help-0

[alpine sable]

so it only matters what the fully simplified version is

not whats in the sqrt term

a perfect square means you can take a sqrt of it and get an whole number

is that correct?

[vale wigeon]

sure, if you insist.

[alpine sable]

ok, thank you

[fresh fulcrum]

W = { t E Z | 1 < t < -3 } would the elements within this set just be the empty set ?

[pale geyser]

yes

,, \set{t | 1 < t < -3} = \set{t | 1 < t} \cap \set{t | t < -3} = empty set

[ocean seal]

mymoomin

[fresh fulcrum]

thanks @pale geyser ❤️ ( i pinged just like u wanted XD )

[pale geyser]

\o/

ty

[heady elk]

I'm working on a math report (on the mathematics within the knights tour), which discusses Hamiltonian cycles, I was wondering if someone could explain the concept of NP, or Nondeterministic Polynomial Time, along with what the difference is between NP, NP Hard, and NP complete is, as im struggling to understand it from what I've researched online. If so thx!

[pale geyser]

a nondeterminstic turing machine is one that can split into arbitarily many copies as part of its program

and if one of the copies accepts, the turing machine accepts

so for instance if you want to find a factor of a number n, a regular turing machine could check every number i less than n, and see if any of them divide n

(this is obviously a very slow program)

but a nondeterministic turing machine could split into one copy for every i, and check if each i divides n at the same time, which is obviously a lot faster

a problem is in P if a turing machine can solve it in polynomial time (so the time taken is some polynomial function of the input size, like n^4 + 3n^2 + 2 or whatever) and it's in NP if a nondeterministic turing machine can solve it in polynomial time

[heady elk]

TYSM! that makes a lot more sense now!

[pale geyser]

\o/!

do you want an explanation of the np-complete stuff as well

[heady elk]

that would be great

from what i understand NP complete is NP Hard and NP Im just not sure what the differece is between the two

[pale geyser]

ok so imagine we had a program that could answer every instance of a specific problem in one step

you just give it the problem and it immediately gives you an answer

we call something like that an oracle bc it's kinda like an oracle

a problem is NP-hard if, given an oracle machine for that problem, you could solve any problem in NP in polynomial time

,,that might be kind of a confusing sentence

[ocean seal]

mymoomin

[pale geyser]

fucken
texit

[heady elk]

That makes sense, thx again!

[pale geyser]

ok!

it's kinda remarkable that np-hard problems exist to me lol
but they do

[primal ether]

no

check the rules

[pale geyser]

and like you said an np-complete problem is one that's in np and np-hard

these are important bc if you could solve a single np-complete problem in polynomial time, then since you can reduce any other problem in NP to that problem in polynomial time, you could solve every problem in np in polynomial time

[cold cedar]

Anyone who can help me spot the error?

[heady elk]

You simplified your equation to s=(4+2t)/5 to isolate S. But then when you solved for t, you plugged it into the equation s= (4+t)/5

[cold cedar]

Oops, that's more of a overall error then

[cold cedar]

Noted, thanks for the observation 😄

[plush aspen]

ummm can anyone help me with this

it's a pretty basic sum but i just can't get my head around it

the answer is 7 but i dunno what's the procedure

[vague coral]

,rotate

[vague coral]

nice handwritting

[plush aspen]

lol sorry

[gray isle]

consider that 27 and 9 are powers of 3

[plush aspen]

ok

3 to the power 3 right

wait i did this step actually

[vague coral]

a^x = a^y --> x = y

[plush aspen]

so x-1=x+2?

ahhhh i feel really dumb rn

[gray isle]

no

[vague coral]

no

[gray isle]

where are you getting that?

[plush aspen]

since herels said a^x=a^y == x=y then i assumed that the powers must be equal

[alpine sable]

Is that $27^{x-1} = 9^{x+2}$

[ocean seal]

Em

[vague coral]

the base should be equal first

[plush aspen]

yep

[alpine sable]

What Herels said is correct. Bases must be the same first

[plush aspen]

3^3=3^2?

[alpine sable]

27 and 9 can both be written with a base of 3

[vague coral]

:(((

[alpine sable]

Almost. What you wrote is 27 = 9

Which is incorrect. What you need to do is account for the variables you had in the exponents initially as well

Where did the x-1 and x+2 disappear?

[plush aspen]

3^3x-1

is that correct

[alpine sable]

Almost

Is 3x-1 the same as 3(x-1) ?

[plush aspen]

no

[alpine sable]

Correct

[plush aspen]

x raised to the power 3 should be 3x, right?

[alpine sable]

x times 3 is 3x

[plush aspen]

is x raised to the power 3 just x?

[alpine sable]

x raised to the power of 3 is x^3

Or x times x times x

[vague coral]

$27^{x-1} = (3^3)^{x-1} = 3^{3(x-1)}$

[ocean seal]

Herels

[alpine sable]

Herels solved it for you

[plush aspen]

ohhhh

i get it

[alpine sable]

Apply the same logic to the other side

For $9^{x+2}$

[plush aspen]

3^2^(x+2)

[ocean seal]

Em

[alpine sable]

$3^{2(x+2)}$?

[ocean seal]

Em

[plush aspen]

this?

[alpine sable]

Yes good

Now the bases are equal

Therefore you can say the exponents must be equal too

[plush aspen]

yeah

ummm what's next?

[vague coral]

read what he said

[plush aspen]

i did

[vague coral]

solve for x ?

[alpine sable]

What did you write?

[plush aspen]

3^3(x-1)=3^2(x+2)

[alpine sable]

And after?

[plush aspen]

one sec

[alpine sable]

Now you can apply $a^x=a^y, x=y$

[ocean seal]

Em

[plush aspen]

so 3(x-1)=2(x+2)

[alpine sable]

Excellent

What would you do now?

[vague coral]

I hope he know how to solve it

[plush aspen]

providing that the indexes are same couldn't i just cancel them both out

[alpine sable]

That's fine if he doesn't

[alpine sable]

You mean the base?

[plush aspen]

i don't

[vague coral]

damn

[plush aspen]

the indexes, not the base

[alpine sable]

The exponent?

[plush aspen]

yep

[vague coral]

it's not index

[alpine sable]

Is 3x=6x?

[plush aspen]

nope

[violet flame]

for x = 0?

[alpine sable]

How do you solve this: 3x=6

Are they equal?

[plush aspen]

x= 6 divided by 3

[alpine sable]

Good. How do you solve this: 3(x-1)=6

[plush aspen]

x-1=2?

[alpine sable]

Yes, and how much is x?

[plush aspen]

1

i think

not sure

[topaz scaffold]

3

[vague coral]

1-1 = 2 xd

[topaz scaffold]

Oof

[alpine sable]

x-1=2
1-1=2
0=2

[vague coral]

you know, the trick is to isolate x. You have x-1 = 2, and we want to only have x = something, so we need to delete - 1

but how to do it ?

[alpine sable]

This will help you solve your problem too, dont worry

[plush aspen]

my brain doesn't wanna work anymore i have been up for too long

[vague coral]

you need to recheck your algebra level

[alpine sable]

Get some sleep. Come back tomorrow

[plush aspen]

ok

sorry if i was a pain in the ass

[vague coral]

no

[alpine sable]

We're here to help dont worry 😄

[vague coral]

how old are you ?

[alpine sable]

Astrophysicist

[plush aspen]

14

baby steps ig

[alpine sable]

I went to uni for astrophysics but gave up

[surreal meadow]

astrophysician
he heals the stars

[alpine sable]

Changed majors

[plush aspen]

bye i need to sleep

[alpine sable]

Goodnight!

[wispy olive]

Can we do this by showing triangle ZPY and triangle XPY are congruent?

Which means that triangles WPZ and WPX are congruent.

Which means.

Equal area.

[alpine sable]

And how would you do that?

What congruency criterion that is?

@wispy olive

[wispy olive]

Yes.

[alpine sable]

.

[wispy olive]

Wait.

This is more of a in-general question.

For other questions like this.

[alpine sable]

I don't think there is enough information for that else it would be straight forward, the only thing which you know here is that WY is a diagonal of the quadrilateral. And nothing else is given like the relation between the sides

[wispy olive]

Asking for that.

[alpine sable]

WY is a diagonal which means that the triangles are congruent

[wispy olive]

Which 2?

[alpine sable]

The two formed from the diagonal

WXY and WZY

[wispy olive]

Name them at least.

Yeah.

That is understandable.

[wispy olive]

@alpine sable

[alpine sable]

I didn't get that point

Of yours

You could probably use the fact that the two triangles are congruent, so WY bisects the angle W, one angle here then you got nothing else so yeah ig

[wispy olive]

Like if there is some other question like this where I can find congruency criterion, can I use that to prove that the 2 triangles have equal area?

[alpine sable]

WP is the same base no other similarities by default

[alpine sable]

I mean it obviously depends

If I am given to find the area of a triangle when a similarty between the other is given my path is going to be very different. But if you have some straight forward congruency criterion go for it, else find those criterions by what is given.

For example if I have a right triangle ABC with a A as the right angle, AM divides the opposite sides in two halfs, and that the other two angles are in the ratio 2:1, then the path is not straight forward to find the ratios of the sides. But what you need to do is prove the congruency here too*

Congruency is required in a lot of places, it might be straight in some, might be puzzling in others

@wispy olive

[wispy olive]

Reading.

Okay!

Thanks!

[alpine sable]

@void hearth you can post here

Perks of questions-0 lol

[void hearth]

oh okay

I'm lost at the drawn such that |x| = 3|y|

this means that the two magnitude values are equal to each other in a 1:3 ratio right

but how does that help me in the next part

[vague coral]

I don't know, but let try the exercise to find out

[wintry tartan]

can i pls get some help with a question?

[sleek elbow]

channel occupied

[wintry tartan]

oops! sorry for the interruption!

[sleek elbow]

no worries

[void hearth]

i figured it out

a) take the scalar of the entire equation

and you find 3m + n = 0

b) the only case this happens is when m = n = 0

[wispy olive]

Should not the area be 4.5.

Instead of 3?

3 * 3 = 9.
9/2 = 4.5.

[gray isle]

why are you doing 3 * 3

[alpine sable]

If there are partial derivatives, are there partial integrals or smthn? 🤔

[vague coral]

kinda, but we call that double integration or triple integration, etc...

[alpine sable]

Oh cool

[void hearth]

it says CD = b - a but I have no clue how you get to that point

[viscid cove]

a+b=ac

-ac+ad=cd

[granite mountain]

that’s not going to work

[viscid cove]

2bc=ad ? (property of regular hexagon, dunno if you can use it)

rly?

[granite mountain]

The second one might work lemme try

[glass lichen]

I mean that property is proven in part b

so likely shouldnt use it in a

[viscid cove]

yeah that's what i thought

[granite mountain]

This one works

[glass lichen]

no

you cant use that for a

since you prove it in b

[viscid cove]

lol, why wouldnt the previous one work then? its all connected

[granite mountain]

Maybe i just don’t know how to make it work

[viscid cove]

i think you can prove b) first

huh? well instead of interrupting, maybe you shouldve let me shown you how its done

[glass lichen]

I mean, b kinda wants you to show that BE is a scalar multiple of CD

then conclude the property

[granite mountain]

For b. ?

[void hearth]

if we're thinking about solving b) and using the results to get a)

but either way I wouldnt know how this works out

[granite mountain]

No, I don’t see how we can use b to solve a

[void hearth]

it'd be appreciated for a full solution, since i've tried every vector combination I can think of

[glass lichen]

let O be the center of the the hexagon... then AO = b

so AD = 2b

[granite mountain]

Exactly and then it’s Ez

[glass lichen]

since it's equilateral triangles

or you can just do CO + OD

[viscid cove]

lia, are you sure you know what you're talking about?

[glass lichen]

and that avoids the point I raised earlier

[void hearth]

I can see it but that assumes you know its all equilateral triangles

[glass lichen]

well it's given

so you can assume that...

it's a regular hexagon

[void hearth]

I suppose, although in my school curriculum we never learn about hexagons

with the nitty gritty triangles, deriving area formula, and so on

[glass lichen]

ok... well it's obvious now that CD = b-a

[viscid cove]

angle in a regular hexagon is 120 so the triangles produced bisect it yada yada

[void hearth]

yeah okay thanks

[viscid cove]

so b) then a) ig

[glass lichen]

no you dont need any result from b to do a

$\vec{CD}=\vec{CO}+\vec{OD}=-a+b$

[ocean seal]

Mosh

[viscid cove]

lol nvm didnt see it was a different side

[alpine sable]

hello

this problem, i use lhospitals rule and i get 1/1/(n+2)

[slender forge]

U taking a limit?

[alpine sable]

diverges or converges

so essentially taking the limit 😛

but my question is, does the bottom n+2 essentially multiply by the top 1 in the numerator

which would make it grow to infinity?

[slender forge]

Yes it goes to (n+2)

[alpine sable]

im just trying to concepturalize here, after you do this limit

do you take that as the series, or do you multiply up and get the finial form to be (n+2)

i think im overthinking it so nevermind

its just the series would be 3, 4, 5, 6 etc then right

because its n + 2

[glass lichen]

$\lim_{n\to\infty}s_n=\lim_{n\to\infty}(n+2)=\infty$

[ocean seal]

Mosh

[alpine sable]

thank you so much. i just needed some conformation 🙂

now with this one here...

im sure the series diverges

but, what does it mean by the sequence?

[jagged raptor]

the sequence is d_n

[alpine sable]

so its asking if the outcome of each series variable is gonna come to 0 or not

is checked / (time_elapsed / 60) equivalent to checked_per_minute in the following python code?

checkpoint = checked  # we create a checkpoint so we can calculate the amount of checks during these 2 following seconds
time.sleep(2)  # sleeps for 2 seconds
checked_per_minute = (checked - checkpoint) * 30 

im trying to find an algorithm to calculate the amount of checks per minute

without having to wait 60 seconds

[jagged raptor]

its asking for $\lim _{n\rightarrow \infty }\dfrac{7-8n}{4+3n}$

[ocean seal]

michαel

[jagged raptor]

if the limit exists then it converges if it doesnt then it diverges

[alpine sable]

then why is there two questions

oh wait okay

[jagged raptor]

they have part a and b like that bc you can use the answer from part (a) to answer part b

[alpine sable]

it has a limit

its -8/3

[jagged raptor]

yes

and you can use that to answer part b

[alpine sable]

well thats not zero

so it shouldnt

[jagged raptor]

yeah

so the series diverges

[alpine sable]

ah okay so i didnt know that was a thing okay sweet. this is just to prove that a function can have a limit and converge, but its series can diverge

[tall ermine]

How do I figure this out?

[alpine sable]

plug and chug?

[tall ermine]

I did but I got -2 and -7

But there is no -7 on the graph so maybe I'm wrong

This is what I got

Uhh nvm

[unborn dome]

can someone help me with this

i think its 2pi/b = 6 but im not so sure
so i think thats b = pi/3
so think thats y = -3sin(pi/3 * x - 2

[median tendon]

Graph it and you'll find out

[void hearth]

use desmos

[median tendon]

I'll give you a few steps to follow for a problem like this:

Find the period visually (count how long in the x axis it takes from one peak to the next)

Find the angular frequency by using the formula omega= 2pi/T where T is the period and omega is the angular frequency.
This is your k value

Then look at the amplitude of the function visually, (count the length in the y axis from bottom peak to top peak and divide by 2)
This is your A value

And C is just how much you need to shift your graph up or down

[unborn dome]

oh right i figured it out

@median tendon its 2pi/7x) -2

i mean

2sin

this

[rustic zenith]

82×20

What anser

[paper bobcat]

Nat sur,e

[rustic zenith]

You look like Tony the tree

[paper bobcat]

i am

[sly mantle]

ok nami cleaned

[heavy spear]

can someone help me with the Theta =3

part i dont understand what it means

[ionic jewel]

can you check if pi-3 is right? i think it is but I'm a bit unsure what the question means

[heavy spear]

you mean 3pi

?

[glass lichen]

no, they mean what they wrote...

[heavy spear]

i dont know i guess i can skip it i dont understand what it means

[ionic jewel]

it's the same thing as question 2

[heavy spear]

oh oik

[ionic jewel]

you found pi/4 by doing pi-3pi/4

[heavy spear]

ok

[ionic jewel]

so I'm getting pi-3 by doing pi-3

[hoary wasp]

hi

nvm

[dawn galleon]

whats c, d e

[ionic jewel]

c is called projection, you can look up the formula

d is called a cross product, you can look up the formula

[dawn galleon]

p = (a·b / b·b) * b

so how do i solve for c

[ionic jewel]

what

you literally have the formula

plug in the numbers

also for e) the area of the parallelogram is the magnitude of the cross product between the two vectors

[dawn galleon]

p=-4,5,-1 x 2,-3,9)/2,-3,9,2,-3,9)2,-3,9)

[dawn galleon]

hello

😭

can someone just do c d e for me

[sly mantle]

@dawn galleon pls don’t just ask for answers. try finding relevant formulae in notes/google and doing it yourself, if you’re stuck then say what you tried

[dawn galleon]

very hard

pls help

google no help

[sly mantle]

google vector projection, cross product, area of parallelogram defined by vectors

[dawn galleon]

ik formula but idk how to plug them in

can u plug the numbers in for me and ill solve from their

[true cairn]

Hi

I need help with this one

How do I go about doing this

[mossy lion]

so theyre telling you that we have some function which brings -5 to 1, -3 to 9, etc.
the inverse just takes the reverse. so if the function brings 1 to 3, then the inverse will bring 3 to 1, for example

[true cairn]

Ok so

the inverse

so for the first one is it 3

[mossy lion]

not quite.
take another example that they give us:
the function brings -3 to 9 and 3 to 9.
so the inverse does the opposite. it bring 9 to -3 and 9 to 3
the blanks are in the spots that 1 is pointing to.

[true cairn]

But on the other graph

it seems 1 is to 3

This is a completely new topic for me

[dawn galleon]

ok i did c and d

cna someone check

if i do that coorect

[topaz scaffold]

The perimeter is the 2 times the length plus the width

[gray isle]

wait, test? emergency?

as in being assessed live?

<@&268886789983436800>

[topaz scaffold]

Rip

Sorry

[dreamy cedar]

Goodbye my prince

[topaz scaffold]

I thought he meant like study guide

[dawn galleon]

hello sir

may u check my work

[topaz scaffold]

This one?

[dawn galleon]

ye so for
A) -32
B) 120.616 degree
C) ??????
D) (42 ,34, 2)
E) 2sqrt731

[topaz scaffold]

You know the formula for vector projection?

[dawn galleon]

For c?

[topaz scaffold]

Yea

[dawn galleon]

p = (a·b / b·b) * b this
Also is my a, b , d and e correct??

[topaz scaffold]

¯\_(ツ)_/¯

I'm in bed and I don't want to get paper and do it

[topaz scaffold]

Do a dot b and b dot b

Those should return scalers

Which then you divide

[dawn galleon]

can u do C for me please not on paper

on here

[topaz scaffold]

a dot b is -42 + 5-3 + -1*9

b dot b is 22 + -3-3 + 9*9

Divide the first value by the second one

And then multiply vector b by that

[dawn galleon]

,calc divide -42 + 5-3 + -19 by 22 + -3-3 + 99

[ocean seal]

The following error occured while calculating:
Error: Unexpected type of argument in function subtract (expected: Array or DenseMatrix or SparseMatrix or Matrix, actual: number, index: 1)

[dawn galleon]

,w divide -42 + 5-3 + -1 * 9/22 + -3-3 + 9 * 9

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Maindisabled#0941

[dawn galleon]

[topaz scaffold]

Oof just realized discord just ate all my asterisks

a dot b is -4•2 + 5•-3 + -1•9
b dot b is 2•2 + -3•-3 + 9•9

There we go

[dawn galleon]

,w divide -4•2 + 5•-3 + -1•9 by 2•2 + -3•-3 + 9•9

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Maindisabled#0941

[dawn galleon]

and now?

[topaz scaffold]

Scale vector b by that

[dawn galleon]

whats scale vector b?

[topaz scaffold]

Multiply the vector by $-\frac{16}{47}$

[ocean seal]

RipeOrange

[dawn galleon]

so {2, -3, 9} x-16/47

[topaz scaffold]

Yea

[dawn galleon]

,w {2, -3, 9} x-16/47

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Maindisabled#0941

[dawn galleon]

wtf

[topaz scaffold]

Do you even know how to multiply a vector by a scaler?

[dawn galleon]

no 😦

[frail gulch]

Wait how are you working with vectors then …

I guess, just imagine its a parenthesis bracket and multiply individual terms by the scalar …

You know these questions would make a lot more sense and be a lot easier to do if you spent like 5 minutes reading what a vector actually represents

[dawn galleon]

cause me have vector class

[random talon]

How would you approach this problem?

[dawn galleon]

{2, -3, 9} X -16/47

i get

(-1,11)

<@&286206848099549185>

[vale wigeon]

what does this even mean?

[dawn galleon]

😭

ok i show u question ok

[vale wigeon]

yes, please do that

[dawn galleon]

its c

[vale wigeon]

so you're projecting a onto b...

[ionic jewel]

he doesn't know vector-scalar multiplication for context ann

[vale wigeon]

pray tell how you would get (-1, 11), a two-dimensional vector, from doing this to two vectors in three-dimensional space?

wait he doesn't??

what

[ionic jewel]

see here:

[vale wigeon]

@dawn galleon so you do not know that multiplying a vector by a scalar simply means multiplying each component by the scalar separately?

or to put that more symbolically, c * [x, y, z] = [cx, cy, cz]

[dawn galleon]

ye 😦

[vale wigeon]

so even though i just told you this fact, there's a mysterious force stopping you from applying it.

did i get that right?

[dawn galleon]

yes

[vale wigeon]

that's quite the conundrum then.

[dawn galleon]

please easy english

[vale wigeon]

is english not your native language?

[dawn galleon]

yes english isnt my first language

ye

[vale wigeon]

if you don't mind sharing, what is it?

[dawn galleon]

what is

[vale wigeon]

your first language.

what's your first language?

[dawn galleon]

urdu

[vale wigeon]

okay nevermind

[dawn galleon]

16

[vale wigeon]

also please don't reply-ping me all the time

it's kind of annoying

[dawn galleon]

sorry

[vale wigeon]

read this again

do i understand correctly that (a) you didn't know this until now, and (b) you read this and understand it, but can't apply it to your problem for some reason?

[dawn galleon]

yes 1 thing

can you carry me through this

[vale wigeon]

what you have is -16/47 * [2, -3, 9].

[dawn galleon]

ye

[vale wigeon]

do you understand why that is the same as [-16/47 * 2, -16/47 * (-3), -16/47 * 9]?

[dawn galleon]

yes i do you just change the numbers up

[vale wigeon]

...hold on

@steel palm channel busy please move

[steel palm]

my bad

sorry

[vale wigeon]

@dawn galleon so you knew this?

but you couldn't write it out until i said it?

[dawn galleon]

no i didnt know it you told me it

[vale wigeon]

okay

do i need to hand-hold you through doing the arithmetic to simplify -16/47 * 2, -16/47 * (-3) and -16/47 * 9?

[dawn galleon]

yes please

[vale wigeon]

okay

do you know how to multiply fractions?

[dawn galleon]

ye

[vale wigeon]

then do it

[hardy jacinth]

easy

[vale wigeon]

multiply -16/47 by 2

[dawn galleon]

-32/94

[hardy jacinth]

wrong

[vale wigeon]

no, that's incorrect. you didn't multiply it by 2.

you multiplied it by 2/2, a.k.a. 1

[hardy jacinth]

here easy see

[vale wigeon]

...

[hardy jacinth]

lets say 1/2 and you need to multiply it by 2

[vale wigeon]

@hardy jacinth if you're so eager to interrupt me, why don't you take the reins?

[dawn galleon]

then what is it

[hardy jacinth]

i thought anyone can try to help on help channels?

[vale wigeon]

yes, kirai. and i'm inviting you to do just that.

go ahead.

explain to maindisabled how to multiply -16/47 by 2.

@alpine sable no spam.

[carmine lion]

wtf

[hardy jacinth]

no i mean i thought everyone can try to help, one helper per person isnt a must i mean

[carmine lion]

fuck off @alpine sable

this channel is occupied

"got it to stop"

[hardy jacinth]

no, @KIRAI#7777 if you're so eager to interrupt me, why don't you take the reins? this isnt the same as what you said just now

[carmine lion]

??

u running a bot?

[sly mantle]

@alpine sable knock it off

[dawn galleon]

,cal -16/47 by 2.

[hardy jacinth]

you thought i was interrupting you, but i was trying to help the other person, both are different

[dawn galleon]

,w -16/47 by 2.

[carmine lion]

it seems space sheep is running a bot

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Maindisabled#0941

[dawn galleon]

,w -16/47 by 2

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Maindisabled#0941

[dawn galleon]

hi what is -16/47 by 2

bot is not working

[hardy jacinth]

bot is working just fine

[sly mantle]

see texit result

[dawn galleon]

it was lagging for me now i see

[dawn galleon]

-32/47

[hardy jacinth]

ok so here is how to multiply fractions

[dawn galleon]

yes

[hardy jacinth]

first remember that every rational number can be expressed in fractions

[dawn galleon]

-16/47 * 2, -16/47 * (-3) and -16/47 * 9? i need to solve this, that is what anny said

oh

[hardy jacinth]

lets say you need to multiply 1/2 by 2

[dawn galleon]

yes

[hardy jacinth]

2 represented in fracctions is 2/1

and you know to multiply fractions, you need to multiply the numerator (upper number) to the numerator of the second fraction and denominator (lower number) to the denominator of the second fraction

so

1/2 x 2/1 =
1 x 2 = 2
2 x 1 = 2

2/2

[dawn galleon]

yes i get it

[hardy jacinth]

good

[dawn galleon]

so -16/47 * 2, -16/47 * (-3) and -16/47 * 9?
for this
it will be -36/47, 46/47 and 144/47

[hardy jacinth]

you got it

[dawn galleon]

and so 154/47

[hardy jacinth]

you should look for a yt video that explains fractional multiplication

because multiplying is not all

[dawn galleon]

Yes

[hardy jacinth]

you might wanna divide it instead

to simplify it

[dawn galleon]

Ty

@vale wigeon Hi ann sorry for ping i wont do it again
so c is 154/47

[vale wigeon]

no, the answer to c is not a single number.

it's a vector.

but none of its components are equal to 154/47, so you are very far from the right answer anyway.

[gaunt magnet]

ugh

[carmine lion]

i am so confused as to why op doesn't know multiplication and is doing a problem on vectors

[vale wigeon]

also, for that matter... it looks like you really wanted to have the bot do the calculation for you

but you were struggling with getting the bot to understand you

[dawn galleon]

can u make me come close very close

the bot understands me

[vale wigeon]

for one, multiplication is typically written with an asterisk * and not the letter x or anything else

,w -16/47 * [2, -3, 9]

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ann#0413

[vale wigeon]

here.

the bot did it for you.

[vale wigeon]

honestly? i'm just as confused as you.

[carmine lion]

this better not be a troll istg

[dawn galleon]

so -32/47 and 48/47 and 144/47

[ionic jewel]

last one negative

[vale wigeon]

also replacing the commas with 'and' is inappropriate here.

[gaunt magnet]

How on earth is this possible

[gaunt magnet]

wtf

[dawn galleon]

that was easy

[vale wigeon]

this is a vector. it has three numbers as coordinates. you should not be writing the commas between them as 'and'.

[dawn galleon]

by the way

if u all are wondering why im doing vectors bcuz

[slate heron]

bro it's just [-16/47 X 2, -16/47 X -3, -16/47 X 9]
if you remember that you wont have to use a calculator next time

[dawn galleon]

anny confuse me more

thats why

[slate heron]

huh?

[ionic jewel]

Ann literally told you the same thing and you couldn't multiply it out

[carmine lion]

???

holdup

[vale wigeon]

ok first off don't use the letter x for multiplication
and second i said this way back, there's no need to repeat it again

[carmine lion]

you've done it now

Ann is gonna explode

[slate heron]

too lazy to do \*

[ionic jewel]

yes I'm waiting why are you doing vectors?

i have to know

[vale wigeon]

you could just do spaces on either side of the asterisk and it won't get eaten lol

[slate heron]

??????????????

[dawn galleon]

bcuz i have calculus and vectors

[slate heron]

thanks for telling me

[ionic jewel]

ur doing calculus?

[slate heron]

never knew

[vale wigeon]

calculus?! and you struggle with basic arithmetic

[carmine lion]

yet you can't do basic arithmetic?

[dawn galleon]

yes

[carmine lion]

jeesuz

[ionic jewel]

lmao

[vale wigeon]

you have to review basic arithmetic

[slate heron]

whats 9 plus 10

[vale wigeon]

ASAP

[dawn galleon]

i dont review math thats whyi forget, but dont worry i will do good

[dawn galleon]

19

[carmine lion]

you cannot proceed in more advanced areas of maths unless you know the basics first.

[vale wigeon]

i dont review math

bad

bad bad bad

very bad

[dawn galleon]

no u can

[slate heron]

incorrect, it's 21 due to the Yu-Stuped conjecture

[vale wigeon]

youre setting yourself up for failure, maindisabled.

you are SETTING YOURSELF UP FOR FAILURE.

[dawn galleon]

u dont need to use basic math when u go to calc

[carmine lion]

?????

[vale wigeon]

now you're just being obnoxious, louis.

[carmine lion]

im losing braincells

[vale wigeon]

yes you do.

all the fucking time.

[dawn galleon]

im gonna go to a good university

after this

[carmine lion]

ok i think this is definitely a troll now

[vale wigeon]

if you don't know basic math then you will NOT be able to learn any uni-level math at all.

[dawn galleon]

i can even show u

[vale wigeon]

you can't run before you crawl.

YOU CAN'T RUN BEFORE YOU CRAWL.

[dawn galleon]

if u dont beleive me

[slate heron]

which one and what degree

[carmine lion]

nah

[dawn galleon]

no i had 91% in advance functions

[carmine lion]

lets not feed the troll

bruh

mfw people say they memorise for maths

:/

[vale wigeon]

<@&268886789983436800>

just in case

[carmine lion]

yea

[dawn galleon]

i dont memorise math

because thats bad

[slate heron]

everyone memorises it to some degree

[carmine lion]

yes, but understanding and apprecieating will make you a better learner an student

[tame falcon]

What's going on here?

[sly mantle]

i’ve been lurking

[carmine lion]

a person asking for help on vectors when they can't do basic arithmetic

and they're claiming and saying all sorts of obnoxious stuff

[dawn galleon]

im telling the truth

[tame falcon]

It's in your best interest to review the basics @dawn galleon . Making a leap here is more counterproductive than helpful.

[dawn galleon]

i dont have time to review basics now

i need to learn calculus

[carmine lion]

"don't have time"??

[tame falcon]

School calculus is 20% calculus and 80% faculty with algebraic manipulations and trigonometry.

[rigid smelt]

why does it seem like you are studying very mechanically just to get high grades

[dawn galleon]

u are right

[rigid smelt]

even tho i dont think thats possible

[dawn galleon]

im studying to get high grafes only

grades

[slate heron]

about a few months ago i realised that i've been memorising most of math and never understanding the concepts behind it, and i'm re-learning math basically from scratch. it's not hard to do - and once you stack mathematical knowledge from the very basics, the better you'll do at advanced mathematics

[rigid smelt]

it seems like your teacher just tells you what to study and what not to and that will come out on the tests

which is not gonna happen in uni

[dawn galleon]

and what u learn in grade 9, 10 and 11 dosent get used in calc

[rigid smelt]

it does

[slate heron]

yes it does lol

[dawn galleon]

its all new stuff

[violet flame]

Thats so wrong

[tame falcon]

Anyway Maindisabled, if you're going to ask for help here and not review the necessary basics, it neither helps you, nor the person helping you out.

[carmine lion]

what you learn from grade 1 carries over until uni

[tame falcon]

You have a wrong impression of calculus, I'm afraid.

[carmine lion]

you can't make any progress if you don't have the basics

[slate heron]

i personally think we shouldve been taught set theory in year 1, before we even start addition

[dawn galleon]

i will come back when i get 100% on calculus

[tame falcon]

Sure. Goodluck.

[slate heron]

and forget everything about it the next year

[rigid smelt]

by having your teacher tell you what to study and then get high grades because of that, then sure

[tame falcon]

If you have no further questions, this channel is open for use.

[rigid smelt]

im just more interested in how you would do in uni

[dawn galleon]

i would work hard

[slate heron]

i guess if you're pursuing an arts subject in uni it would matter that much but still, maths is something very useful in every subject

[dawn galleon]

no computer science

[slate heron]

LMAFAOO

[dawn galleon]

i want to go to computer science

[slate heron]

WHAT

[rigid smelt]

dear god

[slate heron]

then come on dude, you have to start learning maths properly

[tame falcon]

Can we move off-topic conversation to #discussion ?

This channel could be opened up for asking questions

[gaunt magnet]

wait

hi

may i get help

[slate heron]

yes

[gaunt magnet]

for this

i got

a= -9 and b is 2

[vale wigeon]

that is correct.

[gaunt magnet]

im so smart

ok 1 more question

i got

(-1, 11)

[vale wigeon]

yes that is also correct.

[gaunt magnet]

ok good check this

we can use the definitions of the cross and dot product
$$u.v = |uv|\cos{\theta}$$
$$u \times v = |uv|\sin{\theta}$$

[ocean seal]

Usman

[gaunt magnet]

since $|u \times v| = |uv|\sin{\theta}$ and $u.v = |uv|\cos{\theta}$, sub them in
$$(|uv|\sin{\theta})^{2} + (|uv|\cos{\theta})^{2}$$
and then simplify from there

[ocean seal]

Usman

[gaunt magnet]

$$|u|^{2}|v|^{2}\sin^{2}{\theta} + |u|^{2}|v|^{2}\cos^{2}{\theta}$$
factor out $|u|^{2}|v|^{2}$ and then take a look at your hint
$$(|u|^{2}|v|^{2})\underbrace{(\sin^{2}{\theta} + \cos^{2}{\theta})}_{\text{Equal to 1}}$$
$\therefore$
$$|\vec{u} \times \vec{v}|^{2} + (\vec{u}.\vec{v})^{2} = |\vec{u}|^{2}|\vec{v}|^{2}$$

[ocean seal]

Usman

[gaunt magnet]

and you get ${(\sin^{2}{\theta} + \cos^{2}{\theta})}$

[ocean seal]

Usman

[gaunt magnet]

${(\sin^{2}{\theta} + \cos^{2}{\theta})}=1$

[ocean seal]

Usman

[gaunt magnet]

is that right

channel in use

got to another channel

[alpine sable]

oh

[dawn galleon]

Hello guys

once again

sorry to bother

but

[carmine lion]

😔

[dawn galleon]

for D do u get (42 ,34, 2)

[dawn galleon]

what

[carmine lion]

nothing

dw

[dawn galleon]

im doing good

[ionic jewel]

,w magnitude of ( (-4,5,-1) cross (2,-3,9))

yep

[dawn galleon]

🙂

[dawn galleon]

for e do u get 2sqrt731

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by 兔子#6562

[ionic jewel]

yep

[alpine sable]

can $\sqrt{a} \times \sqrt{b} = \sqrt{ab}?$

[ocean seal]

Ash Ketchum

[ionic jewel]

yep

[alpine sable]

ok

ty

(:

[gaunt magnet]

hey

quick question

[vale wigeon]

@alpine sable not just can but is (so long as a and b are both ≥ 0)

[ionic jewel]

is it not generally true in C?

never really thought about it

[gaunt magnet]

do u get 214

[placid zinc]

,w (3i + 4j + 6k) dot ((6i - k) cross (-7i + 6j + 2k))

[ocean seal]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kaynex#7520

[placid zinc]

Ye

[reef pebble]

need help,I want someone to teach me how to do this,i dont want direct answers for the Module,i want to be taught how

i need someone to help me understand this

[placid zinc]

What's your question?

Yikes there's a prayer on the top of it. Some schools, man

[ionic jewel]

positive integers greater than 6 could be written $\bZ^{\geq6}$

[ocean seal]

bunny

[ionic jewel]

oh not setbuilder

[ionic jewel]

i mean its a Christian school idk what u expect

[carmine lion]

¯_(ツ)_/¯

[placid zinc]

Oh yeah fair point

[carmine lion]

u can't really complain about that

[reef pebble]

the instructions are next to Excercise one which is literally at the bottom

[placid zinc]

So is your question exercise 1?

[ionic jewel]

$S = {n | n > 6 : n \in \bZ}$

[ocean seal]

bunny

[ionic jewel]

i dislike that you can't spoiler latex as a hint

[carmine lion]

i mean

how is the bot gonna spoiler

||$test$||

[ocean seal]

abe

[carmine lion]

damn it

[reef pebble]

no

the instructions were

[placid zinc]

,texsp spoiler

[ocean seal]

Kaynex

[carmine lion]

woah

[ionic jewel]

woah

[placid zinc]

Had to look that one up, it's not used often

[carmine lion]

thats cool

[reef pebble]

Write the rule method or set builder-notation

1. the positive integers greater than 6

@placid zinc

[ionic jewel]

that is exercise 1

[ionic jewel]

also the answer is above, not really sure how to walk people through set-builder for this but if you have questions?

[carmine lion]

what the f

BRUH

we're not done

this channel is occupied

literally 2 different people posted in here

[reef pebble]

no i mean i dont understand set notation

[carmine lion]

[reef pebble]

please help

[ionic jewel]

honestly i don't have the patience or time to explain set builder notation, but there's plenty of tutorials online (most likely a good Khan academy one) you should try watching first

[sly mantle]

axiom schema of specification go brr

[carmine lion]

1. graph the original function such that it is one to one; i.e it passes both the horizontal and vertical line test

2. draw the line y=x

3. reflect the graph of the original function across the line y=x

[mossy lion]

$S = {n | n > 6 : n \in \bZ}$

[ocean seal]

nix (@ me for the love of euler)

[mossy lion]

S is the name of the set
Inside is basically saying
"All n such that n>6 and n is an integer"
Which is just saying "all integers greater than 6"
The bar "|" is kind of the "such that"

idk hope that helps

[wintry vortex]

Earlier I had a thing that said SIN (-) = y/r Does anyone know how I would find that cheat sheet on google?

I remember the sin and cos formula but not the rest

[gray isle]

Earlier I had a thing that said SIN (-) = y/r
where are you seeing that?

oh

geez

(-) is NOT a substitute for theta

[carmine lion]

wait whaaa

why is he on a quiz

[wintry vortex]

It was in my study guide but I didnt save it as a picture

[slate heron]

LMAO

[wintry vortex]

I dont have that symbol on my keyboard either =p

[slate heron]

θ this is why I have greek keyboard even though I don't speak greek lol

Are you looking for something like this

[gray isle]

(t) is a great substitute

[slate heron]

What a crappy image

[gray isle]

but yeh, we can't help with timed quiz/test

[wintry vortex]

um it was a thing that said the formaul square root x^2+y^2=r

then sin = y/r and cos = x/r

[mossy lion]

I'd just Google trig identities tbh but ye thats a quiz so we can't help

[wintry vortex]

im not asking for help on the questions just was hoping someone would know of a a spot with the formulas 🙂

ty though

[mossy lion]

It looks better if you put a slash before it

$\sin(\theta)$

[hardy jacinth]

pythagoras feburary update 2022 sneak peaks:
|| JOJOJOJOJOJOJOJOJOJOJOJOJOJOJOJOJOJOJOJO ||

[ocean seal]

nix (@ me for the love of euler)

[hardy jacinth]

,help

[ocean seal]

A brief description and guide on how to use me was sent to your DMs!
Please use ,list to see a list of all my commands, and ,help cmd to get detailed help on a command!

[wintry vortex]

found a way to look at it again

thats what i meant =p

Question on the way I answered if anyone knows, does standard form mean fraction or decimal? I hate getting things wrong because the wants a really specific way its answered

[alpine sable]

is it an equilateral?

is this a test? @alpine sable

why are you on google forms if not 👀

nor a test

its a homework

if it were a test

there would be points

we have a 5 questions everyday type of homework

for each subject

ok

its an equilateral?

right??

@alpine sable

<@&286206848099549185>

how did you conclude that its a isosceles

[graceful harness]

you have to wait 15 min til helpers ping

next time

[alpine sable]

i did not

i just miclicked

but i think its equilatral

Idk what is it asking tho, the question is not clear

it is :/

what triangle is it asking about

pqr

mrn

ayo?

<@&286206848099549185>

[alpine sable]

.

[alpine sable]

.

@alpine sable what does the ratios of the sides being equal tell you about?

that the

sides are equal

not really

they are in a ratio

:/

they need not necessarily be equal

hmm

so is it an scalene?

you are doing guesswork now lol

[alpine sable]

what does it tell? about something atleast

like MN and PQ

angle m = angle q

mn=pq

[alpine sable]

what does this tell you

transvarse

parallelogram

[alpine sable]

this is incorrect too

;;-;

okay MN and PQ are probably parallel to each other (are they?) @alpine sable

its isosceles only :/

@alpine sable ...

ig equilateral

aaaaaaaaaa

[alpine sable]

are they parallel? @alpine sable

yes

they aqre

and why?

BPT

THALES THEOREM

okay

now since they are parallel

what can you conclude from that

parallelogram

ugh why

opposite sides parallel

I mean

yeah you could, but its not necessary

corresponding angles in a parallel lines

bro its equilatral right?

:/

[alpine sable]

add up to 180

what is the relation between angle rmn and rpq now? @alpine sable

they are

umm

alt exterior

no wait

not that

it the property of the transverse

like

idk exxact term

but they are equal

Corresponding angles

yes

yeah

so now your problem is done ig

soo its equilateral triangle?

now we know that 2 sides are equal

the method for the third side is similar so, do it yourself 😉

yay its equilatreal

ughghghgh no

I mean

why

isosceles triangle

right

its isosceles triangle

am i right

omsai

@alpine sable

@alpine sable

mark what you think is correct

its a homework anyways

ok done

submitted

[dim moat]

2. A manufacturer of open tin boxes wishes to make use of pieces of tin with dimensions 8 in. by 15 in.
   by cutting equal squares from the four corners and turning up the sides
   a. Let x inches be the length of the side to be cut out; express the number of cubic inches in the
   volume of the box as a function of x.
   b. What is the volume of the open tin boxes if x is 10 inches?

help i dont understand

the topic is functions

<@&286206848099549185>

[vale wigeon]

@dim moat do you still need help with this?

[dim moat]

yea

[vale wigeon]

have you made any progress?

btw are you sure the number in b is 10? it looks very strange to me

[dim moat]

that's why it is confusing

i dont get it

it needs to be <10 right?

no

less than 8

[alpine rivet]

d2(3x3)/dx2??

[vale wigeon]

@dim moat less than 4, actually.

since the dimensions of the base will be (8-2x) by (15-2x)

there's something wrong with the question, and i suspect it's to do with the numbers being wrong

[dim moat]

ohhhhhh

i get it

thank youu very much!!

[floral sentinel]

Hi I’m confused about this problem. How did they get the limits of the integral 0 to a?

[pearl marlin]

He is finding the area of fourth part of ellipse , here you can see that part is under 0 to a

Or you can see for that part , form where to where value of x varies

0 to a

[floral sentinel]

So if the integral has dx, we look at the x axis?

[pearl marlin]

Yes

[floral sentinel]

Thank you

[alpine sable]

Please explain this

[pearl marlin]

Trigonometry ratios

[tough hatch]

for any interior angle A of a right triangle

where opp is the length of the side of the triangle opposite to A
and hyp is the length of the hypotenuse of the triangle

[bleak hearth]

hey quick question

why cant i simplyfy this to -2

shouldnt the 7^2x+7^-2x cancel out

why not

[bleak hearth]

reallu

why

nah

yea

[gray isle]

basic exponent laws

[alpine sable]

$a^{-1}=\frac1a$

[ocean seal]

Em

[bleak hearth]

if x = 1 in this they equal

[bleak hearth]

ohh yea forgot about 1/49

yea mb cheif ty

that was muckin me up for a mo

mb

[alpine sable]

Sub everything in

[final osprey]

oh i thought i had to use lhopitals rule

🤦

[median tendon]

Only use lhopitals rule when 0/0 or inf/inf

[alpine sable]

I think he knows, just miscalculated

[final osprey]

Got it

Thanks

I am not sure about this one, i know (I) has to be true and probably (II) too

[pearl marlin]

Try f=x and y=1/x , now check f.g

[tough hatch]

these are not the only conditions to be satisfied so you can use lhopital's