help-0

[harsh belfry]

ahh perhaps

will try that out

it did accept this though

[gentle ingot]

You have to multiply by the derivative of the inside function

You don't have the correct derivative

Even though you remembered to apply it, you just did it incorrectly

Wait

[harsh belfry]

I am definitely confused

[gentle ingot]

Nvm u changed it to 12x lol

Ignore that you got the right answer I just didn't see it

[harsh belfry]

yeah i changed it to 12x and divided by 2

no dice

[gentle ingot]

😔

[harsh belfry]

I think it may be bugged

[gentle ingot]

Simplify radical?

Thats grasping for straws though

[harsh girder]

yes

[harsh belfry]

thanks for the help you two then lol

[gentle ingot]

Of course

[vivid ginkgo]

hello. how do i solve x/2 = 14? thanks 🙂

[static kindle]

to eliminate y, you need to make the y coefficients in both equations the same and you do this by multiplying second equation by 7 to get 28x - 7y = 91 then add the top equation to get 38x = 89

[harsh belfry]

Found my derivative for the bottom half of the function

I was thinking of apply quotient rule here, but there really should be a more efficient way to do this.

I just can't remember

[quaint trout]

You can rewrite it as 7/2 (7x+9)^(-1/2) and apply the chain rule and power rule

[harsh belfry]

could I rearrange the original problem here to

[quaint trout]

Oh, nvm, I read the derivative as the function

(7x+9)^(-1/2)

[harsh belfry]

a little confused on what you mean

[quaint trout]

$$y = \frac{1}{\sqrt{7x+9}} = (7x+9)^{-\frac12}$$

[ocean seal]

Lunasong the Supergay

[quaint trout]

Why would 0^n be 1? @static kindle

[static kindle]

yeah no I realised what I did that's why I deleted my message

[quaint trout]

0^n means 0 * 0 * 0 * ... * 0 (n times) which is always 0 no matter what n is (assuming n positive)

[harsh belfry]

ah ah I see

thank you

[quaint trout]

👍

[surreal radish]

i have a huge confusion in sets, like i dont understand the difference between proper subset and subset, and i always get confused between the symbols of both, can any one pls help me

can anyone pls help me

thanks

[elder glacier]

@desert zephyr yup

not sure really how to answer this.

[tidal thistle]

CAN A RATIONAL EQUATION HAVE RADICALS

[red lynx]

🥺

[quaint trout]

A is a subset of B if all the elements of A are also elements of B, e.g. $A = {2,4,5}$ and $B = {2,4,5,10}$, or A = B. So a set is always a subset of itself.

A is a proper subset of B is A is a subset of B and it is not equal to B.

There are different confusing conventions for the notation. I like $\subseteq$ for subset and $\subset$ for proper subset, because it works like $\leq$ and $<$.

But a lot of people also use $\subset$ to mean subset and not just a proper subset, and then they denote a proper subset using $\subsetneq$.

[ocean seal]

Lunasong the Supergay

[surreal radish]

thanks @quaint trout

so, this is the symbol for subset

and this is the symbol of proper subset

right?

[quaint trout]

@surreal radish that's what i use

But some people use the second one for just subset

So you have to check what the conventions in your specific book is

[surreal radish]

oh ok

thanks

like the set iself and null set wont come under proper subset right

[quaint trout]

Null set does come under proper subset

Only the set itself is excluded

[surreal radish]

oh ok

[sick phoenix]

https://www.asukaexpress.com/CANON-F-788SG-NAVY-BLUE-SCIENTIFIC-CALCULATOR-canon-calculator-asuka-express

Hi anyone with this model, i cant change decimal to frac :C

[quaint trout]

Can you send a picture of your actual calculator's buttons?

[sick phoenix]

same as the pic

[quaint trout]

Okay, try typing in 1 then a b/c then 2 and then =

Does it then come up as 0.5?

[sick phoenix]

yeps

[quaint trout]

Uh, it says 500

Wtf

What's the m thing? Are you in a weird mode

[sick phoenix]

its in the normal mode tho

[quaint trout]

1/2 is not 500

That's not normal

Click on shift and then mode

[sick phoenix]

its always like that for dec

10^-3

[quaint trout]

It doesn't say 10^(-3) anywhere

[quaint trout]

And show options

[sick phoenix]

i assume it’s in comp mode

[quaint trout]

Click on the right arrow

To see more options

And show me all the options you get

[quaint trout]

Okay

First

Go out of the menu

Then click Alpha and then DEL

[sick phoenix]

uhuh

[quaint trout]

To clear

[sick phoenix]

okies

[quaint trout]

Click 3

For All

[sick phoenix]

IT WORKS NOW

tysm :]

[quaint trout]

Lol, whenever your calculator is fucked up, just clear the set up like that

You changed to a weird mode somehow

[sick phoenix]

ahhh prob when it was squashed in my bag

[quaint trout]

[chrome depot]

In a pyramid where the base is a square and one of sides goes through one of vertices of that base

Are all the side lengths same? (Not base length)

[quaint trout]

What do you mean the side goes through one of the vertices?

[chrome depot]

Here

Looks like this

Dont mind the M equals whatever thing, its from another problem

I know H and a

[quaint trout]

Did you mean that that edge of length H is perpendicular to the base?

[chrome depot]

Yeah

Are all the edges of same length?

[quaint trout]

No

[chrome depot]

Mhm

[toxic island]

i think your answer is correct

[chrome depot]

Well that seems obvious from picture xd

[elder glacier]

yea the question was bugged just found out.

[quaint trout]

@chrome depot

The two green edges are equal because of Pythagoras

They would both be equal to sqrt(H^2 + a^2)

[chrome depot]

Yeah yeah ik thay

T*

I was worried about the third one

But seems like its not

I can calculate the area of some triangle with "a*h/2"?

[chrome depot]

Assuming that h is height for tjay side

That*

[quaint trout]

For the third side, it would be equal ti sqrt(H^2 + 2a^2)

By looking at the green triangle in my picture

[flint kettle]

What rules are there for figuring out Row Echelon Form

Cause I'm trying to calculate the eigenvectors for a matrix

I have the eigen values

Just can't figure out how to do REF properly

x

This is how far I got

[quaint trout]

That's correct except usually you would swap the rows to be in the order

0 1 2.5

0 0 -9

0 0 0

And if you require leading entries to be 1, divide the 0 0 -9 row through by -9 to get 0 0 1

[fervent tulip]

How do you apply transativity to

x < y <= z

I would think this implies

x <= z

[upper escarp]

,help

[ocean seal]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[quaint trout]

It does, it also implies x < z which is stronger @fervent tulip

[fervent tulip]

ty i thought about it for a sec i was just having a dodobrain moment

because you can just do cases right

case 1: y = z => x <= y
case 2: y < z => x <= y

[quaint trout]

I'm not sure, what you are doing, you are trying to find a relationship between x and z, not x and y

[steel acorn]

how do I attempt to solve this question?
A software company has four sections employing 50, 35, 40 and 25 IT workers. The average monthly salary for these four sections are respectively Rs. 30000, 35000, 40000 and 50000. Compute the average monthly salary for the whole institutions.

[quaint trout]

Let S be the sum of all the salaries, S1 the sum of all the salaries in section 1, S2 the sum of all the salaries in section 2, etc

What you want is S / total number of employees

[chrome depot]

So if H = 21 and a = 20, then that side is equal to ~ 21.67?

[steel acorn]

oh there are total of 16 employees?

[quaint trout]

Uh no

[steel acorn]

then?

[quaint trout]

,w sqrt(21^2 + 2(20)^2)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Lunasong#7197

[quaint trout]

@steel acorn 50 + 35 + 40 + 25

[chrome depot]

Hmmm

[quaint trout]

No idea where the 16 comes from

[steel acorn]

I thought there were four workers in each of the four sections

[quaint trout]

[steel acorn]

so I did
(30000+35000+40000+50000)/4

and the answer didn't match

[chrome depot]

Ah i see, i made a mistake in calculation. Anyways, in this triangle, do we have 2 pairs of sizes with same area? Like, 2 sides that contain H have the same area and other 2 have the same?

[steel acorn]

mine is 38000 but the answer is 37k and something

[quaint trout]

Well, that's wrong, because there aren't 4 workers in each section

[steel acorn]

how many are there?

I just can't understand the question

[quaint trout]

They clearly say the first section has 50 workers, the second has 35, the third has 40, and the fourth has 25

Like, are you even reading it?

[steel acorn]

oh

I assumed too much

[quaint trout]

Now you need to find the total salary of each section

Then add that up to get the total salary for the whole company

[steel acorn]

they gave the total salary, no?

for each section

[quaint trout]

Then divide by the total number of employees

No they gave the average salary

[steel acorn]

F

how do I find that then?

[quaint trout]

Do you know the formula for average?

[steel acorn]

yes it's mean

[quaint trout]

Average salary = Total Salary / No of employees

[steel acorn]

sum of data/no.of data

[quaint trout]

You have the no of employees for each section, and the average salary

[steel acorn]

oh oh

[quaint trout]

So you can find the total salary

[steel acorn]

damn... I didn't think it was this type of question

[quaint trout]

[steel acorn]

stats is so hard

thanks for helping

[warm temple]

Can someone explain how line 2 becomes line 3?

[quaint trout]

Distributive property

(X+Y)Z = XZ + YZ

here X = A, Y = (-1)B, Z = (A+(-1)B)

[chrome depot]

@quaint trout (sorry for ping) - could you address this?

[steel acorn]

wait it says to find the average salary of the whole institute

not total salary

[quaint trout]

Yes, you need the total salary to find the average salary

[chrome depot]

If that is true, then we can calculate the height of particular side that doesnt have H as its edge and just calculate the area of that side like that

[quaint trout]

Yes

[steel acorn]

we already have average salary, no?

why do it again?

[quaint trout]

For each section

You want it for the whole company

[steel acorn]

so I should just add them?

[quaint trout]

No

You need to find the total of the salaries for the whole company

And then divide by the total number of employees

[chrome depot]

Alright. I need to calculate the total area of all sides (except base). My general formula would be: aH + ah.

Small "h" is height of side that doesnt have H as its edge. Since we have 2 of each, the 2 and 2 cancel out.

Is that true?

[steel acorn]

isn't that the same thing?

155000 * 15 = Total salary```

then divide by 15 again?

btw it's 150

not 15

[quaint trout]

Did you make these numbers up or are they from the problem?

[steel acorn]

from the problem

I added all the salary for average

and all the workers

[quaint trout]

You added all the workers and got 15?

And that's wrong

[steel acorn]

150

[quaint trout]

You cannot do that

[steel acorn]

why?

[quaint trout]

Average salary of whole company
= S/T = (S1 + S2 + S3 + S4)/(T1 + T2 + T3 + T4)

So you need to find S1, S2, S3 and S4

Where S1 is the total salary of section 1 etc

[steel acorn]

what's S1?

oh

[quaint trout]

And T1 is the number of employees kf section 1

[steel acorn]

lemme try

[steel acorn]

hmm

[lunar oracle]

Can u help me with this? :((

[quaint trout]

Uh I am having brainded moment, but are you sure the two triangles without H have a perpendicular side?

Unless you mean h is the length of the perpendicular and not the edge

If you do, then it's correct

[quaint trout]

Multiply out the options until you see one that looks the same

[lunar oracle]

Thank you

[chrome depot]

@quaint trout can u see the small h?

The height of triangle BCS

[quaint trout]

Yes

[chrome depot]

Thats what I mean

[quaint trout]

Then that is correct

[chrome depot]

Also, I assume that triangle CDS

Has thay same h

That*

[quaint trout]

Yes

[chrome depot]

I mean i dont assume ... They have same sides xd

Edge lengths*

Gosh its hard translating

[alpine sable]

hey guys

somon help

how is the result 3+2/24 there

where did 3 came from

[quaint trout]

1/8 = 3/24

1/12 = 2/24

[alpine sable]

i still don't get it

[sick phoenix]

common denominator

[sick phoenix]

wait first, station is still in use

[alpine sable]

ohh

i get it now

[sick phoenix]

ok good :>

[steel acorn]

how do I find the median when they skip a class?

like 0-10 then 20-30

[flint kettle]

yessir ❤️

[sick phoenix]

could someone guide me through qii

i tried plotting it on the graph but its super unreasonable ish ?

heres the ans ^

<@&286206848099549185>

[harsh girder]

what's your plot, the plot is about x^3 and x^2*y

[sick phoenix]

same value as the ans 9(ii)

i dont think the y int is the same as the ans

i graphed it online

[harsh girder]

These points are on a straight line

[sick phoenix]

yeps

how would u find b

cause bx=y-int, and wouldnt x be 0

[harsh girder]

Do you know how to use two points to find the equation of a line?

then x^2*y=a+b*x^3

you know a and b

[sick phoenix]

but we need to use graph to find a and b

[harsh girder]

If you have already drawn the line, then find two points on it to determine the equation of the line

[sick phoenix]

our cher told us to find the y-int by reading graph tho :C

[harsh girder]

The y-intercept is a, for x^2*y=b*x^3+a

the slope is b

[tight locust]

x^2y = Y

x^3 = X

[chrome plinth]

whats the formula for finding the slope of 5 poinnts

[glass lichen]

What?

Do you mean slope for line of best fit?

[chrome plinth]

yes

[pseudo ocean]

what does f''(x)>0 imply

like f(x) concave or convex........

[glass lichen]

It's concave up

[strange raven]

What are these R, Q and C?

[strong furnace]

sets of Reals , rationals and complex numbers

[crisp grove]

real, rationals and complex

[strange raven]

Thanks

[elder glacier]

can someone help me with the last question about the interval, im really not sure

[drowsy field]

how to solve things with fractional part

[fair vine]

Is there a official term to differentiate between projecting in same dimension and different dimensionality? i.e 3d -> 2d vs 2d -> 2d ?

[crisp grove]

@drowsy field honestly it's very difficult

[drowsy field]

yes

[young oyster]

Hi guys, I need help with one problem, anyone can help me?

[crisp grove]

you have to break the integral down into many pieces

[drowsy field]

wow

[crisp grove]

channel busy @young oyster

mind you thoses pieces won't be finite

[drowsy field]

oh

[crisp grove]

if you have a function $f$ say $f:[0, 1] \to [0, \infty)$

[ocean seal]

Ryuzaki

[crisp grove]

you have to break the interval down into pieces ${a_0, a_1, a_2, \cdots }$ s.t. for your function $0 \leq f(x) < 1 $ in $[a_0, a1)$ and so on

[ocean seal]

Ryuzaki

[crisp grove]

as tan(x) tends to infinity, it'll be difficult

[drowsy field]

[crisp grove]

but not impossible

[drowsy field]

ah ok

[crisp grove]

you can try doing something like this

$$\int_0^{\tan^{-1}(1)} tan(x) \dd x + \int_{\tan^{-1}(1)}^{\tan^{-1}(2)} (tan(x)-1) \dd x + \int_{\tan^{-1}(2)}^{\tan^{-1}(3)} (tan(x)-2) \dd x$$

[ocean seal]

Ryuzaki

[crisp grove]

see if you get anything

[drowsy field]

hm ok i will try

[crisp grove]

@drowsy field note that you can break the integral and take on part only in terms of tan(x) and 2d part only in terms of the constants

u need to do something similar for -pi/2 to 0 case

[drowsy field]

ok

[crisp grove]

I hope few terms will cancel out

but I could be wrong

[drowsy field]

ye i could ask my math teacher for this becuz it feels a bit too difficult

thonks for the help tho

[crisp grove]

[elder glacier]

<@&286206848099549185> can someone help me with the interval question

[crisp grove]

$|p\times q| = |p| |q| \sin(\theta)$

[ocean seal]

Ryuzaki

[elder glacier]

right

but where does that come into effect while finding the interval of r

@crisp grove

ohhhh

make r(0,01) = pqsin(x)

but what is |p||q| in this case

[crisp grove]

unit vectors?

read the question lol

[alpine sable]

A and B can do a piece of work in 12 days, B and C in 15 days and C and A in 20
days. How much time will A alone take to finish the job?

how exactly do i solve it

?

help

@here

@everyone

[crisp grove]

given A and B takes 12 days

that means they do 1/12 th the job in one day

[alpine sable]

ik

then what

[crisp grove]

do the same for B,C and A,C

[alpine sable]

what after that

i have already done it

[crisp grove]

how much will they do combined then?

means if A,B,C were to do together

[alpine sable]

oo

1 sec

[alpine sable]

3/60 + 4/60 + 5/60

am i right?

[crisp grove]

idk

tell me how would you go about finding it

not the answer

not here to check yr calc

[alpine sable]

me legit bro

2 × 3 = 6 that means 20 × 3 = 60

15 + 15 = 30 and 30 + 30 = 16 so 15 × 4 = 60

[crisp grove]

I can see tht you have added them

$A+B+C$ I mean

[ocean seal]

Ryuzaki

[alpine sable]

;-;

[crisp grove]

but have u divided them by 2?

$A+B=1/12 \ B+C=1/15 \ C+A=1/20$

[ocean seal]

Ryuzaki

[alpine sable]

divide by 2?

[crisp grove]

$2(A+B+C)=(1/12+1/15+1/20)$

[alpine sable]

but why

[ocean seal]

Ryuzaki

[alpine sable]

why did we divide it

[crisp grove]

u need A+B+C

you have 2(A+B+C)

[alpine sable]

oooo

[crisp grove]

how would you find it otherwise?

anyway given you have A+B+C now can you find what A is?

[alpine sable]

thats 3/47 right?

[crisp grove]

told you not here to check yr calc

idk what it is

[alpine sable]

idh cal dude

[desert lintel]

Is it possible to solve x^x = 5?

analytically

[spark falcon]

@static crypt nerd

[naive glen]

Question in r. I have a list of vectors
l <- list(c(1,0), c(0,1))
and vector v
v <- c(2,2)

Say I want to find the dot product between the first vector in l and v, then the code should be
l[1] %% v, yet i get the error:
Error in l[1] %% v : requires numeric/complex matrix/vector arguments

[blissful tundra]

Hey

I need help from someone

Geometry

[naive glen]

<@&286206848099549185>

[blissful tundra]

H e l p

[versed cobalt]

someone can tellme if this is right?

[glacial ether]

How would I go around doing this? I'm just lost on how to start this

<@&286206848099549185>

[hushed pasture]

$y = x^{-2} \text{ then } \frac{dy}{dx} = -2x^{-3}$

so c is -2

[hazy knoll]

what

r u being srs or trolling i have no clue what you just wrot

e

[ocean seal]

Salah

[hushed pasture]

@hazy knoll isn't that correct?

[hazy knoll]

oh you did a bot command i thought the command you typed was the response

mb

oh ye i get it

ty

[night saffron]

Hey everyone is this room free now?

[hazy knoll]

yeah

[night saffron]

I'm up to the last question here

For a quick rerun of questions 3a 3b and 3c first:

for 3a we rearrange for t^-1 and end up with y(x) = 2/(x-4) - (x-4)/2

For 3b I did dy/dx = dy/dt / dx/dt = (-t^2 -1) / 2

For 3c I did d^2y/dx^2 = d/dx[dy/dx] / dx/dt = -t^-1/2

Now for 3d I don't remember the equation of the tangent line so I need help

The equation of the tangent line of a parametric curve at a specific value of parameter t to be precise

[thorn kindle]

What point is it?

What point do you have when t=1?

@night saffron

[night saffron]

Oh yeah sorry

I haven't even started so give me a sec

[thorn kindle]

Lol. Ok.

[night saffron]

(6, 0)

It's like 4 am in australia so that took me way longer than it should have lol

I want to get this finished before I go to sleep

help please

[loud blade]

Hello could someone explain these questions of Fog and Gof?

[charred flint]

I assume f o g is just outside your screenshot?

f o g means applying f to g(x), so find what g outputs, then feed that into f for your answer

[loud blade]

Oh is it implying I can do any value? Like take any point or does it want me to go from 1-6? Like pick the first point from F and G then do the problems like f+g?

[charred flint]

yeah it wants your answer to be a set of inputs and outputs like it gives for the functions

[loud blade]

Ohh

[alpine sable]

Someone please help me I don’t understand anything (this is work my teacher gave me so I pass the class) <@&286206848099549185>

[loud blade]

Is it cool if I do an example and then send it to double check also thanks for helping me bro!

[charred flint]

sure

[loud blade]

Is that correct?

[glossy aspen]

what 9+10

[charred flint]

@loud blade idk why you have f o g for that question, it's just f+g?

it's a different sort of thing

f+g is just adding both outputs, like (2,5) and (2,8) sum to (2,13)

[tame sorrel]

Been stuck on 13 for a while now

[blazing rose]

what lol

[loud blade]

Wrong person Lol

[loud blade]

OOOOOH THATS SO EASY my bad I was watching a video doing fOg so I got confused and mixed it up thanks!

[loud blade]

Is that better?

[charred flint]

yeah keep that up

[tame sorrel]

Anyone help with this?

[prisma cape]

try find the roots for x^2-2x-3=-4 and x^2-2x-3=5

by factoring

thats not enough tho

you only got the max value and the min value by the time

wait no

gimme a sec

ok right

as the coefficient of x^2 its going to be open upwards

and -4 is clearly the min value of everything if you do completing the square

then you try to do x^2-2x-3=5

x is either -2 or 4

[tame sorrel]

It says a is supposed to be 2

[prisma cape]

but then heres the problem

[tame sorrel]

Can't figure out how to get there

[prisma cape]

you dont know whether -2 and 4 are -a or a

then you test the values of 2 and -4

if the value is larger than 5 then its wrong

cuz the max value over the interval is 5

[tame sorrel]

Wdym test values of 2 and -4

[prisma cape]

because we know -2 and 4 are the roots to x^2-2x-3=5

[delicate goblet]

Without using a calculator determine the square roots of the irrational numbers to two decimal places. (Hint: Start with your answers to question 4, then apply Heron's Methoid)
a) √75

4. answer for √75 is 8.7 and I am really confused on what to do.

[prisma cape]

that means one of these two values are def going to be -a or a

but the prob is we dont know which one

so we try to see the negative of -2 and 4

[tame sorrel]

Why? Kind of confused how we get there

[prisma cape]

eh

[tame sorrel]

Wait

Because -a?

[prisma cape]

yes

we know the interval is -a<=x<=a

and we're sure that -2 is -a or 4 is a

do you get it until here?

[tame sorrel]

Yes

Is a or -a right?

[prisma cape]

no

we're saying 2 or 4 is a

[tame sorrel]

2 or -4?

[prisma cape]

eh

[tame sorrel]

Because 5 is the upper limit of the range and -a is the lower limit of the domain?

[prisma cape]

no

thats wrong

1 is the lower limit of the domain

we can actually ignore the lower limit now

i mean -4

[tame sorrel]

-a is the lower limit of the domain I thought?

[prisma cape]

yes its the lower limit of the domain

but its not the lower limit of the range

[tame sorrel]

Okay go on please

[prisma cape]

so we get that either -2 or 4 has to be the absolute max value of the range

but how do we determine which?

basically 4 cant be a

because if the range is -4(which is -a)<=x<=4

then the max value would become larger than 5

so the range can only be -2<=x<=2

you can try 2 as the upper limit of the domain as well

its -3 which is both higher than the absolute minimum and lower than the absolute maximum

[tame sorrel]

Can you get on call man? I'm having the hardest time understanding this. If you're okay with it

[prisma cape]

eh sry i cant really disturb my family

but we can use a cheating method to do this

just go to desmos graphing calculator

[tame sorrel]

Ye?

[prisma cape]

look which values have 5 has y coordinate

which is -2 and 4 according to what we know

[tame sorrel]

So basically it's just trial and error on the two values we get from 5=x^2-2x-3 right?

[prisma cape]

then we try to substitute each value as a into the domain

[prisma cape]

yes

just see which one doesnt make sense

[prisma cape]

as you see the range of values here would become -4<=f(x)<=21

which is different from what the question stated

[vagrant osprey]

hello can I ask something about percentage?

[prisma cape]

but then we try to have -2 as a

inspect the range of values

[vagrant osprey]

what a percentage 23,600 from 44,730? thank u

[prisma cape]

sure

[prisma cape]

eh

can you just send out the question

[tame sorrel]

52.76

[vagrant osprey]

can u teach me how?

[prisma cape]

:/

[tame sorrel]

Thanks man, I think I understand now

[prisma cape]

thats good : D

im bad at explaining lol

sry if im unclear

[vagrant osprey]

no question, its the result of the land area I calculated, i need to know the percentage

[prisma cape]

ok

you're trying to find how many percent is 23600 of 44730 right

[vagrant osprey]

i have example from my friend

[prisma cape]

then just do 23600/44730*100%

[tame sorrel]

(Your area/total area)*100 percent

[prisma cape]

yes

[prisma cape]

@vagrant osprey this is the general formula you can use

[vagrant osprey]

oh okay thank u so muchhh

i cant even do math

[prisma cape]

np

[placid raven]

Hope someone can help me with statistics. How should I go about to use t-tests to compare three response variables to see if they significantly differ from each other?

[delicate goblet]

Without using a calculator determine the square roots of the irrational numbers to two decimal places. (Hint: Start with your answers to question 4, then apply Heron's Methoid)
a) √75

4. answer for √75 is 8.7 and I am really confused on what to do.

[formal solar]

Hey guys

In question 8, part B, part 2,a

Lim f(x)/x as x approaches minus infinity is equal to one

But how does it prove anything?

What can I deduce?

[lavish drum]

did i solve this correctly?

[fresh quail]

hi

idk how

[charred flint]

take the derivative with respect to x and y separately

you'll be able to use those 2 results to get dz/dx and dz/dy

[wheat wyvern]

have i solved this correctly?: 1+2=3

@placid raven

[placid zinc]

Codek

[alpine sable]

I'm not sure where to go from here

ive just realised how dumb i am now

how?

[charred flint]

@alpine sable y/sqrt(y) simplifies

[alpine sable]

what do u mean?

[charred flint]

like you can divide exponents if they have the same base

x^a/x^b = x^(a-b)

y/sqrt(y)=sqrt(y)

[alpine sable]

Oh I see

thx : D

I got lim y->0+ 4sqrt(y) = 0 which is correct : D

i just have a quick question

Assume y = mx + b

if units for x are kg and units for y are s what does m and b represent?

[halcyon glacier]

m is the rate at which the amount of s changes with respect to the amount of kg changing
b is the offset between the amount of s and the amount of kg

[alpine sable]

so what would be the units

s/kg

or none at all

[halcyon glacier]

i think they're unitless

i'm not sure though

[sterile basin]

can i ask here for resources ?

[compact lynx]

@alpine sable units of

m must be s/kg

and b must be s

say m = 2 and b = 3

and x = 4

to have y = mx make sense, as in, perform a function on x to "convert it" into s

m must be s/kg

bc u need 2 s/kg * 4kg for the kgs to cancel

and then similar thing with b

in order for it to remain in s and for adding the terms to make sense

you need it in the same units as mx, which we know now that once evaluated it will be s

[strange umbra]

Can anyone help me on this one?

[mint nest]

Can someone help:

the problem i'm having is finding the antiderivative of the function

I got to x(x^2 + 1)^(1/2)

but idk how to go from there

like if it was to the power of 2, i could just expand

but idk what to do for this

[alpine sable]

can someone pls help me answer this

[thorn kindle]

u=x^2+1, du = 2x dx, dx = du/2x

[onyx canyon]

b

[thorn kindle]

Then it becomes the integral of (sqrtu)/2 du

[onyx canyon]

did u even read the problem

[turbid drum]

b

oh nvm

[alpine sable]

i need a 100% because i have a really bad grade in geometry

[onyx canyon]

thats not even a geometry problem

[alpine sable]

is it b?

its basics

i just started school

[compact lynx]

think about it a bit

[spice breach]

can i ask how i solve these logarithms which arent isntantly obvious?

[thorn kindle]

A good life hack for these sorts of problems is to use actual numbers

[marble storm]

pls help for both

[thorn kindle]

If 1 is less than 2 and 2 is less than 3 then is 1 less than 3?

[compact lynx]

@spice breach change of base

[spice breach]

?

[compact lynx]

log_b(a) = log_10(a) / log_10(b)

[spice breach]

the problems arent advanced enough for me to use that i think?

[compact lynx]

is generally how this is used

[spice breach]

the other problems atleast

[alpine sable]

thanks for the guidance..online school had me lacking off, so idk if i should overthink or not

[spice breach]

it says the answer is 5/3 @compact lynx

[thorn kindle]

What common base do 8 and 32 share? They are both powers of?

[spice breach]

2

3 and 5

[thorn kindle]

Yep

[spice breach]

oh

i get it

[thorn kindle]

So log2(32)/log2(8) = 5/3

[compact lynx]

^, change of base

[spice breach]

why am i allowed to suddenly change it from 8log to 2log?

[compact lynx]

change of base

[spice breach]

and x is 2 in this case

[compact lynx]

log_2^3(2^5)

= log_2(2^5) / log_2(2^3)

= 5/3

[glass lichen]

u-sub

[spice breach]

oke thanks

[mint nest]

whats that

[glass lichen]

You perform a u-sub then integrate

[tight locust]

it's like chain rule but in reverse

[compact lynx]

yo am i high or is P(B) here not correct

im thinking it should be

8/10 * 2/9

or 8/45

[spice breach]

2/10 and 1/9

because A and B are the keys that open the lock

you got 10 keys 2 open

so you randomly select keys

[compact lynx]

B is the event that the second key opens the lock though

and you're not replacing the keys

[spice breach]

yhea but you already took one key out right?

[compact lynx]

yeah so

it should be 8/10 * 2/9

no?

[spice breach]

no 2/10

only 2 open

8 dont

[compact lynx]

yeah

[glass lichen]

for B?

[compact lynx]

so to find the event

that the second key opens

the first key can't open

and then the second key opens, chosen out of 9

[spice breach]

so the chance to get a key that opens is 2/10

[compact lynx]

no, it's 2/9

because you've already chosen a key that doesn't open

[glass lichen]

For B you dont care if the 1st key also opens the door

[compact lynx]

ah okay even then is it not 10/10 * 2/9

[glass lichen]

no

[spice breach]

why because there arent replacements

so you choose a key from 10 keys and afterwards a key from 9 keys

[glass lichen]

cause B is the event the 2nd picked opens the door.

[compact lynx]

i guess you'd have the add the cases where the first key opens and the first key doesn't open

[spice breach]

ah

mb

2/10 2/9

[compact lynx]

so (2/10)(1/9) + (8/10)(2/9) ...?

[spice breach]

no its 2 seperate events

[compact lynx]

ah that gives 1/5

[glass lichen]

Yeah, I think LTP applies

[spice breach]

so A is if the first key were to open thje lock

[compact lynx]

which is 2/10

[spice breach]

and B is if the second were to open the lock

[compact lynx]

yes

and if i dont care tha tthe first opens

i need to consider two cases

P(B) = P(1st key opens, 2nd key opens) + P(1st key does not open, 2nd key opens)

[spice breach]

2/10 and 2/9 right?

or sorry

2/10 and 8/10 x 2/9

[glass lichen]

P(2nd opens) = P(2nd opens|1st opens)P(1st opens)+P(2nd opens|1st doesnt open)P(1st doesnt open)

by law of total probability

[glass lichen]

which is this

[compact lynx]

yea okay cool

misunderstood the q

thought B was the event that the first key doesnt open adn the second key chosen opens

but the answer makes sense if you interpret the question like that yeah

[glass lichen]

Nope, B is just the 2nd one you pick has to open the lock

[compact lynx]

yea makes sense

[spice breach]

can i ask another question about logs? how do i solve this one with the rule?

[compact lynx]

well

what does a log mean

[glass lichen]

definition of logs

[compact lynx]

log_a(x) = b

means that a^b = x

yeah

so log_5(x) = 2 means..

[glass lichen]

$\log_a(x)=b\iff x=a^b$

[ocean seal]

Mosh

[spice breach]

x=2^5?

[compact lynx]

no

[glass lichen]

2 isnt the base

[spice breach]

5^2

[compact lynx]

yea

and that's just by the definition of a log

[spice breach]

but if thats the case

the answer should be 25 right?

a=25

?

but the answer sheet says 32

thats why im so confused

[compact lynx]

yea just a typo or something then

it's for sure 25

[spice breach]

so this would be 3^4

aka 81?

[glass lichen]

yes

**b=**81

[compact meadow]

Ayo

How do I know if the function has a minimum x value

[spice breach]

calculate the discriminant

[compact meadow]

The fuck is that

[spice breach]

D= sqrt(b^2-4ac)

[compact meadow]

Hol up look at my question I'ma send my pic

Bro I'm on graphs and shit

[spice breach]

basically calculate B^2 - 4AC

wait

what am i saying

you want to know if it hits the x line?

[compact meadow]

Let me send it

@spice breach

[spice breach]

ah

look

[compact meadow]

How do I know if there's a minimum x value

[spice breach]

do you have your function?

[compact meadow]

The shit on the right ?

The graph ?

The green line ?

[spice breach]

yhea

[compact meadow]

Wait what's the function

The green line M

?

[spice breach]

yhea the green line

[compact meadow]

Ok

How do I know if I have a minimum x value ?

[spice breach]

well its a straight line

so it cant have one

because it will always go straight up or down

[compact meadow]

So when ever it's a straight ass line it has no limit so that means no minimum ?

[spice breach]

yes

[compact meadow]

And plus the line never stops

And it has no maximum ?

Since the line is infinite

[spice breach]

see how this one

"stops" at 0.15y and then goes back up

so its minimum is 0.15

[compact meadow]

Ohhhhhh

Yea it does stop

That's the dot the stop

[spice breach]

and this one

[compact meadow]

Yup

[spice breach]

stops at 0

and goes back down

[compact meadow]

That shit has a max at well

[spice breach]

so its maximum is 0

[compact meadow]

At 0

[bold mantle]

Hel0

[spice breach]

@compact meadow what domains can you choose from?

[compact meadow]

What's a domain

[bold mantle]

all real numbers that will work

[spice breach]

https://cdn.discordapp.com/attachments/490557019623915520/893266753180815390/QDOBA.png

[bold mantle]

I think

[spice breach]

the third question

[compact meadow]

Is a domain a dot ?

Oh

The options are

[spice breach]

no the domain is basically its minimum and maximum x values

[compact meadow]

Domain is all real numbers

Domain is a subset of all real numbers

[glass lichen]

it isnt

[bold mantle]

Wait so the domain of that is 0, 20?

[spice breach]

why isnt it?

[compact meadow]

wait what ????

[glass lichen]

Domain is the set of allowed inputs

[bold mantle]

x or y?

[spice breach]

x

[glass lichen]

inputs

so x

[compact meadow]

Wtf is a input

The letters ?

[bold mantle]

No

The numbers

[spice breach]

but if you get sqrt(x)

[glass lichen]

f(x)=y has input x and output y

[compact meadow]

Ohh the numbers

[spice breach]

the minimum x value is 0

[spice breach]

while the max is infinite

[compact meadow]

So 0 7 21 0

[glass lichen]

no

[spice breach]

or is the way i state it incorrect?

[glass lichen]

"infinity is a maximum" is bs

[bold mantle]

r u in algebra 1 advanced rn?

[compact meadow]

Algebra 2

[bold mantle]

Oh I'm in algebra 1

[compact meadow]

How do I know if the function has a maximum x value ?

It doesn't have a maximum right ?

Since the line doesn't stop anywhere

[spice breach]

take the derivative and equal that to 0

[glass lichen]

yes

no max and no min value

[spice breach]

but because this is a straight line

[compact meadow]

🔥🔥🔥🔥

[spice breach]

the derivative would be a number and no x

[compact meadow]

I was right let's goo

[spice breach]

so you cant equal it to 0

[compact meadow]

Glooks mosh medium

[spice breach]

so there isnt a maximum or minimum

[compact meadow]

Mr dim

What's a derivative

[glass lichen]

calculus thing

[spice breach]

ignore me listen to mosh

mosh has the big brain

[glass lichen]

dont worry about it if you don't know it

[compact meadow]

Ok

[spice breach]

mr mosh

[compact meadow]

Mosh the third question is

[spice breach]

can i ask a question?

[compact meadow]

Domain is all real numbers
Domain is a subset of all real numbers

Which one is it

How do I find out

Which one it is

[glass lichen]

well, are there any x values you cant plug into a linear equation?

keeping in mind a line is of the form y=mx+b

[compact meadow]

What's a x value

[glass lichen]

...

[compact meadow]

The number ?

[glass lichen]

the value of x

[compact meadow]

What's the value of x in that questions

[glass lichen]

that's what im asking you

[compact meadow]

There's 2 21 0

[glass lichen]

in y=mx+b, can x be an real number?

[compact meadow]

Idk

[glass lichen]

or is there a value x cant take on?

[compact meadow]

Idk

Eli5

[glass lichen]

Check your notes if you dont know

[compact meadow]

What x gonna take on 🧐

I think

Domain is a subset of all real numbers

Since it goes to infinity

[glass lichen]

no, it's all real numbers

for the reason any x value can be plugged in and get a sensible output

[compact meadow]

Oh shit you were right 🔥🔥🔥🔥

How were they all real numbers

How did you know

[spice breach]

@glass lichen im sorry im asking alot of questions about log but how do i solve these type of questions (i dont understand how i make the 4 or 1/2 into logs aswell)

[glass lichen]

You just look and say y=mx+b hmm, m*x will be a real number for any x, and mx+b will be a real number for any m x and b, so any x can be plugged in

[teal linden]

id be scared if i were u

[glass lichen]

you don't, those are expressions, nothing to solve.

[spice breach]

i mean the question is rewrite the expression as a single log

so how do i make the 4(a 2 base) into a 3log?

[glass lichen]

4=log_3(3^4)

by definition of logs

[spice breach]

ah im stupid thanks

[compact meadow]

Mosh

How do I find out if the function has a minimum Y value

[glass lichen]

well again, any x value can be plugged and any y value can be gotten out of the function

[compact meadow]

So no for both ?

It doesn't have a minimum or a maximum

Since the graph is infinite both ways?

[glass lichen]

yes

[vagrant rover]

Why don't you flip inequalities?

[glass lichen]

2/9 is positive

so multiplying both sides by 2/9 doesnt change the ineq

[spice breach]

would the log_9(x-3) become log_3(x-3)^2?

[vagrant rover]

Ohhhhhh

Okay okay

MNy bad

lol

[glass lichen]

no, you can just apply change of base to make the log_9 into log_3

$\log_9(x-3)=\frac{\log_3(x-3)}{\log_3(9)}$

[ocean seal]

Mosh

[spice breach]

can you please explain how changing of bases works because i cant seem to grasp the concept

[compact meadow]

There's 2 y intercepts ?

@Mosh

Which one is the one that intercepts

The one straight on the line

Or the one right by it

Which point

Intersects means go through

Ohhhh

The one on the right

Like a Lil to the right

[spice breach]

@glass lichen

i tried to solve this

[compact meadow]

But not exactly on the line ?

Or the one exactly on the line

Oh the dot is exactly on the line thats why

And the line intersects through the dog

Dot

And there's 2 x intercept

[glass lichen]

yes

[compact meadow]

And there is a minimum x value ? @glass lichen

[spice breach]

this cant be right can it?

[glass lichen]

yes

[glass lichen]

yeah cause it's wrong.

$\log_9(x-3)=\frac{1}{2}\log_3(x-3)$

[ocean seal]

Mosh

[spice breach]

why is this that

[compact meadow]

And the domain is all real numbers ?

Or sunset

Subset

[glass lichen]

domain is R.

[spice breach]

oke but then you got sqrt(x-3) times (x+3) to solve

right?

[glass lichen]

to simplify, yes

again, there's nothing to solve

[spice breach]

sorry

to simplify

but what will you end up with?

oooh

the answer sheet just simplifies it into log9

so it will be log_9(x-3) and then 2log_3(x+3)

so it will become log_9(x+3)^2

and then you got to solve (x-3)(x+3)^2

to simplify it into one log_9?

[glass lichen]

there's nothing to solve

so stop saying solve

[spice breach]

oke how do i say it in english

please tell me

[glass lichen]

simplify

[spice breach]

is it compute?

[glass lichen]

simplify, combine the logs into 1, etc

[spice breach]

oke so solve is only x=123

[glass lichen]

solve is solving for the variable(s)

[alpine sable]

An ellipse has all the combinations of x and y possible in it in general form?

x,y,x^2,y^2,xy

[small bear]

What do you mean by this?

[alpine sable]

Like a standard ellipse

Does it have all the terms?

[alpine sable]

These

[small bear]

take a circle x^2 + y^2 = 1, does it have all of the terms?

[alpine sable]

Nope