help-0

[pearl marlin]

okk so first try to simplify the bracket

[kind drift]

it do be 21 tho

[chrome sleet]

https://cdn.discordapp.com/attachments/881621956598857778/886291818763935794/unknown.png

can somone help me

solve x

[vague coral]

what is this

[chrome sleet]

idk

my hw

i dont get it

oh i solved it

it fine

ty

[ivory gulch]

hello

this channel is not occupied correct?

[chrome sleet]

i got

72

[chrome sleet]

degree

[ivory gulch]

ok could i get help with this?

[finite scarab]

Write 0.000000000000412 in standard form?

[chrome sleet]

yea

[finite scarab]

May someone help me in this one?

Rip

[chrome sleet]

4.12x 10 somthing

so

angel bcf

is 38

and triangel DBC

since line BD and DC

[ivory gulch]

"Assume that functions f and g are differentiable with f(-2) = 3, f'(-2) = -4, g(-2) = 2, and g'(-2) = 5. Find and equation of the line tangent to the graph of F(x) = f(x)g(x) at x= -2"

[chrome sleet]

Is same

[ivory gulch]

wait should i go to diff one now

[chrome sleet]

so the triangle

is isolate

or somthing

so it both 38degree

the thired angle is 102

oh

oh yea

and

the z bit

i forgot

since it dg and cf

is pallel

angle bcf is same with dbc

it say in question

and the

image

have the

arrow

i copyed it down

yea

sorry rip

but am i right

for x=72

ok

i cant ss

im on laptop

sad that y i draw it

oh

ok

emm

ok

yea

oh

i see

im still unsure

but i think

i understand it

wat topic is it

im gonan watch on yt to see

ok

ok

but i cant

take

a image of it

yea

i can type it out

there is

[fringe depot]

can i see ur steps🥲 ? im havin trouble with tat too

[chrome sleet]

the arrow

bit

[glad moon]

Can anyone help me out with statistics?

[alpine sable]

-8,-3 and -1,-2 whats the slope that goes between them?

[chrome sleet]

AE DBG CF are parallel
DA =DB=DC
angle EAB=angleBCF=38 dregess

[alpine sable]

which channel?

works?

ok

[pearl marlin]

dm me

[fringe depot]

sureee, i truly appreciate it

[karmic sleet]

Can i post an image here? I need help and I did a sort of scheme

So, this has to do with programming, is there a sort of formula that given degrees, it gives me a coordinate (in this case, x and y)?

I also inserted some examples of the outcomes I would like to create given some degrees

Sure, I need to draw gradients, and thus I need a sort of formula to give me the x and y coordinates of the drawing points given degrees
If i want to create a gradient with 0 degrees, the first colour should start at x=half width, y=0 and end at x=half width, y = height
The numbers (x and y) on the right are an exact position the starting point should be

With the starting point I could then retrieve the ending point because it is the inverse from the center
However I am not sure this question is good on this server, but I thought there have to be a sort of calculation specific for this problem

Yes, deg is a number between 0 and 360

Sure, I wanted to avoid that

But I found a method, using sin and cos function

https://www.desmos.com/calculator/5kfrnpwhyl

[wind hawk]

yes, but you need a radius. If you want to do your own research look up polar coordinates.

The basic premise is that it uses (radius, angle) to plot points.
You can then convert that to cartesian (x, y) like this:
x = r × cos( θ ) y = r × sin( θ )

another way to go about it is start with the x, y coordinates, then use inverse tangent to find the angle at that coordinate

[karmic sleet]

I don't have the x y coordinates, I need to find them given the degrees and a square

[wind hawk]

wait im confused, did you define deg 315 => x =0, y = 0, or was that given?

because you cant define an angle to a point

an angle covers all radii with that angle, meaning an infinite number (or finite if its confined to a box, but still more than one) of (x, y) coordinates for that angle

[karmic sleet]

If I give 315 i want the starting point to be x=0, y=0

[wind hawk]

so you only want to use the edges?

[karmic sleet]

Exactly

[wind hawk]

ah ok

[wind hawk]

well in that case you do have the x, y coordinates.

when y = 0
x = 0, 0.1, 0.2, 0.3,...1

when y = 1
x = 0, 0.1, 0.2, 0.3,...1

when x = 0
y = 0, 0.1, 0.2, 0.3,...1

when x = 1
y = 0, 0.1, 0.2, 0.3,...1

[karmic sleet]

To make it clear, if i give 135, I need the starting point to be x=1, y=1
Cause it is the bottom right corner

[wind hawk]

however, I wouldnt do it like that

I would have 0, 0 be at the center

[karmic sleet]

How would you approach this problem?

[karmic sleet]

@wind hawk Here I used degrees to retrieve the correct x,y coordinates but not mapped to a square, but to a circle

[wind hawk]

you need to draw gradients, right? so why are you just using the edges?

[karmic sleet]

Cause I need to draw gradients in a square

[wind hawk]

but what kind of gradient, circular?

[karmic sleet]

No, linear

[wind hawk]

then why are you using 360 degrees?

[wind hawk]

wait maybe that wasnt claer

do you want it to look like this?

(but in a square)

@karmic sleet

[stark matrix]

I found U5 to be 37 but idk how to go from there

[karmic sleet]

No, i need a gradient like this

[glass lichen]

Generalize part a to do part b

To find u5 you needed S5 and S4

Or S(5-1)

[stark matrix]

I got U5 = 37 by doing Un = Sn - Sn-1 but now that i have U5 idk what to do to complete B

[earnest panther]

I think that what you described is precisely the method you should use.
Indeed, since:
S(n) = u(1) + u(2) + ... + u(n - 1) + u(n)
and
S(n - 1) = u(1) + u(2) + ... + u(n - 1)
then subtracting them yields:
u(n) = S(n) - S(n - 1).

Now, you already have S(n) in terms of n. Can you figure out how to express S(n - 1) in terms of n?

[fiery crest]

I need help with laplace / controls stuff

With some given transfer functions I'm supposed to use the step u(t) = 1 t>= 0 and check in which cases the output goes to a constant value when t goes to infinity. Find said value

[elfin fiber]

hi

[fiery crest]

for example G(s) = 3 / (s+5)

It's to do with final value theorem but our professor just didn't show how to use it, yay

[elfin fiber]

brooo

[alpine sable]

What

[fiery crest]

Are the math majors scared of electro engi

[alpine sable]

Maybe

[elfin fiber]

broooo

i need help

ugh

[alpine sable]

With what

Bro what's with that profile pic

You gonna get clowned

[elfin fiber]

who?

[elfin fiber]

brooo

it's called math

[alpine sable]

Bro

I know

But what queation

[elfin fiber]

find the circumference of these circles

[alpine sable]

Oh

[elfin fiber]

give ur answers to 1 decimal place

yeah this shit

[alpine sable]

Which circles

Dm me the questions

[elfin fiber]

ok

it's on a paper

[alpine sable]

Take a picture or type them up

Lmao

[elfin fiber]

K

Imao

@alpine sable

Bruh

[alpine sable]

Bruh

That's easy

Here I'll help you

[elfin fiber]

K

Imao

[alpine sable]

To find the circumference you have to do d*π where d is the diameter

Since all of the circles have only the radii listed you have to replace the d in the formula with 2r as the radius is half of the diameter

[elfin fiber]

Bro I never done this shit before

[alpine sable]

Ok do you know what a radius is

[elfin fiber]

No

[alpine sable]

The radius is that line from the center of the circle to one of the edges

[elfin fiber]

Oh ok

So now what

[alpine sable]

Yea so the highlighted part

[elfin fiber]

@alpine sable

Yeah

[alpine sable]

So now you multiply the length of that by 2

[elfin fiber]

Ok

[alpine sable]

And then multiply that by π

To get the circumference

[elfin fiber]

What is that sign?

[alpine sable]

Yk like 3.141593654...

[elfin fiber]

Hm??

[alpine sable]

But what grade are you in

[elfin fiber]

8

[alpine sable]

Ah

[elfin fiber]

Ye

[alpine sable]

Then you'll probably just have to use 3.14

[elfin fiber]

Oh

What’s that?

Now

[wind hawk]

https://www.desmos.com/calculator/ci2vyvanag

[alpine sable]

Umm

So you don't know what pi is

[elfin fiber]

No

[alpine sable]

You do know that the instructions for how to do this are on the sheet right

It even says what pi is and how to find the circumference

[elfin fiber]

Yeah ik what it is

[alpine sable]

Are you just trolling

[elfin fiber]

No

Bro

I jus read

I hate math

[alpine sable]

Why

Math is great

[elfin fiber]

Nooo

Omg

[alpine sable]

It is great

Anyways do you still need help or are you good...?

[elfin fiber]

Yeah I do

[alpine sable]

Umm

I'll explain why pi is 3.14... first

Yk

[elfin fiber]

Ok

[alpine sable]

So pi is how many times the diameter goes in the circumference

That's why you get the circumference if you multiply the diameter by pi

And the diameter is the length across the middle of the circle from on edge to another

So the radius is half of that since it's only from the middle of the circle to one edge

[elfin fiber]

Oh ok

So what do I do?

Like

So I times 3.14 by 3?

@alpine sable

[alpine sable]

No

See the green is the diameter and the red is the radius

[elfin fiber]

Ohh

[alpine sable]

So when you only have the radius you first multiply it by 2 to get the diameter

Then you multiply that by 3.14 to get the circumference

Or close to it

pi goes on forever

That's why I do the ...

Since you can only ever get an approximate value

When you're older you won't have to multiply by pi and you can just leave the symbol in the answer

[elfin fiber]

Ok so I times

[alpine sable]

But not for gr 8

Yeah

[elfin fiber]

Oh

Yeah ok

[tropic maple]

Can someone tell me what.I did wrong?

[alpine sable]

Mmm

Not me

Lmao

[elfin fiber]

So that equals 6.28

[alpine sable]

Sowwy

[tropic maple]

Lmao

[elfin fiber]

Loll

[tropic maple]

Does it look right?

[alpine sable]

Umm

[elfin fiber]

No

Imao

[tropic maple]

Can you tell me?

[alpine sable]

18.84

[elfin fiber]

What

[tropic maple]

I spent like 8+ hours on a few problems I need a break

[alpine sable]

That is the answer for the first one

[elfin fiber]

Ok

How

[alpine sable]

Bruh

[elfin fiber]

Tho

[tropic maple]

What

Bruh

[sinful relic]

@elfin fiber You multiply the diameter by pi to find the diameter of the circle, not the radius with pi

[alpine sable]

Here I'll explain with an example from the first one since I already told you the answer

[sinful relic]

Because then you don't have the whole circumference of the circle

[alpine sable]

For the first one you do 3x2xpi

Oop

I meant

3 times 2 times pi

There

[sinful relic]

$3\cdot{2}\cdot{pi}$

[elfin fiber]

How do I know the diameter for the first one?

[ocean seal]

Lil Sachi

[alpine sable]

Cause the radius is half of the diameter

[sinful relic]

multiply the radius by 2

[elfin fiber]

Oh ok

[alpine sable]

Yeah so

[elfin fiber]

3*2=6

Ok so

[sinful relic]

yes

now multiply by pi to get the circumference

[alpine sable]

3*2*pi=6*pi=6*3.14...=18.84 approximately

Do that for all the other ones but fill in the numbers

[elfin fiber]

So I Pi is 3.14

[alpine sable]

About

[sinful relic]

@alpine sable would it work if you said 6 * 3 * 1.14

approximately

answer

[elfin fiber]

Ohh

Ok I see

For the second one it’s diameter?

[sinful relic]

because 3.14 times the diameter is the circumference of the circle

[alpine sable]

Just use this formula Circumference=2 times radius times pi

[elfin fiber]

So do I do the same thing?

Ok

[alpine sable]

All of them only give you the radius

[sinful relic]

^^

so multiply by 2 to get the diameter

[alpine sable]

I only highlighted the whole thing green to show you the difference between the radius and diameter

[elfin fiber]

Ok

[alpine sable]

Gr 8 math

Brings back memories

Sniff

[elfin fiber]

The answer is 2

Imao

[sinful relic]

No

Not the circumference

but the diameter is 2

[alpine sable]

2 times pi

That's the answer

The diameter is 2 and you have to multiply that by pi

[elfin fiber]

Yeah 6.28

[alpine sable]

Yeye

There you go

Now you're all set

[elfin fiber]

Omg tysm

[alpine sable]

See math isn't so bad

[sinful relic]

this would be the circumference of this arc if it was 2

approximately

[alpine sable]

Yeah approximately

[elfin fiber]

Alr

[alpine sable]

A bit less than 2

[sinful relic]

therefore you have to multiply by 3.14 to fill the rest out

yeah

[elfin fiber]

Is the third one diameter?

[alpine sable]

No

[elfin fiber]

How do I know if it’s diameter or radius?

[alpine sable]

Radius

Diameter is the one from edge to edge

Radius is the one from center to edge

[elfin fiber]

Ohh

Ok

[alpine sable]

Lmao

[sinful relic]

diameter marked with blue and radius marked with red in the picture listed below

[alpine sable]

I already showed him one lmao

[elfin fiber]

Her

…….

[alpine sable]

Diameter is green, radius is red

[alpine sable]

Ah kk

[elfin fiber]

25.12

[alpine sable]

Yeah screw you too lol, you keep sayin bro and when I say bro you never corrected so how is it my fault lmao

Yeah

The third one is 25.12

Correct

[elfin fiber]

Imao

Yeah

And the last one is 15.7

Lol

[alpine sable]

Yep

[sinful relic]

yes

[alpine sable]

Wait no

[elfin fiber]

Lolll

[alpine sable]

2.5*2=3

[sinful relic]

,w 5 * pi

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Lil Sachi#5747

[alpine sable]

3*pi=9.42

[elfin fiber]

No I think it’s 5

[alpine sable]

Wait nvm

[elfin fiber]

I used calculator idk tho

[alpine sable]

Sorry

[elfin fiber]

Lol

[alpine sable]

Yeah

[elfin fiber]

Np

[alpine sable]

I thought it was 1.5 for a bit

[elfin fiber]

Lol

[alpine sable]

Yeah so you're good

[elfin fiber]

How to add??

[alpine sable]

2.5*2pi=\5pi=15.7

[elfin fiber]

Hahahah I’m jk

[alpine sable]

Hrm?

[elfin fiber]

Imaoo

[alpine sable]

Lmaoooo

[elfin fiber]

Lol

[alpine sable]

Thank you for using the Jimmy Neutron math help service, your ticket number was 0002 but we have just closed your session for you as a result of your problem having been resolved or deemed unresolvable. If you need any help requiring it just send it back to us via direct message.

[elfin fiber]

WAit what

Imao

[sinful relic]

[elfin fiber]

https://tenor.com/view/why-you-do-this-jimmy-why-jimmy-why-big-rocks-wilderness-lore-lore-gif-22185568

It’s Been a week in gr.8

[sinful relic]

nice

[fiery crest]

I am for a fact mentally defficient but

[alpine sable]

This is an automated response, messages out of sessions will not be checked unless a new session is created or an old one is reopened.

[alpine sable]

Wait really

[fiery crest]

how does someone go from 1 / (Ms^2 + k) to 1 / (s^2 + sqrt(KM)^2)

[alpine sable]

Who knows

[fiery crest]

They're aiming to get the expression to follow 1 / s^2 + a^2

[alpine sable]

Why does a birb even have to do math lmao

[fiery crest]

idfk will you help or not

[alpine sable]

Maybe

Hol up

Um

So your question is...

[fiery crest]

I get the sqrt(k)^2 part

[alpine sable]

can you post full question?

[fiery crest]

The dude skips just a few steps before doing the inverse

He wants it in the form of 1 / (s^2 + a^2)

Basically what he ends up reverse transforming is 1 / (s^2 + sqrt(KM)^2)

[alpine sable]

is this from yt vid or something

[fiery crest]

I get it up to 1/(mS^2 + sqrt(k)^2))

yes

[alpine sable]

link?

[fiery crest]

https://youtu.be/RJleGwXorUk?list=PLUMWjy5jgHK1NC52DXXrriwihVrYZKqjk&t=535

I think he messed up

since he's not consistent

[elfin fiber]

Hello

[sinful relic]

hi again

[elfin fiber]

Hellooo

Helpp

[sinful relic]

which question

[elfin fiber]

First one

[sinful relic]

kk

z + 7 = 4

isolate z

by removing 7

easy

[elfin fiber]

What

[sinful relic]

z = 4 - 7

[sleek elbow]

you need to only have z on one side without anything else

[elfin fiber]

So I have to explain it?

I’m the ques?

[sinful relic]

z + 7 = 4 <=>
z = -3

there, explained

[elfin fiber]

What about second ques

[sinful relic]

since -3 + 7 = 4
4 = 4

[sinful relic]

w + 5 = 5
w = 0

[sleek elbow]

channel in use

[elfin fiber]

Help second ques pls

[sinful relic]

.

[urban lily]

channel busy?

[sinful relic]

yes

[urban lily]

okay

[elfin fiber]

First one is 6?

[sinful relic]

no

[elfin fiber]

Howwww

Ughhhhh

[sinful relic]

equation mean you have need to have the same result on both sides
if you insert 6 in $z + 7 = -4$ you get $6 + 7 = -4 \ 13 = -4$ and there isn't the same answer on both sides now

[ocean seal]

Lil Sachi

[elfin fiber]

Oh no

[sinful relic]

?

[elfin fiber]

I’m talking about

G+7=13

That one

[sinful relic]

make g stand alone on the left side by subtracting both sides by 7

[elfin fiber]

Whaaaaassaa

https://tenor.com/view/bunnies-what-confused-meh-gif-13712192

[sinful relic]

what is 13 - 7?

[next bridge]

channel in use?

[sinful relic]

yes

[elfin fiber]

6

@sinful relic

[sinful relic]

yes, now you got the answer

[elfin fiber]

Ok

[sinful relic]

g + 7 = 13
g = 6 because 6 + 7 = 13, 13 = 13

[elfin fiber]

Is c 0?

[elfin fiber]

Yeah

[sinful relic]

no

[elfin fiber]

Oh noooo

Omg this is so damn hard

I’m dying

K is 16

Lol

[sinful relic]

yeah

[elfin fiber]

D is 16 too?

Wauttt

Waittt

Why is there

So many of the same

Equations

[sinful relic]

${\color{green}{5}}$

[elfin fiber]

@sinful relic

[ocean seal]

Lil Sachi

[elfin fiber]

@sinful relic

Helppp

[sinful relic]

stop pinging

im gonna check now

[elfin fiber]

Loll

Ok

On the second row

[sinful relic]

$\color{green}{p}-\color{red}{9}=\color{pink}{16} \ \color{green}{p}-\color{red}{9}+\color{red}{9}=\color{pink}{16}+\color{red}{9} \ \color{green}{p}=\color{red}{25}$

[ocean seal]

Lil Sachi

[sinful relic]

answer there @elfin fiber

[elfin fiber]

Ok

I don’t get i

[sinful relic]

$\color{green}{p}-\color{red}{9}=\color{pink}{16} \ \color{green}{p}-\color{red}{9}+\color{red}{9} \ \color{pink}{16}+\color{red}{9} \ \color{green}{p} = \color{red}{25}$

[elfin fiber]

25??

[ocean seal]

Lil Sachi

[elfin fiber]

Hm

Lol

6=4+m

Idk

[mystic sinew]

hey I know p != q

I need to prove that not p != not q

can I do this via contrapositive?

[alpine sable]

do a chart and bash

[elfin fiber]

Help

[bitter yoke]

with what

[elfin fiber]

This

@bitter yoke

[topaz scaffold]

That is the opposite operation of division?

[elfin fiber]

Idk?

[topaz scaffold]

6/2 = 3

What do I do to get 3 back to 6?

[bitter yoke]

for the 3. problem just multiply both sides by the denominator
and for the 5. problem just divide by the coefficient of the unknown

[elfin fiber]

@alpine sable

Help pls

Ok

[elfin fiber]

I don’t get it

Can u show me how to do the first one?

[bitter yoke]

problem 3 is of the form x/a = b then x = a*b
problem 5 is of the for ax = b then x = b/a

(x/4=11) * 4
x = 44

[elfin fiber]

How did u get that 44?

[wary stream]

Using math, 11 * 4

[elfin fiber]

Oh

So do I do same for the rest of them?

[bitter yoke]

yup

exactly the same process

[elfin fiber]

Alr tysm

Is b 108?

@bitter yoke

[wary stream]

Yes

108 is correct

[elfin fiber]

Okkk

Yayyy

[bitter yoke]

nice

[mystic sinew]

?

hey I know p != q

I need to prove that not p != not q
can I do this via contrapositive?

[alpine sable]

just make a chart for if p=true for false

with contrapositive, you could prove not q != not p

then it is the same if you put rhs as lhs and lhs as rhs

[elfin fiber]

What do I do for 5 @wary stream

[wary stream]

The opposite operation

You divide

[elfin fiber]

Division?

[wary stream]

Yes

[mystic sinew]

that's what' I wanted to prove?

[alpine sable]

@mystic sinew thats how you can prove it with contrapositive.

[alpine sable]

yes

[elfin fiber]

How do I do 2r = 18??

[alpine sable]

as you can flip lhs and rhs

[wary stream]

Divide by 2

[elfin fiber]

This one

[wary stream]

On both sides

[elfin fiber]

18 divide by 2

?

Oh nooo

This is hard

[wary stream]

Yes

[elfin fiber]

Wym bish sides?

Both**

🧋🧋🧋🧋💗

Lolll

[alpine sable]

to solve k*(random variable)=n. if (k!=0) you have that the random variable = n/k.

[wary stream]

You started with 2r = 18, you divide by 2 on both sides

[elfin fiber]

So like I did 18 divided by 2 which is 9

Now what?

[wary stream]

So $$2r=18 \implies \frac{2r}{2} = \frac{18}{2} \implies r = 9$$

[ocean seal]

dldh06

[wary stream]

Nothing

9 is the answer

[elfin fiber]

Ohh I see

[wary stream]

Channel busy

Oh wait

[worn ore]

?

[elfin fiber]

What about 12g = 144

[worn ore]

same

[wary stream]

Same process

You divide

[worn ore]

divide by 12 on both sides meaning rhs and lhs

[elfin fiber]

Tysm

Ok

Rhs??

[worn ore]

what class u in ?

[elfin fiber]

8

[worn ore]

right hand side and left hand side

rhs and lhs

[elfin fiber]

Ohh

Ok

Imao

[worn ore]

lol

[elfin fiber]

Waittt

I did

12 divided by 144

[worn ore]

but theres more to it, idk what opposite method means but theres an easier way too probably u know it too wait ill tell u by doing a question

[elfin fiber]

I got a weird answer

[worn ore]

12 ?

[elfin fiber]

YeH

[worn ore]

yes its correct

[elfin fiber]

The second one

[worn ore]

congo

[elfin fiber]

0.83333333

That was the answer

[wary stream]

Which one?

[elfin fiber]

The 12g = 144

[wary stream]

It said opposite operation, because all had multiplication involved

[wary stream]

No

[elfin fiber]

Yeah

[worn ore]

Hmm I see

[elfin fiber]

So whattt

[wary stream]

$$144/12 \neq 0.8333$$

[ocean seal]

dldh06

[worn ore]

Maybe I was doing it the easier way

[worn ore]

Yeah

[wary stream]

How did you calculate that number?

[worn ore]

It's true those are not equal

[elfin fiber]

What’s the answer?

[worn ore]

144 by 12 is 12

[wary stream]

Use the times table

[elfin fiber]

What

[wary stream]

Don't give answers like that

I'm trying to walk them through how to find it

[elfin fiber]

How is it 12??

[worn ore]

Oh yea

[wary stream]

How did you calculate this?

[worn ore]

Do 12×12

[elfin fiber]

I did 12 divided by 144

[wary stream]

Using what exactly?

A calculator?

[worn ore]

144 divided by 12 it should be

[elfin fiber]

Wym?

Ohhh

[wary stream]

Or brain? Or what?

[worn ore]

Maybe

[worn ore]

Genius

Lol

[elfin fiber]

Calculator

Imaoo

[worn ore]

Lel

[wary stream]

You typed it wrong

[elfin fiber]

Oh

It was the other way around lol

[wary stream]

Did you type exactly 144/12?

[worn ore]

Those are simple calculations don't use calculator it will gell u in future

[wary stream]

In the calculator

[elfin fiber]

Yeah

[wary stream]

No you didn't

[elfin fiber]

Lolll

Hm??

I wrote 144 and then 12

Imao

[wary stream]

You shouldn't have gotten 0.8333 if you typed 144/12 in a calculator

[worn ore]

@wary stream ur in which class ?

Or collage ?

[wary stream]

College

[worn ore]

Ohhh nice

I'm in 11th

[elfin fiber]

Oh sorry

Yeah the other way around I meant oof

[worn ore]

He typed 12/144 I think

Wait

[elfin fiber]

She

Imao

[wary stream]

Did you mean 0.08333?

[elfin fiber]

Yeah

[worn ore]

Lol

[wary stream]

Like there's an extra 0?

[elfin fiber]

Yeah

[wary stream]

Because 0.833 and 0.08333 were two different numbers

[elfin fiber]

I forgot to put it Imao

Yeah

[worn ore]

Sed

[elfin fiber]

Is c 2??

The answer?

[worn ore]

No

[wary stream]

No

[worn ore]

The third part ?

[elfin fiber]

Oh noo

Yeah the c

[worn ore]

Wrong

[wary stream]

Did you do 5/10

Or 10/5?

[worn ore]

Lol

[elfin fiber]

10u= 5

That one

[wary stream]

So what did you do?

[worn ore]

See wait I'll tell u a thing

[elfin fiber]

10/5

Lol

[wary stream]

Wrong

You want the variable by itself

So you have to divide by 10

[elfin fiber]

Yeah

[wary stream]

So why did you divide by 5?

There's not a 5 next to the variable

It's a 10

[elfin fiber]

Ok so

So u do by bigger number?

[wary stream]

What do you mean

[elfin fiber]

So like 10 is bigger than 5

Right

[worn ore]

Do u know the tricks ?

Like

If u multiply

Then on the other side

[wary stream]

No, you divide by the number next to the variable

[worn ore]

It divides

[wary stream]

What number is next to the variable?

[worn ore]

Exactly

[elfin fiber]

Ohh ok

I see

[worn ore]

Take this for reference

Well my camera sucks

So

Sed

[elfin fiber]

Ok

I’m doin it rn

Lol

[wary stream]

Also, repost that assignment because it's buried now

[elfin fiber]

I can see

What

[wary stream]

Because I'm not scrolling back up to just reread the problem

[worn ore]

Btw which stream did u choose in 11th ?

I choose science

[wary stream]

Stream?

[worn ore]

Yea

[wary stream]

I'm from US, we don't pick our path

[worn ore]

Whatttt

Lucky

[worn ore]

So ?

What u did ????

[elfin fiber]

Guys

[worn ore]

Curious ^_^

[elfin fiber]

The answer is 0.5?

[wary stream]

The classes they gave me

[wary stream]

Yes

[elfin fiber]

Yyyayayyyyy

Loll

[worn ore]

I'm from India here they give streams on bases of marks

[elfin fiber]

What is streams?

[worn ore]

Ummm like

It's

This moment of choosing, for students in India, comes after the Class 10 examinations. This is the golden moment of reckoning when a student has to choose between the three streams in which they would further pursue a career – Science, Commerce or Arts/Humanities. ... Commerce. Science. Arts/Humanities.

here

googled it

[elfin fiber]

Ohhh

[worn ore]

it was kinda hard to explain loll

[elfin fiber]

Yeah

Lol

Oh so u she to choose a subject

Or smth like that

[worn ore]

Umm @wary stream I want to know more

[worn ore]

Yz

[elfin fiber]

Why is

6x = 36

The answer is 0.166666667

Wtf

[worn ore]

Yes so, x is the variable u need to find what u should multiply by 6 to get 36

[worn ore]

Wow

U did it opposite

[wary stream]

You did math wrong

[elfin fiber]

Oh noo

[wary stream]

Divide by the number next to the variable

[worn ore]

Plsls

[wary stream]

Not the other way around

[elfin fiber]

Soooo

[wary stream]

Don't clutter a math help channel with off topic conversation

[elfin fiber]

6 by 36?

[wary stream]

No

[elfin fiber]

Omgggg

[worn ore]

oh yeah

[wary stream]

What number is next to the variable?

[elfin fiber]

6

[wary stream]

Divide by 6

[worn ore]

?

36

[elfin fiber]

6?

[wary stream]

Yes 6

You're doing 6x = 36

Right?

[worn ore]

Well do u know like what happens between rhs and lhs ?

[elfin fiber]

Yeah

[wary stream]

Stop trying to confuse the kid by asking what value multiplied by what to get that value

[wary stream]

As I said, divide by the number next to the variable

What number is that?

[elfin fiber]

6

[worn ore]

Y- yes sir

[wary stream]

So divide by 6 on both sides

[elfin fiber]

So the answer is 6?

[wary stream]

If you read the directions, it literally stated opposite operation, and all of those are multiplication, so it wants division, not some other technique

[wary stream]

Yes

[elfin fiber]

Ok

[worn ore]

Yea ?

That's what I am doing too

[wary stream]

But you're saying multiply blank times blank to get blank, that's not the opposite of multiplication.

[worn ore]

No no that's so that I could tell the meaning of that question

Like what's it asking

[wary stream]

It was asking apply the opposite operation to find the variable, and the opposite operation is division

[worn ore]

It is saying what to multiply to 6 to get 36 so if we divide 36 by 6 (36/6) we would get it

It's division

[elfin fiber]

e) is 10
f) is 3
g) is 3
h) is 25
I) is 3
J) is 11
K) is 1
L) is 4
M) is 6
N) is 4

[worn ore]

Pro

[elfin fiber]

Is that right?

Imao

[worn ore]

Did u look somewhere lmao

[elfin fiber]

No

[worn ore]

Those are right tho

[elfin fiber]

I jus used calculator

Imao

[wary stream]

It's all good

[elfin fiber]

Yayyyy

Yesss

[wary stream]

This is just basic math, use a times table instead of a calculator

[elfin fiber]

Okk

[wary stream]

The only difficult one would have been 5/10, but besides that, everything is knowing your times table

[elfin fiber]

Yeah

True

I have some of the word problems

Idk how to them

I’ll do them tmrw

[worn ore]

👌

[arctic wren]

how can i derivate: $6sh -\frac{3s²\sqrt{6}}{4} + \frac{s²\sqrt{6}}{2} +\frac{\sqrt{6}}{2}$ with respect to sh ?

[ocean seal]

Guilhotina

[hushed pasture]

is that multi var calculus??

[arctic wren]

i don't know

and i might wrote the equation wrong

[arctic wren]

i don't see multi var calc and this exercise is at the end of optimisation problems

$6sh -\frac{3s²\sqrt{2}}{4} + \frac{9s²\sqrt{2}}{4}$

is the right one

[ocean seal]

Guilhotina

[topaz scaffold]

Well if you're differentiating with respect to sh you only have the first term there

The rest are constants

iirc

[arctic wren]

ooo ty

so probably i made worng somesteps before this final equation

[elfin fiber]

Ty guys for helping me out

!!!

[white walrus]

If there is a 20% chance that Person A wins a race and 30% chance person B wins a race, then how do you calculate which one wins the race? O_O

[glass lichen]

most likely neither, since there's 70% B didn't win, and 80% A didnt

[white walrus]

Ty.
What if it was 60% and 40%?

[glass lichen]

figure it out yourself

I explained my logic

[topaz scaffold]

You can't exactly calculate which one wins the race...

[glass lichen]

that too

[topaz scaffold]

You can only calculate the probability

[white walrus]

This is kinda new to me T_T, trying to wrap my head around this bit.
How do I calculate the probability? Or is the 40% and 60% already the probability?

Not sure if I'm being an idiot here.

[glass lichen]

clearly 40% and 60% are probabilities

[white walrus]

That's what I thought hmmmmmmm

I need to figure out something a lot more complicated. I guess this direction isn't the right one. Thanks for the replies.

[glad moon]

Could I get some help when someone is available

[alpine sable]

i have a question

how do people know how many years people have watched a video

like The song Baby shark has been played 7.04 billion times

Played back-to-back, that would mean Baby Shark has been streamed continuously for 30,187 years.

like how do you calculate that

[wary stream]

$$\text{Amount of times} \cdot \text{duration in seconds} $$

[glass lichen]

unit conversion

[ocean seal]

dldh06

[wary stream]

Then convert that value to years

[alpine sable]

i dont understand

so lets say a 25 minute video has 1.042.136 views

[wary stream]

Commas or decimal?

[alpine sable]

do i just 25 * 1.042.136

[alpine sable]

million

1042136

[wary stream]

So a 25 minute video is 25 times 60 seconds

[alpine sable]

1500

[wary stream]

,calc 25( 60)

[ocean seal]

Result:

1500

[alpine sable]

,calc 25 * 60

[ocean seal]

Result:

1500

[wary stream]

So 1500 times 1,042,136

[alpine sable]

so 1500 * 1042136

[wary stream]

Is how many seconds have been played

[tame moss]

hello

[alpine sable]

,calc 1500 * 1042136

[ocean seal]

Result:

1.563204e+9

[tame moss]

what rule is this?

[wary stream]

Convert that to years

[alpine sable]

how

well 1500 * 1042136 = 1563204200

seconds

[wary stream]

Online calculator is easiest

[alpine sable]

can u recommend any

[wary stream]

You can Google it, and it converts

So Google 1563204200 secs to years

[alpine sable]

49 years

no idea how it works

[wary stream]

Give me a minute to type it out because I'm on mobile

[alpine sable]

oh ok

[wary stream]

$$\frac{1563204200 \text{secs}}{1} \cdot \frac{1 \text{hour}}{3600 \text{secs}} \cdot \frac{1 \text{day}}{24 \text{hour}} \cdot \frac{1 \text{year}}{365.24 \text{day}}$$

Only thing was I accidentally flipped it

It should be hour/sec

Day/hour

Year/day

[alpine sable]

so 1563204200 * 3600 * 24 * 365?

dont understand

or is it divided

[wary stream]

It should be 1563204200/(3600*24*265)

[alpine sable]

Ooooh now i understand

Thank you so so much

[karmic sleet]

Thank you

[ocean seal]

dldh06

[wary stream]

There, fixed

[alpine sable]

Im gonna save this

but is it just the opposite to calculate years to seconds?

[wary stream]

By opposite, if you mean multiply, yes

[alpine sable]

no i meant like 49 years / 365 / 24 / 3600 = 1536204200

is it just like that

oh wait nvm

[fiery basin]

I forgot how to find the angle of this line. anyone able to help?

[wary stream]

Law of cosines

[fiery basin]

uh

idk how to do that

imma look up a video

[glass lichen]

tan(theta)=m

[fiery basin]

I just got into 9th grade. should I have learned that? because I dont even know what tan or cos is

[glass lichen]

I mean... you should know trig to find the angle

so yes

You need trig unless you want to hold a protractor and be inaccurate

[fiery basin]

ohhhhhhh

i just didnt know what that was

I didnt know what cos or tan was

[glass lichen]

k

[fiery basin]

thanks

[scarlet heath]

just want to confirm

the answer is D right?

because solving for G = -1 and H = 5

and squeeze theorum states g(x) = h(x)

and if that is true f(x) will = what g(x) and h(x) equaled

[glad moon]

In December 2018, the average price of regular unleaded gasoline excluding taxes in the United States was $3.06 per gallon. Assume that the standard deviation price per gallon is $0.08 per gallon and use chebyshevs inequality to answer the following.

1. What minimum percentage of gasonline stations had prices working 2 standard deviations of the mean?
2. What minimum percentage of gasoline stations had prices within 1.5 standard deviation of the mean? What are the gasoline prices that are within 1.5 standard deviations of the mean?
3. What is the minimum percentage of gasoline stations that had prices between 2.74 and 3.38
   Anybody can help?

[wary stream]

Just use the distance formula

[next bridge]

I did i got 12 but it says wrong

[wary stream]

That's already not possible to get. There should be a radical still

[wary stream]

How?

[next bridge]

when i added them together it gave me 12

[wary stream]

Because your rounding is not correct

,w sqrt(26)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dldh06#2659

[wary stream]

That's 5.1 not 5.0

[next bridge]

what about the others? were those also rounded incorrectly?

[wary stream]

Also, for better accuracy, don't covert to a decimal

Leave it as $\sqrt{26}$

[ocean seal]

dldh06

[next bridge]

🤔 mk now what abt the other answers?

[wary stream]

All the others are good

It was just probably the accuracy of your answer

,w sqrt((-5--2)^2+(4-1)^2)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by dldh06#2659

[next bridge]

so the answer would be 4.24?

[wary stream]

As I said, keep the radicals

[next bridge]

OH

uh

[wary stream]

So $\sqrt{18} = 3 \sqrt{2}$

[ocean seal]

dldh06

[next bridge]

soo i got 8.12 as the answer

😔

[wary stream]

For what?

[next bridge]

for the perimeter

[wary stream]

But how?

[next bridge]

i added all the radicals together

[wary stream]

If you have a side that's 5 and 4, that's already more than 8

[next bridge]

bestie idk i been stuck on it since morning

try to solve it

and tell me

what u get

if u want

u dont have to

😩

[wary stream]

I'm not telling you what the answer is, I'll confirm if you're answer is correct after you get an answer

[next bridge]

Ig

Well

i got

8.12

[wary stream]

As I said, that's not it

Because if $\sqrt{26} \approx 5$ and $\sqrt{18} \approx 4$, that already adds up to more than 8

[ocean seal]

dldh06

[alpine sable]

Is this channel busy

[wary stream]

Yes

[alpine sable]

okie can u ping me when it’s not?

[wary stream]

No

[next bridge]

hmm

[alpine sable]

Smh 💀

[wary stream]

So if 2 sides already is greater than 8, that means your answer is not correct

[next bridge]

Ya

so what did i do wrong?

[wary stream]

What did you type in the calculator?

[next bridge]

i typed 5+4+2

i took out the decimals

[wary stream]

Keep the decimals for more accuracy

[wary stream]

Use sqrt(26), sqrt(18), and sqrt(8)

The reason your answer isn't correct is it's not accurate enough

[scarlet heath]

is this channel still busy

[next bridge]

yes

[wary stream]

,w sqrt(8)+sqrt(26)+sqrt(18)