#help-0

1 messages · Page 764 of 1

bitter sage
#

what formula do i use

wary stream
#

Do you know how to find the norm?

bitter sage
wary stream
#

Magnitude

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Norm

bitter sage
#

ya i found it

wary stream
#

Same thing

tight locust
#

take the square root of the dot product of the vector with itself

bitter sage
#

|u| and |v| = 2

wary stream
tight locust
#

which literally is just its magnitude by definition

bitter sage
#

here

#

this is what i have

wary stream
#

You know u + v, not u and v separately

bitter sage
#

ok

wary stream
#

Just find the norm

bitter sage
#

so its |2,2,0|?

tight locust
#

yeah

#

find the magnitude

bitter sage
#

like this

tight locust
#

nice one

bitter sage
#

?

tight locust
#

i'm so proud that you finally learned what the euclidean norm is

bitter sage
#

i was never taught that

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sorry

tight locust
#

it's literally just pythagoras

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consider R^2 for a second instead of R^3. if you have the component form of a vector that means that you know the legs of the triangle

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and the norm (or magnitude) will be the hypotenuse

bitter sage
#

so whats the euclidean norm formula?

tight locust
#

sqrt(sum of each component squared)

bitter sage
#

oh i have learned that

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it wasnt called that tho

wary stream
#

You probably heard magnitude

bitter sage
#

ya

#

can somn remind me what the formula is for finding angle

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given two vectors

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its cosx=a . b/|a||b| right?, and how do i do this question

bitter sage
#

what

bitter sage
#

its occupied

coral pagoda
bitter sage
#

i did that

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but i got i got x = cos^-1(sqrt2)

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and its undef

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cuz U+v = (2,2,0)

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and u = (2,0,0)

coral pagoda
#

Yes, so if we dot them, we should get 4, and if we take the magnitude of u, we get 2, and magnitude of u+v is 2√2

bitter sage
#

ya i got 4

#

ya

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i have 4/2 x 2sqrt2

coral pagoda
#

Thus, $\cos(\theta)=\frac{4}{4\sqrt{2}}=\frac{1}{\sqrt{2}}$

ocean sealBOT
#

dackid (jump king +)

bitter sage
#

oh

coral pagoda
#

Which is indeed a valid value for cos(x)

bitter sage
#

i thought it was just sqrt2

coral pagoda
#

No, it is 1/√2.
If it helps, we can rationalize that to √2/2

bitter sage
#

ok ya x = 45 degrees

coral pagoda
#

You got it!

bitter sage
#

but i dont think thats how htey want me to do the question

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looking back at it

coral pagoda
#

Okay, well, see how you can do it that way. Luckily, 45° triangles are not difficult to deal with

bitter sage
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how do i graph (2,0,0)

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do i graph it like in 3d plane?

coral pagoda
#

Well, you could. But you can also recognize that the z-plane is not being used, so just take a cross-section of the 3D plane

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The x-y plane to be exact

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If you do not wish to do that, then yeah: draw it on a 3D plane

bitter sage
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how do i do tjat

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just x and y/

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like this?

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@coral pagoda

ivory zodiac
#

is this channel in use?

bitter sage
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ya

worthy hazel
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what is 27-(362-291)-(671+925) minsed by 30%

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take your time

coral pagoda
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I have to go to bed now. However, what you drew Alobz is three points, but you need to draw vectors (which are very different)

bitter sage
coral pagoda
#

No...those aren't vectors, and your indicators for u,v, and u+v are in the completely wrong spots

bitter sage
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can u quickly draw it then im so lost

coral pagoda
#

No I can't. I recommend you watch a YouTube video on what vectors are and how to work with them.

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Either that or Khan academy. I assure you they have plenty of videos on the subject.

bitter sage
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ok

hearty cliff
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if y = f(x), do you say that the differential of y (dy) is wrt x?

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because the definition makes it kinda dependent on dx?

worn dew
#

can i have a hard math question that answer was 16?

tight locust
#

what

acoustic fractal
#

Find three unique solutions to the equation y=4 x-11y=4x−11​. Enter your answers as an ordered pair in the form (x, y)(x,y)​.

Please help

worn dew
tight locust
#

integral from -inf to 0 of 16e^x dx

acoustic fractal
tight locust
#

what field are you solving over

worn dew
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any hard question

tight locust
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i just gave you one

hearty cliff
ocean sealBOT
noble goblet
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i need to do 5 and 8 i am so cunfuzed z_spin

dusky bluff
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@hearty cliff 16 will be the answer

subtle nebula
tight locust
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no.

dusky bluff
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@noble goblet In the case of problem 5, use the concept of left hand limit and right hand limit

noble goblet
dusky bluff
#

Are you familiar with the concept of left hand limit and right hand limit?

noble goblet
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like ik what it means i j don’t know how to apply it

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or how to solve for c

mint moth
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Can someone find the mistake and explain to me

dusky bluff
#

Look for some examples, you will understand. Look for " limit problem for step functions".

rigid smelt
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this line is absolute non-sense, the limit of sin(x)/x^3 as x tends to 0 is not 1/x^2, neither is tan(x)/x^3

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and what happened in between these steps? If you are intending to multiply the numerator by (cos(x) + 1), at least do that to the denominator also

dusky bluff
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@rigid smelt I think you should use L' hospital rule.

rigid smelt
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please, this is all doable without l'hopitals rule

narrow scroll
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How do I factorise 32q + 15pr - 24r - 20pq and and (2m - 3)^2 - 2(1+3m)?

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thanks

rigid smelt
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channel might be busy, you should move to an unoccupied one

alpine sable
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@rigid smelt are you sure x is in radians?

rigid smelt
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what does that have to do with the limit being solvable? And why are you asking me?

alpine sable
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You can apply sina/a=1 only if a is in radians and and a should be tending to 0

dusky bluff
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@rigid smelt I think you forgot to write cosx +1 in the denominator

rigid smelt
#

....have anyone of you noticed that this is not my problem?

mint moth
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Oh right i forgot to put it to the denomitator

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Then its 1/2

rigid smelt
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anyway, your second approach is the way to go

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no its not 1/2

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you forgot something very important

dusky bluff
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It's -1/2

mint moth
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Teacher told us that its 0

rigid smelt
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its not

mint moth
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It became very sus

rigid smelt
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like i said, the first approach was very bad

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and the way you evaluated sin(x)/x^3 makes no sense whatsoever

mint moth
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Anyways tq so much for the help @rigid smelt im having the math test in 18 mins

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Im just going to hope that the teacher notices it

split slate
#

What's the formula for finding the maximum and minimum of a sine graph?

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I'm very confused, since I can't find anything worthwhile on Google

charred flint
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sin goes between -1 and 1

split slate
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But what if we shift the graph?

charred flint
#

then it shifts the max and min

split slate
hearty cliff
split slate
hearty cliff
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y = f(x)

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no?

dusky bluff
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@split slate Are you shifting it on x-axis or y-axis?

split slate
#

Like, in:

$
y = k + a \times sin(bx \pm c) \pm d
$
ocean sealBOT
#

HappyAlt

split slate
#

This is the equation I was using for this graph:
$y=1-3sin\left(2x\right)$

ocean sealBOT
#

HappyAlt

split slate
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Wait hold on

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Is it just: $\left|k\right| + \left|a\right| = Maximum$

ocean sealBOT
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HappyAlt

split slate
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Because the maximum and minimum only apply to the y-axis

dusky bluff
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Yes I think so, but I am confused about d

split slate
#

because it will keep on passing through the x-axis

tight locust
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||||||||||||||||||||||||||||||||||||||||||||||||||

astral lion
#

could you please simplify for me ?

sage bronze
# astral lion

$$\sqrt {2yz^{2}} = (2yz^{2})^{\frac {1}{2}}$$
$$\sqrt [5] {2y^{2}z} = (2y^{2}z)^{\frac {1}{5}}$$

ocean sealBOT
#

HELLOBELLO

sage bronze
#

now use exponents laws to simplify

astral lion
#

ty

#

where can i find commands for the bot ?

ionic jewel
#

the math formatting language it uses is called latex, see #latex-help

astral lion
#

i heard about that

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thank you

restive orchid
#

Can someone help me for this question? I need for the value of h

merry coral
#

wut

unique goblet
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Like, You don't need to type

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9-k=4

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-k=4-9

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-k=-5

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k=5

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NO

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IF 9-K=4

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THEN 9-4=K

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EASY

restive orchid
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no no

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ans for k is correct

unique goblet
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YEASH

restive orchid
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but h is wrong

unique goblet
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If h+2=6

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Then 6-2=h

restive orchid
#

but the ans teacher gave is -8

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and i have no idea why

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ok nvm, i know why alr

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thank you @unique goblet

brazen yoke
#

whats 0.225 rounded to the 4th decimal place

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0.2250?

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can I write 0.225

unique goblet
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Yeh

alpine sable
#

how would you write f(x) = 2*(x-1)*(x-5.5) into f(x)=2x2 - 13x + 11 i know how to do it the other way. but not this way.

alpine sable
#

but where does the -13x come from?

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im sorry "2x2" is suppose to be "2^2"

clever folio
#

Are you sure you aren't making a mistake when you try it yourself?

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When I did it I got 2x^2 -13x +11 like you said it was supposed to be.

alpine sable
#

but how did you do it?

clever folio
#

I just did foil

alpine sable
#

i got it so far, makes sense: ```2*(x -2) * (x -11)

(2x -2) * (2x -11)

2x^2 * ...``` but im a little but confused with the rest

#

just continue?

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2x^2 * -2 *-11?

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no if you got (a+b)(c+d) then it will be ac+ad+bc+bd

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whats the meaning of life?

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ill answer that after i understand this 😄

alpine sable
#

"(a+b)(c+d) then it will be ac+ad+bc+bd" this makes sense. i just have to think on it for a bit i think.

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lets say you got(x-2)(2x+3) then it will be x*2x + x * 3 -2 * 2x - 2 * 3 just use this for your problem

thorn kindle
#

Yeah

alpine sable
soft zodiac
#

The function whose graph is the graph of y=x^3 horizontally compressed by a factor of of 1/5 is y = ?.

I know that if I want to horizontally compress the function by like 2, I just add 2 in front of the x. But if I added 1/5, then it would be stretching? How do I compress it by 1/5?

subtle nebula
#

can anyone guide me on how to solve this

vale wigeon
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as-written this doesn't make any sense

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can you ask your teacher to check this for typos?

gray isle
#

the question probably intended $a_n$

ocean sealBOT
#

ℝamonov

subtle nebula
#

h

vale wigeon
#

in which case, what it asks is: at what position does the number 32 appear in this sequence?

alpine sable
#

what values ​​can y assume when x is a natural number

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consider if every value for Z can be in the definition set

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bro how fast is this sevrer

clever folio
#

Shaky are you saying the outputs can only be Z?

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Because that won't be true for all of those.

alpine sable
#

yes

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why

clever folio
#

For ex in (c) when x=2

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y=sqrt(2) which is not an integer.

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For the actual question are they trying to ask you to list out all the values like a,b,c,...?

alpine sable
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For each of the functions, consider whether all values ​​from X can be included in the definition set

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thats the question

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i dont understand what youre trying to say

clever folio
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I see.

alpine sable
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Z are the inegers?

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integers

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-3, -2, 0, 1 ,52

clever folio
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Usually Z refers to the set of integers:

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0,1,-1,2,-2,3,-3,...

alpine sable
#

yeah i know what integers are

clever folio
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I think my confusion is I'm not sure given the way the question is worded what exactly they're expecting your answer to be.

alpine sable
#

no

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it cant

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all numbers of z

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u cant put all numbers of z into x's place

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for example a negative number into the square root

clever folio
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Yeah that's what I was getting at by mentioning (c)

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Since sqrt(2) is not an integer.

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The integers are closed with respect to addition and multiplication.

alpine sable
#

not cube roots as well

clever folio
#

This just means you can multiply and add any two integers and get an integer.

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But nth roots, divisions etc the integers aren't always closed with respect to these ops.

alpine sable
#

answer, No, you can't put negative integers at x's place because you can't take the square or cubic roots of negative integers.

clever folio
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For ex sqrt(3) and 1/2 are not integers.

alpine sable
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oh yeah

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and not all positive integers but some

clever folio
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Yeah yeah

alpine sable
#

no

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you can put

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it into

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it just wont give an integer

clever folio
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Idk what exactly they want your answer to look like but you see how you can find examples of natural numbers where the y values in your prob won't be integers right?

alpine sable
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but u can still put an integer

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in x

clever folio
#

Yeah I'm not saying you can't

alpine sable
#

No, it doesn't work for c and d because you can't put negative integers at x's place because you can't take the square or cubic roots of negative integers.

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That should be the answer

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itll work for the others

clever folio
#

Can x be only natural numbers or can x also be negative?

woven crane
clever folio
alpine sable
#

i meant integers

clever folio
#

Gotcha shaky. That makes sense.

alpine sable
woven crane
#

maybe just send the screenshot for the actual question, problem statement inclusive?

clever folio
#

I think you are wrong about cube rooots of negatives?

alpine sable
#

i di????????

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you can't take the cube number of a negative number, can u?

clever folio
#

I could be misremembering but I thought that cubert(-x)=-cubert(x).

woven crane
clever folio
#

Maybe I'm having a dumb moment lol.

alpine sable
#

cube root

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,w calc (1)^(1/3)

woven crane
alpine sable
#

,w calc (-26)^(1/3)

alpine sable
#

wait what

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can you take the cube root of a negative number

clever folio
#

Yeah I'm having a dumb moment cube roots are defined for any real number.

woven crane
#

yeah

alpine sable
#

,w calc (-26)^(1/2)

alpine sable
#

tf

clever folio
#

You can always take a cube root of a real number.

woven crane
#

we can see it as solution of x^3 - n = 0

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there will be complex roots also

alpine sable
#

i thought u couldnt take square roots and cube roots of negative numbers

woven crane
#

but you need not bother with those

vale wigeon
#

negative numbers have real cube roots

clever folio
#

It's just the even powered roots that are a problem iirc?

vale wigeon
#

and fifth roots, and seventh roots, and any roots of odd degree

alpine sable
#

whats the answer then

woven crane
#

for?

alpine sable
#

for my question

vale wigeon
#

can you repost your question

alpine sable
#

For each of the functions, consider whether all values ​​from X can be included in the definition set

vale wigeon
#

??

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oh god, you're messing up the translation again, aren't you...

woven crane
#

Ohh

alpine sable
#

question 2: What values ​​can y assume when x is a natural number

woven crane
#

so its two separate questions 🤦‍♂️

alpine sable
vale wigeon
#

google translate tends to suck

alpine sable
#

lol

vale wigeon
#

anyway, which part?

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part d?

alpine sable
#

whata question are we at?

vale wigeon
#

i'm asking you that lmao

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it's you who needs hel

alpine sable
#

well

vale wigeon
#

help*

#

actually

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maybe i should fuck off

alpine sable
#

no

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don't

vale wigeon
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i have better things to do than fight through an impenetrable language barrier

alpine sable
#

let's skip the first question

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question 2_

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What values ​​can y assume when x is a natural number

vale wigeon
#

are you sure it says "natural number"

alpine sable
#

Yessss

vale wigeon
#

it sounds kinda weird because the only complete answer that can be given for any of a-f is

alpine sable
#

i've read it 7 times now

vale wigeon
#

tautological at best

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like

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what are you even gonna do

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how are you gonna describe the set {sqrt(n) | n in N}, which would be the answer for part c, in any other way that isn't needlessly contrived

alpine sable
#

idk lol just insert any value at x's place and see what y will be

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y can be any value?

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lol

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this question is weird

vale wigeon
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no i didn't say that

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sigh

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why am i even trying.

alpine sable
#

what?

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the question is literally just what can y be when you place a number at x's place

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y can be from ]-inf,+inf[

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that should just be the answer

fiery berry
#

Hi

alpine sable
#

nothing else

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hi

fiery berry
#

What language do you speak

alpine sable
#

English

fiery berry
#

First language

alpine sable
#

Danish

fiery berry
#

Oh ok i cant if it was chinese i could but my german is shakey and danish is non existant

alpine sable
#

i can a bit german too tho

fiery berry
#

Is your english or German better

alpine sable
#

english

fiery berry
#

Ok then bettee keep in English

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Which question do you need help with

alpine sable
#

scroll up in the chat

latent iron
#

There are 8 different swimmers
How many different way are there to organize the swimmerd in 8 different lanes

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Shouldn't it be 8 choose 8?

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The answer says it's 8 factorial

vale wigeon
#

it matters who goes in what lane lol

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of course it's 8 factorial

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or 8 permute 8 if you have a fetish for using either P or C for every single combinatorics question

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[purposeful exaggeration]

latent iron
#

But thought ncr was the correct use

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Thanks :)

wary badge
#

Help :-)

#

I am stucked

safe stone
ocean sealBOT
astral briar
#

6/(x-1)+5/(x+1)=6/(x-2)

wary badge
astral briar
#

what is the method required to solve this quesiton

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6/(x-1)+5/(x+1)=6/(x-2)

wary badge
astral briar
#

like you know how to solve qudractic equations

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using the qudratic formula

wary badge
#

Lol

astral briar
#

this thing

wary badge
#

It's easy 😑

astral briar
#

k then

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how do i solve it

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6/(x-1)+5/(x+1)=6/(x-2)

astral briar
wary badge
#

@astral briar very easy just stop

astral briar
wary badge
#

@astral briar is it for ur exam?

astral briar
#

i just want to know how to solve problems like this

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are you going to help or not

wary badge
#

@astral briar ok I will

astral briar
#

thanks

#

ann is typing

brazen thorn
wary badge
#

.....

vale wigeon
#

@brazen thorn channel busy please move!

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anyway

astral briar
vale wigeon
#

@astral briar i was going to suggest that you multiply both sides by (x-1)(x+1)(x-2), as alev no doubt was going to do as well

wary badge
wary badge
#

Stop 🛑

astral briar
#

this is our channel

#

our

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one second

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i will multiply boths sides

vale wigeon
#

ugh

astral briar
#

give me a second

wary badge
#

Ugh

astral briar
#

as if i am a pain to you

vale wigeon
#

it's not you lol

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it's the unfunny joke you just made

astral briar
#

i thought it was funny

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TrollSad \

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ok i will do the porblem one sec

vale wigeon
#

also, for the future

astral briar
#

whqt

vale wigeon
#

if you want to post in one of the questions channels, it's usually a better idea to post in one of the higher numbers

astral briar
#

k

vale wigeon
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not because they're any different in their purpose

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but because the lower numbers tend to have a lot of people intruding

wary badge
#

@vale wigeon do u have any idea where I did wrong

vale wigeon
#

incorrect factorization of tan^3(A) - 1 is what i can see immediately

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it's (tan(A) - 1)(tan^2(A) + tan(A) + 1)

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but you have a 2 multiplying the tan(A) in the second parenthesis

wary badge
astral briar
#

k i did it

vale wigeon
#

pray tell why it would be 2tan(A), alev?

astral briar
#

i will figure this out

#

one sec

vale wigeon
#

that looks correct

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now it's a matter of expanding out and tidying up

astral briar
#

can you use reply featur

wary badge
#

Oh k

vale wigeon
astral briar
#

so i know who you are talking to

ocean sealBOT
vale wigeon
#

$(x-1)(x^2 + 2x + 1)$ would not expand back out to $x^3 - 1$, alev.

ocean sealBOT
astral briar
#

x^3 = x^2*x

vale wigeon
#

@astral briar i was talking to alev just now, as i made clear by mentioning them by name.

wary badge
#

@astral briar solve it urself

astral briar
#

and dirty handwriting

wary badge
#

@vale wigeon Thanks a lot

astral briar
#

i cant read easily

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hmmmmmm

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@vale wigeon what do i do now

vale wigeon
#

now it's a matter of expanding out and tidying up

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expand everything

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you should get a collection of x^2, x and constant terms

astral briar
#

remove brackets?

vale wigeon
#

i don't know what you mean by that

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but i do not mean that you should just blindly erase every single pair of parentheses

astral briar
#

uh

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2(5+6)

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remove brcakets

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10+12

vale wigeon
#

that's called distributing or expanding in english

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anyway yes this is what i want you to do

vale wigeon
#

................................

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you're literally on a math server

astral briar
#

k

vale wigeon
#

do you think me a nerd who deserves naught but mockery now?

astral briar
#

i am doing what u said

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expand

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dont search expansion in youtube btw

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dont do it

vale wigeon
#

adding a keyword like 'algebra' should filter out any unintended or unsavory results.

astral briar
#

here

vale wigeon
#

you're not done yet

astral briar
#

more expansion

#

?

vale wigeon
#

yes more expansion

#

i wouldn't say "expand everything" if i didn't want you to expand everything

#

but of course, why would you listen to such a nerd as me?

astral briar
#

(6x-12) * x =????

vale wigeon
#

you've never multiplied something by x before?

astral briar
#

wait

vale wigeon
#

(6x - 12) * x = 6x * x - 12 * x, as should be clear to you

astral briar
#

6x*x????

#

6x^2???

vale wigeon
#

yes

astral briar
#

k

vale wigeon
#

it strikes me as odd that you're putting up with me even after expressing your utmost disdain for me, what with calling me a nerd (derogatory) and all.

astral briar
#

6x-12 * x+1 ??????

astral briar
#

6x-12 * x+1 ??

vale wigeon
#

no

#

blighter, have you ever expanded things that look like (a+b)(c+d) before?

astral briar
#

wait

frank ferry
#

hello

vale wigeon
#

perhaps you may have heard of that blasted FOIL mnemonic that some students use to avoid thinking too hard about it?

frank ferry
#

can i get help

astral briar
vale wigeon
#

@frank ferry hello, this channel is currently busy. please post your question in another of the #questions-_ channels.

frank ferry
#

ok

astral briar
#

ily

frank ferry
#

ok

astral briar
#

6x-12 * x+1 ??????

#

a+b * c-d???

#

how do i do

vale wigeon
#

alright first off

#

you should not leave off the parentheses as you just did.

astral briar
#

yes

astral briar
#

but i just left it

#

anyway

#

what to do

#

(a+b)*(c-d)

#

how to do this

#

pls

vale wigeon
#

expanding a product like this is a matter of applying the distributive law, which you said you were familiar with, several times.

astral briar
#

so how

vale wigeon
#

(a+b)(c+d) = a(c+d) + b(c+d) = ac + ad + bc + bd

#

like this, roughly.

wary badge
#

@vale wigeon is he trolling?

vale wigeon
#

i don't know.

astral briar
#

i am not asking 1+1 am i?

wary badge
vale wigeon
#

...you just prompted me to read their about me

astral briar
brazen thorn
#

In an isosceles right triangle the measure of the angle other than right angle is
help pls

vale wigeon
#

won't you look at that

astral briar
#

isosceles triangle

#

90degrees

#

2 45 degree angles

astral briar
#

thats my about me

vale wigeon
#

god

#

this has become such a shitshow

sly mantle
#

yikes

astral briar
brazen thorn
brazen thorn
#

its from triangles chapter

astral briar
vale wigeon
#

alotoflust, your question has a blank space for a single word, yes?

astral briar
#

if it is an isosceles

wary badge
#

@brazen thorn u can have my notes

vale wigeon
#

or

#

no, wait, it's a number

brazen thorn
vale wigeon
#

alev this is over the top

#

none of this trig shit is necessary for alotoflust's question

brazen thorn
#

. The value of 0.3 ̅ in simplest form is
this one pls

wary badge
#

Oof

vale wigeon
#

....

#

......

frank ferry
#

any helpers can help me on one question :((((

brazen thorn
#

\

wary badge
frank ferry
#

oh ok

#

its sets

brazen thorn
alpine sable
#

1/3

frank ferry
#

i think that with 0.3 is like

#

infinite

#

0.333333333333333333333333333333

alpine sable
#

Yes

frank ferry
#

and so on

wary badge
#

Wait

#

It's 1/3

brazen thorn
#

this 1

wary badge
#

Small Mistake that's all

brazen thorn
wary badge
brazen thorn
#

pls answer this 1 too while at it

vale wigeon
#

@wary badge don't give out answers

wary badge
#

Oh got it

#

I am doing some mistakes :-)

vale wigeon
#

no

#

the fact that you're making mistakes isn't the issue

#

the issue is that you are going against the rules of conduct for this server

lone heartBOT
#
Rule 7

When asking for help, do not insist on getting just the answer; we are here to help you learn, not cheat. Likewise, if you are providing help to others, try your best to explain and elaborate instead of simply giving away the answer.

supple prawn
wary badge
#

I didn't revealed answer

misty holly
#

i think this is free now, so i just wanna clarify why 2z^2 is the cube root of 8𝑧^6 instead of just 2z like the cube root of 27y^3 which is 3y?

#

if anyone would like to answer my question please ping me

misty holly
#

oh! the z has to be 2nd power bcuz the exponent in 8z^6 is 6 and if u do z only, that is just z^3, yes?

mortal void
#

okay i assume its free now

#

please check if i made some mistake here

remote drift
#

Only same powers variables can be sub @mortal void

slow portal
#

Can someone help me integrate sqrt(1+(241.9822x-535.4727)^2) dx?

#

guess ill die

rigid smelt
#

do you know the identity tan^2(u) + 1 = sec^2(u)

#

try to apply that identity here

#

see in what way can you make 1 + tan^2(u) appear

alpine sable
#

I have a question
Why did she leave

glass lichen
silver lichen
#

Help plss

wary stream
#

Which one specifically and what have you done?

silver lichen
#

I want all

#

I have done 2

#

nd

wary stream
#

Which two have you done?

silver lichen
#

2nd

#

Question

wary stream
#

Channel busy

#

Use a number to plot -7 * 2

silver lichen
#

Ok

sly mantle
#

@alpine sable you’re already on thin ice due to your history. condescending msgs like that worsen your case

silver lichen
#

But my brain is not working

worn dew
#

My brain not working either

stable orbit
#

SinA=

(a) TanA- CotA        (b) TanA/CotA    (c) TanA- SecA     (d) CosA- SecA

#

Help pls

alpine sable
#

if you guys ever need help with long division go to math warehouse they show working and answers

worn dew
#

Where to find math warehouse @alpine sable

alpine sable
worn dew
#

That's for fifth grade

alpine sable
#

you asked for long division

worn dew
#

I'm on grade 9 now

alpine sable
#

oh ok

#

download gauthmath

worn dew
#

It's called quadratic equation

worn dew
alpine sable
#

ya free math solver

#

it finds a teeacher to solve ur question

#

or you can try snapask but its paid

worn dew
#

Oh really that will help me so much

rose carbon
#

How does this work?

rigid smelt
#

algebra

#

firstly c^2 is a common factor of c^2a^2 + c^2b^2

#

and then square and square root cancels

#

after that, assuming c is not 0, c/c=1

rose carbon
#

pardon me for my questions, im trying to learn haha

#

So the square cancels the square root so it would be ca + cb ?

rigid smelt
#

no

#

thats not how it works

#

can you factor c^2 out of c^2a^2 + c^2b^2 for me?

rose carbon
#

idk how i would go about it actually

#

sorry 😦

rigid smelt
#

have you heard of factorisation before?

rose carbon
#

yeah

rigid smelt
#

then just apply that to c^2a^2 + c^2b^2

#

factorise it

#

take the "common thing out"

#

||if you are still stuck, heres a hint, it should look something like c^2 * (something)||

rose carbon
#

right so c^2(a^2+b^2)

rigid smelt
#

yes

#

so now we have $\sqrt{c^2 \cdot (a^2+b^2)}$

ocean sealBOT
rigid smelt
#

are you clear?

rose carbon
#

oh yeah ok

#

so then ${ca+cb}?

rigid smelt
#

no

#

again it doesnt work like that

rose carbon
#

i typed it wrong idk how to use the bot

ocean sealBOT
rigid smelt
#

you can not simplify sqrt(a^2 + b^2)

rose carbon
#

ohhh i see it now

#

makes sense

#

so then we can do something like

#

like this

#

and it ends up being

#

makes sense, thank you

#

im trying to learn math but for now its being super hard since it has not clicked for me yet

#

thanks for your help 😄

verbal cradle
#

hey i have a question. in this question where did A and B come from? how is it related to the small letter a and b in the coordinates?

fringe robin
#

all are seperate variable A B are points and a b are x and y coordinate

verbal cradle
#

OHH thank you thank you

wary badge
#

$help

ocean sealBOT
#

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

wary badge
#

$$ If sin^2 x + sin x = 1 , Then Find the value of tan^4 x -tan^2 x $$

ocean sealBOT
fringe robin
#

you could take 1 as sin^2x +cos^2x in rhs

wary badge
#

My bad

#

I got the answer

fringe robin
#

Cool

wary badge
#

I forgot to frame sin^2 = cos^2@fringe robin

wary stream
#

,rotate

ocean sealBOT
wary badge
#

.......

#

I got cosx = sinx = tanx

glass lichen
#

you dont...

#

you also never answered the question

fringe robin
#

do you have to find tan^4x-tan2x or tan^4x + tan^2x

fringe robin
wary badge
#

No No Sorry Sin^2 x = Cos^2 x , cos x = tan x

fringe robin
#

Ok

wary badge
#

@fringe robin do u have any idea?

fringe robin
#

Tryin

wary badge
#

Can I use cos ^ 4 - cos ^ 2 = tan ^4 - tan ^ 2

fringe robin
#

if you do quadratic eqn calculation then you get sin x as (sqrt(5)-1)/2 using that you mebbe get

wary badge
#

We have Gotten tan x = cos x

#

So can I convert the question from tan ^ 4 - tan ^ 2 to cos ^4 - cos ^ 2

fringe robin
#

yes

#

is the answer 1?

glass lichen
#

no

stable orbit
#

if anyone has extra questions for trigno pleas forward

fringe robin
#

i used sin x as x in the og eqn and got value of sin x then found out value of tan^4x-tan^2x

glass lichen
#

I mean, I think the only way really is to find sin(x)=, then cos(x)=

#

cause you can show the goal equation is equivalent to $-[\cos(x)\sin(x)]^2$

ocean sealBOT
fringe robin
fierce frigate
#

URGENT HELP PLS

fierce frigate
#

its 9 pm and i got to do alot of things

#

this homework

#

is annoyin

#

T_

wary stream
fierce frigate
#

YES BUT WHEN I DO IT

#

IT JUST TURNS INTO NEGATIVE

fierce frigate
#

AND DECIMALS

#

i know its

a/ sin A = b/ sin B

#

but when i fill it in

#

like

glass lichen
#

like what?

fierce frigate
#

5.4/sin 42 =8/sin tetra

glass lichen
#

yeah

wary stream
#

Maybe you have the calculator in the wrong mode?

#

Like deg vs rad

glass lichen
#

Your problem is using the calculator, cause everything you've said is correct

#

unless you fucked up isolating for theta

wary stream
#

You mean theta?

fierce frigate
#

i do
sin theta x 5.4 = sin 42 x 8
sin theta = (sin 42 x 8) / 5.4

#

yes u know what i mean

#

it turns into negative

wary stream
#

Make sure you're in the proper mode

#

Like I said, degree vs radian mode

fierce frigate
#

how do i do that

fervent gust
wary stream
fierce frigate
#

scientific

wary stream
#

The type

#

Ti - 84?

tropic wagon
#

which model

fierce frigate
#

Casio fx-350ES plus

wary stream
#

Look at the top of the screen

#

Does it say D or R?

fierce frigate
#

wait

#

i know where i made my mistake

wary stream
#

I told you the mistake

#

You're most likely in the wrong mode

sly nebula
#

P+ 1/p =√5, p4 -1/p4 =?

Plz solve me this 😭😭 or me getting f in exm

fierce frigate
#

noi note the modee

#

i didnt count the sin first

#

i just placed it all in the calc

#

so it was wrong

wary stream
fierce frigate
#

ur not allowed to ask help during an exam

sly nebula
#

Nh assignment i searched my books and get only p4+ 1/p4 @wary stream

sly nebula
#

Sad life op

#

Huh

strange raven
#

Hi

sly nebula
#

Hello

strange raven
#

What's the effective and efficient way to learn proofs?

sly nebula
strange raven
fringe robin
wary stream
tropic wagon
#

we can't answer the question if you are in the middle of the exam

opaque island
#

Can somebody help with this?

wary stream
opaque island
#

How

wary stream
#

$$f(x) = x + 5$$
$$f(5) = 5 + 5 \implies f(x) = 10$$

#

That's a simple example

opaque island
#

So how do I do it with my problem

ocean sealBOT
#

dldh06

wary stream
#

You're given f(1), plug in that value

#

Into the f(x) equation

#

Same thing with g(x)

opaque island
#

So f(a+1)

wary stream
#

That's not what's written

opaque island
#

And g(4a-4)

wary stream
#

Don't change the question like that

gray isle
#

no, you're overthinking this

#

you're given
$$f(a) = a + 1$$
to determine $f(1)$, simply replace all instances of $a$ with 1.

ocean sealBOT
#

ℝamonov

opaque island
#

So 2?

#

I’m confused

gray isle
#

yes, in the first question
f(1) = 2

wary stream
#

Yes, for that part, but it's asking for 5f(1)

opaque island
#

So 5f(2)

wary stream
#

What? No

#

That changes the problem

opaque island
#

Oh I thought you put the 2 in

gray isle
#

f(1) is 2

wary stream
#

You plug in 1

gray isle
#

f(1) is not f(2)

opaque island
#

I’m better off watching someone solve it and I’ll ask questions along the way

#

If we can do that

gray isle
#

this goes back to the basics of algebra and substitution

#

concepts you should have a decent understanding of

opaque island
#

Ok so f(a)=2?

gray isle
#

no

opaque island
#

😐

gray isle
#

f(a) = a + 1
(given in the question)

wary stream
#

f(1) = 2, is proper

opaque island
#

So that’s correct though

wary stream
#

As stated by Ramonov previously

opaque island
#

F(1)=2

gray isle
#

f(a) isn't the same as f(1)

#

F isn't the same as f either

opaque island
#

Well it’s doing that sense I’m on phone

gray isle
#

f(a) = a + 1
and
f(1) = 1 + 1 = 2
don't make any unwarranted changes

opaque island
#

Bro I literally am so confused please just solve it step by step for me

#

Then I’ll ask questions

#

When I’m confused

wary stream
#

We're telling you how to do it

gray isle
#

you're given
$$f(a) = a + 1$$
to determine $f(1)$, simply replace all instances of $a$ with 1.

ocean sealBOT
#

ℝamonov

gray isle
#

doing that gets you
$$f(1) = 1 + 1 = 2$$
do you understand that part so far?

ocean sealBOT
#

ℝamonov

opaque island
#

Yes

gray isle
#

ok good

#

similarly can you determine the value of g(1)?

opaque island
#

0?

gray isle
#

yes

opaque island
#

Ok what nowh

wary stream
#

Determine $$5f(1) - 4g(1)$$

ocean sealBOT
#

dldh06

gray isle
#

now the question is asking for
$$5f(1) - 4g(1)$$
and you already determined the values of $f(1)$ and $g(1)$ so sub those values in.

ocean sealBOT
#

ℝamonov

opaque island
#

10f?

gray isle
#

wtf is 10f

wary stream
#

Why is there an f?

opaque island
#

Dunno I did 5 f(2)

gray isle
#

wheres is f(2) coming from

opaque island
#

The 2 we got earlier

wary stream
#

f(1) = 2

gray isle
#

f(1) = 2

#

f(1) = 2

#

f(1) is 2

opaque island
#

So just 5f+2

wary stream
#

f(2) = 3

gray isle
#

no

opaque island
#

Bruh

gray isle
#

f(1) has the value of 2

#

5f(1) is the product of 5 and f**(1)**

opaque island
#

Ok

shadow mango
opaque island
#

Bro I literally don’t know what you guys are even talking about

#

I’m honestly so confused

gray isle
#

do you 100% know what f(1) = 2 means?

opaque island
#

So what do I do with 5 f(1)

wary stream
#

If f(1) = 2, replace f(1) with the value of 2

shadow mango
#

substitute the value basically

opaque island
#

So 5+2?

wary stream
#

No

shadow mango
#

noo-

opaque island
#

Bro

wary stream
#

It's 5*f(1)

gray isle
#

5f(1) is the product of 5 and f(1)

opaque island
#

So 10

shadow mango
#

5 multiplied by f(1)

gray isle
#

and since f(1) has the value of 2,
would you agree that
5 * f(1) = 5 * 2

opaque island
#

So the awnser is 10

wary stream
#

Not the final answer

opaque island
#

Well the other side 4 x 0

#

So it’s just 10-0

#

Right?

wary stream
#

Yes, now that's correct

opaque island
#

So final awnser is 10

wary stream
#

Yes

opaque island
#

Ok now the next one

gray isle
#

can you try the second question on your own?

wary stream
gray isle
#

you more or less need to recall how to do basic substitution

#

(which should be intuitive)

opaque island
#

Ok thanks

#

I’m sure I understand it

#

Bye

inland shale
#

pls help

small bear
#

Do you know any theorems including a right triangle?

inland shale
#

yes pythageron therom

small bear
#

alright, did you apply it in this case?

inland shale
#

yed

#

yes

small bear
#

So, what did you get as a result

inland shale
#

15 squared plus 12 squared =c suared

small bear
#

very good

spark zenith
#

@alpine sable You are so smart

shadow mango
#

ah but 12^2 isnt the value of the base here is it?

inland shale
#

so i just do that?

small bear
#

Ah, correct Mochi

#

Let us look at the triangle again

inland shale
#

ok

shadow mango
#

Note that the base of the right triangle seems to be half of the length of the side of the square

inland shale
#

oh

#

it would be 6 squared

shadow mango
#

mm hmm

inland shale
#

so i do that equation and then what??

#

thats my answer?

shadow mango
#

what did you get the value of s to be?

inland shale
#

16.2

#

rounded to the nearest tenth

#

@shadow mango

shadow mango
#

yup that should be your answer

inland shale
#

ok

#

thx

inland shale
#

i also had a question

#

for this

#

i know how to solve for the triangle but not the parallelogram

shadow mango
#

well we have a right triangle here

inland shale
#

yes

#

u use the opythag therom here

#

*pythag

shadow mango
#

what did you get the height of the parallelogram as?

inland shale
#

we need to find that

#

let me do that

shadow mango
#

yeah go ahead

inland shale
#

cause it is connected to the oparallellogramk

spark zenith
inland shale
#

dont worry abt it

shadow mango
inland shale
#

mochi

#

the answer is 4

shadow mango
#

nice now 4 happens to be the height of the parallelogram right

inland shale
#

yes

summer adder
#

hi all, i need help

shadow mango
#

What is the formula for the area of a parallelogram?

shadow mango
inland shale
#

i do not know

inland shale
#

thats why i asked

shadow mango
inland shale
#

ok

shadow mango
#

It would be nice to go through the area and perimeter formulas of basic polygons

shadow mango
inland shale
#

ok

#

so that would simply be

#

4x5

#

?

shadow mango
#

oh no

inland shale
#

oh wait

#

no

shadow mango
#

our height is 4

inland shale
#

yes

spark zenith
#

what grade is he?

inland shale
#

5th

#

im 13

#

im homeschooled

#

thats why it doesnt make sense

shadow mango
#

since opp sides are equal our corresponding base is 4