#help-0

1 messages · Page 874 of 1

raw shard
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yeah

subtle cedar
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Then divide and distribute and that jazz and make it 24

snow nest
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then just expand the brackets and that shit

subtle cedar
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This is a sweet discord server tysm

raw shard
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well actually add everything together on the left side

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then subtract constants

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but i’m sure you knew that

subtle cedar
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Yes

snow nest
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the scary thing of maths is you don't know what others know

raw shard
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lol

snow nest
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so i'm always scared to assume that say, you know how to do the navier stokes equation

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you don't but like

raw shard
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what field is that in

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like what kind of math specifically

subtle cedar
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Algebra is where I’m at

raw shard
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makes me think of vectors

snow nest
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lol no

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it's one of the 'great math problems'

raw shard
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oh

snow nest
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the Millennium Prize Problems

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if you knew how to do it you'd quite literally win a million USD

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"To date, the only Millennium Prize problem to have been solved is the Poincaré conjecture, which was solved in 2003 by the Russian mathematician Grigori Perelman. He declined the prize money."

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why the heck did he decline a million

old hemlock
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Is x^(2/6) equal to x^(1/3)? If you do legal math and simplify the exponents, it is the same. However, if you graph them, they are not the same. X^(2/6) will never be negative since you square it. X^(1/3) however can be negative. Therefore they are technically not equal.

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Take x=-1 for example, they both give different answers

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If they are equal, they should give the same answers

raw shard
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they are equal for positive x

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actually wait

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the 2/6 one has even exponents

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so it turns negatives positive

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the 1/3 one leaves it as positive or negative

snow nest
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i'm getting the same answers for both?

old hemlock
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For x=-1?

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-1^2 is 1

raw shard
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are you doing the root first or power first

violet surge
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whats h can anyone help me really quick

old hemlock
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Doesn't matter, you square the negative either way

raw shard
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law of sines

tight venture
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What’s 34.5 • 2?

raw shard
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you square root the negative

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not square

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basically this is confusing

old hemlock
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Can we move to another channel?

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If you dont mind

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I got more questions about this

raw shard
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ok

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what channel

old hemlock
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Idk what topic of math this is

raw shard
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@violet surge do you know law of sines?

violet surge
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no

raw shard
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do you know some trig?

violet surge
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a little

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not that much

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im in grade 9

old hemlock
raw shard
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so law of sines is A/sin(a) = B/sin(b) = C/sin(c)

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the capital letters are the side lengths

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the lowercase letters are the angles opposite to the side lengths

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you know i might be overcomplicating this

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when you split the triangle, is the base 6000 for both triangles?

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aka is it split directly down the center

violet surge
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hm i get what you're saying

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but if you split it straight down

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i dont think its 6k for each

raw shard
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then law of sines is all i can think of

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there could be another way but i don’t know one

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wait is this from like, an assignment

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actually no that won’t help, i can already see the base won’t be 6000

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@violet surge do you want to try law of sines?

violet surge
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yeah sure

devout summit
violet surge
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70-70-40

raw shard
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wow i over complicated it

violet surge
raw shard
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not surprised

violet surge
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ohhhh i solved it

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lets go

raw shard
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i can do advanced stuff but not basic stuff without overcomplicating it lol

violet surge
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lol

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hopefully one day i can be good at trig

cyan willow
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Part a is 12 and b is 14, why?

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I cant figure it out

snow nest
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okay so

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@cyan willow

cyan willow
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hello

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Wait

snow nest
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if there are four options for each question

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oh okay

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waiting

cyan willow
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This might help u ?

snow nest
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what is that

cyan willow
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Binomial cd function

snow nest
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like what do those values signify

cyan willow
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it's the table

snow nest
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i am big dumb never heard of that

cyan willow
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Actually nvm, show me your way

alpine sable
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hi does this tree have a depth of 3 or 4?

snow nest
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hang on wait i've forgotten my combinations

alpine sable
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I got points taken off because my program said it was 3

snow nest
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gimme a second

cyan willow
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Oki

frank nacelle
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hey

cyan willow
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Ye

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Hi

late parcel
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This isn’t specifically a math question but is a thinking question

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Can I ask it

cyan willow
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Ok

raw shard
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if it’s related to math yes

frank nacelle
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what is the purpose of \e

late parcel
frank nacelle
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,help

ocean sealBOT
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A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

late parcel
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I’m confused between C and D

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Would you consider D a density I depended?

raw shard
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c

frank nacelle
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ur right

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its c

raw shard
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c has nothing to do with population

late parcel
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?

frank nacelle
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habitat decreases as population increasise

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floods are natural disasters and happen even if population is low or high

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habitat can be reduced due to high population

late parcel
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Ok thanks

frank nacelle
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,tex e

ocean sealBOT
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sainallani

frank nacelle
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what is the purpose of euler's constant

raw shard
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it’s basically the face of calculus

frank nacelle
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sorry im in alg 2 rn

raw shard
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other than that i really don’t know, i just know it’s really important

frank nacelle
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oh ok

raw shard
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do you know e^(pi*i)?

frank nacelle
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no clue man

raw shard
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never mind then

late parcel
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Thank you so much

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Really appreciate the help

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That was AP environmental by the way

frank nacelle
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no problem

late parcel
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But it uses a lot of math

frank nacelle
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oh should i take it?

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im in 9th grade

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should i take it next year?

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is it ez and useful if im not gonna go into science major?

late parcel
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I’m a senior. From what I have heard it is one of the easiest APs but for me it’s hard

frank nacelle
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oh

late parcel
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I love science so it’s intersecting to me but it’s all on the teacher when it comes to difficulty

dense lotus
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how would i solve this

late parcel
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My teacher spend 9 years at Virginia Tech and has like 2 masters and a bachelors degree so it is an intense class at my school

rapid nova
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e^(pi i) is just its special case

raw shard
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that’s the one everyone knows

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if they don’t know e^(ix) they don’t know e^(pi*i)

bleak ridge
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,rotate

ocean sealBOT
raw shard
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do you know if the angle opposite to 100 degrees is also 100 degrees?

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probably not actually

bleak ridge
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Ye itd only be that if you extended the left line down

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Thatd prob be a way of finding it out

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Idk if itd be the best

raw shard
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i have something

dense lotus
raw shard
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now that i think about it i can’t think of anything

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i thought of something but it was incomplete

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so it wouldn’t help

dense lotus
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i dont know where to start in the problem

raw shard
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neither do i

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everything i’m thinking of is 1 step short

bleak ridge
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I mean

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Just start writing formulas

raw shard
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i did

devout summit
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(5x+y)+(5x-y)=180 - 100

bleak ridge
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100 + 2x + y + 5x + y = 180

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Ye

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Then you can uhh

raw shard
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not sure how you got that

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you mean 5x+y+2x+y

bleak ridge
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Since the angles add up to 180 in the triangle

dense lotus
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7x + 2y = 80 tight

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right

bleak ridge
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I think focusing on the bottom left corner

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Would be a very good idea

raw shard
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it’s not a rectangle

devout summit
raw shard
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i don’t know how you got that

short night
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need help

raw shard
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occupied

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i can’t think of any way those things are connected in this situation

dense lotus
rapid nova
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do right arrows mean they are parallel?

dense lotus
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yes

devout summit
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Sum of co-interior angles is 180°

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(100)+(5x+y+5x-y)=180

raw shard
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i guess i forgot what that meant

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because apparently that makes sense

dense lotus
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Can you highlight the co interior angle lines for representation?

devout summit
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The red ones

dense lotus
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Got it

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How would you solve for Y in this situation?

devout summit
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5x-y=2x+y

dense lotus
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100 = 7x + 2y, where 7x would be 56?

cedar slate
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?

devout summit
dense lotus
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That’d be in the top right, right?

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And how would i get the value of Y from the equation 5x-y=2x+y

snow nest
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5x - y = 2x + y
5x - 2y = 2x
-2y = -3x
2y = 3x
y = 3x/2

dense lotus
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Thank you

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Got it

wise stump
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Isn't sin3pi/4 = sqrt2/2

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but cos3pi/4 = -sqrt2/2?

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doesn't that mean they're not equal at x = 3pi/4

limber urchin
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Yeap 3pi/4 is not an answe

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7pi/4 as well

white blaze
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is there a function that i can use to produce a landscape similar to this but with more bumps to it? rn im using the following:
sin(x) * (abs(square(x ** 2 + y ** 2)))) / sin(x)

bleak ridge
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You could use that as a base function and use perlin noise or smthn to add that randomness

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Idk if thats applicable to your problem but

white blaze
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ah thats such a good idea

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thank you :) my mind is so beat rn i really appreciate it!

bleak ridge
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Np

paper saddle
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does anyone know how to solve for p, focus, and directrix for this parabola equation?

sweet dove
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Need some help :/

paper saddle
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but u shouldnt have skipped me

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cause no one helped me yet

glass wren
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can anyone tell me why i cant do ths

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apparently its because the individual limits does not exist but i dont understand why ;-;

craggy niche
charred flint
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@glass wren it's fine to think it works like that

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it's just that you shouldn't have an equals sign for something that's not a number that exists

glass wren
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oh i see

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thanks for the insight

formal bane
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do u guys know any app good for math? like photomath

quiet finch
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It's not as convenient as simply taking pictures of problems but it can do more

formal bane
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ok ty i will try, i have calculus assignment 😭

gloomy hazel
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can someone help me to do this

"the given limit represents the derivative of a function y=f(x) at x=a. Find f(x) and a."

solar jetty
#

hi
can someone suggest some projects to be done with newton raphson method
a unique one infact
where you explain the project objective
methodology
problem statement
and algorithm

scarlet heart
inner sequoia
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why is it like this

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i thought distributive property made (a+b)^2 = a^2 + b^2???

loud cedar
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think about it

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(a+b)^2=

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(a+b)(a+b)

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which means

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there are:

a times a
a times b
b times a
b times b

lapis valley
loud cedar
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a times a and b times b can be expressed as a^2 and b^2

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then there are two abs so 2ab

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@inner sequoia

lapis valley
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You let $u = t^3+4$ so $du = 3t^2 \ dt \rightarrow dt= \frac{du}{3t^2}$ and then if u substitute dt it just becomes the 2nd line.

inner sequoia
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thanks

ocean sealBOT
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hduxueiwkwnxudi

scarlet heart
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never mind i figured it out

lapis valley
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nice

wheat prawn
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for this calculation what am i doing wrong

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i get the wrong answer

sacred orchid
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is dis channel busy or no?

slow wraith
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what postulate is this?

paper saddle
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do you know all the different postulates

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@slow wraith

slow wraith
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We're only studying about SAS, AA, SSS

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this is for an exercise btw

paper saddle
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ok well is there are 2 sets of correlating sides and 1 set of correlating angles

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so if you had to take a guess which postulate would you think it is

slow wraith
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SAS?

paper saddle
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yea

slow wraith
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ohhh i see

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thanks

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i didnt get it at first

paper saddle
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np

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its the same thing with all the other postulates too

slow wraith
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this one is AA right?

paper saddle
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aa is angle angle

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but it isnt giving you any angles

slow wraith
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its SSS then?

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bc theyre both triangles???

paper saddle
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its sss

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but wdym they are both triangles

slow wraith
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yeah i thought so

paper saddle
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all postulates are gonna be only triangles

slow wraith
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no its like SSS bc both of them are congruent triangles right

paper saddle
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the postulates prove if two triangles are congruent

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but congruency isnt supposed to be used as proof of a postulate

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because the main reason for them is to find whether triangles are congruent

slow wraith
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ohhhhh

paper saddle
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so the reason its sss is because there are 3 sides that are congruent

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it only gives you 2 sides but you can find the 3rd side to be congruent because of how the triangles connect

slow wraith
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i see

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thanks a lot

paper saddle
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np

light kestrel
#

Can someone walk me through how to do number 2

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,rotate

ocean sealBOT
light kestrel
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first i take the derative of r right

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i mean isolate the r

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so r = sqrt(15/pi)

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no

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fkkk

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relate rates make my brain hurt

spice path
#

seems like the right track

spice path
#

Awww yeah bruz

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Spesh maths

shadow widget
#

you australia?

spice path
#

Hell yeah

shadow widget
#

awesome lol

spice path
#

I did that last year

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So good luck on your exam

light kestrel
#

Dame

shadow widget
#

if u know how to do the question pls help out

shadow widget
spice path
#

Well I'm also doing calc study atm

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I'll have a lil peak

shadow widget
#

thankss

scarlet agate
#

can i ask a question

spice path
#

bruh, why are they all asking in the one chat

wanton spoke
#

I see. Yeah idk either It's just that I am used to have only 1 equation for a worded problem. May I ask if I can solve the problem using one equation only? Like, formulate a different equation and solve that to find n, the number of students?

ashen blade
#

gonna assume this channel is free since there hasn't been a comment in 10 mins

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https://i.imgur.com/XsEggRW.png
from the 3rd to 4th step
why do they divide x+y by z
as opposed to the entire thing?
it's (x+y)(dx/dt + dy/dt) = z(dz/dt)
so shouldn't z divide the entire thing?
dz/dt = [(x+y)(dx/dt + dy/dt)] / z

solar jetty
#

hey

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can someone suggest applications of newton raphson method

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an equation

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or smthing like that

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like for eg: manning equation

mellow tinsel
#

For a two by two matrix:
If A^3*A^3=I, A^3≠I, and A^2≠I, how do I figure out what A is?

chrome patrol
#

Can anyone tell this

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please can anyone share the written solution for this? will really help, thanks :p

thorn kindle
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No.

pulsar lance
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Differentiate numerators and denominators to find limits and then equate both of those limits to find p

ashen blade
#

sorry, does anybody have an idea about this?

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https://i.imgur.com/XsEggRW.png
from the 3rd to 4th step
why do they divide x+y by z
as opposed to the entire thing?
it's (x+y)(dx/dt + dy/dt) = z(dz/dt)
so shouldn't z divide the entire thing?
dz/dt = [(x+y)(dx/dt + dy/dt)] / z

chrome patrol
ashen blade
#

bro go solve it yourself
people here aren't going to do your homework for you

chrome patrol
#

ok rude but its okay understood

ashen blade
#

im literally stating facts

chrome patrol
#

ok

ashen blade
#

at least make an attempt at the problem before asking

chrome patrol
#

ok

alpine sable
#

How do i write an equation using the point-slope form?

alpine sable
#

Thanks

lapis goblet
#

how do i find the surface(s) of intersection of 2 ellipsoids

jaunty crane
#

There English below and answer at the side

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Pls help

lapis goblet
#

<@&286206848099549185>

lapis goblet
#

what about the volume

plush wagon
#

please help me understand the given solution of problem

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i am confused

pulsar yarrow
rich basin
#

for (d), why can you simply just find the derivative and then you can calculate for when it equals 0 you can find the time for which it will be empty

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like if you have something like v = u +at, how can you differentiate in respects to t, and get "a" to find when v = 0?

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you can't because a is a constant, but why in (d), you can calculate t, and find the equation equalling to 0

jaunty crane
opaque totem
#

can anyone help me

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with this

gray reef
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Can't sorry

opaque totem
#

issfine

raw nexus
#

Hello this channel free?

opaque totem
#

yeaa kinda

opaque totem
raw nexus
#

I've worked out, the total weight of the empty ferry to be correct 30.4367 MN

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I'm just stuck on this question below?

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The answer is 3505 m^3 but not sure how to get this answer

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The distance D is 0.4m

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Please can someone help me?

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<@&286206848099549185>

light oyster
#

If i choose x and y from the interval [a,b], its obviously (x,y) always in [a,b], but how can i denote it?
its $(x,y)\subseteq[a,b]$ or $(x,y)\in[a,b]$?

ocean sealBOT
#

小馬

light oyster
#

For a function f defined on the interval [a,b], for some c$\in$[a,b], is it always true that f(c)$\in$[f(a),f(b)]?

ocean sealBOT
#

小馬

light oyster
#

OK

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solved my problem lol

alpine sable
#

Given the expression $\sqrt{ T^2 + 4T\sin\alpha + 4w^2 }$, with everything but $w$ being positive real numbers, how do I get it to the form $Cw$ where $C$ is a real number?

ocean sealBOT
#

leadersheir

alpine sable
#

<@&286206848099549185>

#

pls help me i have no idea to do question :Want to write three types of mark on a stick that is not one long, which is a line that divides the stick into 10 equal parts. A mark that divides the wood into 15 equal parts. and the line that divides the wood into 18 equal parts When cutting the sticks as written here How many sticks will you get in all?

alpine sable
ocean sealBOT
#

bertaunth

alpine sable
#

since everything other than $w$ is a positive real number (a constant)

ocean sealBOT
#

bertaunth

keen basalt
#

Can anyone help me solve this problem?? Thanks in advance 💗

wary iron
#
pulsar yarrow
keen basalt
pulsar yarrow
#

d/dx (cos(2x)) = -sin(2x) * 2 using chain rule

keen basalt
pulsar yarrow
#

But this doesn't work because you're enlarging the domain of the function

alpine sable
#

can i ask a question about a direct investigation i currently have, its on 'loopy polygons' and the main part is finding a formula that links the number of shapes and the perimeter so you can estimate the perimeter by only having the shape

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and the the formula section is what i am struggling on the most, please dm me if you feel like you can help 🙂

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thank you in advance

pulsar yarrow
#

just a suggestion

alpine sable
#

so that is part a of the direct investigation, i have created the six shapes asked and found the inner/outer perimeter

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this is the graph plus a few patterns+notes i've noticed, but i'm really struggling to find a pattern linking the number of squares in the loop, to the inner/outer perimeter

rapid nova
alpine sable
rapid nova
#

i understand but for a start answer my question

alpine sable
rapid nova
#

also try considering different shapes of loops with the same amount of squares

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you will see their perimeters match

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that's because you can always rearrange squares in such a way that it becomes rectangular, and on each step the perimeters do not change

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(if you move square by square)

alpine sable
# rapid nova that's because you can always rearrange squares in such a way that it becomes re...

yeah but for some reason i can't think to find a pattern that links the number of squares to the perimeter. like i'm not sure how i'm supposed to know the perimeter with just the number of squares. i'm listening to your advice and i understand rearranging the shape to a rectangular way to keep the same perimeter but to me changing the shape of the shape, i'm not show how that would help me

rapid nova
#

if you know how to calculate perimeters for a rectangular loop, then you also know how to calculate it for every loop with the same number of squares

rapid nova
harsh belfry
#

I wasnt too sure on how they got to this step.

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Did they just divide by 10?

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then toss over the dh/dt?

light oyster
#

yeah

alpine sable
harsh belfry
#

Alright, then I'm not sure why its not working with my numbers

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I was given

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Which gave me

light oyster
#

$10 = 324\pi\frac{dh}{dt}$

harsh belfry
#

Sure

ocean sealBOT
#

小馬

light oyster
#

$1 = 32.4\pi\frac{dh}{dt}$

alpine sable
#

Do I ask questions here? Like I'm extremely new to the group

ocean sealBOT
#

小馬

light oyster
#

yeah

alpine sable
harsh belfry
#

My ROC is 8 (Theirs is 10)

light oyster
#

$\implies dt = 32.4\pi dh$

ocean sealBOT
#

小馬

harsh belfry
#

They have 324pi I have 9pi

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So my equation is

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I would just divide by 8

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right?

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For some reason I keep getting marked wrong

alpine sable
light oyster
#

multiply by 3.14

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or is the problem of unit?

harsh belfry
#

this is my last attempt on trying to get the correct answer 😅

light oyster
#

like ms^-1

harsh belfry
#

Perhaps I could post the original question.

#

Maybe I got a step wrong?

#

I'll outline my process

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is the formula for volume

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my r, as stated in the question is 3 times my height

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therefore r:

light oyster
#

calculate dV/dt first

harsh belfry
#

I don't think thats the move here

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maybe

vapid oak
#

that is the move yes, becuase you need to find dr/dt

harsh belfry
#

Only once i insert r I can find my derivative right?

light oyster
#

yeah

harsh belfry
#

So now I think i find the deriv

#

Am I incorrect?

harsh belfry
# harsh belfry

Because v=1/3pir^2h would give a very different derivative than

harsh belfry
harsh belfry
#

Not sure if I did that part correctly

light oyster
#

then it becomes finding dh/dt

#

since you replaced r

alpine sable
#

Do we ask calculus related questions here?

light oyster
#

yes

harsh belfry
#

Channel in use

harsh belfry
#

Im a little bit confused.

alpine sable
#

Oh as I said I'm extremely new so sorry

light oyster
#

$\frac{dV}{dt} = \frac{d}{dt} \frac{1}{3}\pi(\frac{3h}{2})^22h$

ocean sealBOT
#

小馬

light oyster
#

yeah

#

thats right

harsh belfry
#

After that point I then just plugged in 2 for r

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and got 9pi

vapid oak
#

you cannot just do that

light oyster
#

but the question told you to calculate the rate of change

harsh belfry
#

then theres the mistake I guess

#

what should I do

vapid oak
#

yes, but you just plugged something into the idea of rate of change for Volume to try and work out height

harsh belfry
#

I was just following this if it helps make sense

harsh belfry
#

I'm very new to ROC calculus questions

vapid oak
#

i dont have much paper with me but ill try my best to explain

#

yeah they are very hard so no worries

#

basically you want to differentiate the Volume function

#

so you want to differentiate V= 1/3 * pi * (3h/2)^2 * h

harsh belfry
#

OH

#

Sorry I skipped a step

#

I actually meant i plugged in r into this equations

#

second

#

writing it

light oyster
#

I thought its my mistake lol

harsh belfry
#

Nah nah, I had forgotten to mention that I found the derivative already

vapid oak
#

well what did you get for the derivative

harsh belfry
vapid oak
#

you're forgetting quite a few variables there

harsh belfry
#

huh

vapid oak
#

expanding the brackets first, the expression is $\frac{\pi \cdot 9h^3}{12}$

ocean sealBOT
#

Omfish

vapid oak
# harsh belfry

do you undertstand where I got that from just from simplifying this expression

harsh belfry
#

I dont...

vapid oak
# harsh belfry

so we have 1/3 and pi, and then the (3h/2)^2 becomes 9h^2/4 and theres an extra h

#

so Ive combined it all

#

$\frac{1}{3} \cdot \pi \cdot \frac{9h^2}{4} \cdot h$

ocean sealBOT
#

Omfish

harsh belfry
#

yeah I did that part

#

I just simplified it

#

I think this guy did the same thing as me

vapid oak
harsh belfry
#

Is this explanation wrong?

vapid oak
#

ok thats perfect then if you understand that

#

no the explanation is correct

harsh belfry
#

Whats wrong with mine?

warm brook
ocean sealBOT
harsh belfry
#

ah I see

#

ok

vapid oak
#

and then you equate it to 8, to find dh/dt

harsh belfry
#

Would that be correct?

#

Also thanks @warm brook

warm brook
#

Yes, I think so

harsh belfry
#

This is where I get stuck.

#

I have no Idea what to do next

vapid oak
#

you want to find dh/dt

#

does knowing that help?

harsh belfry
#

I don't think so

#

could I perhaps do this

vapid oak
#

wait

vapid oak
harsh belfry
#

oh really?

#

ok

vapid oak
#

that is looking good

#

and remember, you know that equals 8

#

so, still using r as a variable, try and find out what dh/dt is

harsh belfry
#

once I simplify this it should work out

vapid oak
#

well im not sure why you've decided to use b as dh/dt but yes

harsh belfry
#

ah because Its easier to type

#

😂

vapid oak
#

that is your formula for the rate of change of the height

#

and so now you may plug in your value of r

harsh belfry
#

8/9pi

#

I think thats it isnt it

warm brook
#

Yes

harsh belfry
#

I'll go check if its right

warm brook
harsh belfry
#

oh that would have been easier

#

haha

#

i havent slept in over 24 hours so I'm a bit out of it

#

will write that in my notes

#

Thanks.

warm brook
#

Yeah I presumed you knew that you were trying to solve for dh/dt

#

yeah ofc

harsh belfry
#

Thanks a bunch you guys

vapid oak
#

hope you learnt something or that this helped you figure somethings out 🙂

harsh belfry
#

Knowing the steps certainly helps

#

haha

raw nexus
#

This channel free?

harsh belfry
#

Yes'

grave saddle
#

Im to assume my end dates are october 2021.
How would I calculate how many months there are to this date from any date (month and year)

#

so like if I have march 2020, ill get 19

raw nexus
#

I have worked out the up thrust acting on the spar bouy to be 6.5749MN

#

It's asking "what is the tension"

#

Which I'm not sure how to work out?

alpine sable
#

can someone help me with this guy? I've currently done it like this so far but I don't really know how to continue or if I'm even on the right track. Thanks in advance!

alpine sable
#

Any ideas on how to solve

#

thanks, you can tag me

alpine sable
#

Solve in this order.

#

Exponent means square, squareroot stuff.

cyan willow
#

Guys are these two thingy true

#

Or is one of them wrong

alpine sable
#

I guess it is.

#

I mean both correct.

alpine sable
harsh belfry
#

No idea what occurred in this step

plain halo
harsh belfry
#

In this problem I am given the speed of 600

#

I am solving for the rate in radians that the elevation

#

My angle is 45 deg

#

I keep getting the answer incorrect

visual bolt
#

ok

harsh belfry
#

I think I would be using tangent at 45 degrees 5/x

#

Would I start by finding the derivative?

visual bolt
#

yes yes do that for tan 60 and 70

harsh belfry
#

ah so the derivative without the angle

#

then i input 45?

visual bolt
#

wait I am doing sth in that question

#

just a sec

thorn wasp
#

If I have to "vertically shrink [a function] by a factor of 2", I multiply the original function with 1/2 right?

#

the function in hand is, sqrt(x). so shrinking by a factor of 2 will make y = 1/2sqrt(x). right?

#

or is it the opposite?

harsh belfry
#

😅

visual bolt
spare vale
#

I mayve labelled wrong

tender anchor
#

Are vectors in the domain of multivariable functions? E.g If we have a multivariable function f(x,y) defined everywhere, can we write f(<1,1>) = f(1,1)? I would assume not but I'm just checking

oak chasm
#

@tender anchor If the vector is in the domain, yes. For example, if the function is ℝ² → ℝ, then you can use any vector in ℝ² as input.

tender anchor
#

oh cool. Thanks for helping!

oak chasm
#

No problem.

glacial hawk
#

can someone help me with this?

#

i literally cant get the answer for this

tender anchor
#

PU = -UP

#

so it becomes EU + UP - EP

#

which is EP - EP

glacial hawk
#

ohhhhh

#

so its -UP?

oak chasm
#

You can also see it this way: EU - (EP + PU).

#

EU - EU.

glacial hawk
#

wait so EU-EP-PU=-UP?

visual bolt
#

0?

oak chasm
#

Nope.

glacial hawk
#

oh wait its 0

#

cause it cancels

tender anchor
#

yep

glacial hawk
#

thank you so much

spare vale
glacial hawk
#

this statement would be true right?

spare vale
#

Ignore the jaffas 😤😤😤

glacial hawk
grim pelican
#

need help

#

for part a I went ahead and computed for the standard equation of the sphere

#

idk if thats what they want tho

grim pelican
#

i did the first part idk the 2nd part

lapis valley
waxen cypress
#

Hi! Just wanna ask how I can antidifferentiate this equation. The it’s dydx for the sequence of integrating but i’m not sure how I can integrate this trig with polynomial inside

rigid kiln
#

my gut says integration by substitution but I'm not sure

novel kettle
#

Plss help me 💀

#

How do I do that

rigid kiln
#

you can find this angle

novel kettle
#

Ok but it should be 360° right

rigid kiln
#

the interior angles of that shape will sum to 360 yeah

novel kettle
#

Ohhh so the out side one doesn't matter? Then do I find a° or the other one that you did

rigid kiln
#

the other one will help you find a

#

here's a hint

novel kettle
#

Oh ok thank you

rigid kiln
#

no prob, hope that makes sense

novel kettle
#

So that will be 60° so now I do 180°-125°=a° which will be 55°

tulip swallow
#

what is pronumeral

novel kettle
#

I don't even know kekw

unkempt umbra
#

Quick question:
if the sum of 4 vectors is the 0 vector, does it mean that they form a parallelogram? or does it just mean that they form any regular quadrilateral ?

tulip swallow
#

if u move in 4 straight lines and end up back where u started

#

what would that be (yes a quadrilateral)

#

but if the vectors are not connected end to end like that, they don't form anything

#

take (1,1),(1,-1),(-1,-1),(-1,1) vectors going away from origin. they don't form anything

stark plover
#

By what does the function y = 4^x need to be stretched to "end up" with 7^x? Express your answer in the form log(a)b.

tawny fable
#

Hi

#

Can a linear equation with more variables than equations have one unique solution?

raw shard
#

@stark plover start with 4^(n*x) = 7^x

#

take ln of both sides

#

if you know logarithms well and you look at it for a second, it’s obvious what n should be

stark plover
#

@raw shard isn’t this the starting equation though?

raw shard
#

if a and b are constants i don’t think it’s possible for those two to always be equal

#

actually it’s definitely not possible

#

7^x grows much faster

stark plover
#

So the best we'd be able to do is define a and b in terms of x and b/a?

raw shard
#

define a or b in terms of x

#

if it need to be in that format, pick a few x values, maybe 1 2 and 3 and try stuff

#

i still don’t think this will work

#

can’t think of a reason why it would, even if it’s defined in terms of x

arctic gust
#

then both eqs would be the same

raw shard
#

they need it in terms of a log

arctic gust
#

oh

raw shard
#

technically something stupid like log2(2^((7/4)^x)) will work

#

but i hate this

#

that’s a test

rose plaza
#

and whats the problem?

dull ocean
#

how do i work with n

raw shard
#

@rose plaza you aren’t allowed to ask for help on tests

raw shard
#

there’s a timer in the top right, and stuff is blacked out

#

there’s a time limit on a study guide

dull ocean
#

bruh

rose plaza
#

he tried

#

._.

raw shard
#

lol

#

better than some other people

#

some people post the whole uncropped thing

rose plaza
#

:DDD

raw shard
#

sometimes you can literally see people post stuff that obviously says test

#

no

rose plaza
#

no dude

raw shard
#

as soon as i saw that you blacked stuff out i was suspicious

#

still doesn’t explain why there’s a time limit on a study guide

#

and i know that’s a time limit and not a timer

#

there’s a progress bar under it

#

well, beside it

fading zephyr
#

is this a graded evaluation

raw shard
#

they literally said it was a study guide, but you can see a time limit

#

doesn’t check out

tall wing
#

band

fading zephyr
#

someone else confirmed it's an exam, so banned

eager pebble
#

lmaooo

#

hey guys can u help with question pls

raw shard
#

yeah

#

i can try to help

eager pebble
#

I tried looking up the formula for linear approximation and it's f(a)+f'(a)(x-a)
but idk what to do with that

raw shard
#

yes that’s it

#

you pick a value close to x

#

basically pick a value a that is close to x, that you know the value of f(a)

eager pebble
#

But you have to x's here right? 6.05 and 6

#

so something in between?

raw shard
#

yeah x would be 6.05 and 6

#

so something close to there that you know the value of 1/a

#

do you know what 1/6 is?

eager pebble
#

yeah

raw shard
#

so you can probably just skip that part

#

and just do 6.05

#

so use 6 as a

eager pebble
#

so what would x be? 6.05?

raw shard
#

yes

eager pebble
#

hmm ok

#

@raw shard I plugged that in and got 0.16528 but it says its wrong

#

then it gave me this as a hint

raw shard
#

you didn’t subtract 1/6

#

i guess that works too

eager pebble
#

hmm let me try again

raw shard
#

@verbal marsh what’s after that 2 on the end?

raw shard
#

had a feeling it was

#

ok

rose plaza
raw shard
#

so they took out a (1-x^2)^(-7/3)

rose plaza
#

if u factor it out you have to adjust the terms in the inside of the bracket

raw shard
#

multiply the coefficient by (1-x^2)^(-7/3) and the stuff after the coefficient by (1-x^2)^(7/3)

verbal marsh
raw shard
#

the number in the front

#

the 2/3

#

i knew i shouldn’t have said coefficient lol

#

probably to get ride of the negative exponents in the parentheses

#

i guess whatever to get rid of the negative exponents

verbal marsh
#

For better context

raw shard
#

i was about to say you can simplify it a bit more lol

verbal marsh
#

Is this for formality? Because can’t you tell the expression is > 0 at x = 0 from the first line of the second derivative?

#

Oh wait

#

There’s a dividing by zero moment

raw shard
#

oof

#

no way to prevent that

#

also idk i don’t remember much about second derivatives

verbal marsh
#

It’s cool, my question has been answered

fresh quail
#

can someone guide me through this double integral problem

lapis goblet
#

sinx/x doesn’t have an elementary solution I though

#

Integral of sinc x is like Si(x)

fresh quail
#

it does if u change

#

the order of integration

#

it would give an elementary solution

#

just trying to figure out

lapis goblet
#

If x =2, x = sqrt(y)

#

Then you have to solve for y

#

Same for y = 4, y=0

#

I’d recommend graphing it

#

Easier to visualize

fresh quail
#

ok

#

so y = x^2

lapis goblet
#

Yeah so graph the function along with the boundaries

#

Then find which lines are used when going vertically

alpine sable
#

Is that right so far and need help filling rest out

#

I don’t understand the rest of it

lapis goblet
#

yeah

#

looks right so far

#

the other 2 boxes for the sqrt is asking what happens when a is bigger than 1

#

lets say

#

y = 3sqrtx

#

try graphing it on desmos seeing what happens

#

then try y = -3sqrtx

#

and finally when a is between -1 and 1, which would be a fraction or 0. y = .5sqrtx , y = -.5sqrtx

#

i think you should be able to draw some conclusions from these graphs

alpine sable
#

Ok I’ll give it a go. Thanks @lapis goblet

lapis goblet
#

np

glacial cave
#

TRADING TW ION FOR FENNEC

#

oh worng server

#

my bad

brave remnant
#

Hello

#

Can someone explain to me

#

What value (I should) use to represent a value approaching negative infinity

jagged trout
#

big negative numbers

brave remnant
#

What should the constraints be

arctic gust
#

whats the whole q

brave remnant
arctic gust
#

the entire question?

brave remnant
#

Not important…

arctic gust
#

oh

#

so its just the most negative negative numbers

brave remnant
#

Which are

arctic gust
#

like -10000000

brave remnant
#

Anything it should be > or < ?

#

What should the constraints be

arctic gust
#

tbh thats not how you solve limits

brave remnant
#

Probably not

arctic gust
#

i think you use a few rules

brave remnant
#

Yes I know

#

You can use a rule for this

#

However

#

It should be possible without of course

lapis goblet
#

just keep plugging in large negative numbers and see what happens if you dod

jagged trout
arctic gust
#

even if you approx using this method you still wont get the answer unless you simplify/factorize

brave remnant
#

That’s true

#

But usually you only want the approx value

#

On tests etc

lapis goblet
#

just plug in larger and larger negative numbers

#

like -10, -100, -1000

brave remnant
#

Great

lapis goblet
#

see what happensa nd see if it converges at 0 or diverges to infintiy/ negative infinty what have you

arctic gust
#

lol its easier to factorize than squaring/adding/subtracting those huge negative values

brave remnant
#

Well I would probably do both

lapis goblet
#

i mean for lim -> inf , of 1/x

#

you can't simplify further

brave remnant
#

^

lapis goblet
#

just plug in and see what happens

#

in this case itll just get closer to 0

#

so lim at inf is 0

arctic gust
#

anyway if you get 1/x anywhere, if it approaches negative infinity it becomes 0

lapis goblet
#

yes

arctic gust
#

but thats only if you are lucky

lapis goblet
#

basically if the x is in the denominator then it'll prob appraoch 0

arctic gust
#

if you get x in the numerator theres a very low chance you'll get it right

brave remnant
#

!thank @arctic gust @lapis goblet @jagged trout

arctic gust
#

yw

cinder sorrel
#

what about this

arctic gust
#

lol

#

its a nice trick to use on your friends tbh

cinder sorrel
#

yeah

#

is it true that sq rt i = 1

#

??

raw shard
#

i think the problem is that on one side they did i^5 first and on the other they did sqrti first

#

actually that’s definitely the problem

cinder sorrel
#

i thought it doesnt affect

arctic gust
#

the trick is in the 5th step RHS

cinder sorrel
#

(whats rhs )

arctic gust
#

right side

#

it should be plus minus 1 not just -1

raw shard
#

stuff like this confuses me

cinder sorrel
#

it should be -1 ^4

#

not ^2

cinder sorrel
arctic gust
#

yeah

lapis goblet
#

they didn't put +- sqrti for step 6

arctic gust
#

i^4 ig

cinder sorrel
arctic gust
raw shard
#

@lapis goblet i^2 is -1

lapis goblet
#

no im saying because the sqrt

arctic gust
#

same on the right side

#

it should be minus or plus

cinder sorrel
lapis goblet
#

technically you do

cinder sorrel
#

its just more explanatory

#

well not exactly

#

you are demanded to give one right equation

#

not all the correct ones

raw shard
#

i don’t get this so i’m just gonna say something is obviously wrong lol

cinder sorrel
#

if i say sqrt9 is 3 im not wrong

lapis goblet
#

it's a set of 2 solutions

#

-1 = -1, 1= 1

#

this is what happens when you take sqrts

#

ppl usually omit the negative because they have no use for it

cinder sorrel
#

but its not wrong if we disregard either of them

lapis goblet
#

or the asnewr is only defined when y>= 0

arctic gust
#

you have to check if the square root gives a positive or negative value

#

if positive, both should be

cinder sorrel
#

when we say a = b, we dont necessarily mean that a equals nothing but b

raw shard
#

step 3 is definitely the problem

cinder sorrel
raw shard
#

(sqrt(i))^5 = -sqrt(i), sqrt(i^5) = sqrt(i)

#

actually i guess step 2 and 3 are the problems

#

because step 2 implies step 3

lapis goblet
#

even then

#

they dind't put +- in front of sqr

alpine sable
#

Guys, emergency : I need to use Math to figure out who roped me into this.

mild yacht
#

hey, can someone figure out what n equals to? totally lost herw

glass lichen
#

and what have you tried?

mild yacht
mild yacht
#

but i always get lost

glass lichen
#

$(n+2)!=(n+2)(n+1)!$

ocean sealBOT
mild yacht
#

yesh

#

that i know

#

these are the options btw

glass lichen
#

Yeah... so apply what I gave you

#

then it's simple algebra

thorn wasp
mild yacht
#

nvm got it

#

<3 ty

raw shard
#

@thorn wasp possibly do both sides do the power of 10

#

so you have 10^ln(x+1) / x = 10000

#

and maybe rewrite 10 as e^ln(10)

#

actually that doesn’t really help

#

are you three aware that only one person can use a channel at a time

elfin wasp
#

sorry, didn't see.

vernal fog
#

$\sum_{x=1}^{\infty} \frac{1}{x}$

im not sure if this results in 2 or infinity, and im not sure how to look for it online
i am stuck with the little math i learned at school and im trying to learn some things rn
how would i put this equation to words?

#

$\sum_{x=1}^{\infty} \frac{1}{x}$

ocean sealBOT
#

Java³

glass lichen
#

the harmonic series diverges

vernal fog
#

actually i meant

$\sum_{x=1}^{\infty} \frac{1}{x²}$

ocean sealBOT
#

Java³

glass lichen
#

converges to pi^2/6

vernal fog
#

in find infinity confusing

#

thanks

glass lichen
vernal fog
#

thx

limpid flower
#

Hi, is there a simple explanation why any algebraic number has a multiplicative inverse that is also an algebraic number?
I googled it and found only explanations that uses properties of rings, which is a concept I'm not familiar with, and I once saw a very simple proof that didn't include any ring related stuff.

lucid imp
#

I just need help with this 1 question and I should be able to do the rest myself

#

I just completly forgot how to figure this out

warm brook
#

@lucid imp
Go down from the top, what’s the limit as x->1 from the left and from the right?

#

If they’re the same, then the limit exists

lucid imp
#

or is it not 2 since its a open circel

#

circle

warm brook
#

Holes don't matter for limits, you just look at the value it approaches

warm brook
lucid imp
#

oh

#

okay

#

Preciate it

lucid imp
#

what do i do after

warm brook
alpine sable
#

Think about it for 0.5 seconds. 😬

lucid imp
#

since the numbers are not the same is it DNE

warm brook
#

Yes

warm brook
lucid imp
#

okay thanks

alpine sable
#

grumble grumble

warm brook
# lucid imp okay thanks

In general if
[\lim_{x\to c+} f(x) = \lim_{x\to c-} f(x)]
then $\lim_{x\to c} f(x)$ exists and is the result above.

ocean sealBOT
lucid imp
#

wait if it has a + next to it

#

does it mean

#

it comes from the right

warm brook
#

Yes

lucid imp
#

and - means from the left

#

oka

#

thanks

#

just want to make sure this is correct

warm brook
#

Yes