help-0

[vernal creek]

So ylou get the term: 7(-2y) + 9y = -45

[slow bone]

also nice pfp

Very nice pfp

[vernal creek]

Thank you

[vernal creek]

multiply this out and you should get a solution for y

[slow bone]

-14+9y=-45

14-9= 5

-5

is y negative 5?

[vernal creek]

no

7(-2y) = -14y
-14y + 9y = -5y

[slow bone]

Sorry

[vernal creek]

np

[slow bone]

I forgot my Y

ok what step is next

[vernal creek]

then you have -5y = -45

[slow bone]

sp

Should I put -5 and -45?

as the answer

[vernal creek]

well no

You have to divide both sides by -5 so on the left side you only have y left

so y is -45/-5

[slow bone]

-9y

?

[vernal creek]

just 9

y = 9

[slow bone]

oh

Ok

What nex

t?

[vernal creek]

Do you have to solve for x as well?

[slow bone]

probaly

actually

Yes

Yes I do

[vernal creek]

then since you know y = 9 you can put that in the top equasion

[slow bone]

What would the equation be

[vernal creek]

-2y = x but put 9 instead of the y

[slow bone]

-18?

[vernal creek]

yes

[slow bone]

so

it didnt work

Math pains me to another level

It hurts

[vernal creek]

switch them

x goes first then y

So (x, y)

[slow bone]

YES

I GOT IT RIGHT

im using this for math

Please tell me if this is correct

-3yx-6=18

nvm im stuck

What do I do with the 3?

[vernal creek]

Do the same principle

I can't just do the math for you

Good luck

[slow bone]

I already got it wrong

[vernal creek]

Or search Substitution on Youtube and watch a vid on it

[slow bone]

tried

doesent work

You explain it best

quick and fast

[vernal creek]

no

Sorry

It's 2.30 am

[gray isle]

how did you get
-3yx-6=18

[slow bone]

Messed that question up

And forgot the multiplactation sign

-8x3=24

-24

What am I supposed to divide

MANE

[dusk cliff]

you substitute y in for -8x

well

the opposite

-8x for y

-10x+3(-8x)=34

[slow bone]

7x-8

=

[terse bay]

bro are you seriously asking for help on delta math do they not have videos explaining how to get the answer

[slow bone]

I dont understand when they explain

[dusk cliff]

-10x-24x=34

-34x=34

[terse bay]

aw fr im sorry then

[dusk cliff]

x=-1

[slow bone]

Im slow when it comes to math

x=-1

Y=-24?

Right

open yo own

[dusk cliff]

y=8

[slow bone]

-4(9)+36=-36

No

9x4=36

35

what

-4(9)+36=-36

-36+36=0

.close

[lone heart]

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[slow bone]

.close

.reopen

[lone heart]

✅

[slow bone]

.close

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[lone heart]

@silver tangle Has your question been resolved?

[remote heron]

whats the question? @silver tangle i can try

im super tired but maybe i can help

[lone heart]

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[warm vector]

im not entirely sure how to do this but does anyone know how to find the volume of this shape?

[raw shard]

i don’t think there’s enough information

[warm vector]

oh the question was presented like this

[raw shard]

you can assume 20cm is also one of the line lengths in the top corner

but that would only be an assumption

also we don’t even know the height

[warm vector]

so you're saying this question is impossible?

[raw shard]

unless they state it used to be a cube

[warm vector]

the teacher said it was a composite shape

[sick scaffold]

how would i factor this? the grouping method doesnt work

[raw shard]

occupied channel

[sick scaffold]

oh ok, sorry

[raw shard]

yeah this question isn’t possible @warm vector

[warm vector]

oh

dang

thx anyway

[raw shard]

no problem

if you were wondering we’re missing more than one measurement

we would also need the height

[warm vector]

oh

[raw geyser]

.close

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@warm vector Has your question been resolved?

[warm vector]

.close

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[jaunty crane]

xy=2+3y

[jaunty crane]

can someone tell me if i move y from x

ill get x=2+3y divide by y?

[glass lichen]

yes you'd get x=(2+3y)/y

[jaunty crane]

thx

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[violet panther]

Hi what is the average acceleration of first 3 second?

[violet panther]

I thought I just need to add them up and divide it by 3

But the textbook answer is 58

[lone heart]

@violet panther Has your question been resolved?

[dull gale]

Heres something to consider

You chose to evaluate at 1, 2, 3

Why? Why not pick 1 and 3 or 1, 3/2,2,5/2,3?

[scarlet atlas]

i know this is a math server but can someone help me with this?

[dull gale]

This channel is currently in use liony. Try another

[scarlet atlas]

ok

[dull gale]

@violet panther

[violet panther]

I chose these numbers because u have to find the average acceleration between t=1 and t=3.

???

[dull gale]

I mean, why only pick the integers between those two numbers

[gritty wasp]

does your original question provided a distance?

[dull gale]

You're calculating the average value of a function here, since acceleration is defined for any real number t

[gritty wasp]

i feel like if theres a distance in the question wouldve made more sense to others but idk

[dull gale]

Actually lemme check one thing

Do you know about integration yet @violet panther?

You can certainly answer this in two ways I suppose. One involves thinking of integration and the other is really more physics based

[prime flax]

can someone help me with this

grade 10 math

expand and simplify

[dull gale]

Try another channel arsh, this is in use

[violet panther]

No i don’t think I learned it before

And this is the original question

[dull gale]

Okay

So

[violet panther]

And it’s my work so far

[dull gale]

Then ill help with the simpler explanation in just a sec

But I want to get across the understanding that..

Choosing 1, 2, and 3 was arbitrary and indeed you kind of want to talk about the acceleration at all times between 1 and 3

[violet panther]

Ok

[dull gale]

When you learn calculus you learn about integration which is kind of the proper way to talk about the acceleration throughout 1 to 3

So if you were given a function and asked for it's average then you need to 'sum' up the values of the function with integration

But ignoring that, for the simpler solution. Try not to think of the acceleration actually

If I move 9 m in 10 s then my average velocity is 9/10 m/s

[violet panther]

Ya

[dull gale]

But at some times within that movement I could have been faster than that as long as I was slower other times

[violet panther]

Yes

[dull gale]

And acceleration is to velocity like velocity is to distance

So notice, we can use two values of the distance (0m and 9m) to get the average velocity

[violet panther]

Where did get 0 and 9 from?

[dull gale]

My made up example

Just observe that we can get the average velocity with just two values of distance

[violet panther]

Oh okay

[dull gale]

But if we tried to get average velocity without using distance we would actually need to sum up all the velocity values in an integral (again not that you know now)

[violet panther]

But how can I calculate the ave acceleration for this question? Without knowing the integral thing?

[dull gale]

All that I just described in my example

Works for that, essentially

Again

Velocity is to distance as acceleration is to velocity

[violet panther]

But I don’t know the distance

[dull gale]

But you want to talk about average acceleration right?

Velocity is then your 'distance' from. That perspective

[violet panther]

So does that mean I have to sub in t=3 and t=0 to 4t^3 + 6t?

[dull gale]

Why t=0?

You know what the answer should be, you said

Try it with... Correct values for t and see if it works

Btw from a physics perspective there are two statements here we can make

Average velocity is the change in position divided by change in time

And average acceleration is the change in velocity divided by change in time

[violet panther]

So I have to use t=1 and t=3 ?

[dull gale]

You want to know the change in velocity from start to finish. And in this problem it 'starts' at t=1 and 'ends' at t=3

[violet panther]

126-10 / 3?

Could you show me the equation?

I’m so confused

[dull gale]

You're close!

[violet panther]

Am I close?

[dull gale]

Remember, you should have change in velocity over change in time

What is the change in time from t=1 to t=3?

[violet panther]

2

[dull gale]

So your denominator is 2

And the numerator should be the change in velocity

[violet panther]

Ohhhhhhhhhh

Wow I got it

Thank you so much for explaining to me this again and again. I’m sorry I could understand faster… I really appreciate for your help!

[dull gale]

Np! Happy to help

[violet panther]

:)))

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[zealous adder]

How do I do 6?

<@&286206848099549185>

[lone heart]

@zealous adder Has your question been resolved?

[robust geode]

Since the hour is randomly generated between 1 and 12,then there is 12 random possibilities

And the fact that it is random should let you know something about the probability that each of these hour is the selected hour

[prime badge]

you get a fraction it has probability of zero

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[next pulsar]

I want to prove that the 2-norm forms a normed space when you endow the vector space F^n with it, showing positivity and scalar multiplication was easy but i am struggling with proving the triangle inequality / subadditivity

[next pulsar]

my teacher told me to use this result

but i don't see how this helps me because the norm is squared

[lone heart]

@next pulsar Has your question been resolved?

[vivid ginkgo]

feel free to tag @/helpers

[vivid ginkgo]

.

[next pulsar]

Nah I think I understand now

.close

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[supple tundra]

Why don't we equate this to $(x,y)$ in line [1]

[ocean seal]

azeem321

[supple tundra]

That is, shouldn't it be $2x+y=x$ and $3x=y$

[ocean seal]

azeem321

[river remnant]

Isn't A and B the exact same value?

[tough hatch]

read #❓how-to-get-help

[supple tundra]

yes

.close

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[proud bolt]

We roll the dice. If the result is less than 3 we have the right to roll one more time. What is the probability that the total score is greater than 4

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[proud bolt]

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[eager ravine]

hey can i say this?

[eager ravine]

like is correct?

i know that the principal square root only gives the positive square root, so i kinda assume that to be the same as the absolute value of the square root

[coarse sparrow]

do you mean: can I say this: $\sqrt{x} = \abs{\sqrt{x}}$

[ocean seal]

LeonNeol

[eager ravine]

yeah

like is y^2 = x, then sqrt(x) = |y|?

i'm just trying to make it general

no specific value for it

are there any cases that it can fail?

or maybe examples of those cases

[coarse sparrow]

$\sqrt{x^m} = \abs{x^{\frac{m}{2}}}$ if m is even

I think?

oh shoot

[eager ravine]

oh i mean just for square roots

[jolly drift]

can anyone help me with this?

sorry if number 1 was cutted, here it is

[crisp grove]

√x is always non negative is more appropriate

[eager ravine]

the principal square root of x will give a positive number y, since principal square root always give a positive square root. so can i say this using the principal square root?

like just the principal one and not the plus minus

that's the same as the |y| right?

is there a difference in +-sqrt(x) and -+sqrt(x)?

i mean there is but i don't know what it means

[vale wigeon]

$\mp$ is a pretty niche symbol

[ocean seal]

Ann

[vale wigeon]

the only use i can think of for it is if you have two $\pm$ signs but you only want to talk about the combinations in which they're taken as opposite

[ocean seal]

Ann

[vale wigeon]

like for example $\cos(x \pm y) = \cos(x) \cos(y) \mp \sin(x) \sin(y)$

[ocean seal]

Ann

[coarse sparrow]

are you on light mode Ann?

I think the TeX bot takes in the user's mode for the TeX generation?

[eager ravine]

isn't y a set of possible values for the square root of x? and if i take the square root of x, it will give me all the possible square root, y or -y. but if i take the principal square root of x, it will only give me the square root of x that are more than or equal to 0, which will only be y such that y >= 0 or |y|. will this show that my original equality correct?

[ocean seal]

Results provided by WolframAlpha

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Requested by .₆₆₆...#0422

[vale wigeon]

no, who do you take me for?

[coarse sparrow]

sorry for going offtopic

[vale wigeon]

there's a config option you can set that controls tex render color

it's independent of what theme you use

[coarse sparrow]

oh yeah I was wondering about the tex

thanks for clearing that up

[eager ravine]

i mean the principal square root, like √x = y. the √ only gives the positive square root. so √x = |y|?

not x = y^2

pretty sure these 2 brings different meanings

[eager ravine]

yeah

i'm making some notes abt square root. so the last sentence sqrt(x) = |y| is incorrect then?

but y can't be negative if i'm taking the principal square root of x, i believe

i'm a little confused abt that actually

i see

sure

not really, cause there will be 2 y's here. i just wanna take the principal square root of x, which i believe will make y>= 0 and hence principle square root of x = |y|

yeah but by taking the principal square root, aren't we just gonna have 1 y, that's positive?

i have no specific number for that

y = sqrt(x)

+-sqrt(x)?

y = x^2
can i just take the principal square root like
y = sqrt(x)?

i was reading https://math.stackexchange.com/questions/1448885/is-sqrt64-considered-8-or-is-it-8-8 and encountered this. since the answer uses absolute value symbol, i assume that i can generalize this.

[silver viper]

$\sqrt{x^2} = \abs{x}$

[ocean seal]

kiid

[eager ravine]

i'm sorry if i was being ignorant

my bad

yeah, cause i think

sqrt only gives positive square root

yes

i dont think so, since there are 2 possible values for x

oohh i think i'm gettin g it

[ocean seal]

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[eager ravine]

so the takeaway is that sqrt(x) = |y| is true. sqrt(x) will always give a positive value but y can either be a positive or negative?

sqrt(x) is then equal to y or -y? but we'll write that as +-sqrt(x) = y, right?

since sqrt(x) will always be positive, i assume that it will give a positive real number y. (by sqrt(x), i mean the principal square root)

[tough hatch]

sure

[lone heart]

@eager ravine Has your question been resolved?

[eager ravine]

so if y>=0, y = |y|. which shows sqrt(x) = y = |y|?

[tough hatch]

yes

[alpine sable]

hey guys

I have a srs math question

[coarse sparrow]

#❓how-to-get-help

[eager ravine]

alright then thanks

.close

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[near flicker]

The first image shows the question, the second one is the curve which I drew.
-->
The answer in the markshcme is 5.7 to 5.9 but I get it as 3.46
Please correct my mistake for the tangent

Level : O level Math 4024.
<@&286206848099549185>

[lone heart]

@near flicker Has your question been resolved?

[pallid trout]

It would help to know which question in particular, I am guessing c(i) you want help with?

[near flicker]

(a)-(c) basically

[near flicker]

If you could identify my mistake because I don't get the right answer or either draw the graph for me if possible

[lone heart]

@near flicker Has your question been resolved?

[glass lichen]

Nope

Also #❓how-to-get-help

[alpine sable]

@near flicker dAmN yOuR pFp HaS pUnS.

Anyway, why did you not extend the curve?

[near flicker]

Umm.. why was I supposed to do that?

[alpine sable]

Wasn't that asked in the [b] part?

[near flicker]

Ah I need help in tangent. I was just practicing tangent as of now

[alpine sable]

Oh ok.

To be honest, it looks like you tried to draw the tangent from 3.25 instead of 3.5.

[alpine sable]

So, which question of tangent?

[near flicker]

(c)

[alpine sable]

How to measure gradient and what it represents?

[near flicker]

Nah where it asks you to draw tangent at 3.5

[alpine sable]

So, you want to know how to draw tangent?

[near flicker]

Yeah

[lone heart]

@near flicker Has your question been resolved?

[near flicker]

It wouldn't be resolved ig , too long

.close

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[coarse sparrow]

can you find the slope of that line?

[amber jackal]

Nope that’s what i am confused of🥲

And I have to put an equation

Which is kinda confusing for me

[coarse sparrow]

so parallel lines share the same slope

you can pick 2 point from the pink line

(x1, y1) and (x2, y2)

[ocean seal]

LeonNeol

LeonNeol

[amber jackal]

OHHHH

ok I got it thank you

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[rustic thistle]

hello i need help with angles of circles

[rustic thistle]

for the 2nd one, how do i find the missing arc?

[wary stream]

Find arc QR using inscribed angles

Then you know sum of angles in circle totals to be 360

[rustic thistle]

whats the formula of inscribed angle to arc again?

[wary stream]

You can Google that

[rustic thistle]

so SQ is 95?

i have a lot more questions bc i had a gap year an my midterms are tomorrow

is it okay if i dump them here?

[wary stream]

I mean, you should look up resources first then come back if you have more questions

This concept is all over the internet

[rustic thistle]

yea ive been trying for the past hour but i cant seem to type in the correct things

[wary stream]

You looked up inscribed angles and solved that just fine

[rustic thistle]

ye but that was only possible after u told me i needed to use inscribed angles

[wary stream]

Because that's what the document is titled as, "Inscribed/Central Angles"

[rustic thistle]

yea i struggle finding what to use in which situations

for this one what does the mEFC thing mean? or is it important?

[wary stream]

That's what you're looking for

mEFC is the arc you are looking for

[rustic thistle]

i cant rlly see an arc from those letters

[gray isle]

measure of the arc EC that passes through F
i.e. the major arc

[rustic thistle]

oh nv,

[sacred leaf]

major arc

[rustic thistle]

nv,

is it 234?

[coarse sparrow]

Does it mean something else without the m?

[rustic thistle]

idk i didnt learn most of the terms

i dont think ik any of the formulas for these

[wary stream]

You can Google those formulas

[rustic thistle]

idk how to, like for example the first one

i have no idea whats going on there

[wary stream]

Do you know what a secant, tangent, and chord of a circle is?

[rustic thistle]

barely

idk what the difference between a chord and a secant is

[wary stream]

Then you should start there

Determine what they are

[rustic thistle]

my assumption was that a secant is like a divider

and a chord is a line

[wary stream]

Reading these should help
https://www.mathwarehouse.com/geometry/circle/angles-of-intersecting-chords-theorem.php
https://www.mathwarehouse.com/geometry/circle/angle-tangent-and-chord.php
https://www.mathwarehouse.com/geometry/circle/tangent-secant-side-length.php

Those provide the appropriate information for you to solve those questions

[rustic thistle]

ty ill try

oh and is there a difference between mABC and ABC

[wary stream]

mABC is the measure of ABC and ABC just dictates that arc

Meaning arc ABC

[rustic thistle]

oh thanks

[coarse sparrow]

Oh in my country we just have to understand it

If it is used in math expression then it is the measure

Otherwise it’s the arc

[rustic thistle]

for this one, by the material u gave me

i thought PSQ was 88

im pretty sure im wrong but can you tell me why?

waitt i think thats a secant

[wary stream]

You're just looking for mPS, not mPSQ

[rustic thistle]

wouldnt i need to look for PSQ to find PS?

[wary stream]

No, because the question mark is lined up for PS

[rustic thistle]

idk i thought i need PSQ then -65 from it

[alpine sable]

hey guys so i have a really hard equation i can't seem to solve it

it's 1.41421356237309504880168872420969807856967187537694807317667973799

squared

[raw shard]

bruh

[rustic thistle]

is mPS 153?

[next chasm]

which ones u need

[rustic thistle]

im just tryna find out how to do em

[next chasm]

which ones

all of them?

[rustic thistle]

yea

i think ive figured them out

[rustic thistle]

now i need these

[next chasm]

hold on brb

[lone heart]

@rustic thistle Has your question been resolved?

Channel closed

Closed by @rustic thistle

Use .reopen if this was a mistake.

[rustic thistle]

.reopen

[lone heart]

✅

[coarse sparrow]

Channel is taken

#❓how-to-get-help

[rustic thistle]

these two got me confused

for 14. i got x = 38 is that correct?

and for 15. i got x = 45

[small bear]

Both of them look correct

[rustic thistle]

ty

now these

the only thing ik is that the major arc of e is 195

[lone heart]

@rustic thistle Has your question been resolved?

[ripe atlas]

heyy

[alpine sable]

@rustic thistle omg we are on the same page

Not the same page but i mean im learning this too

[rustic thistle]

ah lmao nice

[lone heart]

@rustic thistle Has your question been resolved?

[rigid island]

https://cdn.discordapp.com/attachments/808552988477095946/908061559518036058/unknown.png

hi

for 1

why is it 4!

should it not be 3

please @ me when you r eply :)

[alpine sable]

@rigid island this is occupied

[rigid island]

?

[alpine sable]

This channel is occupied

By @rustic thistle

[rigid island]

the last message sent here was an hour ego

[alpine sable]

I meant read #❓how-to-get-help

@near flicker Can I DM you? Need to discuss something so if you're cool with it then send a friend request (temporarily or just allow me to DM temporarily and you can remove/close after that).

[lone heart]

@rustic thistle Has your question been resolved?

[zealous adder]

There is a test question with 6 options. The most valuable option is worth 6 marks and the least valuable is worth 1. What is the expected mark you'll get if you choose randomly?

<@&286206848099549185>

Do I just do

E(x) = 6(1/6)+5(1/6)+4(1/6)+3(1/6)+2(1/6)+1/6

[raw shard]

there’s no x in there

so it’s always the same

wait i might misunderstand

[lone heart]

@rustic thistle Has your question been resolved?

[clever tapir]

Can I use channel

[wary stream]

No

It's occupied

Read #❓how-to-get-help

[acoustic summit]

hello

i would like some help on how to solve this

<@&286206848099549185>

i need help

[kindred warren]

ok

ask

[lone heart]

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[royal meadow]

yep, it's a true statement

[wary stream]

I agree too, true statement

[lone heart]

@tardy pulsar Has your question been resolved?

[tardy pulsar]

how would you solve?

[tardy pulsar]

how would you solve?

[royal meadow]

rewrite the left side with only sin and cos and simplify

[tardy pulsar]

.close

[lone heart]

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[sly dome]

hi anyone help pls

[sly dome]

pls which one

[lone heart]

@sly dome Has your question been resolved?

[raw shard]

woah

[radiant barn]

Hello

[lone heart]

@sly dome Has your question been resolved?

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[dense spire]

Can someone please describe the transformations for me

I already know it’s a vertical translation up 1

Horizontal trans left 8

I just need the rest

[lone heart]

@dense spire Has your question been resolved?

[lone heart]

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[slate kayak]

Can someone check if these are correct?

Photomath said that the last one bottom right is x = 0 + k . 2pi

But is my answer equivalent?

[alpine sable]

bruh. I was typing. Good thing there are more available chats. bye.

[slate kayak]

I didn’t see you typing how was I supposed to know

[finite flax]

He must have been in his file explorer

[alpine sable]

A message is supposed to show up here. bruh.
That was rude too btw.

[finite flax]

Anyway. Blue, 0 is congruent to multiples of 2pi

[slate kayak]

Ah okay thnx

[dense spire]

.reopen

Rip lol

[alpine sable]

If your done. type .close @slate kayak

[floral cradle]

hi guys can help?

[slate kayak]

I still need help on another question but i want to try it for myself first so i dont wanna close it just yet

[alpine sable]

Go to an available chat. Blue is not done yet. Also, ping the helpers role after 15 mins if no one replied.

[floral cradle]

oh ok

[slate kayak]

Does anyone know the difference between when they ask:

calculate the exact answers / calculate the exact answers on [0,2pi]

[gentle ocean]

leave it in exact form

so like if the answer an irrational number like a surd

then leave it in surd form

[slate kayak]

Okay

.close

[lone heart]

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[lone heart]

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[glossy iris]

can someone please explain why couldn't I have done the formula like I did in the second photo?

[coarse sparrow]

because you did wrong

$q^2 - (2t + 3t)^2 = (q - 2t -3t)(q + 2t + 3t)$

[ocean seal]

LeonNeol

[glossy iris]

oh

thanks

. close

.close

[lone heart]

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[hallow hinge]

Why cant y be less than 2?

[glass lichen]

assume it was, then you'd show a positive thing is negative

which is a contradiction

alternatively: look at the transformations

[hallow hinge]

So the square root of 1 isnt -1?

And 1

[glass lichen]

no

sqrt(1)=1

[hallow hinge]

I subbed in 1 for y

[glass lichen]

yeah

you said -1=1

which is false

[hallow hinge]

I thought it was both -1 and 1

But nope

[glass lichen]

nope, welcome to why even roots suck

sqrt(x) is positive by definition of principal root
however solving something like x^2=a means x=+-sqrt(a)

[hallow hinge]

Right right

[glass lichen]

the act of taking the square root is what gives the +-, the square root existing already is that it's positive unless specified not (ie if you have -sqrt(1) then you get -1)

[warm marsh]

squaring both sides will help get rid of the sqrt leading to the equation 1=3-x

nvm

[glass lichen]

Could be phrased better but you get the idea

[warm marsh]

I'm in 8th grade I'm still learning geometry

[hallow hinge]

Ty

.clos

.close

[lone heart]

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[frank nacelle]

Hello

[ocean seal]

sainallani

[frank nacelle]

can be simplified to

[ocean seal]

sainallani

[frank nacelle]

I need help on the domain

[oak barn]

consider what screws up the dominator

also if stuff cancelled you got "holes"

[frank nacelle]

Yes, I have done that. I have gotten the Vertical Asymptote as $x=-1/4$

[ocean seal]

sainallani

[oak barn]

so whats the problem?

[frank nacelle]

I know about the holes as well

nevermind

I just looked at the graph wrong.

Thank you!

.close

[lone heart]

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[prime flax]

can someone help me with this grade 10 math question please

[finite flax]

@prime flax you just need to "complete the square". What would k have to be?

[prime flax]

wdym by complete the sqaure?

[finite flax]

that is the whole thing of this problem

it's the topic

check online

there are lots of examples

remember that you need to factor out the leading coefficient before you do it

[prime flax]

??

i've never done this before

[finite flax]

that's ok

[prime flax]

my teacher never taught us that shwy im confused

[finite flax]

this is an essential skill for math

I think she might have

that's what this problem is all about

google it

when somebody gives you a topic

or your notes is about a topic, or a unit

you need to be able to quickly look up what things mean

when you don't have the notes

Google "completing the square"

[prime flax]

yea, we never earned it this math lesson is one chapter behind the next one

the next chapter is about the qaudratic formula and completing sqaures

the topic i have hw for today is factoring qaud expression ax^2 +bx + c

[finite flax]

do they want you to end up with the product of two binomials?

[prime flax]

no, they end up with two values

[finite flax]

...for k.

[finite flax]

so that ax^2 + bx + c = (dx+e)(fx+g)?

ok ok

so let's try these and make sure we understand what they wanted

9x^2 + 15x + 6

actually, let's start with 4

9x^2 + 15x + 4

notice that the point cannot be to factor an integer out of every term

because it isn't possible

[prime flax]

yea

for four i don't think it works

[finite flax]

so I think they want the product of two binomials

let's use AC method

we need two numbers whose product is AC and whose sum is 15

[prime flax]

yea i've tried this, and 6 works

[finite flax]

that is, whose product is 9 times 4 is 36 and whose sum is 15

ok so what are they

[prime flax]

12 times 3

[finite flax]

very good

what do we do with those

[prime flax]

we use these ass 12x and 3x

*as

[finite flax]

yes

9x^2 + 3x + 12x + 4

no matter how we factor out an integer, we will get a common binomial

3x(3x + 1) + 4(3x + 1)

(3x + 4)(3x+1)

the thing is

we didn't know what k should be at the start

to make this possible

[prime flax]

oh so we basically have to take an extra step, since 9 and k (ac isn't limited,) but we want to make sure the two integers we use should add up to the b coefficient 15, and those two numbers should be the prduct of ac

[finite flax]

yes

presumably, that was doable

you needed a product of 9k and a sum of 15

[prime flax]

alright this makes alot more sense now thankyou so much!!

[finite flax]

so maybe poking around with integer values of k was "good enough"

yes

but

completing the square will be faster

you will see next time

[prime flax]

alright 🙂

[finite flax]

ok, bye

[prime flax]

bye thanks again

.close

[lone heart]

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[lucid lantern]

I need to calculate the variance.

I know the probability of 0 is 0.36, 1 is 0.26, 2 is 0.19, 3 is 0.09, and 4+ is 0.1

[lone heart]

@lucid lantern Has your question been resolved?

[lucid lantern]

<@&286206848099549185>

.close

[lone heart]

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[scenic oak]

i tried substituting y=vx but i end up getting stuck at

[scenic oak]

$\int \dfrac{2e^{2v}dv}{1+e^{2v}-ve^{2v}}$

[ocean seal]

aujiel

[crisp grove]

u subbed it wrong

also why did yr nomi and denomi flip?

[scenic oak]

its a FOLDE question

[lone heart]

@scenic oak Has your question been resolved?

[lone heart]

@scenic oak Has your question been resolved?

[scenic oak]

<@&286206848099549185>

[lone heart]

@scenic oak Has your question been resolved?

[lone heart]

@scenic oak Has your question been resolved?

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[shut sleet]

need halp asap plz, thnx

[coarse sparrow]

maximum height is the vertex

[shut sleet]

how do you find the turning point/ vertex?

you use quad formula?

and wuts H(t)

[solar pebble]

complete square

[shut sleet]

why complete the square may i ask?

for H(t) do you just replace that with 0?

[solar pebble]

no, put it in the form

$a(x-b)^2 + c= 0$

[shut sleet]

srry, don't get it

[ocean seal]

Xetrov

[solar pebble]

have you ever put a quadratic in vertex form i think its called

[shut sleet]

ye

oh

i see, so do i replace H(t) with 0?

so it can be a quadratic?

[solar pebble]

Yeah

it is a quadratic anyway

But you don't need to replace with 0

you just need to transform the form of the quadratic

[shut sleet]

hm. ok, i will give it a shot

[solar pebble]

ok

then set (x-b) to 0 to get the x of the vertex

or the t

[shut sleet]

so i wrote down 0=-4t^2+16t+8^2-8^2+9

am i in the right path?

$0=-4t^2+16t+8^2-8^2+9$

[ocean seal]

Qweryoung

[solar pebble]

ok, take out a 4 from 4 and 16

[tacit scroll]

What xetrov said makes it significantly easier to complete the square

[shut sleet]

ye i got 0=(-4t+8)^2-55

[solar pebble]

if you expand that you get a 16t^2 term

I'll let @tacit scroll take over

[tacit scroll]

That’s the right idea but you shouldnt have a coefficient of x^2 inside the brackets

That’s why xetrov said abt taking 4 out from 4 and 16

[shut sleet]

ok

take out 4 or -4

nvm

so

now i got 0=(-t+2)^2+9

[tacit scroll]

Before you complete the square, the first step is to take 4 out of the -4t^ and 16t

[shut sleet]

oh i see

[tacit scroll]

👍

[shut sleet]

still 0=(-t+2)^2+9 lol

[tacit scroll]

What happened to the 4?

[shut sleet]

i moved it to the left?, which got divided by 0

am i not supposed to do that

oh lord

[tacit scroll]

Sorry if I wasn’t clear, I meant to factorise out 4 of the -4t^2 and 16t terms

[shut sleet]

so 0=4(-t^2+4t)+9

[tacit scroll]

YES

[shut sleet]

then you moved the 4 to the left side of the equation?

srry im a slow learner , especially in math

[tacit scroll]

No worries, unfortunately you cannot divide everything by 4 as then you need to divide the nine by 4 too

[shut sleet]

huh

[shut sleet]

lmao i see what i did

[vale wigeon]

@karmic sandal do not encourage people to interrupt occupied channels.

[young prism]

Can sum1 help me with this?

Woppss

[tacit scroll]

So qweryoung you can start to complete the square as you normally would now you have factorised out 4

[shut sleet]

ok got it , tysm @tacit scroll @solar pebble

[vale wigeon]

there are many dozens of them for a reason.

[tacit scroll]

Np

[young prism]

Im sorry i just need sum help but ty

[vale wigeon]

@young prism you should post in one of the available help channels.

[young prism]

I just ask for a help doe..is that bad?

[young prism]

Okok tysm

[vale wigeon]

@karmic sandal there is no need to be this mean to other users.

[solar pebble]

woop banned

[vale wigeon]

oh, looks like they left or got banned

[lone heart]

@shut sleet Has your question been resolved?

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[formal garden]

pls help
Solve for x in each of the
following polynomial equation. (5pts each)

1. 3(x + 6) = 2(2x – 6) + 24
2. x^2 – 6x + 9 = 0
3. 5x^2 – 6x = 2
4. 16x^4 = 81
5. x^5 – 7x^4 = -12x

Is it possible that the desired
values for x will not be fit or true for the given
polynomial equation upon checking? If so, what type
of solution is that?

[lone heart]

@formal garden Has your question been resolved?

[formal garden]

<@&286206848099549185> sorry for ping

[lone heart]

@formal garden Has your question been resolved?

[solar pebble]

@tall walrus somewhere else

[alpine sable]

what do you mean?

[formal garden]

already done

.close

[lone heart]

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[untold mountain]

hi

[untold mountain]

please help me

I am so desperate

I need to solve the volume of this colored shape

[iron gorge]

solve for the volume of those 3 triangular pyramids that arent colored and then subtract them from the total volume of the cube

[lone heart]

@untold mountain Has your question been resolved?

[untold mountain]

LOL

its wrong

[iron gorge]

huh

explain

[untold mountain]

216 x 1/3

72 is the answer

dum

[iron gorge]

Then whyd you ask for help if you clearly know the answer?

[lone heart]

@untold mountain Has your question been resolved?

[untold mountain]

I got the answer

right after you said it

xd

[polar frigate]

Why do we use cross product for b?

[placid zinc]

This isn't your channel #❓how-to-get-help

[polar frigate]

the guy earlier doesnt need help

[lone heart]

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[sterile vale]

wat

Where the heck do we arrive at d =

[raw shard]

this question is weird

like why is there randomly a c

[lone heart]

@sterile vale Has your question been resolved?

[glass lichen]

wdym

$2(l-d)^2=c^2 \ (l-d)^2=\frac{c^2}{2} \ l-d=\frac{c}{\sqrt{2}} \ d=l-\frac{c}{\sqrt{2}}$

[ocean seal]

Mosh

[simple cliff]

Speed

Gg

[alpine sable]

He rial sped.

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[glossy iris]

can someone please explain why should I write 11x as a sum of exactly 8x + 3x in this case?

[glossy iris]

nvm

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[supple egret]

Can someone tell me how do i even start solving this, and some help for solving that |x| < 1 case? Thanks!

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@supple egret Has your question been resolved?

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[alpine sable]

[8 | (x+3) (x-3)] + [5 | 3(x+3)] + [1 | 3-x]

[alpine sable]

the [] means the start and end of the fraction

and | means the line between both sides of the fraction

the upper side and bottom side

how do i cancel those out?

[gray isle]

the explanation of your notation is much appreciated but please write it like
8/((x+3)(x-3))+ 5/(3(x+3))+ 1/(3-x)

[alpine sable]

alright

makes sense

[gray isle]

the parentheses the clearly indicate your numeratorsvand denoms

1 sec

$\frac{8}{(x+3)(x-3)}+\frac{5}{3(x+3)}+\frac{1}{3-x}=0$

[alpine sable]

yes

oh i forgot

its an eqasion

is all of that = 0

and i need to solve it

[ocean seal]

ℝamonov

[alpine sable]

yes exactly

[gray isle]

consider combining the fractions into a single fraction by considering the lcd

[alpine sable]

how do i do that

[gray isle]

or multiplying both sides of the equation by the LCD directly

[alpine sable]

whats LCD?

sry my math vocabulary in english isnt that advanced

[gray isle]

lowest common denominator

[alpine sable]

whats that in this current situation?

[gray isle]

i.e lowest common multiple of the denominators of your fractions

[alpine sable]

hm

[gray isle]

recall the basics of combing fractions through addition/subtraction

[alpine sable]

i see

i dont think i know how to do it with variables in the bottom

[gray isle]

e.g. $$\frac12 + \frac16$$

[ocean seal]

ℝamonov

[alpine sable]

yes i know how to do that

[gray isle]

the idea is the same with variables present

[alpine sable]

can you show me?

its confusing

[gray isle]

well show me how you'd simplify the much simpler example with just numbers above

[alpine sable]

so the common factor or however you call it is 6

so i will make the bottom part 6

and multiply the upper part with the number it took me to get from the bottom part to 6

so 2 * 3 is 6

1 * 3 is 3

and you get 3/6 + 1/6 = 4/6

[gray isle]

you can simply 4/6 further but ok.

[alpine sable]

oh yea

2/3

[gray isle]

are you able to identify the LCM of your denominators here?

[alpine sable]

x +/- 3

one of them

i dont know which

x and 3 for sure

[gray isle]

very poor notation

so I'm not sure what you actually mean

[alpine sable]

either x - 3 or x + 3 i think

it involves 3 and x

[gray isle]

let's use a simpler example,
would you be able to identify the LCM of
ab and bc?

[alpine sable]

?

whats ab and bc

[gray isle]

ab represents the product of the variables a and b

[alpine sable]

oh ok

so its b

[gray isle]

bc epresents the product of the variables b and c

no

youre confusing LCM with HCF/gcd

[alpine sable]

uh..

[gray isle]

if you wanted to combine
$$\frac{1}{ab} + \frac{1}{bc}$$
into a single fraction, what would be the most efficient way to do that?

[ocean seal]

ℝamonov

[alpine sable]

hm

c/b +a/b ?

[gray isle]

no

[alpine sable]

hm

[gray isle]

how are you getting that

[alpine sable]

idk

[gray isle]

recall what you did with the numerical example

[alpine sable]

but i dont know what the numbers are

[gray isle]

when you did that, did you make certain things just vanish for no reason?

[alpine sable]

no

[gray isle]

so why are you doing that here?

[alpine sable]

m..

[gray isle]

the goal is still the same

get the same denominator by multiplying your fractions "1"

[alpine sable]

i dont know how

its confusing

with variables

[gray isle]

it may be a good idea to look up lcm

let's use an even simpler example

$\frac 1a + \frac1b$

[ocean seal]

ℝamonov

[alpine sable]

hm

1/ab + 1/ab?

[gray isle]

no

[alpine sable]

wait no

the bottom is ab

so

a/ab + b/ab

[gray isle]

() around those ab pls

but yes

[alpine sable]

cool

[gray isle]

and pretty much apply the same idea to the previous example

[alpine sable]

ight ill try

(bc)/(abbc) + (ab)/(abbc)?

[gray isle]

a little inefficient

note that both denominators already had a single factor if b

so it wasn't necessary to involve additional multiplication by b/b

i.e the LCM of ab and bc is simply abc

all you need to multiply to ab to get abc is c
similarly
bc * a = abc