#help-0
1 messages · Page 779 of 1
Like with the values given
And trying to abstract it so instead of 2500 it's just "d" as a distance
Right, you can replace 2500 with d for the distance between Frisco and Kansas City.
You don't need any other values.
Well, I guess you can use the times.
Let the distance from Frisco and Kansas City be d. Let f(t) be the distance traveled from Frisco to Kansas City on the first trip and g(t) the distance traveled from Frisco to Kansas City on the second trip, where t represents time.
f(8:00 AM) = 0 and f(5:00 PM) = d.
g(8:00 AM) = d and g(5:00 PM) = 0.
Then, f(8:00 AM) - g(8:00 AM) = -d and f(5:00 PM) - g(5:00 PM) = d.
0 is between -d and d
So by the IVT, f(t) - g(t) must equal 0 at some t in = [-t, t]
Then at some point the busses cross (the distance between them becomes zero) at some time t.
I feel like I messed this up a bit 
t from 8 to 17
f(t) - g(t) is continuous
f(8) - g(8) = -d
f(17) - g(17) = d
0 is between -d and d
Oh, you're fine.
The only thing is t ∈ [8 AM, 5 PM]
Since t isn't a distance.
You'll want to define f(t) and g(t) better.
They're both the distance to Frisco at time t.
f(t) is the distance to Frisco at time t on the first trip.
g(t) is the distance to Frisco at time t on the second trip.
Sorry, from Frisco, not to Frisco.
The distance is between two points, so the distance from Frisco to Kansas City, if those are the two points, is constant, so you don't want to use that definition.
If it's the distance from the bus to Frisco, that isn't constant.
The only place I am getting hitched up is physically interpreting f(8:00 AM) - g(8:00 AM) = -d
Well, what's f(8 AM)?
The distance from Frisco at 8 AM on the first trip. So 0.
What's g(8 AM)?
The distance from Frisco at 8 AM on the second trip. So d
What's f(8 AM) - g(8 AM)?
Well yeah, 0 - d = -d. But what does that mean physically? 😅
It's a negative distance so I guess it's meaningless physically
Only a quantity that exists within the mathematics necessary to get a solution
But I can';t help but feel like there should be a way to visualize it
It's how much closer the second bus is to Frisco than the first bus.
The second bus starts out as -d closer than the first bus.
Or d farther.
OhH!!!!!!!
Wow thank you so much
I think I'll have to rewrite it once or twice more but this makes a lot more sense
You're welcome.
So I have the correct answer
however, apparently theres an issue.
I ended up messaging my professor
and this is what he said
Right, you took the limit.
so essentially would my answer end up being
What's f(x + Δx)?
(x+h)^3
Yes.
Thanks, wanted to make sure since I only have one attempt left.
Make sure to use Δx.
I really hope this works out... I hate the awkward notation for change in x
would be nice if it was represented by h or just delta
9x^2+x^2=15^2
why am I not allowed to sqr root both sides of the equation and end up with
9x+x=15
i am dying
got it right, thanks chai
You're welcome.
@shrewd prism Powers and roots don't distribute over addition.
First combine like terms.
so if I did 10x^2=15^2 then I could sqr root
Yes.
You're welcome.
10x^2=15^2
x^2=1.5^2
x=1.5
this is wrong right? ^
10x^2=15^2
x^2=(15^2)/10
x^2=22.5
x=sqrroot(22.5)
Yes, it's incorrect. The second one is correct.
But there's a catch.
x² = 22.5 has two solutions.
ohhh right the + and - thing right
Right.
ok ty
ok tysm
No problem.
and subtraction right?
Right.
so if I had 3x^2 * x^2 =...
could I square root it into this?
sqrroot(3)x*x
wait no I need to square root the 3
Yes, if you do the square root on the 3.
Powers and roots distribute over multiplication and division.
hmm ok tysm for all ur help
You're welcome.
I didn't know about this until now ;-;
Sorry to bother you Chai, but I assume this problem is incorrect due to a similar issue. But I'm not given a deltax to work with which is confusing me.
What would I do here?
What's f(x)?
o right so if I had 3x^2 +y^2 = ...
can I still sqrroot the whole equation?
I meant + oops
Oh, OK.
You could, but you can't distribute.
sqrt(3x² + y²)
Square root of the whole thing.
Not sqrt(3x²) + sqrt(y²).
right so sqrt(3)x+y?
huh what's the difference
The difference between what?
(x)^3-9x
@harsh belfry What's f(3)?
(3)
Yessir
Would it not be written like this?
would I be able to distribute a power/root on an equation with 2 different variables on one side at all?
@shrewd prism If they're multiplied or divided.
Powers and roots distribute over multiplication and division.
Perhaps?
Im confused
You're welcome.
Right.
What's f(x) - f(3)?
x^3-9x
Chai T. Rex
\[\frac{x^3 - 9x}{x - 3}\]
Factor the top.
If I factor the numerator it should be x^2+3x
x?
Chai T. Rex
ahhhh
Then you factor x² - 9.
then cancel the x's
No, you can only cancel whole factors.
There's no factor of x on the bottom.
There's a factor of x - 3, but that's not x.
So factor x² - 9 on top.
no
Right, you can't do that because x - 3 is a whole factor.
x isn't on the bottom as a factor.
You can only cancel factors.
Factors are things you multiply, not add or subtract.
On the bottom, the only factor you have is x - 3, not x.
x isn't multiplied by something on the bottom, so x isn't a factor.
Does that make sense?
x is multiplied by something on top.
It's a factor there, but not the bottom.
So factor x² - 9.
at fisrt, when i was learning i did the same thing😆
No.
am I doing something wrong
@harsh belfry do u know to find zero of polynomial?
With a difference of squares, you have something squared minus something squared.
It's a difference of two squares.
Does that make sense?
You can’t factor out if there is a plus/minus sign @harsh belfry
I really really don't understand anything right now.
isn't there something about (a+b)(a-b) right
I don't know what to say
about quadratics or something
1 method is that u could try to find the values of x for which x^2-9 is 0
yeah
yes
omigosh right ok
x² - 3² is a difference of squares.
It's the difference (subtraction) of two squares.
Does that make sense?
(x+3)(x-3)?
yes
waw ok ty
So, we have x² - 3².
yes
I'll have to look into it more on my own to make sure I understand this
but I get the premise
16?
No, factor it.
(5)(5) - (3)(3)
@harsh belfry different language, but look at the bottom one
Do you remember how I showed you to factor a difference of squares?
a² - b² = (a + b)(a - b)
We have 5² - 3².
How do you factor that?
(5+3)(5-3) if I'm following the format
I do
OK, so x² - 9 = (x + 3)(x - 3).
Chai T. Rex
Now we have three factors on top.
We have one factor on bottom.
Can we cancel one of the factors on top with the one on bottom?
would x-3 on the top and bottom cancel out
x^2+3x would be our answer
I never would have been able to do this holy shit
u will be
Well, if you practice on some more problems with maybe some help when you get stuck, you'll be able to do it.


The length of a rectangular magazine is 8 cm more than its width and the area of the magazine is
240 cm2. Find the dimensions of the magazine.
How is this question quadratic?
you wrote $5^{\ln_5(2)}=5$. this is incorrect
Sneaky
yes
thank you
Have you tried to solve this?
no because i dont know what to do
Okk do you have any idea about derivative?
Take the derivative of given equation then find dy/dx , at value (7,1) find the values of dy/dx ( that will be slope of tnagent) now use point slope form find equation of that tangent ,same for (-1,5) ,
When you get two tangents just find the point of intersection by elimination,or other mehtod you line
is finding derivative the only way to solve this?
I know this method ,but wait for someone ,they will help
bcz my teacher teaching circle without derivative
Write equations of tangents at both points and find intersection of both
Okk let me check
You can get the angle to the point.
From the center of the circle.
Then the tangent of the angle is the slope to from the center to that point.
center (2,1)?
And then the tangent line is perpendicular to the radius line.
Write equation of (7,11) and (-1,5)
And (7,11) and (-1,5)
Substitute in equation of circle and show that D=0
D= discriminant = b²-4ac
So, the slope you got for the radius line, you take the negative reciprocal of it.
@alpine sable Yes.
So, let's find the radius slope from center (2, 1) to point (7, 11).
Rise is 10, run is 5.
Slope is 2.
Tangent line is perpendicular to radius line.
what is rise and run
Do you know how to find a slope?
no
Do you know how to find a gradient?
no also
OK, so the slope is how far it goes up over how far it goes right.
The rise over the run.
So, from (2, 1) to (7, 11), it goes up 10.
It goes right 5.
OK, so that's the radius line slope.
The slope of the radius from the center to that point.
Now a tangent line is perpendicular to a radius line.
A perpendicular slope is the negative reciprocal.
2
-2
-1/2
See how I took the negative, then the reciprocal?
im confused
Yes
@alpine sable Where are you stuck?
all

can i check that the limit for 1/x^2 as x tends to 0 doesnt exist? or is it + infinity
even though the both the left and right side tends to (same value) infinity
When do we say that the limit exists?
Go look up "when the limit exists" real quick
the limit can be represented as +inf but technically the limit doesn't exist as +inf isn't a number
I think we can if we work on extended real line.
when the left hand side limit = right hand side limit
oh
And does it?
Example when it doesn't: 1/x
ya it does to +infinity
but.i think ramonov said it isnt a number
Existence of a limit is a technical question with respect to this definition
as far as I'm concerned
Infty is not a number, of course, but at least it's the same for right- and left-sided limit
We say DNE for cases like 1/x, x to 0, and +INF for cases like 1/x^2, x to 0
For infinite solution a1/a2=1/b2=c1/c2
Is there a method for 1 solution and no solution ?
Why z
That is variable
Oh you are right
Thank you so much
Hmm so it is a no solution right ? @split oriole
Oooh got it
anyone knows what I'm supposed to do here? I kind of don't get it
Is this a test?
nopee, my test is next week
Well the first problem, what does P stand for?
that's what I don't know. They were written like that without any further explanation
I don't even know where the numbers came from
huh
P is population
t is time in years, since time is the only thing that the population depends on
In this problem
It doesn't matter, they ask you to find years, years is time "t"
You wanna find such t that P =....
That P=48
Which leads to the equation
P(t)=48
Solve for t
Get years needed
Oh yes, put t=0 for your interest, you'll get the initial amount of goats, when 0 years have passed
ayt ayt thank youu so much
I have figured upto that number of sylow 2-subgroups will be 1 or 3 and the number of sylow 3-subgroups will be 1 or 4. But I don't know how to determine the exact number of those two sylow p-subgroups.
Here Z 24 is cyclic ,so every subgroup will be normal
Now use this fact
For any general series tests
First question to ask yourself:
"Is it alternating?"
Second question:
"Is the limit to 0?"
Third question:
"Can I integrate it?"
It isn't alternating.
Limit is obv 0.
It looks integrable
Integral test is a winner here
@placid zinc That’s a very useful suggestion. Got it! Thanks~
@placid zinc can u help pls
if I have how does it go from that to that
√3 + 2√3 - 4 / √3 + 2√3 + 4
3√3 - 4/3√3 + 4
So, I figured that number of both the sylow 2-subgroup and sylow 3-subgroup will be 1 since they will have to be conjugate of each other. Right?
So, I think this answer given in the book is wrong, right?
hello
Hey
are you trying to ask
how does this √3 + 2√3 - 4 / √3 + 2√3 + 4 become 3√3 - 4/3√3 + 4?
yes
(x+a) (x+b) formula?
no
no :/
√3 is simply equivalent to 1 * √3 which is 1√3
ohh
1 * any value will return the value itself right? eg. 1 * 10 = 10, 1 * 100 = 100 etc.
yea so √3 + 2√3 - 4 is basically = 1√3 + 2√3 - 4 = 3√3 - 4
of course you dont have to show the 1√3 part if you know how it works
oh ok
what do you mean become only 1? it becomes 3√3
i meant
after adding 2
yea
but what abou √3 + √3?
√3 + √3 is 2√3
but now the qn is asking 1√3 + 2√3 so its 3√3
okay how about this
you know factorization?
1√3 + 2√3 = √3 (1 + 2) = 3√3 * factor out √3
Hey there! The path to fail is dead. @dense carbon
The equation is clearly wrong. The right hand side will be 5√3 - 4/√3 + 4.
how do i use the second statement to get the qn in the first sentence
i initially tried to change it to sin5x/5x * 5x/sin4x but it doesnt work
i could use the double angle formula but i think the qn wants us to use the second equation
divide and mulitply num by 5x and divide and multiply denominator by 4x
oh right yeah
i get (1)(5/4)

If my rate is 20kPa/min do i have to convert to seconds? If so, how? Cause Pa = kg/m.s²
What rate?
20kPa/min
multiply by 1 for unit conversion. eg multiply by min/(60 sec)
See you need to convert into seconds?
See that what you want?
Rate is 20kpa per minute and if you want in seconds just divide it by 60; 20/60 = 1/3kpa/sec
@arctic wren
Tyy
Yea np👍
im new to the course im doing i know its low level for u guys
dont rinse me lmao
have you ever done things with composition of functions before?
how does this simplify to n+2/(n+1)! as i am getting the answer of n+2/(n+1)n!
have you plugged numbers into functions before?
@chilly tide channel busy please move
yes
to which one
iv plugged into function before
okay, so you know that, for example, f(42069) would be just 10 + 42069
but not this level
@chilly tide any one that's free right now
yeah!
ok
we all overthink things from time to time
well thanks hahah
because (n+1)*n! is (n+1)!
(n+1)n! is (n+1)!
ye i kinda figured out indirectly when i substituted n=4
i dont understand how you know just by looking at the statement but it is true
Because 5!=5 x 4 x 3 x 2 x 1, which is 5 x 4!
if n is 4 you would multiply 5 to 4 factorial that is n +1 to n!
n! is n * (n-1) * (n-2) * ...... * 3 * 2 * 1
(n+1) * n! is (n+1) * n * (n-1) * ..... * 3 * 2 * 1 which is (n+1)!
It's the concept of instant conversion of higher factorial into lower factorial
Practise questions to get mastery of this concept!
By shortcut method I know answer is 3/2
But I want to know if this question of mine when asked in exam, how am I supposed to solve it with proper method which doesn't require me to use binomial expansion
divide numerator and denominator by x^10
^
they're clearly both tenth-degree polynomials, which hopefully is obvious without any expansion
Still infinity by infinity form
???
X to the power 10 will be cut in denominator but what about those binomials..
(x+1)^10/x^10 = ( (x+1)/x )^10 lol
Well, once you divide by x^10, they will be simplified
you will have $\frac{(1 + \frac1x)^{10} + (1 + \frac2x)^{10} + (1 + \frac3x)^{10}}{1 + (1 + \frac3x)^{10}}$
Ann
That is clean latex
Oh
Power is same so they come within bracket
And then it becomes 0
Wow it was easy thanks
a committee of four is to be selected from 10 candidates, 5 men and 5 women. Assuming each candidate is equally likely to be selected, determine the probabilities that the chosen committee contains: i) no women ii) two men and two women
10C4?
That is the probability
no it isn't captain_mat01
I checked the answer on my textbook its 1/42
I just dont understand how they get it
10C4 is the total number of committees possible
Ive never seen probability in permutations and combinations question
Probability gets me everytime
qweb, what you have here amounts to choosing a committee at random from the 10C4 possible committees that could be formed
so the (favorable outcomes)/(total outcomes) formula can and should be used
alr thank u so much
any idea why this dosent work?
x=1/9 gives different values for each side of the equation
If I wanted to find the speed at any point in time of a car ride. I would take the derivative of a function of distance and time. How would I plot that function of distance and time?? Would I plot the point at each second and connect it like a peicewise function? Or would I use splines to approximate it? How would this be done?
it does work for sqrt x = -1/3
,w 7(-1/3) + 9 = 10(-1/3) +10
it doesnt if u take into account negative sqrt
hmm okay, thanks for the help !
np
i got a question on an assignment and i forgot like everything about radical functions over the summer, heres the question
60ft/sec = sqrt( 2(?)(32.2ft/sec^2) ) | solve for the (?)
im not sure how to handle the 32.3ft/sec^2
inside the radical
this is the full question https://i.imgur.com/aIyPZCY.png
here is what i think the function is https://i.imgur.com/ZSgDFm0.png
square both sides
solve for h
oh yeah thanks a lot, i forgot like all the simplifying stuff for math
np
Oh
9^(3 + 9^333)
what is the last 2 digits of this
some nerd got this
however I got 29, simply because it seems all powers all 9, 9^x where x is 3 more than a multiple of 9, seem to end in 29
I now realise 81 is the correct answer
10+g(x)
1 fuck off
2 no
i need help with m e math not ur discord nitro shite
(1 + x)(3 - x) + 12 i think
since it's just g of x but with 10 added after
you could expand it to make it simpler
Yes
Yes
thank you
Hi everyone, I was studying a maths course when I came across this section which detailed Addition and Multiplication on the vector space R2.
The first operation, addition, looks like vector addition
However, the second, I have never seen before.
I was wondering if anyone could help enlighten me.
idk if there's a name but they are just defining an operator
their "multiplication" operator does what it says it does
it's probably gonna ask to prove that's a vector space or something
Right,if I am not mistaken, the second one looks like it's asking to multiply 2 vectors . From recent memory, multiplying two vectors are usually either vector or dot product . So when this turned up, I was super confused.
it's called a binary operation if it doesn't define what the operator is
it's a newly defined operator, yeah binary operation
they are arbitrarily telling you what to do if you see v_1 • v_2
what topic is this? looks like advanced algebra
Undergraduate Maths
I think it could be classified under abstract algebra?
Has to do with fields and groups. This photo came from a section called complex numbers, specifically where they are building the complex numbers from group and field axioms.
ah yes, it's algebra then, and R2 is a set where the elements in your case, are (x1, y1), (x2, y2), and the elements x1,x2,y1,y2 are elements in R. hope this makes sense!
how would I calculate the length of the function cosh(x) from a different x points?
specificly these 2 marked points
you mean the arc length right? there is an arc length formula integral sqrt(1+f'(x)) dx from point A to point B
so your function will be integral sqrt(1+sinh^2(x)) dx from x=-10 to x=10
,w integral sqrt(1+sinh^2(x)) dx
Yup, it makes sense. Although, my main confusion came from seeing two elements in R2 being multiplied together to produce another coordinate.
To the best of my knowledge, R2 is a vector space. It's home to all the coordinates on the normal x and y axis.
These coordinates can be treated as vectors.
The vectors can be added in this fashion which is similar to the first
statement in the first picture I posted.
However, I have never seen two vectors which can be multiplied together give another vector, besides vector product, but those usually use 3D vectors and return 1x3 vectors (3D coordinates).
That's multiplication of C 
This
I didn't expect it to be so big...
sure enough, their R^2 is really just budget C
hmm why does it look like that
oh it has to be sqrt(1+(f'(x))^2)
@serene linden that's from John Conway's functions of one complex variable
wait it is that
That's one of the many ways to define the field of complex numbers
Is the integral a difficult one?
cause it says undefined...
,w tanh(10)|cosh(-10)|-tanh(-10)|cosh(-10)|
Oh, so does that mean that these two operations are specific to complex numbers only? Sort of like properties?
oh i see, you have a
What do you by ''specify'' in this case?
Yeah so
R^2 endowed with this product + vector addition of R^2 makes it a field
and in fact
ah yes. good spot! i forgot about that
if you mean ''specify'' in the sense that this field is now isomorphic to the algebraic closure of R
Then yeah
I have just never seen two R2 coordinates get multiplied to give another coordinate in R2 in this way before so it was kind of confusing
yeah so, this multiplication really defines C
Oh
This comes out intuitively
So
You already know that the field of complex numbers
Is really just adjoing to the real numbers
an element called i
such that i^2 = -1, right?
And with this
We can usual algebraic manipulations such that this forms a field
Now
Let's do the following
Sorry to interrupt, but this photo taken from further down the notes, is more familiar to me, especially the multiplication bit. Perhaps this has something to do with the previous photo, just that I can't see the connection?
Given $x_{1}+y_{1}i$ and $x_{2} + y_{2}i$ both in $\mathbb{C}$, we know that $(x_{1}+y_{1}i)(x_{2}+y_{2}i) = x_{1}x_{2} + x_{1}y_{2}i + y_{2}x_{1}i + y_{2}y_{1}i^{2} = (x_{1}x_{2}-y_{1}y_{2}) + (x_{1}y_{2}+y_{1}x_{2}) i $
\
\
If we interpret the imaginary part as the second coordinate, we get that
$$(x_{1},x_{2}) \cdot (y_{1}, y_{2}) = (x_{1}x_{2}-y_{1}y_{2}, x_{1}y_{2}+y_{1}x_{2})
$$
MisterSystem
Can you see it now?
You have seen
when you learned about complex numbers
Did your teacher talked about polar form?
And how complex numbers can be identified with points in the plane?
Is that the same as polar coordinates, basically representing real coordinates (x,y) as (r, theta)?
Yup, imaginary axis replaces y axis.
yeah
exactly
I see the connection between your explanation and the imaginary axis, and I am guessing that this image is a more formal way to define the imaginary axis. However, how does it connect to polar coordinates?
I just mentioned polar form
Because I think people recognize this geometrical interpretation of the complex numbers
More easily
When talking about polar form
But ofc, this is connected to the polar form.
This lecture is part of an online undergraduate course on complex analysis.
We review the basic arithmetic of complex numbers, and given some applications to some problems in number theory related to sums of two squares. At the end we briefly cover the quaternions.
For the other lectures in the course see https://www.youtube.com/playlist?list...
This video is really good
It introduces C at the beginning
Using this construction
give it a check if you get interested
Got it. Thank you for helping me clear up the confusion and for the references/resources. 🙂
Np 😄
try drawing a picture maybe?
lmc

so just from the picture and idk if this helps
but you can get uhh
oh im not gonna type that
nah theyre not trivial usually
well they are and they arent
but you do have to keep trying stuff
lemme try scribblin
oh, nice
$P(A \cup B) = P(A) + P(B) - P(A \cap B)$. But $P(A \cap B) = P(A) \cdot P(B)$ since they are independent events.
\
\
Now use the fact that $P(A) = 1 - P(A^{c})$ to conclude that $P(A) = \dfrac{2}{3}$
MisterSystem
Can you continue from here?
There is a mathematical approach that mistersystem stated and that was exactly what I did
All you have to do now is find P(B)
Which you should be able to do since you know P(A \cap B) = P(A) P(B)
nice
is there a mistake in this?
the answer integrates 2 and the -8/sqrt(3x+4) terms independently. so the du occurs only on the -8 term
but why do i get a different answer if i consider both the terms together
oh..
What do you exactly mean by this part?
the answer kinda does this way. splitting the integral for both terms
i am considering them together and then solving
well hello there
hi
What if x=0 
this channel is already occupied by me. please take another channel
i don't think so but I'm dumb so
Alright i thought you finished
just replace x with a number and find out
It actually is true
not yet
thanks
have a good day too!
can anyone point the mistake in this approach?
u need to sub in the x values again
so it would be 2/3 (3x+4) - 16sqrt(3x+4)/3
but the answer is 2x - 16sqrt(3x+4)/3 + c
you can split the integral
and first part is 2x and you can use u sub for the rest
but why does not splitting the integral result in a completely different answer?
u couldn't get this answer right?
yeah true
x should not be equal to 0 loul
<@&286206848099549185>
x gets cancelled, so it's 4/1 now. So it's practically true
how does that apply here?
however, by this logic, collectively doing it must lead to the correct answer (which is not the case here)
oh ok. but my q is why does collectively doing it lead to the wrong answer?
however i think i have definitely seen cases where my approach works correctly (just not in this case)
take another channel
there is ongoing discussion
hmm ig
yeah
just remembered i had called helpers earlier. helpers, forgive me lol
Can removable discontinuities still form vertical asymptotes?
Let h(x) = f(x)/g(x), where f and g are polynomials. There are three zeros of g, one of which is a zero of f, but if we factor f and g, we can cancel this common zero. So if we remove the common zero then our number of vertical asymptotes should just be 2 right?
Let me try it in Desmos
Ah yeah it seems you're right
@unkempt hatch can you repost your question and issue you're having
sure
It doesn't really matter if you split the integral here
basically, my q is what's the mistake here?
but it's leading me to a diff ans
you forgot the +C and where's the rest of your work
wdym by the rest of my work
well the original integral is in x
your current result is in u
your final result should be in x
u just substitute u as 3x+4 right?
basically this
don't forget about the constant of integration
hello
ohk, even with adding c my answer is not correct
note that 2/3 (3x+4) can be expanded
and the sum of constants is just another constant
ahhhh ok. so when i expand and get +8, it just morphs into +c (in the case of the correct answer: 2x - 16sqrt(3x+4)/3 + c)?
please take another channel. this is occupied
yeh pretty much. you should reach the same result.
Is this channel occupied?
Cool
What is unique factorization Theorem and product notation
M2.3
I know all of it but that just sound weird
Is that the factor^2 (or the number the factor repeated)
What is that
I have never seen this sign before
And How exactly can i use this without a calculator
Yeah
This is a specification for exam without a calculator
Can you please tell me what 2n say and why n=1 and why 10
And what to do if there is somthing on the left
Like 4-
Or -2
You're multiplying 10 different numbers, and they follow the pattern of 2n, when you plug n = 1,2,3...9,10
So the 10 is 10 numbers, 2n is how I progress which is multiply the previous number plus 2 and n=1 is the start point ?
Alright
So what's the upper bound ?omg I feel so stupid
Is it upper and lower bound
so for this question, u start from n=1 and u stop at when n=10
Yeah I understand that but lil is saying somthing different I think
I said there 10 are 10 number where you multiply
So what are you trying to say
What's upper bounds
No
It is the sum of numbers
It is the sum of numbers you multiply
why are you using the word sum here
The word is product
if the lower bound n=5, and the upper bound is 10, you’d start at n=5 to n=10
-2 is being multiplied to the whole thing
But how can I get the pattern here
The next one will be 3×what ?
9?
Guys?
Sorry
Why we added 1
The first one would be 3×3-1 you made the second one 3×4-1
so we’d go from x=3 to x=4 to x=5 ... until u get to x=7
Why ? How did you know that
He didn't say n+1
by definition of the notation
Who said x should increase by 1 every time why not two
What definition
What property why you assume I know that
have you done stuff with summation or sigma notation before?
No
I don't remember
Where can I get the basics I need
look up summation notation for the bare basics of this type of notation
Wait a minute I only saw the sum sign in A level biology
Nah I finished it with A*
No just the biology
You can take it as one year
No you can choose
It's A level as and a2
A2
Yeah
You can do it in one year
A level maths doesn’t do the sun sign
Only further maths
Apart from statistics tho
For maths statistics is part of it
Which kinda sucks
I suppose, but the a level module makes you memorise the damn sampling techniques
how do you choose which one will be -lambda and which one will be +lambda?
in the 2 ode that you make, one will have positive coeff, the other will have -ve coeff
so one sol will have sine cos, and the other sinh cosh
Do you have any articles you suggest or videos
Khan for basics
Prof Leonard for more depth
Yes
Partial DE
Alright thank you
Ummm youtube is so confusing
Do you have any part of a text book that explain it
the explaination/notation should be pretty simple
still not sure what your issue is with understanding it
I just want to be academically aware of details
Videos on YouTube don't even mention the terminology
what videos are you watching
I finished the khan academy 3 min video and now watching the organic chemistry tutor
They look like explaining it just for fun not for exams
How would expect the explaination for exams to be different?
Org Chem is pretty good too
Like in text books contain the slightest details and the people who wrote are expert in exams so they know hoe to portray it from the beginning with suitable terminology to the academical level needed for exams
We all know youtube is just an extra thing it can't be the main
what's the sun sign?
@alpine sable British Mathematics Syllabus is an absolute pisstake
🌞
Sigma does not look like the sun 
Yeah so it's signa
if you're not satisfied with what YouTube provides, do you have a textbook with such explainations?
No I am asking you if you know any
generic math textbook or #book-recommendations
but it really feels like you're trying to overcomplicate things
It's in M2.3
I need to know concepts and vocabulary of product notation and unique prime factorisation
and like I mentioned, product notation shouldnt be that hard to grasp
$\prod_{n=1}^{4} n$
ℝamonov
e.g the above would represent
1 * 2 * 3 * 4
So product notation is like sigma notation but *
yes
8^7 ?
Yes
My calculator has no product notation
WHy did he add 0x?
This channel is occupied
As you see
SO i dont udrestand from where this 0x are gotten
simplify by hand
So what about unique prime factorisation
What does it mean
expressing integers as a product of primes
Yeah we need the unique way of it
e.g 6 is the product of the primes 2 and 3
hence its unique prime factorisation is 2 * 3
That's just the prime factorisation and I know I
It
What is the unique prime factorisation
The prime factorisation is inherently unique
unique is an unnecessary word being added on
But in M2.3 it said prime factorisation once and another time unique prime factorisation Theorem
Use the concepts and vocabulary of prime numbers, factors (divisors), multiples, common
factors, common multiples, highest common factor, lowest common multiple, and prime
factorisation (including use of product notation and the unique factorisation theorem)
well the unique prime factorisation theorem just states that the prime factotisation is unique
Why is it in unique please involve concepts and vocabulary
unique as in there is only one
there is only one prime factotisation for each integer greater than 1
I looked it up and that's really disappointing
It's not unique
What next?
-x/xˇ3 = xˇ-2
correct?
It is not root))
not sure what you mean
they introduced all those terms with 0 to keep terms aligned and so that you don't make mistakes like what you just did
in fact I don't even know what you did
$ax^m - bx^n \neq (a-b)x^{(m-n)}$
ℝamonov
yes
Why he keeps those
note how in their work all their terms align nicely
so when they're doing subtraction, they're actually subtracting like terms
well depending on your divisor, you may not know if they're needed.
but in general you should do it anyway
So, when he subtracted first 0x with power term, the others delete after that?
uh huh...and?
So, when he subtracted first 0x with power term, the others delete after that?
wdym by others 0x
what is wdym?
wdym means what do you mean
0x are the terms he added to ease this problem
so i asked
Whe he did 0xˇ3 -3xˇ3
Others are romved after that_
?
you were being unclear by not writing the power
gaps are implied to be 0
the terms are already in the first row to indicate the powers of each column so it is unnecessary to write them out every single time
the main purpose of writing them at the start was to keep everything aligned
where is what needed?
It's quite common in math courses
multiply by pi/180°
yeah but can u tell me why it's like that
because of the unit circle?
and I also need the formula for vice versa
2pi because of the circumference of the unit circle and there is also 360 degrees there
pi means half the circle, which is also 180 degrees. 1 degree is therefore pi/180
180 pieces of pi makes a pi
180 degrees make a pi u mean?
but i don't understand the formula tho