help-0

[mint fulcrum]

yeah

[ashen anchor]

you can always just say 2.718 = e - epsilon

[keen mulch]

Why would you ever change e to a decimal if not told too?

[placid zinc]

If the assignment says to use 2.718, do that

[mint fulcrum]

yeah, but i'm saying leaving it as e is more accurate

because it never said to use 2.718

[placid zinc]

Do whatever your teacher wants, at the end of the day, haha

[mint fulcrum]

yeah

[placid zinc]

But if they want e, they want e

[upbeat wing]

yeah true, but anyway i solved it by taking e=2.718 so

[keen mulch]

Why would you change e to a decimal

[placid zinc]

Yeah that's not a usual thing to do. Get used to not using a decimal approx for e in future classes

[gray isle]

and what sort of calc are you using to evaluate 2.718^490

[ashen anchor]

im just gonna leave that there

[mint fulcrum]

approx. sign is key

[upbeat wing]

i wanted to give like an numeric ans

[alpine sable]

I see no point in this discussion to be honest.

[ashen anchor]

me too LOL

[keen mulch]

Only change to a decimal if asked. Otherwise the final answer will be an approximation not an exact value

[ashen anchor]

but why truncate before an operation?

that carries your truncation errors throughout the operation

compounding it

once again. (approx) = (true) - epsilon.

taking large powers will severely reduce accuracy since that (true - epsilon) term gets taken to a large power

[keen mulch]

I mean change to a decimal at the final answer

Only if asked to answer in a decimal ofc

[keen mulch]

If you’re replying to me

[ashen anchor]

not you

original people who asked haha

[karmic yarrow]

Is there an effective way to solve for d?

I know that 13 and 60 are rel prime, so there has to be some value d that works

[ashen anchor]

where did 13 come from?

[stoic widget]

anyone knows how to do this? my answers are all wrong ;-;

[north needle]

Isn’t the first one just subbing in 2 second for t

[light sleet]

Btw for order of operations

with the 2^5 for example

what is it just muliplication

if so in what way?

[toxic dock]

i mean, youd have to simplify it

but its

2x2x2x2x2

so 3x2x2x2x2x2

because exponents are how many times something is multiplying itself

does that make sense

[light sleet]

Hmmm Alright

ty

[toxic dock]

ye

[prisma adder]

Can anyone help in proving a strongly equivalent metric?

[light sleet]

alright so uh

What did I do wrong? D:

[sour dove]

Remember pemdas (or bedmas)!

I think you added before multiplying

[jovial forum]

How do i solve

[light sleet]

You're right, I did, tell me what do I multiply and add so I wont get jumbled please

[jovial forum]

How do i solve 4x^3 + 4y=0 and 4y^3 +4x =0 using substitution?

[light sleet]

This chat is occupied

[sour dove]

Follow the pemdas step by step.
B is brackets. The only one I see that needs computation is [8 - (4-9)] which is [8 - (-5)] which is [8 +5] which is [13].
Now exponent. The only one I see is 2^5, which is 32.
Now what you're left with is
[3x32 +13x(-2)] + 7[13].

[toxic dock]

@sour dovedude you should be paid for this

you're working overtime..

[sour dove]

Next is MD, which is multiplication and division, which have the same importance. So you go from left to right if you see anything not clear (ex: 36/2. We do 36 which is 18, then divide by 2,which is 9)

[sour dove]

Ain't that the dream Lmao.

I really love teaching peeps so I like doing this :)

[sour dove]

So with that we have 3x32, which is 96.
13 x -2, which is 26.
7 x 13, which is 91.
So it's now [96 - 26] +91.

So now is addition and subtraction, same rule applies as the above.
So 96 - 26 is 70.
And 70 + 91 is 161.

@light sleet does that all make sense?

[light sleet]

Yes, now It does, tysm for your help sir!

[toxic dock]

I hear you, I'm a high-school math tutor lol

check out GoPeer

[light sleet]

dude i have 20 bucks rn If I was right next to him I'd give it to him for helping

[toxic dock]

alright well there are online forms of payment so don't say it if you don't mean it!

[light sleet]

¯_(ツ)_/¯

[shut sleet]

How do you solve x using quadratics formula(if possible)

[toxic dock]

so im thinking you should calculate the scale factor and equate them to eachother

in this case, (x + 5) / x = ((x+2)+6)/6

so i put the bigger shapes lengths over the smaller shapes lengths

and the scale factor you get from the big base over small base should equate the big side over small side

which allows you to solve for x

[sour dove]

I'm doing the same next semester, except for my local community College (well, for CS but I'm going to try to squeeze math too if they'll let me lol)

And thanks I'll check it out!

[toxic dock]

of course! i think if you search up gopeer melody on google i come up

im melody p

you get a good amt of students

$20/hr and you get to keep it all

[sour dove]

Oh dang

[toxic dock]

whats your major?

can you follow this?

do you know how to "complete the square"??

quite literally

ratio of big:small

[ashen anchor]

was this a typo?

[toxic dock]

which part..

do you want me to explain in a vc

[civic yacht]

Given (𝑥) = d + cx where ∈ ℝ (𝑥 member of Real numbers), and (−1) = 1 and
(1) = 7. Determine:
a. C and D values ​​
b. Function Form (𝑥)
c. The value of N , if g(𝑛) = 13
d. Range if domain {0,2,4}
can someone help im a bit confuse on this one

[ashen anchor]

it just looks like you added wrong... unless im way too sleepy to see right

wouldnt the similarity condition be

(x+5)/x = (x+8)/6

[toxic dock]

yes but i was sure you could add 6+2

[civic yacht]

ty

[toxic dock]

i wanted to show how i was combining the two lengths to create the value of the big length

[iron temple]

sin130 = ?

[toxic dock]

do you have a calculator

[iron temple]

no

[toxic dock]

okay go to google

and type exactly that

YEPPPP

[iron temple]

I wonder how it came out of me

[alpine sable]

Is it a question from book or your own fantasy?

[toxic dock]

you have to be in college i think

[iron temple]

book

[toxic dock]

and you input your info, etc

check them out

[ashen anchor]

it still just looks like a typo. I didn't want the student to get the wrong idea

[iron temple]

i have test in shcool

i havenot calculator

[toxic dock]

it's definitely not, thanks though

@ashen anchor

[alpine sable]

Then try to use sin(a+b) or sin(a-b) multiple times or try cos(x±y) since sin(c) = cos(90°-c).

hope this channel aint occupied

oh nvm

[toxic dock]

aight you know SOHCAHTOA

[ashen anchor]

(x+6) + 8/6 is not the same thing as (x+8)/6

[toxic dock]

its (x + 2) + 6

which is the same as x + 8

[ashen anchor]

incorrect usage of parentheses then.

[toxic dock]

no its not

LMAO

(x + 2 ) is a portion of the big side, 6 is the remainder and also the small side

you add those together

getting x + 8 which he knows how to do im sure

all over the small side, 6

please go away

[ashen anchor]

im severely confused

[rocky silo]

Why cannot 5(n^2+2) be a perfect square. I get that n^2 + 2 is not divisible by 5. But what does it have to do with 5()

[toxic dock]

are you the student who asked?

[iron temple]

guys downloand photomath best app for math

[ashen anchor]

no, i'm just making sure the student doesn't get led astray by an ambiguous math statement

[iron temple]

took photo and this program solve your problem

my english is very bad

sorry

i am from Georgia

[toxic dock]

it's not ambiguous, I was making sure he wasn't confused with a side length that didn't exist

[alpine sable]

@iron temple Try this.
sin(130°) = cos(50°)
cos(150°) is known (same as sin(30°)) and then use
cos(3x).

[toxic dock]

i think you're just bored, and if he was confused, he would've made it known

[iron temple]

sin130 = cos(180-50) ?

[ashen anchor]

or a lack of answer due to confusion and too scared to seem dumb or not even seeing your answer yet. You're overly hostile over this

[quaint trout]

Consider the prime factorization of a perfect square. It must consist only of even powers of primes. So, 5(n^2 +2) will have an odd power for 5 since 5 does not divide n^2 + 2, so it is not a perfect square. Channel otherwise occupied, so ask elsewhere if you need more help.

[toxic dock]

dude that is the answer

you just have to multiply both sides of the equation by 6x

move the terms to one side

and solve as a quadratic

[iron temple]

guys where are u from

?

[toxic dock]

like you arent the student, whats the point

[ashen anchor]

because i care about the student understanding

[toxic dock]

no one else pointed anything out, and the other volunteer tutor answered the same way

in ratio form

[iron temple]

i am 13 yo

😡

[toxic dock]

stop talking if youre not asking questions

about math

[iron temple]

u are devil

[ashen anchor]

okay ms hostile :p you still had a typo that could lead a student astray

while the other tutor was unambiguously correct

[alpine sable]

No, sin(130°) = cos(90°-130°).

i think this channel is free

cuz i dont understand anyth on what they said

[magic geyser]

it doesn't specify if it's a right angle triangle

[alpine sable]

it says unique triangles so im guessing every triange

or normal

[ashen anchor]

i mean to me, it just looks like one can be drawn

[magic geyser]

Well can't 88 be the hypothenusa?

[ashen anchor]

fair point

[magic geyser]

question is unclear for me

been decennia long since I have done geometry (trigonometry) lol

[ashen anchor]

eh there's probably an elegant method that im not thinking about since i havent done this in a while

[ashen anchor]

exactly hah

[ashen anchor]

something makes me think that this would violate the sine rule, but that's just a random hunch from me

[sour dove]

Sorry this is late, I was catchimg up, but I actually agree with @toxic dock here. Although the final numerator on the right hand side is x + 8, in reality it's (x +2) +6, and then that's all Over the larger base value of 6.

I think that's a bit more clear on showing what's going on. Looks like it got heated though lol

O think there was a

[ashen anchor]

sdf

excuse me

she actually changed her typo that she so adamantly said she didn't make (without even apologizing for getting so needlessly aggressive towards me LOL)

[ashen anchor]

so gonna have to call cap on this. I agree with yall's final answers tho. I was simply just calling out a typo

[jovial forum]

How do I find the values valid values for x and y for
4x^3 + 4y = 0
4y^3 + 4x = 0

feeling really dumb

[ashen anchor]

substitution?

[jovial forum]

Can you show me how?

[ashen anchor]

sure thing

ill take a stab at it

[jovial forum]

thanks, that would be great

[shut sleet]

thanks , i will try that

[jovial forum]

Oh thanks, I get that

I'll do some more practice questions with this as a reference

[ashen anchor]

actually, are complex answers allowed?

like the complex number i?

i assumed you needed reals

[raw shard]

those would be some very complex numbers then lol

[ashen anchor]

yup! which is why i ignored it in the first place kek

[toxic dock]

Someone here thinks my explanation was confusing, let me know if you would like me to get in a vc and explain

[shut sleet]

ok

[ashen anchor]

nobody said that, you just made a typo that you fixed. it's all good now

[shut sleet]

cheers mate

[small gale]

pls find any of the red angles

there are four of them

this is killing my brain

[ashen anchor]

that 120 degrees is referring to the yellow angle AEC?

[toxic dock]

30 deg

If you pay attention to the other triangles , they’re also 30 30 120

[small gale]

wait

yellow lines have been given degrees

red ones are not found

[ashen anchor]

wonderful, what exactly have you tried so far

[small gale]

all these angles are found

i can't make any more progress

heck it was in my exam today

i filled 30° lel

which seems correct

but idk how

to get to the answer

[toxic dock]

So

See how the red by the 120

Is a right angle

Top angle is 30

180 - 90 - 30

The right top red angle

Would be 60

Added to 30, it’s complimentary angle underneath

And then the last red angle would also be in the middle small triangle, measuring 30

[small gale]

but how can we say that

it wasn't mentioned in the question

[toxic dock]

If it were mentioned, it’d be giving you the measure

[ashen anchor]

its under an implicit assumption that ED is parallel to BC

[toxic dock]

Since the angle on the right is 90 deg

And that

Since they’re similar shapes

The angle measures are the same

[small gale]

ye if they were parallel i would have chosen angle BCE = angle DEC

alternate interior

[ashen anchor]

you got it!

did you make that parallel assumption on the exam?

if not, i can see why things were difficult

then again, there's probably some information tucked away in that picture that implicates the parallel nature but im too lazy to find it

so i just assumed

[small gale]

no it was mcq test

i just picked 30

[ashen anchor]

oh by random :p

[small gale]

all others were wrong

[small gale]

ye lel

but

there were four options

60, 65, 45, 30

60, 65 are clearly not correct

[ashen anchor]

well now you know why it has to be 30 from her answer above

[small gale]

exterior angle property

so i had to make a guess between 30 and 45

45 was looking way too big for that tiny angle so i went for 30

lel

[ashen anchor]

LOL you're going to become an engineer :p

[small gale]

xD

[ashen anchor]

just to make sure, you understand now right?

her solution was pretty thorough

[toxic dock]

And I got my right angle by his explanation of the triangle AED being similar (same angle measures) as triangle ABC

I think the kid should be fine

[small gale]

you said it was 90 by the looks of it right

[toxic dock]

Mhm, assuming the top triangle base line is parallel to the whole triangle base

[small gale]

i see

well, our teacher will explain anyway

thanks for help !!

[toxic dock]

🙃

[ashen anchor]

good luck

[small gale]

thanks

:)

[near falcon]

how do I find the arc length of a sector

[ashen anchor]

if you know the radius,r, and the measure of the angle in radians, theta.

arc length = r x theta

that x just means multiply, not the variable x

[near falcon]

erm, whats a theta

[toxic dock]

Or in baby terms, what fraction of the circle do you have? Actual Degrees/360

Multiply that by the circumference of the circle

[near falcon]

144/360

[toxic dock]

Now multiply that by the circumference equation

@alpine sable uh oh no no

[near falcon]

if 12 is the radius, so 24 is the diameter and the circumference would be, 75.36 and then multiply 2/5

[toxic dock]

Exactly

@near falcon

[near falcon]

ok

[toxic dock]

Since you are only looking for 2/5 of the circle, mult that by total circ which you calculated to be 75.36

Good job

[near falcon]

😄

[toxic dock]

:)

[near falcon]

math is very confusing yet fun

[toxic dock]

So fun

[whole mango]

is there someone free for a question?

😃 thanks

[ashen anchor]

fire away

[whole mango]

how can i solve that equation?

[ashen anchor]

do you need an algebraic solution or just the numeric answer?

[whole mango]

i d like to understand how to solve it

[ashen anchor]

there are many ways. using algebra or even just graphing both sides and seeing where they intersect

[toxic dock]

Mind if I take over? @ashen anchor

It looks fun

[ashen anchor]

its not a race

if you have an answer, say it

[near falcon]

lol

[whole mango]

sure, give a minute

expand or not?

[toxic dock]

I’m going to take over.. let me draw it up for you

[rustic knot]

Let R be the radius of the circumscribed circle in the triangle ABC. Ask for the following:

c=R, When B=20° )=A

[toxic dock]

I don’t think the attitude is necessary

[whole mango]

ok imma try

[near falcon]

[whole mango]

what man

i got some like x^9 + 1 + 3x^6 + 3x^3 = ..

[alpine sable]

Can someone tell me the answer?

[whole mango]

i think times plus the first

[toxic dock]

so an exponent is how many times you multiply something

right?

like 2^3 is 2x2x2

[whole mango]

yeah @toxic dock

[toxic dock]

well the base term is (x^3 + 1)

so that's being multiplied by itself 3 times

you basically foil

[alpine sable]

Nothing works lol

[toxic dock]

and then foil again

so let me show you

[ashen anchor]

i can guarantee at least 2 more real solutions

might be a pain to find tho

[whole mango]

that shuold be the solutoin

[ashen anchor]

at least 2 more REAL solutions

there will definitely be some complex

when you find one of those remaining reals, apply some symmetry of the cubic equation and the second should fall out

uh... by definition?

[toxic dock]

LMAOAOA IAHSKSHDIDND

[ashen anchor]

yeah the pesky part is getting those last 2 remaining reals

we got lucky with there being an integer solution

how did you get those?

calculator or algebra?

i understand, but i think the student wants to know how to solve

[ionic jewel]

I know this is basic and all but why is that a thing ? i don't understand how we move the denominator of the opposites like this. Can someone explain like im 5

[echo grove]

The common denominator is basically 6, so you multiply the left one by 2 and the right one by 3. That way, both are over 6

And you can get rid of the fraction

[ashen anchor]

nvm

i actually solved it

@whole mango

just factoring

wasnt that hard

i overestimated the problem and was just like screw it

so anyway i started factoring

with the knowledge that i am expecting a real quadratic to pop out. i also used some calculators to help

and then complex nonsense after

my pattern was (linear)(quadratic)(nonesense)

so i factored into that form

[ashen anchor]

[ionic jewel]

But there is no denominator where did it go xd

This is what i mean. Why isn't it like this ? I think im too stupid to do math

[ashen anchor]

you're not stupid

Blue explained already but maybe hearing again that you need to multiply both sides by 6 should help?

and you choose 6 since its the smallest number that 2 and 3 can divide into

[alpine sable]

Square root of 16 is 4 is it rational or irrational?

[ashen anchor]

is that question effectively... "is 4 rational"?

in that case, yes 4 is rational

since 4 = 4/1

[ionic jewel]

Uhhhh imma drop out this ain't for me thanks anyway

[alpine sable]

yes

[ashen anchor]

ill try to explain in writing

[alpine sable]

Square root of 55 is 7.4162

Is it rational or irrational?

[ashen anchor]

@ionic jewel

[ionic jewel]

Ohhhhhhhhhhhhhhhhhh i see now

[alpine sable]

@alpine sable so for my question here

It's rational

?

[ashen anchor]

do you really see it now? i guess just visually seeing it was key haha

[alpine sable]

what

[ionic jewel]

Yeah yeah i do. Its kinda annoying how 1 min ago i couldn't even comprehend how it works

[ashen anchor]

i would say that sqrt(55) is irrational since the decimal numbers continue without pattern

[ionic jewel]

Yeah i don't understand it that way

[alpine sable]

How then?

[quaint trout]

The squareroot of a natural number is rational iff it is a perfect square. So the squareroot of a natural number can either be a natural number or it is irrational

[ashen anchor]

the lack of pattern in the decimals implies that there are no two integers that can be divided to give it

[alpine sable]

Square root of 49 is 7 so it's probably a rational number right?

[ashen anchor]

you cheeky :p

i should really say integers

[alpine sable]

Square root of 49 is 7 so it's probably a rational number right?

Right?

[ashen anchor]

it most definitely is rational

good job

[alpine sable]

Square root of 64 is 8 it's rational

Square root of 1 is 1 it's rational right

[ashen anchor]

1 is rational yes

[alpine sable]

can someone help me here lol

[quaint trout]

I will help you with one of them to explain how you should do it. So you want to find the two consecutive perfect squares around 18, that would be 16 and 25. So
16 < 18 < 25 then
4 < sqrt(18) < 5

[tired drum]

|x-3| >(and equal to) 4+x how would you do this?

[quaint trout]

Consider cases. Case 1) x-3 >= 0
Case 2) x-3 < 0

You can simplify the absolute value in different ways for the two cases

[tired drum]

Lol i dunno how to do the symbol

[tired drum]

Wait so what happens to 4+x?

[quaint trout]

You leave it as is

So if x-3 >= 0

Then |x-3| = x-3

So it becomes x-3 >= 4+x

[tired drum]

I thought your supposed to bring everything to one side and find 2 cases for x

[quaint trout]

You don't have to do anything. You can do anything that works. I think this is the easiest way.

[tired drum]

Wait so i complete ignore the 4+x?

[quaint trout]

You don't ignore it

I am saying we consider two possibilities

[tired drum]

Wait hold can you send me your working lol, it’d probably be easier for me to understand

[quaint trout]

|x-3| can be equal to x-3 or it can be equal to -(x-3) depending on the value of x.

That's how absolute value is defined

So that gives us two different inequalities

x-3 >= 4+x and -(x-3) >= 4+x

You have to solve both

[tired drum]

Mhm yeah I got that much

but the x’s cancel out

[quaint trout]

Yes, so the first inequality has no solution

Since it says -3 >= 4 which is false

[tired drum]

Wait so assume this was true, what would the value of x be since it’s been cancelled out?

Would it be 0?

[opal reef]

what order does the associative property and distributive properties go in?

[quaint trout]

No, it has no value

You want all x that satisfies x-3 >= x+4 but this is not true for any x

So no x satisfies the inequality

[tired drum]

So we completely ignore case 1? And follow through with case 2?

[quaint trout]

Yes, you say that case 1 has no solutions

Then consider case 2

[tired drum]

Alright thanks

[quaint trout]

But also note

[tired drum]

?

[quaint trout]

That case 1 holds when x-3 >= 0 and case 2 holds when x-3 < 0. So when you solve the second case, you have to add the restriction that x-3 < 0

[tired drum]

Alright gotcha, so it has to satisfy case 1 as well right?

[quaint trout]

No, we're done with case 1. Case 1 has no solutions.

[tired drum]

Then wdym by adding the restriction that x-3<0?

[quaint trout]

Now you need to find the x that simultaneously satisfies -(x-3) >= x+4 and x-3 < 0

Solve the first inequality and tell me what you get

[tired drum]

Oh yeah thats what I meant

Kk

[quaint trout]

Okay

[tired drum]

Got x < (and equal to) 1/2 for case 2

[quaint trout]

No

[tired drum]

Thats wrong?

Oh wait

It’s x < (and equal to) -1/2 for case 2

[quaint trout]

Yes

Now, for this question, it works out okay

But let's say that we got x < 5

Then we are saying x = 4 is a solution

But case 2 only applied when x < 3

So we shouldn't consider any numbers larger than 3

So we want the simultaneous solution of x < 5 and x < 3, which is x < 3

[tired drum]

Mhm

[quaint trout]

But in this case, it is x < -1/2 and x < 3 which just simplifies to x < -1/2

Since everything smaller than -1/2 is smaller than 3 anyway

[tired drum]

so final solution is x < (and equal to) -1/2 since it satisfies both the inequalities right?

[quaint trout]

Yes

[tired drum]

Alright thanks for all the help

[stone scroll]

How can I solve this? Thanks

[fast oak]

If f(x)=x^2+9 and g(x)=x-9, find f(x)/g(x)

how

how u get that?

ohh i know now

[alpine sable]

can someone answer/help me

[fast oak]

how to solve it

use calculator @alpine sable

[stoic parrot]

do you know how to find square roots??

if not then, you can think of it as

4^2 = 16

[alpine sable]

No calculator for it

[alpine sable]

I know how to simplify

But how do you find the nearest perfect square

[stoic parrot]

hmm

[alpine sable]

For ant number

Any*

[stoic parrot]

see their method once

maybe youll understand

🙂

[fast oak]

(x^2+9)/(x-9) i simplify it??

[stoic parrot]

cant be simplified i guess

[fast oak]

so i need foil method?

[stoic parrot]

foil method?

ahh i see

[fast oak]

(x^2+9)/(x-9) i dont know to solve this

[stoic parrot]

its the simplest form

if it was x^2 - 9 then it couldve been factorised

but even then the denominator will remain

[fast oak]

ok i try

wait

there a multichoises

[stoic parrot]

oh

so what're the options?

[fast oak]

so the answer is (x^2+9)/(x-9)

A. x B. x^2-x C. (x-9)/(x^2+9) D.(x^2+9)/(x-9)

[alpine sable]

#1 is 3 and 4 and 4 and 5

I'm I right?

[fast oak]

If f(x)=x^2+9 and g(x)=x-9, find f(x)/g(x)
this is the given

[stoic parrot]

Ans is D

[fast oak]

ok ty

[stoic parrot]

so you want to say: answer for number 1 is 3 & 4 and for question number 4 its 4 and 5??

[solar pebble]

quantum mechanics questions belong here?

[alpine sable]

No

[alpine sable]

Wrong

[solar pebble]

lol its not a whether you want it, its a whether it is within the scope of the server

[ashen anchor]

i def wont be able to answer but shoot your shot, I'm sure someone will know

also he was being sarcastic... i think haha

[solar pebble]

Alright

Coloumbs Law is k * q1q2/r^2

Why is one r of the r^2 lost when its an operator of a wave function

[forest jacinth]

Never took quantum mechanics, but my guess from a couple of searches and basic electrical engineering would be that Coulomb's Law doesn't work because there is no such thing as forces in quantum mechanics, so you are left with calculating potential energy of a charge, calculated as W=Qt*V (noting Qt as a test charge and V as potential of a charge). If you take a reference point that is far away, the potential of a point charge will be V = k *Q/r

[ashen anchor]

i've never done quantum but I do know that forces wont work so you best bet is potential energy stuff

[forest jacinth]

Basically, one of the terms of distance will be lost while deriving the formula for potential of a point charge

[ashen anchor]

hey wtf

we said the same thing LOL

[solar pebble]

AH

I have a force

I want the energy

[forest jacinth]

Good to know that our ideas are similar lol

[ashen anchor]

other than that... i have 0 idea. I hope you figure it out tho. good luck!

[solar pebble]

thanks

[timid dome]

Can someone please enlighten me with this exercice

we set for x > 0, f(x) = (x+1)/x
1) let y > x, compare f(x) and f(y)
2) compare 98576,597/98576,596 and 98576,598/98576,597

[forest jacinth]

If you need a more formal proof of why you lose one of the terms, I can give you one

[fast oak]

f(x)=2x+4 g(x)=3x^2-1
find f(x)*g(x)

[vague coral]

it's just a multiplication

[fast oak]

here my answer

6x^3-2x+12x^2-4

do i need to swap it

6x^3+12x^2-2x-4?

[vale wigeon]

no, you don't "need to" do anything

you can swap the x^2 and x terms if you want

you can also not

[fast oak]

but in my multiple choise

i know now

[alpine sable]

No.

[lethal dock]

Is $(4a³ - 10a² + 6a) ÷ 2a$ simplified as $2a² - 5a + 3$?

[ocean seal]

JUGisMUG🎃

[alpine sable]

Yes.

[lethal dock]

Alright thanks

[alpine sable]

Not just thanks. Gimme a million dollars for that. 🖐️

[lethal dock]

Am broke af

[alpine sable]

Go code something cool and then gimme 1 million.

[alpine sable]

But don't forget you owe me a million xD.

[timid dome]

1/x will be greater than 1/y

[lethal dock]

[timid dome]

so f(x) : (1+1)/x > 1/y + 1/x

so (x+1)/x > 1/y + 1 wich is 1/y + y/y = (1 + y)/y

[solar pebble]

$y>x \leftrightarrow y-x>0 \leftrightarrow \frac {y+1}{y} - \frac{x+1}{x} = \frac{1}{y} - \frac{1}{x} < 0 \rightarrow x \to \infty, f(x) \to 1$

[ocean seal]

Xetrov

[solar pebble]

arrows didn't work but oh well

[timid dome]

oh yeah thanks !

yeah exactly thnx!

[alpine sable]

Could someone please help me understand what's happening here?

This was the question

OH

wait
It's (A-lambda(i))v = 0

I think

[glass lichen]

Yes

You find eigenvectors from finding a basis of [A-tI|0]

[alpine sable]

oh, it says it right there

I should probably learn what the word basis means

[glass lichen]

Independent spanning set

[alpine sable]

Question.

Linear Algebra has got me thinking on how to put 3D space onto my PC, right?

What happens if I build an engine based on Linear Algebra but then throw calculus into the mix?

Can I even do that?

[glass lichen]

Here the basis is just {[1,1]^T}

[alpine sable]

@alpine sable You're doing Eigenvectors already? Damn. . . We are only on chapter 2.2, lol.

[glass lichen]

This all eigenvectors for t=9 are given by the span of [1,1]

[alpine sable]

I'm in my 4th year of uni and there's a maths module, and I didn't do A-level maths
Not in the greatest of places right now

Thanks, I'm going to have to look a lot of this stuff up

Because I've missed a lot

@alpine sable Bro, I empathize so hard. . . .

My life has been a sequence of escaping abuse via bad habits and screwing up in school ,lol.

[glass lichen]

That sounds like multivariate calc with more words..

[alpine sable]

@glass lichen Ooooh.

[tight birch]

how do i write this in set notation?

is this correct?

[near falcon]

whats a decimeter, decameter,hectameter exactly

[glass lichen]

Metric units

[near falcon]

I know they are metric units but how big in comparison to a meter and centimeter are they

[glass lichen]

Milli centi deci base deca hecto kilo

[tight birch]

Is it correct to use the Union symbol or just "and/or" ?

[glass lichen]

No, use and

[tight birch]

okay okay thanks

[near falcon]

so they are 10x the one before them?

[glass lichen]

Well or

They're metric so yes

[near falcon]

how many kilometers are in a mile

[glass lichen]

Google it

[outer vector]

about 1.6ish

[elder glacier]

quick question say in a proof about perfect squares, am I able to assume that perfect squares end in 0,1,4,5,6 or 9. Or must I also prove that using modulo proof?

[civic yacht]

10 dm = 1m
1dam = 10m
1 hm = 100m

[near falcon]

you call them dam?

[civic yacht]

ye atleast in my country

idk what to call it in english

its short for decameter

[near falcon]

My mother told me that decimeter = dm decameter = Dm

just the capilization difference

[civic yacht]

ok

[wary stream]

1.609 km per 1 mile

[fiery crest]

of course wolfram won't show me the steps for this

[primal ether]

expand the denominator

[fiery crest]

-1 + 1 +2j

[primal ether]

then "realise" the fraction by multiplying by its conjugate

[fiery crest]

2j

what conjugate

if all i have is 2j

0+2j * 0-2j?

[primal ether]

the conjugate of a+bi is a-bi so

multiply by -2j

top and bottom of fraction

[fiery crest]

-2j/4

I

m still left with a j

[primal ether]

do you know how to get the argument of a complex

[fiery crest]

obviously not

[primal ether]

do you know argand diagrams

[fiery crest]

nop

[primal ether]

is this more mechanics than pure maths?

-2j/4 simplifies to -j/2

[fiery crest]

yeah and what does -j/2 tell me

[wary stream]

It's a complex number

[fiery crest]

Yes I could tell that much

but how does this equal -pi/2

[wary stream]

Euler's formula

I think

[primal ether]

the argument is the angle it makes (in radians) with the positive x-axis

[wary stream]

Don't post in an occupied channel

[fiery crest]

3 people are literally saying different things rn

[primal ether]

if you plot -i/2 on an argand diagram it looks like this

then the angle it makes with the positive x-axis is -90 degrees which is -pi/2 in radians

[fiery crest]

wtf is an argand diagram

can't I just use my calculator to tan it?

[primal ether]

ok

you can tan it but you need to know its position in an argand diagram surely?

[fiery crest]

no

[elder glacier]

if you dont know its position via quadrants and just tan it, you'll prob end up missing a negative, or have the wrong complementary angle

always good to draw a small diagram when finding arg

[fathom quail]

pls help

[maiden meadow]

A plane flying horizontally at an altitude of 1 mi and a speed of 500 mph passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when the plane is 2 mi away from the station.

pls help

[arctic wren]

Is this integration correct ?

$\int{\frac{450}{x+8} - 25} = 450ln(|x+8|) - 25x +c $

$\int{\frac{450}{x+8} - 25} = 450ln(|x+8|) - 25x +c $

[devout summit]

$\int\frac{450}{x+8}-25,dx=450\ln|x+8|-25x+C$

[ocean seal]

Euclid31415

[arctic wren]

ty

[mortal lark]

Hi

Need some help

[devout summit]

And yes it is correct btw

[mortal lark]

Could u give a hint

Of how to do it?

[arctic wren]

ty again, so my book answer is wrong

[mortal lark]

Thw first question

The*

Any1?

[late parcel]

How do I do 52

[mortal lark]

What 52

[mortal lark]

Mind help me first?

[arctic wren]

guys

read the rules

[alpine sable]

IDK doubling equation. Should I go with the traditional way?

[arctic wren]

and

#❓how-to-get-help

#rules

[devout summit]

Setup two linear equations and solve for their individual prices and then find what the question is asking

[late parcel]

Sorry I thought nobody was goi g to help you

[mortal lark]

Any way without algebra?

[fringe turret]

<@&286206848099549185> im confused what will i do

[devout summit]

No I suppose.

[oak chasm]

@fringe turret Sorry, this channel is busy. Please don't ping Helpers until 15 minutes after you post your question.

[fringe turret]

oh alright im sorry

[alpine sable]

I can’t read your writing for 54

[mortal lark]

Hmmm. It says there is suppose to be no algebra

[hearty quail]

?

is this in use?

[vagrant cobalt]

$x-y>0, x^4-y^4= (x-y)(x+y)(x^2+y^2)$

makes sense?

[ocean seal]

usernamephobic

[devout summit]

Woah then you are supposed to do it mentally?

[hearty quail]

yea

[vagrant cobalt]

^^isn't that just unitary methods?

[hearty quail]

?

[vagrant cobalt]

not you

it was occupied, but you got your answer.

[devout summit]

Unitary method? With two quantities?

[hearty quail]

i dont really get it then i guess

[devout summit]

Or well you could use the fact x^4 is an increasing function for x>0

[vagrant cobalt]

$x-y>0 \implies x^4-y^4>0 \implies x^4>y^4$
from previous factorization

[ocean seal]

usernamephobic

[mortal lark]

Not sure

[fresh parcel]

isnt that kind of obvious though

[hearty quail]

i just started proofs calm down

[fresh parcel]

ok

[hearty quail]

can you explain how that proves the statement?

i understand x-y>0

[austere violet]

Hi all, need a little help with this question

[devout summit]

Each of the factors (x-y), (x+y) and (x^2+y^2) are positive separately. So, multiplying them gives a positive quantity

[hearty quail]

oh

[fresh parcel]

and then you can rearrange it to say that x^4 = y^4 plus some amount

[hearty quail]

haha

yea i get it

[noble sinew]

x+y>0, x^2+y^2>0. Product of positive numbers are ...?

[alpine sable]

Asian needs help?!

[hearty quail]

positive

[noble sinew]

so now we just proved it

[alpine sable]

In which grade are you in mate?

[mortal lark]

Hmm.

[mortal lark]

Help me answer this

[fresh parcel]

hi is this channel open

[mortal lark]

No

Not really

[fresh parcel]

alr

[alpine sable]

Which one?

[mortal lark]

First

[alpine sable]

4 Kg halim costs 53 taka.
Implies,
1 Kg halim costs 53/4 taka.
Therefore,
10 Kg halim costs 53/4*10 taka.

[mortal lark]

Uf it was that easy

[alpine sable]

Yes sir.

But it's incomplete.

[mortal lark]

There is jalipi

[alpine sable]

Complete it further.

[alpine sable]

Do it yourself.

[mortal lark]

Hmm

But the thing is

The cost of jalapi and halim is combined

[alpine sable]

Find cost of 1 Kg jalapi and then add them.

[mortal lark]

4kg haram and 3 kg = 53 tk
5kg jalapi and 2 kg halim = 37 tk

[alpine sable]

Oh wait,

[mortal lark]

How does this even help me?

[alpine sable]

I interpreted the question incorrectly.

My bad.

[mortal lark]

Yeah...

Okay

Lemme try

[alpine sable]

3j + 4h = 53
5j + 2h = 37

[devout summit]

But isn’t that basically algebra?

[alpine sable]

Yes.

[mortal lark]

But in math terms it is mental maths

These questions weird

U have to find j and h mentally

[alpine sable]

is there an easier way to find a factor of 12/6 rather then going through each equation. i genuinely cannot find a start factor for this equation. pls help

[austere violet]

yes pls

been stuck on this problem for a while arghh

[alpine sable]

You're really Asian?

[austere violet]

yeah xd

[devout summit]

Which sub part are you stuck at?

[alpine sable]

Oh, which country if I may ask?

[austere violet]

erm mainly part c but im not sure whether i got a and b correctly so might as well ask all

[austere violet]

hong kong

[alpine sable]

Why awake so late? Is it a due test?

[vagrant cobalt]

..

[devout summit]

(a) would be just multiplying probabilities 0.55 and 0.72

[austere violet]

just clearing some assignments and lecture videos

[fresh parcel]

but what if he passes the english course

and then passes the math course

[devout summit]

That is assuming he already passed English…

Ok let me analyse properly

[fresh parcel]

yeah but if he passes first then the chance of passing math increases to 0.63

oh okay

[acoustic topaz]

can someone tell collinearity formula

i have exam coming up

[glass lichen]

Google

[alpine sable]

P(M|E) = P(M•E)/P(E) = 0.63
=> P(M•E)/0.72 = 0.63
=> P(M•E) = 0.63*0.72

[fresh parcel]

yeah

[alpine sable]

That's a constant ig.

[fresh parcel]

i didnt learn measure theory ;-;

[austere violet]

so 0.55 already included that john passes the math exam when he passes the english course?

[acoustic topaz]

ok

[dry jacinth]

Any pointers as to how to proceed from (a) to (b)?

oops cut off some of the question

... respectively converge to on the interval (0, 2π).

[devout summit]

Sorry mb I made a mistake

[vagrant cobalt]

did you find the fourier series?

[dry jacinth]

for f

for g

Ignore the k, that would be infinity but I was having fun using Desmos

[vagrant cobalt]

,w sin(nx-n\pi)

[dry jacinth]

I'll note that for the first one I used a "trick" by shifting it in input/output to get a pure sine series

[vagrant cobalt]

is sin(nx-n\pi) = (-1)^n sin(nx)

[dry jacinth]

Otherwise the fourier series would've been a horrible mess of sines + cosines

[vagrant cobalt]

hmm.. seems like a horrible mess, unfortunately I dont wanna write anything on paper, sorry

[dry jacinth]

that's alright, and yes, I think that equation is true if you do some quick algebra with the sine of a sum formula

hm

Yeah, from there I recovered that the first summation is (pi - x)/2 and I think I can now use that to massage something out of the fourier series for g

Since it has -pi * sin(nx)/n

That observation was helpful thank you

[sullen imp]

Is this sequence convergent?

It's limit is e^(-1/2)

But online calculators say it is divergent for some reason

[alpine sable]

Guys how do i do this i cant do it

[sullen imp]

Channel is occupied

Go to another one which is free

[sullen imp]

<@&286206848099549185>

[remote heron]

let me try for a sec

i have doubts

[sullen imp]

Ok thx

[remote heron]

i dont have as much time as i wanted but i feel like your best bet is gonna be monotone convergence

its trivial to bound this below, then just show its decreasing

thats the rough part but it shouldnt be impossible i think?

im just on a new machine and my tablet isnt fully set up, its messing with my workflow

although new to analysis and stuff so grain of salt

my guess is convergence but probably not bad to show

alternatively since you seem to know the limit you could try it directly but i have doubts about the algebra :p

[fringe shoal]

I can't seem to figure how to start this one

I tried doing a proof by assumption and working backwards but that got me stuck

[wild marten]

umm h(t) is the composite of 2 functions

[crisp grove]

u do know that f*g~FG

[fringe shoal]

yes

[crisp grove]

work backwards because the forward and backward transformation are not that different

[alpine sable]

Can some one help me for the 22 question

[remote heron]

for which problem

[remote heron]

which?

[alpine sable]

the first one

[remote heron]

do you know what the problem is asking?

can you say it in words

you dont have to, just to be sure

[alpine sable]

you see that N up in th number 3

[jade token]

I guess it's find what n is

[alpine sable]

jes

[remote heron]

okay

[jade token]

So 3^n=27

[alpine sable]

jes

[remote heron]

I'd say try some numbers

[jade token]

Log both sides

By 3

[remote heron]

the answer is to use logs

but you dont need to here

[jade token]

n=log_3(27)=3

[remote heron]

just try like

3^0, 3^1, 3^2, ...

[alpine sable]

im in 9th grade btw

[jade token]

Yeah you could also do that because the numbers are small

In which country?

[alpine sable]

albania

[jade token]

Different countries have different curriculums

Hmm

[lucid cedar]

@remote heron would you be willing to hop on the vc? I have a question which is kinda hard to formulate through text
sorry for asking in the middle of someone's question

[jade token]

Have you guys covered Logarithms?

[remote heron]

😳

hmm i can try, i switched to windows to use onenote but my audio driver is all kinds of fucked up

i might not be able to hear you

[lucid cedar]

aiight

[alpine sable]

so do you know my question

its ok if u dont know

[jade token]

Ah, what do you usually use?

[alpine sable]

3 to the power of what number would give 27

or think of it like this how many 3’s multiplied give an answer of 27

so this is how you do it

yes

the answer is 9

right

[jade token]

@alpine sable not quite

[alpine sable]

sorry

its okay

look

[jade token]

How many times 3 is multiplied together to get 27

[alpine sable]

9

[jade token]

Don't worry, it's not a problem if you don't get a math concept at first

As in like 3*3*3*3*3*3...etc

Whoops

[alpine sable]

no that would be correct if question was asking $3 * n = 27$

[ocean seal]

şaka şaka

[jade token]

I wish I ha a texer rn

Oh there's TeXit

Nice

[alpine sable]

so how do i write the answer

[alpine sable]

when there is a little number on top it means how many times the big number is multiplied by itself

ooooo

i think i get it

[jade token]

So how many times 333...etc

Little annoying

[alpine sable]

so how many 3’s multiplied by itself is $3^2$

[ocean seal]

şaka şaka

[alpine sable]

3

[jade token]

Yeah

[alpine sable]

ok thnx guys

[alpine sable]

ye thats answer for n

[jade token]

Yeah so 3*3*3 is 27

👍

[alpine sable]

what about the second one

[alpine sable]

.

https://cdn.discordapp.com/attachments/490557019623915520/899692192782766083/20211018_181509.jpg

[oak chasm]

How many 5s multiplied together is 125?

[manic loom]

Reduce all bases to the same number, then cancel them out and equalize the exponents

[alpine sable]

i dont understand much english

im from albania sorry

[jade token]

So how many 5s multiplied together will give 125m

So what's 5x5

Also he's in grade 9

He's just learning exponents

Go easy on him

[alpine sable]

its 25

[jade token]

Awesome

Now what's 25*5?

[alpine sable]

75

nono

125

[manic loom]

@alpine sable Are you just learning exponents or are you learning exponential functions?

[alpine sable]

what is exponents

[manic loom]

Oh lol

Alright

[oak chasm]

@alpine sable Right, so you multiplied three 5s together, so 125 = 5 · 5 · 5 = 5³.

[alpine sable]

ou

[jade token]

Ok, so 3 5s multiplied together or 5^3=125

[oak chasm]

OK, so write:

5ⁿ⁺² = 125
5ⁿ⁺² = 5³

[jade token]

So n+2=3

So what's n?

[alpine sable]

i have to find n

[alpine sable]

i think its 1

nooooo

its 4

[oak chasm]

No, if n is 1, then 5ⁿ⁺² = 5¹⁺² = 5³.

n = 1 is correct.

[alpine sable]

really

[jade token]

No it's 1

[alpine sable]

first think what power of n would give 125

[jade token]

1 is right

Yep!

[oak chasm]

@alpine sable We're not doing powers of n, we're doing powers of 5.

[alpine sable]

no i have to find n

[oak chasm]

You already did.

[alpine sable]

ye i wrote wrong

ok

[oak chasm]

Here ^

[alpine sable]

i didnt understand your question

i got it wrong

1 is right

ok

u understand how u got answer right?

jes i think

what about the 3rd one

https://cdn.discordapp.com/attachments/490557019623915520/899692192782766083/20211018_181509.jpg

how much is 6/6/6/6/6/6/6/6/6/6

[hollow hill]

Hi

cansomeone help me

?

[alpine sable]

hello

umm do you mind if they help me for this question its the last one

[oak chasm]

@hollow hill Find a channel that people just said they're done with the channel or that the last timestamp is more than 30 minutes ago.

[alpine sable]

have u been taught this before in class

[alpine sable]

jes

[oak chasm]

@alpine sable If you multiply 9 copies of 6 together and then you multiply 5 more copies of 6 together, you get 14 copies of 6 multiplied together, right?

[alpine sable]

ok i got it

the n is 14

i think

yes

so what do u have now

ok

the last one

d

wait ur not done with that question

ok

i did it the n was 14

what do u have then

th last one

whats the base that is to the power of 14

https://cdn.discordapp.com/attachments/490557019623915520/899692192782766083/20211018_181509.jpg

d.

c isnt finished

ok

[alpine sable]

^

[vagrant cobalt]

n=6

[alpine sable]

How does this work I was absent for todays class can anyone help by any chance>?

[alpine sable]

you mean to d.

question

[alpine sable]

i dont know th base

how do i find it

you use the same base as the two numbers that were being multiplied had

so 6

so u have $6^{14}$

[ocean seal]

şaka şaka

[alpine sable]

but question c wants the base to be 36

i dont get it

[jade token]

Ok so, 36=6x6

[alpine sable]

jes

[jade token]

So you can essentially split 36^7 into 6^7*6^7

=6^14

[alpine sable]

question c asks you how many copies of $36$ give the same result as (9 copies of 6 + 5 copies of 6)