help-0

[alpine sable]

you need a number under aleph

[manic glade]

א_1 if you prefer

[alpine sable]

yes

I prefer $\mathfrak{c}$

[ocean seal]

Ledog

[manic glade]

so notation choices aside

the statement is true?

if A={ 8n |n in N} => |P(A)| = |R| ?

[alpine sable]

why did you even mention small n here

yes now correct

and its because |A|=|N|

[manic glade]

yeah i couldnt imagine it being otherwise but wanted to make sure since technically the only proof the book gave is for P(N)

and i didnt want to redo their whole proof just to use that

[alpine sable]

Well compositions of bijections are bijections right

[manic glade]

mentioning cantors theorem should be enough right?

[alpine sable]

sure

[manic glade]

sweet

[lean wolf]

4b pleaseee

[queen wing]

IB Oxford book...

The problem is pretty simple though.

[feral crypt]

… that’s not very nice

[queen wing]

It's just a bad book

I had it too, and I'm sorry for him.

[feral crypt]

I guess lol. I’d prob refrain from calling problems simple as it can come off as condescending

[queen wing]

So, look at the totality of Luca's and Ian's answers.

[queen wing]

No, I was just telling him not to be afraid of it.

[feral crypt]

Hmm I sorry, I guess I just misunderstood your message

[queen wing]

It's basically asking, that in the eventuality of either just one of them or both of them get the correct answer, how probable is it that Luca got it right.

[lean wolf]

soo

is it conditional probablity?

[queen wing]

Yes

[lean wolf]

isnt this the formula?

[queen wing]

A given B.

[queen wing]

Exactly.

Now, just one person needs to get the problem right, so we look at the highest probability.

[lean wolf]

thts 55/63

[queen wing]

Yeah, you need the common denominator.

That's 63

That 55/63 gives you the intersection

Actually

Yeah, that should be the intersection.

[lean wolf]

yh

wht do i do after tht

55/63 is correct answers

not intersection

[queen wing]

OK, this got me confused. Classic of me. My calculator is somewhere else. 🤦‍♂️

BRB

Dude.

Well, there is a whole probability tree to draw then.

I misread it from the start.

High School problems. So unlike the real life ones I'm in.

They really do help you think.

[lean wolf]

i got it bro dw

thanks a lot tho

[queen wing]

Well, I was useless, but thanks for not humiliating me.

[lean wolf]

nah i appreciate u outtin in the time

puttin

[high field]

how is this wrong

[queen wing]

The p part is right.

Look at the other part closer.

[high field]

-2+3 is 1 and it has minus in front of it so it's -1

oh nvm

i just realized-

[queen wing]

dw, that happens

[vale wigeon]

https://tenor.com/view/funny-team-hahaha-gif-18072160

[spare fern]

Use exponent rules

[bleak hearth]

hey can some 1 pls explain how its log base 2 2^1

[queen wing]

Because it's another way to write 1.

[bold tree]

Log (n) to base n is always 1

[bleak hearth]

but wheres the other 2 comeing from

i get base 2

but why the lother 1

[queen wing]

From the base of the existing log

log 2 of 5

[bleak hearth]

ohhhhhhhh

[queen wing]

They make the bases the same, so they can simplify

[bleak hearth]

that makes sense

so if it was -2 instead of -1

then it would be -4

[bold tree]

Bases are already same. You just want to represent 1 in terms of log so you can simplify it.

[bleak hearth]

ahh ty

[gritty pine]

can any explain me why

im thinking to getting that by taking the MCD

[vale wigeon]

because 7^3 = 343.

[gritty pine]

thanks, i was getting confused because it wasn't here 7^3

[unreal valley]

Divisor * Quotient + Remainder = Dividend
Right??

[peak wind]

11a and 12a

[alpine sable]

yes

[unreal valley]

Thanks

[vale wigeon]

@sharp sable @peak wind one of you will have to move to another channel

okay, khalid has moved

@peak wind which one do you want help with first

[peak wind]

11a

[vale wigeon]

okay

have you made any progress so far?

[peak wind]

I can't make the equations

[vale wigeon]

can't as in "i tried but they came out wrong" or can't as in "i don't even know how to begin"?

[peak wind]

I tried but it was very odd and in fractions

[vale wigeon]

ah so you have some work to show

yes?

[peak wind]

Ok

[vale wigeon]

that was a question

let me be more clear: can i see the answer you got and how you got there?

[peak wind]

Plz wait I'm trying to make it little bit clear it's all scrambled up

[vale wigeon]

okay

that is a good idea

ping me once you've made your work presentable

[peak wind]

After this it's all messed up

[vale wigeon]

okay i can say right off the bat

your 5 looks very hard to distinguish from capital S

also it's not $CP = 100 - \frac{3}{4}MP$, it's $CP = \frac{3}{4}MP - 100$

[ocean seal]

Ann

[vale wigeon]

a = b-c is not the same as b = a-c

this seems to be the only mistake you've made so far.

correct it and keep going.

it may help if you simplify the fraction 90/108 to 5/6.

@peak wind do you understand what i've said here?

[peak wind]

Ok

Can MP be negative

Sry i got it
Thx for ur help 🙏🙏🙏🙏

[peak wind]

12a plz

@vale wigeon yeah thnx for ur 🙏

[vale wigeon]

you should not be getting a negative MP

wait hold on

okay this one's on me, i gave you the wrong equation

it should have been CP = (3/4)MP + 100

because cost price is greater than sale price, thus we have a loss.

i will blame it on a mistake in translating my approach into your work

anyway ok @peak wind can you share what you've done for 12a?

[peak wind]

@vale wigeon got it

@vale wigeon i dont know how to start

The answer

[vale wigeon]

SP = 0.85MP bc of the discount, but also SP = 1.19CP because of the profit percentage

[peak wind]

I just know what's give but don't know how to get the answers from given data

[vale wigeon]

you want to know the profit percentage from selling at marked price

[vale wigeon]

do you understand this? Y/N

[peak wind]

@vale wigeon y

[vale wigeon]

alright

you can get from here that MP = SP/0.85 = (1.19/0.85)CP

,calc 1.19/0.85

[ocean seal]

Result:

1.4

[vale wigeon]

thus MP = 1.4CP

do you understand this?

[peak wind]

Yes

[vale wigeon]

great

do you understand how to convert this into the profit % from selling at marked price?

@heavy spear channel busy please move

[heavy spear]

sorry

[peak wind]

@vale wigeonyeah got it thnx

[heavy spear]

can i type here ? i have a basic question

[vale wigeon]

i suppose we're done for now then

yes sidd

[heavy spear]

i need to know the horizontal asymtodes

[peak wind]

@vale wigeon yeah

[heavy spear]

i cant seem to get them for some reason

can someone help me i kknow it is where y= 0 but i cant find them on this graph

y doesnt exist i mean

[gritty pine]

can i do this only when is there a perfect square?

[gray isle]

do what

[gritty pine]

it was this before

[gritty pine]

double radical

[gray isle]

the radical product property applies even if you don't use perfect squars

it just won't necessarily lead to simplification

e.g.
$$\sqrt{10} = \sqrt{2}\sqrt{5}$$
which is actually less simplified than what you originally started with

[gritty pine]

may it has to be done because 27^0.5 its 5.19615242271

[ocean seal]

ℝamonov

[gritty pine]

omg thanks

but if i want

can i just end it with 1/27^0.5?

or have i to semplify?

[gray isle]

depends on what the end goal is

usually you'd simplify as required

[gritty pine]

if does it say that i have to semplify may i have to do double radical

thanks man, now im starting to understand

[gray isle]

well after expressing sqrt(27) as sqrt(9)sqrt(3)
you'd further simplify the sqrt(9) to 3

[gritty pine]

ye ik that

and then 3 * 3^0.5

[gray isle]

and then also rationalise the denominator

[gritty pine]

i still have to learn how rationalise i guess

i've just praticed a bit about fractional radicals

[gray isle]

$\frac{1}{3\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}$

[ocean seal]

ℝamonov

[gray isle]

will lead to rationalising the denomintor

[gritty pine]

so have i just to take the denominator sqrt?

[gray isle]

bad wording

[gritty pine]

hmm

oh

now i saw the dot

mybad

[gray isle]

"take" is such a vague word

[gritty pine]

"copy" is better?

[gray isle]

no

don't try and describe this process with one word

[gritty pine]

oh

so i guess that im taking all of the radicals out of the denominator and moving them to the numerator?

then i have to multiply the numerator and denominator by the product of the radicals

i guess? idk im going rn to learn how to rationalize

[gray isle]

consider a value that when multiplied to the denominator will result in a rational denominator,
multiply the numerator and denominator of your fraction by that value

[gritty pine]

oh

ty

[cloud rain]

How do I solve this ratio maths?

A sum of money is divided into the ratio 2:3:5. If the smallest share is
$50. Find the total amount of money that is shared.

[alpine sable]

The smallest share corresponds to the ratio 2

[cloud rain]

yes

[alpine sable]

The total amount of "ratios" is 10

[cloud rain]

ok

[alpine sable]

Since each ratio corresponds to $25, which I find by dividing money over ratio

The total amount is 250, or money per ratio times amount of ratios

[cloud rain]

Can you explain this step again?

[alpine sable]

You have $50 over two ratios

Hence each ratio corresponds to $25

I'm using the word ratio because I don't know what to call those numbers

[cloud rain]

what does "over" mean

as in, in digits

[amber urchin]

"Divided by"

[cloud rain]

I still don't get how the 25 appeared

[alpine sable]

50/2

[cloud rain]

So what's the $25 here

what is the role of the number

I mean what does it do?

[alpine sable]

Nothing much really

[cloud rain]

what?

[alpine sable]

It doesn't do much

Its just part of the computation

It represents the amount of money per ratio

[cloud rain]

So I divide 50/2 then get 25.....then what?

[alpine sable]

Then you have the amount of money per ratio

And the total amount of ratios

So you find the total money by multiplying them

[ionic jewel]

maybe you should attach some physical meaning to the "ratio"

[alpine sable]

You're right, the wording is really confusing

[ionic jewel]

if someone has $50 value of coins, and they have two coins how much is each one worth?

[cloud rain]

sooo,

2x25 + 3x25 + 5x25
?

[cloud rain]

25

[ionic jewel]

yes

now the second person has 3 of these coins, how much money do they have?

[ionic jewel]

although this one is right if you understand it

[cloud rain]

3x25

[cloud rain]

OK

[ionic jewel]

yes, then the last person with 5 coins has 5*25 right?

[cloud rain]

yes

[ionic jewel]

so that's why we added 2x25 + 3x25 + 5x25

the sum of the money from all the people

[cloud rain]

250

[ionic jewel]

yep

do you understand why?

[cloud rain]

Somewhat

thnx!

[glad aspen]

heya can someone confirm this suspicion for me

we've got this function

$f(x) = (x+5)\sqrt[3]{x^{2}}

[sage bronze]

f(x) = $(x+5)\sqrt[3]{x^{2}}$

[ocean seal]

HELLOBELLO

[glad aspen]

thanks 🙂

and the paper says that its derivative is

f'(x) = $\frac{5(x+2)}{3\sqrt[3]{x}}$

[alpine sable]

frac for division

[ionic jewel]

\frac{top}{bottom}

[glad aspen]

ah thanks

[alpine sable]

\divisonsymbol

[sage bronze]

U forgot the \ before sqet

[ocean seal]

NightElemental

[glad aspen]

there we go 😆

thanks guys

[ionic jewel]

oh there we go that looks much better

who posted the latex in a different font

[alpine sable]

me dunno

[glad aspen]

anyway, it asks us to verify if that correct. At first glance it looks correct, but its not right?

[sage bronze]

Wait

[ionic jewel]

(x+5)(2/3)(x^(-1/3)) + x^(2/3) by product rule

dont think that simplifies you your other expression

[gritty pine]

is this true because
the sqrt(A) is like saying A^0.5, if i do A^0.5 * A^0.5 is like saying that A^0.5 * A^0.5 = A^1 that equals to A?

[ionic jewel]

yes

[gritty pine]

oh ok

thanks

[ionic jewel]

true for a >= 0

[sage bronze]

Is corrects

I think

[sage bronze]

I m getting th same

[glad aspen]

mhm alright thanks, ill try and do rewrite my working out

find out what I did wrong

thanks guys 😃

[full imp]

its asking for M

can someone help please?

[wary stream]

,rotate

[alpine sable]

2x/4= 4x - 35
How do you find the solution?

<@&286206848099549185>

[alpine sable]

Why is it not 4x-35*4 ?

Why is it 4* 4x-4*35?

[shell widget]

a(b-c) = ab - ac

[vale wigeon]

it isn't just 35 that gets multiplied by 4, azizi.

[sage bronze]

Ok

Lemme write it out

Wait

[full imp]

ok

[sage bronze]

First u solve for f(x)

[alpine sable]

Why not? You only time 4 once on the other side of x?

[vale wigeon]

you multiply both sides by 4

this means you multiply 4x-35 by 4

not just the 35

you can't multiply selectively like you're trying to do

[full imp]

i know

[alpine sable]

Oh so when its multiplying and dividing, it isn't the same as addition and subtraction?

[sage bronze]

Okie then inverse the function

After inversing we get $f^{-1} (x) = \frac {2+3x}{3x}$

If im not wrong

Then we replace x with 1

Equate it with m+3

@full imp

[ocean seal]

HELLOBELLO

[full imp]

😱

thank you

[sage bronze]

Ur welcome

[shell heron]

why does $$\frac{-(2+r)}{8-p}$$ equal $$\frac{2+r}{p-8}$$

[ocean seal]

edineee

[placid zinc]

-x/y is the same as x/(-y)

So you want to put the negative on the bottom

Then distribute that negative:
-(8 - p)
= -8 + p
= p - 8

[shell heron]

it is because you can multiply the denominator and numerator by -1?

[solar cradle]

That's a way you can see it too

[shell heron]

oh okay thanks, now i get it

[unborn dome]

can someone help me out with this question plz im a bit confused since i know sin is SOH but i dont know what the opposite is...

[solar cradle]

Do you know trig functions?

oh yeah, didn't read the caption lol

[thorn vortex]

The opposite side is the one which is NOT adjacent to the considered angle

In this case it is a

[solar cradle]

You can also just remember, the opposite is the side that is opposite the angle

[unborn dome]

wut

im confusedl ol

ive heard of 3 4 5 triangles but im not entirely sure how its positioned here

i cant use the same approach because i dont have a

otherwise it would've been something like sin(theta) = a/c

[solar cradle]

This isn't a 3 4 5 triangle

and you're close sin(A) = a/c

[wary stream]

The trig function you use is base on the angle you are using

[unborn dome]

ah

so B is 5

i mean

a is 5

sin(5) = x/5?

[wary stream]

If you are at angle B, the opp = b, adj = a, hyp = c but if you are at angle A, the opp = a, adj = b, and hyp = c

[wary stream]

What's x in this context?

[unborn dome]

a

like SOH

[wary stream]

Yes

[unborn dome]

opposite over hypotneuse

[wary stream]

That's correct

[unborn dome]

but thats just a = 5sin(5)

[wary stream]

Yep

That's right

[unborn dome]

wait what

so would i just simplify that

5sin(5) or

[wary stream]

Plug that into a calculator

[unborn dome]

-4.79

[wary stream]

Are you in degree or rad?

[unborn dome]

think in rad

[wary stream]

Make sure you are in degree

[unborn dome]

24.96 degrees?

but like

a and b are not angles

[wary stream]

No, recalculate with the calculator in degree mode

[unborn dome]

they're just sides

[wary stream]

Don't convert to degree mode

[unborn dome]

wut

[wary stream]

Set your calculator in degree mode

Then type in 5sin(5)

And calculate that

[unborn dome]

ah

its already in degree

.435

[wary stream]

Yes, that's right

[unborn dome]

for side a?

[wary stream]

Yep

[unborn dome]

i see

what about side b.

cant i just do like

.435^2 + b^2 = 5^2?

[wary stream]

Yes

You can do that

[unborn dome]

which is sqrt24.81 idk if thats right

[wary stream]

It's not 24.81

Wait

That's correct

[unborn dome]

what

[wary stream]

It's right

[unborn dome]

sqrt24.81?

ayy tysm

also uh @wary stream how would one go about solving this?

would i have to refer to unit circle and just

uuh

[wary stream]

Do you know the mnemonic All Students Take Calculus?

[unborn dome]

heard ofi t yeah

is it like all sin

then tan and cos

[wary stream]

Yes

[winter mango]

yes from 1-4 accordingly

[wary stream]

Going clockwise

[unborn dome]

and if this case

its quadrant 2

so id be using sin

wait.

[winter mango]

just do the pythagoras thing first

then put the signs after

is what i do

[wary stream]

It's 1, 4, 3, 2

[unborn dome]

pythagoras thing?

[wary stream]

That mnemonic

[winter mango]

2nd quad is sin

[unborn dome]

like you draw like 2 triangles or something?

[winter mango]

nah just draw a triangle

[unborn dome]

mhm

[winter mango]

the angle its opposite is 3

its hypo is 5

get its adjacent

[wary stream]

Sorry, you're right, I went backwards

[winter mango]

get the cosine with the basic rules, adj/hypo

then see what quad ur in

[unborn dome]

so its adjacent would be 4

[winter mango]

and put the sign

yes

cos is negative in 2nd quad

[unborn dome]

OOOOOOH

[winter mango]

so -4/5

[unborn dome]

AND ITS NEGATIVE

BECAUSE the choordinate plane

[winter mango]

yep

[unborn dome]

god i feel so.....

[winter mango]

if you were doing like a full on proper answer you'd do a triangle with it's hypo belonging on the 2nd quad

basically a triangle with the angle open towards the 2nd quad

and you'd plot the y or x values accordingly

if that confuses you just make a random triangle and put the signs later

[unborn dome]

ty so much

but uh

one question

that kinda juist solves it for CAH and TOA

how would one get the rest

do u like

divide sin

overe

[winter mango]

just get the values of cos/sin/tan respectively

and do 1/the value

that's the definition of sec/csc/cot

[unborn dome]

?

[winter mango]

ye like in the first question it asked for cosine

that's -4/5

then the secant

is -5/4

just 1/cos

[unborn dome]

oh its just flipped?

[winter mango]

the reciprocal or however its spelled

ye

[unborn dome]

so csc is the reciprocal of sin?

makes a ton of sense yea

[winter mango]

yep, i dont know why that's the case or if that's just the definition but that's their value

[unborn dome]

tyvm

that makes sense for finding quadrant related values

but whatabout like direct values

[wary stream]

Unit circle, I think

Use that

[unborn dome]

cant really find -7pi/4 on unit circle tho

there is 7pi/4

ahh i would follow trig rules

with the 2pi - thing

[wary stream]

Add 2pi to -7pi/4 to make it positive

[unborn dome]

so for sec it would be sqrt 2

like 1 /cos

and cos is

sqrt 2 / 2

cuz pi/4 - 2pi

[wary stream]

Sounds right

[unborn dome]

poggies

[celest anvil]

what i tried

i found the intersection point to be ln(3)

i multiplied the integral answer by 2 for the e^-x

[solar cradle]

You should draw out the functions and you'll see where you went wrong

[solar cradle]

Okay, look at your integral. The would find the area enclosed by y = 3, y = e^(-x) and x = ln(3)

[celest anvil]

yea but how do i include all 3 equations?

[solar cradle]

You'll want to break it into two integrals

[celest anvil]

then add both of them?

[solar cradle]

yes

[celest anvil]

like this?

[solar cradle]

almost, your limits will be different

[celest anvil]

oh is it -ln(3) to 0 then 0 to ln3 for the other?

[solar cradle]

yeah, you got it!

[celest anvil]

[plush stump]

tan(th) = -2, sin(th) > 0. how is this done again?

[solar cradle]

How is what done? Are you trying to find th?

[gritty pine]

when should i learn how to rationalize radicals?

after algebra 1?

or after preliminaries?

[plush stump]

@solar cradle yes theta

[gritty pine]

😦 server problems

[gritty pine]

no problem, found out when

like right now

[solar cradle]

@plush stump okay, just recall $$\tan\theta = \frac{\sin\theta}{\cos\theta}$$

[ocean seal]

Billy Clintorus

[alpine sable]

a

[solar cradle]

We're given $\tan\theta = -2$ and $\sin\theta > 0$. What values of $\sin \theta$ and $\cos \theta$ would satisfy these conditions?

[ocean seal]

Billy Clintorus

[plush stump]

hm

[amber urchin]

sin(x) / cos (x) = - 2, sin^2(x) +cos^2(x)=1

Sorry, tried to give a hint on question

[plush stump]

it's fine, I thought you were going to ask a question like that guy earlier.

So that identity is the hint somehow.. hmm

yeah no, this isn't clicking. been studying all day so kinda burnt out too

@amber urchin or @solar cradle where do we go from there algebraically if you don't mind

[amber urchin]

In that case sin(x) = - 2 cos (x)

So we substitute this sin (x) into second equation

We get 5 times cos^2(x) = 1

[plush stump]

ah so we do like a weird trig system basically

[amber urchin]

Yeah, hopefully there were no mistakes, if not then it should be good

And sum of squared sine and squared cosine is always 1, so that is useful as well

@solar cradle

[plush stump]

thanks!

Is that an unorthodox method? or

[amber urchin]

I think it is commonly used method

Usually when questions asks about sine or cosine knowing tan(x) or cot(x) then this method is used almost every time

[plush stump]

oh, very nice!

mind if I dm you?

[unborn dome]

is this correct?

[topaz scaffold]

,w 15sin(155 degrees)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by RipeOrange#4907

[topaz scaffold]

,w 15cos(155 degrees)

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by RipeOrange#4907

[topaz scaffold]

Maybe

[unborn dome]

ah....

i mean it said rounded but i just kept the 4 in there cuz

[topaz scaffold]

Rounding on the first one a bit tough

[unborn dome]

yea the other one has to be 6.34

or

@topaz scaffold would it be -13.595

[topaz scaffold]

Sine would be the y

Cosine would be the x

[unborn dome]

yea

i think thats what i did atleast

uh can someone help me out with this?

not entirely sure what to do

all i did was 360 - 220

which is 140

then im assuming i just do 220 - whatever gives me 140

so 80?

wait no its sin

so

is it like 180 - 40

so it owuld be 40

[topaz scaffold]

Look in the right quadrants

^^

Very useful

[unborn dome]

im very confused

do i have to draw triangles for this?

might help hold on

and

im still confused rip

i guess i cant just do 360 - 220

hard to...

since you have like sin 220

cant really draw a triangle

in the first quadrant crossing that angle point if its 0 to 90

upside down in the first quadrant? wait what

right

cant i just say

360 - 220 is 140

and 180 - 40 gives me 140

so its 40?

visualizing kinda makes it a bit more difficult

wut...

so

the sin function is only positive in first and second quadrants

cos is first and fourth?

but how does that help in thsi case...

so id use second quadrant for sin

and fourth for cos

with like

360

and

oh

cant i just do sin(220) and convert that into degrees?

cant i just say sin(40degrees) for my answer?

ah...

man i feel so..

so @violet ore for cosine would it be 140

ty

[alpine sable]

Create a transversal using GeoGebra Geometry

What is a geogebra

[thorn kindle]

google it lmao

[alpine sable]

Ouch

@thorn kindle there isnt a clear definition for it

Wait its a app

How should I display the angles

Alr

[scarlet oriole]

I need to learn probability and statistics for electronics engineering anyone has a full course playlist that can suggest me to watch?

[unborn dome]

can someone help me with this question i am just super confused

is it like 40 pi x 5280 or something

[ocean yacht]

I need help

what is 1+1?

[snow nest]

21

[ocean yacht]

ohhhh

ok

my teacher kick me out of the class

....

[sly mantle]

@ocean yacht don’t troll @snow nest don’t give troll answers

[snow nest]

o7

[ocean yacht]

@sly mantle I just want to know what was 1+1

[ionic jewel]

pinging the mod yourself

[ocean yacht]

[sly mantle]

either you’re a troll or you really don’t know 1+1 which implies an age below that required for discord

[ocean yacht]

ohhhhhhhhhh

but I am one

years old

ummmm

[sly mantle]

further joking doesn’t help your case

you’re on thin ice

[ocean yacht]

Among us

[sly mantle]

b&

[red spear]

I wonder if some people found that to be hilarious

doubt it though

[graceful harness]

why is there among us emote

in math server

[pliant oracle]

sometimes mathematicians can be sussy bakas

[red spear]

lmao

[graceful harness]

good answer

[frank dome]

I feel like I completely forgot how to do these someone help

[undone dock]

You've got the gradient right, you just need to find the y intercept

Just find the y value at x=0

[ionic jewel]

<@&268886789983436800>

[tall wing]

banned

[unborn dome]

SHeesh

@peak storm massive rip

i only ask questions on mah review sheet cmon bruh

i dont even think the server lets u go for homework questions

too scared to try.

[alpine sable]

hello

wait wrong thing

[flat vale]

If Area of the graph = 0, then area = avg value of a function?

[thorny panther]

use integral to find bounded region
which region is the bounded region?? :v

is saying y=0 the equivalent with y axis?

[ionic jewel]

y = 0 is the x axis

[thorny panther]

oh.....

[finite pecan]

(sorry idk if ur done asking a question but it seems like it and all the other chats r full)

what does this circle mean

[alpine sable]

oh shit i get it now

thanks

[warped blade]

are there integers that do not distribute over multiplication?

where a * (b + c) != (a*b)+(a*c)

[alpine sable]

@finite pecan the circle integral is performed on a space which has lower dimension than the ambient space

[finite pecan]

sorry i dont know what that means

[alpine sable]

so like

it's compact

as in not infinite in size

[finite pecan]

so a closed space?

[alpine sable]

sorta

it's a normal integral w the circle to remind us of the domain

[finite pecan]

what

[alpine sable]

of integration

[finite pecan]

;-;

[alpine sable]

eg, 1d/2d

i dunno man i did a course on this when i was 12 and i can't remember anything now ;-;

but yea its just a regular integral with a finite domain

im guessing

[finite pecan]

ok ty

[alpine sable]

sorry i wasn't of much help

[tribal geyser]

Can someone help with 15)b?

Idky im not getting the answer

<@&286206848099549185>

[ionic jewel]

find m(10)

[livid lintel]

i got 3.62 wasn’t sure if it was right

[snow nest]

,calc 7e^-0.66

wait what

[ocean seal]

Result:

3.6179593414419

[snow nest]

yeah ur right

[thorny panther]

so u can find area of the shaded region outside of a function using the integral of the function???

-1 to 0 :v

[stable leaf]

the intergral is the area from the function to the axis

if that is what you are trying to get at

[thorny panther]

ahh I thought u can only find area if it's directly under the curve/above to the axis

[stable leaf]

No

when it is below the axis

you go from the x axis until it hits the function

Its just always the regions between the x axis and the function

like here is another example i guess

[thorny panther]

ah

[lethal vortex]

how do i find for the common ratio?

[supple tundra]

Assuming that $T_1,T_2,T_3,...T_n$ represent the 1st, 2nd, 3rd, 4th,... terms of the sequence. We also know that the general term of a geometric progression can be represented as $T_n = ar^{n-1}$ So $ar + ar^2 = ar^2+ar^3$. Can you take it from there?

[ocean seal]

azeem321

[alpine sable]

found this on a package, any ideas on how to figure out what A, B, C, and D stand for?

[empty kindle]

how do u find the first nine terms?

[supple tundra]

Do you understand what the formula you have been given represents? What does $S_n = \frac{n}{2}(n-24)$ mean to you?

[ocean seal]

azeem321

[empty kindle]

hm?

[alpine sable]

check what the n stands for in the forumla

[empty kindle]

Number of terms

so i sub 9 into n?

[lusty plaza]

you have two expressions = 8, so a=d

[supple tundra]

$S_n = \frac{n}{2}(n-24) $ means in plain english "the sum of the first n terms"

[alpine sable]

that’s the only part I have figured out, it looks simple, but dunno lol

[lusty plaza]

read the rules

[empty kindle]

erm

[lusty plaza]

that means you have 4 expressions with 3 varaibles

just substitute

[supple tundra]

Do you get it?

[empty kindle]

kinda

can we chat in dms

[supple tundra]

Sure shoot

[ocean seal]

azeem321

[supple tundra]

But that's about as far as I've gotten. I don't know how to show this. Any hints would be appreciated

[empty kindle]

azeem help mehh

[sweet elm]

woah

how do you use texit bot

wait nvm

[vital glacier]

Hello guys could i ask some questions about matrices

If there are two identical rows in the matrix, after performing Gaussian Elimination, does that mean that there is guaranteed to be a zero row?

[fossil saddle]

I'm kind of stupid, so can someone please explain where the extra $1 came from. I want to stump my classmates (I'm in middle school). I want to look smart when school starts again.

(You start with $50)

[vital glacier]

2. Before asking a question, make sure that the channel you are using is not currently in use. An occupied channel would generally have an ongoing discussion or a trailing unanswered question. Likewise, when you are done using a channel, make this clear so that it's open for others to use.

.....

do u mind finding an unoccupied channel?

[fossil saddle]

Oh sorry. I'm new. Yeah I'll find an available channel sorry

[vital glacier]

ill help you with this anyways @fossil saddle

even though im not a helper

[supple tundra]

you robbed my channel too

[vital glacier]

oops

i thought it was finished

lol

i guess ill go find another channel 🤣

[supple tundra]

nah it's fine dw

[clear gyro]

Is anyone free that could help explain to my cousin? In #help-9

[alpine sable]

let’s just say you robbed my channel as well.

[supple tundra]

this discord gets really active on sunday night. guess u US folks left it to last minute to get your homeworks done

[cerulean vine]

Yo can anyone send me the quadrant rule pic

No i mean the one with the directions

[clear gyro]

My cousin has homework do for his first day so I'm finding help for him:)

[cerulean vine]

Like left is negative

Right is positive

What did i do ):

[pure hill]

@alpine sable A = 7/2
B = 9/2
C = 19/2
D = 7/2
you can see that A+B = 8 also B+D = 8 so A = D from here A+C = 13 and C-A = 6 (here I replaced D by A as they are equal) by solving these equations you will get the answer!

[cerulean vine]

YO CAN SOMEONE SEND ME THE QUADRANT RULE PIC WITHOUT THE SIN COS TAN THING

[supple tundra]

this sufficient king?

[cerulean vine]

not diss

i know dis

i want the simplified one

which is just

negative

and positive

[supple tundra]

King, I know it's not my place to say. But I think you should just learn the graphs. It will make it much easier for you

[cerulean vine]

ye i just need the simpler one

[alpine sable]

kinda embarrassed not figuring out how to solve this first grader puzzle, but I am really not getting it. how did you get your answers?

[pure hill]

I have already explained it which part you didn't understand?

[sweet elm]

lets go through it one by one

A + B = 8 = B + D

which means that A + B = D + B

take out the B

[stable leaf]

looks like a system of equations

[sweet elm]

and you get A = D

now that we know A = D,

[pure hill]

@cerulean vine I guess what you are asking is that x is +ve in 1st and 4th quadrant and y is +ve in 1st and 2nd quadrant? Is the the thing that you are asking or something else?

[sweet elm]

check out A + C and C - D

take the two answers

13 and 6

[cerulean vine]

Yo

[sweet elm]

and find their differences

13 - 6 = 7

7 = 2A

7/2 = 3.5 = A = D

[cerulean vine]

you know the basic quadrant rule where you learn moving down is negative and up is positive and each quadrant is like negative or positive

[sweet elm]

now find B

8 - 3.5 = 4.5 = B

lastly, find C

[pure hill]

I can't understand what you are trying to say, sorry.

[sweet elm]

13 - 3.5 = C = 9.5

[alpine sable]

Gotcha gotcha, so simple now you’ve explained it. couldn’t figure it out, thx

[sweet elm]

ight

glad i could help

[reef geyser]

can anyone help me with this

[cerulean vine]

SURE

[sweet elm]

wait a sec

[reef geyser]

THANK YOU

[cerulean vine]

wait

this is a weirder one

[sweet elm]

yea sometimes your brain just thinks too hard and just goes blank

[cerulean vine]

i dont understand

the question

XD

[sweet elm]

wait ill do it

wait a sec

[cerulean vine]

its a ratio question

[sweet elm]

,calc π*6

[ocean seal]

The following error occured while calculating:
Error: Undefined symbol π

[sweet elm]

wait how do i

,calc pi*6

[ocean seal]

Result:

18.849555921539

[cerulean vine]

,calc pi×6

[ocean seal]

The following error occured while calculating:
Error: Undefined symbol pi×6

[cerulean vine]

,calc pi*8

[ocean seal]

Result:

25.132741228718

[cerulean vine]

8/10 : 12/10

Do we make it a ratio?

[sweet elm]

,calc 18.849555921539/0.8

[ocean seal]

Result:

23.561944901924

[sweet elm]

man

i also dont understand

[cerulean vine]

SAME

[sweet elm]

im in middle school

[cerulean vine]

Oh lel

[reef geyser]

WAIT WHAT

u learn pi in middle school???

[sweet elm]

is this indonesian or malaysian?

[cerulean vine]

Katherine r u from malaysia by any chance?

[vagrant glacier]

that is so sad

[cerulean vine]

Jinx

[reef geyser]

yuppp i’m malaysian

[sweet elm]

yea im 14

in mrsm

malaysian

[cerulean vine]

Oh wth

[reef geyser]

OHHH interesting

which one

[cerulean vine]

I am a immigrant malaysian

[sweet elm]

cant tell you too much

[cerulean vine]

So thats why

I recognise

[sweet elm]

can i take a look at your textbook?

[cerulean vine]

That looks like circles

Whereby this is a ratio question

1 : 1/8?

What does the question mean by actual

Does that mean

You substitue

12cm

OUHH WAIT

[sweet elm]

,calc 8/pi

[ocean seal]

Result:

2.5464790894703

[cerulean vine]

15?

I think the ans is 15

@reef geyser not to sure but i think the ans is 15

As this is a ratio question

I converted 12cm into mm

So 120

And then we get 120 : 8

So then we divide

And get

[reef geyser]

ur smart thank u

[sweet elm]

OH YEAA

[cerulean vine]

15 :1

15 : 1

[sweet elm]

I MIXED UP DIAMETER WITH CIRCUMFERENCE

[cerulean vine]

So i think

[sweet elm]

im an idiot

[cerulean vine]

That maybe the ans

[reef geyser]

OKAYYY I SEE U PULLING THRU

[cerulean vine]

Katherine im not to sure

If im right

But thats my answer

[reef geyser]

it looks right

[cerulean vine]

Since it is a ratio question

[sweet elm]

,calc 120/8

[ocean seal]

Result:

15

[sweet elm]

thats correct

[cerulean vine]

So 1 : 1/15

So n = 15

[reef geyser]

THANK YOU

[sweet elm]

damnit i didnt even have to use π

nice

[cerulean vine]

Ye

This is a ratio question

I think so

If it was a circle questioj

I would have known

Who says the actual value is 8mm

When doin a circle ques

[sweet elm]

i understand the question but just got diameter and circumference mixed up

cm to mm

12cm/8mm = 120mm/8mm

[cerulean vine]

Cm to mm

[cerulean vine]

Ahh ok thats fine atleast you tried

[tough hatch]

eh?

no

[cerulean vine]

Why delege

[sweet elm]

[cerulean vine]

Read da question

K show me your ans

I really was not sure about the ans

[sweet elm]

WAIT I THINK WE'RE ALSO WRONG

[cerulean vine]

So ples prove me wrong

[sweet elm]

But idk

[cerulean vine]

Yo just do it normally

[sweet elm]

wait we are right

120/8

[cerulean vine]

Ye we are right

[sweet elm]

= 15

[cerulean vine]

Even if you do algebra

We still right

[sweet elm]

15 : 1 = 1 : 1/15

[cerulean vine]

1/1 cancels each other out

So n = 12cm/8mm

n = 120/8

[tough hatch]

answer is right, but masochistic solution

[cerulean vine]

n = 15/1

[cerulean vine]

What do you mean?

Its a objective ques

So you dont need working

[tough hatch]

.

[cerulean vine]

Ohh

So its not a good way to explain?

[tough hatch]

show the entire equation

1 : 1/15 implies you already knew that n = 15

[cerulean vine]

Yes

I was just tryna show it

In a ratio manner

[tough hatch]

just say 1 : (1/n) = 15

[sweet elm]

120/8 : 1
= 15 : 1
= 1 : 1/15

[cerulean vine]

Ok i understand

[tough hatch]

in the process you didn't actually show how you got n = 15, merely substituted

[cerulean vine]

Thank you for the info

[sweet elm]

15/15 : 1/15

[tough hatch]

no need for : 1 in 120/8 : 1

[cerulean vine]

Thats extra

Ik

[tough hatch]

it's just 1 : (1/15) = 120 : 8

for sake of clarity

[cerulean vine]

Thats just how i was thought when doing subjective

Questions

So that theres

Definitive proof

That its a ratio

[halcyon pulsar]

Hellow

Is anyone good in chemistry?¿

I need help bro

🍎🍎

[pure hill]

which branch of chemistry organic , inorganic or physical?

[halcyon pulsar]

Organic

[pure hill]

yeah what's the probelm?

[halcyon pulsar]

Write the chemical reactions for following conversion
a) ethylene to ethyl alcohol
b) ethylene to ethane
c) ethyne to ethene

Im having issue on this one

[pure hill]

what's the issue you are facing?

[halcyon pulsar]

I m bad in organic

And dis question is kinda important in my test

🗿🗿

Sorry, im probably cheating

[pure hill]

okay so lets start form the start you just need the reagents right?

[halcyon pulsar]

Yes

[pure hill]

so I am writing the reagents these are all one step reactions

a) H2O
b) H2/Ni
c)H2/Ni 1 equivalent

or you can use H2/Pd for the 3rd one

[halcyon pulsar]

I'm really grateful for your help sir

[pure hill]

✌

[halcyon pulsar]

Is there anything else i would need to write other than used reagents

Like certain temprature

Or something

[pure hill]

no that's not required I think depends on which grade you are in

[halcyon pulsar]

Im in 12th grafe

And terrible in organic.

In chemistry

[pure hill]

yeah then its okay no need for temperatures and pressures

[halcyon pulsar]

Actually

[halcyon pulsar]

Understandable, thank you for your help.

[pure hill]

Its okay you will soon be good at it

[halcyon pulsar]

Hail The Dark Lord

[merry herald]

hey can anyone help me with this question? I'm having a hard time trying to work it out

just the formula would be helpful

[topaz scaffold]

a+b+c+d = 360

For exterior angles it would be (180-a)+(180-b)+(180-c)+(180-d)

Which you can rearrange to get 180 + 180 + 180 + 180 - (a + b + c + d)

Sub in 360 for a+b+c+d

180 + 180 + 180 +180 - 360

And you get 360

[tired hamlet]

how would I get started on this one? I can easily do it when there is just a number on one side but this is confusing me

[vale wigeon]

write down the domain restriction for x, which here will be x ≥ 3 (so that later you can check all solutions you get against this condition)

then square both sides

you will get some roots still

isolate those and square again

[alpine sable]

Hi!

[tired hamlet]

why would I get roots, wouldn't it just be x-3+2x+1=2x+8?

[vale wigeon]

no