#help-0
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is there any more efficient way to compute something like $3781 \mod{54}$ by hand without doing long division?
bot
@red kindle Has your question been resolved?
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Fermat's little theorem says that if $p$ prime and $a$ an integer where $a$ doesn't divide $p$, then $a^{p-1} \equiv 1 \mod{p}$. So, is $3620^3 \mod{73}$ solve-able with fermat's little theorem?
bot
@red kindle Has your question been resolved?
0.37 as a simplified fraction.
huh
@red kindle Has your question been resolved?
a = 3620^3, p = 73
apply (3620^3)^(73-1) = 1 mod 73
That gives you a big ass number = 1 mod 73, and then you just apply the actual theorem "p divides aᵖ⁻¹ - 1"
OR
to get a nice clear answer
((3620^3)^(73-1)-1) mod 73 = 0
If you do get that, then you confirm it's a prime
The teacher was really just being tricky by using a number with an exponent already on it so people would try to do something like 3620^3-1 = 1 mod 73, I think
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Anyone know what I'm doing wrong here?
My suspected issue was that I was getting an incorrect t
When I solved by hand, I got t = 2000 + 25q - q^2
Which when I multiply by q, I get the total revenue (T) to be 2000q + 25q^2-q^3
Derivative would be 2000+50q-3q^2 of that.
When I set that equal to 0, I got something weird.
And don't know if I should even bother trying to move forward with that direction.
@tardy torrent Has your question been resolved?
<@&286206848099549185> Still haven't figured out. Pls help.
@tardy torrent Has your question been resolved?
😤
Hello, how are you getting that value for t? I think you should explain the process involved to find T in terms of t because it looks like there are economy concepts that not everyone knows
@tardy torrent Has your question been resolved?
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Find y if sin (y + 6) = cos 2y, if y is acute.
I don't understand how to solve these type of questions, if someone could help it would be great
degrees or radians
i'm assuming degrees
sin sum formula
sin(y)cos(6) + sin(6)cos(y) = cos(2y)
now then, double angle cosine
cos(2y) = 2sin(y)cos(y)
cos(6)sin(y) + sin(6)cos(y) = 2sin(y)cos(y)
i havent been taught these formulas, ive been taught only simpler formulas. so there must be another way which is a bit more "basic"
transcendental equations usually do not have closed form solutions
okay
okay ill try that one sec
can you please frame that with the values, so i understand better?
wdym
i gave you the formula
use a little bit of brainpower. the cosine of a number always equals the sine of the sum of 90 and that number
im sorry im not really good and trigonometry, ill try this one
so what is the cosine of 2y?
if cos(x) = sin(90+x) then cos(2y) = sin(90 + 2y)
it's just a straight substitution
that's how you use formulas
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Can I please get help on this.
I have no work on this one right now because I’ve been trying multiple problems but I keep getting the answers wrong
slope is (change in y)/(change in x)
I know but when I get an answer it says it’s wrong
-4/3?
show your working?
^^
It was correct how did you find it?
show your working to compare
24 971 cm 2 to the nearest 100cm2
you seem not to be calculating change in y correctly
Oh
Take (-2, 2) (5, -2)
as well as change in x
sometimes the coordinates were added instead of subtracted
which may seem confusing because you are working with negative numbers
along the same line?
like for example (8, 16) (10, 10)
this one was all positive
but the coordinates were added?
Nono like another question I’m stuck on
ig should be fine
as you know, slope = rise/run right?
Yes
can you calculate the rise and the run?
My brain just died when you said that.
hmm, is it because you are familiar with finding the rise and run between 2 points?
but not when there are no points to find a slope?
I think?
okay, which two points are easy to reference the slope from?
maybe a start point and end point for the slope?
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lol i guess that's resolved
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I dont understand how to transform it into a simpson formula
its usualy h/3 ( y0 + yN + 4(y1+ y2+y3+...) +2(y2+y4+...)) right
Wait nvm
I understand it
.close
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@silver tangle Has your question been resolved?
Bye
What does the ^ notation refer to
could somebodyhelpwith calculus
i dont understand this question it is about optimization
Don't ask in an occupied channel
Read #❓how-to-get-help
ill give you six thousand dollars if you help me
No
No
@silver tangle Has your question been resolved?
@silver tangle Has your question been resolved?
@silver tangle ?
what the hell is a a+bx+series...?
also what's the question?
$\hat{\cos(x)}$ means the fourier series of $\cos(x)$ not cos x itself
Ryuzaki
you have a initial data?
you can't assume it'll have a form like that
it may not
you might have got the idea from heat equation
but no, these equations are inherently different
depends on the initial data like say you are given
\begin{align*}
u_{tt} &= c^2u_{tt} \
u(x, 0) &= f(x) \
u_t(x, 0) &= g(x)
\end{align*}
then your solution will be of the form $u(x, t) = \frac{1}{2}(f(x-ct)+f(x+ct))+\frac{1}{2c}\int_{x-ct}^{x+ct} g(x) \dd s$
Ryuzaki
but if you are given boundary data instead of initial data, then It'll be something + a fourier series
that something may not always be a "a+bx"
why are you assuming you'll have something like a+bx+ct+dxt ???
as I said it can even be e^x or a discontinuous function
can someone teach me how to do math? I have no idea of what these letters mean.
Honestly, watching YouTube is your best option.
ie assuming the solution is of the form $X(x)T(t)$ and not of the form $a+bx$
Ryuzaki
alright, I'll be back.
read the chapter/notes carefully
Ye
Practice makes perfection xd
OK so he's not ASSUMING solution is of the form
He's simply solving a BV problem and showing if \lambda=0 is a eigen value then only possible value for X(t) = a+bx, together with the BV conditions mean taht a=b=0, so, only trivial solution
he's now showing that it's a solution but showing that it's not
No
if your boundary conditions allow a solution like a+bx then you do
but SLBVP problem don't allow that in general, they'll only have +ve eigen values
0
ok maybe that depends on what you call lambda
but the standard equation is $X''+\lambda X=0$
Ryuzaki
you'll get non trivial solutions (i.e. eigen functions) iff lambda > 0
if you are using -lambda, then <0
$\widehat{\cos(x)}$ is the fourier series of cos(x)
Ryuzaki
it's already written in form $0+1\cdot \cos(1\cdot x) + 0\cdot\cos(2\cdot x)+\cdots$ so as you see $a_n=0$ unless $n=1$
Ryuzaki
or -1
that's what it's saying
what is the fourier series of cos(x)?
really?
a_n=1?
for all n?
Hi can someone explain how the 3+root3 came
<@&268886789983436800>
Please don't ping moderators or other users randomly for math help. Also, read #❓how-to-get-help and use a new available channel.
what is the close form of this recursive function
even a link/article appreciated
read #❓how-to-get-help , don't hijack other people's channels
what do you mean
ok
let me see
Sry meant to tag helpers
<@&286206848099549185>
Please use an available help channel. Don't step over a channel already in use by someone else.
Consider reading #❓how-to-get-help once.
?? It’s been like 2hrs since last question???
ok
@silver tangle Has your question been resolved?
well, no, the range of your 3 functions is -1 <= y <= 1
the range of your piecewise* function is that
your range has to be strictly greater than 3, and less than or equal to 1
oh shit wrong channel, sorry
use one of free channels
it's pandemonium over here
Hi
<@&286206848099549185>
I need help with a problem
Now let's make this easy and say that the premium paid product is just a $100 lifetime fee.
Now let's say that all free users on the site that still haven't paid after month 1 (month 2 free users), will then be 50% less likely to convert compared to the first month free users. And then subsequently for month 3, those existing month 3 free users will then be 50% less likely to convert compared to the month 2 free users, and so on, etc...
What is the average lifetime value in dollars (or equation) generated for free users if we extrapolate out to one year?
Noooooo.
It looks like one but noooooo.
,w plot cosh(x), x^2, |x^3| from -10 to +10
Hold on.
The catenary is the natural shape of a free hanging rope or chain and can be found everywhere. From the the wires of a pylon to the thread of a spider's web. From the world of bubbles to the world of architecture. What is the catenary and why is it all around us?
Presented by James Grime http://youtube.com/singingbanana
Made by Ben Bailey http:...
No. cosh is an exponential function. It will always exceed a polynomial.
Just realized this channel is someone else's.
Next time, open a new channel to ask.d
ohh
Or #discussion
@past hornet Watch this tho'.
Great explanation of cosh and catenary.
am stuck on this
i figured the limit of that value at the bototm
would be 1^inf
which is 1
your final simplification form is correct
now the limit
both num and denum are inf
?
oof sorry
it's 1/e
?
can anyone help me with my 8th grade home work
just ask 🙂
i need help
I mean, we can't see the table for how much he gets paid....so....
the table
You're in 2 different channels. I'll default to whomever is helping you in the other channel.
👍
So In my calc class we're learning how to integrate by using u-substitution. And i'm having trouble finding what value "u" should be. trying some practice problems. was wondering if somebody could point me in the right direction as to where to start and what u should be in this problem.
what is that exponent on -1/x^2
3/8
i can’t but it’s definitely possible
wait a second
you might be able to do u sub actually
rewrite it as multiplication instead of division
it says to make u=-1/x^2 in the hints
yes that’s right
d/dx -1/x^2 = d/dx -x^-2 = 2x^-3 = 2/x^3
ahh you smart smart
i see what you did there.
so lemme try it.
like this right.
yes your right
so then don't i have to do the whole. du=-2/x^3 *dx
and then solve for dx
so that I can substitute du into the integral.
messed up
u = -1/x^2, du = 2/x^3 dx
which are both in the integral
the original integral
no multiplying by a constant or moving terms around necessary
at least i don’t think
ok multiplying by -1 is necessary
but that’s it
so your saying I don't need to solve for dx, I just put what we have for du wherever dx is?
no
find whatever du is equal to in the original integral
if you have all that stuff replace it all with du
I'm some trouble understanding this.
-(u)^(3/8) du
should be the only thing in the integral now
the way you did it had two variables in the integral
which you don’t want
could you write that one part out? i'm not too sure what you mean.
which part exactly?
like after you find out what u and du are. how exactly does that go into the integral?
ok so you already know that whatever u is defined as is in the original integral so we don’t need to talk about that
yes
we have du = 2/x^3 dx
can you find something like that in the original integral?
if not you can multiply both sides by a constant
well yeah in the original integral you could just split it into 2/x^3 * -1/x^2^3/8 right
no
wait i misunderstood
yes
your lack of parenthesis confused me but i figured out what you meant
sorry i just saw that.
although that’s not necessary here
because u sub will work
wait never mind you didn’t mean what i was thinking of
yes you can do that
you found something that resembled du
would you be able to go into voice so I can share my ipad screen with you?
the problem is that that is positive and du is negative, although we can multiply du by -1
sorry no
okay well ima try and work this one out. thanks for your help.
this explains it better than me, https://tutorial.math.lamar.edu/Classes/CalcI/SubstitutionRuleIndefinite.aspx
In this section we will start using one of the more common and useful integration techniques – The Substitution Rule. With the substitution rule we will be able integrate a wider variety of functions. The integrals in this section will all require some manipulation of the function prior to integrating unlike most of the integrals from the prev...
can someone help me find perimeter
you use pythagorean theorem for the longest triangle side
then you find circumference and divide by two
then add that+long triangle leg+bottom triangle leg
so 9 ^2 + 14^2 =c^2?
yea
ok thank u
wai for the circumstance it’s pi (9) /2?
this is a very funky ice cream cone.
@silver tangle Has your question been resolved?
Oh cool this server has texit
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How could I simplify:
$80+84+88+92+96+100...+n_{36}$
Lambdalo
as in, just write this as a nice formula
The Sum symbol
yeah I knew that, just how specifically
The top part is the highest integer it goes to and the bottom part is the integer it starts at.
And the formula in the middle
?
wait
$\sum_{k=80}^{36}k+4$
wait but probably switch 36
with the actual result
Lambdalo
You put the formula there which is in this case. 76 + 4n
if you switch 36 and 80, this would mean
(36 + 4) + (37 + 4) + ... (79 + 4) + (80 + 4)
which is incorrect, that's true
The bit at the bottom is the starting value for N. So n = 1
$\sum_{N =1}^{36}76+4n$
Phaseloli666
is that true though?
the problem is, that 76 rises as well, which it doesn't in my original series
this would mean
(76 + 4*1) + (76 + 4*2) + (76 + 4*3) + ... + (76 + 4*36)
= 80 + 84 + 88 + ...
oh wait you're right
You can find the formula from $T_n = a + d(n-1)$
Phaseloli666
so only the variable that you define as the starting point actually rises, interesting
All i did was 80 + 4(n-1)
As 80 is the start Point and d is the difference between the terms
many thanks
@alpine sable Has your question been resolved?
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Is it correct to say Z/2Z = {0, 1} or would that be wrong?
Nvm, different question
what exactly is the operation in Z/2Z?
is it basically a group (Z, z mod 2)? Hope that makes sense
Is z a complex number
Or I mean Z or z or wotever
Z are the integers
Z_2 has 2 operations..
- and *
cause it's a field
we didn't learn about fields yet, only groups
hope group is the right term
group homomorphisms and stuff
I wonder how I can show that this is a group homomorphism
the second set there has * as operator
but idk what the operator is in Z/2Z
f([x] * [y]) = f([x]) * f([y]) is what I wrote down
but then I thought wait, how do I know that * is defined in Z/2Z
isn't the operator in Z/2Z mod?
No
or am I misunderstanding
Z_2 is just {0,1} with modular + and *
ohh I see
ie 1+1=0 since 2 is 0 mod 2
hm but then I'm not sure if I have to pick modular + or * for the equation I wrote above
to show that it's a group homomorphism
usually we only deal with groups that have 1 operation
I'd guess it's R * on the right group
R?
but what about the left group Z/2Z
it has + and *
I have to pick * I suppose
I figured out that it's not a group homomorphism hope that's right
or do I actually need to use both + and * to show that it's a group homomorphism?
I also wonder, if I have a map Z/2Z -> Z, [x] -> x, let's take as an example [16]. [16] = [0] in Z/2Z. But if I put [16] in the map, do I get [16] -> 16 or [16] -> 0 <=> [16] -> 16 mod 2? 🤔
the latter I hope
@raven girder Has your question been resolved?
.close
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Why do I need lhopital to prove this is zero?
i could just plug the minus infinity to e^x and it'd be 0, no?
what am I missing here?
@alpine sable x^3 -> -∞
You're not multiplying ∞ by 0 explicitly
When do we know if we should use lhopital or not?
You're multiplying a number that gets bigger and bigger and bigger without stopping by a number that gets smaller and smaller and smaller (closer to 0) without stopping
When you get a situation like ∞ • 0, -∞ • 0, ∞/∞, 0/0
The first two you can rewrite so you get one in the form of the last two
They did LH
e^(-x) differentiates to -e^(-x)
However you could say it's 0 from the get go via growth logic
ok but are the general steps correct?
what’sthis?
How do I close help channel?
@glass lichen @raven rover thanks for your help guys
Just type .close
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Why is this 1 and not 0?
it seems the solution wants me to take exponent but i don't understand why i need to
oml it was that simple LOL
@zealous bloomwait so does that mean you can only use l'hopital when there's ∞ • 0, -∞ • 0, ∞/∞, 0/0 (like what shen said?)
I don't recall all forms necessary to use L'Hosptal's rule...I remember 0/0 was one, but that's all I can recall for now.
0⁰ DNE
Wait I thought that was undefined/indeterminate
so... im not supposed to just plug in the zeros?
the solution raised everything with an exponent
i still don't understand why it did that
never said the limit doesn't exist
only said that Lhopital is not applicable in the ∞/0 case
oh
also 0⁰ is undefined
@alpine sable Has your question been resolved?
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hello
ah i see, yeah i was thinking that too, but i just doubt if my answer is correct or not since i cant find it on google and need to pay for the answer ;-;
okay 1 more question
how do i determine truth or falsity?
especially the (c) one
got me confused
are my answers correct if all of the statements are false except (a)
alright thank you ❤️
.close
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no open again
it's just huwaa
for the (a)
isit correct if i made a statement
Everyone does not like strawberry
indicating that without the negation it will become
Someone likes strawberry
did it do correctlyyy
i am so confused on predicate logic
We're talking about (a)?
Yeah that's correct
More strictly:
"It is not the case that someone likes strawberries"
ahh... i see i see, so it's equivalent to ∀x~P(x) right
and literally just ~∃xP(x) without the bracket
can someone tell me the solution of this instead of x is 1/2 ,the second one?
maam
this is my channel
sorry
😭 its ok
sometimes the bracket got me
dammit
but i will try my best to understand this topic
"study logic" is a statement right?
nvm its not
n.n im done .close
.close
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If I have the function f(x) = 64x^3 - 16x^2 + 12x -1 how do I find f^-1(x) =
There's a few methods to finding inverses of functions. One is to "change" f(x) to y, so it will be y = 64x^3 - 16x^2 + 12x -1.
Then, switch the x and y's so it will be x = 64y^3 - 16y^2 + 12y -1.
Then, solve for y.
At then end you'll have y = answer, and just stick your inverse notation back in: f(x)^-1 = answer
But this is just A method.
So how do I rearrange it for y, I've always been bad at rearranging.
I just don't know where to start
What do you mean rearrange for y?
rearranging to make y the subject of the formula
I already rearranged it for you, so you actually just have to solve for y.
I guess I should factorise it to take y out of the brackets
? Are you asking how to solve for y?
Or how to rearrange it? I'm confused
@void magnet Has your question been resolved?
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<@&286206848099549185>
do you know the equation for point slope form?
yep
not in the slightest, no
because you're correct
but you said your not sure if im right
exactly
bcs i said is the answer that and you said yep
yeah it is
yep
are you sure?
not in the slightest, no
k
Find the graph of this
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@hollow zephyr Has your question been resolved?
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@hollow zephyr Has your question been resolved?
can someone help?
bro how dare you
Derivate of ln(u) is u'/u
Not 1/u
That's your mistake
I wasn't blaming you @hollow zephyr
Bro 
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hello
can someone show me how she found the derivative of A(x) to be that?
what rules did she use
open the original image because this is hard to see
use desmos
@pale terrace Has your question been resolved?
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Hey guys
so
I'm not sure if this is right
Bc it doesn't make sense
Idk
is it correct?
I got 2.9558 grams for part b
and 117.2316 seconds for c
until 20 grams remain
see #❓how-to-get-help , you should claim your own channel
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how would I factor this out im supposed to be able to factor out (h-2)
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can someone help me
you can calculate the full area of the pizza first
and then get the radius
(and then get the arc length)
5/6 radians = (180/π)*(5/6)
900/6π degrees
150/π degrees is about 47.74 degrees
47.74/360=13.26% of the circle
20/13.26%=150.82
the full pie is 150.82 square inches
πr^2=150.82
r^2=150.82/π
r=√(150.82/π)
r=6.928
d=2r
d=13.85
27. the diameter of the pizza is 13.85 inches
ill let u do 28
hmm
u can do that or
20=(1/2)(r^2)(5/6)
48=r^2
√48=r
r=6.928
d=2r
d=13.85
somehow my teacher got 4sqrt6 inches
but she didn’t send the work which is what i’m trying to find out how to do
how
√48 simplifies to 4√3
since diameter is 2*radius, it should be 8√3
ur teacher probably multiplied 2 to the √3 on accident
uh
the angle is 5/6 radians
the angle in the full pizza is 2*pi radians
(area proportional to angle)
no
no
full circle isnt 2rad
full pizza is 2π radian
what?
it’s 2pi
damn alright thanks
anyways #28 should be easy to do
since ur calculating arc length and we have the angle in radians u can just use arc length = radius * radian
is it 10sqrt3/3 ??
the radius is 4√3, multiply that by 5/6
u are correct
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if you're trying to find a 4 digit code, and the first digit is 7 and for the other 3 digits are the first digit multiplied 2 times, what is the answer
the first digit is 7
the other 3 digits can be calculated by 7^3 (7*7*7) as ur multiplying 7 by itself twice
7^3 is 343
your answer is 7343
What do you mean by other three digits are first digit multiplied by 2? 7*2=14??
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Hey, I know this is math help but anyone good a organic chem here?
Nope
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How do we find the angle working backwards from area
how did you do it forwards?
just calculating the areas of the sectors and subtracting, right?
to do it backwards
(wait a sec - creating diagram)
To do it forwards I did A= (theta/360)*3.14159r^2
wait a sec
what's R?
anyways
we have this
just calculate the highlighted area between the circles (uh i can't highlight that in geogebra)
the wiper would sweep that area if it were to turn for 2pi radians
area wiped is proportional to angle
r is radius
but which?
The length of the wiper
I found the are aby first calculating with the 22" wiper
Then calculating the 6" that were not cleaned
And subtracting
yeah that's right
We arent calculating area though
I am tryingto calculate the angle if area sweeped is 10"^2
I have to leave but thanks for the help
If you can respond to my question in one message please do I will read it over once I get home
i mean
area is proportional to angle
so you know the area
thus you can calculate the angle from there
How
The area is 508.24
Not sure how to ratio that down to ten
Nvm
Divide both sides by 50.824
No that wasnt it
i mean
My dumbass got 50.824 mixed with 50.284
Tysm got it
(assuming that the area is actually 508.24 - i haven't checked @white drum)
You got it right?
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help
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How do I know if I should use sine or cosine or tangent to find the total height of something?
Based on where the angle is located
So if it is touching the base and the hypothenuse?
Are you given values for the base and hypotenuse?
So which trig function relates the hypotenuse and the height?
I don’t remember 😭
I remember like the formulas but not how you use it
Yes
Why though?
Because you need the height. Given the position of the angle and the value of the hypotenuse, you will either use sine or cosine. If you used cosine, you'll be finding the base and that's not what you want. So by process of elimination, the logical one is sine
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Hi
I have to graph the black function on paper but after i factor im getting a different looking function...
u are factoring it wrong.see the numerator
thank you have a good day
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I was actually doing a physics question which asked to calculate work done by Force F after block reaches height h from ground but I can't understand that if x axis is l and y axis is h then why the professor has taken dx and dy and hypotenuse as dl
@alpine sable Has your question been resolved?
@alpine sable I think those are two separate diagrams and the labels are not related to each other
no, prof took a small part which he called dl out of the path, it is of 1 question only
path of what?
the wedge or the block on the wedge?
can you share the the full question, it's hard to guess what your professor was doing based on half a screenshot
ah okay
and this is the part I have doubt
and l is the horizontal distance?
well if u take dl as dx and dh as dy here and hypotenuse as something else, it will still cancel out after being multiplied with cos theta and give same input
okay wait, what is dw?
work done
ah alright
umgcos theta is the force and dl is the distance covered
this is what he did next step
okay that makes sense
I think he shouldn't have used l and dl to mean different things
wherever he has used dl just rename it to another variable like ds to avoid confusion
yeah, dx is basically dl right? and dy is dh
yes, and hypoteneuse is ds
yeah, that's what I also thought, hypotenuse be just another variable
thanks a lot for the help @pearl jasper
cool 🙂
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Find the mass of a particle which has a speed of 5.0 m/s and a kinetic energy of 5.0 J ?
KE=½mv²
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hello! could someone go through this with me?
You can calculate the derivative to determine the monotonicity of the function
ok so the derivative of the function, do you know what i need to do afterwards?
if f'>0 then f is increasing,if f'<0 then f is decreasing.
ok
If derivative equals zero, the time is the answer.
when it says 'during the first four hours' is there a certain calculation that i do as well ot determine that?
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what is the underline thing mean? I am confused
Maybe I am domb
It's the result from dot multiplication of n and (p-p1)
n⋅(p-p1) = (ai + bj + ck) ⋅ ((x-xp)i + (y-yp)j + (z-zp)z) = the result you underlined
K..?
Ok wait a sec bro let me read it
Ok the result you gave me is different than the underlined result though
How do I translate it to the underlined result
Okay I'll explain how you do dot multiplication then
Alright, so now you have to do the same with
(ai + bj + ck) ⋅ ((x-xp)i + (y-yp)j + (z-zp)z)
Treat x-xp like a single constant
Same with y-yp and z-zp
Ok
Doing so you should find that the expression is equal to
a(x-xp) + b(y-yp) + c(z-zp)
Multiply a, b, and c in and you get the underlined thing
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how do i get the limit of this term?
ah, the limit here looks a bit weird, were meant to get the limit of the whole term, not just the numerator
this does not look like one of the 7 indeterminate forms
do you know what those are?
im looking them up rn
okay, the idea is to take the limit of the numerator and the limit of the denominator and take the quotient?
yes
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gello
hello
The 12th Term of an arithmetic progression whose 15th term is 53 and whose 67th term is 261 is?
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1.) 16.041=-15sin(31.5-C)+D
2.) 0.332= -15cos(31.5-C)
can someone solve for c and d plz?
The numbers are not so nice.
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I am trying to understand how to dynamically rotate a vector3 point in respect to both a pivot point, and based on an axis (im using it for programming atm) (as well as an angle ofc)
how can i dynamically or mathematically to be exact find the vector direction in which i should rotate?
i will provide some pictures to show what i mean from the unity engine, but i implore you to think of this as a mathematical problem since i already made it work, but i wanna make it more clean
per example here
if i select X i expect it to distribute around my target, as well with respect to the X direction
Sad
similarly with y etc
feel free to ping me once you have any suggestions to solve this vector3 problem
@digital steeple Has your question been resolved?
<@&286206848099549185> is there someone who could potentially assist me with the vector3 logic?
oh god you're asking about quaternions.
yes pardon, it also includes quaternions
3blue1brown demystified it in a couple (three?) videos but they are long and I never watched them all in one sitting. I have no idea rn
yea thats understandable i am myself kinda confused about quaternions
But what i know about them is in a nutshell they are vector3 with angles
Go experience the explorable videos: https://eater.net/quaternions
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Pre...
^ not the first one
for Unity's purposes....
but it has more to do with complex analysis
(broadly)
I didn't finish complex analysis.
no i simply need to understand my question for now, and afterward i can spend time studying quaternions and complex analysis properly in my spare time
but i pinned your video in my list
right. But that's the closest I ever came to understanding it.
ah i see
In Unity, most tutorials implore you to use the conversion functions angleToQuaternion or whatever
thats why i emphasized essentially to think of this as a mathematical problem
i know the methods to a point, i know how to use them, i dont know how to put them together
and thats not due to my lack of programming knowledge, but more on my lack of quaternion and vector3 when they play together knowledge
@digital steeple watch that one video because I just did and now I at least feel confident about the math involved
ill have a look shortly
don't look there though
walk through this
you can actually fiddle with the numbers while he's talking, it's amazing
Walking through it i wanna rephrase my issue
As i watched i realized my question was probably not targeted properly to what i am trying to figure out
I am trying to figure out the euler angles ill have to rotate (since unity like you mentioned allows you to simplify initializing a quaternion by giving it a euler set of angles) that respect a target pivot and target axis
Per example:
Vector3 actualAxis = Vector3.zero;
if (axis.x > 0)
{
actualAxis.z = 1;
}
if (axis.y > 0)
{
actualAxis.x = 1;
}
if (axis.z > 0)
{
actualAxis.y = 1;
}```
here you are gonna notice i am mockingly using a second vector, which i adjust manually to figure out the 2 different points
quaternions will always find the shortest angle traversal between two points on a sphere.
In this case euler angles are kinda an unsimplification
its simpler to understand for me due to x - y - z
it will trace an arc of a Great Circle
while quaternions look like rotation matrices
you're not gonna make sense of it in euler
i am not following
Does unity have a quaternion library
yes it does
It should be fairly easy to solve then
Quaternions just take an axis to rotate about and an angle
The imaginary part are the three components of the vector to rotate about and the real part is double the angle
yea my issue is just distincting what axis do i offset my target point dynamically, based on the axis i wanna rotate towards
hello lads i have no contribution to this conversation and i am shit at math but whats the 4th dimension ive always wondered
in really simple terms
Do you mean for the pivot point
nah i mean just in general
math equivalent of photobombing or leaving shit on the porch
target point => Offset point from my pivot
target point offset axis => what axis do i use to offset my item using math?
axis => my intended axis i wanna distribute my vector3 around
i know target point, i know axis
is this talking about me or 4th dimension haha
i dont know the offset axis (or to rephrase, the offset direction)

@alpine sable