help-0

[lucid imp]

okay thanks

[calm wind]

Before I go any further, is this factored correctly?

[lucid imp]

correct?

you add .1

and subtract .1

[warm brook]

Yes

[lucid imp]

correct?

[calm wind]

my apologies i thought yall were finished with your problem. sorry for interrupting

[lucid imp]

and the first one*

[lucid imp]

that is correct

[fresh prairie]

help

[elfin wasp]

can't you just cancel the square and square roots?

then its just 2(root12-4) + (root 48 - 6)

[fresh prairie]

no, its a squared + 2ab + b squared

u cant cancel anything

like i kinda know how to do it, but its too complex for me to figure it out

[indigo rover]

take a look at this

[elfin wasp]

you can't do that?

[indigo rover]

not sure if it helps lol

[elfin wasp]

then cancel it down further etc

[fresh prairie]

idk

[indigo rover]

yeah, he got a point

[elfin wasp]

leme get on paint

[amber iron]

Hi guys

[elfin wasp]

there.

[amber iron]

How would I setup the triple integral for this in rectangular coordinates

[wary stream]

Don't do people's work for them

[elfin wasp]

ah

[fresh prairie]

it wasnt correct anyways

the answer was 2

this was correct

who's the sad that keeps deleting the messages lol?

[indigo rover]

sorry, had to delete

[fresh prairie]

why?

i already clicked that link

lol

[indigo rover]

cause this

anyways

you know the answer know

though it doesn't show all the steps to get there

[elfin wasp]

@wary stream do you know what that means?

the a14 thing, not sure if its A^14

[wary stream]

Think of it as coordinates

1,4 in the matrix

So row 1, column 4

That element

[elfin wasp]

thanks.

I see

[rich basin]

how would we go by graphing the following

for (f)

[mossy pine]

What equation would I use to set this up?

I do not need the answer I just need to know how to setup or just what this type of equation is called so I can watch a YouTube video

[bleak ridge]

Do you agree that base * height = area

[alpine sable]

if someone understands that shit

[mossy pine]

Yes

[alpine sable]

its german

[bleak ridge]

Just plug what you know into that and you have your equation

[rich basin]

can someone please explain <@&286206848099549185>

[mossy pine]

I got that x = 2sqrt(10) but it’s not right from the equation 50 = x^2+10 @bleak ridge

[analog inlet]

can someone please help me on math space

[amber iron]

<@&286206848099549185> please help

i want my last bounds to be wrt z

so integral from 0 to 4 of A dz

where A = area of each "layer"

i need help finding the double integral for A

[hollow dew]

can someone help me with my pre calc

[bleak ridge]

Depends

[hollow dew]

can i post the question in here

the whole assignment is like these questions

[loud oyster]

polar coordinate is (r, degree)

-r value essentially means the arm goes backwards

[hollow dew]

how would you identify the answer

[placid rock]

Where is 270 degrees on the circle?

[hollow dew]

B

[placid rock]

ok remember the - in the -5

that means instead of being B it would be A because you are going in the opposite direction

so the steps to solve these kinds of questions are
first find the degrees on the circle
then if there is a negative symbol choose the opposite direction

[hollow dew]

so would this one be C

[placid rock]

yes

[hollow dew]

okay thank you

[placid rock]

no problem 🙂

[hollow dew]

what if the degree and radians are negative?

[placid rock]

Then you go the other way around the circle, you can find out what amount of degrees this is by doing 360 - (degrees negative). For example say you have -90 degrees then you do 360-90 = 270 degrees (from there just solve it normally)

[hollow dew]

I have -60 so would i pick the line that is on 300 right?

[placid rock]

yes

[hollow dew]

thank you

[placid rock]

np

They might give you a question where the degrees are more than 360, say for example 900. What you do there is subtract 360 till you get a number less than 360. i.e. 900-360 = 540, 540 - 360 = 180 then you use 180

[fallen rain]

is this channel available ?

[placid rock]

I think so unless @hollow dew has anymore questions?

[hollow dew]

im good thank you

[fallen rain]

can someone help me with this question please?

<@&286206848099549185>

[cunning obsidian]

Maybe ya should work out the scale of y axis first? >_>

[jovial heart]

lets say i have a 1% chance to win the lottery

how many tries must i take in order to up it to 80%

or around 80%

[prime badge]

160

[tough hatch]

that's not possible
if you have a 1% chance to win the lottery, then you always have a 1% chance to win the pottery unless the probability itself changes

[prime badge]

that's pretending to not understand

1 − 0.99 ^ x = 0.8
0.99^x = 0.2
x = 0.99log 0.2
x = ln 0.2 / ln 0.99
x = 160

[lapis goblet]

Pottery 😂

[cunning obsidian]

I think it depends?

What lottery first of all

[tough hatch]

so when i have a 100% chance to win the lottery, and i try ten times, do i suddenly have a 1000% chance of winning?

[cunning obsidian]

That would be 1^10=1

I think

[prime badge]

yeah, you don't get 1000% doing this

[cunning obsidian]

Probability of any event is strictly less than or equal to 1

But this q is intriguing for me

[tough hatch]

you can't increase the probability of something happening just by making it happen multiple times.

[prime badge]

you can't try several times, and know that your next try is 80%

that's imnpossible, it's gambler's fallacy, 2/3 is right

but you can commit to doing 160 tries, and you'll have 80% to win

so depends on which one you want

either impossible or trivial

[late parcel]

Because of the controversy you never have to use a bracket right

Only parens if you want?

[tough hatch]

you can use parentheses all the way, but sometimes multiple instances of them can be nauseating

[late parcel]

What’s nauseating

[tough hatch]

an issue here is whether a "try" is for the same lottery or for the next

[late parcel]

So i don’t even need to know how to ever use a bracket in Calc and just always use parens. Cool

[tough hatch]

uncomfortable to look at, i meant

[prime badge]

yeah, that's a third interpretation

[late parcel]

Can I give you an example

[prime badge]

that's definitely pretending to not understand

[late parcel]

Or I’ll wait till you help frowny

[prime badge]

i'm clear, thank you it's actually π_π after me

you don't do parens for the fraction

yeah all parens everywhere is what people do

[cunning obsidian]

About the lottery problem, i think every lottery should be independent of one another

So the chance of you winning the lottery can only be 1% for every lottery

Correct me if I’m wrong

[late parcel]

Is this channel open

Where is that undefined

Is it at -2

The fact that the denominator is squared is what’s confusing me

[alpine sable]

Yeah, It's at -2. Only at -2 in the real numbers

[late parcel]

Why does number 5 how no POI

This is my work

I got the correct derivatives

I did the first derivative test correctly

I think the second one is done correctly also but why is there no point of inflection

Is it because it is undefined at -2?

[candid bobcat]

Can someone help me with 1A and 1b

I missed class directions

And I have no clue if the acceleration that is solved from the equation is plugged into the velocity or the initial or final acceleration is plugged into the velocity equation

[late parcel]

I had a question in progress

[alpine sable]

help

[north needle]

What do you want done with it?

In terms of sin or cos

[alpine sable]

i did product rule but idk how to simplify it

i dont even know if i did it right

[north needle]

What you need to differentiate it?

[alpine sable]

yes

[alpine sable]

you dont even need to use the product rule for this one

chain rule, yes

ok can u tell me how to do it

f(x) = g(h(x))

f'(x) = g'(h(x))*h'(x)

i got the derivative of each

but idk how to simplify

what'd you get after you took the derivative

(3sin^2(x))(cos(x)(-3cos^2(x))(sin(x))

WAIT

i typed the

negative sign wrong

yes i believe so, it looks like you're multiplying everything together

(3sin^2(x))(cos(x)-(3cos^2(x))(sin(x))

ok so i did this

is it wrong

yes that's correct

ok how would i simplofy it

simplify

factor terms

how

do both sides have a 3

[alpine sable]

hey guys any help

[north needle]

Painful but basically for 1).
4^2 is 16 right?

So you know the root of 17 will be 4. Something

[white yoke]

hundredths? yikes

[north needle]

But cause you want it to the nearest hundredth you need it to be 4.ab

Which is painful

Oh that’s even more painful than I though

[alpine sable]

Is there any calculator for this shit tho

[north needle]

Any calc can do this

But cause it said approximate I thought you had to work it out mentally

[alpine sable]

@north needle okay what equation could I say to the calculator

Like Photomath

To recognize it

[north needle]

Use Desmos

Or a normal calculator

[raw shard]

use (a+b)^2 = a^2+2ab+b^2

[alpine sable]

and

[raw shard]

set a to 4 and be to like 0.1

[alpine sable]

what's next

[north needle]

If you want to do it on a calc all you are doing is plugging in numbers

[hushed flower]

why to hundreths bruh

[alpine sable]

I don't fucking know

why

[north needle]

You can literally do this

[alpine sable]

4.12

and 6.63?

[north needle]

Approximating to the hundredths is pain

[north needle]

That’s 2).

[alpine sable]

yeah

[hushed flower]

how are you meant to mentally approximate to the hundredths

[north needle]

You cry

And then don’t

Maybe with Paper, lots of paper, but still no

[alpine sable]

which means it's nearly impossible?

Well they designed this for us to fail

[raw shard]

linear approximation moment

i literally gave you something that could help

[alpine sable]

I'm only 13 grade 7 lawl and they ask me to approximate to 100

[gray isle]

you could use sqrt algorithm

which is a bit of a pain

[raw shard]

i guess just take a guess, then square it

if it’s too big go down a bit

too small go up a bit

[alpine sable]

anyone know how to create a slide with only one function/graph that will let the marbles slide and hit all the stars

here’s an example of how it works

but the trick is you can only use one function to solve this

[north hemlock]

The population of City X in 2010 was 896000. It grew to 1444000 by 2020. Assuming the maximum supportable population of this city is 2300000, use the logistical growth model to predict the population in 2030.

[thorn kindle]

what is logistic growth formula

You should know this

[ebon stream]

Can someone dm me please

[summer sage]

I'm kinda stuck on this plz help

[lethal ore]

It's actually simple if you take a closer look at it. Just think which two triangles you need to prove as congruent so as to conclude that AB=ED? @summer sage

[summer sage]

so if bc=ad and ea=ac then ab=ed cuz it's sss?

[onyx gyro]

where's the f?

[lethal ore]

Check again dear. There's no F

[summer sage]

oh sry lol I meant ea

[onyx gyro]

ss alone does not imply congruency between triangle ACB and EAD

[lethal ore]

Think. You're supposed to prove that AB=ED. So you can't use SSS then

[summer sage]

can I use sas?

[lethal ore]

For that you need an angle to be equal. Now tell me can you see/find a pair of equals angles?

[summer sage]

bca and ead?

[onyx gyro]

how would you prove that they're equal?

[lethal ore]

That's right. But you gotta find a way to prove that they're equal

[summer sage]

that's where I'm stuck on actually

[lethal ore]

Dude. Change your picture man. It looks like you're laughing at other discord users 😂😂😂
It's kinda funny though

[onyx gyro]

lmao

[lethal ore]

Check triangle ACD

[summer sage]

it's kinda cute

[summer sage]

I'm confused

[lethal ore]

Angles opposite to equal sides are equal

[summer sage]

hmm so angle bad is 60?

wait no

[lethal ore]

Nooo

[onyx gyro]

uh
the specific measures of the angles aren't really relevant to the problem

[summer sage]

hmmm

[lethal ore]

In triangle ACD check which two sides are equal and then which two angles are equal because of the previous reason

[summer sage]

so angle bca is equal to ead because of ad and cd?

or am I wrong....

[lethal ore]

You're not wrong but the reasoning behind it is wrong

[summer sage]

hmm

[onyx gyro]

the important clue here is complements

[dusty willow]

Can anyone here help in logic?

Please help me 😔

I've been asking all day and have not gotten any help

It's annoying that I need to keep asking

I will pay someone to help me

[lethal ore]

See in triangle ACD,
AD=CD(given)
It implies that ACD=CAD
BCA and EAD both are supplimentary angles of ACD and CAD respectively
So we can conclude that ACD=EAD
@summer sage

[summer sage]

ohhhhhh thank you so much

[onyx gyro]

mouse moment

[lethal ore]

So sorry man. I don't know how to go about this problem but I surely will think about it though

[agile fulcrum]

how do i solve this with either direct comparison test or limit comparison test?

i dont get to use ratio test

testing for convergence or divergence

[lethal ore]

Here it forms a geometric progression with a particular first term and common ratio.
But I haven't come across these terms though, direct comparision test, limit comparision test and ratio test

I can help you find the sum of this series up to infinity. But I don't know if that's required here

[agile fulcrum]

i need to prove it converges

[dusty willow]

Have you done logic, @lethal ore?

[buoyant edge]

Simple to show it converges by geometric series

[hard haven]

can someone help me on this

[stark trail]

probably show that $\lim_{n\to\infty}\frac{\frac{9^2}{10}\left(1-\left(\frac{9}{10}\right)^n\right)}{1-\frac{9}{10}}$ converges would be enough?

[ocean seal]

Muzan Jackson

[lethal ore]

I got nothing. Sorry ☹️

[lethal ore]

You still there?

In order to prove that the series is converging, we gotta show that the sum of those term would be a constant term. I can prove that the series is converging in this way. Let me know if you wanna know further @agile fulcrum

[oblique mural]

is this channel open?

[agile fulcrum]

is the limit of a log the log of a limit?

[alpine sable]

no

for when x > 0, possibly

actually, it might always be equivalent, i am unsure

i'll go with yes, yes it is

[dire juniper]

no brainer question, welp

[alpine sable]

If anyone is interesting in helping lemme know

[frosty drift]

Help

[lapis hedge]

Multiply across and simplify if possible

[frosty drift]

Bro what does that even mean

I’m tryna get answers 😭

[rough compass]

+- 2

yes

[west glen]

howd you get that

[rough compass]

wait ill show 1s

[west glen]

cheers

[frosty drift]

Huh?

[rough compass]

idk if its correct u can check

[lapis hedge]

$$\frac{a}{b}\cdot\frac{c}{d}=\frac{ac}{bd}$$

[ocean seal]

Leslie Miller

[lapis hedge]

Lol messed up

[rough compass]

@west glen basically i subtracted an extra tan^2 (x) from both sides to get the identity sec^2 x - tan ^2 x = 1

and then u get 2tan^2 x = 8

[thorn kindle]

Tanx = 2

[potent sinew]

What is considered the standard inner product of vectors?

[rough compass]

-2 aswell

[potent sinew]

oh sorry

[edgy perch]

Henlo again

[west glen]

@rough compass thx man

[thorn kindle]

Yep

[sudden topaz]

can someone help me with ppart a?

my course material never explicitly states how to determine the bandwidth off a sine, since it goes negative and all

[unique tiger]

is this channel open?

[wheat prawn]

could sm1 explain how 7pie is = to 0

for the reference angle

[alpine sable]

P and J have pills, if P has 2 more pills thans he has irl, they would have each one 11 pills . If J has 2 more pills than he has irl, they would have each one 10 pills, how many pills has P and J ?

[solid breach]

Help me

[tired drum]

How would I do this?

[vale wigeon]

do you know, in general, how to divide complex numbers?

(y/n)

[tired drum]

Yeah

You get the conjugate

[vale wigeon]

and what's troubling you here?

[tired drum]

I cant get it into the form a+bi lol

It wont sim I-lift

*simplify

[vale wigeon]

do you have some work to show?

[tired drum]

Yep

[vale wigeon]

okay, then out with it

you should have presented it at the beginning instead of waiting for someone to come along and ask

[tired drum]

Oh okay my bad

[vale wigeon]

there are several mistakes here

[tired drum]

Really?

[vale wigeon]

one that can be attributed to a typo - the denominator in the second line is supposed to be 3 - 2i^2

and another that isn't: 2i * (-sqrt(2)i) is not equal to -2sqrt(2)i.

[tired drum]

Can u explain why?

[vale wigeon]

why don't you instead explain why you think $ai \cdot bi = abi$?

[ocean seal]

Ann

[vale wigeon]

because it seems that by your logic multiplying i with itself would just give you i again instead of -1, and that flies in the face of the very definition of the imaginary unit.

[tired drum]

You said my mistake was in -2i times -2sqr(2i) right?

[tired drum]

It should be -ab

[vale wigeon]

at no point did i mention -2sqrt(2i), and at no point did that appear in your work either.

[tired drum]

Oh my bad I missed power

Hold on let me resend my work

[vale wigeon]

do not shove i under a square root when it was not under a square root.

[tired drum]

How about now?

@vale wigeon

Where would i go from here

[vale wigeon]

you have an i^2 that you have for some reason chosen not to rewrite as -1

[tired drum]

Yeah, but what would that change?

What would I do after that?

It would just be + 2 (sqrt 2)

[vale wigeon]

yeah well you now have some real terms and some imaginary terms

i hope it doesn't take a huge stretch of the imagination to rewrite -2i + 2sqrt(3)i as one term

[tired drum]

Then what would I do?

[vale wigeon]

...

you're really overthinking this

[tired drum]

Lol

[vale wigeon]

your fraction is almost done

all that you need to do now is a little cleanup

(sqrt(6) + 2sqrt(2) + (-2+2sqrt(3))i)/5

[tired drum]

Math written in words confuses me

Lmao but thanks

I pretty sure I know what i need to do

[subtle elbow]

how do u solve dis

[warm brook]

I’ll write out the first term for you
n=1
t_1= 2t_0 - 3
t_1=2(1)-3
t_1=-1

Now use this idea for the next 3 terms. Plug in n, then see that the (n-1) term has already been found by the last iteration

[rapid heron]

i) because AC, BC and AB are the radius of the circle

AC = BC = AB = 10cm

ii) now ∆ABC is equilateral therefore angle b = 60° or π/3

Now use the Linear pair property and find out the angle CBE.

iii)you can calculate the region CBE perimeter by add the radius and the arc length.

Arc length: S = r*theta

iv) To calculate the area of CBE use sector area formula.

[alpine sable]

help

<@&286206848099549185>

plzzz

[lone heart]

From

#❓how-to-get-help

Rule 4

If your question has not been answered for a minimum of 15 minutes, you may use the Helpers tag once. Please do not try to bump your question using this ping unnecessarily. Do not abuse this ping. Do not individually ping users with the Helpers tag without their express permission.

[alpine sable]

oh sorry

[strong wing]

Hey where is the mistake in this?

[stone shard]

log(0.5) is a negative number, so 2log(0.5) > 3log(0.5)

[strong wing]

ok ty!

[hardy geyser]

why is it 3pi should it be pi + half a pi/2

[vale wigeon]

do you mean pi + pi/2?

[hardy geyser]

no?

cause it’s a radian plus half a radian right

[vale wigeon]

oh, so you think the stuff you circled should be pi + (pi/2)/2?

[hardy geyser]

yes

[alpine sable]

can someone explain

[vale wigeon]

so pi + pi/4, in other words.

[alpine sable]

me

[hardy geyser]

yes like that

[vale wigeon]

you realize pi/4 is 45 degrees, right?

not 90.

[alpine sable]

pls

[vale wigeon]

...ok @hardy geyser we're gonna have to move

[hardy geyser]

i move to 9

@alpine sable i think you needa turn it into slope form

[alpine sable]

how

i tried

is it like t

they replace x with 0 to find y

and they replace y with 0 to find x

[hardy geyser]

it says to find the intercepts it occurs when or the other is 0

[alpine sable]

yes

[hardy geyser]

so i’m guessing that’s how i do it

[alpine sable]

i just figured it out

[hardy geyser]

u

[alpine sable]

thanks

[hardy geyser]

oh cool

[alpine sable]

nice name

thanks

hiya fellas how would i do this? I'm guessing t is the subject so i'd put p there instead but then what?

[hardy geyser]

@alpine sable get p by it self

i think

[alpine sable]

???

[lapis hedge]

^ Yes. Remove anything not attached to p and then anything attached to p

[alpine sable]

i don't get it xd

[hardy geyser]

the inverse of -2 is?

[alpine sable]

+2

[hardy geyser]

yeah add it to the other side

[alpine sable]

p= +2

wait do i swap the p and t

[hardy geyser]

u still have 3p

what is the inverse of multiplying

[alpine sable]

so p= t+2

dividing

[hardy geyser]

yes so what do u do to the other side

[alpine sable]

idk

[hardy geyser]

3p = t + 2

[alpine sable]

ooohh

[hardy geyser]

the inverse of multiplying is dividing

[alpine sable]

alright

thanks

Any help?

[alpine sable]

@alpine sable YouTube search how to calculate square root with division method.

In a cubic equation let's say
ax³ + bx² + cx + d = 0.
How do we write this in form of
my³ + nx + o = 0?

Tried watching YouTube and they were trying something with synthetic division but didn't understand why they were doing that.

Ping if possible.

[lime wadi]

sup y'all

i've tried to graph a parabola in ALEKS but the result is always seems to differ from the Mathway ones

is there any solution for this, from a mathematical perspective?

[lapis hedge]

Yes. Remember what a function is. For an input you get an output.

[lapis hedge]

For synthetic division to work you need to create placeholder terms to account for the missing terms w/ variable

[alpine sable]

@alpine sable hey is my answer right here

The other one is the question

And the one below is the answer

[lapis hedge]

Looks good

[alpine sable]

@lapis hedge All correct?

[lapis hedge]

ye

[alpine sable]

thanks

answer is above the question

[woeful pulsar]

doesn't look related lol

[alpine sable]

fuck

[woeful pulsar]

where is 138 from

[alpine sable]

Totally fucked up

[woeful pulsar]

also your presentation is oof

[alpine sable]

@woeful pulsar now

any opinions?

[woeful pulsar]

It looks reasonable but tbh how were you supposed to approximate it?

[alpine sable]

I don't even know they just said appromixate to the nearest hundretjs

[alpine sable]

@woeful pulsar anyways my answer here is all spot on right?

[woeful pulsar]

tbh I don't feel this should be simply "plug into calculator" assignment

but since you have it, it feels really pointless lol

[alpine sable]

so this is basically right @woeful pulsar lol

[woeful pulsar]

yeah I guess, assuming you rounded correctly

[strange coral]

can someone tell me an equation to sum
1+1/2+1/3+1/4+1/5.…....+1/n

[woeful pulsar]

there's no closed form iirc

why do you want to sum it

[strange coral]

i was watching something then i found this thing called the euler-macheroni constant (i probably spelt it wrong)

i was wondering if i could calculate it from
(integral from 1 to inf of 1/x) - (that sum at n=+infinity)

[woeful pulsar]

yeah there are ways let me check something

[lavish grove]

hi there is french students here by coincidence ?

[woeful pulsar]

https://www.youtube.com/watch?v=fw1kRz83Fj0
yeah hmm, this might help

but idk, it seems to only sum converging series ig

mathologer has quite a bit on it

[strange coral]

1/n diverges i think

[woeful pulsar]

let me search other stuff

welp found this from another mathologer video @strange coral but I don't think it converges that quickly

https://www.jstor.org/stable/2004048?seq=1

Apparently that power sum thing can be used, Donald Knuth used it to calculate it to 1271 places @strange coral

[strange coral]

oh wow

[woeful pulsar]

what's your aim here?

[alpine sable]

oops sorry

is this in use?

[woeful pulsar]

any further questions?

[strange coral]

nope

[strange coral]

was just a random thought while watching random math videos lol

[vapid oak]

Seems to be true, however I might be wrong

[sand geode]

@vapid oak thank you very much

[woeful pulsar]

do you think it is true or false?

[vernal jay]

good morning! I need some assistance on an assignment

if someone could pls just tell me how to do it and the process before getting the answer, that'd be great!

[vapid oak]

Depending on what branch of math it is, I'd be happy to help as best as I can

[vernal jay]

it is statistics for advanced math decision making

[vapid oak]

Yeah I'm sorry I can't help you there. Either someone else can help you or you can ping the helpers in 15 minutes 🙂

[turbid maple]

send help

[raw shard]

@turbid maple do 36^(3/2) first

then do 1 over that

[turbid maple]

is it 1/216

[vernal jay]

<@&286206848099549185> Hi! Could really use help on my statistics work, I just need someone to coach me through all six questions please! :)

repost of what I need done ^

[vague iris]

what's the difference of the 'a' in the formulas of ellipse and hyperbola?

[sullen nova]

WHERE IS THE PRIZE AT?

Ans

[vernal jay]

can no one help me?! 😭

[sullen nova]

Ans me first

[gleaming sluice]

it is the green triangle, in the first round the blue square cannot be the prize since of its unique shape and the yellow circle cannot be the prize because of its unique color, otherwise one of them would know where the prize is at. In the second round the three remaining shapes are the green triangle, the blue triangle and the green circle. The green circle cannot be the prize since it has a unique shape of the remaining shapes and the blue triangle cannot be the prize since it has a unique color of the remaining shapes. This only leaves the Green triangle by the start of the third round which means that both people would know the prize.

[dark ruin]

how do i get better at maths? without the help of school

any good tips

im not entirely shit

i mean

where do i learn about new stuff

if its not for school

[glass lichen]

Google...

Buy a textbook

[arctic gust]

try these channels they're pretty cool
https://www.youtube.com/channel/UCoxcjq-8xIDTYp3uz647V5A
https://www.youtube.com/channel/UCYO_jab_esuFRV4b17AJtAw

[arctic gust]

☝️

though its not school - related

[raw shard]

if you say what you’re interested in you might get better recommendations

[uncut wolf]

Hi can somebody help me with this please, ty

[arctic gust]

which one?

[uncut wolf]

all 4, i am not good at geometry

[arctic gust]

for 1st use pythagoras

PM would be sqrt(13^2-12^2) and AM would be sqrt(15^2-12^2)
AM-PM=AP so there you go

[uncut wolf]

tyy

[arctic gust]

now the second q

PR+QR is basically the diameter so the radius should be 5 cm

so the distance OR is radius-PR which is 2 cm

now, drop a perpendicular from O to AB

and name the new point (lets say S, for example)

[rare ledge]

Why is the formula E.A when according to the definition it should be E/A?

[arctic gust]

since perpendicular cuts AB in half, AS=BS=AB/2

[ancient agate]

I think you have your formula wrong

[arctic gust]

guys one question at a time

[ancient agate]

Electric flux is = EAcos(x)

[rare ledge]

It's the same formula everywhere

[rare ledge]

Yeah the one above is in vector form but still

It should be E/A according to the definition right?

[ancient agate]

why should it be E/A

[rare ledge]

Electric field lines per area

[ancient agate]

That is what electric flux is

And since the formula for electric flux is EAcos(x) and the electric field lines hit the vector surface perpendicular you have cos0 = 1

[arctic gust]

@rare ledge he is correct it really is EA

[rare ledge]

Yeah but I can't understand why :/

I can't find an explanation online

[ancient agate]

But I don’t get why you think it would be E/A

[ancient agate]

@rare ledge may I ask what grade you are in

[rare ledge]

12th grade

[ancient agate]

Don’t worry about the derivation then

[hearty cliff]

do you know what the discriminant is?

[ancient agate]

I mean, you could look it up there’s plenty of online explainations of the derivation for electric flux but I wouldn’t worry about it

[arctic gust]

E/A is called field intensity

[rare ledge]

Okay

Is the definition above wrong then?

[arctic gust]

No EA is flux

[ancient agate]

What

[supple umbra]

no thats what need help with

[ancient agate]

No it’s correct

[arctic gust]

its field over an area

[rare ledge]

I meant the one I sent in the picture

[hearty cliff]

so the discriminant is basically the part inside the square root in the quadratic formula

[ancient agate]

That is correct man

[rare ledge]

Okay

Alright thanks guys

[supple umbra]

lets say my teacher gave me 1 class on this 2 weeks ago and i forgot how to do that

[hearty cliff]

so the quadratic formula is $\frac{-b^2 \pm \sqrt{b^2 -4ac}}{2a}$

[ocean seal]

codeo

[supple umbra]

oh 2a

ok

[raw shard]

no, the stuff in the root

[hearty cliff]

$D = b^2 - 4ac$

[supple umbra]

oh

[ocean seal]

codeo

[hearty cliff]

that's the discriminant

[supple umbra]

mb

[uncut wolf]

@arctic gust ty for the 2nd one! now only 3rd and 4th

[supple umbra]

ok

[hearty cliff]

so because it's inside a square root there are only real roots when D is not negative

if D is 0 there is only 1 root and otherwise there are 2

[cosmic sun]

Guys I have a doubt in probability

🔴 In a large population 40 % votes for A and 60 % for B. Suppose we select at
random 10 people. What is the probability that in this group exactly 4 people will
vote for A?

Could someone help please : (

[hearty cliff]

the random variable for the no of people voting A is a binomial distribution

[cosmic sun]

so 10C4 ( 0.4)^4 * (0.6)^6

[hearty cliff]

wait

[cosmic sun]

this would be the answer ?

[hearty cliff]

yep looks right

[lethal dock]

How will I solve this?

[cosmic sun]

Thanks

[lethal dock]

If p + (1/p) = 5, show that p² + (1/p²) = 23

[sage summit]

are you sure it's not show that p² + 1/p² = 23 ?

[lethal dock]

Oh it is

Yes

[ancient agate]

Just sbs for your p + 1/p

And you’re middle term is 2p1/p

Which is 2

[lethal dock]

Sbs?

[ancient agate]

Square both sides

[lethal dock]

So (p + (1/p))² = 5²

[ancient agate]

Yup

[lethal dock]

Hmm what do I do after that

[ancient agate]

Expand and the answer should be right in front of you

[lethal dock]

Oh

[ancient agate]

you see it

[lethal dock]

1² = 5²

[ancient agate]

Bro what

[lethal dock]

Nvm I divided it

[ancient agate]

??

[lethal dock]

2p² = 5²

[ancient agate]

no

[lethal dock]

.

[ancient agate]

Just expand (p+1/p)^2

[lethal dock]

(1/2p)^2 ?

I'm kinda confused

[ancient agate]

Do you know that (a+b)^2 = a^2 +2ab + b^2

[lethal dock]

Yes

Ohhh so I use the formulae

For expanding

?

[ancient agate]

So use that to expand (p+1/p)^2

Yes

[lethal dock]

Oh I see

[ancient agate]

Can u see how you get the answer now

Channels in use mate

[cosmic sun]

Sorry..

[ancient agate]

All goods

[lethal dock]

p² + 2(p + (1/p)) + (1/p)²

?

[ancient agate]

Yep

No

p x 1/p x 2 for your middle term

[lethal dock]

What?

[ancient agate]

Why are you adding p + 1/p for your middle term

Just follow the formula

[lethal dock]

Cus thats a + b

[wanton folio]

hello

[ancient agate]

$(a+b)^2=a^2 + 2ab +b^2$

[ocean seal]

noway124

[lethal dock]

Oh damn I was supposed to multiply there?

Sry

[wanton folio]

If you have these possibilieties you can simply calculate it for k=0 and k=1

[lethal dock]

$p² + 2(p * (1/p)) + (1/p)²$

[ocean seal]

JUGisMUG🎃

[ancient agate]

There u go

[plucky crow]

whats the ans

[ancient agate]

Now what’s p * 1/p

Is this a quiz

[wanton folio]

You can do this yourself. Don't be lazy.

[plucky crow]

its hwk

so for 1

[cosmic sun]

here you go

[plucky crow]

i got

1

then 2,3,8,

2,4,8,

do i calc the sum

of the series

[uncut wolf]

<@&286206848099549185> Could I get help with the 2nd and 4th one?

[plucky crow]

to infinity

[ancient agate]

Ah why just give ans

[cosmic sun]

sometimes it helps , he can solve other questions in a similar way

[ancient agate]

interesting

[cosmic sun]

@lethal dock if you have any doubt with the solution, lemme know

Now I have a probability question, I need a little help with that 😂

🔴 A box has three identical-looking coins. However, the probability of success
(Heads) is different for each coin: coin 1 is fair, coin 2 has a success probability of
0.4, and coin 3 has a success probability of 0.6. We pick one coin at random and
throw it 100 times. Suppose 43 Heads come up. Using this information, assess the
probability that coin 1, 2, or 3 was chosen.

[lethal dock]

What the point of this and how is it equal to 2?

[cosmic sun]

I used this formula

a = p , b= 1/p

[lethal dock]

Ohhh

I've only known that formulae as like a² + 2ab + b²

That works too?

[cosmic sun]

Same thing

[lethal dock]

I see

[cosmic sun]

ye

[lethal dock]

Thank you so much, i understand these questions now!!

I can do the rest by myself

[cosmic sun]

Great : )

[strange swan]

I need help with number 15

[lethal dock]

hmm.... p² + (1/p²) is 25, how did that 2 colored in red come from to make it 25-

[cosmic sun]

nono p² + (1/p²) + 2 = 25

2 goes to other side

p² + (1/p²) = 25 -2

p² + (1/p²) = 23

[alpine sable]

Is my answer right

[hearty cliff]

just put it in a calculator and check

[lethal dock]

But if (p + (1/p))² can be 5² which is 25, where does the 2 come from

And how does 2 move the RHS

[cosmic sun]

From here

[meager barn]

do open formula (a+b)^2

[cosmic sun]

a = p , b= (1/p ) , 2ab = 2 * p * ( 1/p ) = 2

[alpine sable]

Bruh.

[lethal dock]

Isn't 2ab ignored? Like p² + (1/p²) + 2(p * (1/p)) is the same as (p + (1/p))²

[gleaming sluice]

p/p=1

[lethal dock]

Where did that +2 come from

Isnt the 2 in 2ab supposed to be multiplied

[wary stream]

$2 \frac{1}{p} p = 2 \frac{p}{p} = 2

[strange swan]

<@&286206848099549185>

[meager barn]

they got canceled,try solving it in paper

[lethal dock]

My fractions are weak, how did p × (1/p) become (p/p)

[hearty cliff]

mate

that's how fraction multiplication works

[lapis hedge]

you multiply straight across

[lethal dock]

Ohhhh

[alpine sable]

Hi, how can I think about negative exponents? I don’t quite understand. For example, how can I know 2^-3 = 0,125

[lethal dock]

@gleaming sluice tysm!! That cleared my doubts

[meager barn]

2^-3 = 1/2^3 = 1/8

[alpine sable]

I know that 2^-3 = 1 / 2^3, that would be 1/8, how can I then know the answer to 1/8?

Say it was a different number like 1/32

[gleaming sluice]

you can just only look at the denominator and see that 2^3 = 2 * 2 * 2 = 8

[meager barn]

you want answer in which base? e.g if in base of 2 its 2^5 ig

[alpine sable]

What I meant is finding the answer in decimals

for instance what would 3^-3 be? 1/27, then what would the answer be in decimals?

[meager barn]

then you have to perform simple division by old school method,
1/27 solve it by keeping the "1" in dividend and "27" in divisor, then quotient will be 0.037

<@&268886789983436800> can I post picture of answer??

[fading zephyr]

sure

[limber bear]

hey any mods around

[fading zephyr]

sup

[limber bear]

i got a question

xy=4

x+4y

[meager barn]

check this

[limber bear]

find the minimum value for x+4y

[fading zephyr]

please use an empty channel, this one is currently taken. also, you don't need mods for this

[meager barn]

when channel becomes empty?

[fading zephyr]

when the previous question has been answered or no one has posted anything in a while (~20 min)

[rancid steeple]

Not sure where to ask so i'll do it here. If you have an answer, please ping me.

Trying to derive the "multiplier" term for the regula falsi method of approximating roots (in my class they call it the "radius of convergence")

Basically, the recurrence for approximating the root is (for a fixed constant a)

$x_n = a - f(a) \frac{f(x_{n-1}) - f(a)}{x_{n-1} - a}$

[ocean seal]

random variable

[rancid steeple]

I want to find the constant $R$ such that if $\alpha$ is the root of the function f, then $|x_{n+1} - \alpha| \sim R |x_{n} - \alpha|$

[ocean seal]

random variable

[rancid steeple]

taylor expanding $g(x) = a - f(a) \frac{f(x) - f(a)}{x - a}$ is not giving me the expected result, which is apparently $ (a-\alpha)\dfrac{f''(\phi)}{2f'(\phi)}$ for some $\phi$ in an interval near $\alpha$

[crisp grove]

for Regula-Flasi, rate of convergence is ϕ I think

[ocean seal]

random variable

[rancid steeple]

found something

http://compmath-journal.org/dnload/Robin-Kumar-and-Vipan-/CMJV06I06P0290.pdf

[analog summit]

Nice stuff sth i could never understand(

[next lynx]

I have a question but I'm not sure how to phrase it well, sorry if it's a bit confusing.
I have 2 coordinates on a grid, a center point of a circle (P1) that is 100m in radius, and a random point within the circle(P2). I need to find the coordinates(P3) of the closest outer edge of the circle relative to P2. Attached is a poor mspaint drawing demonstrating what I mean, the inner colored points are various P2's, with the ones on the edge the missing P3 I need to find. I assume this is trig, which I sadly missed in school, so please don't judge if this is a stupid/easy question.

[arctic gust]

nice stuff

[ancient saddle]

Hello, is this what you mean?

[arctic gust]

find equation of the line joining p1,p2

[faint wyvern]

sex?

[arctic gust]

then find where the line intersects the circle

you can do this by substituting in the circle equation

which is (x-g)^2+(y-h)^2=r^2

where g and h are coordinates of P1

i hope u got ur answer @next lynx

[bleak ridge]

I would personally do

$r * \frac{P_2-P_1}{|P_2-P_1|} + P_1$

[ocean seal]

PapaBread

[bleak ridge]

But I guess that's just a matter of preference

Where || is the magnitude of the vector

[ancient saddle]

If this is your problem, I suggest to draw vertical segments from P2 to R and from P3 to R so you get 2 similar right triangles

[next lynx]

What is y and h in that?

[bleak ridge]

Surprisingly enough that's an interesting way to derive my equation

[next lynx]

What exactly is the output of this, don't I need 2 end values, the X and Y for the unknown point?

[bleak ridge]

I'm just writing it shorthand where every operation is applied to both x and y

So you get a coordinate pair

[next lynx]

Ah Im dumb I see now

[bleak ridge]

$\frac{(P_2-P_1).x}{|P_2-P_1|}=\frac{(P_3-P_1).x}{R}$

[ocean seal]

PapaBread

[bleak ridge]

Yeah that's a direct derivation of the x part of this equation

Geometry

Cause the x distance from P2 to P1 is to the distance from P2 to P1 as the x distance from P3 to P1 is to the radius

And the same but opposite for y

So yeah that's what the broken down equation looks like ig

[viscid harbor]

Any1 know how to do this?

<@&286206848099549185>

[bleak ridge]

Do you know how to add fractions

[viscid harbor]

i did the steps until x/2 = 10

idk how to do that

$r

$r

[arctic latch]

i forgot what the difference between

proportionate and inverse proportion

[bleak ridge]

Just multiply both sides by 2

[arctic latch]

variation

yeah

but whats the difference

[viscid harbor]

so 2x = 20

[bleak ridge]

x/2 * 2 = x

Cause the /2 cancels out

[viscid harbor]

oh y

so why isnt it x/2 * 2 = x * 2

since yr multipliying all by 2

[bleak ridge]

Do you mean like the relationship between two variables?

[viscid harbor]

ok so here are my steps

[bleak ridge]

Because when you do x/2*2

You get

$\frac{2 * x}{2}$

[ocean seal]

PapaBread

[bleak ridge]

There's a 2 on all terms of the top and bottom so you're left with x

[viscid harbor]

2*3X/4-2xX2=2 *5

thats my first step

2*3X/4-2xX2=2 *5

first one

3X/4-2X/2=10

2nd step

x/2=10

last one

idk what todo now

[bleak ridge]

I don't follow your work

[viscid harbor]

breh

this is example

[bleak ridge]

That's for when you only have one x

[viscid harbor]

fk

[bleak ridge]

And what you do once you simplify the two fractions into one

[viscid harbor]

what i do

[bleak ridge]

The first step I would do is to simplify the two into one

[viscid harbor]

am so confused

[bleak ridge]

Do you agree that x/2 is the same as 2x/4

[viscid harbor]

ye

[bleak ridge]

Just multiplying top and bottom by 2

So you can do that and then you can add the two fractions

[viscid harbor]

um

id understand so ill just not do my hw

[bleak ridge]

So you get 3x/4 - 2x/4 = 5

Then you just subtract the two fractions because they have the same bottom part

And go from there

[viscid harbor]

i got $\frac{3x/4} = 10$

$\frac{3x/4} = 10$

[ocean seal]

King_Of_Lion

[viscid harbor]

breh

ok bye

[bleak ridge]

{3x}{4}

[viscid harbor]

imma go

[magic pine]

Hello, do you guys have tutor sessions here?

[remote heron]

i dont think so in general

on what topic

[magic pine]

uhm, EQUIVALENCE RELATION

[remote heron]

hmm probably ppl who can help you but idk about tutoring

[magic pine]

I thought I understood the concept but then when I tried to answer them, I was shocked to find myself scratching my head lol

[remote heron]

like what sort of question?

[magic pine]

uhm..

[remote heron]

or what topic?

what are you confused about

[magic pine]

Let me get back to you, I'll try to re learn it 😄

[magic pine]

Our professor's just sharing his screen to show videos from YouTube and I can't ask questions because of that

[remote heron]

not a spectator sport 😄

[magic pine]

what does that mean if I might ask

[remote heron]

like you should try to engage with the material as soon as you have the tools to do so

even if its just constructing trivial examples

well i guess classes are good too

idk what youre supposed to get out of a class where you watch videos and cant ask questions

like showing = is an equivalence relation on the real numbers using the definition

[magic pine]

Apparently, our professor has a "malfunctioning" mic and uses that as an excuse to share yt videos from our topic

[next lynx]

Maybe I still am misunderstanding this, so P3(x) = radius *[ {P2(x) - P1(x)} / Abs{P2(x) - P1(x)} ] + P1(x) and P3(y) = radius *[ {P2(y) - P1(y)} / Abs{P2(y) - P1(y)} ] + P1(y)?

[remote heron]

find some common binary operators and test those

[magic pine]

in the case of equivalance relation, whenever I encounter a mathematical problem, Im perplexed

[remote heron]

do you know the definition?

just memorize the 3 pieces

then find some operators, i think = < and > are the common first ones

show that they are or why they break

[magic pine]

I see I see

thanks for the tip

[remote heron]

like uhh

we know that for any equivalence relation and some element $a$, that $a \sim a$

[ocean seal]

jan Niku

[remote heron]

there are other conditions that must be true, but this is one of them

so can you tell me out of: $=, >, <, \leq, \geq$

[ocean seal]

jan Niku

[remote heron]

which ones can we already rule out as being equivalence relations?

(aka check, is 1=1? is 1<1?)

[bleak ridge]

Ye

[magic pine]

1=1 is a reflexive

[remote heron]

yea equals gives you reflexivity right

but is 1<1 or 1>1?

[bleak ridge]

Well actually the one thing that isn't separated is the bottom part

The |P2-P1|

[magic pine]

this is not true

[bleak ridge]

That has to stay constant, you'd probably just use pythag for that part

[remote heron]

yea

so youve lost reflexivity, and < or > are definitely not equivalence relations

because they are not reflexive relations

next one to check is symmetry, you want $a \sim b \leftrightarrow b \sim a$

[ocean seal]

jan Niku

[remote heron]

so you still have left out of the pool of 5: $=, \leq, \geq$

[ocean seal]

jan Niku

[remote heron]

which are symmetric?

[next lynx]

I dont know what you mean by this

[bleak ridge]

So the two equations would be

[magic pine]

uhm

[remote heron]

how about just for =?

[green glacier]

Hey i can help you

[remote heron]

can you guys start a thread

[magic pine]

this is true

[green glacier]

Theres a conversation going on so lets move to a different channel

Or dms i dont mind

[remote heron]

this is true when your relation is symmetric

its not true in general

consider an example like uhh

[bleak ridge]

$P3_x = r * \frac{P_2.X-P_1.X}{\sqrt{(P_2.x-P_1.x)^2+ (P_2.y-P_1.x)^2} + P_1.x$

Sorry one last thing

[remote heron]

$a \sim b \to a-b > 0$

[ocean seal]

jan Niku

[remote heron]

well 5 ~ 4 because 5-4 is 1, which is greater than 0

[bleak ridge]

Bruh

[remote heron]

but 4-5 is -1, which is less than 0

so even though 5~4, 4 isnt ~5

so ~ as defined here isnt symmetric

then its not an equivalence relation

[magic pine]

~ = equivalent, right?

[remote heron]

related

[magic pine]

ohhhhh

[remote heron]

relations are like

way looser than functions

[magic pine]

im sorry about that

[remote heron]

because as you can imagine that ~ as defined has like

i mean infinitely many numbers are related to 4

any number bigger than 4 should be related to 4

doesnt really work as a function (fails in a lot of ways)

but still useful

ur fine relations are weird

[magic pine]

Im a bit confused, are you giving me sample questions?

[remote heron]

im just saying like

well you mean what we were on before?

these are like the trivial or easy examples

[magic pine]

Im just new in this channel. I was shocked that you can "code" here lol

[remote heron]

<= and >= and =

oh, its just a latex bot

for rendering maths

[bleak ridge]

It's epic

[ocean seal]

jan Niku

[magic pine]

woah

I see

[remote heron]

okay so

[magic pine]

Is it okay if you can give me a real example?

[remote heron]

try the one i defined before

[magic pine]

Im getting the general concept of it but there is another right? The transiitive one

[remote heron]

let $a \sim b$ if $a-b >0$ be defined over the real numbers. Show that $\sim$ is an equivalence relation or explain why it is not.

[ocean seal]

jan Niku

[remote heron]

well i guess i already explained why

lmc

trying to think of another one thats just numbers

how about like

[magic pine]

take your time and thank you for your time

😄

[remote heron]

Let $a \sim b$ iff $2 \mid (a+b)$ over the positive integers.

[ocean seal]

jan Niku

[remote heron]

show its an equivalence relation, or explain why its not

( 2|(a+b) means a+b is even)

[magic pine]

so like, 2=2

[remote heron]

not quite

did you want to try again? Or i can show an example of a case for reflexivity

brb

[magic pine]

I think the latter, I thought I can handle the examples.

[remote heron]

well what if i just asked

we wanna show that a~a right

for some positive integer

what would it mean for a~a

using how ~ is defined

[magic pine]

yes

[remote heron]

so our relation is

some number is related to another if their sum is even

so what does it mean for a number to be related to itself

[magic pine]

if it is related to itself, then it is reflexive

[remote heron]

in the context of the definition of ~ though

theres a sum involved

[magic pine]

uhm...

[remote heron]

like here lemme show with the earlier one

and maybe that framework will help

for this relation

if i wanted to check reflexivity

I'd check if a-a>0

aka, this is the same as checking if a~a