help-0

[real quartz]

my bad

i mean

horizontal

[eternal spindle]

oh

why so?

[real quartz]

just think as deg1 / deg2 doesnt have it

🙂

[eternal spindle]

1/x has

[real quartz]

so in your case, b is equal to 0

1 isn't deg1

x is

[eternal spindle]

but deg 1/deg 2 can be 1/ deg 1

[real quartz]

why not just simplefly your excersise by letting b = 0

that way we can make the limits easier

now think

[eternal spindle]

also, the curve is like this, right?

[real quartz]

if the limit became the form 1/(ax+b)

how could it have at least an horizontal asymptote equals to 1

becase lim x to inf of that limit is equal to 0

[eternal spindle]

ya

[real quartz]

so our only option is that

make that form in the excercise become (ax+b)/(cx+d)

$f(x) = \frac{x+1}{x+2}$

[ocean seal]

mickey

[eternal spindle]

ya u right

[real quartz]

now you can find g(x) now yea

[eternal spindle]

yay

thanks

that was some cool functional analysis

[alpine sable]

Help

[hybrid moon]

I’m struggling what to find next

[alpine sable]

help plzzz

Plsss

Help

question? @alpine sable

what is the question @alpine sable

[alpine sable]

Find the area of the triangle

$(4n - 8)*(4n + 8) * 0.5$

[ocean seal]

Shaky

[alpine sable]

?

16n^2 + 32n - 32 n - 64
(16n^2 - 64) * 0.5

That's what I put?

does it say what n is?

[gray isle]

@hybrid moon what do you have atm

did you manage to find the side lengths of your rectangle ( in terms of x)

[slender girder]

guys i am looking for a good book to study multivariable calculus

please help me

[alpine sable]

@alpine sable ??

[alpine sable]

ah?

Sorry

[hybrid moon]

Only that one length

[alpine sable]

What were you saying?

[tranquil parcel]

Stewart is fine, spivak is more rigourous

[gray isle]

which length?

y?

[slender girder]

ty ty

[hybrid moon]

10/16y

[alpine sable]

does it say the value of n?

[slender girder]

https://www.amazon.com/Multivariable-Calculus-James-Stewart/dp/1305266641 @tranquil parcel wat do you think?

[alpine sable]

It has no value

[tranquil parcel]

Too expensive, go for spivak

[gray isle]

where's 10/16y coming from?

[slender girder]

i am about to pirate

[hybrid moon]

Omg

Isn’t X proportion length 10/16y

[alpine sable]

then the answer should be (16n^2 - 64) * 0.5

4 minutessss

[gray isle]

And this is becoming a cesspool of question spam again as usual

[alpine sable]

Thankssss

[wary stream]

Don't give out answers

[alpine sable]

I'm not even sure if it's correct lol, but can't that be simplified more?

[tranquil parcel]

8n^2 - 32

[gray isle]

@hybrid moon let's move to #help-3

[alpine sable]

K, is that the answer?

[wary stream]

Did you not see that I said no to give out answers?

[tranquil parcel]

Oh sorry

[wary stream]

The goal is to help people, not give out answers

[slender girder]

bruh my library is bad

[alpine sable]

Lol

[slender girder]

i see 0 helpful book

[tranquil parcel]

Area of triangle = 1/2bh

[tranquil parcel]

base and height are given

So carry out the multiplication

[alpine sable]

don't you need a value for n or can you just do it in the way i did it?

[tranquil parcel]

If it’s not given then you have to leave it like that

[alpine sable]

okay

[slender girder]

guys i need help again

i am looking for a good discrete math textbook

[wary stream]

Ask in #book-recommendations

[slender girder]

sounds like a better idea

ty

[halcyon matrix]

Hello, I need help with a past exam question. I have read the mark scheme but still don't quite understand the method:

[upbeat bloom]

Is <Z, *> a cyclic group?

[halcyon matrix]

How do I go about this estimation?

[jolly stone]

you can look at the slopes P_young/P_old on the scatter plot with 17 data points, and find the range of the highest slope and lowest slope hold on let me reread the question
looks like there are 2 groups of k, representing 2 values of k
you can estimate the value of k for each data points in both groups, no need to be exact

what have you done so far? dimensional analysis basically is substituting the dimensions and work out what the final dimension is

[raw nexus]

yeah i dont understand

i havent done much

im not sure where to begin

[jolly stone]

rho = density = mass/volume, so kg/m^3

velocity V is m/s, and area A is m^2

and K is a constant so no need to do anything

[raw nexus]

okay

[jolly stone]

you can substitute only the dimension to K rho v^2 A

so it's kg/m^3 * (m/s)^2 * m^2

im assuming M L T is mass, length, time i guess?

[raw nexus]

yeah

[jolly stone]

yep from now on it's just algebra, you can continue from this

[raw nexus]

could you help me abit more please

[jolly stone]

what are you stuck on?

[raw nexus]

yeah the algebra

my worst nightmare

[jolly stone]

ok i fixed to M/L^3 * (L/T)^2 * L^2

[ruby seal]

Can someone tell me what topology is ?

I need definition please

[jolly stone]

you have M/L^3 * L^2 / T^2 * L^2

you can expand (L/T)^2 = L^2/T^2

[wary stream]

Google it

[ruby seal]

I did , but i didn't find the definition i was looking for

[raw nexus]

(L/T)^2 = L^2/T^2 so L=0?

[ruby seal]

I only remember that it was related to collection of open sets

[raw nexus]

@jolly stone sorry to at you

[ruby seal]

I'm asking about topology t

Not field of math lol

[jolly stone]

nonono im just expanding (L/T)^2 = L^2/T^2 by exponential rules

[slender girder]

what does "calculus" mean

like single vairable or multivariable

it does not specify

[wary stream]

Technically both

[jolly stone]

hmm i dont really know how to explain pre-algebra level math, sorry ;w;

[slender girder]

i am guessing it covers Differential equations
Parametric equations and polar coordinates
Infinite sequences and series
Vectors and the geometry of space
Vector functions
Partial derivatives
Multiple integrals
Vector calculus?

[ruby seal]

It's simple, if it doesn't specify then it's for reader to understand

[wary stream]

Calculus is comprised of differential, integral, and multivariable

[ruby seal]

No

Parametric equations and polar coordinates isn't calculus ...

[slender girder]

hmm 🤔

[ruby seal]

Sure it's related , but no....

[wary stream]

Differential equations is still part of calculus. People refer Differential equations as calc 4

[slender girder]

but yeah i am trying to study multivar calc

[ruby seal]

Oh

That's possible very likely

[slender girder]

Official Course Description: Functions of several variables, vector-valued functions, partial derivatives and applications, double and triple integrals, conic sections, polar coordinates, vectors and vector calculus, first order ordinary differential equations. Applications to physical sciences. Use of symbolic manipulation and graphics software in calculus. 💀

this is from the syllabus

[ruby seal]

Well yeah that's the list of topics covered in this course

[dense citrus]

sounds like analysis 1

[ruby seal]

Analysis 1?

What's that

[dense citrus]

the way such a lecture is called over here

[ruby seal]

Why is that?

[dense citrus]

¯_(ツ)_/¯

[ruby seal]

I don't understand why would the word analysis be used for that

[dense citrus]

I've never seen the world calculus except on the internet

[slender girder]

analysis is like a level above calculus i think

or multiple level

real analysis is real pain

[ruby seal]

Depends what analysis we are talking about here

There are many "analysis"

Functional analysis for example

and even tensor analysis

[slender girder]

💀

so dead

[dense citrus]

I just put a name on the curriculum. You could maybe also call it real analysis

[outer lagoon]

The sum of any n consecutive numbers will always be divisible by n if n is odd. Can someone help me prove this conjecture?

[jolly stone]

let k be the starting point, and you have: k, k+1, k+2, ..., k+(n-1)

now you can find the sum of these n numbers to find out what that expression is

[outer lagoon]

so by induction?

is there no other way? more basic

[jolly stone]

nope just simple number theory

what's the sum of k, k+1, k+2, ..., k+(n-1)?

you can find sum of k first and 1+2+...+(n-1)

so basically n * k + (n-1) * n/2

[outer lagoon]

but that's knowing that there is a formula for (1+2+...+n) which is n(n+1)/2. what if I didn't know that?

[jolly stone]

you can prove by induction

or you can use some summation manipulation to find the formula for that

[outer lagoon]

oh well lol technically we haven't learned that in this book, or even summation

[jolly stone]

S = 1+2+...+n
S = n+(n-1)+...+1

[outer lagoon]

so I'll just have to pick 1

[jolly stone]

oh

so proving that without knowing what the summation is...?

you learned induction before the formula for that?

[ruby seal]

lol

[jolly stone]

that is weird, still thinking of other ways without using that

and even proving that by induction alone i dont think it is easy to prove

[outer lagoon]

okay, anyway. Supposing I can use that first method. I get nk + n(n+1)/2

[jolly stone]

it's actually n(n-1)/2

[outer lagoon]

n * k + (n-1) * n/2

hummm

[jolly stone]

factor n out to be n * (k + (n-1)/2)

the sum S = n * (k + (n-1)/2) is divisible by n if (k + (n-1)/2) is an integer

when you can factor out n and still have an integer left

you need to prove that (k + (n-1)/2) is an integer

but since we know that n is odd, then n-1 is even

and that makes (n-1)/2 an integer

k + (n-1)/2 is also integer

[outer lagoon]

so n being odd is from assumption ?

[jolly stone]

yep

[outer lagoon]

okay.

so to prove that it only works when it's odd, can I give a counter example for when it's not?

[jolly stone]

1 + 2 = 3 but not divisible by 2

[outer lagoon]

I mean yes I understand that but do you think that's enough for the proof?

[jolly stone]

they only asked for odd numbers, so no need to care about even numbers

[outer lagoon]

basically my teacher doesn't lecture at all so we cant ask this type of questions

[jolly stone]

damn thats sad

[outer lagoon]

oh no. They asked me to make a conjecture. and that was my conjecture. that it only works when n is odd

[jolly stone]

yep

[outer lagoon]

so I probably have to show why not even then

oh well..ugh..lol

[jolly stone]

hmm so you need to prove that it wont work for even number n too?

[outer lagoon]

A counter example is usually enough

[jolly stone]

yeah but that doesnt prove for all even number n

actually in that case you can still look at original term

(n-1)/2 will not be an integer

meaning that the sum S = n * (k + (n-1)/2) cannot factor n and left with integer

[outer lagoon]

hum..

[jolly stone]

so S is not divisible by n

[outer lagoon]

okay.

[alpine sable]

I think a counterexample is fine for showing it doesn't work for every even number

you don't need to prove it

[ruby seal]

um so

Can someone tell me what topology is ? plz

like give definition

but own made definition

like not copied from wiki plz

[alpine sable]

I was literally about to copy paste the wikipedia page

[ruby seal]

:/

[outer lagoon]

just one more dumb question because I haven't done this type of stuff in a while. why are we adding up to n-1? I saw this solved somewhere else and they added up to n

[wary stream]

Ask in the #math-discussion channel

[ancient obsidian]

Someone explain this to me

[ruby seal]

.

[wary stream]

Negative exponent is reciprocal

[alpine sable]

when the exponent is negative it is the reciprocal of that exponent

but positive

[ancient obsidian]

Alright

Thxs guys

😎 👍

[agile talon]

How do I find mean and standard deviation for a binomial random variable?

[misty moat]

substitution or addition?

[wary stream]

Try to not give out answers

[alpine sable]

sorry

[ancient obsidian]

Help?

[alpine sable]

can you rewrite 8 as 2^n where n is some number?

@ancient obsidian

[wary stream]

What have you tried?

[ancient obsidian]

Give me a sec

[alpine sable]

Hmmm

[ancient obsidian]

I just don't know how they got rid of the 8 -1

[alpine sable]

The biggest difference in the picture is that they somehow made the 8^-1 vanish

Right

[wary stream]

Where did the z come from?

[ancient obsidian]

z^0 equals 1 right?

[wary stream]

$$8 = 2^3$$

[ocean seal]

dldh06

[alpine sable]

It would be helpful to you, if you could rewrite 8 as 2^n

yep

[wary stream]

Use that and it'll help simplify it

[ancient obsidian]

Ok

Thxs

Would this be the answer

?

[wary stream]

Yeah, looks like it

[ancient obsidian]

[wary stream]

The final answer was almost completed here

[ancient obsidian]

Yep

[red whale]

yo

You are driving into St. Louis, Missouri, and in the distance you see the famous Gateway-to-the-West arch. This monument rises to a height of 192 m. You estimate your line of sight with the top of the arch to be 9.2° above the horizontal. Approximately how far (in kilometers) are you from the base of the arch?

i know its tan

im trying to submit .84 km but its not correct whatd i do wrong 😦 its been so long since school

[wary stream]

What did you try?

Like work wise

And diagram too

[red whale]

tan(9.2) = op/adj

the right triangle opp side is 192m

the angle over horizontal is 9.2 degrees

and adj side length is x

so tan(9.2) = 192/x

x = 192/tan(9.2)

its probably something rly stupid I havent done school work in so long

[wary stream]

How did you type it into your calculator?

Because everything you said is correct

Just probably a mistake with inputting it into a calculator

[misty moat]

substitution or addition? anybody?

[umbral hatch]

1= addition 2= sub

cronus

[wary stream]

Don't give out answers

[umbral hatch]

sorry im new

[wary stream]

You already posted this earlier and someone helped you already

[fiery bronze]

I would need help with this question

[wary stream]

Read #rules and #❓how-to-get-help

[agile talon]

I need help answering this. Please don't give me the answer but help me understand how to solve it. Thanks.

[umbral hatch]

k

[fiery bronze]

my question was posted first @agile talon

[agile talon]

i didnt ask for priority

[fiery bronze]

as per rules you need to go in another question section

[wary stream]

Someone already asked before you, making this channel taken

So ask in a different one

[wary stream]

What have you tried?

[fiery bronze]

i don't know if i got the concept of acceleration right. Is it how fast it goes from minimum speed to maximum one?

[wary stream]

I'm pretty sure that acceleration is just the slope of the v-t plot

[fiery bronze]

so 170 is correct?

[wary stream]

Yes

I believe so

[fiery bronze]

distance = speed x time right?

[umbral hatch]

yep

[wary stream]

For distance, you can just find the area under the plot

[fiery bronze]

so it would be 170 x 1 = 170

[wary stream]

Yes

No

Wait no

Area under that part

[umbral hatch]

where is his question?

[wary stream]

Since it's a triangle, find the area of the triangle

[wary stream]

@umbral hatch

[fiery bronze]

where do you see the triangle?

[umbral hatch]

ok cool, so its a speed time graph

[fiery bronze]

alright.

[umbral hatch]

so u get that the gradient of the graph is accelaration?

[fiery bronze]

right

[umbral hatch]

well in such graphs the distance travelled is the area under the graph

to do this u simply divide the graph into shapes

[fiery bronze]

ok

[umbral hatch]

for e.g. here u can do a triangle, rectangle and another rectangle

[fiery bronze]

ohhh i get it

and you sum up the areas?

[umbral hatch]

yep

[tranquil parcel]

,w limit as x approaches infinity of lnx - ln(x+1)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Thalapathy#3541

[tranquil parcel]

How is this 0

?

[wary stream]

Channel is taken

[fiery bronze]

what did you get? for 10 minutes?

[tranquil parcel]

Oh sorry

[wary stream]

Ask in a different channel

[umbral hatch]

what did u get as in like distance or what?

[wary stream]

How would you find it?

[fiery bronze]

you need the sum of the areas right?

what did you get as speed?

[red whale]

i got -8397

-839.7

[fiery bronze]

wait what?

[wary stream]

Make sure you're in degrees

[wary stream]

He was doing his problem and left for a bit

[fiery bronze]

oh ok cause distance can't be negative.

[wary stream]

Technically it can

[umbral hatch]

yeee displacement on the other hand can

[umbral hatch]

distance is scalar

[fiery bronze]

in real life though could it?

anyway, let's get back to the problem.

base of first triangle is 1

height is 170

area= (170 x 1) / 2 right?

area of first triangle = 85

[wary stream]

For the triangle, yes

[misty moat]

where i dont see it

[wary stream]

Well, looks like they deleted it because the purpose of this server is to assist, not give out answers

[misty moat]

so then i didnt get any help lmao

[fiery bronze]

ok now let's do the rectangle. Base is 6 and height is 170 right?

[wary stream]

Base is not correct

[fiery bronze]

base is 6*

6 x 170 = 1020

area of first triangle + area of rectangle = 1020 + 85 = 1105

[wary stream]

Still not quite

[fiery bronze]

i don't get it sorry

[agile talon]

so do people know the other channels exist or nah?

[fiery bronze]

why do you keep interrupting?

[agile talon]

sends one message

[fiery bronze]

i mean... it was already told to you to post in another channel

[fiery bronze]

ohhhh, the base is 5

[wary stream]

Hopefully that helps

[fiery bronze]

it really does, thanks mate!

[wary stream]

That's how you should split up the plot

Shapes like that

[fiery bronze]

5 x 170 = 850

area of first triangle + area of rectangle = 850+85 = 935

[umbral hatch]

ok im back

[wary stream]

,calc 1701.5+5*170

[ocean seal]

Result:

935

[wary stream]

Looks good so far

[fiery bronze]

area of second triangle (1 X 90) / 2

area of second triangle 45

935 + 45 = 980

[wary stream]

Yep

[fiery bronze]

area of second rectangle = 1 X 80 = 80

980 + 80 = 1060

Total area = 1060

[wary stream]

That's total area up to 7 mins, I believe

So you need to add the area from 7 to 10

[fiery bronze]

ohhh right

your drawing doesn't include from 7 to 10

[wary stream]

That was my mistake, I forgot to draw it but you can easily represent the shapes too

[fiery bronze]

area of third rectangle = 3 x 80 = 240

[wary stream]

Yes

[fiery bronze]

total area = 240 + 1060 = 1300

therefore distance in 10 minutes is 1300

[wary stream]

Yes

[fiery bronze]

now to know who between raj and dita goes further in 10 minutes we need to convert 6.3km/h in meter per 10 minutes

raj walks at a costant speed of 1.05km/10 minutes

which is 1050m in 10 minutes

Therefore Dita goes further in the first 10 minutes by 250m

Yess, it showed as correct

thanks @wary stream for the help 🙂

[agile talon]

need help understanding this

when i needed him the most he vanished

[umbral hatch]

i would help but idek

[agile talon]

it's ok

<@&286206848099549185> pls ive been waiting like an hour

[umbral hatch]

it is true help this man

[agile talon]

<@&286206848099549185>

[lavish cypress]

don't ping twice, which part do you need help on?

[agile talon]

both

[lavish cypress]

well you know a simple linear regression is of the form y-hat = ax + b right?

[agile talon]

yeah but i genuinely do not understand this and i cant figure out why

[misty moat]

any1 know 2.

[umbral hatch]

channel taken

[agile talon]

i have my notes and all and im just stumped

[lavish cypress]

the predicted value of y (in this case, the top speed in mph), is equal to a constant coefficient times x (in this case, the weight in lbs), plus another constant.

[agile talon]

ok yeah

[lavish cypress]

the coefficient and constant can be found under the column labeled Coefficient

[agile talon]

yes

[lavish cypress]

so now you know how to do part a

[agile talon]

but i dont understand how to solve part a whatsoever

[lavish cypress]

use this, and read the coefficients out from the table

[lavish cypress]

I already contextualized the variables for you in here

[agile talon]

the top speed in mph being 107.58? or am i tripping ?

[lavish cypress]

where did you get "top speed" from?

[agile talon]

no clue. i told you im completely stumped i dont understand this question at all

[lavish cypress]

it's mentioned nowhere in the problem, nor in this channel

[agile talon]

ok

so...

oh alright

uh this channel is still taken cause i havent gotten help

[umbral hatch]

ur question is too powerful to be left alive

[agile talon]

[lavish cypress]

you have gotten help, but you are not communicating what you do not understand, other than with vague statements such as "I'm completely stumped"

[agile talon]

I am completely stumped = I have no idea about anything on this question whatsoever. I straight up do not understand what to do for this question but I was able to solve the rest of my questions.

[lavish cypress]

https://www.khanacademy.org/math/ap-statistics/bivariate-data-ap/assessing-fit-least-squares-regression/v/interpreting-computer-regression-data

watch this

[agile talon]

alright give me a few

[agile talon]

this is where i have gotten so far

[lavish cypress]

well that's it, make sure to add units for weight

[agile talon]

and for part b i just insert 4 for x and do the equation?

[lavish cypress]

yes

[agile talon]

i believe this is correct.

[lavish cypress]

yes

[agile talon]

thanks for the help and helping me understand it

[bold mantle]

I was working on a summer math review packet, and when I did one of the questions, the answer I got wasn't there, I even looked it up on Google and it matches what I got

I got 2613.81 ft³

[jolly stone]

yep never doubt yourself

it's correct

[thorn vortex]

All of the answers there are indeed false

[bold mantle]

Is that sarcasm?

[misty moat]

any1 know?

[jolly stone]

nope

pi * r^2 * h indeed

[bold mantle]

Ok

[vital iron]

I need help with pre algebra

X-8 𝜋= 𝜋

Pls ping me

[proper sable]

Someone please help I don’t understand this

<@&286206848099549185>

[ripe cipher]

Use the midpoint formula!

(-1 + - 7)/2 = x

x = -4

y = (-2 + - 4)/2

y = -3

Therefore the midpoint is (-4, -3)

[slender girder]

YO IS THAT YOU?

[lavish cypress]

no

[gleaming snow]

Why is it wrong, i followed the equation

Or is the answer 0?

Nvm its negative.

[random talon]

Is this channel available?

[glass lichen]

Yes

[random talon]

I'm new to set theory and I have a quick question. In proving the existence of the singleton set, if we have some sets A,B,C, I already know that by the pairing axiom we can create the set {A,A}. But how can I justify the existence of the set {A} in order to use the extensionality axiom?

[slender girder]

gusy i need help again

[lavish cypress]

The singleton set {A} is the set that only contains A right? You prove that {A, A} has this property, and use extensionality to prove that all sets that only contain A are equal.

[slender girder]

this doesn't make much sense

[random talon]

Translate it to English. There is an integer x such that for all integers y it happens that x>y. Now the question is, is it true?

[slender girder]

can't it be the other way around?

[random talon]

Yeah. I know that by the Pairing Axiom we can get the set {A,A}. And I know that we can use the extensionality axiom to say that {A,A}={A}. But my question is that, if I only know that A is a set, how can I know that {A} exists? Like should I use separation axiom or some other axiom?

[slender girder]

For all integers x, there exists an integer y such as x > y

[lavish cypress]

you do not know {A} exists, you are essentially defining it as {A, A}

[fringe spindle]

i mean it can, but it doesn't have the same meaning. just remember an instance when one of our professors specifically made this clear to our lecture class

[random talon]

Idk why you need to know this. But clearly the statement you sent in the picture is false. The second you mentioned is true

[slender girder]

we are not in the same class unfortunately

[fringe spindle]

yeah, unfortunately....

[slender girder]

i agree :(( the statement in the pic is confusing to me

[lavish cypress]

do you understand the english translation?

[slender girder]

no

there is an integer

let say x = 8

8 is not > 10

wtf is the emoji there

bruh

isn't x infinity then?

for it to be bigger than everybody else in the integer set

[lavish cypress]

no

[slender girder]

so what

[lavish cypress]

that is just a statement

it says "there exists an integer x, such that for all integers y, x is greater than y"

[slender girder]

x does not exist

jk i am not sure

[lavish cypress]

that's all that statement means

it doesn't define x, or y

[slender girder]

oh thank you

what if m + n is not even 💀

[random talon]

Do the proof and see what happens

[slender girder]

i know but there is a logic

that i don't have to do the proof

to show

it is like a type of implication

but i forgot :((

[drifting hound]

hey guys what is 21/103 divided by 905/84?

[slender girder]

bro just use calculator

if m + n is even , then m - n is even

m+ n is p

m- n is q

p -> q

if not p -> what?

[glass lichen]

Then you wouldnt be proving the implication

[slender girder]

why

[glass lichen]

cause the implication is m+n is even => m-n is even

so you have to assume m+n is even, then show m-n is even

[slender girder]

what if it is not even

[lavish cypress]

then you don't care

[gleaming snow]

Can anyone helo me figure this out?

On letter be i put 9pi/4

[oak chasm]

@gleaming snow The reference angle is the smallest angle you need to add or subtract to get to the x axis.

[gleaming snow]

What formula do i use

[oak chasm]

So, where is 7π pointing?

[gleaming snow]

3pi

[oak chasm]

Well, start at 0.

One revolution is 2π.

[gleaming snow]

Pi

[oak chasm]

So, you go around once to get angle 2π. You go around twice to get angle 4π. You go around three times to get angle 6π. Then you have π left.

Which way does π point?

[gleaming snow]

7pi?

I got B right cuz i got an illustration

[gleaming snow]

Are you asking for which quadrant?

[slender girder]

how can i write the negation sign

nvm wrong place

[candid coral]

I have a problem I need he,p with

Fourth one down

[strong elbow]

first one is 69

ohhh

Fourth one is 420

[candid coral]

I LOVE THAT NUMBER

[candid coral]

Thanks so much

[strong elbow]

np

anytime

[strong elbow]

we know u do

[candid coral]

I will leave now

[placid zinc]

Codek

[white kiln]

im confused on number 5

[atomic whale]

What Is 500 + 500?

[placid zinc]

codek

[alpine sable]

to have at least two then you can have burger and hotdog, cake and burger, hotdog and cake or you can have all three

[placid zinc]

@white kiln
Any intersection of two or three circles counts as "at least two"

Can also count how many had "not one"

[atomic whale]

Why Is Nobody Helping Me 😭

[alpine sable]

1000

Just type it on google next time

[raven rover]

As @alpine sable said, you can just Google this.

[atomic whale]

But Isn't This Server Helps You On It?

[alpine sable]

It is a simple addition problem, what do you want to know about it?

[raven rover]

Idk if this person is joking or not

[alpine sable]

hello lit dudes 😎

[slender girder]

math is fucking hard

when the professor says no collaboration on the homework

[atomic whale]

Why So Rude ;-;

[slender girder]

i am sad

[atomic whale]

For My Test

[alpine sable]

I am 4

@slender girder here is not the place for conversation

how old are you guys

[slender girder]

true

i am trying my best

[alpine sable]

who is Joe mama and what is he banging

[raven rover]

I'm just sharing my thoughts

[tiny granite]

<@&286206848099549185>

Pls

[alpine sable]

5-x=-3, y-8=-6, 4-z=-1

solve for each of those variables

@tiny granite

[tiny granite]

Well

There’s 3

Variables

So it’s

So idk how

[alpine sable]

well

you need to subtract some number from 5 to get -3

what do you think that number would be?

[west vine]

lol

[tiny granite]

I think

Umm 7

Bc

U need to carry over a number

[alpine sable]

whats 5-7?

[tiny granite]

From 1 place

To 2nd digit of the 5 number

So

It makes .8

[slender girder]

how can i write the negation sign

[tiny granite]

-2

[slender girder]

guys

does this just mean "write a truth table"

[west vine]

negation sign

!

[slender girder]

why is this prompt so long

[west vine]

or ~

or NOT

[slender girder]

yup i asked that before, but i somehow asked that again

i am going crazy

[west vine]

theres so many

signs

google it

[slender girder]

but yeah can you help me with my second question?

[west vine]

Yeah

if its all true

then its a tautology

pretty much

[slender girder]

aight

bet

[alpine sable]

yes, but we want -3, so it has to be 8

[tiny granite]

Ok then What’s next

[rustic delta]

does anyone know how to do this question?

[tiny granite]

?

I got that

Now what?

[alpine sable]

hold on

im reframing this question

my process is wrong

Hello everybody

it seems as though I've found a mistake

3sqrt(5) != sqrt(20), 2sqrt(5) does equal sqrt(20). Why is Google telling me that 3sqrt(5) is correct?

[final ember]

no your right

[velvet dove]

what does this mean

[alpine sable]

yeah... $2\sqrt{5}=\sqrt{20}$

[ocean seal]

Tommm

[velvet dove]

like i know it moves the function to the right

but how

[final ember]

it means moving your function right

[velvet dove]

is there a proof?

[alpine sable]

Because every x coordinate is 1 less than it would be

[alpine sable]

@tiny granite here, solving for these you get x=8, y=2, z=5

[velvet dove]

ohh

thx

[alpine sable]

i forgot negative signs on all of them

Lol

you'll get 5.24-(8.85)=-3.61

[velvet dove]

wait a minut4e

if it were doing that

then why is the function going right

and not left

[alpine sable]

Wait oh yeah

Is the function not going left?

Because if you graph the line x

And then graph the line x-1

The line x-1 looks like it moves left from the line x

[final ember]

its opposite

if its inside the ()

[alpine sable]

Wait

[alpine sable]

But why

[final ember]

idk how to explain why tho. I just memorized it

[alpine sable]

I don't think it's like that

I think the real function isn't x-1

[final ember]

there is probably a youtube vid somehwere

[alpine sable]

Since f(x) just means a function in terms of x

[velvet dove]

i think i figured it out

yeah

hold on

let me show u

[final ember]

all ik its opposite

[alpine sable]

f(x) would mean replacing all the x variables with x-1

Kk

Show

this is simply transformations of polynomials

$y=af(k(x-d))+c$

[ocean seal]

jswatj

[velvet dove]

ur trying to do vertex form right?

[alpine sable]

Well yeah

so k=1, and d=1 since d>0 then it is a shift to the right

[slender girder]

guys

what is hyperbolic trigonometry

[alpine sable]

and a=1

[slender girder]

i am confused

[velvet dove]

i havent learned that lol

what form is that

[alpine sable]

Trigonometry with hyperbolas?

[velvet dove]

no

🤦‍♂️ focus on my problem plz

[alpine sable]

you can read up on it here

http://mrsfofx.weebly.com/transformations.html

[alpine sable]

You said you figured it out

Acc explain it to me

[velvet dove]

bro what

i looked up the "general equation for transformations"

google showed me vertex form

[alpine sable]

I never heard that putting it in brackets made it opposite

[velvet dove]

idk what that is

@alpine sable theres a logical explanation behind it

hold on

[glass lichen]

sinh(x), cosh(x), tanh(x), etc

just trig but instead of defined via the unit circle, it's defined by a parabola

[alpine sable]

Woah

[alpine sable]

its transformations of a polynomial

[glass lichen]

https://www.youtube.com/watch?v=EvLm6iAYK9Q Not the most introductory video, but a good one

[alpine sable]

So all you need to do to become a very cool person is boost the server

[slender girder]

thank you

i know this place doesn't do homework

[velvet dove]

which is best represented in vertex form

i dont see that formula anywhere else lol

as in, the formula u presented us

@alpine sable

u can check it on desmos

it's right

[alpine sable]

Hrmmm

Yes I see your point

And the point labeled 5,6

Lol

[velvet dove]

yes

[alpine sable]

But I am still confused

Perhaps more confused than you initially were

[velvet dove]

how

[alpine sable]

Ohhhhhh

No I get it

[glass lichen]

what have you tried?

[rich basin]

So i used the formula

v = f lambda

[velvet dove]

it makes sense but im trying to figure out how it exactly relates to the function moving towards the right

Let me break it down with words

[rich basin]

so if this is two adjacent nodes

so it should whatever lambda be

so i thought the answer would be 92 / 475

[alpine sable]

It's cause the function moves down

[rich basin]

units would be m/s Hz^-1

@glass lichen but then the answer is wrong

I mean i got it wrong

Which i have no idea why i got it wrong

[glass lichen]

Yeah, cause that's 1 whole wavelength

[alpine sable]

Since saying f(x-1) really means saying that when x=something y=something-1

[rich basin]

Yeah, lambda would be the whole wavelength if i'm wrong

[glass lichen]

yes

you want half the wavelength

,w graph y=sin(x)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by moshill1#9771

[glass lichen]

let's say the horizontal axis is time and vertical is displacement, on a standing wave the nodes are where displacement is 0

so in this example 0, pi and 2pi

[rich basin]

Yeah that is true

[glass lichen]

now 0 to 2pi is 1 wavelength, so 0 to pi is half the wave length, which is the distance b/w points of no displacement

[rich basin]

So since thst is just 1/2 of lambda

so i would be v = f lambda

but then once we find the lambda we would halve it?

[glass lichen]

yes, you'd find lambda w/ the universal wave eqn, then halve it

[rich basin]

let me try putting it in the calc

[glass lichen]

,calc .5*92/475

[ocean seal]

Result:

0.096842105263158

[alpine sable]

If you have a function in terms of x which is f(x+2) and another function, g(x), which is that function in terms of (x-1) than the other function, g(x), would be replacing all the x variables in the first function with x-1. Doing that gives us (x-1)+2 which is g(x)=x+1 which is one less on the y-axis than f(x)=(x+2). This is why the function moves 1 down making it look like it moves 1 to the right.

[velvet dove]

Wait no, check this out: g(x) = f(x-1) has the same slope as f(x), just a different x coordinate. If we plug in the x coordinate "5" into g(x) = f(5-1), we'll get f(4). This just means that we'll need to use the y-coordinate that we get from f(4), just with the x-coordinate "5" instead, since the x-coordinate of "5" is for g(x), which is what we're trying to solve. Tell me if you don't understand btw.

[alpine sable]

Bruh moment

[rich basin]

@glass lichen Thanks that is the correct answer, and also what would exactly be the units for this?

[glass lichen]

wavelength is [L]

[rich basin]

wouldn't the units be m Hz^-1

[glass lichen]

and 1/2 is [1] so, you have a final answer w/ units [L]

so m

[alpine sable]

Of course they have the same slope, the coefficient of x didn't change

[glass lichen]

$\left[\frac{v}{2f}\right]=\left[\frac{L\cdot T^{-1}}{T^{-1}}\right]=[L]$

[velvet dove]

if you try to solve for g(x) with "5" they're gonna give you f(4). Plug this into the f(x) function and use the y-coordinate of f(x) with g(x), because you're solving for g(x), not f(x)

[ocean seal]

Mosh

[velvet dove]

well i mean yeah

[rich basin]

@glass lichen Yeah, that is right thanks, so troublesome to find the units when the equation is so long

[velvet dove]

neither did the exponent

so

[alpine sable]

Are you in high school or is this for kumon or something

[glass lichen]

that... isnt a long eqn

[velvet dove]

high school

[alpine sable]

Ah ah

What grade man

[velvet dove]

12

[alpine sable]

Damn

[velvet dove]

this is pre-calc work

[rich basin]

If the equation is so long, wouldn't it be really difficult to find the answer?

I mean the units

[velvet dove]

this shit really isnt difficult if u understand it, which im trying to do rn. i have a somewhat clear understanding of it

[glass lichen]

I mean... not really, like if you're adding things in the eqn they have to be dimensionally similar

[velvet dove]

but im not gonna spend all of my time on one question

so cya

[thick meteor]

who's down to tell me what I'm doing briefly

[alpine sable]

K cya

[thick meteor]

just a quick explanation

[alpine sable]

For what

[thick meteor]

what I'm doing in algebra 2

[glass lichen]

So if I have a formula like $A+B$ then I know that $[A]=[B]$

[rich basin]

@glass lichen Like a mulitude of multiplkications and divisions, where the units would lose track

[ocean seal]

Mosh

[rich basin]

they would have to be the same then

But then what would if we have A,B,C,D,E. with different units

each arranged and mulitplied and divided at random intervals

[glass lichen]

Then it just becomes slightly more algebra

cause you can pretty much treat units like algebra/variables

[rich basin]

hmm, that seems alright i guess. So if i have a unit A and unit b

And when i divde both A and B together

would the units then be AB^-1

@glass lichen I mean lets use something that we know already, like the equation above

Would it still be valid if i have it as mHz^-1

[glass lichen]

Yes, $\left[\frac{A}{B}\right]=\frac{[A]}{[B]}$

[ocean seal]

Mosh

[glass lichen]

no

[alpine sable]

What's the question

[glass lichen]

cause that's not units of length, which wavelength is

[rich basin]

like frequency the units are in Hz

[glass lichen]

$[mHz^{-1}]=[L\cdot T]$

[ocean seal]

Mosh

[rich basin]

and if we use the logic from above with A/B, wouldn't it still be valid?

[glass lichen]

it's a length times a time

@alpine sable using those reactions wont work.

[slender girder]

guys i have a quick quesiton

[glass lichen]

what do you mean?

[glass lichen]

in use.

[alpine sable]

Ik, they're for the command user

[glass lichen]

Yeah im aware.

[slender girder]

if NOT q implies NOT p; if NOT q implies r

what do i do?

[alpine sable]

I just press on them for fun lol

[glass lichen]

channel is still in use

[slender girder]

is there a way to combine these two statements?

[rich basin]

like i'm saying wouldn't mHz^-1 be as valid as m for the case of the above equation

[slender girder]

oh

[thick meteor]

can I send a pic 0-0

[glass lichen]

those are different things Boruto

[glass lichen]

channel in use.

[alpine sable]

Dm it

[glass lichen]

m*s isnt the same units as m

[rich basin]

hmmm, seems like i have to use the answer as a determination of the units?

[glass lichen]

no

You can use the fact [v]=[L/T] and [f]=[Hz]=[1/T]

to know that [v/f]=[L]

which I said already

[rich basin]

I get that, but like i wouldn't come up with that

Like if there are other problems with similar configuration as that i wouldn't thought of that kind of way to get the units

Like what strategy should i use to have this sort of minimisation

[glass lichen]

dimensional analysis and algebra

you sit there and say "velocity is in m/s, frequency is in Hz which is 1/s, so v/f is (algebra interlude) m"

[rich basin]

What about if i multiply some equation of which the units are in lets say N

like forexample 500 N * Hz

Would it be as valid if were to write it as 500NHz = 500NT^-1 ?

[glass lichen]

what's H in the RHS of that?

[rich basin]

My bad

[glass lichen]

but no, cause Hz isnt 1/T, it's 1/s

the T is just the symbol in dimensional analysis for "time units"

similarly L is the symbol for "length units"

L can be m, km, feet, picometers, etc

[rich basin]

Right

[glass lichen]

[s]=[min]=[hour]=[year]=[T]

[rich basin]

So you only did the cancelation here, because v's units can be arbitary units T?

[glass lichen]

v's units arent arbitrary, they're m/s

in dimensional analysis that's L/T

you can do what I did w/ m's and s's

and you'd still get m

[rich basin]

So then instead of NT^-1 it would be Ns^-1

[glass lichen]

Yes

[rich basin]

therefore they will be both valid in the context of dimensinoal analysis

[glass lichen]

yes, you can either work w/ the specific units directly or the general things

the one caveat is if you have something in say km/h and something in m, you need to change the units yourself, whereas using L and T you dont cause you;d just be multiplying on a dimensionaless number

[rich basin]

Then I still don't get why mHz^-1 would an invalid units from the above?

[glass lichen]

for what?

[restive kindle]

Hello, can anyone help me to solve this exercise by the gauss method

[glass lichen]

velocity or the final answer?

[glass lichen]

in use.

[restive kindle]

please

[rich basin]

This

[glass lichen]

Hz doesnt have units T, it has units 1/T

[alpine sable]

sen?

[glass lichen]

in use

[rich basin]

that is sine

[glass lichen]

the numerator of what I put is the units from velocity

[restive kindle]

yes

[rich basin]

Yeah i get that, but my question is wouldn't it be as valid for which m/sHz^-1 be for it to be units m

[glass lichen]

m/(sHz^(-1)) or (m/s)Hz^(-1)?

[rich basin]

(m/s)Hz^(-1)

[glass lichen]

that's units of m

cause the s's cancel

and what I wrote

$\frac{v}{f}=vf^{-1}$

[ocean seal]

Mosh

[rich basin]

Okay, thanks this helped alot. I appreciate the help alot

[alpine sable]

i get the 6 and how to get the x and y. i just don't understand why 3/2 is graphed like that, need explainations

[gray isle]

what's your issue with the location of where x=3/2

3/2 is just 1.5

(the number halfway between 1 and 2)

[alpine sable]

so just simplfy it?

[gray isle]

3/2 is already simplfied

i just expressed it differently

[alpine sable]

or re-write it in decimal i mean

[gray isle]

to give you something you might be more familiar with

[alpine sable]

now the question is why?

why is 3/2 so impossible to graph as X

[gray isle]

wdym by impssobile

[alpine sable]

like why do we have to re-write it decimal to graph it instead of graphing 3/2 as x

because 3/2 as slope would work

[gray isle]

we don't need to rewrite it as a decimal

[alpine sable]

show

[gray isle]

3/2 is equivalent to 1.5

that's all there is too it

[alpine sable]

oh

ok

[gray isle]

explicitly express 3/2 as 1.5 or 1 + 1/2 if it helps you

[alpine sable]

i see

thanks

[gray isle]

alternatively

3/2 is the number halfway between 0 and 3

[round solar]

Hi I need help for this question. I got the correct answer which is 25% but I’m unsure of whether my actual working out is correct

[tame thunder]

well personally, 30x4=120
30=1/4th of 120

and 1/4th is 25% out of 100%

But thats just me personally, theres other ways you could do it

[frigid hatch]

just x = discount/price • 100

[round solar]

Cool thanks

[round solar]

Thanks

[wispy fjord]

The eleven players of the Azzurri Football team have their heights measured. The measurements in
metres are 1.46, 1.37, 1.65, 2.17, 1.28, 1.84, 1.61, 1.29, 1.66, 1.35 and 1.66.
(a) Which of these heights would be considered an outlier? Explain your answer.
(b) Comment on the effect that the outlier has on the mean height when it is included.
Show mathematical evidence.

can someone help me with this

[tame thunder]

outlier would be like 2.17

because it deviates further from the average IMO

but i think someone else could help w/ that cuz i kinda rushed it

[alpine sable]

Why does y=sin(xy) look like below? Should I just accept it as fact?

,w graph y=sin(xy)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Tommm#9248

[gray isle]

<@&268886789983436800>

[thorn vortex]

thanks

[harsh edge]

hello I am a bit confused on what I did wrong here

I'm not sure if it's the first part or the second part, or maybe even both that I got wrong

[novel spruce]

what's this integral called?

[harsh edge]

o wait

is this channel in use or

[novel spruce]

sorry

[harsh edge]

ah ok

and it's fine lol

[remote heron]

looks like a line integral @novel spruce

[novel spruce]

yeah thats what I thought but the answer was a vector, and I thought a line integral would give a scalar? https://math.stackexchange.com/a/3280249

could be the answer was wrong it wasn't from a reliable source

[novel spruce]

i think you diden't read the question carefuly

"zeros between -2 and -1"

did you mean between -2 and 1?

[harsh edge]

I thought they were referring to the sign change in f(x)?

like how in f(x) of -2 , it's -1 but when you go to the f(x) of -1 it's 4.5

or is that just completely wrong

[novel spruce]

ah i see

seems like an ambiguous question to me

[harsh edge]

oh boy time to lose some credit 👍

bruhh there's even more of these, imma just email my teacher. thanks for the talk tho

[novel spruce]

sry im doing something else otherwise id try and help more

[harsh edge]

it's fine lol

pretty understandable too

[sly mantle]

@novel spruce it's unambiguously a line integral

[harsh edge]

oh if you're fine with it, could you see what may be wrong with my problem. later

@sly mantle

[novel spruce]

ok

the answer should be in R though right?

since we're summing a bunch of dot products R . dr

[sly mantle]

yes

[novel spruce]

ok the answer was wrong tysm

[sly mantle]

no prob

[wary badge]

Can I equate alpha^2 + beta^2 + gama^2 as (alpha + beta + gama)^2?

[novel spruce]

I drew the function

I think your mistake was x=4 being a relative minimum

[harsh edge]

oh is it 2

[novel spruce]

it is the minimum in the sample, but x=2 is the only relative minimum, after x=4 it could keep decreasing

[wary badge]

@novel spruce is it a exam?

[harsh edge]

I was the unsmart and forgot graphs could be continuous

tyvm tho

[wary badge]

Graphs can uncontinuous too 😕

[harsh edge]

yes reason I said could