help-0

[lone heart]

@tight locust Has your question been resolved?

[formal sentinel]

#❓how-to-get-help

[remote heron]

work?

look at a derivation

[tight locust]

Yeah how does it work lmao

[remote heron]

i dont understand what you mean

its a result of using a sample instead of a population

if you look at a derivation and chug through it, youll see where it comes from

[tight locust]

Why does multiplying the biased estimator by n/(n-1) produce an unbiased estimator

[remote heron]

its a little involved but its mostly just series

[tight locust]

Thanks for not answering the question at all.

[remote heron]

I'm not sure what to tell you lol

have you tried looking at a derivation?

[tight locust]

Yeah but i don't get it

[remote heron]

which part?

multiplying by n/(n-1) is just a fancy way of saying "switch the denominator"

[tight locust]

Something about E

What is E(something)

[remote heron]

the expected value

there are lots of different derivations

which one are you looking at

http://math.oxford.emory.edu/site/math117/besselCorrection/

this one begins by explaining the operators a bit

[tight locust]

Oh this is a good explanation

[remote heron]

i can say from having done it that its not particularly enlightening to be able to derive it

if you can convince yourself to believe it without seeing it plop out yourself you can save yourself some time

at least i didnt find it really helpful when i did it in stats 101 but ymmv

it was good practice, at least

[tight locust]

But why does E[x_1] = μ

[remote heron]

thats your expectation of any sample

you reach into a big collection of things

the thing you expect to grab is the thing which is most present

or thats maybe not said very well

like if you have a big bag of money, its mostly 1's, but a couple 5's

and you grab a bill without looking, you probably expect it to be about 1

[tight locust]

Ok sure. So you expect the mean of any random sample to be close enough to the population mean

One more thing

Where does 1/n^2 come from?

[remote heron]

its a common property of variance

look up "linearity of variance"

[tight locust]

It seems like an extra factor of n has been added to the denominator

[remote heron]

maybe think of it like

variance measures the spread of the data

and you can maybe think of that like

that 1/n on each x

its really squishing everything together

it severely reduces the spread of the data

[tight locust]

Right.

So where does the extra factor of n come from

In the denominator

[remote heron]

you can actually derive that too :p

although id say like dont derive something if it seems intuitive

https://www.probabilitycourse.com/chapter3/3_2_4_variance.php

[tight locust]

Doesn't really seem intuitive to me haha

[remote heron]

its theorem 3.3 here

honestly uhh

i mean it can help to think about moments

if you have any intuition from physics or calculus

or it was helpful to me

but you can maybe even think of it like uhhh

loosely maybe inverse square?

picture a bunch of people standing in a crowd in a big city square, and the smallest box you need to draw to contain them all

if everyone moves some distance towards the center, how is that gonna change the size of the box?

is it linear? doesnt seem reasonable, right

[tight locust]

Ah i see

I can't even follow this proof lmao

[remote heron]

like reduce the side of a box by a factor of 1/2 what does it do to area

yea shoot for intuition lol

[tight locust]

What is μ_Χ

[remote heron]

its defined at the top

i would say these are derivations that are good to do though 😄

these linearity and stuff

but bessels correction IDK

[tight locust]

There's too many thing to prove to prove the thing you want to prove

[remote heron]

yea since proving stuff is more involved than like

idk if you guys arent using this notation in your course it may be overload

[tight locust]

Nah lol nothing close to this

Just a list of formulas for calculating p values and confidence intervals

Stuff like that

But I find the computation aspect really boring and tedious. There's a lot of interesting math underneath it though

Like just looking at all these weird distributions like the pdf for the t-distribtion it makes me wonder how anyone would even think of that

[remote heron]

yea

that stuff was not like

interesting to me or helpful or anything

i did enjoy bessels correction proof but it didnt help me understand anything

honestly the only good thing about my second stats course was learning how to program

[tight locust]

I mean I like knowing how to compute p values but I don't like doing the same calculation 50 times for hw

[remote heron]

it gets better

well idk about stats but in general math classes get better lol

and if it gets worse, there will come a time you are praying to be doing the hw you have now 😄

my first stats teacher did it right, which was using python and R and stuff to immediately farm off everything you could by hand to a computer

to get more immediate like

vague question -> representative data -> computer chugging maths -> answer pathway

idk if something like that is accessible to you

but a lot of tools are prebuilt

[tight locust]

Haha. I'm only allowed to use my calculator on exams though

I've started making programs to handle all that

Programming on a TI84

[remote heron]

lol

[tight locust]

It doesnt have a keyboard even

[remote heron]

could be worse

on my prob exams now they only let us have 4-function

like these

[tight locust]

Lol what? What's the point of restricting your calculator to that

[remote heron]

theyre afraid someone is gonna use their calculator to check their answers to integrals

doesnt make sense right

[tight locust]

You can still technically do that

[remote heron]

sure

[tight locust]

Reimann sum or smth

[remote heron]

reimann style

ye

[tight locust]

Wait there's no exponentiation even?

[remote heron]

im exxagerating a little bit lol

ill try to find the one they give us

man idk its some shitty scientific calculator

like the ones they used to give you in middle school they keep in those shitty plastic bins with the handles

its just annoying since they dont have any stats functions

doing binomial coeffs by hand sucks

doing anything by hand sucks

[tight locust]

haha i'd be fucked without my programs

i don't even remember what the standard error is off the top of my head

[remote heron]

yea my exam score sucks since our calculator stuff

i like to check everything

i mean i just uhh

i dont get it

not letting ppl use technology makes less and less sense

as time goes on

you oughta give them a calculator and a offline computer with a IDE of their choice

[tight locust]

full wolfram alpha access

as long as you can remember what the formula for the distributions are

alright thanks for the links

[remote heron]

no problem

if you get hella stuck and really absolutely have to finish

i do have notes on that proof of the correction somewher

i think

[tight locust]

i've really been looking for a more complete explanation of everything

[remote heron]

but i dont think its worth it fwiw

you need a good teacher

or a good tutor

[tight locust]

nah i'm just doing this to understand it. i'm kinda ocd about knowing the logic behind every single formula

it's a curse

[remote heron]

bro that used to be me lol

then you get into a proofs based class

youll realize i think, or at least i did

the proofs uhh

well idk

the logic isnt hidden in the proof or the derivation

i just wanted the intuition

proofs and derivation arent a good source of it, usually

[tight locust]

yeah i see what you mean.

sometimes the proof obscures the structure behind it

[remote heron]

id say again uhh

if you like physics and calculus

look into moment generating functions

it allows porting some intuition about like

well classical motion a little bit from physics into statistics

in a weird, not entirely analogous way but it helps

[tight locust]

[remote heron]

https://gregorygundersen.com/blog/2020/04/11/moments/

i like this page 😄

[lone heart]

@tight locust Has your question been resolved?

[vale wigeon]

@tight locust can you say once again what your question is

[jaunty shard]

<@&286206848099549185>

The average (arithmetic mean) test score for all the students in a class is 84. The average score of m boys in the class was 79, while that of n girls was 87. What is the ratio of m to n

Can someone help???

[alpine sable]

The class consists of m boys and n girls

[jaunty shard]

and?

[alpine sable]

That's all you need

You have average of m = 79

Average of n =87

Average of m+n = 84

[jaunty shard]

it is asking ratio then l will divide 79 to 87?

[alpine sable]

Wut

No

[jaunty shard]

then can u say how to solve it

<@&286206848099549185>

[vale wigeon]

@jaunty shard @alpine sable please move to a different, unoccupied channel.

[jaunty shard]

there is no unoccupied channel

endtimes is here for 1 hour and not asking anything

whatever

[lone heart]

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[lone heart]

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[woven zephyr]

used double angle and got 6sinxcos60 + 6cosxsin60 = 8sqrt(3)cosx

[woven zephyr]

what do i do next

[lone heart]

@woven zephyr Has your question been resolved?

[woven zephyr]

<@&286206848099549185>

[alpine sable]

you know values of cos60 and sin60 to simplify further

[lone heart]

@woven zephyr Has your question been resolved?

[woven zephyr]

cos 60 =1/2 and sin60 = sqrt(3)/2?

[alpine sable]

yes

[woven zephyr]

so replace it the sinx and cosx in 6sinxcos60 + 6cosxsin60 = 8sqrt(3)cosx?

[alpine sable]

?

replace cos60 by 0.5 and sin60 by sqrt(3)/2

[woven zephyr]

yeh i meant that

so would i get 3sinx+3sqrt(3)cosx = 8sqrt(3)cosx?

[alpine sable]

yes

[woven zephyr]

what do i do next?

[alpine sable]

cant you see?

[woven zephyr]

no

[woven zephyr]

@alpine sableu there?

<@&286206848099549185> can anyone help?

[woven dock]

next step will be move the terms witg cos(x) to one side, and sin(x) to the other side.
After that you might wanna get a tan(x) using tan(x)=sin(x)/cos(x)

[lone heart]

@woven zephyr Has your question been resolved?

[woven zephyr]

so u get tanx = 5sqr(3)/3?

[woven dock]

Lemme check

Yea, that should be it.

[woven dock]

And of course, you'll have two answers for this.

[woven zephyr]

so add 180 to this?

[woven dock]

If you did find the angle in 0° to 90°, yea.

[woven zephyr]

thank for that i got it

.close

[lone heart]

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[rigid pike]

Hey I have a question in maths

[alpine sable]

Send it

[rigid pike]

How do i find the maximum gradient for this function

[chrome salmon]

Find f'(x)

[rigid pike]

f'(x)=-5e^(-x)

this is the f'(x)

what do i do next?

[glass lichen]

That's the gradient..

[rigid pike]

thats it ?

[glass lichen]

yep.

[rigid pike]

These two points should be the gradient for the function i sent above, however, I'm not sure how to work it out by paper and pen

[glass lichen]

you mean gradient of the secant?

[rigid pike]

do you know the graphing app desmos?

[glass lichen]

yes....

However I asked a question to you

that had nothing do w/ the fact you're using desmos

[rigid pike]

no

not that

[glass lichen]

then I have no clue what you're referring to

if not the derivative or the gradient of the secant.

[rigid pike]

it's the derivative

[glass lichen]

yeah.

[rigid pike]

https://www.desmos.com/calculator/ql39zhvg8w

[glass lichen]

Then you showed a random snapshot of desmos saying 2 points "should be the gradient" which implies slope of the secant

[rigid pike]

we haven't studied the slope of secant yet

[glass lichen]

I highly doubt that

[rigid pike]

I'm in year 11

[glass lichen]

You learn slope of lines before calculus

[rigid pike]

I'm really not sure.

All I know is that I had to design a slide and I used 3 functions doing so. Then after deriving and doing everything to calculate it. I need to find the gradient for each function

[glass lichen]

Ok

then you're done.

[rigid pike]

I've highlited the bits

can you see it?

[lone heart]

@rigid pike Has your question been resolved?

[chrome salmon]

I dont think anyone will download it

[rigid pike]

I'm just struggling with this question if you can read a bit up

you'll see it 😦

[chrome salmon]

Can you send ss

[rigid pike]

okay

So this is the function and I need to find it's maximum gradient

[chrome salmon]

But they haven't written that in the question

[rigid pike]

It says finding the gradient for function 1 🙂

[glass lichen]

and like I said already... you're done that question

[chrome salmon]

Then f'(x) is all

Don't go any further

[rigid pike]

f'(x)=-5e^(-x) that's it

i don't need to sub in the 3 or 1 into x?

[glass lichen]

You asked find the gradient for that function

You're done after that

[rigid pike]

I'm sorry I'm just so nervous about it

what about this one?

[gray isle]

as usual start with differentiation

[raven rover]

Gradient is essentially slope, for one dimensional functions, I believe

Therefore, if you’re trying to maximize the slope, or derivative (aka f’(x)), then you’d need to find where the second derivative = 0, and the third derivative is negative.

This is finding maximum values for f**’**(x)

[lone heart]

@rigid pike Has your question been resolved?

[raw shard]

note that that function can only be differentiated twice

the third derivative is always 0

[lone heart]

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[alpine sable]

what would be the set W1∩W2 ? I need it to find a basis of W1∩W2. Please if anyone could help. I already worked on the bases and spans of W1,W2 and found them.

[alpine sable]

I am working on it and found out that dim(W1∩W2)=1. do I do it correct?

W1: $W_1 = {(x,-x,z,-z); x,z \in \bR} \ = {(x,-x,0,0) + (0,0,z,-z); x,z \in \bR} \ = {x(1,-1,0,0)+z(0,0,1,-1); x,z \in \bR} \ = span{(1,-1,0,0),(0,0,1,-1)}$
W2:I used ( 0 0 1 0 ) as e3 and ( 0 0 0 1) as e4 (as my coordinate vectors) and find out that the basis is {( 0 0 1 0), ( 0 0 0 1)}. Also ofc dim(W1)=dim(W2)=2

[ocean seal]

just_dom

[woven dock]

Hint: you can rewrite W_2 in the form of W_1 instead of just span{e_3,e_4}

[woven dock]

And this makes sense too if you can find the intersection between span vectors.

[alpine sable]

I think the intersection between span vectors is the basis ( 0 0 1 -1) = dim(1)

[woven dock]

Yea, me too

[alpine sable]

yeah but how can I show this basis that I denoted before? like is there any definition of a general set W1∩W2 or sth to help me?

[woven dock]

W_1:= (x,y,z,t) with x+y=0,z+t=0
W_2:= (0,0,z,t) for all z,t in F

Since it's an ∩

We can concluded x+y=0 and (x=0 and y=0)

Similar for z and t

[alpine sable]

and how from this I go to the part with the basis? ;/

[woven dock]

Hmmm for this I'm not sure. I don't know how to use the basis to get this conclusion.

[alpine sable]

but we sure dim(W1∩W2)=1 is right? like I can see it

[woven dock]

Since we can find one vector to span the entire W1∩W2, I guess the dimension is 1

[alpine sable]

how do I find that vector?

[woven dock]

This?

[alpine sable]

yes

[woven dock]

I used this method.

[alpine sable]

for the z+t=0 means z=-t?

[woven dock]

Yea

So we have z=-t and (t∈F and z∈F)

Ooo

In R

[alpine sable]

what is F here?

[woven dock]

Sorry

R

My bad

[alpine sable]

can u show me the step of how we got the basis bcs my brain will explode

[woven dock]

Okay then we have x=y=0, z=-t for all z∈R

(0,0,z,-z)

Then we have (0,0,1,-1)

For the basis

Not sure if there's any intermediate steps not written

[alpine sable]

why u put z=1?

[woven dock]

Since it's z∈R and {1} span R?

I'm not good with intermediate steps, do you have it on your notes or something?

[alpine sable]

could not be anything else than 1 than?

yes I have a lot of notes, which one u need?

[woven dock]

The z can be anything

You can do even

(0,0,1/√2,-1/√2)

[alpine sable]

so there will be a lot of possible bases of W1∩W2 but the dimension will be always 1

[woven dock]

Yep

[alpine sable]

oke thanks

.close

[lone heart]

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[sick ledge]

Please help idk how to prove by maths

[sick ledge]

Ping if you have answer cuz I gtg now

[lone heart]

@sick ledge Has your question been resolved?

[lone heart]

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[silent glacier]

.reopen

@alpine sable you said that sinx+cosx=sqrt(2) * sin(x+pi/4)... Is that a standard equation that is just generally true?

[alpine sable]

yes

[silent glacier]

ohh

i havent learned it yet though

so is there another way to solve it without using this or not?

[alpine sable]

what have you learned so far?

[silent glacier]

the basic equations like: sin^2x + cos^2x = 1 , -1≤cosx≤1 (and the same for sin)

[alpine sable]

sin^2x + cos^2x = 1
(sinx+cosx)^2-2sinxcosx=1
(sinx+cosx)^2=1+2sinxcosx
sinx+cosx=sqrt(1+sin(2x))

| sqrt(1+sin(2x) | <= sqrt(2)
sqrt(1+sin(2x) <= sqrt(2)
1+sin(2x)<=2
sin(2x)<=1

@silent glacier

[silent glacier]

hmm

ohh

that makes sense

okay i got it thanks

.close

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[quaint pine]

so |x-2| >= 4

[quaint pine]

does this mean x-2>=4 AND x-2<=-4

or

[silent glacier]

or

[quaint pine]

x-2>=4 OR x-2<=-4

how did u know

[silent glacier]

lol

[quaint pine]

like

how can u prove it

[smoky cloud]

x-2>=4 or x-2<=-4

[silent glacier]

if x-2>=4 AND x-2<=-4 then
x>=6 AND x<= -2 which is obviously impossible

so it's or

[quaint pine]

ok thx guys

.close

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[potent sinew]

How do I calculate the sum of this?
Sum[Sqrt[i],{i,1,n}]

[alpine sable]

I don't think you're gonna like the closed forms of this

[smoky cloud]

bro is such summations possible ?

[alpine sable]

Yea it immediately reminds me of polylogarithm

You can then relate it to hurwitz zeta

But it doesn't give you anything useful

[smoky cloud]

ya

[alpine sable]

What I meant initially is: there is a closed form but it is not nice

[potent sinew]

can you show it?

[alpine sable]

https://en.m.wikipedia.org/wiki/Harmonic_number

See under generalisations

[lone heart]

@potent sinew Has your question been resolved?

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[fallen frost]

How would I solve this question? I'm not sure where to start with it

[fallen frost]

.close

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[white palm]

Bruh

B C and E

They represent a function of x

I don’t understand

Most of them are functions of x

[jagged trout]

https://www.mathsisfun.com/sets/injective-surjective-bijective.html

[white palm]

I can’t find my answer

[white palm]

Can u elaborate?

[jagged trout]

It don't look like that D is bijective

[white palm]

Yeah I'm stupid asf

I read the question

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[fallen frost]

How are there 2 lengths of PT here? I can only find 1

[fallen frost]

I worked PT out to be 4root11

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[opal mesa]

how can i prove this limit converges without using the p test

and without using the limit

just purely with the comparison theorem

[worthy urchin]

Well 1/x^2 is convergent

You have to use the theorem that says absolute convergence implies convergence

[opal mesa]

so you can say 1/x^3 needs to be less than equal to 1/x^2

[worthy urchin]

Yes

[opal mesa]

perfect

thanks bro

[worthy urchin]

no worries

[opal mesa]

.close

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[rotund osprey]

what is the intersection of the asymptotes of a conic section?

[rotund osprey]

i know how to find it and all but I just dont know what it has to do with the conic section

[lone heart]

@rotund osprey Has your question been resolved?

[rotund osprey]

<@&286206848099549185>

[alpine sable]

I'll assume you know what an asymptote means, I hope this illustration helps to clear out the idea.

[rotund osprey]

Yes I do

but lets say you have a Parabola and you find the asymptotes

does their intersection have to do something with the parabola

like that point C

I found it

thats also the point where the axes of the conic section intersect

.close

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[edgy quest]

(x-6)(x+3)=(x-5)(x-2)

[edgy quest]

x=?

[hushed condor]

x² -3x -18 = x² -7x +10
4x -28 =0
4x = 28
x = 7

[buoyant kayak]

don't do people's work for them

[lone heart]

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[upbeat laurel]

Do you know L'Hôpital?

like, the L'Hôpital rule?

[lone heart]

@earnest charm Has your question been resolved?

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[alpine sable]

Hi

[alpine sable]

i need help for advanced mathematics

is it here where i can write my question ?

[buoyant kayak]

yep

[alpine sable]

I have the fields Q(sqrt3) and Q(j sqrt3)

L is the smallest field such as Q(sqrt3) U Q(j sqrt3) is included in L

I search [L : Q]

I know that [Q(sqrt3) : Q] = 3 and [Q( j sqrt3) : Q ] = 3

And [L : Q] =< 3 x 3 = 9

Since [L : Q] = [L : Q(sqrt3)] [Q(sqrt3) : Q] = ... x 3

I know that [L : Q] is 3, 6 or 9

but i dont't know

any help ?

[remote heron]

whats j?

[remote heron]

.

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

j is the complex number such as j^3 = 1

L=Q(sqrt3, j) and since the minimal polynomial of j has degree 3,
[L:Q]=[Q(j, sqrt3):Q(sqrt3)][Q(sqrt3):Q]=3×3=9

thank you !

And what about

Q(sqrt3) instead of Q( j sqrt3) ?

We still have [Q(sqrt3 : Q] = 3

In this case, L is the smallest field where Q(sqrt3) U Q(sqrt3) is include in L

We should have [L : Q] = 9 too ?

We have [L : Q] is 3,6 or 9 too

x^3-5 is irreducible in Q(sqrt3)

so it's 9 no ?

What does the minimal polynomial tell you about the degree?

the degree of minimal polynomial of X is equal to [Q(X) : Q]

so it's 3

Yes

And is x^3-2 irreducible over Q?

yes Eisenstein theorem

What does that tell you about the degree

Apply tower property done

We have so [L : Q] = [Q(sqrt3, sqrt3). Q(sqrt3] [Q(sqrt3) : Q] = 3 x 3 ?

Yes

thank you !

Even though it didn't come up directly, a good tip I want to give you though, is that you should always first look if you can simplify L

That will save you a lot work

[lone heart]

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[lone heart]

@lethal robin Has your question been resolved?

[glass lichen]

nope

[split oriole]

How 2 come forward?

[lone heart]

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[fathom mango]

Hello, I need help with this please

[fathom mango]

Thanks a lot but it is now hitting everything but 1 point. I changed the number to 11

That didn't work either, that is so weird

maybe it's a messed up question

it's something I got assigned by my teacher for extra work

it worked! omg thanks so much

how did you know it was x > (7) btw so i just know if I need to explain

haha smart

.close

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[alpine sable]

.reopen

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[elfin fiber]

@alpine sable

[alpine sable]

alr some ppl should be with you shortly

[elfin fiber]

i alr have

yeah

LMAO

[alpine sable]

which question? 14?

[elfin fiber]

13]

pl

s

obama balls

[elfin fiber]

13 bro

[alpine sable]

ok so, the we need to find the volume of the bins (rectangular prisms) and the volume of the cans (cylinders). We need to find that first

[elfin fiber]

ok so

lemme try that

[elfin fiber]

how do i find the

reactangualr one

there's no diagram

bru

[alpine sable]

we don't need one. We get the measurements

2.5, 2 and 2

multiply them three

[elfin fiber]

10

what's next?

[alpine sable]

from my understanding, we need to find how many cans can fit inside a bin

so we need to divide 10 by 0.53

0.53 being the volume of the cylinder

[elfin fiber]

ok

how did u find the

cylinder colume

volume**

[alpine sable]

the diameter is 0.75

for this formula we need the radius

[elfin fiber]

ohh

ok

[alpine sable]

so just divide the diameter by 2, and you get the radius

[elfin fiber]

inwish i had the digarm

this is so confusimg

even tho they gave the numbers

[alpine sable]

anyways. 10/0.53 is 18.86 and we need to round to the nearest can

which makes the answer 19

[elfin fiber]

ok

that's it?

[alpine sable]

I think so

[elfin fiber]

oki

what abt ques 14

nvm

not that one

[alpine sable]

which one

[elfin fiber]

14

[tiny minnow]

for a

[alpine sable]

for A we just need the volume of the tank

so its 18, 55, 22

[tiny minnow]

find the volume the water first

[alpine sable]

oh wait

oh shit

[tiny minnow]

dont give the answer only

[elfin fiber]

what is

ye

[tiny minnow]

u know how to find volume?

[elfin fiber]

yes but i keep forgeting the formula

[alpine sable]

18 x 55 x 22= 21780 cm

we need liters

[elfin fiber]

yeah that'sbtrue

[alpine sable]

so 21780/1000

[elfin fiber]

oh

dang ok

[alpine sable]

21.78 liters

[elfin fiber]

ok done

[alpine sable]

for B i'm assuming we just change the height to 5.4

[elfin fiber]

that seemed so hard

[alpine sable]

L x W x H= Volume

[tiny minnow]

i just checking 🙂

[elfin fiber]

okii

[elfin fiber]

oki

[alpine sable]

55 x 22 x 5.4= 6534 cm

6534/1000

[elfin fiber]

ahh

[alpine sable]

6.534

@tiny minnow could you double check that one?

feelin kinda mixed on 14.B

[elfin fiber]

yes pls

[tiny minnow]

yes

correct

[elfin fiber]

i have a quiz tmrw

i might just fail

oof

[tiny minnow]

wel;

[elfin fiber]

k only 2 ques left

15 and 16 pl

pls*

@alpine sable @tiny minnow

where'd u guys go?

[alpine sable]

for 15, find the volume

A

for 15.A find the volume

6 x 6 x 0.15= 5.4

5.4 m^3

for 15.B

it's asking for each meter cubed, the cost is 110

so 5.4 x 110

594$ is your answer

[elfin fiber]

divide?

[wary stream]

Don't fully solve the problem for the person, let them figure it out

[elfin fiber]

oh no

[alpine sable]

oh ok ok sry

[alpine sable]

no that is m to the 3rd power

whenever ppl use ^ it means exponent

[elfin fiber]

like

ohh

yeah ok so

5.4 times 3 timess?

[alpine sable]

no, thats just the unit

[wary stream]

No, it's the unit

m^3 is the unit for volume

Meters cubed

[elfin fiber]

oh yeahh ok

ok

ok done

anwyay

what about ques 16

[elfin fiber]

here

[alpine sable]

oh I'm not sure

you should ping the helpers for this one

[elfin fiber]

okk

<@&286206848099549185>

@alpine sable can u help me with the last one pls?

tyy

[elfin fiber]

ques 16

IKR

oki

ok

yes

can i jus do

like rectangle

for the size

yeah

i need to have three diff ones right?

no

oh

so i need to find the volume of the boxes now?

the dimensions>?

i drew a

ractangle, cube

and a traingle

nvm i shouldn't do a traingle

square is fine

what

😭

ok

um

i thought u needed 3 diff

shapes or whatever

anwyay

no

oh

lemme draw

ok

so

what do indo

wait

where did 3 times 4 come from

or were jus makin it up

like

ohh

ok

ok

alr

do i need to write smth

do i need write smth in the ractangle?

like length and sruff

ok

ok

there's 4

right

can u show on a paper

ok

ok

ok

thanks

i'm askin someone cuz i don't rlly undertsanf that ques sorry

is that ok?

@tiny minnow

yo can u help me?

it's always the last ques ugh

<@&286206848099549185>

[tiny minnow]

ok

[elfin fiber]

tysm

here

ques 16

[tiny minnow]

until a , b, c, or d?

[elfin fiber]

ye

if u can

[tiny minnow]

u know if 12 = 1x12
=2x6
= 3x4

i cant help a cause of i cant send pic

[elfin fiber]

ok

[tiny minnow]

@elfin fiber add friends

[elfin fiber]

kk

[lone heart]

@elfin fiber Has your question been resolved?

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[elfin fiber]

tysm everyone for helping me out you guys r the best!!

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[deft field]

hi

im not getting this

and I'm really confused

[lone heart]

@deft field Has your question been resolved?

[lone heart]

@deft field Has your question been resolved?

[formal sentinel]

If you can write the area of a square based on a side of the square, x, then see what you can answer

[lone heart]

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[severe silo]

Help

[lavish cloak]

hello

[severe silo]

How

This sw turning me crazy

[rigid smelt]

it seems like you are leaving out important information

if not, then this exercise is too vauge

[severe silo]

This all what was given

@rigid smelt

[rigid smelt]

can you tell me what the area of circle C might be?

[severe silo]

9pi

[rigid smelt]

yes

[severe silo]

Nvm me figuref it out alr

[rigid smelt]

sure

[bleak sphinx]

who can do 7th grade math?

[severe silo]

How about for this one?

[rigid smelt]

what have you tried for that problem

[severe silo]

I got sector of AOB

[rigid smelt]

you should be more specific, got the area? the angle? the circumference?

theres a lot of things that you might be referring to

[bleak sphinx]

@rigid smelt can you help me

[rigid smelt]

please read #❓how-to-get-help

[severe silo]

Length of sector aob

I got perimeter of aob

But idk how to get cod

Because Im not sure how to get the radius

@rigid smelt

[rigid smelt]

right, you dont need the perimeter

you can just get right into finding the area

ok firstly, do you agree that the area of ABDC is difference of the area of sector AOB and sector COD?

[severe silo]

Yeah

[rigid smelt]

good, so now lets find the area of sector AOB in terms of alpha

since its the easiest

[severe silo]

Okay I have to submit it now

[rigid smelt]

is this a test?

[severe silo]

Nope sw

Its from the book

[rigid smelt]

i assume that means you are not interested in getting this solve then

anyway, you should go down that path, close the channel if you have no further question

[severe silo]

I'll just ask my tutor later

[rigid smelt]

sure

[severe silo]

Thanks sm for the help

.close

[lone heart]

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• Show your work, and if possible, explain where you are stuck.
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• Be polite and have a nice day!

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[alpine swift]

Hello

[alpine swift]

Calculate the surface area of this object. Each side is 1 cm

How would I be able to solve this and how would I be able to solve others similar to this

No it’s not on the ground

No

1

Is that all that is?

So say on side was 6

6x6= 36 and than I would add them for each visible side?

I have a couple more questions.

What formula would I use for a question like this one?

[bold lion]

Yo

Uh

What is 12

Is it an algebraic expression or polynomial

[alpine sable]

You don't even need to do that @/switch

Just calculate each exposed rectangle

Ah I see

Yeah makes sense

[alpine swift]

I’m not sure I’m understanding

I have to calculate the surface area

What would the formula be though?

[alpine sable]

No

Add them

Wait no

Mb

You multiply the side lengths and add those faces

[alpine swift]

Would the answer be 882cm2?

I’m going to try to solve it now

Ok

What would I do to calculate this prisms surface area?

Would it just be the surface area of all sides added together?

Hey, you guys there?

<@&286206848099549185>

[woven dock]

Yes!

Just add them all up

[alpine swift]

So it would be 864cm2?

[woven dock]

I didn't calculate, gimme some time.

,calc 1612+2010+1210+1610

[ocean seal]

Result:

672

[woven dock]

I got 672

[alpine swift]

Huh

Why’s that?

[woven dock]

Not much, I just add them up

Show your work?

[alpine swift]

Ok just a sec

The top one is what I did

I think what I did wrong is I use the formula for a square and not a triangle

Correct?

[woven dock]

Yep

[alpine swift]

Initially when I had done this question I had received 672 aswell

What is the formula i must use?

[woven dock]

It's just area of triangle

And you have 2 triangles.

So

16*12/2*2

[fringe ember]

a frenchman from paris! what an honor, sir!

[alpine swift]

Lol I’m Canadian hahaha

[fringe ember]

seriously?

[alpine swift]

What does the * mean?

[fringe ember]

mutliplicatio

[alpine swift]

What about the slash

[fringe ember]

division

[alpine swift]

So 16x12 divided by 2 x 2 ?

[fringe ember]

yes

[alpine swift]

So that would be 64?

For the surface area of the prism I only got 608

[lone heart]

@alpine swift Has your question been resolved?

[alpine swift]

<@&286206848099549185>

Was the surface area 192cm2?

Oops

Is the answer 256cm2?

[severe sluice]

neither

i think we should do a walkthrough-like thing?

[alpine swift]

Yes

[severe sluice]

so

the surface area

it's equal to all the sides of this shape

right?

[alpine swift]

All visible sides

[severe sluice]

no

i mean

all sides

[alpine swift]

Even the one that is connected to triangle?

[severe sluice]

(the sides at the back - which aren't visible - still counts)

[alpine swift]

I was doing that

I meant the ones that connect to each other

[severe sluice]

uh
you mean the part that connects the cube with the prism thing?
no

[alpine swift]

Yes

[severe sluice]

yeah they don't count

so

andways

lets start with the bottom side of the prism

what are its measures?

(ping me when youre back)

[alpine swift]

What

@severe sluice

[severe sluice]

i mean

the side

at the bottom of the shape

[alpine swift]

It’s dimensions are 12 by 6

[severe sluice]

so what's the area?

[alpine swift]

72

[severe sluice]

next up

for the other rectangular side (i mean this)

[alpine swift]

30

@severe sluice

[severe sluice]

now for the 2 triangular sides

[alpine swift]

They are 60 in total

[severe sluice]

there's one on the back as well

yeah

[alpine swift]

Are you still here?

@severe sluice

[severe sluice]

yeah i'm here

and now for the top side of the prism

you can calculate the area on the side there

(note that the area of the bottom of the cube is equal to the area of the top side of a cube - i think that that mght help)

[alpine swift]

It’s not

The top is 78

[severe sluice]

uh

right

however, we have a part that's covered by the bottom of the cube

so that part does not count

[alpine swift]

-4cm

Right?

[severe sluice]

but the area of that part is exactly equal to the area of the top of the cube

so they cancel each other out

[alpine swift]

What

[severe sluice]

nevermind

just subtract by the area covered by the bottom

[alpine swift]

Would it not be minus 4cm out of 78?

[severe sluice]

subtract by 4cm

right

[alpine swift]

That’s what I’ve been saying hahaha

[severe sluice]

and then add the area of the top of the cube

+4cm

78 - 4 + 4 = 78

and now for the sides of the cube

[alpine swift]

15

Oh no

Nvm

16

[severe sluice]

yeah

now add them all up together

16

+78

+30

+60

wait what

[alpine swift]

Dude

That’s what I had initially got.

So did I do it right or not lol?

[severe sluice]

eh

it's 196

*184 i'm dumb

not 192

[mortal mica]

6×13+5×12+6×5+12×6

[severe sluice]

12x6?

[alpine swift]

Where did you get 78

Nvm

[mortal mica]

whats 6*13 ummmm... ×5 would be half times 10 so... 6×13 is 65+13, 78,
78+60+30+36×2 thats.. 72
78+72+60+30
150+90
240

12*6 is bottom bit

base

12

times width 6

[alpine swift]

Dude I’m pretty sure it’s 192

[mortal mica]

unless shape hollow?

there are 4 different sides, 2 triangles which make 1 rectangle size 12 by 5

i got 240 🤷‍♂️ enjoy

[mortal mica]

theres the working

ping if im wrong

[alpine swift]

I got both 240 and 192

You guys are telling me two different things

[severe sluice]

what???

i mean

@mortal mica where did you get 6x12

[mortal mica]

;/

[alpine swift]

Bottom side

[mortal mica]

i answered that

[mortal mica]

.

look at the shape

[alpine swift]

Who’s the one who’s right here

[mortal mica]

see the side length 6, and 12.

[mortal mica]

u tell me

do u disagree witj my working?

[alpine swift]

Im sorry

[mortal mica]

do u see where i get all the factors from?

what? no lmao not sorry

its a yes or no

lol tf

[alpine swift]

I got 256

[mortal mica]

did u get where i got 6×12?

[severe sluice]

yeah

[mortal mica]

how

count how many sides there are

top, bottom, and 3 sides

2 sides are identical, the triangle ones

and 3 sides are rectangles

when u have 2 same triangles, u can flip one of them to make a rectangle with same dimentions, right?

aka cutting a rectangle from corner to corner gives 2 identical triangles

oop, i guess ur gonna write ur working

cool

lol

[mortal mica]

u sayin its 196 or smthn?