(x) (1)
(1) -> k * f(-x) = -k * f(x)
does this prove the third property?
Ok
Yes
but it's pretty similar for even i think
yes, $(f+g)(-x)=f(-x)+g(-x)=-f(x)-g(x)=-(f+g)(x)$
Mosh
so odd functions are closed under addition
yes.
f(-x) = f(x) (1)
(1) -> k * f(-x) = k * f(x)
also 0 has to be an element of both Re and Ro
is it?
it is
i'm thinking about how to prove that
just show the 0 function is odd and even.
so it's enought to say that
f(x) = 0
f(-x) = -f(x) = -0 = 0 in Ro
and
f(x) = 0
f(-x) = f(x)= 0 in Re
```?
Mosh
you want 0 in the middle of the string of equality not at the end
you assumed it was odd and even in your proof
yes you're right
R^Ro ⊕ R^Re = {f + g | f ∈ R^Ro, g ∈ R^Re }
And we have to show that
R^Ro ⊕ R^Re = R^R
yep
Well I'm not exactly sure how to start this proof
Could you give me a hint?
It's probably a shit hint if you don't know sinh and cosh but:
Take inspiration from the exponential definition of sinh and cosh
$\sinh(x):=\frac{e^x-e^{-x}}{2}\ \cosh(x):=\frac{e^x+e^{-x}}{2}$
Mosh
alternatively, you want to somehow introduce f(-x) in somehow to use even and odd proprties
(also note that the sum of those is e^x)
i think i have seen something like this a few years ago in highschool
i'll try
$\g(x) = \frac{f(x) + f(-x)}{2}
\
h(x) = \frac{f(x) - f(-x)}{2}
\
g(x) + h(x) = \frac{f(x) + f(-x) + f(x) - f(-x)}{2}
\
g(x) + h(x) = \frac{2 f(x)}{2}
\
g(x) + h(x) = f(x)
\\\
g(x) = \frac{f(x) + f(-x)}{2} = \frac{f(-x) + f(x)}{2} = g(-x) \rightarrow even
\\\
h(x) = \frac{f(x) - f(-x)}{2} = -frac{f(-x) + f(x)}{2} = -h(x) \rightarrow odd$
xbr
basically f(x) is a sum of an even and an odd function

and does this directly imply that R^Ro ⊕ R^Re = R^R?
yes, as long as f is in R^R
cause you've shown f is a sum of an odd function and an even function
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does a real valued function of one real variable exist whose antiderivative is a complex velued function?
I've done some googling but didn't find anything (probably due to my mathematical immaturity :/ )
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<@&286206848099549185>
@thorny sentinel Has your question been resolved?
Not one that i have come across so far, but im no expert at calculus
¯\_(ツ)_/¯
have you maybe taken complex analysis?
Nah im not even in college lol
cuz I suppose you would've came across one if you did and it does exist and it has been discovered
oh
ok
guess I'll just wait for someone with more insight 🙂
@thorny sentinel Has your question been resolved?
does a real valued function of one real variable exist whose antiderivative is a complex velued function?
hope it's not a stupid question
no.
Yes, y=x
you can plug complex numbers into 0.5x^2+C.
I see. I gues it wasn't clear in the question. I'm looking for the case where the only antiderivative is non real
sine and cosine can be written as complex functions.
but they have a real antiderivative
I'm looking for a function that doesn't have one
Yeah, which can be written as a complex function.
Ok, let me restate my question: does a real valued function of one real variable exist which doesn't have a real valued antiderivative, but has the complex-valued antiderivative?
what are you defining as a complex valued function..?
then no
cause you're not satisfied with the fact R to R functions are a subset of C to C functions.
oh right, by complex i mean it has nonzero imaginary unit
Then no
Is there a proof or a reference you can give? or at least an intuitive explanation
integration maintains domain I suppose.
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Decide if it's possible to find four vectors in $\mathbb{R}^4$ such that, every 3 of them are basis.
Michal
Any ideas ?
those arent R^4 vectors
then yes, as long as each 3-vector subset is independent
it should by extremal properties of bases
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Hello! So this question is from calculus a full cource but I dont get how they come to the conclusion that B=0
I get everything else though!
so your factors are (A+1) and (x(A-1) + B)
if either of those is 0, then that whole side of the equation becomes 0
(if A+1 = 0, then it becomes 0*[x(A-1) + B] which is 0)
yup
right, so for the factor on the right, it's [x(A-1) + B] = 0
So it has to be that x(A-1) = -B no matter what x is. The only way for that to happen is if x(A-1) and B are both worth 0
Let's say you pick any other value for A. Let's say -2. The factor becomes -3x + B = 0. But you can't make it so B is always equal to -3x, because B is a constant.
So it doesn't work.
the only time that right hand factor will be zero is when A = -1 and B = 0
does that help?
but
cant B be another number?
since the whole term will become 0 anyways when A=-1?
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Hello I’m having trouble isolating my variables to get the inverse
so what do you think you should do next
wait it's a take home test
can't get help with tests here
no my teacher said it was review
it says take home test at the top
Ik but he said it was a review. I promise it’s not a test.
We have an exam next Wednesday
I understand the confusion and I apologize for how this may look. Can you close my ticket as completed.
.close
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How do I find the derivative of log(3x-2)?
According to my notes, it's g'(x) / g(x) * ln(b)
Which I got 3 / (3x-2)*ln(10)
But using the derivative calculator it's not right
How do I do it
is the base of this log meant to be 10 or e
The calculator assumes its base is e, and your answer assumes its base is 10
so it depends on that
yes
well actually, it depends on if your answer is 3/((3x-2)ln10) or 3/(3x-2) *ln10
Should be the former(the log is in the denominator)
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if i have
no
why
this is basically spam
i mis said it wrong
I said it wrong
wait
so if i have the odds, 3133507531 out of 436116003068178632599586304885865102436987283273192588087066946205825385420102245537617641171508064231363006853389201952225629937253532766998346708022315458543404066186915809029438078922052852453720811267502691138577239348756804955313693393091406303393978608038048294775593159201377364139187142305434603252709617151318958922901417601677040658907901408937709530384849660728157676437361951488873238454079633326062998564370475129597220298716911739158299214865235291416480348618758676919027696256066573122899301892912081375412160180698274455765997411725112824776559729034126511125728785207316456433746195093026529168420804699808556231371820824328024241019054519605469721555033733292097536/6197148516394364188900141323882322297210558701995146720297131484855101557855486731958221825570944947984004858553140186641155182016082966859736962550177180088600405321238825249746403835469727033342501800712896634341355449588496565230819852486507103432027694702173423912538079766299114717526424477880616639449302766419689877623466381205865605118390274355471509815278332251971759244543740352243076811277717664865760571719052087465244804777251295251995674217073974490490639368917793497383548456310727391232146480195472325811180553427557484142696840113044630459874629946903509481288793101524546602637214862483656004358674999005683914545225086663429140282193350054143291262884451455852063961426683890652699785527976797456599012104868536777488904438653913152719206119693088299602007397720839957389279772575408178106779022036761970796031083638898838300999211395119392678116082151174675257415694403682741632963982317824529718557167903433530955641359259898743752340961013280091956109688607349893209675381881203380524958393734988046719982595235111430847956368856989676534079417326438466595922976484817758530826916589148548056446877738990
whats the percent
Its not spam its a real question i swear
0
<@&268886789983436800>
now go away
how
what is your problem
i need help
why are you so butthurt because i asked for help with a big number
.close
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Not sure how to start? A unit length stick is broken into two pieces at a uniformly distributed random point. Then the left
piece is broken again into two pieces at a uniformly distributed random point, and one takes the left
one of the resulting two. Find the expectation of its length.
@rain crypt Has your question been resolved?
@rain crypt Has your question been resolved?
are you looking for the average length of the left most stick?
yes
so i'm not sure how you're supposed to go about this, but I would start by adding up all possible values of the length of the stick after the first break, then divide that by the amount of possible values
and then do that again for the second break
have you seen integrals?
yes
do you know how to add up all the possible lengths of the left stick?
not really kind of abstract to me
it's basically just an integral in this case
varies from 0 to u (u being the length of a unit stick)
random experiment consists in tossing three fair coins. If the result is three heads or three tails,
it is considered to be a success; any other result is a failure. This experiment is repeated 1000 times.
Find the expectation of the number of successes.
what about this one ?
what are the chances one of the experiments succeeds?
1/2
not quite
the first coin can land either way, sure, but there are two other coins that need to land on the same side
oh I meant 1/8
the first coin is 1/2 right?
it can be either heads or tails
as long as the other two land on the same thing as the first one
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Gotta need some help right here at let's try
I do not understand the question at all on how to solve it
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Hello I need help
alright, what are the parameters you're looking for?
I really don’t know, because im not sure what form is the best for this problem
Like general factorised or cannonic
Well what are the pros and cons
General= i got c, factorised = i got the zeros of the function and cannonic: I got h,k
But im not sure how to find cannonic because I dont have h and k
how do you find the h and k usually?
And also I dont have the zeros of the function so I can’t use factorised
h by doing like -b/2a or (x1+x2)/2
But I don’t understand how to find it on a table of number like this
try starting with the equation ax^2+bx+c and putting in the information that can be found from the table
I can only get the c
And one random point
But I still can’t find a and b
Like c is 12
How ?
ok, well let's start from the very beginning
What do I need to do ?
the first logical step would be to find the difference between each point subsequently
so on a scratch sheet of paper, remember that the table does skip a few numbers
Like to find the reflexion axis ?
you know
in this particular case
it might be easier to place the points on a graph and see what it looks like
there is an algebraic way, but I'm not sure you've seen it yet
Could you just explain to me, maybe ive seen it
the algebraic way is to find 2nd difference
Like doing (0+4)/2 ?
I think it might give the h
Because 0 and 4 give the value of 12
if you don't want to graph
you have to find 2nd difference
and solve with a system of 3 linear equations
well if you consider Ax^2 + Bx + C = y, then you could just make three equations and treat it like a système d'équations linéaires
that's how you are supposed to solve
¯_(ツ)_/¯
Like when you substitute the variables to find others
yep
Oh yeah I see ok I will try
or you could say that this looks very much like a parabola
And so I do this for a in b right ?
and that it has the same y value in x= 0 and x = 4
so the reflection axis is probably straight in the middle
yes
Wait but when I do it, a or b cancel out so I can’t find them
is this taken....
Yes but you can take 10
thank your kind sir
No problem
they shouldn't. what coordinates did you pick?
2 and -4
For x and y in respect order
I find that a=(-8-b)/2
And when I replace it in -4=4a+2b+12 it cancel out
you need to use a different point
you have 2 unknown variables
that means you need to use two different equations to solve it
so you need two different coordinate pairs
Oh like the other method of substracting an equation from an other ?
ye
Ok I will try
Well substitution didn’t worked
That’s what I used when all the variables canceled out
Well thank you for your help
I will try it by myself
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I took this a while ago so not at the moment
I can start something
I’ll share it in a few
alright
maybe 6 I am not sure
don't do people's work for them, and "6" is not a radius of convergence
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What did you try?
I believe what you need to do instead, use the rational root theorem, find a root of that expression, then use long division
Have you done polynomial long division before?
I suggest watching some videos
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I got a question
long division
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Can someone explain how i do this? Im kinda confused
They r asking for what values of x is y=0
What
Lemme try and phrase it better
The question that they are asking is
"What values of x can you substitute so that y will become equal to 0?"
Theres 3 factors on the rhs
We know that y will become 0 if at least one of these factors is 0
5 con never be zero for any value of x
Can (30-1.5x) be 0 for some value of x?
Yes i think?
What is that value?
How would i write this out?
Sorry im a bit confused
12+2x=0
Its ok thats y im here lol
What about the 5 at the start? Do i do anything to that?
U cant because 5 cannot become 0 for any value of x
Yes
Okay. I got it, thanks!!! :D
Glad i could help 😀
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I have a couple questions about vectors.
- If you are told to write a vector in i+j+k form, are you just supposed to calculate the unit vector version of that? For example, if the components are <3,4>, are you supposed to write the vector in ijk form like 3/5i+ 4/5k?
- If you are given a vector in ijk form, are you supposed to assume that it is a unit vector?
- if the components are <3, 4>, i think you're supposed to write it as 3i + 4j
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question: find the length of XY
I know pythagoras theorem, how do I use it and solve the question?
First you can use the pythagorean theorem to find XB, and see if you can work it out from there.
You can find XB by first finding AB and then subtracting 8cm.
Once you've gotten XB, you can work out XC
got both XB and XC
hmm
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someone help im stuck for abt 3 hrs already
@proven hedge Has your question been resolved?
<@&286206848099549185>
i need to use the ping because my problem was already here for abt 20 mins
<@&286206848099549185>
stop pinging
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arranging an algebraic equation in an ascending order in the regards of y, it will start from the smallest variation of y to the biggest and if there is a variation of x there, will it come at the end as we are doing it in the regards of y?
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in this-then equations when we are trying to solve: If P, Then Find Q
then we minipulate P so that it becomes Q=(something)
Can someone explain how to solve this...?
i am already in this channel, go to a avalable channel
now could a this-then equation be solved like this too
Hello
where we manipulate P so that, it looks like a part of Q but not the whole Q; Q(piece)=(something)
and we take that (something) that the Piece of Q is equal to. and plug it into the original Q to find the answer
for ex; if 153=2(x+x)y, then find 2y(2x)-193
rewrite; 153=2y(2x), then plug 153 into 2y(2x)-193
153-193
=-40
TLDR; if we have a; If P, then find Q equation
so we take P and do we make one side of the P completely look like Q, Or do we can just make one side of p just equal to partially look like q
<@&286206848099549185>
is anyone there?
OR, if the problem says If (p), then find (q), then we have to make one side of p completely look like q
and , if the problem says, if (p), then find the value of (q), then we can make one side of p look like a part of q, and then plug the value into the original Q to find the value
TLDR AGAIN: IS THERE A DIFFERENCE BETWEEN "IF P, THEN FIND Q" and "IF P, THEN FIND THE VALUE OF Q"
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How would I approach this problem? I'm a little clueless about it 
@shadow stream Has your question been resolved?
. Find the longest pole length that can be put in a room of 10m ×5m
wth? is this question right?
So you are given with only two dimensions? 
Is fx pmf?
uh idk if i have the wrong understanding but if its continuous then its a pdf right?
i believe it is continuous between 2 and 3?
Yeah typo from me
it should be a pdf
yeah
im not sure how to approach this question 
You know how to change variables in integration?
not really 
