help-0

[lime salmon]

A line with slope m passes through the origin and is tangent to
y= In (2x). What is the value of m?

I have the slope equals 1/x, and I have Y=1 so 1=ln(2x)

answer is 2/e but i’m not quite sure how to get there

i plugged 1=ln(2x) into mathway and got e/2 but idk how to get there.

[summer igloo]

<@&286206848099549185>

[oak chasm]

@summer igloo Sorry, this channel is busy. Please read the rules and tips for getting help in #❓how-to-get-help.

[summer igloo]

huh

[broken pine]

is this channel still busy?

[oak chasm]

Yes.

[broken pine]

rip

[oak chasm]

@tawny dawn Sorry, this channel is busy.

[tawny dawn]

right-o

[oak chasm]

@lime salmon Use e to the power of both sides.

e¹ = eˡⁿ⁽²ˣ⁾
e = 2x

[lime salmon]

that’s nice

[glass lichen]

what

[lime salmon]

uh

back to natural logs

[young kite]

I just thought it was a cool math thing

Sorry should I repost somewhere else

[glass lichen]

#discussion if you dont have a question..

[lime salmon]

anything i could look up to find a video on how to do that? i feel like i missed that from a few years ago

[oak chasm]

Look up the logarithm rules or laws.

[lime salmon]

awesome thanks

[oak chasm]

e to the ln of something is that something.

[lime salmon]

i see

ok so e to the ln of 98 is 98

i know that because

ln is inverse

[oak chasm]

Right.

It undoes e to the power of something to give you the exponent.

[lime salmon]

but i don’t see where that plugs in here

[oak chasm]

Well, you have ln(2x) = 1.

You can undo the logarithm by using the exponential.

[lime salmon]

OH

yeah now that’s big brain

awesome that makes sense

thanks!

[oak chasm]

You're welcome.

[analog nymph]

wait nvm

[glass lichen]

ok...

[analog nymph]

pretend i asked nth

thx

[glass lichen]

but yes, you were correct, however f(1)=0 so..

[oak chasm]

Yes, numeric equality is transitive, which means if you have a chain where a bunch of things are equal to the next, the first and last are also equal to each other.

[analog nymph]

i realized 0 = infinite f(1), f(1) is still 0

lol

[wanton folio]

f(1)=2f(1) -> f(1)=0

[oak chasm]

f(x) + f(1) = f(x), subtract f(x) from both sides.

[wanton folio]

chai

what level are you, undergrad, grad, highschool?

[oak chasm]

I made it through part of undergraduate.

[wanton folio]

what year?

[oak chasm]

Junior.

[tight locust]

what is your major/concentration

[wanton folio]

for a european

[summer igloo]

can i send question here?

[wanton folio]

that's 1 or 2?

[oak chasm]

Oh, third out of four.

[wanton folio]

ah lol

[oak chasm]

Freshman, sophomore, junior, senior is how it goes.

[summer igloo]

@oak chasm

[oak chasm]

@summer igloo Yes, I believe it's empty.

[wanton folio]

why did you didnt go to senior?

[oak chasm]

I had personal issues to attend to.

@summer igloo There aren't many prime numbers under 6, so try them out.

[wanton folio]

Ok

wait a minute

did they seriously write: If a is a positive prime number??

[oak chasm]

Yes, because the negative integers can also be prime, since they too can have only two positive divisors.

[wanton folio]

what about -1?

1,-1, and itself

[oak chasm]

Those have one positive divisor rather than two.

There are two ways to consider prime numbers: we only care about the positive ones or we care about all the numbers with exactly two positive divisors. Usually, you only care about the positive ones.

But there are some times when the negative ones are useful.

[wanton folio]

please give me one source where the definition prime numbers include negative integers

I'm not saying they're not useful - but prime number are by definition positive.

[oak chasm]

Here's an example: https://math.stackexchange.com/a/1649531/396325.

[wanton folio]

Look: There are many other numbers, which can be and are named prime, even non-real ones. In the context, which explicitly has to be clarified, the number can be called prime. Suppose I need a definition for prime for my proof, but I want to include 15. I can define: In the following section, a prime is a number with only two divisors and 15. This is essentially what Hungerford did. If I say a number is prime (and without explicitly defining it before) it is accepted by the entire mathematical community that the set consists of only positive integers.

[crystal narwhal]

https://www.bbc.co.uk/bitesize/guides/zp48msg/revision/7 can somebody please explain the logic behind inputing the answer from the previous iteration into the new one and why do we stop when the decimals are equal

[warm brook]

okay, so
[f(x)=x^3+bx+c]
To find a root of $f(x)$, we need to find $x$ such that $f(x)=0$.
Then we see that
[x^3+bx+c=0\implies x^3=-bx-c]
Now the idea of iteration is to call the term, $bx$, $bx_n$ in order to create the iterative formula
[x_{n+1}=({-bx_n-c})^{1/3}]
now the idea here is to find a fixed point, $x^\star$, of this equation, which means
[x^\star=({-bx^\star-c})^{1/3}]
You stop when the decimals are about equal because you get close to this equilibrium point.

[oak chasm]

@warm brook Use \sqrt[3]{...} for cube root.

[ocean seal]

kirby

[warm brook]

thanks, for now, i’ll leave it like this bc i am on my phone

i have cbrt as a formula on my assignment template so i’ve gotten used to it lmfao

[warm brook]

the logic behind putting the last answer comes from the iterative formula, which is simply [x_{n+1}=f(x_n)] for some function $f$. To get $x_{n+2}$, you do
[x_{n+2}=f(x_{n+1})]
so you plug in the answer from the last iteration

[ocean seal]

kirby

[crystal narwhal]

I still don't understand why it works

The formula

Say you put the ur previouse iteration into the new one, now why is this iteration more accurate why do you put each previous iteration.

I dont understand the logic behind it

[warm brook]

the idea is that you want to find an x such that f(x)=0

the reason it works is that as n goes to infinity x_{n+1}~x_n

[mossy lion]

or maybe i think you mean f(x)=x

[warm brook]

okay i screwed up notation, but I’m meaning in the context there where trying to find a solution to x^3+bx+c=0

[mossy lion]

at least the f(x) in the iterative formula

yeah

[warm brook]

this is equivalent to x=cbrt(-bx-c)

[crystal narwhal]

How does this get me closer to an wiser such that itl equal zero

And the answer to tht to get closer to a solution

Why not any other number why the previous awnser

I know it works i just don't know how

[warm brook]

I’m so lost what’s puzzling you here

[crystal narwhal]

Ita fine maybe it'll come to me when I sleep and think about it when I'm fresh

Thanks anyway for the help :)

[warm brook]

I can give you an analytic reason why it works, but I don’t know if you know calculus

if $x_{n+1}=f(x_n)$ and $f(x_0)$ is somewhat close the root of the polynomial, then $f(x_n)$ has a small change in value, so it’s decreasing and getting closer to $x_{n+1}$ so $x_{n+1}-x_n$ is getting closer and closer to 0

[ocean seal]

kirby

[graceful yoke]

Why is derivative written as d/dx?

[raw shard]

infinitely small change in x over a function of x

wait no

idk how to phrase it

[eternal osprey]

if Io is constant... how would one find uncertainty in cos^2 theta?

[graceful yoke]

Also how do you integrate something when the integral has a value on the top and bottom of it?

[raw shard]

@graceful yoke go to a different channel and ping me since this channel is occupied

#help-3 is open

[eternal osprey]

Theta uncertainty is also +- 1 degree

[tight locust]

It's not d/dx

it's dy/dx

or df(x)/dx

which is often written as d/dx f(x)

this also explains the notation for the second derivative

d/dx(d/dx f(x)) = d^2/dx^2 f(x)

[raw shard]

that notation always kinda confused me, because i would have thought the denominator would be (dx)^2

[tight locust]

does this confuse you even more?

you have to use the quotient rule on dy/dx

[raw shard]

it actually does confuse me more

i don’t get how we would even use the quotient rule there

[tight locust]

$\frac{d}{dx} (\frac{dy}{dx}) = \frac{d/dx(dy) dx - d/dx(dx) dy}{(dx)^2}$

[ocean seal]

EndTimes

[graceful yoke]

dy/dx is how u find the gradient of a straigjt line between 2 points on a graph so is the derivative just the gradient between 2 points of a graph equation?

[tight locust]

i'm not sure i did that right

$\frac{(dy)'dx - (dx)'dy}{(dx)^2}$

[ocean seal]

EndTimes

[tight locust]

$(dy)' = d/dx dy = d^2y/dx$

[ocean seal]

EndTimes

[tight locust]

$(dx)' = d/dx dx = d^2x/dx$

[ocean seal]

EndTimes

[tight locust]

$= \frac{d^2y - dy/dx(d^2x)}{(dx)^2}$

[ocean seal]

EndTimes

[glass lichen]

what

[tight locust]

help

[glass lichen]

stop spamming random symbols... what question?

[tight locust]

scroll up

it came from wikipedia

you have to use the quotient rule to find the real way to write the second derivative

[glass lichen]

what are you defining as the "real way" to write the 2nd derivative...?

you just differentiate twice

[tight locust]

https://en.wikipedia.org/wiki/Second_derivative#Alternative_notation

[raw shard]

they were trying to explain the notation for the second derivative

[tight locust]

oh i see

here's the thing

d^2u = d(du)

du^2 = du*du

i guess that makes sense?

weird way to write it though

you would think that du^2 = d(u^2) but it's actually du^2 = (du)^2

what the fuck

[glass lichen]

yeah... this is why you just, differentiate twice

[raw shard]

i love math but this is kinda stupid

[grizzled seal]

how would i go about this question? its saying that if they had 3 or 5 tickets out of 75000 what is the probability theyd win 3/5 times

like i mainly just need a formula, i have no clue what it would be

[tight locust]

you're missing the point entirely

"d" is an operator applied to a function or variable that means the infinitesimal change in that variable

so when you say dx what you really mean is d(x)

[glass lichen]

Im aware of that

[tight locust]

so then confusion arises when you take the second derivative of y.
what is d/dx (dy/dx)?

[glass lichen]

the derivative of the derivative of y

[tight locust]

but symbollically?

[glass lichen]

.

[tight locust]

symbollically

[glass lichen]

$f''(x)=\lim_{h\to 0}\frac{f'(x+h)-f'(x)}{h}$

[ocean seal]

Mosh

[tight locust]

don't use lagrange here. differential ratios are more useful

[alpine sable]

I'll reply in #help-7｜zen1thxyz lol

[tight locust]

so then:
d(dy/dx)/d(x) = (d(d(y))/(dx * dx)

and the n fold composition of d applied to a function or variable u is $d^nu$

[ocean seal]

EndTimes

[tight locust]

and the nth power of du: $(du)^n = du^n$

[ocean seal]

EndTimes

[glass lichen]

You asked symbolically what a derivative is, first principles is the definition of a derivative

[tight locust]

so then we have d(d(y))/(dx * dx) = d^2y/dx^2

you have to understand what the notation means in order to manipulate it

of course i meant within the notation of leibniz

actually read that section of the wikipedia page lmao. did you?

[nocturne gazelle]

can some1 explain how the 2nd step went to the third

i dont understant how they got that sum from there

[wanton spoke]

To help out a classmate in need, the students of 9-Strontium decided to send a cash aid of $2 000. The students shared the cost equally. At the last minute, 10 students from the SSG chipped in, lowering the contribution per person by $10 for each student. How many students are there in 9-Strontium?

When a ball is thrown straight up into the air, the formula h = vt − 16t^2 gives the height h of the object above the ground after t seconds. Its initial velocity is given as v. After how many seconds will the object hit the ground if it is thrown with a velocity of 128 feet per second?

The local park measures 60 m by 50 m. Part of the park is torn up to install a sidewalk of uniform width about it, reducing the area of the park itself by 321 m^2. How wide is the sidewalk?

In these thre problems, which one do you think is the hardest?

[graceful yoke]

Id say 2

[warm brook]

[\sum_{i=n}\delta^i=\delta^n+\delta^{n+1}+\dots]
What happens in the difference

[ocean seal]

kirby

[warm brook]

Then recall $\delta^{n+a}=\delta^n\delta^a$

[ocean seal]

kirby

[warm brook]

That’s all you really need related to this infinite sums

@nocturne gazelle if you need me to be more precise, just ask where

@stark wing this channel is taken but what do you even mean

[thorn kindle]

There are free graphing calculators available online

Try desmos.

[bleak ridge]

Dæsmos

[raw shard]

just add 1 to both sides then divide both sides by 9

[prisma onyx]

"The number of different subsets that can be formed from the set {a,b,c,d,e,f} is"

would it be 2^6

[raw shard]

if i remember correctly yes

[thorn kindle]

Sum from n=0 to 6 of (6 choose n)

Which yeah i think equals 2^6

[prisma onyx]

alr ty

someone told me it was 32 and i got confused because i was pretty sure it was 2^6

[thorn kindle]

32 is way too small

Unless you by chance only meant the number of subsets of a certain size

[ocean seal]

marc

[raw shard]

bruh

[alpine sable]

There is absolutely no possible way an integer could be multiplied by two and the result be odd.

How would one prove such a basic statement?

[ocean seal]

marc

[stiff pawn]

if the RHS is true in that type of statement, then yes, the statement is true

[alpine sable]

Something like "It will rain today, thus cats meow"?

Now you've got me, that's a nice question.

[warm brook]

If the first is true and the second is false, the entire statement is false [edited to reflect the true result]

[nocturne gazelle]

just aw this sec let me look

why are we subtracitng then

[warm brook]

@zinc cosmos yes, just realized i misspoke

[nocturne gazelle]

transition from 2 to 3, 3 to 4, and 5 to 6 confuse me

[warm brook]

the sum is of a finite set, so you want to only consider the finite part of the infinite sum from 0 to n-1

[alpine sable]

Same here, fam

[warm brook]

@nocturne gazelle i presume delta is small? This falls apart if delta >= 1

that’s what i assumed when explaining it

[alpine sable]

so is this just proving that {0^1, 0^2, 0^3, 0^4, etc} is a regular language?

[bleak ridge]

Thats a lot of points

[oak chasm]

@alpine sable 0ᵏ where k is a multiple of 2 or 3. 1 isn't a multiple of 2 or 3.

[glass lichen]

0 is meant to be theta I think

[oak chasm]

That's for L2 ⋃ L3.

Oh.

Well, θᵏ where k is a multiple of 2 or 3.

[glass lichen]

16 points for 1 isnt a multiple of 2 or 3

[oak chasm]

You can make nice state machines for both languages.

[small pumice]

help?

[alpine sable]

1 * 2 =2

[oak chasm]

Right, so 2 as k is fine.

But 1 as k isn't.

2 is a multiple of 2.

[alpine sable]

oh im so stupid

[oak chasm]

@small pumice Sorry, this channel is busy.

[alpine sable]

but besides the 0^1 part, i just need to prove that shiz

[oak chasm]

Right.

Do you know about remainders?

[small pumice]

should i go to another?

[alpine sable]

ye

[oak chasm]

@small pumice Yes, find one that has a last chat timestamp of more than 30 minutes ago or where they just said they're done with the channel.

@alpine sable OK, so when you divide a number by 2, if you get a remainder of 0, it's even.

When you divide a number by 3, if you get a remainder of 0, it's a multiple of 3.

[alpine sable]

gotcha, makes sense idk why I thought 1 would work lol. Anyways, after that its the set 0, 0, 0, etc?

[oak chasm]

Sorry?

What do you mean by "the set 0, 0, 0, etc"?

[alpine sable]

like 0^2, 0^3, 0^4 after union-ing 0^k for multiples of 2's and 3s

[oak chasm]

No, first we need to see how to handle the multiples.

You've done finite state machines, right?

[alpine sable]

as in just making the state diagrams?

[oak chasm]

Yes.

[alpine sable]

yea

[oak chasm]

OK.

So, how would you make a finite state machine that allows only an even number of 0s?

[alpine sable]

probably like:

((q0)) ---> 0 (q1)
((q0)) 0 <--- (q1)

where q0 is the accept state and initial state

[oak chasm]

OK, good.

How would you make one to only accept a multiple of 3 zeroes?

[alpine sable]

I guess like this

[oak chasm]

Good.

Now, you can also, if you want to, do this.

You can have, for the even machine, have 4 or 6 or 100 states.

And then you connect them in a circle.

And then every other one, you have an accepting state.

Does that make sense how that would allow exactly an even number of zeroes?

[alpine sable]

yea that makes sense

[oak chasm]

Same with the multiples of 3.

You could have 3, 6, 9, 339 or some multiple of 3 states in the machine.

Every third state accepts.

Does that make sense?

[alpine sable]

yea

[oak chasm]

OK.

[alpine sable]

now to combine these two?

[oak chasm]

So, we need a state machine with a certain number of states.

The number of states needs to be a multiple of 2 and a multiple of 3.

What's the least common multiple of 2 and 3, so that we can get the smallest number of states that work for both 2 and 3?

[alpine sable]

6

[oak chasm]

Right, so draw two 6-state machines that are connected in a circle.

In the left one, do even numbers of zeroes.

In the right one, do multiples of 3 numbers of zeroes.

Then, show your machines.

[alpine sable]

sounds good one sec

[oak chasm]

Good. Don't forget to mark the starting state on the right.

[alpine sable]

sadly doesn't let me do more than one on the same file

[oak chasm]

Now, the union of the languages will be the union of their accepting states.

Since everything else is identical about the machines.

So, draw L2 ⋃ L3 as the six-state machine that has L2's (left one) accepting states combined with L3's (right one) accepting states.

L2 ⋃ L3 accepts any strings in L2 or L3, and sure enough, we have all the accepting states for both of them.

What do you get for that state machine?

[alpine sable]

just one extra

[oak chasm]

Good.

Now, L2 ⋂ L3 has the accepting states that are in both of them. None that are in only one of them.

If an accepting state is in L2 ⋂ L3, it has to be in both L2 and L3.

What do you get?

[oak chasm]

Good, so now you have the finite state machines to prove those languages are regular.

[alpine sable]

beast

ty!

[oak chasm]

You're welcome.

[supple laurel]

how do i do

[oak chasm]

@supple laurel Use the Pythagorean theorem first.

[supple laurel]

these are like

quadratic word problems

i gotta use quadratics to solve

[oak chasm]

Right.

And the Pythagorean theorem is quadratic.

a² + b² = c²

All terms are quadratics.

[supple laurel]

oh

ok so

a^2 + b^2 = 26^2

[oak chasm]

OK, what's a + b?

[supple laurel]

= 34

[oak chasm]

OK, and do you know the quadratic formula?

[supple laurel]

yes

[oak chasm]

OK, so we have a² + b² = 26² and a + b = 34.

Let's add those together.

a² + b² + a + b = 26² + 34

Does it make sense how I added the equations together?

[supple laurel]

no

[oak chasm]

OK, let's do it a different way.

a² + b² = 26²

Now we know that's correct.

[supple laurel]

yes

[oak chasm]

And we're allowed to do the same thing to both sides, right?

[supple laurel]

yes

[oak chasm]

So, let's add a + b to both sides:

a² + b² + a + b = 26² + a + b

Does that make sense so far?

[supple laurel]

how are they equal to eachother

[oak chasm]

Because we did the same thing to both sides.

We added a + b to both sides.

a² + b² = 26²
a² + b² + a + b = 26² + a + b

See how I added a + b to both sides?

[supple laurel]

oh

yeah

i see

[oak chasm]

OK, now a + b = 34.

If we have a + b equal to something, we can replace a + b with that, right?

Like if x = 6, I can replace x with 6.

[supple laurel]

yes

[trail hamlet]

can someone know the list of my friends on discord?

[oak chasm]

OK, so:

a² + b² + a + b = 26² + a + b
a² + b² + a + b = 26² + 34

[supple laurel]

ok

[oak chasm]

@trail hamlet Please try in #discussion.

[alpine sable]

Only if you share mutual friends with each other. They can see those specific friends.

[alpine sable]

Sorry

Didnt read in time :/

[oak chasm]

@supple laurel OK, now we can move the terms on the right to the left.

a² + b² + a + b = 26² + 34
a² + b² + a + b - 26² - 34 = 0.

Do you see how I moved the 26² + 34 terms to the other side?

[supple laurel]

yes

[oak chasm]

OK, now 26² + 34 is 710.

So, we have a² + b² + a + b - 710 = 0.

[supple laurel]

ok

[oak chasm]

Now we're going to use the quadratic formula to get a.

So, we need something a² + something a + something = 0, right?

[supple laurel]

yes

[oak chasm]

So, find all the a² terms.

a² + b² + a + b - 710 = 0.

That's the only one, right?

So, we add the coefficients of a² together.

It's just 1.

And we have 1 a² + something a + something = 0.

Does that make sense so far?

Hmm, we need to back up a bit.

a + b = 34, right?

[supple laurel]

uh

yeah

[oak chasm]

OK, so solve that for b.

What do you get?

[faint niche]

c:

[supple laurel]

hold on

im pretty sure im not supposed to do it this way

ill just ask my teacher

sorry

[oak chasm]

Right, you're not.

That's why I said we need to back up a bit.

[ocean seal]

marc

marc

marc

[alpine sable]

hey guys

[tiny minnow]

guys

Can i have question?

my teacher ask this

[oak chasm]

No, it's up to 1 that are coprime.

Usually, that means less than n because n isn't coprime to n.

But 1 is coprime to 1.

It only works for an exponent of 1 or higher.

Zero exponents are ignored.

Since it's a multiplicative function, you need f(n) = f(1 · n) = f(1) · f(n), so f(1) = 1.

So, f(p⁰) = 1.

[tight locust]

[gleaming snow]

Is my answer correct

[split silo]

@gleaming snow f(a+h) is incorrect

(a+b)^2 does not have the decomposition form as (a+b)^3

https://www.symbolab.com/solver/step-by-step/6\left(a%2Bh\right)^{3}?or=input

[alpine sable]

Find the total number of 5-digit numbers that can be formed such that the first and last digits are distinct even digits and the remaining three digits are distinct odd digits.

yeah

and since its 5 digit 0 cant be the first right

isn't it just 5 and not 5!

they have to be distinct right

yeah its 4 and 4

yeah

right

5x4x3 x3!

wait we don't need the 3! right

well there are 5 choices for #1, 4 choices for #2, and 3 choices for #3

i thought i had to permute

the 3 numbers

yeah

tsym

do you know how to do this question too?

alright

okay

yeah

[woeful lion]

is this channel free?

aight

[alpine sable]

i was thinking A had 4 choices, B, C, D, E, had 3 choices, and F had 2 choices, but what if A and E had the same color?

yeah

it coud be a b a b a b

yeah

yeah but can't it also be xyxyxy

ok

yeah

yes but the thing is, e and a can have the same color, so it would make f have 3 colors

[quartz oxide]

Yeh it’s probs more complicated than you thought

[stable vigil]

what is the √16

what is the √16

[alpine sable]

4

find some empty channel next time too

-1 * 4i^2

[alpine sable]

do you know how to solve it?

[quartz oxide]

Thinking xD

[alpine sable]

yeah

yep

i know theres a formula to solve this type of problem

but its like really advanced

[quartz oxide]

Hmm,
Consider the differences between any adjacent pair a,b
They should be 1 or 2 or 3 mod 4 (never 0)
so we just want to find all cases for
a+b+c+d+e+f=0 mod 4

Just an idea

[alpine sable]

yea

https://www.quora.com/Given-a-circle-that-is-divided-into-N-identical-sectors-and-we-have-k-different-colors-to-paint-it-How-many-ways-can-we-paint-it-under-the-condition-that-no-adjacent-pieces-have-the-same-color

im just gonna use the answer lol

[buoyant edge]

don't believe it's possible unless you have some more restrictions

you can solve for how many possible ciphers there are with that one mapping, but you can't solve that specific one (i.e. find the other mappings)

Oh I did not understand your original question then

Well the one mapping should tell you everything you need to know then

What's the mapping

But caesar shifts are uniform no?

[ocean seal]

marc

[covert forge]

hey this is a question i need help with. im in college level stats, people can dm me if they wanna help me

[orchid python]

can you tell me more?

[covert forge]

<@&286206848099549185>

[bleak ridge]

Wotd you try

Inversenorm?

[covert forge]

?

I don’t understand, could you clarify?

[bleak ridge]

What was the method you used to get -0.84

[covert forge]

The little table thing I think

[bleak ridge]

Your teacher gave you like a table of function values?

[covert forge]

No it was a table of a scores and whatnot

Z scores

[bleak ridge]

Z scores and their associated probabilities?

[covert forge]

I think?

[bleak ridge]

So you found 0.2004 on the thing and found the z score for it?

2.005**

[covert forge]

I think? Let me warn you I really don’t know what I’m doing

[bleak ridge]

Hmm

-0.84 is the right value it looks like

Oh is that their answer?

Or is it your answer

[covert forge]

No that’s mine

I tried -0.84 and it said it’s wrong

Maybe the software is wrong?

[bleak ridge]

Yeah maybe

[covert forge]

Cause me, my dad, and you have all gotten this “wrong”

[alpine sable]

There should be a button to report the answers is incorrect

[bleak ridge]

Thats really strange

[alpine sable]

It will alert your teacher for the my math lab thing

[covert forge]

Okay

[alpine sable]

how do i work this out?

the answer is 5.94 m

[bleak ridge]

Do you know the trig formulas

[alpine sable]

yes

to yr 10 extent

[bleak ridge]

So you can figure out the length of AB

[covert forge]

Thanks, I think the software is wrong. I emailed the teacher.

[bleak ridge]

Np

[alpine sable]

ah i got it thanks

i forgot to halve ab

[bleak ridge]

Oh

Np

[jade sky]

Hi, I was wondering, is (1/cos(x/8)) = cos(8/x) ?

[alpine sable]

no since 1/cos is secant

[polar barn]

no

[alpine sable]

cos(8/x) is where the angle is being flipped

[jade sky]

basically, I have sec(theta) = x/8. I want to put this in terms of either cos, sin, or tan

I'm not sure how to

[alpine sable]

$\sec{\theta} = \frac{x}{8} \rightarrow \frac{1}{\cos(\theta)} = \frac{x}{8}$

[ocean seal]

bertaunth

[alpine sable]

and if you flip the 1/cos = x/8 you get

$\frac{1}{\cos(\theta)} = \frac{x}{8} \rightarrow \cos(\theta) = \frac{8}{x}$

[ocean seal]

bertaunth

[jade sky]

ahhhh

thanks!

I was plugging in the x/8 in the theta, instead of having 1/cos(theta) = x/8

[alpine sable]

im stuck on this

not sure how to picture it

[rocky atlas]

Atlanta is a girl?

[bleak ridge]

Atlanta georgia

This is technically west but you get thr point

[alpine sable]

my god i couldnt even comprehend 3 dimensions

[rocky atlas]

3d figure

[bleak ridge]

You could honestly just represent it in 2

[alpine sable]

this helps a lot

[bleak ridge]

Idk why they have to make it confusing

I guess a major component of the question is their distance from eachother

So it couldnt be 2d

[rocky atlas]

The third line from Atlanta to Georgia should be the distance

[bleak ridge]

Yeah lemme add that

[alpine sable]

so do i need to use Pythagoras for that?

[rocky atlas]

If it's 90 degree

[bleak ridge]

And its north to east so it should be

90

[alpine sable]

ah right

great stuff

[analog summit]

If i send too much LaTeX function will it be spamming?

[bleak ridge]

If its purposeless prob

But if its useful and relevant then I cant imagine anyone would care

As long as youre not interrupting

[oak chasm]

@analog summit You can test in #latex-testing, then post your long thing in another channel once it works, then hit the delete source reaction under the generated image.

[orchid python]

how can I solve this please help

[orchid python]

can anybody help???

[fast oak]

hello

any one there

[hollow pelican]

hi guys does anyone know how to solve this question without graphs?

[fiery remnant]

do you know how to get period, frequency, and amplitude?

algebraicly?

[orchid python]

can anybody show me the example of how to solve this??

[weary crag]

i wanted to ask ... in questions like this when we form 3 cases like c>0 c=0 and c<0, the cases with "<" and ">" are always continuous right? we only have to take lhl and rhl and compare in the "=" case only... am i right??

[hollow pelican]

nope

[weary crag]

let c be a point on the real line

[hollow pelican]

is there a specific formula?

[grim delta]

you have to use cofactor expansion
which is trivial in this case if you expand along the second column

[glacial cave]

guys i need help

my english is not the best

but

a cyclist oh his first day rode 30km

[grim delta]

drop this into a matrix and RR then you should be able to figure out what values of a make the columns linearly dependent (i.e. has at least 1 free variable)

[glacial cave]

on his third day his the distance that he drove applies on the first day as 3:2

what does that mean?>

[grim delta]

the ratio is 3 to 2

[glacial cave]

yeah

and?

and the second day ratio is 3:5

how do i solve that?

[grim delta]

so for every 60km rode on the first day there are 90km rode on the third
the distance traveled on the third day should be 90/2 cause youve only got 30km

i think

[fiery remnant]

this should help

[glacial cave]

hmm can u explain it a little bit easier?

[orchid python]

can you be more specific, thank you so much

[muted turret]

Four fair dice D1, D2, D3 and D4, each having six faces numbered 1, 2,3,4,5 and 6, are
rolled simultaneously. The probability that D4 shows a number appearing on one of D1, D2
and D3 is:
a) 91/216
b) 108/216
c) 125/216
d) 127/216

Answer Please 🙏 <@&286206848099549185>

[wet cove]

how do i find

(4,-1)

idk the name of the thing in english

the equasion is y=mx+b

[civic jungle]

I was half expecting cool examples of periodic functions but instead it's just examples of questions

[wet grove]

86x + 172 = 2322 find x. Help please 🙂

[lapis hedge]

Move the terms without the variable

[thick meteor]

what would happen if Pinocchio said "my noes will grow now"

[thorn kindle]

You cannot evaluate the truth of a statement about an event until the event has transpired

[thick meteor]

man you talkin to someone that failed English 2

[thorn kindle]

Therefore it is neither truth nor lie until it actually occurs

And given that Pinocchio's nose only grows when he tells a lie, and his statement at that moment in time is neither truth nor lie, his nose shall not grow

[thick meteor]

it's a paradox

if it wouldn't grow then the statement would be false causing it to be a lie

which in turn would make it grow

[thorn kindle]

But it only becomes a lie after the fact

[thick meteor]

making him say a lie

which would make his noes grow

[thorn kindle]

At that moment in time when he says it he is not telling a lie. In fact, at the exact moment it is stated, you cannot tell whether it is true or false. Can you have a statement about something that's neither true nor false?

Just offering my own take on it

[thick meteor]

unfortunately it's my turn and the conversation is over

[thorn kindle]

[tight locust]

[tight locust]

What is unclear

[wet grove]

i found the answer already haha

[brisk sentinel]

Can someone check over my math before I turn it in, please

[tight locust]

You got three of them wrong

Not telling which ones

[analog summit]

Yeah that's your homework

[raw nexus]

Can i quickly ask do Strain and Elastic Modulus have the same SI base unit (Pa)? and would Mpa and Gpa be derived unit?

[lapis hedge]

Let me ask you, what is strain?

[orchid python]

please help me with that

[raw nexus]

what do you mean? like a description strain is Change in Length /Original Length

[shell ridge]

omg guys

can somebody please tell me the difference between a column graph and a histogram APART from the spaces

[orchid python]

<@&286206848099549185>

[lapis hedge]

Right, which by definition is unitless

[raw nexus]

your supposed wait 15 mins i think before @ the helpers

[shell ridge]

bruh

@everyone

[raw nexus]

so it doesnt have a SI base unit?

or derived unit

[lapis hedge]

it's a ratio, so when you divide... any unit will cancel

oops wrong person

[raw nexus]

im confused if i was to work out strain i have to put my answer in pa

[shell ridge]

<@&286206848099549185>

@

[lapis hedge]

Are you talking about stress?

[raw nexus]

strain

[shell ridge]

3.14159

[raw nexus]

oh yeah sorry stress

strain is dimensionless

so stress has a SI base unit

and derived unit

[lapis hedge]

yes pascal

[shell ridge]

guys what's the difference between a column graph and histogram apart from the spaces?

[raw nexus]

is Elastic modulus pascal too?

and would Mpa and Gpa be dervived unit?

or would Mpa and Gpa be SI unit?

[lapis hedge]

Yes. We are dealing with ratio of stress and strain, right?

[raw nexus]

because im currently making a table

[raw nexus]

does that seem right? sorry to bother you

[lapis hedge]

yes

[raw nexus]

is there anything you see thats wrong?

[plain osprey]

Guys this is the distribution function of newspaper per person. What is the variance in the average expense per person if every newspaper is 5$?

[lapis hedge]

looks good

[raw nexus]

thank you 🙂

[plain osprey]

The average expense would be 7.5 per person i can calculate that but idk how to do the variance

[cunning obsidian]

I think variance is s.d. squared?

[raw nexus]

Is this correct?

[plain osprey]

Whats s.d?

[undone dock]

standard deviation

[oblique bronze]

Hi, i was wondering if someone could help me understand how to calculate the expected value of an absolute value. I have this variable

And i want to calculate E(IXI)

But i am not sure how to do this

[rapid nova]

the function is odd, so since you want the expected value of its absolute value, you just need to find an average value of the function in range [0, 1]
to do this you can calculate the integral from 0 to 1 and divide it by the range size (which is 1 in this case so your answer is just the integral value)

[dull onyx]

how can i find the inverse of this function im axtually so lost

[rapid nova]

square both sides, simplify, then square again

[dull onyx]

oh

hold on

i did that and reached a point i couldn’t do anything

[oblique bronze]

Ok, so i take the integral of t*1/2 * (1 - t - t^3), from 0 to 1.

[rapid nova]

yes

[oblique bronze]

But this gives me the wrong expected value, it gives me 0.183 and it is supposed to be 1/2

[rapid nova]

oh wait

you function is NOT odd

then you need to find an integral separately for [0, 1] and [-1, 0]

[narrow trench]

hello

a doubt

ok

another one going on

lemme ask elsewhere

[dull onyx]

@rapid nova im stuck at the same point again

2-2sqrt(1-x^2) 😰

[rapid nova]

int from 0 to 1 is 0.375
int from -1 to 0 is 0.625
their average is 0.5

btw

[oblique bronze]

Ok, Thanks for the help but i found a way to calculate it. If we integrate the function and multiply it by t/abs(t) we get the right answer

[rapid nova]

since there are no negative values

[oblique bronze]

Oh ok, thats what you meant

[rapid nova]

you can just to int from -1 to 1

and get 1 / 2 right away

[rapid nova]

\begin{gather*}
f(x) = \sqrt{1 + x} - \sqrt{1 - x} \
\qty(f(x))^2 = (1 + x) - 2 \sqrt{1+x}\sqrt{1 - x} + (1 - x) \
\qty(f(x))^2 = 2 - 2 \sqrt{1+x}\sqrt{1 - x} \
\frac{\qty(f(x))^2}{2} - 1 = - \sqrt{1+x}\sqrt{1 - x} \
\frac{\qty(f(x))^4}{4} - \qty(f(x))^2 + 1 = (1 + x)(1 - x)
\end{gather*}

[ocean seal]

rept1d

[dull onyx]

lemme read it slowly

yes i got it but like do i just leave it like that

[rapid nova]

you solve the quadratic equation in terms of x

[dull onyx]

what quadratic

[rapid nova]

[ x^2 + \frac{\qty(f(x))^4}{4} - \qty(f(x))^2 = 0 ]
[ x = \pm \sqrt{ \qty(f(x))^2 - \frac{\qty(f(x))^4}{4}} = \pm \frac{1}{2}\sqrt{ 4 \qty(f(x))^2 - \qty(f(x))^4}]

[ocean seal]

rept1d

[dull onyx]

ohh

okay thx

@rapid nova wait in the 4th step

shouldn’t it be + 1

[rapid nova]

it was + 1 while on the right side

[dull onyx]

oh

i moved the two first

then divided

[rapid nova]

then you'd have -2 on left side

[dull onyx]

yep

ok im stupid

[neon ibex]

Hey math heroes I need help solving the following equation: r^2-2*cos(x)*r+1=0
I can't find any good explanation, though I know the answer should be r=e^{+-ix}.
Anyone knows?

[r^2-2 \cdot cos(x) \cdot r+1=0]
[\rightarrow r=e^{\pm ix}]

Texit bot is not doing my bidding

[dull onyx]

no idea how u solved this 😭 @rapid nova

[neon ibex]

Ooh sorry was this channel used, sorry

[dull onyx]

no its fine @neon ibex

[valid wind]

start by completing square,

$r^2-2r\cos x +\cos^2x +1 -\cos^2 x$

and notice $1-\cos^2 x =\sin^2 x$

[ocean seal]

AlexATG

AlexATG

[alpine sable]

@valid wind hey you know a thing or two about eiganvalues?

[somber locust]

hi , can somebody help me please, how to get sine and cosine value of an angle with unit circle? for example sine 1 degrees, sine 27,7

[alpine sable]

In the first image of this problem, what is when X1 > 0 what is after that

Xg > X1?

i am confused..

[rapid nova]

it's just an equation of the form $x^2 = a$

its solution is $x = \pm\sqrt{a}$

[ocean seal]

rept1d

[tame sorrel]

what's happening?

frequency density = frequency/ width right?

so the latter half, 180/0.4

understandable

what's 3/n?

<@&286206848099549185>

this is the histogram btw

[crystal cedar]

how do i find the missing term and factor it i can do some of it but some other question like ab + y ex is confusing

[tame sorrel]

can you post that somewhere else?

[crystal cedar]

ok

where

[tame sorrel]

anywhere that's not occupied?

im waiting for help

[tame sorrel]

.

[meager marsh]

i do not understand not a single thing of this, i havent learned roots in school yet someone please explain
math is hard

[strange urchin]

When dealing with quaternions, how are the additional constants defined? For example, i² = -1, but what about j and k? What are their definitions?

[vale wigeon]

@strange urchin i^2 = j^2 = k^2 = ijk = -1

as a consequence of this, you have ij = k, jk = i and ki = j, but ik = -j, ji = -k and kj = -i

@meager marsh no wonder you don't understand this - the image you sent is a complete mess!

[meager marsh]

yea

[pulsar lark]

The answer said it is D, why x =a?
I know:
(x-a)(x-a-1)=(x-a)
(x-a-1)=1
x-a=2
x=2+a
x=a+2
(Sorry my english is bad)

[lethal dock]

Can u simplify $2p × 2c$ and get the answer as $4pc$?

[ocean seal]

JUGisMUG🎃

[alpine sable]

Yes.

[alpine sable]

Because if x = a,

x-a = 0

[strange urchin]

So, you are telling me that x=√-1 has infinitely many unique solutions?

[alpine sable]

0*(x-a-1) = 0

Which is true @pulsar lark.

[lethal dock]

And what if it was $3p + 2c$, can u do $5pc$ in this case?

[ocean seal]

JUGisMUG🎃

[alpine sable]

No.

[lethal dock]

So only multiplication?

What about division though?

[pulsar lark]

I under stand now, thank you

[alpine sable]

And division.

Yes.

[lethal dock]

Oh alright

Thanks

[alpine sable]

👍 to both.

hi is this channel free to use?

[cunning obsidian]

The way you solve equation assumed x != a if you are looking on an explanation

Yes

[alpine sable]

I’m not sure how to solve this

if I have a X,Y coords in a circle, and I know the heading, how can I find the coords of the (X,Y ) + 5 in that heading?

[alpine sable]

Do you know how to solve simulataneous equations with 2 variables?

Like x + y = 2, x - y = 1

These types?

[alpine sable]

yeahh

[outer prairie]

Someone knows where I can find material about signals and systems?

[alpine sable]

but for this one I keep getting confused

[alpine sable]

f(5) = -1 means a/(5+b)=-1

Similarly

a/(-1+b)=-4

Divide both equations.

a will be removed.

like that?

[alpine sable]

Yeah, you can also do it this way.

[alpine sable]

a = -5-b
a = 4-4b
Means
-5-b = 4-4b
3b = 9
b = 3.

Agreed?

why does a= 4-4b?

[alpine sable]

a/(-1+b) = -4

a = -4(-1+b)

a = 4-4b

[alpine sable]

This one got me. Which class is it from?

[alpine sable]

ohh

so final answer is a=-8 and b=3

[alpine sable]

Maybe, I didn't calculate all.

-8/(5+3) = -1 works. I think yes.

ahh okay got it

[alpine sable]

what about (b)?

When is a function undefined?

yea

does it mean 0?

No. Like a/0.

When denominator is 0.

oh

[alpine sable]

Is it related to programming?

[alpine sable]

it was somehow related, but only a small part of it. however, I think I solved it.

[alpine sable]

Oh nice job!

wait so i still dont get the question for b (im so sorry)
since we already get
f(x)= -8/x+3

[alpine sable]

Yeah, for what value of x will the denominator be = 0?

x+3 = 0
Iff x = ?

-3

[alpine sable]

Yep.

Done there.

What type of object are the elements of an algebraic group?

[alpine sable]

OH I UNDERSTAND NOW THANK YOUU

[edgy cape]

can someone help plz

I tried finding the derivative of c1 and c2 and saying that c1=c2 but i got the wrong answer

[alpine sable]

👍 👍

[alpine sable]

Have you differentiated them yet?

$\dv{(C1(2))}{x}=\dv{(C2(2))}{x}$

[edgy cape]

C1'= 4/4x-7 and c2'=ax/(x^2+b)^1/2

[ocean seal]

Quod Erat Demonstrandum.

[edgy cape]

ye I did that to get: 4= 2a/(4+b)^1/2

[alpine sable]

And, C1(2) = C2(2).

Now, solve the simultaneous equation.

[alpine sable]

I'm just going to assume your second derivative is correct.
Now,

[edgy cape]

Ok so I got a(4+b)^1/2=18 and 2a(4+b)^-1/2=4 as my simultaneous eqn's

[alpine sable]

,w 18=a(4+b)^0.5, 4=2a/(4+b)^0.5

Why Wolfram?

[alpine sable]

Yeah so now, multiply em together or something and solve.

[edgy cape]

Thanks a lot

[alpine sable]

Solve first.

And tell me what you get.

[edgy cape]

a=6 and b=5

[alpine sable]

It's correct?

[edgy cape]

yes

[alpine sable]

Nice job!

[edgy cape]

thanks man

[alpine sable]

👍

[slim spire]

,w 18=a (4+b)^0.5, 4=2a (4+b)^(-0.5)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by SkyTwX#9807

[alpine sable]

I don't know about eigenvalues but can I see the image you were talking about?

[alpine sable]

Ah, so Wolfram likes to follow scientific notations now.

Well, can't hate this update.

[slim spire]

The mathy way:

,w 18=a sqrt(4+b), 4=2a sqrt(4+b)^-1

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by SkyTwX#9807

[slim spire]

xD

[pulsar lark]

No idea to solve.pls help

[crystal crag]

for real roots, discriminant>=0

[cursive drum]

@pulsar lark

https://www.youtube.com/watch?v=nvpBgOm-LqY

[pulsar lark]

More hints?

[slim spire]

Do you know what the disciminant is?

[pulsar lark]

The triangle sign?

[slim spire]

Yes!

[alpine sable]

If the quad eqn has real roots, then d≥0

[slim spire]

The roots of a 2nd degree polynomial are reals iff Δ>=0

[alpine sable]

I don't think it needs that much details

So D= b² - 4ac

[pulsar lark]

-k+10 is c?

[alpine sable]

a= co efficient of x²
b=co efficient of x

[alpine sable]

Yez

Yeah, so that's how you find the range @pulsar lark

[pulsar lark]

Lemme try try

[alpine sable]

So, the range should be (___ , ∞)

[pulsar lark]

(2)^2-4(-20)(-k+10)>=0 ?

[slim spire]

No, a=2 and b=-20 you switched them

[pulsar lark]

Ohhh

[slim spire]

Or maybe you switched in the formula: Δ=b^2-4ac

[pulsar lark]

Am I correct?😩😫😫😫😫😫

[slim spire]

,w (-20)^2-4(2)(10-k)\geq 0

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by SkyTwX#9807

[slim spire]

Great! What you did is very good except for the first line:
you are not searching when the polynomial itself is greater or equal to 0

You are just looking for which k the polynomial has real roots, and this happens when Δ≥0
I hope this is clear 👍🏻

[alpine sable]

Why does it look like your stomach is upset? 🤣

[pulsar lark]

What should i write at the first line?

[slim spire]

Maybe Δ≥0

So that your teacher knows where the 2nd line is coming from

[pulsar lark]

Oh I understand now

Thank you

[slim spire]

Np

[alpine sable]

Recently I started to continue playing Pokémon Ultra Moon.

What should I evolve my eeveE into?

@slim spire

[slim spire]

Idk I'm not a pokemon expert lol

[pulsar lark]

The conclusion: The range of k is -40 to +♾️, right?

[wary stream]

Don't start an off topic conversation in a math help channel

[cunning obsidian]

First line not quite >_>

Others yes u re doing good

[slim spire]

Yes, when you say k≥-40 this means any real number in the interval [-40,+∞)

[pulsar lark]

Nice

[alpine sable]

Well yeah but you currently no one is asking for help you see. I am well aware of the rule. Don't worry.

[wary stream]

If you're aware then you should know that there is a #discussion channel for anything off topic

[alpine sable]

That's the dedest channel lol.

Please help me with my homework

[wary stream]

What did you try?

[mystic sinew]

this makes no sense though

like there are infinitely many points that are the same distance away from (root2, root3)

just because it's the same distance from that point doesn't mean the cords are the same

[devout summit]

The restriction of m,n,M,N does not allow infinitely many such points though

[mystic sinew]

im very confused

[devout summit]

What is the question?

[shut parcel]

Can someone help me with my algebra homework? Here’s the question: A jacket and two pairs of pants together cost $175. The jacket is valued at three times the price of one pair of pants. What is the value of the jacket? What is the value of a pair of pants?

[devout summit]

So yeah m,n,M,N are integers is given...

[mystic sinew]

yeah but M doesn't necessarilly have to be equal to m

[pulsar lark]

Am my conclusion right?

[devout summit]

We have to prove that it does.

[mystic sinew]

but the proposition makes no sense to me

[alpine sable]

@alpine sable you know what that letter is on first image when x1 > 0, xg > ?

And what is going on here

[shut parcel]

Can someone help me with my algebra homework?

[alpine sable]

Its an eiganvalue but what are those boxes representing

[devout summit]

Ok wait. You did not distribute -8 inside (-k+45) properly

[cunning obsidian]

^, also to add up specific to HKDSE

Say your stance at last I think

[devout summit]

Why does it not make sense according to you?

[slim spire]

,w (-20)^2-4(2)(x-25)\geq 0

[mystic sinew]

I see no reason why both of them being the same distance away from a point would necesarily imply that the both of them are the same point

you could easily do a proof by counter example by show you points the same distance from that point where those 2 points aren't the same

[alpine sable]

<@&286206848099549185>

[slim spire]

Okay wolfram is trash

[shut parcel]

Can someone help me with my algebra homework? Here’s the question: A jacket and two pairs of pants together cost $175. The jacket is valued at three times the price of one pair of pants. What is the value of the jacket? What is the value of a pair of pants?

[devout summit]

The question basically wants us to prove that for any circle centred at (√2,√3), there is never a case that two integer points lie on it at the same time.

[slim spire]

Your sign before 45 in the 3rd line is wrong

[mystic sinew]

ahhhhhhhh so that there's only one integer sol

[devout summit]

Yes!

[slim spire]

Let x=price of jacket, y=price of pants. Mathematically you know: x+2y=175 and x=3y find x and y to solve the problem

[devout summit]

Basically proving uniqueness of that point

[mystic sinew]

ah jeez I can't read today keep making the same mistakes

[fallen plank]

@slim spirecan you help in channel 9 lmao

[shut parcel]

I got 105 for jacket and 35 for pants

@slim spire I got 105 for jacket and 35 for pants. Is that correct?

[slim spire]

Try replacing x=105 and y=35, if it works, it works.
Spoil: ||it does work indeed! congratz||

[shut parcel]

@slim spire Thank you, Sky

[pulsar lark]

Why not x be pants and 3x be jacket?

[shut parcel]

@slim spire Could you help me with me one more question

[pulsar lark]

Then 2x+3x=175

[shut parcel]

What do you mean @pulsar lark

[pulsar lark]

1 Jacket = 3 pants?

[shut parcel]

x + 2y = 175 and x = 3y are the two equations

@pulsar lark x + 2y = 175 and x = 3y are the two equations

[ruby ether]

yea #help-1 i have answered him

[shut parcel]

@slim spire Could you help me with another question?

@slim spire Which two points are on the line represented by 5x-2y = 10?

@slim spire Do I do the to find x, let y = 0 and vice versa method? I did that and got points of (2,0) and (0,-5). I’m unsure if that’s how I should’ve done it

[slim spire]

Points of the form (x,y) belongs to the line if 5x-2y=10. For instance (2,5) belongs to the line if you set x=2 and y=5, where (3,3) doesn't because 5(3)-2(3)=15-6=9 is not 10

[civic jungle]

I got (4,5) and (6,10)

[slim spire]

What you did is good: you found two points that belong to the lines!

[civic jungle]

@shut parcel

[shut parcel]

@slim spire so would my final answer of (2,0) and (0,-5) be correct?

[slim spire]

If you need any two points that belong to the line, then yes! Notice that, as @civic jungle said, there are multiple other solutions (because a line contains infinitely many points!)

[shut parcel]

@slim spire How come (5,0) and (2,0) would also work?

[slim spire]

Oops I said (2,5) would work but it doesn't because 5(2)-2(5)=0 is not 10 sorry my bad haha!

[slim spire]

Do the computation for (5,0): it doesn't work! In fact, it is not a point from the line

[wary stream]

FYI, you don't have to keep pinging Sky. It gets annoying to that person if you keep pinging them, unless they don't mind

[shut parcel]

@wary stream He literally said to ask away so what’s your issue

[wary stream]

But literally in every single message of yours, you pinged

@shut parcel Would you like it if someone did it to you?

@shut parcel Don't you see how annoying it gets?

[limber quiver]

@shut parcel

[shut parcel]

@wary stream You’re not even Sky and you’re out here mad for no reason🤣

[tribal fern]

Can I ask a question here?

[shut parcel]

@wary stream I wouldn’t mind, especially if someone is in need of asking so🤡

[tribal fern]

What happens between these two lines?

[wary stream]

Can you stop pinging me?

[shut parcel]

@limber quiver Ok but are you Sky😳

[limber quiver]

i just wanted to ask for help, saw ur name first

[slim spire]

factorize cos(2x)

[shut parcel]

@wary stream You’re the one talking to me so you stop😌

[slim spire]

I don't mind, don't worry haha 🙂 But thank you

[shut parcel]

@slim spire You tell em, Sky😎

[tribal fern]

Not sure what that means, do they factorize and cancel eachother out or what?

[alpine sable]

correct or no corret

[tribal fern]

What do you mean, I don't know how to factorize cos and sin, been ages since I last worked with that

[distant verge]

how would i state the sequence of transformations to obtain the following rules from the original function?

[slim spire]

Just factorize the product, for instance ac+bc=c(a+b) I factorized c
Now set a=2sin(2x), b=-1 and c=cos(2x)

[slim spire]

Good 👍🏻

[ruby ether]

yes correct

can someone help me with set

[alpine sable]

the degree is like the power ?

[ruby ether]

yes......

[distant verge]

:)

[alpine sable]

Sadly I don't know.

[tribal fern]

ALright, I see now thanks. But how did you just see to do that? Is it because Cos2x is there twice(negative and positive) so that follows that -1 is a factor in a parenthesis or what?

[normal minnow]

I need help reviewing for my test tommorow

can anyone help

[pulsar lark]

What is question A ask ?

[glass lichen]

what's the discriminant

[pulsar lark]

B^2-4ac?

[glass lichen]

yes