help-0

[fierce frigate]

oh

the bases

yes

we looking for the smaller one

so its 80/50

wait

idk

lt me check

si

50/80 = b1/b2

5/8 = 5/8

how does it help me find areaa

what

OH

huh

i am so confused

i understand what u mewan

mean

the sum of a+b

but i dont know how it helps

Ok how does that help?

I mean we can fill in ?

Ph

What's n?

Hah

What the

So ⅝

???

The bases are 50/80

So ⅝

What

In the area?

Hah

So

4000= ⅝² × A2

Wbat

What

I'm confused

Yes

a isn't area right?

Ok

[marsh sparrow]

Hello

i am

[fierce frigate]

We looking for A2 (small one)

[marsh sparrow]

from class 7

i need help

[alpine sable]

can anyone help with this

[marsh sparrow]

with my hw

[fierce frigate]

Dude

😭

[marsh sparrow]

Oh ok

[fierce frigate]

Ok so

A1 u said was the one with founded area right?

[alpine sable]

fuck right

Sorry

[fierce frigate]

I'm lost

[fierce frigate]

So A1= 5/8 x 4000

Forgot to square

But question

Why

[alpine sable]

2nd

[fierce frigate]

Why

Why it isn't what I originally said

Oh and the d) one is the same right?

Same as a)

Waitn

Nvm

Found out

Ok thanks

I'll return soon

Cause I'm bout to die

Doing all my hw b4 I go camping

K brb

[alpine sable]

Mhm

It's electrical engineering

[edgy perch]

Hi if I may ask again, is this also correct?

[alpine sable]

nope I'm outside

I'll make it when I'm at home

[fierce frigate]

i missed caalculated this one

it isnt 18.275

its 28.125

correcction misstpe

[wispy olive]

Is not this only for when x > 0?

Or is it for always?

[fierce frigate]

yeep

[wispy olive]

We also have to do for when x is negative, right?

#chill .

[wispy olive]

.

[subtle seal]

Hello! I'm trying to understand the GCD of two polynomials

[toxic mango]

Bro what is when add - +

[toxic mango]

The topic name

Pls

[wispy olive]

?

[subtle seal]

should be fields or groups

[toxic mango]

Bro

-9 + 9 like this topic name

[subtle seal]

arithmetics?

[toxic mango]

Lol

Bro I forget it I know the topic but name forget

[fierce frigate]

wait why do we square it?

square n

you know the ^2

what?

why do when finding an aarea theere will aalways be squared
while when findingg volume its cubed?

reading through ppt

it says that but dont explain why

why tho

what

twice all sides??

[tame sorrel]

double i think he means?

well look at it this way i think

square all sides equal

so area is a^2

when you double it's sides

(2a)^2

no?

[fierce frigate]

okok

so all 2d shapes when doing whatever this is called, i square it

so all 3d shapees i cube it?

cause one of the example for 2d shapes was a circle

and it was squared as well

okok thx

[cyan jungle]

I need help in maths

[eternal arrow]

This question is tough. I don’t know what to do :/

[fierce frigate]

hAHA

[cyan jungle]

Need help in question no. 6. My answer wont match

This is the rest of the working

[slender marten]

What's the initial condition?

It could affect what |1 - x| is.

y(1/2) = 6?

Yeah, that's the error.

[cyan jungle]

The boundary condition is given which is y=6 and x=0.5

[jaunty root]

What type of discontinuity does undefined and indeterminate make?

[cyan jungle]

So the only mistake here is ln |1-x|?

[slender marten]

Yes.

You need to factor out the negative sign.

[cyan jungle]

Oh okay got it

[slender marten]

$\int \frac{\dd{y}}{y} = - \int \frac{\dd{x}}{x - 1}$.

[ocean seal]

stabulo

[slender marten]

I might as well send it now I wrote it. xD

[cyan jungle]

Thanks guys

[jaunty root]

What I mean do indeterminate forms and undefined forms in rational context makes a specific discontinuity in graphs (ie asymptote, removable discontinuity) sorry if my question doesn't make any sense

[glass lichen]

if you have 0/0, then you typically have a removable discontiniuity

likewise w/ inf/inf

[fierce frigate]

How do I do this

For the b one

Do I have to find the radius?

So no need to find radius

Ok

My teacher's way isn't like that lol

myy teaecher

[fierce frigate]

this is also correct right?

okok

thank you

i think this is my final question b4 i move on to another question

tomorrow i have to go around universities (online) and then campingg, and i finish the hw to prevent stress

so thank

you

[velvet whale]

f(x) = |x| + 4, define f(3).

heelppp

[glass lichen]

just evaluate at x=3...

[velvet whale]

so

3+4?

=7, right

?

[glass lichen]

yes |3|=3

[velvet whale]

the value

is

7?

[fluid moth]

i have to relearn math. Would you agree with this order?

1. algebra
   2.pre calc --> calc
2. linear algebra
3. probability and stats

i want to build my math foundation for my college courses and i have until january to take my examinations

[fast oak]

Guys any one remeber how ??

[primal berry]

Which part are you stuck on or is it just all of it?

[fast oak]

yes

can u answer number and send pic how u do the solving

number 1

[primal berry]

I'll give you a hint about a way of solving it.
The "U" means Union and is the addition of the two sets
e.g. A is the set {1,3,5,7} while C is the set {0,1,2,3,4}
"add" these sets together and you end with - {0,1,1,2,3,3,4,5,7}
But there are multiple elements in the set, that's not allowed. Take out the duplicate elements and you end with - {0,1,2,3,4,5,7}

[fast oak]

ok ty u

i get it now

[primal berry]

You get/understand the n/intersect operation as well?

[fast oak]

no

[primal berry]

How can I put this without giving a direct answer...

Lines intersecting

If that doesn't make sense, please say

[velvet whale]

What is the image set of the function y = 2. Sen (x / 2)?

[fast oak]

infiniteof number? of set?

[velvet whale]

graphic

A)
[2,3]

B)
[-1,2]

C)
[2,2]

D)
[1,2]

E)
[ -2,2]

[primal berry]

Not quite, "n" or "Intersect" is the intersection of two sets,
E.g. {1,2,3,4} and {2,4,6}
The intersect of these two sets would be {2,4}

[fast oak]

how

[velvet whale]

idk how to do this question

[primal berry]

@velvet whale
Could you ask this in another chat please?

[velvet whale]

ok

[primal berry]

How as in how does intersect work or?

[fast oak]

how is work

[primal berry]

Simplest way I can put it is just look at the sets and see which elements are in both
For example A = {1,3,5,7,9} and B = {1,4,9}
The "1" and the "9" are in both
Therefore A Intersect B = {1,9}

[fast oak]

ohh ok

first and last

[primal berry]

In the example yes, in others it may be different

Just ensure you check all the elements in the set

[fast oak]

ok 👍 👍

how about the set is not intersect

[primal berry]

If the sets have no elements in common then it's called the empty set and has no elements in

So basically {}

[fast oak]

umm can i ask how many ubjects does a set of five elements have 4,8,16,32 which one?

subjects*

[primal berry]

What do you mean by subjects?

[fast oak]

is jsut a given

[primal berry]

Oh, do you mean subsets or?

[primal berry]

Have you met the "choose" function? Or Factorial? (Factorial is "!")

[fast oak]

nope

[glass lichen]

,rotate

[primal berry]

Hmmmm

[fast oak]

can answer number 3?

or how to know the set

[glass lichen]

Do you know power sets?

[fast oak]

collection of set

all subject

[glass lichen]

Power set of A is the set of all subsets of A

[fast oak]

example?

[glass lichen]

You implied you knew power sets...

[fast oak]

8 in number 3

[glass lichen]

No

[fast oak]

4?

[glass lichen]

Don't guess

Do you know power sets Y OR N

[fast oak]

no

[fast oak]

what 2n elements?

[glass lichen]

??

There's no 2n elements

[fast oak]

😦

[glass lichen]

If X has n elements P(X) has 2^n.

[fast oak]

ok

[candid torrent]

power set 😔

stinky

[fast oak]

i know now

five elemrnt have 16?

[glass lichen]

No

2^5 certainly isn't 16

[fast oak]

:0

[opal cloud]

ngl this is a life saving server

[fast oak]

ohh i get it

each element have 2^

[glass lichen]

Poorly phrased but sure

[fast oak]

and five element

[glass lichen]

A set with 5 elements*

[fast oak]

element 2^ five (5)

ok ty sorry if im so not good to understand

what happend if element is letters?

[earnest panther]

In order to determine the amount of subsets, you are only concerned with the amount of elements in the set - not the elements themselves.
Thus, whether your set was A = {1, 2, 3, 4, 5} or A = {a, b, c, d, e}, the amount of subsets would still be the same: 2^5 = 32.

[fast oak]

ok

ty u

[proper socket]

can i have help with (a) <@&286206848099549185>

[earnest panther]

Consider the following: If $\frac{u}{v} = i \cdot k$, then you can rewrite the equality as $u = v \cdot i \cdot k$. $\$
Thus, if you were to substitute $v = a + bi$, you could show both $v$ and $u$ in terms of $a, b$, and thus prove that the expression evaluates to zero.

[ocean seal]

RoiKadmon

[wicked plover]

@earnest panther hey could you help me as well

[proper socket]

@earnest panther kinda confused about the substituion

if i let v=x+iy(since im more used to that format)

what do i sub it into specifically

is it like

[earnest panther]

You're going to get $u$ as a function of the real and imaginary parts of $v$ (meaning $x$ and $y$), and also $k$. When we substitute the equality, we get: $\$
$v = (x + i \cdot y) \cdot i \cdot k = kx i + k i^2 \cdot y \$
and you can continue to find a standard form for $v$ this way.

[ocean seal]

RoiKadmon

[proper socket]

so do we want to find the most simple form of v before we sub it back into the original proof to hence show it = 0

[earnest panther]

Yes. Once you find the standard form for $v$, you can substitute it in the expression $\overline{u} \cdot v + \overline{v} \cdot u$ and get that it equals 0 regardless of the choice of $x$ and $y$.

[ocean seal]

RoiKadmon

[proper socket]

aight ty for the help

[dim falcon]

does someone know how to study the continuity of this func.. couldnt do it myself idk what to do

[earnest panther]

In this case, you can show that each entry is bounded from above, in absolute value, by the magnitude of $(x, y, z)$ as a vector. Meaning: $\$
$|x| \leq \sqrt{x^2 + y^2 + z^2} \$
and the same applies to the other two variables. This way, you can show that the numerator is bounded by $(\sqrt{x^2 + y^2 + z^2})^3$, and you can cancel that with the numerator to show that the entire expression is bounded by $\sqrt{x^2 + y^2 + z^2}$, which tends to zero as $(x, y, z) \xrightarrow{x, y, z \rightarrow 0} (0, 0, 0)$. $\$
As a general idea in this type of function, it helps to consider the general degree of the polynomials in the numerator and the denominator and to try to use that to bind the expression, if possible.

[ocean seal]

RoiKadmon

[rocky spindle]

where is the problem

[pulsar willow]

Can anyone tell me if a NAND2 gate is a NAND gate with 2 inputs or just a mistype?

"Convert the Boolean expression obtained to NAND2 logic."

Created it in logisim with NAND gates but 3 have 3 inputs.

<@&286206848099549185>

[alpine sable]

same as the big sigma, but with multiplication instead of additions

Sigma stands for S : Sum

The big P is a Pi, standing for Product

you're probably more used with the smaller case pi though ^^

[glass lichen]

It's a capital Pi

The notation is Big Pi

[oak jewel]

how is this not correct

That is BS

[velvet condor]

,w d/dx 6x^2/(x^3+1)^2

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Minh Baka#9435

[oak jewel]

see

and i keep getting its false

i should use wolfram to begin with

it says its "(-6 x² (x³ + 1) (3x² (x³ + 1) - 3x² (x³ - 1)) + (x³ + 1)² (6x (x³ + 1) - 6x (x³ - 1))) / (x³ + 1)⁴"

[velvet condor]

i dont wanna read this....

argh

i suppose you can double check using wolfram alpha....

[oak jewel]

not on a test

i have to use this insanity

[velvet condor]

bruh

[oak jewel]

but yeah im glad its correct

i refuse to think wolfram and i got that wrong

[pseudo ocean]

can i ask my question now....

[oak jewel]

ye

[pseudo ocean]

given that x,y,z,t>0 and x+y+z+t=2 minimize $\frac{x^4+y^4+z^4+t^4}{x^3+y^3+z^3+t^3}$

[ocean seal]

bo may lai so may vcl

[oak jewel]

im of no help but i saw your question

[velvet condor]

well

i believe this is some kind of

am gm

brb

[pseudo ocean]

ye thats what we are studying rn

that am gm thingy

[velvet condor]

ah

found a way

you know

@pseudo ocean

theres a type of am gm that states

$(a_1^2+a_2^2+....+a_n^2)(b_1^2+b_2^2+....+b_n^2)\geqslant (a_1 \times b_1+a_2 \times b_2+....+a_n \times b_n)^2$

[ocean seal]

Minh Baka

[velvet condor]

i believe you know this

so

anyways

back to the problem

by applying the inequality stated above

you have $(x^4+y^4+z^4+t^4)(x^2+y^2+z^2+t^2)\geqslant (x^3+y^3+z^3+y^3)^2$

[ocean seal]

Minh Baka

[velvet condor]

or

$\frac{x^4+y^4+z^4+y^4}{x^3+y^3+z^3+t^3}\geqslant \frac{x^3+y^3+z^3+t^3}{x^2+y^2+z^2+y^2}$

[ocean seal]

Minh Baka

[velvet condor]

similarly you have

$(x^3+y^3+z^3+t^3)(x+y+z+t)\geqslant(x^2+y^2+z^2+t^2)^2$

[ocean seal]

Minh Baka

[velvet condor]

idk

also not now bc this channel is in use

so you get $\frac{x^3+y^3+z^3+t^3}{x^2+y^2+z^2+y^2} \geqslant \frac{x^2+y^2+z^2+y^2}{x+y+z+t}$

[ocean seal]

Minh Baka

[velvet condor]

you get the idea

it will eventually "reduce" to $\frac{x+y+z+t}{4}$ which equals $\frac{1}{2}$

[pseudo ocean]

oooooooo

smartie

[ocean seal]

Minh Baka

[pseudo ocean]

thanks

I think I found a way to generalize this problem

but forget about it

thanks @velvet condor

[velvet condor]

you are welcome....

[shadow oak]

Math

[cyan terrace]

how do i prove that a function is differentiable?
by proving that f'(x) is continuous?

more specifically

[craggy salmon]

yeah either that or by using the first principle of derivatives

[cyan terrace]

so is this proof correct?

[edgy perch]

Henlo peeps

Is this solution correct or do I need to sleep and try again tomorrow

[alpine sable]

help

please

[royal meadow]

what have you tried

[alpine sable]

everything

i did y= square root of x-1*3+4

[royal meadow]

well

that's not it

what function do you get after the first step

[alpine sable]

a line

curved

going to the left

is it y=2timesqureroot of x -8

[royal meadow]

no

[royal meadow]

no

[alpine sable]

hi

someone tell me waht this is

[small bear]

m is a real number, m is an element of R

[alpine sable]

so does that mean 2 solutions?

[small bear]

if you were solving an equation, and you got that it is true for all m that are elements of R, it means every m is a solution

[alpine sable]

so 2

for sure

[small bear]

No

Does the set of real numbers contain only 2 elements?

[alpine sable]

no

one element

so its 1?

solution

[small bear]

What is that element?

[alpine sable]

m

[small bear]

Alright, let's go through what R means

R is the set of real numbers

[alpine sable]

okay

[small bear]

all numbers that are integers, fractions, decimals, etc

so this set contains things like 4, 0.21341, 5000, -10.123..., 5/4 etc

As you can see, there are many other numbers in this set

definitely more than 2

[alpine sable]

so indefinite innit

infinite*

[small bear]

So since m could be 4, 0.21341, 5000, -10.123..., 5/4, there are how many solutions?

Exactly

[alpine sable]

thanks you

[small bear]

npp

[alpine sable]

is there any way

to write this

in a diff way

[glacial cave]

yeah

last option

what grade are u in?

[alpine sable]

8th

home schooled

[glacial cave]

@alpine sable ok so i gave u an answer

but can u explain

why is it g=h(e-10)?

cause i dont think u will udnerstand anything just by us giving u answers

[alpine sable]

calculator

told

[glacial cave]

u dont need calculator

[alpine sable]

were allowed to use it

[glacial cave]

its just stupid to use a calculator for this stuff

i mean u can but

idk

[alpine sable]

:/

[glacial cave]

can u tell me what "he" and "10h" have in common?

my english is not the best but i will try my best to explain it to u

[alpine sable]

he is him

and 10h means 10 hours

he is a boy

fuck

i read that wrong

they both have h

[glacial cave]

do u do math just to get rid of it?

[alpine sable]

wym

[glacial cave]

u are not serious rn

thats what i mean'

[alpine sable]

oh

is this 8

im pretty sure it is

since 24 divded by 12 is 2

and 4 x 2 = 8

[raw shard]

it’s 8

[alpine sable]

ty

[glacial cave]

^

[raw shard]

4/12 = 8/24

[alpine sable]

is this 14?

[small bear]

Don't give out answers, also this seems like a test and you aren't allowed to cheat on tests in this server

[glacial cave]

i was about to say that

[alpine sable]

na

[raw shard]

@small bear i didn’t

[alpine sable]

h

i got proof

ill show ya

[raw shard]

i confirmed that their answer was correct

that’s not giving out answers

[glacial cave]

what did u do to get 14?

[alpine sable]

27 divded by 2

is 13.5

[glacial cave]

and how did u get t?

[alpine sable]

so i rounded

[glacial cave]

smh

ok so

[raw shard]

well

you have 14.2 and 14

so rounding isn’t an option

[alpine sable]

14 is closest to 13.5 tho

[raw shard]

ok let me just do this step by step i guess

you have -254 = -10k-2-8k

which simplifies to -252 = -18k

oh you are right

oops

it is 14

[alpine sable]

:)

thanks

can so

[raw shard]

that’s right

now multiply it by 5 and you’ll see it there

aka just (-5r+15)/7

wait no

[alpine sable]

3rd one?

[raw shard]

that’s wrong

[alpine sable]

hmm

[raw shard]

give me a second

need to work this out

[alpine sable]

sure

2nd one isit?

[raw shard]

5r+7s = 15, 7s = 15-5r

no

[waxen copper]

pls help

[raw shard]

i basically just gave you the answer right here

channel is occupied

[alpine sable]

ahh

so last one

thanks

@raw shard

[raw shard]

yeah

[alpine sable]

thanks for the help men

[raw shard]

no problem

[raw shard]

what am i supposed to do with this

[sinful chasm]

quantam, are you well versed with integration?

[raw shard]

nope

barely know anything about it

[waxen copper]

pls help

[misty path]

Help

[raw shard]

@waxen copper i would assume that in that equation you take output of machine a + output of machine b / 2

so multiplying it by 2, you should have 30 = output of machine a + output of machine b

you already have the equation for the output of both machines

that should be enough information

[fallen crow]

dont know if this question goes here because is physics but

water drops of a mass of 3.5*10^(-5) falls into the ground at a ratio of 10 drops per second. What is the average force ejerced by the water on the ground?

xd

[alpine sable]

hello

does anyoen mind helping me

[mild snow]

-3^2 is 9, however most people would right it as (-3)^2

Yes

The issue is with order of operations

because arguably -3^2 could be re-written as -1*3^2

It's a lame trick question

In that scenario the answer is 18

[wary stream]

Because there is a difference between -(3)^2 and (-3)^2

[mild snow]

was it f(3) or f(-3)

ohhhhh

yeah in that case it's really -(x^2)+2x+3

[karmic rapids]

Can you help me here, I somehow stuck on this exercise

I tried 2 ways

[mild snow]

Looking at this the first thing I would do is factor the numerators

That would allow you to nicely cancel out the denominators of both fractions

From there you should have a fairly simple function to solve

[slow swift]

Damn its so bright

[tardy crown]

nice handwriting

[karmic rapids]

I tried to do that on 2nd picture

[slow swift]

Oh reverse complete the square for the top?

[karmic rapids]

you kidding right?

[slow swift]

3x plus 1 3x minus 1?

Yeahhhh

If u do that one of cancels

[mild snow]

Sorry it's really hard to read that handwriting

it's so bright

[karmic rapids]

I will share on original brightness lmao

[slow swift]

@karmic rapids

[round ibex]

hello boys

[slow swift]

Sus name 😔

[round ibex]

nah im not racist lol

[round ibex]

i have an assignment and i need help

[karmic rapids]

omg i tried to factor this but failed but now i tried again and it worked, i dont how to explain

[mild snow]

ok

[slow swift]

You have severely overcomplicated this

[lilac cargo]

how can i solve this limit? :c

any hint

[slow swift]

Ive got no clue mate im shit at maths

[proper rover]

oof. That might be early calculus

I'm guessing plugging in 3 for x gives undefined?

[slow swift]

Who knows im plugging in 3 rn thi

Tho

Seeing what i get

[proper rover]

oh you know what you'll get 0

either that or 0/0

[slow swift]

Its 0

Yeah

[lilac cargo]

undefined

[slow swift]

Nope

Ots 0

Its

0/0

[proper rover]

yeah, so gotta find the point it's approaching

[slow swift]

No clue what the approaching stuff means

[proper rover]

0/0 doesn't equal 0 though

[slow swift]

Mind blown

This probably higher level maths than what i do so yeh

[proper rover]

it means that the graph looks like it's approaching a different point, even though the actual point is at y=0

[slow swift]

Not a question of subbing in 3

Right

[proper rover]

so you've got to find what point the graph seems to be approaching

it's very basic calculus

[slow swift]

An asymptote?

[proper rover]

it might be a horizontal asymptote

[slow swift]

Ah ok

[proper rover]

it might not be, though, it could be just a point discontinuity

[slow swift]

Got no clue what kind of graph ur working with tho

[proper rover]

in other words, the graph could jus skip that one point and then keep going

[slow swift]

Ohh i see

[proper rover]

https://www.youtube.com/watch?time_continue=4&v=15LI9Za0tIc&feature=emb_title

[slow swift]

First principle?

Yet to cover that in my revision

Basically i failed maths right

And im doing resits

So im revising everything from year 1 to year 2 now

First principles is something im gnna get to in differentiation

Rn im on uhhh

This stuff

Go on

Indicie laws

If you divide em minus the powers from each other

So 8^2

2****

Nws

Again just minus the powers

And remember a single number like 3 alone isnt just 3

Its 3 to the power of 1

So 3^-1 divided by 3 is 3^-2

Nws

[tough marsh]

hey

can someone help me with a simpe equation?

-5x > 15

Like it should be -3

or am I wrong?

🤔

[slow swift]

Its -3 yeah @tough marsh

But

Remember to flip the sign

[tough marsh]

because on my brother's test it's 3.5

and i'm like wtf?

[slow swift]

What

Thats wrong lol

Its just x is smaller than minus 3

[tough marsh]

yea
I just thought like I am wrong and etc

[slow swift]

Nah thats probs just a typo

[tough marsh]

Okay thx

[slow swift]

Nws

[tardy crown]

is there another way to write this as an integral?

[slow swift]

What in gods name even is that

[blazing rose]

Anyone know how to start off here?

i dont understand anything u just said

yeah that i know

since we are looking to find the work done by pumping the liquid out of the tank, do we integrate from 0 to 2?

im not sure

Work = mgd?

ok but how can i write this in an integral form

like i dont get it

yeah i wanna learn it

what integration formula would i use

[buoyant kayak]

<@&268886789983436800>

[blazing rose]

i think im using this channel rn lol

[buoyant kayak]

this is a test and he keeps asking for help on it

check #help-1

yeah it is

you've already proven it

[blazing rose]

damn

u just got exposed af

[night geyser]

dealt with

[blazing rose]

LOL

[night geyser]

more because they offered money

[buoyant kayak]

thanks 👍

[blazing rose]

whyd u make a triangle

which 2

oh so since its variable we integrate

[minor crypt]

its always the easiest questions that people are willing to pay for

people being kids

[alpine sable]

can someone help me wit this

i am so sorry

i just want help

and no one is helping

me

[hybrid idol]

be patient, don't spam, its inconsiderate.

[alpine sable]

how does one point on x^2

relate

to the other

parabola

oh ok

so how would we do the problem

because i am really lost

[buoyant kayak]

it's comparing the graph of $x^2$ to the graph of $3(x+2)^2+3$

[ocean seal]

a disappointing son

[alpine sable]

but i do not know how to get the points

[buoyant kayak]

so for your first point, it wants you to find the y value in the graph x^2 when x=-2

so what is y when x=-2?

[alpine sable]

4

[buoyant kayak]

correct

so there is a point on the graph x^2 that is (-2,4)

now, for your new graph, you know the transformations

[alpine sable]

but i do not know how they correspond

[buoyant kayak]

left 2, up 3, vertical stretch by a factor of 3

that is compared to the parent function x^2

[alpine sable]

ok so it would be (-4,7)

am i correct?

[buoyant kayak]

that would be left two and up 3, but you're forgetting the vertical stretch by a factor of 3

[alpine sable]

how would i implement

that

onto the points

[buoyant kayak]

well, what does a vertical stretch do?

[alpine sable]

move it up?

[buoyant kayak]

not quite

[alpine sable]

im not sure

[buoyant kayak]

does vertical stretch effect x or y?

[alpine sable]

y

[buoyant kayak]

right

so by stretching it, you multiply the y value by the factor of the stretch

[alpine sable]

oh

ok

so it would be

(-4,21)

so for the next one

(-2,9)

right?

@buoyant kayak

it is wrong

its -4,15

what about for the second one

ok

the 3rd one is incorrect

but the first two are

thank you

what woulud be the range

though

in interval notation

wdym

[bleak nexus]

@everyone

[alpine sable]

i dont think everyone works lol. and also, why would you ping 30k people

[bleak nexus]

sry :/

[slow swift]

What the dog doin

[gloomy forge]

what does this question mean?

[buoyant kayak]

what happens when you take the inverse of a function?

[hushed pasture]

because every antecedent have only one image then every image has only on antecedent as well which means the inverse function is a bijective function too

[gloomy forge]

x coordinates become y coordinates?

[buoyant kayak]

yes, and...?

[gloomy forge]

and...

i don't know

[buoyant kayak]

well the y coordinates don't just stay y coordinates do they?

do we have two y coordinates?

[gloomy forge]

i honestly dont know

1 inverse and one normal?

[buoyant kayak]

so you know that x becomes y but you don't know what y becomes?

[gloomy forge]

the x?

[buoyant kayak]

yes

[gloomy forge]

okay

[buoyant kayak]

and what needs to be true for a function to exist?

[gloomy forge]

i have no idea 🤣

[buoyant kayak]

do you know of the vertical line test?

[gloomy forge]

ah yes

[buoyant kayak]

what does that tell you?

[gloomy forge]

if its a function or not

[buoyant kayak]

and how do you know if it's not a function?

[gloomy forge]

if the line intersects more than once?

or twice?

[buoyant kayak]

and what is the case when it intersects more than once?

one x value has...

[gloomy forge]

repeated

[buoyant kayak]

not so much repeated

[gloomy forge]

wdym

[buoyant kayak]

i mean, in the picture i drew, one x value has...

it has 2 of something

2 of what corresponds to the same x value?

[gloomy forge]

2 coordinates

[buoyant kayak]

what type of coordinates?

[gloomy forge]

x coordinates? 💀

[buoyant kayak]

2 x coordinates correspond to the same x value? that doesn't make sense, 4 does not equal 2

think of x as the input and y as the output

in this picture, if i were to go to the place where the blue line intersects the x axis, how many outputs do i have?

[gloomy forge]

2?

[buoyant kayak]

yes

so 2 outputs corresponds to what

?

[gloomy forge]

x

[buoyant kayak]

...

[gloomy forge]

im so confused

y?

[buoyant kayak]

yes

you have one x value that you're at. that x value in my picture is the place where the blue line intersects with the x axis.

however, if you go to that x value and draw a vertical line, you see that it touches two points

and let's call that x value 2. so we're at x=2, and we'll call the y values 3 and -3.

we're at x=2, and we have outputs y=3 and y=-3

and that makes it not a function, according to the vertical line test

[gloomy forge]

yes

[buoyant kayak]

and you said yourself...

[buoyant kayak]

.

if the line intersects more than once, that makes it not a function

[gloomy forge]

yes

[buoyant kayak]

so, in other words, if the input has more than 1 output, it's not a function

does that make sense?

[gloomy forge]

yes

[buoyant kayak]

can you write if the input has more than 1 output, it's not a function in terms of x and y?

[jade birch]

Yes

That is the definition of a function

@buoyant kayak

[tawny fox]

Lol

[buoyant kayak]

yeah thanks lmao

didn't quite need an answer from you though

[polar matrix]

Hey, could u help me. I have exercise that I just feel that I can't get right. I'm not great with maths to begin with...

the question is to calculate the angles. I got the a) but can't figure out the b) and c)

[polar matrix]

Please, anyone🥺

[raw shard]

@polar matrix i can maybe help

give me a few minutes

[tight locust]

law of sines and law of cosines

wait you don't have the lengths

[raw shard]

@tight locust @polar matrix make a right triangle using side v as the hypotenuse

[tight locust]

you can calculate them using the lattice points though

the easiest thing might be to just actually calculate what the vectors are

and leave that in rectangular form

then use the formula

[polar matrix]

ok, what would u say is even the asked angle in b)

If I use the 90° angle I get something like this. But still don't know what is the asked angle?

also it was just a rough sketch so not in scale

[bold panther]

Could someone help me plz?

[alpine sable]

multiply by the conjugate

[hidden fjord]

sorry if i dont sound smart like you guys but can someone help with this one question

we're reviewing powers rn

[fervent tartan]

@alpine sable mind helping me?

if not its ok

[alpine sable]

"the high temperature on Wednesday is the least of the three days"

since the number line includes Monday and Tuesday, you just need to look for the inequality that represents the number lower than the lowest

hope that makes sense

[bold panther]

Like this?

???

[alpine sable]

sorry, I was helping someone out

you multiply the equation by the conjugate of the numerator and denominator

[flint badger]

uh

you can just expand it using the sin(a+b) formula though

[bold panther]

I originally tried that before asking for help but then I got stuck simplifying it further :((

[flint badger]

where'd you get stuck?

[bold panther]

What do I do after this?

[flint badger]

well you need to simplify sin(pi/4)

ima be honest im drawing a blank here

but im sure you can simplify it

[bold panther]

Kk

[flint badger]

(√2)/2 should be it

[bold panther]

Kk

[flint badger]

it's gonna look really nasty

[bold panther]

Lolll

[flint badger]

i feel bad for you

im allowed to use this bot right

$\frac{\frac{\sqrt{2}\cos \left(α\right)+\sqrt{2}\sin \left(α\right)}{2}-\frac{\sqrt{2}\cos \left(α\right)-\sqrt{2}\sin \left(α\right)}{2}}{\frac{\sqrt{2}\cos \left(α\right)+\sqrt{2}\sin \left(α\right)}{2}+\frac{\sqrt{2}\cos \left(α\right)-\sqrt{2}\sin \left(α\right)}{2}}$

[ocean seal]

eggdog

[hidden fjord]

@flint badger can you guide me a bit with this one question? sorry if I sound a bit dumb since im in 9th grade

[flint badger]

uhh yeah whats up

@hidden fjord

[bold panther]

AYYY Thx for helping me answer was actually really simple :D

[flint badger]

what'd you get?

[bold panther]

Tan(a)

[flint badger]

oh wow

[hidden fjord]

hold up

so am I trying to simplify here or something? we're doing things about powers

[flint badger]

yeah uh

[proven heart]

Yes

[flint badger]

this is basically just combining powers

and then dividing

so ill let you imagine the numerator as

[proven heart]

Or just cancel them separately

[flint badger]

2 * y * y * y * 3 * x * y * y * y

yeah you could do that but

[proven heart]

Oh yeah

[flint badger]

i just wanna make it simpler

[hidden fjord]

this?

[proven heart]

Yeah

[flint badger]

yeah and then

multiply all the 6 terms together

[hidden fjord]

example?

[flint badger]

and make sure to multiply the coefficients

if you multiply all the y terms together you should get y^6

[proven heart]

Wait.....just cancel terms .that's way easier?I mean...if you want to

[flint badger]

and if you multiply 2 and 3 you get 6

ILL SHOW HIM THAT AFTER

[hidden fjord]

yes

ic

[proven heart]

Ok 😅

[flint badger]

so on the top you should get 6xy^6

[hidden fjord]

ok

and then do I have to solve x and y? or am I set on that

[flint badger]

well you're not setting them equal to anything

[hidden fjord]

alright

[flint badger]

try to do the bottom

[hidden fjord]

ok

8xy^2?

[flint badger]

also you made a mistake here

[hidden fjord]

oops

[flint badger]

oh wait nvm

thats right

I read the question wrong lmao

[proven heart]

lol

[hidden fjord]

is denominator that?

[flint badger]

no so

if you rewrite the bottom out its just 2 * x * 4 * y * x * x

if you combine all the x terms you should get x^3

and there's only one y so you shouldnt have y^2 its just y^1 or y

but you got the 8 right

[hidden fjord]

ohh ok

[flint badger]

so instead its

8x^3y

[proven heart]

what

Oh

[hidden fjord]

?

[proven heart]

Yeah he is right ...what's your question tho

[flint badger]

simplify the entire thing

[hidden fjord]

yo, thanks so much for the help and i'll definetely be practicing this

[flint badger]

if you did everything right you should have (6xy^6)/(8x^3y) right

[hidden fjord]

i didnt have a question I was just responding to the "what"

[proven heart]

Oh.confusion😅

[hidden fjord]

i had numerator right I just needed to flip around some things, didn't have the power of 3

[flint badger]

ok but ur not done yet btw

[hidden fjord]

oh ok

[flint badger]

you need to try to cancel out as many x and y terms as you can

so um how do I explain this im a terrible teacher

$\frac{6xy^6}{8x^3y}$

[ocean seal]

eggdog

[flint badger]

ok so can you simplify 6/8

[hidden fjord]

3xy^6 then? for numerator

[flint badger]

\frac{3xy^6}{4x^3y}

$\frac{3xy^6}{4x^3y}$

[ocean seal]

eggdog

[flint badger]

yes

[hidden fjord]

and cancel x out for both?

or cant do that

[flint badger]

ok but how do you cancel

[hidden fjord]

would u multiply 1x?

[flint badger]

uhh no

basically when you have something like

x/x^3

where the numerator has a lower degree

than the denomiator

MAGISTRATE

wait ur name is not magistrate

i dont know how to freaking explain this

[proven heart]

May I ?

[flint badger]

yeah

[proven heart]

Try to?

[hidden fjord]

😄

[flint badger]

dont cheat on the iready buddy

[proven heart]

Ok so ..the simplest way is just to realise that x^3 is just three x s multiplied together right?

[hidden fjord]

yes kfc

ofc

yeey

[flint badger]

oh wait thats a good way to explain it xD

[fierce frigate]

kfc

lmao

ahajsdfgagshjd

[proven heart]

Well there is only one x on the top .so...only one of the 3 x s in the bottom can cancel with the top x .which means that you'll just be left with x^2 on the denominator

[proven heart]

bruh 😑😂

[fervent tartan]

im not cheating i said help me not tell me the answer

[proven heart]

Do you get it?

[hidden fjord]

so numerator x is gone, so it would be 3y^6?

[flint badger]

thats the iready though lmao

isntt hat a diagnostic

[proven heart]

Yep but now do the same thing for the y s

[hidden fjord]

over the 4x^2y?

[fervent tartan]

yes

[flint badger]

yes

[hidden fjord]

so in this case, numerator is y^5, and denominator has no y?

[flint badger]

correct

[raw shard]

@fervent tartan no one is gonna help you on a test lol

[proven heart]

No...wait what

[flint badger]

$\frac{3y^5}{4x^2}$

final answer

[ocean seal]

eggdog

[fervent tartan]

alr

[raw shard]

that’s called cheating bruh

[proven heart]

Oh so yeah just on the numerator right

[hidden fjord]

yeye

[proven heart]

But wait spicy noodles

Do you know about negative powers?

[flint badger]

$\frac{y^n}{y^m}=y^{n-m}$ heres a rule im pretty sure you know @hidden fjord

[ocean seal]

eggdog

[flint badger]

oops i probably shouldnt have done that

[proven heart]

Ah yes this @hidden fjord

[raw shard]

that rule doesn’t apply

[hidden fjord]

im still in 9th grade and we just got introduce

so not yet

[flint badger]

it does because its y^6/y lol

[vapid herald]

this is jsut +- infinity right

[glass lichen]

in use.

[raw shard]

@flint badger you never mentioned that

[flint badger]

i know i didnt but its in the original question

are we really gonna argue over this

LOL

[proven heart]

Ok like just know this.when you divide terms with the same base but different powers ,you can keep the same base but just subtract the powers.Whereas ,when you multiply terms with same base but different powers ,you can keep the same base and just simply add the powers

[flint badger]

$y^ny^m=y^{n+m}$ is for multiplying

[ocean seal]

eggdog

[proven heart]

Like do you see it,for example,x^3 multiplied by x^5

[proven heart]

Just add 3 and 5

[hidden fjord]

yeye so we learned this, and if for say there was an equation like (p^5)^10 we just multiply?

[proven heart]

Well that's a different story

[flint badger]

yeah in that scenario you multiply the powers

[hidden fjord]

ok ok