help-0

[shell narwhal]

i have no clue on how to solve it

[wary stream]

Make an augment matrix

Then Gaussian elimination

[shell narwhal]

ok i did that

Ok ill send you a pic

In 2 mins

like this ?

[wary stream]

Looks good, but you need to get it into RREF

[shell narwhal]

hmmm how do i do that

[wary stream]

Do you know what RREF is?

[shell narwhal]

Yhea

but idk how to do it

[edgy hearth]

hey can u guys help me ?

about math ?

[shell narwhal]

use another channel

[wary stream]

Find the pivot values and make that entire column except for the pivot value 0s

[shell narwhal]

What ?

[fleet pollen]

what is Weighted frequency?
in the data management category

[wary stream]

No, no one in a math help server can help you \s

[whole moth]

Z y x w = 1

[shell narwhal]

Ik but my teacher said its wrong

[whole moth]

Hes wrong

[shell narwhal]

If i remember correctly there should be infinite solutions or something like that

but im not 100% sure

[wary stream]

That's wrong

[whole moth]

How

[shell narwhal]

Can you show me how to do that

[wary stream]

Which columns are the pivots?

[shell narwhal]

Well first digit of each row

So 1st and 3rd

[wary stream]

So are all the elements in the column except the pivot 0?

[shell narwhal]

not in my picture

[wary stream]

Meaning?

[shell narwhal]

I need to modify my matrix ?

[wary stream]

This matrix?

Yes

[shell narwhal]

Yes

[wary stream]

Continue to reduce it

[shell narwhal]

how ? Thats the part where i dont know how :c

[wary stream]

You do what you did to reduce the last line

[shell narwhal]

Does this work ?

[fair rover]

is this channel open

[shell narwhal]

we are using it rn try another one

[wary stream]

Yes, now write equations in terms of the pivots

[elfin panther]

Write the equation of the line that passes through the given points.(0,-1)(2,6)

[wary stream]

Find slope and use point slope

[elfin panther]

how would I do that im new to this

[shell narwhal]

something like this: ax+by…=ax+by… ?

[wary stream]

You can look up resources, like Khan Academy

[wary stream]

Close

[shell narwhal]

i dont really understand what youre saying :c

[wary stream]

To make it easier, write the equivalent equations from that matrix

[shell narwhal]

Ok

[wary stream]

Then manipulate those equations so it equals the pivot variables

[shell narwhal]

Can you send me a picture ?

[wary stream]

Nope

I'm telling you what to do

Which variables were the pivot variables?

[shell narwhal]

well english isnt my first language so its hard for me to understand

x and z ?

[wary stream]

Yes

Set the equations equal to that

[shell narwhal]

Like this ?

[wary stream]

Yes

That's pretty much it, unless your teacher wants a different form

[oblique mural]

Can someone help

[shell narwhal]

ok thank you very much ill ask my teacher if it’s correct thank you very much @wary stream

[wary stream]

Don't post in multiple channels

[oblique mural]

Oh sorry

[fleet pollen]

Am i right?

[candid dove]

no

[fleet pollen]

damn

where did i do wrong? the interval?

[alpine sable]

@fleet pollen Your status is a fact.

[fleet pollen]

yes mate, its always a fact 😂

thats what im believe in

[alpine sable]

8×1
8×4 3
8×9 5
8×16 7
I think this is the pattern.

[alpine sable]

Looks fine.

I might be missing something so ask again in #probability-statistics ig.

how do i create an equation for f(x) where there is 1 hole, has 2 vertical asymptotes and a y-intercept of 2

[fleet pollen]

thx man im asking them. i hope is right 0

[half frost]

Terminology question... if I remap a curve range from 0 to 256 to 0 to 1, can I use the term UNIT, as this is now a UnitCurve?

I have a curve named AnimVelocity which is a linear curve from 0 to 256. I made another remapping the AnimVelocity to 0 - 1.

If I were to call it UnitAnimVelocity, would it make sense to you?

If you were looking at a bunch of graphs, and saw UnitAnimVelocity, would you think that it has something to do with 0 to 1?

[rich basin]

Solve this using trigonometric inequalties

what i'm confused is that how does |Z| < 2 infer that it is a triangle

[charred flint]

?

[ripe zenith]

Not completely sure. But if |z| < 2 then z can be -2<z<2 so for z-3 maybe something like -5<z-3<-1?

which would give a range of 1 to 5?

[civic jungle]

I bet z is a complex number here

Draw a picture

[shy thicket]

Someone probably can

just ask your question

[rich basin]

@civic jungle can you please give me an explanation on why it is < and not <=

@ripe zenith yeahh, please explain why < and not <=

[ripe zenith]

because z has to be less than that value vs z possibly being equal to that value.

[rich basin]

why though?

is it because of it being the modalus of z to be less than z

not =

hence it will not always be equal to that value?

[tawny fable]

Hi there!
Small question:
Given a^2 is an even number and a/b = sqrt2.
Can I assume that a is an even number?

[civic jungle]

I don't get your confusion. |z|<2 is a hypothesis. What's weird at all?

[tawny fable]

I dont think I get it.. What do you mean?

[ocean seal]

marc

[tawny fable]

Got it

Love this community.

You guys are awesome.

Thank!

Thanks*

[ocean seal]

marc

[red bronze]

can someone help me in standard form to general form of circle

that's the standard form help me to get the general form i try getting it but my anwer is too far from the standard form

[paper canopy]

can somebody help me ?

[desert fable]

bro just plug in E = mc delta t

ok this question is answered

i dont understand this

https://artofproblemsolving.com/wiki/index.php/2018_AMC_10B_Problems/Problem_16

can sb pls help

[rich basin]

@civic jungle what i don't get about is how does this mean that the answer is < than and not <=

so then what would this answer be then?

[cloud mirage]

@plain pike

@plain pike

@plain pike

@plain pike

[safe crypt]

so what can z be

and what can z+2

[rich basin]

@safe crypt just finding the range

don't need to konw what z is

[safe crypt]

yea but you can figure out what the range is if you consider what z can be

[rich basin]

i mean you can because you are finding the modulas of z

they give you the mdoulas z

so how i thought of this question

correct me if i'm wrong

is to make them into vectors

[safe crypt]

yeah so if mod(z) = 2

wtf is zed?

oh is z a vector?

[rich basin]

no z is a complex number

it is just tha ti think of them like vectors

so basically i changed it into vectrs

[safe crypt]

ok, so what is the smallest number z can be on the real plane, amnd the largest?

[rich basin]

yeah, but i am trying to do them using triangle inequalities because they are asking it to do it like that

i can do it with locus really quickly

So basically What i did was split them into vectors

z and 2 into different vectors

and the result of it being z

[safe crypt]

kinda but it's easier than that

[rich basin]

but isn't that the triangle inequality

[safe crypt]

you don't actually really have to consider the imaginary cases

[rich basin]

but that is what my teacher did

[safe crypt]

nope

I mean I might be wrong lel

you can use the triangle inequality to justify no imaginary comp

[green hawk]

Hi, can anyone please help me with this

Note: Radius of the green quadrant = diameter of the yellow semicircle

And the question is the length from A to B

[tepid jungle]

What channel should is being used to time series?

[green hawk]

Sorry? I dont understand..

[flat remnant]

is r the radius of the bigger circle? is that a square?

[mighty grotto]

guys

how to

factoring polynomials

[noble sinew]

find (guess) the roots

[mighty grotto]

can you help me with this one

im going to have a math exam like

8 days later

[noble sinew]

what is the question?

[mighty grotto]

this

[noble sinew]

and what does the equality have to do with anything?

and don't use . as a multiplication sign, use *

[mighty grotto]

hmm idk

[noble sinew]

so you want to factor $\frac{2}{5}x^2+5x^3+x^2y$?

[ocean seal]

ScapeProf

[noble sinew]

notice something that is in all the terms?

[mighty grotto]

wait

same question

but with this

im kinda

confused

i will

tell you the answer then

you will explain it

to me please :0 ?

[strange raven]

Hi

[noble sinew]

why are we jumping around in questions? And same idea as other question (and all factoring questions like these) - find something that is in multiple terms and then you can factor it

[mighty grotto]

like

we will combine

all the x^2

and

throw it to the first ?

then

we will rewrite the others

yes

[strange raven]

Do anyone know negation?

Does*

In proofs

[amber iron]

Hello

can someone help please

[mighty grotto]

how

[ocean seal]

Krit

[mighty grotto]

hmm

[ocean seal]

Krit

[strange raven]

Will anyone tell c and d

?

Plzz

[mighty grotto]

by using

common factor ?

[strange raven]

no one expected that to not happen.

[ocean seal]

Krit

[mighty grotto]

oh

[noble sinew]

when would that be false? Think logically (or just write out the statement)

[mighty grotto]

but can we do it by using common factor

can you show me :0

ohhh

that's mean

we will throw the a

to first

and rewrite the others

yes ?

[ocean seal]

Krit

Krit

[mighty grotto]

ohh i got it

thank you m8

[ocean seal]

Krit

[mighty grotto]

we will apply this to other excercises

that will work yes

exer*

alr thanks man

[alpine sable]

can anyone help?

[fleet hearth]

it looks like a quadratic

[grand fable]

solving for x and y?

[alpine sable]

yes

yeah

yes and the x and y must be integer

s

Isolate y and think of it as a function f(x) 🙂

[grand fable]

why is there a semicolon after it

[alpine sable]

dont mind that semicolon

does not change anything

[grand fable]

ok

[alpine sable]

i am trying to isolate y

[grand fable]

y=-(x^2+7)/(6+x)

[alpine sable]

how?

[grand fable]

factorise it

[alpine sable]

i got this

is it right?

no

i don't know roots

i don't know that thing is in my homework

we have not learned roots

uh yeah

nope

[rapid verge]

how would i solve the first question?

5a

[quaint trout]

Do you know how to find the rule of a line if you have two points on the line? @rapid verge

[rapid verge]

y=mx+c

and gradient is rise/run right]

[quaint trout]

Yeah

So that's a yes, you know how to do that?

[rapid verge]

yeah ik how to do rise over run

[quaint trout]

Okay, so the x intercept is the point whose y coordinate is 0, and the y intercept is the point whose x coordinate is 0. So you have two points: (-3, 0) and (0,3)

So do your thing with those two points

[rapid verge]

ohhh

so would q b be points (4,0) and (0,5)

[quaint trout]

Yes

[rapid verge]

omg u saved me so much time thanks so much

[quaint trout]

Np

[stable crow]

Hello, I’m not sure is this a math-related type question but is there anyone who uses GeoGebra or Desmos knows how to make this type of graph? Many thanks!

The equations are:
y=8-0.04 x
y=34-0.02 x

[alpine sable]

just add a range and domain for each function

[stable crow]

How about this part?

[alpine sable]

is that not your second function?

[stable crow]

no

[alpine sable]

oh

what are you trying to do?

[stable crow]

For the red linear line under y=8, its the combination of both equation

[alpine sable]

is this what you mean? @stable crow

[stable crow]

No

I'm just trying to recreate this diagram

[alpine sable]

i'm not too sure what you mean b combining functions

[stable crow]

both equation add up together

[alpine sable]

like this?

[stable crow]

so the red linear line under y=8 is the sum of the two dotted line under y=8

[stable crow]

I think so, yea

[alpine sable]

the sum of the lines is the lowest one

[stable crow]

It the highest one

lowest one is y=8-0.04x

[green hawk]

r is the radius of the green circle

[rich basin]

for (d) and (f)

are the solutions for the following wrong?

i got answers for the following that are back to front

so forxample (d) instead of that solution

i got 1 - root(3) * i

[quaint trout]

,w 2cos(5pi/6)

,w 2sin(5pi/6)

[rich basin]

also i can't see the results

[quaint trout]

The given solution is correct

[rich basin]

what ? what have i. done wrong

[quaint trout]

I don't know what you did

So I can't say

[rich basin]

So what i did was 2(cos(5 pi/6) + isin(5pi/6))

and then i changed it to 2(-1/2 + i root(3)/2)

from 2(-cos(pi/3) + isin(pi/3))

@quaint trout you know what i did wrong?

[quaint trout]

,w cos(5pi/6))

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Lunasong#7197

[quaint trout]

You calculated wrong

[flat remnant]

ok. i think if you can prove that the distance from the top right corner to where the yellow and green circle touch is r, youll get further

[rich basin]

I'm using the charts?

[quaint trout]

cos(5pi/6) ≠ -cos(pi/3)

cos(5pi/6) = - cos(pi/6)

[rich basin]

wait what why?

isn't it cos( 5 pi - 3pi/6)

[quaint trout]

cos(pi-t) = -cos(t) here t is pi/6

[quaint trout]

I have no idea where you got this

[rich basin]

nevermind

okay thanks

[rustic trout]

does anyone know what im doing wrong in the last one

[rustic trout]

<@&286206848099549185>

[winter jewel]

This is really easy question, but how can I calculate percentage of 1 number in 3 numbers.

[scenic token]

can i come here for chemistry

[past adder]

Can someone explain to me an intuitive understanding of what R_q is and what objects belong to that class?

[fallow pagoda]

@alpine sable 20 ]

np

[placid steeple]

can someone explain the 2nd line

i dont understand how its -4/5*x=32

ignore that small circle

this is a really easy question

[raw shard]

@placid steeple factor out the x

so you’re left with x*(1-(9/5))

i’m sure you know what that turns into

[rigid kiln]

any idea what the prime means in this instance?

[placid steeple]

wdym mean by factor out x

[rigid kiln]

the notations a little wonky

think of it as like

this is x - (x * 9/5)

i think they mean just think of it as

x- x(9/5)

and remember x = x(5/5), so you can just take away the fraction

5x/5 - 9x/5 = -4x/5

does that make sense @placid steeple

[placid steeple]

thanks, i finally wrapped my head around this, it was bothering me for two days lol 😅 dont know why

[placid steeple]

yes it does

[silver current]

how do I do this

,,1.7^x = 5

[ocean seal]

jacinthaa

[silver current]

solve for x

[glass lichen]

Just to distinguish b/w elements which go together

ab=cd for all a=c and b=d is equivalent

[alpine sable]

how do i find the rate of change from 0.5-1 on a graph

the result should be 16 but i can't get to it can someone helppPpP

[pliant zephyr]

ok see that 5^2≡1(mod 24)
therefore 5^100≡1mod24
=> 5^100+55≡1+55≡8 (mod 24)
now to find the answer u need to find 8^100 mod(24) which u can do ig

[alpine sable]

so the asnwer is 8^100 mod (24)?

because i got that answer but in the notebook answer pages it's 16

[pliant zephyr]

yep

[alpine sable]

okay thank uu

[pliant zephyr]

like u still need to find 8^100 mod 24 ,I just simplied to make it easy

so the answer 16 is the final answer

[alpine sable]

−5y−1=−3x what is this is standard form

[maiden meadow]

It's y = (3/5)x + 1/5

[lone heart]

From

#❓how-to-get-help

Rule 7

When asking for help, do not insist on getting just the answer; we are here to help you learn, not cheat. Likewise, if you are providing help to others, try your best to explain and elaborate instead of simply giving away the answer.

[vale wigeon]

(this applies to both of you)

[placid steeple]

@rigid kiln is this crct

[maiden meadow]

So what's going on is

You had to bring the 1 to the other side by finding its opposite

Then divide the whole right side by negative 5

[alpine sable]

how do i find the x intercept of 3x-1/2y=4

[maiden meadow]

bring the (1/2)y to the right side and that gives you negative (1/2)y and subtract it from 4

so it will be 4 minus (1/2)y

[glass lichen]

x intercept is when y=0..

[maiden meadow]

oof i forgot abt that

[alpine sable]

ok thaanks

[alpine sable]

then what is -1/2y

isnt that 0?

[glass lichen]

???

what

[placid steeple]

guys, when you reciprocate a negative fraction, does the - sign go awayy

[alpine sable]

here ill just take a ss of it

[glass lichen]

the equation of the line is 3x-0.5y=4

you sub in y=0...

[alpine sable]

there

[glass lichen]

yeah... you just plug in y=0

[glass lichen]

no

[alpine sable]

then that makes the nafgetiveone half 0 right

[glass lichen]

yes... 0.5*0=0.

[alpine sable]

?

[glass lichen]

?

? means nothing

[alpine sable]

whats that mean

[glass lichen]

you dont know how to multiply by 0?

[alpine sable]

no

[glass lichen]

????????

[alpine sable]

thats why im here

[placid steeple]

,,(-4/5)*x=32

[ocean seal]

brishtu2828™

[placid steeple]

can anyone solve with steps 😅

[glass lichen]

multiply both sides by the reciprocal

[glass lichen]

google basic multiplication then.

[alpine sable]

ok brb

[zinc dew]

Lol kind sus you know how to use latex and not how to solve simple algebraic equations lol

[glass lichen]

cause Im not going to sit here and explain how a*0=0

[alpine sable]

is it 0

[glass lichen]

yes.

[alpine sable]

ok so is the answer just 0 then

[glass lichen]

no

you have 3x=4, x clearly isnt 0

[alpine sable]

is it 1/4

wait no

its this one

[glass lichen]

no

[alpine sable]

ok

[glass lichen]

how do you isolate for x in 3x=4?

[alpine sable]

idk

[glass lichen]

do you know division?

[alpine sable]

kinda

not really tough

[glass lichen]

so what's the opposite of multiplying by 3?

[alpine sable]

dividing

[glass lichen]

yes..

$3x=4\implies\frac{3x}{3}=\frac{4}{3}$

[ocean seal]

Mosh

[glass lichen]

so x=4/3

[alpine sable]

idk how you got that but ok

[glass lichen]

I divided by 3...

to cancel the 3 on the 3x

[alpine sable]

that means the answer is 4

[glass lichen]

????

[alpine sable]

x

4x

is answer

[glass lichen]

???

[alpine sable]

cause the 3 os gone

[glass lichen]

yeah, so x=4/3

like I said

[alpine sable]

yeah so the 3 is gone

[vale wigeon]

what problem did yall start with

[alpine sable]

cause you divided

[wild marten]

3x=4

[glass lichen]

x-intercept of 3x-0.5y=4

had a small bump w/ the fact 0.5*0=0

[alpine sable]

its .5

how do i find the slope on a graph

[alpine sable]

hey abriham i'm stuck on finding 8^100 mod(24)

how are the steps exactly?

@glass lichen helps

[mortal lark]

hi

what does this even mean

[alpine sable]

right now im at

$8^2 ≡ 16 (mod24)$

[mortal lark]

hi

[alpine sable]

hihihi

[mortal lark]

what does this mean

not getting the question

[alpine sable]

me neither xD

[ocean seal]

Sans undertale

[mortal lark]

whats a triangular table

where is it shown

and what does it even mean

the answe is 180 degrees right?

[alpine sable]

i solved mine btw if ur reading this abriham

thx

[alpine sable]

That's what you should know, not us.

[mortal lark]

hmmm

but nothing's shown

but got the answer

[alpine sable]

It may mean something along the lines of this:

[alpine sable]

Alright.

Actually along the way, I discovered a rule to get the sum of any amount of consecutive numbers that start from 1.

[mortal lark]

oh

nice!

[alpine sable]

You multiply the last number by the median number, so in this case it was 11 * 6.

[mortal lark]

the answer to this is 324 right?

[mortal lark]

oh makes sense ig

[glass lichen]

just write out the terms

[mortal lark]

1 sec = 4
2 sec = 4 X 3 = 12
3 sec = 12 X 36 = 36
4 sec = 36 X 3 = 108
5 sec = 108 X 3 = 324

thats how i got the answer

[glass lichen]

yeah

that's right

[mortal lark]

is it correct?

ok

ty

[glass lichen]

each bacterium triples

[mortal lark]

yeah

[glass lichen]

so if you have 4, you get 12

[mortal lark]

yeah

so on and so on

[alpine sable]

But the thing is, the original one remains.

So these four will give you a 12 alongside the original 4.

[mortal lark]

huh?

[alpine sable]

So at the 2nd second, you get 16 bacteria.

[mortal lark]

thats something i just learned now

[alpine sable]

All I'm saying is that if it was the way you guys thought of it, the first second there will be only 3 bacteria not 4.

Anyway, do you know how do to compound interest?

It's the exact same way with your rate being 300%.

[mortal lark]

nope

idk abt it

[alpine sable]

Oh.

Well let's do it the primitive way then.

[mortal lark]

yeah..

[alpine sable]

So really the total is 1024.

[mortal lark]

ok

ok good

ty

answer to this 8?

[pliant zephyr]

okay so 8^2≡16(mod and 8^3≡8mod24
so if u see the pattern its like 8^(2n)≡16(mod 24) and 8^(2n+1)≡8(mod24)
then 8^(100)≡16 mod 24
you can prove it rigorusly by induction ig

[alpine sable]

yeah i wrote almost 2 pages but i got 16 at the end ahahahah

[mortal lark]

any1 tell me the answer thoo?

this

[crisp grove]

find the prime factorization

[mortal lark]

doesn't help

[crisp grove]

will after u find it,

,w factor 1010

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ryuzaki#5323

[mortal lark]

yeah

then?

[alpine sable]

hi can so help me prepare for a math test?

[crisp grove]

the answer will by sum of all the (prime power + 1)

for yr case (1+1)(1+1)(1+1)

=8

[mortal lark]

oh

ok

ty ig

now

[crisp grove]

nopr

[mortal lark]

this answer is 198

abc = 806

is that correct?

[crisp grove]

whats abc? $a\times b\times c$ or $100a+10b+c$?

[ocean seal]

Ryuzaki

[mortal lark]

we have to find abc

[crisp grove]

u have to find abc-cba

[mortal lark]

yeah

[crisp grove]

assuming it's the latter, we have $abc = 100a+10b+c$ and $cba=100c+10b+a$

[ocean seal]

Ryuzaki

[crisp grove]

rest is your job

[mortal lark]

ig it

its correct

so

for this

it's 6 right?

cuz i first multiply the radius by 2

then just multiply by 3.14

i get

18.84

then divide by 3.14

i get 6

[crisp grove]

only thing I'll tell you is that it's wrong

[mortal lark]

why?

@crisp grove tell me how to solve it

:((

[crisp grove]

flattening out the circumference is flatted out,

length will be = the perimeter of the circle

[mortal lark]

it is

perimeter is 18.84

so lenth is 18.84

and div by 3.14 is 6

right?

[crisp grove]

speed = 3\pi /second

[mortal lark]

yeah

then

wait

i am confused

what does 3\pi mean

@crisp grove

[crisp grove]

$3\pi$

[ocean seal]

Ryuzaki

[crisp grove]

read the question

[mortal lark]

but doesn't that mean

it's 3.141.......

right?

[bleak ridge]

3 * 3.14159

[exotic brook]

distance / speed

[mortal lark]

but don't u multiply it with the diameter?

[exotic brook]

diameter is 2 pi r

which is the distance

speed is 3 pi

time = distance / speed

[mortal lark]

okay, i am just geting more confused

[exotic brook]

what's the diameter?

2 * pi * r

[crisp grove]

circumference, not diameter

[exotic brook]

oh yeah oops

[bleak ridge]

Oh wait

Yeah it's just pi

[exotic brook]

no it's 2

18.84... / 3*pi

(2 * pi * r) / (3 * pi)

[mortal lark]

i am just getin more confused

[exotic brook]

ok so the radius is 3.

[bleak ridge]

3 meters / 3pi meters/sec

[exotic brook]

it's not 3 meters.

that's the radius

[mortal lark]

yeah

[exotic brook]

the dude runs around the circumference

[bleak ridge]

It says the circumference is 3

[exotic brook]

the circumference is 2 * pi * radius

[mortal lark]

and the diameter is 6 meters

so

[exotic brook]

forget about the diameter

[mortal lark]

6 x 3.14 is 18.84

[bleak ridge]

Oh wait

[exotic brook]

circumference is 2 * pi * r

[bleak ridge]

Misread the question

[exotic brook]

exactly

so circumference is 18.84...

[mortal lark]

and that divided by 3.14 (the speed)

[exotic brook]

yep

[mortal lark]

is

6

right?

[exotic brook]

no

it's divided by 3.14 * 3

the speed is 3pi not 3

[alpine sable]

can someone please help me prepare for this test?

[exotic brook]

and not pi

18.84 / 3pi

[bleak ridge]

Perhaps

[exotic brook]

= 2

[mortal lark]

what 3pi

explain plz

[exotic brook]

velocity is 3 pi

not 3

[mortal lark]

yes

so the velocity is

3.14......

right?

[exotic brook]

no

[mortal lark]

or is it diffrent

[exotic brook]

3.14 is pi

this is 3 pi

so 3 * pi

[mortal lark]

yeah

[exotic brook]

so 9.424

[mortal lark]

oh

ohh

i am getting it now

[exotic brook]

ye

so distance is 18.84

speed is 9.42

[mortal lark]

the invisible multiplication

[exotic brook]

distance / speed = ?

[mortal lark]

2

[mortal lark]

2

[exotic brook]

:)

yep

[mortal lark]

tytytytytytty

[exotic brook]

np

[harsh wharf]

anyone know how to solve this?

i have

no idea how to

[late badger]

Force = Mass times Acceleration

where Force is in Newtons (N), mass is in kg, Acceleration is in m/s^2
so for the other two, you'll need to convert units

[harsh wharf]

thank you bro ill have that in mind

[severe sluice]

that's actually the net force (vector sum of all forces)

so when you deal with multiple forces you'll have to add them up first

[hearty orbit]

How do i find the limit of $\lim_{n \to \infty} \frac{v^n}{n!}}$

[ocean seal]

goldenturtle

How do i find the limit of $\lim_{n \to \infty} \frac{v^n}{n!}}$
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                                                  $
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spurious, as in `$x}$'. But perhaps the } is legitimate and
you forgot something else, as in `\hbox{$x}'. In such cases
the way to recover is to insert both the forgotten and the
deleted material, e.g., by typing `I$}'.

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[late badger]

I thought you needed help with the limit question

[severe sluice]

oh yeah

just thought it would be better to send that on calculus

[late badger]

are you familiar with Stirling's approximation?

[hearty orbit]

oh sry i will go to another channel

[severe sluice]

no?

[late badger]

it is a shortcut to use for this limit

you can use it if you want

[severe sluice]

but how can I use that?

[late badger]

Applying Stirling's factorial approximation:

[tranquil pivot]

wtf is this

is this calculus?

[severe sluice]

ooh

i get it now

[tranquil pivot]

this is certainly some form of advanced math

[late badger]

as such:

[severe sluice]

yep that's definitely 1.
thank you!

[late badger]

true, unless no vectors are given
I see it as a F = ma type thing, and the person with the question need to be cautious with the units

[late badger]

it is (let's show here for those curious) :

[bleak ridge]

What happened to the v

[late badger]

since the x in the power on the right (in the numerator) expands to become x^x divided by e^x
and then the e^x cancels out its copy in the numerator, and the x^x cancels out its copy in the denominator
and of course the sqrts in the numerator and denominator cancel each other
we get 1
lim x --> infinity of 1 is remained
no x to substitute in, then answer is 1
QED

[late badger]

v?

[bleak ridge]

Like uhh

v^n/n!

Or are you answering another question

[late badger]

probably

[bleak ridge]

Oh you're answering this

Reasonable

[alpine sable]

helo anyone

[strange blade]

is it really valid to move the alpha coefficient inside like that??

since it's a sum

[buoyant kayak]

is it not being raised to a power using log rules?

[buoyant kayak]

that's $e^{stuff}$, ain't it?

[strange blade]

@buoyant kayak but there's sum inside

[ocean seal]

a disappointing son

[strange blade]

e^x1 + e^x2 ... e^xn

(e^x1 + e^x2 ... e^xn)^alpha != adding alpha to every e^x

[buoyant kayak]

ah, i'm not too sure then

[half crypt]

Damn you guys are smart

[alpine sable]

can anyone explain me how to solve this problem? I tried to prove by making use of properties of log but it became a mess...

p.t. means prove that

Can someone help me with compound / simple interest. You can tag me

[west geyser]

Could someone please prove "A union (B union C) = C union (A union B) = B union (A union C)"?

I want a proof that doesn't use examples or a "if x belongs to A then x belongs to A union..." but a purely "logical" one

I can visualise and understand it very easily but I don't know how to actually prove it

[wary stream]

You have to wait at least 15 minutes before pinging helpers

[vast isle]

Oh

sorry 😭😭😭

[wary stream]

As well as that is a quiz, so if it academic dishonestly to get help on quizzes, we cannot help you cheat on that stuff

[vast isle]

at least ur honest w it but sirry again😭😭😭

[fierce fern]

hello what is the answer to this 7x+2x+19x

[zinc dew]

28x*

[fierce fern]

x dont stack?

[zinc dew]

Wdym

[fierce fern]

like x³

[zinc dew]

No thats when you multiply them

[fierce fern]

there is also a question here that is 18x⁵ ÷ 6x³

can you explain i have a hard time catching up in class

[west geyser]

18x^5/6x^3 = 18(x)(x)(x)(x)(x)/6(x)(x)(x) = 3(x)(x)/1 = 3x^2

the three xs in the denominator will cancel three xs on the numerator because they represent the same number as 2/2 = 1 = x/x

leaving only 2 xs

6 will divide 18 into 3 parts as 6*3 = 18

generally you'd just subtract the powers of the variables in division because that's what's happening here, 18x^5/6x^3 = (18/6)(x^5-3) = 3x^2

(sorry for so many mistakes btw, been studying for so long my head hurts and I can't think straight)

[fierce fern]

so its 3x²

[bleak ridge]

yes

[fierce fern]

yes finally

[west geyser]

<@&286206848099549185>

[fierce fern]

can i put the number after the variable ex: x2

[west geyser]

yes you can, it would mean the same thing, but it will be gross

also on computer people may write x^2 as x2 so it will also create confusion

[bleak ridge]

I don't think anyone would ever do that

Unless they're clinically insane

[fierce fern]

so i can make (x+5) = 5x

[west geyser]

if you google questions with variables a lot of them are simplified in the format of xn

also it's faster and easier

[bleak ridge]

[west geyser]

no one ever writes 2(x) as x2

so x2 is interpreted as x^2

online

[fierce fern]

what is x+5 is it 5x?

[bleak ridge]

x+5 is x+5

[west geyser]

are multiplication and addition same?

[fierce fern]

this is the question (x+5)(x-7)

[vocal nymph]

Times out

x^2 - 7x + 5x - 35 = x^2 -2x -35

[bleak ridge]

[west geyser]

I think the only reason you asked this is because you don't understand what the first number in a multiplication means, if you write 2*5, it is interpreted as two fives that is, 5+5, but if you write 5*2 it means, five twos that is 2+2+2+2+2, although the values of both will be the same, the interpretation will not be. 5x means five xs, that is x+x+x+x+x, but x5 would mean, x fives, and that is an exponential function.

I am sorry

it won't be an exponential function, my brain automatically interpreted x5 as x^5 due to force of habit

but you get the point

[west geyser]

this is why please never write 2x as x2

[vocal nymph]

A handy way to multiply out

@fierce fern

[fierce fern]

yeah

[bleak ridge]

Or just distribute both terms

[west geyser]

someone?

I can't find any proof online

online as in search engines

[fierce fern]

ty for the explaination i got it in your method

[vocal nymph]

🧅

[vocal nymph]

👍

[west geyser]

by "logic" I mean proving it using identities like, "(A union B) = (A - (A intersection B)) + (A intersection B) + (B - (A intersection B) = A + B + (A intersection B) - 2(A intersection B) = A + B - (A intersection B)"

no examples used here

pure logic

[west geyser]

I want a proof for this, this way

[wary stream]

Why fast?

Also you have to wait at least 15 minutes before pinging helpers

If you don't know what alternate exterior angles are, you should look it up

[unkempt umbra]

can anyone help me a bit with this exercise?

[fresh parcel]

you could try using a venn diagram

union is commutative

i think

[fresh parcel]

well it obviously converges

because multiplying decimals just gets you somewhere between 0 and 1

[alpine sable]

u cant ask qs in a test

thats called "cheating"

[unkempt umbra]

i have to somehow use the cauchy sequence definition

[fresh parcel]

i have no idea what that is

im sorry im unable to help you with it

[unkempt umbra]

it's ok np

[unkempt umbra]

<@&286206848099549185> maybe know..

[plush herald]

@unkempt umbra ah, a fellow UBB student

[oak chasm]

<@&268886789983436800>

[bleak ridge]

[tame falcon]

Thanks

[alpine sable]

what exactly do you mean by have to

[unkempt umbra]

it's an exercise placed right after that lesson

[alpine sable]

well I have a pretty simple proof that the sequence is convergent which doesn't rely on proving the sequence is cauchy

[unkempt umbra]

sure, show it

[alpine sable]

it is easy to see that x_n is bounded by 1 because all the terms are products of numbers in (0,1), and it's also easy to see the sequence is monotone (decreasing) because each element in the sequence is the previous times some number in (0,1)

but you are asked to find the limit anyway

so doing the above or showing the sequence is cauchy or what not doesn't really do anything

[alpine sable]

I believe all the factors would cancel out except the first and the last

[wild olive]

$\dfrac {9p}{p^2}$

[ocean seal]

Jabba the black

[wild olive]

how do i solve this

well simplify it

[alpine sable]

9/p

[unkempt umbra]

how?
3/4 * 8/9 * .... * (n^2-1)/n^2

[alpine sable]

you can get some "useful cancelling" but it takes some work

[fresh parcel]

i dont think its a telescoping series

youd have to make one

[wild olive]

yeah that's the answer but can you show the steps

[bleak ridge]

That is the step

[alpine sable]

(n^2 -1 )/ n^2 = (n-1)(n+1)/n^2 = (n-1)/n * (n+1)/n

[alpine sable]

divide by p

[fresh parcel]

oh

[bleak ridge]

Well you don't really divide by anything

It just cancels out

[alpine sable]

= (1/2 x 3/2) x (2/3 x 4/3) x ....

[wild olive]

tyy

[bleak ridge]

I guess one step would be splitting it up

[fresh parcel]

so its just 1/2 multiplied by the last term +1?

[alpine sable]

prtty much

[wild olive]

9p/1p = 9
p^2/p results in p^(2-1) = p^1 = p

[bleak ridge]

$\frac{9p}{p^2} = \frac{9}{p} * \frac{p}{p}$

[ocean seal]

PapaBread

[tight locust]

wow!

[alpine sable]

unclear what you mean but no I don't think so

[fresh parcel]

yeah my bad i meant that the terms should cancel out

[unkempt umbra]

i think it it just (n+1)/2n

[alpine sable]

$\frac{1}{2}\frac{n+1}{n}$

[ocean seal]

Botnuke

[alpine sable]

yes

[fresh parcel]

leaving only the first term and the last term

yeah and because n+1/n approaches 1

the limit should be 1/2

[unkempt umbra]

i think this was the hardest step

thank you all

[alpine sable]

also randomly going to add that it's not really obvious that the sequence converges from this alone lol

[fresh parcel]

oh okay

[alpine sable]

np yw

fun q tbh

[hidden junco]

What is thsi value ? for d = 4

[lost gorge]

4C2

Which is 6

[hidden junco]

What does 4c2 mean ?

[lost gorge]

[n]
[r]

= nCr

Where nCr = n!/r!×(n-r)!

[hidden junco]

ah gotcha I remember this now

[fresh parcel]

binomial coefficient

[rigid kiln]

Is a set being closed under a binary operation the same thing as the operation being associative?

[glass lichen]

No

[soft creek]

Having a hard time proving this: Let f: X -> Y be a function, prove that if for all y element of Y, f^-1({y}) = {x} for some x element of X, then f is injective. (where f^-1({y}) is the inverse image. I'm thinking that it shows that every y has an x, and the 'for some' allows us to somewhat choose what x is, and we can choose a unique x each time, but not sure if I am on the right track

[bright merlin]

Well if you are already assuming existence of inverse then definitely from that it follows that f must be injective

[empty ridge]

My interpretation is that f^-1({y}) has to be a set with one element (but only one, otherwise the function would not be injective, try to reason why).

[soft creek]

I know that a bijection must exist for the inverse to exist, but it's slightly different with inverse images, I believe that is what my professor taught

[sly mantle]

we can speak of preimages for any function, including nonbijective

[soft creek]

Ahh I see the notation, if it were outputting say {x1, x2} that would mean the one input would go to 2 (or as many as you want) outputs, which is not injective

[bright merlin]

Oh I see it now..its a set..and you need to prove the existence and uniqueness of an element correspondinf to each such set

[zealous cliff]

is there a problem with this question or am i dumb cuz it doesnt make sense

also ik it isnt hard im in year 9 (idk what they call it in america)

[empty ridge]

Yep! That's it.

[charred vortex]

Come to questions 9 it's not in use

[zealous cliff]

ok

[soft creek]

Okay so translating this to more proof language, with implications and whatnot, I'm having a tough time moving this into proving that it's injective. The proof the professor goes off of goes something along the lines of [x1 = x2 => f(x1) = f(x2)], How do I show that? Or is there another way to prove injective functions that I am missing?

[sly mantle]

that's not the definition of injective

[bright merlin]

Its the other way

[soft creek]

or actually the other way around? [f(x1) = f(x2) => x1 = x2] It makes sense that the two outputs would mean that the two inputs are the same

Gotcha

[empty ridge]

Yep the other way around is always true (if you use the same inputs, you produce the same output!)

[sly mantle]

the other way is definition of f being well defined

[soft creek]

Now does that hold true for inverse images? Like [f^-1(x1) = f^-1(x2) => x1 = x2]?

[empty ridge]

Note that inverse images are sets, not functions.

f^-1(x1) would meand all the x's that would produce f(x) = x1 (for an x1 in Y).

For all x in f^-1(y), you have f(x) = y.

Try to prove it generating a contradiction... that is suppose that the premisse is true, but the conclusion is false... If this generates a contradiction, then the implication must be true.

[soft creek]

Hm okay, yes I see that, I think I have enough to start the proof, thank you! I'll come back if I have any questions. Thanks guys!

[empty ridge]

👍

[wild olive]

$\dfrac{-9}{3} = p$

[ocean seal]

Jabba the black

[wild olive]

how do i solve for p

i forgot all the basics 😢

[sly mantle]

@empty ridge @soft creek contradiction unneeded

[wild olive]

oh i mean

simplify

mb

just realized i typed it wrong im sorry 😭

hold on

$\dfrac{-9]{p}= -3$

god what am i doing

wdym

[ocean seal]

Jabba the black
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[wild olive]

i can't use this bot anymore

[soft creek]

What are we trying to do with this? Solve for x? This gives nothing to work towards

Well first I would move the 5 to the other side, do you know how to 'undo' a square root?

Yes, So we can rewrite as $y = 5(3 - 2x^2)^{(1/2)}$

[empty ridge]

Agreed. I suggested as a way to make sense of the proposition, what it meant... What would happen if it wasn't true...

[ocean seal]

taxborn

[soft creek]

Do you agree with that?

Now how do we get the 5 to the other side?

Correct

$y * {1/5} = (3 - 2x^2)^{(1/2)}$

[ocean seal]

taxborn

[soft creek]

Now what? We want to get rid of that 1/2 power, how do we move that to the other side?

We can't get the x by itself without moving the square root or one half power to the other side

Let's start simpler

$\sqrt{x}$

[ocean seal]

taxborn

[soft creek]

How can we get that x by itself?

If that is the square root of x, what exponent can we raise that expression to, to get simply: x

No, 1/2 is the power for square root, what if we square it? Or raise that to the power of 2?

Anything to the power of 1 is itself

Perfect

Yes

So, if we take the original:

$y*(1/5) = \sqrt{(3 - 2x^2)}$

[ocean seal]

taxborn

[soft creek]

, if we raise both sides to the power of 2, the right hand side will no longer have x 'hidden' under an exponent, right?

Since the right hand side exponent will just be 1

Does that get you to where you need to be and solve it from there?

Perfect!

Yes

[ebon pawn]

I'm currently trying to get a GED since my homeschooling was unsuccessful and I have the knowledge of a 6th grader. Would it be easy for me to study for the GED or will I need to learn some things first that you're expected to know?

[rigid kiln]

boutta ask a question way stupider than where I am academically but does this work or do I have to do stuff to the 1 as well

[rigid kiln]

what age are you in 6th grade?

[tropic sail]

11

[ebon pawn]

Right now, I am almost 19. I was 12 in 6th grade.

I was also in honors class. Unsure of what subjects I currently know, and I doubt there's an easy way for me to check what I already know.

[rigid kiln]

one sec, I'm just looking over what the GED test actually entails

[ebon pawn]

Honestly, I'm sorta sad that the homeschooling ever happened. It was very cool being ahead of everyone else and now I have to deal with all of this and settle with a GED that will prevent me from ever going to a really good college. Sorry for going off-topic, I just can't help but be bitter throughout studying for the GED.

[rigid kiln]

I feel you, I've been shafted by academic standards a lot

[ebon pawn]

Haha. Bad luck can really mess everything up.

To be honest, I feel like if I were allowed to remain in public school, I would get some pretty damn good grades and have a high GPA.

But I had the opportunity taken from me. It sucks, but I hope I can someday figure it all out.

[rigid kiln]

To be honest I think the best thing to do would be to look over the practice test, see what you know, and judge from that

[plain halo]

idk what you have to do but im pretty sure this doesnt work

[rigid kiln]

ah fair dues. think all my work lately is just giving me brain farts

[rigid kiln]

if you're curious i'm proving that a set isn't a group because the inverse isn't in the set

Yeahhhh that's my other though, thought i might have gotten away with that

cheers

[plush herald]

how can I prove that this sequence is increasing?

I tried both of these methods, but neither seem to be easy to solve

afaik, the monotony of a sequence can be determined by subtracting two consecutive terms to see which one is bigger, or dividing them to see if the result if greater than or lower than 1
are there any methods? or a way to do anything with any of the 2 above?

[strange coral]

Qm seems to be equal to m/1+m

[plush herald]

yeah, it seems like they're the same

[strange coral]

uhm what about differentiating it then?

[plush herald]

can I do that? :O

[strange coral]

d/dx m/1+m is 1/(m+1)²

its greater than 0 so its increasing i think

[plush herald]

can I just do that and it has the same monotony?

[chrome mirage]

is a quadratic with complex coefficients a function? eg: (x+1)(x+i) or x^2 + (i+1)x + i and is it possible to graph?

[strange coral]

it should

[plush herald]

alright

and how do I show it's the same as m/1+m?

[plain halo]

you can use the rules of arithmetic progression here

1+3+...+2m+1 increases by 2 every time

we can prove this via 2m+1 - ( 2(m-1) +1)

so d becomes 2

a1 = 1

an = 1 + 2(n-1) = 2n -1

so an+1 is 2n+1

[plush herald]

so I just replace those sums with their respective arithmetic progression sum formula?

[plain halo]

yeah

i think that should worl

work*

[plush herald]

alright, thanks a lot @strange coral and @plain halo ! :P

[plain halo]

anytime :)

[wispy wing]

can i have some help please?

<@&286206848099549185>

<@&286206848099549185>

[wary stream]

Only ping the helpers once

[wispy wing]

sorry

[west geyser]

as I said, I have no trouble visualising it, I just want a proof based on known concepts

[still sundial]

is this true?

[wispy wing]

yes

[still sundial]

nice

[wispy wing]

u know this?