help-0

[alpine sable]

There is always parenthesis, we just leave them out for better readability

[whole herald]

^

[alpine sable]

2+2+3 means (2+2)+3 but this is equal to 2+(2+3) so it doesn't matter

[sinful relic]

what i mean is you donwrite (a) + (b) - (c) + (c) * (100)

t dont

you only add parenthesis

when you need them

but you are saying there is always a parenthesis around a number

[whole herald]

not around a number

[alpine sable]

They are always there, you just leave them out sometimes when there is no chance of confusion

[sinful relic]

so 6 is always (6) you just dont write the parenthesis

[whole herald]

basically

[alpine sable]

Yes you can view it like that

[unreal pier]

anyone can help

[whole herald]

don't overpost

[unreal pier]

ok

[oak chasm]

@unreal pier Please read the rules and tips for getting help in #❓how-to-get-help.

[alpine sable]

The "+" thing takes two values, one on the left and one on the right.
So 2+3+4 wouldn't really make sense if we don't agree that this means (2+3)+4
I.e. (2+3) is on the left and 4 is on the right

[sinful relic]

wdym not around a number?

[native knot]

I am doing homework rn

why is the second option not correct

[sinful relic]

i just need to know if there is always a parenthesis around a number, sometimes u just dont write em

[native knot]

"For every real number x , there is an real number y such that y is less than or equal to x ."

[alpine sable]

Yes. You can think of it like that. You just don't write them when the expression doesn't give rise to confusion and you know exactly where you'd put them.

That's actually a good assumption

[alpine sable]

Because you cannot just swap x and y. For example the given statement isn't true, however for every real x there is actually a y less than it, i.e. y=x-1 so the second statement is true

[native knot]

well my instructor made it so "For every real number x , there is an real number y such that y is less than or equal to x ." is considered wrong? @alpine sable

[whole herald]

the last sentence: "this can be done no matter what y is" is wrong

only when y is negative

y = -2

-2 -1 < -2
-3 < -2

correct

[alpine sable]

What I tried to illustrate here is that the statement ∃y ∀x x ≥ y is not equivalent to ∀x ∃y x ≥ y because one is false and one is true. In general you cannot swap ∀ and ∃

[whole herald]

or am I understanding it wrong

probably

[oak chasm]

No, it's correct.

[whole herald]

yeah yeah

[oak chasm]

If y is 100, then x = 99 will work.

[alpine sable]

?

Can someone help me for this question.

A quadratic polynomial when divided by (x+2) leaves a remainder 1, and when divided by (x−1), leaves a remainder 4. What will be the remainder if it is divided by (x+2)(x−1)?

[native knot]

so then only the last two are right

for example here

why can the first option not work

[sinful relic]

@whole herald but why'd u say not around a number

[native knot]

because no matter what x is chosen there always something larger no?

[alpine sable]

If they mean "expression for the statement" as in "equivalent statement" then yes

[whole herald]

Because when you multiply both sides by two, the parenthesis is around all numbers

a + b + c = d
2(a + b + c) = 2d

not a number

[alpine sable]

Although assuming the real number axioms, all false statements are equivalent so

[crystal ivy]

someone talks spanish?

please

[native knot]

okay

[alpine sable]

You can translate "no matter which element is chosen in S" as ∀x ∈ S and "you can find another element" as ∃y ∈ S. [Although I'd have to point out that they should probably have said "in S"]

[sinful relic]

@whole herald but you only add the parenthesis to it when it's necessary?

[magic viper]

when working with "linear functions" what does this mean? ("
f(3)=11 and f(-2)=23,5")

[sinful relic]

that when x is 3 the value is 11

[magic viper]

ok thanks

[loud sentinel]

hey guys I have a question about this… see when I enter the value on the left on my calculator my answer differed from the answer in the mark scheme// the working on the right is the work scheme… but I wonder does rationalizing or not raitionalizing the denominator makes a difference

Cause I get diff values

[alpine sable]

Such a linear function does not exist unless linear means affine

[loud sentinel]

Idk I could be dumb

[gentle flame]

In US high schools, linear means affine

[sinful relic]

@whole herald do u only write the parenthesis there when it's necessary

for example when u had to multiply by 2 u added the parenthesis instead of it being invinsible

[native knot]

would this be correct @alpine sable

[alpine sable]

No

[native knot]

which one is incorrect?

[alpine sable]

All of the ones that don't have a checkmark

Except the last

[native knot]

how is n element of natruals a statement

[alpine sable]

n ∈ ℕ is stating that n is a natural number

[sinful relic]

@magic viper dansker?

[native knot]

but there is no true or false to that?

[alpine sable]

Does your class have a definition of the word "statement" that deviates from the usual use in english?

[magic viper]

ja lol

[zealous spire]

LOL

[alpine sable]

Well either n is a natural number or not, depending on n

[sinful relic]

lol, arbejder I med lineære funktioner?

[native knot]

but n is not given

[magic viper]

?🤨

[magic viper]

jep 1.g

[alpine sable]

Does "statement" mean "formula without free variable"?

[sinful relic]

nice

det nemt nok

[magic viper]

var syg da de begyndte på det der var basic så fattede det ikke

[alpine sable]

I.e. this

[sinful relic]

det matematik i den her server er nok lidt mere kompliceret

[sinful relic]

rip

[magic viper]

hvad går du på?

[sinful relic]

er næsten lige blevet færdig med niende

[magic viper]

så du er også 1.g'er?

[sinful relic]

ja

[magic viper]

hh?

[sinful relic]

men en lineær funktion er bare af typen $f(x)=a\cdot{x}+b$

[ocean seal]

Lil Sachi

[sinful relic]

hh?

[magic viper]

jaer præcis

sender lige opgaven 2 sek

[sinful relic]

K

jeg kan finde ud af matematik helt op til slutningen af 2g kek

[magic viper]

Bestem forskriften for den lineære funktion
f(x)
i hvert af nedenstående tilfælde, når:
f(3)=11

[sinful relic]

er der ikke mere?

[magic viper]

jo men det er bare en af dem

[sinful relic]

send billed

[magic viper]

den jeg har problemer med

[sinful relic]

af opgaven

tror der er mere

[magic viper]

ok

[sinful relic]

11 = a * 3 + b

ngl det spørgsmål er lidt mærkeligt da en lineær funktion ikke er f(x) men f(x) = ax + b eller y = ax + b

[magic viper]

PRÆCIS

jeg tænkte præcis det samme

[alpine sable]

What language are you guys using?

[sinful relic]

når du har indsat 3 på x's plads så har du 11 i værdi så jeg tænkte 11 = 3a + b

men ved ikke om det er rigtigt

[sinful relic]

danish

[magic viper]

det giver mening

for man skal jo bestemme forskriften

[sinful relic]

$\textcolor{green}{11}=\textcolor{blue}{a}\cdot\textcolor{purple}{3}+\textcolor{magenta}{b}$

[ocean seal]

Lil Sachi

[magic viper]

er du stx'er hhx'er eller htx'er?

[sinful relic]

htx

dig?

[magic viper]

jeg fandt frem til at det giver 11=10*8+0,2

[sinful relic]

yes, that's what i wrote

[sinful relic]

uhm

hvor får du $10\cdot{8}+0.2$ fra

[ocean seal]

Lil Sachi

[sinful relic]

0.2 er b værdien, den er ikke givet i det spørgsmål

[magic viper]

11=10,8+0,2

skrev forkert

[sinful relic]

nej

[alpine sable]

(3p - 4)(2p2 + 4p -5)

can someone explain this to me? 2 = squared/cubed

[sinful relic]

$(3p - 4)(2p^2 + 4p - 5)$

[ocean seal]

Lil Sachi

[sinful relic]

distribute the terms

[alpine sable]

idk how to

[magic viper]

btw htx her

[sinful relic]

nice

[alpine sable]

idfk how i got in higher level in the first place 🤷‍♂️

[magic viper]

tror du at de 2 opgaver i a hører sammen

[sinful relic]

3p * 2p^2

[magic viper]

eller har min lærer bare været mærkelig

[sinful relic]

nej, det er to forskellige forskrifter

[magic viper]

ok

tak

[alpine sable]

log((10^(x*log(a)))) = x*log(a) why does the 10 disappear?

oh im starting to understand it now. i thought log was opposite i think. if something is inside log, it makes it smaller the larger the number is right?

aah yea of course, thanks a lot. i feel stupid now haha

but square root is the inverse of a power too right?

yes ok. but so basicly what log((10^(xlog(a)))). is. is just, the inverse power of 10 to the power of xinverse of a. - that makes sense

so if you have 10 to the power of something. and put it inside a log. it will just cancel the it out. makes sense now. thanks agian

[rigid palm]

Whats the source of this?

(very mathematical question, I know)

[native tartan]

what does the de morgan's law of sets state?

can anyone elaborate it

[oak chasm]

Do you know DeMorgan's laws in other contexts?

(A ⋃ B)' = A' ⋂ B'
(A ⋂ B)' = A' ⋃ B'

[native tartan]

yeah but i want to know what exactly it states

[oak chasm]

It states that if you complement a union or intersection, you change the operation to the other one and complement the two sets.

[native tartan]

okay got it

[keen salmon]

Can someone help me define this set recursively or find the pattern

this is so hard

I have been looking at those numbers for an hour

yeah

It is on my ps

and it requires us to find a recursive set for i

(it doesn't ask whether there is one or not)

yeah, like I can't even see how this can be constructed like a string

[cerulean olive]

im a bit confused

do i cross multiply

and then divide?

oh

[keen salmon]

@alpine sable like the other once are easy, just this one

[safe stone]

(c) might be like (d) if you convert to binary

[keen salmon]

@safe stone wdym

[safe stone]

1, 2, 5, 7, 10, ... -> 1, 10, 101, 111, 1010,

something like that

[keen salmon]

@safe stone that's might work

so this is the binary list

I am confused if he is adding numbers to each other

wait I have some errors in my converting

This is the true list

[safe stone]

hm the first one is correct actually

1001 seems to be odd

a stretch but it could be all binaries number that has the number of 1 >= half the length of the number

actually no because then 1001 should be there too

i think you just missed 111 in the original list

[keen salmon]

Now I am sure

this is the one, I checked google

still see no pattern lool

[alpine sable]

the pattern is 1 😏

dunno

im bad at math

[keen salmon]

no, adding 1 doesn't give us all numbers

[alpine sable]

i know

well i think

cause i havent learnt this in school

[oak chasm]

The last two numbers are the same there.

ghci> map bin [1,2,5,7,10,12,25,27][1,10,101,111,1010,1100,11001,11011]```

[keen salmon]

I wrote them wrong

but I still can't see the pattern for the numbers before

I give up guys

let him just give me wrong on this one

no pattern at all

If there is a typo I leave uni, and go open a supermarket

never squeezed my brain so hard

I mean staying up is not enough for this

maybe we should convert the numbers to hexadecimal lol

if not we try all the notation from 2 to 100

[oak chasm]

@keen salmon Well, one possibility is natural numbers that are coprime to 5354228880.

[keen salmon]

idk what you mean

[oak chasm]

Never mind, it's not right.

[winter rock]

@alpine sable bro could u help me

[keen salmon]

@alpine sable just forget it

I will ask the other students, and I will ask if the numbers are written wrong

[winter rock]

@alpine sable

Thx

Wait

I draw

[keen salmon]

I don't get what you mean here

[winter rock]

The question is to find AB × AC wich are 2 vectors

The thing in yellow is the answer btw

But I don't know how we should know that BAC = 45

The angle BAC I mean ofc

And how AC = 4sqrt2

I don't understand

Each angle of this should be 90 right

So BAC

Should be cos(90)

Wich is zero

No?

Look

The answer is BAC=cos(45)

But I don't know how to find this answer

And the question is to find AB × AC knowing that ABCD with center O is a carré(the thing I draw) where AB=4

[daring roost]

could someone help me with the proof?

ab and eb are just that

[surreal tinsel]

can i get some help please?

can the question be in another language if im able to translate it into english?

[daring roost]

A is square root of b-a

pythagoras

you square root it

how do they work

i havent learnt it

[ivory gulch]

could someone help with this problem?

so what im thinking so far is if the tangent line is perp. to x-3y=1 [or y=(1/3)x-1/3], than it must have the same slope of 1/3. So y'=3x^2 -6x = 1/3.

[alpine sable]

Its perpendicular nit parallel

[ivory gulch]

oh

dumb

am

lol

[alpine sable]

So slope of tangent is -3

[ivory gulch]

is that a rule

like slope of a perp line is opposite

wait

no

[alpine sable]

Yes ^

[ivory gulch]

god i promise im not as stupid as i sound

?

bruh

i have no idea what you're asking me rn

im taking calc 1 at university

ok so x=1

plug into orig equation? or derivative

its all good

so ok x=1, now what

no

idk

wait yeah no

i didnt

$x^3-3x^2+4$

[ocean seal]

ski

[ivory gulch]

well of the perp line yes

so 3x^2-6x = -3

oh

wait

yeah no i did that right correct?

not sure how to do that

oh u just set the two expressions equal to each other

to find point of intersection

[alpine sable]

Uhh no need to do that just put x= 1 in y=x³-3x²+4 and you got (a,b) = (1, y)

[ivory gulch]

well i got x=1 by setting y' = -3

was i supposed to do tha

[alpine sable]

Yes now put x= 1 in original equation to get y co-ordinate

[ivory gulch]

ok

y-1

(1,1)

no

it doesnt

[alpine sable]

y= 2

[ivory gulch]

lol

forgot the x^3

so (1,2) is final answer

[alpine sable]

Yes

[ivory gulch]

que?

ok

so

please excuse bad handwriting but does this look right?

[alpine sable]

Yes

You can also solve it by splitting numerator

[ivory gulch]

nice

...

ill just stick w monkey brain way bc that's what ive been taught lmao

[alpine sable]

$\frac 12(x² - Ax^{-1})$

[ocean seal]

Spica

[ivory gulch]

ok so im done with hw, and i understand most of it but there's still one i don't get 100%

$\lim _{x\to :4^-}\left(cx^2-b\right),:\lim _{x\to 4^+}\left(-2\sqrt{x}+c\right)$

[ocean seal]

ski

[ivory gulch]

so i set those two values equal bc its differentiable

$cx^2-b=-2\sqrt{x}+c$

[ocean seal]

ski

[ivory gulch]

now derivative of both sides (because i can i guess??)

$2cx=\frac{-1}{\sqrt{x}}$

[ocean seal]

ski

[ivory gulch]

now plug in 4, 8c=-1/2

divide by 8, c=-1/16

now plug c in

$-1/16x^2-b=-2\sqrt{x}-1/16$

[ocean seal]

ski

[ivory gulch]

4 for x

$-1/16\left(16\right)-b=-2\sqrt{4}-1/16$

[ocean seal]

ski

[ivory gulch]

and i get c= -1/16, b=49/16. this alright?

[alpine sable]

This both equal and
$$\lim_{x\to 4^{+}} f'(x) = \lim_{x\to 4^{-}} f'(x)$$

[ocean seal]

Spica

[alpine sable]

So you'll get 2nd equation from this

In terms of b,c

[ivory gulch]

yeah but

that proves continuity

not differentiable right?

[alpine sable]

First one proves continuity 2nd one proves differentiability

[ivory gulch]

so take derivative of both sides

and solve for c

then when i plug c back in, do i plug into this? $cx^2-b=-2\sqrt{x}+c$ or this $2cx=\frac{-1}{\sqrt{x}}$

[ocean seal]

ski

[ivory gulch]

would have to be first one bc theres no b value in second

and it doesnt really matter right bc they're equal anyway

[alpine sable]

$$\lim_{x\to 4^-}\qty(cx^2-b) = \lim_{x\to 4^+}\qty(-2\sqrt{x}+c)$$
$$16c-b = -4+c \dots (1)$$
$$\lim_{x\to 4^-} 2cx = \lim_{x\to 4^+}\qty(\frac{-1}{\sqrt{x}})$$
$$4c = \frac{-1}{2} \dots (2)$$

[ocean seal]

Spica

[alpine sable]

Solve (1) and (2)

That's what I'm saying

@ivory gulch

[ivory gulch]

ok one sec

sorry was grabbing mail lol

[light sleet]

i completely forgot how to do this arithmatic

[ivory gulch]

triangles must equal 180 degrees, and channel is occupied

[light sleet]

can someone help me through it?

[light sleet]

oh uh ok and sorry

[ivory gulch]

no problem

: )

[light sleet]

:D

[ivory gulch]

ok so 2 is -1/4?

[alpine sable]

?

Um is this channel busy?

[ivory gulch]

lyes

[ivory gulch]

like (2) is -1/4

?

[alpine sable]

From (2)
c = -1/8 then put c in (1) to get b

Ohh wait c = -1/16 I forgot its 2cx not cx

[daring roost]

can i get help?

[ivory gulch]

feel free

[daring roost]

second q?

need help

[ivory gulch]

i thought u said give help lol my bad

check the other question channels for an unoccupied one

or me and spica are ab done here could wait until then

so i got the same thing i had before. c=-1/16, b=49/16

[alpine sable]

Yes

[velvet merlin]

Number 10

Help

(9th grade)

It’s explicit rule btw

[daring roost]

i was meant to go before btw

[daring roost]

root 12

[velvet merlin]

that’s the answer?

thx

[daring roost]

i think

n is the term in the sequence

10 +2

square root it

[velvet merlin]

no

You have to plug in

The term

wait

hold up

[daring roost]

it said 10 is the term

[velvet merlin]

oh yeah

[daring roost]

@ivory gulch are you free

[velvet merlin]

nvm teacher posted a video he said I’m supposed to put the 10

Where it says n

[daring roost]

thats literally what i said

n+2

[velvet merlin]

That’s what he did the term was 20

WaitpOh

[daring roost]

square root

[velvet merlin]

LOOOL

MB

@daring roost alright one mode

More

[daring roost]

ok

tell me

[tropic sail]

sin(x) + sin((10.0 / 3.0) * x)

im want to scale this function uniformly by 50% but I have no idea how I would do it

each attempt i do leads in it loosing its form or being to squished or squashed

does anyone know how scaling this would be done?

[pale monolith]

Hi guys anyone knows how this number happened as the answer

But the answer is 100g the correct answer

[magic root]

How do I solve this :|?

oh

grade 9

I just want to know in what order you do that

like how would you guys solve it.

I downloaded that thinking it was the awnser to my question 😐

I swear.. everyone in this chat rn is on drugs or something

what no lol

[stuck jolt]

No

[astral dagger]

[stuck jolt]

Ffs

[restive tulip]

Aa

[dusk canyon]

[rare temple]

[tame falcon]

Ugh

[astral dagger]

[jade canyon]

？wtf

[peak geyser]

yo wtf

[stuck jolt]

I dislike the guys who do this

[peak geyser]

entitled shits

[restive tulip]

[tame falcon]

Apologies for the ping everyone, a user just started mass role pinging. They've been banned.

[warm brook]

so funny

[sharp arrow]

and i was excited about a new talk

[unborn seal]

who is the one I'm going to kill

[unborn tapir]

Ok.

[stuck jolt]

Lads, everyone relaxxxxxxx

[astral dagger]

[stuck jolt]

It is what the person wanted

[jade canyon]

owo

[stuck jolt]

Let’s not let him get his wish

[astral dagger]

https://tenor.com/view/shooting-the-office-gun-michael-scott-gif-5266899

[lilac dragon]

I have a suggestion. how about only those with the advanced role be able to ping the advanced helpers? if that's possible

[night geyser]

it's not.

[lilac dragon]

ah. that sucks

[night geyser]

discord ping perms are really limited

[stuck jolt]

What a great idea

[astral dagger]

it is possible to only be able to ping on the respective channel?

[night geyser]

also not.

here are all the controls we have over pings:

[sly mantle]

a role is either pingable everywhere or nowhere

[night geyser]

• what roles can ping everyone/here?
• what roles can be pinged by everyone?

thats it

[stuck jolt]

60 seconds to write a message, oof

[night geyser]

there are workarounds using a bot for this

thats what we do with talks

but honestly the advanced helper roles are probably gonna be overhauled soon anyway

sooo

who slowmoded tf

[lilac dragon]

how/why so?

[vale ginkgo]

[night geyser]

theyre not really used for their intended purpose atm

might just end up deleting them

[wispy olive]

The question is how do you have Honorable role with only about 2793 messages.

[night geyser]

why do you care so much

[unborn seal]

I was very active on short period

[night geyser]

man this is why i want to decolour roles

[unborn seal]

and no it is not a lot

[night geyser]

people start using them as status symbols or some shit

[unborn seal]

It has no sense

I agree with Namington

[wispy olive]

I was just asking.

[fading scroll]

Ping?

[wispy olive]

Welp.

[west vine]

[alpine sable]

Need some help on this a bit clueless

[wispy olive]

Well then I will stop doing that, is that fine?

[winter rock]

Hey,

I got an question

Here in my theory

In the third point

It says AB × AC = 1/2 (AB² - AC² - BC²)

But here in the correction of an ex I did

It's typen that AB × AC = (AB² + AC² - BC²)

Could anyone help me and tell me why did we changed?

Here's the correction btw

[rustic rock]

is that high school

[alpine sable]

How do i solve this problem? If there is two r values, is this still simultanous equations?

[hushed acorn]

how is the answer root(5) for the adjacent side?

i keep on getting root(1) when i use the Pythagorean theorem to solve for the adjacent side

[winter rock]

@rustic rock yh it's highscool

[pallid sail]

@hushed acorn this is incorrect

u mean something like photo math?

[tropic sail]

So i want this to be scaled so the maxima is 50% higher. And when I squish and squashed it, it lost its shape

The function?

[hushed acorn]

ah so i'm not going insane?

[viscid quiver]

would anyone mind helping me with some basic geometry

I'm not really understanding it

[tacit mesa]

ok

send it

[broken halo]

no

sry

cant cheat

i dont make the rules

[viscid quiver]

let me send a screenshot

@tacit mesa it's about perpendicular bisectors

[tacit mesa]

u sure this is basic geometry man

u taking ap or something?

just send it anyways

[hushed acorn]

send the screenshot here

[broken halo]

ap college math geoligmathics class

[tacit mesa]

wait what do u need help with??

[hushed acorn]

nah bisectors is basic geometry

i learned that in 8th grade

[broken halo]

dam

[tacit mesa]

finding the perpendicular bisector?

[broken halo]

im 80 dont remember 8th grade

[hushed acorn]

ye

[tacit mesa]

oh then ez

[broken halo]

also have oldtimers that might be a reason

[viscid quiver]

yeah this might be really basic for yall

just need some help with it

[broken halo]

i think

u just make a cross

with the ab

just add perpendick line

[viscid quiver]

okay let me try it myself first

[tacit mesa]

ok what r u confused abt tho

open the compass half of the way to a and b

[hushed acorn]

a bisector, by definition, is a division of two parts. perpendicular is essentially what the roads at an intersection look like (90 degrees from origin)

[viscid quiver]

hmm okay

so would this be a way to construct a perpendicular bisector of AB?

the line might not be perfectly 90 degrees, which is why geogebra is saying it's wrong probably

[tacit mesa]

ok

well

u have cd right there

[broken halo]

^ shes not know

[viscid quiver]

okay

[tacit mesa]

draw the line between c and d

[viscid quiver]

so I have cd already, and I used the compass tool to make two circles from cd, and found the intersecting point

[broken halo]

"what is he saying" -kami

[viscid quiver]

and a line through those points should give me the perpendicular bisector right?

[broken halo]

dont listen

pls

[tacit mesa]

yes

cd is the perpendicular bisector of the line segment

a and b

[inner lantern]

busy?

[viscid quiver]

but how is cd the perpendicular bisector

how do you know that?

[broken halo]

she doesnt

[tacit mesa]

where cd um intersects ? that’s ab e

Uh because

It tells you

?

[viscid quiver]

hmm okay

[tacit mesa]

i’m on my phone so it doesn’t rly align perfectly

[viscid quiver]

oh yeah, it says you can use CD or EF which implies that they are perpendicular bisectors of AB

is that correct?

[tacit mesa]

i mean that’s what i just explained

c and d are the perpendicular bisectors of ab

[viscid quiver]

okay

but why doesn't this work still

that should be the perpendicular bisector

[tacit mesa]

umm idk what ur doing here idk what this is, like as in what you’re working in

does that make sense?

[broken halo]

its

[tacit mesa]

Try using a different tool?

[broken halo]

GeoGebra

[viscid quiver]

I'm working in geogebra

geogebra requires you to be really precise, so that might be the problem?

[tacit mesa]

Perhaps

[viscid quiver]

I have a few more questions, and I should be fine

I don't really understand what it means by "construct a regular hexagon with line segment AB as one of its six sides"

[tacit mesa]

it’s -5

[viscid quiver]

@tacit mesa I think that's the big problem I have right now

[tacit mesa]

do u not understand how?

Like how to find these things?

[viscid quiver]

yeah

yeah

I'm just confused on that

I don't know why, maybe it's because I have apathy for math?

I don't understand how other people can do this fine, but I just can't

even if I rack my brain

yeah I just don't really understand how to find the hexagon from that

[tacit mesa]

ngl idek what a hexagon looks like

[viscid quiver]

seriously?

damn

[tacit mesa]

LOL

[viscid quiver]

lmao

I just kinda need some help with this

since math really stresses me out in school

as it's somehow the one subject I am trash at

and because of how bad I am at it, I am slowly growing a hatred for it which probably isn't that good

could anyone help me out?

[alpine sable]

Just search for a graph plotter

[broken halo]

pls hlp

[raw geyser]

bruh

ok did you try it yet?

[alpine sable]

16

[broken halo]

good u know

[alpine sable]

Just pick the third checkbox

[viscid quiver]

this was a classwork, when the teacher was online, and obviously now he's not lmao

[alpine sable]

Maybe

[alpine sable]

You should've been attending to your class

Then ask

[broken halo]

whats the Euler-Mascheroni's constant

[alpine sable]

It's a constant related to the gamma function, that's why it's represented as $\gamma$ , it's also the limit between the natural logarithm and the harmonic series, you could also just google it

[broken halo]

ye but was in ur about me so assumed u knew

wat is gamma function

[alpine sable]

The gamma(n) = factorial (n - 1)

[ocean seal]

BeyondTheInfinity

[magic geyser]

who the heck keeps ghost pinging me

[zealous spire]

PEMDAS

[tepid jungle]

What does the O mean here?

[noble goblet]

how would i do #17

[glass lichen]

google Big O notation

[tepid jungle]

@noble goblet differentiate

find the slope at a

[noble goblet]

im still confused iendekdkkw

[tepid jungle]

and then use the equation of a straight line with your slope and point

[glass lichen]

basically you truncate the taylor at n and everything else is larger than stuff on the order (y-x)^(n+1), so the truncated terms are O((y-x)^(n+1))

[tepid jungle]

f(x)=x^n, then f'(x)=nx^(n-1)

@glass lichen so rather than writing out the truncated terms, you just write O((y-x)^(n+1))?

[broken halo]

do u know how PEMDAS actually works tho?

[alpine sable]

What do you not understand?

[tepid jungle]

@noble goblet you just drop the power of the x and subtract 1 from it, and constant terms are equal to 0

Just look up differentiation

[glass lichen]

https://en.wikipedia.org/wiki/Big_O_notation

[broken halo]

know fully

[glass lichen]

like for example $e^x=\sum_{i=0}^\infty\frac{x^i}{i!}=1+x+O(x^2)$

[ocean seal]

Mosh

[tepid jungle]

Ya, reading it now

[glass lichen]

where I truncated at the linear term

so as x tends to 0, e^x is "asymptotically equivalent" to 1+x

[tepid jungle]

can i just ask 1 more question of you fam

I am just high on mdma at the moment and trying to figure this question I have to do but I can't see properly

So this is basically asking

find a p such that all this stuff on the left is less than or equal to the truncated stuff of h^P

@glass lichen don't tell me the answer because it's a quiz question, but the direction

[glass lichen]

Yeah.. no clue lol

[tepid jungle]

it's a numerical mathematics class

approximation of differentiation

fuarkkkkk

[glass lichen]

yeah I only know big O for doing physics approximations

[tepid jungle]

I took some md to do a bit of partying with my girl but then I realised I have this quiz due

bruhjhhhh

you study physics????

[fiery adder]

im having some trouble with this question - im trying to approach is as P(person 1 doesn't draw their own name or person 2's name) times P(person 2 draws their own name) but idk how to calculate the second one of those

i think the first one is (n-2)/n

but i dont think 1/(n-2) is enough for the second probability

also because this having probability 1/n doesnt make sense

[tepid jungle]

@fiery adder why n-2/n for the first person

why not 1/n for the first person

[fiery adder]

why would it be 1/n

n-2/n is prob you pick a name other than your own and other than person 2's

[tepid jungle]

if you have 5 people

there is a 1/5 chance the first person picks their name

[alpine sable]

Who pinged

[fiery adder]

P(person 1 doesnt draw their own name or person 2's name)

[tepid jungle]

oh I thought you meant what I was referring to

just brute force 4 names

sorry I am not of help at this moment

i think with 4

3/4 chance they don't pick 2

for the first person

so there's a 1/4 chance the first person

's name is picked

lket me rephrase

@fiery adder there is a 1/4 chance the 2nd person's name is picked by person 1

so the Pr of never stopping = 1/4 + STUFF

then

there is a 3/4 chance

of person 1 picking anything other than person 2

therefore

[dusty willow]

And this is why nobody uses that symbol anymore

[tepid jungle]

1/3 of person 2 picking their own name

if 3 are left

[broken halo]

which symbol

[dusty willow]

The division symbol

It's unclear if this is 8/(2*(2+2)) or 8/2 * (2+2)

[solar notch]

guys am I doing a stupid by taking Calc 3 AND Diff Eq. at same time?

[dusty willow]

One gives 1 and the other gives 16

[dusty willow]

Nah

[tepid jungle]

@fiery adder therefore, the Pr of finishing at 2 is Pr=1/4 + (3/4)*(1/3)

[solar notch]

cause rn my C3 is great but im totally lost in Diff. Eq.

[dusty willow]

What's the probability that I'm going to fail this semester?

[tepid jungle]

@fiery adder therefore, the probability of finishing after 2, is the complement of that

@fiery adder therefore, the probability of finishing AFTER 2 is Pr = 1 - [1/n + (n-1/n)*(1/n-1)]

[alpine sable]

The obilus?

[dusty willow]

Is that what it's called?

[alpine sable]

Yeah

And the "/" is called a solidus

[dusty willow]

Okay. Cool.

[alpine sable]

From memory the obilus only divides the succeeding term, while the solidus is enacted on all following terms

[wary stream]

Even if that's true, it's still good to use parentheses with the solidus because of order of operations.

1/n+1 vs 1/(n+1) are technically two different statements

[alpine sable]

help I am stuck

I don’t understand how am I supposed to proceed

I don’t see any paths, it’s like guessing, how am I even supposed to find an answer

hi super basic question but what does x <<< 0 mean

i cant find anything on this

[fiery adder]

context?

[alpine sable]

one sec

[glass lichen]

x much less than 0

[alpine sable]

"what do the uncertainties reduce to if the uncertainty in $x$ (i.e., $\delta x$) is very small (i.e., $\delta x \lll 1$)?"

[ocean seal]

rеd

[alpine sable]

and then there's a few equations i've been evaluating for uncertainties

[glass lichen]

like it literally means much much much less than 1

[alpine sable]

oh so x is much less than 1

oh lovely

can i just say it's approaching 0

and calculate as though it was 0

[glass lichen]

nuiance says no

cause "being less than 1" and "approaching 0" are technically different

example .1

.1 isnt approaching anything, but we can pretty much say it's <<1

[alpine sable]

gotcha

dang that's going to be annoying but this makes sense thank you

[languid shale]

Can someone please help me with this question

[glass lichen]

maybe in the exact context you can just say tends to 0, but id say verify with your prof

[alpine sable]

gotcha

yeah it's just a lot of expressions

so saying that it basically = 0 just makes it a lot more cohesive

i'm 90% sure that's what the prof was going for but i'll double check

[red carbon]

Whoever keeps calling, please stop

[alpine sable]

I know this is a math server, but can anybody help me with this quick computer science question?

[buoyant kayak]

don't ask just send

[alpine sable]

Its fairly simple

Ok

I didnt know if it was considered math

How would an ipad process data

[steady saffron]

just do the basic operations so x is on one side of the equation. then its solved

[languid shale]

k

[twin crystal]

hi can someone explain how do i say this

[left citrus]

Post the question no need to ask

[twin crystal]

i want convert ms to ns

how would i say it in english languae

how many nanosecon are in one 1 milli second

[left citrus]

Milli to nano

[twin crystal]

but isnt like 1 millon ms per ns

so there is 1 million ms per every ns

yeah but im trying to understand in terms of prefixs and to derive it myself

[wispy sorrel]

how in the world do you find a quartic function for 3 given (x, y) points (just those points are given)?

[twin crystal]

yes but from the pic i posted

how can you explain it

to be the answer from your point of view

because it is correct

there are 1 million ns in in 1 ms

1000

ms

milli is 10^-2

3

yes

yes

1 billion

10^-9

ok i see

there are many ns in 1 second because ns is smaller

1000

if i divide 10^-3 / 10^-9

this is 10 ^6 right

i think i just want to focus on the pic i posteds it is too much numbers and to keep track of

10^-3 / 10 ^-9 is 1000000

one million correct

?

isnt it 10^6

im just saying based on the pic

-3 - -9 is 6

my textbook did this

lol

so now im confused lol

i see your point

but cant i say 1 million ms per ns?

ok i see so i will try your apparoach and see what i get it

thank you!

[silver swan]

so i need to help with geometry even though it might be super basic i need help

[left citrus]

Go on

Just post the questions no need to ask

[silver swan]

so should i send pic or smthing

[left citrus]

Sure

That would be helpful

[silver swan]

so i have to find the area

[left citrus]

Alright what’s the area of the rectangle?

Do you know how to find the area of a rectangle?

[silver swan]

yeah

[left citrus]

Which is b*h right?

[silver swan]

yeah

i believe 80

[left citrus]

So 8*6=48 and that’s the area of the rectangle

[silver swan]

im sorry the ones that are

[left citrus]

Sorry what’s the height of the rectangle? The picture is a bit hard to tell from

[silver swan]

i think 8

[left citrus]

So it’s 8 across and 8 high?

[silver swan]

no 10 base

so base would be 10 and h would 8

[left citrus]

So what’s the arrow at the bottom showing with the 8

[silver swan]

my teacher made her own measurements

[left citrus]

Oh ok that’s cool gotchu

So the rectangle as we know then is 80

And we also know that the triangle’s base is 10 too right?

[silver swan]

so have to go

gotta go out

[left citrus]

Ok….?

[wispy sorrel]

is it possible to solve a system of three equations with 5 variables per equation?

[left citrus]

It very much depends

In most cases however… no

[wispy sorrel]

ok thank you

was asking this because given 3 points to find a 4th degree poly with

[left citrus]

No you can’t lol

[cobalt harbor]

how can you tell that a line is perpendicular to another line just from the slope? Is it inverse?

[wispy sorrel]

bruh my teacher gave this as an exercise during class and nobody could figure it out

lol

[left citrus]

I’ll tell you what… the perpendicular line’s gradient is -1/(the first lines gradient)

[left citrus]

Lmao I would be interested to see the picture

[sonic root]

how is this incorrect

[cobalt harbor]

so the negative reciprocal?

[wispy sorrel]

f(x) = 4th degree poly, points (1,3), (2,6,), and (-2, 138)

ig there would be multiple answers

[left citrus]

That’s an interesting question I woulda just started by drawing it out in a graph form and see from there

[bold mantle]

I am convinced this is impossible

Number 8

[kindred warren]

0 to infinity

i guess

[bold mantle]

Whatttt

[kindred warren]

yeahlol

thats such a weird question

[bold mantle]

The answer says its 9.15 to 9.25 cm

[kindred warren]

wtff

[kindred warren]

wfff

[bold mantle]

I really don't know what the people who made this book were thinking

[kindred warren]

how does that make sense lmao

[bold mantle]

Idk

I'll ask my teacher about it tomorrow

[alpine sable]

Integral of e^pizza is e^pizza

Plus c

[kindred warren]

derivative of e^pasta = e^pasta

[astral dagger]

but pizza = pizza(chimken)

then it's a chen lu

or substitution, I mean

[simple compass]

Quick question, how would I use FOIL for this? My math class just started today and I forgot how I solve it, lol

[golden nymph]

What’s foil

[glass lichen]

Foil 2 at a time

[golden nymph]

What’s foil guys that’s the first time I hear such an expression

[glass lichen]

choice is yours what 2 you do first since multiplication here is associative

[simple compass]

Oh, which terms would I FOIL?

[glass lichen]

.

[simple compass]

It's kind of like a formula, not really sure how I would explain it here...

[glass lichen]

I'd personally do the (x-4)^2 first cause that has an explicit formula

[golden nymph]

Is foil an abbreviation of sth?

[glass lichen]

First Outer Inner Last

[golden nymph]

Lol

[glass lichen]

google it if you dont know it

[golden nymph]

That’s actually cool

I know how to expand brackets just didn’t know that there is such a thing called foil

[simple compass]

Okay, thanks!

[golden nymph]

But that would only work in binomials

A more general one wouldnbe

Just have every possible combination dude

[simple compass]

Would I be in the right step?

[glass lichen]

last line is wrong, cause the x+6 doesnt magically disappear

[simple compass]

Yea, I was wondering how I would foil (x + 6) with a different term

[glass lichen]

yes FOIL is only for binomials, the general process is the same as FOIL though

[simple compass]

Since there are 3 terms...

[golden nymph]

Istg I know how expansion works it’s just that I didn’t know that abbreviation thing

[glass lichen]

$=(x^2-8x+16)(x+6) \ =x(x^2-8x+16)+6(x^2-8x+16)$

[ocean seal]

Mosh

[glass lichen]

by regular distribution

[golden nymph]

The trick I do is do it in order

1,1 1,2 then 2,1 2,2 then 3,1 3,2

Oof I think what I just sent is confusing as heck

Idk read it out loud it may make more sense that way

[glass lichen]

yeah.. it doesn't

In general you add up all products of terms. Ie you multiply the x^2 by x and 6, the -8x by x and 6, and the 16 by x and 6

[simple compass]

Will this be correct?

[golden nymph]

It’s not

[simple compass]

Oh

Would it be x^4 + 2x + 2?

[golden nymph]

I am not superman to check every term but I know there has to be x^3

Also incorrect lol

Largest power you have is x^3

Do it in steps dude

First have your bracket (x-4)^2 simplified with the x+6 next to it in the third line

Then in the fourth have the whole thing

And then the simplified finalized in the fifth

[simple compass]

I see

I'll just redo it

[golden nymph]

No it’s occupied

[rugged spruce]

simplify

[golden nymph]

Oh you’re helping

A helping beluga

What a blessing

I am not sarcastic tho it may sound like I am

(Not at all) fun fact: I have a full portrait of beluga on my pc from 2019 before it was cool. And I discovered it by chance when I was trying to organize that mess of a hard drive.

Just ping me ford focus when you finish because I am starting to get bored here

[atomic sparrow]

(-1)^(12) - will this product be positive or negative? how do you know?

@golden nymph

[golden nymph]

Even powers give positive numbers

Negative times negative is positive

And powers is just repetitive multiplication

So yeah

[simple compass]

@golden nymph I'm pretty sure this is wrong, but I just can't figure out what I did wrong...

[golden nymph]

Look

When you multiply the x terms together

You treat the coefficients (the numbers) alone and the variables alone

What you do to the coefficients is multiply them

[simple compass]

Okay

[golden nymph]

What you do to the variables (only if you have the same) is add their powers

Then you return them to be together

The fault is in the third line in the fourth and sixth terms

You didn’t multiply the coefficients you added them

See what I mean?

(-8x)(6)

What will it be?

Yo

[simple compass]

-8x + 6?

[golden nymph]

I am saying multiply them

[simple compass]

-48x?

[golden nymph]

Exactly

[simple compass]

I see now

[golden nymph]

What you did wrong is that you added -8 to 6

[simple compass]

Yea

[golden nymph]

And you did the same to the last term

Now try again

[simple compass]

Okay, thanks!

[finite breach]

In rolling three fair twelve-sided dice simultaneously, what is the probability that the resulting
numbers can be arranged to form a geometric sequence?

[golden nymph]

That’s one evil question

[finite breach]

in calculating the probability, do you take each individual geometric sequence possible, then add all the probabilities?

[golden nymph]

That’s what I would do

[finite breach]

im confused as to how to approach it

because that seems kinda bashy

[golden nymph]

Each outcome is equiprobable

[finite breach]

i initially skipped this problem in the placement test bc i thought it would waste too much time

now i have to do it as homework lmao

[golden nymph]

,calc 16*6

[ocean seal]

Result:

96

[golden nymph]

First term last line

You magically put in a 2

[golden nymph]

Idk just try to count them efficiently

[simple compass]

Oh, shoot. Didn't mean to put that. It was from the last one I did

[golden nymph]

Other than that it’s all good

[simple compass]

Okay, thanks!

[finite breach]

how would i get all the sequences

or part of them

under 12

like any systematic way to do it

[golden nymph]

You know that if you have a,b,c forming a geometric sequence

Then that means c,b,a form one too

So that’s useful

You can try to make a<=b<=c

And start with a being 1

[finite breach]

does 1 1 1, 2 2 2....12 12 12 count? thats pretty stupid

if it does

[golden nymph]

And then do the b from 1 and rising

And see if there is a c which will make it a geometric sequence

If so include it

Then step the a by 1 and repeat

[golden nymph]

Yup lol they do

[finite breach]

i think

you have have a first term of 1

and then a common ratio of

[golden nymph]

I just told you how I would do it though I think there could be more efficient ways

[finite breach]

2

[chrome skiff]

Can someone explain to me simply what a determinant is? I dont understand the "by the book definition" its complex for me.

[finite breach]

and 3

hmmmm

lemme finish this rq

[golden nymph]

Hi Traveler, Paimon thinks you can ask your question in a non-occupied channel!

[golden nymph]

I don’t think that’s so good