help-0

[naive shuttle]

first option (- infinity, infinity)

[sour cypress]

ugh spam then

https://tenor.com/view/russian-russian-dance-dance-gif-17754237

https://tenor.com/view/russian-russian-dance-dance-gif-17754237

[naive shuttle]

senpai

[frozen light]

dont need options

[sour cypress]

yes?

[naive shuttle]

oh mr smart guy

[sour cypress]

?

[naive shuttle]

i got you

i love you senpai

[sour cypress]

...

blushes

[naive shuttle]

mwah

[sour cypress]

https://tenor.com/view/im-a-man-im-a-guy-im-a-dude-male-fake-moustache-gif-16004329

https://tenor.com/view/russian-russian-dance-dance-gif-17754237

[naive shuttle]

i love you even more

[sour cypress]

https://tenor.com/view/soviet-cat-sovicat-soviet-ussr-cat-gif-21826197

[sour cypress]

Oh I get it...

[naive shuttle]

no i am joking i am not gay

[sour cypress]

https://tenor.com/view/milk-and-mocha-bear-couple-kisses-kiss-love-gif-12498627

[naive shuttle]

ima shut up so i wont get banned with you

[frozen light]

domain would be greater than 0
range would be -infinity<f(x)<infinity
vetical asymptote = 0
horizontal asymptote = none

[sour cypress]

Finally someone cares about me

And I only know 2+2

[frozen light]

what?

[naive shuttle]

robertoo

can i have your brain for one day

ill pay

HOW

which one

@frozen light

[frozen light]

range is option a

[frozen light]

well for starters you could stop watching netflix while studying XD

[sterile thistle]

hi

if the area of the base of a prism is 6cm^ what is the volume of the prism

[naive shuttle]

i am watching math documentary

okay

[frozen light]

working or answer?

[alpine sable]

Hello

Is this taken?

[sterile thistle]

@frozen light answer

[alpine sable]

Sorry about that I’ll go to a different question

[frozen light]

?

[frozen light]

depends

[naive shuttle]

robert

that was domain

the options for domain is thoes 4

[frozen light]

?

send

ss

[frozen light]

(2 × 6) + (perimeter of base × height)

[frozen light]

x axis

[naive shuttle]

domain is correct?

[frozen light]

options for domain

1, infinite

[naive shuttle]

so its correct?

[frozen light]

no

[naive shuttle]

OH

[frozen light]

option

c

[naive shuttle]

my bad

i love you man

thanks

[frozen light]

:)

[alpine sable]

Her robertoo

Hey*

U can help me classify polygons?

[harsh belfry]

Have been working on this for awhile now.

Was wondering which step I did incorrectly.

(Sorry if it's hard to follow. I'm erratic)

my product rule and derivatives are correct, however I think the things I chose to be my f(x) or g(x) could be incorrect

But the more my sleep deprived brain thinks about it the less I'm sure of anything.

Would appreciate any help here.

[alpine sable]

Hey vn

Can u help me for a bit

With polygons

[harsh belfry]

I have an exam in 3 hours buddy 😅

Sorry.

[alpine sable]

Oh sorry

Study hard

[short pumice]

Hey is this chsnnel free?

[harsh belfry]

In use

[naive bobcat]

help

[harsh belfry]

Hey cheri, I'm currently using this channel
😅

[naive bobcat]

hi

[naive bobcat]

oh umm

how i remembered anyone can use it tho?

they just needa answer this

[harsh belfry]

Could you use another channel. I have an exam in less than two hours.

And I'm stuck on my question

[naive bobcat]

oh uh sure?

[harsh belfry]

#❓how-to-get-help

[royal meadow]

d/dx (f(gh)) = f'(gh)(g'h + gh')

should be something like (1/x(sqrt(x^2 - 1)))(sqrt(x^2-1) + 2x^2/(sqrt(x^2 - 1))

[naive bobcat]

no one is responding in the other channels can i please have help?

[harsh belfry]

Oh, do I still need to take that expression and do?

I think I see it

Currently solving for it.

[harsh belfry]

Would this work?

[royal meadow]

it doesn't feel likely that every single root will cancel

[royal meadow]

do you see how i got this

[harsh belfry]

A little bit hard to see your process since its in text form

Going to transfer it on to paper

[royal meadow]

yeah sorry i can't texit consistently

[fossil shoal]

Ah nevermind, Welch does that averaging thing and I basically only have one "spike".

[alpine sable]

Can someone help

[naive bobcat]

HELP

[placid zinc]

See my YouTube link?

https://youtu.be/CSd3Ue8QRyg

[naive bobcat]

IT HAS . AND 0??!!1

[alpine sable]

Help @placid zinc

[placid zinc]

@naive bobcat
So 0 shouldn't be any problem. Nothing changes there

When you're doing these, pretend the . isn't there. Then, add it back in at the end

In the first question, the decimal place goes 2 + 2 digits in

[warm smelt]

if i have a permutation of PQR so:

PQR
QPR
RPQ
PRQ
QRP
RQP

How do I figure out the ones that don't have a leading P ? Can't come up with a formula

hi @placid zinc do you remember me? It's been a while. What happened to your honorable role ?

[rigid wind]

[total permutation] - [permutation of characters not P]

[royal meadow]

say there are n letters

the first one can be any letter other than the one you don't want to be first

so n-1 choices

then there's n-1 letters left, and they can go in any order, so it's just (n-1)!

so in total it's just (n-1)(n-1)!

[warm smelt]

thanks

[surreal widget]

answer pls

[sand geode]

hi all,
could anyone help me understand this Theorem in simple terms?

[sand geode]

Should be D @surreal widget

[noble sinew]

What about it?

[sand geode]

I feel like there's a lot of mathematical language i do not understand there

[noble sinew]

Like?

[sand geode]

for each ε > 0.. what does it mean?

[noble sinew]

Another way to say for all epsilon>0

[sand geode]

yes.. what's epsilon.. how does it fit into the theorem and what is it in simple english?

[noble sinew]

I mean why are you reading this if you don’t even know that?

You could also call epsilon x or whatever doesn’t matter

And says you need the absolute value of the partial sum to be less than that epsilon

[bleak pelican]

help?

[topaz scaffold]

For 1 set 2 variables for width and length

Then set up an equation with them with the info given in the prompt

The solve those equations

[tender star]

What is the formula for the surface area? Please someone tell me I'd appreciate it.

[daring schooner]

I'm no expert. But I think you should find the area of triangles and multiply it by no. of triangles. Then add it with area of the square.

[tender star]

Yeah I figured it out in #help-8. Thanks tho!

[forest jacinth]

"On the partitions of sets P(X) of set X we have defined an operation of union U. Show that the operation is closed, associative and commutative."
I understand that my structure is (P(X), U) and I have no problem intuitively solving the problem (because, well, of course those properties hold for the operator), however when it comes to writing a proof I feel stumped (probably because I only proved problems which defined operations on sets of numbers, not something more abstract). If anyone decides to help to solve, I don't need help proving every property, a solution to any one will suffice and I will do the rest on my own.

[ancient agate]

Can someone give me a hint on how to start

oh sorry didn’t see your question above mine

[forest jacinth]

All good, we sent our messages at the same time

[alpine sable]

yall, im asian

[ancient agate]

lol

[alpine nacelle]

Let's prove it's closed. A, B two elements of P(X), then every element of AUB is in X, so AUB is in P(X)

[alpine nacelle]

I won't try to write a formal proof 'cause laziness, but shouldn't E(T) be 10 since one Englishman should leave by turn, on average ?

And then E(N) would be 55

[ancient agate]

I’m not too sure how approach the formal proof however, all I get too is for n = 0,1,2…, set Xn to be in the number of Englishmen in the pub after nth round

[forest jacinth]

Many thanks. 🙌

[ancient agate]

And that we must consider Mn = (Xn + n)1{n<T}

idk if im completely on the wrong path or

[alpine nacelle]

You didn't answer my question

[ancient agate]

oh sorry, but I think so yes

I’m still quite new to this type of mathematics

[alpine nacelle]

Each turn, you're picking a random permutation, the number of Englishmen who leave is the number of fixed points of the permutation

And if X is the number of fixed points of a random permutation, E(X) = 1

[ancient agate]

alright alright yep

[alpine nacelle]

So I'm tempted to say E(T) = 10*E(X)

[analog kettle]

how do you find the 2 equations for this?

[ancient agate]

right right

fuck you’re so smart

[analog kettle]

one of them is y= 2x+1 right?

[ancient agate]

I don’t have solutions but when my prof releases them I’ll have a look

[devout sigil]

does this pass through the origin?

[analog kettle]

oh ig not

not really sure how to do this one but don't you need the derivative for it?

[devout sigil]

no

just use discriminant=0

so if a tangent line passes through the origin we can let this tangent line be y=ax

[sick phoenix]

hi, apparently my 1d and 2b is wrong,, could someone explain?

<@&286206848099549185>

[static kindle]

how can I find the point where two exponential curves intersect?

without the aid of a graphical caluclator

[glass lichen]

Do you have a specific problem...?

[gleaming tree]

hi can someone help me? where does the 0.93 got?

[static kindle]

Not on hand @glass lichen but for, say, 1000 * (1.09)^t) = (10000 * (0.75)^t) how do I find t?

Huh

[glass lichen]

Simplify then take logs...

[quiet cedar]

I want to know whats the prediction I need to use for the particular integral, please ping me 🙂

is it Ypi = Asinx + Bcosx + Csinx + Dcosx (wouldn't be too complicated??)

[glass lichen]

Guess is just a linear combination of sin and cos

[quiet cedar]

but how do I start tho

[glass lichen]

Guess then ug in the guess to determine the coefficients

Plug*

[pine marsh]

how is that last example in B?

[quiet cedar]

thats the asnwer

answer

[glass lichen]

Yeah...

And?

[quiet cedar]

idk im so confused

[glass lichen]

You solve the homogenous version then plug in the guess, that'll give the general solution

[alpine nacelle]

Yes, that's the average number of people that leave each turn

[quiet cedar]

This ?? Asinx + Bcosx + Csinx + Dcosx

[alpine nacelle]

Thanks for pinging without even reading the conv

[glass lichen]

No, just the A and B term...

Clearly the C and D term are accounted for already

[quiet cedar]

Oooo I get it noww

Thank you

[sick ledge]

the unit of gravitational constant is m3⋅kg−1⋅s−2
and the unit of columb law constant is Nm2C-2
could someone explain them what do they mean to me?
the m2 and m3 thing inside the constant unit

ping me if you are willing to help thx a lot
and wish you all best of life

like in gravitational constant,
kg-1 s-2 means per kg per second am i right?
then wtf is m3?
same for columb N for force,every square root of electric charge (cuz -2,so expect square root of particle charge for calculation)
then wtf is m3?

how is m3 related to gravitational constant though
like where does the m3 come out from in gravitational constant
i know like f = ma so kg-1 * m * s-2 makes sense for g
but like the m2 where is it derived from?
also same for m2 in columbs formula

what does m2 represents in gravitational constant
i know like m2 is like a factor for r2
and mathematically i know why m2 is there cuz it is to be divided by r2
but i just dont know why it exists

i refuse to understand it that way

m2 is there for a reason

just like kg-1 meaning that the constant is in general equation of per kg

so its merely representing the proportion?

gravity exists because mass generates gravity
friction exists because atoms of one object interferes with atoms of another object

so yeah i know its stupid but i have to make sure i understand

yes there is a certain extent to first principle reasoning
you dont have to go like too deep
but those symbols are human constructed and is there for a reason

those are axioms and it can be understood both abstractly and logically

some axioms*

yeah i kind of know it is something like that
and thx bro

so what about the m2 in columb's formula?

i mean if its simple formula then why not understand it?
you get to know the reasoning behidn it

lol

coulombb

no like coulomb's law

laughing for my stupidity

anyway

oh yes its analogical to G

im stupid

thx

it may have been derived with complex formulas
but sometimes you know why it works that way by intuition and you dig deeper

anyway

thx all

and i just realised i have asked in a wrong server cuz of how similar the pfp looks

oh ok

i mean just an abstract understanding is ok with like basic concepts
i ask for nothing more
like why its F = ma but not F = m + a
and why isnt F = m*v instead

those can be understood with abstract reasoning

yeah there is like a physics server with a completely same background colour and almost similar symbol or whatsoever

[simple quiver]

is this right and what do i do next?😅

[rich niche]

ye its right

[sick ledge]

but why do we define force like that?
why not M*V?
whats the difference between A and V in Force formula?
because force is not motion
its more like acceleration for continuous devlierance of motion
so its not motion

[simple quiver]

so it cancels out the square root and becomes sin0/cos0 right?

[sick ledge]

that would be momentum

[rich niche]

firstly force is not ma

its dp/dt

[sick ledge]

dp/dt with differential acceleration

[rich niche]

dp/dt is always true, but in some cases mass is not constant with time

then we prefer to use this

[sick ledge]

oh i think i get what you mean now

yeah no reason to dig that deep

thx bruv

indeed

but i have no right to say that

[rich niche]

btw why physics talk in a maths server

[sick ledge]

cuz im more incompetent than anyone else

because i messed it up but physics can also be math

[rich niche]

*applied math

[sick ledge]

but anyway thx all

[simple quiver]

yea i did to this

thanks

[small laurel]

Can anyone please justify did I do it wrong since I’m new to pure maths? Thanks!

[alpine sable]

Is this form valid when integrating an improper integral

[sick ledge]

hope it doesnt bother just last one
despite the formulas being derived from phyiscal phenomenon,
it needs certain extent of abstract reasoning in order to come to this formula combined with concepts,instead of like blindly repeating observation

so what i am trying to do is make sense like newton did

like force = mass x acceleration (noob formula because i am noob)
why it isnt velocity is because acceleration tells you about the easiness of an object to reach to a certain velocity x m/s
rather than the motion at the time

example:

two objects can have same extent of motion,with one have much higher acceleration and one with much lower accleration
the one with much higher accleration must exert much greater force

because force is about continuous motion to generate motion/pressure in a certain time frame according to my understanding
so like it has to be acceleration instead of velocity

like they define it not only because of observation but abstract reasoning as well
@alpine sable

super sorry for the ping but this is something that bothers me so so so so so much
how to penetrate the concepts to the level until you know enough

like force is calculated by projecting the accleration of a certain object
to a certain time interval
to measure the certain force

because i was quite bothered with the fact that force isnt calculated with velocity
so as i said like two objects with same motion at one point it can generate different force(with the same motion and mass)
because accleration differs in two objects

[obtuse sluice]

how do i make a quadratic recursive equation

wtf is a quadratic polynomial

what

🧊

I’m gonna ask

something else

how am i acting like a prick

🗿

i mean I’m sorry

but damn

[sick ledge]

yeah i know but like
accleration is slightly different than velocity
just divided once more by the time already makes great difference
and the fact that it involves two state of motion already implies that force needs two velocity (motion transferred at one point) rather than like the instantaneous velocity
anyway yes imma stop here
thx for your time really appreciate it

a = v/t

like two motion state

yes i guess i just try to perform rational thinking on anything

[small laurel]

Do I have to take away 1.5 & -1.5 & -4.5? Thanks

[sick ledge]

alr thx
Imma speedrun calculus when i have time

[topaz scaffold]

Nice nice

Calculus is fun to learn by yourself

At least it was for me

[glass lichen]

Calc 3 is multivariate, it's not just R3

[icy mauve]

@everyone

[strange umbra]

2x+3y−z=1
x−2y+3z=2
−2x−3y+z=4

what is the geometrical arrangements of the equations

i got 0 0 0 5 for third row

using echelon form

what is that?

no

im trying to get the geometrical arrangements

"Match the sets of simultaneous equations with the geometrical arrangements of three planes."

yes

it doesnt have a solution as it is not consistent

it doesnt has a inverse either

and im just trying to find its geometrical arrangement but not solution

that what i get in a matrix calculator

yes please

how do you get there?

how do you get the 7

that why its asking its geometrical arrangements

[glass lichen]

They already said it has no solution cause of the 0=5 row

Geometrically the 3 planes never cross

[royal meadow]

by 'geometrical arrangements' do you mean 'interpret this geometrically'

yeah

??

[glass lichen]

What??

[royal meadow]

what exist in different planes

[glass lichen]

The 3 planes don't cross, that's it.

[amber iron]

Hi is anyone here good at verifying proofs

[glass lichen]

Well you failed then

[strange umbra]

the answers are planes meet at a single point, sheaf of planes, two parallel planes with the third intersecting them, triangular prism, three parallel plane

its a multiple coice

[royal meadow]

they never all meet, and none of them are parallel

[strange umbra]

they doesnt cross at a single point but two might cross at a point

[royal meadow]

so there's only one option left right

[glass lichen]

No

They don't cross period.

[royal meadow]

i think any two of the planes will intersect in lines

[glass lichen]

Oh you mean taken 2 at a time

Right

[strange umbra]

i tried triangular prism and its not the answer

[royal meadow]

shit

the first and third are parallel

[royal meadow]

it's here

[strange umbra]

here

[royal meadow]

first and third are parallel, the third is just doing its own thing intersecting both

[strange umbra]

oh ok so i guess its two parallel planes with the third intersecting them

[royal meadow]

can't believe i missed that

[umbral pagoda]

Is there an app that can determine where the mean is on an image of a bell curve? <@&286206848099549185>

[rigid wind]

image?

[rigid wind]

use a ruler and guess ..

[silk terrace]

Hello, can someone help me find the symmetric difference of the 2 sets

[echo idol]

dont ask to ask just ask

[glass lichen]

Write A as intervals, then just do the set difference

[silk terrace]

how would you do that the solutions to x^2<=x+1?

[glass lichen]

Solve it...

[royal meadow]

x^2 - x - 1 <= 0

[silk terrace]

Ty

[royal meadow]

draw a diagram, find the roots and then it's intuitive

[barren helm]

7⁹³/ 7⁹⁰

how to do it?

[glass lichen]

Exponent laws

[barren helm]

wat ta

no

cube root

or something

[glass lichen]

???

[proper rover]

compute the 9^3, then subtract the bottom exponent from the top

[barren helm]

da heck

bruh

[glass lichen]

Like I told you the answer and you said no

[barren helm]

tlee me ps

tell

[glass lichen]

So why are you asking for help if you know what the correct answer is

[glass lichen]

I already you'd you

Told*

[barren helm]

idk how to work it out

[glass lichen]

Apply the spot opiate exponent laws...

[echo idol]

read your lesson on exponent laws

[glass lichen]

Appropriate

[proper rover]

google it. Divide exponential numbers or smth

[barren helm]

idk wat tht is

[royal meadow]

google it

[barren helm]

k

[glass lichen]

Power laws, index laws are both synonymous

[barren helm]

||google is the next math thing or smthing||

[glass lichen]

Nah, we're just not gonna tell you stuff you should have in your notes/easily searchable

[barren helm]

ok

People get on my nerves, a lot... like, a lot a lot ❤️

i do not

btw

huh?

bruh

?

[echo idol]

yes

[barren helm]

is it kile tht

like*

k

so

answer is

7³

right>

?

[echo idol]

yes

[barren helm]

k

ty every one

bye

and goodnight

[proper rover]

Hi, so I'm attempting to create a parametric array for architecture as shown below. The goal is to generate an array of windows (rectangles), with a consistent gap while adjusting the length of each rectangle based on the wall space available. The array is generated based on one rectangle, whose length is then added to the gap to find the offset vector. The problem is that at different angles, the offset distance is affected by the component x and y vectors. the goal is to generate a vector of angle theta and magnitude f

So I need to find the equation required for x(y) to equal f, where F is a variable and the angle is known. The equation should say, "given theta, f = x(y)," basically solving for both x and y.

https://cdn.discordapp.com/attachments/891474420755992656/895710682241171476/20211007_113356.jpg

[barren helm]

da hell

[royal meadow]

ok so

[barren helm]

answer is i am 13 and dume

[royal meadow]

you want to find x and y given f and theta?

[barren helm]

k bye

[proper rover]

that's correct

[royal meadow]

(x, y) = (fcos(t), fsin(t))

[proper rover]

ok, and t is the angle, correct?

[royal meadow]

yes

[proper rover]

got it, I'll try it now.

It looks like it's working!!! Thank you!

[granite lily]

I find 17 very impossible to solve this help plzz

[oak hound]

can u people look trough #prealg-and-algebra pls?

[barren helm]

hi

um

so

a triangle pqr in which pq=7cm,angle pqr=40⁰ ,angle rpq=90⁰

[royal meadow]

this channel's in use, try another

[barren helm]

k

ty

[royal meadow]

channel in use

try another

[royal meadow]

s = (v^2 - u^2)/2a
a = F/m = uR/m = umg/m = ug
s = (v^2 - u^2)/2ug

that should be more than enough to work with

[alpine sable]

can someone help me w this

spreading it everything? calm down i sent it to one channel n didn’t get a reply 😂😂😂

yea help w me it what’s wrong w that

[merry umbra]

American school is a branch of industry full of students(enrolled employees) hard labor no learning just workers

[alpine sable]

expecting people to do it for me ? calm down i asked for help 😂😂😂

you jus taking it outta proportion

What's the logic behind |x| > a being "or", while |x| < a being "and"?

[forest jacinth]

A number can't simultaneously be bigger than a and smaller than -a, while it can be both smaller than a and larger than -a

Similar logic applies to or

[alpine sable]

oh

thanks

Is this channel free?

[rare ledge]

2$

[alpine sable]

I mean

Occupied

[rare ledge]

its free

[alpine sable]

Ok then

In a shop there are 40 boxes of fruits
17 of boxes are with apples
12 of boxes are with apples and bananas
Other boxes are with bananas
How many boxes are with bananas

[rare ledge]

...

[alpine sable]

What?

Can someone help me with that fast

[lapis goblet]

Yeah

[forest jacinth]

Read the question again

[alpine sable]

Why?

[lapis goblet]

17 + 12 +z =40

[alpine sable]

Fixed it

[lapis goblet]

Do they want banana box exclusively

[alpine sable]

Yes

[lapis goblet]

Then my equation holds

[alpine sable]

So this means

29 + z = 40

[lapis goblet]

Yes

[alpine sable]

z=40-29

[lapis goblet]

Yes

[alpine sable]

Which is 11

Tysm

[lapis goblet]

precisely

[blazing rose]

if i was to find the area bounded by these 3 lines

would it be the area bounded by these points?

[lapis goblet]

yes

[rare ledge]

wont you count the boxes which contain both apples and bananas too? (according to the question)

[lapis goblet]

Only wants baba exclusive box

[rare ledge]

if it was written "bananas only" then your answer wouldve been correct

okay ig

[blazing rose]

how would i construct the integrals tho

top - bottom?

[lapis goblet]

Your bounds of integration would be the points

[blazing rose]

yeah i get that

im saying to make the integrals to find the area with respect to x

Would it be this?

wait what

idk why its blank lmfao

[lapis goblet]

I believe you would do integral from -3 to 2 of x^2 - 9x/2

Like subtract the 2 functions

[blazing rose]

like this?

[lapis goblet]

Yeah you could do that lol

But you can do it all at once

Just by doing -3 to 2 of the parabola - line

[grim pelican]

hey can help? UwU

[blazing rose]

wdym

[lapis goblet]

nvm your way works

I’m confusing myself

[blazing rose]

oh alright

thanks

what about finding the volume of the bounded region

[elder viper]

don't duplicate posts in multiple channels

[blazing rose]

using crossections

[elder viper]

@grim pelican

[lapis goblet]

Volume around what? @blazing rose

[blazing rose]

cross sections, not revolutions

[lapis goblet]

Hmm

[blazing rose]

cross section is a square perpendicular to the y-axis

[grim pelican]

oops my bad

[lapis goblet]

I don’t get this

Like a square in the zy- plane?

[blazing rose]

have you learned cross sections?

[lapis goblet]

I forget lol

[blazing rose]

o lmao

but yeah

thats the idea im pretty sure

the squares are perpendicular to the y axis and kinda stick out in the 3rd dimension

[lapis goblet]

I still don’t get volume tho, it’s still 2 flat surfaces

Mahbe u mean cube

[blazing rose]

no no

idk how to explain it i just learned it

im just trying to check if my work is right lmao

[lapis goblet]

No clue then lol, I’ll try and look it up see if remember anything

[blazing rose]

so basically the base is the bounded region, and squares come out of the base

like this

drawing is super bad tho

[lapis goblet]

Huh

I don’t recall ever doing thing but maybe you just like

Integrate the area of the square or something

From the bounds of your original

And the side of the square would be what 9 in this case

[blazing rose]

alright thanks for your help

[alpine sable]

Quick question, is this a compound/complex shape or is it basic?

[tame crag]

Hey, I'm doing a Grade 12 Math course so I can get into a college program. I've been out of high school for six years, and my online course doesn't review much. How does y = ( x - 3)^2 become x^2 - 6x + 9? Where is the 9 coming from? Why are the 3s being added and multiplied?

Another question had this formula: p (x) = _- 4 3xx + 2 2  + 6 x. That's literally how it was written in the practice questions. Apparently that's "one polynomial function, − 4 x 2 + 6x, is being divided by another, 3 x + 2 , " Where is the division? Did the person writing the questions screw up?

[royal meadow]

wrt. the second one, they screwed up

[alpine sable]

Uhm

[royal meadow]

wrt. the first, (x-3)^2 = (x-3)(x-3) = x(x-3) - 3(x-3) = x^2 - 3x - 3x + 9 = x^2 - 6x + 9

[alpine sable]

Is my question too complicated

Or malformed

[royal meadow]

oh, i didn't see yours

[tame crag]

I thought so. They clearly didn't format the equation properly.

[royal meadow]

idk the definition of basic vs complex

[alpine sable]

Welp

[royal meadow]

do you have a definition

[alpine sable]

It says it is made up of two basic shapes

For compound

[royal meadow]

define basic shape

[alpine sable]

It's either compound or basic.

[royal meadow]

that's... general

[vague pecan]

if i had to guess i would say compound because it it two pyramids stacked on one another

[royal meadow]

it's platonic tho

[vague pecan]

a composition of two simple shapes

[alpine sable]

So the two simple shapes can be the same?

[placid zinc]

The way it has two colors makes me think they're leading you to an answer, but yeah "basic" is not a real thing

[royal meadow]

that's a wikipedia picture i think

colours probs not relevant

[alpine sable]

it's compound

im pretty sure

[alpine sable]

Lol color is crucial

[royal meadow]

not in this case

[alpine sable]

Don’t think “pretty sure” is a satisfiable answer

Color can be 2 shapes crashing into each other

No offense

[alpine sable]

Non taken

[royal meadow]

negative, did you google octahedron?

to find the picture

bc it's the wikipedia picture

[royal meadow]

.

[alpine sable]

So why is it compound

Or is it compound idk

[royal meadow]

compound shapes don't actually exist

pls can you answer my q

[alpine sable]

because the structure looks like a pyramid

2 pyramids

Whats ur q

Dependent on the color

[royal meadow]

.

[alpine sable]

I don’t get the question

Yes I got it from the internet

If that’s what u mean

[royal meadow]

yeah, so if it didn't come with the question

then the colours probs aren't significant

[alpine sable]

Yes I’m asking my own question

?

[royal meadow]

i see

[alpine sable]

Idk who mentioned colors

[royal meadow]

this guy

[alpine sable]

I was just asking if it was compound

[royal meadow]

the problem is that 'compound' isn't well-defined

[alpine sable]

they probably are

[royal meadow]

bruh

the guy asking just took a random picture off the internet

they're not significant

[alpine sable]

dude

It's dependent

On the question

[royal meadow]

there is no actual homework question

[alpine sable]

Ye

[royal meadow]

they're just curious

[alpine sable]

ok

[royal meadow]

here's the wikipedia pic for a cube

are the colours significant

no

[alpine sable]

well it's a cube

[royal meadow]

i agree.

[alpine sable]

Going off the defintion that exists. Is it compound?

The octahedron

[royal meadow]

what definition

you've defined compound shape in terms of basic shape

but you haven't defined basic shape

[alpine sable]

The definition on google

Not my definition

[royal meadow]

i can't find a definition for basic shape on the front page of google

[alpine sable]

The first result

[placid zinc]

Are the "basic shapes" literally 2D objects

[abstract prairie]

you know what would be cool

[alpine sable]

Maybe?

Idk might be 3d

[royal meadow]

this is not a mathematical definition

[placid zinc]

[royal meadow]

they literally talk about like body shape

[alpine sable]

@alpine sable im pretty sure u pulled that question off from visualising solid shapes

Huh

basic compound and complex

shapes

Yeah

U pulled it from visualising solid shapes

Go search there

I pulled it

What does that mean

U got it from there

Also this is math def I found

From where

[royal meadow]

that doesn't properly define basic shape

it gives some examples, but no proper definition

[alpine sable]

it defines outlines and examples

[royal meadow]

because basic shape is only a rough category

[alpine sable]

There is probably more on the site

[royal meadow]

not a rigorous concept

[tame crag]

I still don't understand this. Why do you put x and 3 outside of the two (x-3)s?

[royal meadow]

i bet there isn't

[alpine sable]

Did u search for the definition?

[royal meadow]

(a+b)c = ab + bc

[alpine sable]

How did u not find any results

[royal meadow]

i did

i couldn't find any good results

[alpine sable]

tf is that 2nd question

[tame crag]

That's ILC for you

[alpine sable]

Does anyone else know

Wuts ilc

[alpine sable]

you cannot define really

Then why does my teacher use a non existent term

Bruh

[alpine sable]

U took mpc?

[tame crag]

Independent Learning Centre I think. It's where I'm taking this math course. There's a lot of typos in the questions and answers. It's weird.

[alpine sable]

damn bold

Ah

[royal meadow]

sounds sketchy

[alpine sable]

Yo so is there no definition

Wut

[alpine sable]

Well there are

[royal meadow]

there's no precise mathematical definition

[alpine sable]

My teacher uses this term

But you can call them "theories"

[tame crag]

I don't know what that is.

[royal meadow]

yeah, it's not a real maths term

it's just a sorta vague description

[alpine sable]

it's basically not yet confirmed

[royal meadow]

for lower-level maths learning

[alpine sable]

Welp

Ok

[alpine sable]

it's a course after 10th.

here in sweden there are many courses u can pick after ur 10th.

mpc stands for maths physics and science

[tame crag]

I've been out of high school since 2015

[alpine sable]

@tame crag

[royal meadow]

ok

i don't care

do you understand it, or

[tame crag]

No, I don't.

[alpine sable]

bruh its simple

[royal meadow]

shh

ok so

we're doing (x-3)(x-3)

let x be a, let -3 be b, let (x-3) be c

so i'm saying (a+b)c = ac + bc

ie. (x-3)(x-3) = x(x-3) - 3(x-3)

any better?

[torpid vine]

can someone help me with math 8 grade level

[warm brook]

@torpid vine don't spam the questions channels

with the same question

[alpine sable]

I helped

[royal meadow]

...?

[torpid vine]

.

[alpine sable]

can somone solve this math problem

[surreal sun]

Do it slowly, step by step and it should be fine

[alpine sable]

and which method are u using

[silk veldt]

I will calculate it with work

[alpine sable]

BODMAS or PEDMAS

im pretty sure its bedmas

okay then first solve the brackets

4

oh wait

does 2 need to be inside the braket

?

[tough tangle]

@indigo marlin

[silk veldt]

@alpine sable

[tough tangle]

ask your question here

[indigo marlin]

Oh hiya

8.2
0.067
−
0.108
+
(
6.9
0.063
)
2

oop why it done that

one sec

[silk veldt]

I think I can help you on this one

[indigo marlin]

oh thats good ill send a pic

One sec sorry

Ill send it on private so its quicker

Unless u can work out it like that

[silk veldt]

Send it to me

[tough tangle]

ok send it to him

only

[indigo marlin]

Tysm for offering I needa go now sorry

Ty tho

[silk veldt]

Just reach out whenever you need help again!

[dreamy ridge]

how do i do part g

[pliant verge]

Is this the correct way to say this? If not, can you correct me?
10^n(x/10^⌈log10(x+1)⌉)
10 to the power of n, multiplied by x divided by 10 to the power of the ceiling of logarithmic 10, x plus 1

[bright mesa]

im confused on how to foil a radical like can they multiply one another

if so can I get to what

but its in the radical

?_?

so would it be 9

radical

?

oh wait do I factor them after they become 9 and take the pairs out?

[alpine sable]

can anyone help me with this. Ive been trying the past hour to get this right but theres always one part wrong

[bright mesa]

tysm I appreciate it I asked how ya got it but I think I figured it out because u did the factors of 9 and took
the pairs of 3 on the outside

tysm

[alpine sable]

thats what im saying

its so wack

can someone help me solve this

[modest sky]

i need like advice in a way. how can i get comfortable with radians. i know the basics but when i have to make a scale to plot a sinusoidal function on a graph, i take 10 minutes and most of the times, its not even an efficent scale. thats what i need most help with

help </3

[marble storm]

am i doing this correctly i just want to make sure im on the right trac k

[noble sinew]

b) and c) are wrong

[oak chasm]

@marble storm The filled in circles are where the function is, not the empty circles.

[modest sky]

uhh

[marble storm]

yahhh

[alpine sable]

Is it 0?

Which one?

Those values are correct

[abstract junco]

i need help desperately

[gaunt sky]

@abstract junco
Since the functions are linear, you only need to calculate 2 points for each one and then connect them.

[abstract junco]

alr

[gaunt sky]

I've been thinking about this problem.

Imagine that 1024 people participate in a tournament, in a swiss tournament style.

There are 9 matches in total for each participant, (2 of them can't get matched more than once).

What's the maximum amount of participants that can get 9 wins?

[alpine sable]

I think it’s half

512

Is it swiss? (have to go vs someone with same rating)

Or can anyone match anyone provided they haven’t played before

@gaunt sky

[gaunt sky]

It could be half if people could play against the same people again and again. I don't it can be such a high number in this kind of match table.

[alpine sable]

No, not specifically

Imagine you have a round table of 512 people and 512 more people come and stand behind them

And after that the 512 standing people can move to the left

[gaunt sky]

people who win the first match will also be seeded against people who also won the first match

[alpine sable]

Hence all different games

[alpine sable]

right

then it’s just 2 i think

[gaunt sky]

2 seems a bit low, no?

[alpine sable]

no

1024 / 2^9

[gaunt sky]

I don't get where the 2^9 comes from, would you elaborate?

[alpine sable]

For each game, half the people win and half lose

So after game one half the people have won all their games

After game 2 it’s half of thst

So it’s all the people divided by 2x2x2 nine times

hence 2

[gaunt sky]

That makes sense, thanks for the help 🙏

Then a more complicated question: How many people can go 8-1?

since even if you lose the first game you can still win the remaining 8. Or you can lose a random one in the middle.

And how would you generalize the problem?

[gaunt sky]

Is it 8x2 = 16?

[alpine sable]

It’s just the 9th row of pascal’s triangle x 2

So 18 not 16

[gaunt sky]

2x9 then

Hmm

[alpine sable]

What you’re basically doing is doing 8C9 x 2

Since there are 9 games

And you have to win 8

How many ways are there of picking 8 things from 9

x2 because 1024 is 2^10

[gaunt sky]

Ok, this makes sense

[alpine sable]

The next one would be 7C9 x 2

And the next one would be 6C9 x 2

You also have to divide by a value because the games are non-distinct

Google “combination formula”

[gaunt sky]

Will do

[alpine sable]

And pascal’s triangle

[gaunt sky]

I know about pascal's triangle, I just didn't associate it with this problem

It does make sense though

[blazing rose]

Can someone explain how i can draw the shaded region

im confused on which shaded region is the correct one

[charred flint]

@blazing rose when you draw the graphs, there's be exactly one region with 3 sides that are those 3 equations

[gaunt sky]

@blazing rose maybe the visual guide might help

[charred flint]

oh wait the question is really strange, there are 2 regions O_o

I would just ignore the 2/9y equation

[small bear]

There are 3

[lucid imp]

is this channel open?

[small bear]

What have you done so far?

[alpine sable]

Im taking the PSAT in a couple days, any tips on revision for the math portion?

[lucid imp]

nothing, I have no idea how to do these graph questions

table*

[small bear]

Well it is asking you for H'(3), can you first find the derivative of H'(x)?

[lucid imp]

alright give me a sec

[lucid imp]

1/5

?

[small bear]

How did you get that?

[amber iron]

is this channel open after this?

[lucid imp]

to find the derivative of ln its 1/(argument) * derivative of argument

H(3) = 1/5

[small bear]

Is H the argument?

Look at the function closely

[lucid imp]

5 is

since based off the table

[small bear]

ln(F(x)) <--

not ln(H(x))

[lucid imp]

but it says H(x) = ln(f(x)

[small bear]

It does, and?

[lucid imp]

so if the x in H(x) is 3

then wouldn't i replace the x in f(x) with a 3 as well

and based off the graph

that would be 5

table*

[small bear]

Let's replace them later, can you give me the derivative of H in terms of x?

[lucid imp]

alright

[small bear]

Don't skip steps

[lucid imp]

How would I do that

[small bear]

We want H'(x)
From H(x) = ln(F(x)) we take the derivative of both sides
H'(x) = [ln(F(x))]'

Can you simplify the right hand side?

[lucid imp]

I've never seen this before

would I use the log rule?

1/arg *derivative of arg?

[small bear]

We are looking for the derivative of a composition of functions, so yeah

The log rule works here

[small bear]

Can you write what we get after using that

[lucid imp]

so 1/f(x) *f'(x)

like that?

[small bear]

Great!

[lucid imp]

ayy

[small bear]

We have H'(x) = f'(x) / f(x)

What happens when you plug in x=3?

[lucid imp]

it becomes 4/5

[small bear]

Yup, that's all

[lucid imp]

Thanks so much!!!

[small bear]

Anytime

[lucid imp]

You think you could help me with 2 more?

if you have time?

[small bear]

Try them yourself, if you get stuck post here, either I or someone else will assist

[lucid imp]

Alright

[blazing rose]

thats what im trying to understand

do i use all the regions?

[lucid imp]

is this corrct

[blazing rose]

I went on desmos and tried this but theres more than 1 region

[blazing rose]

no. you gave 1st derivative. question is asking for 2nd derivative

[lucid imp]

oh

this then

[gaunt sky]

That should be the only one where all the 3 functions together make an area. Although there is indeed one more from only the quadratic and the y=9

[lucid imp]

RIP

[small bear]

Uh, I really don't know which one you should pick, perhaps find the area of all and whichever is the nicest go with that; go with the one that you feel would be the easiest to find

[lucid imp]

only got a minute left on hw with 3 questions left

[blazing rose]

yes

[blazing rose]

theres even more than this tho

1 sec

ill send a diagram

[gaunt sky]

Oh true, Theres that one too

[small bear]

I'd go with purple ^^

[blazing rose]

maybe its every possible one?

like multiple regions/

?

[small bear]

Don't think so

[blazing rose]

damn

i plugged this into my calc

TI-NSpire CX CAS

[small bear]

Which areas are you talking about? (Those vertical lines aren't given for this problem [at least in the image you attached])

[blazing rose]

im confused af tbh

[small bear]

Can you post the whole question?

[blazing rose]

that is the whole question

part a) [the part im on] is saying to just draw the region

part b is constructing integral(s) to get the area of the region

[amber iron]

Could someone help me with understanding this calc stuff

[small bear]

Well, I guess for completeness calculate all of them, and write all the areas of those regions. Silly problem but yeah, should work

[blazing rose]

im so confused with this problem

[amber iron]

why wouldn't df(x,y)/dx also be 0 if it's defined as equal to z?

nvm

got it

[gaunt sky]

@small bear
Wait, are you sure H'(x) = f'(x) / f(x)?
If H(x) = ln(f(x)), shouldn't H'(x) = f'(x) * (ln(f(x))' = f'(x)*f'(x)/f(x)?

where (ln(f(x)))' = f'(x)/f(x)

[abstract junco]

i need help

[gaunt sky]

same thing as before. You might wanna rearrange the 2nd function so y is alone on the left side

[abstract junco]

and how do i do that

[upbeat gorge]

should be -1

[gaunt sky]

yes true

now again, calculate any 2 points in the graph and connect them. It's a linear function

[hallow cosmos]

Can I have some help here? I'm so lost

it looks so simple, yet everything I tried was wrong

[small bear]

The rule doesn't imply what you wrote, also in brackets it should be ln'(f(x)) which is different than (ln(f(x))'

,w derivative of ln(f(x))

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by peaceGiant#0724

[gaunt sky]

whats ln'(f(x)) equal to?

[small bear]

When factoring, you are supposed to take out x^2 from both the terms, however you left x^2 in the brackets alone

[small bear]

,w ln'(f(x))

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by peaceGiant#0724

[cloud dew]

I have no idea what to do for this

[small bear]

Occupied, please go to another channel

[gaunt sky]

why is it 1/f(x) and not f'(x)/f(x)? :/ I'm so confused

[small bear]

The chain rule says the derivative of f(g(x)) is f'(g(x)) * g'(x)

in the first case, rather in f'(g(x)) the derivative isn't acting on g

[hallow cosmos]

hmm I see you're point, yeah I saw my mistake

I got it, thanks

[gaunt sky]

I'm talking just about log'(f(x))

[small bear]

I wrote x^2 but I meant sqrt(x), I hope the point is clear

What is log'(x)?

[gaunt sky]

1/x

[small bear]

Sub x with f(x) since the chain rule took care of the other part

[gaunt sky]

but I think of it as x'/x which is 1/x

[small bear]

Which is the same as f'(x) / f(x)

[gaunt sky]

unless I'm just confused and remembering wrong

but why is f'(x) = 1

[small bear]

It isn't

H'(x) = [log(f(x))]'
      = f'(x) * log'(f(x))
      = f'(x) * 1 / f(x)
      = f'(x) / f(x)

[gaunt sky]

yes, but the only part I'm confused about is still why f'(x)/f(x) = 1/f(x)

[small bear]

Maybe it is troubling you that in the second part, we are differentiating with respect to f(x) since the ' is ambiguous

[gaunt sky]

this step right here

[small bear]

Because we are differentiating with respect to f(x) and not just x

Are you familiar with Leibniz notation?

[gaunt sky]

oh, so it's like d f(x) /df(x)?

[small bear]

d log(f(x)) / df(x)

[gaunt sky]

ok, it's starting to make more sense, but now how to you know the ' means d (...) / df(x)

[small bear]

Chain rule implies that, I thought it was obvious so I just proceeded that way, my apologies

[gaunt sky]

all good, it's not your fault

ah yes, of course

I had forgotten about that one

Thanks mate

[small bear]

No worries

[ivory gulch]

hello

this is open right?

i watched the video and the view an example for this problem and i still just don't understand

i know how to google the formula for a cone

isnt is like 1/2 r^2 pi

lemme check

okay cool

i was kinda close

1/3 h pi r^2

how fast the coffee is rising

when its 7in deep

so that's what is dh/dt when h=7

?

yeah sure

but negative

oh wait

no yeah im dumb

i agree

yeah no i was thinking smth else

ok so yes i agree

6in^3 / min

1/3 r^2 h pi

[ocean seal]

marc

[ivory gulch]

$V'=\frac{\pi }{3}\left(2rr'h'\right)$

[ocean seal]

ski

[ivory gulch]

?

[twin badger]

Anyone using this

[ivory gulch]

bruh

yes

[twin badger]

Okay

[ivory gulch]

r' = dr/dt

h' = dh/dt