help-0

[storm tundra]

lol okay

thanks peeps

math nerds

nope

[golden nymph]

Nope

[golden nymph]

I am not

[storm tundra]

was a joke, love yall

[golden nymph]

Trust me there are people here

That when they speak I think they are just typing random words

And not forming sentences

[vast marsh]

yo

[storm tundra]

4

[vast marsh]

is it busy in here

[storm tundra]

yeperoonie

[golden nymph]

Umm

2+2

Is that really worth pinging me?

[kindred hull]

Even my calculator couldn’t figure that one out

[velvet condor]

fk u

[random talon]

Dude, don’t ping everyone

[sly mantle]

b&

[gentle jolt]

goddamn it mutherfukcjaer

[alpine sable]

STOP PINGING

STFU

[random talon]

You had posted your question 3 minutes ago. Be patient

[gentle jolt]

you dear sir are an inconsiderate piece of aluminum foil that i will promptly discard

[fading scroll]

What?

[dusk canyon]

[alpine sable]

i aint got time for this. im out

[gentle jolt]

@dusk canyon nice name

thats an example of when you can ping someone you dummy dum dum
still love you though
piece of shit

yeah kvictor this is just how i treat people it means little, its all a figure of speech

if you are telling me to be respectful then well
naw

[whole herald]

be respectful bro

[pearl marlin]

Send me that question

[pastel jasper]

What is this? thanks @wary stream

[crisp grove]

anyone tagged?

[wary stream]

Sigma

[golden nymph]

Capital sigma

[vale ginkgo]

[sly mantle]

you're on thin ice

everyone who has the analysis role, there was a pingspammer. disregard it

[alpine sable]

Who is pinging like bruh so annoying

[gentle jolt]

i already took care of their question in dms
its good he found it

in no way do i personally thing i should be on "thin ice"
But i dont mod this server

Now if you could remove slow mode that would be nice
(unless like thats just how this channel normally is)

[orchid python]

hey

[cursive frost]

How do I get the closed formula for an if the sequence (an)n=0,1,2… is defined as a0=1, a1=2, and an=an-1 + 6an-2 +2

[jagged plover]

<@&286206848099549185> I asked this in question 1 a half hour ago but my question got drowned - with this question i managed to get to Pr(X - 3Y > -40) after standardizing but i'm not sure what to do from here

[golden nymph]

Wait, you can divide random variables???!!!!!
I don’t know what will happen if you do so. And I don’t know how you managed to get to X-3Y but continuing from that is the easy part. You have that a linear combination of normal random variables is a normal random variable so you can let W=X-3Y and you can get E(W) and sd(W) from the formulae then you can standardise and find in the table.

[sharp inlet]

This is the same thing as asking to find the probability that X - 2Y > 0

[jagged plover]

i'm taking a slightly different approach now so i can standardize the right hand side

i have a couple questions regarding this.
is E(X/Y) = E(X)/E(Y)?
and in a ratio distribution, what do we do to the variances of two random variables, X and Y, to obtain the variance of the random variable X/Y?

[alpine sable]

Dude , you can't talk to people like that...

[agile sequoia]

Hey, I've been struggling how to answer this kind of questions. I only understand a little

[alpine sable]

Oh!

Okay so look at it this way yato.

What makes a function invertible?

[agile sequoia]

What do you mean invertible? Sorry I'm kind of dumb right now

[alpine sable]

Hmmmm....alright let me dial this back a bit.

f(x) is just a fancy way of saying y, which means you put x in and get f(x) so y is your solution set, right?

[agile sequoia]

Ohh, so I'm just plugging it in?

[alpine sable]

Yes.

And luckily you have a finite set of x's to choose.

[gentle jolt]

i can if its obviously sarcasm
i guess this isnt the server for it

[junior blade]

STOP TROLLING IN THE QUESTIONS CHANNEL

[alpine sable]

Bro, coda... Let me ask you something...how is anyone supposed to know you're being sarcastic via text?

[agile sequoia]

So the first one would be f(3)>0?

[alpine sable]

No war, I'm just calmly trying to explain Emotional intelligence here.

Also, don't you understand what respect is?

The people here work hard to get their brains big, do you think we work hard just to be disrespected?

Would You Want to work hard only to be disrespected?

Be honest.

[gentle jolt]

experience and the ability to hold cognitive dissonance is how you can parse sarcasm, its not nessesarily easy but is a useful skill on the internet
but you can ask me more questions in dms

[alpine sable]

Coda, that makes no sense man and even if it did? It's not welcome here so you're just being disrespectful and thinking of yourself without thinking of others.

[dawn charm]

This channel is for asking questions not for having discussions, there’s a channel for that. Or do that in private.

[alpine sable]

Sorry Williammm, I'll have a talk with coda see if we can sort this out.

[gentle jolt]

sure sure, i got the picture it wasnt welcome here when the other mode said something

i respect the fact that in this context what i did was not great at all, it was wrong. however i am now being questioned on it, so i am answering honestly

[wispy olive]

It got slow-moded woah.

[agile sequoia]

Um

[alpine sable]

Dammit shadow I'm in the 98%

yo uh

i was lost at the part with the grapes

given
f(x, y) = (y³ - 4y, x³- 4x)
α(t) = (t, 2t)
how do I evaluate f(α(t))?

[jagged plover]

hey, i got to this point, but i realised that regardless of what the mean or stdev of the new variable is, the right hand side will be 0

so Pr(X - 2Y > 0) = 0.5 is what i got, but it's wrong by the looks of it

[velvet condor]

bro..............

[velvet condor]

isnt it just f(t, 2t)

[alpine sable]

so
t³ - 4t, 2t³ - 8t? im not really sure

[velvet condor]

double check your working pls this is a calculating error

[alpine sable]

OH I got it

[astral dagger]

which part you don't understand?

you shouldn't ping them already

[waxen cape]

I got y= 18x + ___ just having a hard time getting the y in the problem and my bad

just need helping solving it, my math is going wrong

[vast marsh]

I’d foil (3x-8)(3x-8) right

[glass lichen]

what's the question.....?

[waxen cape]

how do I get the y that's perpendicular using -4 2 from the original set

[glass lichen]

perp slope is negative reciprocal of one another

[waxen cape]

it is I already got the neg recip it's 1/18 which turns into 18x

[glass lichen]

that isnt negative reciprocal

[waxen cape]

can you help me understand where I went wrong because since of the fractions that's what I got 1/6 over 3

[glass lichen]

yeah, the slope is 1/18, what's the negative reciprocal of 1/18?

[waxen cape]

18x I stated that already

I just need help solving for the y intercept of the equation since I went wrong there

[glass lichen]

negative reciprocal, also reciprocating doesnt introduce x's

$\frac{1}{18}$ has a negative reciprocal of $-18$ so then plug that slope and the point into slope-point formula

[ocean seal]

Mosh

[waxen cape]

I know that I'm just stating it as 18x in general I know what the negative is of it

[glass lichen]

Ok, well what you've said is wrong.

[waxen cape]

I just need help with the y intercept in the equation since that's where I go wrong

[glass lichen]

Refer to what I said 2 messages ago..

Plug the slope of -18 and the point (-4,2) into point slope

[waxen cape]

-18(x+4)+2

[glass lichen]

yes

y= that

[waxen cape]

it says to simplify though

18x+74

[glass lichen]

yeah

that's wrong

[waxen cape]

I didnt put the neg

I know

[vast marsh]

2(3x-8)^2

[glass lichen]

so stop doing bullshit

you cant just willy nilly change the numbers

[waxen cape]

dude this is what is being shown to me by example smart ass

on the question

why do you think Im asking you

[vast marsh]

It’s literally the math discord why do u think ppl r gonna join

[glass lichen]

Yeah, you still cant change stuff around willy nilly

which you are doing, and have said you know you're doing it

-18 is -18, not 18

[waxen cape]

dude I know I have to put the negative ignore it, if you wanna be anal

this is what's being shown to me in example

[glass lichen]

ok.. and?

that's proper working, what you did is wrong

[vast marsh]

Look ur subject up on YouTube and find someone by the name of “the organic chemistry tutor”

[waxen cape]

my dude I put the negatives after

but goodbye

[glass lichen]

this clearly shows you didnt, since you proposed -18*4+2 was positive.

[waxen cape]

my guy

I still got the answer correct

-18x-70

but take your ego elsewhere

there is no right way to anything in life

[fallow nebula]

:KekwLaugh:

[glass lichen]

It's not a matter of ego, you posted your working and I pointed out the error, to which you admitted to knowing it was wrong and why it was. What's the point of asking for help if you're just going to mess around?

If you want help, accept that people will point out the flaws then attempt to correct it with you

[golden nymph]

Dude

Get people out of your nerves

Calm down a bit

[waxen cape]

because negative reciprocal means you can ignore everything and then add the negatives after to make the equation correct but good for you

[glass lichen]

It doesn't

[cold aspen]

i need some help with understanding the nature of an array

would someone help me out with that

?

Problem #3: (40 points)
Given an array A of N distinct integer elements with the following property:
• The first k elements (0 < k < N - 1) are in strictly increasing sequence followed by the
strictly decreasing sequence.
Example:
A = {1, 3, 4, 5, 7, 14, 11, 7, 2, -4, -8}. It monotonically increases from 1 to 14, then
decreases from 14 to -8
Implement a sub-linear (O(logN)) running time complexity program in Java that, given an
array with the previous property, determines whether a given integer is in the array

[golden nymph]

Is that cs?

[cold aspen]

yeah but not really

i just need help understanding what this array is supposed to look like

[golden nymph]

You need to search?

[cold aspen]

yeah

i know how to

[golden nymph]

So?

[cold aspen]

i just need to know if this means that it starts decreasing directly in the middle

or just anywhere

[golden nymph]

I only have basic knowledge of cs

[golden nymph]

Yes

It said k

k is anywhere

[cold aspen]

im assuming that k is a constant that a user would provide

[golden nymph]

It just means some numbers in ascending order followed by some numbers in descending order

[cold aspen]

so i would know

[golden nymph]

The array is built with these propertues

That there is a number somewhere where it starts decreasing

I guess that’s that

You need to make the algorithm for any k

[mellow canyon]

any idea how to do this? should I just try to put an equation into my calculator? how do I know where it would end on the outer limits

[golden nymph]

A graphing calculator?

So I guess the equation is in the form y=ax^2

And you have (40,10) as a point

Sub it in to get the a then graph the equation

[mellow canyon]

Yes, or you can just use something like desmos I guess. How would you get it so that the parabola ends at 40cm?

[golden nymph]

That’s trial and error

[mellow canyon]

doesn't a parabola with that kind of graph go out forever?

how would it abruptly stop like that?

[golden nymph]

I guess it means until you reach the x=40cm part

So you want for 10, 20 and 30

[mellow canyon]

hmm maybe the illustration just stops there because that's all you need?

[golden nymph]

Or you can cheat from Elsie and her 1/4a=40

[golden nymph]

Yes that’s what I mean

[mellow canyon]

well that makes a bit more sense. so I just need to find 40,10 and move into from there I suppose

[golden nymph]

To get the a

[golden nymph]

?

To find what

[mellow canyon]

that's interesting, do you mean the a in ax^2?

[golden nymph]

Move where

[golden nymph]

Yes

[mellow canyon]

to find the 4 different areas I just need to find the 40,10 line first and then move inward from there by 10 each time

[golden nymph]

I don’t get what you are trying to do

You need heights not areas

[mellow canyon]

how does that work? I thought that 1/4a was to find the focal part

[golden nymph]

And you have a function

[mellow canyon]

yes I know. so if I just move x back each time by 10, then I can solve for height

[golden nymph]

You have a function

You can plot it

And just see what y values are at x=10, 20, and 30

[mellow canyon]

well for now I have a non to scale drawing

[golden nymph]

Again again

From the beginning

Because I feel confusion

You need y values

[mellow canyon]

yes, y values for 10,20etc

[golden nymph]

You get the y values from a function

This function you plot

On a graphing calculator

[mellow canyon]

well that's the questoin

how would I find an equation with this little information?

I guess I have 40,10

[golden nymph]

It told you the equation of a parabola

Just put k and h as zero

Because they are not important

And now we need to find the a

So our function is y=ax^2

You can use the (40,10) point

As in 10=a(40)^2

To get the a

[mellow canyon]

ahh yes I see

[golden nymph]

Having the a, you have the function

Plot and search

[mellow canyon]

so your plugging in the point into the quadratic equation

as an x and y?

[golden nymph]

Yup to solve for the constants

[golden nymph]

Any point on a curve is (x,y)

So yup

[mellow canyon]

ahh that is quite cool, didn't know you could do that. thanks

[golden nymph]

You’re welcome

[spring hamlet]

how do you add constructions?

like line seg AB and line seg CD

[elfin fiber]

i need help

[spring hamlet]

with what

[elfin fiber]

mathhhh

lol

[glass lichen]

wow, we had no idea...

[elfin fiber]

lol

[glass lichen]

are you going to ask something meaningful or just.. mess around?

[elfin fiber]

i'm gonna ask chill

where r the ppl that were here yesterday?

@alpine sable

@glass lichen

help pla

[glass lichen]

no

I dont help people that ping for no reason.

[elfin fiber]

wym for no reason????

k

then don't

[weak helm]

Do you need help for the circumference questions?

[elfin fiber]

no the word problems

[weak helm]

Ohh

[elfin fiber]

ye

[stiff vortex]

can someone define postulates.. im in 10th geometry
cuz i need help understanding it

[weak helm]

The first one you find the circumference and then mutiply it by 2

[glass lichen]

there was no reason to ping me

[elfin fiber]

ye i get that one

[weak helm]

ok

[elfin fiber]

bruh i literally asked for help

[glass lichen]

Dont care

[weak helm]

Second one you find the radius

[glass lichen]

dont ping random users

[elfin fiber]

well leave then..

[weak helm]

and then use that to find circumference

[elfin fiber]

ok

how do i do that?

do i need to draw it?

[worn ore]

u know what is circumference ?

right

[elfin fiber]

yeah

[worn ore]

nice

then

theres a formula

[weak helm]

Ya there is a formula for it

Did you learn it?

[elfin fiber]

yeah

ik

it

[worn ore]

2pir r

[elfin fiber]

yeah u have to times it by 2

[worn ore]

its simple then just find the value of r

[worn ore]

pie r times 2 yeah

[elfin fiber]

ohh

[worn ore]

r is the radius

[elfin fiber]

so do i do 4.5*2 whatever the answer u times it by 3.14?

[worn ore]

in b part ?

[elfin fiber]

the word problem

4

[worn ore]

oh wait

[elfin fiber]

ok

[arctic viper]

4*pi *2 ?

[worn ore]

yeah so its saying that he skates twice that circle

[arctic viper]

unless im missing something

[elfin fiber]

ye so?

[worn ore]

telling \

me slow typer

sed

[arctic viper]

4.5*

[elfin fiber]

hm?

4.5*2

[arctic viper]

times pi

[worn ore]

a circumfrence is pie*r times 2

so r is given

its 4.5

[elfin fiber]

which is 9

[worn ore]

yeah

times 3,14

3.14

[elfin fiber]

so then 3.14*

yeah

[worn ore]

yesyes

[elfin fiber]

3.14 into what?

9

[vivid anvil]

It would be 2 * 3.14 * the radius

[worn ore]

well i always take the value of pie 22/7

[worn ore]

yes ]

[elfin fiber]

wait what?

[worn ore]

yeah its the same

[raven rover]

The circumference of a circle is 2πr

[elfin fiber]

omg

[vivid anvil]

to find the circumference

[raven rover]

π is about 3.14, and we need the radius

[elfin fiber]

π what's that?

[arctic viper]

pi

[vivid anvil]

Pi

[worn ore]

pie the 3.14 thing

[elfin fiber]

oh

ok

[worn ore]

lel

[elfin fiber]

so then what do i dooo?

[vivid anvil]

Do you have the radius yet?

[worn ore]

4,5

4.5

[elfin fiber]

yeah

[vivid anvil]

So then

2 * 3.14 * 4.5

and that will be your circumference

[worn ore]

see do 2 pie r
where r is 4.5
pie is 3.14
just multiply them

ezy

[worn ore]

yeah

[elfin fiber]

isn't it supposed to be 4.52+93.14?

[raven rover]

2πr

r = 4.5, π is about 3.14

circumference is about 2πr = 2 * 3.14 * 4.5

[elfin fiber]

ohh ok

[worn ore]

pro

[elfin fiber]

whats the answer??

[worn ore]

u tell

[elfin fiber]

nooo

[arctic viper]

pog

[elfin fiber]

loll

[worn ore]

tell even if its wrong

[elfin fiber]

28.26?

[arctic viper]

just say 9pi

[elfin fiber]

is that it?

whatt

[worn ore]

yes its kinda correct

remember it said

[elfin fiber]

wym kinda Imao

[worn ore]

he goes 2 times

[elfin fiber]

so

wait

[worn ore]

multiyly it by 2

[elfin fiber]

so first 2*3.14?

[worn ore]

see 2 *3.14 *4.5 was just for one revolution

if u do multiply it again by 2

[elfin fiber]

jus show me

like

ugh

[arctic viper]

wait isnt it 18pi lol

[elfin fiber]

wtf

brooo

my brain

[worn ore]

yeah

[worn ore]

sed

[arctic viper]

yeah its getting late lol

[worn ore]

its the same thing

wait ill tell u

[elfin fiber]

ok

quickkk

@worn ore

[wary stream]

Don't ping people. Just be patient

[elfin fiber]

ok

[worn ore]

Yeah

[elfin fiber]

did u get it?

[worn ore]

Yup

Uploading

[elfin fiber]

OH

ok

[worn ore]

radius of circle= 4.5m

[elfin fiber]

56.52?

[worn ore]

yeahhhh

[elfin fiber]

yay

thankss

[wary stream]

Next time, don't give people the full solutions, let them figure it out

[worn ore]

u will not like........ totally copy me

right ?

[elfin fiber]

no

[worn ore]

yeah

[elfin fiber]

i checked

the calculator

lol

[worn ore]

o

[elfin fiber]

what about ques 5?

[worn ore]

...

wait

the first part is easy

[elfin fiber]

loll

yeah ok

[worn ore]

yeah everything is given

[wary stream]

It's just circumference formula

[elfin fiber]

what's diameter again?

[worn ore]

its the twice of radius

[elfin fiber]

how do i know if it's a diameter or radius?

[wary stream]

It tells you

What it is

[worn ore]

the question will say it

[elfin fiber]

45.9m

[wary stream]

Yes, that's the number

[elfin fiber]

so i do

45.9 *2

[worn ore]

see diameter is twice the radius

[worn ore]

no u need to find the radius

do that

umm opposite caculation that u were doing yesterday

[elfin fiber]

oh noo

[worn ore]

2*r=45.9

[elfin fiber]

wait so

[worn ore]

find r

[elfin fiber]

ohh

[elfin fiber]

22.95?

i divided

[worn ore]

yeah

its the radius

[elfin fiber]

ok

[worn ore]

now calculate the circumference

[elfin fiber]

72.063?

[vivid anvil]

diameter is the entire distance across the circle

Radius is just halfway

[elfin fiber]

ohh

ok

[wary stream]

How did you calculate that?

[elfin fiber]

oh

[worn ore]

lol

[vivid anvil]

And if you ever want to find the radius

when the diameter is given

divide the diameter by 2

[elfin fiber]

loll

yeah that's what i did

but

[wary stream]

How did you calculate that number

[worn ore]

u did 2* pie* r right ?

[elfin fiber]

yeah

Lol

[wary stream]

Not the right formula

[elfin fiber]

3.14

[wary stream]

Wait

[worn ore]

wot

its right

[wary stream]

I was thinking of area

[worn ore]

2 pir r

[wary stream]

My bad

[worn ore]

lol square

[elfin fiber]

o is the answer right?

[worn ore]

no

[elfin fiber]

........

[worn ore]

ur answere is coming the half of what it should

lol

[elfin fiber]

so what do i do next?

[worn ore]

what was the value r that u got

[wary stream]

,calc 22.95*pi

[elfin fiber]

oh

[worn ore]

ye

[ocean seal]

Result:

72.099551399886

[vivid anvil]

[wary stream]

You just did 22.95 times pi

[worn ore]

maybe u did not myltiply it by 2

[worn ore]

yeah

[elfin fiber]

yeah

[wary stream]

The formula is 2pi*R

[elfin fiber]

ok

so what

what

wait

[wary stream]

Plug the radius in

Get value?

I mean, I don't know what else you want

[elfin fiber]

lol

so i got 22.95?

so i times it by 2?

[wary stream]

And pi

Don't forget about pi

[elfin fiber]

what's the pi?

oh

[vivid anvil]

3.14

[elfin fiber]

3.14

[vivid anvil]

jinx

[wary stream]

3.1415

[elfin fiber]

didn't i alr do that???

[wary stream]

You calculated the circumference wrong

You did 22.95 times pi

You forgot the 2

[elfin fiber]

ye

[wary stream]

Because 2pi * r

There's a 2 in the formula

[elfin fiber]

144.126?

[vivid anvil]

correcto

[elfin fiber]

ok

what did i do first?

[wary stream]

You found r first

[elfin fiber]

which

was 22.95?

[wary stream]

Yes

[elfin fiber]

how did i get that?

i forgot

[wary stream]

Diameter divided by 2

[wary stream]

You should either write down the steps or pay more attention to the people helping you

[elfin fiber]

yeah

help with b) pls

[vivid anvil]

repost the question

[elfin fiber]

for the diameter i need to divide??

[elfin fiber]

here....

[vivid anvil]

You have the diameter

So you need to divide the diameter by 2

to get the radius

then apply the same formula from earlier

[elfin fiber]

b part

[vivid anvil]

to get your circumference

[vivid anvil]

I was just explaining lol

[elfin fiber]

lol

for ques 3

@vivid anvil

the b

is the answer 28.26?

@worn ore

[vivid anvil]

yep

[elfin fiber]

ok

i need help with 5 b

pls

[vivid anvil]

5b

[elfin fiber]

yee

[vivid anvil]

You must do 5a first

[elfin fiber]

i

did

[vivid anvil]

unless you already have the circumference

[elfin fiber]

ye

[vivid anvil]

and what did you get

[elfin fiber]

144.126

[vivid anvil]

Ok good

The distance between cars is 6 metres

[elfin fiber]

yeah

[vivid anvil]

and the circumference is 144.126

So how would you go about finding out how many cars are there in total?

[elfin fiber]

add?

or times idk

[vivid anvil]

it's on the outside

the entire circumference is 144.126

and the distance between each car is 6 metres

[elfin fiber]

ok so

divide?

idk

[vivid anvil]

yes

[alpine sable]

Hi , where can i find free algebra problems to solve?

[elfin fiber]

oh

[elfin fiber]

google it?

[vivid anvil]

google exists lol

[elfin fiber]

Imao

[vivid anvil]

just type in whatever you want exactly

and it'll show up

or there's always kutasoftware

which has good practice sheets

[vivid anvil]

And what did you get?

[elfin fiber]

ok so

i got 24.021?

[vivid anvil]

so how many cars are there

if one were to have a distance of 6 metres

[elfin fiber]

idk

what

isn't that the answer?

[vivid anvil]

one covers 6 metres

so how many cars are there

if the highest is 24.021

[elfin fiber]

ok so times it by 6?

[vivid anvil]

each car covers 6 metres

So how many cars would you need

to get 24.021?

or 24 metres in total

[elfin fiber]

whatt

idkk

[vivid anvil]

LOL

[elfin fiber]

6

what

ughh

bro idk

[vivid anvil]

count up by 6

[elfin fiber]

wym

[vivid anvil]

each car has a distance of 6 metres

[vivid anvil]

start at 0

Picture this

Each car covers 6 metres in total

[elfin fiber]

6 cars?

[vivid anvil]

the entire thing is 24

each car

covers 6 metres

[elfin fiber]

24?

oh

[vivid anvil]

[elfin fiber]

3??

hm?

[vivid anvil]

literally add 6

until you get 24

[elfin fiber]

is that the answer?

[elfin fiber]

yeah i got it Imao

is that right???

[vivid anvil]

6 + 6 + 6 is 18

not 24

try again

🦦

[elfin fiber]

oh yeahh' so 4?

[vivid anvil]

finally

[elfin fiber]

yayy

LOL

TYYY

BESTIEEE

[vivid anvil]

np

[elfin fiber]

💙

[alpine sable]

help

1/2 ( -3y + 10 )

Combine like terms to create an equivalent expression.
Enter the any coefficients as simplified proper or improper fractions or integers.

[vivid pagoda]

PEMDAS

what do you do first?

[alpine sable]

ok first

1/2 is 0.50

[vivid pagoda]

yes

[alpine sable]

times

-3y + 10

[vivid pagoda]

yes

[alpine sable]

how to find y

[vivid pagoda]

have you learned of the distributiv property?

[alpine sable]

yeah

[vivid pagoda]

0.5 * (-3y + 10) is what?

[alpine sable]

28

[vivid pagoda]

how did you get 28=

[alpine sable]

ok

so 0.5 x 3

-3

• 1.5

• 29.5

28

[vivid pagoda]

now, 0.5 * -3 is -1.5, but remember its -3y

[alpine sable]

yes

[vivid pagoda]

you need the y

[alpine sable]

-1.5y

• 10

omg

8,5

ez

[vivid pagoda]

no wait

you also need to multiply the 0.5 with 10

[alpine sable]

8.5y

oh

ez

5

[vivid pagoda]

so you have -1.5y and 5

[alpine sable]

yes

-7.5

[vivid pagoda]

how are you getting -7.5

[alpine sable]

1.5 x

5

bro whats the answer

i aint gonna be shit

[vivid pagoda]

you cannot add -1.5y and 5

1.5 in a fraction is what?

[alpine sable]

hm

1 and 1/2

[vivid pagoda]

can you add 1 and 1/2 into a fraction

[alpine sable]

uh

3/2

-3y/2 + 5

ez

ez

ez

[vivid pagoda]

yes, so its -(3/2)y + 5

yes

[alpine sable]

ez

is that the answer

[vivid pagoda]

that is the answer

[alpine sable]

bruh i had the answer in my calculator all along

FUCK

[vivid pagoda]

but you did it yourself, which is a lot better

[alpine sable]

I GOT IT WRONG

KHAN ACADEMY

NOOOOO

I HATE MY LIF

[vivid pagoda]

ok

[alpine sable]

https://tenor.com/view/invincible-omni-man-punching-gif-21625389

[alpine sable]

I WILL DO THIS TO U

[vivid pagoda]

what was the answer?

[agile sequoia]

hi for second question, how do i know when to use brackets or parentheses when making it interval notation. i got the first question right already.

[vivid pagoda]

brackets include the given number. parentheses exclude

you just know theyre minecraft gamers

those damn pfps

[vivid pagoda]

(3,4] would mean greater than 3 to less than or equal to 4

[alpine sable]

yes

how would I find the domain of this function?

[glass lichen]

Well, what makes sense for a weight?

[vivid pagoda]

ok

[tall wing]

band

[vague coral]

🤔

[glass lichen]

b&

[vivid pagoda]

🤔interesting

[alpine sable]

any positive number

[glass lichen]

Non negative

[alpine sable]

yea

[glass lichen]

Cause a weight of 0 makes sense

So your domain is any non neg number

[alpine sable]

so would it be w>0

[glass lichen]

W>=0

[alpine sable]

oh

thanks

[glass lichen]

What? I had already said 0 was sensical

[alpine sable]

ya just realized that

[atomic lodge]

Hello

Can anyone help me with this one

Question 24 —- Find the derivative

[icy gyro]

for the first term u can use the formula (u'v - uv')/v^2

[wintry vortex]

this being used?

My question is when I use the law of sines to get B it says no solution, and I cant use the law of Cosines because I ont have enough information

is it just no solution?

[alpine sable]

is there a channel for graph theory?

[humble tiger]

help..

[vagrant frost]

In guessing terms I can guarantee it’s not E

[humble tiger]

uhuh

is there a rule or something i should use to solve this?

[vagrant frost]

Wouldn’t it just be a * b * c * d * e = 45?

[icy igloo]

helpp

[humble tiger]

mm

i don’t know

i have an explanation but i don’t get it

[vagrant frost]

Does each letter have to be a different number

[humble tiger]

yes

[alpine nacelle]

hint: all factors are integers

6-a, 6-b, etc

what are the prime factors of 45 ?

6-a, 6-b, ... are five distinct integers such that there product is 45

now you should see a way

[humble tiger]

hmm

[alpine nacelle]

45 = 3²*5

you have to write 3²*5 as a product of 5 distinct integers

and that's why there is a unique solution

[quiet basin]

hey

[buoyant pulsar]

can someone please explain this to me im extremely lost

sorry 😅

[placid zinc]

So as we've talked about, you're interested in the vertex of that parabola. Where is it?

[buoyant pulsar]

(0,-200)

[placid zinc]

https://iitutor.com/turning-points-and-nature/

[buoyant pulsar]

how do i solve for turning point if v and t are both undefined

[placid zinc]

t is the independent variable, so you'd be taking the derivative in terms of t

v is a real number and you don't know it yet. Leave it as v and solve

[hushed pasture]

we need to find v so that we reach 200ft

[buoyant pulsar]

h'(t)=32t+v

right?

[slender girder]

is this in use?

[vast marsh]

How do I do this?

Is it the absolute value?

Oh

Could u show an example?

So if h(-4) what would I do

[thorn kindle]

Find the point on the x axis that is -4

Draw a vertical line to the function

See what y value the function has there

Yeah like that

[vast marsh]

So wait what am I looking for

So h(-4) is what

What do I put there

6

So

I see

There isn’t one

Wait

Is it -1

-2*

Right)

Sweet

So for the answer I just write -2

?

[solemn remnant]

can any of you help me find "week 0"

[vast marsh]

Nice

Yessir

And for -2 6

Ik

[granite lily]

Hey @analog rose could u help me out

Hey @analog rose could u help me out

[vast marsh]

Ban

[restive tendon]

how would i evaluate this limit

also please ping me if u respond

ty 😄

[alpine nacelle]

@restive tendon multiply by conjugate

[restive tendon]

@alpine nacelle got it will do

ty

also one more question, im guessing i use some sort of identity in this question but which one

to eval limit

[alpine nacelle]

Do you know Taylor formula ?

[restive tendon]

nope :?

whats that

[alpine nacelle]

let me think 2 sec about an easy way

[restive tendon]

kk

[alpine nacelle]

wait it's just 0, no ?

0/-infinity

[restive tendon]

idk it might be

interdeterminate

so im thinking if i apply some sort of trig identity it would work out>?

but im not sure

[alpine nacelle]

it is 0

[restive tendon]

oh ok cool

[alpine nacelle]

and it's not indeterminate

btw

[restive tendon]

oh indeterminate****

[restive tendon]

whnat wopuild me

[alpine nacelle]

it's still not

[restive tendon]

oml

what would be*

[clear violet]

is anyone able to help me with a math question i don’t understand how to start it off

[alpine nacelle]

@restive tendon https://en.wikipedia.org/wiki/Indeterminate_form

[restive tendon]

oh awesome ty

[alpine nacelle]

0/inf is not one of those

[restive tendon]

preciate it

[alpine nacelle]

so it's not indeterminate

[vast marsh]

How would I do this

[sleek yarrow]

0

4

1

0,6

0,5

are the answers

[vast marsh]

Oh

But how do u find the@

[winter rock]

@sleek yarrow how did u find 0,6?

Shouldn't the domain be [0;5]

[vast marsh]

There isn’t a point of 6 for g(x) should t it be 5?

[vague iris]

Why do these two have different graphs?

[alpine sable]

I don’t know but I think the bottom one is the one you focus on first.

[left perch]

It’s kinda blurry 😅

[restive tendon]

oops wait

?

@left perch

[left perch]

First, draw the function's graph.

as well as the line's graph

At four locations, this line meets the graph of the function f(x). As a result, there are four possible values for b.

Only three of them are positive.
Because the graph of the function and the graph of the line y=2 cross at the positive values, f(x)=2, then for the three b with positive values

I think

[broken schooner]

hi I'm trying to solve this simultaneous equation

x+y=9

x^2-3xy+2y^2=0

[alpine sable]

Because of the order of operations

[vague coral]

think about this (a-b)² = a² -2ab + b² @broken schooner

oh wait you cant here 🤔

[vague iris]

Okay so imaginary numbers do not have graph?

[broken schooner]

@vague coral I tried substituting 9-y in place of x

[alpine sable]

Well, they do, but not in the x,y on R

[broken schooner]

but I kept coming out with the wrong answer

I'm not sure why

[alpine sable]

so in ur case

-1 can be put in the first equation but no the second

It's because $\sqrt{x^2}=|x|$

[ocean seal]

jswatj

[alpine sable]

or u can just think of it like it's being squared first so it can handle numbers in R

[vague iris]

The answer will be imaginary number if I substitute negative integers to the second equation.

[vague iris]

Is this correct?

[alpine sable]

Yes

[vague iris]

Okay Thank you!

[little owl]

how do I take the second derivative of a circle? I am able to get the first one through implicit differentiation, which is -x/y, but I am so confused for the second. how do i find a derivative of an expression?

if anyone knows how to explain pls @ me

[ancient saddle]

Hello, differentiate 2 times the circle's equation

[little owl]

yeah

i differentiate the equation once to get -x/y right

and then i differentiate that

but idk how

[ancient saddle]

use the quotient rule

[little owl]

i got x-y/y^2

but my book says something else

[ancient saddle]

what happened with dy/dx?

[little owl]

wdym?

[ancient saddle]

$\frac{d}{dx}\left(-\frac{x}{y}\right) = -\frac{y-x(dy/dx)}{y^2}$

[ocean seal]

leonardogtf

[ancient saddle]

Notice that you already know what dy/dx is too, so you can replace it

[ancient saddle]

on the numerator: derivative(x) * y - x*derivative(y)

[steep briar]

Implicit differentiation avoids quotient rule I believe, should be easier to do.

[ancient saddle]

Yes, but it has the same amount of steps, so I considered continuing what he already had worked

[steep briar]

True

[ancient saddle]

the answer is -R^2/y^3, right?

[little owl]

i can tell this is a dumb question but why is the derivative of y just dy/dx?

[steep briar]

dy/dx means the derivative of y with respect to x, just a definition.

dy would be called the differential of y, on the other hand.

[little owl]

does dy/dx mean you are dividing the derivative of y with the derivative of x?

or what does it really mean for something to be respect to x?

[steep briar]

Agreed

[alpine sable]

(-3,4) reflected over the x axis, would that be (-3,-4)??

just a quick question, sorry for bothering

[steep briar]

No, it does not mean division. It's an abuse of notation that sometimes works, but in general it does not. The technical term for it is d/dx is an operator.

[steep briar]

If you say y=f(x), dy is like saying "f(x+ε)-f(x)", as ε goes to 0. But that's just 0, which doesn't help. If you divide it by dx, which is like saying "(x+ε)-x", then you get an actual number (try it for simple polynomials like x²). That number is the slope of the function at that point (aka "tangent" line).

[little owl]

yeah that makes sense

i guess i just have no idea how to make sense of it when it comes to implicit differentiation

[little owl]

because with -x/y, i dont know how to take the derivative when there are two variables in the expression

[steep briar]

Oh one moment

^ so that's the chain rule, again an abuse of notation, but here you can think of it as the dg/dg cancelling out (this is only really true for single variable functions, which f is).

In this case, y is a function of x, so we say d(y(x))/dx=dy/dx * dx/dx, but dx/dx=1 so it's just dy/dx

(so f(g(x))=y, and g(x)=x if you're looking at the picture)

[ancient saddle]

Additionally, 3b1b YouTube channel has a series of videos that can give you a lot of intuition about fundamental concepts of calculus, there's even a chapter about implicit differentiation. Maybe you should try watching those too

[little owl]

sorry, for d(y(x))/dx, is dx/x the other function, and is y(x) the inner function? would you mind going thru the specific steps in the chain rule for this?

@ancient saddle i did! i might have to watch them again lol

i watched a couple of them

[noble goblet]

how would i solve #21 i don’t exactly understand what it’s asking for or how to write an answer

[little owl]

i think what i am asking is does dy/dx mean the change in y per change in x? and the respect to part just means the bottom one?

[steep briar]

Yes.

[little owl]

thank you so much!

[toxic crow]

its asking u to draw a graph on the interval [0,4] that doesnt satisfy the intermediate value theorem

"if f is a continuous function whose domain contains the interval [a, b], then it takes on any given value between f(a) and f(b) at some point within the interval."

[steep briar]

dy/dx is analogous to Δy/Δx by the way, which is the slope of a line from algebra.

[toxic crow]

so if theres a jump discontinuity @noble goblet , something like this will satisfy that question

[barren jacinth]

at x = -3, is that point differentiable or not??

[noble goblet]

ohhh ok so i j draw the graph based on the info given?

[noble goblet]

ohhh tysm lmao i can’t read

[alpine sable]

anyone know how to do this, little confused on how it would work with radicals

[noble goblet]

so i’m not too sure i did it right

[placid zinc]

@alpine sable
d(√x)/dx = 1/(2√x)
Remember to use the product rule here

[alpine sable]

alright thank you ill try that out

[toxic crow]

#21 is satisfied if thats what you're asking, I didnt check the rest

[noble goblet]

ok tysm

[upper dagger]

Hey guys I’m so confused how the square root of 1 doesn’t equal -1

[faint mauve]

Sqrt(1) = +-1

[upper dagger]

So it does equal it?

[faint mauve]

Yea...

[upper dagger]

that’s so weird khan academy counts it wrong

[faint mauve]

Nope

Im wrong

Its just 1

Because you cant get to negative numbers by using square roots @upper dagger

[fathom sequoia]

How do I find x here:

[faint mauve]

Multiply everything by (4x-2)

You will get 3x-1=16*(4x-2)

[fathom sequoia]

ok

then what

[faint mauve]

And that is 3x -1=64x-32

And then we shift x to the one side and numbers to the other

So its

[fathom sequoia]

$3x-1=16\left(4x-2\right)$

ok

[ocean seal]

Bongo

[fathom sequoia]

Thank You Man. Appreciated 👍

[fiery adder]

can i ask sumn or is this still taken

[faint mauve]

3x-64x=-32 +1

[fathom sequoia]

I was stuck on it for One Hour straight

No Joke.

[faint mauve]

yea np

[faint mauve]

Sure

[fiery adder]

i need some help mking sense of this proof

[fiery adder]

https://math.stackexchange.com/questions/46822/density-of-irrationals

[vast marsh]

I’ve never seen this in my life

Oh shit my bad

[faint mauve]

@fiery adder im bad at proofs 😦 sry dude

[fiery adder]

rip

[earnest falcon]

Could anyone help me out with 3 (a). I know you have to do the conjugate but idk why it’s throwing me off so hard
https://cdn.discordapp.com/attachments/326138772477575180/886762895084486706/image0.jpg

[fathom sequoia]

guys

can I cancel the 2

$\ \frac{2^{3x-1}}{2^{4x-2}}=16$

[ocean seal]

Bongo

[fathom sequoia]

Because when I try 2 it gives me something weird

like its not correct can some1 help

[wary stream]

The two as in the base?

[fathom sequoia]

yes bro

can I

[wary stream]

No you can't cancel that out

[fathom sequoia]

ok but if I convert it to logarithm fomr I get:

$\frac{3x-1\log2}{4x-2\log2}=\log16$

[ocean seal]

Bongo

[fathom sequoia]

so can you help me please out

so I can cancel it now or no

[wary stream]

No

[fathom sequoia]

why not

oh ok i learnt this

When i graph it it doesn't show for some reason

[wary stream]

Because it's not possible

[fathom sequoia]

ok

when I convert it to log form its not shwoing it

showing*

the one on the right is the logarithm form and the left is exponent form