#help-0
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can you show a picture or screenshot of exactly what it says in the book
even if they used the word "equivalent" it's probably in an informal sense that you should not attach yourself to
if you insist
i mean like
the point this paragraph is trying to make is that it does not matter exactly how you represent natural numbers, so long as it is clear what represents what
like, it does not matter if you write the number 5 as 5 or V or 五 or cinq so long as you understand that these all mean the same thing
i'm going to go semi-formal here and say that in general for two systems to be considered 'the same' we need to have a way to translate between them that goes both ways and preserves all relevant information
Yes
thus my question is,
is the natural number is also "the same" with a one-side finitely long "chain" graph?
i mean, you can certainly number the vertices of such a graph with natural numbers in such a way that each vertex is connected to its successor
but is there some reason why you ask this
@gritty veldt Has your question been resolved?
Not really, just curiosity. A thought that pops up in my mind. That help me confirms my understanding.
Thanks!
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can you only apply this formula when the lim x-> a is same as the constant a?
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Compute $\int_0^2 \lfloor x^2 \rfloor,dx$ ... Idk where to start
KaiML
Compute $\int_0^2 \lfloor x^2 \rfloor\,dx$ ... Idk where to start
you don't know how to find the integral of x^2 ?
first, do you know how to find the intergral of x^2 ?
Yep
ok, so do that first
just indefinite first
ok, so this is a definite integral, so you don't need C
so now plug in your values. do you know how to do that?
they seemed to have ignored the "floor"
[(x^3)/3 - (x^3)/3], plug in the higher value for the first (x^3)/3 and then the lower value for the second (x^3)/3
huh
consider graphing y = floor(x^2)
Ok...
from x=0 to 2
maybe i'm misunderstanding the question, it looks to me like it's a definite integral problem? am i wrong?
note that 1^2 = 1
sqrt(2)^2 = 2
sqrt(3)^2 = 3
sqrt(4)^2 = 4
Yea It is but its a floor function
floor (x²) is discontinuous on the points √2 and √3 in the given interval, so you need to do a piecewise integral accordingly
Okay I graphed it, but not sure what to do next
1, √2 and √3* my bad
consider the relation between definite integrals and (signed) area under a curve
The definite integral is the area under the curve right? Seeing as the curve is itself in pieces, you need to add up the area of these pieces
after graphing the question is pretty much reduced to calculating the sum of areas of a few rectangles
So to say, split the integral into multiple smaller integrals that you can evaluate
Without worrying about the function being discontinuous
So I just find area of the rectangles and add?
Yep, that's what a definite integral does
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Is there any distinction between types (as in type theory) and sets?
@slim fog Has your question been resolved?
@slim fog Has your question been resolved?
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could someone help me with this problem Determine the remainder when the number 33725^1579 + 8465 is divided by 11.
i know i need to use some type of congruent method with modulus yet i dont see any similarities between the 2 numbers 33725 and 8465
Tried to divide by 11? If they are divisible by 11 no matter what power it's the rest by 11 is 0. Is 1579 divisible by 11? Try to see this sections theorems/definitions to see if something can help you.
They are divisible by 5 anyway but I don't see what this can help you.
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I need some help with these please
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what should i write for 6b? That slope and speed are the same?
For a distance time graph, the slope represents speed and can be calculated by dividing the distance travelled by the time it took to travel that distance
so the slopes for the two graphs represent the speeds across those distances
thus, the steeper the slope, the faster the car is going over that time period
make sense?
No problem yes it is
car 1's speed can be found as 60m/1h
and car 2's speed can be found as 80m/2h
which is 40m/h
kk tysmm
no problem 🙂
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In proving an equation is dimensionally accurate, we ignore constants. However with the equation v^2=u^2 + 2as we can include the '2'. Why is this?
@tawny jetty Has your question been resolved?
Context? Where did these equations come from? What dimensions are you talking about?
Disregard last question,
How would I answer the following question using arithmetic progression? I think I have to rearrange the formula for working out the sum of an arithmetic progression, but I am not sure.
The company find that the initial cost for producing a part is £450, each year the cost increases by £18.
Find the year in which the cost first goes over £600
It's a simple linear relationship
450+18x>600? solve for the lowest value of x that keeps the equation true
$C(y) = 450 + \sum_{i=1}^{y} 18 = 450 + 18y$
phlp
There's your arithmetic progression
@tawny jetty Has your question been resolved?
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why was this wrong?
Infinity - infinity is indeterminate
@native knot Has your question been resolved?
@native knot none of the above
Why ?
You should look for examples where you can't ansEr
ye i figured out what i did wrong
The hard one might be 1^infinity
after finding out the 7 indeterminate forms
also
why was this wrong? @velvet osprey
What did you do to answer ?
First all the intervals given are parts of R+
So you don't need to study the function when x<0
Then if you take the dérivativ of the functions when x>0 what do you get ?
You get 1/2 -cos(πx)+1 right ?
Soap
So
What can you tell of this function ?
The sign oscillate so you can't say much right ?
So I think what you did was right
Then you have to find out where your calculus misteaks were
so i have a question what if I was asked to determine for example [-1/3, 1/3]
what do I do then?
because at x = 0 its not continous?
No it's not
But it can still be increasing
You would have to do a variation tab
And look at where the first function lays beetwin -a and 0
For a certain a
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Can someone explain to me the result and how did you get it?
Use a calculator?
yeah ok but the calculator gives me a result while the books gives me another
Then you didn't properly type it in
There is a very painful and long winded way of doing this
@alpine sable Has your question been resolved?
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to do a differentiation of a function defined parametrically, you just do the derivative of the y function over the derivative of the x function right?
keto11
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Hi, Im learning about 3d algebra and Iam not sure what they mean by this question. Even after looking at the answer Iam a little bit lost:
Question: "List the 48 different possible ways that the 3D axes may be assigned to the directions “north,” “east,” and “up.” Identify which of these combinations are left-handed, and which are right-handed."
Answer:
Any specific choice that isn't making sense?
Im really confused about this "righthanded" and "lefthanded" coordinate system
Like the next 2 questions are about it and i got all answers wrong
even though I thought I finally understood it
You know what, ill watch some yt videos and clear it up for myself, thanks for the heads up on trying to help me solve it :)!
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How would I go about scaling this grid on the x and y axis without making the exponents and ! Extremely large?
Increase the y min and y max?
Kinda
So I want the x:0 and y:1 to be like x:0 and y:100
I’m kinda not so good at this kind of math so I’m not sure how to say it
So I think the zoom out one
Do second window and change them there I think
Wdym?
Ok ok wait, what I actually need is for the grid to be scaled on the x axis
I’m sorry about that
@eternal crest Has your question been resolved?
In Desmos you can choose the x min, x max, y min, and y max yourself
I’m not trying to use it in a calculator really I’m using it in Minecraft haha but I need the x axis to be scaled by 10 so like the wave would be wayyy longer but the graph not changing
You change the x min and x max to be 10 times larger or something
This is what I need help with
@eternal crest Has your question been resolved?
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It can be factored to (x^2+5)^2
You can break it up as partial fractions $\frac{ax+b}{x^2+5}+\frac{cx+d}{(x^2+5)^2}$
Sneaky
being a case of this last one: an irreducible quadratic raised to some power
Just found it in a video I see, I was trying to do it like the denominator was made of linear factors
That pic is really helpful thanks
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i can't tell if this is right or not, i'm not sure if i'm allowed to just integrate each term
are p1 and p2 vectors?
I'm confused because usually P would be a scalar and gradP would be a vector
isn't grad p supposed to be a scalar
oh, right
usually to reverse a gradient you just integrate one, get a +g(other variable) term, and integrate that one to figure out that extra term
that makes more sense, i think i've just screwed up the initial problem
trying to solve an euler equation and not really getting it
for fluid mechanics? yeah that's hard
yep, i love mechanics but i wish i knew about all the god damn integrals i was gonna have to do
by far my hardest class
thanks anyways
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Since the two systems are solved with different x values I can’t add them right?
you can add them yeah
Really?
Yes....
I believe u but damn
It's just 2 linear equations in A,B,C, and D... it doesnt matter where the equations came from.
I thought because the left sides for both systems are 1 but the right sides are different it wouldn’t be allowed
Thanks
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Hey there, basic question that keeps tripping me up
.
wheres the question lol
If i have a function that takes in n and n is in hundreds, how would I rewrite the function so that it just takes single values instead
Still writing it out lol
define single values
Yeah, fair enough lol
so you want n=1 to really become n=100?
Yeah, essentially
horizontal dilation
So just multiply n by 1/100?
$f(n)\to f(\frac{1}{100}n)$
Mosh
yep
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where's cos(1/sqrt(2)) coming from
$\frac{1}{\sqrt{2}} = \frac{1-\tan^2(22\frac12\deg)}{1+\tan^2(22\frac12 \deg)}$
ℝamonov
is all you really need
solve for tan^2(22.5°)
show work
wait up
Btw, $\sqrt{2}-1=\sqrt{3-2\sqrt{2}}$
Euclid31415
Inheritanc-e ♦
$\sqrt{3-2\sqrt{2}}=\sqrt{(\sqrt{2})^2-2\sqrt{2}+1^2}=\sqrt{(\sqrt{2}-1)^2}$
Euclid31415
Yes
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Can someone recommend good books for reviewing/wrapping up algebra II?
oh wrong channel
Ask in #book-recommendations
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nerd
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How can I get this into arctan
i struggle with getting things into their standard trig identify form when it comes to integrals
Where did you come up with x = 2u
4=2^2
So putting x = 2u will get 4u^2 + 4
In the denominator
Then you factor the 4
And are left with the arctan
if x = 2u, then shouldnt the denominator be written as 2u^2 + 4
not 4u^2
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can someone please explain how to do this to me
did u solve the asympototes
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Unfunny but, what is 69^420 x 420^69
Use a calculator
I dont have oneon hand and im too lazy to go on google
,w 69^420*420^69
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What will the value of x, if x = 5 mod 2
do you know what mod means?
if you divide two numbers the remained is the mod
so 5mod2 is the remainder of 5/2
so 2.5
no
the remainder is the amount that isn't divisible
2 goes into 5 two whole times, and has a remainder of 1
so 5mod2 = 1
oh
and if I have the 1 and the 5
can any questin be formed
what kind of question?
means with mod
how questions come
what question I gave you
thats just a example
I mean do we have simplification
or anything
5x = 4mod6
i'm pretty sure that if the number in the front is less than the number in the back (4<6) you just use the front number (4mod6 = 4)
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Hi
Im so confused about this
I get the part about the restriction of the domain
so we have to find the other angle that has the same value but is in the doman
so how did we go from -10pi/9 to pi/9
so youre confused on the reference angle part?
is that a reference angle?
yes, they have the same reference angle
arcsin has the domain restriction [-pi/2, pi/2]
by knowing they have the same reference angle
we memorized the unit circle
not this though
i jsut know anything /6 or /3 or /4 or /2
don't need the unit circle for this
-10pi/9 is pi/9 away from pi, which is the x axis
what if it was -11pi/9
reference angle if 2pi/9
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I know part A is 0 by Green's Theorem and that for B, you can't use Green's theorem since the denominator (x^2+y^2) is 0 at the origin. How do you do part C?
someone in my class asked the professor and got a hint about using the region between c1 and c2 (since of course one of them has to enclose the other since they are not touching or intersecting). not really sure what he means yet
@north wren Has your question been resolved?
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3x - y = -5
3x + y = -2
Came up with the coordinates (0,-5) & (1.66,0) B. (0,-2) & (-0.66, 0)
How Do I verify my answers for Linear Equations with 2 variables? :DD
feels like Im doing something wrong
how'd you get 4 points
erm, 4?
(0,-5) & (1.66,0) B. (0,-2) & (-0.66, 0)
to check, plug in your coordinates for each variable in each equation and verify both equations hold true for each point. for example
why are you randomly setting x and y to 0
but yeah there are only 2 equations so you should only get 1 point of intersection
actually in general w/ n equations and n unknowns you should get 1 solution
for linear systems
how exactly?
3(0) - (-5) = -5?
setting x or y to 0 can get you the x and y intercepts of the individual lines but that does not help you determine the solution / point of intersection in any way
3(0)+(-5) does not equal -2
so (0,5) is not a solution since it doesn't satisfy both equations
wait but the ex. had 4 points
looks like they were finding points of intercept
those questions are asking for different things
yeah
it was not clear what you actually wanted but writing just
3x - y = -5
3x + y = -2
would usually imply that you want the point of intersection
and there are lots of ways to do it but one of them is elimination
in this case you can just add the equations together
to get 6x=-7
also leave stuff in exact form
so the x coordinate of the solution is -7/6
e.g. leave 1/3 as 1/3 instead of writing 0.33 (which isn't the same as 1/3)
original was
3x - y = -5
y - 3x = -2
had to turn it into general form, plus the instruction indicated to use graphing method --
"graphing method" is a bit vague but i assume they mean just graph the lines and then see where they intersect. the intersection point of the lines is the solution to the system
Id prefer to use decimals in this case since i have to graph it
what you may have been doing beforehand was finding the 4 points where each line intercepts the axes
which could help you graph the lines
depending on how you're doing this
you could have each gap on your diagram represent 1/3 units here
which allows you to be a lot more precise
am getting lost
lets roll back
so my coordinates are wrong right? so I must be doing something wrong
yeah we've been laying it all on p quick lol
well
those 4 coordinates you gave at the beginning
some of the intercepts are wrong
are the x and y-intercepts of each of the 2 equations
yes
i didn't check if they are right
but if they aren't it might just be an arithmetic mistake
assuming that 1.66 is supposed to be 5/3
check your signs
the thing that's confusing me i think
is why would you need to find the intercepts to solve the system
it goes
3x - 0 = -5
3x = -5
3x 3x
-5/3 = -1.66
wdym by
3x = -5
3x 3x
crossing out 3x by itself
and dividing -5 by 3
so I can graph it?
well then overlooking that questionable notation to represent that, you should've indicated division by 3
-5/3 is the correct x intercept for that line now
yes. attempt to graph it, make your graph sufficiently large to be as precise as needed
yeah although still wouldn't you need to algebraically solve the system to find where they intercept
can't just look at the graph
if your graph is good enough, you can
the graph will show the location of the point of intersection (i.e. the solution of the system)
welp ure right on this
welp I got a jist of how to recheck
i guess
so thanks
:DDD
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I guess i need help w this?
Just need to find H length. not even sure if it's possible . I feel like it is. All that is known is circumference. LINE DE = in length to ARC SE +.05cm
@alpine sable Has your question been resolved?
@alpine sable It's possible once you find the length of DE
If r is the radius, the length h is
r^2 + DE^2 = (r+h)^2
which gives h = sqrt(r^2 + DE^2) - r
OK so basically its not possible with given information for sure ?
I think you just need the angle DCE
Yes lots of ways to do it w one other piece was really hoping there was a way but glad there isn't
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yy
Please how i can help u?
tim were doing a experiment about spring, heres the statistic he gets from the experiment,
the external force(gw) :20, 40 ,60, 80, 100
the total length of the spring(cm) :4, 6, 8, 10, 13
the original length of the spring is 2 cm
the question asks for the x
i got 27.5g as the weight, but its wrong
can someone point it out the error i have made
it relates to hooke's law btw
<@&286206848099549185>
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Help
send qn
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I would like to move an object which is in a 3D world in the direction in which it is looking. I know that there are formulas for this but I just can't find anything about it. I already have found a formula for the x and y axis which I made a method for:
public Vector3d vecFromRotation(AircraftInstance aircraftInstance, double speed) {
float f = MathHelper.cos(-aircraftInstance.yRot * ((float)Math.PI / 180F) - (float)Math.PI);
float f1 = MathHelper.sin(-aircraftInstance.yRot * ((float)Math.PI / 180F) - (float)Math.PI);
float f2 = -MathHelper.cos(-aircraftInstance.xRot * ((float)Math.PI / 180F));
float f3 = MathHelper.sin(-aircraftInstance.xRot * ((float)Math.PI / 180F));
return new Vector3d((double)((f1 * f2) * speed), (double)(f3 * speed), (double)((f * f2) * speed));
}
But I need it for all 3 axis (x, y, z).
look at the documentation of what is inside aircraftInstance ?
thats my own class lol
I am not sure how you can encode the orientation of a plane in 3D with just two numbers xRot and yRot
and what do those mean ?
Well I only want to get a direction from my rotation. I have the x y and z rotation.
what is an x rotation
Yaw, pitch, and roll rotations
probably the direction you want is one of the three columns of the matrix
thx
I would just use matrices or unit quaternions if I were doing 3d stuff
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Why is a shift cipher "limited to 26 keys"? when I try 40 as a key it works fine
that's just key 14
Very interesting
And how is -n mod m done exactly?
<@&286206848099549185>
So it seems (z * x + a) % x == a % x explains both questions
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channel is occupied
Ok
we need to multiply both sides by something that will get us 9t/7m
i would do (9/4) / (7/5)
this would also be (9/4)(5/7) = (45/28)
so multiply both sides by that
and simplify the fractions afterwards
Yeah we get 45/28
yes, multiply both sides of 4t/5m = 7h by that
I hate these kinds of problems
the only way i can make this easier for you is if i do it myself
and i can’t do your work for you
i’ve already said all i have to say
treat it as a physics problem
ignore them
or don't
all you have to do is multiply both sides by 45/28
i mean don't ignore me is an option
there is no need to treat this as a physics problem, that sounds like you’re over complicating it
overcomplicating is what they asked
I see no issue with overcomplicating a problem, it's not a sin
5 men together have 4/7 t/h of power. Divide it by 5 and multiply by 7
means 7 men have 4/5 t/h
9 / (4/5) = 45/4 hours
must be
GENIUS ME
YA YAY
Look, genius I found a way!
- Multiply time with 1st value of men
- Divide with new value of Men
- Divide with old value of Trenches
- Multiply with new value of Trenches
And boom!
You got the answer!
I'mma LEARN Those ways by heart cuz sequence of values will be same~
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How would I go about solving X in this equation
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cross-multiply
Close
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hi i have a quick question about probability. if i have a coin and get Heads 4 times in a row or if i get 2 Heads and 2 Tails, the probability is the same right? its 0.5^4 either way
Assuming it's fair and the tosses are indep then yes
All outcomes are equally likely
Or no, cause there's more way to get HTHT
@alpine sable Has your question been resolved?
Yeah thats what im wondering
But if its an ordered without repition ?
If you have 4 coins and then get heads of tails
Is it a binomial probability??
when you say 2 heads and 2 tails, do you mean getting 2 heads and then getting 2 tails
i.e. does order matter
if order does matter, then yes the chances are the same
if order doesn't matter then 2 heads and 2 tails has a much higher chance than 4 heads
because 2 heads and 2 tails could be HHTT, TTHH, HTHT, THTH, HTTH, THHT
each of those individually has a .5^4 chance, so getting 2 heads and 2 tails is 6 times as likely as getting HHHH
although again if you just mean HHTT then yes they're equally likely
@alpine sable
Oh that makes sense yeah so if its ordered then it has to be that exact order which means theres one possiblity as opposed to multiple if its not ordered
Thank you
yup
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Hi, i'm trying to solve this expression but i'm having trouble finding the right moves and i've gotten completely stuck on what to do. The circled expression is the end goal.
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how do i do this
It's secant or cosecant
yeah
i dont know 1) how to differeniate or 2) apparently the entire rest of the problem because desmos says my equation is wrong
Sec and csc just differ by a phase shift pi/2, like cos and sine
right but how do i know which is which in this scenario when there are other phase shifts
Sec has a minimum at x=0
There are multiple answers to a question like this you can decide to write it as a secant or a cosecant.
The "vertices" of the parabola like shapes are where the secant/cosecant part of the function takes on 1 or -1
The fact that y achieves 4/-4 at the "vertices" tells you its of the form
4*sec(something)
Or 4*csc(something)
Extrema is more apt than vertices imo
Yes i agree but I'm just using the term " vertex" as it's a quick analogue to a familiar graph
With quotes to boot xD
sorry but i really dont understand what your saying lol
so it doesnt matter if i choose sec or csc
okay so now for that question say i want to assume its csc, how do i find the equation
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How th do i fo 8 iii?
Are u able to visualize folding the rectangle with square-cut corners to form a cuboid with open top
i thought they mean the area of this shape is 11x^2 + x -2
im an idiot
its this isnt it?
shaded regions are cut out
the square at the very bottom, where did that come from
open cuboid would have just 5 faces, since 6th face is open/void
ok
so for volume u just take product of the length, width and height
thanks for the help 🙂
cursed emoji
🙂
ffs
its supposed to be a emoticon
anyway ima go
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So far I've used conservation of momentum to get velocity of the red ball after to be 4u(-i+j) and the velocity of the white ball after to be u(2i+4j)
Then taking the line of centres to be -i+j as per the question I've tried to resolve my velocities to use Newton's experimental law
Which gave e=(4u+root2 u)/(5root2 u)
Does anyone see where I've gone wrong
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Hi I am working with graphs and using "fully connected" graphs as in the image.
There are 4 levels between nodes 1 and 200, and 4 in each level. I need to find the total ammount of paths from 1 to 200 using this graph, both unidirecionally and bidirectionally.
I figured out the equation for the number of paths for unidirectional(can only go to a node in a higher level) is (number of nodes per level)^(number of levels), ex: in the picture, the total ammount of paths is 4^4=256. I just need help to find the equation for the number of paths if the graph is bidirectional. I have made the following table with some values if its any help.
@strange chasm Has your question been resolved?
what does number of nodes per level mean
@small stag im making a picture for you
Green is level 1, Blue is level 2, Pink is level 3 and Yellow is level 4
Number of nodes per level is 4 in this case
All levels have the same ammount of nodes
@strange chasm Has your question been resolved?
<@&286206848099549185> any help here?
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will someone please help? Thank you so much!
@last sinew Has your question been resolved?
is the last one the incorrect one
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hello may i ask question for this question, i cant seems to get the value of x
its prolly 30
is TSUV a trapizoid
it is
cause then x is just 38
i thought itll be 30
cause UV and TS are parallel
meaning angle UTS and angle UVT are alternate interior angles
is this question possible?
um
then since angles in a quadrilateral add up to 360 degress you can find x
wait explain why it is 68
uh coz OT and OU is the radius
ahh I was about to write that down lol
then its isoceles triangle
yeah cause it's the radius so they form two isosceles triangles
I couldn't figure out why I wasn't getting an answer until I saw I wrote 38 * 2 = 72 lol
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hi
Okay, so for this you could try solving it in your head, but it's annoying and I think the point of this is teaching you equations, isn't it?
First of all, the rule of thumb is to always set your variable to be the thing you actually want to know
In this case, x = leo's current age
Can you express Pat's current age in terms of that?
??
Ok yeah, do you agree p=x-5 is saying the same thing?
ya
You don't want to add more variables, it'll make things more complicated
So try to express the various quantities in terms of your unknown
Anyway
Now, can you write down "twice Pat's present age" only using x
that's twice leo's current age
close, but be careful about your multiplication
(x -5) times 2
you meant to write 2(x-5)
which is 2x-10
but yeah
correct
so now, what's "Leo's age plus 10"?
uhh
no tricks
remind me, what is x?
leo
ok yeah
so just x+10
now, what does the problem tell us about these two quantities?
2x-10 = x+10
So Leo is 20 years old
And let's just quickly check
Pat is 15
In 10 years, Leo will be 30=15*2
oh ok
In summary, here's the method :
so is 20 the answer?
We set x to be our answer and we found x=20
- Set your unknown to be what you want to find
- Express all of the quantities involved using x, and always think about what x is and if what you're writing makes sense
- Now, the statement of the problem should tell you some of these are equal. Now you can solve and get the answer.
okay ty
But yeah, I can't stress this enough, don't wing it
What you're writing has to make sense to yourself
After that, math works because it's a universal language for things that make sense
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Hi
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you want to solve for x and y in terms of m?
@untold sequoia
...do you have the instructions for the problem as it appears in your textbook?
maybe it'll be easier to see what your goal is
even if it's in another language.
okay
i can tell you for sure that you have made it way, way, way more complicated than it needs to be
it seems to have escaped your notice that this is a system of linear equations, and so can (and should) be solved as a system of linear equations
yeah but they're linear in x and y
and your work doesn't respect that
again
you've made things more complicated than they need to be
from 6x + (m-1)(m-1 - mx) = 4 you could have expanded it as 6x + (m-1)^2 - m(m-1)x = 4
and then you could have grouped the x terms as [6 - m(m-1)]x + (m-1)^2 = 4
so you have (6 + m - m^2)x = 4 - (m-1)^2
do you not agree that this equation is much much easier to solve for x than the nonsense you came up with
so you can clean up a bit more here
to get (m^2 - m - 6)x = (m-1)^2 - 4
which turns into (m-3)(m+2)x = (m-3)(m+1)
so you have three meaningfully different cases: one where m=3, another where m=-2, and a third where m is neither 3 nor -2
do you understand how to continue from here?
no
the case m=3 is very different from m=-2
it's not clear what you're talking about right now
you are not making it clear which case you're claiming to have infinite solutions and which case you're claiming to have no solutions.
see this is what you should have said instead of "then no x is a solution"
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11 Brad travelled from his home in New York to Chamonix.
• He left his home at 1630 and travelled by taxi to the airport in New York.
This journey took 55 minutes and had an average speed of 18km/h.
• He then travelled by plane to Geneva, departing from New York at 2215.
The flight path can be taken as an arc of a circle of radius 6400km with a sector angle of 55.5°.
The local time in Geneva is 6 hours ahead of the local time in New York.
Brad arrived in Geneva at 1125 the next day.
• To complete his journey, Brad travelled by bus from Geneva to Chamonix.
This journey started at 1300 and took 1 hour 36 minutes.
The average speed was 65km/h.
The local time in Chamonix is the same as the local time in Geneva.
Find the overall average speed of Brad’s journey from his home in New York to Chamonix.
Show all your working and give your answer in km/h.
@alpine sable Has your question been resolved?
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if we are given a venn diagram like this and we are asked to find (in set notation) the subset which has no elements, can we say that (B n C) n A' c B?
or (B n C) n A' c C?
small c denoting subset and and n denoting intersection (since i dont have those symbols on my keyboard)
why are you using subset?
i dont know, the question asked us what subset has no elements
i gave that as answer on my exams
You make an intersection of disjoint sets
Or do they want you to write the section in the venn diagram that's empty?
$B\cap C\cap A^c$ I believe
Mosh
no, i dont have the question rn since i sat for the exam a little bit over 6 hours ago but yeah we had a venn diagram like that and i could only notice B intersect C intersect A prime not having any elements
so i gave that as an answer
A^c is A prime?
It's not necessary
hmm
And once you wrote subset symbol, it became a statement
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hi
When dealing with cubed roots and graphing them as functions
do i use the decimal form?
Wdym by decimal form
well if my first input is x = 0
then my answer would be index 3 radical then radicand of 5
so to graph is my answer just x = 0 and y =5
Is the +5 under the radical?
Reasonable
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would the answer to a) be 6+6+6 = 18 ?
i'm not sure how to approach this
i'm sure it's just summing in some way but i can't figure out the right way to get answer to a
Usually you don’t add combinations, you multiply them.
oh i see
summing would be viable only if there was one role to be elected i think
so 6P3 would be 120
is this the right approach
i assume it's just 6P3 if one role is already decided 🤔