help-0

[digital steeple]

if you need an explanation please ask in an available help

#help-9 - 18 - 21

[bleak ridge]

I would prob use a combo of rotation matrices and quaternions

[finite flax]

if you know the target point and the axis in Unity, there is a function that takes an axis and an euler angle to do the rotation.

[digital steeple]

my issue is not doing the rotation, my issue is merely finding what direction vector i should use based on the angle i wanna rotate to (so it respects a certain axis x-y-z etc)

[bleak ridge]

I guess you could do this with euler angles

If you use rotation matrices

[finite flax]

you said you know the destination point and the rotation axis, just not the rotation?

[digital steeple]

in this picture per example, rotation isnt the issue, but figuring that Z in this particular image is the direction vector i need to use to offset my initial point

[finite flax]

hmmm....

[digital steeple]

per example i am not sure if it helps

[bleak ridge]

Do you mind if I give an example of what I would do

[digital steeple]

using math wizardly to figure out its z

certainly papa i appreciate it

[finite flax]

Mr. Bread is baking some math brownies

[bleak ridge]

Heres prob the steps I would do:

So you have a point to be pivoted p
Origin point to be rotated about o
Rotation axis rot
Pivot angle piv

1. make a rotation matrix using the vectors, rot, and normalized vector (p-o) (and of course the cross product of the two to finish it off)
2. assuming unity has some method to construct matrices using euler angles, and assuming you chose rot to be the right vector, just multiply this matrix by a matrix constructed using the euler angles (piv,0,0)

It kinda veers away from what youre doing I imagine but its what Id personally do

The final step would be to just take the vector you chose for the "(p-o) normalized" vector and multiply it by the distance between p and o

Then just add on o

I mean maybe quaternions would be a bit simpler and you wouldnt have to construct multiple matrices but unless youre doing this like 500000 times a second hopefully itd be fine

[sleek flame]

Hi

a really basic

question

[finite flax]

do you not see

[sleek flame]

if there is 8 and we have to round it off to the 10 place or 100 what will be the answer

[finite flax]

that there is already a question being asked here

[sleek flame]

srry i am new

[finite flax]

oh, you're just an asshole

[sleek flame]

yeah

;/

like its fricking basic

[finite flax]

at least we will remember this hilarious and creative prank, right

[sleek flame]

?

i am at ggrade 8

this is just a chapter inwhich we have 1 topic inwhich we have to round of angles and theres this

[digital steeple]

thanks that helped me understand stuff, not exactly what i needed but it helped me visualize what i wanted

.close

[lone heart]

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[whole wadi]

$$2\cdot 10^{x-5}=\frac{14}{7000}$$

[ocean seal]

Theophania

Theophania

Theophania

Theophania

[whole wadi]

What would the next step be here? Log on both sides, right?

[ocean seal]

Theophania

[whole wadi]

Thanks yeah.

[ocean seal]

Theophania

[silver viper]

you dont need log

wait nvm same thing

[silver viper]

continue from here

[whole wadi]

$$x-5=-3$$

[ocean seal]

Theophania

[whole wadi]

$$x = 2$$

[ocean seal]

Theophania

[silver viper]

👍

[whole wadi]

Okay this one seems easy

$$10^{-x}=5$$

[ocean seal]

Theophania

[whole wadi]

$$\log _{10}\left(10^{-x}\right)=\log _{10}\left(5\right)$$

[ocean seal]

Theophania

[whole wadi]

$$-x=\log _{10}\left(5\right)$$

[ocean seal]

Theophania

[whole wadi]

$$x=-\log _{10}\left(5\right)$$

[ocean seal]

Theophania

[whole wadi]

$$x = -0.698970004336019...$$

[ocean seal]

Theophania

[whole wadi]

.close

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[zealous bloom]

I would recommend distributing first to make things a bit simpler

[lone heart]

@keen basalt Has your question been resolved?

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[mellow horizon]

<@&286206848099549185>

[mellow horizon]

help me pls

<@&286206848099549185>

[chrome salmon]

You just gave two equations what's the question

[jaunty bramble]

Two is enough

It is find x,y?

[chrome salmon]

I know but what is to be done is what I'm asking

[jaunty bramble]

Sorry I got it wrong

[chrome salmon]

Ok np

[jaunty bramble]

[alpine sable]

someone is already using this channel

#❓how-to-get-help

take any other unoccupied help channel up top

it'll be in the category that is called "math help (occupied)" and it'll have a name next to it like help-num | name

[jaunty bramble]

What part of geometry?

[lone heart]

@mellow horizon Has your question been resolved?

[mellow horizon]

<@&286206848099549185>

help me pls

find x,y

[sand geode]

hi @mellow horizon

[lone heart]

@mellow horizon Has your question been resolved?

[halcyon grove]

will dividing the first equation by xy help?

[mellow horizon]

hi

[mellow horizon]

next??

[alpine sable]

doubt

[harsh swallow]

x/y + y/x + 8/(x + y) = 16/xy

[mellow horizon]

what if x or y=0?

[harsh swallow]

That could work

Or 1

0 doesnt work

[alpine sable]

you still here?

i think you can simplify the second equation to (6y-x)^2*(2y+3x)^2=0 now you can solve for x and put that in to first and get solutions i guess

[mellow horizon]

can u write on paper and send it to me?

[alpine sable]

send what?

[lone heart]

@mellow horizon Has your question been resolved?

[mellow horizon]

send your opinions

[alpine sable]

what opinions?

[rapid heron]

He's asking you to send the steps you have done in order to solve this question, on a paper.

[lone heart]

@mellow horizon Has your question been resolved?

[lone heart]

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[lone heart]

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[supple tundra]

Struggling to make sense of rotations about different axes

In 2-D, an anti-clockwise rotation would be a positive rotation whilst a clockwise rotation would be negative

For a 90 degree rotation, shouldn't the x-axis be mapped to -z as in the sketch?

[bleak ridge]

Its flipping over like this

Not pivoting around

The picture makes it weird but

It should be a rotation about the z axis

Not a rotation about the y axis

[supple tundra]

Alright, I think I get that. How do you decide in which direction would be a positive or negative rotation?

So the axis being rotated around, should i imagine that being fixed and things rotate around it?

[bleak ridge]

It should be clockwise facing towards the axis

So if you were facing the axis of rotation as the red arrow

Itd be clockwise to that arrow

[supple tundra]

Got it, thanks a lot!

.close

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[bleak ridge]

Np

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[runic pulsar]

how do i find this

[supple tundra]

differentiate $g(x)$ first

[ocean seal]

azeem321

[lone heart]

@runic pulsar Has your question been resolved?

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[runic pulsar]

.reopen

[lone heart]

✅

[runic pulsar]

@supple tundraand after i do that?

[supple tundra]

sub in 2 for x. i.e. g'(2)

[runic pulsar]

oke thanks

.close

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[alpine sable]

Hi

[alpine sable]

I have a question about maxes.

What is the maximum value of the derivative of f(x) = 3x^2 - x^3?

So I basically took the derivative of this and made it f(x) to clear up confusion. That was:
f(x) = 6x - 3x^2
So then I took the derivative of that and set it equal to 0
f'(x) = 6 - 6x
0 = 6 - 6x
6 = 6x
x = 1

Apparently the answer is 3, but I got 1.

You did one too many derivatives

But they're asking for the max value of the derivative of f(x)?

The second derivative is just for saying if it is a max/min

So wouldn't I start with that one?

Because when they ask for the max value of f(x), you take the derivative, solve for x, and so on..

But they asked for the max value of f'(x), so I would take the derivative of that, solve for x, and so on

Yes

So I didn't do it wrong

Kinda confused

dude what

I got it now.

they're asking for y value and you plug that into... ok

.close

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[harsh swallow]

@alpine sable I'd like to help but i don't know what you're asking

oh so the goal is to find the formula for the line that goes through those two points

distribute it to what?

you have x - 0

the 0 falls away

you start with y = ax + b

or y = mx +

idk what you would call b in that case

and you can find b really easily in your case because one of the points is on the y axis

so you fill in 0 for x

which means you get y = b

and you know y so you know b

but it looks like you've already done that

and then the slope

you find that correctly too

i don't really understand why there is that - 0

because that falls away

• 0 means doing nothing

subtracting 0

🙂

ok

maybe if you do it here

so i can see all your ideas

and help

[lone heart]

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[supple tundra]

The textbook states that this is the matrix for a rotation about OZ -45 degrees. Isn't that 45 degrees and NOT -45 degrees.

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@supple tundra Has your question been resolved?

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@supple tundra Has your question been resolved?

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@supple tundra Has your question been resolved?

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[jaunty needle]

im confused with 20-8/6-3, isnt it division first?

[hidden knoll]

is the question (20-8)/(6-3)

or is it 20-8/6-3

[jaunty needle]

it has 20-8 over a line and 6-3 under it

[jaunty bramble]

If it wrote that way

[hidden knoll]

yes it's basically (20-8)/(6-3)

[jaunty bramble]

It is not division first

[severe sluice]

that's a fraction

[jaunty needle]

no

it just shows division

[hidden knoll]

it's

[jaunty needle]

how theres no paranthesis in the problem

[hidden knoll]

20-8
6-3

right

[severe sluice]

the value of a fraction a/b is (a) : (b) in parentheses
(idk i think that's the notation for a fraction)

[hidden knoll]

this is the same thing as (20-8)/(6-3)

[jaunty needle]

so its 4

[hidden knoll]

it's the whole top divided by the whole bottom

correct

[jaunty needle]

Oh, but for another question I got it correct with parenthesis

[hidden knoll]

wdym

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[jaunty needle]

nvm

to small to be in paranthesis

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[restive island]

Is this correct?

I just want to make sure

[severe sluice]

Is 3 actually SSA though?

i mean

where's the angle?

[restive island]

I thought it was on D

[onyx swallow]

should be SSS

[severe sluice]

ehh

ssa is fine

[restive island]

Yeah that’s what I was thinking

I thought because when B and D intersect, they make a right angle

[severe sluice]

wait no

[onyx swallow]

em where is the angle

[severe sluice]

it's not ssa

[onyx swallow]

how is it sas

[severe sluice]

ADE=CDE is proved in 4

it

is not given

[restive island]

Oh

Should it be SSS then?

[bleak ridge]

Isn't there some theorem for when they share sides

[severe sluice]

i think so

[restive island]

Because there’s no angle

[bleak ridge]

Oh wait sss is enough to prove congruency

I was thinking of aaa

[restive island]

AAA?

I haven’t learned that yet

[onyx swallow]

ADE and CDE should be SAS

s is sides, you got 2, and the angle inbetween, which is A

[onyx swallow]

its similarity, AA means the last angle is equal, so we just write AA

[restive island]

Okay, so it’s AA then?

[onyx swallow]

angle angle, 2 angels ar equal

implies similarity of 2 triangle(meaning that you can expand one triangle by some factor to get congruent triangles

[restive island]

But there’s one side though (AB and CB)

Should I be AAS or AA?

I also wanna make sure everything else is correct

[onyx swallow]

AA is similarity, denoted by ~, what u r doing here is congruency ≌

[restive island]

Oh

[onyx swallow]

remember, S is side

A is angle

so can you figure out what should 6 be?

[restive island]

It should be SAS because A is a side, D is a side, and E is a right angle

The same thing applies for CDE

[onyx swallow]

E is not a right triangle, we havent arrived at that yet

[restive island]

Oh

[onyx swallow]

we know ∠ADE=∠CDE tho

PS: remember, the angle MUST be in between the 2 sides, thats why we say SAS instead of "SSA" or "censored"

[restive island]

So, we know that E isn’t a right triangle yet and that ADE = CDE, and that the angle must be in between 2 sides

[onyx swallow]

congruent triangle imply angle congruency, so i dont know what is the reasoning for 4

[onyx swallow]

if i have a straight line, what angle is it? 180

it is split among 2 equal angle, they must be 90 and 90 individually

[restive island]

Wait

Don’t tell me it’s SSS

[onyx swallow]

it is SAS u r right

you ONLY have 2 S and an angle inbetween

so SAS

[restive island]

Exactly, so 6 is SAS

[onyx swallow]

yup

the reasoning for 7 should be, congruent triangle implies congruent angle

[restive island]

Okay that makes a lot more sense now

I feel like reason 4 should be something about an angle bisector

[onyx swallow]

nop

[restive island]

and sorry if I sound dumb rn I’m struggling a bit lol

[onyx swallow]

U get ALL stuff equal if you have congruent triangles

why do we say things are congruent? because everything are THE SAME, but it is just in different positions

what does ABC congruent to DEF mean?

AB=DE,BE=EF,CA=FD

everything is the same, but they're in different position(maybe shifted on the plane, maybe rotated, but the shape are the EXACT same)

this is probably more straightforward

[restive island]

Yeah it kinda is

[onyx swallow]

you got what i was saying?

[restive island]

A bit, so basically if angles are congruent, they may be in a different position

[onyx swallow]

yep

its the same stuff at different position, thats what congruent means

hope this makes the definition clearer

[restive island]

Yeah it does

Forgive me if I’m wrong but

reasoning 4 should be: In a triangle, angles opposite of congruent sides are congruent

Since what you said are that congruent angles are the exact same as another just in a different position

[onyx swallow]

angles at the same place of each individual triangles have the same value

[restive island]

Exactly

[onyx swallow]

the order for ABC ≌ DEF matters, as it means A corresponds to D, B corresponds to E,

now can you refine your reasoning for 7?

[restive island]

Btw this is what happens when I hover over 4

[onyx swallow]

what do you mean?

[restive island]

You see the highlighted angles near D?

[onyx swallow]

yup

[restive island]

That’s why I was thinking 4 was what I said

[restive island]

aka this

Same thing happens when I hover over 7 but instead the angles are near E

[onyx swallow]

2 angles indicators should be at different height for clarity

it is their fault

[restive island]

Yeah it’s weird but I gotta deal with it

[onyx swallow]

aka like this

now you can clearly see that the 2 angle indicators

[restive island]

Yeah

[onyx swallow]

so can you refine 7?

[restive island]

I’ll try

the options are very…different

[onyx swallow]

can you screenshot options for 7 and 8?

[restive island]

This is what makes the whole thing seem very confusing

[onyx swallow]

for 8

what is the know properties we've derived?

*are

AED=CED right?

[restive island]

Yeah

for 7

8 is AC is perpendicular to BD

[onyx swallow]

AED+CED=180 right?

[restive island]

Yes

[onyx swallow]

combining 2 properties what do we get?

[restive island]

An angle?

[onyx swallow]

AED=CED, and AED+CED=180

we can solve AED and CED

[restive island]

It doesn’t really state it’s measurement but I’m guessing it is since AED and CED are two split triangles

[onyx swallow]

no

i meant angle

[restive island]

Oh

then yeah it’s 180

[onyx swallow]

∠AED=∠CED, ∠AED+∠CED=180

what can we get from these 2 equations

[restive island]

supplementary angles??

[onyx swallow]

and they're equal

so?

its simply 2 equations, we can solve the 2 angles

what are they？

[restive island]

congruent angles added to congruent angles are congruent angles then

[onyx swallow]

emmmmmmm no

write ∠AED as X

∠CED as Y

X=Y and X+Y=180

solve for X and Y

[onyx swallow]

plug X=Y to the second equation, we get X+X=180

[restive island]

So you’re telling me that Y is the same as X basically

[onyx swallow]

ye its basically 7

we're trying to do 8 first

[restive island]

Oh ok

[onyx swallow]

im a horrible teacher

[restive island]

It’s fine dont worry about

[onyx swallow]

so we know these 2 properties

[restive island]

Yeah

So for the options for #8, the diagonals, an altitude, and consecutive sides are out of the list because they’re completely irrelevant

So it’s down to if two lines form a linear pair, if a line is perpendicular to one of two parallel lines, and if two intersecting lines form a right angle

[onyx swallow]

check the first option

2 lines fors a linear pair

what does that mean?

[restive island]

Oh shoot

It’s the first option then

[onyx swallow]

∠AED+∠CED=180

[onyx swallow]

yes but u need to understand why

[onyx swallow]

that means that they form a line right?

[restive island]

Yes

[onyx swallow]

cause 180 degree means a line

congruent angle

that mean ∠AED=∠CED right?

[restive island]

Yeah it does

[onyx swallow]

cause that is from 7

if you solve the 2 equations

what do you get?

[restive island]

A linear pair

[onyx swallow]

both angles must be 90 degrees

cuz 90=90 and 90+90=180

[restive island]

so you get supplementary angles

[onyx swallow]

yes supplementary combines with congruency means they're both 90

[restive island]

That makes a lot more sense now

[onyx swallow]

30 120 is also supplementary

[restive island]

any two angles that = 180 is supplementary

[onyx swallow]

but they're NOT equal,

ONLY 90 and 90 follows both properties

[restive island]

I meant two angles that have a sum of 180

[onyx swallow]

yes

[onyx swallow]

now do you get it?

[restive island]

Yeah I definitely do

I just wanna make sure for 3 and 4 though

[onyx swallow]

now a quick question, if 2 angles are equal and they sum to 120

what are the 2 angles?

[restive island]

Oh boy

Measurements or something like a complementary/supplementary angle?

[onyx swallow]

measurement

2 angles sum to 120, and they're congruent

[restive island]

60 and 60

[onyx swallow]

yup, i think you got it

you simply solve the 2 equations

[jaunty bramble]

[restive island]

Kinda like how you did with AED and CED

[onyx swallow]

yup!

so option 1 is correct for 8

[restive island]

Should I do the same with ADE and CDE

Oh wait

they’re congruent

or the same thing

4 is the same as 7

The D and E is switched and the same for CED

[onyx swallow]

YES

[restive island]

is 3 still AA or no?

[onyx swallow]

no

[restive island]

Oh

[onyx swallow]

for 3, what properties do you have for the 2 triangles

[restive island]

Well there’s two sides on both triangles and one angle

[onyx swallow]

em equal angle is NOT yet known

[restive island]

I forgot

[onyx swallow]

look at 1 and 2 again

what are they?

[restive island]

Sides

or lines

There’s no E in those triangles, I just realized that

But there is an angle for D

[onyx swallow]

so?

[restive island]

It should be SSA, no?

[onyx swallow]

3 sides means?

[restive island]

oh

SSS

[onyx swallow]

S mean sides

YES!

use only the info u have derived so far

[onyx swallow]

AAS means 2 angle and 1 side

[restive island]

Wait…what??

[onyx swallow]

SAS means an angle squished inbetween 2 sides

congrats!

[restive island]

4 and 7 were CPCTC

No I didn’t get it right

[onyx swallow]

u r correct

congruent object means every part are the same

[restive island]

I accidentally chose the wrong answers

[onyx swallow]

again, restating what is congruency

[restive island]

Equal angles

[onyx swallow]

congruent means EVERYTHING are the same but position

so if 2 triangles are congruent

all corresponding angles are EQUAL, but position is shifted

[restive island]

I should’ve picked CPCTC, I didn’t realize it was there

I learned what I did wrong now, I was right about everything else

[onyx swallow]

oh so the pic u r showing is the solution?

[restive island]

Yes

[onyx swallow]

rip

[restive island]

Yeah I know

[onyx swallow]

but glad u understood the concept

ppl say that its more important to learn stuff

but marks matters, so rip

[onyx swallow]

cuz altho tru, ppl always look at marks

[restive island]

Eh it’s okay, I’ll just deal with it

Yeah that’s what I hate about school, it’s all about marks

[onyx swallow]

at least u understand it now, ull ace the next test abt congruency

[restive island]

I definitely will, thank you for helping me!

[onyx swallow]

ikr

[onyx swallow]

my pleasure

[lone heart]

@restive island Has your question been resolved?

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[weak badge]

can someone help me with some more matrices stuff, I kinda just wanna double check im on the right path

[wary stream]

Post your question

[weak badge]

ive done a b and c

but I was having trouble with double checking the left eigenvalue as I've never done it

and since I thought the left eigenvector is a row, and its by 2 I don't think its actually possible to multiply it by L in the first place

[lone heart]

@weak badge Has your question been resolved?

[weak badge]

<@&286206848099549185>

[chrome salmon]

You mean 1×2 matrix?

You can find right eigenvectors of L^T and that will be equivalent

[weak badge]

yea its a 1x2 row matrix

I wanted to use this equation to check my answer

but as v is a row matrix and L is 2x2 it doesn't even work

[chrome salmon]

It does tho

Well its left so $\bar{v} L$

[weak badge]

so that would be * the scalar eigenvalue 3/2 yea?

[ocean seal]

it's Sam

[weak badge]

so left vector * scalar eigenvalue

and I still don't get how you * the L

[chrome salmon]

$\textcolor{red}{\begin{bmatrix} x&y\end{bmatrix} \begin{bmatrix} 9/10 & 3 \ 3/10 &0 \end{bmatrix} = \begin{bmatrix} \frac{9x+3y}{10} & 3x \end{bmatrix}}$

[ocean seal]

it's Sam

[weak badge]

.close

[lone heart]

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[chrome salmon]

Is it over?

[lone heart]

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[hardy smelt]

How do you find a & r in a geometric series, for example 1/(2^n). In the textbook, a is 1/2 and r is 1/2. Does this come from factoring out 1/2?

[hardy smelt]

I feel like this should be easy to understand but for some reason I'm not getting it :/

I mean I understand you can manually calculate a1, a2, a3 etc. and find that a common ratio exists, but there has to be an easier way, right?

[vale wigeon]

the series $\sum a \cdot r^n$ has common ratio $r$

[ocean seal]

Ann

[hardy smelt]

right

[bright hedge]

i think in this case

its using the fact that

$\sum_{n=0}^{\infty} r^n = \frac{1}{1-r}$

[ocean seal]

not discordmod

[bright hedge]

so now lets say it starts at 1 instead of 0

we could rebound it by decreasing the starting index and increasing everywhere its used

so we could say

[chrome salmon]

r in numerator

[bright hedge]

we could say this

$\sum_{n=1}^{\infty} r^{n-1} = \frac{1}{1-r}$

[ocean seal]

not discordmod

[bright hedge]

this and

[hardy smelt]

ok

[bright hedge]

this are the same

[hardy smelt]

right

[bright hedge]

(we just reindexed)

but in ur example

we had

$\sum_{n=1}^{\infty} ({\frac{1}{2}})^n$

[hardy smelt]

1/(2)^n

[ocean seal]

not discordmod

[bright hedge]

yes but it could be rewritten like this right?

[hardy smelt]

wait is (1/2)^n = 1/(2^n)?

[bright hedge]

yes

cuz 1 to any power is still 1

[hardy smelt]

ah right

[bright hedge]

so now

[hardy smelt]

would that hold true with other numerators ?

no

[bright hedge]

you can distribute it

[hardy smelt]

nvm

[bright hedge]

$\frac{2}{3}^6$

would be

[ocean seal]

not discordmod

[bright hedge]

$\frac{2^6}{3^6}$ right

[ocean seal]

not discordmod

[bright hedge]

anyways

[hardy smelt]

yea

[bright hedge]

$\sum_{n=1}^{\infty} ({\frac{1}{2}})^n = \sum_{n=0}^{\infty} ({\frac{1}{2}})^{n+1}$

[ocean seal]

not discordmod

[bright hedge]

i reindexed this sum

i decreased the starting n by 1 and i increased it everywhere else

[hardy smelt]

ok

[bright hedge]

you can think through this and see why it works

1/2^1 = 1/2^(0+1)

so it ends up being the same thing

anyways

we know that when you add powers

you are just multiplying so

$(\frac12)^{n+1} = (\frac12)^n \cdot \frac12$

[ocean seal]

not discordmod

[bright hedge]

this is true right?

[hardy smelt]

yea

[bright hedge]

so now we can say

$\sum_{n=0}^{\infty} ({\frac{1}{2}})^{n+1} = \frac12 \cdot \sum_{n=0}^{\infty} ({\frac{1}{2}})^{n}$

[hardy smelt]

I seeeeeee

yeea

[ocean seal]

not discordmod

[bright hedge]

now we know what the right side is

it is just

$\frac{1}{1-\frac12}$

[ocean seal]

not discordmod

[bright hedge]

but we have to multiply it by a half

so it becomes

$\frac{\frac12}{1-\frac12}$

[ocean seal]

not discordmod

[bright hedge]

(so the reason that the a value was 1/2 was because the book factored out a 1/2)

[bright hedge]

was that all you needed?

[hardy smelt]

kind of

I can understand how you got there

and I could repeat it if needed

[bright hedge]

would it be okay to open this help channel to other people? (is your question done)

[hardy smelt]

yea go ahead

.close

[lone heart]

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[dusk pecan]

hi there, trying to do this related rates of changes question.

[dusk pecan]

i remember the teacher did some complicated stuff with the derivatives, just not quite sure where to start! the correct answer is B

[lone heart]

@dusk pecan Has your question been resolved?

[dusk pecan]

<@&286206848099549185>

[hot ember]

yes

[lone heart]

@dusk pecan Has your question been resolved?

[dusk pecan]

<@&286206848099549185> sorry don’t mean to spam but could you please have a look at this?

[alpine sable]

.open

.reopen

[chrome salmon]

You have been given how the rate of surface area changes from this you can determine the rate at which a side increases and then for volume

[dusk pecan]

could you do working please? im not sure how to do that

[chrome salmon]

I can only give hints

You know the formula of surface area and volume?

[dusk pecan]

A=6s^2 and V=s^3

[chrome salmon]

So what is dA/ds

[dusk pecan]

12s

it's not an exam i'm doing, its a pratice paper for a test i have tomorrow so i'm not cheating on a test

i can send u the whole practice paper so you know im not cheating i just need to know the process and working out

[chrome salmon]

Ik but it's about your understanding and you solving it

[dusk pecan]

i can understand from working

its all good ill email my teacher

thank you though

[dusk pecan]

.close

[lone heart]

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[wheat prawn]

bro

[wheat prawn]

can sm1 help me

i cant solve this trig prove

@alpine sable could u please help me

sorry for ping

but i have bene stuck on this

for like hours

[alpine sable]

I can't read your handwriting on the right hand side of the equation

[wheat prawn]

$\frac{sin2x}{1-cos2x}=2csc2x-tanx$

[alpine sable]

Was this the original problem, or have you done something so far?

[wheat prawn]

thats is the original

bruh

how do u do it in a fraction

[alpine sable]

\frac{}{}

[ocean seal]

Roberttt

[wheat prawn]

there

[alpine sable]

I'm sorry Im on the bus right now, wait a few minutes and tag the helpers so someone can help you out

Sorry buddy!

[wheat prawn]

alright thanks for trying

<@&286206848099549185>

@chrome salmon sorry for the ping but could u please help

been stuck for hours

im really sorry for the pinmg

[chrome salmon]

Let's wait for hvna

[wheat prawn]

she gone to school

[noble sinew]

start with writing out the definitions of the trig stuff

[chrome salmon]

Idk the best way to solve this

[wheat prawn]

wym

the identities?

[noble sinew]

yes you have a tan and csc

[wheat prawn]

which side is better to work on:?

i was trynna solve from left

but idk what to do

[noble sinew]

show RHS multiplied by (1-cos(2x)) is equal to sin(2x)

[wheat prawn]

what

[noble sinew]

what?

[wheat prawn]

i didnt understand what u said

multiplied by 1-cos2x?

[noble sinew]

showing sin(2x)/(1-cos(2x)) is equal to RHS

[wheat prawn]

oh

ok

[noble sinew]

is equivalent to showing sin(2x) is equal to RHS multiplied by (1-cos(2x))

is it not?

[wheat prawn]

i dont understand what u mean multiplied by 1-cos2x

[wheat prawn]

could u write it out

like from the bot

[noble sinew]

$a/b=c$ if $a=b \cdot c$

[ocean seal]

ScapeProf

[wheat prawn]

yea

[noble sinew]

so I can move (1-cos(2x)) to the other side?

what is it you don't understand?

[wheat prawn]

oh have not learned that

[noble sinew]

you just said "yea"

[wheat prawn]

we are just using identities to solve

i thought u meant something else

we cant move it to the other side

we have to prove 1 side = the other

[noble sinew]

its equivalent my friend

[wheat prawn]

yea but the teacher wont mark it right

since we have not learnt that yet

and im already like piled with a lot of homework

would we want to do that or no

because i really dont know what to do

because we need a sin and cos on the bottom

@noble sinew do u know?

@chrome salmon can u help plzzz

<@&286206848099549185>

<@&286206848099549185>

plz could sm1 help

[lone heart]

@wheat prawn Has your question been resolved?

[wheat prawn]

<@&286206848099549185>

plz

its been 2 hours

my test is tom

sm1

[sand geode]

Hi @wheat prawn

[wheat prawn]

TYHANKYOU

[wheat prawn]

i have been stuck on this question\

@sand geode

[sand geode]

Alright let's take a look

[sand geode]

We start here?

[wheat prawn]

yes

that is the original

[sand geode]

Ok

[wheat prawn]

no

not that

we start from the original

[wheat prawn]

.

from here

[sand geode]

What are we supposed to do here? Simplify?

[wheat prawn]

no we are supposed to prove 1 side = the other

its a trig prove question

[sand geode]

Oh I see, sorry

Just a sec

[wheat prawn]

alr

[sand geode]

Can you take it from there maybe?

[wheat prawn]

i can barely see that

[wheat prawn]

wouldnt the 2 go ontop of the 1?

[sand geode]

It would

[wheat prawn]

now would we multiply each side by 1?

like sin/cos by sin

and 2/sinx by cos

[sand geode]

Mhmm

[wheat prawn]

so this

@

@sand geode what do we do

from here

[sand geode]

Keep going

[wheat prawn]

idk what t odo

there is so many things

i can do

but

i just get stuck

@sand geode maybe a hint?

[sand geode]

That's how far I've gotten

[wheat prawn]

what did u do on 5th and 6th step

[lone heart]

@wheat prawn Has your question been resolved?

[lone heart]

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[rapid heron]

.reopen

[lone heart]

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[rapid heron]

@wheat prawn

Slove the LHS not the RHS

[lone heart]

@rapid heron Has your question been resolved?

[rapid heron]

Paper website if you don't understand the website version

http://mathcentral.uregina.ca/qq/database/qq.09.06/mark1.html

Little tricky lol

[lone heart]

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[coarse pewter]

Hi guys, can you help me solve this one?

[alpine sable]

They're nothing to solve, you mean simplify?

[coarse pewter]

Yes2, I think that what its called

Im trying to learn how to simplify

[alpine sable]

The 2s cancel. 2/2 =1

[coarse pewter]

I'm confused, i'm sorry. can you help me why it is cancelled?

[alpine sable]

Because 2 divided by 2 is equal to 1

[coarse pewter]

but where did the division come from?

[alpine sable]

That's what the line means

Between two and one and x and 2

[balmy light]

look at it this way

2/1 is the same as 2

dont bealive me, pick any number and divide it by one in the calc, you will get the number you chose

now we need to do 2 multiply x/2

2 X x = 2x /2 = x

answer is x

[coarse pewter]

Okay, so 2 because it is a common factor, will get cancelled?

Okay I get it now. Thank youuuu ❤️ ! I think It's already solved.

.close

[lone heart]

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[alpine sable]

how do i show that the minimum of this function is positive?

[alpine sable]

i did took the derivative for t under the integral but it came out wrong

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

<@&286206848099549185>

[lone heart]

@alpine sable Has your question been resolved?

[alpine sable]

.close

[lone heart]

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[uneven lily]

I have a proof for (i), but don't have an idea about (ii). can someone help me to how to start the proof for (ii)?

[lone heart]

@uneven lily Has your question been resolved?

[lone heart]

@uneven lily Has your question been resolved?

[lone heart]

@uneven lily Has your question been resolved?

[analog locust]

hi

how do you change a scale?

like for an example

I have the value x = 3

from a scale of 1-10

what would x be in a scale of 1-100?

or in a scale of 0-255?

[lone heart]

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[lone heart]

@scenic musk Has your question been resolved?

[lone heart]

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[misty bobcat]

Describe all pairs of positive integers $m, n$. For which the number $\log_3$ m + $\log_3 n$ is rational. Explain that pairs other than those described do not match.

[ocean seal]

Michal

[harsh swallow]

What do you need the help with?

the concept?

[lone heart]

@misty bobcat Has your question been resolved?

[raven rover]

^^

You can't just post a question and expect people to do it. You need to show an effort or at least some thought process towards your approach.

[lone heart]

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[misty bobcat]

No

[lone heart]

@misty bobcat Has your question been resolved?

[misty bobcat]

My current result is mn = 3 ^ (p/q)

But i dont know of it's enough

[lone heart]

@misty bobcat Has your question been resolved?

[lone heart]

@misty bobcat Has your question been resolved?

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[ocean seal]

Yeetus

Yeetus

[lone heart]

@desert zephyr Has your question been resolved?

[brave solar]

i think you need to take the eigenvector as the initial condition

[lone heart]

@desert zephyr Has your question been resolved?

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[inner bolt]

how would i go about finding a closed form for this

[ocean seal]

fall

[inner bolt]

i tried repeated substitution but it only got me a more complicated looking formula

[lone heart]

@inner bolt Has your question been resolved?

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[inner bolt]

.reopen

[lone heart]

✅

[inner bolt]

<@&286206848099549185>

[lone heart]

@inner bolt Has your question been resolved?

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[inner bolt]

.close

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[deep cove]

https://i.imgur.com/RIgcjYb.png

[deep cove]

How did they get .9603?

[ebon condor]

It tells you how

[deep cove]

I dont understand the

https://i.imgur.com/xJzMdeW.png

I did try playing around with it but end up wit .95 or .97

Oh

Wait hmm

[deep cove]

https://i.imgur.com/CUdJlkY.png

Yeah I am lost 😫

pretty sure I need to z score 420, 20.48

[ebon condor]

Looks like a mean and std

With a bound

It’s terrible notation

Also I have to go, sorry for starting without being able to finish

[deep cove]

no problem, take care

[modest zodiac]

I think that $Z_{a,b}$ is a Gaussian with mean $a$, and STD (or variance ??) $b$

[ocean seal]

polikuj2

[deep cove]

how could I use that to get their ans? >_<

[modest zodiac]

Using a calculator, and its function to compute probabilities of a Normal distribution

[deep cove]

its z=x- mu / std right?

https://i.imgur.com/RZMOyOx.png

then converted to z score, I get .931756

[modest zodiac]

What is z score ?

[deep cove]

its like how far a data is from the mean

where z=0 is the middle

[modest zodiac]

Oh, ok, didn't know this name

[deep cove]

do you know what is done specifically to get their ans?

my ans is off by 3% ..

actually im even confused if its 450.5 - 420 here or the other way around

[lone heart]

@deep cove Has your question been resolved?

[deep cove]

https://i.imgur.com/RIgcjYb.png

How do they get .9603 here?

https://i.imgur.com/xJzMdeW.png

Does this mean find the probabily that the num will be <= 450.5 given the mean=420 and std=20.48?

[modest zodiac]

That's what I understand from it

[deep cove]

do you know how they did it?

I dont get .9603 no matter what I do

[deep cove]

zscore(1.48925)=.9318

still not correct..

<@&286206848099549185>

[modest zodiac]

Ok, think I got it

A normal function is symetric

What you're computing is both sides, but you want only one

[deep cove]

what do you mean?

even if I calculate both the lefthand side (420-20.48) and calculate for the z score its not close to the ans at all

[mortal turtle]

I also performed the z score calculations and they were not accurate, I found similar notation on this page: https://www.statisticshowto.com/probability-and-statistics/binomial-theorem/normal-approximation-to-the-binomial/ but it doesn't seem to be shedding any light

they didn't do the calculations for the sdev correctly

do the calculations under the radical by yourself and you'll get the right answer

@deep cove

ping me if u see this

the sdev should be like 17.38965 instead of 20.48

[lone heart]

@deep cove Has your question been resolved?

[deep cove]

Thank you so much! I used the 17.38 and it does give the correct value!

[lone heart]

@deep cove Has your question been resolved?

[lone heart]

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[candid niche]

Hi I was just introduced to the 'is proportional to'-symbol and I can’t wrap my head around it

One example given was that if A ∝ 1/B^2 and we double B, A will be reduced with a factor of 0.25

[candid niche]

I do not understand where 0.25 comes from and why A is being reduced my understanding was that they both double?

[smoky cloud]

kk

see bro but b as 2b what do u get ??

[candid niche]

not sure I understand? Like A ∝ 1/2b^2 ?

[smoky cloud]

so A' ∝ 1/(2b)^2 = A' ∝ 1/4b^2
so 1/4=0.25 this is how it comes

[kindred warren]

doubling B gives $\frac{1}{(2B)^2}$

[ocean seal]

Tra-Guy

[kindred warren]

which is $\frac{1}{4B^2}$

[ocean seal]

Tra-Guy

[candid niche]

thanks for clearing it up guys i have a better understanding of proportion now!

[smoky cloud]

proportion is really ez man
any further doubts u can dm too (idk abt him though but u can to me )

[lone heart]

@candid niche Has your question been resolved?

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[plain sigil]

Someone please I’m struggling

Lol

<@&286206848099549185>

[sonic wyvern]

definition of midpoint i think

[plain sigil]

Thankyou!

[sonic wyvern]

i miss geometry

[plain sigil]

It’s easy for the most part

[bleak ridge]

Have I seen you before

[sonic wyvern]

have u?

[bleak ridge]

I recognize your pfp and name for some reason

[plain sigil]

.

[sonic wyvern]

sas

[smoky cloud]

SAS ig

ya

[plain sigil]

Thankyou guys

[sonic wyvern]

do u see why

[plain sigil]

No

[sonic wyvern]

ok well

[smoky cloud]

thank you
bcos it has been so long I've see congruency

[sonic wyvern]

you're given that sw and tu are congruent

thats one side

then you're given that sv and tv are congruent

thats two sides

then you're given thats angle vsw and angle utv are congruent

thats an angle

thus sas

[plain sigil]

Ahhhh ok

Still a confused I’m gonna keep sending them if that ok

@sonic wyvern

[sonic wyvern]

well

there are no right angles

u can rule that out

i believe its angle bisector

[plain sigil]

Ok

[sonic wyvern]

but it could be vertical angle

i honestly forget what that is

[plain sigil]

I was think vertical angle

@sonic wyvern

[sonic wyvern]

what do you think

[plain sigil]

SSS?

[sonic wyvern]

we just found out that two sides of each triangle are congruent

where did we prove that a third is congruent

we didnt

we proved that two sides and an angle from each are congruent

[plain sigil]

Ohhhhh that makes sense

Thankyou

[sonic wyvern]

yes

[plain sigil]

How can i repay you

[sonic wyvern]

$5

was vertical angle theorem correct

[plain sigil]

Yes!

[sonic wyvern]

i think i was confusing angle bisector and vertical angle theorem

[plain sigil]

Ahh ok

Check DMS

.close

[lone heart]

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[alpine sable]

I think u are

[lone heart]

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[vague iris]

Why is it in decimals and not expressed in pi? I'm confused. Our teacher didn't teach this to us.

[bleak ridge]

Wdym

[junior tartan]

what's the conversion rate from radians to degrees

[vague iris]

are the 2.69 rad and 50.25 in radians?