help-0

[golden nymph]

If you check for integer r

Sorry internet suddenly stopeod

Back again

Idk if there are cases where rational r’s are accepted but let’s not risk it

[arctic wren]

is this channel free ?

[finite breach]

i got 1/96

which

doesnt seem right?

i feel like there should be more

[harsh belfry]

lol the genshin refeence

[alpine sable]

would this not be right??

[golden nymph]

Simplify

And rationalize the denominator

I think the computer doesn’t recognize it as the answer saved

1,1,1
1,2,4
1,3,9
2,2,2
2,4,8
3,3,3
3,6,12
4,4,4
4,6,9
5,5,5
6,6,6
7,7,7
8,8,8
9,9,9
10,10,10
11,11,11
12,12,12

[alpine sable]

hmm alright thank you

[golden nymph]

Considering when I go descending I have those but not the all repeated in account so times 2 minus 12 and I have 17*2-12=22

Out of 12^3=

,calc 12^3

[ocean seal]

Result:

1728

[golden nymph]

So

,calc 22/1728

[ocean seal]

Result:

0.012731481481481

[golden nymph]

,w 22/1728

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ZozzDude#8586

[golden nymph]

I hope I am correct

,calc 1728/96

[ocean seal]

Result:

18

[alpine sable]

i am bad at exponents pls help

send the q

[silver bear]

How to do #4?

[golden nymph]

You will need a rational r in the cases where your first term is a multiple of a perfect square (4, 8, 9 and 12 but half of them are just two big)

Lol I didn’t take lines in cartesian form

Or actually

Set the three expressions equal to each other as equal to t

And for each expression isolate the variable

That way you get an expression for each variable in t

Which is basically your vector equation of the line

I think you can continue from there?

[silver bear]

So set the first 3 equation equal to t right?

[golden nymph]

Don’t kill me please I only watch jojo I didn’t watch any other anime

[silver bear]

That part I get

[golden nymph]

Yup

[silver bear]

Then how do u determine if they are perpendicular

[golden nymph]

Can you continue from having the vector equation of lines?

Or do you need help after that

[silver bear]

I forgot the vector equations lol

[golden nymph]

??

After getting the vector equation of the lines

The line it contains

Just plug in two random values of t to get two points on the plane lol

And for the perpendicular line

The direction vector is the normal vector of the plane

Do you need more help

[silver bear]

Ok I got it

Ty

[golden nymph]

Looking at question 3

There is an evil way to transform the cartesian equations to vector

[silver bear]

Ah shit

[golden nymph]

You can choose two values of x and solve for the other variables

That way you have two points on the line so you can do the parametric then the vector

But yeah you’re welcome

[hollow dagger]

hi so this isnt homework or anything im just genuinely lazy rn

[golden nymph]

Lazy doing what

[hollow dagger]

so for every 2 tablespoons of sour cream has 2 grams of carbs in it, how many grams of carbs would there be in a cup\

[golden nymph]

Lazy to do the not-homework?

Oh lol that’s defo not hw

[hollow dagger]

i dont have hw today was my third day of school 😭

[golden nymph]

,w cups in tablespoons

Your answer is 16

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ZozzDude#8586

[hollow dagger]

omg

ty lol

[golden nymph]

And this is why you don’t press more

[hollow dagger]

i didnt 🖐️

[golden nymph]

I hope you make a delicious meal

Or a healthy one

[golden nymph]

Someone did but it doesn’t work until the person asked press it so I did lol

[silver bear]

@golden nymph don’t worry, u not a weeb yet

[golden nymph]

That was a bit late but ok

[golden nymph]

No

[proven adder]

yes

[golden nymph]

I don’t even know what the operations in hamburger mean

Can you multiply sets by numbers or wtf is happening

[proven adder]

math

[fair osprey]

? Is this math?
The only th8ngs I can tell are that grape=1 cookie=2, hamburger = z/2z?

[remote temple]

2 numbers that multiply to 60 and add to -7

impossible?

[proven adder]

its my math

[alpine sable]

can someon help me with the answer

Pls

[terse wren]

wat

[proven adder]

i havnt learned what to do with the squared, all ik is that you need to multiply the 2 by both terms (4d2) and (d2)

dk if that helps

[zinc zephyr]

No lmao

squared is multiplying the number by itself a number to times

[proven adder]

ik thats what u do when its not squared

[zinc zephyr]

for example

lets say 2²

so 2*2 = 4

[proven adder]

ik

[zinc zephyr]

if 2³

its 2*2*2

[proven adder]

i was talking about the 2 in front of the bracket

[buoyant kayak]

hol up

how did you do two asterisks and not have it italicize

[proven adder]

hes a baller

[zinc zephyr]

you add a \ before the first *

like this

[buoyant kayak]

i see

[zinc zephyr]

without

[buoyant kayak]

2*2*2

[zinc zephyr]

*with*

[buoyant kayak]

yoo

insane

[zinc zephyr]

true

[analog plinth]

anyone here know discrete math

[buoyant kayak]

i'm sure there's quite a few

[chrome skiff]

What is the difference between determinants and matrixes?

[oak chasm]

A determinant is a scalar and a matrix isn't.

[elfin fiber]

hey

[pearl wraith]

guys how do i solve this for each individual square

i got to the vertex of the entire area

[chrome skiff]

Matrix is a vector?

[pearl wraith]

but i dont know how to get the perimeter of each individual square

[lean night]

can i ask the question here?

[oak chasm]

@chrome skiff Yes.

[lean night]

can someone help me find this answer?, find f(4+h) base of this example, i got struggle 😦

[glass lichen]

Det is a mapping from the space of square matrices to the corresponding scalar field.... a matrix is a matrix

[alpine sable]

can someone explain to me how to find the answer to this?

i feel like this is a super easy question

im just dumb

[ancient saddle]

Hello, try drawing the number line and put E at 1. Then draw a point G that is 9 units away of E, at what position is this point?

[alpine sable]

oh so it is super easy lol

hey guys quick q

Two scales were used to measure the weight of a rock. The result from the first scale is 25±0.3, and the result from the second scale is 27±0.1. Which scale is more accurate?

i think the first is more accurate and the second is more precise

can someone confirm pls

[chrome skiff]

Is it true that its used by scientest? Why does scientist use matrix to calculate things. Isnt it much easier to use microsoft excel?

[glass lichen]

... what?

[half delta]

can some one explain how to do the 2nd question;-;

[glass lichen]

I mean, of course matrices are used in science, you can write systems of DEs as matrices, test independence via Wronskian matrix

It's used in DE and MultiVar stuff

Which is very applicable to science

[chrome skiff]

Thnx. Looks usefull. Its seems i really need to learn it. But its hard. 😫

[alpine sable]

can bias be negative?

[oak chasm]

Without knowing what the true mass of the rock is, you can't tell which is more accurate.

Accuracy is how close the measurement is to the true value.

[elfin fiber]

can someone pls help

with question 13..

PPL

[fair osprey]

I tried to help in DM’s, but idk how to explain how 13 works (I’m thinking 4:3 as ratio, then add them bc it’s a “segment”. Divide 28 by 7, and it’s 4. Multiply result by 4 and by 3 for wins and loses but it’s just how I do stuff)

[elfin fiber]

yeahh

[fair osprey]

You pinte s a person, not the helper role xD

[elfin fiber]

oh no

[tranquil tulip]

a) 3/7 = x/28

[elfin fiber]

how

what'

[tranquil tulip]

because if you win 4/7 games that means you lose 3/7

and if you play 28 games you don’t know how many games you lose so that’s what x is

[elfin fiber]

well

[elfin fiber]

how 3/7??

[tranquil tulip]

because if you win 4/7 games that means you lost 3/7

[fair osprey]

The other part of 4/7

No ties

[wary stream]

It's how fractions work

Pay attention

[elfin fiber]

oh

u simplify?

[wary stream]

$$\frac{4}{7} + \frac{x}{7} = \frac{7}{7}$$

What is x?

[ocean seal]

dldh06

[wary stream]

Where 4/7 is the amount of games won

And x/7 is amount lost

[elfin fiber]

oh

[fair osprey]

To find that do 7-4

[elfin fiber]

4?

[wary stream]

7 - 4= 4?

[fair osprey]

Subtracting fractions, you leave the denominator (I think it’s the right term) alone if it’s the same

[elfin fiber]

no

i multiplied it

[wary stream]

Why?

[elfin fiber]

3

cuz i thought u simplify

but

[wary stream]

No

[fair osprey]

Simplify is divide

[elfin fiber]

oh

ok

but why the answer says 12??

[wary stream]

Because it's not done yet

How many games did the team lose?

[fair osprey]

Because, 3 time 4 is 12. But to get there, you need to do other things first

[elfin fiber]

what to do?

[wary stream]

Math

[fair osprey]

Wait, explain step by step/how you think when you solve this or try to solve it

For every 6 red beads, there are 2 blue beads. How many blue beads are there if there are 24 beads in total?

[elfin fiber]

what math? bruh

[elfin fiber]

ok

[elfin fiber]

kk soo

5?

[alpine sable]

That would require there to be more than 12 red beads, which is impossible

[elfin fiber]

oh

[wary stream]

I don't even think this is possible to solve properly

[alpine sable]

I think she meant 16 beads total

[fair osprey]

I meant 24, typo

[wary stream]

Or 12

[elfin fiber]

ohh

i was likeee

ok well

[alpine sable]

@elfin fiber now solve it

[elfin fiber]

i jus wrote the answer no idea

[elfin fiber]

ok

[alpine sable]

If its 24

[elfin fiber]

12?

[fair osprey]

||(How I would solve this.

1. Add the 2 beads, for total beads ratio thing, idk name
   You get 8
2. Divide 24 by 8, to see how many fit into it. Also, tells you how many to multiply by
   You get 3
3. Multiply what you got (3) but the number of beads per set of beads.(2 blue)
   You get 6
   Equations:
   2:6, 2+6=8
   24/8=3
   3*2=6)||

It’s how I think it could be solved

[elfin fiber]

u tell me how to solve 13 plsss

why u teeling me this

[alpine sable]

Is there are are 12 blue beads, then there will be (6*12)/2 red beads, so no

[wary stream]

By using ratios

And math

[fair osprey]

I’m trying to see how you don’t know how to, by seeing this or it’s just us doing it

[elfin fiber]

idk broooooo

ugh

fuck it

[alpine sable]

@elfin fiber if you are just told directly how, what will you do when you have to solve a similar question

[elfin fiber]

true

[undone isle]

schrodinger spitting facts!!!!

[elfin fiber]

but idk how to do it??

[vivid anvil]

The answer’s “-0”(/s)

[elfin fiber]

BRUH

stop annoying me and get out

[fair osprey]

Read through this, does it make sense?
Then try to do this one
2 cats for ever 3 dog in pet shop, 20 total pets in pet shop, only cat or dog. How many are cat

[alpine sable]

If there are 2 blue beads per 6 red beads, then the ratio is 2:6, the total sum of both integers in the ratio has to be 24 because there are 24 beads in total, so what do you have to multiply the ratio by in order to make the sum of both integers 24?

[elfin fiber]

ok

idk

[elfin fiber]

oh ok

i'll try

[alpine sable]

How

You literally just add the values in the ratio together and divided it by 24

[elfin fiber]

that is hard

[alpine sable]

24/8 is not hard

[wary stream]

You honestly need to review basic math. If you don't even understand how to divide, that's just bad

[elfin fiber]

ik how to divide

[alpine sable]

@elfin fiber https://www.education.com/worksheets/preschool/math/

[elfin fiber]

.....

ik how to do it bruh

[undone isle]

lol

shrodinger spitting facts ngl

[alpine sable]

Then why can't you solve the question

Im just not sure what you dont understand

I have told you exactly what to do

[fair osprey]

Maybe go on khan academy, and do a I think 4th to 6th grade math review course ?

[wary stream]

I think K to 5 first

[alpine sable]

I think that naos problem is comprehension

[fair osprey]

Does anyone know an alternative way to explain it?

[wary stream]

I think it's honestly basic math and numbers

[earnest rover]

quick question.

f(11) doesnt exist right!? Since 11 is not included

please

like thats all

[wary stream]

Channel busy

[earnest rover]

ik im interrrupting but its so quick

FUCK

NOBODY WANTS TO HELP LOL

just so quick i swear

[wary stream]

Leave this channel

It is busy

[earnest rover]

ok fine

[alpine sable]

It will be even quicker in an empty channel

[alpine sable]

Perhaps both

[wary stream]

Just search through the previous conversations and you'll understand

[fair osprey]

@elfin fiber do these

1. Add 2 and 6
2. Divide 24 by the sum that you got
3. Multiply the blue beads and red beads separately with the product you got from step 2
   (2 blue per 6 red)

[elfin fiber]

why do i needa do that?

it's not even the ques

[fair osprey]

Ik it’s not

[alpine sable]

😔

It is

Its just rephrased

[fair osprey]

But I’m trying to teach you how to solve it

[wary stream]

If you had, $\frac{3}{7}$, how would you make the denominator become 28?

[ocean seal]

dldh06

[alpine sable]

@elfin fiber do you know what a ratio is?

[wary stream]

I honestly doubt it

[alpine sable]

Then there's the problem

[fair osprey]

I was helping nao with ratios problems earlier, so yes?

[elfin fiber]

what

[alpine sable]

@elfin fiber do you know what a ratio is

[civic ruin]

does he not know how to do it

[elfin fiber]

so the division part is 3?

[alpine sable]

Yes, 24/8 is 3

Meaning...

[civic ruin]

congratulations

[elfin fiber]

stop assuming gender dumbass

[civic ruin]

sorry dumbass

[alpine sable]

nao: 🧠

[undone isle]

derkek!!! hello!!!

[wary stream]

Do you know what 28/7 is?

[fair osprey]

I was helping nao do these https://cdn.discordapp.com/attachments/886841106086625310/887164879226691584/Image_2021-09-13_at_7.25_PM.jpg

[alpine sable]

@elfin fiber 24/8=3, but what does that mean in regards to the question?

If you dont understand this, it is useless

[fair osprey]

(Nao what are your pronouns? If you are ok with me using them)

[elfin fiber]

she/her

[wary stream]

It?

[alpine sable]

(Why are you typing like this)

[elfin fiber]

honestly

[wary stream]

jk

[civic ruin]

damn bro these really hurting my brain

[elfin fiber]

these two aren't even helping

[alpine sable]

Naos pronouns are /🧠

[elfin fiber]

idk why they're here

[wary stream]

No one asked you

[elfin fiber]

gtfo

[alpine sable]

We are but you arent listening to our advice

[fair osprey]

Bc it’s not directly relevant to math which is the topic at hand rn

[alpine sable]

@elfin fiber

[elfin fiber]

what advice bitch?

[alpine sable]

What's the answer to x^2-12x+52=0

I'm having trouble using the quadratic formula

[wary stream]

Channel busy

[alpine sable]

Channel taken

Oh whats a non taken channel

[wary stream]

Don't do people's work

[elfin fiber]

WTF

HUN

[idle tusk]

Okay.

[elfin fiber]

AU DID THE WRONG QUES

IMAO

[wary stream]

Delete it

[fair osprey]

UPVOTE

[idle tusk]

Did all the questions in the image.

[elfin fiber]

Imao

[elfin fiber]

do 15 pls

[wary stream]

Did you not read what I said? Don't do people's work and delete it

[plush herald]

Hello

[elfin fiber]

now that's called helping

[wary stream]

No it's not

[alpine sable]

Tfw 0 ambition

[fair osprey]

Nao, you need to learn how to do them or else you won’t know on a test

[wary stream]

It's called giving answers

[elfin fiber]

jk

[wary stream]

And we are not chegg

[plush herald]

Can someone help me?

[wary stream]

No

[undone isle]

go to different channel

[plush herald]

Ok

[elfin fiber]

i'm jk

[elfin fiber]

u go to diff chanel maybe

since ur so annoying

[undone isle]

?????

[fair osprey]

Use the /j, please

[idle tusk]

Okay.

[elfin fiber]

k

um

ok HELP PLS

[fair osprey]

...

[vague iris]

hello. do i need to subtract the expenses to the profit?

[fair osprey]

Channel busy rn

[elfin fiber]

how do i do 3??

[vague iris]

ohh sorry

[elfin fiber]

how

[alpine sable]

What

Wdym "how do I do 3"

What do you do with the 3 that you got from 24/8?

Is that what you're asking?

[elfin fiber]

i got 3

multiply

[fair osprey]

Yeah, but schrodinger is asking what is means in context of question

[elfin fiber]

what r the amount of beats again?

[civic ruin]

isnt it your question

shouldnt you know that

[alpine sable]

2 and 6...

[elfin fiber]

dumbass shut up

[elfin fiber]

oki

6 and 18?

idk

[alpine sable]

Yes, so if you got 3 from 24/8, then what you have to multiply the ratio by 3

[fair osprey]

YES

[alpine sable]

What is the ratio?

[elfin fiber]

6:18?

[alpine sable]

Im so happy i could cry

I never thought this day would come

[elfin fiber]

ok

loll

[fair osprey]

Try simplify ing it as well

[alpine sable]

No its -0:-0

[elfin fiber]

ok

lol

[alpine sable]

So then how many blue beads are there?

[elfin fiber]

2/6?

[fair osprey]

Now try this

[alpine sable]

Answer this

[elfin fiber]

wait

[fair osprey]

That’s simplified, so yes

[alpine sable]

She needs to figure out the amount of blue beads first

[elfin fiber]

oh

ok

[alpine sable]

Well not fully, it should be 1:3

But the question doesnt ask her to simplify

She needs to finish solving the question

Simplifyinf would revert her progress

[elfin fiber]

6?

was it?

[fair osprey]

YESS

[elfin fiber]

okk

[fair osprey]

This

[elfin fiber]

so

i'm doing 13 now

i don't have enough time

[fair osprey]

Ok...

[elfin fiber]

loll

[alpine sable]

🎉

[elfin fiber]

so um'

[fair osprey]

Go step by step

[elfin fiber]

for 13 a

ok'

what

[vague iris]

hello. do i need to subtract the expenses to the profit?

[fair osprey]

Use this, but adjust the numbers to fit 13a

[civic ruin]

what are you calculating

[vague iris]

im writing a function

[civic ruin]

i still dont know

[wary stream]

This channel is still busy

[civic ruin]

net profit?

[alpine sable]

4-2+63(524)

[wary stream]

Use a calculator

[alpine sable]

no

pemdas

or some shit

[wary stream]

Yes

[vague iris]

wait can we talk in #help-9

[fair osprey]

Chat busy

[alpine sable]

k

[wary stream]

Or calculator

[alpine sable]

@vague iris i already answered your question in #help-9

[vague iris]

thank you so much!

[fair osprey]

@elfin fiber how is 13a going?

[daring prawn]

hello WTF are taylor series and why do trig ratios use them

[wary stream]

It's a math concept

You can Google it

[elfin fiber]

ok

um

[elfin fiber]

'i didn't do it

[wary stream]

Why not?

[fair osprey]

Try to? Isn’t it due tomrow

[elfin fiber]

i was doin smth

[elfin fiber]

YEAH

I'M DED

OMG

oh god

[fair osprey]

So try to do it?

[elfin fiber]

ok

idk

can u tell me the steps

pl

[fair osprey]

Use this to help if needed?

[wary stream]

No, because you need to understand it

[elfin fiber]

noo

well i will obvi understand

after u tell me the steps

[wary stream]

No you won't

[fair osprey]

Here’s how I solved the bead one. Use as reference

[elfin fiber]

i will

and i did

before

[wary stream]

We tell you how to do it and you still don't understand

[elfin fiber]

where is the ques?

[fair osprey]

This was the bead question, it’s just the steps on how to solve

[elfin fiber]

yes ik

but the ques is diff

[fair osprey]

Or try solving this instead of 13 a first

2lakes per 4oceans on earth. If there are 18 total bodies of water(oceans of lakes), how many are lake

[elfin fiber]

ok

ok

so

i'm copy answers

idk

[fair osprey]

...

[elfin fiber]

yeah

sorry

i jus give up

[fair osprey]

You won’t know how to solve these on tests, in the future though

[elfin fiber]

is it 4/7??

[fair osprey]

?

[elfin fiber]

yeah well

jus tell me a pls

and i'll figure out the rest

pls pls pls

[fair osprey]

?

A what

[elfin fiber]

13 a

loll

[wary stream]

No

We no tell you answer

[elfin fiber]

ik the answer

but tell me how to do it pls

[wary stream]

That's your job to figure out

[elfin fiber]

noooo

idkk

[fair osprey]

Do you learn better with visuals?

[elfin fiber]

yeah

[fair osprey]

Give me like 5 mins

[elfin fiber]

k

[fair osprey]

That help?

@elfin fiber

[elfin fiber]

yeahh

i got itt

[fair osprey]

Can you make a diagram like that for the beads question?

[night sinew]

how does x = 2 - |y| equal to two intercepts?

for y

[elfin fiber]

i got that one

[night sinew]

oh sorry

[fair osprey]

Then make a diagram for this
5stars for every 2ncircles
21 shapes altogether

[elfin fiber]

help with 15 pls

[fair osprey]

You should be able to do it with the same way you did ratios

https://cdn.discordapp.com/attachments/886841106086625310/887164879226691584/Image_2021-09-13_at_7.25_PM.jpg like how you did 5

[elfin fiber]

kk

[fair osprey]

And how you find equivalent fractions

[elfin fiber]

howw

what

show me ex pls

[fair osprey]

Just try to solve it first

[elfin fiber]

i did

[fair osprey]

Reference back to the other ones that you did

[fair osprey]

What did you try?

Explain it step by step

[clever linden]

can someone help?

[elfin fiber]

no

[elfin fiber]

but

it's

the ques so confusing

[fair osprey]

Make a ratios with 3 numbers using 300 250 and 100

[elfin fiber]

ok

300:250:100???

[wary stream]

No

[elfin fiber]

pls quick

[fair osprey]

Yes

Now make an equivalent ratio, where the first one (300) is 900 instead

[elfin fiber]

how?

is it 900?

[frozen mortar]

hi

[elfin fiber]

OH GOD

[wary stream]

Because that's what the question says

[elfin fiber]

how do i do it in lowest terms?

[fair osprey]

Read question carefully

[fair osprey]

What did you do when you simplified? Reverse that?

[elfin fiber]

divided?

[fair osprey]

Eg. 60:55:7 but 60 is 120 instead.
120 divided by 60 is 2 so I multiply all others by 2
55 * 2 = 110
7 * 2 = 14
120:110:14

[elfin fiber]

how is that 120?

[fair osprey]

🤦‍♀️ ?

[elfin fiber]

hm

oh

k

[elfin fiber]

100 would be 200??

@fair osprey

[fair osprey]

?

There’s no100

[fair osprey]

Reread carefully

[fair osprey]

How is -0 a thing?

[elfin fiber]

nvm

[fair osprey]

Do 15 using ratios and this

[elfin fiber]

i got it

divide by 10 and then 5 ig

[alpine sable]

Nao thought that -0,7 was the coordinates of a letter on a cartesian plane

[elfin fiber]

yeah accidentally so chill

[alpine sable]

"accidentally"

[elfin fiber]

yeah i mean

i knew it wasn't a thing but

idk my brain

@fair osprey 17 pls

[dapper siren]

what's 1+1? please help

[ionic perch]

i only know 9+10 = 21

💀

[dapper siren]

I fogor💀

[undone isle]

meep you to secksy

[alpine sable]

@elfin fiber you should be able yo solve these yourself by now, we have given you the methodology required

[elfin fiber]

yeah i did it

[alpine sable]

Look back on past advice, and use it to get the answer to this question

[elfin fiber]

I'M DONE

YESSS

lolll

[elfin fiber]

bestieee accept req

[alpine sable]

You just want to be able to dm me for help whenever you need it

[fringe robin]

#friends with benefits

take h=2 for a?

[alpine sable]

(Unofficial)

[violet panther]

Especially for Qb

I don’t know how to draw the graph

[onyx hare]

is this channel occupied?

cause i need help

[alpine sable]

Why is the first entry point of 3A = 6?

Shouldnt it be 12?

[alpine nacelle]

it should yeah

[alpine sable]

And -2 next to 4?

Is this a typo? Or mistake?

Or am i missing a concept

[alpine nacelle]

the "solution" seems completely off

it is randomly the right entry or not

[alpine sable]

Interesting okay

Thank you

[gloomy dew]

help im confused

[elfin fiber]

no i'll ask here but i jus wanted to friend lol

[tough hatch]

on what, exactly?

[violet panther]

Could someone help me to find k???

[quartz oxide]

Just substitute in the expressions for h

[violet panther]

???

[quartz oxide]

for example, h(t+1)=30(1.65)^(t+1)

Oh you just made a mistake simplifying

Look closely when simplifying the fraction

Of course the 30 cancels out, but what about the (1.65) terms?

[twin island]

how do u get good at math...

[violet panther]

Ohhh I think I got it!

[quartz oxide]

Good

[violet panther]

I have same question…😅😅😅I really wonder how to be good at math

[violet panther]

Thank you!!

[rocky garnet]

i think for me is to learn the basics like multiplication,addition,subtraction,addition and other more like fraction and exponent

this can help you in the long run like calculus and advanced algebra

[sterile heath]

Hi

[rustic rock]

oof

[rustic rock]

duh

[split slate]

What exactly am I doing wrong for this question?

[alpine sable]

show work.

[split slate]

$\frac{a}{\sin{(A)}}=\frac{b}{\sin{(B)}}\\therefore a=\frac{8\times\sin{(38^{\circ})}}{\sin{(43^{\circ})}}$

[ocean seal]

HappyAlt

[split slate]

Sorry, long to type out

[fringe robin]

its correct

[split slate]

apparantly this is the correct answer

[oak chasm]

,calc 8 sin(38 degrees)/sin(43 degrees)

[ocean seal]

Result:

7.2218528533616

[fringe robin]

[oak chasm]

As you can see, when you run it through a calculator, you get the answer they said, so you did the work right.

[split slate]

yo wait, my scientific gave me a different answer

[fringe robin]

you must have given in radians

[oak chasm]

You might have it on radians mode instead of degrees mode.

,calc 8 sin(38)/sin(43)

[ocean seal]

Result:

-2.8504696141438

[split slate]

🤦

[oak chasm]

That's what you get when your calculator is in radians mode.

[split slate]

I thought that if I put in the "degree" symbol, even in radian mode, it would recognize it as one

but I forgot, you can also express radians with a symbol

and casio doesn't know the difference

Thanks

[oak chasm]

No problem.

[rocky garnet]

wdym i just answered someone's question

[sterile heath]

[warped pine]

whats the factor of 8x³-1000?

[pearl marlin]

write it like (2x)^3-(10)^3

[warped pine]

wow, thank you!

[warped pine]

Oh btw, can it be expanded more or thats where it ends?

[pearl marlin]

a^3-b^3 use this

[weak cradle]

Have you learned the "difference of cubes" formula?

[warped pine]

yes ive had, but when i try to check my answer or simply it again, it gives a different answer

[weak cradle]

Can you show me what you did and what is happening when you try?

[warped pine]

So when i try to expand it, im getting the answer (2x-10) (2x²+12x+100)
I dont know if i did anything wrong or messed up the solution

[pearl marlin]

you can break it in linear factors ( if you have idea of complex numbers)

[weak cradle]

That's close, but not quite the right factorization

The (2x-10) term is correct

The other term is off in a couple of ways

[warped pine]

I've also thought of that so itried to change it to (x²+10x+100) but still got another wrong answer

[weak cradle]

That's also not quite right

So we know that a^3-b^3=(a-b)(a^2+ab+b^2)

What are a and b in this scenario?

[warped pine]

a=2x and b=10?

im not sure about my a and b in the problem

[weak cradle]

Yeah, that's right

[warped pine]

so we have to use
(a-b)(a²-ab+b²) right?

[somber laurel]

guys what is HcF

im Not Skilled guy

[undone dock]

Highest common factor

[somber laurel]

ik

how to take HcF

[undone dock]

Like find it?

[somber laurel]

yep

[weak cradle]

+ab not -ab

[undone dock]

You can use euclids algorithm

[somber laurel]

bruh

im in 7 grade

euci what

[undone dock]

Oh, find prime factorisation of the numbers using a factor tree then

[warped pine]

oh yes, ive been very confused lately sorry

[somber laurel]

ok i guess

thanks

for help

[undone dock]

And then whatever is shared between the prime factorisation (like forexample, if they all have 2^2, 3 and 5 in common) and multiply them together. (For the same examlple, 2^2 * 3 * 5 = 60 so 60 is hcf)

[undone dock]

Youre welcome

[warped pine]

i tried to solve for the 2nd term again and i got (2x²+20x+100),

[weak cradle]

Ooh really close

What's (2x)^2?

[warped pine]

I dont think 2x² can be simplified or be expanded

[weak cradle]

Not 2x^2

(2x)^2

They're different

[warped pine]

oh, 4x²

[weak cradle]

Right

[hot vector]

.

[warped pine]

a² is 2x² ab is 2x×10 is 20x and 10² is 100
I still dont know why my 2nd term is wrong (2x²+20x+100), where did i make a mistake?

[warped pine]

So do I need to change 2x² on the 2nd or leave it like that?

[weak cradle]

Because a^2 is not 2x^2

[warped pine]

but a is 2x? So it must be 2x² but if it isnt what would it be?

[weak cradle]

What you said earlier

What is a^2=(2x)^2

[warped pine]

4x

wait what

[warped pine]

OH, thank you so much!!!

[warped sage]

hello can anyone help me with the integration of this

these are my steps

is it correct? if it is, I got stuck in last step

do I integrate 1/(5^x ln(5)) too ?

[oak chasm]

@warped sage If you do substitution, you need to completely switch over to the new variable.

You still have 5ˣ in the denominator.

You can convert that to u.

[warped sage]

yeah how do I get rid of it XD

[oak chasm]

u = 5ˣ + 2, right?

[warped sage]

ye

[oak chasm]

You're replacing 5ˣ, right?

[warped sage]

yes

[oak chasm]

So, solve u = 5ˣ + 2 for 5ˣ to see what to replace it with.

[warped sage]

I got lost lol
how do I solve u = 5^x +2 for 5^x

[oak chasm]

Do you know how to solve u = x + 2 for x?

[warped sage]

you mean x = u-2 ?

[oak chasm]

Right.

[warped sage]

oh I see

[oak chasm]

So, do the same sort of thing with u = 5ˣ + 2 for 5ˣ.

[warped sage]

u-2

[oak chasm]

Right, so replace 5ˣ with u - 2.

Then it's all u and no x.

[warped sage]

and do the integral of that ?

[oak chasm]

Yes.

[warped sage]

so it will become integral of

oh alright thank you

[oak chasm]

Right, and the 1/log(5) is a constant that can come out in front of the integral.

[ocean seal]

Chai T. Rex

[warped sage]

hmm I think I should separate the fractions right ?

[oak chasm]

Yes.

[warped sage]

it becomes easier

it looked easy but I don't know it just keeps involving more steps lol

[alpine sable]

hi

whats 1/sqrootX as not a fraction

[oak chasm]

@alpine sable Sorry, this channel is busy.

[alpine sable]

ok sorruy

[warped sage]

it will become integral of (1/2u - 1/2u-4 )?

I can take the 1/2 out

[oak chasm]

Almost.

[warped sage]

I hope I didn't mess up the sign

[oak chasm]

1/(2u) - 1/(2(u + 2))

When writing fractions in text chat, you should surround the top and bottom with parentheses unless they're a single number or single variable.

[warped sage]

will do

yeah I messed up the sign sorry

[oak chasm]

And you're right about taking out the 1/2.

[warped sage]

I am left with (1/(u)-1/(u+2))

one sec

is it ln(u) - ln( u+2) ?

multiplied by the things I left outside

the integral

and never forget +c ofcourse

[oak chasm]

Yes, that's right.

[ocean seal]

Chai T. Rex

[oak chasm]

Now you just need to convert u to x.

[warped sage]

ye

[oak chasm]

Oh, yeah.

[warped sage]

thank you a lot

[ocean seal]

Chai T. Rex

[oak chasm]

Don't forget the C.

You're welcome.

[warped sage]

yeah Never forget the C

or you lose half mark

[alpine sable]

What can multiply 431

?

[pastel schooner]

can someone help me understand and how to do this?

[rigid smelt]

can you find the derivative of h(x)?

[pastel schooner]

if x = -1 I could do -3/-3x^2

and find the derivative of -3/-3x^2

maybe.

-3 / (-6x) = h'(x)

which is 1/2x = h'(x)

or am I flat out wrong

[rigid smelt]

no, thats not really how it works

if you plug in -1, you are basically differentiating h(-1) which is, technically speaking, a completely different function

basically, here you just treat f(x) as a variable

but the catch is that f(x) is dependent on x

[brazen oak]

Im pretty sure you use the chain rule

[rigid smelt]

so as you are differentiating with respect to x, you also have to differentiate f(x)

which is f'(x)

[brazen oak]

wait sorry, need to rethink this

[pastel schooner]

so its f'(x) / (-6x)

= h'(x)

[rigid smelt]

you really need to be careful

the derivative of u/v is not u'/v'

[rigid smelt]

technically you're not wrong, thats also another way of saying it

anyway, mattnye, do you know how to differentiate a rational function?

[pastel schooner]

I do not I believe

[rigid smelt]

quotient rule?

[pastel schooner]

thats the only one I havnt studied

i know the others ones

[rigid smelt]

so you do know product rule?

[pastel schooner]

yes

[rigid smelt]

ok great

do you agree that h(x)= - f(x)/3 * x^(-2)?

[brazen oak]

wait,

if h(x) = f(x)/(-3x^2)

then,

(-3x^2)h(x) = f(x)

differentiate both sides, you only need to find it at -1

you already know h'(-1)

and you know h(-1) too

you can use the chain rule

[alpine sable]

If DEF x DEF = ABCDEF

And find each letter

[golden nymph]

So each letter is a digit?

[vale wigeon]

do different letters necessarily stand for the same digit?

there is a short (ish) solution that involves modular arithmetic

[golden nymph]

F can be 1, 5 or 6

[golden nymph]

Interesting

[vale wigeon]

if the answer to my clarifying question is yes, there is only one solution. if not, there are two.

[golden nymph]

Epic

Sooo what’s that method?

[vale wigeon]

okay i kind of lied about it involving modular arithmetic

let n = DEF, then n(n-1) must be divisible by 1000.

so either n or n-1 is a multiple of 125, and the other must then be a multiple of 8

[alpine sable]

nope

[golden nymph]

Nani?

[alpine sable]

different letter=different letter from another letter

if like yeah

a is 1 then 1x1

and b cant be 1

[tawny lantern]

Hi is anyone free to help me solve a question?

How do I prove this?

[oak chasm]

There are four solutions, one with unique digits.

[vale wigeon]

@tawny lantern channel busy please move

[vale wigeon]

four?!

[alpine sable]

poog

[oak chasm]

Yes.

[alpine sable]

so how?

[oak chasm]

Well, Ann showed the way.

f² ≡ f (mod 10)

f² - f is a multiple of 10

[alpine sable]

can this solution be a guesswork?

[oak chasm]

Find all the fs that work.

[alpine sable]

guess the numbers that can fit?

[oak chasm]

If you want to try all 1000 defs.

This is a shorter way.

[alpine sable]

hha yeah...

[oak chasm]

You then have the possibilities for fs. Then (10e + f)² - (10e + f) is a multiple of 100.

Find all e f pairs that work.

You then have the possibilities for efs. Then (100d + 10e + f)² - (100d + 10e + f) is a multiple of 1000.

Combine the ef pairs with all possibilities for d.

See which work.

[alpine sable]

alr

[oak chasm]

Then do def² for each to see what abcdef is.

You'll get four defs.

So, four abcdefs.

[alpine sable]

waiiiiit

and see which one fits?

[oak chasm]

Yes, like f² - f is a multiple of 10, right?

[alpine sable]

yes

[oak chasm]

So, 0² - 0 = 0. That's a multiple of 10, so f can be 0.

1¹ - 1 = 0. That's a multiple of 10, so f can be 1.

2² - 2 = 2. That's not a multiple of 10, so f can't be 2.

And so on.

[alpine sable]

wait

DEF works as 625

[vale wigeon]

chai, how exactly did you conclude there are 4 solutions?

[oak chasm]

Well, there are four solutions for f.

[alpine sable]

ohhhh

[oak chasm]

And then it turns out each of them has a solution for ef.

[alpine sable]

i picked one and tested it

[vale wigeon]

that isn't what you said at the start

[oak chasm]

And so on for def.

[vale wigeon]

is it?

can you show your 4 solutions under a spoiler tag

[alpine sable]

one of the 1s are 625

625 x 625?

think i got it

=390625?

DEF works perfectly

abc=390

[oak chasm]

||0,1,141376,390625||

[alpine sable]

def 625

[alpine sable]

niiiice

thanks chai and ann

im new here q-q

[oak chasm]

No problem.

[vale wigeon]

@oak chasm those first two are not six-digit numbers

[alpine sable]

yeah so it doesnt work right?

[vale wigeon]

exactly my point, but chai seems to insist it does

[oak chasm]

It depends on whether you consider it to be or not.

[vale wigeon]

those two violate the convention in cryptarithm problems that the leading digit of every number involved isn't zero

those are the grounds on which i am objecting

[oak chasm]

Ahh, OK.

[alpine sable]

smart vs smart?

haha

you 2 are smart tbh

thx

[tidal gust]

How do I prove that 3 back to back natural number's average is not a whole number

Here is what I have come up with

But it is not a proof IMO

[vale wigeon]

??

if you mean the average of a, a+1 and a+2, that's just a+1

which is a whole number always

did you mean the average of three consecutive perfect squares?

[tidal gust]

Yes my bad

[vale wigeon]

okay, so your work is fine (i hope)

[tidal gust]

Look at my picyure thats what I mean

[vale wigeon]

you can simplify (3a^2+6a+5)/3 into a^2 + 2a + 5/3

5/3 is not an integer while a^2 + 2a is

[tidal gust]

Aahh true thanks

[alpine sable]

How do I prove that a factorization of a polynomial is unique?

I've tried to prove by contradiction but can not find a way to solve with it

[golden nymph]

What do you mean by unique?

2x^2+14x+20
=2(x^2+7x+10)
=2(x+2)(x+5)
=(2x+4)(x+5)=(x+2)(2x+10)

Does the last two expressions act as the same thing in your argument?

I gave an example

[alpine sable]

ummm... I think no

[golden nymph]

Hmm

Can you use the factor theorem?

[alpine sable]

I will consider 2(x+2)(x+5) as the final step

[golden nymph]

I see

[alpine sable]

I mean p(x)=c_1*(x+k_1)(x+k_2)...(x+k_n)=c_2(x+q_1)(x+q_2)...(x+q_n) iff q_i=k_i for all i and c_1=c_2

[golden nymph]

I seee

I don’t know much about proofs but I am trying to help

Does this statement say anything about if q_1 and q_2 for example swithced places?

Like k_1=q_2 and k_2=q_1

[alpine sable]

Yes, I think it's already well ordered

[golden nymph]

Does this help in some way?

[sacred sapphire]

you could represent 3 consecutive squares alo by (x-1)^2 +x^2 +(x+1)^2

it cancels things out faster

[alpine sable]

let me check

Whats the point of the C matrix?

it doesnt seem to be used at all?

[golden nymph]

Send somewhere else please this one’s occupied

[alpine sable]

ok

[golden nymph]

Guys cmon

[alpine sable]

I don't think so becuz q and k is not restrict to integer

[golden nymph]

Lol idk what factor theorem has to do with integers

All I know it means that roots tell us factors

[alpine sable]

I mean I don't have r(x) in my representation of p(x)

[golden nymph]

What I mean is that I don’t think the only if is appropriate as they can switch positions and they would still be equal

[alpine sable]

i see

[golden nymph]

Lol what’s r(x)

I hope I am helping in some way

[alpine sable]

remainder

[golden nymph]

Umm

What I mean is can you somehow get from the point that the roots of the polynomials don’t magically change so it would imply the same thing for the factors?

Idk I think a more advanced person could help I guess that’s all I can suggest

[alpine sable]

How about I order in a form that q_1<=q_2<=...q_n and so do k

[golden nymph]

Yeah I guess that’s good

[alpine sable]

ummm... if the case that p(x)=0 imply x=-k_i for some i, becuz p(x) also equal to c2(x+q1)(x+q2).... ,then there exist (q_n-k_i)=0 for some n

thus q_n=k_i

and since the order we just construct before, we can show that k_i =q_i for all i ?

[golden nymph]

Idk from where your q appears in this argument but I think this just became more advanced from me to comprehend

Where are the advanced people in this channel?!!!!!

[alpine sable]

I guess that is my answer and the case is closed

I think this channel is free to use now

[golden nymph]

Yaaay

[stark trail]

yay

[quick echo]

my physics teacher is so bad at teaching, can someone just tell me which formula to use for this question?

[fervent anchor]

Who ping me 5 times?🤨

[shell widget]

@quick echo The linear speed here is the tangential velocity and the formula that relates the centripetal acceleration to tangential velocity is a_c = v^2 / r, where v is our tangential velocity.

Since our tangential velocity at the start is v_i, lets name the corresponding centripetal acceleration a_ci = (v_i)^2 / r

The new tangential velocity is (v_i)/4, and so the new corresponding centripetal accelration is A_c = [(v_i)/4]^2 / r = (v_i)^2 / 16r

But we also know that a_ci = (v_i)^2 / r, so we plug that in our new acceleration, and we get A_c = a_ci / 16

So the new centripetal acceleration is 1/16th of the previous centripetal acceleration.

I did it for u so that u could understand and hopefully try any other questions like these urself.

[quick echo]

its fine im generally good at math

[shell widget]

nice

[quick echo]

thnx btw

[shell widget]

np

[alpine sable]

hello

i have a stupid question.....

i got a geometric sequence of (1\2)(5/6)^2n-2

i am just trying to get it down to (5/6)^2n so that i can a sum

when i break down that exponet, how is it supposed to look? im very bad at this honestly

is it (5/6)^-2 and (5/6)^2n?

[shell widget]

Yes

[alpine sable]

okay, what do i do with the (5/6)^-2 then

do i multiply that by the (1/6)

because im trying to get the odd probabilities of this pmf

or would the exponet be positive here?

for the one thats being removed away

my teachers ones looks likes 7s

just letting you know lol

i just dont understand how the exponet that is being broken off is not negative

but positive there

if anyone could help me that would be great for some closure lmao

hi lads, im taking math lessons overseas in turkey and unfortunately nobody in my class is speaking turkish, if someone could kindly explain this bit to me would be very appericiated

[lunar vigil]

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