help-0

[bleak ridge]

Yeah

[junior tartan]

2.69 rad means "2.69 radians"

[vague iris]

i thought it looks like something like 3pi/4 or something

[bleak ridge]

How many degrees is 3.1416 radians about

[vague iris]

I searched in google. is it 180 deg?

[bleak ridge]

Yes

So whats the conversion rate

From radians to degrees

[vague iris]

180/pi

[bleak ridge]

Yes

[vague iris]

Wait am i just gonna multiply the 2.69 to 180/pi?

[bleak ridge]

And they just want you to use 3.1416 for pi so what's the rate for this specific problem

Also yeah

[vague iris]

180/3.1416 ?

[bleak ridge]

Yeah

[vague iris]

Ohhh I get it now. Thanks!!

[bleak ridge]

Np

And you're good with converting the decimal to dms right?

Or no

[vague iris]

yess

[bleak ridge]

Epic

[vague iris]

thanks again

/close

.close

[lone heart]

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[mighty berry]

How would I even start this substitution? I cannot factor the ellipse equation and I cannot write x,y in terms of s,t

[formal sentinel]

x^2+2xy+2y^2 almost looks like a perfect square

Compute s^2 and you'll see it immediately

[mighty berry]

Well, yes, but there's a 2 in front of the y^2

Wait, is it s^2 + t^2?

[bleak ridge]

That sounds right

[formal sentinel]

It is

[mighty berry]

Oh my god, I'm blind haha

Thank you!

.close

[lone heart]

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[formal sentinel]

I hope that they didn't say the area was pi

[lone heart]

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[bright hedge]

okay so

you understand why the first line is what it is

and now you understand what P = xy means

right?

instead of f(x) ur teacher just used P (i assume it means product)

[smoky cloud]

what is that u need in the q ??

[brazen cape]

yes i understand that much

[bright hedge]

alright so

in the first line she manipulated the equation to get x in terms of y

so she had

[brazen cape]

im just needing a walkthrough so i better understand

[bright hedge]

$x + y = 30 \implies x = 30 - y$

[brazen cape]

okay cool

[bright hedge]

by subtracting x from both sides

so then we wanted to maximize the product of the two numbers

whcih was

$P = xy$

[ocean seal]

not discordmod

[bright hedge]

but we know what x is in terms of y

so we have

uh

[ocean seal]

not discordmod

[bright hedge]

okay so we haev this

so replace x in P with what it is interms of y

so

[smoky cloud]

oh k

[bright hedge]

$P = (30-y) \cdot y$

[ocean seal]

not discordmod

[bright hedge]

distribute

$P = 30y - y^2$

[ocean seal]

not discordmod

[brazen cape]

oh okay

and then she took the derivative

[bright hedge]

so now we know that there will be a critical point where the derivative equals 0

(in this case, because it is an upside down quadratic, the point we find will be the max)

,w plot 30x - x^2

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Zettachad#0445

[bright hedge]

we would be finding that max point

so we take the derivative of bot hsides

$\frac{d}{dy} P = \frac{d}{dy} 30y - y^2$

[ocean seal]

not discordmod

[bright hedge]

which is

$\frac{dP}{dy} = 30 - 2y$

[ocean seal]

not discordmod

[bright hedge]

we know that it will have a critical point where the derivative is 0

so

$0 = 30 - 2y$

[ocean seal]

not discordmod

[bright hedge]

$2y = 30$

[ocean seal]

not discordmod

[bright hedge]

$y = 15$

[formal sentinel]

didnt someone JUST ask about this x + y = 30, max(xy) = ?

[ocean seal]

not discordmod

[bright hedge]

same guy he wanted a walkthrough

[formal sentinel]

o

[brazen cape]

sorry

[bright hedge]

so yoyo

[brazen cape]

okay awesome

[bright hedge]

do you understand how i got to y = 15?

[brazen cape]

yes

[bright hedge]

okay cool

so we know that it will be a max if

$f''(x) < 0$

or if the sign of the derivative changes around the number we found

so in this case

we can do

[brazen cape]

in the opposite case would a min be at f"(x)>0

[bright hedge]

yers

[brazen cape]

thats epic okay

[bright hedge]

but the second derivaitve tests fails sometimes so we have to check the sign around f'(x)

[formal sentinel]

max is f''(x) < 0

[bright hedge]

(the second derivative tests fails if f''(x) = 0

oops

yeah ur right

[ocean seal]

not discordmod

[bright hedge]

so it would be the opposite of this

[brazen cape]

fixed it

thank you

[bright hedge]

okay

$\frac{d}{dy} \frac{dP}{dy} = \frac{d}{dy} 30 - 2y$

[ocean seal]

not discordmod

[bright hedge]

this is

$\frac{d^2P}{dy^2} = -2$

[ocean seal]

not discordmod

[bright hedge]

so in this case the second derivative is always negative

meaning that for y = 15, (the point we found) the second derivative is negative

which means the point we found was a max

[brazen cape]

if it were to equal zero would i just need to test around the critical point

test pts

[bright hedge]

yep exactly

[brazen cape]

great!! thank you so much that was very helpful

[bright hedge]

you're welcome!

would it be okay to close this?

[brazen cape]

absolutely!

[bright hedge]

happy to help 😄

.close

[lone heart]

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[gilded vale]

What happens when a log is an exponent?

[formal sentinel]

Well, $a^{\log_{a}b} = b$.

[ocean seal]

Len

[formal sentinel]

It's not too important here though

[bright hedge]

for this

it is the same as

$\frac{e^{\ln(3) \cdot \log_{2}(4 \sqrt{5})}{e^{\ln(3) \cdot \log_{2}(\sqrt{5})}$

[ocean seal]

not discordmod

$\frac{e^{\ln(3) \cdot \log_{2}(4 \sqrt{5})}{e^{\ln(3) \cdot \log_{2}(\sqrt{5})}$
```Compilation error:```! File ended while scanning use of \frac .
<inserted text> 
                \par 
<*> 328662734008745984.tex
                          
I suspect you have forgotten a `}', causing me
to read past where you wanted me to stop.
I'll try to recover; but if the error is serious,
you'd better type `E' or `X' now and fix your file.```

[formal sentinel]

xd

[bright hedge]

im struggling

[formal sentinel]

It's a lot easier if you subtract the powers

And use the division log role xd

[bright hedge]

oh

[formal sentinel]

I see what you did tho

[bright hedge]

naw i was making it going to e

then i was gonna subtract the powers

xD

[bright hedge]

anyways

so this is

$3^{\log_2(4 \cdot \sqrt{5}) - \log_2(\sqrt{5})}$

[ocean seal]

not discordmod

[bright hedge]

which then you can apply log rules

(subtracting two logs is log of a quotient)

so

$3^{\log_2(\frac{4\cdot \sqrt{5}}{\sqrt{5}})}$

[ocean seal]

not discordmod

[bright hedge]

which is

$3^{\log_2(4)}$

[ocean seal]

not discordmod

[bright hedge]

which is just 9.

[gilded vale]

I’m confused about the 3log2

[bright hedge]

which step

[gilded vale]

Once you combine everything after you turned it into a subtraction

[bright hedge]

$\log(x) - \log(y) = \log(\frac{x}{y})$

[ocean seal]

not discordmod

[bright hedge]

this?

[gilded vale]

Yeah

[bright hedge]

this is kinda just a rule

because you know how if you subtract powers of exponents, then you are dividing

and because log() is the inverse of exponents its rules get flipped

[gilded vale]

Oh wait I think I know why I’m confused, I think you wrote the step wrong there should be a three there right?

[bright hedge]

no there shouldn't be a 3 there

$\frac{a^b}{a^c} = a^{b-c}$

[ocean seal]

not discordmod

[bright hedge]

this is a rule for exponets

[gilded vale]

So the only thing you’re doing is dividing the exponents

[bright hedge]

yes

[gilded vale]

And you don’t included the second 3 because they’re the same base??

[bright hedge]

yes

the only way you would include the second 3 if it was something like

$\frac{3^4}{27^3}$

[ocean seal]

not discordmod

[bright hedge]

then this would be

$3^{4-3(3)}$

[ocean seal]

not discordmod

[bright hedge]

because 27 is 3^3

[gilded vale]

Ok I think I get it, I might get some extra help from my teacher but I get the basic idea thank you

[bright hedge]

you're welcome! is it okay to close this channel?

[lone heart]

@gilded vale Has your question been resolved?

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[honest umbra]

I got b but apparently the answer is c?

[chrome salmon]

How?

[honest umbra]

nvm found my mistake have a good day

[misty dagger]

Ok What you got

lol

I was about to say

[honest umbra]

when I was trying to find the velocity I multiplied by radius instead of circumference

[misty dagger]

ok close it

[honest umbra]

have a good day guys

.close

[lone heart]

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[lone heart]

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[alpine sable]

Can someone write out and show me these 2 plz?

[misty dagger]

Just used a calculator lmao

[alpine sable]

@misty dagger ??

[misty dagger]

Aren't you trying to graph it?

-3 to 5 within x range

Used calculator in y-graph. Just type -2abslxl

From -3 to 5 range

boom

If your not allowed to used calculator on it, then i can tell you after

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

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[alpine sable]

@misty dagger I can use a calculator

[alpine sable]

I just don’t understand what u mean

[misty dagger]

Ok I show you it real quick

And make sure you look at your table for y

[alpine sable]

Yeah I know how to do that

Im@looking more for the evaluation

Do u know how to do?

[misty dagger]

Yea

Oh shoot

That give you answer

Oh well

Got any questions? I am about to go to bed.

You can evaluate without a calculator, but I don't have times to do that since it's pretty late.

But you can check your answers with calculator

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

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[hazy stirrup]

How do you do question 21b

i've done 21a

but i don't see how i can sub tan(a) and tan(b) into these equation

s

[lone heart]

@hazy stirrup Has your question been resolved?

[hazy stirrup]

what

nice

ok ty

[gray isle]

sub/eliminate y

[severe sluice]

I ALREADY WARNED YOU BEFORE

STOP.
POSTING.
ANSWERS.

[alpine sable]

What

[hazy stirrup]

where di the 1/2y come from

2nd line

what

still dont get why its x = 1/2 y

wdym

its ok if u don't get it

i'll just wait for the next class

no

doesn't say

ok

.close

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[whole wadi]

A line goes through points P (0, 2) and Q (a, 0) is parallel to the line y = 2x + 1. Determine the number a.

[flat remnant]

what have you done by now? where did you get stuck? have you drawn a picture

[whole wadi]

$2=\frac{0-2}{a-0}$

[ocean seal]

Theophania

[whole wadi]

Is this correct?

$2=\frac{-2}{a}$

[gray isle]

yes. than solve for a

[ocean seal]

Theophania

[whole wadi]

a = -1

Is the triangle right-angled, if the corners have the coordinates:
a) (-2, 3), (1, -5) and (6, 6)
b) (0, 0), (7, 4) and (2, 11)?

Motivate your answer.

How can you tell?

[flat remnant]

find the angles of the sides of the triangle and see if they form a right angle

a picture would help

[flat remnant]

great

[whole wadi]

$$\left(-2,3\right) = A$$
$$\left(6,6\right) = B$$
$$\left(1,-5\right) = C$$
$$m_{AB}=\frac{3-6}{-2-6}=\frac{-3}{-8}$$

[ocean seal]

Theophania

[flat remnant]

good

[ocean seal]

Theophania

Theophania

[flat remnant]

exactly

[whole wadi]

.close

[lone heart]

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[clear pivot]

R on the set {1, 2, 3, 4, 5} defined by the rule (x, y) ∈ R if 3 divides x − y

[clear pivot]

Element of R = {(1,1),(1,4),(4,1),(2,2),(2,5),(3,3),(4,4),(5,2),(5,5)}

I just want to check with my answer. Am I correct ? Tq.

[lone heart]

@clear pivot Has your question been resolved?

[chrome salmon]

Yes

[clear pivot]

Hello Sam, thank you once again 😅

.close

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[alpine sable]

help

[alpine sable]

i dont need help with any of thhe questions themselves
i just need help understanding the equation
and the example
i got answers from tons of people ik but i dont feel comfortable turning in the work without actually learning it
been stuck on this for weeks and its due tmr 😭

can someone explain step by step the example

i rlly dont get it

i tried to follow pendas but it turns out wrong

[devout summit]

You need help understanding where the formula comes from or the calculation itself?

[alpine sable]

calculation

i been on this for weeks

its due tmr

i love procrastinating

[devout summit]

I don't think calculation for this is that easy by hand

[alpine sable]

i have a calculator 😭

if i stick with PEMDAS i get this

i can't go any further bc the numbers would be too small

can you spot a mistake in the steps i made so far

[devout summit]

I think yes

You wrote 1+(0.02/4) as 1.02/4

While it should have been 4.02/4

[alpine sable]

OH MY GOD

LORD

lmaoooo

small mistake

thhank you so much

.close

[lone heart]

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[errant kernel]

help

[severe sluice]

wait sorry

alr occupied 😦

[errant kernel]

huh?

oh sorry :(

im just new

[severe sluice]

i was writing this before it was occupied

[timid tinsel]

a6-7b=?

[errant kernel]

Im really so so sorry

[severe sluice]

it's fine

im the one who should be sorry

its your channel

[errant kernel]

No no sorry i didnt know anything about this server im just new

[severe sluice]

you know the equation for a line, right?

i mean

for the question

[errant kernel]

can someone help me? im stuck here and i still dont know how to solve this or answer its hard for me :)

[severe sluice]

yeah i can

[errant kernel]

:0

[severe sluice]

you know the equation for a line, right?

[errant kernel]

Yup

but its kinda confusing me

since my teacher doesnt teach us he just send a video

[severe sluice]

so you know how to find the slope of the line

given the equation?

[errant kernel]

nope

im sorry im to dumb yk

[severe sluice]

uh

y=ax+b

right?

[errant kernel]

oh yes

[severe sluice]

so a would be the slope
right?

(you remember that?)

[errant kernel]

yup

[severe sluice]

so i'm pretty sure you can just check of the first 2 columns now

next up for the y-intercepts

[errant kernel]

oh wait i get it now

[severe sluice]

uh
do you understand the y-intercepts yet?

[errant kernel]

well my teacher send a video of that so i do get it i will just re watch it :D

[severe sluice]

uh yeah
feel free to dm me if you have any additional questions

[errant kernel]

ty for the help :> have a nice day!

Oh ok

.close

[lone heart]

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[cinder sundial]

YY

[cinder sundial]

A and B are event, P(A)=3/8, P(B)=3/4, P(A∪B)=7/8

the question asks for P(A' |B)

i got 3/4 - 1/4 =2/4 as the answer

that's what i had in my mind

[placid zinc]

P(A' | B)
= P(A' ∩ B) / P(B)
= [P(B) - P(A ∩ B)] / P(B)

So your Venn Diagram work is good, but don't forget that a division comes with the notation

[cinder sundial]

what you mean "don't forget that a division comes with the notation"

[cinder sundial]

its P(B)-P(A∩B) right

oh i have to divide it by P(B)

P(A' |B) is when event B happens but i don't want the part when event B and event A both happens at the same time, right

[cinder sundial]

and in venn diagram it gonna looks like this, so here we got P(B)-P(A∩B)

[vale wigeon]

you calculated P(A' & B) rather than P(A' | B)

[cinder sundial]

symbol ∪ and symbol & having the same meaning in math, right

[vale wigeon]

no

also, "have" not "having"

[cinder sundial]

thank you

[vale wigeon]

∪ means union, ∩ means intersection

& is, in some sense, the same as ∩

[cinder sundial]

got it thank you

[alpine sable]

What is &? Never seen it used

[cinder sundial]

i think it mean "and" in english

[alpine sable]

Okay I guess, but you should jsut use ∩

[alpine sable]

also: it means*

[cinder sundial]

ok get back to the question, i know the Conditional probability
formula is P(B|A)=P(A ∩ B)/P(A)

[cinder sundial]

thank you

[alpine sable]

Yes, and you want to find P(A'|B) right

[cinder sundial]

in my understanding the formula means we want the probability when event A happens but i don't want the part when event A and event B both happens at the same time.

am i right

[alpine sable]

No that's the wrong understanding

[cinder sundial]

ohh

[alpine sable]

P(B|A) means something like this: What is the probability of B if we know A happened?

[cinder sundial]

can i have some example

[alpine sable]

Sure

Let me think of one

Okay, lets say you have a dice

A - we got an even number

B- we got a four

[cinder sundial]

then P(B|A) is when we got an even number and the number is four?

[alpine sable]

Probability that we got four under the assumption we got an even number, is : P(B|A)=P(AnB)/P(A) = (1/6))/(1/2)=1/3

And this answer makes sense

Because if you KNOW you got an even number, then the chance of getting a 4 is 1/3 because there are only 3 even numbers

[cinder sundial]

yes

i wonder what it looks like in venn diagram

[alpine sable]

Okay also other way to look at it

Do you know like what is Omega in probability?

[cinder sundial]

no i dont, i haven't learn about that yet

[alpine sable]

So how do you define P(A)?

[cinder sundial]

P(A)=n(A)/n(S)

[alpine sable]

and what is n(S) and n(A)?

[cinder sundial]

A is a event, S is the sample space

the n stands for numbers

thats the formula

[alpine sable]

Okay perfect, so basically the same thing but different notation

So

There is another way to look at the conditional probability

P(A|B) is basically just looking at smaller sample space

the sample space is now B

And you look at the events that fall in A and B at the same time

because if it isnt in B then its not in your new sample space kind of.

But honestly the dice example is the best and if it doesnt feel that comfortable yet then just use the formula to calculate

The intution will come naturally.

[cinder sundial]

in venn diagram it gonna looks like this right

i can't understand why i have to divide it by P(B) aka the sample space

it should be just P(B)-P(A∩B)

the diagram looks like P(B)-P(A∩B)

[alpine sable]

Yeah the diagram is wrong

I mean, the diagram doesnt show the conditional probability

maybe this helps you

[cinder sundial]

is it (3/4-1/4)/(3/4)

that will be equals to 2/4

P(A' |B)= [P(B)-P(A∩B)]/P(B)

[cinder sundial]

am i right?

[alpine sable]

why is that?

lets go slower

P(A'|B)=P(A' n B)/P(B)

We want to find P(A' n B)

[cinder sundial]

i think its possible to draw (A' n B) on venn's diagram

[alpine sable]

okay yeah

[cinder sundial]

i think i have done that before

[alpine sable]

you are correct

[cinder sundial]

so its [P(B)-P(A∩B)]/P(B)

am i right

[alpine sable]

Yep

[cinder sundial]

then we put the numbers in

(3/4-1/4)/(3/4)

let me calculate it

[alpine sable]

How did you calculate P(AnB)?

[cinder sundial]

P(AnB) is part of the whole question

(3/8)+(3/4)-(7/8)=P(AnB)

[alpine sable]

yep

[cinder sundial]

yes its correct

(3/4-1/4)/(3/4)=2/3

[alpine sable]

yep

[cinder sundial]

i think the question is solved

thank you so much

[alpine sable]

[cinder sundial]

thank you

.close

[lone heart]

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[pulsar ember]

Heya! Could anyone help me with this question for number 2?

[clear pivot]

2(-2)-11 is equal to what ?

I assume the ordered pair is (x,y)

[pulsar ember]

so its a?

[clear pivot]

u answer my question first

[pulsar ember]

-15?

[clear pivot]

ok, is -15 less than 5 ?

[pulsar ember]

yea

[clear pivot]

then the solution pair is a solution of 2x-y<15

you have to do the same steps to find which is not the solution pair

[pulsar ember]

:O

ohh okie tysm I understand it much better

.close

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[undone garnet]

Can you pls help me wid this question?

[lone heart]

@undone garnet Has your question been resolved?

[undone garnet]

<@&286206848099549185>

[lone heart]

@undone garnet Has your question been resolved?

[olive vigil]

2a-4b-ax+2xb
factorisation

<@&286206848099549185>

<@&286206848099549185>

[raven rover]

@olive vigil Read #❓how-to-get-help

Clearly you didn't

Asking a used channel and pinging helpers twice in the span of less than 5 minutes

[olive vigil]

ok sorry

[undone garnet]

<@&286206848099549185> any1 lol?

[wary stream]

Looks like linear algebra, try asking in #linear-algebra

[undone garnet]

sure

.close

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[narrow meadow]

how do I integrate 1/((x^5) + (x^4))?

[narrow meadow]

I've tried integration by parts

doesn't seem to work

since switching them back and forth and what not doesn't seem to help

I've tried integration by partial fractions

can't seem to get the right answer

It seems to be a pretty simple question but idk what I'm missing/doing wrong

and there doesn't seem to be anything to substitute

so yeah, I'm running out of ideas

[alpine sable]

Factor out (x+1)

[narrow meadow]

mhm

[alpine sable]

And then do partial fractions

It should be really simple after that

[narrow meadow]

yeah I did that but apparently I did something wrong since I got the wrong answer

I'll send working out if u want

[alpine sable]

Please

[narrow meadow]

it's messy though so I'll have to reorginse 1 sec

[alpine sable]

Haha alright, tag me when you're done so I se eit

[narrow meadow]

obviously I've done somethign wrong since the answer is wrong but

idk what

lol knowing me I probably understood partial fraction's method wrong

[alpine sable]

Yeah whenever you have a power of x that is > 1 you have to expand it out

Hang on

[narrow meadow]

ohhh

[alpine sable]

I'll type it out

[narrow meadow]

so I split it into like 4 more fractions

like 1/x + 1/x etc

lol sry you do you

don't let me interupt you

[ocean seal]

hvna

[narrow meadow]

wait now I'm confused

cause the extent to which my prof taught us was like using partial fractions to solve stuff like x^2 - 1

by splitting it into (x-1) * (x+1)

so turning x^4 into the four fractions at the start

looks alien to me

😂

can you explain what you did there?

[alpine sable]

You mean to separate it?

[narrow meadow]

why did you turn x^4 into x^4 and x^3 and x^2 etc

[alpine sable]

I'm not sure if there's some rigorous process for it, I just subtract one from the exponent and repeat the fraction until I don't have any powers > 1 left

It works if you try it out now

Again, not in any way rigorous

[narrow meadow]

didn't know you could do that

[alpine sable]

It's only for when you fully factor the denominator of the original equation and there's some power >1 left over

Then you have to do this

[narrow meadow]

ohh icic

so like if I have a (x+1)^2 left over

I turn it into x+1 squared and normal x+1

[alpine sable]

Yes

[narrow meadow]

and add it to the list of bullshit I have to work through?

[alpine sable]

Yes

[narrow meadow]

icic

[alpine sable]

Have you done any matrix work?

[narrow meadow]

lmao no idea what that is 😂

I'm doing year 1 undergrad calc if that answers your question

😂

[alpine sable]

Haha alright, it doesn't take long to learn though and it's a lot easier to figure out partial fractions if you learn it

[narrow meadow]

oh it's a method?

I thought it was like a topic 😂

haha

[alpine sable]

The method is called Gauss-Jordan Elimination

[narrow meadow]

all these weird names...

[alpine sable]

But it uses something called a coefficient matrix

It's way easier than it sounds

I'm an actual idiot when it comes to Linear algebra and I figured it out in a day or two

[narrow meadow]

:o

[alpine sable]

When I was in calc 2 I brushed off partial fractions because I thought I'd never use it

But it comes up often enough

[narrow meadow]

lol all this calc is marking the end of me

I jsut wanna get it over with so I can take comp sci in year 2 🤣

[alpine sable]

Yeah the more you know though the better. It makes everything else way easier if you understand calc

[narrow meadow]

yeah it seems practical

still pain in the ass though xD

[alpine sable]

Anyway, you good on that integral?

[narrow meadow]

yeye

should I .close?

[alpine sable]

If you feel confident

[narrow meadow]

okok

I'll say something again if I run into another problem 😂

.close

[lone heart]

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[alpine sable]

hello

[alpine sable]

Do you have a question?

i have an exam tmrw

yeah

Post it

a couple actually

this

What have you tried so far?

i tried to solve it as a normal inequality but that didn't work

photomath sloved it but i didn't understand the explaintion

Can you show me a picture of what you did?

its just a random messy paper

That's fine

wait

ill show you the right answer first

this

and this is the bit that i didn't understand

@alpine sable

[gray isle]

they combined their terms into a single fraction

[alpine sable]

^

[alpine sable]

wdym exactly

ahhh im slow

[gray isle]

exactly as i said

[alpine sable]

why is the x-2 still in the bottom tho

[gray isle]

recall basic fraction addition/subtraction

[alpine sable]

so like they multiplied 1/x-2?

so it gets to both sides?

[gray isle]

() and not quite

no

[alpine sable]

i don't study math in english thats why im slow

[gray isle]

they first subtracted 1 from both sides

and then expressed 1 as (x-2)/(x-2)

and then simplified

[alpine sable]

waa

can you show me like a visual explanation

[gray isle]

starting with your initial inequality, are you able to subtract 1 from both sides fo the inequality?

[alpine sable]

just do it in paint

[alpine sable]

like move 1 to the other side?

[gray isle]

i dislike that wording

and deliberately chose NOT to use the word "move"

[alpine sable]

i never did math in english

idk the words for things

so yeah it sounds weird

[gray isle]

what language do you usually do you math in

[alpine sable]

arabic

[gray isle]

i mean your english is decent enough

so it shouldn't be that hard to follow these instructions

[alpine sable]

ik but my school teaches math in arabic

[alpine sable]

im not trying not to im just not good at it

[gray isle]

if you know what "subtract" means
and you know what a side of an equation/inequality is

subtract 1 from both sides of the inequality
that should be a pretty simple step
but if you really insist
like move 1 to the other side
is how some would describe it

[alpine sable]

okay

but the x thingy

[gray isle]

that comes after

do this one step at a time

[alpine sable]

yeah i know i moved it to the other side

[alpine sable]

im just stuck at this

[gray isle]

would you be able to simplify something like
$$\frac23 - 1$$

[ocean seal]

ℝamonov

[alpine sable]

1/3

[gray isle]

no

[alpine sable]

thats what you mean

[gray isle]

1/3
isn't correct

[alpine sable]

wait what

[gray isle]

how are you getting 1/3

[alpine sable]

moved 2/3 then 1 - 2/3

[gray isle]

and this is why i hate the word "move"

how exactly are you "moving" that 2/3

[alpine sable]

idk what to use instead lol

[gray isle]

recall the basics for adding/subtracting fractions

[alpine sable]

what i mean by move is like
x + 3 = 5
after "moving"
x = 5 - 3

this is what i mean

[gray isle]

1 - 2/3 would be equal to 1/3
however
2/3 - 1 is NOT the same as 1 - 2/3

[alpine sable]

that becomes -1/3

[gray isle]

yeh. 2/3 - 1 is -1/3

and would you be able to clearly show all steps to get that

[alpine sable]

just 1 - 2/3 lol

or 2/3 - 1

for -1/3

[gray isle]

how about i use a more complicated example

$\frac37 - \frac23$

[ocean seal]

ℝamonov

[gray isle]

how would you simplify that

[alpine sable]

idk how say that thing in english

but like

[gray isle]

show your work mathematically

[alpine sable]

multiply by the reverse thing

[gray isle]

show your work mathematically

[alpine sable]

like -2/3 x -3/2

you can do that to remove the -2/3

[gray isle]

whut

[alpine sable]

but its gonna be a wrong solution

frick i can't explain anything

[gray isle]

i don't understand what you're trying to do with that

like -2/3 x -3/2
you can do that to remove the -2/3

[alpine sable]

ik

[alpine sable]

im just saying is that the thing we did here

[gray isle]

to combine fractions through addition or subtraction
you first need to get a common denominator

[alpine sable]

oooh

you mean

[gray isle]

e.g.

[alpine sable]

a thing in both sides

like 2 in both sides of the / thing

so we subtract

[gray isle]

showing the work for the simplification of $\frac23 - 1$ would be \
$\frac23 - 1 = \frac23 - \frac33 = \frac{2-3}{3} = -\frac13$

[ocean seal]

ℝamonov

[alpine sable]

i think ik what you meant now

ty

@gray isle wanna help me do another one?

its an easier one thought

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

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[ivory gulch]

ayo

[ivory gulch]

so i rlly don't know what to do here tbh. prof didn't mention an 'initial condition' in class

[alpine sable]

First of all, find y' and write out the whole equation

And then you just substitute the initial condition to verify that it works

[ivory gulch]

well just subtract y from both sides

and that's y'

[alpine sable]

Yep

And then verify if it works with the initial condition

[ivory gulch]

so plug in -ln(6) = x and 3pi = y

[alpine sable]

no, $y=-\frac{3\pi}{\ln(6)}$

[ocean seal]

hvna

[ivory gulch]

how do you figure?

when you plug in -ln(6) in the equation y you'll get 3pi

so coordinate for initial condition is (-ln(6), 3pi)

[ocean seal]

ski

ski

[ivory gulch]

how do you get this from this information

[lone heart]

@ivory gulch Has your question been resolved?

[lone heart]

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[alpine sable]

is it possible to solve birthday problem without using computer/brute forcing

[glass lichen]

The probability birthday problem?

[alpine sable]

yes

[glass lichen]

Yes

[alpine sable]

hits 50% at 23 people

[glass lichen]

Just find the general probability for n people

Then solve when P(n)>=1/2

[alpine sable]

i have this so far

[glass lichen]

Yeah you'll have a bunch of factorial floating around

[alpine sable]

what do i do from here

i have no idea how to approach this other than just plugging all the values in

[devout summit]

What is your goal?

[alpine sable]

find that chance that coinciding birthdays is 50% at 23 people but symbollically, without plugging all values in

if that was incomprehensible i'll try better to explain

[devout summit]

It isn't exactly 50% though

[glass lichen]

1st n in N st P>1/2

[alpine sable]

yeah

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

i give up. homeworks due in 10 mins

.close

[lone heart]

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[lone heart]

@alpine sable Has your question been resolved?

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[alpine sable]

Does this seem right so far

[alpine sable]

<@&286206848099549185>

I don't know linear algebra sorry

Still have to learn

Rip

How old r u

[charred flint]

2nd line is wrong

[deft geyser]

why did you multiply x^T AA^T x?

unless AA^T is A?

like the A in the lhs

[alpine sable]

rip why

[alpine sable]

Yeah A is supposed to be M^TM

[charred flint]

oh nvm it's fine

[alpine sable]

Example of what I'm trying to do but with A cholesky decomp

In this example A is just some random matrix

But I'm trying to prove for this A in a similar fashion

[alpine sable]

why lol

Curiosity

[clever sky]

He's 22 ;)

[glass lichen]

What?

[clever sky]

@alpine sable is 22

[ebon steeple]

Can some one pls help me with my hw

[alpine sable]

3 is c

Prime can be divided by 1 and his number

5 is a

Its less than 3 not less and equal

Last b is 7 a is is 24

4 i dont know

Literally lol

[finite sonnet]

can you post 4 stand-alone?

like just post question 4

[alpine sable]

Wdym

[finite sonnet]

im talking to ttk lol

[alpine sable]

4 is a

[finite sonnet]

i thought you said that you didnt know tho

[alpine sable]

I searched

[finite sonnet]

oh ok

[alpine sable]

Now i know

Ur welcome @ebon steeple

[ebon steeple]

@alpine sable ur the best u save me

[alpine sable]

Ohhh i like to help people

Thanks for the kind words

[ebon steeple]

Np

[alpine sable]

@ebon steeple

[ebon steeple]

I know but question 3

is hard

[alpine sable]

Oh k i Wil try

[ebon steeple]

:

Thanks

[alpine sable]

What school is this?

High-school?

[ebon steeple]

3-4 is - 1 right

[ebon steeple]

Nope it’s grade 7

Haha

But 3-4 is negative 1?

[alpine sable]

Yes its - 1

Lol

[ebon steeple]

How do u -1
-
6 divide 5

This thing is hard

[raw shard]

what

(-1/6)/5 = (-1/6)*(1/5)

[ebon steeple]

?

[alpine sable]

Can we use latex here?

[raw shard]

yes

[alpine sable]

It would be better for explain

[raw shard]

• means multiplied by

[ebon steeple]

I know but what does / mean

[raw shard]

division

[alpine sable]

When you divide an number which is an fraction u flip it

[raw shard]

1/5 = 1 divided by 5

[ebon steeple]

So what is the final answer for this

I did all the steps

But stuck on the last

[alpine sable]

Remember to simplify idk if they teach it

2-5/6,multiply by 6 2, so u can get off the fraction

[ebon steeple]

But that’s not a - that’s a negative for the 1 that why it’s hard

[alpine sable]

I don't understand

[ebon steeple]

But thank you so much u explain the steps : )

[alpine sable]

It might be 1/5

[ebon steeple]

Like this

The image is loading

[raw shard]

(3+1/2+1+2/3) / 5 = (3+1/2+1+2/3) * (1/5)

make it so they all have the same denominator

[alpine sable]

Ye exactly

Sorry im not good in explaining

If only i knew latex lol

[raw shard]

i don’t know latex and i’m usually fine

[alpine sable]

$\helllo $

Rip i tried

[ebon steeple]

No u all explain good thanks I finished the work sheet

[alpine sable]

Ur welcome

@raw shard can i ask you something

[raw shard]

yeah what

[alpine sable]

Im recapping all my study and i just don't understand this

Why 1/2?

[raw shard]

good site choice

[alpine sable]

Thanks ;]

[raw shard]

,w sin(pi/6)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by quantum#6320

[raw shard]

guess that’s why

[alpine sable]

Oh lol circle unit

Nvm thanks

[raw shard]

@ebon steeple close the channel if you’re done

[alpine sable]

Confuse me sometimes because they don't explain, but that's good so you figure it out

Trig is my weakness

From t/4 to pi/6, why

Apparently 30 degree is standard

@ebon steeple if you need help dont hesitate6

[lone heart]

@alpine sable Has your question been resolved?

[lone heart]

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[little fern]

how would i approach this calculus problem?

[little fern]

also when it says "the tangent line approximation" is it known from the question at what point that line is tangent to?

do you even need to know that?

im just very confused by this question

[lone heart]

@little fern Has your question been resolved?

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[winged lantern]

I need help with a linear algebra question: Find the vector component of vector a orthogonal to vector b, if vector a = <3,-1,7> and b = <-4,-2,9>

[ebon condor]

I dont understand

Like projection?

[alpine sable]

Hmm

[ebon condor]

find $c | c\perp b$

project a onto c

[ocean seal]

KurtDee

[ebon condor]

https://en.wikipedia.org/wiki/Vector_projection

Does this make sense?

[analog locust]

.open

[ebon condor]

?

[winged lantern]

wait

I went to go use the bathroom what happened

[ebon condor]

I'm working with you nelly

idk why people are posting othe rproblems

[winged lantern]

oh thanks

yes, it's a projection

So I have a vector projection of a onto b, I found the magnitude and the direction; now it's asking for the vector component of a orthogonal to b

[alpine sable]

Ohhh, inverse of a 3x3 matrix

👀

noice

[ebon condor]

yes I expressed how it's done

[winged lantern]

So this formula would be the one I would use to find it?

[raven chasm]

i think i solved

all good

[ebon condor]

Well yes but

How would you find theta?

[alpine sable]

👍

[winged lantern]

^

Was gonna write that

dot product over the magnitudes of the vectors

[ebon condor]

that should be everything

[winged lantern]

Appreciate it

[ebon condor]

remember you're solving for $\perp b$, not b

[ocean seal]

KurtDee

[winged lantern]

I thought in the forumla I posted, it was a1

or would it be a2?

because of this

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[remote heron]

<@&268886789983436800>

remove dis deez nuts poster

[sly mantle]

b&

.close

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[quartz osprey]

hello

i need some help with this

not really sure what to ddo once i have this infiormation

so i have the u and stuff

its gonna be x^3/3 (u)^5/5

right?

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[stiff pawn]

du should be $15x^{2}dx$

[ocean seal]

RyanDuarte56

[stiff pawn]

so $x^{2}dx=\frac{du}{15}$

[ocean seal]

RyanDuarte56

[stiff pawn]

so the integral becomes $\int_{-1}^{4}\frac{u^{4}}{15}du$

[ocean seal]

RyanDuarte56

[stiff pawn]

got it?

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[nocturne onyx]

any suggestions on how to solve this limit?

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[nocturne onyx]

no

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[nocturne onyx]

<@&286206848099549185>

[nocturne onyx]

anyone know how solve this limit?

[devout summit]

Try the substitution n=-m

[gray isle]

recall your definitions of e

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