#help-0

1 messages · Page 832 of 1

glossy briar
#

then what does the other one do

warm brook
#

@devout hornet I know that this got buried, but if you have any questions/comments, please do
The way to find c in this case is to use the product and the constants given by (n+1)! and your (x-x_k)

warm brook
glossy briar
#

oh

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so its not a function

warm brook
#

Yes, tbh zeta can be named anything, but it was just chosen with that variable for whatever reason

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It's just conventional

glossy briar
#

someone needs to right a book full of these weird functions and there nmes as well as what they do

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like the one where if you have an even number of factors you add 1 or an odd number of factors you subtract one

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where it suprisingly can escape root n

warm brook
glossy briar
#

hang on let me find the name of the function

warm brook
#

Granted, the existence of the internet makes it kinda redundant for such a physical collection. I'm not aware of a collection of functions on the internet but there is the OEIS which is an encyclopedia of integer sequences

glossy briar
#

oh its mu

warm brook
#

uh

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I mentioned that functions can be named anything, the label like that isn't really as iconic as the zeta function

glossy briar
#

its part of mertenes conjecture

warm brook
#

Yea, that's the notable part

devout hornet
warm brook
glossy briar
#

what do you mean by buried tomc123?

warm brook
#

I meant it got buried because there's a discussion happening in questions

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while I was helping them lmao

glossy briar
#

oh thanks

#

also how do you make the bot screen your question

#

like this $\zeta(2)=\pi^2/6$

ocean sealBOT
#

Mrmangoman1123

warm brook
#

That's LaTeX, it's a typesetting language used typically in math, or other academic settings

glossy briar
#

i know but how do you right in latex

warm brook
#

I've been using it for the better part of like 3-4 years now

glossy briar
#

thanks

#

it is helpfull

#

hey do you have a favourite constant

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mine is the Buenos Aires constant and it equalls 2.920050977316...

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it is used for finding primes

warm brook
#

feigenbaum's constants are interesting, they represent the limiting ratio of the bifurcations of nonlinear maps

glossy briar
#

errrrrrrrrrrrrrrrr..........................

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its approximatly 4.6692016

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that is really cool

covert cradle
#

4 right? factoring, completing the square, quadratic formula, extracting the roots?

warm brook
glossy briar
#

yes its always two

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because of the add or minus sign

somber cape
#

@covert cradle solutions in this case means roots

covert cradle
somber cape
#

look into the fundamental theorem of algebra, https://en.wikipedia.org/wiki/Fundamental_theorem_of_algebra

The fundamental theorem of algebra states that every non-constant single-variable polynomial with complex coefficients has at least one complex root. This includes polynomials with real coefficients, since every real number is a complex number with its imaginary part equal to zero.
Equivalently (by definition), the theorem states that the field ...

somber cape
devout hornet
#

part d?

devout hornet
#

anyone good with matlab

somber cape
#

👍

covert cradle
#

how about?

wispy olive
#

See.

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We divide the coefficient of the linear term by 2 and then square it to get 50.

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So $(bx/2)^2$ is 50.

ocean sealBOT
#

Senku Ishigami

wispy olive
#

Solve for x.

covert cradle
#

ok

jagged imp
#

uh

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for one, you're forgetting about the 2 in front of x^2

covert cradle
#

wow

devout hornet
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anyone?

wispy olive
torn hemlock
#

do u want to solve the inequality

lilac nest
#

No it's not, you have to factor out 2 right?? So it would be 2(x²+ ... +25) then the answer would be 10x, since is multiplied by 2 it becomes 20x right?

torn hemlock
#

a+b+c=3,a,b,c>0

wispy olive
#

Me wrong.

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I forgot that part.

jagged imp
#

i dont know how senku got 10x with their method lol

lilac nest
#

Nope it's 20x

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a²+2ab+b²

jagged imp
#

oh wait it is fuck me

wispy olive
warm brook
# devout hornet anyone good with matlab

So I would start here with the interface to take in the vectors,
then key in the 3 values you used to estimate the derivative and travel along j=1 to j=n using the boundary value given to you in the outline of the problem.
Granted, I would start by writing it in a for loop, then try to get a different solution vectorising it

#

I don't have the solution in front of me nor an inkling to use matlab rn, but that's what I would do

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@wet cove multiply both sides by 7 and divide it by 5 (this is the same as multiplying both sides by 7/5)

wet cove
#

som1 help meh

covert cradle
lilac nest
#

You don't have to, it's just to make things easier, 2x²-20x+50 is still a perfect square

alpine sable
#

when I solve for the homogeneous solution, x_h for part a, i keep getting c1 and c2 = 0

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is that how its supposed to be?

silver current
alpine sable
#

im trying to make a money printer script where it gives a bonus depending on certain variables;

There's ink_left, max_ink, paper_left, max_paper, print_amount, max_print_amount.

print_amount is the lower bounds of whats returned and max_print_amount is the upper bounds

if ink_left/max_ink == 1 and paper_left/max_paper == 1 then it will return max_print_amount
else if ink_left/max_ink == 0 and paper_left/max_paper == 0 then it will return print_amount

but i'm not sure how to get it working when ink_left/max_ink and paper_left/max_paper is anything but 1 or 0

thorn kindle
alpine sable
elder glacier
#

if its c i can help

alpine sable
#

lua 😔 but its just maths is it not?

tall phoenix
#

5 x (___) + 2 = 0 can you fill the blank?

warm brook
elder glacier
#

@alpine sable do you have the actual question?

warm brook
ocean sealBOT
alpine sable
#

2x

warm brook
#

yes right

alpine sable
warm brook
ocean sealBOT
alpine sable
#

yes

warm brook
# alpine sable yes

Then yes, c1 and c2 will be 0
A way to think about this so you don't have to solve the first order system is just that this is after all of the exponential terms have effectively reached 0, so it makes sense that the differential equation solution is 0

#

so you're just left with the particular solution

alpine sable
#

ok so I used Acos(2t) + Bsin(2t) as the ansatz for the particular solution

#

$$x(t) = -\frac{3}{17}\cos\left(2t\right)-\frac{5}{17}\sin\left(2t\right)$$

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and this is what i got

#

it is close but not quite 4sin2t when u plug it in

thorn kindle
ocean sealBOT
#

bee_ryan

alpine sable
#

when u plug this x(t) back into the original eqn, you dont really get 4sin2t back @warm brook

sharp canyon
#

DO Y'ALL KNOW rational algebraic expressions?

alpine sable
#

can u pls verify my $x_p(t)$

ocean sealBOT
#

bee_ryan

warm brook
#

Well

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4sin(2t)

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I just divided out the 3 from the ddot(x) term

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to make it easier to work with

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doesn't change the soln

alpine sable
#

hmm

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let me check again

warm brook
#

the imprecise™️ desmos check also seems to validate it

alpine sable
#

wtf

warm brook
#

what in the

alpine sable
#

ok im just gonna trust your method

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omg it worked!! thank you so much

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wow

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i should trust the math, and not doubt it

tall phoenix
#

woah

alpine sable
#

put your faith in the mathematics

warm brook
#

mm thanks wolframalpha

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oh wait

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I'm actually a dumbass

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nope, even with x it still does the same thing

warm brook
#

I finally got it to work, and it verified the answer was correct, but considering it took 2 people to use wolfram alpha for it not to misinterpret something

gray oxide
#

Is this statement true?

alpine sable
#

yes

velvet condor
#

bro.....

alpine sable
gray oxide
#

Thank you :)

velvet condor
#

not you....

elder glacier
#

@coral dragon do you know trig?

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no

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simple sin cos tan

sinful relic
#

Yeah I also often have problems when there's much text but here I think you can use hos and hyp

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adjacent and hypotenuse

elder glacier
#

@coral dragon

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its asking you for the opposite in the first question

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and you have ur hyp

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so do you use sin cos or tan?

sinful relic
#

I forgot the formulas

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Nvm it's sin

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you don't have hyp

elder glacier
#

what

sinful relic
#

Nvm it's cod

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cos

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I just woke up

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sorry

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wait

elder glacier
#

we do not have adjacent

sinful relic
#

no

#

it's tan

elder glacier
#

bro

sinful relic
#

tan^-1(6/15)

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,w tan^-1(6/15)

ocean sealBOT
#

Failed to get a response from Wolfram Alpha.
If the problem persists, please contact support.

sinful relic
#

,w arctan^-1(6/15)

elder glacier
#

,w arctan(6/15)

sinful relic
#

Yeah I was right lol

elder glacier
#

bro you did ((tan^-1)^-1)

sinful relic
#

no

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bad calculator

elder glacier
#

arctan is tan^-1

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??

sinful relic
#

oh

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lol

elder glacier
#

wolfram is goated

sinful relic
#

but that was my second attempt because it didnt work

elder glacier
#

because you did tan^-1(6/15)

#

which is tan^(-16/5)

sinful relic
#

,w arctan(6/15)

sinful relic
#

why can't it just it as what i want lol

daring roost
#

Can someone like explain to me

#

Why the ^-1 is the inverse

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Is it because it’s the reciprocal?

agile torrent
#

its not reciprocal

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its inverse function of tan x

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in case of tan, you get a ratio for a particular angle

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but in tan^-1 you get the angle as result for a particular ratio

daring roost
#

But what does -1 do

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Compared to normal

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Like why is the -1 do

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Could you convert it into 1/tan(x)

warm brook
#

no you can’t, it’s a problem in notation i suppose, but typically ^-1 attached to a function means the inverse. hence why arctan is also the inverse of the tan function

#

so $f^{-1}(x)\ne (f(x))^{-1}$ is what i mean by that. the left side is the inverse of $f$ and the right side is the reciprocal of $f$

ocean sealBOT
daring roost
#

Oh

tired drum
#

Can someone please help me with question I attempted it several times and got it wrong and it even searched it up but the working is wrong

daring roost
#

Ok so the -1 is just notation

warm brook
#

yes

tired drum
#

Three ants are located at the corners of an equilateral triangle ABC. The triangle has sides of length 1m. Ant A starts walking towards ant B, ant B starts walking towards ant C and ant C starts walking towards ant A. All the ants walk at a speed of 1cm/s. If the ants keep walking towards each other, will they ever meet? If so, where, and after how long in metres or centimetres?

quaint trout
#

Convert to the same unit first

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Then just write it as a fraction and simplify

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the one is in cm, the other is in m

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Write them both in cm

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Or both in m

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Do that first

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What did you get?

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Incorrect

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3m and 3cm are not the same

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How many cm is one m?

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No

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No

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@mental peak stop

mental peak
#

?

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why are you pinging me

quaint trout
#

Don't act dumb or I will call the mods to check the logs

mental peak
#

iam studying for my exam tom wtf

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look

quaint trout
#

<@&268886789983436800> keeps spamming images here and deleting, now acting dumb

alpine sable
#

no one asked, and go to #chill bea

quaint trout
#

Yep

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Now, if 1 m = 100 cm. Then 3m = how many cm?

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Yeah

fading zephyr
#

who keeps spamming?

quaint trout
#

So it is 60cm and 300cm

#

bea

quaint trout
mental peak
#

iam not spamming wtf

fading zephyr
#

i do see the deleted messages in the log

night geyser
#

jeez 5 image deletions in 1 hour

fading zephyr
#

what's the matter, @mental peak

mental peak
#

sorry dude i sent the image on the wrong channe;

quaint trout
#

Now the ratio between two things is just the "fraction" comparing the two. So the ratio of 5 to 2 is 5/2, and the ratio of 60cm to 300cm is...?

night geyser
mental peak
#

no 2 times

night geyser
mental peak
#

iam lagging

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literally iam on 12 ping

elder glacier
#

12 ping wtf

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thats so high

mental peak
#

120*

night geyser
#

120 ping is an eigth of a second

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just knock it off

mental peak
#

sorry broo i got used to 30 ping jeez

night geyser
#

apologies for the interruption.

mental peak
#

i pressed the damn button so many times

austere obsidian
quaint trout
#

Do you still need help bacon?

elder glacier
#

interesting

austere obsidian
#

x = 1 + 1/2 + 1/3 + 1/4 + ...

Is the value of x finite?

quaint trout
#

No

elder glacier
#

no

#

its a limiting sum

austere obsidian
#

how this applies to the above series

quaint trout
#

It's not a geometric series

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So not applicable

elder glacier
#

oh whops

quaint trout
#

An infinite series converges to L if the sequence of partial sums converges to L

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The sequence of partial sums here is unbounded so does not converge to any L

austere obsidian
quaint trout
#

Because of the definition of convergence of series

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It converges to a value if the sequence of partial sums gets closer and closer to that value

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That's the defn

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That does not happen here

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The partial sums here can get arbitrarily big and is unbounded

alpine sable
#

can i ask sumthing

#

i'm dumb at math need to understand something about linear equations

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3x + 2x × x = 12
Is this a linear equation? Cuz if we add the expression first than multiply the variable we'll get the value of x as square
But if we multiply any of the expression with the variable x first it'll not be possible to add the other expression later cuz the value will change to x² and we can't add two expressions with different variables 😀

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can sumone explain that

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n y

verbal ermine
#

you can’t add first

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always multiply

placid zinc
#

You can add x and x².
For example, 3 + 9 = 12
However, there's no nice way to simplify x + x²

#

It's not linear because there's no y (or, there's no input/output)
And there's an x²

alpine sable
#

aoh got it thats wut i needed to know thx

tired drum
#

solving the differential equation and finding the curve.

tired drum
silver current
#

at the centeroid of the triangle

carmine lion
#

i dont understand

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part (d)

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can someone please explain

vivid tree
#

Lads help me pls

#

Orangev help me pls

cinder wedge
#

Question: Anton has n cubes with edge lengths a, a + b, a + 2 b,. . . , a + (n - 1) b, where n is a
is a natural number with n ≥ 1 and a and b are positive numbers.
By stacking some of the cubes on top of one another, he can build towers out of these; also a
A single cube should be viewed as a tower. The height of a tower is then the sum
the edge lengths of the cubes used.

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First, let n = 4.
Show that a maximum of 14 different tower heights are possible.
Enter a pair (a, b) for which exactly 14 different tower heights are possible.

#

I do not understand the question with the series : a, a+b, a+2b...

tired drum
#

Just a satisfying solution

elder glacier
#

can someone help me on how to approach this q.

crisp grove
#

just find the value explicitly

elder glacier
#

could you elaborate?

#

lecturer hasn't gotten this far, yet expects hw on it. xd

alpine nacelle
#

Replace everything in f in the equality you want to prove

#

You'll see that you can find a c

crisp grove
#

@elder glacier have you tried anything? like anything??

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number of elements in A, Also channel busy@visual lake

elder glacier
#

ill chuck another 15 min at the question and ill see if i get any further.

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@heavy otter @night geyser

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@fading citrus

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??

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I am not going to argue with you mate

fading citrus
#

What actually is this right now, stop

#

I can check deleted logs as well you know that

elder glacier
#

thats fine, check deleted logs.

#

he's a liar.

#

Not entertaining this.

crisp grove
fading citrus
#

Back on topic, thanks

dusk panther
#

Can someone help me

rigid wind
#

factor the first one

#

what have you tried really

sacred sapphire
#

Vee is saying you just factor out an x in the first equation, thal leaves you with an expression with y's in it only which you can solve

alpine sable
#

ratio bozo

#

is this right

elder glacier
#

@alpine sable what do you mean

alpine sable
#

can u help me

elder glacier
#

If I have difficulty with a concept or a question, I ask for help.

glass lichen
#

Just ignore them, they're known to troll

elder glacier
#

How have i trolled?

glass lichen
#

no, anheuser has

elder glacier
#

oh

lost glade
#

did the channel is unoccupied ?

elder glacier
#

@alpine sable how is you asking me my purpose trolling tho xd

sacred sapphire
#

sigh

gilded turret
#

hey this isnt really math question but i know you guys are smart can someone explain to me why you can't calculate enthalpy directly for some reactions you have to do multiple components

#

just ping me if you know the answer, would be appreciated

sacred sapphire
#

I was literally wondering the same

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oh hwait

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nvm

#

i think i know why

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wait

lethal lichen
#

Can anyone help me with these questions?

sacred sapphire
#

by Multiple components do you mean

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multiple reactions' elthalpy are given and you gotta use hess's law?

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@gilded turret

gilded turret
#

yes

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like

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im doing this lab report where we do that to get the bottom equation

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but im confused why we cant just react Mg + 1/2O2

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and measrue enthalpy change of tat

summer cairn
#

#bots sorry guys i can’t find the channel

gilded turret
#

@sacred sapphire

sacred sapphire
#

hang on im just thinking

gilded turret
#

kk

sacred sapphire
#

ah yes

median dirge
#

Hi

sacred sapphire
#

i think its cuz its easier ot measure the enthalpy change through those reactions that are given.

#

like experimentally

median dirge
#

Everyone!

sacred sapphire
#

cuz

median dirge
#

Oh Thermodynamics

sacred sapphire
#

if you see

median dirge
#

Hemlo Enthalpy

gilded turret
#

so wikipedia says this but i dont understand why "it cannot be measured directly" for mg + 1/2o2

sacred sapphire
#

yeah

#

look

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when you combust magnesium

median dirge
#

Enthalpy of Reaction... Enthalpy of Reaction... and enthalpy of formation nice

gilded turret
#

listening

median dirge
#

Hess' law will allow u to add enthalpies as they are state functions lol

sacred sapphire
#

it lasts for a short time whilst allso producing high intensity light

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which makes it hard to measure directly the emhalpy change to a satisfactory degree of acuracy

gilded turret
#

oh really?

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didnt know that

sacred sapphire
#

im not too sure as im not that much of an expert on this, but i remember our teacher talking about something related tothis

gilded turret
#

i read this but i dont get how it being "extremely exothermic" makes it difficult to measure

sacred sapphire
#

yeah its extrememly exothermic

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hence the extremely bright light

sacred sapphire
#

the fact that its extremely exothermic implies that theres ALOT of energy given awsay from the reaction . This happens really quickly as well hence making it hard to measure

gilded turret
#

i never realized what this lab is actually doing

#

that looks so cool

sacred sapphire
#

yeah

gilded turret
#

thank you so much bro

sacred sapphire
#

all good m8

gilded turret
#

actually understood some chemistry for once

red ledge
#

U answered this man's question, and that's what this channel for, I mean, He asked one question and he got an answer, but if he asks more, means it's another question than the first one, therefore, If I ask by the end of his question, that would mean I'm not interrupting him, It's my question now and u have to answer mine now

#

So are we clear?

sacred sapphire
#

ah yes that feeling

gilded turret
#

yes

#

go ahead

red ledge
#

Alright that's fair.

#

Does the friction force happen or arise when two contacted bodies moving?

#

Why do people say that there's a friction though the body is not moving?

sacred sapphire
#

yes frictional force may be present

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oh

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thsts called static friction

gilded turret
#

ooh physics

sacred sapphire
#

consider this

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a LARGE closet on carpet

red ledge
#

Therefore the static friction isn't a force since it's not moving!

sacred sapphire
#

if i push it slightly will it move?

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no

red ledge
#

Is it a force tho?

sacred sapphire
#

yes

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Static friction is a force

red ledge
#

Explain to me then!

sacred sapphire
#

i was trying to d so

red ledge
#

Therefore the static friction isn't a force since it's not moving!

sacred sapphire
#

no

gilded turret
#

bro chill out

sacred sapphire
#

ok

#

listem

gilded turret
#

yes listen to him

sacred sapphire
#

im am standing on the ground not. moving

red ledge
#

If he has answers, I will

sacred sapphire
#

that means weight is not a force

#

with your logic

glass lichen
#

friction is a force

red ledge
#

Weight? What is weight? I mean weight isn't mass

sacred sapphire
#

YES

red ledge
#

U mean mass?

gilded turret
sacred sapphire
#

weight

gilded turret
#

like

glass lichen
#

mass and weight are different

sacred sapphire
#

i mean weight

gilded turret
#

tension force

sacred sapphire
#

sigh

glass lichen
#

mass is the mass of the object, weight is the force of gravity on an object

sacred sapphire
#

mosh you explain

gilded turret
#

what is this kid lol

red ledge
#

Tho we call it a force!

glass lichen
#

Yes, it's gravity

gilded turret
#

m g bro

#

simple

red ledge
#

How come it is a force then?

glass lichen
#

same units as force

red ledge
#

When it consists of two forces?

gilded turret
#

mass is mass

glass lichen
#

???

gilded turret
#

gravity is a force

glass lichen
#

what 2 forces are you talking about>

gilded turret
#

^^

glass lichen
#

Gravity is 1 (one) force

gilded turret
#

exactly

red ledge
glass lichen
#

yes

gilded turret
#

i literally just said that bro

glass lichen
#

mass isnt a force

#

it's... mass

gilded turret
#

said that too..../

glass lichen
#

gravitational acceleration isnt a force either... it's acceleration

red ledge
#

Then when the body isn't moving friction shouldn't be a force then! it's just friction!

gilded turret
#

i havent taken physics in 2 years cmon bro

red ledge
#

It doesn't affect the body!

glass lichen
#

it does

gilded turret
#

????

red ledge
#

It doesn't make it move, it doesn't change its state!

glass lichen
#

it prevents the object from moving

gilded turret
#

^

red ledge
#

Buy what made us sure mass isn't a force?

gilded turret
#

bruh

glass lichen
#

units

gilded turret
#

im out i gotta finish my chem have fun dealing with him

glass lichen
#

If I push on a box and the box doesn't move, then there has to be a force counteracting my applied force by Newton's 3rd law

red ledge
glass lichen
#

mass clearly doesnt have the same units as force

#

so it cant be a force

#

[m] != [F]

gilded turret
#

ok bro

#

you're not measuring any force when you measure mass

#

when you measure weight you're measuring the force of gravity based on its mass

red ledge
#

Okay What is mass?

sacred sapphire
#

look you r mass is the same wheather your on the moon or on jupiter or while floating in space,

#

BUT

#

your weight isnt

glass lichen
#

mass: the amount of shit in the object

gilded turret
#

ok bye bye fr

sacred sapphire
#

this is cuz weight is the force you are experiencinng by virtue of the gravitaional feild you are in

#

and the gravitational feild of earth isnt the same as that of the moon

#

eh?

#

oh wait

glass lichen
#

catshrug blocked, not dealing with it

sacred sapphire
#

are you the troll guy?

#

so hear me out. firstly For a force to exist need not mean there is motion.

red ledge
#

Does space have mass?

sacred sapphire
#

no

red ledge
#

Does friction have mass?

#

Please stop

glass lichen
#

friction is a force

sacred sapphire
#

depending on the normal force experienced by the object

gilded turret
sacred sapphire
#

which further may depend on some component of the

#

mass

gilded turret
#

i need to work on my chem but this is too funny

sacred sapphire
#

so in genral friction force experienced by an object does depend on that object's mass

#

actually

#

how bout i send you a website

glass lichen
sacred sapphire
#

that explains this

dreamy bone
#

Guys

#

Apparently

gilded turret
dreamy bone
#

critical points can be found when either f'(x) = 0 - which I understood
but also it can be found when f'(x) is not defined or if it DNE

#

I don't get what that means

glass lichen
#

yes, Fermat's theorem

dreamy bone
#

or how to calculate that...

red ledge
#

So we can't see forces?

sacred sapphire
#

This will clear your doubts

red ledge
#

Does any object have mass?

glass lichen
red ledge
sacred sapphire
#

question:

red ledge
glass lichen
#

The honest answer is they're just a mathematical object to explain motion

sacred sapphire
#

what grade are you im just curous, you dont hae to answer if you dont want to

red ledge
#

By imapct u mean what the forces did which is the result

glass lichen
#

yes

#

example the force of gravity pushes things down towards the center of the earth/body

#

(or pulls them, I digress)

#

Friction impedes motion, Normal force keeps objects on the surface they're on

#

etc

red ledge
#

I mean what makes it this perfect?

glass lichen
#

That's just how gravity works, there's an attractive pull b/w the planet and the object

red ledge
#

Like how it controls it? I mean it's non a living entity or something

glass lichen
#

cause it's a function of mass

#

and distance the object is from the center

#

$\abs{F_g}=\frac{GMm}{R^2}$

red ledge
ocean sealBOT
red ledge
#

I mean why it's always down to the center?

sacred sapphire
#

observation

glass lichen
#

cause we model everything as point masses.

red ledge
#

I mean there is a reason

glass lichen
#

Physics is just a model to explain phenomena, it's not a set in stone rulebook for the world

sacred sapphire
#

a process of trying to match theory with observation

red ledge
#

Okay how do we know that specifically this force is gravity? And how do we know that gravity is what pushes things down and not like an effect of gravity..

glass lichen
#

...

red ledge
#

What made us so sure that graivty is one singluar force?

glass lichen
#

put something in a vacuum and let it drop

#

only force is gravity, and the object fell

#

so gravity pulls downward.

red ledge
#

Okay Mass shouldn't be a force, but if it remained or became this way then it's a force since it keeps the object from changing

#

But if mass changes! then the object would be effeceted

#

Therefore, mass is a force

sacred sapphire
#

you would have learnt this in school?

red ledge
#

Umm but different kind of forces I think because it dosen't have the abiilty to control

sacred sapphire
#

right?

glass lichen
#

mass isnt a force

red ledge
glass lichen
#

if mass changes, then the force of gravity changes... cause it's a function of mass

glass lichen
sacred sapphire
glass lichen
#

You should always be asking your teacher/educator questions about what they're teaching you, cause most people here aren't trained teachers

red ledge
#

I guess there's no rule that says u have to be at a school in order to ask question

glass lichen
#

True, but you can also be self-reliant and google answers/find answers yourself

sacred sapphire
#

note: the rules also say to provide any progress. Progress may include what youve learned beofrehand regarding the question

#

i should probs leave this to mosh

astral latch
#

Any chance I can slide in w a question if the previous one is resolved?

red ledge
glass lichen
#

no

red ledge
#

Bruh I think u were wrong when u said gravtion force changes

glass lichen
#

it does change

red ledge
#

Gravity doesn't depend on mass

glass lichen
#

ok

#

Im done

red ledge
#

Right?

#

Mass isn't what makes gravity?

#

Just because gravity changes! Doesn't mean the mass was the reason that made it change!

red ledge
sacred sapphire
#

"U answered this man's question, and that's what this channel for, I mean, He asked one question and he got an answer, but if he asks more, means it's another question than the first one, therefore, If I ask by the end of his question, that would mean I'm not interrupting him, It's my question now and u have to answer mine now
So are we clear?"

glass lichen
#

I did answer the questions, you failed to understand what was being said many times

sacred sapphire
#

@astral latch

#

you can ask

#

if you want

astral latch
#

Sweats appreciate it

red ledge
#

U just got tired and frustrated

sacred sapphire
#

well

#

its hard typing

glass lichen
#

You kept saying mass is a force, when I said it wasn't

red ledge
#

So u didn't actually answer my questions that are still not answered.

glass lichen
#

You weren't listening

sacred sapphire
#

well

red ledge
glass lichen
#

ok, stop pinging me. Im done with this conversation.

sacred sapphire
#

i literally sent you a resource

red ledge
#

You're so annoying bro.

red ledge
glass lichen
#

@alpine sable I'm more than happy to get mods if you continue to troll

red ledge
#

Because of u! U are the bad reason! Bad causes to be triggered. So u should be stopped!

#

Don't blame me of ur bad behaviour! U want me to stop and shut up?

glass lichen
astral latch
#

rapidly changing topic (admittedly to my benefit)
(see eq below)
wolfram alpha gives a real solution as smth and an integer solution as a=3, b=3, how would I mathematically arrive at the integer solution? I admit the algebra is a bit scuffed because it stems from 2+sqrt(3) = (sqrt(a)+1)/(sqrt(b)-1) and I just messed around w it until I got the above, but unsure of how to proceed

errant harbor
#

Anyone want to jab at my question-3?

ocean sealBOT
#

Timely Leaf

sacred sapphire
#

good question

#

im trying to solve it

#

by squaring

#

both sides

red ledge
#

You told me to shut up.

astral latch
#

Ahhh yeah I'll try that too - I'd tried rationalising the denominator when it was in its previous form but that didnt help much

sacred sapphire
#

yeah

astral latch
#

got it to the current state to try and move the variables to one side and constants to another

#

its rly weird tho, cus symbolab gives the real solution too - only wolfram alpha gives both the real and integer solution

red ledge
#

Exactly! Neither to anyone asking here, U are just here trolling and interrupting. which isn't the purpose of this channel.

#

Cause u are a troll, U didn't answer.

#

Thank u. @fading citrus

#

Well u should stop then if u think what I'm doing is wrong. U seem to know what is right and wrong. But choose to do the wrong.

astral latch
#

lads please if someone sees this channel I just want them to see my question n help me learn maths

red ledge
#

Well! Obv u don't get mad because it's funny to u, but I get mad because it isn't funny

#

F{x} ?

#

Me and u

astral latch
#

wait sor eli this channels in use rn, not just by 2 trolls tho ;;

#

$(2+\sqrt{3})^{2}b=a+2\sqrt{3}\sqrt{a}+6\sqrt{3}+12$

ocean sealBOT
#

Timely Leaf

astral latch
#

@sacred sapphire got this

#

still painfully messy though

sacred sapphire
#

yeah

#

im seeing if isolating a is helpful

astral latch
#

for what its worth, for an integer solution both a and b are 3, so ofc if you just replace either of them with the same variable or have the prior knowledge that a=b then its piss easy n everything cancels out

#

but yeah no clue how this expression works normally

young citrus
#

why the limits so hard to learn

red ledge
red ledge
sacred sapphire
red ledge
#

We would just tell u that either limts aren't hard and u are stupid or limits are hard for everyone... But there's always a reason for everything...

sacred sapphire
#

because just a sheer algebra method doesnt seem to get me anywhere

red ledge
#

At a point u found out that limits are hard

red ledge
#

We need to know that point

#

So we can judge

#

And that's the question u are looking to answer for.

astral latch
#

the original question is:

red ledge
#

@young citrus Okay?

astral latch
#

$tan(75) = \frac{\sqrt{a}+1}{\sqrt{b}-1}$

stray vessel
#

A little question. If set A is a ring, and set B is a ring too, A X B will be a ring?

red ledge
#

Maybe we can help u.

ocean sealBOT
#

Timely Leaf

sacred sapphire
#

AAAH

#

ok

#

wait

glass lichen
astral latch
#

The question does say use an addition or subtraction formula, so it did work through into tan 30 +45 which simplifies into 2+sqrt(3)

young citrus
sacred sapphire
#

i think the question needs a more geometric approch

stray vessel
sacred sapphire
red ledge
astral latch
stray vessel
sacred sapphire
#

sin75/cos75

#

thats a hint

#

i got it

#

btw

red ledge
#

Bro just tell us more how do u find it hard and why do u find it hard. That should be enough. @young citrus

crisp grove
# stray vessel cartezian

yeah but u need to modify the operations a bit. what you are seeking is direct product. cartesian prod will not give you a ring because you don't have a + and . defined yet. that's what direct prod does

red ledge
#

Because I'm sure it might be hard to get it, but it's not hard to understand.

young citrus
stray vessel
#

ty

sacred sapphire
sacred sapphire
#

i sent my solution for @astral latch

astral latch
#

sorry wait - how did you break it apart? my mental trig table is a bit rusty

#

is it the same just addition(sin) and subtraction(cos) rules?

#

with 30 and 45

sacred sapphire
#

sin75 = sin30+45

astral latch
#

Ah yeah neato - makes sense! tysm

sacred sapphire
#

all good

red ledge
glass lichen
astral latch
#

Oooooh yeah

#

admitedly I meant the even dumber one where I never memorised sin(30, 45, 60) etc. painpeko

red ledge
astral latch
#

but yeah - question is resolved if anyone wants to pop in~

red ledge
#

@glass lichen Can we just have a little and structured quick discussion?

#

That means I just have one question in my mind.

#

I guess u won't mind since u know the answer and I noticed that u help people.

#

I wonder, Is wind a force?

#

Does everything has an affection basically a force?

#

Well! Not again! it's the same question but was never answered.

glass lichen
#

you asked if water is a linear combination, so pipe down

red ledge
#

@glass lichen

sacred sapphire
red ledge
#

?

#

Guys..

#

@sacred sapphire Is wind a force?

runic crane
#

Anybody help in algebra?

#

Can u help

#

I mean

sacred sapphire
#

wind refers to a colective movement of particles

crisp grove
#

no

unborn trout
#

guys i failed in math
any help would do good :((

runic crane
#

What u need help

red ledge
sacred sapphire
keen jasper
red ledge
unborn trout
keen jasper
#

ah, no. it's a source of energy, but wind itself isn't a force

sacred sapphire
#

"wind" is not a force, rather it refers to collective movement

red ledge
sacred sapphire
#

but when one says 'wond force acting on an object' that refers to the force that collective movement of paarticals applies onto an object

runic crane
unborn trout
sacred sapphire
#

whats ur question

red ledge
runic crane
red ledge
#

What makes a force a force?

sacred sapphire
#

THE term "wind " is not a force

#

but "wind force " is a force. i.e the thrust force caused by the wind

runic crane
#

Ok imma brb

sacred sapphire
#

wond resistance is a different matter which i dont think @red ledge wannted to talk about

daring cipher
red ledge
#

Now, I'm the one who answers questions?

daring cipher
#

You may not be capable of it yet.

red ledge
#

Maybe I am but u will never know. Therefore, I will ignore ur question.

daring cipher
#

Then your question will also be ignored, good luck finding someone who will answer it.

sacred sapphire
#

LMAO

daring cipher
#

Google also exists if you didn't know.

sacred sapphire
#

TRUE

red ledge
#

U never answered my question, U just ignored it

#

And when i did the same!

sacred sapphire
#

wrong

red ledge
#

U just got mad!

sacred sapphire
#

your question was answered

warm wedge
#

wrong

daring cipher
#

Wrong

warm wedge
#

correct

daring cipher
#

Correct

red ledge
red ledge
daring cipher
#

No one needs to answer it. We have human rights to stay silent.

sacred sapphire
#

i sent source

warm wedge
#

correct

red ledge
#

U didn't answer it

sacred sapphire
#

do you want your questi to be answered????

red ledge
#

U just sent me resources.

sacred sapphire
#

which have those answeres

#

that fact that you prioritise where you get the answers from as opposed to the answers themselvees show that you are asking questions for the pure sake of annoyance

daring cipher
#

Once again let me remind you one of the server rules.

We are not here to do your homework for you.
Figure the question yourself rather than being an ignorant little child.

glass lichen
#

Ok, drop the ad hominums

red ledge
#

Does that mean that he gave me the answer to my hw? I should hurry and make sure I get the answers

#

Wow

sacred sapphire
#

<@&268886789983436800>

red ledge
#

What are u calling them for?

dreamy cedar
#

All of you need to calm down lol

#

These questions dont belong here abstract

#

these are conceptual physics questions

red ledge
sacred sapphire
#

bro

red ledge
#

If u consdier these were homework questions

sacred sapphire
#

u literally said those wernt hw questions

red ledge
#

So how did u know?

sacred sapphire
#

i didnt

#

quote me

warm wedge
#

no he didnt

dreamy cedar
#

Huuurb

#

Can you guys clear out of here so people can ask questions

warm wedge
#

yessir

dreamy cedar
#

sir opencry

warm wedge
#

miss?

daring cipher
#

lord?

warm wedge
#

senpai?

tall wing
#

Tor

daring cipher
#

oniichan?

tall wing
#

anyways the channel is free for whoever wants to ask next

celest flower
#

Nah

#

Stop the Cap 🧢

#

??

#

like

#

(╯°□°)╯︵ ┻━┻

junior blade
desert thunder
#

Ñ

celest flower
#

emoji's keep flowing from this mans keyboard

#

lol

#

hi clark

celest flower
#

:))

low topaz
#

Is TREE(10^100) larger than rayo's number

sacred sapphire
#

NOICE

celest flower
#

Rayo's is much bigger

#

than tree

low topaz
#

Is rayo's number bigger than TREE(g64)

alpine sable
#

Assume that the cryptographic key (ie the pair (a, b) in [ax + b] _41) is changed daily. After how many days are you forced to repeat the same crypto? (Alternatively: on how many attempts is the encryption broken?)

crystal narwhal
#

How do u do this?

tame falcon
tame falcon
frigid gorge
#

someone help

#

pls

fresh sluice
#

The answer is f.

#

You can say so, since you split 50 hours into at least 2 days.

#

In 24 hours, it'll be 9:00 AM.

#

Then 24 hours again, we get 9:00 AM.

#

Finally add two hours, since 50-48=2.

gloomy wharf
#

elps

#

helps

#

pls

fresh sluice
#

Now, we get 11 A.M.

gloomy wharf
#

2 mnutes

frigid gorge
#

oh thx

gloomy wharf
#

before i have to submit

fresh sluice
#

Well.

#

It's 12.

#

Since each game, four times get's us 28.

#

Since 4*7=28.

#

Now, since out of five, the mean is 40.

#

So then, 40/5=8. Now, 40-28=12, so that's the answer.

gloomy wharf
#

tysmm

warm wedge
#

yeah its 12

fresh sluice
#

Your welcome.

frigid gorge
gloomy wharf
frigid gorge
#

greatest common factor?

gloomy wharf
#

yes

frigid gorge
#

oh bet

gloomy wharf
#

it's 6

#

@frigid gorge

frigid gorge
#

oh yea i also got 6 thx tho

gloomy wharf
#

yww

alpine sable
#

\frac{\left(2x-\frac{3}{4}\right)}{\frac{3}{2}}+\frac{\left(4x-\frac{7}{3}\right)}{\frac{7}{9}}=\frac{8}{3}

#

how do i

#

{\frac{\left(2x-\frac{3}{4}\right)}{\frac{3}{2}}+\frac{\left(4x-\frac{7}{3}\right)}{\frac{7}{9}}=\frac{8}{3}}

#

Please Solve this on an 8th grade level for me

frigid gorge
alpine sable
#

what have you tried so far?

#

@frigid gorge

alpine sable
dreamy bone
#

Hey guys just wanted to clarify that

#

A function can be continuous, but not differentiable, but if it is differentiable, it has to be continuous?

#

right?

alpine sable
#

yes.

dreamy bone
#

Thanks!

silver current
# frigid gorge

You could do it the normal way, but do you know the concept "The exterior angle is equal to the sum of two interior opposite angles"

errant harbor
#

If I can get $20 a day and there's a savings account which gives 0.014% daily interest (5.35% apy), how long (Every x days) should hold I before putting my accumulated amount into the savings account if it costs $4 per transfer?

x = Every day/ 2 days/ every week/ every 2 weeks, etc?

tight locust
#

is it compounded or simple

tawny fox
#

What is it asking for c??

errant harbor
tawny fox
#

The first two parts are self explanatory but ya idk about c

tight locust
errant harbor
lilac nest
#

No, you can't simplify fractions like that, what you can do is simplify the fraction by eliminating equal quantities or reducing divisible quanties

#

In this case you can do 1 simplification

#

Yeah

alpine sable
#

Anyone know how to do this

lilac nest
#

Keep in mind that alpha must be different than 0 and 180 though, bc you can't divide by 0

#

No you just didn't consider it anymore at a certain point, so yeah it's wrong

#

It was an equation

#

It should be cos(x) = 5sin(x)/13sin(x)

lilac nest
#

You can simplify both the sin

ocean sealBOT
lilac nest
#

Yeah you got to the point at line 3 right?

#

Then you can simplify both the sines from the right fraction

#

Cos(alpha) = 5/13

lilac nest
#

So did you find the answer?

#

You can either do that or just use arccos(5/13)

#

You're welcome

wary matrix
#

Can someone please help me with 5ii

alpine sable
#

Where should I start?

#

I think I got it. Is it C?

#

a = 1 and b = -1?

wary matrix
#

Please wait 15 mins before you post the question @alpine sable </3

storm lava
#

@alpine sable it seems to me that you are right

#

from the matching derivatives i got the a = 1 and then matching f(1) gives b = -1

wary stream
alpine sable
wary matrix
#

Oh I thought it was 15 mins before someone doesn’t get a reply

#

Nvm

alpine sable
storm lava
#

there might be another number, you just use this number to calulate the function value of that function at both "ends" and derivatives

wary stream
viscid kraken
alpine sable
#

that's.. a long time

viscid kraken
#

help

alpine sable
#

never really seen anyone follow that rule lmao

#

as you can see ^

buoyant kayak
#

there are also 10 channels

#

not like you need to wait for this specific one to be done

#

plus there's more channels for specific classes

wary stream
wary stream
dreamy bone
#

guys I was just wondering that

steel estuary
#

Hello guys, any of you now how to implement a Gaussian elimination? i am lost D:

dreamy bone
#

how do I determine if the critical point is minima or maxima

#

like do you guys use the double derivative?

buoyant kayak
storm lava
dreamy bone
#

wait what?

buoyant kayak
#

is this $2x+\frac{x^2}{x^4}$?

ocean sealBOT
#

a disappointing son

lilac nest
#

(2x+x²)/x⁴

#

Yeah the simplification is (2+x)/x³

buoyant kayak
# dreamy bone and?

oh you don't want absolute min and max, nevermind. refer to what kai'sa said

lilac nest
#

For the second one do you mean sqrt(x³) or something else?

dreamy bone
buoyant kayak
dreamy bone
#

after that?

buoyant kayak
#

well, if you're at a minimum, what are the points around your critical point gonna look like?

dreamy bone
#

and just compare?

wary stream
dreamy bone
#

oh right okok

lilac nest
#

Go to another channel too busy here

dreamy bone
#

fair enough thanks disappointing son...

#

and kai!

#

tc guys

buoyant kayak
#

the red pts are near the critical pt

#

,rotate

ocean sealBOT
buoyant kayak
#

rewrite as exponents and multiply

lilac nest
#

Yeah

#

Then you have same base so you can use the exponent properties to multiply them

buoyant kayak
#

not times 3

#

to the third power

lilac nest
#

He means $x^(3*1/2)$

buoyant kayak
#

oh yeah

ocean sealBOT
#

Andrea276

lilac nest
#

You got what I mean though

#

((Cube root of 3)²)/sqrt(x) ??

junior tartan
#

testing $\nthroot{3}{x}$

lilac nest
#

I'm not good at that either

junior tartan
#

$\cbrt{x}^{2}$

buoyant kayak
#

$(\sqrt[3]{x})^2/\sqrt{x}$

#

hmm

junior tartan
#

well that was my next idea

#

ah square brackets i see

buoyant kayak
#

im still learning the bot lol

lilac nest
#

Instead of a product you now have a quotient, so you can apply the same properties as before

ocean sealBOT
#

a disappointing son

junior tartan
#

$\frac{\sqrt[3]{x}^{2}}{\sqrt{x}}$

ocean sealBOT
#

PlesleronTepryos

junior tartan
#

ayyyyyy

dreamy bone
#

What's the difference between finding minimum and maximum using the differentiable/continous law and finding minimum and maximum using double derivatives??

junior tartan
#

you can simplify that further

lilac nest
#

X^(2/3)/x^(1/2)

junior tartan
#

wait no exponents subtract

buoyant kayak
#

not minima/maxima

junior tartan
lilac nest
#

X^(2/3-1/2)=x^(1/6) so yeah it's right

junior tartan
#

oh wait i can't subtract wtf

#

nvm me

buoyant kayak
dreamy bone
junior tartan
buoyant kayak
dreamy bone
#

in calculus context idk man

#

i'm super confused

#

like

#

stationary and turning points

buoyant kayak
#

stationary point is a critical point

#

turning point is when the slope changes from negative to positive