help-0

[late parcel]

I see it

[clever mountain]

i believe spooky ghost is using this channel

[strong vapor]

Is it true that the NQF is 2?

[near falcon]

._.

how do i find the area of a sector

[clever mountain]

https://www.cuemath.com/measurement/area-of-a-sector/

[near falcon]

ty

[clever mountain]

np

how to get the coords of the point the green line is in the white circles outer ring.

the red dot in the center is the possition of the coords i want to get

[alpine sable]

I have the equation g(x)= |2x-5|+1, but I don’t know what those lines mean. Could someone tell me?

[clever mountain]

I'm using this channel

[alpine sable]

oh mb

[devout summit]

Note that the y-coordinate of centre and the external point is same.

[clever mountain]

oh yeah 1 sec

[late parcel]

Is this channel open

[clever mountain]

oh the white circle's coords are actually (200, 250)

[clever mountain]

no sorry

[devout summit]

Anything else that’s different?

[clever mountain]

no that's it i believe
i can re look it all over really quickly though

[devout summit]

Ok wait what is that white point you marked on the circle?

[clever mountain]

oh nvm that's it i just looked that was the only inaccurate thing

[clever mountain]

that is the circle that i am trying to rotate along the ring to the red point below it

[devout summit]

Calculate distance between the circle’s centre and that point on the outside

[clever mountain]

824.6 pixels

[devout summit]

Ok 200*sqrt(17) to be exact

[clever mountain]

for the distance?

[devout summit]

Yes

[clever mountain]

i see

[devout summit]

Then, if you translate everything such that the circles centre goes to (0,0) what would the coordinates of the outside point be?

[clever mountain]

1096.5856099730654

if the white circle is at 0, 0(aka top left)

[devout summit]

The coordinates of external point will become (800,200) !

[clever mountain]

which external point? the circle on the ring or the spot the line is traveling too?

[devout summit]

Spot the line is travelling to

[clever mountain]

you want me to set it to that? cause right now that doesn't move

[devout summit]

Wait you are using a computer software?

[clever mountain]

yeah python

[meager crater]

Is this still being used?

[clever mountain]

yes sorry

[meager crater]

ok no worries

[devout summit]

But we could do calculations on paper right? Why do you need to change the program?

[clever mountain]

that's just what I'm running it on it doesn't matter where the calculations are run i just need the formula for getting the coordinate of intersection, i have been trying to find it for a while.

[devout summit]

I think coordinates would come out like this.

$\left(\frac{1000\cdot 20+200\cdot (200\sqrt{17}-20)}{200\sqrt{17}},\frac{450\cdot 20+250\cdot (200\sqrt{17}-20)}{200\sqrt{17}}\right)$

[clever mountain]

sheesh

[devout summit]

You could simplify in this case

[clever mountain]

how so?

what is that 500 in the first one?

[vapid oak]

a number

[devout summit]

Ok well, it was supposed to be 200

[clever mountain]

oh ok, thanks for the clarification

[ocean seal]

Euclid31415

[vapid oak]

2,180 , 9,230

[alpine sable]

hi can anybody help me with math?

[clever mountain]

i don't think that's accurate

[vapid oak]

ok

[clever mountain]

1. don't ask to ask
2. im using this channel

[alpine sable]

?

[vapid oak]

he called dibs on this channel

[clever mountain]

XD

[clever mountain]

first coord comes out as 20195.149287499273

oh nvm it comes out as 219.40285000290663

[devout summit]

And second one as 254.8507125007266…

[clever mountain]

253.88057000058132

[west hearth]

$\int _{-\infty }^{-9}\frac{32}{x^2-64}$

[ocean seal]

(ENGR) M_0_1

[west hearth]

this integral would diverge right?

the question says it converges though..

which is very strange

[devout summit]

I checked. WolframAlpha is giving me what I wrote.

[clever mountain]

unfortunately this does not give the right coordinates 😦

@devout summit

the circle should always be on the ring never inside of it or out side

[devout summit]

But this is specifically for case you wrote and not moving

I checked for that specific case you wrote. It does satisfy

[clever mountain]

as you can see in the video at 10+ mark i reopen it to the state i showed it for and it does not give the right result

[clever mountain]

pls different channel im using this one

[robust marsh]

oh sorry

[clever mountain]

all g

[devout summit]

I know!

Ok I know where you made a mistake

That 200*sqrt(17) is the distance between the centre and the point outside.

[clever mountain]

so the 200 should be = the distance?

or the 17

ok with it being in the place of the 17 it works on the situation of the white circles coords being (1.02, 1.02)

[devout summit]

200*sqrt(17) as a whole is the distance

[clever mountain]

oh ok

[devout summit]

You wrote here as (x coordinate of centre)*sqrt(17)

[clever mountain]

right

[devout summit]

In the denominator too btw

Please do show if it works

[clever mountain]

testing it right now

So close

@devout summit Now it just needs to slide along the green line to the length of the radius, this is way farther than I have gotten. thanks so much.

[devout summit]

Why is there a “,0” in your definition of point2?

[devout summit]

There shouldn’t be a need of that

[clever mountain]

just to tell it not to remove anything from the value

def length(v_1, v_2, distance_to_surface):
    value = 0
    for x in range(len(v_1)):
        value += math.pow(v_2[x] - v_1[x], 2)
    return math.sqrt(value) - distance_to_surface

i use the function for other things so it needs that input but in this case i set it to 0 so it doesn't do anything

[devout summit]

Where is v_1[y] and v_2[y] here?

Could you define a separate distance function and try if it works

[clever mountain]

those are what are passed
v_1 = player_coords
and
v_2 = laser_point

[clever mountain]

unfortunately i know this wont change anything for a fact

[devout summit]

But the formula should work then

[clever mountain]

it think it might give me 1 minute actually

[clever mountain]

holy shit i think it works let me just change a few things

[devout summit]

You should have asked for a general formula in terms of variables from the beginning

[clever mountain]

i changed it to this

x = ((laser_point[0] * (circle_width * circle_width)) + (player_coords[0] * (point2 - (circle_width * circle_width)))) / point2
    y = ((laser_point[1] * (circle_width * circle_width)) + (player_coords[1] * (point2 - (circle_width * circle_width)))) / point2

cause I think the radius isn't actually 20 pixels i think it's closer too 200

or somtehing

and now it works way better

[devout summit]

Is your circle width defined as fixed?

[clever mountain]

yeah

[devout summit]

That’s a problem right

[clever mountain]

oh wait nvm it changes as it moves

[devout summit]

Your circle radius changes here

[clever mountain]

yeah it changes when it moves

[devout summit]

Why is there (circle width)*(circle width) here?

[clever mountain]

it just made it work for some reason XD

cause the pixels is actually bigger than 20 it's a multiple of it

[devout summit]

So you might have defined that as square root of radius or something

[clever mountain]

right

[devout summit]

But we are looking for exact results aren’t we

[clever mountain]

i think i can find those given some code tweaking

[clever mountain]

holy shit i found it it works perfectly now thank you sooooooo much

x = ((laser_point[0] * point) + (player_coords[0] * (point2 - point))) / point2
y = ((laser_point[1] * point) + (player_coords[1] * (point2 - point))) / point2

[devout summit]

What does it look like now? I am curious

[clever mountain]

sure thing 1 minute

[clever mountain]

perfection!

[devout summit]

Yay!!!

[waxen iron]

first question

im confused

geometry b tw

[buoyant kayak]

do you know how to do synthetic division?

[main quail]

How would I simplify this?

I think that’s the first step but if it’s not a quadratic and not 2 perfect squares idk how to do it

[coral pagoda]

That will certainly work. Some things cancel out as well

[drifting wadi]

$(2x-1)^3((2x-1)^2+4x)$

[ocean seal]

DeathWalker1

[coral pagoda]

(2x-1)^2 =4x^2-4x+1. So (2x-1)^2+4x is just 4x^2+1

So it simplifies nicely to (2x-1)^3(4x^2+1)

[worn gazelle]

Hi

[coral pagoda]

Well, nicer anyways

[drifting wadi]

$(2x-1)^2 =4x^2-4x+1$

[ocean seal]

DeathWalker1

[worn gazelle]

I need help with conic section

[coral pagoda]

Deathwalker, yes. This has been addressed

[drifting wadi]

can u please find a channel that is not taken

[worn gazelle]

Oh

My bad

I thought you just kinda asked anywhere mb

[coral pagoda]

Yes. But if a channel is busy, you need to ask somewhere else.

There are 9 other perfectly good locations :)

[worn gazelle]

👍

[drifting wadi]

yeah i was going to finish it off but uve already done it

[coral pagoda]

#precalculus is also a perfect channel for your question

[worn gazelle]

Great, thanks

[crimson raven]

send help in (b)
i thought it was the best to take the johor bahru-miri to go back in saturday
but when i check the answer

it shows me this

how do u get a 2155 hrs flight and then 1930 hrs
it says go back to peninsular malaysia meaning johor bahru from miri

[alpine sable]

<@&286206848099549185> anyone know how to convert an improper fraction to a mixed fraction?

[drifting wadi]

yes

[alpine sable]

Plss tell me

[drifting wadi]

firstly ask the question

and if u dont get a response for 15mins then u ping

[alpine sable]

Ok

[drifting wadi]

dont ping straight away

[alpine sable]

I need to convert

37/15 to mixed

[alpine sable]

oh sorry, i didnt know

[drifting wadi]

37/15 = 2.46.....

[alpine sable]

ohhh

[drifting wadi]

and if u 2*15 u get 30

u still need 7 more

so the answer is

[alpine sable]

ohhh Okay!

Thanks

It helped

[crimson raven]

<@&286206848099549185>

[alpine sable]

quick question.. maybe someone can help me... when you are dealing with in an infinite integral, and you have two finite summations inside the integrand, what exactly can you do to the summations and the integral?

[alpine sable]

do you mean something like this: \
$\int \Sigma \Sigma$

[ocean seal]

bertaunth

[alpine sable]

yes, exactly that

but the two summations are finite

are there variables

or do the summations just yield constants

yes, and orthogonal functions as well

honestly, if your i -- > n isn't too long, i would just brute force write each term out and then distribute the integral

[placid zinc]

@random galleon
No it isn't

[storm crescent]

linear transformation is when f(c+d)=f(c)+f(d) and f(cx) = c*f(x), so for each question, check if this is satisfied or not

[midnight girder]

hello!

the local maximum of this graph would be points a and s correct?

or is there soemthing im missing

[fresh parcel]

local max

but the derivative at a isnt 0

the derivative at e is 0\

[violet bison]

Hey! Can someone help me with this: A square ABCD is given. Points P and Q are taken on the sides AB and BC such that the BP is equal to the BQ.BH is the height of the triangle BPC. Find the angle DHQ. I need the solution solved with vectors

[midnight girder]

so it wouldnt be a?

it would be e and s?

hey guys sorry this channel is occupied

[paper bloom]

yea

[midnight girder]

its still wrong for me

@paper bloom no idea what else it could be, i tried a, e, s, then a and s, then s and e, then s alone

<@&286206848099549185> is there something im not seeing?

i swear it should be rlly simple ahh

[coral pagoda]

What is the definition of a local maximum?

[midnight girder]

a point where the value is greater than all the other values near it on a function/that interval

[coral pagoda]

Interval is a key word here

[opal reef]

i believe it would be points E and S, are you looking for 2 points?

[midnight girder]

any amount

[coral pagoda]

If a is a local maximum, then to the left and right of a, there is an open interval (a-e,a+e) so that all values that are not a are strictly smaller

[midnight girder]

however i tried that already

[opal reef]

points e and s are not 2 local maximums descending?

[coral pagoda]

Look at e and s. We see that there is such a d>0, (e-d,e+d), so that every value in this interval (that is not e) is strictly smaller than f(e)

Technically, a is also a local maximum. This one is a little more subtle, but in this portion of the reals, [a,d) is an open interval.

And it is not hard to see that there is indeed a real number d, so that for [a,d) every other value is smaller than f(a)

Your answer should end up being a,e,s.

[midnight girder]

ive definitely tried that already ://

[coral pagoda]

It is the correct answer.

[midnight girder]

i completely agree with your explanations and that was actually my first answer

hmm not sure why it didn't work

[coral pagoda]

Now, if the domain is the reals, then local maximums occur exactly when the derivative is 0. Which is at both e and s.

It is more likely that is the answer they are looking for

[midnight girder]

which was my second answer

and it still counted wrong

[coral pagoda]

And it is correct

[midnight girder]

im beginning to think they just want me to put e

[opal reef]

make sure its not caps sensitive

[midnight girder]

because ive tried a and s, e and s, a e and s, and s alone

no it is not

[coral pagoda]

No. e is certainly the absolute maximum, but there is more than one local maximum

[midnight girder]

it's multiple choice

hmm

[opal reef]

what does the question exactly say

[midnight girder]

Check the boxes of the points where the graph has a local maximum

[coral pagoda]

e and s

[opal reef]

yes

[coral pagoda]

Those are the correct answers

a could be. All depends on the domain. Technically it should be

[midnight girder]

maybe i'll email my professor about this

i only have one try left

[coral pagoda]

Sounds like the program is just incorrect. It happens

[midnight girder]

maybe i just choose e and email because i'm certain i had it correct

[coral pagoda]

Clearly it isnt R because all elements to the left of a aren't even mapped

e and s are probably the answer they expect, but a,e, and s is 100% the right answer.

[violet bison]

Hey! Can someone help me with this: A square ABCD is given. Points P and Q are taken on the sides AB and BC such that the BP is equal to the BQ.BH is the height of the triangle BPC. Find the angle DHQ

[sick torrent]

Which is correct?

<@&286206848099549185>

Damn

[coral pagoda]

Here's a hint: if c is a constant, c^n is also a constant

[sick torrent]

Oh right the derivative of a constant is 0

[coral pagoda]

Correct

So what is the derivative of c^n?

[sick torrent]

n

[coral pagoda]

Noo

[sick torrent]

Oh wait

[coral pagoda]

Think about what you said here

[sick torrent]

The power rule

[coral pagoda]

No...

[sick torrent]

Oh

[coral pagoda]

Think about it for a second.

[sick torrent]

n*c^n-1 ?

[coral pagoda]

No

[sick torrent]

Oh

[coral pagoda]

This paired with the fact that c^n is a constant tells us what?

[sand pawn]

Ok, I have a general query. We know from the Godel's incompleteness theorem, mathematics is incomplete and has serious flaws in it.

So my question is, Are scientists working to develop a new system/s of science which will overcome the limitations of Mathematics?

[sick torrent]

C is a constant?

[coral pagoda]

c^n is a CONSTANT, so what is the derivative of c^n?

[sick torrent]

0

I think

[coral pagoda]

It's not that math has flaws, it's that math is naturally imperfect. Unfortunately, it really isnt something that can be avoided, no matter how hard you try

[coral pagoda]

There ya go

[sick torrent]

Oh

So the answer is d

[sand pawn]

Ok. so what should be the solution that scientists come up with to deal with such imperfect nature of Maths?

[coral pagoda]

Hate to break it to ya, but there is no solution.

[sick torrent]

Thank u

[coral pagoda]

Because here's the thing: we can't ever guarantee where the inconsistencies of our axiomatic structure lies. So we can't fix what we don't know needs to be fixed.

Moreover, there are some claims that are just impossible to prove.

[sand pawn]

well, that is deep true. We will not know our fault until we know it

[coral pagoda]

But even then. Just because we find one issue does not mean we found them all

[alpine sable]

guys where is the general chat of this server?

[coral pagoda]

It is very possible that some of the million dollar questions literally cannot be proven.

[harsh belfry]

I would guess #events

[charred flint]

#discussion

[alpine sable]

ok

[harsh belfry]

ah i see

[coral pagoda]

No. Discussions and math discussions

Anyways, we will never know all of the issues of our axiomatic structure, and that is a certainty.

[sand pawn]

Maybe or not maybe. Even if, let's say we found some solutions to the million dollar problems, it may also break at some special condition. So maybe there's nothing certain called "The most general equation".

Ok, thanks for the explanation @coral pagoda

[alpine sable]

1+1 equals what?

[sand pawn]

In decimal system, "2"

[alpine sable]

oh my god

Such brain

[sand pawn]

BTW, you should see the Godel's incompleteness theorem and all it's related works. Then you will understand that even such a simple question "1+1=?" can be complicated to such extent barely imaginable

[alpine sable]

ok

I can manage to complicate any relationship easily

[coral pagoda]

Lol, not really. I think you might be giving the Godel's Incompleteness Theorem a little too much credit.
It is powerful, but it doesn't mean what we know is wrong. Far from it actually.

[alpine sable]

I’m sorry are you guys still speaking English

Math is the only subject I don’t completely ace every test in sadly

[coral pagoda]

Math is not easy

[alpine sable]

I understand that

[sand pawn]

I am not saying that we know wrong. We are right when we are limited to some conditions or contexts

[alpine sable]

you guys sound like you’re theorising the meaning of all existence and how it’s related to respiratory disease

[coral pagoda]

More or less honestly

[alpine sable]

okay

[sand pawn]

Thinking rationally is the way to success in mathematics. BTW, maths is also not that hard. It requires your utmost patience and perseverance and also a bit of logical thinking.

[inner sequoia]

help

what to do if multiple fractions are stacked

like (1/x/y)

[sand pawn]

Just say it here. Anyone will pick u up for help

[sand pawn]

Can you sent a photo of your problem here?

y/x maybe?

[drifting wadi]

depends what is dividing what

[coral pagoda]

No...this is something that is certainly wrong. Math is hard as f. Some topics can be understood more easily than others, but math as a whole is very difficult. Anyone who tells you different is lying.

[inner sequoia]

fucking negative exponents

[drifting wadi]

flip and make it positive

[inner sequoia]

what would be positive

[drifting wadi]

the power

so intead of ^-1 it would be ^1

after u flip

[sand pawn]

a^(4) * b^-(x+1) * c^(y-2)

[inner sequoia]

why would it be a^4

-1-3 = -4

[sand pawn]

It is under an inverse operation. Inverse it and there you have "4"

[inner sequoia]

so for ex
1/-4 = 4?

[sand pawn]

It depends. I will not also say Maths is easy af. If I say, I will be definitely lying

[sand pawn]

Nope

(a^-4)^(-1) = a^4

[inner sequoia]

oh shit

wait

i forgot about that

i forgot i didnt have to put the one over and could just multiply

thanks for pointing that out

lemme do it myself now and see if its right

[alpine sable]

Guys in my opinion in terms of hypixel level I think 4 is larger than 12

Am I correct?

[sand pawn]

No problem dude! First time in Maths? When you will go to college or High school and do some integrals... you will always face that awkward situation when you forget to put that "+C" after the indefinite integral. Always was a fact for me anyhow 😂

[inner sequoia]

yeah

[inner sequoia]

wait its not working

I got (a^4)(b^(-x-1))(c^(y-2))

is that correct

[sand pawn]

yes

That was the comment I wrote before

[inner sequoia]

so y-2 = 5?

[sand pawn]

I think you have done a mistake here. The answers should output as expression exponents. But the exponents are natural numbers

[inner sequoia]

i have this

[sand pawn]

Possibly "x,y,z" must have values. Please read your textbook question properly

[inner sequoia]

so how does that equation relate to ((a^4)(b^4))/c^5

[inner sequoia]

these are my choices

i have to find the value of x and y

[sand pawn]

Ok, this is making sense now

y-2=-5
-(x+1)= 4

(x,y)=(-5,-3)

[sand pawn]

@inner sequoia

[inner sequoia]

why is y-2=-5?

[sand pawn]

Because the number "c^5" divides the expression

Thus, when being expressed in exponent, the "-" sign appears

[inner sequoia]

where is c^4?

[inner sequoia]

but thats 5

not 4

[sand pawn]

Yep. I did a mistake there

[inner sequoia]

oh

OH

negative exponents divide

so multiplying by a number w/negative exponents is same as dividing by one with a positive exponent?

[alpine sable]

UNO

[sand pawn]

yes

BTW, both the base number has to be the same along their exponent

[inner sequoia]

yep i know

thank you so so much for the help

i finally understand

[sand pawn]

BTW buddy you really made me laugh after a long time

thanks for that

[coral pagoda]

Glad you got a kick out of it :)

[sand pawn]

After simplification, the '7a' terms will cancel out. Thus, the answer will not consist of anything in 'a' terms

[brisk sentinel]

Idk what the rule is

[wind jolt]

2 4 6 8  10 12
1 ? 9 25 49 81

argh

Alright, notice any pattern? specifically for the bottom row?

[alpine sable]

can anyone help my brother

im having exam

5(8)/(15)+1 (3)/(20)

[brisk sentinel]

ok so the top is going up in twos and the bottom is going up by 16, 24, 32

[wind jolt]

Hm. Good observation, Im looking for something else though

Does the bottom row remind you of any other sequences of numbers

[brisk sentinel]

like an equation?

[unborn ridge]

can i have help on these

[somber osprey]

what the fuck

[unborn ridge]

b c d

how do i make a decimal improper

[wind jolt]

I'm looking for a sequence here. Like the fibonacci sequence, 1 1 2 3 5 . . . Except this one isn't the fibonacci sequence, its a different one

[brisk sentinel]

Idk if i know the sequence I see a pattern

[wind jolt]

Do you know what a square number is?

[brisk sentinel]

yes

[wind jolt]

Okay. What do all the bottom numbers have in common?

[brisk sentinel]

so all the bottom row are square numbers

[unborn ridge]

isn't this just O=(E-3)^2

[wind jolt]

Yeah, exactly. So we know that somewhere in the list of steps to turn E into O, we need to square the number. Now there's one more step we need to take, and it might help to rewrite O now that we know its a sequence of square numbers

$E = 2, 4, 6, 8, 10, 12$

[ocean seal]

noah

[sand pawn]

Who ghost-pinged me here?

[thorn sundial]

do you guys know this?

[wind jolt]

$O = (-1)^2, 1^2, 3^2, 5^2, 7^2, 9^2$

[ocean seal]

noah

[sand pawn]

Just subtract that from 90°

[sand pawn]

Yes. See my above response

[brisk sentinel]

so I just need to find where E turns into O now?

[sand pawn]

What was your question?

[brisk sentinel]

Im trying to find the rule, and I know that some of the numbers in the group are square numbers

[sand pawn]

Well, you should find the "function" here. Why am I feeling this is a codeforce's programming problem?

[brisk sentinel]

idk what that is its for my WebWork hw

[sand pawn]

I think the function is f(n)=(n-3)^2

where 'n' is the even numbers

[brisk sentinel]

how did you find that

[sand pawn]

I am guessing this similarity in this pattern:

(12-3)^2= 81
(6-3)^2 = 9
(8-3)^2= 25
(10-3)^2 = 49
(2-3)^2 = 1

Thus by checking this guess, I concluded that the pattern will be "(n-3)^2"

[brisk sentinel]

so to find 3 you just asked yourself what (2-x)^2 = 1, and then figured out the pattern

[sand pawn]

I haven't did any algebra. I just ran some guess and check in my head

that's it

[brisk sentinel]

oh ok, well thank you

[fathom raptor]

hiii! im quite confused with my math worksheet. it's about the remainder theorem. the direction states, "use the remainder theorem to determine whether the number is a root of the given polynomial. show the complete solution of each item."

P(x) = x³ - 3x + 4 ; 4

do i have to change the sign of 4 or let it be and solve immediately?

[alpine sable]

breh

guys

i need help for my brother

i have an exam

5(8)/(15)+1 (3)/(20)

[sand pawn]

Just paste the image of the problem

[alpine sable]

Ok

[sand pawn]

someone will pick it up here

[alpine sable]

There

[sand pawn]

401/60

[alpine sable]

steps pls

[alpine sable]

Thx

[sand pawn]

"4" is a root of this cubic polynomial

[fathom raptor]

how so? i'm sorry ;;

[sand pawn]

My bad.. it is indeed a root. I just checked desmos for it

https://www.desmos.com/calculator/atxwjeunac

[split slate]

Why would this not be a function?

[ebon ore]

I need help

I wrote this

[split slate]

And also, is this the same as writing: f(x) = x^2 + y^2 = 49, -7 <= x <= 7?

[split slate]

Occupied help channel mate

[ebon ore]

it is about Christopher Columbus

[ebon ore]

ok

[split slate]

#❓how-to-get-help

[ebon ore]

ty

[fathom raptor]

i see, thank you!

[sand pawn]

Sorry, how are we suppose to help a geography student?

[sand pawn]

This is a function. I see no reason why it wouldn't be

[split slate]

From my answers

I mean, it's either a function or a relation

[gentle ingot]

If you graph it you'll see how it doesn't pass the vertical line test

If you dont know what that is then sorry in advance

[sand pawn]

BTW, isn't it a multi-variable function?

[gentle ingot]

I think so ye

[strong vapor]

Is this right?

[sand pawn]

So by 'zeroes' you mean the roots of an equation?

More explicitly, the 'x' intercepts?

[strong vapor]

Yung the quadratic function= ax2+bx+c form

Lmao where did the yung came from💀

[sand pawn]

Ok, so the zeroes are the roots of the quadratic equation?

[strong vapor]

Yup

That’s the one you will add and multiply

Ok thanks

But I think it should be like this

[sand pawn]

Sorry, Use it

Instead of the 'a' and 'b', put your 'zeroes'

[strong vapor]

Okkkk sure

[sand pawn]

That was your answer

[sand pawn]

BTW, have you did the full solution?

[fathom raptor]

yes. i'm on a different part of the worksheet now 👍 i got a remainder of 56 tho ;;

[brisk sentinel]

open chat?

[sand pawn]

Just input 4 in the function. If the output is nonzero, then the input is not the root

[fathom raptor]

yes, thank you!

[sand pawn]

Wdym?

[brisk sentinel]

i tried doing (infinity,4) and its getting mad

I know the pic is different

[sand pawn]

Can you give more details about your question?

[brisk sentinel]

The graphs of two functions, f and g are shown below. and that's all I got

[sand pawn]

Have you tried (4,4)?

[brisk sentinel]

i tried [4,4] for a and it says its incorect

the (-2,4) was correct for b

[sand pawn]

[4,4)

I am seeing use of 3rd brackets in coordinate geometry after a long time

[brisk sentinel]

When I try that it says "Single point intervals must use '[' and ']'"

[sand pawn]

I found the function f(x)=|x-1|+1

[brisk sentinel]

is that how I solve A?

??

[sand pawn]

yes

I am getting same results (-2,4) unfortunately

[brisk sentinel]

it says incorrect for a

😦

[sand pawn]

By the way, can you use union set operator for this? @brisk sentinel

[gentle ingot]

For a it should be (-inf,-2] U [4,inf) right?

[brisk sentinel]

it says "The left endpoint of an interval can't be positive infinity"

[gentle ingot]

Sorry I meant negative lol

[brisk sentinel]

Thank both of you so much!!!

[sand pawn]

Great job man

[cunning raven]

can someone tell me where I made mistake in the 2nd question? (h'(pi/3))

please @ me when respond

<@&286206848099549185>

[tight birch]

how do i write integrals with bounds in TeXIT?

,help

[ocean seal]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[dreamy rover]

You applied the wrong formula. It is (vdu - udv)/v²

[sweet vessel]

how do you find angle c and d???

[alpine sable]

The length of the sides of a brick is 20cm, 10cm, 4cm, the density of the material from which it is built is 2000 kg / m³, g = 9.81m / cm², to determine the force with which the brick acts on the table is placed A) on the side with smallest area B) With the largest

[shut goblet]

if i have a vector (2+a, -1+2a, -4) and a line (1+t, -t, 1-3t), how can i find the value of a so that the vector and the line are parallel?

[devout summit]

@cunning raven This is not quotient rule. You have applied quotient rule incorrectly.

[wicked urchin]

value of a in terms of t?

[shut goblet]

wdym

[devout summit]

$\left(\frac{f(x)}{g(x)}\right)'=\frac{f'(x)g(x)-g'(x)f(x)}{(g(x))^2}$

[ocean seal]

Euclid31415

[wicked urchin]

how do u tpye this

[devout summit]

Latex

[wicked urchin]

whats that

[devout summit]

Google it

[cunning raven]

thanks a lot for answering.

[cunning raven]

thanks a lot for answering

[formal spoke]

Can anyone help in questions 2

[sweet vessel]

<@&286206848099549185>

[fierce osprey]

I have a math test in a few hours and don’t know how to solve this question in my review. If someone could explain that would be great

[sweet vessel]

Multiply numerator and denominator with 3isqrt(-2)

Seems like that could work

[fierce osprey]

Yeah thats what we are supposed to do, but its more of idk how to multiply the denominator

[mint moth]

I think its just multiply numerator and denominator with √-2

[sweet vessel]

Oh actually yeah

[fierce osprey]

the answer is -5/3, she gives it to us so we can check our work

so however you are supposed to get that

[mint moth]

Welp i got 5/3

[warped holly]

can someone explain why is it the degree, lt, lc, and ct?

[alpine sable]

Degree: Highest power of the polynomial.
LT: Leading term of the polynomial.
LC: Leading coefficient of the polynomial.
CT: Constant term.

If you expand (3x+7)²(x³+x²-3x-1),
you get

,w expand (3x+7)²(x³+x²-3x-1)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Quod Erat Demonstrandum.#7284

[alpine sable]

@warped holly see the leading term (9x⁵).

[scarlet atlas]

help anyone pls

[warped holly]

wait how was it expanded tho

[vale wigeon]

@scarlet atlas channel busy please move

[scarlet atlas]

ok

[vale wigeon]

@warped holly you don't need to know the full expansion here

it appears all you care about is the leading and constant terms

and getting those from a product is very easy

you have (3x+7)(3x+7)(x^3 + x^2 - 3x - 1)

to get the leading term, take the leading terms from every parenthesis and multiply them

to get the constant term, take the constant terms from every parenthesis and multiply them

really that's it

[warped holly]

ohhh i got it

[alpine sable]

(3x+7)²(x³+x²-3x-1)
=(3x+7)(3x+7)(x³+x²-3x-1)
= Painful multiplication

[warped holly]

okay thanks will analyze this

[alpine sable]

Ann already did it, nice.

[warped holly]

how to get the constant term here?

[vale wigeon]

where do you think the constant term could possibly come from

[warped holly]

last term

[vale wigeon]

okay, so?

what's troubling you with doing that?

[warped holly]

i'm not sure of my answer

its puzzling me cus of the fraction

[vale wigeon]

what is your answer?

[warped holly]

i was thinking of 2x^2 / 7

[vale wigeon]

that's not a constant term

2x^2/7 has an x in it

how can it be a constant term

[warped holly]

oh yea, constant term doesnt have a variable

then i suppose its 3 / 7?

[vale wigeon]

yes of course it's 3/7.

[warped holly]

okay thanks got it

[thick lotus]

In Discrete Math, what does Lagranges theorem say about subgroups' size in a finite group

My take on it is that it just says that the order (size) of the subgroup divides the group, but does it say anything more than that?

[kindred hull]

Maybe ask in #discrete-math too if u haven’t already

[vale wigeon]

no, that's it.

[thick lotus]

Thanks!

[thick lotus]

I just dont get how Modulo works for polynomials

This is a solution to a question asking to find

what the solution to this is

and R is

[vale wigeon]

it works almost exactly the same as for numbers

you treat multiples of k(x) as zero

[thick lotus]

I got [x^4 + 1] just like they did

but i dont get how x^4 + 1 turns into the other thing

[vale wigeon]

what's k(x)?

[vale wigeon]

ah

so k(x) = x^3 + 2x + 2 = x^3 - x - 1

thus x^3 = x + 1 in your ring

[thick lotus]

..what haha

[vale wigeon]

remember your coefficients come from Z_3, right?

in Z_3, 2 is the same thing as -1.

[thick lotus]

Yeah

[vale wigeon]

so this shouldn't surprise you.

[thick lotus]

Err im not sure what happened there

you made them into -x -1 sure (not sure why but i get how u did it)

and then x^3 = x + 1 by putting them on the other side

[vale wigeon]

in R, k(x) is the same as zero

x^3 - x - 1 = 0

add x+1 to both sides

x^3 = x + 1

[thick lotus]

Oh dang..

So thats how you do it.. You just put the highest degree factor on one side and the rest on the other of the k(x)

[vale wigeon]

i mean that's not necessary

but personally i find that's the most convenient simplification route

[thick lotus]

And you do this whenever your result exceeds x^whatever that exponent is?

Would I do this for [x^3 + 1] as well for instance?

[vale wigeon]

sure

every element in R is equivalent modulo k(x) to some polynomial of degree at most 2

[thick lotus]

ah and the 2 comes frm the highest degree of k(x) being 3?

not that its in Z_3

right

[vale wigeon]

yes the 2 is a natural number, not the 2 from Z_3

[thick lotus]

Jesus this feels so much better now

ive been totally lost on this, kinda digging my head in the sand

Thank you so much Ann

So last question on that part

It asks if [x] is a primitive element

How do I find that out, I know a primitive element is basically just if it generates the group right?

[vale wigeon]

yes, you need it to generate the multiplicative group

[thick lotus]

How do I find that out?

If it is

[vale wigeon]

well in your case i would just evaluate the first few powers of it

where by evaluate i mean reduce them modulo k(x)

to see if you eventually hit all 26 polynomials in R

tho i think maybe it's enough to just do that for x^2 and x^13 to make sure neither one reduces to 1

well for x^2 it's obvious

,w x^13 mod (x^3 - x - 1)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[vale wigeon]

bruh

that didn't work

,w simplify x^13/(x^3-x-1)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[vale wigeon]

hmm..

looks like x^13 is equivalent to 1 in R after all

let's see

[wheat walrus]

help me with 1+1

[vale wigeon]

maybe i lied there

[tame falcon]

Stop trolling

[vale wigeon]

x^13
= x^11 + x^10
= x^10 + x^9 + x^8
= x^9 + 2x^8 + x^7
= 2x^8 + 2x^7 + x^6
= 2x^7 + 3x^6 + 2x^5
= 2x^7 + 2x^5
= 4x^5 + 2x^4
= x^5 + 2x^4
= 2x^4 + x^3 + x^2
= x^3 + 3x^2 + 2x
= x^3 + 2x
= 3x + 1
= 1

...

wtf

okay

so i was right after all

x^13 = 1

so x is NOT primitive

[cunning bolt]

Can somebody help me out with some math vectors on high school level?

I have the following information:
I know that the scalar product of vector a and b is 5 (a*b=5)
I also know the length of vector b is 2 (|b|=2)
I know angle v is 20 degrees (v=20°).

From the information above, I should find the length of vector a (|a|)

[vale wigeon]

$a \cdot b = |a| |b| \cos(v)$

[ocean seal]

Ann

[vale wigeon]

@cunning bolt

[cunning bolt]

hmm, can you maybe show it with numbers inserted?

@vale wigeon 😄 I don't know |a|

[wary stream]

Plug in the values you know and use algebra to fithe missing one

[cunning bolt]

So like this?

$|a|=\frac{2}{cos(20)}$

[ocean seal]

Juia

[wary stream]

Close

[cunning bolt]

damm

[wary stream]

You forgot about |b|

[cunning bolt]

ahh i see 🤣

[vale wigeon]

but you do know everything else

[wary stream]

Wait not b

a * b

You forgot that

[cunning bolt]

thats the scalar product right?

[wary stream]

Yes

[cunning bolt]

so like this:

$5=\frac{2}{cos(20)}$

[ocean seal]

Juia

[cunning bolt]

Then a would be:

$a=2,49$

[ocean seal]

Juia

[wary stream]

No

[cunning bolt]

Then can you help me 😅

[wary stream]

Why is 5 on that side?

[cunning bolt]

Because:
I know that the scalar product of vector a and b is 5 (a*b=5)

[wary stream]

Use this information, plug in what you know

You know |b|, v, and a * b

[cunning bolt]

yes

$a \cdot b = |a| |b| \cos(v)$

[ocean seal]

Juia

[wary stream]

So plug in what you know

[cunning bolt]

$5 = |a| |2| \cos(20)$

[ocean seal]

Juia

[cunning bolt]

like so?

[wary stream]

Yes

[cunning bolt]

Then a is 2,501523861

[wary stream]

You typed that into your calculator incorrectly because I'm not getting that value

[cunning bolt]

What calculator do you use?

[wary stream]

You realize that you typed 2

Not 20

[cunning bolt]

damm, by bad.

[wary stream]

As I said, you typed it in incorrectly

[cunning bolt]

Now I am getting:
a = 2,660444431

[wary stream]

Yes

[cunning bolt]

Okay 👍
Thanks for the help! Now I will write it up 😄

[lapis valley]

is this correct

sorry my brain is not workign rn

[agile compass]

Seems correct

[lapis valley]

how about this

[languid basalt]

I have everything correct but I have no idea how “z” was solved, I was only writing notes down. Can anyone explain?

[abstract glade]

You simply use the Pythagorean theorem

[languid basalt]

K cool but idk how I got those variables

Where’d the 7 come from

I get 13, not 7

[wary stream]

That 7 might suppose to be a z

[languid basalt]

Oh lol

Lol thanks

One more question

Where’s the 2 from

[abstract glade]

i've got no idea

[languid basalt]

Do you think it’s also a variable?

[wary stream]

I think you created the ratio incorrectly

No, having two unknowns in that ratio makes it much harder to solve

[languid basalt]

So how would I actually write it?

I just realized the answer is right, but not the work

[wary stream]

In both triangles, what is the hypotenuse?

The smaller triangle and larger triangle

[languid basalt]

Z and Y

[wary stream]

No

Z is not a hypotenuse

[languid basalt]

Oh it’s 13

[wary stream]

Yes

[languid basalt]

My bad 😥

[wary stream]

Now what side relates to z?

[languid basalt]

Y

[wary stream]

Not exactly

The side z is a leg in the large triangle

What's the corresponding leg in the small triangle?

[languid basalt]

6

[wary stream]

Yes

Do you think you can create the ratio from there?

[languid basalt]

Yes

Thank you for your help

[zenith spruce]

can someone help me with advanced math

[inner rose]

how advanced??

is there a specific question

[high scaffold]

Only albert einstein can solve that advance

[inner rose]

haha

[zenith spruce]

yes

[inner rose]

send it, ill see if i can do it or not

[zenith spruce]

k

55x9(16)-4x1=

gulp

imma gonna fail my classes

[wary stream]

Use a calculator

Order of operations

[inner rose]

yes this

[zenith spruce]

your never gonna learn from a calculator cause u dont need to do anything

[inner rose]

and that

[wary stream]

PEMDAS

Or BODMAS

[zenith spruce]

sigh fine ill use a calc

[inner rose]

use PEMDAS or BODMAS, it would be pretty direct

[wary stream]

Same thing as PEMDAS

But brackets, order, division, etc

Because other countries use the term brackets instead of parentheses

Order instead of exponents

Yes, same meaning

[zenith spruce]

what is 1+1

[wary stream]

Don't ask troll questions

[zenith spruce]

sigh fine

k this isnt a troll question i actually need help

39/50 + 1/50 =

[inner rose]

since denominators are equal, u can simply add the numerators

[zenith spruce]

wha-

i need to pay attention in class more dont i

[inner rose]

yes

[zenith spruce]

i have no idea

[zenith spruce]

what any of that means

[inner rose]

numerators are numbers in top of the fraction

[zenith spruce]

ok

[inner rose]

and denominators are numbers which are in the bottom of the fractions

so if its like 1/2

[wary stream]

https://m.youtube.com/watch?v=MCuvUHsy4m4

That's unlike denominators though

[zenith spruce]

ok

[wary stream]

But you have to get a common denominator to add

[zenith spruce]

😕

[wary stream]

There

[high scaffold]

7916

[zenith spruce]

alredy got it

[zenith spruce]

thx

[wary stream]

Did you have a specific question for this?

[inner rose]

@wary stream still no help 😦

[wary stream]

Time zone issue then. More people who help are active at different times because they live in different countries

[inner rose]

okay

[zenith spruce]

I GOT THE ANSWER

i think

[high scaffold]

That's true

[wary stream]

You literally just add the numerators

Follow the graphic I sent

[zenith spruce]

40/50?

[wary stream]

Yes

[high scaffold]

No

[wary stream]

But you can simplify

[zenith spruce]

.

oh

[high scaffold]

Divide that with 2

[wary stream]

Yes, but not simplified

[zenith spruce]

0.4

[high scaffold]

No

[zenith spruce]

well @wary stream said it was 40/50 so

[wary stream]

And there is a larger common term that is better to use

[wary stream]

But not simplified

[zenith spruce]

all what matters is i have the answer?

[jade token]

If the answer isn't simplified, it's also kind of wrong

[high scaffold]

Still you have to simply for that answer

[jade token]

would you rather I write 3 as 3 or 1+1+1?

[zenith spruce]

1+1+1

[wary stream]

The solutions from books, teachers, etc prefer a simplified solution but 40/50 is correct

[jade token]

or even worse 0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1+0.1

yeah

[zenith spruce]

so i was correct

[jade token]

yep

[zenith spruce]

thats all that matters

right?

[jade token]

It depends

If you were writing this on a test, you may be marked wrong for not simplifying it

[wary stream]

Yes, it's correct. Can you not read what I've been saying?

[zenith spruce]

@jade token been confusing me

[high scaffold]

@zenith spruce

[wary stream]

It's correct but not simplified

[wary stream]

Don't do the work for them

[high scaffold]

Okay

[jade token]

What I'm saying is that while it's technically correct, it's not simplified, so you may be marked wrong on a test.

[wary stream]

The concept was GCM of 40 and 50

[wary stream]

Teachers aren't cruel enough to mark it wrong, they'll take a few points off

But not mark completely wrong

[jade token]

yeah, if it were being marked by hand. I just have math contest PTSD

[wary stream]

As long as process is correct and you have the proper outcome value, a non simplified answer is valid

[jade token]

yeah, but a contest which isn't marked by hand, such as the AIME, you're asked to submit the answer in like numerator + denominator

and once I forgot to simplify

and sillied a question

[wary stream]

That's on the software side. Sites that auto grade are coded by humans and humans normally forget about the case of equivalent solutions

[jade token]

It's on Bubble paper

like each answer you have 3 bubbling boxes from 0-9

so the answer goes from 000-999

and it's automatically marked

to speed up the process

Canadian contests are different luckily

but US contests are crazy imo

[wary stream]

Did you not read what I said? Unsimplified solutions are correct but normally they expect a simplified solution

So problems like that expect a simplified solution

[jade token]

yeah, I'm agreeing with you lol

just to clarify, I'm trying to agree with what you're saying lol

[narrow carbon]

Hello, is it possible to compare two compound interest without any principal amount given?

[tight birch]

how do i make a trigo function wider?

what do i do with the function

[wary stream]

Changing the frequency value

[tight birch]

how? say i have sin(x)

[wary stream]

That's the general form of a sin function

[tight birch]

ohhh i see thanks thanks

[wary stream]

sin(x) means A = 1, B = 1, C = 0, and D = 0

Changing B will change the frequency

[tight birch]

yep yep, that image is exactly what i need. graci!

wait follow up question. can i write the components of this piecewise function as trigo functions or no

they seem too "circular" for me to rather than "wavy"

i know that the best way is to write them as semicircles but i am curious how do i distinguish semicricles from trigo waves

coz they look very similar

nvm i think i figured it out

[wary stream]

Trig functions look more wavy than that

[tight birch]

think its the change in slopes

[wary stream]

Notice how a sine wave has noticeable peaks and valleys?

[tight birch]

yep. and i noticed that the max slopes are at different points too

thanks btw 👋

[alpine sable]

hello can anayome help me

[dim oasis]

Quite possibly

[wary stream]

No, no one in a math help server can help you with a math question that you did not post \s

[alpine sable]

ok

[alpine sable]

i have to Write down the numbers in scientific ways

[dim oasis]

,rotate

[alpine sable]

i dont understand it

[wary stream]

https://www.youtube.com/watch?v=_BtzXojuM1o&ab_channel=TheOrganicChemistryTutor

The first like 10 minutes, maybe more is good

[alpine sable]

help

[wary stream]

Slope equation
$$m = \frac{y_2 - y_1}{x_2 - x_1}$$

[dim oasis]

A good way to find the gradient there is to find two spots where the line crosses integer points

[ocean seal]

dldh06

[alpine sable]

can u tell me only the first one pls

[wary stream]

No

I gave you a resource, use it

Understand it

Then come back

[dim oasis]

You can see that the line goes through the points (0, -1) and (6, 1); use that with the slope formula
@alpine sable

[wary stream]

If you don't have the knowledge, learn it first to understand what it is

[alpine sable]

wait so how do i solve it again???

[wary stream]

Then come back if it still confused you

[alpine sable]

they dont give me any points

but i dont know english

im from albania

[dim oasis]

They do, you just need to look for them in the graph

[wary stream]

Find two points that intercept the line, as lex mentioned

[wary stream]

Then look up resources in your own language

Like "writing numbers in scientific notation"

[rose glade]

hi i got question how he get that equation

he multiply both side by 2?

[wary stream]

Yes

[rose glade]

oh thanks

The trigonometric function is sometimes more complicated than I think

[dim oasis]

Sure thing

[wary stream]

https://www.youtube.com/watch?v=2DPivVFCdqA&ab_channel=KhanAcademy

Resource

Simple as that

[dim oasis]

Or that okay

Getting to 1-on-1 with someone to help them would be fun but I guess we’re just googling for people

[wary stream]

Learning by text is bit more difficult to understand, sending a video with worked examples is easier

[dim oasis]

I’d do it the same way Sal Khan does so I guess it’s up to you

[wary stream]

Then if the person still doesn't understand then help more

[rose glade]

need help

to search, we need to put a minus on the value of X?

(-x)^3-cos(-x)

(-x)^3+cosx

then wa we can do

[wary stream]

Look up other resources

Google is your friend

[placid steeple]

need help

i have no idea how to solve this one

[small bear]

They made a slight error. n=1999! not x. Can you solve it using that?

[fading scroll]

1999! Factorial?

[prisma mountain]

how does k^2 + 4k + 4 become (k+2)^2 ?

would it not be (k+2)(k+2)?

[dim oasis]

It’s a squared binomial

It is (k+2)(k+2)

[prisma mountain]

somehow my prof got to the first way

im confused

[dim oasis]

Since it’s the same thing multiplied by itself, you can write it as itself ^2

[prisma mountain]

yeah thats what i figured

however when u expand (k+2)^2, it becomes K^2+4 no?

[placid steeple]

you doin quadratics too? Lol

[dim oasis]

Nope, that would be (k+2)(k-2)

[prisma mountain]

nah this is post calc 2, third year, but some stupid basic shit

[placid steeple]

oh lol

[dim oasis]

(k+2)^2 is k^2 + 2k + 2k + 4, or k^2 + 4k + 4

[placid steeple]

i am sick and tired of maths tbh

cant wrap my head around these stuff

[prisma mountain]

i see, so the way she did it makes sense after all

guess i was mistaking my expansion

[dim oasis]

Yeah she just factored the expansion

[prisma mountain]

was overthinking it, makes sense thanks

[dim oasis]

k^2 + 4 is a difference of squares, where the factors would have opposite signs

[wary stream]

You wrote this wrong

It’s k^2 - 4

[dim oasis]

[prisma mountain]

wait but then wouldnt the initial expansion need to be different?

as in, (k+2)(k+2) cant become K^2-4

[dim oasis]

$(k+2)^2 = k^2 + 4k + 4$

[ocean seal]

lexitorius

[placid steeple]

$h

[prisma mountain]

yeah im trolling with my expansion i guess

was just applying the square to each item in the brackets

thats clearly wrong..

[wary stream]

Because $$(k+2)^2=(k+2)(k+2)$$

[ocean seal]

dldh06

[wary stream]

Then FOIL

[dim oasis]

Foil is kinda dum but it works

[prisma mountain]

yeah my mistake was thinking $$(k+2)^2=(k^2 + 4)$$

[ocean seal]

Blood (사드)

[dim oasis]

Pascal’s triangle is where it’s at

[placid steeple]

(K+2)^2 = K^2 + 4 + 4K

[wary stream]

FOIL is the mnemonic for distribution when multiplying 2 binomials

[dim oasis]

I know what it is lol

[placid steeple]

$$(K+2)^2 = K^2 + 4 + 4K$$

[ocean seal]

brishtu2828™

[placid steeple]

wow this works amazing

[prisma mountain]

yeah got it, simple brain fog to clear up, thanks

[wary stream]

We established this, also don’t interrupt an occupied channel

And use #bots for latex testing

[dim oasis]

Or #latex-testing

[placid steeple]

@wary stream help bro

[wary stream]

Or #latex-testing

[wary stream]

No

[dim oasis]

Idm tho, I’m glad you’re interested in writing with latex brish

[wary stream]

Because you pinged me for help and interrupted an occupied channel