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vale wigeon
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"all natural number sets even if written using different scripts"?

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...

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can you show a picture or screenshot of exactly what it says in the book

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even if they used the word "equivalent" it's probably in an informal sense that you should not attach yourself to

gritty veldt
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I see fair enough

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gimme a sec

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I guess the word I'm looking for is isomorphic?

vale wigeon
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if you insist

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i mean like

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the point this paragraph is trying to make is that it does not matter exactly how you represent natural numbers, so long as it is clear what represents what

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like, it does not matter if you write the number 5 as 5 or V or 五 or cinq so long as you understand that these all mean the same thing

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i'm going to go semi-formal here and say that in general for two systems to be considered 'the same' we need to have a way to translate between them that goes both ways and preserves all relevant information

gritty veldt
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Yes

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thus my question is,
is the natural number is also "the same" with a one-side finitely long "chain" graph?

vale wigeon
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i mean, you can certainly number the vertices of such a graph with natural numbers in such a way that each vertex is connected to its successor

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but is there some reason why you ask this

lone heartBOT
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@gritty veldt Has your question been resolved?

gritty veldt
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Thanks!

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alpine sable
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can you only apply this formula when the lim x-> a is same as the constant a?

alpine sable
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for example can you apply this formulae here?

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copper tangle
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Compute $\int_0^2 \lfloor x^2 \rfloor,dx$ ... Idk where to start

ocean sealBOT
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KaiML

Compute $\int_0^2 \lfloor x^2 \rfloor\,dx$ ... Idk where to start
copper tangle
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Do I need to know the integral of floor?

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Cuz I dont know the integral of floor

topaz grove
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you don't know how to find the integral of x^2 ?

copper tangle
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floor x^2

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not x^2

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Its a floor function

topaz grove
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first, do you know how to find the intergral of x^2 ?

copper tangle
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Yep

topaz grove
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ok, so do that first

copper tangle
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with the given bounds?

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Or just indefinite

topaz grove
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just indefinite first

copper tangle
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Ok

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x^3/3+c

topaz grove
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ok, so this is a definite integral, so you don't need C

copper tangle
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Right

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no c : x^3/3

topaz grove
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so now plug in your values. do you know how to do that?

copper tangle
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Not really...

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Is this FTC? I don't quite understand how to use that

gray isle
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they seemed to have ignored the "floor"

topaz grove
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[(x^3)/3 - (x^3)/3], plug in the higher value for the first (x^3)/3 and then the lower value for the second (x^3)/3

copper tangle
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huh

gray isle
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consider graphing y = floor(x^2)

copper tangle
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Ok...

gray isle
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from x=0 to 2

topaz grove
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maybe i'm misunderstanding the question, it looks to me like it's a definite integral problem? am i wrong?

gray isle
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note that 1^2 = 1
sqrt(2)^2 = 2
sqrt(3)^2 = 3
sqrt(4)^2 = 4

copper tangle
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Yea It is but its a floor function

brazen forge
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floor (x²) is discontinuous on the points √2 and √3 in the given interval, so you need to do a piecewise integral accordingly

copper tangle
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Okay I graphed it, but not sure what to do next

brazen forge
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1, √2 and √3* my bad

gray isle
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consider the relation between definite integrals and (signed) area under a curve

brazen forge
gray isle
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after graphing the question is pretty much reduced to calculating the sum of areas of a few rectangles

brazen forge
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So to say, split the integral into multiple smaller integrals that you can evaluate

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Without worrying about the function being discontinuous

copper tangle
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wait what...

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Ok?

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I am a little confused

brazen forge
copper tangle
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So I just find area of the rectangles and add?

brazen forge
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Yep, that's what a definite integral does

copper tangle
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Huh ok thx for the help

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slim fog
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Is there any distinction between types (as in type theory) and sets?

lone heartBOT
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@slim fog Has your question been resolved?

lone heartBOT
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@slim fog Has your question been resolved?

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cunning bloom
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could someone help me with this problem Determine the remainder when the number 33725^1579 + 8465 is divided by 11.

cunning bloom
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i know i need to use some type of congruent method with modulus yet i dont see any similarities between the 2 numbers 33725 and 8465

merry haven
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Tried to divide by 11? If they are divisible by 11 no matter what power it's the rest by 11 is 0. Is 1579 divisible by 11? Try to see this sections theorems/definitions to see if something can help you.

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They are divisible by 5 anyway but I don't see what this can help you.

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cunning bloom
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alpine sable
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I need some help with these please

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fluid zealot
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what should i write for 6b? That slope and speed are the same?

chilly panther
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For a distance time graph, the slope represents speed and can be calculated by dividing the distance travelled by the time it took to travel that distance

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so the slopes for the two graphs represent the speeds across those distances

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thus, the steeper the slope, the faster the car is going over that time period

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make sense?

fluid zealot
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yepp it does thank you

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is part a correct?

chilly panther
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No problem yes it is

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car 1's speed can be found as 60m/1h

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and car 2's speed can be found as 80m/2h

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which is 40m/h

fluid zealot
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kk tysmm

chilly panther
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no problem 🙂

fluid zealot
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alpine sable
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tawny jetty
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In proving an equation is dimensionally accurate, we ignore constants. However with the equation v^2=u^2 + 2as we can include the '2'. Why is this?

lone heartBOT
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@tawny jetty Has your question been resolved?

lofty axle
tawny jetty
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Disregard last question,

How would I answer the following question using arithmetic progression? I think I have to rearrange the formula for working out the sum of an arithmetic progression, but I am not sure.

The company find that the initial cost for producing a part is £450, each year the cost increases by £18.

Find the year in which the cost first goes over £600

lofty axle
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It's a simple linear relationship

alpine sable
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450+18x>600? solve for the lowest value of x that keeps the equation true

lofty axle
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$C(y) = 450 + \sum_{i=1}^{y} 18 = 450 + 18y$

ocean sealBOT
lofty axle
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There's your arithmetic progression

lone heartBOT
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@tawny jetty Has your question been resolved?

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native knot
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native knot
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why was this wrong?

solid cargo
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Infinity - infinity is indeterminate

lone heartBOT
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@native knot Has your question been resolved?

velvet osprey
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@native knot none of the above

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Why ?

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You should look for examples where you can't ansEr

native knot
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ye i figured out what i did wrong

velvet osprey
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The hard one might be 1^infinity

native knot
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after finding out the 7 indeterminate forms

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also

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why was this wrong? @velvet osprey

velvet osprey
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What did you do to answer ?

native knot
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well i took the derivatives of both functions

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and then evaluated them at points

velvet osprey
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First all the intervals given are parts of R+

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So you don't need to study the function when x<0

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Then if you take the dérivativ of the functions when x>0 what do you get ?

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You get 1/2 -cos(πx)+1 right ?

native knot
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$-\cos \left(\pi x\right)+\frac{1}{2}$

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ye

ocean sealBOT
velvet osprey
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So

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What can you tell of this function ?

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The sign oscillate so you can't say much right ?

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So I think what you did was right

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Then you have to find out where your calculus misteaks were

native knot
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so i have a question what if I was asked to determine for example [-1/3, 1/3]

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what do I do then?

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because at x = 0 its not continous?

velvet osprey
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No it's not

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But it can still be increasing

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You would have to do a variation tab

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And look at where the first function lays beetwin -a and 0

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For a certain a

lone heartBOT
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alpine sable
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Can someone explain to me the result and how did you get it?

wary stream
alpine sable
wary stream
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Then you didn't properly type it in

alpine sable
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I can show you my book

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result is 2^12

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<@&286206848099549185>

north needle
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@alpine sable Has your question been resolved?

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simple current
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to do a differentiation of a function defined parametrically, you just do the derivative of the y function over the derivative of the x function right?

ocean sealBOT
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keto11

simple current
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neat schooner
#

Hi, Im learning about 3d algebra and Iam not sure what they mean by this question. Even after looking at the answer Iam a little bit lost:
Question: "List the 48 different possible ways that the 3D axes may be assigned to the directions “north,” “east,” and “up.” Identify which of these combinations are left-handed, and which are right-handed."

Answer:

placid zinc
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Any specific choice that isn't making sense?

neat schooner
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Im really confused about this "righthanded" and "lefthanded" coordinate system

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Like the next 2 questions are about it and i got all answers wrong

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even though I thought I finally understood it

neat schooner
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eternal crest
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eternal crest
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How would I go about scaling this grid on the x and y axis without making the exponents and ! Extremely large?

raven rover
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Increase the y min and y max?

eternal crest
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Kinda

raven rover
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Or just zoom out

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Which increases every coordinate

eternal crest
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So I want the x:0 and y:1 to be like x:0 and y:100

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I’m kinda not so good at this kind of math so I’m not sure how to say it

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So I think the zoom out one

warm marsh
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Do second window and change them there I think

eternal crest
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Wdym?

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Ok ok wait, what I actually need is for the grid to be scaled on the x axis

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I’m sorry about that

lone heartBOT
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@eternal crest Has your question been resolved?

raven rover
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In Desmos you can choose the x min, x max, y min, and y max yourself

eternal crest
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I’m not trying to use it in a calculator really I’m using it in Minecraft haha but I need the x axis to be scaled by 10 so like the wave would be wayyy longer but the graph not changing

raven rover
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You change the x min and x max to be 10 times larger or something

eternal crest
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In the equation?

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<@&286206848099549185>

eternal crest
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@eternal crest Has your question been resolved?

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hybrid plume
#

It can be factored to (x^2+5)^2

jagged imp
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You can break it up as partial fractions $\frac{ax+b}{x^2+5}+\frac{cx+d}{(x^2+5)^2}$

ocean sealBOT
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Sneaky

jagged imp
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being a case of this last one: an irreducible quadratic raised to some power

hybrid plume
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Just found it in a video I see, I was trying to do it like the denominator was made of linear factors

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That pic is really helpful thanks

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rigid kiln
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i can't tell if this is right or not, i'm not sure if i'm allowed to just integrate each term

charred flint
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are p1 and p2 vectors?

rigid kiln
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(forgot to close the brackets, whoops)

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components of the vector p

charred flint
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I'm confused because usually P would be a scalar and gradP would be a vector

rigid kiln
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isn't grad p supposed to be a scalar

charred flint
rigid kiln
#

oh, right

charred flint
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usually to reverse a gradient you just integrate one, get a +g(other variable) term, and integrate that one to figure out that extra term

rigid kiln
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that makes more sense, i think i've just screwed up the initial problem

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trying to solve an euler equation and not really getting it

charred flint
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for fluid mechanics? yeah that's hard

rigid kiln
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yep, i love mechanics but i wish i knew about all the god damn integrals i was gonna have to do

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by far my hardest class

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thanks anyways

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hybrid plume
#

,rotate

ocean sealBOT
hybrid plume
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Since the two systems are solved with different x values I can’t add them right?

glass lichen
#

you can add them yeah

hybrid plume
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Really?

glass lichen
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Yes....

hybrid plume
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I believe u but damn

glass lichen
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It's just 2 linear equations in A,B,C, and D... it doesnt matter where the equations came from.

hybrid plume
#

I thought because the left sides for both systems are 1 but the right sides are different it wouldn’t be allowed

#

Thanks

lone heartBOT
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fallow hollow
#

Hey there, basic question that keeps tripping me up

fresh parcel
#

wheres the question lol

fallow hollow
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If i have a function that takes in n and n is in hundreds, how would I rewrite the function so that it just takes single values instead

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Still writing it out lol

glass lichen
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define single values

fallow hollow
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Yeah, fair enough lol

glass lichen
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so you want n=1 to really become n=100?

fallow hollow
#

Yeah, essentially

glass lichen
#

horizontal dilation

fallow hollow
#

So just multiply n by 1/100?

glass lichen
#

$f(n)\to f(\frac{1}{100}n)$

ocean sealBOT
glass lichen
#

yep

fallow hollow
#

Yeah okay, thats what i thought. Man thats gonna look ugly lol

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Thanks

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vapid smelt
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vapid smelt
#

Could someone help me solve this, thanks!

gray isle
#

where's cos(1/sqrt(2)) coming from

vapid smelt
#

sry

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lol

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it was supposed to be 1/sqrt(2)

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only

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not cos

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writing mistake

gray isle
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$\frac{1}{\sqrt{2}} = \frac{1-\tan^2(22\frac12\deg)}{1+\tan^2(22\frac12 \deg)}$

ocean sealBOT
#

ℝamonov

gray isle
#

is all you really need

vapid smelt
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ik, but i got sqrt(2) - 1

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using that

gray isle
#

solve for tan^2(22.5°)
show work

vapid smelt
#

wait up

devout summit
ocean sealBOT
#

Euclid31415

vapid smelt
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ye

#

but i have to prove $sqrt{3 - 2\sqrt{2}}$

ocean sealBOT
#

Inheritanc-e ♦

devout summit
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$\sqrt{3-2\sqrt{2}}=\sqrt{(\sqrt{2})^2-2\sqrt{2}+1^2}=\sqrt{(\sqrt{2}-1)^2}$

vapid smelt
#

oooooo

#

oohh

ocean sealBOT
#

Euclid31415

vapid smelt
#

yeeee

#

thanks

devout summit
#

Yes

vapid smelt
#

gotcha

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thanks

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dire crown
#

Can someone recommend good books for reviewing/wrapping up algebra II?

dire crown
#

oh wrong channel

dire crown
#

yeah.

#

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empty crow
#

nerd

lone heartBOT
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alpine sable
lone heartBOT
alpine sable
#

How can I get this into arctan

velvet pelican
#

I mean it's already a standard integral

#

But if you want, x=2u

alpine sable
#

i struggle with getting things into their standard trig identify form when it comes to integrals

#

Where did you come up with x = 2u

velvet pelican
#

4=2^2

#

So putting x = 2u will get 4u^2 + 4

#

In the denominator

#

Then you factor the 4

#

And are left with the arctan

alpine sable
#

not 4u^2

velvet pelican
#

No

#

It's x^2

#

(2u)^2

alpine sable
#

ohh i see

#

I need to practice a lot with trig integrals, lol

#

thank you!

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dark pelican
#

can someone please explain how to do this to me

magic geyser
#

did u solve the asympototes

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alpine sable
#

Unfunny but, what is 69^420 x 420^69

lone heartBOT
alpine sable
#

and yes im serious

#

😎

devout summit
#

Use a calculator

alpine sable
#

I dont have oneon hand and im too lazy to go on google

devout summit
#

,w 69^420*420^69

ocean sealBOT
alpine sable
#

Greatness

#

Now i know 👍

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alpine sable
#

What will the value of x, if x = 5 mod 2

alpine sable
#

i want to know the process

#

to solve this kind of question

gleaming granite
alpine sable
#

no

#

i wanna go ahead of my class

gleaming granite
#

if you divide two numbers the remained is the mod

#

so 5mod2 is the remainder of 5/2

alpine sable
#

oh

#

thats easy

#

so we just have to divide them

#

right ?

gleaming granite
#

yes

#

and find the remainder

alpine sable
#

so 2.5

gleaming granite
#

no

#

the remainder is the amount that isn't divisible

#

2 goes into 5 two whole times, and has a remainder of 1

#

so 5mod2 = 1

alpine sable
#

oh

alpine sable
#

can any questin be formed

gleaming granite
#

what kind of question?

alpine sable
#

means with mod

#

how questions come

#

what question I gave you

#

thats just a example

#

I mean do we have simplification

#

or anything

gleaming granite
#

yeah

#

5mod2 = 1

alpine sable
#

5x ≡ 4 (mod 6)

#

this is different

#

?

gleaming granite
#

5x = 4mod6

#

i'm pretty sure that if the number in the front is less than the number in the back (4<6) you just use the front number (4mod6 = 4)

alpine sable
#

ok

#

how do I close this chanel

gleaming granite
#

.close

alpine sable
#

.close

lone heartBOT
#
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lucid wadi
#

Hi

lone heartBOT
lucid wadi
#

Im so confused about this

#

I get the part about the restriction of the domain

#

so we have to find the other angle that has the same value but is in the doman

#

so how did we go from -10pi/9 to pi/9

buoyant edge
#

so youre confused on the reference angle part?

lucid wadi
#

is that a reference angle?

buoyant kayak
#

yes, they have the same reference angle

#

arcsin has the domain restriction [-pi/2, pi/2]

lucid wadi
#

but how did we get it

#

get from -10pi/9 to pi/9

buoyant kayak
#

by knowing they have the same reference angle

lucid wadi
#

we memorized the unit circle

#

not this though

#

i jsut know anything /6 or /3 or /4 or /2

buoyant kayak
#

don't need the unit circle for this

#

-10pi/9 is pi/9 away from pi, which is the x axis

lucid wadi
#

what if it was -11pi/9

buoyant kayak
#

reference angle if 2pi/9

lucid wadi
#

oh ok thanks

#

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north wren
#

I know part A is 0 by Green's Theorem and that for B, you can't use Green's theorem since the denominator (x^2+y^2) is 0 at the origin. How do you do part C?

north wren
#

someone in my class asked the professor and got a hint about using the region between c1 and c2 (since of course one of them has to enclose the other since they are not touching or intersecting). not really sure what he means yet

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@north wren Has your question been resolved?

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alpine sable
#

3x - y = -5
3x + y = -2
Came up with the coordinates (0,-5) & (1.66,0) B. (0,-2) & (-0.66, 0)

alpine sable
#

How Do I verify my answers for Linear Equations with 2 variables? :DD

#

feels like Im doing something wrong

gray isle
#

how'd you get 4 points

alpine sable
#

erm, 4?

gray isle
#

(0,-5) & (1.66,0) B. (0,-2) & (-0.66, 0)

alpine sable
#

Used Graphing method

#

sub x and y to 0

north wren
#

to check, plug in your coordinates for each variable in each equation and verify both equations hold true for each point. for example

gray isle
#

why are you randomly setting x and y to 0

north wren
#

but yeah there are only 2 equations so you should only get 1 point of intersection

#

actually in general w/ n equations and n unknowns you should get 1 solution

#

for linear systems

alpine sable
north wren
#

yes but then plug that into the second equation

#

notice that it doesn't hold true

gray isle
#

setting x or y to 0 can get you the x and y intercepts of the individual lines but that does not help you determine the solution / point of intersection in any way

north wren
#

3(0)+(-5) does not equal -2

#

so (0,5) is not a solution since it doesn't satisfy both equations

north wren
#

looks like they were finding points of intercept

gray isle
#

those questions are asking for different things

north wren
#

yeah

gray isle
#

it was not clear what you actually wanted but writing just

3x - y = -5
3x + y = -2
would usually imply that you want the point of intersection

north wren
#

and there are lots of ways to do it but one of them is elimination

#

in this case you can just add the equations together

#

to get 6x=-7

gray isle
#

also leave stuff in exact form

north wren
#

so the x coordinate of the solution is -7/6

gray isle
#

e.g. leave 1/3 as 1/3 instead of writing 0.33 (which isn't the same as 1/3)

alpine sable
north wren
#

"graphing method" is a bit vague but i assume they mean just graph the lines and then see where they intersect. the intersection point of the lines is the solution to the system

alpine sable
gray isle
#

get used to using fractions

#

they're much better

north wren
#

what you may have been doing beforehand was finding the 4 points where each line intercepts the axes

#

which could help you graph the lines

#

depending on how you're doing this

gray isle
#

you could have each gap on your diagram represent 1/3 units here
which allows you to be a lot more precise

alpine sable
#

am getting lost

#

lets roll back

#

so my coordinates are wrong right? so I must be doing something wrong

north wren
#

yeah we've been laying it all on p quick lol

#

well

#

those 4 coordinates you gave at the beginning

gray isle
#

some of the intercepts are wrong

north wren
#

are the x and y-intercepts of each of the 2 equations

north wren
#

i didn't check if they are right

#

but if they aren't it might just be an arithmetic mistake

gray isle
#

assuming that 1.66 is supposed to be 5/3
check your signs

north wren
#

the thing that's confusing me i think

#

is why would you need to find the intercepts to solve the system

alpine sable
#

-5/3 = -1.66

gray isle
#

wdym by

3x = -5

3x 3x

alpine sable
#

and dividing -5 by 3

alpine sable
gray isle
#

well then overlooking that questionable notation to represent that, you should've indicated division by 3

#

-5/3 is the correct x intercept for that line now

#

yes. attempt to graph it, make your graph sufficiently large to be as precise as needed

north wren
#

yeah although still wouldn't you need to algebraically solve the system to find where they intercept

#

can't just look at the graph

gray isle
#

if your graph is good enough, you can

north wren
#

unless you use a computer that does it perfectly

#

or that

gray isle
#

the graph will show the location of the point of intersection (i.e. the solution of the system)

alpine sable
#

welp I got a jist of how to recheck

#

i guess

#

so thanks

#

:DDD

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#

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alpine sable
#

I guess i need help w this?

lone heartBOT
alpine sable
#

Just need to find H length. not even sure if it's possible . I feel like it is. All that is known is circumference. LINE DE = in length to ARC SE +.05cm

lone heartBOT
#

@alpine sable Has your question been resolved?

warm brook
#

@alpine sable It's possible once you find the length of DE
If r is the radius, the length h is
r^2 + DE^2 = (r+h)^2

#

which gives h = sqrt(r^2 + DE^2) - r

alpine sable
#

OK so basically its not possible with given information for sure ?

warm brook
alpine sable
#

Yes lots of ways to do it w one other piece was really hoping there was a way but glad there isn't

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#

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cinder sundial
#

yy

lone heartBOT
tiny minnow
#

Please how i can help u?

cinder sundial
#

tim were doing a experiment about spring, heres the statistic he gets from the experiment,
the external force(gw) :20, 40 ,60, 80, 100
the total length of the spring(cm) :4, 6, 8, 10, 13

#

the original length of the spring is 2 cm

#

the question asks for the x

#

i got 27.5g as the weight, but its wrong

#

can someone point it out the error i have made

#

it relates to hooke's law btw

#

<@&286206848099549185>

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#

@cinder sundial Has your question been resolved?

lone heartBOT
#

@cinder sundial Has your question been resolved?

lone heartBOT
#

@cinder sundial Has your question been resolved?

cinder sundial
#

.close

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glacial cave
#

Help

lone heartBOT
fringe ember
#

send qn

glacial cave
#

Ak=kc

#

<@&286206848099549185>

fringe ember
#

at a glance, i would say 90

#

but let's check

glacial cave
#

whats a glance?

#

Oh nvm

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#

@glacial cave Has your question been resolved?

glacial cave
#

.close

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keen geyser
#

I would like to move an object which is in a 3D world in the direction in which it is looking. I know that there are formulas for this but I just can't find anything about it. I already have found a formula for the x and y axis which I made a method for:


    public Vector3d vecFromRotation(AircraftInstance aircraftInstance, double speed) {
        float f = MathHelper.cos(-aircraftInstance.yRot * ((float)Math.PI / 180F) - (float)Math.PI);
        float f1 = MathHelper.sin(-aircraftInstance.yRot * ((float)Math.PI / 180F) - (float)Math.PI);
        float f2 = -MathHelper.cos(-aircraftInstance.xRot * ((float)Math.PI / 180F));
        float f3 = MathHelper.sin(-aircraftInstance.xRot * ((float)Math.PI / 180F));
        return new Vector3d((double)((f1 * f2) * speed), (double)(f3 * speed), (double)((f * f2) * speed));
    }

But I need it for all 3 axis (x, y, z).

sage summit
#

look at the documentation of what is inside aircraftInstance ?

keen geyser
#

thats my own class lol

sage summit
#

I am not sure how you can encode the orientation of a plane in 3D with just two numbers xRot and yRot

keen geyser
#

i have all of them

#

x y and z

sage summit
#

and what do those mean ?

keen geyser
#

Well I only want to get a direction from my rotation. I have the x y and z rotation.

sage summit
#

what is an x rotation

keen geyser
#

pitch roll and yaw

#

x y and z

sage summit
#

probably the direction you want is one of the three columns of the matrix

keen geyser
#

thx

sage summit
#

I would just use matrices or unit quaternions if I were doing 3d stuff

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#

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verbal olive
#

Why is a shift cipher "limited to 26 keys"? when I try 40 as a key it works fine

prime badge
#

that's just key 14

verbal olive
#

Very interesting

#

And how is -n mod m done exactly?

#

<@&286206848099549185>

#

So it seems (z * x + a) % x == a % x explains both questions

#

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alpine sable
lone heartBOT
alpine sable
#

Mhm

#

<@&286206848099549185>

raw shard
#

channel is occupied

indigo storm
#

Ok

raw shard
#

we can represent this problem as 4t/5m = 7h

#

t = trenches, m = men, h = hours

alpine sable
#

Yea

#

I followed that google-web-process and perhaps its wrong!

raw shard
#

we need to multiply both sides by something that will get us 9t/7m

#

i would do (9/4) / (7/5)

#

this would also be (9/4)(5/7) = (45/28)

#

so multiply both sides by that

#

and simplify the fractions afterwards

alpine sable
#

Yeah we get 45/28

raw shard
#

yes, multiply both sides of 4t/5m = 7h by that

bleak ridge
#

I hate these kinds of problems

alpine sable
#

Don't we have simple logic making method?

#

It's kinda confusing yk

raw shard
#

the only way i can make this easier for you is if i do it myself

#

and i can’t do your work for you

alpine sable
#

Sure

#

Continue

raw shard
#

i’ve already said all i have to say

prime badge
#

treat it as a physics problem

raw shard
#

ignore them

prime badge
#

or don't

raw shard
#

all you have to do is multiply both sides by 45/28

prime badge
#

i mean don't ignore me is an option

raw shard
#

there is no need to treat this as a physics problem, that sounds like you’re over complicating it

prime badge
#

overcomplicating is what they asked

#

I see no issue with overcomplicating a problem, it's not a sin

#

5 men together have 4/7 t/h of power. Divide it by 5 and multiply by 7
means 7 men have 4/5 t/h

#

9 / (4/5) = 45/4 hours

alpine sable
#

Is answer

#

11.25?

#

YEAHHH

prime badge
#

must be

alpine sable
#

GENIUS ME

#

YA YAY

#

Look, genius I found a way!

#
  1. Multiply time with 1st value of men
  2. Divide with new value of Men
  3. Divide with old value of Trenches
  4. Multiply with new value of Trenches
    And boom!
#

You got the answer!

#

I'mma LEARN Those ways by heart cuz sequence of values will be same~

lone heartBOT
#

@alpine sable Has your question been resolved?

lone heartBOT
#
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languid pendant
#

How would I go about solving X in this equation

languid pendant
#

I know I want to get rid of the divisions but I don't know how

#

.close

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#
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languid pendant
#

.reopen

lone heartBOT
#

novel siren
#

cross-multiply

languid pendant
#

It has been resolved in a dm

#

Thanks to hayat

merry haven
#

Close

languid pendant
#

.close

lone heartBOT
#
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languid pendant
#

Sorry my bad

#

It's still in occupied?

lone heartBOT
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alpine sable
#

hi i have a quick question about probability. if i have a coin and get Heads 4 times in a row or if i get 2 Heads and 2 Tails, the probability is the same right? its 0.5^4 either way

glass lichen
#

Assuming it's fair and the tosses are indep then yes

#

All outcomes are equally likely

#

Or no, cause there's more way to get HTHT

lone heartBOT
#

@alpine sable Has your question been resolved?

alpine sable
#

Yeah thats what im wondering

#

But if its an ordered without repition ?

#

If you have 4 coins and then get heads of tails

#

Is it a binomial probability??

north wren
#

when you say 2 heads and 2 tails, do you mean getting 2 heads and then getting 2 tails

#

i.e. does order matter

#

if order does matter, then yes the chances are the same

#

if order doesn't matter then 2 heads and 2 tails has a much higher chance than 4 heads

#

because 2 heads and 2 tails could be HHTT, TTHH, HTHT, THTH, HTTH, THHT

#

each of those individually has a .5^4 chance, so getting 2 heads and 2 tails is 6 times as likely as getting HHHH

#

although again if you just mean HHTT then yes they're equally likely

#

@alpine sable

alpine sable
#

Oh that makes sense yeah so if its ordered then it has to be that exact order which means theres one possiblity as opposed to multiple if its not ordered

#

Thank you

north wren
#

yup

alpine sable
#

Alright thanks

#

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fleet maple
#

Hi, i'm trying to solve this expression but i'm having trouble finding the right moves and i've gotten completely stuck on what to do. The circled expression is the end goal.

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dark pelican
#

how do i do this

lone heartBOT
thorny patio
#

It's secant or cosecant

dark pelican
#

yeah

#

i dont know 1) how to differeniate or 2) apparently the entire rest of the problem because desmos says my equation is wrong

glass lichen
#

Sec and csc just differ by a phase shift pi/2, like cos and sine

dark pelican
#

right but how do i know which is which in this scenario when there are other phase shifts

glass lichen
#

Sec has a minimum at x=0

thorny patio
#

There are multiple answers to a question like this you can decide to write it as a secant or a cosecant.

The "vertices" of the parabola like shapes are where the secant/cosecant part of the function takes on 1 or -1

The fact that y achieves 4/-4 at the "vertices" tells you its of the form

4*sec(something)

#

Or 4*csc(something)

glass lichen
#

Extrema is more apt than vertices imo

thorny patio
#

Yes i agree but I'm just using the term " vertex" as it's a quick analogue to a familiar graph

#

With quotes to boot xD

dark pelican
#

sorry but i really dont understand what your saying lol

#

so it doesnt matter if i choose sec or csc

glass lichen
#

It doesnt

#

The only effect the choice has is you'll have a different phase shift

dark pelican
#

okay so now for that question say i want to assume its csc, how do i find the equation

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crystal narwhal
#

How th do i fo 8 iii?

lone heartBOT
crystal narwhal
#

here is the anwnser for it

#

but it doesnt say how they got it

granite sleet
crystal narwhal
#

i thought they mean the area of this shape is 11x^2 + x -2

#

im an idiot

#

its this isnt it?

#

shaded regions are cut out

granite sleet
#

open cuboid would have just 5 faces, since 6th face is open/void

crystal narwhal
#

ohh

#

other than that is this shape right?

granite sleet
#

yes

#

u fold the side faces and get a cuboid(3D shape)

crystal narwhal
#

ok

granite sleet
#

so for volume u just take product of the length, width and height

crystal narwhal
#

thanks for the help 🙂

#

cursed emoji

#

🙂

#

ffs

#

its supposed to be a emoticon

#

anyway ima go

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willow dragon
lone heartBOT
willow dragon
#

So far I've used conservation of momentum to get velocity of the red ball after to be 4u(-i+j) and the velocity of the white ball after to be u(2i+4j)

#

Then taking the line of centres to be -i+j as per the question I've tried to resolve my velocities to use Newton's experimental law

#

Which gave e=(4u+root2 u)/(5root2 u)

#

Does anyone see where I've gone wrong

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strange chasm
#

Hi I am working with graphs and using "fully connected" graphs as in the image.
There are 4 levels between nodes 1 and 200, and 4 in each level. I need to find the total ammount of paths from 1 to 200 using this graph, both unidirecionally and bidirectionally.
I figured out the equation for the number of paths for unidirectional(can only go to a node in a higher level) is (number of nodes per level)^(number of levels), ex: in the picture, the total ammount of paths is 4^4=256. I just need help to find the equation for the number of paths if the graph is bidirectional. I have made the following table with some values if its any help.

strange chasm
lone heartBOT
#

@strange chasm Has your question been resolved?

small stag
#

what does number of nodes per level mean

strange chasm
#

@small stag im making a picture for you

#

Green is level 1, Blue is level 2, Pink is level 3 and Yellow is level 4

#

Number of nodes per level is 4 in this case

#

All levels have the same ammount of nodes

lone heartBOT
#

@strange chasm Has your question been resolved?

strange chasm
#

<@&286206848099549185> any help here?

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@strange chasm Has your question been resolved?

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@strange chasm Has your question been resolved?

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last sinew
lone heartBOT
last sinew
#

will someone please help? Thank you so much!

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@last sinew Has your question been resolved?

jagged imp
#

is the last one the incorrect one

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formal spoke
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formal spoke
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.close

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lime abyss
#

hello may i ask question for this question, i cant seems to get the value of x

floral schooner
#

is TSUV a trapizoid

sand agate
#

it is

floral schooner
#

cause then x is just 38

sand agate
floral schooner
#

cause UV and TS are parallel

#

meaning angle UTS and angle UVT are alternate interior angles

lime abyss
#

this is the full question

#

38 isnt in the answer choice

#

or 30

floral schooner
#

the question never says it's a trapizoid

#

I was going off of that assumpion

lime abyss
#

is this question possible?

floral schooner
#

um

silver viper
#

then since angles in a quadrilateral add up to 360 degress you can find x

lime abyss
#

wait explain why it is 68

silver viper
#

uh coz OT and OU is the radius

floral schooner
#

ahh I was about to write that down lol

silver viper
#

then its isoceles triangle

floral schooner
#

yeah cause it's the radius so they form two isosceles triangles

#

I couldn't figure out why I wasn't getting an answer until I saw I wrote 38 * 2 = 72 lol

lime abyss
#

so the answer is 22?

#

am i right

#

omg thankyou youre an absolute genius !!

#

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alpine sable
#

hi

lone heartBOT
alpine sable
vale sapphire
#

Okay, so for this you could try solving it in your head, but it's annoying and I think the point of this is teaching you equations, isn't it?

alpine sable
#

ya

#

l = 5+ p

vale sapphire
#

First of all, the rule of thumb is to always set your variable to be the thing you actually want to know

#

In this case, x = leo's current age

alpine sable
#

alrighty

#

x = 5+p

vale sapphire
#

Can you express Pat's current age in terms of that?

alpine sable
vale sapphire
#

Ok yeah, do you agree p=x-5 is saying the same thing?

alpine sable
#

ya

vale sapphire
#

You don't want to add more variables, it'll make things more complicated

#

So try to express the various quantities in terms of your unknown

#

Anyway

#

Now, can you write down "twice Pat's present age" only using x

alpine sable
#

2p

#

oh

#

using x?

#

2x???

vale sapphire
#

that's twice leo's current age

alpine sable
#

o

#

uh

#

2x - 5

vale sapphire
#

close, but be careful about your multiplication

alpine sable
#

(x -5) times 2

vale sapphire
#

you meant to write 2(x-5)

#

which is 2x-10

#

but yeah

#

correct

#

so now, what's "Leo's age plus 10"?

alpine sable
#

uhh

vale sapphire
#

no tricks

alpine sable
#

(2x -10) + 10?

#

so 2x?

vale sapphire
#

leo's age

#

you wrote "twice Pat's age plus 10"

alpine sable
#

oh

#

x + 10

vale sapphire
#

remind me, what is x?

alpine sable
#

leo

vale sapphire
#

ok yeah

#

so just x+10

#

now, what does the problem tell us about these two quantities?

alpine sable
#

2x-10 = x+10

vale sapphire
#

Yes!

#

now you can solve

alpine sable
#

so

#

x = 20

vale sapphire
#

So Leo is 20 years old

#

And let's just quickly check

#

Pat is 15

#

In 10 years, Leo will be 30=15*2

alpine sable
#

what does 15*2 mean

#

times?

vale sapphire
#

yes

#

it's the usual symbol when you're writing with a computer

alpine sable
#

oh ok

vale sapphire
#

In summary, here's the method :

alpine sable
#

so is 20 the answer?

vale sapphire
#

We set x to be our answer and we found x=20

#
  1. Set your unknown to be what you want to find
  2. Express all of the quantities involved using x, and always think about what x is and if what you're writing makes sense
  3. Now, the statement of the problem should tell you some of these are equal. Now you can solve and get the answer.
alpine sable
#

okay ty

vale sapphire
#

But yeah, I can't stress this enough, don't wing it

#

What you're writing has to make sense to yourself

#

After that, math works because it's a universal language for things that make sense

alpine sable
#

yah ty

#

.close

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lethal yacht
#

Hi

lone heartBOT
#

@lethal yacht Has your question been resolved?

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vale wigeon
#

you want to solve for x and y in terms of m?

#

@untold sequoia

#

...do you have the instructions for the problem as it appears in your textbook?

#

maybe it'll be easier to see what your goal is

#

even if it's in another language.

#

okay

#

i can tell you for sure that you have made it way, way, way more complicated than it needs to be

#

it seems to have escaped your notice that this is a system of linear equations, and so can (and should) be solved as a system of linear equations

#

yeah but they're linear in x and y

#

and your work doesn't respect that

#

again

#

you've made things more complicated than they need to be

#

from 6x + (m-1)(m-1 - mx) = 4 you could have expanded it as 6x + (m-1)^2 - m(m-1)x = 4

#

and then you could have grouped the x terms as [6 - m(m-1)]x + (m-1)^2 = 4

#

so you have (6 + m - m^2)x = 4 - (m-1)^2

#

do you not agree that this equation is much much easier to solve for x than the nonsense you came up with

#

so you can clean up a bit more here

#

to get (m^2 - m - 6)x = (m-1)^2 - 4

#

which turns into (m-3)(m+2)x = (m-3)(m+1)

#

so you have three meaningfully different cases: one where m=3, another where m=-2, and a third where m is neither 3 nor -2

#

do you understand how to continue from here?

#

no

#

the case m=3 is very different from m=-2

#

it's not clear what you're talking about right now

#

you are not making it clear which case you're claiming to have infinite solutions and which case you're claiming to have no solutions.

#

see this is what you should have said instead of "then no x is a solution"

lone heartBOT
#
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alpine sable
#

11 Brad travelled from his home in New York to Chamonix.
• He left his home at 1630 and travelled by taxi to the airport in New York.
This journey took 55 minutes and had an average speed of 18km/h.
• He then travelled by plane to Geneva, departing from New York at 2215.
The flight path can be taken as an arc of a circle of radius 6400km with a sector angle of 55.5°.
The local time in Geneva is 6 hours ahead of the local time in New York.
Brad arrived in Geneva at 1125 the next day.
• To complete his journey, Brad travelled by bus from Geneva to Chamonix.
This journey started at 1300 and took 1 hour 36 minutes.
The average speed was 65km/h.
The local time in Chamonix is the same as the local time in Geneva.
Find the overall average speed of Brad’s journey from his home in New York to Chamonix.
Show all your working and give your answer in km/h.

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#

@alpine sable Has your question been resolved?

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@alpine sable Has your question been resolved?

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cedar vault
#

if we are given a venn diagram like this and we are asked to find (in set notation) the subset which has no elements, can we say that (B n C) n A' c B?

cedar vault
#

or (B n C) n A' c C?

#

small c denoting subset and and n denoting intersection (since i dont have those symbols on my keyboard)

glass lichen
#

why are you using subset?

cedar vault
#

i dont know, the question asked us what subset has no elements

#

i gave that as answer on my exams

glass lichen
#

You make an intersection of disjoint sets

#

Or do they want you to write the section in the venn diagram that's empty?

cedar vault
#

the region in blue?

glass lichen
#

$B\cap C\cap A^c$ I believe

ocean sealBOT
cedar vault
#

so i gave that as an answer

cedar vault
glass lichen
#

??

#

the complement of A is A^c

cedar vault
#

yes complement

#

we call that prime here idk

#

anyways yeah

glass lichen
#

ok, well yeah

#

it's the subset that contains stuff in B and C, and not in A

cedar vault
#

okay okay

#

but

cedar vault
#

is that wrong?

devout summit
#

It's not necessary

cedar vault
#

hmm

devout summit
#

And once you wrote subset symbol, it became a statement

cedar vault
#

so i may lose points for that.. hmm

#

anyways, thank you

#

just had a doubt

#

.close

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#
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alpine sable
#

hi

lone heartBOT
alpine sable
#

When dealing with cubed roots and graphing them as functions

#

do i use the decimal form?

bleak ridge
#

Wdym by decimal form

alpine sable
#

well if my first input is x = 0

#

then my answer would be index 3 radical then radicand of 5

#

so to graph is my answer just x = 0 and y =5

bleak ridge
#

Is the +5 under the radical?

alpine sable
#

oh

#

no

#

ok nevermidn then thanks i missed that

bleak ridge
#

Reasonable

alpine sable
#

.close

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shell obsidian
lone heartBOT
shell obsidian
#

would the answer to a) be 6+6+6 = 18 ?

#

i'm not sure how to approach this

#

i'm sure it's just summing in some way but i can't figure out the right way to get answer to a

toxic rose
#

Usually you don’t add combinations, you multiply them.

shell obsidian
#

oh i see

#

summing would be viable only if there was one role to be elected i think

#

so 6P3 would be 120

#

is this the right approach

#

i assume it's just 6P3 if one role is already decided 🤔

toxic rose
#

One role is already decided, but for two different people.

#

So in some cases one will be chairman

#

And in the other half of the cases it will be another person as chairman

shell obsidian
#

okay thanks for the hint

#

i'll figure it out

#

can it be just 6x5 = 30

#

is it that simple