#help-0

1 messages Ā· Page 843 of 1

hidden fjord
#

i seeeee

flint badger
#

$\left(p^5\right)^{10}=p^{5\cdot :10}$

ocean sealBOT
#

eggdog

flint badger
#

or in other words

#

$\left(a^b\right)^c=a^{bc}$

ocean sealBOT
#

eggdog

proven heart
#

That is when you take the power to another power.im talking about multipliying /dividing terms with powers

hidden fjord
#

ok

flint badger
#

yea thats different stuff

proven heart
#

And yes you will get negative numbers when add/subtract the powers .BUT negative powers just mean that they are the reciprocal of the positive power term

flint badger
#

@hidden fjord basically i dont like to hit rules at you but since you get the idea this will be true:

$:a^{-b}=\frac{1}{a^b}$

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i should stop doing that

proven heart
#

Yep

flint badger
#

$:a^{-b}=\frac{1}{a^b}$

proven heart
#

What bro šŸ˜‘

ocean sealBOT
#

eggdog

proven heart
#

Oh nvm

#

Anyway gtg bye

flint badger
#

bye

hidden fjord
#

i need to just practice this a bit more

#

and ill be good

flint badger
#

so @hidden fjord you know when you had

#

$\frac{x}{x^3}$

hidden fjord
#

i cant believe u taught me more than my lazy math teacher in a week

flint badger
#

in that one problem

ocean sealBOT
#

eggdog

hidden fjord
#

yes

flint badger
#

thats basically just the same as

#

$x^{1-3}$

ocean sealBOT
#

eggdog

flint badger
#

and that's x^-2

#

which if you apply the rule is 1/x^2

hidden fjord
#

yea, because of the rule

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yes

flint badger
#

so thats how you got x^2 at the bottom

#

yea have fun with algebra

hidden fjord
#

fr

flint badger
#

i had a bad algebra teacher

hidden fjord
#

homie, have a great day/night, if I could pay u back I would. ur the best

flint badger
#

you too,

#

gn

hidden fjord
#

have a good one!

vapid herald
#

is this just +- infinity

glass lichen
minor dagger
#

can someone please help me with b

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<@&286206848099549185>

proven heart
#

Ok so....you note the critical values first.but since the question specifically asks about 1(one).that's the only critical value .we gotta worry about here

proven heart
#

@minor dagger you there?

minor dagger
proven heart
#

Hmm so now you approch value 1 for the left side and from the right side using limits

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Hope you know those right?

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Left limit and right limit?

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Oh wait you just wanted b part nvm šŸ˜‘

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Well if you knew that g was continuous at x=3 ,then Left limit at x=3 and the Right limit at x=3 and the function value at x= 3,all must be equal

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Get three equations and play algebra with them ,and you get c.and I hope you know how to do that?

proven heart
proven heart
#

šŸ˜…

minor dagger
#

I’m processing ToT

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So for an equation I input 3 where x is and got 8/3

proven heart
#

Oh .ok šŸ‘.process slowly and concretely .should be able to get it

proven heart
#

Do you Voice chat?

#

If you comfortable with dat?

minor dagger
#

The square root equation

proven heart
minor dagger
#

I need help with c

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@proven heart

native cloud
#

Is there a channel for physics?

alpine sable
bold panther
#

Could someone help me with these two problems?

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<@&286206848099549185>

tight locust
bold panther
#

then k is also divisible by ten(?)

tight locust
#

yeah sure. you could write it as the set of integers k such that k = 10n

bold panther
#

it says that its wrong T_T

tight locust
#

10n, where n in Z

bold panther
#

tyyyy

alpine sable
#

Can anyone help with c and d I’ve already done a and b

kind turret
#

hi I need help with doing 3n[(2n^2+7n-8)+(-2n^2+3n)] please show work its not for a test its just I have trouble timesing the equation because my parent was drunk and my brother was tired and high so he just rushed it

tight locust
#

lmao

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,w (0.82)^6(1-0.82)^2

tight locust
#

,w 0.82^6

alpine sable
#

Should I just repost mine since it got clogged up

kind turret
#

,w

tight locust
dusty quiver
#

is this something divided by 20C16?

alpine sable
#

The bottom answer is for question c right?

tight locust
#

d

wary stream
stone ruin
#

do barycentric coordinates go from the corners

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or the edges

fervent cairn
#

Is there any difference in how a function is read when it is phrased like this?

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that's just a different way of saying inverse of f(x)

keen mulch
fervent cairn
#

Oh the graph just started like that

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I wanted to ask before I did anything

keen mulch
#

Oh

fervent cairn
#

So you do read it the same way

keen mulch
#

Sorry read it the same way as what?

fervent cairn
#

as a normal function

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I was confused as if you would read it any different based on how it's written in the question

next spear
#

i have no idea how to ddo this can i get some help please?

fervent cairn
#

While usually it is f(x)=x, it is written as y = f(x)

keen mulch
#

F(x) and y can be interchanged

lapis goblet
keen mulch
#

Like y=x and f(x)=x is the same thing

fervent cairn
#

yeah but how can you read a graph when you just have y=y

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f(x) as written is y too no?

next spear
fervent cairn
#

that's what I thought at first

lapis goblet
keen mulch
#

Y=y wouldn’t be a function

next spear
wary stream
# next spear i have no idea how to ddo this can i get some help please?

This video explains how to factor polynomials. It explains how to factor the GCF, how to factor trinomials, how to factor difference of perfect squares, or how to factor cubic polynomials.

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ā–¶ Play video
lapis goblet
#

yeah many ways

next spear
fervent cairn
lapis goblet
#

It’s just for simplicity’s sake

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Just naming one variable the output of another function

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So instead of writing f(x) every time you just write y

fervent cairn
#

Why not just write y=x lol

lapis goblet
#

Also it helps to visualize in an xy- Cartesian plane

fervent cairn
#

when you write f(x) it reads as.. function of x

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I guess

lapis goblet
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Because that’s what it is

keen mulch
#

F(x) is still a variable

fervent cairn
#

okay but y=f(x) literally means f(x) = f(x) no?

lapis goblet
#

A function f(x) that is dependent on the inputs of x

ancient saddle
#

y = f(x) means that the y-coordinate is a function of x, you don't take for granted that y is just f(x)

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It's used for graphing a function f(x) in a cartesian plane

lapis goblet
#

^

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When doing things in higher R^n space you can set the function equal to z, for example, for xyz-space

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So instead f(x) = y, you can have z = f(x)

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For now just think of them as equivalent though

fervent cairn
#

I dont understand the application of the concept at all; you can graph a function already in its normal f(x) form

rigid wind
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there are properties for a function, for example there's only 1 y value for every x in its domain

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and you can think of other analysis like taking derivative of y w.r.t x

lapis goblet
#

I think that’s called injective

fervent cairn
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Yeah I think i'm definetely confused; the way I understand what ure saying rn is that for this question, for example, you would put the function in this shape

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and I know that's not it because it's not letting me do that lol

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Oh wait

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I think I got it

lapis goblet
#

What that question is asking is what happens when you transform the function by some scalar

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In this case -1

keen mulch
fervent cairn
#

so just this?

ancient saddle
# fervent cairn I dont understand the application of the concept at all; you can graph a functio...

When you graph f(x), you graph a collection of points over the cartesian plane where y=f(x) at every point. That's what is usually used for graphing one variable functions, but there are other type of curves that can be graphed on the cartesian plane. For example, both x and y coordinates can be a function of some parameter t -> x=f(t), y=g(t), that would create a curve too, where y is not a function of x

fervent cairn
#

Where it just has certain, different, specifications for the what the function is

ancient saddle
#

that's just a one variable function

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it's just graphed with y=f(x)

fervent cairn
#

ye a different specification

keen mulch
fervent cairn
#

Yes, they're specifying that the Y values are the input

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and the X values are the output

quartz osprey
#

how do i go about solving this problem

fervent cairn
#

while in standard form it means that

quartz osprey
#

i dont know how to get started

fervent cairn
#

the X values are input

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the Y values are output

fervent cairn
keen mulch
ancient saddle
#

yes, -f(x) is just f(x) with the opposite sign

past sundial
#

Can someone explain in simple terms why a volume of a sphere is 88/21 r^3?

quartz oxide
#

it’s 4/3(pi)r^3
But if you take pi=22/7 it becomes 88/21

past sundial
#

But why 4/3

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That’s really random

quartz oxide
#

:/
I don’t think there’s an easy proof that doesn’t involve calculus

past sundial
#

Could u uh try to explain and I’ll ask if I don’t get what u’re saying?

quartz oxide
#

Maybe you can check out this video

past sundial
#

Kk

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Thanks

quartz oxide
worthy falcon
#

Help pls

keen mulch
#

Have you made a start?

worthy falcon
#

?

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A start?

keen mulch
#

Do you know how to start it

worthy falcon
#

Oh

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Nope

wary stream
past sundial
quartz oxide
#

Well it’s like a 3-d version of triangle
Triangle is 1/2 of rectangle
And cone is 1/3 of cylinder

stone ruin
#

okay

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so this triangle is in 3d space

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i have the x/y/z coordinates of all of the vertices on the triangle

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but only the x/y coordinate of that blue dot

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how do i find its z coordinate

next spear
#

dont think abt it too hard

next spear
pliant warren
#

how to solve DE?

celest perch
#

how to do this

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z is complex number

raven rover
#

I think you need to find the magnitude of the complex number (I'm not sure what the correct terminology is)

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But you figure out exactly what's inside the absolute value bars (magnitude) or whatever

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Something like that?

full musk
#

hiiiii do you guys know the equation for this sequence

rigid wind
#

seems like +5 then -10 then +5 then -10

full musk
#

how do i write that as an equation?

pliant warren
#

use the 0/0 rule

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L'Hospital's Rule

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when both numerator and denominator are 0 on lim then use L'Hospital

jagged imp
#

clyda what makes you think its .278 rad? Don't you get arctan(0)?

pliant warren
#

16-16 = 0

jagged imp
#

its not 0/0

pliant warren
#

112-112=0

lapis goblet
#

It is 0/0 lol

jagged imp
#

ok i misread the problem

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i thought it was 28x

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ill see myself out

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can't deal with the shame

pliant warren
#

nooo help me on DE

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Im dying here

lapis goblet
jagged imp
#

might it not just want an exact answer?

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it is arctan(2/7)

pliant warren
#

you differentiate both

jagged imp
#

just try arctan(2/7)

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instead of a decimal approximation

pliant warren
jagged imp
#

since it doesn't give an amount of d.ps

pliant warren
#

need help tho.

jagged imp
#

decimal places

lapis goblet
#

It’s because

jagged imp
#

i said arctan(2/7)

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not 2/7

lapis goblet
#

You factored the top wrong

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Difference of squares

jagged imp
#

the top is not (x-4)^2 lmfao

lapis goblet
#

Wait what

jagged imp
#

freshmans dream moment

lapis goblet
#

damn bro I’m forgetting this shit

pliant warren
#

this is precal right?

jagged imp
#

,w limit as x approaches 4 of arctan((x^2-16)/(7x^2-28x))

jagged imp
#

look, it is literally arctan(2/7)

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if theres an issue with putting in arctan(2/7)

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thats an issue with the program

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not you

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arctan(2/7) should be correct

lapis goblet
#

What program are you using

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It should have like a symbol box or something

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In the on screen keyboard maybe

pliant warren
#

You differentiate then put lim

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you will get arctan 2/7

lapis goblet
#

His problem is inputting into his program

runic pulsar
#

how do i work this one out

upbeat gorge
#

If you’re taking a calculus class, you can use limits, so make the left-side limit at 7 and right-side limit at 7 equal to each other

strong vapor
#

What should I do with this😭😭

#

I spent 45 minutes and I got a wrong answer

crisp grove
alpine sable
#

Is this solution correct?

runic pulsar
#

@upbeat gorge thats actually what i tired but it didnt work

clear vessel
#

Find the value of p and a if 2x^4 -+ px^3 + qx -4 leaves a remainder of 36x + 32 when it is divided by x^2 -2x - 3

strong vapor
#

Help me😭😭

alpine sable
#

Ban me plz

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PlZ

runic pulsar
#

@upbeat gorgei did, i put c=7 and it showed as wrong

upbeat gorge
#

Send a picture of your rough working

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Or your solution

runic pulsar
#

no working because i dont know how to get the answer, so i wanna know how do i work this out

upbeat gorge
#

Don’t get confused by the notation of the hint

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You’re looking at $\lim_{x\rightarrow7^-}f(x)=\lim_{x\rightarrow7^+}f(x)=f(7)$

ocean sealBOT
golden kettle
#

can someone help me with this one

little anchor
#

Hey

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Is value of y = 18

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Just for confirmation

lost gorge
little anchor
lost gorge
#

Np artist Hecker

little anchor
#

Lol

hardy geyser
#

i did the math it’s 5 cents but how is it 5 cents without doing math 😭

cursive crescent
#

What is ā€œwithout doing the math?ā€

hardy geyser
#

like this

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how i explain it without doing the math

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i can’t understand

cursive crescent
#

I mean mental math will tell you 5 cents pretty quick, because 1.05 is a dollar more than 5 cents and the total is 1.10 with a difference of 1

#

But that’s still doing the math. Any method of solving would technically be math

hardy geyser
#

how is it not .10 cause .10 plus 1 dolla

cursive crescent
#

Because that would make the total $1.20, which is 10 cents too much

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So we know we need 10 cents less, or 5 cents less on each

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So 0.05 + 1.05 works

hardy geyser
#

lemme read over this i’m still confused 😭

#

@cursive crescent OK YES I SEE! THABK YOU!!!!

cursive crescent
#

No problemo

hardy geyser
#

@cursive crescent i read it as your adding plus the ball is that good or is it flawed ?

jovial edge
#

How do I calculate this?

feral merlin
#

what is the meaning of C we use in the bottom of a integral
does it is a representation or we can put any equation there

#

the c denotes the limit right if we are doing it for circle and remove the c we can write it from 0 to 2Ļ€

placid zinc
#

C is the curve

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"curve" being whatever path we're taking the integral over

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@feral merlin

neon widget
#

hello

alpine trench
#

@jovial edge

jovial edge
#

Oh

#

So we use Poisson distribution for determining the probability that a lift will be unacceptable

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And then use that probability in a binomial distribution

alpine trench
#

yes, it says the number of breakdowns is poisson distributd

stark plover
#

The Question

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The Markscheme

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My working out for part e

#

,rotate

ocean sealBOT
stark plover
#

Can someone please help my understand why in part e: r = (1+0.004)^12 when the Q states that it’s compounded monthly?

alpine trench
proper dove
#

Anyone can help with the lesson "Evaulate limits graphically"?

alpine sable
#

thought it is 2 * acb?

#

apparently its not 80

#

no idea

#

can some1 pls help me

feral merlin
#

@placid zinc ok so its just a represntation right it just mean curve

void solar
#

AOB is an isosceles

alpine sable
#

a1 = 180-90-40=50

void solar
#

2AOB = ACB
AOB = 20
OAB = OBA
180 - 20 = 2OAB

feral merlin
magic jacinth
alpine sable
#

already tried it

void solar
feral merlin
#

@placid zinc i mean this

magic jacinth
alpine sable
#

it was 50

void solar
fiery creek
#

any answers?

compact vault
void solar
alpine sable
#

I’m 12

white meteor
fiery creek
alpine sable
#

Q+2

white meteor
#

thx

teal stone
#

gutenmorgen

#

i need some help

jagged trout
#

Moin

alpine sable
#

With what

fiery creek
void solar
# fiery creek nu

x position in point 1 is 6 x point in point 2 is -2
-2-6 = -8
x position in point 1 is 8 y point in point 2 is 2
2-8 = -6
Now you pythag

fiery creek
alpine sable
#

What is the answer to this???

teal stone
#

with a question

alpine sable
#

1+-2

void solar
# alpine sable 1+-2

Heres a way i explain negitive numbers
Lets represent postive numbers as apples
and negitive numbers as worms that will eat one apple each

4+-2 is like saying you have 4 apples and plus 2 worms which will eat two apples. Leaving you with 2 apples
Whenever you plus a negitive number its the same as minusing that number

1+-2 is the same as 1-2

teal stone
#

"the number of diagonals of an ABCDE polygon, knowing that the bisectors of sides AB and CD form an angle of 30Āŗ is:"

alpine sable
#

@void solar stay high is my favourite song lol

teal stone
#

this question

alpine sable
#

@void solar thanks so much add

#

Add?

void solar
#

addition

teal stone
#

little help?

void solar
# compact vault

Probability of first red sweet is 3/5
probability of second sweet is 2/4 because he ate one red sweet
then times them

void solar
# white meteor any1?

Intersection means they have the same y value so you can equate the two equations
x+1 = px + q when x = 1
1+1 = p+ q

alpine sable
#

@void solar how come your not a helper you are so good at helping people

white meteor
#

thx @void solar

alpine sable
#

You should be promoted

white meteor
#

so confusing

alpine sable
#

Yeh

void solar
#

You guys are the only people i've answered because well its pretty simple

#

Im still learning myself

void solar
lapis stream
#

So is this over?

void solar
#

Would assume so

lapis stream
#

There is a series of simplifications i don’t understand

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Let me write it

#

First of all

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How do you divide the two numbers there by two when the two is stuck in a weird place?

rigid wind
#

shouldn't matter where it is

#

you divide both sides of the equation by 2

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and distribute /2 properly

lapis stream
#

From 1-262144*r they extracted 1-r somehow

#

And then it went away with the other 1-r

forest sage
white meteor
#

any1 knows this

void solar
#

You know what the equation is for liner equation

white meteor
#

i tried doing y minus y0 equals m times x minus x 0

#

but it aint working

gray isle
#

can you show all your work

white meteor
#

i got -k=3n-30

gray isle
#

you are told that ||the line also passes through the origin||

#

apply ^ to get the values of k and n directly

void solar
#

You have gradient and y-int so you should have equation

gray isle
#

instead of applying slope formula using (6,k) and (n,12)

void solar
# white meteor

Find equation
Sub K into equation and solve
Do same with n
k-n

white meteor
#

is it 122

#

*22

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got 10 seconds

#

left

void solar
#

Is this a test

white meteor
#

no its an excersice

#

im solving

void solar
#

Your not allowed to ask for help on a test

#

Hmm

#

Sus

white meteor
#

AHAHHA

#

ong it aint a test

#

dw

jagged trout
#

@lapis stream

699050 = (2 - 524288*r)/(1-r) // (2 - 524288*r)/(1-r) that's not good, let's try to bring the divisor to something like (2-...r)
699050 = (2 - 524288*r)/(1-r) | :2
699050/2 = ((2 - 524288*r)/(1-r))/2
349525 = (2 - 524288*r)/(2*(1-r)
349525 = (2 - 524288*r)/(2-2r) // (2 - 524288*r)/(2-2r) is better because the divisor has the same form

349525 = (1 - 262144*r)/(1-r) // The 2 is gone but fairly, that was not needed directly
349525 = (1 - 262144*r)/(1-r) |*(1-r)
349525*(1-r) = 1-262144*r | *(..)
349525 - 349525r = 1 - 262144r |-1 + 349525r
349524 = 87381r | :87381
r = 349524/87381
r = 4
void solar
#

@white meteor I already gave you the steps to solve it

white meteor
#

@void solar yeah yeah i got it

#

thanks alot

#

appreciate it

lapis stream
#

Thanks

#

I’ll need to stare at it for a bit

sullen moat
#

i'm trying to map images of mars

#

i need to figure out the angle to rotate the non-map image
i have the minimum latitude, maximum latitude, easternmost longitude, and westernmost longitude

#

so i have the four border points, not sure that's really helpful
i also have a bunch of angles, but i'm not sure which are needed. there are some on that page.
anyone familiar with this?

jagged trout
#

@lapis stream

// Or a little bit shorter
699050 = (2 - 524288r)/(1-r) | *(1-r)
699050*(1-r) = 2-524288r | *(..)
699050-699050r = 2-524288r | -2+699050r
699048 = 174762r | :174762
699048 / 174762 = r
r = 4
lapis stream
#

What does | mean?

jagged trout
#

What you have to do

chilly zodiac
#

How do I solve $x^4+x+1=0$?

ocean sealBOT
#

Lightaris

jagged trout
#

@lapis stream

699050 = (2 - 524288r)/(1-r) // First we multiply with (1-r) | *(1-r)
699050*(1-r) = ((2 - 524288r)*(1-r))/(1-r)
699050*(1-r) = (2 - 524288r) // (1-r)/(1-r) = 1
And so on...
crisp grove
#

u r memeing here?

woven idol
#

should this be 5x only or 5x + 5, or 6x?

lapis stream
#

Wait I should have learned this particularpoint years ago

#

I’m not good at triple fractions

jagged trout
#

You will multiply both sides with 1/2 šŸ˜‰

#

because $699050/1 * 1/2 = 699050/2$

ocean sealBOT
#

Moriarty

lapis stream
#

Same thing as dividing by 2

jagged trout
#

Yeah, but when you have a fraction, a division is a multiplication of the divisors:
$\frac{2-524288r}{1-r} * \frac{1}{2} = \frac{2-524288r}{2*(1-r)} = \frac{2-524288r}{2-2r}$

ocean sealBOT
#

Moriarty

lapis stream
#

So this was originally a geometric sequence

#

A1= 2

#

An= 524288

#

I don’t know how but n=10

#

Sum is 699050

jagged trout
#

@chilly zodiac

x^4 + x + 1 = 0 |-1
x^4 + x = -1 | x()
x * (x^3 + 1) = -1

So x * (x^3 + 1) must be negative, that's only possible when x xor (x^3 + 1) is negative
and x^3 + 1 must be the inverse of x, that's not possible when you are in R, the solutions must be in C
jagged trout
jovial edge
lapis stream
rapid coral
#

how i can get the vaule of 45?

360 is the 100%.
360 =     x= 0, z= -2
180 =    x= 0, z= 2
45 =    x= Āæ?, z= Āæ?
rapid coral
#

type this

jagged trout
#

this

jagged trout
lapis stream
#

We’ve got the equation for the sum of the values of the series

#

And we needed to extract r

#

But first we needed n

dawn osprey
#

hey

jagged trout
dawn osprey
#

can we post any type of question in here?

lapis stream
#

I guess

dawn osprey
#

or should i say, put an analysis question in pre calc

dawn osprey
lapis stream
alpine nacelle
#

If you don't translate the problem, Moriarty will probably have a hard time explaining

#

You can solve again from the beginning

jagged trout
#

@lapis stream
Sum for geometric series

$S_n = \frac{a*(1-r^n)}{1-r}$

ocean sealBOT
#

Moriarty

jagged trout
#

@lapis stream You see, n is the number of the sum of the nth step of the series

lapis stream
#

Wait, i think i may be able to solve it

unkempt umbra
#

in first order logic, is the formula itself a subformula of it?

rapid coral
#

the maximum number is 360, type 360 = 100%, 180 = 50% ... 360 contains these unknowns x = 0 and z = -2. How do I know the unknowns if the number is 45?

x and z are coordinates
guy... what coordinates would you give me if the number was 45?

#

help... plis

alpine trench
alpine sable
#

hello everyone! does anyone here understand macedonian?

jagged trout
#

when the macedonian is written in english then yes

alpine trench
hushed pasture
jovial edge
#

So I just feel like it’s kinda suspicious how the solution was fully typed out

#

Do you have like the answer sheet for the assignment…

alpine trench
#

No

#

I wrote it myself

jovial edge
#

You actually typed that whole thing out just for me?

alpine trench
#

Yeah

jovial edge
#

Wow thanks man

alpine trench
#

I have probability theory also

#

Just had a lecture about poisson distributions

jovial edge
#

Ah, I see

alpine trench
#

So I also wanted to test myself :P

jovial edge
#

My professor actually uses the same colors and style in his solutions

rapid coral
alpine sable
#

What did I do wrong?

#

supposed to be -(x+2)^2 i think

#

in 3rd step

gray isle
#

lack of parenthees

alpine sable
#

or maybe just simplify 2nd step as it is

#

that will give you a mistake less answer

#

cause if you take 1 out as common , there maybe some mistakes in the sign that you might not notice

gray isle
next patrol
#

is the answer 2.5cm and 7.2cm

#

i just need confirmation so i know how to answert these types of questions

sturdy monolith
#

i guess it is 2.5 , 12 @next patrol

#

as frequecy 8 is represented by 8cm then frequency 12 should be represented by 12 cm

next patrol
#

thats true let me recheck my calculations

#

acc

#

no it is 7.2 i am sure

#

bc the class width is different

#

anyone else?

#

opinions?

sturdy monolith
next patrol
#

@sturdy monolith

#

2.5cm*

#

not 3

alpine sable
#

'rotate

#

can someone help me with this please

#

i dont get the former part of the proof

charred flint
#

@alpine sable which part exactly?

#

for integer polynomials roots are always pairs like a +/- sqrt(b)

#

unless b is 0 but yeah

cedar topaz
#

can someone help me explain

charred flint
#

coterminal is just adding or subtracting 360 as much as you need to

alpine sable
# cedar topaz

keep adding or subtracting 360 until its in the range 0<x<360

cedar topaz
#

ah alright

alpine sable
alpine sable
charred flint
#

oh so the problem says P(m)=2018

#

so if you want to make it a polynomial* that equals zero you need to subtract 2018 first before you do things

tawny fox
#

What is 1+1 if not 2 sully šŸ”«

alpine sable
alpine sable
alpine sable
crude hazel
#

how do you solve for initial velocity in a projectile given the launch distance and the airborne time

jagged trout
#

d/t?

tight locust
#

y(t) = 1/2at^2 + v0sin(theta)t + y0
x(t) = v0cos(theta)t + x0

charred flint
#

I have no idea why the rx+l part is there O_o

#

I'd think you can just skip to R(x)=(x^2+x-4)Q(x)

tight locust
#

a, t, x, and y are presumably known

tight locust
crude hazel
#

y0 is not 0

tight locust
#

is x0 0?

alpine sable
crude hazel
#

x0 is not 0 either

tight locust
#

what is x0?

crude hazel
#

4m

tight locust
#

it doesn't really matter anyways. what matters is delta x

tawny fox
#

😳

tight locust
#

delta x = v0 cos(theta) t

#

deltax/(t*cos(theta)) = v0

crude hazel
#

@tight locust would -y0 = v0 * sin(theta)t - 4.9t^2?

#

nvm I get it now

mental pewter
eager badger
#

hi, just curious about the interval [0, 1). this has no maximal element right? i'm slightly confused

median dagger
#

what would be the easiest way of solving this?

steady jewel
#

2y= 4a-4

#

4a-2y=-4

median dagger
#

but how did u get 2y=4(a-1)

steady jewel
median dagger
#

can u join vc

#

for a sec

silver axle
#

multiply everything by y(a-1)

#

and then you get 2y = 4(a-1)

steady jewel
#

ohhh denominators

#

in my language it is another word

#

much smaller

silver axle
#

xd

steady jewel
#

didn't know in english

#

🤣

median dagger
#

im so confused

#

can u join vc

#

and expalin

silver axle
#

basically

#

do you agree with me

#

that any number divided by itself (for example, 3/3)

#

is equal to one?

median dagger
#

yeah

silver axle
#

ok

#

so if i have 4/y

#

do you agree with me

#

that 4*y / y*y = 4/y

median dagger
#

wouldnt u move the 4 over there since its multiplied it would be divided there

#

so 2/4(a-1)=y

silver axle
#

is equal the same?

median dagger
#

yes

silver axle
#

so you multiply everything by y(a-1)

and then you have

2y/y(a-1) = 4y(a-1)/y(a-1)

#

with me so far?

median dagger
#

no 😭

#

i need to see someone do it on paper

steady jewel
#

what grade ur in

median dagger
#

10th but i have psat

#

OHH

#

u HAVE TO CROSS MULTIPLY IT

steady jewel
#

yes

median dagger
#

i got it now thanks

steady jewel
#

np

fading summit
#

is 3 congruent to 5 (mod 2)?

#

it seems so counterintuitive but by definition is seems to be true

#

3 - 5 = -2, and that is divisible by 2

#

am i missing something?

glass lichen
median dagger
#

ok how ab this one

#

so ^-1/2 would become

#

a=1/x^2

fading summit
#

cos im coming from a code mindset where modulo means remainder

eager badger
glass lichen
#

Yeah it's remainder

#

Both 3 and 5 have remainder 1 when divided by 2

#

So they're congruent mod2

fading summit
lethal pike
#

How do I solve this ?

remote heron
#

whats your hypothesis?

#

any thoughts?

#

@lethal pike

#

o gees i may have cann of worms here i didnt read the whole problem flonshed

lethal pike
#

Well sure, I solved something similar.
I think it goes along the same reasoning.

lethal pike
steady jewel
lethal pike
#

Salut, hai mai bine pe privat in romana ca sa nu faca astia urat.

#

I'll try to solve it alone.

unreal kettle
#

hi all, for question 2: is option 1 true as well?

#

also, is it true that for any given matrix A:

rank(A) always = rank(A ^t)

but

nullity(A) not always = nullity(A ^t)?

tropic dagger
#

considering the parabola y=ax^2+bx+c, how can i convert it into vertex form (identify the x and y cords of the vertex), then when i have it in vertex form, find the roots? this is done algebraiclly using just y=ax^2+bx+c, so just symbolically. if anyone has any resources on this please let me know it would be greatly appreciated!

alpine valley
#

Can someone help explain this to me?

steady jewel
#

dam

median dagger
#

@steady jewel yk this?

rigid kiln
#

so I get that r is the identity element now, but I don't understand how q is the inverse

#

can someone explain?

#

waaait nvm i'm dumb

mellow juniper
#

Hey Shah, what situations do you thing a set of functions will produce no answer ?

rigid kiln
#

s*q = identity

mellow juniper
#

More importantly, what is an answer to a set of functions in the first place?

agile sluice
#

So this is the question in my book.
line n is parallel to line m ( 5x - 2y = 15 ) and goes through point C ( -10, -15 ).
compose an equation of line n in px + qy = r
can someone help me do this? i know that directional coefficient of line m = directional coefficient of line n so p = 5 but how do i continue now that i have 5x + qy = r?

alpine sable
#

Can anyone help me out with how he factored this polynomial? I can't tell what solution he used:

thorn kindle
#

This is very simple

#

What is the derivative wrt x?

#

@agile sluice

mellow juniper
#

Ossi do you know what makes two lines parallel? (in terms of slope)

agile sluice
mellow juniper
#

Alright that is the concept behind this question

#

what makes two lines parallel is that they have the same slope

#

do you know what the slope of m is ?

royal meadow
#

nothing necessitating derivative

agile sluice
royal meadow
#

because it's parallel to 5x - 2y = 15

agile sluice
#

owh that way

#

then its pretty easy

mellow juniper
#

That's what I was trying to get you to see. You need the same slope value

agile sluice
#

yeah thanks, i only did it for behind the x lol

frigid gorge
#

how do i solve this

alpine sable
#

Can anyone help me out with how he factored this polynomial? I can't tell what solution he used:

alpine sable
thorn kindle
#

Well it's simple. You need to find some (ax+b)(cx+d) = 3x^2 + 7x + 2

#

Expand the left side

#

acx^2 + (ad+bc)x + bd

#

Now you have a system of equations:

alpine sable
thorn kindle
#

Um its just basic algebra lmao

royal meadow
#

it's not called anything

alpine sable
#

See I've done plenty of factoring of polynomial work but I'm drawing a blank here.

thorn kindle
#

ac = 3, ad+bc = 7, bd = 2

frigid gorge
#

someone help

alpine sable
#

1305 + 2918

#

u do the calc

#

some1 help me on this 1

agile sluice
agile compass
#

What have you tried Murphy

agile compass
#

That seems correct

alpine sable
#

I AM GENUINELY FUCKING ANGRY

frigid gorge
agile compass
#

Thats the same

alpine sable
agile sluice
alpine sable
#

he used his entire paycheck and paid 1305 and 2918

#

paychech is 1305 + 2918

agile compass
#

$\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$

ocean sealBOT
#

Tiessie

agile sluice
# alpine sable huh

wait because i dont understand that text lmao, this is like 8 year old math but its confusing af

royal meadow
#

it's not the same

#

it's because when you have x^2 = n/h

alpine sable
royal meadow
#

x = +-sqrt(n/h)

alpine sable
#

apparently i needed to do + thingy

royal meadow
#

because if a^2 = b, (-a)^2 = b also

agile compass
#

Oh yeah

royal meadow
#

there are two answers

agile compass
#

Exactly

alpine sable
#

there is a neg

#

and a pos

#

the ans was the pos one

#

if a proper math teacher

#

was to read what i wrote

#

100% sure no1 would disagree with my ans

frigid gorge
#

no it wasnt e

agile sluice
#

then it H

alpine sable
#

u said it was e

#

imagine

#

at this point drop out of 1st grade

#

@frigid gorge

frigid gorge
#

i didnt say it was e

#

lol

alpine sable
#

please

#

how tf

#

is this wrong

#

im discussing asnwers with a friend

#

and somehow

#

my ans is wrong

#

its

#

2b^3/5/p

#

or is ti

#

2b^3 / 5 p

#

huh

#

my brain

#

cannot comprehend this

#

no

#

cuz if thats that

#

it would be

#

5/p = 5p

#

wow

#

u rly said that

#

@alpine sable

ripe gust
#

wtf i feel stupid when i see this

fervent anchor
#

,w 5px^2=2b^3

rigid wind
#

it's not /(5/p)

lethal pike
#

I don't know if what I solved is correct. Is there a proper rigorous solution to this ?

alpine nacelle
lethal pike
alpine nacelle
#

first row, second column of X^2, the coeff should be 0

#

since the second column of X has only its second entry non zero, and first row has only the first entry non zero

#

so your calc of X^2 is wrong already

#

choose a n, and try to conjecture from that, as a starter

#

n = 4 would be good to have time to see what happens

#

(if n = 2, then X^2 = 0, and if n = 3, then X^3 = 0)

brisk wedge
#

bro solve rs agarwal and ncert.

quartz osprey
#

how tf do i even set up this problme

#

it wants inventory cost

#

so what i see is that

#

kx+px+hxt

#

like what the fuck else do i do

tropic sail
#

hello how would I simplfiy this expressiosn?

#

$\sqrt{16-4\sqrt{2}}$

ocean sealBOT
lapis goblet
#

Factor a 4

#

From the the inside

#

@tropic sail

dapper patio
#

bit confused about this step

buoyant edge
#

$\frac{1}{2^{k-1}} = 2^{-(k-1)} = 2^{1-k} = \frac{2}{2^k}$

ocean sealBOT
#

Chris24

kindred mantle
buoyant edge
#

@dapper patio

lapis goblet
#

all you can do here is this

#

4(4-sqrt(2))

dapper patio
lapis goblet
#

Then sqrt of that all

#

2 (sqrt(4-sqrt(2))

kindred mantle
#

can you not get it in the form

dapper patio
kindred mantle
#

$\sqrt{(a+b)^2}$

ocean sealBOT
#

DistilledWater

kindred mantle
#

thats very sad

buoyant edge
#

1^k = 1 for all k, so

#

$(k+1)(\frac{1}{2})^k = (k+1) \frac{1^k}{2^k} = (k+1)\frac{1}{2^k}$

ocean sealBOT
#

Chris24

dapper patio
#

omg im an idiot, tysm!

kindred mantle
#

but why

#

they dont have to be

#

$\sqrt{3-2\sqrt{2}}$

#

it works here

ocean sealBOT
#

DistilledWater

kindred mantle
#

you can get rid of big root

#

it would be $\sqrt{2} - 1$

ocean sealBOT
#

DistilledWater

kindred mantle
#

and the big root is gone

#

how?

gloomy wharf
#

help pls

kindred mantle
#

find scale factor

plucky crow
#

if its reflected in the y axis, all of the negative values become the value of the positive ones and the positive ones become the negative, how do we do this? we just make it -x, because --x = x (positive ones) -x = -x (negative ones)

#

actually just come dms

#

dont wanna clog the channel

alpine sable
#

heres my work

plucky crow
#

bruh

#

literally just sub

#

u into the first equation for y

#

then its a power rule problem

#

y = 40x^2 - 9

#

dy/dx = 80x

alpine sable
plucky crow
# alpine sable

or dy = 8du, dy/du = 8, du = 10xdx, du/dx = 10x, 8*10x = 80x

alpine sable
#

ty

tidal lion
#

whats 1+1

crimson blade
#

how does ∫ e^4x/4 * (2x - 2) = 1/2 ∫ (x-1) e^4x?

#

wdym?

#

yeah, but how can you move one so it doesn’t have to be integrated?

#

like, surely you can’t just slap it out without doing something?

#

the 1/2

#

it’s outside the integral

#

sure one sec

alpine sable
#

M Y
F I N A L
M E S S A G E
C H A N G E
**D A **
W O R L D
G O O D B Y E

dreamy cedar
fading zephyr
#

hmm

sly mantle
#

jfc

crimson blade
#

excuse my awful writing abilities

#

basically, ∫ e^4x/4 * (2x - 2) = 1/2 ∫ (x-1) e^4x but i have no idea how

#

hm

tidal lion
#

hey

lethal pike
lethal pike
alpine nacelle
#

this coeff yes, but not the whole matrix

#

my guess would be that for n = 4, X^4 = 0

#

for each power you remove "a diagonal"

#

just an intuition tho, I didn't really think about it, nor check

lethal pike
#

Maybe this it the final form

#

for k=n

alpine nacelle
#

nope

#

for n = 3, X^3 is full of 0, for example

#

you're not making progress in the problem 'cause you should be trying to prove your conjecture and calculating things, and you don't calculate

#

and your 1 on last row don't even make sense

#

how is your X defined ?

#

take n = 3 and write out X

kindred mantle
#

thanks

shrewd echo
#

No problem.

inner sequoia
#

help

#

why is (-64)^2/3 = 16?

royal meadow
#

what's (-64)^(1/3)

inner sequoia
#

oh shit wait

#

i did 4x2 and not 4^2

#

;-;

#

but i have a question

#

why would i have to raise it to the 2nd power and not multiply it by 2

#

2/3 is double of 1/3, not (1/3)^2

royal meadow
steady mist
#

hey guys

#

can you help me with a problem

#

plz

#

i dont understand this question

flint badger
#

@steady mist what are you confused with exactly

steady mist
#

ik u factor out the (x^2-3)^-5/3

#

but idk what to do after that

flint badger
#

$\frac{1}{\left(x^2-3\right)^{\frac{2}{3}}}-\frac{1}{\left(x^2-3\right)^{\frac{5}{3}}}$

ocean sealBOT
#

eggdog

flint badger
#

you got here right?

inner sequoia
#

so

#

if 2^a/b

#

wait

#

if (2)^(a/b)

#

then

#

2^a/2^b ?

#

so 2^(1/2)

#

is (2^1)/(2^2)

#

so 2/4 or.. 1/2?

steady mist
#

if i wanted to mathaway i could but it doesnt answer my qeustion

#

im so confused

flint badger
#

you need to find the LCM

flint badger
#

try to figure that out

royal meadow
#

wait

#

yes

#

wait

#

no

#

2^(a/b) = 2^a * 2^(1/b)

#

2^(a-b) = 2^a/2^b

night narwhal
#

Is this channel occupied

#

Need some help with my calculus 2 problem

raw shard
#

i think it’s free

night narwhal
#

Okay so am wondering

#

How am I able tp reduce the problem from that original form to this one

#

As for me this is so exhausting as trying to figure it out

steady mist
#

thanks for being useless guys

buoyant kayak
#

yknow a better way to get help would be something along the lines of "anyone else know how to do this?"

shrewd echo
gentle prism
#

Someone help pls

buoyant edge
#

Composite shapes. You can break it down into simpler shapes whose area formulae you know and then sum those areas.

quartz osprey
#

how do i do this

gentle prism
#

I can get the top part but idk about the bottom

#

Actually

#

Nvm

#

I got it

buoyant edge
#

Nice.

gentle prism
#

So i cut it like this

#

But what about that little part to the side

#

Do i leave that alone and not count it

buoyant edge
#

You can do that and you can even remove the horizontal line. Make it 1 rectangle.

gentle prism
#

Oh yeah

buoyant edge
#

The curved part is a semicircle.

gentle prism
#

Oh ok

buoyant edge
#

Do you see why that's a semi-circle?

gentle prism
#

Yeah

charred lintel
#

how do I do this?

buoyant edge
#

@charred lintel Try factoring out a 3. So express the polynomial as 3 times another polynomial.

#

Since all of the coefficients are multiples of 3.

night narwhal
#

@shrewd echo thank you

alpine nacelle
#

And your polynomial is 3(x-1)(x-23)

buoyant edge
#

@quartz osprey You seem to understand how to get the answer, but your differentation is off.

quartz osprey
buoyant edge
#

Looks like it.

quartz osprey
#

alright

buoyant edge
#

You're missing a negative and an h.

quartz osprey
#

where did i go wrong?

#

h stays?

#

oh yave kd should be 0

buoyant edge
#

yes and h/2 is a constant

#

so the h stays

quartz osprey
#

wait

#

derivitive of hx i got 1

#

is tht wrong?

#

does pD become 0 or is it stay there

buoyant edge
#

Well, pD is a constant, right?

#

If you're unsure that p and D are constants, notice that C is a function of x and x alone, so we know then that all the other letters are constants.

quartz osprey
#

bleh

#

uhh

#

oh yea i see

#

wait so if its a constant does it sstay or something like that

celest anvil
#

how to do this?

#

what is this problem called

glass lichen
#

span

#

You easily note that your 1st vector needs to be scaled by 2 to match the 1st component

#

$[2,a,16,9]=2[1,-2,5,3]+b[0,-2,4,4]+c[0,0,-2,-5]$

ocean sealBOT
verbal forum
#

Could someone please explain this to me? We never talked about rates of oscillation in my class

#

(#18)

celest anvil
#

but im not sure why this works for a but not for 16 and 9

glass lichen
#

so you need to make $16=10+4b-2c$ and $9=6+4b-5c$

ocean sealBOT
glass lichen
#

then you can solve for a

#

and this is a pretty easy system to solve

ripe gust
#

man idk wtf i be saying half the time

buoyant edge
#

@quartz osprey The derivative of a scalar multiple of something is equivalent to the scalar multiple of the derivative.

ripe gust
#

i was doing quadratcis the other day and i said 77 out of nowhere

celest anvil
#

what is the process for this problem

ripe gust
#

d-24d+23

ripe gust
silver dew
ocean sealBOT
#

gramschmidtty