#help-0
1 messages Ā· Page 843 of 1
$\left(p^5\right)^{10}=p^{5\cdot :10}$
eggdog
eggdog
That is when you take the power to another power.im talking about multipliying /dividing terms with powers
ok
yea thats different stuff
And yes you will get negative numbers when add/subtract the powers .BUT negative powers just mean that they are the reciprocal of the positive power term
@hidden fjord basically i dont like to hit rules at you but since you get the idea this will be true:
$:a^{-b}=\frac{1}{a^b}$
i should stop doing that
Yep
$:a^{-b}=\frac{1}{a^b}$
What bro š
eggdog
bye
i cant believe u taught me more than my lazy math teacher in a week
in that one problem
eggdog
yes
eggdog
fr
i had a bad algebra teacher
homie, have a great day/night, if I could pay u back I would. ur the best
have a good one!
dont crosspost
Ok so....you note the critical values first.but since the question specifically asks about 1(one).that's the only critical value .we gotta worry about here
For the a)part atleast
@minor dagger you there?
Yes
Hmm so now you approch value 1 for the left side and from the right side using limits
Hope you know those right?
Left limit and right limit?
Oh wait you just wanted b part nvm š
Well if you knew that g was continuous at x=3 ,then Left limit at x=3 and the Right limit at x=3 and the function value at x= 3,all must be equal
Get three equations and play algebra with them ,and you get c.and I hope you know how to do that?
Or just two equations .Idk.BUT either way you should be able to solve for c
Oh .ok š.process slowly and concretely .should be able to get it
In which equation did you input it tho?
Do you Voice chat?
If you comfortable with dat?
The square root equation
Bro ,you are actually right .well done
Thank you, I have one more question
I need help with c
@proven heart
Is there a channel for physics?
if an integer k is divisible by 5, then ?
then k is also divisible by ten(?)
yeah sure. you could write it as the set of integers k such that k = 10n
it says that its wrong T_T
10n, where n in Z
tyyyy
Can anyone help with c and d Iāve already done a and b
hi I need help with doing 3n[(2n^2+7n-8)+(-2n^2+3n)] please show work its not for a test its just I have trouble timesing the equation because my parent was drunk and my brother was tired and high so he just rushed it
,w 0.82^6
Should I just repost mine since it got clogged up
,w
i gave you the answers
is this something divided by 20C16?
Oh I didnāt even notice ty
The bottom answer is for question c right?
d
Don't give out answers
Is there any difference in how a function is read when it is phrased like this?
that's just a different way of saying inverse of f(x)
Shouldnāt the new graph be translated 1 unit left and 2 units up?
Oh
So you do read it the same way
Sorry read it the same way as what?
as a normal function
I was confused as if you would read it any different based on how it's written in the question
i have no idea how to ddo this can i get some help please?
While usually it is f(x)=x, it is written as y = f(x)
F(x) and y can be interchanged
you can use diamond method
Like y=x and f(x)=x is the same thing
yeah but how can you read a graph when you just have y=y
f(x) as written is y too no?
sorry?
that's what I thought at first
Y=y wouldnāt be a function
thanks
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yeah many ways
thanks
Why would you ever phrase a function like y=f(x) then?
Itās just for simplicityās sake
Just naming one variable the output of another function
So instead of writing f(x) every time you just write y
Why not just write y=x lol
Also it helps to visualize in an xy- Cartesian plane
Because thatās what it is
F(x) is still a variable
okay but y=f(x) literally means f(x) = f(x) no?
A function f(x) that is dependent on the inputs of x
y = f(x) means that the y-coordinate is a function of x, you don't take for granted that y is just f(x)
It's used for graphing a function f(x) in a cartesian plane
^
When doing things in higher R^n space you can set the function equal to z, for example, for xyz-space
So instead f(x) = y, you can have z = f(x)
For now just think of them as equivalent though
I dont understand the application of the concept at all; you can graph a function already in its normal f(x) form
that expression is to tell you y is a function of x
there are properties for a function, for example there's only 1 y value for every x in its domain
and you can think of other analysis like taking derivative of y w.r.t x
I think thatās called injective
Yeah I think i'm definetely confused; the way I understand what ure saying rn is that for this question, for example, you would put the function in this shape
and I know that's not it because it's not letting me do that lol
Oh wait
I think I got it
What that question is asking is what happens when you transform the function by some scalar
In this case -1
I have a formula sheet which might help @fervent cairn
so just this?
When you graph f(x), you graph a collection of points over the cartesian plane where y=f(x) at every point. That's what is usually used for graphing one variable functions, but there are other type of curves that can be graphed on the cartesian plane. For example, both x and y coordinates can be a function of some parameter t -> x=f(t), y=g(t), that would create a curve too, where y is not a function of x
So kinda like piecewise functions?
Where it just has certain, different, specifications for the what the function is
ye a different specification
Do you understand why theyāve used f(x)?
Yes, they're specifying that the Y values are the input
and the X values are the output
while in standard form it means that
i dont know how to get started
also can someone verify here? this question only has one attempt so I wanna be sure
I think the point (-5,-3) needs to be come (-5,3)
yes, -f(x) is just f(x) with the opposite sign
Can someone explain in simple terms why a volume of a sphere is 88/21 r^3?
itās 4/3(pi)r^3
But if you take pi=22/7 it becomes 88/21
:/
I donāt think thereās an easy proof that doesnāt involve calculus
Could u uh try to explain and Iāll ask if I donāt get what uāre saying?
Johnny Ball discusses Archimedes and the volume of a sphere.
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Maybe you can check out this video
This isnāt calculus as far as I know
Have you made a start?
Do you know how to start it
Factor using whichever method you know
Wait now it introduces that a cone is 1/3 of cylinder
Iām now confused
How does that work?
Well itās like a 3-d version of triangle
Triangle is 1/2 of rectangle
And cone is 1/3 of cylinder
okay
so this triangle is in 3d space
i have the x/y/z coordinates of all of the vertices on the triangle
but only the x/y coordinate of that blue dot
how do i find its z coordinate
it just does ig
dont think abt it too hard
i dont think they know the method....
how to solve DE?
I think you need to find the magnitude of the complex number (I'm not sure what the correct terminology is)
But you figure out exactly what's inside the absolute value bars (magnitude) or whatever
Something like that?
hiiiii do you guys know the equation for this sequence
seems like +5 then -10 then +5 then -10
how do i write that as an equation?
use the 0/0 rule
L'Hospital's Rule
when both numerator and denominator are 0 on lim then use L'Hospital
clyda what makes you think its .278 rad? Don't you get arctan(0)?
16-16 = 0
its not 0/0
112-112=0
It is 0/0 lol
ok i misread the problem
i thought it was 28x
ill see myself out
can't deal with the shame
you differentiate both
.
need help tho.
decimal places
Itās because
the top is not (x-4)^2 lmfao
Wait what
freshmans dream moment
damn bro Iām forgetting this shit
this is precal right?
,w limit as x approaches 4 of arctan((x^2-16)/(7x^2-28x))
look, it is literally arctan(2/7)
if theres an issue with putting in arctan(2/7)
thats an issue with the program
not you
arctan(2/7) should be correct
What program are you using
It should have like a symbol box or something
In the on screen keyboard maybe
His problem is inputting into his program
how do i work this one out
If youāre taking a calculus class, you can use limits, so make the left-side limit at 7 and right-side limit at 7 equal to each other

@upbeat gorge thats actually what i tired but it didnt work
Find the value of p and a if 2x^4 -+ px^3 + qx -4 leaves a remainder of 36x + 32 when it is divided by x^2 -2x - 3
Show your solution
Help mešš
@upbeat gorgei did, i put c=7 and it showed as wrong
no working because i dont know how to get the answer, so i wanna know how do i work this out
Donāt get confused by the notation of the hint
Youāre looking at $\lim_{x\rightarrow7^-}f(x)=\lim_{x\rightarrow7^+}f(x)=f(7)$
CST
can someone help me with this one
Yep
Thx beluga jr
Np artist Hecker
Lol
What is āwithout doing the math?ā
I mean mental math will tell you 5 cents pretty quick, because 1.05 is a dollar more than 5 cents and the total is 1.10 with a difference of 1
But thatās still doing the math. Any method of solving would technically be math
how is it not .10 cause .10 plus 1 dolla
Because that would make the total $1.20, which is 10 cents too much
So we know we need 10 cents less, or 5 cents less on each
So 0.05 + 1.05 works
lemme read over this iām still confused š
@cursive crescent OK YES I SEE! THABK YOU!!!!
No problemo
@cursive crescent i read it as your adding plus the ball is that good or is it flawed ?
How do I calculate this?
what is the meaning of C we use in the bottom of a integral
does it is a representation or we can put any equation there
the c denotes the limit right if we are doing it for circle and remove the c we can write it from 0 to 2Ļ
C is the curve
"curve" being whatever path we're taking the integral over
@feral merlin
hello
poisson distribution then binomial
@jovial edge
Oh
So we use Poisson distribution for determining the probability that a lift will be unacceptable
And then use that probability in a binomial distribution
yes, it says the number of breakdowns is poisson distributd
Can someone please help my understand why in part e: r = (1+0.004)^12 when the Q states that itās compounded monthly?

Anyone can help with the lesson "Evaulate limits graphically"?
thought it is 2 * acb?
apparently its not 80
no idea
can some1 pls help me

@placid zinc ok so its just a represntation right it just mean curve
AOB is an isosceles
a1 = 180-90-40=50
2AOB = ACB
AOB = 20
OAB = OBA
180 - 20 = 2OAB
But if i want to remove the integral and write it in normal form can like for a circle
I cam write the limits from 0 to 2Ļ

oab is not 80
already tried it
maybe answers wrong?
should be
@placid zinc i mean this

it was 50
So AOB = 80?
But then 2AOB dosent equal ACB
Am i missing something?
no idea
Do you know the change in y and change in x
Iām 12
any1?
nu
Q+2
thx
Moin
With what
hlp meh
x position in point 1 is 6 x point in point 2 is -2
-2-6 = -8
x position in point 1 is 8 y point in point 2 is 2
2-8 = -6
Now you pythag
nvm
What is the answer to this???
with a question
1+-2
Heres a way i explain negitive numbers
Lets represent postive numbers as apples
and negitive numbers as worms that will eat one apple each
4+-2 is like saying you have 4 apples and plus 2 worms which will eat two apples. Leaving you with 2 apples
Whenever you plus a negitive number its the same as minusing that number
1+-2 is the same as 1-2
"the number of diagonals of an ABCDE polygon, knowing that the bisectors of sides AB and CD form an angle of 30Āŗ is:"
@void solar stay high is my favourite song lol
this question
little help?
Probability of first red sweet is 3/5
probability of second sweet is 2/4 because he ate one red sweet
then times them
Intersection means they have the same y value so you can equate the two equations
x+1 = px + q when x = 1
1+1 = p+ q
@void solar how come your not a helper you are so good at helping people
thx @void solar
You should be promoted
Yeh
You guys are the only people i've answered because well its pretty simple
Im still learning myself
abcd = a x b x c x d
sub in a and c
So is this over?
Would assume so
There is a series of simplifications i donāt understand
Let me write it
First of all
How do you divide the two numbers there by two when the two is stuck in a weird place?
shouldn't matter where it is
you divide both sides of the equation by 2
and distribute /2 properly
From 1-262144*r they extracted 1-r somehow
And then it went away with the other 1-r
Use the formula
You know what the equation is for liner equation
can you show all your work
i got -k=3n-30
you are told that ||the line also passes through the origin||
apply ^ to get the values of k and n directly
You have gradient and y-int so you should have equation
instead of applying slope formula using (6,k) and (n,12)
Find equation
Sub K into equation and solve
Do same with n
k-n
Is this a test
@lapis stream
699050 = (2 - 524288*r)/(1-r) // (2 - 524288*r)/(1-r) that's not good, let's try to bring the divisor to something like (2-...r)
699050 = (2 - 524288*r)/(1-r) | :2
699050/2 = ((2 - 524288*r)/(1-r))/2
349525 = (2 - 524288*r)/(2*(1-r)
349525 = (2 - 524288*r)/(2-2r) // (2 - 524288*r)/(2-2r) is better because the divisor has the same form
349525 = (1 - 262144*r)/(1-r) // The 2 is gone but fairly, that was not needed directly
349525 = (1 - 262144*r)/(1-r) |*(1-r)
349525*(1-r) = 1-262144*r | *(..)
349525 - 349525r = 1 - 262144r |-1 + 349525r
349524 = 87381r | :87381
r = 349524/87381
r = 4
@white meteor I already gave you the steps to solve it
i'm trying to map images of mars
here's what i'm trying to map https://www.uahirise.org/ESP_011405_0930
if you open "black and white map projected" and "black and white non-map" you'll notice the difference between the two
i need to figure out the angle to rotate the non-map image
i have the minimum latitude, maximum latitude, easternmost longitude, and westernmost longitude
so i have the four border points, not sure that's really helpful
i also have a bunch of angles, but i'm not sure which are needed. there are some on that page.
anyone familiar with this?
@lapis stream
// Or a little bit shorter
699050 = (2 - 524288r)/(1-r) | *(1-r)
699050*(1-r) = 2-524288r | *(..)
699050-699050r = 2-524288r | -2+699050r
699048 = 174762r | :174762
699048 / 174762 = r
r = 4
What does | mean?
What you have to do
How do I solve $x^4+x+1=0$?
Lightaris
@lapis stream
699050 = (2 - 524288r)/(1-r) // First we multiply with (1-r) | *(1-r)
699050*(1-r) = ((2 - 524288r)*(1-r))/(1-r)
699050*(1-r) = (2 - 524288r) // (1-r)/(1-r) = 1
And so on...
u r memeing here?
should this be 5x only or 5x + 5, or 6x?
I get this one finally
Wait I should have learned this particularpoint years ago
Iām not good at triple fractions
Moriarty
Same thing as dividing by 2
Yeah, but when you have a fraction, a division is a multiplication of the divisors:
$\frac{2-524288r}{1-r} * \frac{1}{2} = \frac{2-524288r}{2*(1-r)} = \frac{2-524288r}{2-2r}$
Moriarty
So this was originally a geometric sequence
A1= 2
An= 524288
I donāt know how but n=10
Sum is 699050
@chilly zodiac
x^4 + x + 1 = 0 |-1
x^4 + x = -1 | x()
x * (x^3 + 1) = -1
So x * (x^3 + 1) must be negative, that's only possible when x xor (x^3 + 1) is negative
and x^3 + 1 must be the inverse of x, that's not possible when you are in R, the solutions must be in C
What do you mean with, you don't know?
Hi, may I dm you about the solution?
Yeah
how i can get the vaule of 45?
360 is the 100%.
360 = x= 0, z= -2
180 = x= 0, z= 2
45 = x= Āæ?, z= Āæ?
alright thank you so much
type this
this
Did you mean, you will find the geometric series formula?
Weāve got the equation for the sum of the values of the series
And we needed to extract r
But first we needed n
please
hey
And what's the problem with this?
can we post any type of question in here?
I guess
or should i say, put an analysis question in pre calc
alright
Where does n come from?
If you don't translate the problem, Moriarty will probably have a hard time explaining
You can solve again from the beginning
@lapis stream
Sum for geometric series
$S_n = \frac{a*(1-r^n)}{1-r}$
Moriarty
@lapis stream You see, n is the number of the sum of the nth step of the series
Wait, i think i may be able to solve it
in first order logic, is the formula itself a subformula of it?
the maximum number is 360, type 360 = 100%, 180 = 50% ... 360 contains these unknowns x = 0 and z = -2. How do I know the unknowns if the number is 45?
x and z are coordinates
guy... what coordinates would you give me if the number was 45?
help... plis
š³
hello everyone! does anyone here understand macedonian?
when the macedonian is written in english then yes
Can't you just write in the server?
you'd better translate for increasing your help chance
I can
So I just feel like itās kinda suspicious how the solution was fully typed out
Do you have like the answer sheet for the assignmentā¦
You actually typed that whole thing out just for me?
Yeah
Wow thanks man
Ah, I see
So I also wanted to test myself :P
My professor actually uses the same colors and style in his solutions
anyone can help me whit this? #help-9 message
lack of parenthees
or maybe just simplify 2nd step as it is
that will give you a mistake less answer
cause if you take 1 out as common , there maybe some mistakes in the sign that you might not notice
is the answer 2.5cm and 7.2cm
i just need confirmation so i know how to answert these types of questions
i guess it is 2.5 , 12 @next patrol
as frequecy 8 is represented by 8cm then frequency 12 should be represented by 12 cm
thats true let me recheck my calculations
acc
no it is 7.2 i am sure
bc the class width is different
anyone else?
opinions?
can u show ur calculation?
'rotate
can someone help me with this please
i dont get the former part of the proof
@alpine sable which part exactly?
for integer polynomials roots are always pairs like a +/- sqrt(b)
unless b is 0 but yeah
coterminal is just adding or subtracting 360 as much as you need to
keep adding or subtracting 360 until its in the range 0<x<360
ah alright
the part where R(x)=P(x)-2018
multiplying it with its conjugate makes sense since the coefficients must be integers
oh so the problem says P(m)=2018
so if you want to make it a polynomial* that equals zero you need to subtract 2018 first before you do things
What is 1+1 if not 2
š«
then 9+10 is not 21
oh i see, so why is R(x) = (x^2+x-4)Q(x)+rx+l
im more confused with the rx+l part
how do you solve for initial velocity in a projectile given the launch distance and the airborne time
d/t?
y(t) = 1/2at^2 + v0sin(theta)t + y0
x(t) = v0cos(theta)t + x0
I have no idea why the rx+l part is there O_o
I'd think you can just skip to R(x)=(x^2+x-4)Q(x)
a, t, x, and y are presumably known
oh this is really simple. assuming x0 is 0
y0 is not 0
is x0 0?
i see thanks
x0 is not 0 either
what is x0?
4m
it doesn't really matter anyways. what matters is delta x
help
hi, just curious about the interval [0, 1). this has no maximal element right? i'm slightly confused
it doesn't
but how did u get 2y=4(a-1)
Idk how to explain in english hold on š
multiply by the denominators
multiply everything by y(a-1)
and then you get 2y = 4(a-1)
xd
basically
do you agree with me
that any number divided by itself (for example, 3/3)
is equal to one?
yeah
wouldnt u move the 4 over there since its multiplied it would be divided there
so 2/4(a-1)=y
is equal the same?
yes
so you multiply everything by y(a-1)
and then you have
2y/y(a-1) = 4y(a-1)/y(a-1)
with me so far?
what grade ur in
yes
i got it now thanks
np
is 3 congruent to 5 (mod 2)?
it seems so counterintuitive but by definition is seems to be true
3 - 5 = -2, and that is divisible by 2
am i missing something?
Yes they're both odd
ah wait i think i was misunderstanding, does a is congruent to b (mod m) really mean that a mod m equals b mod m?
cos im coming from a code mindset where modulo means remainder
so the lemma isn't true or?
Yeah it's remainder
Both 3 and 5 have remainder 1 when divided by 2
So they're congruent mod2
got it
How do I solve this ?
whats your hypothesis?
any thoughts?
@lethal pike
o gees i may have cann of worms here i didnt read the whole problem 
Well sure, I solved something similar.
I think it goes along the same reasoning.
romania
yes.
sal
Salut, hai mai bine pe privat in romana ca sa nu faca astia urat.
I'll try to solve it alone.
hi all, for question 2: is option 1 true as well?
also, is it true that for any given matrix A:
rank(A) always = rank(A ^t)
but
nullity(A) not always = nullity(A ^t)?
considering the parabola y=ax^2+bx+c, how can i convert it into vertex form (identify the x and y cords of the vertex), then when i have it in vertex form, find the roots? this is done algebraiclly using just y=ax^2+bx+c, so just symbolically. if anyone has any resources on this please let me know it would be greatly appreciated!
Can someone help explain this to me?
dam
so I get that r is the identity element now, but I don't understand how q is the inverse
can someone explain?
waaait nvm i'm dumb
Hey Shah, what situations do you thing a set of functions will produce no answer ?
s*q = identity
More importantly, what is an answer to a set of functions in the first place?
So this is the question in my book.
line n is parallel to line m ( 5x - 2y = 15 ) and goes through point C ( -10, -15 ).
compose an equation of line n in px + qy = r
can someone help me do this? i know that directional coefficient of line m = directional coefficient of line n so p = 5 but how do i continue now that i have 5x + qy = r?
Can anyone help me out with how he factored this polynomial? I can't tell what solution he used:
Ossi do you know what makes two lines parallel? (in terms of slope)
euhm idk lol, im from netherlands and never heard of that
no lol
Alright that is the concept behind this question
what makes two lines parallel is that they have the same slope
do you know what the slope of m is ?
p will be 5, q will be -2
nothing necessitating derivative
why is q -2
because it's parallel to 5x - 2y = 15
That's what I was trying to get you to see. You need the same slope value
yeah thanks, i only did it for behind the x lol
how do i solve this
Can anyone help me out with how he factored this polynomial? I can't tell what solution he used:
The 81 degree angle is on a straight line so the angle next to it is 99 degrees. 99 + 4x + 5x = 180. Solve that for x.
Well it's simple. You need to find some (ax+b)(cx+d) = 3x^2 + 7x + 2
Expand the left side
acx^2 + (ad+bc)x + bd
Now you have a system of equations:
What's that formula called though?
Um its just basic algebra lmao
it's not called anything
See I've done plenty of factoring of polynomial work but I'm drawing a blank here.
ac = 3, ad+bc = 7, bd = 2
someone help
isnt this just E
What have you tried Murphy
That seems correct
i need an explanation
Thats the same
this.
you just do 2918 - 1305 and thats it
huh
he used his entire paycheck and paid 1305 and 2918
paychech is 1305 + 2918
$\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$
Tiessie
wait because i dont understand that text lmao, this is like 8 year old math but its confusing af
not it was just 1 ans
x = +-sqrt(n/h)
apparently i needed to do + thingy
because if a^2 = b, (-a)^2 = b also
Oh yeah
there are two answers
Exactly
there is a neg
and a pos
the ans was the pos one
if a proper math teacher
was to read what i wrote
100% sure no1 would disagree with my ans
no it wasnt e
then it H
no way
u said it was e
imagine
at this point drop out of 1st grade
@frigid gorge
please
how tf
is this wrong
im discussing asnwers with a friend
and somehow
my ans is wrong
its
2b^3/5/p
or is ti
2b^3 / 5 p
huh
my brain
cannot comprehend this
no
cuz if thats that
it would be
5/p = 5p
wow
u rly said that
@alpine sable
wtf i feel stupid when i see this
,w 5px^2=2b^3
it's not /(5/p)
I don't know if what I solved is correct. Is there a proper rigorous solution to this ?
feels wrong with X^2 already
I don't know how to solve it
first row, second column of X^2, the coeff should be 0
since the second column of X has only its second entry non zero, and first row has only the first entry non zero
so your calc of X^2 is wrong already
choose a n, and try to conjecture from that, as a starter
n = 4 would be good to have time to see what happens
(if n = 2, then X^2 = 0, and if n = 3, then X^3 = 0)
bro solve rs agarwal and ncert.
how tf do i even set up this problme
it wants inventory cost
so what i see is that
kx+px+hxt
like what the fuck else do i do
mchw
bit confused about this step
$\frac{1}{2^{k-1}} = 2^{-(k-1)} = 2^{1-k} = \frac{2}{2^k}$
Chris24
How would one remove the big root?
@dapper patio
cant
all you can do here is this
4(4-sqrt(2))
ahhh i see, thanks :)
can you not get it in the form
wait but what about the k+1/2^k? shouldnt it be ((k+1)/2)^k?
$\sqrt{(a+b)^2}$
DistilledWater
thats very sad
1^k = 1 for all k, so
$(k+1)(\frac{1}{2})^k = (k+1) \frac{1^k}{2^k} = (k+1)\frac{1}{2^k}$
Chris24
omg im an idiot, tysm!
DistilledWater
DistilledWater
find scale factor
if its reflected in the y axis, all of the negative values become the value of the positive ones and the positive ones become the negative, how do we do this? we just make it -x, because --x = x (positive ones) -x = -x (negative ones)
actually just come dms
dont wanna clog the channel
bruh
literally just sub
u into the first equation for y
then its a power rule problem
y = 40x^2 - 9
dy/dx = 80x

or dy = 8du, dy/du = 8, du = 10xdx, du/dx = 10x, 8*10x = 80x
ty
whats 1+1
how does ā« e^4x/4 * (2x - 2) = 1/2 ā« (x-1) e^4x?
wdym?
yeah, but how can you move one so it doesnāt have to be integrated?
like, surely you canāt just slap it out without doing something?
the 1/2
itās outside the integral
sure one sec
M Y
F I N A L
M E S S A G E
C H A N G E
**D A **
W O R L D
G O O D B Y E
hmm
jfc
excuse my awful writing abilities
basically, ā« e^4x/4 * (2x - 2) = 1/2 ā« (x-1) e^4x but i have no idea how
hm
hey
still don't know how to solve it to be honest.
for n=4 it will still be 0
this coeff yes, but not the whole matrix
my guess would be that for n = 4, X^4 = 0
for each power you remove "a diagonal"
just an intuition tho, I didn't really think about it, nor check
nope
for n = 3, X^3 is full of 0, for example
you're not making progress in the problem 'cause you should be trying to prove your conjecture and calculating things, and you don't calculate
and your 1 on last row don't even make sense
how is your X defined ?
take n = 3 and write out X
thanks
No problem.
what's (-64)^(1/3)
oh shit wait
i did 4x2 and not 4^2
;-;
but i have a question
why would i have to raise it to the 2nd power and not multiply it by 2
2/3 is double of 1/3, not (1/3)^2
a^bc = (a^b)^c
@steady mist what are you confused with exactly
$\frac{1}{\left(x^2-3\right)^{\frac{2}{3}}}-\frac{1}{\left(x^2-3\right)^{\frac{5}{3}}}$
eggdog
you got here right?
wait
so
if 2^a/b
wait
if (2)^(a/b)
then
2^a/2^b ?
so 2^(1/2)
is (2^1)/(2^2)
so 2/4 or.. 1/2?
you need to find the LCM
no
wait
yes
wait
no
2^(a/b) = 2^a * 2^(1/b)
2^(a-b) = 2^a/2^b
i think itās free
Okay so am wondering
How am I able tp reduce the problem from that original form to this one
As for me this is so exhausting as trying to figure it out
thanks for being useless guys
yknow a better way to get help would be something along the lines of "anyone else know how to do this?"
Composite shapes. You can break it down into simpler shapes whose area formulae you know and then sum those areas.
Nice.
So i cut it like this
But what about that little part to the side
Do i leave that alone and not count it
You can do that and you can even remove the horizontal line. Make it 1 rectangle.
Oh yeah
The curved part is a semicircle.
Oh ok
Do you see why that's a semi-circle?
Yeah
how do I do this?
@charred lintel Try factoring out a 3. So express the polynomial as 3 times another polynomial.
Since all of the coefficients are multiples of 3.
@shrewd echo thank you
1 is obvious root, so the other one is 69/3 = 23
And your polynomial is 3(x-1)(x-23)
@quartz osprey You seem to understand how to get the answer, but your differentation is off.
is it just getting the derivitive like literally ?
Looks like it.
alright
You're missing a negative and an h.
wait
derivitive of hx i got 1
is tht wrong?
does pD become 0 or is it stay there
Well, pD is a constant, right?
If you're unsure that p and D are constants, notice that C is a function of x and x alone, so we know then that all the other letters are constants.
bleh
uhh
oh yea i see
wait so if its a constant does it sstay or something like that
span
You easily note that your 1st vector needs to be scaled by 2 to match the 1st component
$[2,a,16,9]=2[1,-2,5,3]+b[0,-2,4,4]+c[0,0,-2,-5]$
Mosh
Could someone please explain this to me? We never talked about rates of oscillation in my class
(#18)
i got -8 which was correct. i did (-2 + -2 + 0)*2
but im not sure why this works for a but not for 16 and 9
so you need to make $16=10+4b-2c$ and $9=6+4b-5c$
Mosh
man idk wtf i be saying half the time
@quartz osprey The derivative of a scalar multiple of something is equivalent to the scalar multiple of the derivative.
i was doing quadratcis the other day and i said 77 out of nowhere
what is the process for this problem
ngl that looks like a di-
begin by writing W as a linear combination $s\textbf{u} + t\textbf{v}$
gramschmidtty

