help-0

[alpine sable]

its coming out to be -96

f(-2)=-(-2)-11=-9

[alpine sable]

f(1)=-1-11=-12

exact diffeq equations are type of diffeq that can be directly solved like
$$(x+y)dx + xdy =0$$
can be solved like
$$xdx+ydx+xdy = 0$$
$$xdx +d(xy) = 0$$
and then you can directly integrate them
there are ways to identify and solve them and turn non exact in exact which'll you encounter in near future

[flat crane]

f(-2) = -9
f(1) = -12

therefore 4 * (-9) + 5 (-12) = -96

[ocean seal]

Spica

[alpine sable]

now jus sub h=0

cause h->0 and the expression is finite

[rapid hazel]

ohhh woww

I'm so dumbb

[rapid hazel]

now I understand

thank you @flat crane

[tardy peak]

Pls help

<@&286206848099549185>

[alpine sable]

use trigonometry

since f is inversely propotional to d^2 , then f = k/d^2 where k is a constant
for f=6 they have given d=6 so find the value of k from it
then for d=3 find f as you will now have k and d

oh u deleted qn

[alpine sable]

use trigonometry in triangle odc

cos of angle COD = OD / OC

OD = r

OC = 2r

cos COD = 1/2 then angle COD is 60 degrees

[flat crane]

DC will be r * sqrt(3)

but why no pi

oh you use 22/7 ?

[alpine sable]

huh?

[flat crane]

I don't see pi in the options

although it's asking area of circle

[alpine sable]

we use 22/7 ig

[flat crane]

ok

[ruby sparrow]

originally, the question was to solve this using Cramer's rule

but I'm not so fluent in this rule in this case so I gotta ask you guys

how do we apply cramer's rule in this case

[glass lichen]

Cramer's doesnt find inverses

it solves systems

[ruby sparrow]

ik it's used to find the xyz value

and yeah it's weird tbh

[glass lichen]

yes, it solves systems.

Like I said

[ruby sparrow]

but the original question was to find A^-1 using Cramer's rule

but man this is a weird question

if it's just using normal equations then it's no big deal using it to get the x y z

[glass lichen]

yeah, if you're given adj(A)... just find the inverse w/ the adjoint matrix

[ruby sparrow]

A^1 = adj(A)/det(A) right

[glass lichen]

yes.

[ruby sparrow]

i got the answer from the quick trick

but just for practice lol

assuming if my prof doesn't want us to do the normal way

or maybe just typo issue

[glass lichen]

idk, ask your prof.

cause nowhere is Cramer's said in that screenshot

[ruby sparrow]

ah it's in my printed book

[glass lichen]

Ok...

[ruby sparrow]

it's the same question that's why

[glass lichen]

k

[alpine sable]

hello guys I'm new here and I'd like help in solving my math problems

I'm really stupid when it comes to math

[glass lichen]

yeah...

[ruby sparrow]

yeah the og was this

that's why i said it's weird

[glass lichen]

that clearly doesnt say use cramer's

Cramer's refers to problem 6

[ruby sparrow]

the problem 7

[glass lichen]

which is a system

yeah idk, ask your prof

[ruby sparrow]

hmm u r right then

let me just ask again

[ruby sparrow]

so it's not exactly I'm stucking with question in this case

but it's the prof thing

[tardy peak]

so wats the answer?

[tardy peak]

i didnt get it

[alpine sable]

help guys

[hexed yoke]

A has to be one of the numbers in the set (2,3,5,7,11) and b as well, and because The final number has to equal an integer the number inside the square root has to be a square number which is 1 4 9 16 etc. This means that 2Aminus B must equal a square number .So the top row is two times the primes (2a) and then the left column is the B numbers and then I just found two A minus B and then I just circled the ones that equal a square number 149 etc. and then you can just work out that’s A = this and B = that

[ruby sparrow]

what's the radius tho

need to know the DO or OM length

but if u ignore it

it's 3:1 ratio

because in this case, DO = OM = MC for same radius of circle O

so you get a 30-60-90 triangle

assume that OD = 1, OC = 2 and DC = sqrt 3 if that's the case

and formula for the area is side ^2 while area of cirlce is pi*radius^2

so it'll be 9/pi thing

so around 9:3 or 3:1 ratio

@tardy peak

[onyx sluice]

Can someone help me with an exercise

I know the solution

but I need the proccess

Solve the following quadratic equation

x^2 -4x +25

[alpine sable]

just use shridhar acharya

u might know it as the quadratic formula

[onyx sluice]

the result is x=4+or-3i

[alpine sable]

.

[onyx sluice]

what that

ok

ye i know

Im in the process

but I cant get that exact answer

[alpine sable]

x = (-b +- sqrt(b^2 - 4ac))/2a

yes

hey man i need help in a q

[onyx sluice]

Can u finish helping me please

[alpine sable]

just plug in the values man

[alpine sable]

.

in this equatio

[onyx sluice]

ye I know

But I dont know how to finish

[alpine sable]

so you want me to solve this step by step and give you your homework

[onyx sluice]

no

[alpine sable]

[onyx sluice]

Just tell me what I do after this part, (4 +- 2i sqrt (21))/ 2

[quick escarp]

https://www.youtube.com/watch?v=iI_2Piwn_og can someone explain to me from 7:30 to 8:15 cause I'm so confused on that part anyone please

[alpine sable]

yea so ur gonna get 2 +- isqrt(21)

done

[onyx sluice]

did u divide

what did u do there?

[tardy peak]

thnks aloottt

[alpine sable]

yeah

[tardy peak]

<@&286206848099549185>

pls help

[onyx sluice]

thank u

[alpine sable]

:3

How to induction when you got 2 variables?

[vague coral]

induction is on n not x

[alpine sable]

Oh?

How are we supposed to know which one

[vague coral]

induction is always on natural numbers

[alpine sable]

Hmm i see

[dim nacelle]

can i ask a question?

I have a linear algebra problem i need some help with. Is it ok to ask in this channel?

[fluid solstice]

yes

[dim nacelle]

Let
u1 = [1 1 1],
u2 = [1 0 1],
u3 = [1 0 −1],
u4 = [112],
Is there a linear mapping L such that L (u1) = u2 and L (u3) = u4? If yes: How many such Ls are there? Enter such a matrix L. If the answer is no: Explain.

The only way i could fiqure it out is by L(u1+u3)=u2+u4 and then guessing a linear mapping that suits. Is there a more mathematical method i could use to get L

[alpine sable]

my brain is fried

https://cdn.discordapp.com/attachments/879132863117791273/891690757688283136/unknown.png

339.5 x 49.75

16890.125

it says wrong

[tardy peak]

i can relate

[alpine sable]

yes

it should be this rihgt?!

right?

[coral moss]

rounded to the nearest 10 for 340, not to the nearest whole number

so the lower bound for 340 is 335 not 339.5

[alpine sable]

I cant believe ive done this

[coral moss]

lol

[alpine sable]

channel free?

i assume so 👀

please help

[lethal plinth]

is having a ti-84 for analytique geometry cheating?

[glass lichen]

yes, provided the individual limits exist

it would not

cause the limit as x goes to -2 DNE

since sided limits dont agree

no, cause the sided limits arent equal

...

did you not read what I just said

[glass lichen]

.

?????

k, no need to be a dick, mistakes happen.

[toxic radish]

How would I solve for for B

[alpine sable]

I looked at the answer explanation and I still don't understand it.

[toxic radish]

then I get 100000 = 75000 ( 1.024)^x

what would I do next

i don't know how to solve for exponent

[toxic radish]

why would I divide both sides by 75000

?

just trying to understand here

i get 1.333 = 1.024^x

[alpine sable]

https://cdn.discordapp.com/attachments/490557019623915520/891688189872447518/image0.jpg Im kinda stuck in (b)

is there some formula im supposed to use

[alpine sable]

what grade is that?

i have no idea how to turn |sin(nx)| into |sin((n+1)x)|

[alpine sable]

college first year

[small bear]

It says induction, you need to turn |sin(n+1)x| into something using |sin(nx)|, not vice versa

[alpine sable]

no idea how to do that either

[small bear]

and |sin( (n+1)x )| = |sin (nx + x) |

[alpine sable]

yes

I still dont see a way to put sin nx in there...

[small bear]

addition formula

[alpine sable]

oh

[small bear]

write d=a_k+1 - a_k

[alpine sable]

i been avoiding that because i dont know how to get rid of the cos

[small bear]

Well, we need to get rid of that cosine, what is true about cos(x) in general?

Or I should rather say |cos(x)| since the absolute value

Do you know the range of cosine?

[alpine sable]

-1 1 ?

[small bear]

yes, so |cos(x)| <= 1

does that make sense?

[alpine sable]

yes

I will try to write it and figure something out now

[small bear]

Alright, you should also know inequalities regarding the absolute value

for example |x+y| <= |x| + |y|

try to use everything I said, if you're still stuck, ping me

[alpine sable]

i will

thank you

[dim nacelle]

Anyone who can help me with this problem?

[alpine sable]

yup got it thanks a lot

helo

Can i know

why the domain is (0,infinity)?

[abstract fractal]

Domain? It looks to me like the domain is (-infinity, 0)U(0, infinity)

[alpine sable]

oh

[fading summit]

is arcsin(-x) = -arcsin(x)?

i mean it looks like an odd function

this must be the case right?

[fleet pollen]

how ? ive been thinking this for the whole day

[twilit ibex]

How do I solve this?

I thought of using the binomial equation solver and calling (-729) = i^2*729.

But I don't know what to do with the i^2?

[willow anvil]

It's just 3i right?

[fleet pollen]

o i got it YZ= square root YX and XZ

[willow anvil]

I'm really struggling on this probability question. There are 10 card, 5 of which are consonants. When 4 are chosen at random what is the probability of getting at least 3 consonants

I got 55/210 but I have no idea if that's right. I just did some combinations over 10C4

<@&286206848099549185>

[stable pecan]

I get 70/210

[formal fossil]

HI, can anyone help me with this equation , i solved it, but i'm not sure i have right .

[stable pecan]

5C3*7C1/10C4

[willow anvil]

@stable pecan why 7c1

[stable pecan]

The fourth card can either be a consonant or not - it will be selected from the total number of cards left, which is 7 after taking 3 consonant cards

[willow anvil]

I think I did (5c3 x 5c1 ) + (5C4) all over 210

Oh that makes sense

What's wrong with the reasoning behind my method, ways of choosing 3 consonants + ways of choosing 4 consonants

[eternal cave]

i need help

[left granite]

Dont ask to ask just say it

[stable pecan]

I am not sure, you should probably get this verified by someone else but my guess is that my way of counting incorporates all the permutations of how the 4 cards can be selected (where 3 are treated as the same??) and yours doesn't. Notice if you compute the ways of choosing 4 consonants like this - 5C3*2C1(ways of choosing 3 consonants then the next card is selected by the 2 consonants left) then your way and my way give the same results

[fathom dragon]

is this room available for help?

[elfin fiber]

Pls

Help

hm??

[clear knoll]

which problem, 5?

[elfin fiber]

6

[clear knoll]

im not sure how they want you to round, i guess 1/4's makes the most sense?

[fathom dragon]

can anyone help me out?

[glass lichen]

#❓how-to-get-help

[clear knoll]

sorry nao just kinda took over, try another q'

[elfin fiber]

yes but idk what that means

[clear knoll]

questions channel*

you don't know what rounding means?

If you have 4.8 and you want to round to the nearest whole number, what number would that be?

[elfin fiber]

oh

uh

idk

5?

[clear knoll]

yes

if you had 4.1 it's 4

[elfin fiber]

yeah ok

[clear knoll]

4.5 is right in the middle tho, typically teachers like to round up (to 5) if that's the case.

so 3/8 is between 1/4 and 1/2, do you know why?

1/4 = 2/8, 1/2 = 4/8

So you can choose to round either to 1/4 or 1/2 then do the subtraction

[elfin fiber]

hm

this is so confusing

is that the ques?

[left granite]

How is this confusing?

[clear knoll]

I have to go sadly but I'd suggest you get a better idea of how fraction addition / subtraction works. Honestly mixed numbers (2 1/4, 3 3/8, etc.) are kinda confusing and it becomes easier as you work with fractions more and more.

but it looks like the question is more asking you to get an idea of how 1/8's work relative to 1/4's

[elfin fiber]

oh

[left granite]

You can change a denominator by multiplying both deno and numo

[elfin fiber]

what do i round?

which [art

part**

[clear knoll]

so just round to the nearest 1/4 (in this case, it's either 3 1/4 or 3 1/2) then subtract

[left granite]

Dude

[clear knoll]

i was thinking this, but idk if this has been covered yet in the class they're taking

[left granite]

U let me talk

@elfin fiber

[elfin fiber]

what

[left granite]

So u cant round like

Round to the nearest tenth fior 8.888

[elfin fiber]

do i round the answers?

for the question

[left granite]

Answer y or n

[elfin fiber]

ohh

[left granite]

Ive never heard of rounding fractions. Im assuming ur talking about fraction converted to decimal to rounded

[elfin fiber]

same

[clear knoll]

i don't think they want an exact calculation here, I'm afraid you're gonna confuse them. If you're teaching them how rounding works then go ahead but I wouldn't get into fraction multiplication

[elfin fiber]

i think no

[left granite]

?? Im asking do you know how to round a decimal?

[elfin fiber]

it's not close

[elfin fiber]

kinda

[left granite]

Hey i can tell ur rly confusing this person

[elfin fiber]

brooo

[left granite]

I dont think u need to round to fraction

[elfin fiber]

the answer's no

[left granite]

Its smth u dont do, its kinda an only demical thing

[unique flint]

hey

any1 good at grade 10 triangles

[left granite]

@unique flint not here

[elfin fiber]

uh

[unique flint]

oh

[left granite]

Find another channel @unique flint

[clear knoll]

ok I'm sorry, it's just that decimals are not involved here, and I think introducing them would be (albeit helpful) not what the assignment is looking for

[elfin fiber]

yeah that's true as well

[left granite]

Cool but u shouldnt get offtopic here

We are sidetracking

[elfin fiber]

is the answer no?

[left granite]

U made a simple fraction question confusing

[elfin fiber]

lol

[left granite]

Not u its chef

I talk abt

[elfin fiber]

kk

[left granite]

Ok so all u have to do is - the fraction

4 times basically

So there are 2 pies yes?

[elfin fiber]

mhm

[high crest]

I'm pretty sure your approach overcounts. Let's say we have 3 cards and 2 consonants and we want the probability of choosing at least 1 consonant. The solution should obviously be 1, since all combinations have at least 1 consonant.

[elfin fiber]

uhhhhhhh

[high crest]

,ask ((2 choose 1)(2 choose 1))/(3 choose 2)

[left granite]

@high crest dude not here

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kex#1024

[left granite]

Stop

Bro

Do this in dms

[clear knoll]

https://www.khanacademy.org/math/cc-fifth-grade-math/imp-fractions-3/imp-visually-adding-and-subtracting-fractions-with-unlike-denominators/v/estimating-adding-fractions-with-unlike-denominators

[left granite]

Someone is getting help gere

[high crest]

Didn't notice

[clear knoll]

@elfin fiber this will be helpful for you I believe

[elfin fiber]

ok

[left granite]

Dude lemme explain

Chef ur making this qs rly confusing for them lemme just explain pls

Khan is good but its literally adding or minusing fractions

[left granite]

Can i move this to dms?

[elfin fiber]

ok

[left granite]

Lemme get on pc now

[elfin fiber]

alr

[stable pecan]

Let's go to #help-7｜zen1thxyz

[high crest]

alright

[clear knoll]

@left granite this is from #rules " ● Respect that other people might be at a different stage in their education than you, what is obvious to you might not be obvious to them." please keep that in mind. Instruct without adding another lesson for them.

[left granite]

Im not trash talking them at all

all im saying is that you're making it confusing

it's criticism

[elfin fiber]

ok jus help me broo

[left granite]

kk

wait ur dms are closed

[elfin fiber]

what

[left granite]

it might be me hold on

[elfin fiber]

wait

[alpine sable]

Hi can someone help. Me understand this problem

[left granite]

dont ask to ask

just post the qs

[alpine sable]

I'm getting 9/4 for a and 17/4 for b but when I graph it just doesn't look continuous

Ok

[left granite]

ok i cant help you sadly

im alg 2 h so yea

just wait for someone else to come

[alpine sable]

gotchu

[plucky crow]

you did it no?

that looks continous to me

[alpine sable]

It isn't tho

On x = 2 it's a jump discontinuity

[stable pecan]

<@&268886789983436800> ^

[sly mantle]

b&

[velvet dove]

guys

is this correct (i just took the test but i want to verify)

[alpine sable]

hang on

[torn garnet]

Can some1 help me with Confidence intervals

[alpine sable]

<@&286206848099549185>

[velvet dove]

<@&286206848099549185>

please help

[white bane]

can someone explain the difference between [] and ][ in math. like what does [1,2], [1,2[ and ]1,2[ mean

[hasty kestrel]

id believe so?

its not very uncommon to see functions denoted without their independent variable, so you can just assume that fh = l(x) for example and go from there

[velvet dove]

ok the quiz has several flaws

I will address them to the teacher tomorrow

one of the questions has the same right answer twice

[raw shard]

@velvet dove if that’s function multiplication you’re right

[raw shard]

if it’s function composition you’re wrong

[velvet dove]

look at C and E

the exact same

[velvet dove]

ok how am i wrong

tell me

[raw shard]

if it’s function composition the answer is f(5)

but you’re right

the way they wrote it was just misleading

should have had a multiplication symbol

[abstract fractal]

(fg)(x) is a normal notation for f(x)g(x), no?

[raw shard]

@abstract fractal i’ve never seen that so i got confused

[alpine sable]

what question

[velvet dove]

Yes

but this quiz is based on function composition

usually it’s (fog)(x)

[crimson maple]

how to do this

[abstract fractal]

What's 8/4?

[crimson maple]

that's

2

[raw shard]

do you know what to do when dividing exponents with same bases?

[abstract fractal]

Alright, what's c³/c?

[crimson maple]

c2

c^2

[abstract fractal]

What's d²/d²?

[crimson maple]

d

[abstract fractal]

You sure?

[crimson maple]

wait so no d's?

so 2c2

[velvet dove]

how many times can d^2 go into d^2

[crimson maple]

1

[velvet dove]

then that’s the answer

[abstract fractal]

Yes, the answer is 2c²

[velvet dove]

2c^2*1 or 2c^2

[crimson maple]

ty

[alpine sable]

u can help me ...😥

We consider a random variable X that follows the binomial law B(30; 0.49).

Calculate to the nearer 10 −4: p(X=19) =

recall that for $B(n,p)$ we have $\ P(x=k)=\binom{n}{k}p^k q^{n-k}$

[ocean seal]

Al3dium

[alpine sable]

for k being the number of successes, can you give yourself an attempt to the problem?

(and for q being 1-p)

@alpine sable u can give the result with the calcul , operation with number pls

no, this server isn't to give away answers.

can you give it an attempt yourself, considering what i wrote above?

and tell me which part is confusing you and where did you get up to.

im so bad for the calcul.. i don't have a little method or a skill for that

can you show me what our P(x=19) would be without putting anything into a calculator?

or at least what you think it would be.

we'll deal with the calculator later.

it is the probability ... ?

[alpine sable]

yeah no, i'm talking about how you'd use this formula ^, to compute the probability of P(x=19).

reposting the formula.

@alpine sable I would divide it

[torn crescent]

Yo

can someone help me with a problem

[wild olive]

me too :(

[alpine sable]

but what would you divide? can you show me exactly what you'd have by using the formula?

you can have a pic of it for simplicity

@alpine sable 0.49/19x4

We consider a random variable X that follows the binomial law B(30; 0.49).

Calculate to the nearer 10 −4: p(X=19) =

no, n is 30 not 0.49, and also the $\binom{n}{k}$ isn't a fraction

[ocean seal]

Al3dium

[alpine sable]

is this your first time to binomials?

yes... i need a example with numbers for understand

,tex \binomial

[ocean seal]

Al3dium

[alpine sable]

you can read this whole that i wrote a while ago to get a better hand of it.

i have x instead of k here, but it doesn't matter.

OH my god...im very very very bad...

i'll get back to you later, i have to do something, after reading the text, you can have an attempt to your problem.

or look up some youtube resources of binomial distribution, seeing some examples may help you get a better hand of it too.

@alpine sable thx for had take ur time , im sorry , thx again

[sharp trail]

what is -x when x=-2

[crimson maple]

idk maybe u have to transfer it back to positive?

[sharp trail]

i think it is 2 but i'm not sure

[glass lichen]

it is.

-(-2)=2

[crimson maple]

see im too smart

[sharp trail]

ok thank you

yes very smart

[crimson maple]

yeah bro

13 and smart

im too good

lol

[twilit ibex]

Is this flawed?

Please tag me

It is in Danish, but very little of it is natural language.

idiotreglen/idiot rule: cosh^2(v) - sinh^2(v) = 1

[sinful relic]

Hvad for et lvl har du mat på?

[merry umbra]

Why the hell are you guys coming up with these hard ass looking problems

What the hell are you guys in college

[twilit ibex]

Yes, I am

[twilit ibex]

Uni, første semester

har du en løsning?

[oak chasm]

@twilit ibex Squaring removes the sign.

[sinful relic]

Jeg går i 1.g ;-;

[twilit ibex]

Would this then be correct?

Assuming

[oak chasm]

You had (-cosh(v))² = -cosh(v)², but (-cosh(v))² = cosh(v)².

@alpine sable Sorry, this channel is busy.

[alpine sable]

sorry

[sinful relic]

@twilit ibex Hvad er det for et emne?

[twilit ibex]

Is it then safe to assume, that ((cosh(v)^2 - (sinh(v)^2) = (-(cosh(v))^2 - (sinh(v)^2)

Because according to my teacher, it is not 🙂

[sinful relic]

What topic is that?

[twilit ibex]

Complex numbers

[sinful relic]

The only things that I can recognize are sin, cos and tan

[twilit ibex]

and hyperbole functions

[sinful relic]

okay

[twilit ibex]

Nvm

I figured it out

misunderstood the question

"Surprisingly" my professor, who has been doing mathematics for decades, was correct

[somber spoke]

https://cdn.discordapp.com/attachments/797115025868849184/891772397378736148/image0.jpg

<@&286206848099549185> is there a better way to solve this

i reduced it down to this point and just said that if u equate the coffecients and powers the only thing that works is a=0

but it doesnt seem like a very rigorous way to solve

[gray gorge]

Well, to be perfectly rigorous, you'd have to show that $7^{a+5}>(a+7)^5$ for any $a>0$, but I'm not sure if that's required from context

[ocean seal]

Naz(R / I)n

[somber spoke]

??

I mean like

[gray gorge]

In fact, I think there actually is another solution

[somber spoke]

Is there a method to solve like an equation

Oh cool

[gray gorge]

,w 7^(a+5)=(a+7)^5

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Rijinaru#5601

[gray gorge]

the leftmost red dot

[somber spoke]

Ye

[gray gorge]

approx. a ≈ -6.42588741327818...

[spare vale]

Can someone help please

Q13

[somber spoke]

I can explain in a sec

[spare vale]

Okay thanks

[somber spoke]

So is there like an equation you can get to solve it

Because I wouldn’t really be able to draw that graph in an exam

[gray gorge]

not an easy one, as wolframalpha has shown

so unless you are allowed to use a graphic calculator, idk

[rancid nymph]

If I have two positions in a 3D space, with X, Y and Z properties, how do I calculate the X, Y and Z rotations for the first point to face the second point?

[glad hinge]

I can't seem to get this question.

Let f(x) = x^5 - 3x^4 - 6x^3 + 10x^2 + 21x +9, find the multiplicity of 3 as a zero of f(x). Do not use a calculator.

I've already done synthetic division to get it factored to (x-3)(x^4 - 6x^2 - 8x -3), but I can't figure out how to get any further. Help?

[placid zinc]

What's the remainder after another division by x - 3?

An easy way to go about it, just start another synthetic division and see what you get at the end

[glad hinge]

Remainder is 0

Oh no wait I see what you're saying

Hold on I'll try that

[velvet dove]

guys check this out

how tf is it -1/2

1/x +2 = 0
but -1/2 + 2 = 1.5..

[glass lichen]

x=-1/2

1/x=-2

you plugged x=-1/2 into x+2

not 1/x +2

[velvet dove]

wait a minute

so u mean

[glass lichen]

$\frac{1}{\frac{-1}{2}}=-2$

[ocean seal]

Mosh

[velvet dove]

1/(-1/2) is what I did?

oh

ohh

[glass lichen]

is what you do

what you did was wrong

[velvet dove]

ok thanks

[warped basalt]

could someone pls help me w this, i’m so confused?

(ping if u can pls)

<@&286206848099549185>

[fair vine]

i believe a,b,c are 3 points and you apply to all 3 those 3 instructions and write them down in img1,2,3 , first instruction defines a line along wich you mirror the point

[warped basalt]

i understand what to do, i just don’t know how to do it. how do i follow the instructions listed

[fair vine]

you can do it visually, thats arguably why they provide you with that coord system, first reformulate the line: -3x-y=-4 => 4=y+3x => 4-3x =y => draw 4-3x line

after you got that put the points on the paper and just use a orthogonal line to the mirror line to get the mirror point

[high crest]

,rotate

[high crest]

Exactly

[restive hollow]

Can anyone help with number 3

I got this so far

<@&286206848099549185>

[rugged token]

Hi, I don't understand in 4 degree polynomial what does a, b, c, d stands for? I completely don't understand 4 degree polynomial linear so can someone give me a clear explaination.

[covert breach]

u are trying to factor, so roots

u can use factor theorem as u already have 3 roots from what i see

[rugged token]

Ya but I know nothing an=bout 4 degree polynomial

[covert breach]

so afaik (x-1) (x+2)(x-2.5) (x-a)

[rugged token]

So I don't really understand what does abcd stand for

[covert breach]

solve for b and a using the value f(0) = 10

so (0-1)(0+2)(0-2.5)(0-a) = 10

solve for a

then u have your abcd as -1, 2, -2.5, a

[glacial vine]

hi...

can you help me on integrals....

[wind river]

I don’t get this bc I would find this by converting to vertex form how do I do this

[placid zinc]

Let's say you do convert y = 3x² - 5 to vertex form. What do you get?

[wind river]

3(x-0)^2-5?

[placid zinc]

Haha well done, that's a tricky one for most

[wind river]

when i apply the transformations i got a different equation

the question makes me think they applied the transformations to standard form

which idk how u would do that

[placid zinc]

It won't matter, you'll get the same no matter what

They didn't apply them in the order shown

[wind river]

yeah u gotta find out which order they did it but idk how to find that

trial and error?

[placid zinc]

If I do it in the order shown:
-V shift up 3
3(x - 0)² - 2
-H shift left 1
3(x + 1)² - 2
-Reflection over x-axis
-3(x + 1)² + 2
-V stretch by 2
-6(x + 1)² + 4

It's really all about that constant, isn't it

Seems like the horizontal shift can happen at any time

[rugged token]

So what does a, b, c, d stand for? I would like to know these because it helps me to enhance the knowledge

great thanks however

[raw shard]

probably the coefficients

[wind river]

but then how would you get +7 for the vertical shift? if you reflect over the x axis to get -5 and then shift up 3 u get -2

[placid zinc]

You get -5 after reflecting?

[wind river]

+5

then u get +8

which still isnt +7

[placid zinc]

So indeed, you have these things you can do to the constant:
Multiply by -1
Double
Add 3
And you want to go from -5 to +7

Which order do they need to happen in?

[wind river]

ahh

[noble goblet]

how would i do c , this is what i put in my calculator to graph it

[covert breach]

additive inverse of roots

[dry echo]

Can someone tell me what they mean by "using definition" in number 10? Does it want me to find the derivative and then plug in the number?

[tight locust]

do you know what the definition of the derivative is?

perhaps you've seen this before

[dry echo]

yeah

f(x+h) - f(x) over h

That bussiness?

[tight locust]

yeah

[dry echo]

so I just plug in the number directly there

without actually finding the equation of a derivative?

[tight locust]

if you just plug in the number you won't be able to solve. you need to find the derivative of the function itself

because the derivative relies on the behavior of the function immediately surrounding that particular point

[dry echo]

right

I just don't know any other way of doing that anyway, so I can only think of doing it the way you just described

So it confused me lol

[granite lily]

Anyone know how to solve this question?

[dry echo]

I'm new to calculus

Thanks for the help @tight locust

[thorn kindle]

75/sin30

75/sin45

Decreases

[granite lily]

What

[gaunt cove]

can i ask a questiion here

[thorn kindle]

What is unclear?

[granite lily]

The steps

[thorn kindle]

I could not have made it any simpler

[granite lily]

How could I approach this

[thorn kindle]

Draw a picture lmao

[granite lily]

Bruh

[thorn kindle]

Or just think about it. The wires are separated by some angle θ, and we are given that each wire supports the weight by an equal amount. Therefore, each wire must form an angle of θ/2 from the vertical.

This angle of θ/2 from the vertical is equal to an angle of 90-θ/2 from the horizontal. So we then have a right triangle with known angle and known leg, and we want to know the hypotenuse.

Just think about it for a bit

[gaunt cove]

https://tenor.com/view/among-us-dance-dance-among-us-purple-sus-gif-18888988

[hard haven]

Does anyone know why mobius marked this wrong?>

[gaunt cove]

re sus

[charred flint]

@hard haven to shift up 9 you have to have +9 on the outside of the entire function

right now the +9 is under the fraction so it's wrong

[hard haven]

still got it wrong

Do you know why sir?

[charred flint]

uh oh

[hard haven]

LOL

[charred flint]

best guess is they want the 1 on top in parentheses? no idea

[hard haven]

OH U RIGHT

[sly mantle]

@gaunt cove don't post offtopic content

[hard haven]

let me try that

nope it's still wrong

i want to cry

[alpine nacelle]

you want 1/(x+1)² + 9

[boreal isle]

any idea how to do this without using the quotient rule?

i tried using the definition of derivative but i have no idea how to simplify it all

[wary bolt]

Pls someone help me with this

You have to make them add to 100, each question

I already did 1 and 3

[nocturne juniper]

you added the upward shift in the bottom of the fraction and also put the +1 on the x^2 and not the x

so there should be (x + 1)² in the bottom fraction

[covert breach]

how do i solve this?

i dont quite understand what they mean when u devide lhs by y^5

im not getting exact DE afaik

cuz del N / del x = 4

del M / del y = -4/y^5

pls help

[alpine sable]

errr guys

if 1^5 = 5

how much is -1^5 ?

[covert breach]

bruh

im asking a question

[alpine sable]

oh

[covert breach]

its -1 btw

[alpine sable]

why ?

[covert breach]

just use a calculator for this shit.. 🤦‍♂️

-1 to the odd power, if its -1 to the even power then it would be = 1.
also, 1^5 is not 5, its 1

[alpine sable]

😦

ok

[covert breach]

how do i solve this?

[raw shard]

@alpine sable i can explain why

oh wait they already did oops

[covert breach]

<@&286206848099549185>

pls help me with this DE

i dont quite understand what they mean when u devide lhs by y^5
im not getting exact DE afaik
cuz del N / del x = 4
del M / del y = -4/y^5
pls help

[sudden gorge]

hi

does this point mean I have to multiply?

[raw shard]

channel is occupied @sudden gorge

[sudden gorge]

where can i claim a channel?

[covert breach]

u just ask in another channel, where a question isnt already being asked

[smoky isle]

hey

[sudden gorge]

well

[smoky isle]

do you know what the square root of 49 is

its the only one im stuck on.

[covert breach]

7, can u guys please go to unoccupied channels ffs

[boreal isle]

sorry that dude was being a dick

[covert breach]

please help me with this

[raw shard]

@sudden gorge go to #help-7｜zen1thxyz

[boreal isle]

1^5 is the same as 1 x 1 x 1 x 1 x 1

[raw shard]

@covert breach sorry that everyone keeps interrupting you lol

[covert breach]

u guys are being dicks by asking questions in a channel thats occupied

like wtf

[smoky isle]

sorry

[covert breach]

https://cdn.discordapp.com/attachments/490557019623915520/891843278104850472/unknown.png

[smoky isle]

geez

it was quick

[covert breach]

why dont u use a calculator for it then

[smoky isle]

toche

i should have use d acalculator

but

you guys are faster

[covert breach]

but u decided wasting other peoples time was a better idea

[smoky isle]

not true

[covert breach]

someone pls help me with this

<@&286206848099549185>

[smoky isle]

woah buddy

ill help you

uhhhh

try Mx+My dx/-y

mabe7y

im no student at harvard

but i try my best'

[covert breach]

bruh

just leave

cuz u guys keep interupting when im trying to ask a fucking question

[raw shard]

if you are literally just guessing because you don’t recognize anything in the question you shouldn’t answer

[boreal isle]

just calm down ok

[raw shard]

everyone just stop talking

and let @covert breach post a question

[covert breach]

omg...

[boreal isle]

[covert breach]

alright. at least she/he had the curtosy 😂

no

u were being a dick

https://cdn.discordapp.com/attachments/490557019623915520/891843278104850472/unknown.png

[raw shard]

this isn’t even about math anymore it’s just an argument so it doesn’t fit here

please stop talking

[covert breach]

well

i got del M / del y = -4/y^5

and del N / del x= 4/y^5

if i divide both M and N by y^5

bro. stop trying to help

u wont be able to

oh i think i got it

man that devide LHS by y^5 is so vague

now u guys can go ahead and ask if u need/want to

[thorny pier]

what the heck happened here

[raw shard]

people kept interrupting this guy when they wanted to ask a question

[thorny pier]

yea but lmao the amount of people

anyway, is delta math down for u guys

i have one assignmetn on delta math the whole year, and it crashes before its due

[fair osprey]

How do i do this? From what iknow, i need to kinda reverse the right side so it would be 12-2=10, but i don't know how negative 7*something would equal positive 10?

[errant bloom]

To solve this problem your going to want to plug in the point given into the equation to get 12=k(-7)+2. Then to move the 2 over you subtract two from both sides to get 10=k(-7). Next to get -7 over you must divide both sides by -7 to get -12/7=x

[past anchor]

what is the math term for when multiplying this

like multiplying the parentheses together

[fair osprey]

the last step confuses me

[boreal isle]

distributing?

[thorny pier]

foiling maybe

[boreal isle]

i think

[delicate owl]

hi can you guy help me did I graph the right one which suitable for question B ?

[past anchor]

yes

[thorny pier]

I think it works but U need 6

[delicate owl]

Thank you so much 😔 it’s really hard

[tight locust]

that's what she said

haha

[loud verge]

Hey so I need some help with something. I am trying to code something and im stuck on how to get a number. I am trying to make an algorithm so when 4 = 1, 8 = 2, 16 = 3, 24 = 4, and so on. What I basically am trying to do is create a formula to get the numbers I need

[fair osprey]

Coding servers might be able to help more

[loud verge]

its just a mathematical equation im trying to create. If there is no regular math for it ill try another way

[raw shard]

@alpine sable i’m probably wrong but it might just be a way of writing a constant

yeah i’m probably wrong

yeah i don’t know but what i said is the only thing i can think of

also it’s only on one side

so that weird

[sick torrent]

Can someone help me in #help-1

[raw shard]

bruh

[void swift]

Really easy, use log

[loud verge]

what?

[void swift]

Logarithms?

[loud verge]

oh

[void swift]

oh

[sick torrent]

How you find the domain and range of a limit graph?

[void swift]

same as you would any other graph, just watch out for holes and asymptotes

just exclude those from your set

[sick torrent]

I don’t understand

[void swift]

what do you not understand

[sick torrent]

The lines aren’t connecting so is the domain just x is greater or equal to -4 but less than 6?

[void swift]

no

there's an asymptote at x=2

it cannot be 2

[sick torrent]

Oh

[void swift]

so partition your domain into 2 sets

[sick torrent]

X is greater or equal to -4 but less than 2
X is less that or equal to 6 but greater than 2

Correct?

[void swift]

looks fine

[-4,2) U (2, 6]

[sick torrent]

What’s the difference between ( and [

[clear cedar]

Math help?

The perimeter of an Iscoseles triangle is 24cm, find the side lengths

[void swift]

( - not inclusive
[ - inclusive
set notation if you want to learn more

[clear cedar]

Pls help

[void swift]

that's... not enough information to go on

[sick torrent]

What do u mean by inclusive?

[void swift]

[-4 means including -4
(-4 means not including -4

[sick torrent]

Ohhhh

[void swift]

or equal to/not equal to

[clear cedar]

Anyone?

[sick torrent]

Makes sense thank u very much

[void swift]

that's... not enough information to go on

[glass lichen]

clearly not enough info

[clear cedar]

Well it’s all I have

[glass lichen]

well then you cant solve it

simple as that

[void swift]

are they asking for the triangle or a triangle

[clear cedar]

Asking for the triangles sides

[void swift]

you left out

right triangle

[clear cedar]

Oh sorry

[void swift]

something something pythagoras

[glass lichen]

let the legs be x, then you can easily determine the length of the hypotenuse

then just... solve for x

[clear cedar]

Could you explain more?

[void swift]

you have all the info you need to set up an equation

try to do that first

[glass lichen]

I mean explaining more is basically giving the crux of it

[fleet pollen]

how to do B?🤔

[vital delta]

I'm not sure where that exgtra 2k-1 is from

it should only be (2(k+1)-1)

[grizzled sundial]

How would you differentiate y=2ln(x)?

[strong furnace]

consider the 3 cases where you have 2 green / 2 blue / 2 red marbles and solve them and use the addition principle

[grizzled sundial]

that extra 2k-1

[sick torrent]

Isn’t there an infinity?

[vital delta]

dy/dx ln(x) = 1/x

[grizzled sundial]

is the previous term

[void swift]

for the domain, why would there be

[grizzled sundial]

so 2k-1 is the term before (2(k+1)-1)

@vital delta

[vital delta]

how do you know that

[strong furnace]

the (2(k-1)-1) term is hidden in the first expression among the (...)

[sick torrent]

When do u add an infinity to a domain then?

[grizzled sundial]

because n=k is the kth term and we're trying to find the term after k, which is the (k+1) th term

[strong furnace]

are you asking by first principle ?

[grizzled sundial]

no

[fleet pollen]

so is 2/8

[grizzled sundial]

just using he formula

[void swift]

when the domain extends to either infinity, -infinity or both. do you see any cases of that happening here

[strong furnace]

use the product rule and the fact that constant has derivative 0

[grizzled sundial]

?

[sick torrent]

Yes.

I think

[void swift]

there is not

unless there is more than the picture is showing the domain has clear bounds at -4 and 6

[strong furnace]

how'd you come to this conclusion?

[sick torrent]

Isn’t the graph going down to -infinity when the x is close to 2 ?

[strong furnace]

do you know the usual derivative rules and derivatives of transcedental functions?

[vital delta]

im still confused

[void swift]

i think you're mixing up your domain and range

[sick torrent]

Oh?

[grizzled sundial]

umm the derivative of ln(x) is 1/x and i know the differentiation rule

[sick torrent]

What would the range be?

[void swift]

you asked me if the domain (the x) has infinity, i said no

[vital delta]

how do you know which term comes before what. how are you sure its that term

[fleet pollen]

because 2 are the same from the 8 of them?🤔

[void swift]

what do you think? try to make a guess

[strong furnace]

man there's like 3 problems in here

move to different question sections lol

[grizzled sundial]

yeah

[sick torrent]

I have no clue

[grizzled sundial]

whats the question u guys are working on

[vital delta]

the 2k -1

[void swift]

what's the highest value attained? what's the lowest value attained?

[strong furnace]

the series is made up of the terms of the sequence 2n-1 which means nth term would be given by 2n-1 so in case of the first series they show you the 1st , 2nd , 3rd and k-th term but in the second series they show you 1st 2nd 3rd k-th and (k+1)-th term the one term you are talking about is the k-th term

[fleet pollen]

probability

[sick torrent]

Infinity and -infinity?

[void swift]

yes. are there any holes in this graph?

any empty holes?

[sick torrent]

Yes?

[strong furnace]

so just differentiate and use product rule I don't see what you're struggling with

[sick torrent]

There are holes in the x axis but not the y axis am I correct?

[void swift]

holes have both an x and y value, so you cannot phrase it like that

[sick torrent]

Oh

[grizzled sundial]

right thx

[void swift]

when you are checking for holes (discontinuities) you need to check

• is the hole empty?
• are there any other points that "fill in"/share the same x and y as the empty hole?

[viscid quiver]

would someone mind helping me in #help-5 with a basic geometry question after yall are done here?

[void swift]

if there are no other points that "fill in" the empty hole then that is a concern

[somber osprey]

Ah

[void swift]

and you need to mind the hole when writing your domain/range

[viscid quiver]

@void swift @somber osprey please I just need the question answered

[sick torrent]

Oh

Thank u

[opal dock]

hi, can somebody tell me how to simply this

thank you

[vital delta]

@strong furnace

what happened here after he expanded this to 3 * 3^k

[ashen cliff]

How can I find Sn?

ok?

[void swift]

was A something mentioned previously in the question

[ivory thicket]

hello

is exponential equation the same as logistic?

is that a thing

someone might have gave me false info

so im perofming a regression analyisis (ttryna find which equation best fits my data

and i need to anaylise 5 euqations

[sick torrent]

Why wouldn’t the domain be [-4,-2] U (-2,2) U (2,6]

[ivory thicket]

exponential, linear, quadratic, logarmithic. and logistic?

of

okay so will it count as a type of equation?

i need 5

[void swift]

let me ask you then, is there a valid value for x=-2? can you give me a y-value for x=-2

[sick torrent]

Yes

[ivory thicket]

exponential = a * e^(bx)

logistic = 100- (100/(a*e^(bx))

right?

thats what mine is currently

cause im graphing this in excel

[void swift]

are there valid y-values when x is slightly smaller than -2, slightly larger than -2, and when x=-2?

[sick torrent]

Yeah cuz it’s infinite right?

[void swift]

there is no point in -2] U (-2 because there are no gaps here

[ivory thicket]

yellow is my exp. gray is my logistic.

[sick torrent]

I’m confused

[void swift]

if there are valid y values everywhere, then why is there a need to partition them?

[ivory thicket]

yellow is the data im tryna find the equation for

so ima say logstic best fits it

so is it a different type of equation?

[ashen cliff]

I cant find any formula for this, can some one help?

[ivory thicket]

well my teacher said 5 different types of equations

[sick torrent]

There’s a gap here so shouldn’t the domain be [-4,-2] for the first function?

[ivory thicket]

i chose, polynomial linear, eponsential, and logarmitic (you know the obvious ones) and someone suggested logistic so i looked into it, but im not sure if it ocunts as a separate one

[void swift]

@sick torrent you need to partition when there are undefined coordinates. just because you see an empty hole does not mean the graph is undefined at that x-value/y-value. you need to check if there are other parts of the graph that are defining it

[ivory thicket]

power

ill look into it tysm

and instead of exponential ima replace it with logistic

[void swift]

in this case both x=-2 and y=2 are defined by other points in this graph so there are no gaps there and you do not need to partition

[sick torrent]

Ohhhh

I’m understand

[toxic ginkgo]

Hello

I am Maria

[ivory thicket]

is there a word to talk about the first half of a quadratic where it assumes x =0* for all points after?

[waxen silo]

Question, I don't want to just get the direct answers but want to actually learn so I can do well on my t st but some say it's cheating.

[alpine sable]

it doesnt

pls hhelp

[waxen silo]

Is that allowed here

[ivory thicket]

i have no idea what any of this means lol sorry dude

what is "division"

[sick torrent]

The function fails to be continuous at x=-2 and x=2 and x=3 am I correct?

[abstract fractal]

Correct. The function is not continuous at those points

[sick torrent]

Oh

Damn thx

[mint eagle]

i dont even know where to start this haha

[hardy gulch]

is that all that's given to you?

[mint eagle]

it gives me these as the rules of inference

i know you can solve the problem with a truth table but like is that really the only way to do these kinds of problems...

me?

lol

[ashen cliff]

I need help in #help-3

[mint eagle]

<@&286206848099549185> any logicians?

[merry herald]

Any idea on how to solve this?

[clear cedar]

65 pls. It’s my last hw problem

Pls

[merry herald]

<@&286206848099549185> ?

[clear cedar]

<@&286206848099549185>

[merry herald]

someone help me please...

[chrome notch]

Does anyone know how to do this?

[harsh nimbus]

what do you need with this

like simplify

[harsh nimbus]

think about pythagoerean triples

[merry herald]

i got it now its fine...

[harsh nimbus]

oh nice

[merry herald]

is this also simplification

[harsh nimbus]

in a way yes

[merry herald]

alright

[harsh nimbus]

hint go with the most inner sqrt at a time

[raw shard]

yes you can simplify that

@harsh nimbus i don’t think there’s any other way

[harsh nimbus]

yeah true lol

[merry herald]

ok thanks

[fringe socket]

quick question, is the reduced row echelon form of any 3x3 matrix an identity matrix?

[placid zinc]

No

[fringe socket]

hm

[placid zinc]

Consider
0 0 1
0 0 0
0 0 0

[fringe socket]

ooh i see i see

[placid zinc]

Its RREF is
0 0 1
0 0 0
0 0 0
Which is not identity

Now, there's very specific things you can say about such matricies

[fringe socket]

i see

interesting

linear algebra bit mad ngl

[placid zinc]

Lin alg = best course

Bae course

[slow wraith]

can anyone help with a couple of math stuff

[simple hamlet]

.

[slow wraith]

yes please

[strong furnace]

you can start by proving/using the fact that LN is a perpendicular bisector of MD

[slow wraith]

alright

[oak jewel]

Is this open?

What is the reciprocal rule? i don't fully understand it