#help-0

1 messages · Page 758 of 1

alpine sable
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yes.

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and obviously 2x does equal 2x.

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so the eqn is true

hot wedge
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what are those steps where you remove the f, why do we that again

alpine sable
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now same pattern with B.

alpine sable
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we figured out f(2x)=2x

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and we tried f(x)=x

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all i did was substitute that in

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you may be confused because it's somewhat a lot to take in, but it's all we've done together

hot wedge
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the steps where there { symbol is, i got confused there

alpine sable
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do you agree that what you said f(2x)=2x is true?

hot wedge
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yes

alpine sable
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here

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well, the } step is just substituting f(2x) with 2x, since both are equal

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and i drew the } to make it clearer to see where things are coming from

alpine sable
hot wedge
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o

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ok

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nvm i understand

alpine sable
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okay great

hot wedge
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okay

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so the answer is a?

alpine sable
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and same thing with the other }, we assumed at the beginning that f(x)=x so i just substituted f(x) with x since they were equal

hot wedge
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yeah

alpine sable
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hi, is it aloud to ask a lot of questions? i dont want to be annoying

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@alpine sable it is, but not here, this channel is occupied

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oh im sorry

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where can i doe?

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oh okay

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any of the channels that are free, everything is written in there

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@hot wedge so yeah one of the answers is a

hot wedge
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yeah

alpine sable
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but there might be others so we'll go with B now

hot wedge
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on the test only one answer is allowed

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o

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alr

alpine sable
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oh really, wait.

hot wedge
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mhm

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theres no more then option one

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its either A,B,C or D

alpine sable
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then yeah that's the only one.

hot wedge
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i just need to master functions (algebra 1) ones before like mid september whycat

alpine sable
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yeah no others are correct

hot wedge
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mhm

alpine sable
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it just seemed like they accepted more.

hot wedge
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ye

alpine sable
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anything else you need help with?

hot wedge
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uh

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no not now

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tysm

alpine sable
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is this right?

reef dust
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Is it -2 ?

alpine sable
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oops yeah so -32x^15 y^30

reef dust
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👍

alpine sable
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hehe almost forgot that the actual number will remain negative and the exponents will go positive

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huh, the answer came out as -32y^30/x^15

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i don't understand why

reef dust
alpine sable
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oh yeah

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what to do

dawn hatch
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does anyome know the domain and range of a function is?

dawn hatch
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-_-

verbal cargo
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i need help with poblem of fisica (i speak spanish, is a poblem? )

worldly breach
loud sentinel
worldly breach
dense blaze
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would it be wrong to say \
$(G ∨ Y) ∧ (\sim Y ∨ \sim G ∨ L) \equiv G ∨ (Y ∧ \sim Y) ∨ \sim G ∨ L$

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this is under logic

ocean sealBOT
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sevenseas

worldly breach
# loud sentinel

hey so for the second problem it ask do our eyes sees the whole TV so it is a yes?

loud sentinel
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yes

worldly breach
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okok thanks

loud sentinel
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Here’s a better representation

worldly breach
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can anyone explain the amplitude

worldly breach
topaz scaffold
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Amplitude is a measure of how tall the sine wave gets

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So what you can do is take the very top of the wave and subtract it by the very bottom then divide by 2

topaz scaffold
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Hmmm

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I'll do A as an example

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The highest point it reaches is y = 6

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And the lowest point is -4

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So you can do $\frac{6-(-4)}{2}$

ocean sealBOT
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RipeOrange

topaz scaffold
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Which is 5

worldly breach
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oh okay thanks

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how would u solve this?

alpine sable
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Let number Utta U = 1.1975807343 satisfy the equation:
U is the first positive value with a negative slope as the root of (2^U)/(U^2) – (U-1)/U = U^2 while:
(U-1)^U + (U-1)^(1/U) = (2^U)/(U^2) – U and:
(U-1)U + (U-1)(1/U) = (2^U)/(U^2) – U
Is this significant?

reef dust
verbal cargo
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...

worldly breach
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what is the axis of curve?

reef dust
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$So (1+(-3))/2=-1$

ocean sealBOT
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Arya22

reef dust
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y=-1 is axis in this case

worldly breach
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so the axis of curve and amplitude are the same?

reef dust
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Amplitude is a measure

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The line across which we measure it is axis

worldly breach
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what is the line cross?

alpine sable
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<@&286206848099549185>

alpine sable
sleek elbow
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@hot rampart "Anyone good at stats" thats not a question someone can answer easily. read #❓how-to-get-help

wintry vortex
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I have a wierd question lol.

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What is it called when your factoring and do the branching numbers that equal the main nubmer

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i rmemeber learning how to do it but i dont remember what its called

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and i have to write about it xd

alpine sable
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you can helP?

wintry vortex
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oof rough problem robot

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thats a mouthful

alpine sable
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yeah probably should write that in the form of (a+b+c)^2 but cant see how to put it correctly but i m not usre

wintry vortex
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Any help (on mine) would be appreciated 😅 i dont want to write a discussion and just not remember what to call what I did...which I dont lol.

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Sorry bro, im useless at that but I could wolfram it for you haha

alpine sable
inland shale
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i need help

ionic jewel
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and you forgot the +4

ionic jewel
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wait that ain't even right

wintry vortex
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😮 the +4? what plus 4 haha?

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oi

ionic jewel
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why is it 11x^2 in your parenthesis

wintry vortex
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oh im dumb

ionic jewel
wintry vortex
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OHHHHH its not +4 its t^4

inland shale
wintry vortex
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t^4

inland shale
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on the graph

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?

ionic jewel
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no

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like where both statements are true

inland shale
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so how would i know which one is the right choice

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?

ionic jewel
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for example x > 1 interaction with x <2 implied x is between 1 and 2

ionic jewel
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but what you applied is called difference of squares

ionic jewel
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if that sounds better to you

inland shale
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yea

wintry vortex
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Agreed, that was a mistake, i kinda made my T x for some reason. xD but thank you so much!

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I could hug you right now!

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i knew it was a thing how i did it but when i went to write how i came acros my answer my brain went blank

inland shale
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its such a nice server

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:D

wintry vortex
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it has def saved my sanity

inland shale
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mhm

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same lol

wintry vortex
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whats left of it

inland shale
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dont say that

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be postivive

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❤️

wintry vortex
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Meh, sanity is overrated 🤪

inland shale
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lmao

inland shale
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in ur profile pic

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?

wispy olive
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How do we get that -
c *(d+c) = c^2.

light sparrow
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its the font that is throwing you off - its actually d+e not d+c

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and if you look at the diagram, d+e = c

wispy olive
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Ohhh.

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Thanks!

wintry vortex
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@inland shale yes it is lol

native temple
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Why did my elimination fail?

alpine sable
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I can’t see this

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Please upload an image

night tundra
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How do I do this

surreal meadow
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which one

novel lintel
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what would the negation of this statement be? Is it, Prove both intervals contain an integer?

ionic jewel
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This is saying that either the first interval contains an integer, or the second interval contains an integer (but not both), do you know how to negate "(exlusive) or" statements?

fair vine
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not (a&b) = not a or not b

ionic jewel
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The cases where this isnt true is when both intervals contain an integer, or neither of them do.

novel lintel
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its is also possible that neither contain an integer

ionic jewel
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Oh my mistake I misread

ionic jewel
novel lintel
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gotcha, thanks!

night pelican
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hi

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i am confused on how to express this fraction in its simplest form = 3-2/3

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i have the answer but want to try and grasp the concept since i am confused

wary stream
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Is that supposed to be $$3 - \frac{2}{3}$$?

ocean sealBOT
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dldh06

night pelican
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yes

wary stream
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Because first get a common denominator

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Then subtract the two

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Then simplify if necessary

night pelican
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hm alr

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wait so a common denominator of the two numbers that make up the fraction?

wary stream
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A common denominator helps you combine the two numbers

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Like $$2 + \frac{2}{9} \equiv 2 *\frac{9}{9} + \frac{2}{9} \equiv \frac{18}{9}+\frac{2}{9} \equiv \frac{18+2}{9} \equiv \frac{20}{9}$$

ocean sealBOT
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dldh06

night pelican
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my math teacher told me to multiply the bottom number with the middle number + the top number

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so 9 times 2 plus 2

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20/9

wary stream
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That works too

brave urchin
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im just stuck on these type of exponential property questions and just seem to be stuck

wary stream
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Factoring out the GCF

placid zinc
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@brave urchin
What's:
x + 64x

brave urchin
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65x

surreal meadow
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it's a simple question, don't overthink it

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yes it's 65x

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so now instead of x, make it (1/8)^x

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all they've done is factor the (1/8)^x

brave urchin
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what did they do to factor it im just not seeing it i know i learned it a while back but seem to have forgot

surreal meadow
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(ax + bx) = x(a+b)

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cy + dy = y(c + d)

brave urchin
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ah thank i see it a little more clearly now

placid zinc
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@brave urchin
I wouldn't even call it factoring.
t + 64t = 65t
That's true, no matter what t is. So, let t = (1/8)^x:
(1/8)^x + 64(1/8)^x = 65(1/8)^x

alpine sable
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I know that Sin^2y + cos^2 y = 1 but it doesn't help...

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wait sorry I mean Solve siny + 2(cosy)^2 = 1

placid zinc
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Oh you changed the question haha

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The pythagorean identity does help, but only after arranging to:
cos^2(x) = 1 - sin^2(x)

alpine sable
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Okay I'll try a little bit from here

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So I have

siny + 2(1-sin^2y) = 1

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And I'm not sure how to go on again...

sudden crypt
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Maybe try a substitution z = sin(y)

placid zinc
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This is a quadratic equation in disguise.

alpine sable
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oh so 1-z^2 = (1-z)(1+z), is that the trick? Thanks!

placid zinc
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You'll get:
z + 2(1 - z^2) = 1
-2z^2 + z + 1 = 0

alpine sable
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I got

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Z+ 2 ( 1- z^2) = 1

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Z+ 2 (1-z) (1+z) =1

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2(1-z)(1+z)=1-z

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2+2z = 1

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Z = -1/2

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Siny = -1/2

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dam I forgot what y is for that... Okay found my calculator it's 330 degrees

placid zinc
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In order to do this step:
2(1-z)(1+z)=1-z
2+2z = 1
You divided both sides by 1 - z, which gets rid of the 1 - z = 0 solution

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In general, factoring is safe, division is not

alpine sable
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Now I'm stuck again..

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I'm thinking about
sin θ=-1/2
θ= -30 degrees

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and
Tanx = 4/5
X= 38.659 degrees

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and brute force the answers

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Do you guys know any website that calculate derivatives for me with steps?

oak chasm
umbral nest
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What does it mean when it says label the x intercepts and y intercepts

vast bobcat
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the x intercepts are when any point on the parabola touches the x axis

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and the y intercepts are when any point on the parabola touches the y axis

umbral nest
vast bobcat
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that's one of them yes

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but there's another one

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two points cross the x axis

umbral nest
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oh i see

vast bobcat
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so it would be (-2.5,0) and (2.5,0)

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for y intercept it's where the point lines on the vertical line

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so the y intercept is..?

umbral nest
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0, -6

vast bobcat
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yes

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good job

umbral nest
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oh ok thanks

vast bobcat
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try solving the x and y intercepts for 2 and 3

umbral nest
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nah i got it now, thanks for the help

vast bobcat
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okay alg

umbral nest
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thanks have a great day

alpine sable
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Can anyone help me with this?

oak chasm
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@alpine sable Combine the logs into one.

alpine sable
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what is the formula for that?

oak chasm
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Do you know the logarithm rules?

alpine sable
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log ( them multiplying each other)?

oak chasm
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Yes, that's right.

wise zealot
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Im confused

oak chasm
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@wise zealot Sorry, channel is busy. #help-8 looks open if you hurry.

wise zealot
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Okay, thanks

alpine sable
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im wondering for '7a', why they didnt have the domain from 0-10

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as they put 0=<x=<6 instead

oak chasm
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Do you understand how the box is made after the x squares are cut out?

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@alpine sable

oak chasm
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OK, so one of the small ends of the original rectangle.

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The two squares you take out can't be wider than that small end of the original rectangle.

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Does that make sense?

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If they are together wider than the small end then you're not really cutting a square out.

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@alpine sable Does that make sense?

alpine sable
oak chasm
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No, you can't get a negative volume.

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No matter how you cut a piece of cardboard, you can't get a negative volume from it.

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The reason is that if the pieces you cut out have to be squares, then the widest you can get is half the width of the smaller side.

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If you try cutting squares from the corners that are larger, you'll cut the first square from a corner.

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Then the other corner on the small side won't have enough material to make the other square.

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Does that make sense?

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The remaining part of the small side won't have enough width to make the square corner as large as you want it to be.

south abyss
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hey, can i get a proof for adjacent angles? https://foob.cc/Hgv6iWm.png

hi

hey lol, i have 639 uploads on foobhost

flex time: i joined on 8/1/2021
the time of sending this is 1:53:30 AM, on 8/21/2021. (this is utc, im edt)

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<@&286206848099549185>

karmic gorge
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it's been like 10 minutes (give a little more time)

kindred hull
south abyss
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6 and 8

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2 and 4

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1 and 3

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5 and 7

kindred hull
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I believe they are called opposite angles

thorn vortex
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wdym by ''''proof''''

gray isle
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you're referring bro vertically opposite angles or just vertical angles.

kindred hull
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I got him a proof it’s ok

gray isle
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the proof for congruence is simply applying the angle sum on a straight line twice

kindred hull
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Ye that’s what I showed him

alpine sable
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I don't understand what this question wants me to find

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Does it just want me to just randomly to give a note like B, or it needs calculation? I don't see any equation besides the frequency...

karmic gorge
astral dagger
ocean sealBOT
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SubGui

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SubGui

knotty tinsel
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mine should be a very simple one for those here, as your guys' math is way above mine. So what i'm triyng to figure out is the process for finding the base amount, that when added a percentage, equals the known total, so x+3.5%=1391.41 . I'm not just looking for an answer, i'm trying to understand the way it is derived, so I can learn

sharp sigil
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Adding 3.5% is as good as adding 35/1000*x to the initial amount.

cloud olive
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Hi i need hep in writing my answer in range
{y element R : y>=-25/16}
How can i write this in word form? like set of non-negative real numbers such that y ≥ 1
Wil i write set of all real numbers or set of non-negative real numbers?

alpine sable
astral dagger
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I think that's because you're talking about the velocity

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of the sound wave

ocean sealBOT
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SubGui

celest anvil
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not sure how to write the sum

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the triangles are growing at a rate of 2

alpine sable
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how is A not infinite?

celest anvil
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no idea

jolly stone
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i think the triangle iterates to the left

alpine sable
celest anvil
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so it's by a rate of 1/2 starting at 1

alpine sable
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Also triangle area = bh/2
A = 25b/2 = 12.5b
b = sum (1/2)^n to infinity

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All in all the triangles could only take up half the space

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A = 12.5 no ?

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ah write an equation for it

celest anvil
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yes i that's why i did 25*1/2

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thanks i got it

alpine sable
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what was it

celest anvil
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25/2

alpine sable
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ah yea

sonic kelp
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how can i show that the image of $f(x)=x^3+x$ for all $x\in [1,3]$ is the interval $[2,30]$ using the intermediate value theoprem?

ocean sealBOT
gray isle
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that question sounds off.

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that's not what the ivt shows

sonic kelp
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Well the questions says ivt can help haha i know that i can show that 2=inf{f(x) for x in [1,3]} and 30=sup{f(x) for x in [1,3]} but i dont know how to show that

gray isle
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have you done differentiation yet?

sonic kelp
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not yet

gray isle
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i guess you can first deduce that the function is increasing for all x

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from properties of a cubic

steady musk
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Given a family of 5 children and Event A being "first three children are boys" and Event B "There is exactly one girl", are events A and B independent or dependent?

oak chasm
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@steady musk What's the formula for independence?

steady musk
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@oak chasm if P(A and B) = P(A) * P(B), but there is no probability for P(A and B) yet right?

oak chasm
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Well, you can find it.

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What's the probability that the first three children are boys and there is exactly one girl?

steady musk
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I got 0.125 and 0.15625

oak chasm
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Fractions are better.

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1/8 and 5/32

steady musk
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right

oak chasm
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So, anyway, what's the probability that the first three are boys and there is exactly one girl?

steady musk
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5/256?

oak chasm
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How did you calculate it?

steady musk
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multiplying the probabilities

oak chasm
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How do you know it's independent?

steady musk
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well thats the thing

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I dont know if it is

oak chasm
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OK, then you shouldn't multiply them.

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That only works if it's independent.

steady musk
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what other method do you use to work it out then

oak chasm
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Well, the first three are boys.

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And there is exactly one girl.

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So what combinations work?

steady musk
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BBBGB and BBBBG i guess

oak chasm
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How many combinations are there in total?

steady musk
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two

oak chasm
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There are a lot more than two.

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For example, BBBBB, BBBBG, BBBGB, BBBGG, ....

steady musk
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You mean total combinations?

oak chasm
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Yes.

steady musk
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2^5 combinations

oak chasm
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OK, so combinations that work divided by total combinations.

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What's that?

steady musk
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1/16

oak chasm
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Is this true?
1/16 = 1/8 5/32?

steady musk
#

hmm no it doesnt

oak chasm
#

OK, so it's not independent.

steady musk
#

got it ty 👍

oak chasm
#

You're welcome.

knotty tinsel
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@sharp sigil sorry for the delay, busy night at work. i think you misunderstood. i'm trying to find the inital amount. so x + 3.5%=1391.41. I know the value of 1391.41, i'm trying to find out the base amount before the 3.5% was added to give a total of 1391.41. I'm trying to find the inital amount.

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and the method used to come to the answer

oak chasm
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Adding a percentage works by multiplying 1 plus the percentage. Here, it's (1 + 0.035).

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x(1 + 0.035) = 1391.41

knotty tinsel
#

ok, how does that determine what x is?

grim fjord
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@knotty tinsel

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Are you doing some interest question?

knotty tinsel
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i don't understand the question you're asking. what is an interest question? I'm just trying to find a method to answer finding the base amount before a % was added, only knowing the total, as throughout my life i've needed to come to this answer and don't really know a method to do so

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sorry, @grim fjord

grim fjord
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Sort of like

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Money interest

knotty tinsel
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not interest, but related to money yes

grim fjord
#

Do you have the original question?

knotty tinsel
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yes, i have a complete total of $1391.41. i know that that total is a base amount (x) + 3.5% of the base amount. i'm trying to determine what the base amount would be before the 3.5% was added

grim fjord
#

This is interest

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So basically you're finding the principal value

knotty tinsel
#

yes

grim fjord
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Before it reached it's final total.

knotty tinsel
#

yes

grim fjord
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Do u have an answer to the question

knotty tinsel
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sorry, it wasn't specifically about interest, it's about fees being applied to a transaction, so i didn't know it still fell under interest naming

grim fjord
#

Actually it might not be interest

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But anyways

knotty tinsel
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i got an answer, but by trial and error using a % calculator. i'm more looking for a reliable method to get to the answer

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as i'd rather know how to solve it then just get the answer

grim fjord
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Wait

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Give me the answer

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So I can check

knotty tinsel
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well crap, let me see if i can find it again lol. one sec

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1344.35

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but i used a tool and used trial and error to come to the correct answer, so it's probably not exact

grim fjord
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Gotcha

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So

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You know that percentages are numbers over 100 right

knotty tinsel
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i know that 3.5% is a multiplication of .035

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that's about it

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oh i get what you mean

grim fjord
knotty tinsel
#

so x+3.5%=1391.41, and x*1.35=1391.41 correct?

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err

oak chasm
#

1.035

knotty tinsel
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x*1.035=

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ok so with knowing that, how does that help me find x?

oak chasm
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OK, so how is 1.035 connected to x?

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What operation?

grim fjord
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Solve for x

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Alright

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Wait

knotty tinsel
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multiplication

grim fjord
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Take it slow

oak chasm
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What's the opposite of multiplication?

grim fjord
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X is your principal value

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So, you want to find 1 percent of X right?

knotty tinsel
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@oak chasm i understand it's not your intent, but that came off as demeaning

grim fjord
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What do you do

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X is 100 percent

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So how do you find 1 percent

knotty tinsel
#

/100

grim fjord
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Yes

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And that is one percent

knotty tinsel
#

yes

grim fjord
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So you get X/100

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That's 1 percent

knotty tinsel
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i understand that

grim fjord
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Now you want to find the added 3.5

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Percent

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When you add 3.5 to a total

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You add it to a 100 percent right?

knotty tinsel
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yes

grim fjord
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So what's the new percentage?

knotty tinsel
#

103.5

grim fjord
#

Yes

#

And you have 1 percent which is

#

X/100

knotty tinsel
#

yes

grim fjord
#

Now, take X/100 multiply it by 103.5

#

To get your new %

knotty tinsel
#

yes, which is 103.5

grim fjord
#

What

#

Wait

knotty tinsel
#

i don't know x. x has no value

#

given in your example

grim fjord
#

Exactly

#

But you have 1 unknown value

knotty tinsel
#

yes

grim fjord
#

So x/100 times 103.5

#

What do you get

knotty tinsel
#

but asking take x/100 multiply it by 103.5, i can't multiply by 103.5 as i don't know the value i'm multiplying

#

or are you asking what the total is

#

maybe i misunderstood. sorry

grim fjord
#

What

knotty tinsel
#

1391.41

grim fjord
#

No

#

What

#

?

#

You want to find x

knotty tinsel
#

yes

grim fjord
#

You're supposed to not know what X is

knotty tinsel
#

sorry, one minute, work call

grim fjord
#

X/100 multiplied by 103.5 is just 103.5x/100

sonic kelp
#

is $\sqrt{1-tan^2(x)}$ continuous in some domain?

ocean sealBOT
sonic kelp
#

<@&286206848099549185>

rigid smelt
#

yes

#

and ping helpers after a minimum of 15min

sonic kelp
#

oh sorry

rigid smelt
#

and by "in some domain", i suppose you are talking about restricting the domain of sqrt(1-tan^2(x))

sonic kelp
#

Yes i was trying doing $1-tan^2(x)\geq 0$

ocean sealBOT
rigid smelt
#

yes it can be continuous given an appropriately restricted domain

sonic kelp
#

but i got confused because wolfram says that $\sqrt{1-tan^2(x)}$ isnt continuous on its domain

ocean sealBOT
sonic kelp
#

thank you!

rigid smelt
#

its not unless the domain is restricted

white kiln
#

im gay at math help

grim fjord
#

What topics

white kiln
#

u help me

#

ok

#

tank

grim fjord
#

What topics

white kiln
#

I DONT KNOW i skipped class yesterday

#

ok

#

i just found this randomly

grim fjord
#

How do you ask for help if you don't know the question

white kiln
#

i put math on invite link thingy

grim fjord
white kiln
#

okok

#

!1!!!

grim fjord
#

Sets

#

which

#

6?

white kiln
#

i just dont know ok

grim fjord
#

Okay

#

So

#

You see that U symbol?

#

It means union

#

It's basically "and"

#

AUB means the contents of A + B

white kiln
#

ok

grim fjord
#

And when you get that

#

There's the n symbol

#

Which is an intersection

#

Basically the things that two stuff have in common

#

You like bread I like bread that's our intersection

white kiln
#

ok

#

thanks

#

im

#

do that

#

ur epik

knotty tinsel
#

@grim fjord ok back, sorry about that

#

fridays are super busy for work

grim fjord
#

No probs

grim fjord
#

@knotty tinsel Alright

#

Generally, in algebraic equations

#

When you have 1 unknown

#

You can solve it

#

X+5=5

#

One unknown

#

X=0

#

You get that

knotty tinsel
#

yes, though that's a pretty simple example lol

#

so last we were on was X/100 multiplied by 103.5 is just 103.5x/100

grim fjord
#

Yea

#

Exactly

#

103.5x/100 is your new value.

#

What's your new value?

knotty tinsel
#

3.5x

#

wait

grim fjord
#

Your new value is the number

knotty tinsel
#

1.035x

grim fjord
#

That's your new value in terms of x

#

1391.41

#

1.035x = 1391.41

knotty tinsel
#

gotcha

grim fjord
#

Find x

knotty tinsel
#

1.035x=1391.41

#

ah

#

oh shit

#

just had an aha moment

grim fjord
#

You get it?

knotty tinsel
#

1391.41/1.035

#

=x

grim fjord
#

yes!

#

there you go

knotty tinsel
#

Burp, you da man/woman/nonbinary being

lean stone
#

hey whats the answer to part B

#

what is a constant term here

grim fjord
#

oh no binomial

lean stone
#

lmao, not a fan?

grim fjord
#

i fear that

#

binomial

#

is

lean stone
#

its not thaaat hard tho, there are like series qs that mess me over

#

its just long

grim fjord
#

yea

lean stone
knotty tinsel
#

@grim fjord now that its staring me directly in the face, i feel like a moron, which for all intents and purposes i am in this scenario lol

grim fjord
#

lmao

#

just keep doing those questions

knotty tinsel
#

thank you for your help, and more, for explaining in a way that i can understand. i appreciate it

grim fjord
#

no prob, feel free to ask me anything as long as I have reached there in terms of learning

#

@lean stone I'm going to try it

#

Face my fears

lean stone
lean stone
grim fjord
#

Also do you happen to know the difference between the general and special forms?

#

Of binomial

#

I have a math examination on monday

#

it has binomial

#

Very painful

lean stone
lean stone
grim fjord
#

big

lean stone
grim fjord
#

yes

lean stone
#

thats part a? @grim fjord

grim fjord
#

yea

#

Is it correct

#

For part a

#

I'm a binomial infant

#

Waot

lean stone
#

yes maam

#

also the question was flawed

#

lmao it asked me to find the constant but labeled the constant as "x"

#

for part b so dont bother w that

#

u could find the constant term but change the x to like a different letter

grim fjord
#

Oh

lean stone
#

yea see, theres 2 xs

#

@grim fjord did u delete ur working lmao

grim fjord
#

yea i did

lean stone
#

why

grim fjord
#

i thought it was wrong but nvm

lean stone
#

ah, well dont delete it

#

how am i gonna help lmao

grim fjord
#

one sec

#

@lean stone

lean stone
#

uhh

#

u missed out the /4

grim fjord
#

wait I forgot to simplify 10C1 and the others

lean stone
#

no thats fine, but the x

#

its supposed to be x/4

grim fjord
#

i simplified it

lean stone
#

OH

#

ookok thats how u did it

grim fjord
#

yep

lean stone
#

strange way to go about it but cool

grim fjord
#

i mean

#

they did ask for simplest form

#

@lean stone are ya sure the question is wrong?

lean stone
grim fjord
#

does that stand for marking scheme

#

or mamong suss

lean stone
#

the question aint wrong but the way they wrote it looks strange

grim fjord
#

hmm

lean stone
#

its mamongus suss

grim fjord
#

alright i'll try the next one

lean stone
grim fjord
lean stone
#

u got taste

grim fjord
#

yes broke

#

my binomial theorem notes are labelled "pain in the ass"

lean stone
#

lmao

lean stone
#

YO @grim fjord thanks fam

grim fjord
#

does it work?

lean stone
#

i still gotta watch it lmao, but after reading the MS i get it

grim fjord
#

alrighty

lean stone
#

yeah the question aint wrong

#

just gay

grave bough
#

Need help with the following problem:
Find all values of parameter a, so that the following equation has only 1 solution.

ocean sealBOT
#

kingapplefruit

icy trail
#

combine the terms on the left side to get $\sqrt{\frac{8\sqrt{3} + 8}{\sqrt{3}}$

ocean sealBOT
#

querty
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

icy trail
#

$\sqrt{8 × \frac{3 + \sqrt{3}}{3}}$

ocean sealBOT
#

querty

icy trail
#

if you put them in a calculator they're not the same o.O

clear vessel
#

Hey, log x ^3 - log x ^ 2 is just log x right

clear vessel
#

what

#

ahahah

#

okay I thought so

grim fjord
#

i thought x was the base lol

cosmic token
#

hi

clear vessel
#

How do I solve p^2x - 6p^x + 8 = 0 if lg p = 5

alpine sable
#

$p^{2x}-6p^x+8=0$ if $\log(p)=5$?

ocean sealBOT
#

Al𝟛dium

clear vessel
#

yes

alpine sable
#

okay, is the log base 10 or e?

reef dust
clear vessel
#

ooh

#

thanks

reef dust
#

👍

alpine sable
#

Is there a tool that can enter 3 points to find a quadratic equation?

ionic jewel
#

yes

#

probably wolfram tbh

alpine sable
#

If x + 4 = 0 so x =?

ionic jewel
alpine sable
#

Thank you

alpine sable
dense blaze
#

how do i get \
$\lim_{x \rightarrow 0+} \frac{\sqrt{4x^{2} - x^{4}}}{x}$

ocean sealBOT
#

sevenseas

dense blaze
#

the ans is 2

#

i tried rationalising but it became messier

candid sluice
#

notice that $\sqrt{4x^2-x^4} = x\sqrt{4-x^2}$

ocean sealBOT
dense blaze
#

OHHH

#

thank you!

candid sluice
#

np

worn sleet
#

hi, just need a little help with wording
if I have A(X) = 0.5*X^2, is it correct to say "A is a quadratic function of X"?

tulip pier
#

How do you do this?

jolly stone
# tulip pier

it's the area under the normal distribution from mu+sigma to infinity (aka 1 sigma to the right of mean)

ionic jewel
#

you can just look it up on a table

#

actually integrating that would look ugly

tulip pier
jolly stone
ionic jewel
#

this isn't a calculus question at all, it's a normal distribution question

tulip pier
#

i know that the area underneath from mu - sigma to mu+sigma is 68%

jolly stone
#

ok, from that, can you find other areas to find out what is the area from mu+sigma to infinity?

tulip pier
#

oh so that table

jolly stone
#

hint that it's symmetric around mu

tulip pier
#

i always though of it as a diagram\

jolly stone
#

yep that's one way to find directly

#

should be the tail distribution, since it's at the tail infinity

tulip pier
#

so it is 13.6 + 2.1 +0.1 right?

#

15.8%

worn sleet
reef dust
#

Divide by x on both sides
You will get x^(x-1) =1

#

Now there would be 3 cases:

  1. power of x is 0
  2. base is 1
  3. base is (-1) with even power
#

Try solving these cases
You will get all the required solutions

bright pagoda
#

Hey! So my little brother has been playing this one roblox game, and has gotten pretty lucky
In 350,000 attempts, he has gotten 3 1/2,000,000 percent chance items and 2 1/200,000,000 percent chance items
What are the chances of getting that, in that many attempts
I know it won’t be exact but a close number would be nice at least to know

bright pagoda
#

<@&286206848099549185>

small bear
#

So I'm pretty sure someone here could calculate the exact probability, but if you need an estimate then we could do it like this

#

Firstly, the probability that you get 3 items of rarity 1/200000000 (eliminating the percent) in 350000 attempts is (350000 choose 3) (1/200000000)^350000 (199999999/200000000)^(350000-3)

#

This is using the binomial probability

#

Same can be done for the second event (which is going to be an even smaller number

#

(and if the events were independent, which they arent) we would multiply both of those to obtain the final value

sand jetty
ocean sealBOT
#

itzikony

small bear
#

so you are looking at P(A) P(B) < Actual probability < P(B) where P(A) is the 3 items being picked, and P(B) is the 2 items being picked

sand jetty
#

but i may be mistaken, i did probability like a year ago

small bear
#

It's going to be smaller I believe

jagged rapids
#

why is it that if x,y are integers, then $ 2^x \le y $ can't have $x = \floor{log_2(y)}$ as the largest possible x

ocean sealBOT
#

killBird

#

killBird

small bear
#

We could have that, for example y=5 => x=2 which is true

wide raven
#

i can't find a way out

#

<@&286206848099549185>

alpine sable
dense blaze
#

but i didnt learn yet so i cant use it

#

but yup @ Pappa told me how to do it alr 👍

alpine sable
#

oh true

plucky geyser
#

Why are the graphs of these two trigonometric functions the same?

reef dust
verbal coral
#

can someone explain this to me? what is the difference?

vale wigeon
#

order of operations

#

exponents come before multiplication

#

the minus sign in this context acts as multiplication by -1

#

so $-5^2$ would parse as $-(5^2)$, or $-(5 \times 5)$

ocean sealBOT
vale wigeon
#

while $(-5)^2$ is of course $(-5) \times (-5)$

ocean sealBOT
verbal coral
#

but do they have different answers?

#

seems to me like its the same

#

minus * minus = + right

gray isle
#

did you try evaluating them given the new information?

#

the product of two negatives is positive yes

#

if that's what you meant

verbal coral
#

yea so they're both 25 then, i dont understand this

sage bronze
#

And calculate it

gray isle
#

how are you getting 25 for:
$$-(5\times 5)$$

ocean sealBOT
#

ℝamonov

verbal coral
#

ahh

#

i might get it

#

I was thinking -5*-5 for them both, but for -5^2 you have to calculate the 5^2 first and then add the minus

#

is that correct?

#

I think I get

verbal coral
#

I didn't know the rules

glass lichen
#

That's why Ann said order of operations.. then explained it

verbal coral
#

wtf is exponent, idk english math terms

glass lichen
#

A^b has exponent b

verbal coral
#

?

vale wigeon
#

what is your first language?

#

i may be able to find the word in your language

verbal coral
#

danish, but I think I get it now

vale wigeon
#

it's... eksponent in danish apparently

verbal coral
#

yea we haven't learned that term yet apparently

desert moon
#

in the convolution integral, why is one of the functions reflected?

jovial crypt
#

If determinant of a matrix is 0 does this also imply that at least one of it's rows or column must have all elements=0

#

Ik that this is true the other way around but wbu this?

desert moon
#

no

vale wigeon
#

$\bmqty{1 & 1 \ 1 &1}$

ocean sealBOT
vale wigeon
#

@jovial crypt

jovial crypt
#

I see

wide raven
#

Please help

jovial crypt
#

So I can make them non zero with standard operations

vale wigeon
#

vampy, do you have any follow-up questions or should @wide raven move?

jovial crypt
#

All good

#

Thanks y'all

covert agate
wide raven
#

@vale wigeon move ? As in?

fierce frigate
#

help me T_T

vale wigeon
#

@wide raven as in ask your question in another channel, one that isn't occupied already

wide raven
#

Very sorry

alpine sable
loud sentinel
fierce frigate
#

thx

#

but i already found out how

loud sentinel
#

Please see this for reference

#

oh ok

fierce frigate
#

i moveed out to another question

#

thx

loud sentinel
#

sorry was late

#

:/

fierce frigate
#

itsoke

#

but u can help with how do they found this

#

WAIT

#

I UNDERSTAND

#

AHHA

#

FIRST TIME

#

I ACTUALLY UNDERSTAND TRIOGEMETRY

loud sentinel
#

wow congrats

#

sure it can be confusing at first

#

but youll work your way through it

dense blaze
#

hi can i ask if its possible to prove
$\frac{d}{dx} \sqrt{x} = \frac{1}{2 \sqrt{x}}$ using mathematical induction, since there's no n here?

ocean sealBOT
#

sevenseas

vale wigeon
#

how exactly are you going to prove by induction a statement that doesn't involve any natural numbers at all

#

for induction, you need the statment to go "for all natural n, ..."

#

obviously the letter n can be substituted for anything else, but there has to be a natural-valued variable under a 'for all'.

dense blaze
#

yeah ok so i can only use induction when there's a natural number n

glass lichen
#

Yes...

#

You'd prove that just by definition

dense blaze
#

alright thankss

languid pulsar
#

Can someone help me understand the reformulation steps to get the second equation?

gray isle
#

divide numerator and denominator by $e^{z_j^L}$

ocean sealBOT
#

ℝamonov

languid pulsar
#

Ahhhhhhhhhhhhhhhhhhh thank you!

#

Now I get it

covert agate
honest token
#

Hello guys, it's possible to find the equation of a 3th degree function using some coordinates?

#

I know that we can use the general equation of the line for 1st degree function

candid sluice
#

lagrange interpolation is probably what you want

#

im personally not familiar with other polynomial interpolation methods

honest token
#

i'll search about it

#

thanks :p

#

This is just a test with some random points, but this is exactly what i need. @candid sluice thank you.

lyric pulsar
#

Guys can someone help me with a math problem?

#

My brother and me couldn't do it.

stoic cloud
#

Say I have three ratings, 45, 67, 93. And I wanted each to be a different weight percentage of the whole rating, what math would I use to find that?

vale wigeon
#

it's not 100% clear what you're talking about, but personally my best guess is you're looking for a weighted average.

stoic cloud
#

i want each of the three numbers to be a different percentage like 45 is 30% of the whole average and 67 makes up 20% of the whole average

#

@vale wigeon

vale wigeon
#

so you want the first rating to contribute 30% to the average, the second 20%, and the third 50%?

stoic cloud
#

ye

vale wigeon
#

yeah that's definitely a weighted average you're looking for.

#

$A = 0.30r_1 + 0.20r_2 + 0.50r_3$, where $r_k$ are your ratings (which you gave as $r_1 = 45, r_2 = 67, r_3 = 93$ in your example)

ocean sealBOT
devout wasp
#

what differentiation formula can I use to find the derivative of this?

oak chasm
#

Logarithmic differentiation.

#

f' = f (log(f))'

#

@devout wasp

devout wasp
#

Thanks!

stoic cloud
#

for weighted average why dont you divide the number you get by how many u added?

#

why do you just multiply the percentage you want for the numbers then add?

oak chasm
#

What do you mean by the number you get?

stoic cloud
#

(50 * 0.30) + (80 * 0.2) + (90 * 0.5) = 76% Total Grade

Why wouldn't we divide the 76 by 3 ?

#

@oak chasm

#

For weighted average

oak chasm
#

Because that won't give the weighted average.

#

It gives a different number.

#

You divide by the sum of the weights.

#

Like with a normal average, the weight for each number is 1.

#

You add the weights, which is 1 per number, which adds to the count of numbers.

#

Then you divide by that.

#

(1 · 5 + 1 · 2 + 1 · 3)/(1 + 1 + 1)

#

Same thing with different weights.

#

(0.3 · 50 + 0.2 · 80 + 0.5 · 90)/(0.3 + 0.2 + 0.5)

#

See how I added the weights to figure out what to divide by?

stoic cloud
#

OHHH

#

yes

#

i get

alpine sable
#

how do I compute the limes of this one?

vale wigeon
#

but if your weights are percentages adding up to 100%, i.e. 1, it's redundant.

oak chasm
#

@alpine sable What do you mean by limes?

alpine sable
#

the limit 😂

oak chasm
#

What's n going to?

alpine sable
#

as n goes to infinity

oak chasm
#

Do you know derivatives?

#

@alpine sable

alpine sable
#

am I supposed to do with the help of the L'hospital rule?

oak chasm
#

That's probably the easiest way.

alpine sable
#

ok thanks then

oak chasm
#

You multiply the top and bottom by the + version of the parentheses.

vague coral
#

conjugate expression should work too, l'hospital rule is a hack :x

alpine sable
#

alrigtht i'll try it thanks

desert moon
#

why can you just set one of the variables = 0

#

i mean, would any number work?

#

just as well

#

is 0 just for the sake of getting simple looking eigenvectors?

vague coral
# hearty cliff why's it a hack

in a way that it makes things a lot easier, but I'm not saying to not using it, but there are faster ways because who wants to take the derivative of a big function.

plucky crow
#

,w differentiate x to the power of e to the power of sinx

sleek elbow
#

if you have a question, just ask

vale wigeon
#

nfa? nondeterministic?

#

do you need it to be strictly nondeterministic?

#

so a deterministic one will not do?

#

that's why i asked whether you wanted a strictly nondeterministic automaton

#

i.e. whether at least one random branch was required

#

at most 4 states, was it?

#

here's a dfa that does the job in exactly four states

alpine sable
#

i need help on this problem

minor sun
alpine sable
#

yea

#

so i plugged in 3 to x^2

#

and also x-11

minor sun
#

While the thing on the right side of the comma tells you the condition for which you are supposed to apply the function.

#

You have a given value of x = 3

alpine sable
#

yes

minor sun
#

And since the function on the bottom is supposed to be used for values of x greater than 0, you plug in 3 on the bottom

#

So your answer should be 3 - 11

alpine sable
#

ohhh ok

#

that makes sense thank you

radiant lantern
#

I need help on this integral plz

#

I want to subtitue it to arcsinhx

#

But when I do u substitution, it doesn’t work

#

This is the u substitution I did but it a video, it is saying that dx = 2 du and I don’t understand why

minor sun
#

You can treat dy/dx as a fraction

#

You just have to multiply by two on both sides

ancient saddle
# radiant lantern

Hello, multiply by 2 on both sides of equation du = 1/2 dx and you'll get 2 du = dx

compact coral
#

the property for #8.

#

does anyone know?

alpine sable
#

,rccw

ocean sealBOT
ionic jewel
#

transative?

#

since 42 = a, and a = b, b = 42

alpine sable
#

transitive yeah

compact coral
#

okay

#

I hate these properties and "justifying steps."

#

really pointlessly confusing

ionic jewel
#

out of curiosity is this like the class where you get introduced to them or the start of a class where they go over different systems?

compact coral
#

uh

#

so

#

our teacher gave us a worksheet right

#

and said

#

do it

ionic jewel
#

like have you heard the terms "ZFC" or Peano or anything

compact coral
#

no

ionic jewel
#

ah alright

compact coral
#

they didn't even teach it

#

I don't even know all the properties they use LMAO

#

😭

#

so basically looking forward to my 0

ionic jewel
#

yeah in that case good to pick up there, but generally not applicable in the future knowing the names as long as you know the rules

compact coral
#

idek if anything i've wrote is correct

#

:)

#

do you know how to do all this stuff about properties? @ionic jewel

#

and justifying and blah bla blah

alpine sable
#

Can someone help me figure how many terms are in this expression

reef dust
#

3

alpine sable
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Can u pls explain

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if thats ok

reef dust
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Multiply 5 by distributing it over a,b and c

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Done ?

alpine sable
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ohh

reef dust
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So 3 terms are seperated by 2 + signs

alpine sable
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so in equations like that where theres a number outside of some stuff inside brackets you distribute it?

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to the others

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inside the bracket?

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so then how is this one 3 terms

reef dust
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2m+8ab+8

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After simplification

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2m , 8ab and 8 are three unique terms

alpine sable
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ty

reef dust
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👍

alpine sable